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SELECT T1.first_name , T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Display the first name and department name for each employee.
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SELECT T1.first_name , T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the first name and department name of all employees?
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SELECT first_name , last_name , salary FROM employees WHERE salary < 6000
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. List the full name (first and last name), and salary for those employees who earn below 6000.
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SELECT first_name , last_name , salary FROM employees WHERE salary < 6000
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the full names and salaries for any employees earning less than 6000?
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SELECT first_name , department_id FROM employees WHERE last_name = 'McEwen'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Display the first name, and department number for all employees whose last name is "McEwen".
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SELECT first_name , department_id FROM employees WHERE last_name = 'McEwen'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the first names and department numbers for employees with last name McEwen?
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SELECT * FROM employees WHERE department_id = "null"
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Return all the information for all employees without any department number.
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SELECT * FROM employees WHERE department_id = "null"
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are all the employees without a department number?
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SELECT * FROM departments WHERE department_name = 'Marketing'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Display all the information about the department Marketing.
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SELECT * FROM departments WHERE department_name = 'Marketing'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What is all the information about the Marketing department?
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SELECT hire_date FROM employees WHERE first_name NOT LIKE '%M%'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. when is the hire date for those employees whose first name does not containing the letter M?
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SELECT hire_date FROM employees WHERE first_name NOT LIKE '%M%'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. On what dates were employees without the letter M in their first names hired?
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SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE '%M%'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the full name (first and last), hire date, salary, and department number for those employees whose first name does not containing the letter M.
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SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE '%M%'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the full name, hire date, salary, and department id for employees without the letter M in their first name?
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SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE '%M%' ORDER BY department_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the full name (first and last), hire date, salary, and department number for those employees whose first name does not containing the letter M and make the result set in ascending order by department number.
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SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE '%M%' ORDER BY department_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the full name, hire data, salary and department id for employees without the letter M in their first name, ordered by ascending department id?
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SELECT phone_number FROM employees WHERE salary BETWEEN 8000 AND 12000
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. what is the phone number of employees whose salary is in the range of 8000 and 12000?
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SELECT phone_number FROM employees WHERE salary BETWEEN 8000 AND 12000
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Return the phone numbers of employees with salaries between 8000 and 12000.
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SELECT * FROM employees WHERE salary BETWEEN 8000 AND 12000 AND commission_pct != "null" OR department_id != 40
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display all the information of employees whose salary is in the range of 8000 and 12000 and commission is not null or department number does not equal to 40.
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SELECT * FROM employees WHERE salary BETWEEN 8000 AND 12000 AND commission_pct != "null" OR department_id != 40
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Return all information about employees with salaries between 8000 and 12000 for which commission is not null or where their department id is not 40.
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SELECT first_name , last_name , salary FROM employees WHERE commission_pct = "null"
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the full name (first and last name) and salary for all employees who does not have any value for commission?
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SELECT first_name , last_name , salary FROM employees WHERE commission_pct = "null"
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Return the full names and salaries of employees with null commissions.
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SELECT first_name , last_name , salary FROM employees WHERE first_name LIKE '%m'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Display the first and last name, and salary for those employees whose first name is ending with the letter m.
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SELECT first_name , last_name , salary FROM employees WHERE first_name LIKE '%m'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Return the full names and salaries for employees with first names that end with the letter m.
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SELECT job_id , hire_date FROM employees WHERE hire_date BETWEEN '2007-11-05' AND '2009-07-05'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Find job id and date of hire for those employees who was hired between November 5th, 2007 and July 5th, 2009.
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SELECT job_id , hire_date FROM employees WHERE hire_date BETWEEN '2007-11-05' AND '2009-07-05'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the job ids and dates of hire for employees hired after November 5th, 2007 and before July 5th, 2009?
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SELECT first_name , last_name FROM employees WHERE department_id = 70 OR department_id = 90
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the first and last name for those employees who works either in department 70 or 90?
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SELECT first_name , last_name FROM employees WHERE department_id = 70 OR department_id = 90
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the full names of employees who with in department 70 or 90?
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SELECT salary , manager_id FROM employees WHERE manager_id != "null"
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Find the salary and manager number for those employees who is working under a manager.
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SELECT salary , manager_id FROM employees WHERE manager_id != "null"
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the salaries and manager ids for employees who have managers?
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SELECT * FROM employees WHERE hire_date < '2002-06-21'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display all the details from Employees table for those employees who was hired before 2002-06-21.
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SELECT * FROM employees WHERE hire_date < '2002-06-21'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What is all the information about employees hired before June 21, 2002?
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SELECT * FROM employees WHERE first_name LIKE '%D%' OR first_name LIKE '%S%' ORDER BY salary DESC
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display all the information for all employees who have the letters D or S in their first name and also arrange the result in descending order by salary.
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SELECT * FROM employees WHERE first_name LIKE '%D%' OR first_name LIKE '%S%' ORDER BY salary DESC
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What is all the information about employees with D or S in their first name, ordered by salary descending?
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SELECT * FROM employees WHERE hire_date > '1987-09-07'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display those employees who joined after 7th September, 1987.
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SELECT * FROM employees WHERE hire_date > '1987-09-07'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Which employees were hired after September 7th, 1987?
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SELECT job_title FROM jobs WHERE min_salary > 9000
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the job title of jobs which minimum salary is greater than 9000.
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SELECT job_title FROM jobs WHERE min_salary > 9000
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Which job titles correspond to jobs with salaries over 9000?
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SELECT job_title , max_salary - min_salary FROM jobs WHERE max_salary BETWEEN 12000 AND 18000
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display job Title, the difference between minimum and maximum salaries for those jobs which max salary within the range 12000 to 18000.
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SELECT job_title , max_salary - min_salary FROM jobs WHERE max_salary BETWEEN 12000 AND 18000
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the job titles, and range of salaries for jobs with maximum salary between 12000 and 18000?
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SELECT email FROM employees WHERE commission_pct = "null" AND salary BETWEEN 7000 AND 12000 AND department_id = 50
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the emails of the employees who have no commission percentage and salary within the range 7000 to 12000 and works in that department which number is 50.
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SELECT email FROM employees WHERE commission_pct = "null" AND salary BETWEEN 7000 AND 12000 AND department_id = 50
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the emails of employees with null commission, salary between 7000 and 12000, and who work in department 50?
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SELECT employee_id , MAX(end_date) FROM job_history GROUP BY employee_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the employee ID for each employee and the date on which he ended his previous job.
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SELECT employee_id , MAX(end_date) FROM job_history GROUP BY employee_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the employee ids for each employee and final dates of employment at their last job?
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SELECT department_id FROM employees GROUP BY department_id HAVING COUNT(commission_pct) > 10
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display those departments where more than ten employees work who got a commission percentage.
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SELECT department_id FROM employees GROUP BY department_id HAVING COUNT(commission_pct) > 10
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the department ids for which more than 10 employees had a commission?
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SELECT DISTINCT department_id FROM employees GROUP BY department_id , manager_id HAVING COUNT(employee_id) >= 4
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Find the ids of the departments where any manager is managing 4 or more employees.
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SELECT DISTINCT department_id FROM employees GROUP BY department_id , manager_id HAVING COUNT(employee_id) >= 4
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are department ids for departments with managers managing more than 3 employees?
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SELECT department_id , AVG(salary) FROM employees WHERE commission_pct != "null" GROUP BY department_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the average salary of employees for each department who gets a commission percentage.
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SELECT department_id , AVG(salary) FROM employees WHERE commission_pct != "null" GROUP BY department_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What is the average salary of employees who have a commission percentage that is not null?
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SELECT country_id , COUNT(*) FROM locations GROUP BY country_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the country ID and number of cities for each country.
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SELECT country_id , COUNT(*) FROM locations GROUP BY country_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Give the country id and corresponding count of cities in each country.
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SELECT job_id FROM job_history WHERE end_date - start_date > 300 GROUP BY job_id HAVING COUNT(*) >= 2
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display job ID for those jobs that were done by two or more for more than 300 days.
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SELECT job_id FROM job_history WHERE end_date - start_date > 300 GROUP BY job_id HAVING COUNT(*) >= 2
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the job ids for jobs done more than once for a period of more than 300 days?
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SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*) >= 2
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the ID for those employees who did two or more jobs in the past.
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SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*) >= 2
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the employee ids for employees who have held two or more jobs?
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SELECT T1.employee_id , T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id JOIN countries AS T4 ON T3.country_id = T4.country_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Find employee with ID and name of the country presently where (s)he is working.
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SELECT T1.employee_id , T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id JOIN countries AS T4 ON T3.country_id = T4.country_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are all the employee ids and the names of the countries in which they work?
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SELECT T2.department_name , COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id GROUP BY T2.department_name
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the department name and number of employees in each of the department.
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SELECT T2.department_name , COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id GROUP BY T2.department_name
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Give the name of each department and the number of employees in each.
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SELECT * FROM job_history AS T1 JOIN employees AS T2 ON T1.employee_id = T2.employee_id WHERE T2.salary >= 12000
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Can you return all detailed info of jobs which was done by any of the employees who is presently earning a salary on and above 12000?
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SELECT * FROM job_history AS T1 JOIN employees AS T2 ON T1.employee_id = T2.employee_id WHERE T2.salary >= 12000
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What is all the job history info done by employees earning a salary greater than or equal to 12000?
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SELECT job_title , AVG(salary) FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id = T2.job_id GROUP BY T2.job_title
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display job title and average salary of employees.
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SELECT job_title , AVG(salary) FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id = T2.job_id GROUP BY T2.job_title
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What is the average salary for each job title?
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SELECT first_name , last_name FROM employees WHERE salary > (SELECT salary FROM employees WHERE employee_id = 163 )
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What is the full name ( first name and last name ) for those employees who gets more salary than the employee whose id is 163?
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SELECT first_name , last_name FROM employees WHERE salary > (SELECT salary FROM employees WHERE employee_id = 163 )
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Provide the full names of employees earning more than the employee with id 163.
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SELECT MIN(salary) , department_id FROM employees GROUP BY department_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. return the smallest salary for every departments.
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SELECT MIN(salary) , department_id FROM employees GROUP BY department_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What is the minimum salary in each department?
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SELECT first_name , last_name , department_id FROM employees WHERE salary IN (SELECT MIN(salary) FROM employees GROUP BY department_id)
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Find the first name and last name and department id for those employees who earn such amount of salary which is the smallest salary of any of the departments.
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SELECT first_name , last_name , department_id FROM employees WHERE salary IN (SELECT MIN(salary) FROM employees GROUP BY department_id)
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the full names and department ids for the lowest paid employees across all departments.
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SELECT employee_id FROM employees WHERE salary > (SELECT AVG(salary) FROM employees)
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Find the employee id for all employees who earn more than the average salary.
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SELECT employee_id FROM employees WHERE salary > (SELECT AVG(salary) FROM employees)
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the employee ids for employees who make more than the average?
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SELECT employee_id , salary FROM employees WHERE manager_id = (SELECT employee_id FROM employees WHERE first_name = 'Payam' )
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the employee id and salary of all employees who report to Payam (first name).
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SELECT employee_id , salary FROM employees WHERE manager_id = (SELECT employee_id FROM employees WHERE first_name = 'Payam' )
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the employee ids of employees who report to Payam, and what are their salaries?
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SELECT DISTINCT T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. find the name of all departments that do actually have one or more employees assigned to them.
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SELECT DISTINCT T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the names of departments that have at least one employee.
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SELECT DISTINCT * FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T1.employee_id = T2.manager_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. get the details of employees who manage a department.
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SELECT DISTINCT * FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T1.employee_id = T2.manager_id
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What is all the information regarding employees who are managers?
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SELECT * FROM departments WHERE department_name = 'Marketing'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display all the information about the department Marketing.
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SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*) >= 2
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the employee ids for those who had two or more jobs.
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SELECT DISTINCT department_id FROM employees GROUP BY department_id , manager_id HAVING COUNT(employee_id) >= 4
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the unique ids of those departments where any manager is managing 4 or more employees.
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SELECT DISTINCT department_id FROM employees GROUP BY department_id , manager_id HAVING COUNT(employee_id) >= 4
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Give the distinct department ids of departments in which a manager is in charge of 4 or more employees?
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SELECT job_id FROM employees GROUP BY job_id HAVING AVG(salary) > 8000
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Find the job ID for those jobs which average salary is above 8000.
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SELECT job_id FROM employees GROUP BY job_id HAVING AVG(salary) > 8000
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the job ids corresponding to jobs with average salary above 8000?
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SELECT T1.employee_id , T2.job_title FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id = T2.job_id WHERE T1.department_id = 80
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the employee ID and job name for all those jobs in department 80.
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SELECT T1.employee_id , T2.job_title FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id = T2.job_id WHERE T1.department_id = 80
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. what are the employee ids and job titles for employees in department 80?
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SELECT T1.first_name , T1.job_id FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T2.department_name = 'Finance'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What is the first name and job id for all employees in the Finance department?
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SELECT T1.first_name , T1.job_id FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T2.department_name = 'Finance'
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Give the first name and job id for all employees in the Finance department.
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SELECT * FROM employees WHERE salary BETWEEN (SELECT MIN(salary) FROM employees) AND 2500
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display all the information of the employees whose salary if within the range of smallest salary and 2500.
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SELECT * FROM employees WHERE salary BETWEEN (SELECT MIN(salary) FROM employees) AND 2500
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What is all the information regarding employees with salaries above the minimum and under 2500?
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SELECT * FROM employees WHERE department_id NOT IN (SELECT department_id FROM departments WHERE manager_id BETWEEN 100 AND 200)
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. Find the ids of the employees who does not work in those departments where some employees works whose manager id within the range 100 and 200.
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SELECT * FROM employees WHERE department_id NOT IN (SELECT department_id FROM departments WHERE manager_id BETWEEN 100 AND 200)
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the ids for employees who do not work in departments with managers that have ids between 100 and 200?
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SELECT first_name , last_name , hire_date FROM employees WHERE department_id = (SELECT department_id FROM employees WHERE first_name = "Clara")
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the employee name ( first name and last name ) and hire date for all employees in the same department as Clara.
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SELECT first_name , last_name , hire_date FROM employees WHERE department_id = (SELECT department_id FROM employees WHERE first_name = "Clara")
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the full names and hire dates for employees in the same department as someone with the first name Clara?
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SELECT first_name , last_name , hire_date FROM employees WHERE department_id = ( SELECT department_id FROM employees WHERE first_name = "Clara") AND first_name != "Clara"
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the employee name ( first name and last name ) and hire date for all employees in the same department as Clara excluding Clara.
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SELECT first_name , last_name , hire_date FROM employees WHERE department_id = ( SELECT department_id FROM employees WHERE first_name = "Clara") AND first_name != "Clara"
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the full names and hire dates for employees in the same department as someone with the first name Clara, not including Clara?
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SELECT employee_id , first_name , last_name FROM employees WHERE department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%T%' )
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the employee number and name( first name and last name ) for all employees who work in a department with any employee whose name contains a ’T’.
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SELECT employee_id , first_name , last_name FROM employees WHERE department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%T%' )
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the ids and full names for employees who work in a department that has someone with a first name that contains the letter T?
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SELECT employee_id , first_name , last_name , salary FROM employees WHERE salary > ( SELECT AVG (salary) FROM employees ) AND department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%J%')
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. display the employee number, name( first name and last name ), and salary for all employees who earn more than the average salary and who work in a department with any employee with a 'J' in their first name.
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SELECT employee_id , first_name , last_name , salary FROM employees WHERE salary > ( SELECT AVG (salary) FROM employees ) AND department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%J%')
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Given the Table regions having columns as REGION_ID has datatype number, REGION_NAME has datatype text which has REGION_ID and Given the Table countries having columns as COUNTRY_ID has datatype text, COUNTRY_NAME has datatype text, REGION_ID has datatype number which has COUNTRY_ID and Given the Table departments having columns as DEPARTMENT_ID has datatype number, DEPARTMENT_NAME has datatype text, MANAGER_ID has datatype number, LOCATION_ID has datatype number which has DEPARTMENT_ID and Given the Table jobs having columns as JOB_ID has datatype text, JOB_TITLE has datatype text, MIN_SALARY has datatype number, MAX_SALARY has datatype number which has JOB_ID and Given the Table employees having columns as EMPLOYEE_ID has datatype number, FIRST_NAME has datatype text, LAST_NAME has datatype text, EMAIL has datatype text, PHONE_NUMBER has datatype text, HIRE_DATE has datatype time, JOB_ID has datatype text, SALARY has datatype number, COMMISSION_PCT has datatype number, MANAGER_ID has datatype number, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table job history having columns as EMPLOYEE_ID has datatype number, START_DATE has datatype time, END_DATE has datatype time, JOB_ID has datatype text, DEPARTMENT_ID has datatype number which has EMPLOYEE_ID and Given the Table locations having columns as LOCATION_ID has datatype number, STREET_ADDRESS has datatype text, POSTAL_CODE has datatype text, CITY has datatype text, STATE_PROVINCE has datatype text, COUNTRY_ID has datatype text which has LOCATION_ID. Answer the question by writing the appropriate SQL code. What are the ids, full names, and salaries for employees making more than average and who work in a department with employees who have the letter J in their first name?
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