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73 | help-10 | f34195970210460f8cbf7eebc50bcdc4 | 758,664,761,038,078,000 | Michael (Avo) | 01/14/2022 23:45:49 | thats the next question? | 0 | 1 | null | null | null | null | null |
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73 | help-10 | f34195970210460f8cbf7eebc50bcdc4 | 758,664,761,038,078,000 | Michael (Avo) | 01/14/2022 23:45:55 | oh lol | 0 | 1 | null | null | null | null | null |
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73 | help-10 | f34195970210460f8cbf7eebc50bcdc4 | 839,040,537,881,346,000 | ! QWERTY | 01/14/2022 23:45:59 | Lol | 1 | 0 | null | null | null | null | null |
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73 | help-10 | f34195970210460f8cbf7eebc50bcdc4 | 758,664,761,038,078,000 | Michael (Avo) | 01/14/2022 23:46:01 | ye basically that | 0 | 1 | null | null | null | null | null |
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73 | help-10 | f34195970210460f8cbf7eebc50bcdc4 | 839,040,537,881,346,000 | ! QWERTY | 01/14/2022 23:46:30 | -18m⁷n⁴/m⁴ | 1 | 0 | null | null | null | null | null |
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73 | help-10 | f34195970210460f8cbf7eebc50bcdc4 | 839,040,537,881,346,000 | ! QWERTY | 01/14/2022 23:46:36 | Is this the answer | 1 | 0 | null | null | null | null | null |
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73 | help-10 | f34195970210460f8cbf7eebc50bcdc4 | 758,664,761,038,078,000 | Michael (Avo) | 01/14/2022 23:46:43 | well how about your m | 0 | 1 | null | null | null | null | null |
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73 | help-10 | f34195970210460f8cbf7eebc50bcdc4 | 758,664,761,038,078,000 | Michael (Avo) | 01/14/2022 23:46:48 | you can still simplify your m | 0 | 1 | null | null | null | null | null |
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73 | help-10 | f34195970210460f8cbf7eebc50bcdc4 | 839,040,537,881,346,000 | ! QWERTY | 01/14/2022 23:47:06 | -18m³n⁴ ? | 1 | 0 | null | null | null | null | null |
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73 | help-10 | f34195970210460f8cbf7eebc50bcdc4 | 758,664,761,038,078,000 | Michael (Avo) | 01/14/2022 23:47:12 | yes yes | 0 | 1 | null | null | null | null | null |
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73 | help-10 | f34195970210460f8cbf7eebc50bcdc4 | 839,040,537,881,346,000 | ! QWERTY | 01/14/2022 23:47:28 | Ok thanks | 1 | 0 | null | null | null | null | null |
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73 | help-10 | f34195970210460f8cbf7eebc50bcdc4 | 839,040,537,881,346,000 | ! QWERTY | 01/14/2022 23:47:35 | Thia is easier than what I thought | 1 | 0 | null | null | null | null | null |
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73 | help-10 | f34195970210460f8cbf7eebc50bcdc4 | 839,040,537,881,346,000 | ! QWERTY | 01/14/2022 23:47:38 | .close | 1 | 0 | null | null | null | null | null |
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74 | help-10 | 8839f29b919d476cbd64a04259c4de39 | 280,473,855,888,326,660 | Dicypher | 01/15/2022 00:26:13 | im not sure how to solve this | unknown.png | 1 | 0 | null | null | null | null | null |
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74 | help-10 | 8839f29b919d476cbd64a04259c4de39 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 00:28:06 | an arithmetic progression is a progression of the form a, a+d, a+2d, a+3d, ... | 0 | 1 | null | null | null | null | null |
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74 | help-10 | 8839f29b919d476cbd64a04259c4de39 | 692,870,652,583,215,100 | LordTenebrous2 | 01/15/2022 00:29:07 | 3x+4 is the arithmetic mean of x, 10x - 7 so 3x+4 = (x+10x-7)/2 | 0 | 1 | null | null | null | null | null |
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74 | help-10 | 8839f29b919d476cbd64a04259c4de39 | 733,395,796,489,273,500 | Playmaker | 01/15/2022 00:29:12 | the difference of any consecutive terms should be same | 0 | 1 | null | null | null | null | null |
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74 | help-10 | 8839f29b919d476cbd64a04259c4de39 | 733,395,796,489,273,500 | Playmaker | 01/15/2022 00:29:42 | as camileone said u can see there is an increment of d | 0 | 1 | null | null | null | null | null |
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74 | help-10 | 8839f29b919d476cbd64a04259c4de39 | 280,473,855,888,326,660 | Dicypher | 01/15/2022 00:29:59 | oh | 1 | 0 | null | null | null | null | null |
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74 | help-10 | 8839f29b919d476cbd64a04259c4de39 | 280,473,855,888,326,660 | Dicypher | 01/15/2022 00:30:04 | ok im starting to see it | 1 | 0 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 360,346,532,895,260,700 | quadron | 01/15/2022 01:25:11 | Find the domain and range of the following functions:
1. f(x) = x^2 / 1+x^2
2. f(x) = x-3 / 2x+1
I'm having troubles in understanding how the domains and ranges can be found here, so an explanation would help :) | 1 | 0 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 01:27:28 | the domain is all the values of x for which f is defined | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 01:28:14 | that is, every value of x except those values where you run into weird things like zero denominators | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 360,346,532,895,260,700 | quadron | 01/15/2022 01:29:09 | ohh and range is like the set containing all possible f(x)? | 1 | 0 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 01:29:14 | yep yep | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 360,346,532,895,260,700 | quadron | 01/15/2022 01:29:20 | ohk | 1 | 0 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 01:29:21 | all possible values of f(x) | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 360,346,532,895,260,700 | quadron | 01/15/2022 01:29:26 | yes | 1 | 0 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 360,346,532,895,260,700 | quadron | 01/15/2022 01:30:21 | how do i find them tho | 1 | 0 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 01:33:35 | that's when you play around with the function | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 01:33:48 | for example, look at x^2/(1+x^2) | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 01:34:29 | the first thing you notice is that x^2 >= 0, so both the numerator and denominator must be non-negative | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 01:34:43 | so f(x) \geq 0 at least | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 01:35:40 | the next thing is to notice the denominator is always bigger than the numerator, and since they're both non-negative, f(x) < 1 in the worst case | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 01:36:09 | you can check that all values in [0,1) can be attained | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 01:36:23 | an alternate solution is to use partial fractions, i.e. | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 510,789,298,321,096,700 | TeXit | 01/15/2022 01:36:51 | **Camilleone** | 569167697925898261.png | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 360,346,532,895,260,700 | quadron | 01/15/2022 01:36:51 | yes | 1 | 0 | 569,167,697,925,898,240 | Camilleone | 1596 | Camilleone | false |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 758,664,761,038,078,000 | Michael (Avo) | 01/15/2022 01:37:37 | yo, whats happening | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 01:37:50 | then 1/(1+x^2) must lie in (0,1] always | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 360,346,532,895,260,700 | quadron | 01/15/2022 01:38:10 | yes or <infinity | 1 | 0 | 569,167,697,925,898,240 | Camilleone | 1596 | Camilleone | false |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 360,346,532,895,260,700 | quadron | 01/15/2022 01:38:42 | ah makes sense now | 1 | 0 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 569,167,697,925,898,240 | Camilleone | 01/15/2022 01:38:52 | in general partial fractions is your best friend | 0 | 1 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 360,346,532,895,260,700 | quadron | 01/15/2022 01:39:31 | ohh got it now, tysm | 1 | 0 | null | null | null | null | null |
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75 | help-10 | 1952d6a49ee24fbabdd0e5e8fef382f0 | 360,346,532,895,260,700 | quadron | 01/15/2022 01:39:47 | .close | 1 | 0 | null | null | null | null | null |
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76 | help-10 | c068046258724d1d86af03447683df22 | 357,974,039,425,187,840 | will159454 | 01/15/2022 10:13:44 | Stuck on this question | unknown.png | 1 | 0 | null | null | null | null | null |
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77 | help-10 | 75cf3bc23e264cadabf46d1e009b89eb | 772,706,247,434,698,800 | sparkaks | 01/15/2022 11:00:05 | k | 1 | 0 | null | null | null | null | null |
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77 | help-10 | 75cf3bc23e264cadabf46d1e009b89eb | 772,706,247,434,698,800 | sparkaks | 01/15/2022 11:00:11 | damn sorry | 1 | 0 | null | null | null | null | null |
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77 | help-10 | 75cf3bc23e264cadabf46d1e009b89eb | 772,706,247,434,698,800 | sparkaks | 01/15/2022 11:00:15 | .close | 1 | 0 | null | null | null | null | null |
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78 | help-10 | fa49e55ad7af4006a70a3a543dcf18a1 | 644,179,230,162,157,600 | SenZ | 01/15/2022 11:25:56 | d/dx (sin(tan(x ⁴))) | 1 | 0 | null | null | null | null | null |
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78 | help-10 | fa49e55ad7af4006a70a3a543dcf18a1 | 644,179,230,162,157,600 | SenZ | 01/15/2022 11:26:06 | How to do this? | 1 | 0 | null | null | null | null | null |
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78 | help-10 | fa49e55ad7af4006a70a3a543dcf18a1 | 183,668,144,404,037,630 | Ann | 01/15/2022 11:26:31 | ⛓️ 📏 | 0 | 1 | null | null | null | null | null |
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78 | help-10 | fa49e55ad7af4006a70a3a543dcf18a1 | 644,179,230,162,157,600 | SenZ | 01/15/2022 11:28:01 | Lol
I got it as cos(tan(x⁴)) sec²(x⁴) 4x³
Is that correct | 1 | 0 | 183,668,144,404,037,630 | Ann | 0413 | Ann | false |
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78 | help-10 | fa49e55ad7af4006a70a3a543dcf18a1 | 183,668,144,404,037,630 | Ann | 01/15/2022 11:28:48 | seems ok | 0 | 1 | null | null | null | null | null |
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78 | help-10 | fa49e55ad7af4006a70a3a543dcf18a1 | 644,179,230,162,157,600 | SenZ | 01/15/2022 11:29:42 | Can u confirm please, im really confused cause I saw a different answer on youtube | 1 | 0 | 183,668,144,404,037,630 | Ann | 0413 | Ann | false |
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78 | help-10 | fa49e55ad7af4006a70a3a543dcf18a1 | 183,668,144,404,037,630 | Ann | 01/15/2022 11:29:58 | what answer did you see on youtube? | 0 | 1 | null | null | null | null | null |
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78 | help-10 | fa49e55ad7af4006a70a3a543dcf18a1 | 183,668,144,404,037,630 | Ann | 01/15/2022 11:30:04 | it might actually be the same as yours. | 0 | 1 | null | null | null | null | null |
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78 | help-10 | fa49e55ad7af4006a70a3a543dcf18a1 | 644,179,230,162,157,600 | SenZ | 01/15/2022 11:30:31 | It showed cos(tan x⁴ ) sec²(x⁴) | 1 | 0 | 183,668,144,404,037,630 | Ann | 0413 | Ann | false |
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78 | help-10 | fa49e55ad7af4006a70a3a543dcf18a1 | 644,179,230,162,157,600 | SenZ | 01/15/2022 11:30:52 | Which one is correct? | 1 | 0 | null | null | null | null | null |
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78 | help-10 | fa49e55ad7af4006a70a3a543dcf18a1 | 644,179,230,162,157,600 | SenZ | 01/15/2022 11:34:16 | .close | 1 | 0 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 490,460,036,657,840,100 | nm1626 | 01/15/2022 11:38:48 | unknown.png | 1 | 0 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 490,460,036,657,840,100 | nm1626 | 01/15/2022 11:38:57 | Please help me | 1 | 0 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:41:56 | So here the problem states that the function's graph not only crosses (3, 14), but also that the derivative at that point is 0 | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:42:08 | We can get 2 equations in terms of a and b out of these facts | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:42:35 | Since the graph crosses (3, 14), we have
14 = 3^3 + a3^2 + 45*3 + b | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:43:40 | And also, y'(3) = 0 | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 490,460,036,657,840,100 | nm1626 | 01/15/2022 11:43:40 | right | 1 | 0 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:43:51 | y'(x) = 3x^2 + 2ax + 45 using the power rule | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:43:55 | And substituting the values yields | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:44:05 | 0 = 3*9 + 6a + 45 | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:44:12 | From here you can easily solve for a | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:44:24 | And then solve for b using the previous equation | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 490,460,036,657,840,100 | nm1626 | 01/15/2022 11:44:39 | ohh alright i see | 1 | 0 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 490,460,036,657,840,100 | nm1626 | 01/15/2022 11:46:57 | alright how should i do part b? | 1 | 0 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 490,460,036,657,840,100 | nm1626 | 01/15/2022 11:47:11 | i have found a and b
a=-12
b=-40 | 1 | 0 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:47:49 | So it asks us the coordinates of the other stationary point, meaning we need to find value of x for which y'(x) = 0 but x shouldn't be 3 | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:47:57 | Because we already know y is stationary at x = 3 anyways | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:48:10 | Since y'(x) = 0 is a quadratic equation | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:48:20 | You'll need to pick the root which isn't 3 | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 348,696,743,388,381,200 | A Lonely Bean | 01/15/2022 11:48:22 | And that's it | 0 | 1 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 490,460,036,657,840,100 | nm1626 | 01/15/2022 11:48:23 | yes | 1 | 0 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 490,460,036,657,840,100 | nm1626 | 01/15/2022 11:52:02 | OHHH | 1 | 0 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 490,460,036,657,840,100 | nm1626 | 01/15/2022 11:52:04 | THANKYOUUU | 1 | 0 | null | null | null | null | null |
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79 | help-10 | 1b6bfbc010544b65b90a09fcf5b7b6af | 490,460,036,657,840,100 | nm1626 | 01/15/2022 11:55:04 | .close | 1 | 0 | null | null | null | null | null |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 898,205,674,931,122,200 | Dino Palavra | 11/03/2021 16:55:39 | .reopen | 1 | 0 | null | null | null | null | null |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 898,205,674,931,122,200 | Dino Palavra | 11/03/2021 16:55:50 | I have another question if you dont mind | 1 | 0 | null | null | null | null | null |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 898,205,674,931,122,200 | Dino Palavra | 11/03/2021 16:56:19 | @Syst3ms | 1 | 0 | 193,692,307,453,771,780 | Syst3ms | 9959 | Syst3ms | false |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 193,692,307,453,771,780 | Syst3ms | 11/03/2021 16:56:27 | go ahead | 0 | 1 | null | null | null | null | null |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 898,205,674,931,122,200 | Dino Palavra | 11/03/2021 16:58:01 | so the question was actually to do the minimal disjunctive NORMAL form, is that any different? | 1 | 0 | null | null | null | null | null |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 898,205,674,931,122,200 | Dino Palavra | 11/03/2021 17:19:51 | Are you here sir? | 1 | 0 | null | null | null | null | null |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 898,205,674,931,122,200 | Dino Palavra | 11/03/2021 17:23:03 | @Syst3ms sorry for pinging | 1 | 0 | 193,692,307,453,771,780 | Syst3ms | 9959 | Syst3ms | false |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 193,692,307,453,771,780 | Syst3ms | 11/03/2021 17:23:18 | nah | 0 | 1 | null | null | null | null | null |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 193,692,307,453,771,780 | Syst3ms | 11/03/2021 17:23:34 | the "normal" refers to the fact that each term that's OR-ed is a conjunction | 0 | 1 | null | null | null | null | null |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 193,692,307,453,771,780 | Syst3ms | 11/03/2021 17:23:47 | some literals with AND between them | 0 | 1 | null | null | null | null | null |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 193,692,307,453,771,780 | Syst3ms | 11/03/2021 17:24:15 | So for example A v (B(C v D)) is not DNF | 0 | 1 | null | null | null | null | null |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 193,692,307,453,771,780 | Syst3ms | 11/03/2021 17:24:30 | but A v BC v BD is | 0 | 1 | null | null | null | null | null |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 898,205,674,931,122,200 | Dino Palavra | 11/03/2021 17:27:34 | Alright, no more questions im out for real this time 😆 see ya! | 1 | 0 | null | null | null | null | null |
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80 | help-10 | 5a50c3ab6e524f4dad7b10bfea20e3cf | 898,205,674,931,122,200 | Dino Palavra | 11/03/2021 17:29:15 | .close | 1 | 0 | null | null | null | null | null |
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81 | help-10 | 611f7e56e43a47abaf2442e6ef4b8875 | 731,290,349,250,805,900 | winteriio | 01/15/2022 12:16:29 | wondering if i could have some help with this question not too sure how to get the value for c | unknown.png | 1 | 0 | null | null | null | null | null |
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81 | help-10 | 611f7e56e43a47abaf2442e6ef4b8875 | 731,290,349,250,805,900 | winteriio | 01/15/2022 12:30:58 | @Helpers <3 | 1 | 0 | null | null | null | null | null |
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