solution
stringlengths
10
159k
difficulty
int64
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3.5k
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2 values
#include <bits/stdc++.h> using namespace std; const int MAXN = 310, MAXM = 50000 + 10; vector<pair<pair<int, int>, int> > CC; struct Graph { int id, next; } g[MAXN * 2]; int n, m, st[MAXN], a[MAXN], b[MAXN], v, f[MAXN], tot, cnt[MAXN]; pair<int, int> e[MAXM]; int getf(int first) { if (f[first] == first) return first; f[first] = getf(f[first]); return f[first]; } bool Union(int first, int second) { int fx = getf(first), fy = getf(second); if (fx == fy) return false; f[fx] = fy; return true; } void Add(int first, int second) { g[tot].id = second, g[tot].next = st[first], st[first] = tot++; g[tot].id = first, g[tot].next = st[second], st[second] = tot++; } void init() { scanf("%d%d%d", &n, &v, &m); for (int i = 1; i <= n; ++i) scanf("%d", &a[i]); for (int j = 1; j <= n; ++j) scanf("%d", &b[j]); for (int i = 1; i <= n; ++i) f[i] = i; memset(st, -1, sizeof(st)); for (int i = 1; i <= m; ++i) { int first, second; scanf("%d%d", &first, &second); e[i] = make_pair(first, second); if (Union(first, second)) Add(first, second); } for (int i = 1; i <= n; ++i) cnt[getf(i)] += a[i] - b[i]; for (int i = 1; i <= n; ++i) if (cnt[i] != 0) puts("NO"), exit(0); } int fa[MAXN]; bool used[MAXN]; int Gain(int first, int fx, int res) { if (res == 0) return 0; if (res > 0 && a[first] >= res) { a[fx] += res, a[first] -= res; CC.push_back(make_pair(make_pair(first, fx), res)); return -res; } if (res < 0 && v + res >= a[first]) { a[fx] += res, a[first] -= res; CC.push_back(make_pair(make_pair(fx, first), -res)); return -res; } int flow = (res > 0) ? (res - a[first]) : ((v + res) - a[first]); for (int i = st[first]; i != -1; i = g[i].next) if (g[i].id != fx && !used[g[i].id]) { int F = Gain(g[i].id, first, flow); flow += F; if (flow == 0) break; } res -= flow; a[fx] += res, a[first] -= res; if (res + flow > 0) { if (res != 0) CC.push_back(make_pair(make_pair(first, fx), res)); } else if (res != 0) CC.push_back(make_pair(make_pair(fx, first), -res)); return -res; } void DFS(int first) { for (int i = st[first]; i != -1; i = g[i].next) if (g[i].id != fa[first]) fa[g[i].id] = first, DFS(g[i].id); used[first] = true; if (fa[first]) Gain(fa[first], first, b[first] - a[first]); else if (a[first] != b[first]) puts("NO"), exit(0); } void solve() { for (int i = 1; i <= n; ++i) if (!used[i]) DFS(i); cout << CC.size() << endl; for (int i = 0; i < (int)CC.size(); ++i) cout << CC[i].first.first << " " << CC[i].first.second << " " << CC[i].second << endl; } int main() { init(); solve(); fclose(stdin); fclose(stdout); return 0; }
2,500
CPP
#https://codeforces.com/problemset/problem/1175/A tests = int(input()) for each in range(tests): n , k = input().split(' ') n=int(n) k=int(k) count=0 while n!=0: if (n%k==0): n=n//k count+=1 else: rest= n%k n-=rest count+=rest print(int(count))
900
PYTHON3
n, k = map(int, input().split()) a = list(map(int, input().split())) b = list(map(int, input().split())) diff = [x - y for x, y in zip(a, b)] #print(k) #print(a) #print(b) #print(diff) index = sorted(range(len(diff)), key=lambda x: diff[x]) #print(index) cheat = len([x for x in diff if x < 0]) #print(cheat) k = max(k, cheat) bnow = index[:k] blater = index[k:] bnow = [a[x] for x in bnow] blater = [b[x] for x in blater] #print(bnow) #print(blater) print(sum(bnow) + sum(blater))
1,200
PYTHON3
t = int(input()) for _ in range(t): n, x = map(int, input().split()) arr = list(map(int, input().split())) s = set(arr) i = 1 while x != 0: if i not in s: x -= 1 i += 1 if (x == 0) and (i not in s): i -= 1 if x == 0: while (i + 1) in arr: i += 1 print(i)
900
PYTHON3
n = int(input()) a = list(map(int, input().split())) s1 = [i for i in a if i < 0] s2 = [i for i in a if i > 0] s3 = [i for i in a if i == 0] def pr(x): print(len(x), " ".join(map(str, x))) if len(s2) == 0: s2.append(s1.pop()) s2.append(s1.pop()) if len(s1) % 2 == 0: s3.append(s1.pop()) pr(s1) pr(s2) pr(s3)
1,100
PYTHON3
#include <bits/stdc++.h> int main() { int n = 0, m = 0, i = 1; scanf("%d%d", &n, &m); if (n < m) { printf("-1"); } else if (n == m) { printf("%d", n); } else if (((n / 2) + (n % 2)) % m == 0) { printf("%d", ((n / 2) + (n % 2))); } else { i = (n / 2) + (n % 2); while (i % m != 0) { i++; } printf("%d", i); } return 0; }
1,000
CPP
#include <bits/stdc++.h> using namespace std; const int N = 1E6 + 7; vector<long long> pre[N], dis[N]; int t[N]; long long query(int s, long long h) { if (h <= 0) return 0; int p = upper_bound(begin(dis[s]), end(dis[s]), h) - begin(dis[s]); return p * h - pre[s][p - 1]; } int main() { std::ios::sync_with_stdio(false), cin.tie(0), cout.tie(0); int n, m; cin >> n >> m; for (int i = 2; i <= n; i++) cin >> t[i]; for (int i = n; i >= 1; i--) { dis[i].emplace_back(0); for (int c = 0; c < 2; c++) { int x = 2 * i + c; if (x > n) continue; for (long long it : dis[x]) { dis[i].emplace_back(it + t[x]); } } sort(begin(dis[i]), end(dis[i])); int tot = dis[i].size(); pre[i].resize(tot); for (int j = 1; j < tot; j++) pre[i][j] = pre[i][j - 1] + dis[i][j]; } while (m--) { int a, h; long long ans = 0; cin >> a >> h; ans += query(a, h); while (a > 1) { int b = a; a >>= 1; h -= t[b]; if (h <= 0) break; ans += h; int x = 2 * a == b ? 2 * a + 1 : 2 * a; if (x <= n) ans += query(x, h - t[x]); } cout << ans << '\n'; } return 0; }
2,200
CPP
#include <bits/stdc++.h> using namespace std; int main() { string s; int flag = 0; cin >> s; for (int i = 0; i < s.size(); i++) { if (s[i] == '0') { s.erase(s.begin() + i); flag = 1; break; } } if (flag == 0) { s.erase(s.begin() + 1); } cout << s; }
1,100
CPP
count = 0 for i in range(int(input())): p, q = map(int, input().split()) if q - p >= 2: count += 1 print(count)
800
PYTHON3
n = int(input()) minus = plus = 0 for i in range(0, n): a, b = map(int, input().split()) if a < 0: minus += 1 else: plus += 1 plus = min(plus, minus) if plus < 2: print("Yes") else: print("No")
800
PYTHON3
import os,sys from io import BytesIO, IOBase from collections import defaultdict,Counter from copy import deepcopy from heapq import * class Node: def __init__(self,val,occ): self.val = val self.occ = occ self.dec = (val-val//2)*occ def __lt__(self,other): return self.dec > other.dec def __str__(self): return f'{self.val} {self.occ} {self.dec}' def main(): for _ in range(int(input())): n,s = map(int,input().split()) path = defaultdict(set) cost = {} for _ in range(n-1): u,v,w = map(int,input().split()) path[u].add(v) path[v].add(u) cost[(u,v)] = w path1 = deepcopy(path) child = Counter() st = [1] while len(st): if not len(path[st[-1]]): if not child[st[-1]]: child[st[-1]] = 1 if len(st) > 1: child[st[-2]] += child[st[-1]] st.pop() continue i = path[st[-1]].pop() path[i].remove(st[-1]) st.append(i) st,y = [1],[] while len(st): if not len(path1[st[-1]]): st.pop() continue i = path1[st[-1]].pop() path1[i].remove(st[-1]) st.append(i) if cost.get((st[-1],st[-2])): y.append(Node(cost[(st[-1],st[-2])],child[st[-1]])) cost[(st[-1],st[-2])] *= child[st[-1]] else: y.append(Node(cost[(st[-2],st[-1])],child[st[-1]])) cost[(st[-2],st[-1])] *= child[st[-1]] x = sum(cost.values()) heapify(y) ans = 0 while x > s: z = heappop(y) x -= z.dec z = Node(z.val//2,z.occ) if z.val: heappush(y,z) ans += 1 print(ans) #Fast IO Region BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in file.mode self.write = self.buffer.write if self.writable else None def read(self): while True: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) if not b: break ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines = 0 return self.buffer.read() def readline(self): while self.newlines == 0: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) self.newlines = b.count(b"\n") + (not b) ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines -= 1 return self.buffer.readline() def flush(self): if self.writable: os.write(self._fd, self.buffer.getvalue()) self.buffer.truncate(0), self.buffer.seek(0) class IOWrapper(IOBase): def __init__(self, file): self.buffer = FastIO(file) self.flush = self.buffer.flush self.writable = self.buffer.writable self.write = lambda s: self.buffer.write(s.encode("ascii")) self.read = lambda: self.buffer.read().decode("ascii") self.readline = lambda: self.buffer.readline().decode("ascii") sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout) input = lambda: sys.stdin.readline().rstrip("\r\n") if __name__ == '__main__': main()
2,000
PYTHON3
#include <bits/stdc++.h> using namespace std; pair<int, int> P, Q, q[200000], D[8] = {make_pair(-1, -2), make_pair(-2, -1), make_pair(-2, 1), make_pair(1, -2), make_pair(2, -1), make_pair(2, 1), make_pair(1, 2), make_pair(-1, 2)}; int t, t1, t2, n, he, ta, x, y, v[300][300], f[300]; bool b[300][300]; long long k; const long long MO = int(1e9) + 7; void bfs() { he = 0; ta = 1; q[1] = make_pair(100, 100); memset(v, -1, sizeof(v)); v[100][100] = 0; f[0] = 1; while (he < ta) { pair<int, int> P = q[++he]; for (int d = 0; d <= 7; d++) { pair<int, int> Q = make_pair(P.first + D[d].first, P.second + D[d].second); if (Q.first < 0 || Q.first >= 200 || Q.second < 0 || Q.second >= 200) continue; if (b[Q.first][Q.second]) continue; if (v[Q.first][Q.second] != -1) continue; v[Q.first][Q.second] = v[P.first][P.second] + 1; f[v[Q.first][Q.second]]++; q[++ta] = Q; } } } int main() { cin >> k >> n; for (int i = 1; i <= n; i++) { cin >> x >> y; x += 100; y += 100; b[x][y] = 1; } bfs(); for (int i = 1; i <= 41; i++) f[i] += f[i - 1]; if (k <= 40) cout << f[k] << endl; else if (f[40] == f[41]) cout << f[40] << endl; else { t1 = f[40]; t2 = f[41]; t = t2 - t1; cout << ((k - 40) % MO * t % MO + (k - 41) % MO * 14 % MO * ((k - 40) % MO) % MO + t1) % MO << endl; } return 0; }
3,000
CPP
#include <bits/stdc++.h> using namespace std; int q[32], qq[32], pos[32], n, p; bool f[32][32][50005]; pair<bool, unsigned short> fr[32][32][50005]; int main() { scanf("%d%d", &n, &p); for (int i = (int)(1); i <= (int)(n); i++) { int x; scanf("%d", &x); if (x <= 31) { q[++*q] = x; pos[*q] = i; } } for (int i = (int)(1); i <= (int)(*q); i++) { f[i][q[i]][q[i] % p] = 1; fr[i][q[i]][q[i] % p] = pair<bool, unsigned short>(1, p + 1); for (int j = (int)(0); j <= (int)(31); j++) for (int k = (int)(0); k <= (int)(p - 1); k++) if (f[i - 1][j][k]) { f[i][j][k] = 1; fr[i][j][k] = pair<bool, unsigned short>(0, 0); int nv = (k * (q[i] <= 9 ? 10 : 100) + q[i]) % p; f[i][j ^ q[i]][nv] = 1; fr[i][j ^ q[i]][nv] = pair<bool, unsigned short>(1, k); } } if (!f[*q][0][0]) return puts("No"), 0; puts("Yes"); int px = 0, py = 0; for (int i = (int)(*q); i >= (int)(1); i--) { if (py < 0 || py >= p) break; if (fr[i][px][py].first == 0) continue; int v1 = fr[i][px][py].second; px ^= q[i]; py = v1; qq[++*qq] = pos[i]; } reverse(qq + 1, qq + *qq + 1); printf("%d\n", *qq); for (int i = (int)(1); i <= (int)(*qq); i++) printf("%d ", qq[i]); }
2,900
CPP
n=int(input()) if n%2==0: print(str(n-4)+" 4") else: print(str(n-9)+" 9")
800
PYTHON3
#include <bits/stdc++.h> using namespace std; int f(int n, int m, int x) { n -= 2 * (x - 1); m -= 2 * (x - 1); if (n <= 0 || m <= 0) return 0; else { int ans = n * (m / 2); if (m % 2) ans += n / 2 + n % 2; return ans; } } int main() { int n, m, x; cin >> n >> m >> x; cout << f(n, m, x) - f(n, m, x + 1) << endl; return 0; }
1,600
CPP
if __name__ == '__main__': l = int(input()) s = input() now = '' for i in range(l): if s[i] < now: print(f'YES\n{i} {i + 1}') break now = s[i] else: print('NO')
1,000
PYTHON3
''' Auther: ghoshashis545 Ashis Ghosh College: jalpaiguri Govt Enggineering College ''' from os import path import sys from heapq import heappush,heappop,heapify from functools import cmp_to_key as ctk from collections import deque,defaultdict as dd from bisect import bisect,bisect_left,bisect_right,insort,insort_left,insort_right from itertools import permutations from datetime import datetime from math import ceil,sqrt,log,gcd def ii():return int(input()) def si():return input().rstrip() def mi():return map(int,input().split()) def li():return list(mi()) abc='abcdefghijklmnopqrstuvwxyz' mod=1000000007 # mod=998244353 inf = float("inf") vow=['a','e','i','o','u'] dx,dy=[-1,1,0,0],[0,0,1,-1] def b(i): # ord(i) -> Ascii value of i return ord(i)-ord('a') file = 1 def solve(): for _ in range(ii()): n=ii() s=si() ans=0 z,o=[],[] x=[0]*n c=0 for i in range(n): if s[i]=='0': if len(o): x[i]=o[-1] o.pop() z.append(x[i]) else: c+=1 z.append(c) x[i]=c else: if len(z): x[i]=z[-1] z.pop() o.append(x[i]) else: c+=1 o.append(c) x[i]=c print(len(set(x))) print(*x) if __name__ =="__main__": if(file): if path.exists('input.txt'): sys.stdin=open('input.txt', 'r') sys.stdout=open('output.txt','w') else: input=sys.stdin.readline solve()
1,500
PYTHON3
import sys input = sys.stdin.readline def main(): Q = int(input()) UV = [[int(x) for x in input().split()] for _ in range(Q)] for u, v in UV: if u == v: print("YES") elif u > v: print("NO") else: u_one = bin(u).count("1") u_i = [] v_i = [] for i in range(32): if u >> i & 1: u_i.append(i) if v >> i & 1: v_i.append(i) v_one = bin(v).count("1") if u_one == v_one: f = True for a, b in zip(u_i, v_i): if a > b: f = False break if f: print("YES") else: print("NO") elif u_one > v_one: f = True for a, b in zip(u_i, v_i): if a > b: f = False break if f: print("YES") else: print("NO") else: print("NO") if __name__ == '__main__': main()
1,800
PYTHON3
#include <bits/stdc++.h> int main() { int y = 999999, x, l, v, n, t, c = 0, d, e, f, i, j, dizi[100199], dixi[100199], sizi[100199][2], say = 1; scanf("%d %d %d %d", &l, &v, &n, &t); for (i = 1; i <= l; i++) scanf("%d", &dizi[i]); for (i = 1; i <= v; i++) { scanf("%d", &dixi[i]); } i = 1; j = 1; while (y != 0) { if (j > v || i > l) break; if ((dizi[i] - n) <= dixi[j] && (dizi[i] + t) >= dixi[j]) { sizi[say][0] = i; sizi[say][1] = j; i++; j++; say++; continue; } if ((dizi[i] + t) < dixi[j]) i++; if ((dizi[i] - n) > dixi[j]) j++; } printf("%d\n", say - 1); for (i = 1; i <= say; i++) { if (sizi[i][0] != 0 && sizi[i][1] != 0) printf("%d %d\n", sizi[i][0], sizi[i][1]); } return 0; }
1,300
CPP
#include <bits/stdc++.h> using namespace std; void __print(int x) { cerr << x; } void __print(long x) { cerr << x; } void __print(long long x) { cerr << x; } void __print(unsigned x) { cerr << x; } void __print(unsigned long x) { cerr << x; } void __print(unsigned long long x) { cerr << x; } void __print(float x) { cerr << x; } void __print(double x) { cerr << x; } void __print(long double x) { cerr << x; } void __print(char x) { cerr << '\'' << x << '\''; } void __print(const char *x) { cerr << '\"' << x << '\"'; } void __print(const string &x) { cerr << '\"' << x << '\"'; } void __print(bool x) { cerr << (x ? "true" : "false"); } template <typename T, typename V> void __print(const pair<T, V> &x) { cerr << '{'; __print(x.first); cerr << ','; __print(x.second); cerr << '}'; } template <typename T> void __print(const T &x) { int f = 0; cerr << '{'; for (auto &i : x) cerr << (f++ ? "," : ""), __print(i); cerr << "}"; } void _print() { cerr << "]\n"; } template <typename T, typename... V> void _print(T t, V... v) { __print(t); if (sizeof...(v)) cerr << ", "; _print(v...); } void solve() { long long n; cin >> n; vector<long long> a(n); for (long long i = 0; i < n; i++) cin >> a[i]; long long dp[200005]; memset(dp, 0, sizeof(dp)); for (long long i = 0; i < n; i++) dp[a[i]] = 1; long long ans = 1; for (long long i = 0; i < n; i++) { long long x = a[i]; vector<long long> divs; for (long long i = 2; i * i <= x; i++) { if (x % i == 0) { dp[x] = max(dp[x], dp[i] + 1); divs.push_back(i); if (i != (x / i)) { dp[x] = max(dp[x], dp[(x / i)] + 1); divs.push_back((x / i)); } } } for (auto i : divs) dp[i] = dp[x]; ans = max(ans, dp[x]); } cout << ans << "\n"; } signed main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); long long t; t = 1; for (long long i = 0; i < t; i++) { solve(); } }
1,500
CPP
n = int(input()) A = list(map(int, input().split())) answer = 0 lol = 10**9 for i in range(n): num_ = i + 1 for k in range(n): y = 0 y += abs(num_ - (k + 1)) * A[k] y += k * A[k] y += (num_ - 1) * A[k] y *= 2 answer += y if answer < lol: lol = answer print(lol)
1,000
PYTHON3
#include <bits/stdc++.h> using namespace std; long long pow(long long a, long long b, long long M) { long long t = 1; for (a %= M; b; b >>= 1) { if (b & 1) t = t * a % M; a = a * a % M; } return t; } inline int getc() { static const int N = 222; static char buf[N]; static int n = 0, p = 0; if (p == n) p = 0, n = fread(buf, 1, N, stdin); if (p == n) exit(0); return buf[p++]; } inline int R(int& first) { int f = 1, c = getc(); first = 0; while (c <= 32) c = getc(); if (c == '-') f = -1, c = getc(); for (; '0' <= c && c <= '9'; c = getc()) first = first * 10 + c - '0'; first *= f; } static const int N = 5e6, M = N + 5; struct Sieve { int p[M], m, v[M]; Sieve() { for (int i = 2; i <= int(N); i++) { if (!v[i]) p[++m] = i; for (int j = 1; j <= int(m); j++) { int k = i * p[j]; if (k > N) break; v[k] = 1; if (i % p[j] == 0) break; } } } bool operator()(int i) { return !v[i]; } } isprime; int s[M]; map<long long, long long> q[M]; long long f(long long p, long long n) { if (p <= 1) return n - 1; if (q[p].count(n)) return q[p][n]; if (n <= N && p * p >= n) return s[n]; if (!isprime(p) || p * p > n) return f(p - 1, n); else return f(p - 1, n) - (f(p - 1, n / p) - f(p - 1, p - 1)); } int main() { for (int i = 2; i <= int(N); i++) s[i] = s[i - 1] + isprime(i); long long n; cin >> n; long long ans = s[(int)(powl(n, 1.0 / 3) + 1e-5)]; long long m = sqrt(n); for (int i = 2; i <= int(m); i++) if (isprime(i)) { long long t = n / i; ans += f(sqrt(t) + 1, t) - s[i]; } cout << ans << endl; }
2,400
CPP
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int T; cin >> T; while (T) { long long input[3]; long long sum = 0; long long output = 0; for (int i = 0; i < 3; i++) { cin >> input[i]; sum += input[i]; } output = sum / 2; cout << output << endl; T--; } }
800
CPP
import math t = int(input()) for i in range(t): n = int(input()) sum = n * (n + 1) // 2 sum = sum - 2 * (pow(2, math.floor(math.log2(n)) + 1) - 1) print(sum)
900
PYTHON3
#include <bits/stdc++.h> using namespace std; int a[105], b[105], print[105]; int main() { int n, k, i, p; int sum, count; scanf("%d%d", &n, &k); int j = 1; for (i = 1; i <= n; i++) { scanf("%d", &a[i]); b[j] = a[i]; j++; } sort(a, a + i); if (a[1] > k) { printf("0\n"); } else { sum = 0; count = 0; for (int i = 1; i <= n; i++) { sum = sum + a[i]; count++; if (sum >= k) { if (sum == k) { break; } else { sum = sum - a[i]; count--; break; } } } p = 1; for (int i = 1; i <= count; i++) { for (int j = 1; j <= n; j++) { if (a[i] == b[j]) { print[p] = j; b[j] = 0; p++; } } } sort(print, print + p); printf("%d\n", count); for (p = 1; p <= count; p++) { printf("%d ", print[p]); } printf("\n"); } }
1,000
CPP
#include <bits/stdc++.h> using namespace std; const int inf = numeric_limits<int>::max(); const long long linf = numeric_limits<long long>::max(); const int max_n = 101; int n, m, q; bool g[max_n][max_n][max_n], visited[max_n]; bool dfs(int st, int end, int col, int par = -1) { if (st == end) return true; if (visited[st]) return false; visited[st] = true; bool ret = false; for (int i = 0; i < (max_n); ++i) { if (g[st][i][col] && i != par) ret |= dfs(i, end, col, st); } return ret; } int main() { int u, v, c; cin >> n; cin >> m; for (int i = 0; i < (m); ++i) { cin >> u, cin >> v, cin >> c; g[u][v][c] = true; g[v][u][c] = true; } cin >> q; for (int i = 0; i < (q); ++i) { cin >> u, cin >> v; c = 0; for (int j = (1); j < (m + 1); ++j) { fill(visited, visited + max_n, false); c += dfs(u, v, j); } cout << c << endl; } return 0; }
1,400
CPP
#include <bits/stdc++.h> using namespace std; const int mod = 1000000007; int n, m, k, i, j, a[1002][1002], vis[12], col[1002][1002]; int read() { char c = getchar(); int w = 0; while (c < '0' || c > '9') c = getchar(); while (c <= '9' && c >= '0') { w = w * 10 + c - '0'; c = getchar(); } return w; } int count(int x) { int ans = 0; for (int i = 0; (1 << i) <= x; i++) { if (x & (1 << i)) ans++; } return ans; } int dfs(int x, int y) { if (y == m + 1) x++, y = 1; if (x == n + 1) return 1; int s = (col[x - 1][y] | col[x][y - 1]) ^ ((1 << k) - 1), ans = 0, tmp = -1; if (n - x + m - y + 1 > count(s)) return 0; for (int i = 0; (1 << i) <= s; i++) { if (s & (1 << i) && (a[x][y] == 0 || a[x][y] == i + 1)) { col[x][y] = (col[x][y - 1] | col[x - 1][y] | (1 << i)); vis[i + 1]++; if (vis[i + 1] == 1) { if (tmp == -1) tmp = dfs(x, y + 1); ans = (ans + tmp) % mod; } else ans = (ans + dfs(x, y + 1)) % mod; vis[i + 1]--; } } return ans; } int main() { n = read(); m = read(); k = read(); for (i = 1; i <= n; i++) { for (j = 1; j <= m; j++) { a[i][j] = read(); vis[a[i][j]]++; } } if (n + m - 1 > k) puts("0"); else printf("%d\n", dfs(1, 1)); return 0; }
2,700
CPP
import sys, itertools, math def ia(): return [int(i) for i in sys.stdin.readline().strip().split(" ")] def ii(): return int(sys.stdin.readline().strip()) def istr(): return sys.stdin.readline().strip() ### n, x = ia() t = 1 ans = 0 for _ in range(n): l, r = ia() s = (l-t)//x t += s*x ans += r - t + 1 t = r + 1 print(ans)
1,000
PYTHON3
#include <bits/stdc++.h> using namespace std; const int mod = 998244353; int mult(int a, int b) { return (1LL * a * b) % mod; } int sum(int a, int b) { int s = a + b; if (s >= mod) s -= mod; return s; } int sub(int a, int b) { int s = a - b; if (s < 0) s += mod; return s; } int pw(int a, int b) { if (b == 0) return 1; if (b & 1) return mult(a, pw(a, b - 1)); int res = pw(a, b / 2); return mult(res, res); } const int maxN = 3605; int c[maxN][maxN]; int h, w, n; int dp[maxN][maxN]; int f[2][maxN]; void solve(vector<int>& X, int z) { memset(dp, 0, sizeof dp); sort(X.begin(), X.end()); int c = X.back() - 1; vector<bool> bad(c + 2, false); for (int v : X) bad[v] = true; dp[0][0] = 1; for (int i = 1; i <= c; i++) { for (int cnt = 0; 2 * cnt <= i - 1; cnt++) { dp[i][cnt] = sum(dp[i][cnt], dp[i - 1][cnt]); if (i >= 2 && !bad[i] && !bad[i - 1]) { dp[i][cnt + 1] = sum(dp[i][cnt + 1], dp[i - 2][cnt]); } } } for (int v = 0; v < maxN; v++) { f[z][v] = dp[c][v]; } } int fact[maxN]; int main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); cin >> h >> w >> n; vector<int> badX, badY; c[0][0] = 1; fact[0] = 1; for (int i = 1; i < maxN; i++) { fact[i] = mult(fact[i - 1], i); c[i][0] = 1; for (int j = 1; j <= i; j++) c[i][j] = sum(c[i - 1][j], c[i - 1][j - 1]); } badX.emplace_back(0); badX.emplace_back(h + 1); badY.emplace_back(w + 1); badY.emplace_back(0); int freeX = h; int freeY = w; for (int i = 1; i <= n; i++) { int r1, c1, r2, c2; cin >> r1 >> c1 >> r2 >> c2; if (r1 == r2) { badX.emplace_back(r1); badY.emplace_back(c1); badY.emplace_back(c2); freeX -= 1; freeY -= 2; } else { badX.emplace_back(r1); badX.emplace_back(r2); badY.emplace_back(c1); freeX -= 2; freeY -= 1; } } for (int z = 0; z < 2; z++) { solve(badX, z); swap(badX, badY); } int ans = 0; for (int takeX = 0; 2 * takeX <= freeX; takeX++) { for (int takeY = 0; 2 * takeY <= freeY; takeY++) { int z = mult( c[freeX - 2 * takeX][takeY], mult(c[freeY - 2 * takeY][takeX], mult(f[0][takeX], f[1][takeY]))); ans = sum(ans, mult(fact[takeX], mult(fact[takeY], mult(c[freeX - 2 * takeX][takeY], mult(c[freeY - 2 * takeY][takeX], mult(f[0][takeX], f[1][takeY])))))); } } cout << ans; }
2,600
CPP
n = int(input()) a = input() + '$' b = input() + '$' weight = 0 i = 0 while i < n: if a[i] != b[i]: weight += 1 if a[i] == b[i + 1] and a[i + 1] == b[i]: i += 2 continue i += 1 print(weight)
1,300
PYTHON3
#include <bits/stdc++.h> using namespace std; long long mod = 1e9 + 7; long long min(long long a, long long b) { return (a < b) ? a : b; } long long max(long long a, long long b) { return (a > b) ? a : b; } long long fp(long long a, long long b) { if (b == 0) return 1; long long x = fp(a, b / 2); x = (x * x) % mod; if (b & 1) x = (x * a) % mod; return x; } auto random_add = [] { char *p = new char; delete p; return uint64_t(p); }; const uint64_t SEED = chrono::steady_clock::now().time_since_epoch().count() * (random_add() | 1); mt19937_64 rng(SEED); const long long N = 2e5 + 5; vector<array<long long, 6>> ans; long long n, m; string s[N], s2[N]; void mysolve(array<long long, 6> arr) { for (long long i = 0; i < 6; i += 2) { s[arr[i]][arr[i + 1]] ^= 1; } } void solve(long long i, long long j) {} void per(long long i, long long j) { if (s[i][j] == '0') return; vector<array<long long, 2>> v = {{0, 1}, {1, 0}, {1, 1}, {1, -1}}; array<long long, 6> x; long long idx = 0; long long count = 0; for (auto k : v) { long long nx = k[0] + i; long long ny = k[1] + j; if (nx >= 1 && nx <= n && ny >= 1 && ny <= m) { x[idx] = nx; idx++; x[idx] = ny; idx++; if (s[nx][ny] == '1') s[nx][ny] = '0'; else s[nx][ny] = '1'; count++; if (count == 2) break; } } x[idx] = i; idx++; x[idx] = j; idx++; s[i][j] ^= 1; ans.push_back(x); } void per2(long long i, long long j) { if (s[i][j] == '0') return; vector<array<long long, 2>> v; if (i == n - 1) { v = {{0, 1}, {1, 1}}; } else { v = {{0, 1}, {-1, 1}}; } array<long long, 6> x; long long idx = 0; long long count = 0; for (auto k : v) { long long nx = k[0] + i; long long ny = k[1] + j; if (nx >= 1 && nx <= n && ny >= 1 && ny <= m) { x[idx] = nx; idx++; x[idx] = ny; idx++; if (s[nx][ny] == '1') s[nx][ny] = '0'; else s[nx][ny] = '1'; count++; if (count == 2) break; } } x[idx] = i; idx++; x[idx] = j; idx++; s[i][j] ^= 1; ans.push_back(x); } void solve1() { set<long long> st; long long ct = 0; for (long long i = n - 1; i <= n; i++) { for (long long j = m - 1; j <= m; j++) { st.insert(s[i][j]); if (s[i][j] == '1') ct++; } } if (st.size() == 1 && st.find('0') != st.end()) return; array<long long, 6> arr; long long idx = 0; long long y = '1'; if (ct == 2) y = '0'; for (long long i = n - 1; i <= n; i++) { for (long long j = m - 1; j <= m; j++) { if (s[i][j] == y) { if (idx != 6) { arr[idx] = i; idx++; arr[idx] = j; idx++; } } } } for (long long i = n - 1; i <= n; i++) { for (long long j = m - 1; j <= m; j++) { if (s[i][j] == y ^ 1) { if (idx != 6) { arr[idx] = i; idx++; arr[idx] = j; idx++; } } } } mysolve(arr); ans.push_back(arr); solve1(); } void solve3(array<long long, 6> a) { for (long long i = 0; i < 6; i += 2) { s2[a[i]][a[i + 1]] ^= 1; } } void solve() { ans.clear(); cin >> n >> m; for (long long i = 1; i <= n; i++) { cin >> s[i]; s2[i] = '#' + s[i]; s[i] = '#' + s[i]; } for (long long i = 1; i <= n - 2; i++) { for (long long j = 1; j <= m; j++) { per(i, j); } } for (long long j = 1; j <= m - 2; j++) { for (long long i = n - 1; i <= n; i++) { per2(i, j); } } solve1(); cout << ans.size() << "\n"; for (auto i : ans) { set<array<long long, 2>> pp; for (long long j = 0; j < 6; j += 2) pp.insert({i[j], i[j + 1]}); if (pp.size() != 3) { cout << "Bug"; exit(0); } for (auto j : i) cout << j << " "; cout << "\n"; } } signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); srand(time(0)); long long t = 1; cin >> t; for (long long i = 1; i <= t; i++) { solve(); } }
1,500
CPP
my_string = input().split(' ') num = int(my_string[0]) k = int(my_string[1]) while (k > 0): if (num % 10 == 0): num = int(num/10) else: num -= 1 k -= 1 print(num)
800
PYTHON3
size = int(input()) string = input() maxCycleSize = 1 i = 0 while i < len(string)//2 + 1: if(string[0:i] == string[i: 2*i]): maxCycleSize = i if i > 0 else 1 #print(maxCycleSize) i += 1 print(size - maxCycleSize + 1)
1,400
PYTHON3
for _ in range(int(input())) : n = int(input()) m = n arr = list(map(int,input().split())) n = n//2 small = arr.copy() arr.sort(reverse=True) small.sort() result = [] for i in range(n) : result.append(arr[i]) result.append(small[i]) if m%2==1 : result.append(arr[n]) result = result[::-1] print(*result) # for i in range(len(result)-2) : # if abs(result[i] - result[i+1]) > abs(result[i+1] - result[i+2]) : # print('yes')
1,200
PYTHON3
# -*- coding: utf-8 -*- """ Created on Sun May 10 07:41:14 2020 @author: Kashem Pagla """ for _ in range(int(input())): n=int(input()) even=[];odd=[] if(n<4): print("-1") else: for i in range(1,n+1): if(i%2==0): even.append(i) else: odd.append(i) print(*(sorted(odd, reverse=True)+sorted(even[:2], reverse=True)+even[2:]))
1,600
PYTHON3
for _ in range(int(input())): n=int(input()) a=[int(x) for x in input().split()] s=sum(a) if(s==0): print("NO") elif(s>0): a.sort(reverse=True) print("YES") print(*a) else: a.sort() print("YES") print(*a)
900
PYTHON3
#include <bits/stdc++.h> #define pii pair<int, int> #define f first #define s second #define ll long long #define oo 1000000000 #define piii pair<pii, int> #define pb push_back using namespace std; void solve() { int n; cin >> n; vector<int>p(n + 1), pos(n + 1); for(int i = 1; i <= n; ++i) { cin >> p[i]; pos[p[i]] = i; } vector<bool>visited(n + 1, false); vector<vector<int>>cycles; vector<pii>res; for(int i = 1; i <= n; ++i) { if(!visited[i]) { vector<int>cycle; int node = i; while(!visited[node]) { cycle.pb(node); visited[node] = true; node = p[node]; } if((int)cycle.size() >= 2) { cycles.pb(cycle); } } } while((int)cycles.size() > 1) { vector<int>cycle1 = cycles.back(); cycles.pop_back(); vector<int>cycle2 = cycles.back(); cycles.pop_back(); if((int)cycle1.size() > (int)cycle2.size()) { swap(cycle1, cycle2); } reverse(cycle2.begin(), cycle2.end()); for(int i = 0; i < (int)cycle1.size(); ++i) { res.pb({cycle1[i], cycle2[i]}); swap(p[cycle1[i]], p[cycle2[i]]); } for(int i = 0; i < (int)cycle1.size(); ++i) { while(p[cycle1[i]] != cycle1[i]) { res.pb({cycle1[i], p[cycle1[i]]}); swap(p[cycle1[i]], p[p[cycle1[i]]]); } } } if(!cycles.empty()) { int inpos = 0; for(int i = 1; i <= n && inpos == 0; ++i) { if(p[i] == i) { inpos = i; } } if(inpos) { for(int i = 0; i < (int)cycles[0].size(); ++i) { res.pb({inpos, cycles[0][i]}); swap(p[inpos], p[cycles[0][i]]); } res.pb({inpos, cycles[0][0]}); swap(p[inpos], p[cycles[0][0]]); }else { /// cycle size > 2, otherwise there will be some i, where p[i] = i int i = cycles[0][0]; int idx = p[i]; res.pb({pos[i], p[i]}); swap(p[pos[i]], p[p[i]]); res.pb({i, pos[i]}); swap(p[i], p[pos[i]]); while(p[idx] != idx) { res.pb({p[idx], idx}); swap(p[p[idx]], p[idx]); } } } cout << res.size() << '\n'; for(pii pr : res) { cout << pr.f << " " << pr.s << '\n'; } } int main() { int t = 1; // cin >> t; while(t--) { solve(); } return 0; }
2,800
CPP
import sys def main(): n = int(sys.stdin.readline().strip()) for i in range(n): x = int(sys.stdin.readline().strip()) if x not in [1, 2, 4, 5, 8, 11]: print("YES") else: print("NO") main()
900
PYTHON3
#include <bits/stdc++.h> using namespace std; int n, m, f[550][26][26], fx[550][26][26], fy[550][26][26]; char a[550][550]; int calc(int n, int x, int y) { int s = 0; for (int i = 0; i < m; i++) { int v = int(a[n][i]) - int('a'); s += int((i % 2 == 0 ? x : y) != v); } return s; } int main() { scanf("%d%d\n", &n, &m); for (int i = 0; i < n; i++) gets(a[i]); for (int r = 0; r < n; r++) for (int i = 0; i < 26; i++) for (int j = 0; j < 26; j++) { int v = calc(r, i, j); if (r == 0) f[r][i][j] = v; else { int now = n * m; for (int x = 0; x < 26; x++) if (x != i) for (int y = 0; y < 26; y++) if (y != x && y != j && now > f[r - 1][x][y] + v) { now = f[r - 1][x][y] + v; fx[r][i][j] = x; fy[r][i][j] = y; } f[r][i][j] = now; } } int res = n * m, x, y; for (int i = 0; i < 26; i++) for (int j = 0; j < 26; j++) if (i != j && res > f[n - 1][i][j]) { res = f[n - 1][i][j]; x = i; y = j; } printf("%d\n", res); for (int i = n - 1; i >= 0; i--) { for (int j = 0; j < m; j++) a[i][j] = (j % 2 == 0 ? char(x + 97) : char(y + 97)); int xx = fx[i][x][y]; int yy = fy[i][x][y]; x = xx; y = yy; } for (int i = 0; i < n; i++) puts(a[i]); return 0; }
2,000
CPP
for i in range(int(input())): n = int(input()) a = [int(j) for j in input().split()] dp = [10 ** 18 for j in range(n)] dp[0] = a[0] if (n > 1): dp[1] = a[1] + a[0] for j in range(2, n): # 1 1 if (j >= 2): dp[j] = min(dp[j], dp[j - 2] + a[j]) # 1 2 if (j >= 3): dp[j] = min(dp[j], dp[j - 3] + a[j] + a[j - 1]) # 2 1 if (j >= 3): dp[j] = min(dp[j], dp[j - 3] + a[j]) # 2 2 if (j >= 4): dp[j] = min(dp[j], dp[j - 4] + a[j] + a[j - 1]) print(min(dp[max(0, n - 1)], dp[max(0, n - 2)], dp[max(0, n - 3)]))
1,500
PYTHON3
#include <bits/stdc++.h> using namespace std; inline long long add(long long a, long long b) { return (a % 1000000007 + b % 1000000007) % 1000000007; } inline long long mul(long long a, long long b) { return (a % 1000000007 * b % 1000000007) % 1000000007; } long long pwr(long long a, long long b) { if (!b) return 1ll; long long t = pwr(a, b / 2); t = mul(t, t); if (b & 1) t = mul(t, a); return t; } long long modinv(long long a, long long b = 1000000007) { return pwr(a, b - 2); } long long gcd(long long a, long long b) { if (!b) return a; return gcd(b, a % b); } long long lcm(long long a, long long b) { return (a / gcd(a, b)) * b; } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); int t; cin >> t; while (t--) { int n, a, b, c, d; cin >> n >> a >> b >> c >> d; int x = a - b, y = a + b; int p = c - d, q = c + d; int mn = x * n, flag = 1; for (int i = 1; i <= n; i++) { if (mn <= q && mn >= p) { flag = 0; break; } if (mn < p) { int diff = p - mn; mn += min(diff, 2 * b); } } if (mn <= q && mn >= p) { flag = 0; } if (flag) cout << "No\n"; else cout << "Yes\n"; } }
900
CPP
#include <bits/stdc++.h> using namespace std; const int N = 4e5 + 10; struct node { int l, r, op; bool operator<(node b) const { return r < b.r || (r == b.r && l < b.l); } } a[N]; multiset<int> s[2]; int n, ans; int main() { scanf("%d", &n); for (int i = 1; i <= n; i++) { scanf("%d%d%d", &a[i].l, &a[i].r, &a[i].op), a[i].op--; } sort(a + 1, a + n + 1); for (int i = 1; i <= n; i++) { int t = a[i].op; set<int>::iterator it = s[t ^ 1].lower_bound(a[i].l); if (it == s[t ^ 1].end()) { s[t].insert(a[i].r); } else { ans++; s[t ^ 1].erase(it); } } printf("%d\n", n - ans); return 0; }
2,600
CPP
#include <bits/stdc++.h> int gcd(int a, int b) { int tmp; while (a % b) { tmp = b; b = a % b; a = tmp; } return b; } int main() { int n; int l, l1, l2, tmp; int num[1001], ans; for (l = 2, num[1] = 0; l <= 1000; num[l] = 1, l++) ; for (l = 2; l <= 1000; l++) { for (l1 = 2; l1 < l; l1++) { if (l % l1 == 0 && gcd(l1, l / l1) == 1) { num[l] = 0; break; } } } while (1 == scanf("%d", &n)) { for (l = 2, ans = 0; l <= n; l++) { if (num[l]) ans++; } printf("%d\n", ans); for (l = 2; l <= n; l++) { if (num[l]) printf("%d ", l); } putchar('\n'); } return 0; }
1,500
CPP
n = int(input()) pline = input().split(' ') p = [int(i) for i in pline] q = [0 for i in range(n)] for i in range(n): q[p[i]-1] = i+1 res = '' for i in range(n-1): res += str(q[i])+' ' res += str(q[-1]) print(res)
800
PYTHON3
#include <bits/stdc++.h> using namespace std; void solve() { long long int n; cin >> n; long long int s = 0, x = (n + 1) / 2; long long int a[n + 1][n + 1]; for (long long int i = 1; i < n + 1; i++) { for (long long int j = 1; j < n + 1; j++) cin >> a[i][j]; } for (long long int i = 1; i < n + 1; i++) { for (long long int j = 1; j < n + 1; j++) { if (i == j) s = s + a[i][j]; } } for (long long int i = 1; i < n + 1; i++) s = s + a[i][x]; for (long long int i = 1; i < n + 1; i++) s = s + a[x][i]; for (long long int i = 1, j = n; i < n + 1; i++, j--) s = s + a[i][j]; s = s - (3 * a[x][x]); cout << s; } int32_t main() { ios_base::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr); long long int t = 1; while (t--) solve(); return 0; }
800
CPP
n = int(input()) arr = [['' for _ in range(n)] for _ in range(n)] for i in range(n): for j in range(n): if (i+j)%2>0: arr[i][j] = 'W' else: arr[i][j] = 'B' print(''.join(arr[i]))
1,100
PYTHON3
#include <bits/stdc++.h> using namespace std; template <typename T> inline bool chkmin(T &x, T y) { return y < x ? x = y, 1 : 0; } template <typename T> inline bool chkmax(T &x, T y) { return x < y ? x = y, 1 : 0; } const int INF = 0x3f3f3f3f; const int N = 1e7 + 10; int phi[N], prime[N], Min[N], sum[N]; int pcnt = 0; bitset<N> vis; inline int read() { int x = 0, flag = 1; char ch = getchar(); while (!isdigit(ch) && ch != '-') ch = getchar(); if (ch == '-') flag = -1, ch = getchar(); while (isdigit(ch)) x = (x << 3) + (x << 1) + (ch - '0'), ch = getchar(); return x * flag; } inline void init(int n) { phi[1] = 1; for (int i = (2), iend = (n); i <= iend; i++) { if (!vis[i]) prime[++pcnt] = i, phi[i] = i - 1, sum[Min[i] = i]++; for (int j = 1; j <= pcnt && i * prime[j] <= n; j++) { vis[i * prime[j]] = true; phi[i * prime[j]] = phi[i] * (prime[j] - 1); sum[Min[i * prime[j]] = min(Min[i], prime[j])]++; if (i % prime[j] == 0) { phi[i * prime[j]] = phi[i] * prime[j]; break; } } } } int main() { int n = read(); long long cnt = 1; if (n == 1) return puts("0"), 0; init(n); long long ans0 = 0, ans1 = 0, ans2 = 0, ans3 = 0; for (int i = (n / 2 + 1), iend = (n); i <= iend; i++) cnt += !vis[i]; ans0 = 1ll * cnt * (n - 1) - 1ll * cnt * (cnt - 1) / 2, cnt = 0; for (int i = (2), iend = (n); i <= iend; i++) cnt += phi[i]; ans1 = 1ll * n * (n - 1) / 2 - cnt, cnt = 0; for (int i = (n), iend = (1); i >= iend; i--) sum[i] += sum[i + 1]; cnt += (n - 1); for (int i = (1), iend = (pcnt); i <= iend; i++) cnt += sum[n / prime[i] + 1]; for (int i = (1), iend = (n); i <= iend; i++) sum[i] = sum[i + 1] + !vis[i]; for (int i = (1), iend = (pcnt); i <= iend; i++) cnt -= sum[max(n / prime[i] + 1, prime[i])]; ans2 = 1ll * n * (n - 1) / 2 - ans1 - cnt; ans3 = 1ll * n * (n - 1) / 2 - ans0 - ans1 - ans2; printf("%lld\n", ans1 + 2 * ans2 + 3 * ans3); return 0; }
2,700
CPP
n,m=map(int,input().split()) l=[0]*(m) for _ in range(n): a,b=map(int,input().split()) for i in range(a,b+1): l[i-1]=1 if(l.count(0)==0): print(0) else: print(l.count(0)) for i in range(m): if(l[i]==0): print(i+1,end=" ")
800
PYTHON3
#include <bits/stdc++.h> using namespace std; int solve(int n, int k, vector<int> &arr, int mn) { int MX = int(1e6); if (k >= mn - 1) return mn; int i, j; for (i = mn; i >= k + 1; i--) { int tot = 0; for (j = 0; j <= MX; j += i) { int mx = min(j + k, MX); tot += (arr[mx] - (j > 0 ? arr[j - 1] : 0)); } if (tot == n) return i; } return -33; } int main() { int MX = (1e6) + 2; vector<int> arr(MX - 1, 0); int n; scanf("%d", &n); int k; scanf("%d", &k); int i, j; int mn = MX; for (i = 0; i < n; i++) { int temp; scanf("%d", &temp); mn = min(mn, temp); arr[temp]++; } for (i = 1; i < MX; i++) arr[i] += arr[i - 1]; printf("%d\n", solve(n, k, arr, mn)); }
2,100
CPP
#include <bits/stdc++.h> using namespace std; int main() { int t; cin >> t; while (t--) { string str; cin >> str; long long ln = str.length(); long long le = -1, ri = -1; for (long long i = 0; i < ln; ++i) { if (str[i] == '1') { le = i; break; } } for (long long i = ln - 1; i >= 0; i--) { if (str[i] == '1') { ri = i; break; } } if (le == -1 && ri == -1) { cout << 0 << endl; continue; } long long ans = 0; for (long long i = le; i <= ri; ++i) { if (str[i] == '0') ans++; } cout << ans << endl; } return 0; }
800
CPP
#include <bits/stdc++.h> using namespace std; char s[200005], to[128], ch; set<int> p[3]; set<int>::iterator it; int c[3][200005], a, n, q, i; void add(int x, int y, int v) { while (y < 200005) c[x][y] += v, y += (y & (-y)); } int sum(int x, int y) { int ret = 0; while (y) ret += c[x][y], y -= (y & (-y)); return ret; } int F(int x, int y, int z) { if (!p[x].size()) return 0; if (!p[y].size()) return sum(x, n); if (!p[z].size()) return 0; int ret = sum(x, n), f1 = *p[y].begin(), f2 = *p[z].begin(); if (f2 > f1) ret -= sum(x, f2) - sum(x, f1); it = p[y].end(), f1 = *--it; it = p[z].end(), f2 = *--it; if (f1 > f2) ret -= sum(x, f1) - sum(x, f2); return ret; } int cal() { return F(0, 2, 1) + F(1, 0, 2) + F(2, 1, 0); } int main() { scanf("%d%d%s", &n, &q, s + 1); to['R'] = 1; to['S'] = 2; for (i = 1; i <= n; ++i) p[to[s[i]]].insert(i), add(to[s[i]], i, 1); cout << cal() << "\n"; while (q--) { cin >> a >> ch; add(to[s[a]], a, -1); p[to[s[a]]].erase(a); s[a] = ch; add(to[s[a]], a, 1); p[to[s[a]]].insert(a); cout << cal() << "\n"; } }
2,500
CPP
from sys import stdin as cin from itertools import accumulate lmap = lambda f, it: list(map(f, it)) def main(): t = int(next(cin).strip()) for i in range(t): n, x = lmap(int, next(cin).strip().split()) nbrs = 0 for j in range(n-1): u, v = lmap(int, next(cin).strip().split()) if u == x or v == x: nbrs += 1 if nbrs <= 1: print("Ayush") else: print("Ayush" if n % 2 == 0 else "Ashish") main()
1,600
PYTHON3
n,k = [int(x) for x in input().split()] arr = [int(x) for x in input().split()] minimum_score = arr[k-1] count = 0 for i in arr: if i<minimum_score or i==0: break else: count+=1 print(count)
800
PYTHON3
#include <bits/stdc++.h> #pragma comment(linker, "/STACK:256000000") using namespace std; int solve(); int main() { solve(); } const int inf = (int)1e9 + 7; const int dd = (int)2e6 + 7; int cnt[2 * dd], P[dd], S[dd], B[dd], n; string s; int mod, mod2, p = 3; int P1[dd], H[dd]; int P2[dd], H2[dd]; struct MyHash { string S; MyHash(string s, int t, int t2) { S = s; mod = t, mod2 = t; P1[0] = P2[0] = 1; for (int i = 0; i < (int)s.size(); i++) P1[i + 1] = 1ll * P1[i] * p % mod; for (int i = 0; i < (int)s.size(); i++) P2[i + 1] = 1ll * P2[i] * p % mod2; for (int i = 0; i < (int)s.size(); i++) H[i + 1] = (1ll * H[i] * p + get(s[i])) % mod; for (int i = 0; i < (int)s.size(); i++) H2[i + 1] = (1ll * H2[i] * p + get(s[i])) % mod2; } int get(char c) { return c == '(' ? 1 : 2; } int get(int l, int len) { return (H[l + len] + mod - 1ll * H[l] * P1[len] % mod) % mod; } int get2(int l, int len) { return (H2[l + len] + mod - 1ll * H2[l] * P2[len] % mod) % mod; } int check(int i, int j) { int l = 0, r = n; while (r - l > 1) { int m = (l + r) / 2; if (get(i, m) == get(j, m) && get2(i, m) == get2(j, m)) l = m; else r = m; } return S[i + l] < S[j + l]; } }; int solve() { cin >> s; n = (int)s.size(); if (s.find(")") == -1 || s.find("(") == -1) { cout << string(n, '(') + string(n, ')'); return 0; } s += s; MyHash JJ(s, 1e8 + 13, 1e9 + 7); n <<= 1; for (int i = n - 1; i >= 0; i--) { if (s[i] == ')') cnt[i] = 0; else cnt[i] = cnt[i + 1] + 1; } n >>= 1; int pos = -1, c = -1, len = inf, Q; for (int i = 0; i < n; i++) { B[i + 1] = B[i] + (s[i] == '(' ? 1 : -1); P[i + 1] = min(P[i], B[i + 1]); } S[n] = B[n]; for (int i = n - 1; i >= 0; i--) { S[i] = min(S[i + 1], B[i + 1]); } for (int i = 0; i < n; i++) { if ((i ? s[i - 1] : s[n - 1]) == '(' || s[i] == ')') continue; int cur = B[n] - B[i]; int q = min(S[i] - B[i], P[i] + cur); q = min(q, 0); q = -q; int curlen = q + B[n] + q; if (curlen == len ? (cnt[i] + q == c ? JJ.check(i, pos) : cnt[i] + q > c) : curlen < len) { pos = i; c = cnt[i] + q; len = curlen; Q = q; } } string ans = ""; for (int i = 0; i < Q; ++i) ans += '('; for (int i = pos; i < pos + n; ++i) ans += s[i]; for (int i = 0; i < Q + B[n]; ++i) ans += ')'; cout << ans; return 0; }
2,700
CPP
#include <bits/stdc++.h> using namespace std; const int N = 1e3 + 5; struct edge { int y, nxt, z; } e[N * N]; int p[2 * N], deg[2 * N], ans[N * 2], fa[N * 2]; int eid, n, m; char s[N][N]; int getf(int x) { if (fa[x] == x) return x; else return fa[x] = getf(fa[x]); } void merge(int x, int y) { fa[getf(x)] = getf(y); } bool topo() { queue<int> q; int ct = 0, tot = 0; for (int i = 1; i <= n + m; ++i) if (fa[i] == i) { tot++; if (!deg[i]) q.push(i), ans[i] = 1, ct++; } while (q.size()) { int x = q.front(); q.pop(); for (int i = p[x]; ~i; i = e[i].nxt) { int y = e[i].y; ans[y] = max(ans[y], ans[x] + e[i].z); if (--deg[y] == 0) q.push(y), ct++; } } if (ct == tot) return 0; else return 1; } void add(int x, int y, int z) { e[eid] = edge{y, p[x], z}; p[x] = eid++; } int main() { scanf("%d%d", &n, &m); for (int i = 1; i <= n; ++i) scanf("%s", s[i] + 1); for (int i = 1; i <= n + m; ++i) fa[i] = i; for (int i = 1; i <= n; ++i) for (int j = 1; j <= m; ++j) if (s[i][j] == '=') merge(i, j + n); memset(p, -1, sizeof(p)); for (int i = 1; i <= n; ++i) for (int j = 1; j <= m; ++j) if (s[i][j] != '=') { if (getf(i) == getf(j + n)) { puts("No"); return 0; } int x = getf(i), y = getf(j + n); if (s[i][j] == '>') add(y, x, 1), deg[x]++; else add(x, y, 1), deg[y]++; } if (topo()) { puts("No"); return 0; } else { puts("Yes"); for (int i = 1; i <= n; ++i) printf("%d ", ans[getf(i)]); puts(""); for (int i = n + 1; i <= n + m; ++i) printf("%d ", ans[getf(i)]); puts(""); } return 0; }
2,000
CPP
#include <bits/stdc++.h> #pragma comment(linker, "/STACK:500000000") using namespace std; long long K[100009], A[100009]; pair<long long, long long> S[100009]; int main() { int n, i; cin >> n; for (i = 0; i < n; i++) { scanf("%I64d %I64d", &S[i].first, &S[i].second); } sort(S, S + n); for (i = 0; i < n; i++) { A[i] = S[i].second; K[i] = S[i].first; } for (i = 1; i < n; i++) { if (K[i] - K[i - 1] > 20) continue; long long one = 1LL << (2 * (K[i] - K[i - 1])); if ((double)one * A[i] > A[i - 1] || one * A[i] >= A[i - 1]) continue; A[i - 1] -= one * A[i]; A[i] += (A[i - 1] + one - 1) / one; } long long res = K[n - 1] + 1; while (1) { if (res - K[n - 1] > 20) { cout << res << endl; return 0; } long long one = 1LL << (2 * (res - K[n - 1])); if (one >= A[n - 1]) { cout << res << endl; return 0; } res++; } }
1,600
CPP
x,y,m=map(int,input().split()) if x<=0 and y<=0: if m<=max(x,y): print(0) else: print(-1) else: if m<=max(x,y): print(0) exit() if x>y: x,y=y,x op=0 if x<0: ad=(abs(x)+y-1)//y op+=ad x+=y*ad while max(x,y)<m: x,y=max(x,y),x+y op+=1 print(op)
1,600
PYTHON3
#include <bits/stdc++.h> const int N = 1e5 + 5, M = N / 140 + 3; int bel[N], f[N], g[N], tag[M], s[M][140 + 3 << 1]; inline int read() { int now = 0; register char c = getchar(); for (; !isdigit(c); c = getchar()) ; for (; isdigit(c); now = now * 10 + c - 48, c = getchar()) ; return now; } void Update(int p, int v) { int *s = ::s[bel[p]]; for (int i = 140; i <= 140 << 1; ++i) (s[i] += v) >= 998244353 && (s[i] -= 998244353); } void Modify(int p, int v) { int bel = ::bel[p], *s = ::s[bel]; tag[bel] += v; for (int i = bel * 140 + 1; i <= p; ++i) { if (v == 1) (s[g[i] + 140] += 998244353 - f[i - 1]) >= 998244353 && (s[g[i] + 140] -= 998244353); else (s[g[i] - 1 + 140] += f[i - 1]) >= 998244353 && (s[g[i] - 1 + 140] -= 998244353), (s[g[i] - 2 + 140] += f[i - 1]) >= 998244353 && (s[g[i] - 2 + 140] -= 998244353); g[i] += v; } } int Query(int p, int K) { int bel = ::bel[p], sum = tag[bel]; long long res = 0; for (int i = bel * 140 + 1; i <= p; ++i) g[i] <= K && (res += f[i - 1]); while (bel--) { if (std::abs(sum - K) <= 140) res += s[bel][K - sum + 140]; else if (sum < K) res += s[bel][140 << 1]; sum += tag[bel]; } return res % 998244353; } int main() { static int las[N], pre[N]; int n = read(), K = read(); for (int i = 1; i <= n; ++i) bel[i] = (i - 1) / 140; f[0] = 1; for (int i = 1; i <= n; ++i) { int a = read(); las[i] = pre[a], pre[a] = i; Update(i, f[i - 1]), Modify(i, 1); if (las[i]) { Modify(las[i], -2); if (las[las[i]]) Modify(las[las[i]], 1); } f[i] = Query(i, K); } printf("%d\n", f[n]); return 0; }
2,900
CPP
h,l = tuple([int(x) for x in input().split()]) x=(l**2-h**2)/(2*h) print(x)
1,000
PYTHON3
t=int(input()) for _ in range(t): n,k=map(int,input().split()) if k%(n-1)!=0: print((k//(n-1))*n+k%(n-1)) else: print((k//(n-1))*n-1)
1,200
PYTHON3
#209A杨辉三角 n=int(input()) import math if n>1: a=math.factorial(2*n-2)/(math.factorial(n-1)**2) else: a=1 print(int(a))
800
PYTHON3
import sys reader = (s.rstrip() for s in sys.stdin) input = reader.__next__ def gift(): for _ in range(t): ina=int(input()) lst = list(map(int,input().split())) ansp=[lst[0]]+[None]*(ina-1) ansb=[None]*(ina-1)+[lst[ina-1]] dic1={lst[0]:1} dic2={} for i in range(1,ina): front=lst[i] back=lst[ina-i-1] currmaxf=ansp[i-1] currmaxb=ansb[ina-i] ansp[i]=max(front,currmaxf) ansb[ina-i-1]=max(back,currmaxb) freq=dic2.get(lst[i],0) dic2[lst[i]]=freq+1 #print(ansp,ansb) #print(dic1,dic2) len1,len2=len(dic1),len(dic2) ans=[] if ansp[0]==1 and ansb[1]==len2 and ansb[1]==ina-1: #print('kappa',lst) ans.append([1,ina-1]) for i in range(1,ina-1): front=ansp[i] back=ansb[i+1] ele=lst[i] freq1=dic1.get(ele) if freq1: break else: len1+=1 dic1[ele]=1 freq2=dic2.get(ele) dic2[ele]=freq2-1 #print(ele,dic1,dic2,len1,len2,front,back) if freq2==1: len2-=1 if front==i+1 and back==ina-i-1 and front==len1 and back==len2: ans.append([i+1,ina-(i+1)]) yield len(ans) for kap in ans: yield str(kap[0])+" "+str(kap[1]) if __name__ == '__main__': t= int(input()) ans = gift() print(*ans,sep='\n')
1,400
PYTHON3
n = int(input()) num_list = list(map(int, input().split())) # print(num_list) max_ind = num_list.index(max(num_list)) # print(max_ind) num_list.reverse() min_ind = n - 1 - num_list.index(min(num_list)) num_list.reverse() # print(min_ind) swap_num = (n-min_ind-1) + (max_ind) if max_ind > min_ind: print(swap_num-1) else: print(swap_num)
800
PYTHON3
a, b, x, y = map(int, input().split()) import math def reduce_fraction(x,y): k = math.gcd(x,y) return (x // k, y // k) x, y = reduce_fraction(x,y) print(min(a // x, b // y))
1,000
PYTHON3
s=input() if(s.count('0'*7) or s.count('1'*7)):print('YES') else:print('NO')
900
PYTHON3
t = int(input()) for zz in range(t): n = int(input()) a = [int(i) for i in input().split()] a.sort() print(a[n] - a[n-1])
1,000
PYTHON3
#include <bits/stdc++.h> using namespace std; const int INF = 1e9 + 7; const int MAXN = 1e6 + 7; const double EPS = 1e-8; vector<pair<string, string> > res; set<string> all; void move(string s, string t) { res.push_back({s, t}); all.erase(s); all.insert(t); } string randomWord() { string s = "lolkek"; while (all.find(s) != all.end()) { s = ""; for (int i = 0; i < 6; i++) { s += (char)(rand() % 26 + 'a'); } } return s; } string toS(int x) { string s = ""; while (x) { s += (char)(x % 10 + '0'); x /= 10; } reverse(s.begin(), s.end()); return s; } int toI(string s) { int x = 0; if (s[0] == '0') { return 0; } for (char c : s) { if (c < '0' || c > '9') { return 0; } x = 10 * x + c - '0'; } return x; } int main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); srand(time(NULL)); int n; cin >> n; vector<string> a(n); vector<int> type(n, 0); vector<string> bad1, bad2; vector<string> free1, free2; int e = 0; for (int i = 0; i < n; i++) { cin >> a[i] >> type[i]; if (type[i]) { e++; } all.insert(a[i]); } vector<pair<string, int> > bad; for (int i = 0; i < n; i++) { int x = toI(a[i]); if (type[i] == 1) { if (x && x <= n) { if (x > e) { bad1.push_back(a[i]); } } else { bad.push_back({a[i], 1}); } } else if (x && x <= n) { if (x <= e) { bad2.push_back(a[i]); } } else { bad.push_back({a[i], 2}); } } for (int i = 1; i <= n; i++) { string s = toS(i); if (all.find(s) == all.end()) { if (i <= e) { free1.push_back(s); } else { free2.push_back(s); } } } if (!free1.size() && !free2.size() && bad1.size() && bad2.size()) { string s = randomWord(); string t = bad1.back(); bad1.pop_back(); free2.push_back(t); move(t, s); bad.push_back({s, 1}); } while (true) { bool fl = false; while (bad1.size() && free1.size()) { fl = true; string s = bad1.back(); string t = free1.back(); bad1.pop_back(); free1.pop_back(); move(s, t); free2.push_back(s); } while (bad2.size() && free2.size()) { fl = true; string s = bad2.back(); string t = free2.back(); bad2.pop_back(); free2.pop_back(); move(s, t); free1.push_back(s); } if (!fl) { break; } } for (auto p : bad) { int tp = p.second; string s = p.first; if (tp == 1) { move(s, free1.back()); free1.pop_back(); } else { move(s, free2.back()); free2.pop_back(); } } cout << res.size() << "\n"; for (auto p : res) { cout << "move " << p.first << " " << p.second << "\n"; } }
2,200
CPP
input() arr1 = [int(i) for i in input().split()] arr2 = [int(i) for i in input().split()] index1 = 0 counter = 0 for i in arr1: try: if i <= arr2[index1]: counter += 1 index1 += 1 except: break print(counter)
800
PYTHON3
x=input() s=input() count=0 for i in range(len(s)-1): if s[i]!=s[i+1]: count+=1 print(len(s)-count-1)
800
PYTHON3
n = int(input()) if n % 2 == 0: print(int(n/2)) else: v = (n-1)/2 print(int(v-n))
800
PYTHON3
t = int(input()) while t > 0: # n = int(input()) # arr = list(map(int, input().split())) x, y, z = map(int, input().split()) if x != y and y != z and x != z: print("NO") else: if x == y and y == z: print("YES") print(x,y,z) else: l = [x,y,z] l.sort() if l[0] == l[1]: print("NO") else: print("YES") print(l[0], l[0], l[1]) t -= 1
800
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { int n, k, l, c, d, p, nl, np; cin >> n >> k >> l >> c >> d >> p >> nl >> np; int drink = (int)k * l / nl; int lime = c * d; int salt = p / np; int ans = min(min(drink, lime), salt); cout << ans / n << endl; return 0; }
800
CPP
#include <bits/stdc++.h> using namespace std; const int N = 100006; int m; double R, A[N]; void init() { A[0] = 2, A[1] = 2 + sqrt(2.0); for (int i = 2; i < m; i++) A[i] = 2 * (i - 1) + 2 * sqrt(2.0); } int main() { scanf("%d%lf", &m, &R); init(); double ans = 0; for (int i = 0; i < m; i++) { ans += A[i]; } int p1 = 1, p2 = m - 1; double last = ans; for (int i = 1; i < m; i++) { last = last - A[p2] + A[p1]; ans += last; p1++, p2--; } printf("%lf\n", ans / m / m * R); return 0; }
1,900
CPP
from sys import stdin import math N, K = map(int, stdin.readline().split()) pebbles = list(map(int, stdin.readline().split())) print(math.ceil(sum(math.ceil(p / K) for p in pebbles) / 2))
1,100
PYTHON3
#include <bits/stdc++.h> using namespace std; int i, j; const int M = 3e5 + 6; const int MAX = 1e6 + 6; long long arr[M]; long long bit[M]; long long D[MAX]; void add(int idx, long long val, int n) { long long del = val - arr[idx]; for (; idx < n; idx = idx | (idx + 1)) { bit[idx] += del; } } long long sum(int r) { long long ret = 0; for (; r >= 0; r = (r & (r + 1)) - 1) { ret += bit[r]; } return ret; } int main() { ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); ; for (i = 1; i < MAX; i++) { for (j = i; j < MAX; j += i) D[j]++; } int n, m; cin >> n >> m; set<int> ids; for (i = 0; i < n; i++) { cin >> arr[i]; add(i, 2 * arr[i], n); if (arr[i] > 2) ids.insert(i); } while (m--) { int t, l, r; cin >> t >> l >> r; l--, r--; if (t == 2) { cout << sum(r) - sum(l - 1) << "\n"; } else { auto lo = ids.lower_bound(l); auto hi = ids.upper_bound(r); for (auto it = lo; it != hi;) { int id = *it; long long x = D[arr[id]]; add(id, x, n); arr[id] = x; if (x <= 2) it = ids.erase(it); else it++; } } } }
2,000
CPP
# Description of the problem can be found at http://codeforces.com/problemset/problem/804/B MOD = 1e9 + 7 s = input() ans = 0 b = 0 for c in s[::-1]: if c == 'a': ans = (ans + b) % MOD b = (2 * b) % MOD else: b = (b + 1) % MOD print(int(ans))
1,400
PYTHON3
import sys input = sys.stdin.readline ############ ---- Input Functions ---- ############ def inp(): return(int(input())) def inlt(): return(list(map(int,input().split()))) def insr(): s = input() return(list(s[:len(s) - 1]))#might need to remove the -1 def invr(): return(map(int,input().split())) n = inp() s = [1, 5, 10, 20, 100] b = 0 while n != 0: if n<100: for i in range(1, 5): if s[i]>n: b += 1 n -= s[i-1] break else: b += 1 n-= 100 print(b)
800
PYTHON3
a=input() if(a[1::]==a[1::].upper()): print(a.swapcase()) else: print(a)
1,000
PYTHON3
#include <bits/stdc++.h> using namespace std; const int maxn = 1e6 + 7; int a[maxn]; int cnt[maxn]; inline int sqr(int x) { return x * x; } int main() { int t, n; scanf("%d", &t); while (t--) { scanf("%d", &n); for (int i = 1; i <= n; i++) { scanf("%d", &a[i]); cnt[a[i]]++; } int pre = -1; int w = 0, h = 0; for (int i = 1; i <= 10000; i++) { if (cnt[i] == 0) continue; if (cnt[i] >= 4) { w = i; h = i; break; } if (pre != -1 && cnt[i] >= 2) { if (w == 0 || h == 0) { w = pre; h = i; pre = i; continue; } if ((long long)sqr(w + h) * pre * i >= (long long)sqr(pre + i) * w * h) { w = pre; h = i; } } if (cnt[i] >= 2) pre = i; } for (int i = 1; i <= n; i++) cnt[a[i]]--; printf("%d %d %d %d\n", w, w, h, h); } return 0; }
1,600
CPP
n, bx = map(int, input().split()) X = list(map(int, input().split())) m, by = map(int, input().split()) Y = list(map(int, input().split())) def to_10(X, n, bx): ten_base_n = 0 for i in range(len(X)): ten_base_n += X[len(X) - i - 1] * bx ** i return ten_base_n if to_10(X, n, bx) == to_10(Y, m, by): print("=") elif to_10(X, n, bx) > to_10(Y, m, by): print(">") else: print("<")
1,100
PYTHON3
#include <bits/stdc++.h> using namespace std; signed main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); ; long long n, a; cin >> n; vector<pair<long long, long long>> v; for (long long i = 0; i < n; i++) { cin >> a; v.push_back({a, i + 1}); } sort((v).begin(), (v).end()); for (long long i = 0; i < n / 2; i++) cout << v[i].second << " " << v[n - i - 1].second << endl; }
800
CPP
for _ in range(int(input())): n,k=map(int,input().split()) a=[int(x) for x in input().split()] su=0 flip=0 for i in range(0,n-1): if(flip==0): if(a[i+1]<a[i]): su+=a[i] flip=1 else: if(a[i+1]>a[i]): su-=a[i] flip=0 if(flip==0): su+=a[n-1] print(su)
1,300
PYTHON3
##############--->>>>> Deepcoder Amit Kumar Bhuyan <<<<<---############## """ Perfection is achieved not when there is nothing more to add, but rather when there is nothing more to take away. """ from __future__ import division, print_function import os,sys from io import BytesIO, IOBase if sys.version_info[0] < 3: from __builtin__ import xrange as range from future_builtins import ascii, filter, hex, map, oct, zip def ii(): return int(input()) def si(): return input() def mi(): return map(int,input().strip().split(" ")) def msi(): return map(str,input().strip().split(" ")) def li(): return list(mi()) def dmain(): sys.setrecursionlimit(1000000) threading.stack_size(1024000) thread = threading.Thread(target=main) thread.start() #from collections import deque, Counter, OrderedDict,defaultdict #from heapq import nsmallest, nlargest, heapify,heappop ,heappush, heapreplace #from math import log,sqrt,factorial,cos,tan,sin,radians #from bisect import bisect,bisect_left,bisect_right,insort,insort_left,insort_right #from decimal import * #import threading #from itertools import permutations #Copy 2D list m = [x[:] for x in mark] .. Avoid Using Deepcopy import sys input = sys.stdin.readline scanner = lambda: int(input()) string = lambda: input().rstrip() get_list = lambda: list(read()) read = lambda: map(int, input().split()) get_float = lambda: map(float, input().split()) # from bisect import bisect_left as lower_bound; # from bisect import bisect_right as upper_bound; # from math import ceil, factorial; def ceil(x): if x != int(x): x = int(x) + 1 return x def factorial(x, m): val = 1 while x>0: val = (val * x) % m x -= 1 return val def fact(x): val = 1 while x > 0: val *= x x -= 1 return val # swap_array function def swaparr(arr, a,b): temp = arr[a]; arr[a] = arr[b]; arr[b] = temp; ## gcd function def gcd(a,b): if b == 0: return a; return gcd(b, a % b); ## lcm function def lcm(a, b): return (a * b) // math.gcd(a, b) def is_integer(n): return math.ceil(n) == math.floor(n) ## nCr function efficient using Binomial Cofficient def nCr(n, k): if k > n: return 0 if(k > n - k): k = n - k res = 1 for i in range(k): res = res * (n - i) res = res / (i + 1) return int(res) ## upper bound function code -- such that e in a[:i] e < x; ## prime factorization def primefs(n): ## if n == 1 ## calculating primes primes = {} while(n%2 == 0 and n > 0): primes[2] = primes.get(2, 0) + 1 n = n//2 for i in range(3, int(n**0.5)+2, 2): while(n%i == 0 and n > 0): primes[i] = primes.get(i, 0) + 1 n = n//i if n > 2: primes[n] = primes.get(n, 0) + 1 ## prime factoriazation of n is stored in dictionary ## primes and can be accesed. O(sqrt n) return primes ## MODULAR EXPONENTIATION FUNCTION def power(x, y, p): res = 1 x = x % p if (x == 0) : return 0 while (y > 0) : if ((y & 1) == 1) : res = (res * x) % p y = y >> 1 x = (x * x) % p return res ## DISJOINT SET UNINON FUNCTIONS def swap(a,b): temp = a a = b b = temp return a,b; # find function with path compression included (recursive) # def find(x, link): # if link[x] == x: # return x # link[x] = find(link[x], link); # return link[x]; # find function with path compression (ITERATIVE) def find(x, link): p = x; while( p != link[p]): p = link[p]; while( x != p): nex = link[x]; link[x] = p; x = nex; return p; # the union function which makes union(x,y) # of two nodes x and y def union(x, y, link, size): x = find(x, link) y = find(y, link) if size[x] < size[y]: x,y = swap(x,y) if x != y: size[x] += size[y] link[y] = x ## returns an array of boolean if primes or not USING SIEVE OF ERATOSTHANES def sieve(n): prime = [True for i in range(n+1)] prime[0], prime[1] = False, False p = 2 while (p * p <= n): if (prime[p] == True): for i in range(p * p, n+1, p): prime[i] = False p += 1 return prime # Euler's Toitent Function phi def phi(n) : result = n p = 2 while(p * p<= n) : if (n % p == 0) : while (n % p == 0) : n = n // p result = result * (1.0 - (1.0 / (float) (p))) p = p + 1 if (n > 1) : result = result * (1.0 - (1.0 / (float)(n))) return (int)(result) def is_prime(n): if n == 0: return False if n == 1: return True for i in range(2, int(n ** (1 / 2)) + 1): if not n % i: return False return True def next_prime(n, primes): while primes[n] != True: n += 1 return n #### PRIME FACTORIZATION IN O(log n) using Sieve #### MAXN = int(1e5 + 5) def spf_sieve(): spf[1] = 1; for i in range(2, MAXN): spf[i] = i; for i in range(4, MAXN, 2): spf[i] = 2; for i in range(3, ceil(MAXN ** 0.5), 2): if spf[i] == i: for j in range(i*i, MAXN, i): if spf[j] == j: spf[j] = i; ## function for storing smallest prime factors (spf) in the array ################## un-comment below 2 lines when using factorization ################# spf = [0 for i in range(MAXN)] # spf_sieve(); def factoriazation(x): res = [] for i in range(2, int(x ** 0.5) + 1): while x % i == 0: res.append(i) x //= i if x != 1: res.append(x) return res ## this function is useful for multiple queries only, o/w use ## primefs function above. complexity O(log n) def factors(n): res = [] for i in range(1, int(n ** 0.5) + 1): if n % i == 0: res.append(i) res.append(n // i) return list(set(res)) ## taking integer array input def int_array(): return list(map(int, input().strip().split())); def float_array(): return list(map(float, input().strip().split())); ## taking string array input def str_array(): return input().strip().split(); def binary_search(low, high, w, h, n): while low < high: mid = low + (high - low) // 2 # print(low, mid, high) if check(mid, w, h, n): low = mid + 1 else: high = mid return low ## for checking any conditions def check(moves, n): val = (moves + 1) // 2 rem = moves - val sol = (val + 1) * (rem + 1) return sol < n ## for sorting according to second position def sortSecond(val): return val[1] #defining a couple constants MOD = int(1e9)+7; CMOD = 998244353; INF = float('inf'); NINF = -float('inf'); alphs = "abcdefghijklmnopqrstuvwxyz" ################### ---------------- TEMPLATE ENDS HERE ---------------- ################### from itertools import permutations import math import bisect as bis import random import sys import collections as collect import functools as fnt # import numpy as np def solve(): n, m = read() ans = [["B" for x in range(m)] for y in range(n)] for i in range(m - 1): ans[0][i] = "W" for x in ans: for y in x: print(y, end = "") print() # region fastio # template taken from https://github.com/cheran-senthil/PyRival/blob/master/templates/template.py BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in file.mode self.write = self.buffer.write if self.writable else None def read(self): while True: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) if not b: break ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines = 0 return self.buffer.read() def readline(self): while self.newlines == 0: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) self.newlines = b.count(b"\n") + (not b) ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines -= 1 return self.buffer.readline() def flush(self): if self.writable: os.write(self._fd, self.buffer.getvalue()) self.buffer.truncate(0), self.buffer.seek(0) class IOWrapper(IOBase): def __init__(self, file): self.buffer = FastIO(file) self.flush = self.buffer.flush self.writable = self.buffer.writable self.write = lambda s: self.buffer.write(s.encode("ascii")) self.read = lambda: self.buffer.read().decode("ascii") self.readline = lambda: self.buffer.readline().decode("ascii") def print(*args, **kwargs): """Prints the values to a stream, or to sys.stdout by default.""" sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout) at_start = True for x in args: if not at_start: file.write(sep) file.write(str(x)) at_start = False file.write(kwargs.pop("end", "\n")) if kwargs.pop("flush", False): file.flush() if sys.version_info[0] < 3: sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout) else: sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout) input = lambda: sys.stdin.readline().rstrip("\r\n") # endregion if __name__ == "__main__": #read() # sys.stdin = open("input.txt", "r") # sys.stdout = open("output.txt", "w") t = scanner() for i in range(t): solve() #dmain() # Comment Read() # fin_time = datetime.now() # print("Execution time (for loop): ", (fin_time-init_time))
1,000
PYTHON3
q=int(input()) for qq in range(q): n=int(input()) P=list(map(int, input().split())) P.insert(0, 0) root=list(range(n+1)) cnt=list(range(n+1)) for i in range(0, n+1): cnt[i]=1 def getroot(u): if (root[u]==u): return u else: root[u]=getroot(root[u]) return root[u] for i in range(1, n+1): cnt[getroot(i)]=cnt[getroot(i)]+cnt[getroot(P[i])] root[getroot(P[i])]=getroot(i) #print(root) for i in range(1, n+1): print(cnt[getroot(i)]//2, end=" ") print()
1,000
PYTHON3
n = input() up, low = 0, 0 for i in n: if i == i.upper(): up += 1 elif i == i.lower(): low += 1 if up > low: print(n.upper()) else: print(n.lower())
800
PYTHON3
#include <bits/stdc++.h> using namespace std; long long b[500000]; int a[500000]; int main() { long long n; map<int, int> m1, m2; cin >> n; for (long long i = 0; i < n; i++) { long long x; cin >> x; if (x % 2 == 0) m1[x]++; else m2[x]++; } if (m1.size() > m2.size()) { cout << m2.size() << endl; } else if (m1.size() == m2.size()) cout << m1.size() << endl; else { long long p = m2.size() - m1.size(); p = p / 3; p += m1.size(); cout << p << endl; } }
1,500
CPP
import os import sys def oki(s): tm = min(s.count("0"),s.count("1")) if tm %2 == 1: print("DA") else: print("NET") for _ in range(int(input())): s = str(input()) oki(s)
900
PYTHON3
def main(): line = input().rstrip().split() n1 = int(line[0]) n2 = int(line[1]) if n1 > n2: print("First") else: print("Second") main()
800
PYTHON3
k = int(input()) l = int(input()) m = int(input()) n = int(input()) d = int(input()) count = 0 for i in range(1, d + 1): if i % k == 0 \ or i % l == 0 \ or i % m == 0 \ or i % n == 0: count += 1 print(count)
800
PYTHON3
n = int(input()) d = [0, 10, 20, 20, 14] m = n % 4 if m == 0: m = 4 print(d[m] % 5)
1,200
PYTHON3
T = int(input()) import itertools import math for _ in range(T): n = int(input()) nn = int(math.log2(n)) s = input() ans = 0 x = [[0]*(n+1) for _ in range(nn+1)] for i in range(n): r = ord(s[i]) - 97 if r <= nn: x[r][i+1] = 1 for j in range(nn+1): x[j][i+1] += x[j][i] h_list = list(itertools.product([0,1], repeat=nn)) ans = n for ll in h_list: ss = n l,r = 0,n l2,r2 = 0,n aa = 0 for i in range(nn): ss //= 2 if ll[i] == 0: r2 = r r = l + ss l2 = r aa += ss - (x[i][r2] - x[i][l2]) else: l2 = l l = r - ss r2 = l aa += ss - (x[i][r2] - x[i][l2]) aa += 1 - (x[nn][r] - x[nn][l]) ans = min(aa,ans) print(ans)
1,500
PYTHON3
#include <bits/stdc++.h> using namespace std; long long const MOD = 998244353; int const MAXN = 100000; vector<int> grav[MAXN]; int t_in[MAXN]; int t_out[MAXN]; string colors; vector<pair<int, int>> dfs_order[MAXN]; vector<int> cnt[MAXN]; int depth[MAXN]; int parent[MAXN]; int up[MAXN][20]; int _t = 0; int max_d = 0; void dfs(int u, int p = -1, int d = 0) { depth[u] = d; parent[u] = p; t_in[u] = _t++; max_d = max(max_d, d); dfs_order[d].emplace_back(t_in[u], u); for (int v : grav[u]) { dfs(v, u, d + 1); } t_out[u] = _t++; } long long dp[1000000][3]; int main() { ios_base::sync_with_stdio(false); int n; cin >> n; long long a, b; cin >> a >> b; vector<int> v(n); for (int i = 0; i < n; i++) cin >> v[i]; vector<int> ds; auto f = [&ds](int n) { ds.push_back(n); for (int i = 2; i * i <= n; i++) { if (n % i == 0) { ds.push_back(i); while (n % i == 0) n /= i; } } if (n != 1) ds.push_back(n); }; f(v[0]); f(v[0] - 1); f(v[0] + 1); f(v.back()); f(v.back() - 1); f(v.back() + 1); set<int> ds_s(ds.begin(), ds.end()); ds = vector<int>(ds_s.begin(), ds_s.end()); long long res = numeric_limits<long long>::max(); for (int d : ds) { if (d == 1) continue; memset(dp, -1, sizeof(dp)); if (v[0] % d == 0) { dp[0][0] = 0; } else if ((v[0] + 1) % d == 0 || (v[0] - 1) % d == 0) { dp[0][0] = b; } dp[0][1] = a; dp[0][2] = -1; for (int i = 0; i + 1 < n; i++) { int n = v[i + 1]; if (dp[i][0] != -1) { if (n % d == 0) { dp[i + 1][0] = dp[i][0]; } else if ((n + 1) % d == 0 || (n - 1) % d == 0) { dp[i + 1][0] = dp[i][0] + b; } dp[i + 1][1] = dp[i][0] + a; } if (dp[i][1] != -1) { if (dp[i + 1][1] == -1 || dp[i + 1][1] > dp[i][1] + a) { dp[i + 1][1] = dp[i][1] + a; } if (n % d == 0) { dp[i + 1][2] = dp[i][1]; } else if ((n + 1) % d == 0 || (n - 1) % d == 0) { dp[i + 1][2] = dp[i][1] + b; } } if (dp[i][2] != -1) { if (n % d == 0) { if (dp[i + 1][2] == -1 || dp[i + 1][2] > dp[i][2]) { dp[i + 1][2] = dp[i][2]; } } else if ((n + 1) % d == 0 || (n - 1) % d == 0) { if (dp[i + 1][2] == -1 || dp[i + 1][2] > dp[i][2] + b) { dp[i + 1][2] = dp[i][2] + b; } } } } for (int i = 0; i < 3; i++) if (dp[n - 1][i] != -1) res = min(res, dp[n - 1][i]); } cout << res << "\n"; return 0; }
2,300
CPP
#include <bits/stdc++.h> using namespace std; string int2string(int x) { stringstream ss; ss << x; string tmp; ss >> tmp; return tmp; } int string2int(string s) { stringstream ss; ss << s; int x; ss >> x; return x; } long long power(long long a, long long b) { long long res = 1; while (b > 0) { if (b & 1) res = res * a; a = a * a; b >>= 1; } return res; } long long bigpow(long long a, long long b, long long m) { a %= m; long long res = 1; while (b > 0) { if (b & 1) res = res * a % m; a = a * a % m; b >>= 1; } return res; } long long int gcd(long long int a, long long int b) { if (b == 0) return a; else return gcd(b, a % b); } long long int lcm(long long int a, long long int b) { long long int r = a / gcd(a, b) * b; return r; } int main() { cin.tie(NULL); cout.tie(NULL); ios_base::sync_with_stdio(false); int t; cin >> t; while (t--) { int n; cin >> n; int a[2 * n]; for (int i = 0; i < 2 * n; i++) cin >> a[i]; set<int> s; vector<int> v; for (int i = 0; i < 2 * n; i++) { if (s.find(a[i]) == s.end()) { v.push_back(a[i]); s.insert(a[i]); } } for (int i = 0; i < v.size(); i++) cout << v[i] << " "; cout << "\n"; } return 0; }
800
CPP
import math import collections import sys import math def primeFactors(n): l = [] count = 0 while n % 2 == 0: count+=1 n = n // 2 if count > 0: l.append([2, count]) count = 0 for i in range(3, int(math.sqrt(n))+1, 2): while n % i == 0: count+=1 n = n // i if count > 0: l.append([i, count]) count = 0 if n > 2: l.append([n, 1]) return l input = sys.stdin.readline for _ in range(int(input())): n = int(input()) l = primeFactors(n) if len(l) >= 3: print("YES") m1, m2, m3 = 1, 1, 1 m1 = l[0][0]**l[0][1] m2 = l[1][0]**l[1][1] for i in range(2, len(l)): m3*=l[i][0]**l[i][1] print(m1, m2, m3) else: if len(l) == 1: if l[0][1] >= 6: print("YES") print(l[0][0]**1, l[0][0]**2, l[0][0]**(l[0][1]-3)) else: print("NO") else: if l[0][1] + l[1][1] >= 4: print("YES") print(l[0][0], l[1][0], (l[0][0]**(l[0][1]-1))*(l[1][0]**(l[1][1]-1))) else: print("NO")
1,300
PYTHON3
#include <bits/stdc++.h> using namespace std; const int N = 5e5 + 5; const long long L = 1e18 + 18; int Z; struct edge { int s; int t; long long W; int ind; edge(int a, int b, long long c, int I) { s = a; t = b; W = c; ind = I; } }; struct cmp { bool operator()(edge a, edge b) { return a.W > b.W; } }; long long odl[N]; vector<edge> G[N]; vector<pair<long long, long long> > D[N]; void dfs(int v, int oj, int k); int main() { Z = 0; int n, m, k; scanf("%d%d%d", &n, &m, &k); for (long long i = 1; i <= n; i++) odl[i] = L; for (long long i = 1; i <= m; i++) { long long a, b, c; scanf("%lld%lld%lld", &a, &b, &c); G[a].push_back(edge(a, b, c, i)); G[b].push_back(edge(b, a, c, i)); } priority_queue<edge, vector<edge>, cmp> kol; odl[1] = 0; for (auto z : G[1]) kol.push(z); while (!kol.empty()) { edge X = kol.top(); kol.pop(); if (odl[X.t] < L) continue; odl[X.t] = X.W; D[X.s].push_back(make_pair(X.t, X.ind)); for (auto z : G[X.t]) { if (odl[z.t] > X.W + z.W) { kol.push(edge(z.s, z.t, z.W + X.W, z.ind)); } } } k = min(k, n - 1); printf("%d\n", k); dfs(1, 1, k); if (k > 0) printf("\n"); } void dfs(int v, int oj, int k) { for (auto z : D[v]) { if (z.first == oj) continue; if (Z >= k) break; printf("%lld ", z.second); Z++; dfs(z.first, v, k); } }
1,800
CPP
n, h = [int(s) for s in input().split()] width = 0 h_s = [int(s) for s in input().split()] for ele in h_s: if ele>h: width+=2 else: width+=1 print(width)
800
PYTHON3
#include <bits/stdc++.h> using namespace std; const long long N = 100001, h = 25; long long t[2 * N], n, m, d[N], t2[2 * N], d2[N]; long long add(long long a, long long b) { long long ans = a + b; return ans; } void in_build() { for (long long i = n - 1; i > 0; i--) { t[i] = (t[i << 1] + t[i << 1 | 1]); } } void apply(long long p, long long value) { t[p] += value; if (p < n) d[p] += value; } void build(long long p) { while (p > 1) p >>= 1, t[p] = add(t[p << 1], t[p << 1 | 1]) + d[p]; } void push(long long p) { for (long long s = h; s > 0; --s) { long long i = p >> s; if (d[i] != 0) { apply(i << 1, d[i]); apply(i << 1 | 1, d[i]); d[i] = 0; } } } void inc(long long l, long long r, long long value) { l += n, r += n; long long l0 = l, r0 = r; for (; l < r; l >>= 1, r >>= 1) { if (l & 1) apply(l++, value); if (r & 1) apply(--r, value); } build(l0); build(r0 - 1); } long long query(long long l, long long r) { l += n, r += n; push(l); push(r - 1); long long res = 0; for (; l < r; l >>= 1, r >>= 1) { if (l & 1) res = add(res, t[l++]); if (r & 1) res = add(t[--r], res); } return res; } void in_build2() { for (long long i = n - 1; i > 0; i--) t2[i] = add(t2[i << 1], t2[i << 1 | 1]); } void apply2(long long p, long long value) { t2[p] += value; if (p < n) d2[p] += value; } void build2(long long p) { while (p > 1) p >>= 1, t2[p] = add(t2[p << 1], t2[p << 1 | 1]) + d2[p]; } void push2(long long p) { for (long long s = h; s > 0; --s) { long long i = p >> s; if (d2[i] != 0) { apply2(i << 1, d2[i]); apply2(i << 1 | 1, d2[i]); d2[i] = 0; } } } void inc2(long long l, long long r, long long value) { l += n, r += n; long long l0 = l, r0 = r; for (; l < r; l >>= 1, r >>= 1) { if (l & 1) apply2(l++, value); if (r & 1) apply2(--r, value); } build2(l0); build2(r0 - 1); } long long query2(long long l, long long r) { l += n, r += n; push2(l); push2(r - 1); long long res = 0; for (; l < r; l >>= 1, r >>= 1) { if (l & 1) res = add(res, t2[l++]); if (r & 1) res = add(t2[--r], res); } return res; } signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); long long q, gg = 0; cin >> n >> m >> q; memset(t, 0, sizeof(t)); memset(d, 0, sizeof(d)); memset(d2, 0, sizeof(d2)); memset(t2, 0, sizeof(t2)); for (long long i = 0; i < n; i++) { long long x; cin >> x; if (i % 2 == 0) { t[n + gg] = x; } else { t2[n + gg] = x; gg++; } } long long b[m], tmp = 0, k = 0; for (long long i = 0; i < m; i++) cin >> b[i]; for (long long i = 0; i < n; i++) { if (i % 2) tmp += b[i]; else tmp -= b[i]; } if (n % 2) k = 1; vector<long long> v; v.push_back(tmp); for (long long i = n; i < m; i++) { tmp += b[i - n]; tmp *= -1; if (k % 2 == 0) tmp += b[i]; else tmp -= b[i]; v.push_back(tmp); } sort(v.begin(), v.end()); in_build(); in_build2(); long long zz = query(0, n) - query2(0, n); long long lol = 1e18; for (auto it : v) { lol = min(lol, abs(zz + it)); } cout << lol << "\n"; while (q--) { long long l, r, val; cin >> l >> r >> val; if ((r - l + 1) % 2) { if (l % 2) zz += val; else zz -= val; } long long ans = zz, f = 1e18; long long l0 = 0, r0 = v.size() - 1; while (l0 < r0) { long long mid = (l0 + r0) / 2; tmp = ans + v[mid]; f = min(f, abs(tmp)); if ((v[mid] + ans) < 0) l0 = mid + 1; else r0 = mid; } f = min(f, abs(ans + v[l0])); cout << f << "\n"; } return 0; }
2,100
CPP
#include <bits/stdc++.h> using namespace std; const int dim = 52; char a[dim][dim]; int s[dim][dim]; int dp[dim][dim][dim][dim]; void compute(int i1, int j1, int i2, int j2) { if (dp[i1][j1][i2][j2] != 0x3f3f3f3f) return; int ans = max(i2 - i1 + 1, j2 - j1 + 1); if (s[i2][j2] - s[i1 - 1][j2] - s[i2][j1 - 1] + s[i1 - 1][j1 - 1] == 0) { dp[i1][j1][i2][j2] = 0; return; } if (s[i2][j2] - s[i1 - 1][j2] - s[i2][j1 - 1] + s[i1 - 1][j1 - 1] == (i2 - i1 + 1) * (j2 - j1 + 1)) { dp[i1][j1][i2][j2] = ans; return; } for (int i = i1; i < i2; ++i) { compute(i1, j1, i, j2); compute(i + 1, j1, i2, j2); ans = min(ans, dp[i1][j1][i][j2] + dp[i + 1][j1][i2][j2]); } for (int j = j1; j < j2; ++j) { compute(i1, j1, i2, j); compute(i1, j + 1, i2, j2); ans = min(ans, dp[i1][j1][i2][j] + dp[i1][j + 1][i2][j2]); } dp[i1][j1][i2][j2] = ans; } void solve() { int n; cin >> n; for (int i = 1; i <= n; ++i) { cin >> a[i] + 1; for (int j = 1; j <= n; ++j) s[i][j] = s[i - 1][j] + s[i][j - 1] - s[i - 1][j - 1] + (a[i][j] == '#'); } memset(dp, 0x3f, sizeof dp); compute(1, 1, n, n); cout << dp[1][1][n][n]; } int main() { cin.tie(0); ios_base::sync_with_stdio(false); solve(); return 0; }
2,300
CPP
#include <bits/stdc++.h> using namespace std; const int N = 2e5 + 5, P = 998244353; int n, k, m, ans, h[N], fac[N], inv[N]; int qpow(int B, int p) { int R = 1; for (; p; p >>= 1, B = 1LL * B * B % P) if (p & 1) R = 1LL * R * B % P; return R; } inline int C(int i, int j) { return 1LL * fac[i] * inv[j] % P * inv[i - j] % P; } int main() { scanf("%d%d", &n, &k); fac[0] = 1; for (int i = 1; i <= n; ++i) scanf("%d", h + i), fac[i] = 1LL * fac[i - 1] * i % P; h[n + 1] = h[1], inv[n] = qpow(fac[n], P - 2); for (int i = 1; i <= n; ++i) if (h[i] != h[i + 1]) ++m; for (int i = n - 1; ~i; --i) inv[i] = 1LL * inv[i + 1] * (i + 1) % P; for (int i = 0; i <= m >> 1; ++i) ans = (ans + 1LL * C(m, i) * C(m - i, i) % P * qpow(k - 2, m - 2 * i) % P) % P; ans = 1LL * (qpow(k, m) - ans + P) % P * qpow(2, P - 2) % P; printf("%lld\n", 1LL * ans * qpow(k, n - m) % P); return 0; }
2,200
CPP
import sys,bisect input=sys.stdin.readline mod=1 m=3 k=2 L=[] mv=2*(10**5)+1 #mv=15 for i in range(2,mv+1): val=(i*(i-1))//2 L.append(val) T=int(input()) for _ in range(T): n=int(input()) A=list(map(int,input().split())) A.sort() #print(L) ans=0 for i in range(n): mv=A[i] ind=bisect.bisect_right(A,mv+k) v=ind-i-m #print(v,ind,i) if (v>=0): ans=(ans+L[v]) print(ans)
1,500
PYTHON3