solution
stringlengths
10
983k
difficulty
int64
0
25
language
stringclasses
2 values
#include <bits/stdc++.h> using namespace std; int main() { int T; cin >> T; while (T--) { int n, C = 1; cin >> n; int a[n + 1]; set<pair<int, pair<int, int>>> f; f.insert({-n, {1, n}}); while (f.size()) { auto q = (*f.begin()).second; f.erase(f.begin()); int b = q.first, e = q.second, l = e - b + 1, m = (b + e) / 2; if (l <= 0) continue; a[m] = C++; f.insert({-(m - b), {b, m - 1}}); f.insert({-(e - m), {m + 1, e}}); } for (int i = 1; i <= n; ++i) cout << a[i] << " "; cout << endl; } }
10
CPP
#include <bits/stdc++.h> using namespace std; int Gcd(int a, int b) { return b == 0 ? a : Gcd(b, a % b); } int main() { long long ans = 0; int n, m; cin >> n >> m; int gcd = 0; for (int i = 0; i < n; i++) { int num; cin >> num; gcd = Gcd(gcd, num - 1); } while (gcd % 2 == 0) gcd = gcd >> 1; for (int i = 1; i * i <= gcd; i++) { if (!(gcd % i)) { for (int j = i; j < m; j = j << 1) ans += m - j; if (i * i < gcd) for (int j = gcd / i; j < m; j = j << 1) ans += m - j; } } cout << ans << endl; }
11
CPP
def problemA(arr,n): count0 = 0 for i in range(n): if(arr[i]==0): count0 +=1 count1 = n-count0 if(count0>=count1): return n//2,[0]*(n//2) else: if((n//2)%2==0): return n//2,[1]*(n//2) else: return (n//2)+1,[1]*((n//2)+1) if __name__ == '__main__': testCases = input() for i in range(int(testCases)): n = int(input()) arr = list(map(int,input().split(" "))) nans,ans = problemA(arr,n) print(nans) print(" ".join([str(i) for i in ans]))
7
PYTHON3
#include <bits/stdc++.h> long s[100001][2], data[100001]; int main() { long i, n, max = 1; scanf("%ld", &n); for (i = 1; i <= n; i++) scanf("%ld", &data[i]); memset(s, 0, sizeof(s)); s[1][0] = 1; s[1][1] = 1; s[0][0] = 0; s[0][1] = 0; for (i = 2; i <= n; i++) { if (data[i] > data[i - 1]) { s[i][0] = s[i - 1][0] + 1; s[i][1] = s[i - 1][1] + 1; } if (s[i][0] == 0) s[i][0] = 1; if (s[i][1] < 2) s[i][1] = 2; if (data[i] - data[i - 2] > 1) if (s[i - 2][0] + 2 > s[i][1]) s[i][1] = s[i - 2][0] + 2; } for (i = 1; i <= n - 1; i++) { if (s[i][1] > max) max = s[i][1]; if (s[i][0] + 1 > max) max = s[i][0] + 1; } if (s[n][1] > max) max = s[n][1]; printf("%ld", max); return 0; }
7
CPP
#include <bits/stdc++.h> using namespace std; const int N = 100; const double eps = 1e-9; int n, m, d[N], cnt = 0; double k, w, ost = 0, req; vector<pair<int, double> > ans[N]; int main() { cin >> n >> w >> m; k = (double)(n * w) / m; ost = w; for (int i = 0; i < m; i++) { req = k; while (req > eps) { if (abs(ost - req) < eps || ost - req > eps) { ost -= req; ans[i].push_back(make_pair(cnt + 1, req)); req = 0; } else { if (ost > eps) { ans[i].push_back(make_pair(cnt + 1, ost)); req -= ost; } cnt++; ans[i].push_back(make_pair(cnt + 1, min(w, req))); ost = w - min(w, req); req -= min(w, req); } } } for (int i = 0; i < m; i++) for (int j = 0; j < ans[i].size(); j++) d[ans[i][j].first]++; for (int i = 1; i <= n; i++) if (d[i] > 2) { cout << "NO"; return 0; } cout << "YES" << endl; for (int i = 0; i < m; cout << endl, i++) for (int j = 0; j < ans[i].size(); j++) printf("%d %.6lf ", ans[i][j].first, ans[i][j].second); return 0; }
8
CPP
#include <iostream> #include <cstring> using namespace std; long long n,k; char s[105]; long long p[105],cnt=1; long long ans=0; int main() { cin>>s; cin>>k; n=strlen(s); p[1]=1; for(int i=1;i<n;i++) { if(s[i]==s[i-1]) p[cnt]++; else p[++cnt]++; } if(s[0]!=s[n-1]) { for(int i=1;i<=cnt;i++) ans+=k*(p[i]/2); cout<<ans<<endl; } else { if(cnt==1) cout<<k*n/2<<endl; else { for(int i=2;i<cnt;i++) ans+=k*(p[i]/2); ans+=p[1]/2+p[cnt]/2; ans+=(p[1]+p[cnt])/2*(k-1); cout<<ans<<endl; } } return 0; }
0
CPP
#include <bits/stdc++.h> using namespace std; const int mol = 475; int a[30]; int p, x, y; bool check(int xx) { int i = (xx / 50) % mol; for (int j = 1; j <= 25; j++) { i = (i * 96 + 42) % mol; a[j] = 26 + i; if (p == a[j]) return 1; } return 0; } int main() { while (~scanf("%d %d %d", &p, &x, &y)) { int i, Max = 1000000; for (i = 0; i <= 100000; i++) { if (check(x + i * 50)) { Max = min((i + 1) / 2, Max); } } for (i = 0; x - i * 50 >= y; i++) { if (check(x - i * 50)) { Max = 0; } } printf("%d\n", Max); } return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; int n; int dfs(long x=0, int a=0, int b=0, int c=0) { if (x > n) return 0; int res = a*b*c; x *= 10; res += dfs(x+3, 1, b, c); res += dfs(x+5, a, 1, c); res += dfs(x+7, a, b, 1); return res; } int main() { cin >> n; cout << dfs() << endl; }
0
CPP
import sys, os from math import sqrt, gcd, ceil, log, floor from bisect import bisect, bisect_left from collections import defaultdict, Counter, deque from heapq import heapify, heappush, heappop input = sys.stdin.readline read = lambda: list(map(int, input().strip().split())) # read_f = lambda file: list(map(int, file.readline().strip().split())) MOD = 998244353 def main(): # file1 = open("input.txt", "r") # t = int(file1.readline().strip()) for _ in range(int(input())): n = int(input()) a = read(); b = read(); c = read() ans = [a[0]] for i in range(1, n): last = ans[-1] for j in (a[i], b[i], c[i]): if last != j:ans.append(j); break for i in (a[-1], b[-1], c[-1]): if i != ans[-2] and i != ans[0]:ans[-1] = i print(*ans) # file = open("output.txt", "w") # file.write(("").join(ans[:-1])) # # for i in ans: # # file.write(str(i)+"\n") # file.close() if __name__ == "__main__": main()
7
PYTHON3
#include <cstdio> #include <algorithm> using namespace std; typedef long long ll; ll x[1000],y[1000],z[1000],a[1000],ans; int n,m; int main(){ scanf("%d%d",&n,&m); for(int i=0;i<n;i++)scanf("%lld%lld%lld",&x[i],&y[i],&z[i]); ans=0; for(int cas=0;cas<8;cas++){ for(int i=0;i<n;i++){ a[i]=0; a[i]+=cas&1?x[i]:-x[i]; a[i]+=cas&2?y[i]:-y[i]; a[i]+=cas&4?z[i]:-z[i]; } sort(a,a+n); ll mx=0; for(int i=n-m;i<n;i++)mx+=a[i]; ans=max(ans,mx); } printf("%lld\n",ans); }
0
CPP
n=int(input()) s=[] b=[] count=0 for i in range(n): s = input() s = list(map(int, s.split())) b.append(s) for i in range(len(b)): for j in range(len(b)): if(b[i][0]==b[j][1]): count=count+1 print(count)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { int N,d; set<int> mochi; for (cin >> N; N; N--) { cin >> d; mochi.insert(d); } cout << mochi.size(); }
0
CPP
#include <bits/stdc++.h> using namespace std; bool cmp(pair<long long int, char> p1, pair<long long int, char> p2) { return p1.first > p2.first; } long long int mod = 1000000007; int main() { ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); long long int n; cin >> n; long long int p[n + 1], a[n + 2], i, j; for (i = 1; i <= n; i++) { cin >> p[i]; a[i] = 0; } for (i = 1; i <= n; i++) { a[i + 1] = (((2 * a[i] - a[p[i]]) % mod) + mod) % mod + 2; a[i + 1] = a[i + 1] % mod; } cout << a[n + 1] << "\n"; }
10
CPP
#lol temmie = [0,1,1,1,2,1,2,1,5,2,2,1,5,1,2,1,14,1,5,1,5,2,2,1,15,2,2,5,4,1,4,1,51,1,2,1,14,1,2,2,14,1,6,1,4,2,2,1,52,2,5,1,5,1,15,2,13,2,2,1,13,1,2,4,267,1,4,1,5,1,4,1,50,1,2,3,4,1,6,1,52,15,2,1,15,1,2,1,12,1,10,1,4,2] toby = int(input()) print(temmie[toby])
12
PYTHON3
#include <bits/stdc++.h> using namespace std; int t, n, x, y, ans, a[200010][205]; bool ok; vector<int> v[205]; int main() { cin >> t; while (t--) { cin >> n; for (int i = (0); i < (205); i++) v[i].clear(); ans = 0; for (int i = (1); i < (n + 1); i++) { cin >> x; for (int j = (0); j < (205); j++) a[i][j] = a[i - 1][j] + (x - 1 == j); v[x - 1].push_back(i); } for (int i = (0); i < (205); i++) ans = max(ans, (int)v[i].size()); for (int i = (0); i < (205); i++) { for (int j = (0); j < (v[i].size() / 2); j++) { x = v[i][j], y = v[i][v[i].size() - j - 1]; for (int k = (0); k < (205); k++) { if (i == k) continue; ans = max(ans, 2 * (j + 1) + a[y][k] - a[x][k]); } } } cout << ans << '\n'; } return 0; }
8
CPP
st = input() w = int(st) if w>2 : if w%2 == 0 : print("YES") else : print("NO") else : print("NO")
7
PYTHON3
#include<bits/stdc++.h> using namespace std; typedef long long ll; ll mod=1e9+7; vector<ll> tfact(1e7+1,-1); ll n,k; ll mpow(ll x, ll n){ ll ans = 1; while(n != 0){ if(n&1) ans = ans*x % mod; x = x*x % mod; n = n >> 1; } return ans; } ll fact(ll n) { if(tfact[n]<0) { if(n==0) { tfact[n]=1; } else { tfact[n]=fact(n-1)*n%mod; } } return tfact[n]; } ll comb(ll n, ll k) { return fact(n)*mpow(fact(k),mod-2)%mod*mpow(fact(n-k),mod-2)%mod; } int main() { cin >> n >> k; vector<ll> x(n); for(int i=0;i<n;i++) { cin >> x.at(i); } sort(x.rbegin(),x.rend()); ll pans=0; ll mans=0; for(int i=0;i<=n-k;i++) { pans = (pans + x.at(i)*comb(n-1-i,k-1)%mod)%mod; mans = (mod+mans - x.at(n-1-i)*comb(n-1-i,k-1)%mod)%mod; } ll ans =(mod+pans+mans)%mod; cout << ans << endl; }
0
CPP
t = int(input()) for i in range(0,t): t2 = int(input()) position = {} max_x = 0 for x in range(0, t2): x, y = map(int,input().split()) if position.get(x,0) != 0: res_list = position[x] res_list.append(y) position[x] = res_list else: position[x] = [y] max_x = max(max_x, x) movement = "" res_x = 0 res_y = [0] for x in range(0, max_x + 1): res_list2 = position.get(x, 0) if res_list2 != 0: U_num = max(res_list2) - max(res_y) R_num = x - res_x res_x = x movement += 'R' * R_num movement += 'U' * U_num if min(res_list2) < max(res_y): print("NO") break else: res_y = res_list2 else: print('YES') print(movement)
8
PYTHON3
from sys import stdin, stdout n = int(stdin.readline().rstrip()) nameDict = {} for _ in range(n): s = stdin.readline().rstrip().split() name = s[0] if name not in nameDict: nameDict[name]=set() for number in s[2:]: nameDict[name].add(number) for name in nameDict.keys(): rem=set() for no1 in nameDict[name]: for no2 in nameDict[name]: if no1==no2: continue l1 = len(no1) l2 = len(no2) if l1<l2 and no2[-l1:]==no1: rem.add(no1) for no in rem: nameDict[name].remove(no) print(len(nameDict.keys())) for name in nameDict.keys(): print(' '.join([name,str(len(nameDict[name]))]+list(nameDict[name])))
9
PYTHON3
n = int(input()) alh = 'qwertyuiopasdfghjklmnbvcxz' s = input() a = [0] * 28 for i in s: a[alh.index(i)] += 1 k = 0 for i in a: if i > 1: k = 1 if k == 1 or n == 1: print("Yes") else: print("No")
7
PYTHON3
n, a = int(input())+1, 0 d = [0]*n for i in range(1, n): for j in range(i, n, i): d[j] += 1 for i in range(1, n-1): a = (2*a+d[i]) % 998244353 print(a+d[n-1])
8
PYTHON3
#include<bits/stdc++.h> using namespace std; long long mod = 998244353; long long inv[3000009]; long long f[3000009]; long long F[3000009]; long long C(long long m, long long n){ if(n > m || n < 0)return 0; return (f[m]*F[n]%mod)*F[m-n]%mod; } int main(){ long long n,a,b; long long ans = 0; long long k; cin>>n>>a>>b>>k; inv[0] = 1; inv[1] = 1; for(long long i= 2; i <= n; i++) inv[i] = (inv[mod % i])*(mod - mod/i)% mod; f[0] = 1; F[0] = 1; for(long long i = 1; i <= n; i++){ f[i] = f[i-1]*(i)%mod; F[i] = F[i-1]*(inv[i])%mod; } for(long long i = 0;i <= n; i++){ if((k - i*a)%b) continue; long long x= i; long long y = (k-i*a)/b; ans = (ans + C(n,x)*C(n,y))%mod; } cout<<ans<<endl; }
0
CPP
import sys from math import pi, sin, cos input = sys.stdin.readline t = int(input()) for i in range(t): n = 2 * int(input()) R = 1 / (2 * sin(pi / n)) r = R * cos(pi / n) print(2 * r)
9
PYTHON3
#include<iostream> #include <algorithm> using namespace std; int main() { int A[3],B[2]; cin>>A[0]>>A[1]>>A[2]; cin>>B[0]>>B[1]; sort(A,A+3); sort(B,B+2); cout<<A[0]+B[0]-50<<endl; return 0; }
0
CPP
#include <bits/stdc++.h> using namespace std; const int inf = INT_MAX; int main() { int n, m; scanf("%d %d", &n, &m); vector<int> s(n), length(n), t(n), by_s(n), by_t(n), by(n), day(n); for (int i = 0; i < n; ++i) { scanf("%d %d %d", &s[i], &length[i], &t[i]); by_s[i] = by_t[i] = i; } vector<int> f(1 << n, inf); vector<pair<int, int>> from(1 << n); f[0] = 1; sort(by_s.begin(), by_s.end(), [&](const int &x, const int &y) { return s[x] < s[y]; }); sort(by_t.begin(), by_t.end(), [&](const int &x, const int &y) { return t[x] < t[y]; }); for (int i = 0; i < 1 << n; ++i) { if (f[i] != inf) { int pointer = 0, value = f[i]; for (auto j : by_t) { if (!(i >> j & 1)) { while (pointer < n && value + t[j] >= s[by_s[pointer]]) { int p = by_s[pointer++]; if ((i >> p & 1) || value >= s[p]) { value = max(value, s[p] + length[p]); } } if (value + t[j] < s[j] && f[i | 1 << j] > value + t[j]) { f[i | 1 << j] = value + t[j]; from[i | 1 << j] = make_pair(j, value); } } } } } function<void(int, int)> rec = [&](int x, int type) { if (!x) { return; } int i = from[x].first; by[i] = type; day[i] = from[x].second; rec(x ^ 1 << i, type); }; if (m == 1) { if (f[(1 << n) - 1] != inf) { puts("YES"); rec((1 << n) - 1, 1); for (int i = 0; i < n; ++i) { printf("%d %d\n", by[i], day[i]); } } else { puts("NO"); } } else { int p = -1; for (int i = 0; i < (1 << n); ++i) { if (f[i] != inf && f[(1 << n) - 1 ^ i] != inf) { p = i; break; } } if (!~p) { puts("NO"); } else { puts("YES"); rec(p, 1); rec((1 << n) - 1 ^ p, 2); for (int i = 0; i < n; ++i) { printf("%d %d\n", by[i], day[i]); } } } return 0; }
12
CPP
def main(): mod = 10**9+7 fact = [1, 1] for i in range(2, 200000): fact.append(fact[-1]*i % mod) n = int(input()) ab = [list(map(int, input().split())) for _ in [0]*(n-1)] g = [[] for _ in [0]*n] [g[a-1].append(b-1) for a, b in ab] [g[b-1].append(a-1) for a, b in ab] g2 = [set(i) for i in g] child = [1]*n # 子の数 q = [-1, 0] while len(q) > 1: # DFS i = q[-1] if g2[i]: j = g2[i].pop() g2[j].remove(i) q.append(j) else: q.pop() if len(q) > 1: child[q[-1]] += child[i] rank = [(j, i) for i, j in enumerate(child)] rank = [j for i, j in sorted(rank)] dp = [1]*n for i in rank: c = child[i] ans = fact[c-1] temp = 1 for j in g[i]: if child[j] < c: ans = ans*dp[j] % mod temp = temp*fact[child[j]] % mod dp[i] = ans*pow(temp, mod-2, mod) % mod dp2 = [0]*n dp2[0] = dp[0] g2 = [set(i) for i in g] q = [-1, 0] while len(q) > 1: # DFS i = q[-1] if g2[i]: j = g2[i].pop() c = child[j] temp = fact[n-c]*fact[c-1] dp2[j] = dp2[i]*(fact[c]*fact[n-c-1])*pow(temp, mod-2, mod) % mod g2[j].remove(i) q.append(j) else: q.pop() if len(q) > 1: child[q[-1]] += child[i] for i in dp2: print(i) main()
0
PYTHON3
n = int(input()) A = list(map(int, input().split())) B = list(map(int, input().split())) m1 = -1 m2 = -1 for i in B: if i > m1: m2 = m1 m1 = i elif i > m2: m2 = i if sum(A) <= m1 + m2: print("YES") else: print("NO")
7
PYTHON3
n,m=map(int,input().split()) s=[list(map(int,input().split())) for i in range(n)] sign=[-1,1] ans=0 for i in sign: for j in sign: for k in sign: lis=[0]*n for l in range(n): lis[l]=i*s[l][0]+j*s[l][1]+k*s[l][2] lis.sort(reverse=True) a=sum(lis[:m]) ans=max(ans,a) print(ans)
0
PYTHON3
import sys try: sys.stdin = open('input.txt', 'r') sys.stdout = open('output.txt', 'w') except: pass input = sys.stdin.readline for tt in range(int(input())): m,n = map(int,input().split()) if n==2 and m==2: print("YES") elif n==1 or m==1: print("YES") else: print("NO")
7
PYTHON3
#include <bits/stdc++.h> using namespace std; const int MAXN = 1e5 + 10, LOGN = 20; const long long INF = 1e18; vector<pair<int, int> > G[MAXN]; struct UnionFind { vector<int> f; void init(int n) { f.clear(); f.insert(f.begin(), n, -1); } int comp(int x) { return f[x] == -1 ? x : f[x] = comp(f[x]); } bool join(int i, int j) { bool con = comp(i) == comp(j); if (!con) f[comp(i)] = comp(j); return con; } } uf; int N, f[MAXN][LOGN], L[MAXN]; long long C[MAXN]; void dfs(int v, int fa = -1, long long c = 0, int lvl = 0) { f[v][0] = fa, L[v] = lvl, C[v] = c; for (auto e : G[v]) { int u = e.first, cc = e.second; if (u != fa) dfs(u, v, c + cc, lvl + 1); } } void build() { for (int k = int(0); k < int(LOGN - 1); k++) for (int i = int(0); i < int(N); i++) if (f[i][k] != -1) f[i][k + 1] = f[f[i][k]][k]; } int climb(int a, int d) { if (!d) return a; for (int i = int((31 - __builtin_clz(L[a])) + 1 - 1); i >= int(0); i--) if (1 << i <= d) a = f[a][i], d -= 1 << i; return a; } int lca(int a, int b) { if (L[a] < L[b]) swap(a, b); a = climb(a, L[a] - L[b]); if (a == b) return a; for (int i = int((31 - __builtin_clz(L[a])) + 1 - 1); i >= int(0); i--) if (f[a][i] != f[b][i]) a = f[a][i], b = f[b][i]; return f[a][0]; } long long dist(int a, int b) { return C[a] + C[b] - 2 * C[lca(a, b)]; } const int MAXE = 50; int ha[MAXN], cnt = 1; long long distG[MAXE][MAXE], distAG[MAXN][MAXE]; int deha[MAXE]; inline void go(int u) { if (ha[u] == 0) { ha[u] = cnt; deha[cnt] = u; cnt++; } } int main() { ios_base::sync_with_stdio(0); cin.tie(0); fill(distG[0], distG[MAXE], INF); int m; cin >> N >> m; uf.init(N); for (int _ = int(0); _ < int(m); _++) { int u, v; long long d; cin >> u >> v >> d; u--; v--; if (uf.comp(u) != uf.comp(v)) { uf.join(u, v); G[u].emplace_back(v, d); G[v].emplace_back(u, d); } else { go(u); go(v); int nu = ha[u], nv = ha[v]; distG[nu][nv] = distG[nv][nu] = min(distG[nu][nv], d); } } dfs(0); build(); for (int i = int(1); i < int(cnt); i++) for (int j = int(1); j < int(cnt); j++) distG[i][j] = min(distG[i][j], dist(deha[i], deha[j])); for (int k = int(1); k < int(cnt); k++) for (int i = int(1); i < int(cnt); i++) for (int j = int(1); j < int(cnt); j++) distG[i][j] = min(distG[i][j], distG[i][k] + distG[k][j]); for (int i = int(0); i < int(N); i++) for (int j = int(1); j < int(cnt); j++) distAG[i][j] = dist(i, deha[j]); int q; cin >> q; while (q--) { int u, v; cin >> u >> v; u--; v--; long long ans = dist(u, v); for (int i = int(1); i < int(cnt); i++) for (int j = int(1); j < int(cnt); j++) { ans = min(ans, distAG[u][i] + distAG[v][j] + distG[i][j]); } cout << ans << '\n'; } return 0; }
12
CPP
#include <bits/stdc++.h> using namespace std; int ri() { int x; if (scanf(" %d", &x) == EOF) return -1; return x; } long long int rl() { long long int x; if (cin >> x) return x; return -1; } string rs() { string s; if (cin >> s) return s; return ""; } const long long int mod = 998244353; struct SingleCase { int n, k; vector<int> B; bool solveCase() { n = ri(); if (n < 0) return false; k = ri(); map<int, int> A; for (int i = 0; i < n; ++i) A[ri()] = i; for (int i = 0; i < k; ++i) B.push_back(A[ri()]); long long int ret = solve(); cout << ret << endl; return true; } long long int solve() { long long int ret = 1; set<int> S; for (int i = 0; i < n; ++i) S.insert(i); set<int> T; for (auto x : B) T.insert(x); for (auto x : B) { auto it = S.find(x); long long int y = lower(S, it); long long int z = upper(S, it); int yGood = (y >= 0) && !T.count(y); int zGood = (z >= 0) && !T.count(z); int choices = yGood + zGood; if (choices == 0) return 0; ret = ret * choices % mod; if (yGood) { S.erase(y); } else if (zGood) { S.erase(z); } T.erase(x); } return ret; } int lower(const set<int>& S, set<int>::iterator it) { if (it != S.begin()) return *(--it); return -1; } int upper(const set<int>& S, set<int>::iterator it) { if (++it != S.end()) return *it; return -1; } }; int main() { int cases = ri(); while (SingleCase().solveCase()) { }; return 0; }
8
CPP
#include<bits/stdc++.h> #define fi first #define se second #define pb push_back #define pf push_front #define popb pop_back #define popf pop_front #define ins insert #define pq priority_queue #define minele min_element #define maxele max_element #define lb lower_bound //first pos >= val #define ub upper_bound // first pos > val #define cnt_bit __builtin_popcount #define debug(...) " [" << #__VA_ARGS__ ": " << (__VA_ARGS__) << "] " //#pragma GCC optimize("Ofast") //#pragma GCC target("avx,avx2,fma") using namespace std; typedef long long ll; typedef pair<ll, ll> pll; typedef pair<int, int> pii; int d4x[4] = {1, 0, -1, 0}; int d4y[4] = {0, 1, 0, -1}; int d8x[8] = {0, 1, 1, 1, 0, -1, -1, -1}; int d8y[8] = {1, 1, 0, -1, -1, -1, 0, 1}; const ll oo = 1e18; const ll maxN = 1e6; /* Author : Le Ngoc Bao Anh, 10A5, LQD High School for Gifted Student */ void maximize(int &a, int b) { a = max(a, b); } void minimize(int &a, int b) { a = min(a, b); } struct Data { ll r, c; } a[maxN]; void solve() { int n; ll ans = 0; cin >> n; for(int i = 1; i <= n; i++) cin >> a[i].r; for(int i = 1; i <= n; i++) cin >> a[i].c; sort(a + 1, a + 1 + n, [&](Data a_, Data b_) {return a_.r < b_.r;}); int r = 1, c = 1; for(int i = 1; i <= n; i++) { ll needr = a[i].r - r, needc = a[i].c - c; //needr >= needc if(!needr && !needc) continue; //after 1 move, r always increase, r + c is always odd if((r + c) % 2 == 0) { if(needr == needc) { ans += needr; r = a[i].r, c = a[i].c; continue; } r++; needr--; ans += (needr - needc + 1) / 2; } else { ans += (needr - needc + 1) / 2; } r = a[i].r, c = a[i].c; } cout << ans << endl; } /* 6 3 4 7 10 11 12 3 4 6 9 9 10 */ int main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); //freopen("input.inp", "r", stdin); ll tc, ddd = 0; cin >> tc; while(tc--) { //ddd++; //cout << "Case #" << ddd << ": "; solve(); } }
12
CPP
s=input() t=input() c=0 for i in range(min(len(s),len(t))): if s[-1-i]==t[-1-i]: c+=1 else: break print(len(s)+len(t)-2*c)
8
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { vector<pair<int, int>> v; vector<int> vec; int n, x, y; cin >> n; for (int i = 0; i < n; i++) { cin >> x >> y; v.push_back(pair<int, int>(x, y)); } int count = 1; int p = v[0].second, k = v[0].first; for (int i = 1; i < v.size(); i++) { if (p == v[i].second && k == v[i].first) count++; else { p = v[i].second; k = v[i].first; count = 1; } vec.push_back(count); } sort(vec.begin(), vec.end()); if (vec.size() == 0) { cout << count << endl; } else cout << vec[vec.size() - 1] << endl; }
7
CPP
#include <bits/stdc++.h> using namespace std; #define rep(i,n) for (int i = 0; i < (int)(n); ++i) #define rep2(i, s, n) for (int i = (s); i < (int)(n); i++) int main() { int w,h; cin >> w>>h; vector<vector<int>>pq(w+h,vector<int>(2)); vector<int>p(w); rep(i,w){ cin>>p.at(i); pq.at(i).at(0)=p.at(i); pq.at(i).at(1)=1; } vector<int>q(h); rep(i,h){ cin>>q.at(i); pq.at(i+w).at(0)=q.at(i); pq.at(i+w).at(1)=2; } sort(pq.begin(),pq.end()); long ans=0; long a=w+1; long b=h+1; rep(i,w+h){ if(pq.at(i).at(1)==1){ ans+=pq.at(i).at(0)*b; a--; } else{ ans+=pq.at(i).at(0)*a; b--; } } cout<<ans<<endl; }
0
CPP
a = int(input()) for _ in range(a): x =int(input()) li = [1]*x print(*li)
7
PYTHON3
#include <bits/stdc++.h> int gcd(int a, int b) { return b == 0 ? a : gcd(b, a % b); } int lcm(int a, int b) { return ((a * b) / gcd(a, b)); } bool isPrime(long long n) { if (n <= 1) return 0; if (n <= 3) return 1; if (n % 2 == 0) return 0; else { for (long long i = 5; i * i <= n; i += 2) { if (n % i == 0) return 0; } return 1; } } template <class T> inline T bigmod(T p, T e, T M) { long long ret = 1; for (; e > 0; e >>= 1) { if (e & 1) ret = (ret * p) % M; p = (p * p) % M; } return (T)ret; } template <class T> inline T gcd(T a, T b) { if (b == 0) return a; return gcd(b, a % b); } template <class T> inline T modinverse(T a, T M) { return bigmod(a, M - 2, M); } using namespace std; long long a[200005], sum = 0; long long num[100]; map<long long, long long> ss; int main() { long long i, j, k, l, m, n, r; cin >> n >> l >> r; if (n == 0) { cout << 0; return 0; } if (n == 1) { cout << 1; return 0; } long long fl = 0; long long x = n; long long c = 1; vector<long long> arr; while (x != 1) { if (x % 2 == 0) { arr.push_back(c); } x /= 2; c++; } for (auto it : arr) { it = c - it; num[it] = 1; } x = 1; long long countt = 0; for (j = l; j <= r; j++) { x = 1; long long fl = 0; for (i = 1; i <= 51; i++) { x *= 2; if (j % x == 0) { if (num[i] != 1) fl = 0; else fl = 1; } } if (fl == 0) countt++; } cout << countt; }
8
CPP
#include <bits/stdc++.h> using namespace std; int a[100005], n, s, l, range[100005]; struct node { int ans; } tree[4 * 100005]; node merge(node l, node r) { node res; res.ans = min(l.ans, r.ans); return res; } void build(int v, int start, int end) { if (start == end) tree[v].ans = 1e9; else { int mid = (start + end) >> 1; build(2 * v, start, mid); build(2 * v + 1, mid + 1, end); tree[v] = merge(tree[2 * v], tree[2 * v + 1]); } } node query(int v, int start, int end, int l, int r) { if (r < 0 or r < l) return tree[4 * 100004]; if (l == start and r == end) return tree[v]; int mid = (start + end) >> 1; if (r <= mid) return query(2 * v, start, mid, l, r); if (l > mid) return query(2 * v + 1, mid + 1, end, l, r); return merge(query(2 * v, start, mid, l, mid), query(2 * v + 1, mid + 1, end, mid + 1, r)); } void update(int v, int start, int end, int idx, int val) { if (start > idx or end < idx) return; if (start == end) { tree[v].ans = val; return; } int mid = (start + end) >> 1; update(2 * v, start, mid, idx, val); update(2 * v + 1, mid + 1, end, idx, val); tree[v] = merge(tree[2 * v], tree[2 * v + 1]); } multiset<int> bag; bool check() { int x = *bag.begin(); int y = *bag.rbegin(); return (y - x <= s); } int main() { scanf("%d", &n); scanf("%d", &s); scanf("%d", &l); tree[0].ans = 0, tree[4 * 100004].ans = 1e9; build(1, 1, n); int L = 1; for (int(i) = (1); (i) <= (n); (i)++) { scanf("%d", &a[i]); bag.insert(a[i]); while (!check()) { bag.erase(bag.find(a[L])); L += 1; } if (i - L + 1 >= l) range[i] = i - L + 1; else range[i] = 0; } for (int(i) = (1); (i) <= (n); (i)++) { int val; if (range[i] == i) update(1, 1, n, i, 1); else val = query(1, 1, n, i - range[i], i - l).ans + 1, update(1, 1, n, i, val); } int ret = query(1, 1, n, n, n).ans; if (ret > n) printf("%d\n", -1); else printf("%d\n", ret); return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; int main() { set<int> s; int t; for(int i=0;i<6;i++) { cin>>t; if(!s.count(t)) s.insert(t); else s.erase(t); } if(s.size()==0 || s.size()==2) cout<<"YES\n"; else cout<<"NO\n"; return 0; }
0
CPP
# from sys import stdout from bisect import bisect_left as bs from math import log as lg log = lambda *x: print(*x) def cin(*fn, def_fn=str): i,r = 0,[] if fn: def_fn=fn[0] for c in input().split(' '): r+=[(fn[i] if len(fn)>i else def_fn) (c)] i+=1 return r n, = cin(int) mx,u = 1,{'polycarp': 1} for i in range(n): n1,r,n2 = cin(str) n1,n2 = n1.lower(),n2.lower() u[n1] = 1+u[n2] mx = max(u[n1], mx) log(mx)
7
PYTHON3
a=int(input()) for i in range(a): b=input() d=[] c=len(b) if(c==2): print(b) else: k=0 for j in range(0,c): if(k==0): d.append(b[j]) k=1 else: k=0 d.append(b[c-1]) print("".join(d))
7
PYTHON3
import math x1 = int(input()) for i in range(x1): n = int(input()) m=0 c =(math.sqrt(n)) d=int((math.sqrt(n))) if n==1: print(0) elif n==2: print(1) elif n==3 or n==4: print(2) elif c-d>0.5: print(d*2) elif (c-d)==0: print(d*2-2) else: print(d*2-1)
9
PYTHON3
#include <bits/stdc++.h> using namespace std; const int N = 2e6 + 5; int Case; namespace G { int n, m; int hed[N], to[N], nxt[N], cnt; int deg[N], u[N], v[N], d[N], vis[N], par[N], del[N]; bool vis2[N]; inline void adde(int u, int v) { del[cnt + 1] = 0; ++cnt; to[cnt] = v, nxt[cnt] = hed[u]; hed[u] = cnt; } inline void read() { cnt = 1; cin >> n >> m; for (int i = 1; i <= m; i++) { scanf("%d%d", &u[i], &v[i]); deg[u[i]]++, deg[v[i]]++; } } inline void output(vector<int> del) { vector<bool> ans(n + 1, 0); if ((int)del.size() == n) { puts("No"); } else { puts("Yes"); printf("%d\n", n - (int)del.size()); for (size_t i = 0; i < del.size(); i++) ans[del[i]] = 1; for (int i = 1; i <= n; i++) { if (!ans[i]) printf("%d ", i); } puts(""); } } vector<int> ret; int rt, Rt[N], dep[N]; inline void dfs(int x, int pre) { dep[x] = dep[pre] + 1; Rt[x] = rt; par[x] = pre; vis[x] = 1; int T = 0; for (int i = hed[x]; i; i = nxt[i]) { int v = to[i]; if (v == pre) continue; if (vis[v]) { if (dep[v] < dep[x]) { if (!ret.size()) { if (!T) T = v; else if (dep[v] > dep[T]) T = v; } } } } if (T) { int cur = x; ret.push_back(cur); while (cur != T) { cur = par[cur]; ret.push_back(cur); } } for (int i = hed[x]; i; i = nxt[i]) { int v = to[i]; if (!vis[v]) { dfs(v, x); } } } vector<int> getpath(int x, int y) { bool tag = 0; if (dep[x] < dep[y]) swap(x, y), tag = 1; vector<int> a, b; while (dep[x] > dep[y]) { a.push_back(x); x = par[x]; } while (x != y) { a.push_back(x), b.push_back(y); x = par[x], y = par[y]; } a.push_back(x); reverse(b.begin(), b.end()); for (size_t i = 0; i < b.size(); i++) a.push_back(b[i]); if (tag) reverse(a.begin(), a.end()); return a; } bool sx[N], sy[N]; void Answer(int x, vector<int> path, int y) { for (int i = 1; i <= n; i++) sx[i] = sy[i] = 0; for (int i = 1; i <= m; i++) { if (u[i] == x) sx[v[i]] = 1; if (u[i] == y) sy[v[i]] = 1; } for (int i = 0; i < (int)path.size(); i++) if (sy[path[i]]) { path.resize(i + 1); break; } vector<int> s; for (int i = (int)path.size() - 1; ~i; i--) { s.push_back(path[i]); if (sx[path[i]]) break; } s.push_back(x), s.push_back(y); output(s); } vector<pair<int, int> > s[N]; vector<int> RRR; int delnode[N]; inline int DF(int x, int pre) { if (sx[x]) { RRR.push_back(x); return x; } int T = 0; for (int i = hed[x]; i; i = nxt[i]) if (to[i] != pre && !delnode[to[i]]) { int ret = DF(to[i], x); if (ret > 0) { T = 1; break; } } if (T) RRR.push_back(x); return T; } void Sol(int nd1, int cnt0) { for (int i = 1; i <= n; i++) sx[i] = 0; for (int i = 1; i <= m; i++) if (u[i] == cnt0) sx[v[i]] = 1; RRR.push_back(nd1); int R = 2; if (sx[nd1]) R--; for (int i = hed[nd1]; i; i = nxt[i]) { int v = to[i]; if (DF(v, nd1)) R--; if (!R) break; } } inline void solve() { int BLOCKS = 0; for (int i = 1; i <= n; i++) { if (deg[i] % 3 == 0) { output(vector<int>(1, i)); return; } } for (int i = 1; i <= m; i++) { if (deg[u[i]] % 3 == 1 && deg[v[i]] % 3 == 1) { vector<int> r(2, 0); r[0] = u[i], r[1] = v[i]; output(r); return; } if (deg[u[i]] % 3 == 2 && deg[v[i]] % 3 == 2) { adde(u[i], v[i]), adde(v[i], u[i]); d[u[i]]++, d[v[i]]++; } } ret.clear(); for (int i = 1; i <= n; i++) if (deg[i] % 3 == 2 && !vis[i]) { BLOCKS++; rt = i; dfs(i, 0); } if (ret.size()) { output(ret); return; } vector<int> cnt1; for (int i = 1; i <= n; i++) if (deg[i] % 3 == 1) cnt1.push_back(i); if ((int)cnt1.size() > 1) { for (int i = 1; i <= m; i++) { if (deg[u[i]] % 3 == 2 && deg[v[i]] % 3 == 1) swap(u[i], v[i]); if (deg[u[i]] % 3 == 1 && deg[v[i]] % 3 == 2) { int r = Rt[v[i]]; s[r].push_back(pair<int, int>(u[i], v[i])); } } for (int i = 1; i <= n; i++) if (s[i].size()) { sort(s[i].begin(), s[i].end()); for (int j = 1; j < (int)s[i].size(); j++) { if (s[i][j].first != s[i][j - 1].first) { vector<int> ret = getpath(s[i][j].second, s[i][j - 1].second); Answer(s[i][j].first, ret, s[i][j - 1].first); return; } } } } else { RRR.clear(); for (int i = 1; i <= m; i++) if (deg[u[i]] % 3 == 2 && deg[v[i]] % 3 == 1) swap(u[i], v[i]); for (int i = 1; i <= n; i++) sx[i] = 0, delnode[i] = 0, vis2[i] = 0; for (int i = 1; i <= m; i++) if (u[i] == cnt1[0]) sx[v[i]] = 1; RRR.push_back(cnt1[0]); for (int i = 1; i <= n; i++) vis2[i] = 0; int T = 2; for (int i = 1; i <= n; i++) if (deg[i] % 3 == 2) { if (!vis2[Rt[i]]) { vis2[Rt[i]] = 1, Sol(i, cnt1[0]), T--; } if (T == 0) { break; } } output(RRR); return; } } void clear() { for (int i = 1; i <= n; i++) dep[i] = Rt[i] = par[i] = vis[i] = hed[i] = 0, d[i] = deg[i] = 0; cnt = 1; for (int i = 1; i <= n; i++) s[i].clear(); } } // namespace G int main() { int T; cin >> T; while (T--) { Case++; G::read(); G::solve(); G::clear(); } }
12
CPP
#include <bits/stdc++.h> using namespace std; int main() { long long n, k, s; cin >> n >> k >> s; long long num = s / k; long long oneplus = s % k; if (num >= n || k > s) { cout << "NO" << endl; return 0; } else if (oneplus != 0 && (num + 1) >= n) { cout << "NO" << endl; return 0; } long long prev = 1; cout << "YES" << endl; for (int i = 1; i <= oneplus; i++) { if ((prev + num + 1) > n) prev = prev - (num + 1); else prev = prev + (num + 1); cout << prev << " "; } k -= oneplus; for (int i = 1; i <= k; i++) { if ((prev + num) > n) prev = prev - num; else prev = prev + num; cout << prev << " "; } return 0; }
10
CPP
#http://codeforces.com/contest/601/problem/A import sys from collections import deque n, m = map(int, input().split()) g = set() for i in range(m): x, y = map(int, input().split()) x -= 1 y -= 1 g |= {(x, y), (y, x)} cut = (0, n-1) in g q = deque() q.append(0) d = [-1] * n d[0] = 0 while len(q): x = q.popleft() for y in range(n): if cut ^ ((x, y) in g) and (d[y] == -1 or d[y] > d[x] + 1): d[y] = d[x] + 1 q.append(y) print(d[n-1])
7
PYTHON3
for _ in range(int(input())): n=int(input()) a=[int(i) for i in input().split()] ans=0 summ=0 for i in range(n): ans^=a[i] summ+=a[i] summ+=ans print(2) print(ans,summ)
9
PYTHON3
#include <stdio.h> int main() { int n,a,max,min; max = (-999999999); scanf("%d", &n); scanf("%d", &min); for (int i = 0; i < n-1; i++){ scanf("%d", &a); max = max >= a-min ? max : a-min; min = min <= a ? min : a; } printf("%d\n", max); }
0
CPP
n=int(input()) a=input().split() z={} ans=['A']*n for x in a: if x in z.keys(): z[x]+=1 else: z[x]=1 kb,ka=0,0 for i,x in enumerate(a): if z[x]==1: if ka>kb: kb+=1 ans[i]='B' else: ka+=1 ans[i]='A' if ka>kb: for i,x in enumerate(a): if z[x]>2: ans[i]='B' kb+=1 break if ka==kb: print("YES") print(''.join(ans)) else: print("NO")
9
PYTHON3
n, m = map(int, input().split(" ")) points = [] pointOfBoundary = [] for i in range(n): l, r = map(int, input().split(" ")) for j in range(l, r + 1): points.append(j) for i in range(1, m + 1): if i not in points: pointOfBoundary.append(i) length = len(pointOfBoundary) print(length) if length != 0: if length == 1: print(pointOfBoundary[0]) else: for i in range(0, length - 1): print(pointOfBoundary[i], end = ' ') print(pointOfBoundary[-1])
7
PYTHON3
#include <bits/stdc++.h> #pragma GCC Optimize("Ofast"); using namespace std; int main(int argc, char const *argv[]) { ios_base::sync_with_stdio(false); cin.tie(NULL); cerr.tie(NULL); cout.tie(NULL); ; int tests = 1; while (tests--) { int N; cin >> N; vector<int> arr(N); for (auto &it : arr) cin >> it; long long sum = 0; for (int i = 0; i < N; ++i) sum += arr[i]; if (sum % 3) { cout << 0 << "\n"; } else { sum /= 3; long long suffixSum = 0; vector<int> count(N, 0); for (int i = N - 1; i >= 0; --i) { suffixSum += arr[i]; if (suffixSum == sum) count[i] = 1; } for (int i = N - 2; i >= 0; --i) { count[i] += count[i + 1]; } suffixSum = 0; long long ans = 0; for (int i = 0; i < N - 2; ++i) { suffixSum += arr[i]; if (suffixSum == sum) ans += count[i + 2]; } cout << ans << "\n"; } } return 0; }
9
CPP
#include <bits/stdc++.h> using namespace std; template <typename T> inline T qmin(const T &a, const T &b) { return a < b ? a : b; } template <typename T> inline T qmax(const T &a, const T &b) { return a > b ? a : b; } template <typename T> inline void getmin(T &a, const T &b) { if (a > b) a = b; } template <typename T> inline void getmax(T &a, const T &b) { if (a < b) a = b; } inline void fileio(string s) { freopen((s + ".in").c_str(), "r", stdin); freopen((s + ".out").c_str(), "w", stdout); } const int inf = (int)1e9 + 7; const long long linf = (long long)1e17 + 7; const int N = 1e5 + 7; int u[N], v[N], w[N], nxt[N]; int head[N]; long long dist[N]; int n, m, q, tot; priority_queue<pair<long long, int>, vector<pair<long long, int> >, greater<pair<long long, int> > > pq; inline void init() { pq.push(make_pair(0, 1)); for (register int i = (2); i <= (n); ++i) dist[i] = linf; while (!pq.empty()) { pair<long long, int> p = pq.top(); pq.pop(); int u = p.second; long long d = p.first; if (dist[u] != d) continue; for (int e = head[u]; e; e = nxt[e]) { if (dist[v[e]] <= dist[u] + w[e]) continue; dist[v[e]] = dist[u] + w[e]; pq.push(make_pair(dist[v[e]], v[e])); } } for (register int i = (1); i <= (m); ++i) w[i] -= dist[v[i]] - dist[u[i]]; } vector<int> pos[1000006]; int tmp[N]; inline void upd() { if (!tot) return; for (register int i = (2); i <= (n); ++i) tmp[i] = inf; for (register int i = (0); i <= (tot); ++i) pos[i].clear(); pos[0].push_back(1); for (register int cur = (0); cur <= (tot); ++cur) { for (register int i = 0; i < (pos[cur].size()); ++i) { int u = pos[cur][i]; if (tmp[u] != cur) continue; for (int e = head[u]; e; e = nxt[e]) { if (tmp[v[e]] <= cur + w[e]) continue; tmp[v[e]] = cur + w[e]; if (tmp[v[e]] <= tot) pos[tmp[v[e]]].push_back(v[e]); } } } tot = 0; for (register int i = (1); i <= (m); ++i) w[i] -= tmp[v[i]] - tmp[u[i]]; for (register int i = (2); i <= (n); ++i) if (tmp[i] != inf) dist[i] += tmp[i]; } int main() { scanf("%d%d%d", &n, &m, &q); for (register int i = (1); i <= (m); ++i) { scanf("%d%d%d", u + i, v + i, w + i); nxt[i] = head[u[i]]; head[u[i]] = i; } init(); while (q--) { int tp; scanf("%d", &tp); if (tp == 1) { int u; scanf("%d", &u); upd(); printf("%lld\n", dist[u] == linf ? -1 : dist[u]); } else if (tp == 2) { int num, c; scanf("%d", &num); tot += num; while (num--) { scanf("%d", &c); ++w[c]; } } else assert(false); } return 0; }
10
CPP
n,m=(int(i) for i in input().split()) l=[i for i in range(1,m+1)] for i in range(n): l1,r1=(int(i) for i in input().split()) for j in range(l1,r1+1): if(j in l): l.remove(j) print(len(l)) print(*l)
7
PYTHON3
for i in range(int(input())): a, b = map(int, input().split()) if a == 1 or b == 1: print(pow(b, 2)) else: ans = [0]*a while(b != 0): for i in range(a): if b == 0: break else: ans[i] += 1 b -= 1 count = 0 for i in range(len(ans)): count += pow(ans[i], 2) print(count)
7
PYTHON3
n,m = map(int , input().split()) l = [int(i) for i in input().split()] ; sumans = sum(l[:m]) ; temp = sumans j = m for i in range(1,n-m+1): temp += l[j] temp -= l[i-1] sumans += temp j+=1 print(sumans/(n-m+1))
8
PYTHON3
Valor=0 for i in range(int(input())): palabra = str(input()) if palabra.count('+') > 1: Valor +=1 else: Valor -=1 print(Valor)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; const int N = 1e6 + 5; int t, n, m, x, y; vector<int> s[N], v[N]; queue<pair<int, int>> Q; int dx[] = {0, 0, 1, -1}; int dy[] = {1, -1, 0, 0}; bool check(int x, int y) { int cnt = 0; for (int i = 0; i < 4; i++) { int a = x + dx[i], b = y + dy[i]; if (a >= 1 && a <= n && b >= 1 && b <= m) { if (s[a][b] != 1) continue; if (!v[a][b]) cnt++; } } return cnt <= 1; } int main() { cin >> t; while (t--) { cin >> n >> m; for (int i = 1; i <= n; i++) s[i].clear(), v[i].clear(), s[i].resize(m + 1), v[i].resize(m + 1); for (int i = 1; i <= n; i++) for (int j = 1; j <= m; j++) { char c; cin >> c; if (c == 'L') x = i, y = j; else if (c == '#') s[i][j] = 2; else s[i][j] = 1; } Q.push({x, y}); v[x][y] = 1; while (Q.size()) { auto k = Q.front(); Q.pop(); int a = k.first, b = k.second; for (int i = 0; i < 4; i++) { int A = a + dx[i], B = b + dy[i]; if (A >= 1 && A <= n && B >= 1 && B <= m) { if (v[A][B] || s[A][B] == 2) continue; if (check(A, B)) { v[A][B] = 1; Q.push({A, B}); } } } } for (int i = 1; i <= n; i++) { for (int j = 1; j <= m; j++) { if (i == x && j == y) cout << 'L'; else { if (v[i][j]) cout << '+'; else if (s[i][j] == 2) cout << '#'; else cout << '.'; } } cout << '\n'; } } return 0; }
11
CPP
#include<vector> #include<list> #include<algorithm> #include<iostream> #include<string> #include<cstdio> #include<cstdlib> #include<cstring> #include<cmath> using namespace std; int f(int r[],int t[],int s[],int d[],int n,int c,int m){ int i; int l=m; if(d[c]<m){ d[c]=m; for(i=c+1;i<n;i++){ if(r[i]<r[c]&&t[i]<t[c]) l=max(l,f(r,t,s,d,n,i,m+1)); } return l; }else return 0; } int main(){ int h,i; int m,n,o,r[200],t[200],s[200],d[200]; for(;;){ cin>>m; if(m==0) break; for(i=0;i<m;i++){ cin>>t[i]>>r[i]; s[i]=r[i]*r[i]*t[i]; } cin>>n; for(;i<m+n;i++){ cin>>t[i]>>r[i]; s[i]=r[i]*r[i]*t[i]; } do{ h=0; for(i=1;i<m+n;i++){ if(s[i-1]<s[i]){ swap(s[i-1],s[i]); swap(t[i-1],t[i]); swap(r[i-1],r[i]); h=1; } } }while(h); o=0; memset(d,0,sizeof(d)); for(i=0;i<m+n;i++) o=max(o,f(r,t,s,d,m+n,i,1)); cout<<o<<endl; } return 0; }
0
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n, x; cin >> n >> x; long long sumIce = x; int leaveChild = 0; for (int i = 0; i < n; i++) { char a; int giveIce; cin >> a >> giveIce; if (a == '+') { sumIce += giveIce; } else { if (sumIce >= giveIce) { sumIce -= giveIce; } else { leaveChild++; } } } cout << sumIce << " " << leaveChild << endl; return 0; }
7
CPP
n = int(input()) a = [int(i) for i in input().split()] a.sort() u = [False] * n uc = 0 b = [] while uc < n: p = -1 for i in range(n): if (not u[i]) and (a[i] != p): b += [a[i]] u[i] = True uc += 1 p = a[i] #print(b) c = 0 for i in range(1, n): if b[i] > b[i - 1]: c += 1 print(c)
8
PYTHON3
#include <bits/stdc++.h> using namespace std; const long long INF = 1e18 + 10; const int inf = 1e9 + 10, dx[] = {0, 0, 1, -1, 1, -1, 1, -1}, dy[] = {1, -1, 0, 0, 1, 1, -1, -1}; long long MOD = 1e9 + 7; long double eps = 1e-7, pi = acos(-1); const int MAX = 100100; int n; long double r, x[1010], y[1010], a, b, c, delta; bool get_y(long double x1, long double y1, long double x2, long double &y2) { a = 1.0; b = -2.0 * y1; c = y1 * y1 + pow(x1 - x2, 2) - 4 * r * r; if (b * b < 4 * c) return 0; delta = sqrt(b * b - 4 * a * c); long double ans1 = (-b - delta) / (2.0 * a); long double ans2 = (-b + delta) / (2.0 * a); y2 = max(ans1, ans2); } int main() { ios_base::sync_with_stdio(0); cin >> n >> r; for (int i = 0; i < n; i++) { cin >> x[i]; } y[0] = r; cout << setprecision(10) << fixed << y[0] << " "; for (int i = 1; i < n; i++) { long double y2 = -1, ans = -1; int all_test = 0; for (int j = 0; j < i; j++) { all_test += get_y(x[j], y[j], x[i], y2); ans = max(ans, y2); } if (all_test == 0) y[i] = r; else y[i] = ans; cout << y[i] << " "; } return 0; }
9
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n, m; cin >> n >> m; map<int, int> N; for (int i = 1; i < n + 1; i++) { int tmp; cin >> tmp; N[tmp] = i; } int M[11] = {-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1}; for (int i = 1; i < m + 1; i++) { int tmp; cin >> tmp; if (N[tmp]) M[N[tmp]] = tmp; } for (int i = 1; i < n + 1; i++) { if (M[i] != -1) cout << M[i] << ' '; } return 0; }
7
CPP
import sys input=sys.stdin.readline from queue import Queue #sys.setrecursionlimit(10**8) t=1 import math def bfs(a,i,dis,vis): vis[i]=1 s=0;e=0 pp=[0 for i in range(n+5)] pp[0]=i while s!=e+1: z= pp[s] s+=1 vis[z]=1 for j in a[z]: if vis[j]==0: dis[j]=min(dis[j],dis[z]+1) e+=1 pp[e]=j vis[j]=1 #print(s,e,pp) while t>0: t-=1 n=int(input()) b=[int(x) for x in input().split()] a=[[] for i in range(n+1)] for i in range(n): x=i+1 y=b[i] if i!=n-1: a[i+1].append(i+2) if i!=0: a[i+1].append(i) if x==y: continue a[x].append(y) #a[y].append(x) vis=[0 for i in range(n+1)] dis=[i-1 for i in range(n+1)] bfs(a,1,dis,vis) for i in range(1,n+1): print(dis[i],end=" ")
8
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { long long n; cin >> n; long long num = 0, ans = 0; while (num * 10 + 9 <= n + n - 1) num = num * 10 + 9; for (long long i = num; i <= n + n - 1; i += num + 1) { ans += (i - max(1ll, i - n) * 2 + 1) / 2; } cout << ans << endl; return 0; }
10
CPP
from math import ceil class Solution: def __init__(self): self.r, self.x, self.y, self.x_, self.y_ = [int(x) for x in input().split()] def solve_and_print(self): print(ceil(((abs(self.x_-self.x)**2 + abs(self.y_-self.y)**2)**0.5)/(self.r<<1))) if __name__ == "__main__": Solution().solve_and_print()
8
PYTHON3
#include <bits/stdc++.h> using namespace std; int n, m, b; int ans = 0, ans2; int main() { cin >> n >> m >> b; ans2 = b * n; while (n > 1) { int x = n / 2; ans += (x * 2 * m); ans += x; n = (n / 2) + n % 2; } cout << ans << " " << ans2 << endl; }
7
CPP
#include <bits/stdc++.h> using namespace std; const int N = 3e5 + 10; priority_queue<pair<int, int> > que; vector<pair<int, int> > vc[N]; int vis[N], l[N], r[N]; vector<int> ans; int main() { int n, k, mx = -1; scanf("%d%d", &n, &k); for (int i = 1; i <= n; i++) { cin >> l[i] >> r[i]; mx = max(mx, r[i]); vc[l[i]].push_back({1, i}); vc[r[i] + 1].push_back({-1, i}); } int nw = 0; for (int i = 1; i <= mx; i++) { for (int j = 0; j < vc[i].size(); j++) { if (vis[vc[i][j].second]) continue; nw += vc[i][j].first; if (vc[i][j].first == -1) vis[vc[i][j].second] = 1; else que.push({r[vc[i][j].second], vc[i][j].second}); } while (nw > k) { pair<int, int> pii = que.top(); que.pop(); if (pii.first >= i && vis[pii.second] == 0) { ans.push_back(pii.second); vis[pii.second] = 1; nw--; } } } printf("%d\n", ans.size()); sort(ans.begin(), ans.end()); for (int i = 0; i < ans.size(); i++) { printf("%d ", ans[i]); } return 0; }
10
CPP
#include <bits/stdc++.h> using namespace std; int n, m; char p[1000007], q[1000007], s[1000007]; pair<int, int> f[1000007], pf[1000007]; struct seg { int a, k, len; }; vector<seg> G, x, y; void dp() { for (int i = 1; i <= n; i++) f[i] = make_pair(2000000007, 0); f[0] = make_pair(0, 0); for (int i = 1; i <= n; i++) { x.clear(), y.clear(); for (int j = 0; j < (int)G.size(); j++) if (G[j].a > 1 && s[G[j].a - 1] == s[i]) x.push_back((seg){G[j].a - 1, G[j].k, G[j].len}); int r = -n; for (int j = 0; j < (int)x.size(); j++) { if (x[j].a - x[j].k == r) y.push_back(x[j]); else { y.push_back((seg){x[j].a, x[j].a - r, 1}); if (x[j].len > 1) y.push_back((seg){x[j].a + x[j].k, x[j].k, x[j].len - 1}); } r = x[j].a + x[j].k * (x[j].len - 1); } if (i > 1 && s[i - 1] == s[i]) { y.push_back((seg){i - 1, i - r - 1, 1}); r = i - 1; } y.push_back((seg){i, i - r, 1}); G.clear(); seg t = y[0]; for (int j = 1; j < (int)y.size(); j++) if (t.k == y[j].k) t.len += y[j].len; else { G.push_back(t); t = y[j]; } G.push_back(t); if (s[i] == s[i - 1]) f[i] = make_pair(f[i - 2].first, i - 2); for (int j = 0; j < (int)G.size(); j++) { int rx = G[j].a + G[j].k * (G[j].len - 1); pair<int, int> now = make_pair(f[rx - 1].first + 1, rx - 1); if (G[j].len > 1) now = min(now, pf[G[j].a - G[j].k]); if (G[j].a >= G[j].k) pf[G[j].a - G[j].k] = now; if (i % 2 == 0) f[i] = min(f[i], now); } } } int main() { scanf("%s", p + 1); scanf("%s", q + 1); m = strlen(p + 1); for (int i = 1; i <= 2 * m; i++) if (i % 2 == 1) s[i] = p[i / 2 + 1]; else s[i] = q[i / 2]; n = 2 * m; dp(); if (f[n].first > m) printf("%d\n", -1); else { printf("%d\n", f[n].first); int now = n; while (now > 0) { int pos = f[now].second; if (pos < now - 2) printf("%d %d\n", pos / 2 + 1, now / 2); now = pos; } } return 0; }
11
CPP
from sys import setrecursionlimit setrecursionlimit(10**6) from collections import deque import heapq import functools def IntInput(): return int(input()) def M_IntInput(): return map(int,input().split()) def M_StrInput(): return map(int,input().split()) def IntArrayInput(): return list(map(int,input().split())) def modInverse(p,a,m): return ((p%m)*pow(a%m,m-2,m))%m def compare(item1, item2): return item2[0] - item1[0] if item1[0]!=item2[0] else item1[1] - item2[1] # -----------------------Anshul Raj------------------------ # def DFS(s,n,paths,answer): visited = [False] * (n+1) stack = [] stack.append(s) visited[s] = True DFSArray = [] while stack: s = stack.pop() DFSArray.append(s) flag = 0 for i in paths[s]: if visited[i] == False: flag=1 stack.append(i) visited[i] = True if not flag: # print("Leaf ->",s) answer[s-1][1]=0 # print(answer) # print("DFS -->",DFSArray) while DFSArray!=[]: s = DFSArray.pop() if answer[s-1][1]<0: answer[s-1][1] = 0 for i in paths[s]: # print("child",s,i,answer[i-1][1]) if answer[i-1][1]>=0: answer[s-1][1] += answer[i-1][1]+1 # print("childCount -->",s,answer[s-1][1]) return answer def BFS(s,n,paths,answer): visited = [False] * (n+1) answer[s-1][0] = 0 queue = deque() queue.append(s) visited[s] = True while queue: s = deque.popleft(queue) for i in paths[s]: if visited[i] == False: queue.append(i) answer[i-1][0] = answer[s-1][0] + 1 visited[i] = True return answer n,k = M_IntInput() paths = {} AnswerArray = [[-1,-1] for i in range(n)] for _ in range(n-1): u,v = M_IntInput() if u in paths: paths[u].append(v) else: paths[u] = [v] if v in paths: paths[v].append(u) else: paths[v] = [u] if k==n: print(0) elif k==n-1: print(n-1) else: AnswerArray = BFS(1,n,paths,AnswerArray) AnswerArray = DFS(1,n,paths,AnswerArray) # print(AnswerArray) AnswerArray.sort(key=lambda x: x[0] - x[1],reverse = True) # print(AnswerArray) ans = 0 for i in range(k): ans += AnswerArray[i][0] - AnswerArray[i][1] print(ans)
9
PYTHON3
s = input() t = input() u = '' for i in range (len(s)): u+=s[len(s)-i-1] if (t==u): print ('YES') else: print ('NO')
7
PYTHON3
#include <stdio.h> int main(void){ int i,l=0; char s[11],a[11]={}; scanf("%s",s); for (i=0;s[i];i++){ if (s[i]=='B'){ if (l){ l--; a[l]='\0'; } }else{ a[l]=s[i]; l++; } } printf("%s\n",a); return 0; }
0
CPP
#include <iostream> #include <cstdio> #define MN 42 typedef long long ll; ll s[MN][MN][MN], f[MN][MN][MN], g[MN][MN][MN][MN]; int a[MN][MN]; int main() { int n; scanf("%d", &n); n *= 2; for(int i = 1; i <= n; i++) for(int j = 1; j <= n; j++) scanf("%1d", &a[i][j]); for(int len = 1; len <= n; len++) for(int l = 1; l + len - 1 <= n; l++) { int r = l + len - 1; if(l == r) f[l][r][l] = 1; for(int i = l; i <= r; i++) { for(int j = i + 1; j <= r; j++) { if(!g[l][i][j][r]) continue; for(int k = i + 1; k < j; k++) f[l][r][k] += f[i + 1][j - 1][k] * g[l][i][j][r]; } } for(int k = l; k <= r; k++) { if(!f[l][r][k]) continue; for(int k2 = 1; k2 <= n; k2++) if(a[k2][k]) s[l][r][k2] += f[l][r][k]; } for(int LEN = 1; LEN <= len; LEN++) for(int L = 1; L + LEN - 1 < l; L++) { int R = L + LEN - 1; for(int k = L; k <= R; k++) g[L][R][l][r] += f[L][R][k] * s[l][r][k]; } for(int LEN = 1; LEN < len; LEN++) for(int L = r + 1; L + LEN - 1 <= n; L++) { int R = L + LEN - 1; for(int k = L; k <= R; k++) g[l][r][L][R] += f[L][R][k] * s[l][r][k]; } } ll ans = 0; for(int k = 2; k <= n; k++) if(a[1][k]) ans += f[2][n][k]; printf("%lld\n", ans); }
0
CPP
numbers = [int(i)for i in input().split()] n = numbers[0] k = numbers[1] letters = "abcdefghijklmnopqrstuvwxyz" reps = n//k remains = n%k if n<26: password=letters[0:n+1] new_password = (password[0:k]*(reps))+password[0:remains] print(new_password) else: reps1 = n//26 remains1 = n%26 password = letters[0:26]*reps1 + letters[0:remains1] new_password = (password[0:k]*(reps))+password[0:remains] print(new_password)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; const int MAXN = 0; const int LOGN = 0; const int MOD = 1e9 + 7; const int INF = 1e9 + 10; long long N, Q; long long x; long long f(long long x) { if (x & 1) return (x + 1) >> 1; long long id = N - (x >> 1); while (!(id & 1)) id /= 2; --id; id /= 2; return N - id; } void read() { cin >> N >> Q; while (Q--) { cin >> x; cout << f(x) << "\n"; } return; } int main() { read(); }
8
CPP
N = int(input()) K = 0 k = 0 while K < N: k += 1 K += k while N > 0: if N >= k: print(k) N -= k k -= 1
0
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { long long n, count; cin >> n; if (n % 2 != 0) count = 0; else { if (n % 4 == 0) count = n / 4 - 1; else count = n / 4; } cout << count; return 0; }
7
CPP
#include <bits/stdc++.h> using namespace std; long long gcd(long long a, long long b) { return b ? gcd(b, a % b) : a; } const int N = 1e5 + 10; char s[N]; int a[N], n, q; int sum[4 * N]; void up(int id, int l, int r, int pos, int val, int ty) { if (l == r) { if (ty == 1) { sum[id] = (1 << val); } else sum[id] = 0; return; } int mid = l + r >> 1; if (pos <= mid) up(id << 1, l, mid, pos, val, ty); else up(id << 1 | 1, mid + 1, r, pos, val, ty); sum[id] = sum[id << 1] | sum[id << 1 | 1]; } int qu(int id, int l, int r, int ql, int qr) { if (ql <= l && r <= qr) { return sum[id]; } int mid = l + r >> 1; int ans = 0; if (ql <= mid) ans |= qu(id << 1, l, mid, ql, qr); if (qr > mid) ans |= qu(id << 1 | 1, mid + 1, r, ql, qr); return ans; } int cal(int x) { int ans = 0; while (x) { if (x & 1) ans++; x = x / 2; } return ans; } int main() { scanf("%s", s + 1); n = strlen(s + 1); scanf("%d", &q); for (int i = 1; i <= n; ++i) { up(1, 1, n, i, s[i] - 'a', 1); } while (q--) { int ty; scanf("%d", &ty); if (ty == 2) { int l, r; scanf("%d%d", &l, &r); int ans = qu(1, 1, n, l, r); printf("%d\n", cal(ans)); } else { int pos; char c[5]; scanf("%d%s", &pos, c); int val = c[0] - 'a'; up(1, 1, n, pos, val, 2); up(1, 1, n, pos, val, 1); } } }
10
CPP
#include<bits/stdc++.h> using namespace std; int s[1005],n,k,sum; int main() { scanf("%d%d",&n,&k); for(int i=0;i<n;i++) scanf("%d",&s[i]); sort(s,s+n); for(int i=0;i<k;i++) sum+=s[i]; printf("%d",sum); return 0; }
0
CPP
#include <bits/stdc++.h> using namespace std; const int N = 1e6 + 5, mod = 1000000007; int main() { int n, m, t; scanf("%d", &t); while (t--) { scanf("%d", &n); long long ans = 1; for (int i = 3; i <= n * 2; i++) { ans = ans * i % mod; } printf("%lld\n", ans); } }
7
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; vector<int> v; for (int i = 0; i < n; i++) { int a; cin >> a; v.push_back(a); } if (n == 0) { cout << "YES" << endl; cout << 1 << endl; cout << 1 << endl; cout << 3 << endl; cout << 3 << endl; return 0; } if (n == 1) { int val1 = v[0]; int val2 = v[0] + 1; int val3 = val1 * 4 - val2; int val4 = val1 * 3; cout << "YES" << endl; cout << val2 << endl; cout << val3 << endl; cout << val4 << endl; } else if (n == 4) { sort(v.begin(), v.end()); if (v[0] * 3 == v[3] && v[1] + v[2] == v[0] * 4) cout << "YES" << endl; else cout << "NO" << endl; } else if (n == 2) { int val1 = v[0]; int val2 = v[1]; if (val1 > val2) swap(val1, val2); int val4 = val1 * 3; int val3 = val1 * 4 - val2; int mn = min(val2, val3); int mx = max(val2, val3); if (mn >= val1 && mx <= val4) { cout << "YES" << endl; cout << val3 << endl; cout << val4 << endl; return 0; } if (val2 % 3 == 0 && val2 / 3 == val1) { int now1 = val1 + 1; int now2 = val1 * 4 - now1; mn = min(now1, now2); mx = max(now1, now2); if (mn >= val1 && mx <= val2) { cout << "YES" << endl; cout << now1 << endl; cout << now2 << endl; return 0; } } if (val2 % 3 == 0) { int now1 = val2 / 3; int temp = now1 * 4; int now2 = temp - val1; mn = min(val1, now2); mx = max(val1, now2); if (mn >= now1 && mx <= val2) { cout << "YES" << endl; cout << now1 << endl; cout << now2 << endl; return 0; } } if ((val1 + val2) % 4 == 0) { int now1 = (val1 + val2) / 4; int now4 = now1 * 3; mn = min(val2, val1); mx = max(val2, val1); if (mn >= now1 && mx <= now4) { cout << "YES" << endl; cout << now1 << endl; cout << now4 << endl; return 0; } } cout << "NO" << endl; } else if (n == 3) { sort(v.begin(), v.end()); if ((v[1] + v[2]) % 4 == 0 && ((v[1] + v[2]) / 4) == v[0] && v[0] * 3 >= v[2]) { cout << "YES" << endl; cout << v[0] * 3 << endl; return 0; } if (v[2] % 3 == 0 && v[2] / 3 == v[0]) { int now2 = v[0] * 4 - v[1]; int mn = min(now2, v[1]); int mx = max(now2, v[1]); if (mn >= v[0] && mx <= v[2]) { cout << "YES" << endl; cout << now2 << endl; return 0; } } if (v[2] % 3 == 0) { int now1 = v[2] / 3; if (v[0] + v[1] == now1 * 4) { cout << "YES" << endl; cout << now1 << endl; return 0; } } cout << "NO" << endl; } }
8
CPP
#include <bits/stdc++.h> using namespace std; long double m, n, ans; long double dp[100000 + 1]; int main() { cin >> m >> n; ans = 0; long double total = pow(m, n); for (int ii = 1; ii < m; ii++) { ans += pow((double)ii / m, n); } ans = (m)-ans; cout << setprecision(5) << ans << endl; }
7
CPP
t = int(input()) for _ in range(t): n = int(input()) s = list(input()) temp = 0 if n>=11: for i in range(n-10, n): if s[i]=='8': temp+=1 if n<11 or '8' not in s or (temp>0 and s[:n-10].count('8')==0): print("NO") else: print("YES")
7
PYTHON3
from collections import defaultdict from math import ceil t = int(input()) for _ in range(t): n = int(input()) s = list(map(int,input())) s = [c for c in s if c%2] if len(s)<= 1: print (-1) else: print ("".join(str(x) for x in s[:2]))
7
PYTHON3
listlength = input() listlength = int(listlength) x = input().split(' ') x = list(map(int, x)) a = [] def build_list(a): amax = 0 current = 0 for i in range(listlength): current = amax + x[i] a.append(current) if current > amax: amax = current return a print(*build_list(a), sep = " ")
8
PYTHON3
#include <bits/stdc++.h> using namespace std; inline int read() { int x = 0, f = 1; char c = getchar(); while (!isdigit(c)) { if (c == -1) f = -1; c = getchar(); } while (isdigit(c)) { x = (x << 3) + (x << 1) + (c ^ 48); c = getchar(); } return x * f; } struct node { int x, v; } L[21], R[21]; inline int cmp1(const node &a, const node &b) { return a.x < b.x; } inline int cmp2(const node &a, const node &b) { return a.x > b.x; } const int maxn = 100010; struct tree { long long ans; int l[20], r[20]; } t[maxn << 2], now; int nowl, x; int n, m; int a[maxn], sum[22]; int bit[21]; tree merge(const tree &a, const tree &b, int l, int r, int mid) { tree c; c.ans = a.ans + b.ans; for (int i = 0; i <= 19; ++i) { L[i].x = b.l[i]; L[i].v = bit[i]; R[i].x = a.r[i]; R[i].v = bit[i]; } sort(L, L + 20, cmp1); if (L[0].x != mid + 1) L[20].x = mid + 1, L[20].v = 0; else L[20].x = n + 1; for (int i = 0; i < 19; ++i) if (L[i].x == L[i + 1].x) L[i + 1].v |= L[i].v, L[i].x = n + 1; sort(L, L + 21, cmp1); sum[0] = L[0].v; for (int i = 1; i <= 20; ++i) sum[i] = sum[i - 1] | L[i].v; sort(R, R + 20, cmp2); if (R[0].x != mid) R[20].x = mid, R[20].v = 0; else R[20].x = 0; for (int i = 0; i < 19; ++i) if (R[i].x == R[i + 1].x) R[i + 1].v |= R[i].v, R[i].x = 0; sort(R, R + 21, cmp2); int i = 0, j = 20; while (j >= 0 && R[j].x == 0) --j; R[j + 1].x = l - 1; j = 20; while (j >= 0 && L[j].x == n + 1) --j; L[j + 1].x = r; int nowsum = 0; while (i <= 20 && j >= 0) { if (R[i].x == l - 1) break; nowsum |= R[i].v; while (j > 0 && (nowsum | sum[j - 1]) >= x) --j; if ((nowsum | sum[j]) >= x) c.ans += 1LL * (r - L[j].x + 1) * (R[i].x - R[i + 1].x); ++i; } for (int I = 0; I < 20; ++I) { c.l[I] = min(a.l[I], b.l[I]); c.r[I] = max(a.r[I], b.r[I]); } return c; } void build(int o, int l, int r) { if (l == r) { for (int i = 0; i <= 19; ++i) { if (a[l] & (1 << i)) t[o].l[i] = t[o].r[i] = l; else t[o].l[i] = n + 1, t[o].r[i] = 0; } t[o].ans = (a[l] >= x); return; } int mid = (l + r) >> 1; build(o << 1, l, mid); build(o << 1 | 1, mid + 1, r); t[o] = merge(t[o << 1], t[o << 1 | 1], l, r, mid); } void upt(int o, int l, int r, int p, int v) { if (l == r) { for (int i = 0; i <= 19; ++i) { if (v & (1 << i)) t[o].l[i] = t[o].r[i] = l; else t[o].l[i] = n + 1, t[o].r[i] = 0; } t[o].ans = (v >= x); return; } int mid = (l + r) >> 1; if (p <= mid) upt(o << 1, l, mid, p, v); else upt(o << 1 | 1, mid + 1, r, p, v); t[o] = merge(t[o << 1], t[o << 1 | 1], l, r, mid); } void que(int o, int l, int r, int X, int Y) { if (X <= l && r <= Y) { if (now.ans == -1) now = t[o]; else now = merge(now, t[o], nowl, r, l - 1); return; } int mid = (l + r) >> 1; if (X <= mid) que(o << 1, l, mid, X, Y); if (Y > mid) que(o << 1 | 1, mid + 1, r, X, Y); } int main() { n = read(); m = read(); x = read(); for (int i = 1; i <= n; ++i) a[i] = read(); for (int i = 0; i <= 21; ++i) bit[i] = (1 << i); build(1, 1, n); for (int i = 1; i <= m; ++i) { int opt = read(); if (opt == 1) { int X = read(), v = read(); upt(1, 1, n, X, v); } else { int l = read(), r = read(); nowl = l; now.ans = -1; for (int j = 0; j < 20; ++j) now.l[j] = n + 1, now.r[j] = 0; que(1, 1, n, l, r); printf("%lld\n", now.ans); } } return 0; }
12
CPP
a=input() count=0 for i in a: if(i=="4" or i=="7"): count+=1 if(count==4 or count==7): print("YES") else: print("NO")
7
PYTHON3
#include <bits/stdc++.h> using namespace std; typedef long long ll; int main () { ll n; cin>>n; ll a[300005],b[300005]; for(int i=0;i<n;i++){int x; cin>>x; a[x-1]++; } sort(a,a+n,greater<int>()); int j=n-1; ll sum=0; for(int i=1;i<=n;i++){ while(j>=0 && a[j]<i){ sum+=a[j]; j--; } b[i]= sum/i +(j+1); } j=n; for(int i=1;i<=n;++i){ while(j>=1 && b[j]<i) { j--; } cout<<j<<"\n"; } }
0
CPP
d,l={},[input() for i in range(int(input()))] for i in l: if i in d.keys(): d[i]+=1 else: d[i]=1 for i in l[::-1]: if d[i]>0: print(i);d[i]=0
8
PYTHON3
#include <iostream> using namespace std; typedef long long int ll; #define rd(t,n) for (int i = 0; i < n; i++)cin>>t[i] int main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); int n,m;cin>>n>>m; ll t[m];rd(t,m); sort(t,t+m); ll d[m];d[0]=0; for (int i = 1; i < m; i++)d[i]=t[i]-t[i-1]; sort(d,d+m); ll s=0; for (int i = 0; i <= m-n; i++)s+=d[i]; cout<<s; }
0
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; vector<pair<int, int> > v(n); for (int i = 0; i < n; ++i) { cin >> v[i].first; v[i].first = -v[i].first; v[i].second = i; } sort(v.begin() + 1, v.end()); int pos = 1; vector<pair<int, int> > ans; for (int i = 0; i < n && pos < n; ++i) { if (v[i].first == 0) { cout << "-1\n"; return 0; } for (int j = 0; j < -v[i].first && pos < n; ++j) ans.push_back({v[i].second + 1, v[pos].second + 1}), ++pos; } cout << ans.size() << endl; for (int i = 0; i < ans.size(); ++i) cout << ans[i].first << ' ' << ans[i].second << endl; return 0; }
8
CPP
import io,os input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline class segment_tree(object): def merge(self,num,minimum): return min(minimum,num) def __init__(self,n,initial): self.n = n self.arr = [0]*(2*n) self.lazy = [0]*(n) self.layer = n.bit_length() + 1 for i in range(2*n-1,n-1,-1): self.arr[i] = initial[i-n] for i in range(n-1,-1,-1): self.arr[i] = self.merge(self.arr[2*i],self.arr[2*i+1]) def rebuild(self,index): index = index >> 1 while index>0: self.arr[index] = self.merge(self.arr[index<<1],self.arr[index<<1|1]) + self.lazy[index] index = index >> 1 def addtarget(self,index,target): self.arr[index] += target if index<self.n: self.lazy[index] += target def changetotarget(self,index,target): self.arr[index] = target if index<self.n: self.lazy[index] = target def update(self,left,right,target): i,j = self.n+left, self.n+right+1 i0,j0 = i,j while i<j: if i&1: self.addtarget(i,target) i += 1 if j&1: j -= 1 self.addtarget(j,target) i = i >> 1 j = j >> 1 # if i==j: # self.arr[i] += target # if j<self.n: self.lazy[i] += target self.rebuild(i0) self.rebuild(j0-1) def pushdown(self,index): for move in range(self.layer,0,-1): father = index >> move if father<1 or father>=self.n: continue if self.lazy[father]==0: continue child = father << 1 self.arr[child] += self.lazy[father] self.arr[child+1] += self.lazy[father] if child < self.n: self.lazy[child] += self.lazy[father] if child+1 < self.n: self.lazy[child+1] += self.lazy[father] self.lazy[father] = 0 def query(self,left,right): i,j = self.n+left, self.n+right+1 output = 2147483647 # initial output should be changed if you want to change the merge function self.pushdown(i) self.pushdown(j-1) while i<j: if i&1: output = self.merge(self.arr[i],output) i += 1 if j&1: j -= 1 output = self.merge(self.arr[j],output) i = i >> 1 j = j >> 1 return output def main(t): n,m = map(int,input().split()) segments = [] for _ in range(n): front,rear,w = map(int,input().split()) segments.append([w,front-1,rear-1]) segments = sorted(segments) over = segment_tree(m-1,[0]*(m-1)) front = 0 ans = 2147483647 flag = False for i in range(n): # print(i) over.update(segments[i][1],segments[i][2]-1,1) if not flag and over.query(0,m-2)>0: flag = True if flag: while over.query( segments[front][1], segments[front][2] - 1) > 1: front += 1 over.update(segments[front-1][1],segments[front-1][2]-1,-1) # for p in range(segments[front-1][1],segments[front-1][2]): # over.addnum(p,-1) ans = min(ans,segments[i][0]-segments[front][0]) print(ans) T = 1 t = 1 while t<=T: main(t) t += 1
11
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(0); cin.tie(0); int T = 1; cin >> T; while (T--) { string s, t; cin >> s >> t; vector<int> a(26); for (char c : s) { a[c - 'a']++; } if (t == "abc" && a[0] && a[1] && a[2]) { while (a[0]--) cout << "a"; while (a[2]--) cout << "c"; while (a[1]--) cout << "b"; for (int i = 3; i < 26; i++) { while (a[i]--) cout << (char)(i + 'a'); } } else { sort(s.begin(), s.end()); cout << s; } cout << '\n'; } return 0; }
7
CPP
n = int(input()) f, s = 0, 0 for i, j in zip(input(), input()): if i == '1' and i != j: f += 1 elif j == '1' and j != i: s += 1 print(s // f + 1) if f != 0 else print(-1)
7
PYTHON3
for _ in range(int(input())): n = int(input()) a = list(map(int, input().split())) c = {} for j, i in enumerate(a): c[i] = c.get(i, []) + [j+1] x = list(c.values()) if len(x) == 1: print('NO') continue print('YES') s = x[0].pop(0) for i in x[1]: print(s, i) for i in range(len(x)): if i == 1: continue for j in x[i]: print(x[1][0], j)
10
PYTHON3
s=str(input()) cnt=0 for ch in s: if ch is 'a': cnt=cnt+1 mx=2*cnt-1 ans=min(mx,len(s)) print(ans)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; for (int k = 1; k <= n / 2; k++) { cout << k << " " << n + 1 - k << " "; } if (n % 2 == 1) cout << (n + 1) / 2 << endl; return 0; }
9
CPP
#include <bits/stdc++.h> using namespace std; int main() { int i, j, n, top, temp; int stack[101101]; cin >> n; top = 0; stack[0] = -1; for (i = 0; i < n; i++) { cin >> temp; if (temp > stack[top]) { stack[++top] = temp; } else { int low = 1, high = top; int mid; while (low <= high) { mid = (low + high) / 2; if (temp > stack[mid]) { low = mid + 1; } else { high = mid - 1; } } stack[low] = temp; } } cout << top << endl; return 0; }
8
CPP
n = int(input()) sum = 0 for i in range(n): count = 0 arr = list(map(int,input().split())) for j in range(len(arr)): if(arr[j] == 1): count += 1 if(count >= 2): sum += 1 print(sum)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int n, w; int a[300005], b[300005]; vector<int> v; map<int, int> mp; int cnt = 0; int c[300005], d[300005], order[300005], stored[2 * 300005]; int idx[8 * 300005]; long long sum[8 * 300005]; void add(int i, int low, int high, int x, int delta) { if (low == high) { idx[i] += delta; sum[i] += stored[low] * delta; return; } int mid = (low + high) >> 1; if (x <= mid) add(2 * i, low, mid, x, delta); else add(2 * i + 1, mid + 1, high, x, delta); idx[i] = idx[2 * i] + idx[2 * i + 1]; sum[i] = sum[2 * i] + sum[2 * i + 1]; } long long calc(int i, int low, int high, int x) { if (x > idx[i]) return 1LL << 60; if (low == high) return 1LL * x * stored[low]; else if (x <= idx[2 * i]) return calc(2 * i, low, (low + high) >> 1, x); else return calc(2 * i + 1, 1 + (low + high) / 2, high, x - idx[2 * i]) + sum[2 * i]; } bool cmp(int x, int y) { return b[x] < b[y]; } bool cmp2(int x, int y) { return d[x] < d[y]; } int main() { scanf("%d %d", &n, &w); for (int i = 0; i < n; i++) { scanf("%d %d", &a[i], &b[i]); v.push_back(a[i]); v.push_back(b[i] - a[i]); } sort(v.begin(), v.end()); for (int i = 0; i < v.size(); i++) { if (!i || v[i] > v[i - 1]) { stored[cnt] = v[i]; mp[v[i]] = cnt; cnt++; } } for (int i = 0; i < n; i++) order[i] = i; sort(order, order + n, cmp); for (int i = 0; i < n; i++) { int u = order[i]; } long long tmp = 0; for (int i = 0; i < n; i++) add(1, 0, cnt - 1, mp[a[i]], 1); long long ret = calc(1, 0, cnt - 1, w); int pos = 0; for (int i = 0; i < n; i++) { int j = w - i - 1; if (j < 0) break; int u = order[i]; add(1, 0, cnt - 1, mp[a[u]], -1); tmp += a[u]; add(1, 0, cnt - 1, mp[b[u] - a[u]], 1); long long tmp2 = calc(1, 0, cnt - 1, w - i - 1); if (tmp2 + tmp < ret) { ret = tmp2 + tmp; pos = i + 1; } } cout << ret << endl; for (int i = 0; i < pos; i++) c[order[i]] = 1; for (int i = 0; i < n; i++) d[i] = (c[i] == 0) ? a[i] : (b[i] - a[i]); sort(order, order + n, cmp2); for (int i = 0; i < w - pos; i++) c[order[i]]++; for (int i = 0; i < n; i++) printf("%d", c[i]); printf("\n"); }
11
CPP
n = int(input()) s = input() for i in range(1, n + 1, 1): if n % i == 0: x = s[:i] y = s[i:] s = x[:: -1] + y print(s)
8
PYTHON3
#include <bits/stdc++.h> using namespace std; int main(){ string w; cin >> w; string s; int cnt = 0; while(cin >> s){ if(s == "END_OF_TEXT") break; transform(s.begin(), s.end(), s.begin(), ::tolower); if(s == w) cnt++; } cout << cnt << endl; }
0
CPP