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-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What are the full names and hire dates for employees in the same department as someone with the first name Clara?
SELECT first_name , last_name , hire_date FROM employees WHERE department_id = (SELECT department_id FROM employees WHERE first_name = "Clara");
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display the employee name ( first name and last name ) and hire date for all employees in the same department as Clara excluding Clara.
SELECT first_name , last_name , hire_date FROM employees WHERE department_id = ( SELECT department_id FROM employees WHERE first_name = "Clara") AND first_name != "Clara";
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What are the full names and hire dates for employees in the same department as someone with the first name Clara, not including Clara?
SELECT first_name , last_name , hire_date FROM employees WHERE department_id = ( SELECT department_id FROM employees WHERE first_name = "Clara") AND first_name != "Clara";
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display the employee number and name( first name and last name ) for all employees who work in a department with any employee whose name contains a ’T’.
SELECT employee_id , first_name , last_name FROM employees WHERE department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%T%' );
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What are the ids and full names for employees who work in a department that has someone with a first name that contains the letter T?
SELECT employee_id , first_name , last_name FROM employees WHERE department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%T%' );
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display the employee number, name( first name and last name ), and salary for all employees who earn more than the average salary and who work in a department with any employee with a 'J' in their first name.
SELECT employee_id , first_name , last_name , salary FROM employees WHERE salary > ( SELECT AVG (salary) FROM employees ) AND department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%J%');
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What are the ids, full names, and salaries for employees making more than average and who work in a department with employees who have the letter J in their first name?
SELECT employee_id , first_name , last_name , salary FROM employees WHERE salary > ( SELECT AVG (salary) FROM employees ) AND department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%J%');
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display the employee number and job id for all employees whose salary is smaller than any salary of those employees whose job title is MK_MAN.
SELECT employee_id , job_id FROM employees WHERE salary < ( SELECT min(salary) FROM employees WHERE job_id = 'MK_MAN' );
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What are the employee ids and job ids for employees who make less than the lowest earning employee with title MK_MAN?
SELECT employee_id , job_id FROM employees WHERE salary < ( SELECT min(salary) FROM employees WHERE job_id = 'MK_MAN' );
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display the employee number, name( first name and last name ) and job title for all employees whose salary is more than any salary of those employees whose job title is PU_MAN.
SELECT employee_id , first_name , last_name , job_id FROM employees WHERE salary > ( SELECT max(salary) FROM employees WHERE job_id = 'PU_MAN' );
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What are the employee ids, full names, and job ids for employees who make more than the highest earning employee with title PU_MAN?
SELECT employee_id , first_name , last_name , job_id FROM employees WHERE salary > ( SELECT max(salary) FROM employees WHERE job_id = 'PU_MAN' );
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display the department id and the total salary for those departments which contains at least two employees.
SELECT department_id , SUM(salary) FROM employees GROUP BY department_id HAVING count(*) >= 2;
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What are total salaries and department id for each department that has more than 2 employees?
SELECT department_id , SUM(salary) FROM employees GROUP BY department_id HAVING count(*) >= 2;
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display all the information of those employees who did not have any job in the past.
SELECT * FROM employees WHERE employee_id NOT IN (SELECT employee_id FROM job_history);
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What is all the information about employees who have never had a job in the past?
SELECT * FROM employees WHERE employee_id NOT IN (SELECT employee_id FROM job_history);
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display the department ID, full name (first and last name), salary for those employees who is highest salary in every department.
SELECT first_name , last_name , salary , department_id , MAX(salary) FROM employees GROUP BY department_id;
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What are the department ids, full names, and salaries for employees who make the most in their departments?
SELECT first_name , last_name , salary , department_id , MAX(salary) FROM employees GROUP BY department_id;
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display the first and last name, department, city, and state province for each employee.
SELECT T1.first_name , T1.last_name , T2.department_name , T3.city , T3.state_province FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id;
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What are the full names, departments, cities, and state provinces for each employee?
SELECT T1.first_name , T1.last_name , T2.department_name , T3.city , T3.state_province FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id;
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display those employees who contain a letter z to their first name and also display their last name, city.
SELECT T1.first_name , T1.last_name , T3.city FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id WHERE T1.first_name LIKE '%z%';
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What are the full names and cities of employees who have the letter Z in their first names?
SELECT T1.first_name , T1.last_name , T3.city FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id WHERE T1.first_name LIKE '%z%';
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display the department name, city, and state province for each department.
SELECT T1.department_name , T2.city , T2.state_province FROM departments AS T1 JOIN locations AS T2 ON T2.location_id = T1.location_id;
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What are the department names, cities, and state provinces for each department?
SELECT T1.department_name , T2.city , T2.state_province FROM departments AS T1 JOIN locations AS T2 ON T2.location_id = T1.location_id;
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display the full name (first and last name ) of employee with ID and name of the country presently where (s)he is working.
SELECT T1.first_name , T1.last_name , T1.employee_id , T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id JOIN countries AS T4 ON T3.country_id = T4.country_id;
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What the full names, ids of each employee and the name of the country they are in?
SELECT T1.first_name , T1.last_name , T1.employee_id , T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id JOIN countries AS T4 ON T3.country_id = T4.country_id;
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display the department name and number of employees in each of the department.
SELECT department_name , COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id GROUP BY department_name;
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What are the department names and how many employees work in each of them?
SELECT department_name , COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id GROUP BY department_name;
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- display the full name (first and last name), and salary of those employees who working in any department located in London.
SELECT first_name , last_name , salary FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id WHERE T3.city = 'London';
-- Database schema | regions : REGION_ID [ INT ] primary_key , REGION_NAME [ TEXT ] | countries : COUNTRY_ID [ TEXT ] primary_key , COUNTRY_NAME [ TEXT ] , REGION_ID [ INT ] countries.REGION_ID = regions.REGION_ID | departments : DEPARTMENT_ID [ INT ] primary_key , DEPARTMENT_NAME [ TEXT ] , MANAGER_ID [ INT ] , LOCATION_ID [ INT ] | jobs : JOB_ID [ TEXT ] primary_key , JOB_TITLE [ TEXT ] , MIN_SALARY [ INT ] , MAX_SALARY [ INT ] | employees : EMPLOYEE_ID [ INT ] primary_key , FIRST_NAME [ TEXT ] , LAST_NAME [ TEXT ] , EMAIL [ TEXT ] , PHONE_NUMBER [ TEXT ] , HIRE_DATE [ TEXT ] , JOB_ID [ TEXT ] employees.JOB_ID = jobs.JOB_ID , SALARY [ INT ] , COMMISSION_PCT [ INT ] , MANAGER_ID [ INT ] , DEPARTMENT_ID [ INT ] employees.DEPARTMENT_ID = departments.DEPARTMENT_ID | job_history : EMPLOYEE_ID [ INT ] primary_key job_history.EMPLOYEE_ID = employees.EMPLOYEE_ID , START_DATE [ TEXT ] , END_DATE [ TEXT ] , JOB_ID [ TEXT ] job_history.JOB_ID = jobs.JOB_ID , DEPARTMENT_ID [ INT ] job_history.DEPARTMENT_ID = departments.DEPARTMENT_ID | locations : LOCATION_ID [ INT ] primary_key , STREET_ADDRESS [ TEXT ] , POSTAL_CODE [ TEXT ] , CITY [ TEXT ] , STATE_PROVINCE [ TEXT ] , COUNTRY_ID [ TEXT ] locations.COUNTRY_ID = countries.COUNTRY_ID | -- -- What are full names and salaries of employees working in the city of London?
SELECT first_name , last_name , salary FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id WHERE T3.city = 'London';
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the name of the song that was released in the most recent year?
SELECT song_name , releasedate FROM song ORDER BY releasedate DESC LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the name of the song that was released most recently?
SELECT song_name , releasedate FROM song ORDER BY releasedate DESC LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the id of the longest song?
SELECT f_id FROM files ORDER BY duration DESC LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- Find the id of the song that lasts the longest.
SELECT f_id FROM files ORDER BY duration DESC LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- Find the names of all English songs.
SELECT song_name FROM song WHERE languages = "english";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of all songs in English?
SELECT song_name FROM song WHERE languages = "english";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the id of songs whose format is mp3.
SELECT f_id FROM files WHERE formats = "mp3";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the id of all the files in mp3 format?
SELECT f_id FROM files WHERE formats = "mp3";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- List the name and country of origin for all singers who have produced songs with rating above 9.
SELECT DISTINCT T1.artist_name , T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.rating > 9;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the different names and countries of origins for all artists whose song ratings are above 9?
SELECT DISTINCT T1.artist_name , T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.rating > 9;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- List the file size and format for all songs that have resolution lower than 800.
SELECT DISTINCT T1.file_size , T1.formats FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T2.resolution < 800;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the file sizes and formats for all songs with a resolution lower than 800?
SELECT DISTINCT T1.file_size , T1.formats FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T2.resolution < 800;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the name of the artist who produced the shortest song?
SELECT T1.artist_name FROM song AS T1 JOIN files AS T2 ON T1.f_id = T2.f_id ORDER BY T2.duration LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of the artists who sang the shortest song?
SELECT T1.artist_name FROM song AS T1 JOIN files AS T2 ON T1.f_id = T2.f_id ORDER BY T2.duration LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names and countries of origin for the artists who produced the top three highly rated songs.
SELECT T1.artist_name , T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name ORDER BY T2.rating DESC LIMIT 3;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of the singers who sang the top 3 most highly rated songs and what countries do they hail from?
SELECT T1.artist_name , T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name ORDER BY T2.rating DESC LIMIT 3;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- How many songs have 4 minute duration?
SELECT count(*) FROM files WHERE duration LIKE "4:%";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the count of the songs that last approximately 4 minutes?
SELECT count(*) FROM files WHERE duration LIKE "4:%";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- How many artists are from Bangladesh?
SELECT count(*) FROM artist WHERE country = "Bangladesh";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- How many Bangladeshi artists are listed?
SELECT count(*) FROM artist WHERE country = "Bangladesh";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the average rating of songs produced by female artists?
SELECT avg(T2.rating) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T1.gender = "Female";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- How many songs, on average, are sung by a female artist?
SELECT avg(T2.rating) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T1.gender = "Female";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the most popular file format?
SELECT formats FROM files GROUP BY formats ORDER BY COUNT (*) DESC LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- Find the file format that is used by the most files.
SELECT formats FROM files GROUP BY formats ORDER BY COUNT (*) DESC LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- Find the names of the artists who are from UK and have produced English songs.
SELECT artist_name FROM artist WHERE country = "UK" INTERSECT SELECT artist_name FROM song WHERE languages = "english";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of the artists that are from the UK and sang songs in English?
SELECT artist_name FROM artist WHERE country = "UK" INTERSECT SELECT artist_name FROM song WHERE languages = "english";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- Find the id of songs that are available in mp4 format and have resolution lower than 1000.
SELECT f_id FROM files WHERE formats = "mp4" INTERSECT SELECT f_id FROM song WHERE resolution < 1000;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the id of the files that are available in the format of mp4 and a resolution smaller than 1000?
SELECT f_id FROM files WHERE formats = "mp4" INTERSECT SELECT f_id FROM song WHERE resolution < 1000;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the country of origin of the artist who is female and produced a song in Bangla?
SELECT T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T1.gender = "Female" AND T2.languages = "bangla";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What countries are the female artists who sung in the language Bangla from?
SELECT T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T1.gender = "Female" AND T2.languages = "bangla";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the average duration of songs that have mp3 format and resolution below 800?
SELECT avg(T1.duration) FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.formats = "mp3" AND T2.resolution < 800;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the average song duration for the songs that are in mp3 format and whose resolution below 800?
SELECT avg(T1.duration) FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.formats = "mp3" AND T2.resolution < 800;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the number of artists for each gender?
SELECT count(*) , gender FROM artist GROUP BY gender;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- How many artists are male and how many are female?
SELECT count(*) , gender FROM artist GROUP BY gender;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the average rating of songs for each language?
SELECT avg(rating) , languages FROM song GROUP BY languages;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the average song rating for each language?
SELECT avg(rating) , languages FROM song GROUP BY languages;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- Return the gender and name of artist who produced the song with the lowest resolution.
SELECT T1.gender , T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name ORDER BY T2.resolution LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the gender and name of the artist who sang the song with the smallest resolution?
SELECT T1.gender , T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name ORDER BY T2.resolution LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- For each file format, return the number of artists who released songs in that format.
SELECT count(*) , formats FROM files GROUP BY formats;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- How many songs were released for each format?
SELECT count(*) , formats FROM files GROUP BY formats;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- Find the distinct names of all songs that have a higher resolution than some songs in English.
SELECT DISTINCT song_name FROM song WHERE resolution > (SELECT min(resolution) FROM song WHERE languages = "english");
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the different names for all songs that have a higher resolution than English songs?
SELECT DISTINCT song_name FROM song WHERE resolution > (SELECT min(resolution) FROM song WHERE languages = "english");
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of all songs that have a lower rating than some song of blues genre?
SELECT song_name FROM song WHERE rating < (SELECT max(rating) FROM song WHERE genre_is = "blues");
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of the songs that have a lower rating than at least one blues song?
SELECT song_name FROM song WHERE rating < (SELECT max(rating) FROM song WHERE genre_is = "blues");
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the name and country of origin of the artist who released a song that has "love" in its title?
SELECT T1.artist_name , T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.song_name LIKE "%love%";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of the artists who released a song that has the word love in its title, and where are the artists from?
SELECT T1.artist_name , T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.song_name LIKE "%love%";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- List the name and gender for all artists who released songs in March.
SELECT T1.artist_name , T1.gender FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.releasedate LIKE "%Mar%";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names and genders of all artists who released songs in the month of March?
SELECT T1.artist_name , T1.gender FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.releasedate LIKE "%Mar%";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- List the names of all genres in alphabetical oder, together with its ratings.
SELECT g_name , rating FROM genre ORDER BY g_name;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of all genres in alphabetical order, combined with its ratings?
SELECT g_name , rating FROM genre ORDER BY g_name;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- Give me a list of the names of all songs ordered by their resolution.
SELECT song_name FROM song ORDER BY resolution;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of all songs that are ordered by their resolution numbers?
SELECT song_name FROM song ORDER BY resolution;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the ids of songs that are available in either mp4 format or have resolution above 720?
SELECT f_id FROM files WHERE formats = "mp4" UNION SELECT f_id FROM song WHERE resolution > 720;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the ids of all songs that are available on mp4 or have a higher resolution than 720?
SELECT f_id FROM files WHERE formats = "mp4" UNION SELECT f_id FROM song WHERE resolution > 720;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- List the names of all songs that have 4 minute duration or are in English.
SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.duration LIKE "4:%" UNION SELECT song_name FROM song WHERE languages = "english";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of all songs that are approximately 4 minutes long or are in English?
SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.duration LIKE "4:%" UNION SELECT song_name FROM song WHERE languages = "english";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the language used most often in the songs?
SELECT languages FROM song GROUP BY languages ORDER BY count(*) DESC LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the languages that are used most often in songs?
SELECT languages FROM song GROUP BY languages ORDER BY count(*) DESC LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the language that was used most often in songs with resolution above 500?
SELECT artist_name FROM song WHERE resolution > 500 GROUP BY languages ORDER BY count(*) DESC LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the name of the artist, for each language, that has the most songs with a higher resolution than 500?
SELECT artist_name FROM song WHERE resolution > 500 GROUP BY languages ORDER BY count(*) DESC LIMIT 1;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of artists who are Male and are from UK?
SELECT artist_name FROM artist WHERE country = "UK" AND gender = "Male";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of all male British artists?
SELECT artist_name FROM artist WHERE country = "UK" AND gender = "Male";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- Find the names of songs whose genre is modern or language is English.
SELECT song_name FROM song WHERE genre_is = "modern" OR languages = "english";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of the songs that are modern or sung in English?
SELECT song_name FROM song WHERE genre_is = "modern" OR languages = "english";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- Return the names of songs for which format is mp3 and resolution is below 1000.
SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.formats = "mp3" INTERSECT SELECT song_name FROM song WHERE resolution < 1000;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of all songs that are in mp3 format and have a resolution lower than 1000?
SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.formats = "mp3" INTERSECT SELECT song_name FROM song WHERE resolution < 1000;
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- Return the names of singers who are from UK and released an English song.
SELECT artist_name FROM artist WHERE country = "UK" INTERSECT SELECT T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.languages = "english";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the names of all singers that are from the UK and released a song in English?
SELECT artist_name FROM artist WHERE country = "UK" INTERSECT SELECT T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.languages = "english";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the average rating and resolution of songs that are in Bangla?
SELECT avg(rating) , avg(resolution) FROM song WHERE languages = "bangla";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What is the average rating and resolution of all bangla songs?
SELECT avg(rating) , avg(resolution) FROM song WHERE languages = "bangla";
-- Database schema | genre : g_name [ TEXT ] primary_key , rating [ TEXT ] , most_popular_in [ TEXT ] | artist : artist_name [ TEXT ] primary_key , country [ TEXT ] , gender [ TEXT ] , preferred_genre [ TEXT ] artist.preferred_genre = genre.g_name | files : f_id [ INT ] primary_key , artist_name [ TEXT ] files.artist_name = artist.artist_name , file_size [ TEXT ] , duration [ TEXT ] , formats [ TEXT ] | song : song_name [ TEXT ] primary_key , artist_name [ TEXT ] song.artist_name = artist.artist_name , country [ TEXT ] , f_id [ INT ] song.f_id = files.f_id , genre_is [ TEXT ] song.genre_is = genre.g_name , rating [ INT ] , languages [ TEXT ] , releasedate [ TEXT ] , resolution [ INT ] | -- -- What are the maximum and minimum resolution of songs whose duration is 3 minutes?
SELECT max(T2.resolution) , min(T2.resolution) FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.duration LIKE "3:%";