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73 |
help-10
|
f34195970210460f8cbf7eebc50bcdc4
| 758,664,761,038,078,000 |
Michael (Avo)
|
01/14/2022 23:45:49
|
thats the next question?
| 0 | 1 | null | null | null | null | null |
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73 |
help-10
|
f34195970210460f8cbf7eebc50bcdc4
| 758,664,761,038,078,000 |
Michael (Avo)
|
01/14/2022 23:45:55
|
oh lol
| 0 | 1 | null | null | null | null | null |
|||||
73 |
help-10
|
f34195970210460f8cbf7eebc50bcdc4
| 839,040,537,881,346,000 |
! QWERTY
|
01/14/2022 23:45:59
|
Lol
| 1 | 0 | null | null | null | null | null |
|||||
73 |
help-10
|
f34195970210460f8cbf7eebc50bcdc4
| 758,664,761,038,078,000 |
Michael (Avo)
|
01/14/2022 23:46:01
|
ye basically that
| 0 | 1 | null | null | null | null | null |
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73 |
help-10
|
f34195970210460f8cbf7eebc50bcdc4
| 839,040,537,881,346,000 |
! QWERTY
|
01/14/2022 23:46:30
|
-18m⁷n⁴/m⁴
| 1 | 0 | null | null | null | null | null |
|||||
73 |
help-10
|
f34195970210460f8cbf7eebc50bcdc4
| 839,040,537,881,346,000 |
! QWERTY
|
01/14/2022 23:46:36
|
Is this the answer
| 1 | 0 | null | null | null | null | null |
|||||
73 |
help-10
|
f34195970210460f8cbf7eebc50bcdc4
| 758,664,761,038,078,000 |
Michael (Avo)
|
01/14/2022 23:46:43
|
well how about your m
| 0 | 1 | null | null | null | null | null |
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73 |
help-10
|
f34195970210460f8cbf7eebc50bcdc4
| 758,664,761,038,078,000 |
Michael (Avo)
|
01/14/2022 23:46:48
|
you can still simplify your m
| 0 | 1 | null | null | null | null | null |
|||||
73 |
help-10
|
f34195970210460f8cbf7eebc50bcdc4
| 839,040,537,881,346,000 |
! QWERTY
|
01/14/2022 23:47:06
|
-18m³n⁴ ?
| 1 | 0 | null | null | null | null | null |
|||||
73 |
help-10
|
f34195970210460f8cbf7eebc50bcdc4
| 758,664,761,038,078,000 |
Michael (Avo)
|
01/14/2022 23:47:12
|
yes yes
| 0 | 1 | null | null | null | null | null |
|||||
73 |
help-10
|
f34195970210460f8cbf7eebc50bcdc4
| 839,040,537,881,346,000 |
! QWERTY
|
01/14/2022 23:47:28
|
Ok thanks
| 1 | 0 | null | null | null | null | null |
|||||
73 |
help-10
|
f34195970210460f8cbf7eebc50bcdc4
| 839,040,537,881,346,000 |
! QWERTY
|
01/14/2022 23:47:35
|
Thia is easier than what I thought
| 1 | 0 | null | null | null | null | null |
|||||
73 |
help-10
|
f34195970210460f8cbf7eebc50bcdc4
| 839,040,537,881,346,000 |
! QWERTY
|
01/14/2022 23:47:38
|
.close
| 1 | 0 | null | null | null | null | null |
|||||
74 |
help-10
|
8839f29b919d476cbd64a04259c4de39
| 280,473,855,888,326,660 |
Dicypher
|
01/15/2022 00:26:13
|
im not sure how to solve this
|
unknown.png
| 1 | 0 | null | null | null | null | null |
||||
74 |
help-10
|
8839f29b919d476cbd64a04259c4de39
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 00:28:06
|
an arithmetic progression is a progression of the form a, a+d, a+2d, a+3d, ...
| 0 | 1 | null | null | null | null | null |
|||||
74 |
help-10
|
8839f29b919d476cbd64a04259c4de39
| 692,870,652,583,215,100 |
LordTenebrous2
|
01/15/2022 00:29:07
|
3x+4 is the arithmetic mean of x, 10x - 7 so 3x+4 = (x+10x-7)/2
| 0 | 1 | null | null | null | null | null |
|||||
74 |
help-10
|
8839f29b919d476cbd64a04259c4de39
| 733,395,796,489,273,500 |
Playmaker
|
01/15/2022 00:29:12
|
the difference of any consecutive terms should be same
| 0 | 1 | null | null | null | null | null |
|||||
74 |
help-10
|
8839f29b919d476cbd64a04259c4de39
| 733,395,796,489,273,500 |
Playmaker
|
01/15/2022 00:29:42
|
as camileone said u can see there is an increment of d
| 0 | 1 | null | null | null | null | null |
|||||
74 |
help-10
|
8839f29b919d476cbd64a04259c4de39
| 280,473,855,888,326,660 |
Dicypher
|
01/15/2022 00:29:59
|
oh
| 1 | 0 | null | null | null | null | null |
|||||
74 |
help-10
|
8839f29b919d476cbd64a04259c4de39
| 280,473,855,888,326,660 |
Dicypher
|
01/15/2022 00:30:04
|
ok im starting to see it
| 1 | 0 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 360,346,532,895,260,700 |
quadron
|
01/15/2022 01:25:11
|
Find the domain and range of the following functions:
1. f(x) = x^2 / 1+x^2
2. f(x) = x-3 / 2x+1
I'm having troubles in understanding how the domains and ranges can be found here, so an explanation would help :)
| 1 | 0 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 01:27:28
|
the domain is all the values of x for which f is defined
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 01:28:14
|
that is, every value of x except those values where you run into weird things like zero denominators
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 360,346,532,895,260,700 |
quadron
|
01/15/2022 01:29:09
|
ohh and range is like the set containing all possible f(x)?
| 1 | 0 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 01:29:14
|
yep yep
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 360,346,532,895,260,700 |
quadron
|
01/15/2022 01:29:20
|
ohk
| 1 | 0 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 01:29:21
|
all possible values of f(x)
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 360,346,532,895,260,700 |
quadron
|
01/15/2022 01:29:26
|
yes
| 1 | 0 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 360,346,532,895,260,700 |
quadron
|
01/15/2022 01:30:21
|
how do i find them tho
| 1 | 0 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 01:33:35
|
that's when you play around with the function
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 01:33:48
|
for example, look at x^2/(1+x^2)
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 01:34:29
|
the first thing you notice is that x^2 >= 0, so both the numerator and denominator must be non-negative
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 01:34:43
|
so f(x) \geq 0 at least
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 01:35:40
|
the next thing is to notice the denominator is always bigger than the numerator, and since they're both non-negative, f(x) < 1 in the worst case
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 01:36:09
|
you can check that all values in [0,1) can be attained
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 01:36:23
|
an alternate solution is to use partial fractions, i.e.
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 510,789,298,321,096,700 |
TeXit
|
01/15/2022 01:36:51
|
**Camilleone**
|
569167697925898261.png
| 0 | 1 | null | null | null | null | null |
||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 360,346,532,895,260,700 |
quadron
|
01/15/2022 01:36:51
|
yes
| 1 | 0 | 569,167,697,925,898,240 |
Camilleone
|
1596
|
Camilleone
| false |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 758,664,761,038,078,000 |
Michael (Avo)
|
01/15/2022 01:37:37
|
yo, whats happening
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 01:37:50
|
then 1/(1+x^2) must lie in (0,1] always
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 360,346,532,895,260,700 |
quadron
|
01/15/2022 01:38:10
|
yes or <infinity
| 1 | 0 | 569,167,697,925,898,240 |
Camilleone
|
1596
|
Camilleone
| false |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 360,346,532,895,260,700 |
quadron
|
01/15/2022 01:38:42
|
ah makes sense now
| 1 | 0 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 569,167,697,925,898,240 |
Camilleone
|
01/15/2022 01:38:52
|
in general partial fractions is your best friend
| 0 | 1 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 360,346,532,895,260,700 |
quadron
|
01/15/2022 01:39:31
|
ohh got it now, tysm
| 1 | 0 | null | null | null | null | null |
|||||
75 |
help-10
|
1952d6a49ee24fbabdd0e5e8fef382f0
| 360,346,532,895,260,700 |
quadron
|
01/15/2022 01:39:47
|
.close
| 1 | 0 | null | null | null | null | null |
|||||
76 |
help-10
|
c068046258724d1d86af03447683df22
| 357,974,039,425,187,840 |
will159454
|
01/15/2022 10:13:44
|
Stuck on this question
|
unknown.png
| 1 | 0 | null | null | null | null | null |
||||
77 |
help-10
|
75cf3bc23e264cadabf46d1e009b89eb
| 772,706,247,434,698,800 |
sparkaks
|
01/15/2022 11:00:05
|
k
| 1 | 0 | null | null | null | null | null |
|||||
77 |
help-10
|
75cf3bc23e264cadabf46d1e009b89eb
| 772,706,247,434,698,800 |
sparkaks
|
01/15/2022 11:00:11
|
damn sorry
| 1 | 0 | null | null | null | null | null |
|||||
77 |
help-10
|
75cf3bc23e264cadabf46d1e009b89eb
| 772,706,247,434,698,800 |
sparkaks
|
01/15/2022 11:00:15
|
.close
| 1 | 0 | null | null | null | null | null |
|||||
78 |
help-10
|
fa49e55ad7af4006a70a3a543dcf18a1
| 644,179,230,162,157,600 |
SenZ
|
01/15/2022 11:25:56
|
d/dx (sin(tan(x ⁴)))
| 1 | 0 | null | null | null | null | null |
|||||
78 |
help-10
|
fa49e55ad7af4006a70a3a543dcf18a1
| 644,179,230,162,157,600 |
SenZ
|
01/15/2022 11:26:06
|
How to do this?
| 1 | 0 | null | null | null | null | null |
|||||
78 |
help-10
|
fa49e55ad7af4006a70a3a543dcf18a1
| 183,668,144,404,037,630 |
Ann
|
01/15/2022 11:26:31
|
⛓️ 📏
| 0 | 1 | null | null | null | null | null |
|||||
78 |
help-10
|
fa49e55ad7af4006a70a3a543dcf18a1
| 644,179,230,162,157,600 |
SenZ
|
01/15/2022 11:28:01
|
Lol
I got it as cos(tan(x⁴)) sec²(x⁴) 4x³
Is that correct
| 1 | 0 | 183,668,144,404,037,630 |
Ann
|
0413
|
Ann
| false |
|||||
78 |
help-10
|
fa49e55ad7af4006a70a3a543dcf18a1
| 183,668,144,404,037,630 |
Ann
|
01/15/2022 11:28:48
|
seems ok
| 0 | 1 | null | null | null | null | null |
|||||
78 |
help-10
|
fa49e55ad7af4006a70a3a543dcf18a1
| 644,179,230,162,157,600 |
SenZ
|
01/15/2022 11:29:42
|
Can u confirm please, im really confused cause I saw a different answer on youtube
| 1 | 0 | 183,668,144,404,037,630 |
Ann
|
0413
|
Ann
| false |
|||||
78 |
help-10
|
fa49e55ad7af4006a70a3a543dcf18a1
| 183,668,144,404,037,630 |
Ann
|
01/15/2022 11:29:58
|
what answer did you see on youtube?
| 0 | 1 | null | null | null | null | null |
|||||
78 |
help-10
|
fa49e55ad7af4006a70a3a543dcf18a1
| 183,668,144,404,037,630 |
Ann
|
01/15/2022 11:30:04
|
it might actually be the same as yours.
| 0 | 1 | null | null | null | null | null |
|||||
78 |
help-10
|
fa49e55ad7af4006a70a3a543dcf18a1
| 644,179,230,162,157,600 |
SenZ
|
01/15/2022 11:30:31
|
It showed cos(tan x⁴ ) sec²(x⁴)
| 1 | 0 | 183,668,144,404,037,630 |
Ann
|
0413
|
Ann
| false |
|||||
78 |
help-10
|
fa49e55ad7af4006a70a3a543dcf18a1
| 644,179,230,162,157,600 |
SenZ
|
01/15/2022 11:30:52
|
Which one is correct?
| 1 | 0 | null | null | null | null | null |
|||||
78 |
help-10
|
fa49e55ad7af4006a70a3a543dcf18a1
| 644,179,230,162,157,600 |
SenZ
|
01/15/2022 11:34:16
|
.close
| 1 | 0 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 490,460,036,657,840,100 |
nm1626
|
01/15/2022 11:38:48
|
unknown.png
| 1 | 0 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 490,460,036,657,840,100 |
nm1626
|
01/15/2022 11:38:57
|
Please help me
| 1 | 0 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:41:56
|
So here the problem states that the function's graph not only crosses (3, 14), but also that the derivative at that point is 0
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:42:08
|
We can get 2 equations in terms of a and b out of these facts
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:42:35
|
Since the graph crosses (3, 14), we have
14 = 3^3 + a3^2 + 45*3 + b
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:43:40
|
And also, y'(3) = 0
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 490,460,036,657,840,100 |
nm1626
|
01/15/2022 11:43:40
|
right
| 1 | 0 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:43:51
|
y'(x) = 3x^2 + 2ax + 45 using the power rule
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:43:55
|
And substituting the values yields
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:44:05
|
0 = 3*9 + 6a + 45
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:44:12
|
From here you can easily solve for a
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:44:24
|
And then solve for b using the previous equation
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 490,460,036,657,840,100 |
nm1626
|
01/15/2022 11:44:39
|
ohh alright i see
| 1 | 0 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 490,460,036,657,840,100 |
nm1626
|
01/15/2022 11:46:57
|
alright how should i do part b?
| 1 | 0 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 490,460,036,657,840,100 |
nm1626
|
01/15/2022 11:47:11
|
i have found a and b
a=-12
b=-40
| 1 | 0 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:47:49
|
So it asks us the coordinates of the other stationary point, meaning we need to find value of x for which y'(x) = 0 but x shouldn't be 3
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:47:57
|
Because we already know y is stationary at x = 3 anyways
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:48:10
|
Since y'(x) = 0 is a quadratic equation
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:48:20
|
You'll need to pick the root which isn't 3
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 348,696,743,388,381,200 |
A Lonely Bean
|
01/15/2022 11:48:22
|
And that's it
| 0 | 1 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 490,460,036,657,840,100 |
nm1626
|
01/15/2022 11:48:23
|
yes
| 1 | 0 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 490,460,036,657,840,100 |
nm1626
|
01/15/2022 11:52:02
|
OHHH
| 1 | 0 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 490,460,036,657,840,100 |
nm1626
|
01/15/2022 11:52:04
|
THANKYOUUU
| 1 | 0 | null | null | null | null | null |
|||||
79 |
help-10
|
1b6bfbc010544b65b90a09fcf5b7b6af
| 490,460,036,657,840,100 |
nm1626
|
01/15/2022 11:55:04
|
.close
| 1 | 0 | null | null | null | null | null |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 898,205,674,931,122,200 |
Dino Palavra
|
11/03/2021 16:55:39
|
.reopen
| 1 | 0 | null | null | null | null | null |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 898,205,674,931,122,200 |
Dino Palavra
|
11/03/2021 16:55:50
|
I have another question if you dont mind
| 1 | 0 | null | null | null | null | null |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 898,205,674,931,122,200 |
Dino Palavra
|
11/03/2021 16:56:19
|
@Syst3ms
| 1 | 0 | 193,692,307,453,771,780 |
Syst3ms
|
9959
|
Syst3ms
| false |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 193,692,307,453,771,780 |
Syst3ms
|
11/03/2021 16:56:27
|
go ahead
| 0 | 1 | null | null | null | null | null |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 898,205,674,931,122,200 |
Dino Palavra
|
11/03/2021 16:58:01
|
so the question was actually to do the minimal disjunctive NORMAL form, is that any different?
| 1 | 0 | null | null | null | null | null |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 898,205,674,931,122,200 |
Dino Palavra
|
11/03/2021 17:19:51
|
Are you here sir?
| 1 | 0 | null | null | null | null | null |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 898,205,674,931,122,200 |
Dino Palavra
|
11/03/2021 17:23:03
|
@Syst3ms sorry for pinging
| 1 | 0 | 193,692,307,453,771,780 |
Syst3ms
|
9959
|
Syst3ms
| false |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 193,692,307,453,771,780 |
Syst3ms
|
11/03/2021 17:23:18
|
nah
| 0 | 1 | null | null | null | null | null |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 193,692,307,453,771,780 |
Syst3ms
|
11/03/2021 17:23:34
|
the "normal" refers to the fact that each term that's OR-ed is a conjunction
| 0 | 1 | null | null | null | null | null |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 193,692,307,453,771,780 |
Syst3ms
|
11/03/2021 17:23:47
|
some literals with AND between them
| 0 | 1 | null | null | null | null | null |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 193,692,307,453,771,780 |
Syst3ms
|
11/03/2021 17:24:15
|
So for example A v (B(C v D)) is not DNF
| 0 | 1 | null | null | null | null | null |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 193,692,307,453,771,780 |
Syst3ms
|
11/03/2021 17:24:30
|
but A v BC v BD is
| 0 | 1 | null | null | null | null | null |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 898,205,674,931,122,200 |
Dino Palavra
|
11/03/2021 17:27:34
|
Alright, no more questions im out for real this time 😆 see ya!
| 1 | 0 | null | null | null | null | null |
|||||
80 |
help-10
|
5a50c3ab6e524f4dad7b10bfea20e3cf
| 898,205,674,931,122,200 |
Dino Palavra
|
11/03/2021 17:29:15
|
.close
| 1 | 0 | null | null | null | null | null |
|||||
81 |
help-10
|
611f7e56e43a47abaf2442e6ef4b8875
| 731,290,349,250,805,900 |
winteriio
|
01/15/2022 12:16:29
|
wondering if i could have some help with this question not too sure how to get the value for c
|
unknown.png
| 1 | 0 | null | null | null | null | null |
||||
81 |
help-10
|
611f7e56e43a47abaf2442e6ef4b8875
| 731,290,349,250,805,900 |
winteriio
|
01/15/2022 12:30:58
|
@Helpers <3
| 1 | 0 | null | null | null | null | null |
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