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205,867 |
help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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647035568076881920
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Cesar White
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02/03/2022 10:53:44
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i thought i knew this 😭😭
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nan
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nan
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nan
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nan
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help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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183668144404037632
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Kendra Brown
|
02/03/2022 10:54:58
|
are you literally in tears over this?
| 0 | 1 |
nan
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nan
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nan
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nan
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205,867 |
help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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183668144404037632
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Kendra Brown
|
02/03/2022 10:55:13
|
if so, i would advise you to do your best to calm down.
| 0 | 1 |
220517274845577216
|
Lena Jones
|
Lena Jones
|
False
| 5,449,952 |
||
205,867 |
help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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183668144404037632
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Kendra Brown
|
02/03/2022 10:55:41
|
emotional distress is a much more significant issue than one otherwise inconsequential math problem.
| 0 | 1 |
nan
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nan
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nan
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nan
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205,867 |
help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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647035568076881920
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Cesar White
|
02/03/2022 10:56:40
|
ur right. im just unsure as to how i should learn this tbh
| 1 | 0 |
nan
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nan
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nan
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nan
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205,867 |
help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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647035568076881920
|
Cesar White
|
02/03/2022 10:56:56
|
like solving simultaneous equations with 3 variables?
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,449,955 |
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205,867 |
help-1
|
1ed2083b18b84d12ba7c78fe5bdb9e5b
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183668144404037632
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Kendra Brown
|
02/03/2022 10:57:16
|
no
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,956 |
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205,867 |
help-1
|
1ed2083b18b84d12ba7c78fe5bdb9e5b
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183668144404037632
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Kendra Brown
|
02/03/2022 10:57:24
|
what you have here is not a system of equations in three variables
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nan
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nan
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nan
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nan
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205,867 |
help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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183668144404037632
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Kendra Brown
|
02/03/2022 10:57:33
|
at least, not presented as such by the problem
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nan
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nan
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nan
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nan
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help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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183668144404037632
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Kendra Brown
|
02/03/2022 10:58:11
|
rather it is a family of systems of equations in two variables (x,y) where each system within the family is identified by a number (m) called the parameter
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nan
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nan
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nan
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nan
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help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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647035568076881920
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Cesar White
|
02/03/2022 11:01:23
|
lowk not gonna lie i dont know what a parameter is
| 1 | 0 |
nan
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nan
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nan
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nan
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205,867 |
help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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647035568076881920
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Cesar White
|
02/03/2022 11:01:30
|
family of systems of equations?
| 1 | 0 |
420244167726333953
|
James Anderson
|
James Anderson
|
False
| 5,449,961 |
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205,867 |
help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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183668144404037632
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Kendra Brown
|
02/03/2022 11:02:18
|
a collection of many systems of equations
| 0 | 1 |
921607226098090074
|
Pedro Green
|
Pedro Green
|
False
| 5,449,962 |
||
205,867 |
help-1
|
1ed2083b18b84d12ba7c78fe5bdb9e5b
|
183668144404037632
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Kendra Brown
|
02/03/2022 11:02:33
|
...have you used desmos before in any capacity?
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,963 |
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205,867 |
help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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647035568076881920
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Cesar White
|
02/03/2022 11:03:24
|
tep
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,449,964 |
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205,867 |
help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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647035568076881920
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Cesar White
|
02/03/2022 11:03:25
|
yep
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,449,965 |
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205,867 |
help-1
|
1ed2083b18b84d12ba7c78fe5bdb9e5b
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647035568076881920
|
Cesar White
|
02/03/2022 11:03:29
|
to graph equations
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,449,966 |
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205,867 |
help-1
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1ed2083b18b84d12ba7c78fe5bdb9e5b
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183668144404037632
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Kendra Brown
|
02/03/2022 11:03:59
|
you can think of m as a slider
| 0 | 1 |
235104133110169610
|
Marc Garcia
|
Marc Garcia
|
False
| 5,449,967 |
||
205,867 |
help-1
|
1ed2083b18b84d12ba7c78fe5bdb9e5b
|
183668144404037632
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Kendra Brown
|
02/03/2022 11:04:18
|
and each of these equations as a line that is graphed
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,968 |
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205,867 |
help-1
|
1ed2083b18b84d12ba7c78fe5bdb9e5b
|
183668144404037632
|
Kendra Brown
|
02/03/2022 11:04:46
|
and your task is to find the position(s) of the slider at which certain things happen
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,969 |
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205,867 |
help-1
|
1ed2083b18b84d12ba7c78fe5bdb9e5b
|
183668144404037632
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Kendra Brown
|
02/03/2022 11:04:54
|
such as the system having infinitely many solutions, as in your problem
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,970 |
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205,867 |
help-1
|
1ed2083b18b84d12ba7c78fe5bdb9e5b
|
647035568076881920
|
Cesar White
|
02/03/2022 11:09:04
|
ohh ok!!
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,449,971 |
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205,867 |
help-1
|
1ed2083b18b84d12ba7c78fe5bdb9e5b
|
647035568076881920
|
Cesar White
|
02/03/2022 11:09:25
|
can you recommend a video that would teach me all this?
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,449,972 |
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205,867 |
help-1
|
1ed2083b18b84d12ba7c78fe5bdb9e5b
|
647035568076881920
|
Cesar White
|
02/03/2022 11:09:37
|
i tried looking for one but cant find a suitable one
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,449,973 |
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205,867 |
help-1
|
1ed2083b18b84d12ba7c78fe5bdb9e5b
|
183668144404037632
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Kendra Brown
|
02/03/2022 11:24:02
|
i don't have any videos on hand sorry
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,974 |
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205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
610829937292869644
|
Wayne Thompson
|
02/03/2022 12:15:32
|
unknown.png
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,449,975 |
||
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
|
Oliver Jones
|
02/03/2022 12:19:33
|
Do u know log laws
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,976 |
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205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
514829926449545218
|
Cody Jackson
|
02/03/2022 12:19:35
|
.
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,977 |
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205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
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610829937292869644
|
Wayne Thompson
|
02/03/2022 12:20:18
|
yes
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,449,978 |
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205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
514829926449545218
|
Cody Jackson
|
02/03/2022 12:20:31
|
use log laws
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,979 |
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205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
514829926449545218
|
Cody Jackson
|
02/03/2022 12:21:29
|
do you know what e^ln(x) is?
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,980 |
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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610829937292869644
|
Wayne Thompson
|
02/03/2022 12:21:59
|
ah its the 7th one
|
unknown.png
| 1 | 0 |
nan
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nan
|
nan
|
nan
| 5,449,981 |
|
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
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610829937292869644
|
Wayne Thompson
|
02/03/2022 12:22:04
|
i only learned it till 5
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,449,982 |
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
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Oliver Jones
|
02/03/2022 12:22:11
|
use this
|
unknown.png
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,983 |
|
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
514829926449545218
|
Cody Jackson
|
02/03/2022 12:22:23
|
yes
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,984 |
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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610829937292869644
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Wayne Thompson
|
02/03/2022 12:22:34
|
thank u both
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,449,985 |
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
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Oliver Jones
|
02/03/2022 12:22:40
|
do you know the base of ln?
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,986 |
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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610829937292869644
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Wayne Thompson
|
02/03/2022 12:22:44
|
ye e
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,449,987 |
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
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Oliver Jones
|
02/03/2022 12:22:50
|
yup
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,988 |
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
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Oliver Jones
|
02/03/2022 12:23:07
|
so $e^{\operatorname{log}_e(x)} = x$
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,989 |
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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610829937292869644
|
Wayne Thompson
|
02/03/2022 12:30:55
|
how would u do this tho
|
unknown.png
| 1 | 0 |
nan
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nan
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nan
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nan
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
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Oliver Jones
|
02/03/2022 12:31:24
|
ok so
| 0 | 1 |
nan
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nan
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nan
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nan
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
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Oliver Jones
|
02/03/2022 12:31:56
|
sec
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,992 |
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
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Oliver Jones
|
02/03/2022 12:36:28
|
idk an easy solution to it. According to symbolab u should get $\operatorname{ln}^2(x) = \operatorname{ln}^3(x)$
| 0 | 1 |
nan
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nan
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nan
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nan
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
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Oliver Jones
|
02/03/2022 12:36:53
|
thus x = 1 or x = e, but i dont kkknow how they got to that equality
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,449,994 |
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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279869739415633920
|
Erika Davis
|
02/03/2022 12:39:43
|
Take ln of both sides
| 0 | 1 |
nan
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nan
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nan
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nan
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205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
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279869739415633920
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Erika Davis
|
02/03/2022 12:40:16
|
And use logarith properties to simplify/bring stuff out of exponents
| 0 | 1 |
nan
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nan
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nan
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nan
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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279869739415633920
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Erika Davis
|
02/03/2022 12:41:42
|
Take ln of the left side you get
ln (x^ln(x))
You can bring that exponent out as multiplication:
ln(x) * ln(x) = ln^2(x)
| 0 | 1 |
nan
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nan
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nan
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nan
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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279869739415633920
|
Erika Davis
|
02/03/2022 12:42:36
|
Take ln of the right
ln(e^ln^3(x)))
Ln cancels exponentiation with base e
So you get
ln^3(x)
| 0 | 1 |
528652702184374278
|
Gage Jackson
|
Gage Jackson
|
False
| 5,449,998 |
||
205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
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Oliver Jones
|
02/03/2022 12:44:39
|
\begin{align} x^{\operatorname{ln}\,x} &= e^{(\operatorname{ln}\,x)^3} \notag\\
\operatorname{ln}(x^{\operatorname{ln}\,(x)}) &= \operatorname{ln}(e^{\operatorname{ln}^3 x}) \notag\\
\operatorname{ln}\,x \cdot \operatorname{ln}(x^1) &= (e^{(\operatorname{ln}^3 x)})\notag \\
\operatorname{ln}^2\,x &= (e^{(\operatorname{ln}^3 x)})\notag \\
\end{align} wip
| 0 | 1 |
485903210272391178
|
Kelvin Taylor
|
Kelvin Taylor
|
False
| 5,449,999 |
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
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Oliver Jones
|
02/03/2022 12:56:35
|
\begin{align} x^{\operatorname{ln}\,x} &= e^{(\operatorname{ln}\,x)^3} \notag\\
\operatorname{ln}(x^{\operatorname{ln}\,(x)}) &= \operatorname{ln}(e^{\operatorname{ln}^3 x}) \notag\\
\operatorname{ln}\,x \cdot \operatorname{ln}(x^1) &= \operatorname{ln}^3 x \cdot ln(e^1) \notag \\
\operatorname{ln}^2\,x &= \operatorname{ln}^3 x \cdot 1 \notag
\end{align} wip
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,450,000 |
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205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
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Oliver Jones
|
02/03/2022 12:57:44
|
can u correct this @zedzilla
| 0 | 1 |
nan
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nan
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nan
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nan
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205,868 |
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0dc25adf24cb40d2b847dfdbd9a8750d
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279869739415633920
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Erika Davis
|
02/03/2022 12:58:45
|
Third line should be this on the right:
ln^3(x) * ln(e)
= ln^3(x)
| 0 | 1 |
nan
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nan
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nan
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nan
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205,868 |
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0dc25adf24cb40d2b847dfdbd9a8750d
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279869739415633920
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Erika Davis
|
02/03/2022 12:59:16
|
Ln was dropped on the right between line 2 and 3
| 0 | 1 |
nan
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nan
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nan
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nan
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0dc25adf24cb40d2b847dfdbd9a8750d
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279869739415633920
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Erika Davis
|
02/03/2022 12:59:42
|
Yea that looks ok
| 0 | 1 |
nan
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nan
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nan
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nan
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0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
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Oliver Jones
|
02/03/2022 12:59:46
|
sec
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,450,005 |
||
205,868 |
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0dc25adf24cb40d2b847dfdbd9a8750d
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205143587749494784
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Oliver Jones
|
02/03/2022 13:00:34
|
i myself dont understand from line 2 to 3 RHS
| 0 | 1 |
nan
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nan
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nan
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nan
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0dc25adf24cb40d2b847dfdbd9a8750d
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279869739415633920
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Erika Davis
|
02/03/2022 13:00:44
|
Ok you have
| 0 | 1 |
321445119171756033
|
Bryce Martinez
|
Bryce Martinez
|
False
| 5,450,007 |
||
205,868 |
help-1
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0dc25adf24cb40d2b847dfdbd9a8750d
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279869739415633920
|
Erika Davis
|
02/03/2022 13:00:50
|
e^a
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,008 |
||
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
279869739415633920
|
Erika Davis
|
02/03/2022 13:00:55
|
Take ln of that
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,009 |
||
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
279869739415633920
|
Erika Davis
|
02/03/2022 13:01:01
|
ln(e^a)
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,010 |
||
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
279869739415633920
|
Erika Davis
|
02/03/2022 13:01:22
|
Log property lets me bring that exponent inside the log outside as multiplication
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,011 |
||
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
279869739415633920
|
Erika Davis
|
02/03/2022 13:01:39
|
So
ln(e^a) = a*ln(e)
| 0 | 1 |
321445119171756033
|
Bryce Martinez
|
Bryce Martinez
|
False
| 5,450,012 |
||
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
205143587749494784
|
Oliver Jones
|
02/03/2022 13:01:39
|
omg yes
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,013 |
||
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
279869739415633920
|
Erika Davis
|
02/03/2022 13:01:50
|
Yep good stuff
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,014 |
||
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
205143587749494784
|
Oliver Jones
|
02/03/2022 13:01:56
|
logs are the worst algebra ever
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,015 |
||
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
205143587749494784
|
Oliver Jones
|
02/03/2022 13:02:10
|
i'd take trig substitution integration over it (sometimes)
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,016 |
||
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
279869739415633920
|
Erika Davis
|
02/03/2022 13:02:11
|
It doesn't matter what kind of weird exponent you have the property still works the same
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,017 |
||
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
279869739415633920
|
Erika Davis
|
02/03/2022 13:02:19
|
Hahaha i love logs xD
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,018 |
||
205,868 |
help-1
|
0dc25adf24cb40d2b847dfdbd9a8750d
|
279869739415633920
|
Erika Davis
|
02/03/2022 13:02:48
|
Well let me not say that who knows what kinda weird shit they have you do with them in some theory courses
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,019 |
||
205,869 |
help-1
|
07e4a3e4223f4dc4a2318e46105e3641
|
714074341809061898
|
Mariah Ramirez
|
02/03/2022 13:07:41
|
P(x) = x^3+bx^2+cx+d is a polynomial in x. You are given that P(1) < 0, P(4) > 0, P(6) < 0 and P(10) > 0. If all of the roots of P(x) are integers, what is the maximum possible value of |d|?
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,450,020 |
||
205,869 |
help-1
|
07e4a3e4223f4dc4a2318e46105e3641
|
872024354572103731
|
Jessica Hill
|
02/03/2022 13:11:30
|
oh this isn't so bad
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,021 |
||
205,869 |
help-1
|
07e4a3e4223f4dc4a2318e46105e3641
|
872024354572103731
|
Jessica Hill
|
02/03/2022 13:11:34
|
think about it
| 0 | 1 |
675710631143538688
|
Reese Harris
|
Reese Harris
|
False
| 5,450,022 |
||
205,869 |
help-1
|
07e4a3e4223f4dc4a2318e46105e3641
|
872024354572103731
|
Jessica Hill
|
02/03/2022 13:11:50
|
The roots are integers
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,023 |
||
205,869 |
help-1
|
07e4a3e4223f4dc4a2318e46105e3641
|
872024354572103731
|
Jessica Hill
|
02/03/2022 13:12:07
|
If P(1) <0 and
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,024 |
||
205,869 |
help-1
|
07e4a3e4223f4dc4a2318e46105e3641
|
872024354572103731
|
Jessica Hill
|
02/03/2022 13:12:12
|
P(4) > 0
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,025 |
||
205,869 |
help-1
|
07e4a3e4223f4dc4a2318e46105e3641
|
872024354572103731
|
Jessica Hill
|
02/03/2022 13:12:19
|
What can you say happened between (1,4)
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,026 |
||
205,869 |
help-1
|
07e4a3e4223f4dc4a2318e46105e3641
|
872024354572103731
|
Jessica Hill
|
02/03/2022 13:12:22
|
?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,027 |
||
205,869 |
help-1
|
07e4a3e4223f4dc4a2318e46105e3641
|
706934233012371577
|
Darius Clark
|
02/03/2022 13:13:34
|
~~that sounds so haunted in so many ways~~
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,028 |
||
205,871 |
help-1
|
2a3aff6718e54cd2a226b34e380abe79
|
589246519295737857
|
Brett Perez
|
02/03/2022 13:39:51
|
If i have 1000 images and i randomly view 50 of them every day, after how many days would i view every images in theory? Is it like coupon collector's problem?
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,450,029 |
||
205,871 |
help-1
|
2a3aff6718e54cd2a226b34e380abe79
|
205143587749494784
|
Oliver Jones
|
02/03/2022 13:53:01
|
I think they're asking for the mean of the distribution
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,030 |
||
205,871 |
help-1
|
2a3aff6718e54cd2a226b34e380abe79
|
205143587749494784
|
Oliver Jones
|
02/03/2022 13:53:50
|
idk which distribution it would be though, if its a common one
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,031 |
||
205,871 |
help-1
|
2a3aff6718e54cd2a226b34e380abe79
|
261933205387477002
|
Nicolas Miller
|
02/03/2022 14:10:04
|
yes it's exactly the coupon collector's problem
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,032 |
||
205,871 |
help-1
|
2a3aff6718e54cd2a226b34e380abe79
|
589246519295737857
|
Brett Perez
|
02/03/2022 14:19:49
|
Thanks
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,450,033 |
||
205,871 |
help-1
|
2a3aff6718e54cd2a226b34e380abe79
|
589246519295737857
|
Brett Perez
|
02/03/2022 14:19:50
|
.close
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,450,034 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
326803048041283585
|
Liliana Martinez
|
02/03/2022 14:22:55
|
i am not sure how to find the probability of these.
|
unknown.png
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,450,035 |
|
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
326803048041283585
|
Liliana Martinez
|
02/03/2022 14:23:30
|
im supposed to use the z table and this equation
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,450,036 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
326803048041283585
|
Liliana Martinez
|
02/03/2022 14:23:31
|
unknown.png
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,450,037 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
261933205387477002
|
Nicolas Miller
|
02/03/2022 14:32:25
|
do you know what $P(X=a)$ means?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,038 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
326803048041283585
|
Liliana Martinez
|
02/03/2022 14:33:26
|
it means the probability of x=something
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,450,039 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
261933205387477002
|
Nicolas Miller
|
02/03/2022 14:33:37
|
and do you know what the formula $f(a)$ means?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,040 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
326803048041283585
|
Liliana Martinez
|
02/03/2022 14:34:07
|
isnt it just y?
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,450,041 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
326803048041283585
|
Liliana Martinez
|
02/03/2022 14:34:23
|
im stuck at the part finding the mean
| 1 | 0 |
706934233012371577
|
Darius Clark
|
Darius Clark
|
False
| 5,450,042 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
261933205387477002
|
Nicolas Miller
|
02/03/2022 14:38:21
|
where does it ask for the mean?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,043 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
326803048041283585
|
Liliana Martinez
|
02/03/2022 14:38:47
|
to find z, i need to find the mean
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,450,044 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
261933205387477002
|
Nicolas Miller
|
02/03/2022 14:39:09
|
there are 4 parts here
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,045 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
261933205387477002
|
Nicolas Miller
|
02/03/2022 14:39:13
|
none of them have z, nor need z
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,046 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
326803048041283585
|
Liliana Martinez
|
02/03/2022 14:39:57
|
z is the z-table for the probability of the normal distribution
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,450,047 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
326803048041283585
|
Liliana Martinez
|
02/03/2022 14:40:08
|
i am supposed to use it to find the probability
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,450,048 |
||
205,872 |
help-1
|
dde2ece08f3c442cbc8e27ea116709cb
|
261933205387477002
|
Nicolas Miller
|
02/03/2022 14:41:29
|
i know z-tables. i also know none of the 4 questions in your image require z-tables
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,450,049 |
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