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SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating < 5
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find the titles of items that received any rating below 5.
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SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating > 8 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating < 5
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find the titles of items that received both a rating higher than 8 and a rating below 5.
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SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rank > 3 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id HAVING avg(T2.rating) > 5
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find the names of items whose rank is higher than 3 and whose average rating is above 5.
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SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rating) LIMIT 1
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find the name of the item with the lowest average rating.
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SELECT title FROM item ORDER BY title
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. List the titles of all items in alphabetic order .
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SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id ORDER BY count(*) DESC LIMIT 1
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find the name of the user who gives the most reviews.
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SELECT T1.title , T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rating) DESC LIMIT 1
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find the name and id of the item with the highest average rating.
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SELECT T1.title , T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rank) DESC LIMIT 1
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find the name and id of the good with the highest average rank.
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SELECT T1.name , avg(T2.rating) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. For each user, return the name and the average rating of reviews given by them.
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SELECT T1.name , count(*) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. For each user, find their name and the number of reviews written by them.
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SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id ORDER BY T2.rating DESC LIMIT 1
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find the name of the user who gave the highest rating.
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SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.source_u_id GROUP BY T2.source_u_id ORDER BY avg(trust) DESC LIMIT 1
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find the name of the source user with the highest average trust score.
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SELECT T1.name , avg(trust) FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.target_u_id GROUP BY T2.target_u_id
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find each target user's name and average trust score.
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SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.target_u_id ORDER BY trust LIMIT 1
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find the name of the target user with the lowest trust score.
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SELECT title FROM item WHERE i_id NOT IN (SELECT i_id FROM review)
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find the names of the items that did not receive any review.
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SELECT count(*) FROM useracct WHERE u_id NOT IN (SELECT u_id FROM review)
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find the number of users who did not write any review.
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SELECT count(*) FROM item WHERE i_id NOT IN (SELECT i_id FROM review)
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Given the Table item having columns as i_id has datatype number, title has datatype text which has i_id and Given the Table review having columns as a_id has datatype number, u_id has datatype number, i_id has datatype number, rating has datatype number, rank has datatype number which has a_id and Given the Table useracct having columns as u_id has datatype number, name has datatype text which has u_id and Given the Table trust having columns as source_u_id has datatype number, target_u_id has datatype number, trust has datatype number which has NO_PRIMARY_KEY. Answer the question by writing the appropriate SQL code. Find the number of items without any review.
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SELECT count(*) FROM player
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. How many players are there?
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SELECT Player_name FROM player ORDER BY Votes ASC
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. List the names of players in ascending order of votes.
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SELECT Gender , Occupation FROM player
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. What are the gender and occupation of players?
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SELECT Player_name , residence FROM player WHERE Occupation != "Researcher"
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. List the name and residence for players whose occupation is not "Researcher".
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SELECT Sponsor_name FROM player WHERE Residence = "Brandon" OR Residence = "Birtle"
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. Show the names of sponsors of players whose residence is either "Brandon" or "Birtle".
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SELECT Player_name FROM player ORDER BY Votes DESC LIMIT 1
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. What is the name of the player with the largest number of votes?
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SELECT Occupation , COUNT(*) FROM player GROUP BY Occupation
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. Show different occupations along with the number of players in each occupation.
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SELECT Occupation FROM player GROUP BY Occupation ORDER BY COUNT(*) DESC LIMIT 1
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. Please show the most common occupation of players.
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SELECT Residence FROM player GROUP BY Residence HAVING COUNT(*) >= 2
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. Show the residences that have at least two players.
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SELECT T3.Player_name , T2.coach_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. Show the names of players and names of their coaches.
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SELECT T3.Player_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID WHERE T2.Rank = 1
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. Show the names of players coached by the rank 1 coach.
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SELECT T3.Player_name , T3.gender FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID WHERE T1.Starting_year > 2011
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. Show the names and genders of players with a coach starting after 2011.
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SELECT T3.Player_name , T2.coach_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID ORDER BY T3.Votes DESC
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. Show the names of players and names of their coaches in descending order of the votes of players.
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SELECT Player_name FROM player WHERE Player_ID NOT IN (SELECT Player_ID FROM player_coach)
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. List the names of players that do not have coaches.
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SELECT Residence FROM player WHERE gender = "M" INTERSECT SELECT Residence FROM player WHERE gender = "F"
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. Show the residences that have both a player of gender "M" and a player of gender "F".
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SELECT T1.club_id , T1.club_name, count(*) FROM club AS T1 JOIN coach AS T2 ON T1.club_id = T2.club_id GROUP BY T1.club_id
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. How many coaches does each club has? List the club id, name and the number of coaches.
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SELECT T1.club_id , T1.gold FROM match_result AS T1 JOIN coach AS T2 ON T1.club_id = T2.club_id GROUP BY T1.club_id ORDER BY count(*) DESC LIMIT 1
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Given the Table player having columns as Player_ID has datatype number, Sponsor_name has datatype text, Player_name has datatype text, Gender has datatype text, Residence has datatype text, Occupation has datatype text, Votes has datatype number, Rank has datatype text which has Player_ID and Given the Table club having columns as Club_ID has datatype number, Club_name has datatype text, Region has datatype text, Start_year has datatype number which has Club_ID and Given the Table coach having columns as Coach_ID has datatype number, Coach_name has datatype text, Gender has datatype text, Club_ID has datatype number, Rank has datatype number which has Coach_ID and Given the Table player coach having columns as Player_ID has datatype number, Coach_ID has datatype number, Starting_year has datatype number which has Player_ID and Given the Table match result having columns as Rank has datatype number, Club_ID has datatype number, Gold has datatype number, Big_Silver has datatype number, Small_Silver has datatype number, Bronze has datatype number, Points has datatype number which has Rank. Answer the question by writing the appropriate SQL code. How many gold medals has the club with the most coaches won?
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SELECT count(*) FROM gymnast
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. How many gymnasts are there?
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SELECT count(*) FROM gymnast
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Count the number of gymnasts.
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SELECT Total_Points FROM gymnast ORDER BY Total_Points DESC
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. List the total points of gymnasts in descending order.
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SELECT Total_Points FROM gymnast ORDER BY Total_Points DESC
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What are the total points for all gymnasts, ordered by total points descending?
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SELECT Total_Points FROM gymnast ORDER BY Floor_Exercise_Points DESC
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. List the total points of gymnasts in descending order of floor exercise points.
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SELECT Total_Points FROM gymnast ORDER BY Floor_Exercise_Points DESC
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What are the total points of gymnasts, ordered by their floor exercise points descending?
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SELECT avg(Horizontal_Bar_Points) FROM gymnast
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What is the average horizontal bar points for all gymnasts?
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SELECT avg(Horizontal_Bar_Points) FROM gymnast
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Return the average horizontal bar points across all gymnasts.
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SELECT Name FROM People ORDER BY Name ASC
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What are the names of people in ascending alphabetical order?
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SELECT Name FROM People ORDER BY Name ASC
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Return the names of people, ordered alphabetically.
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SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What are the names of gymnasts?
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SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Return the names of the gymnasts.
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SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T2.Hometown != "Santo Domingo"
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What are the names of gymnasts whose hometown is not "Santo Domingo"?
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SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T2.Hometown != "Santo Domingo"
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Return the names of gymnasts who did not grow up in Santo Domingo.
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SELECT Age FROM people ORDER BY Height DESC LIMIT 1
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What is the age of the tallest person?
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SELECT Age FROM people ORDER BY Height DESC LIMIT 1
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Return the age of the person with the greatest height.
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SELECT Name FROM People ORDER BY Age DESC LIMIT 5
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. List the names of the top 5 oldest people.
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SELECT Name FROM People ORDER BY Age DESC LIMIT 5
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What are the names of the five oldest people?
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SELECT T1.Total_Points FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Age ASC LIMIT 1
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What is the total point count of the youngest gymnast?
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SELECT T1.Total_Points FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Age ASC LIMIT 1
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Return the total points of the gymnast with the lowest age.
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SELECT avg(T2.Age) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What is the average age of all gymnasts?
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SELECT avg(T2.Age) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Return the average age across all gymnasts.
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SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T1.Total_Points > 57.5
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What are the distinct hometowns of gymnasts with total points more than 57.5?
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SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T1.Total_Points > 57.5
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Give the different hometowns of gymnasts that have a total point score of above 57.5.
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SELECT T2.Hometown , COUNT(*) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What are the hometowns of gymnasts and the corresponding number of gymnasts?
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SELECT T2.Hometown , COUNT(*) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. How many gymnasts are from each hometown?
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SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown ORDER BY COUNT(*) DESC LIMIT 1
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What is the most common hometown of gymnasts?
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SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown ORDER BY COUNT(*) DESC LIMIT 1
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Return the hometown that is most common among gymnasts.
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SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown HAVING COUNT(*) >= 2
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What are the hometowns that are shared by at least two gymnasts?
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SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown HAVING COUNT(*) >= 2
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Give the hometowns from which two or more gymnasts are from.
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SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Height ASC
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. List the names of gymnasts in ascending order by their heights.
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SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Height ASC
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What are the names of gymnasts, ordered by their heights ascending?
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SELECT DISTINCT Hometown FROM people EXCEPT SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. List the distinct hometowns that are not associated with any gymnast.
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SELECT DISTINCT Hometown FROM people EXCEPT SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. From which hometowns did no gymnasts come from?
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SELECT Hometown FROM people WHERE Age > 23 INTERSECT SELECT Hometown FROM people WHERE Age < 20
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Show the hometowns shared by people older than 23 and younger than 20.
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SELECT Hometown FROM people WHERE Age > 23 INTERSECT SELECT Hometown FROM people WHERE Age < 20
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. From which hometowns did both people older than 23 and younger than 20 come from?
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SELECT count(DISTINCT Hometown) FROM people
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. How many distinct hometowns did these people have?
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SELECT count(DISTINCT Hometown) FROM people
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Count the number of different hometowns of these people.
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SELECT T2.Age FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T1.Total_Points DESC
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. Show the ages of gymnasts in descending order of total points.
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SELECT T2.Age FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T1.Total_Points DESC
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Given the Table gymnast having columns as Gymnast_ID has datatype number, Floor_Exercise_Points has datatype number, Pommel_Horse_Points has datatype number, Rings_Points has datatype number, Vault_Points has datatype number, Parallel_Bars_Points has datatype number, Horizontal_Bar_Points has datatype number, Total_Points has datatype number which has Gymnast_ID and Given the Table people having columns as People_ID has datatype number, Name has datatype text, Age has datatype number, Height has datatype number, Hometown has datatype text which has People_ID. Answer the question by writing the appropriate SQL code. What are the ages of the gymnasts, ordered descending by their total points?
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SELECT sum(T2.balance) FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T1.name != 'Brown'
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. Find the total savings balance of all accounts except the account with name ‘Brown’.
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SELECT sum(T2.balance) FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T1.name != 'Brown'
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. What is the total balance of savings accounts not belonging to someone with the name Brown?
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SELECT count(*) FROM accounts
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. How many accounts are there in total?
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SELECT count(*) FROM accounts
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. Count the number of accounts.
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SELECT sum(balance) FROM checking
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. What is the total checking balance in all accounts?
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SELECT sum(balance) FROM checking
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. Find the total balance across checking accounts.
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SELECT avg(balance) FROM checking
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. Find the average checking balance.
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SELECT avg(balance) FROM checking
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. What is the average balance in checking accounts?
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SELECT count(*) FROM savings WHERE balance > (SELECT avg(balance) FROM savings)
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. How many accounts have a savings balance above the average savings balance?
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SELECT count(*) FROM savings WHERE balance > (SELECT avg(balance) FROM savings)
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. Find the number of accounts with a savings balance that is higher than the average savings balance.
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SELECT T1.custid , T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT max(balance) FROM checking)
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. Find the name and id of accounts whose checking balance is below the maximum checking balance.
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SELECT T1.custid , T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT max(balance) FROM checking)
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. What are the customer id and name corresponding to accounts with a checking balance less than the largest checking balance?
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SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name LIKE '%ee%'
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. What is the checking balance of the account whose owner’s name contains the substring ‘ee’?
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SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name LIKE '%ee%'
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. Find the balance of the checking account belonging to an owner whose name contains 'ee'.
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SELECT T2.balance , T3.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid WHERE T1.name = 'Brown'
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. Find the checking balance and saving balance in the Brown’s account.
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SELECT T2.balance , T3.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid WHERE T1.name = 'Brown'
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. What are the checking and savings balances in accounts belonging to Brown?
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SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM checking) INTERSECT SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT avg(balance) FROM savings)
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. Find the names of accounts whose checking balance is above the average checking balance, but savings balance is below the average savings balance.
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SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM checking) INTERSECT SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT avg(balance) FROM savings)
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. What are the names of accounts with checking balances greater than the average checking balance and savings balances below the average savings balance?
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SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name IN (SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM savings))
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. Find the checking balance of the accounts whose savings balance is higher than the average savings balance.
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SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name IN (SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM savings))
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. What are the balances of checking accounts belonging to people with savings balances greater than the average savings balance?
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SELECT name FROM accounts ORDER BY name
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. List all customers’ names in the alphabetical order.
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SELECT name FROM accounts ORDER BY name
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. What are the names of all the customers in alphabetical order?
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SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid ORDER BY T2.balance + T3.balance LIMIT 1
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. Find the name of account that has the lowest total checking and saving balance.
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SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid ORDER BY T2.balance + T3.balance LIMIT 1
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. What is the name corresponding to the accoung with the lowest sum of checking and savings balances?
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SELECT T1.name , T2.balance + T3.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid WHERE T3.balance > (SELECT avg(balance) FROM savings)
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. Find the names and total checking and savings balances of accounts whose savings balance is higher than the average savings balance.
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SELECT T1.name , T2.balance + T3.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid WHERE T3.balance > (SELECT avg(balance) FROM savings)
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Given the Table accounts having columns as custid has datatype number, name has datatype text which has custid and Given the Table savings having columns as custid has datatype number, balance has datatype number which has custid and Given the Table checking having columns as custid has datatype number, balance has datatype number which has custid. Answer the question by writing the appropriate SQL code. What are the names and sum of checking and savings balances for accounts with savings balances higher than the average savings balance?
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