solution
stringlengths
10
983k
difficulty
int64
0
25
language
stringclasses
2 values
t=int(input()) for tt in range (0,t): n,k=map(int,input().split()) s=input() if s[0]=="1": a=0 else: a=-1 b=-1 d=0 for i in range (0,n): if s[i]=="1": b=i if a==-1: c=b-k c=1+(c-1)//(k+1) d=d+c a=b else: c=b-a-1 if c>(2*k): c=c-(2*k) c=1+(c-1)//(k+1) d=d+c a=b e=n-b-k-1 e=1+(e-1)//(k+1) if e>0: d=d+e if b==-1: if n<=(k+1): print(1) else: print(((n-1)//(k+1))+1) else: print(d)
9
PYTHON3
a, b = input().split() c = int(a+b) print('Yes' if c == int(c**.5)**2 else 'No')
0
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(0); cin.tie(0); int t; cin >> t; while (t--) { int n; cin >> n; if (n == 1) { cout << -1 << endl; } else if (n % 3 == 1) { cout << "5"; for (int i = 2; i < n; ++i) { cout << '4'; } cout << "3\n"; } else { for (int i = 1; i < n; ++i) { cout << '2'; } cout << "3\n"; } } }
7
CPP
#include <bits/stdc++.h> using namespace std; struct less_key { bool operator()(const pair<double, int32_t>& p1, const pair<double, int32_t>& p2) { return p1.first < p2.first || (p1.first == p2.first && p1.second > p2.second); } }; struct pair_hash { std::size_t operator()(const pair<int32_t, int32_t>& k) const { return static_cast<size_t>(k.first ^ k.second); } }; int32_t n; int64_t nx, bx; vector<int64_t> rx; int64_t ny, by; vector<int64_t> ry; int64_t count(int64_t b, vector<int64_t>& r) { int64_t c = 1; int64_t res = 0; for (int32_t i = r.size() - 1; i >= 0; i--) { res += c * r[i]; c *= b; } return res; } int main() { ios_base::sync_with_stdio(false); cin >> nx >> bx; for (int32_t i = 0; i < nx; i++) { int64_t t; cin >> t; rx.push_back(t); } cin >> ny >> by; for (int32_t i = 0; i < ny; i++) { int64_t t; cin >> t; ry.push_back(t); } int64_t Rx = count(bx, rx); int64_t Ry = count(by, ry); if (Rx == Ry) { cout << '='; } else if (Rx < Ry) { cout << '<'; } else { cout << '>'; } return 0; }
7
CPP
#include<bits/stdc++.h> using namespace std; const int N=2e5+7; int n,m,p,sr,sc; char s[N],t[N]; bool walk1() { int L=1,R=n; for(int i=p;i;i--) { if(t[i]=='U')R=min(n,R+1);else if(t[i]=='D')L=max(1,L-1); if(s[i]=='U')L++;else if(s[i]=='D')R--; if(L>R)return 1; } return (sr<L||sr>R); } bool walk2() { int L=1,R=m; for(int i=p;i;i--) { if(t[i]=='L')R=min(m,R+1);else if(t[i]=='R')L=max(1,L-1); if(s[i]=='L')L++;else if(s[i]=='R')R--; if(L>R)return 1; } return (sc<L||sc>R); } int main() { scanf("%d%d%d%d%d",&n,&m,&p,&sr,&sc); scanf("%s",s+1); scanf("%s",t+1); if(walk1()||walk2())puts("NO"); else puts("YES"); }
0
CPP
#include <bits/stdc++.h> using namespace std; const long long LIM = 1e18; const int MAXN = 1e5; int N; bool possible = true; long long A[MAXN], B[MAXN]; vector<pair<int, int> > T[MAXN]; void dfs(int v) { for (int i = 0; i < (int)T[v].size(); i++) { int u = T[v][i].first; int c = T[v][i].second; dfs(u); if (B[u] >= A[u]) B[v] += B[u] - A[u]; else if (A[u] - B[u] > (double)LIM / c) possible = false; else if (B[v] < -LIM + (A[u] - B[u]) * c) possible = false; else B[v] -= (A[u] - B[u]) * c; } } int main() { scanf("%d", &N); for (int i = 0; i < (int)N; i++) scanf("%lld", &B[i]); for (int i = 0; i < (int)N; i++) scanf("%lld", &A[i]); for (int i = 1; i < (int)N; i++) { int p, c; scanf("%d", &p), scanf("%d", &c); T[p - 1].push_back({i, c}); } dfs(0); printf("%s\n", B[0] >= A[0] && possible ? "YES" : "NO"); }
11
CPP
#include <bits/stdc++.h> using namespace std; const int N = 6000; long long stat[N]; long long sc[N]; int main() { ios::sync_with_stdio(false), cin.tie(0), cout.tie(0); long long n, m; cin >> n >> m; long long inf = 1e9; fill(stat, stat + n, inf); for (int i = 0; i < m; i++) { int a, b; cin >> a >> b; stat[a - 1] = min(stat[a - 1], (n + b - a) % n); sc[a - 1]++; } for (int i = 0; i < n; i++) { long long ans = 0; for (int j = 0; j < n; j++) { if (sc[j]) { long long dist = (n + j - i) % n + (sc[j] - 1) * n; if (dist + stat[j] > ans) ans = dist + stat[j]; ans = max(ans, dist + stat[j]); } } cout << ans << ' '; } }
7
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; if (n % 2) cout << "Ehab"; else cout << "Mahmoud"; return 0; }
7
CPP
n = int(input()) A = list(map(int, input().split())) ai = max(A) A.remove(ai) Asub = [abs(ai/2 -a) for a in A] aj = A[Asub.index(min(Asub))] print('{} {}'.format(ai, aj))
0
PYTHON3
import sys n = int(input()) string = input() if n <= 26: alphabet = [0]*26 cnt = 0 for char in string: alphabet[ord(char)-97] += 1 for num in alphabet: if num > 1: cnt += (num-1) print(cnt) else: print('-1')
8
PYTHON3
#include <bits/stdc++.h> using namespace std; long long a, b, c, lena, lenb, lenc, ans = 1e9, ansa, ansb; bool p = 0; long long dig[12] = {1, 10, 100, 1000, 10000, 100000, 1000000, 10000000, 100000000, 1000000000, 10000000000, 1000000000}; int read() { int x = 0, f = 1; char ch = getchar(); while (ch < '0' || ch > '9') { if (ch == '-') f = -1; ch = getchar(); } while (ch >= '0' && ch <= '9') x = x * 10 + ch - '0', ch = getchar(); return f * x; } int getlen(long long x) { int len = 0; while (x) x /= 10, len++; return len; } void dfs(int a, int b, int c, long long na, long long nb, int addlen, int jin, int len) { if (addlen >= ans) return; if (!a && !b && !c && !jin) { ans = addlen; ansa = na; ansb = nb; return; } if (c == 0) { int tot = a + b + jin; dfs(0, 0, 0, na + a * dig[len], nb + b * dig[len], addlen + getlen(tot), 0, 0); return; } if ((a % 10 + b % 10 + jin) % 10 == c % 10) dfs(a / 10, b / 10, c / 10, na + (a % 10) * dig[len], nb + (b % 10) * dig[len], addlen, (a % 10 + b % 10 + jin) / 10, len + 1); else { dfs(a * 10 + (c % 10 - b % 10 - jin + 10) % 10, b, c, na, nb, addlen + 1, jin, len); dfs(a, b * 10 + (c % 10 - a % 10 - jin + 10) % 10, c, na, nb, addlen + 1, jin, len); dfs(a, b, c * 10 + (a % 10 + b % 10 + jin) % 10, na, nb, addlen + 1, jin, len); } } int main() { a = read(), b = read(), c = read(); dfs(a, b, c, 0, 0, 0, 0, 0); printf("%I64d+%I64d=%I64d", ansa, ansb, ansa + ansb); }
11
CPP
#include <bits/stdc++.h> using namespace std; const long long maxn = 70001, base = 173, mo = 1e9 + 9; long long ans, n; string s[maxn]; struct asuka { long long key, l, r; bool friend operator<(asuka a, asuka b) { if (a.r - a.l == b.r - b.l) return a.key < b.key; return a.r - a.l < b.r - b.l; } }; map<asuka, long long> mp[maxn]; signed main() { cin >> n; for (long long k = 1; k <= n; k++) { cin >> s[k]; for (long long i = 0; i < 9; i++) { long long key = 0; for (long long j = i; j < 9; j++) key = (key * base % mo + s[k][j]) % mo, mp[0][{key, i, j}]++, mp[k][{key, i, j}]++; } } for (long long k = 1; k <= n; k++) for (map<asuka, long long>::iterator i = mp[k].begin(); i != mp[k].end(); i++) { if (i->second == mp[0][i->first]) { for (long long j = i->first.l; j <= i->first.r; j++) putchar(s[k][j]); cout << endl; break; } } }
8
CPP
#include <bits/stdc++.h> using std ::reverse; using std ::swap; using std ::vector; template <typename T> T max(T x, T y) { return (x > y) ? x : y; } template <typename T> T min(T x, T y) { return (x < y) ? x : y; } template <typename T> bool chkmax(T &x, T y) { return (x >= y) ? 0 : (x = y, 1); } template <typename T> bool chkmin(T &x, T y) { return (x <= y) ? 0 : (x = y, 1); } template <typename T> T read(T &in) { in = 0; char ch; T f = 1; while (!isdigit(ch = getchar())) if (ch == '-') f = -1; while (isdigit(ch)) in = in * 10 + ch - '0', ch = getchar(); return in *= f; } static const int max1 = 1 << 21 | 1; static const int B = 1000; struct cpx { double r, i; cpx(double _r = 0, double _i = 0) { r = _r, i = _i; } cpx conj() { return cpx(r, -i); } }; cpx operator+(const cpx &a, const cpx &b) { return cpx(a.r + b.r, a.i + b.i); } cpx operator-(const cpx &a, const cpx &b) { return cpx(a.r - b.r, a.i - b.i); } cpx operator*(const cpx &a, const cpx &b) { return cpx(a.r * b.r - a.i * b.i, a.r * b.i + a.i * b.r); } int N, M, L, R[max1]; cpx PolyA[max1], PolyB[max1]; void FFT(cpx *x) { static const double PI = acos(-1); for (int i = (0), ir = (N - 1); i <= (ir); ++i) if (i < R[i]) swap(x[i], x[R[i]]); for (int i = 1; i < N; i <<= 1) { cpx wn = cpx(cos(PI / i), sin(PI / i)); for (int j = 0, t = i << 1; j < N; j += t) { cpx w = cpx(1, 0); for (int k = 0; k < i; ++k, w = w * wn) { cpx p = x[j + k], q = w * x[i + j + k]; x[j + k] = p + q, x[i + j + k] = p - q; } } } } void Mul(vector<int> &a, vector<int> &b, vector<int> &c) { for (N = 1, L = 0, M = b.size() + c.size(); N <= M; N <<= 1) ++L; for (int i = (0), ir = (N - 1); i <= (ir); ++i) R[i] = (R[i >> 1] >> 1) | ((i & 1) << (L - 1)); for (int i = (0), ir = (b.size() - 1); i <= (ir); ++i) PolyA[i].r = b[i]; for (int i = (0), ir = (c.size() - 1); i <= (ir); ++i) PolyA[i].i = c[i]; for (int i = (b.size()), ir = (N - 1); i <= (ir); ++i) PolyA[i].r = 0; for (int i = (c.size()), ir = (N - 1); i <= (ir); ++i) PolyA[i].i = 0; FFT(PolyA); for (int i = (0), ir = (N - 1); i <= (ir); ++i) { int j = (N - 1) & (N - i); cpx ar = (PolyA[i] + PolyA[j].conj()) * cpx(0.5, 0); cpx ai = (PolyA[i] - PolyA[j].conj()) * cpx(0, -0.5); PolyB[j] = ar * ai; } FFT(PolyB); a.resize(b.size() + c.size() + 1); for (int i = (0), ir = (a.size() - 1); i <= (ir); ++i) a[i] = 0; for (int i = (0), ir = (a.size() - 1); i <= (ir); ++i) { long long t = round(PolyB[i].r / N) + a[i]; a[i] = t % B; if (i != a.size() - 1) a[i + 1] += t / B; else assert(t < B); assert(a[i] >= 0); } assert(a.back() < B); while (a.size() > 1 && !a.back()) a.pop_back(); } void Mul(vector<int> &a, vector<int> &b, int c) { a.resize(b.size() + 1); for (int i = (0), ir = (a.size() - 1); i <= (ir); ++i) a[i] = 0; for (int i = (0), ir = (b.size() - 1); i <= (ir); ++i) { a[i] += b[i] * c; if (a[i] < 0) { fprintf(stderr, "wtf\n"); } a[i + 1] += a[i] / B, a[i] %= B; } for (int i = (0), ir = (a.size() - 1); i <= (ir); ++i) assert(a[i] >= 0); assert(a.back() < B); while (a.size() > 1 && !a.back()) a.pop_back(); } bool operator<(const vector<int> &a, const vector<int> &b) { if (a.size() != b.size()) return a.size() < b.size(); for (int i = (a.size() - 1), ir = (0); i >= (ir); --i) if (a[i] != b[i]) return a[i] < b[i]; return 0; } bool operator>=(const vector<int> &a, const vector<int> &b) { return !(a < b); } int n; char Sn[max1]; vector<int> a, b, c, d, e; void qpow(int y) { b.push_back(1), c.push_back(3); for (; y; y >>= 1, Mul(c, c, c)) if (y & 1) Mul(b, b, c); } int main() { scanf("%s", Sn); n = strlen(Sn); if (n == 1) { if (Sn[0] == '1') return puts("1"), 0; } reverse(Sn, Sn + n); int w; for (int i = (0), ir = (n - 1); i <= (ir); ++i) { a.push_back(0); for (int j = (0), jr = (w = min(2, n - 1 - i)); j <= (jr); ++j) a.back() = a.back() * 10 + (Sn[i + w - j] - '0'); i += 2; } w = max(0, (int)((n - 1) * (log(10) / log(3))) - 1); qpow(w); int Ans = INT_MAX, cc = 3 * w; while (b < a) { Mul(d, b, 2); if (d >= a) chkmin(Ans, cc + 2); Mul(d, b, 4); if (d >= a) chkmin(Ans, cc + 4); Mul(d, b, 3), b = d, cc += 3; } printf("%d\n", min(Ans, cc)); return 0; }
10
CPP
n = int(input()) s = list(input()) r = -1 l = n root = [] def find_right(node): global l,r,s,n while n: r += 1 n -= 1 if s[r] == '(': node[2].append([r,-1,[]]) find_right(node[2][-1]) else: node[1] = r return True return False def find_left(node): global l,r,s,n while n: l -= 1 n -= 1 if s[l] == ')': node[2].append([-1,l,[]]) find_left(node[2][-1]) else: node[0] = l return True return False is_correct = True while n: r += 1 n -= 1 if s[r]=='(': root.append([r,-1,[]]) is_correct &= find_right(root[-1]) else: root = [[-1,r,root]] is_correct &= find_left(root[-1]) sol = [[0,1,1]] if is_correct: sol.append([len(root), 1, 1]) for child in root: sol.append([len(child[2])+1, child[0]+1, child[1]+1]) for gr_child in child[2]: if len(gr_child[2]): sol.append([len(root)+len(gr_child[2])+1, gr_child[0]+1, gr_child[1]+1]) print('%d\n%d %d'%tuple(max(sol)))
10
PYTHON3
def solve(): n = input() seq = input() for i in range(len(seq)-1): x, y = seq[i], seq[i+1] if x == '.' and y != '.': first_letter_idx = i+1 if x != '.' and y == '.': last_letter_idx = i if x == 'R' and y == 'L': return f'{i+1} {i+2}' if seq[first_letter_idx] == 'R': return f'{first_letter_idx+1} {last_letter_idx+2}' return f'{last_letter_idx+1} {first_letter_idx}' print(solve())
7
PYTHON3
#include <iostream> #include <vector> #include <algorithm> using namespace std; typedef long long ll; const ll mod = 1e9 + 7; int n,x; ll dp[205][100005]; int s[205]; int mmin = mod; int main() { cin >> n >> x; for(int i = 0; i < n; i++) { cin >> s[i]; mmin = min(mmin,s[i]); } sort(s,s+n); dp[n][x] = 1; int k = x; for(int i = n; i > 0; i--) { for(int j = 0; j <= x; j++) { if(dp[i][j] == 0) continue; dp[i-1][j] = (dp[i-1][j] + dp[i][j] * (i - 1)) % mod; dp[i-1][j % s[i-1]] += dp[i][j]; } } ll ans = 0; for(int i = 0; i < mmin; i++) { // cout << "d[0]["<<i<<"] = "<<dp[0][i] << endl; ans = (ans + (dp[0][i] * i) % mod ) % mod; } cout << ans << endl; }
0
CPP
n=int(input()) count=0 for i in range(2,n+1): if n%i==0: count+=1 print(count)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; long long INF = 10e9 + 7; using namespace std; void cout_vector(vector<long long> &a) { for (auto i : a) cout << i << " "; cout << '\n'; }; void cout_pair(vector<pair<long long, long long>> &a) { for (auto i : a) cout << i.first << " " << i.second << "\n"; cout << '\n'; }; void cout_matrix(vector<vector<long long>> &a) { for (auto i : a) { for (auto j : i) cout << j << " "; cout << '\n'; } cout << '\n'; }; long long max(long long a, long long b) { if (a > b) return a; else return b; } long long min(long long a, long long b) { if (a > b) return b; return a; } long long gcd(long long x, long long y) { while (x && y) x > y ? x %= y : y %= x; return x + y; } long long sum(vector<long long> &a) { long long s = 0; for (long long i = 0; i < a.size(); i++) s += a[i]; return s; } long long comp(vector<long long> &a) { long long ans = 1; for (long long i = 0; i < 5; i++) ans *= a[i]; return ans; } bool da(vector<long long> &a, vector<long long> &binar) { long long n = a.size(); long long ans = 0; for (long long i = 0; i < n; i++) { if (binar[i] == 1) ans += a[i]; else ans += -a[i]; } return (ans == 0); } void solve() { string s; cin >> s; string ans = "NO"; for (long long i = 0; i < 5; i++) { string t; cin >> t; if (t[0] == s[0] || t[1] == s[1]) ans = "YES"; } cout << ans; } int main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); long long t; solve(); return 0; }
7
CPP
#include <bits/stdc++.h> using namespace std; int main() { int a, b, c; int n; cin >> n; int* arr = new int[n]; for (int i = 0; i < n; i++) { cin >> a >> b >> c; if (max(a, max(b, c)) - min(a, min(b, c)) < 3) arr[i] = 0; else arr[i] = abs(a - b) + abs(b - c) + abs(a - c) - 4; } for (int i = 0; i < n; i++) cout << arr[i] << '\n'; }
7
CPP
#include <bits/stdc++.h> using namespace std; using ll = long long; const int N = 5 * (int)1e5; vector<int> conns[N]; int ev[2 * N]; int itv[N]; bool vis[N]; int count(int i) { if (vis[i]) return 0; vis[i] = true; int res = 1; for (auto t : conns[i]) res += count(t); return res; } int main() { ios_base::sync_with_stdio(false); cin.tie(0); int n; cin >> n; for (int i = 0; i < n; ++i) { int a, b; cin >> a >> b; ev[a - 1] = i + 1; ev[b - 1] = -(i + 1); itv[i] = b - 1; } int m = 0; set<int> act; for (int i = 0; i < 2 * n && m < n; ++i) { if (ev[i] > 0) { int j = ev[i] - 1; auto it = act.begin(); while ((it != act.end()) && (*it < itv[j]) && (m < n)) { int t = -ev[*it] - 1; conns[j].push_back(t); conns[t].push_back(j); ++m; ++it; } act.insert(itv[j]); } else { act.erase(i); } } if (m == n - 1 && count(0) == n) cout << "YES\n"; else cout << "NO\n"; }
10
CPP
#include<bits/stdc++.h> using namespace std; int main() { map<long long ,int >ck; int n,s=0,a,b; cin>>n; while(n--){ cin>>a; if(ck[a]==0){ck[a]=1;s++;} else{ck[a]=0;s--;} } cout<<s<<endl; return 0; }
0
CPP
n=int(input()) print(sum([((n//i)*(i+(n//i*i))//2) for i in range(1,n+1)]))
0
PYTHON3
#include <iostream> using namespace std; int main() { int W, a, b; cin >> W >> a >> b; cout << max(abs(a - b) - W, 0) << endl; return 0; }
0
CPP
#include <bits/stdc++.h> #pragma warning(disable : 4996) using namespace std; const int INF = int(1e8); const int mod = int(1e9 + 7); long long gcd(long long a, long long b) { return b ? gcd(b, a % b) : a; } int main() { string n; cin >> n; if (n[((int)(n).size()) - 1] == '1' || n[((int)(n).size()) - 1] == '3' || n[((int)(n).size()) - 1] == '5' || n[((int)(n).size()) - 1] == '7' || n[((int)(n).size()) - 1] == '9') cout << 1; else cout << 0; return 0; }
10
CPP
k = int(input()) while(k>0): n = [int(x) for x in input().split()] if(n[1]!=0): print(str(60*(24-n[0]-1)+(60-n[1])%60)) else: print(str(60*(24-n[0])+(60-n[1])%60)) k=k-1
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { int n, k, v[5050], q, x; scanf("%d %d", &n, &k); for (int i = 0, __l = n; i < __l; ++i) scanf("%d", &v[i]); scanf("%d", &q); while (q--) { scanf("%d", &x); int ans = -1; for (int amt = 1, __l = k; amt <= __l; ++amt) { for (int c = 0, __l = n; c < __l; ++c) { if (x == amt * v[c]) { ans = amt; break; } for (int i = 1, __l = amt - 1; i <= __l; ++i) { int tmp = x - i * v[c]; if (tmp < 0) break; if (tmp % (amt - i) == 0) { tmp /= (amt - i); if (binary_search(v, v + n, tmp)) ans = amt; } } if (ans != -1) break; } if (ans != -1) break; } printf("%d\n", ans); } return 0; }
11
CPP
#include <bits/stdc++.h> using namespace std; struct S { int abre = 0, cierra = 0, completo = 0; }; const int N = 1000005; int n; int t[2 * N]; void build() { for (int i = n - 1; i > 0; --i) { t[i] = t[i << 1] | t[i << 1 | 1]; } } void update(int p, int value) { for (t[p += n] = value; p > 0; p >>= 1) t[p >> 1] = t[p] | t[p ^ 1]; } int query(int l, int r) { int res = 0; for (l += n, r += n; l < r; l >>= 1, r >>= 1) { if (l & 1) res |= t[l++]; if (r & 1) res |= t[--r]; } return __builtin_popcount(res); } int get_mask(char x) { return 1 << (x - 'a'); } int main() { int nn, q, l, x, d, temp, m, p, a, b; char c; string s; cin >> s; n = s.size(); for (int i = 0; i < n; ++i) { t[i + n] = get_mask(s[i]); } build(); cin >> q; while (q--) { cin >> x; if (x == 1) { cin >> a >> c; update(a - 1, get_mask(c)); } else { cin >> a >> b; cout << query(a - 1, b) << "\n"; } } }
10
CPP
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); long long n, m, v, i, j; cin >> n >> m >> v; long long x = n - 2; long long y = ((n - 2) * (n - 1)) / 2; if (y < m - 1) { cout << -1; return 0; } long long p = -1, q = -1; for (i = 1; i <= n; i++) { if (i == v) continue; if (p == -1) p = i; else { q = i; break; } } vector<pair<long long, long long> > ans; ans.push_back(make_pair(p, v)); if (m - 1 < n - 2) { cout << -1; return 0; } long long cnt = 1; for (i = 1; i <= n; i++) { if (cnt == m) break; if (i == p) continue; for (j = i + 1; j <= n; j++) { if (cnt == m) break; if (j == i || j == p) continue; ans.push_back(make_pair(i, j)); cnt++; } } for (i = 0; i < ans.size(); i++) { cout << ans[i].first << " " << ans[i].second << endl; } }
9
CPP
# l = 5 # n = 2 # # # # t = 0 # for _ in range(n): # # f = s[s.find('B'):].find('G') # assert f != -1 # # for j in range(0,f+1): # new_s = s[:f].find('G') # print(s[f], f) # s = input() n = int(str(input()).split(' ')[1]) s = input() for _ in range(n): s = s.replace('BG', 'GB') print(s)
8
PYTHON3
from collections import deque t = int(input()) INF=float('inf') rr = lambda: input() rri = lambda: int(input()) rrm = lambda: list(map(int, input().split())) def solve(N,x,arr): best = 0 sumsofar = 0 for i in range(N): sumsofar += arr[i] if sumsofar % x != 0: best = max(best, i+1) sumsofar = 0 for i in range(N-1, -1, -1): sumsofar += arr[i] if sumsofar % x != 0: best = max(best, (N-1-i)+1) if best == 0: return -1 return best for _ in range(t): n,x=rrm() arr=rrm() print(solve(n,x,arr))
7
PYTHON3
def create_binary_heap(data, lenght): for i in range(lenght): j = max(0, (i - 1) // 2) while data[i] > data[j]: data[i], data[j] = data[j], data[i] i = j j = max(0, (i - 1) // 2) def heap_sort(data): lenght = len(data) for i in range(lenght): create_binary_heap(data, lenght - i) data[lenght - 1 - i], data[0] = max(data[lenght - 1 - i], data[0]), min(data[lenght - 1 - i], data[0]) data = input() data = data.split("+") heap_sort(data) print("+".join(data))
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { int a; scanf("%d", &a); for (int i = 0; i < a; i++) { int l, r; scanf("%d%d", &l, &r); if (l == 1) printf("1 %d\n", r); else printf("%d %d\n", l, l * 2); } }
7
CPP
#include <bits/stdc++.h> using namespace std; bool func(char x, char y) { if (x == y) return true; if (x >= 'a' && x <= 'z' && y >= 'A' && y <= 'Z') if ((int)(x - 'a') == (int)(y - 'A')) return true; if (y >= 'a' && y <= 'z' && x >= 'A' && x <= 'Z') if ((int)(y - 'a') == (int)(x - 'A')) return true; if (y == '1') if (x == 'l' || x == 'I' || x == 'L' || x == 'i') return true; if (x == '1') if (y == 'l' || y == 'I' || y == 'L' || y == 'i') return true; if (y == 'I') if (x == 'l' || x == 'L') return true; if (y == 'i') if (x == 'l' || x == 'L') return true; if (y == 'L') if (x == 'i' || x == 'I') return true; if (y == 'l') if (x == 'i' || x == 'I') return true; if ((y == 'o' || y == 'O') && x == '0') return true; if (y == '0' && (x == 'o' || x == 'O')) return true; return false; } int main() { string s; cin >> s; bool fl = 0; int n; cin >> n; while (n--) { bool f = 1; string t; cin >> t; if (s.size() == t.size()) { for (int i = 0; i < s.size(); i++) if (func(s[i], t[i])) f &= 1; else f &= 0; if (f) fl = 1; } } if (!fl) cout << "Yes"; else cout << "No"; return 0; }
7
CPP
#include <bits/stdc++.h> using namespace std; int main() { string name; int after, before, t; cin >> t; bool ans = false; while (t--) { cin >> name >> before >> after; if (ans) continue; if (before >= 2400 && after > before) { ans = true; } } if (ans) cout << "YES" << endl; else cout << "NO" << endl; }
7
CPP
b,m= 0,0 a = input() for i in a: if ord(i)<96: b+=1 else: m+=1 if b>m: a=a.upper() else: a=a.lower() print(a)
7
PYTHON3
S = input("").split(" ") H = int(S[0]) L = int(S[1]) print(abs(H*H-L*L)/(2*H))
8
PYTHON3
number1 = input() number2 = input() for i in range(len(number1)): if number1[i] == number2[i]: print("0", end='') else: print("1", end='')
7
PYTHON3
w=int(input()) if w<=3: print('NO') elif w%2==0 and w>3: print('YES') else: print('NO')
7
PYTHON3
#include <iostream> #include <vector> #include <algorithm> #define int long long #define rep(i, n) for (i = 0; i < n; i++) using namespace std; typedef pair<int, int> P; int X, K; int r[100000]; int Q; int t[100000], a[100000]; vector<P> query; //(時刻, 内容(-1:ひっくり返す, a[i](>=0):求める)) signed main() { int i; cin >> X >> K; rep(i, K) cin >> r[i]; cin >> Q; rep(i, Q) cin >> t[i] >> a[i]; rep(i, K) query.push_back(P(r[i], -1)); rep(i, Q) query.push_back(P(t[i], a[i])); sort(query.begin(), query.end()); int l = 0, r = X, b = 0, c = X; int dx = -1, prevT = 0; rep(i, query.size()) { int qt = query[i].first; int qa = query[i].second; //更新 if (dx == -1) { int cnt1 = min(b, qt - prevT); int cnt2 = qt - prevT - cnt1; b -= cnt1; c -= cnt1 + cnt2; if (c < b) c = b; l = min(l + cnt2, r); } else { int cnt1 = min(X - c, qt - prevT); int cnt2 = qt - prevT - cnt1; c += cnt1; b += cnt1 + cnt2; if (b > c) b = c; r = max(r - cnt2, l); } prevT = qt; //cout << "debug[l, r, b, c, dx, prevT, qa] = [" << l << ", " << r << ", " << b << "," << c << ", " << dx << ", " << prevT << ", "<< qa << "]" << endl; //クエリ if (qa == -1) { dx *= -1; } else { if (qa <= l) cout << b << endl; else if (qa >= r) cout << c << endl; else cout << b + (qa - l) << endl; } } return 0; }
0
CPP
s=int(input()) a=set() i=1 while True: a.add(s) i+=1 s=s//2 if s%2==0 else 3*s+1 if s in a: print(i) exit()
0
PYTHON3
maxn=1000 s="" for i in range(1,maxn): s+=str(i) n=int(input()) print(s[n-1])
7
PYTHON3
#include <bits/stdc++.h> using namespace std; inline long long read() { char c; long long out = 0, f = 1; for (c = getchar(); (c < '0' || c > '9') && c != '-'; c = getchar()) ; if (c == '-') { f = -1; c = getchar(); } for (; c >= '0' && c <= '9'; c = getchar()) { out = (out << 3) + (out << 1) + c - '0'; } return out * f; } void write(long long x) { if (x < 0) { putchar('-'); write(-x); return; } if (x > 9) { write(x / 10); } putchar(x % 10 + '0'); } int n, l = 1, r = 1000000000; char s[100]; int main() { int i; scanf("%d", &n); if (n == 1) { printf("0 0\n"); fflush(stdout); printf("0 1 1 1\n"); fflush(stdout); return 0; } printf("1 0\n"); fflush(stdout); scanf("%s", s); if (s[0] == 'b') { for (i = 1; i < n - 1; ++i) { printf("1 %d\n", (l + r) / 2); fflush(stdout); scanf("%s", s); if (s[0] == 'b') { l = (l + r) / 2 + 1; } else { r = (l + r) / 2 - 1; } } printf("999999999 %d\n", r); fflush(stdout); scanf("%s", s); if (s[0] == 'b') { printf("0 %d 999999998 %d\n", l, r); fflush(stdout); } else { printf("0 %d 1000000000 %d\n", l, r); fflush(stdout); } } else { for (i = 1; i < n - 1; ++i) { printf("1 %d\n", (l + r) / 2); fflush(stdout); scanf("%s", s); if (s[0] == 'w') { l = (l + r) / 2 + 1; } else { r = (l + r) / 2 - 1; } } printf("999999999 %d\n", r); fflush(stdout); scanf("%s", s); if (s[0] == 'w') { printf("0 %d 999999998 %d\n", l, r); fflush(stdout); } else { printf("0 %d 1000000000 %d\n", l, r); fflush(stdout); } } return 0; }
9
CPP
#include <bits/stdc++.h> using namespace std; void top_dfs(int src, vector<vector<int> >& directed_graph, vector<int>& vis, vector<int>& top_order) { vis[src] = 1; for (int i = 0; i < directed_graph[src].size(); i++) { if (vis[directed_graph[src][i]] == 0) { top_dfs(directed_graph[src][i], directed_graph, vis, top_order); } } top_order.push_back(src); } void solve() { int n, m; cin >> n >> m; vector<int> vis(n + 1, 0); vector<vector<int> > directed_graph(n + 1); vector<int> top_order; vector<pair<int, int> > edges; for (int i = 0; i < m; i++) { int t, u, v; cin >> t >> u >> v; if (t == 1) { directed_graph[u].push_back(v); } edges.push_back(make_pair(u, v)); } for (int i = 1; i <= n; i++) { if (vis[i] == 0) top_dfs(i, directed_graph, vis, top_order); } reverse(top_order.begin(), top_order.end()); int pos[n + 1]; for (int i = 1; i <= n; i++) { pos[top_order[i - 1]] = i; } for (int i = 1; i <= n; i++) { int u = i; for (int j = 0; j < directed_graph[i].size(); j++) { int v = directed_graph[i][j]; if (pos[u] > pos[v]) { cout << "NO" << endl; return; } } } cout << "YES" << endl; for (int i = 0; i < m; i++) { int x = edges[i].first, y = edges[i].second; if (pos[x] < pos[y]) { cout << x << " " << y << endl; } if (pos[y] < pos[x]) { cout << y << " " << x << endl; } } } int main() { int t; cin >> t; for (int i = 0; i < t; i++) solve(); return 0; }
11
CPP
positives = [] negatives = [] zeros = [] n = int(input()) nums = [int(c) for c in input().split()] for e in nums: if e > 0: positives.append(e) elif e < 0: negatives.append(e) else: zeros.append(e) set1 = [] set2 = [] set3 = [] set1.append(negatives.pop()) if not positives: set2.append(negatives.pop()) set2.append(negatives.pop()) else: set2.append(positives.pop()) set3 += zeros set3 += positives set3 += negatives print(len(set1), *set1) print(len(set2), *set2) print(len(set3), *set3)
7
PYTHON3
#include <iostream> using namespace std; int kona, minm; void search(int k, int a, int b, int c){ if(k <= 0){ int am = (a / 5) * 5 * 380 * 0.8 + (a % 5) * 380; int bm = (b / 4) * 4 * 550 * 0.85 + (b % 4) * 550; int cm = (c / 3) * 3 * 850 * 0.88 + (c % 3) * 850; int all = am + bm + cm; if(all < minm) minm = all; return; } if(k >= 200) search(k - 200, a + 1, b, c); if(k >= 300) search(k - 300, a, b + 1, c); if(k >= 500) search(k - 500, a, b, c + 1); } int main(void){ while(cin >> kona && kona != 0){ minm = 100000000; search(kona, 0, 0, 0); cout << minm << endl; } return 0; }
0
CPP
#include <bits/stdc++.h> using namespace std; long long dp[20][50][3000]; int l[20]; map<int, int> m; void init() { memset(dp, -1, sizeof(dp)); int cnt = 0; for (int i = 1; i <= 2520; i++) { if (2520 % i == 0) { m[i] = ++cnt; } } } int gcd(int a, int b) { if (b == 0) return a; return gcd(b, a % b); } int lcm(int a, int b) { if (b == 0) return a; return a * b / gcd(a, b); } long long dfs(int pos, long long pre, bool limits, int mod) { if (pos == 0) { if (pre % mod == 0) { return 1; } else return 0; } if (dp[pos][m[mod]][pre] != -1 && !limits) return dp[pos][m[mod]][pre]; int n = limits ? l[pos] : 9; long long ans = 0; for (int i = 0; i <= n; i++) { int t = lcm(mod, i); ans += dfs(pos - 1, (pre * 10 + i) % 2520, limits && i == l[pos], t); } if (!limits) dp[pos][m[mod]][pre] = ans; return ans; } long long solve(long long a) { long long t = a; int pos = 0; while (a) { l[++pos] = a % 10; a /= 10; } return dfs(pos, 0, true, 1); } int main() { init(); int n; long long a, b; scanf("%d", &n); while (n--) { scanf("%lld%lld", &a, &b); printf("%lld\n", solve(b) - solve(a - 1)); } return 0; }
10
CPP
#include <bits/stdc++.h> using namespace std; const long long MAX = 1000; int main() { long long n; cin >> n; long long k = n / 2520; cout << k << endl; return 0; }
16
CPP
m = input() n = int(input()) for i in range(n): ord = input().split() a,b =map(int,ord[1:3]) if ord[0]=='print': print(m[a:b+1]) elif ord[0]=='reverse': rev = m[a:b+1] m = m[:a]+rev[::-1]+m[b+1:] else: rep = ord[3] m=m[:a]+rep+m[b+1:]
0
PYTHON3
#include <bits/stdc++.h> using namespace std; const long long int N = 1e6 + 5; const long long int mod = 1e9 + 7; const long long int level = 20; long long int dp[2][505][505]; int main() { ios::sync_with_stdio(false); long long int n, k; cin >> n >> k; dp[0][0][0] = 1; for (long long int i = 1; i < n + 1; i++) { long long int x; cin >> x; long long int now = i % 2; long long int last = 1 - now; for (long long int j = 0; j < k + 1; j++) { for (long long int z = 0; z < j + 1; z++) { dp[now][j][z] = dp[last][j][z]; if (j >= x) { dp[now][j][z] |= dp[last][j - x][z]; if (z >= x) dp[now][j][z] |= dp[last][j - x][z - x]; } } } } vector<long long int> ans; for (long long int i = 0; i < k + 1; i++) { if (dp[n % 2][k][i]) ans.push_back(i); } cout << ans.size() << endl; for (long long int i = 0; i < ans.size(); i++) cout << ans[i] << " "; cout << endl; return 0; }
9
CPP
#include <bits/stdc++.h> using namespace std; #define int long long #define rep(i,x) for(int i=0;i<x;++i) const int inf = 1e9; signed main() { int N; while (cin >> N, N) { vector<int> hp(N); rep(i, N) { cin >> hp[i]; } int M; cin >> M; vector<pair<int,int>> S, A; rep(i, M) { string s; int mp, dmg; cin >> s >> mp >> s >> dmg; if (s == "Single") S.push_back(make_pair(mp, dmg)); else A.push_back(make_pair(mp, dmg)); } vector<int> dp1(100010, inf), dp2(100010, inf); dp1[0] = dp2[0] = 0; for (int i = 0; i < S.size(); ++i) { int mp = S[i].first, dmg = S[i].second; for (int j = 0; j <= 100000; ++j) { if (j - dmg >= 0) { dp1[j] = min(dp1[j], dp1[j - dmg] + mp); } else { dp1[j] = min(dp1[j], mp); } } } for (int i = 0; i < A.size(); ++i) { int mp = A[i].first, dmg = A[i].second; for (int j = 0; j <= 100000; ++j) { if (j - dmg >= 0) { dp2[j] = min(dp2[j], dp2[j - dmg] + mp); } else { dp2[j] = min(dp2[j], mp); } } } int mi = inf; for (int a = 0; a <= 100000; ++a) { int sum = dp2[a]; for (int i = 0; i < N; ++i) { if (hp[i] - a >= 0) { sum += dp1[hp[i] - a]; } } mi = min(mi, sum); } cout << mi << endl; } }
0
CPP
#include <bits/stdc++.h> using namespace std; bool cmp(const pair<int, int>& p1, const pair<int, int>& p2) { return p1.first < p2.first; } int markg[105] = {0}, markb[105] = {0}; int main() { int n, m; scanf("%d", &n); scanf("%d", &m); int bh, gh; scanf("%d", &bh); vector<int> vx, v; for (int i = 0; i < bh; i++) { int a; scanf("%d", &a); v.push_back(a); markb[a] = 1; } scanf("%d", &gh); for (int i = 0; i < gh; i++) { int a; scanf("%d", &a); vx.push_back(a); markg[a] = 1; } int day = 0; int cn = 0; while (1) { if (cn >= 100000) break; int idx, idy; idx = day % n; idy = day % m; markb[idx] = max(markb[idx], markg[idy]); markg[idy] = max(markg[idy], markb[idx]); cn++; day++; } for (int i = 0; i < n; i++) { if (markb[i] == 0) { printf( "No" "\n"); return 0; } } for (int i = 0; i < m; i++) { if (markg[i] == 0) { printf( "No" "\n"); return 0; } } printf( "Yes" "\n"); return 0; }
11
CPP
#include<bits/stdc++.h>//AGC019F using namespace std; const int N=1e6+6,MOD=998244353; int fac[N],invfac[N],siz,n,m,ans; int plu(int u,int v){ return (u+v)%MOD; } int dec(int u,int v){ return u<v?u-v+MOD:u-v; } int mul(int u,int v){ return (int)(1LL*u*v%MOD); } int qpow(int u,int v){ int rep=1; while(v){ if(v&1){ rep=mul(rep,u); } u=mul(u,u); v>>=1; } return rep; } int c(int u,int v){ return mul(mul(invfac[v],invfac[u-v]),fac[u]); } int main(){ scanf("%d%d",&n,&m); if(n>m){ swap(n,m); } siz=n+m; fac[0]=1; for(int i=1;i<=siz;i++){ fac[i]=mul(fac[i-1],i); } invfac[siz]=qpow(fac[siz],MOD-2); for(int i=siz-1;~i;i--){ invfac[i]=mul(invfac[i+1],i+1); } for(int i=1;i<=n;i++){ ans=plu(ans,mul(c(n+m-i-i,n-i),c(i+i,i))); } ans=mul(ans,qpow(mul(2,c(n+m,n)),MOD-2)); ans=plu(ans,m); printf("%d\n",ans); // for(int i=0;i<=5;i++){ // for(int j=0;j<=i;j++){ // printf("%d%c",c(i,j)," \n"[i==j]); // } // } return 0; }
0
CPP
#include <bits/stdc++.h> using namespace std; const double eps = 1e-6; const double PI = 3.14159265358979323846264338f; const double pi = acos(-1.0); const int inf = 0x3f3f3f3f; const long long mod = 1e9 + 7; const int MAXN = 50005; inline int read() { int c = 0, f = 1; char ch = getchar(); while (ch < '0' || ch > '9') { if (ch == '-') f = -1; ch = getchar(); } while (ch >= '0' && ch <= '9') { c = c * 10 + ch - '0'; ch = getchar(); } return c * f; } unordered_map<string, int> ma; unordered_map<string, int> ma2; int ans = 0; void dfs(int cnt, string s) { if (ma[s] != 0 && ma2[s] == 0) { ans += ma[s]; ma2[s] = 1; } else { int len = s.length(); for (int i = 0; i < len; i++) { if (s[i] == '?') { dfs(cnt, s.substr(0, i) + s.substr(i + 1, len - i - 1)); for (char j = 'a'; j <= 'e'; j++) { s[i] = j; dfs(cnt, s); } } } } } int main() { int n, m; string s; cin >> n >> m; for (int i = 0; i < n; i++) { cin >> s; ma[s]++; } while (m--) { ans = 0; string ss; cin >> ss; ma2.clear(); int len = ss.length(); int cnt = 0; for (int i = 0; i < len; i++) { if (ss[i] == '?') cnt++; } if (cnt == 0) { if (ma[ss] == 1) ans++; } else dfs(cnt, ss); cout << ans << "\n"; } return 0; }
13
CPP
from math import sqrt , floor n, m = [int(x) for x in input().split()] def cp(x): for y in range(2,floor(sqrt(x)+1)): if x%y == 0: return False else: return True l=[2] for z in range (3,51): if cp(z)==True: l.append(z) l.append(0) if n in l: i = l.index(n) if l[i+1]== m: print("YES") elif l[i+1]!= m or cp(m) == False : print("NO")
7
PYTHON3
#include <bits/stdc++.h> using namespace std; long long A[5 * 1000 + 3][5 * 1000 + 3]; long long sum[5 * 1000 + 3]; int main() { int n, a, b, k; cin >> n >> a >> b >> k; if (a > b) { a = n - a + 1; b = n - b + 1; } for (int j = 1; j <= b / 2; j++) A[j][1] = b - 2; A[b - 1][1] = 0; for (int j = b - 2; j > b / 2; j--) A[j][1] = A[j + 1][1] + 2; for (int i = 2; i <= k; i++) { sum[b] = 0; A[b - 1][i] = 0; for (int j = b - 1; j > 0; j--) sum[j] = (sum[j + 1] + A[j][i - 1]) % (1000 * 1000 * 1000 + 7); for (int j = b - 1; j > b / 2; j--) A[j][i] = (sum[2 * j - b + 1] - A[j][i - 1] + (1000 * 1000 * 1000 + 7)) % (1000 * 1000 * 1000 + 7); for (int j = 1; j <= b / 2; j++) A[j][i] = (sum[1] - A[j][i - 1] + (1000 * 1000 * 1000 + 7)) % (1000 * 1000 * 1000 + 7); } cout << A[a][k]; return 0; }
11
CPP
#include <bits/stdc++.h> using namespace std; string x; int k; int main() { cin >> k >> x; if (k <= 3) { cout << x << endl; return 0; } for (int i = 0; i < (int)(k / 3 - 1); i++) cout << x.substr(i * 3, 3) << "-"; if (k % 3 == 2) cout << x.substr(k - 5, 3) << "-" << x.substr(k - 2, 2) << endl; else if (k % 3 == 1) cout << x.substr(k - 4, 2) << "-" << x.substr(k - 2, 2) << endl; else cout << x.substr(k - 3, 3) << endl; return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; const long long MOD = 998244353; long long qpow(long long x, long long y) { long long ret = 1; while (y) { if (y & 1) ret = ret * x % MOD; y >>= 1; x = x * x % MOD; } return ret % MOD; } int main() { long long n, sum = 0, C = 1; scanf("%lld", &n); for (int i = 1; i <= n; i++) { C = C * (n - i + 1) % MOD * qpow(i, MOD - 2) % MOD; if (i & 1) sum = (sum + C * qpow(3, i) % MOD * qpow(3, n * (n - i))) % MOD; else sum = ((sum - C * qpow(3, i) % MOD * qpow(3, n * (n - i))) % MOD + MOD) % MOD; } sum = sum * 2 % MOD; C = 1; long long ans = 0; for (int i = 0; i < n; i++) { if (i) C = C * (n - i + 1) % MOD * qpow(i, MOD - 2) % MOD; long long tmp = qpow(((1 - qpow(3, i)) % MOD + MOD) % MOD, n); if (n & 1) tmp = (tmp + qpow(3, i * n)) % MOD; else tmp = (tmp - qpow(3, i * n) + MOD) % MOD; if (i & 1) ans = (ans + tmp * C) % MOD; else ans = ((ans - tmp * C) % MOD + MOD) % MOD; } cout << (sum + ans * 3) % MOD << endl; return 0; }
11
CPP
s=input() l=["H","Q","9"] flag=0 for i in s: if i in l: flag=1 break if flag==1: print("YES") else: print("NO")
7
PYTHON3
import bisect s=input() a=[] for x in s: a.append(x) b=set(a) a=list(b) if(len(a)%2==0): print('CHAT WITH HER!') else: print('IGNORE HIM!')
7
PYTHON3
#include <bits/stdc++.h> using namespace std; char s1[100005], s2[100005]; int main() { int len; char *p, *q, c; scanf("%s", s1); strcpy(s2, s1); len = strlen(s1); sort(s1, s1 + len); len -= 1; p = s2; while (len >= 0) { c = s1[len]; q = strchr(p, c); if (q != NULL) { printf("%c", c); p = q + 1; } len--; } return 0; }
7
CPP
#include <bits/stdc++.h> using namespace std; int main() { long long n, c = 0, z = 0; cin >> n; vector<long long> vec; for (long long i = 0; i < n; i++) { long long k; cin >> k; if (k % 2 == 0) { for (long long j = 1; j <= k / 2; j++) { long long num; cin >> num; c += num; } for (long long j = (k / 2) + 1; j <= k; j++) { long long num; cin >> num; z += num; } } else { for (long long j = 1; j <= k / 2; j++) { long long num; cin >> num; c += num; } long long a; cin >> a; vec.push_back(a); for (long long j = (k / 2) + 2; j <= k; j++) { long long num; cin >> num; z += num; } } } sort(vec.rbegin(), vec.rend()); for (long long i = 0; i < vec.size(); i++) { if (i % 2 == 0) { c += vec[i]; } else z += vec[i]; } cout << c << " " << z << endl; }
11
CPP
#include <bits/stdc++.h> using namespace std; template <class T> inline bool chkmin(T& a, T const& b) { return a > b ? a = b, true : false; } template <class T> inline bool chkmax(T& a, T const& b) { return a < b ? a = b, true : false; } const int M = 200005; vector<int> E[M], W[M]; int dfn[M], low[M], stk[M]; int id[M], Son[M], Sz[M], Fa[M], Top[M], dep[M]; int n, m, q, bcc_cnt, dfn_cnt, id_cnt, top; void solve(int u, int v) { int x, w = ++bcc_cnt; do { x = stk[--top]; W[w].push_back(x); } while (x != v); W[u].push_back(w); } void Tarjan(int u, int fa) { dfn[u] = low[u] = ++dfn_cnt; stk[top++] = u; for (auto v : E[u]) if (v != fa) { if (!dfn[v]) { Tarjan(v, u); chkmin(low[u], low[v]); if (dfn[u] <= low[v]) solve(u, v); } else chkmin(low[u], dfn[v]); } } void Get_son(int u) { Sz[u] = 1; for (auto v : W[u]) { Fa[v] = u; dep[v] = dep[u] + (u > n); Get_son(v); Sz[u] += Sz[v]; if (Sz[v] > Sz[Son[u]]) Son[u] = v; } } void Get_top(int u, int p) { Top[u] = p; id[u] = ++id_cnt; if (Son[u]) Get_top(Son[u], p); for (auto v : W[u]) if (!Top[v]) Get_top(v, v); } int LCA(int u, int v) { while (Top[u] != Top[v]) (id[u] < id[v]) ? (v = Fa[Top[v]]) : (u = Fa[Top[u]]); return id[u] < id[v] ? u : v; } int main() { scanf("%d %d %d", &n, &m, &q); while (m--) { int u, v; scanf("%d %d", &u, &v); E[u].push_back(v); E[v].push_back(u); } bcc_cnt = n; Tarjan(1, -1); Get_son(1); Get_top(1, 1); while (q--) { int u, v, w, ans; scanf("%d %d", &u, &v); w = LCA(u, v); ans = dep[u] + dep[v] - dep[w] * 2; if (w > n) --ans; printf("%d\n", ans); } return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; int cnt = 0, n, T, c[2000 + 5], e[2000 + 5], t[2000 + 5], num[2000 + 5]; double f[2000 + 5], P[2000 + 5]; long long p[2000 + 5], g[2000 + 5], s[2000 + 5]; void update(int x, long long a, double b) { if (g[x] < a || g[x] == a && f[x] > b) g[x] = a, f[x] = b; } bool cmp(int a, int b) { return p[a] * (1000000 - p[b]) * t[a] < p[b] * (1000000 - p[a]) * t[b]; } int main() { scanf("%d%d", &n, &T); for (int i = 1; i <= n; i++) { scanf("%lld%d%d%d%lf", s + i, c + i, e + i, t + i, P + i); p[i] = P[i] * 1000000 + 0.5, num[i] = i; } sort(num + 1, num + 1 + n, cmp); for (int i = 1; i <= n; i++) for (int j = T; j >= e[num[i]]; j--) { if (j >= e[num[i]] + t[num[i]]) update(j, g[j - e[num[i]] - t[num[i]]] + (1000000 - p[num[i]]) * c[num[i]] + s[num[i]] * 1000000, (f[j - e[num[i]] - t[num[i]]] + e[num[i]]) * P[num[i]] + j * (1 - P[num[i]])); update(j, g[j - e[num[i]]] + s[num[i]] * 1000000, f[j - e[num[i]]] + e[num[i]]); } for (int i = T; i; i--) update(0, g[i], f[i]); printf("%.10lf %.10lf\n", double(g[0]) / 1000000, f[0]); return 0; }
10
CPP
#include<bits/stdc++.h> using namespace std; int main(){ long long int cnt,t,n,i,a[31]; cin>>t; while(t--){ cin>>n; cnt=0; while(n!=0){ cnt++; n/=2; } cout<<(1<<(cnt-1))-1<<'\n'; } }
7
CPP
n = int(input()) s = input() k = "" vow = "aeiouy" i = 0 while True: if i>len(s)-1 or len(s)==1: break if i+1<len(s) and s[i] in vow and s[i+1] in vow: s = s[:i+1] + s[i+2:] else: i += 1 print(s)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; const int N = (int)1e5 + 5; deque<int> Q; long long q[N * 5]; pair<int, int> f[N * 5]; map<pair<int, int>, bool> mm; int main() { int n, m, b; int mx = 0, tot = 0; ; cin >> n >> m; for (int i = (int)(1); i <= (int)(n); i++) scanf("%d", &b), mx = max(mx, b), Q.push_back(b); for (int i = (int)(1); i <= (int)(m); i++) scanf("%lld", &q[i]); for (int i = (int)(1); i <= (int)((n - 1) * 2); i++) { int x = Q.front(); Q.pop_front(); int y = Q.front(); Q.pop_front(); f[i].first = x, f[i].second = y; if (x > y) Q.push_front(x), Q.push_back(y); else Q.push_front(y), Q.push_back(x); tot++; if (Q.front() == mx) break; } for (int i = (int)(1); i <= (int)(n - 1); i++) { int x = Q.front(); Q.pop_front(); int y = Q.front(); Q.pop_front(); f[tot + i].first = x; f[tot + i].second = y; Q.push_front(x), Q.push_back(y); } for (int i = (int)(1); i <= (int)(m); i++) { if (q[i] <= tot) { printf("%d %d\n", f[q[i]].first, f[q[i]].second); } else { printf("%d %d\n", f[tot + (q[i] - tot - 1) % (n - 1) + 1].first, f[tot + (q[i] - tot - 1) % (n - 1) + 1].second); } } return 0; }
7
CPP
#include <bits/stdc++.h> using namespace std; long long MOD = 1e9 + 7; template <typename T> istream &operator>>(istream &is, vector<T> &arr) { typename vector<T>::iterator a; for (a = arr.begin(); a != arr.end(); a++) { is >> *a; } return is; } template <typename T> ostream &operator<<(ostream &os, vector<T> &arr) { typename vector<T>::iterator a; for (a = arr.begin(); a != arr.end(); a++) { os << *a << " "; } os << endl; return os; } template <typename T, typename U> ostream &operator<<(ostream &os, pair<T, U> &p) { os << p.first << " " << p.second << " "; return os; } long long mul(long long a, long long b, long long md = MOD) { return (a % md * b % md) % md; } long long add(long long a, long long b, long long md = MOD) { long long ans = a + b; if (ans >= md) ans -= md; return ans; } bool valid(int i, int j, int n, int m) { return i >= 0 && i < n && j >= 0 && j < m; } vector<pair<int, int>> dirs = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}}; long long binPow(long long x, long long y) { long long ans = 1; while (y > 0) { if (y % 2 == 1) ans = mul(ans, x); x = mul(x, x); y /= 2; } return ans; } long long modInverse(long long x) { return binPow(x, MOD - 2); } vector<long long> fac(1e6 + 1), inv(1e6 + 1); bool Good(long long x, int a, int b) { while (x) { if (x % 10 != a && x % 10 != b) { return false; } x /= 10; } return true; } int main() { int a, b, n; cin >> a >> b >> n; fac[0] = 1ll; inv[0] = 1ll; for (int i = 1; i <= n; i++) { fac[i] = mul(fac[i - 1], i); inv[i] = modInverse(fac[i]); } if (a > b) swap(a, b); long long ans = 0; int cur = a * n; if (Good(cur, a, b)) ans = add(ans, 1); for (int i = 1; i <= n; i++) { cur += b - a; if (Good(cur, a, b)) ans = add(ans, mul(fac[n], mul(inv[i], inv[n - i]))); } cout << ans << '\n'; }
9
CPP
n=int(input()) a=[] line=input() if line: for x in line.strip().split(): a.append(int(x)) b=sum(a) if n==1: if b==1: print('YES') else: print('NO') elif b==n-1: print('YES') else: print('NO')
7
PYTHON3
def is_palindrome(time): return time == time[::-1] def from_ints_to_time(hour, minute): result = '' if hour < 10: result += '0' result += str(hour) result += ':' if minute < 10: result += '0' result += str(minute) return result def advance(hour, minute): new_minute, new_hour = 0, hour new_minute = minute + 1 if new_minute == 60: new_minute = 0 new_hour = hour + 1 if new_hour == 24: new_hour = 0 return new_hour, new_minute def main(): hour, minute = [int(elem) for elem in input().split(':')] counter = 0 while True: time = from_ints_to_time(hour, minute) if is_palindrome(time): break hour, minute = advance(hour, minute) counter += 1 print(counter) main()
7
PYTHON3
inp1, inp2 = [int(i) for i in input().split()] lista = list() def reverse(n): newStr = "" for c in str(n): newC = 9 - int(c) newStr += str(newC) l = len(str(n)) d = "9"*l d = int(d) newStr = d - int(n) return int(newStr) le = len(str(inp2)) - 1 digit = 5 * (10 ** le) if digit > inp2: print(reverse(inp2)*inp2) elif digit < inp1: print(reverse(inp1)*inp1) else: print(reverse(digit)*digit)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; template <class A, class B> ostream& operator<<(ostream& out, const pair<A, B>& a) { return out << "(" << a.first << ", " << a.second << ")"; } template <class A> ostream& operator<<(ostream& out, const vector<A>& a) { out << "["; for (auto it = a.begin(); it != a.end(); ++it) { if (it != a.begin()) out << ", "; out << *it; } return out << "]"; } mt19937 rnd(time(NULL)); mt19937_64 rnd64(time(NULL)); const int INF = 1e9; const long long INF64 = 1e18; const int MOD = 1e9 + 7; const long double PI = acosl(-1.0); const long double EPS = 1e-9; const int N = 200 * 1000 + 11; int n; int a[N]; bool read() { if (scanf("%d", &n) != 1) return false; for (int i = 0; i < int(n); ++i) scanf("%d", &a[i]); return true; } void solve() { sort(a, a + n); n = unique(a, a + n) - a; int ans = 0; for (int i = 0; i < int(n); ++i) { for (int j = 2 * a[i]; j <= 2 * 1000 * 1000; j += a[i]) { int pos = lower_bound(a, a + n, j) - a - 1; if (pos < n) ans = max(ans, a[pos] % a[i]); } } printf("%d\n", ans); } int main() { cout << fixed << setprecision(10); cerr << fixed << setprecision(10); if (read()) { solve(); } }
10
CPP
n, l = list(map(int, input().split())) a = [0] + list(map(int, input().split())) + [l] a.sort() # print(a) maxm = max(a[1] - a[0], a[-1] - a[-2]) for i in range(n + 1): maxm = max(maxm, (a[i + 1] - a[i])/2) print(maxm)
8
PYTHON3
#include <bits/stdc++.h> using namespace std; string s; bool is_palindrome(int h) { int l = 0; h--; while (h > l) { if (s[l++] != s[h--]) { return 0; } } return 1; } int main() { cin >> s; int ans = 1; int h = s.size(); while (h >= 0) { if (is_palindrome(h) == 0) { ans = 0; break; } else h--; } if (ans == 0) cout << h << endl; else cout << "0" << endl; }
7
CPP
from collections import deque,namedtuple n,m=map(int,input().split()) c=[input() for _ in ' '*n] p=namedtuple('p',['x','y','parent']) visited=[[False for _ in " "*m] for _ in " "*n] y=[-1,0,1,0] x=[0,-1,0,1] def judge( x, y): if(x>=0 and x<n and y>=0 and y<m): return 1 else: #inefficient return 0 def isCyclicUtil(i,j): dq=deque() dq.append(p(i,j,(-1,-1))) while len(dq): q=dq.pop() if visited[q.x][q.y]: return True visited[q.x][q.y]=True for k in range(4): u=q.x+y[k];v=q.y+x[k] if not (judge(u,v) and c[u][v]==c[i][j]):continue if not (u==q.parent[0] and v==q.parent[1]): dq.append(p(u,v,(q.x,q.y))) def iscycle(n,m): for i in range(n): for j in range(m): if visited[i][j]==False: if isCyclicUtil(i,j)==True: return True return False print('Yes' if iscycle(n,m) else 'No')
8
PYTHON3
import sys from collections import deque def II(): return int(sys.stdin.readline()) def LI(): return list(map(int, sys.stdin.readline().split())) def MI(): return map(int, sys.stdin.readline().split()) def SI(): return sys.stdin.readline().strip() def C(n, k, mod): return (FACT(n,mod) * pow((FACT(k,mod)*FACT(n-k,mod))%mod,mod-2, mod))%mod def lcm(a,b): return abs(a*b) // math.gcd(a, b) for _ in range(II()): n = II() s = list(SI()) ans = -1 for i in range(26): temp = chr(i+97) count = 0 tempS = s[:] for j in range(len(s)): if s[j] == temp: count+=1 tempS[j] = '' checkTemp = list("".join(tempS)) if checkTemp == checkTemp[::-1]: if len(checkTemp)%2 == 1: l = r = len(checkTemp)//2 else: l = len(checkTemp)//2-1 r = len(checkTemp)//2 newL = -1 newR = 0 c = -1 for j in range(len(s)): if tempS[j] !='': c+=1 if c == l and newL == -1: newL = j if c == r: newR = j break l = newL r = newR if l != r: count-=r-l-1 l-=1 r+=1 while l >= 0 and r<len(tempS): if tempS[l] == tempS[r] == '': count-=2 l-=1 r+=1 elif tempS[l] == '': l-=1 elif tempS[r] == '': r+=1 else: l-=1 r+=1 # for i in d: # if i > r: # if d.get(l-(i-r)): # count-=2 # d[i] = None # elif i < l: # if d.get(r+l-i): # count-=2 # d[i] = None # else: # if i-l == r-i: # count-=1 # d[i] = None # elif d.get(r-(i-l)): # count-=2 # d[i] = None if ans == -1: ans = count else: ans = min(ans,count) print(ans)
9
PYTHON3
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int n, m, k; cin >> n >> m >> k; cout << ((2 * n * m) - 2) << endl; string f = ""; int flag = 0; for (int i = 0; i < m; i++) { if (flag == 0) { for (int j = 0; j < n - 1; j++) { f += "D"; } if (i < m - 1) { f += "R"; } flag = 1; } else { for (int j = 0; j < n - 1; j++) { f += "U"; } if (i < m - 1) { f += "R"; } flag = 0; } } int len = f.length(); for (int i = len - 1; i >= 0; i--) { if (f[i] == 'D') { f += "U"; } if (f[i] == 'U') { f += "D"; } if (f[i] == 'L') { f += "R"; } if (f[i] == 'R') { f += "L"; } } cout << f << endl; }
9
CPP
#include <bits/stdc++.h> using namespace std; string a, b; int main(void) { ios_base::sync_with_stdio(false); cin >> a >> b; if (a.size() != b.size()) { cout << "NO" << endl; return 0; } bool az = 1, bz = 1; for (char c : a) { if (c == '1') az = 0; } for (char c : b) { if (c == '1') bz = 0; } bool ok = 1; if (az and bz) ok = 1; else if (!az and !bz) ok = 1; else ok = 0; if (ok) cout << "YES" << endl; else cout << "NO" << endl; return 0; }
9
CPP
#include <bits/stdc++.h> using namespace std; typedef long long ll; #define rep(i,a) for(int i=0;i<(a);i++) const ll MOD=1000000007; //const ll MOD=998244353; ll dp[111][5][5][5]; int main(){ int N; cin>>N; dp[0][0][0][0]=1; rep(i,N) rep(j,5) rep(k,5) rep(l,5){ rep(m,4) (dp[i+1][k][l][m+1]+=dp[i][j][k][l])%=MOD; if((j==1&&k==3)||(j==1&&l==3)||(k==3&&l==1)||(k==1&&l==3)){ // AG GA (dp[i+1][k][l][2]+=MOD-dp[i][j][k][l])%=MOD; } if(k==1&&l==2){ // AC (dp[i+1][k][l][3]+=MOD-dp[i][j][k][l])%=MOD; } } ll ans=0; rep(i,4) rep(j,4) rep(k,4) (ans+=dp[N][i+1][j+1][k+1])%=MOD; cout<<ans<<endl; return 0; }
0
CPP
from sys import * n = int(input()) tab = list(map(int, stdin.readline().split())) a = 1000001*[0] max = -1 min = 10000001 xstar = 0 b = 1000001*[0] c = 1000001*[0] for i in range(n): x = tab[i] a[x]+=1 if b[x] == 0: b[x] = i+1 c[x] = i+1 if a[x] > max: xstar = x max = a[x] min = c[x]-b[x] elif a[x] == max and c[x]-b[x] < min: xstar = x max = a[x] min = c[x]-b[x] print(b[xstar], c[xstar])
8
PYTHON3
n = int(input()) a = list(map(int, input().split())) s = set(a) if len(s) > 3: print("NO") exit() if len(s) < 3: print("YES") exit() m = min(s) M = max(s) mid = sum(s) - M - m if M - mid == mid - m: print("YES") else: print("NO")
8
PYTHON3
a=input() str=input() print('YES' if a[0] in str or a[1] in str else 'NO')
7
PYTHON3
#include <iostream> using namespace std; bool isPrime(int n) { for (int p = 3; p * p <= n; p += 2) { if (n % p == 0) return false; } return true; } int main() { int n; cin >> n; int c = 11; cout << c; for (int i = 1; i < n; ++i) { c += 10; while (!isPrime(c)) c += 10; cout << " " << c; } cout << "\n"; return 0; }
0
CPP
t=int(input()) for _ in range(t): a,b,c,d=map(int,input().split()) if b>=a: print(b) else: if d>=c: print(-1) else: dd=1 if (a-b)%(c-d)!=0 else 0 print(b+c*((a-b)//(c-d)+dd))
7
PYTHON3
#include <bits/stdc++.h> using namespace std; const int N = 1e5 + 7; long long mod = (long long)998244353; int n, m; int a[111][111], sum[111]; std::vector<pair<int, int>> pv[111]; int main() { cin >> n >> m; for (int i = 1; i <= m; ++i) { for (int j = 1; j <= n; ++j) { cin >> a[i][j]; sum[j] += a[i][j]; } } for (int i = 1; i <= m; ++i) { for (int j = 1; j <= n - 1; ++j) { pv[j].push_back(make_pair(a[i][n] - a[i][j], i)); } } vector<int> ans; for (int i = 1; i <= m; ++i) ans.push_back(i); for (int i = 1; i <= n - 1; ++i) { sort(pv[i].begin(), pv[i].end(), greater<pair<int, int>>()); int os = sum[n]; int ns = sum[i]; int dif = os - ns; vector<int> tmp; for (int j = 0; j < pv[i].size(); ++j) { if (dif <= 0) break; dif -= pv[i][j].first; tmp.push_back(pv[i][j].second); } if (dif <= 0) { if (tmp.size() < ans.size()) { ans = tmp; } } } cout << ans.size() << endl; for (int i = 0; i < ans.size(); ++i) { printf("%d%c", ans[i], i == ans.size() - 1 ? '\n' : ' '); } if (ans.size() == 0) { cout << endl; } return 0; }
11
CPP
#include <iostream> #include <string> #include <map> using namespace std; int N, Q; int main() { while ( cin >> N >> Q && N ) { map<int,string> start; map<string,int> finish; string name; for ( int i = 0; i < N; i++ ) { int local, western; cin >> name >> local >> western; start[western - local + 1] = name; if ( finish[name] < western ) { finish[name] = western; } } for ( int i = 0; i < Q; i++ ) { int western; cin >> western; bool ok = false; for ( map<int,string>::iterator s = start.begin(); s != start.end(); s++ ) { if ( s->first <= western && finish[s->second] >= western ) { cout << s->second << " " << western - s->first + 1 << endl; ok = true; break; } } if ( ! ok ) { cout << "Unknown" << endl; } } } }
0
CPP
#include <bits/stdc++.h> using namespace std; int func(string s, vector<int> umap) { int i, j, k = 0, ans = 0, y = s.length(); while (1) { for (i = k; i < y; i++) { if (s[i] == '0') break; } if (i == y) return ans + i - k; else if (i > k) { ans += i + 1 - k; k = i; } for (i = k; i < y; i++) { if (s[i] == '1') break; } if (i == y) return ans; int qq = 2 + upper_bound(umap.begin(), umap.end(), i - k) - umap.begin(); int f = 0; if (y - i < qq) { for (j = 1; i + j < y; j++) { if (s[i + j] == '0') break; } if (i + j == y) ans += 2 * (y - i) - 1; else if (j == 1) { ans += y - i; f = 1; } else { f = 1; ans += y - i + j; } } else { int x = 1; for (j = 1; j < qq; j++) { if (s[i + j] == '1') x = 2 * x + 1; else x = 2 * x; } if (x <= i - k + qq) ans++; for (j = 1; j < qq; j++) { if (s[i + j] == '0') break; } if (j == qq) { if (i + qq != y) { ans += 2 * (qq - 1); if (s[i + j] == '0') ans++; f = 1; } else ans += 2 * (qq - 1); } else if (j == 1) { ans += qq - 1; f = 1; } else { ans += qq - 1 + j; f = 1; } } if (f == 0) break; k = i + j; } return ans; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int val = 1; vector<int> umap; for (int i = 2; i < 19; i++) { umap.push_back(val); val = 2 * val + i; } int q; cin >> q; while (q-- > 0) { string s; cin >> s; cout << func(s, umap) << endl; } }
9
CPP
s=input() t=input() a=0 j=0 for i in range (len(t)): if s[j]==t[i]: a=a+1 j=j+1 print(a+1)
7
PYTHON3
#include <bits/stdc++.h> using namespace std; const int N = 100100, M = 200200, P = 1000000007; int ii, i, j, k, n, m, x, y, ans, nn, na, n1, ch, En, np; long long t, a[M], s[N], v, ma, sum; int h[N], dp[N], z[N], pw2[N], p[N]; struct edge { int s, n; long long v; } E[M << 1]; void R(int &x) { x = 0; ch = getchar(); while (ch < '0' || '9' < ch) ch = getchar(); while ('0' <= ch && ch <= '9') x = x * 10 + ch - '0', ch = getchar(); } void R(long long &x) { x = 0; ch = getchar(); while (ch < '0' || '9' < ch) ch = getchar(); while ('0' <= ch && ch <= '9') x = x * 10 + ch - '0', ch = getchar(); } void E_add(int x, int y, long long v) { E[++En].s = y; E[En].v = v; E[En].n = h[x]; h[x] = En; E[++En].s = x; E[En].v = v; E[En].n = h[y]; h[y] = En; } void dfs(int x) { p[++np] = x; z[x] = 1; for (int k = h[x]; k; k = E[k].n) { if (!z[E[k].s]) { dp[E[k].s] = dp[x] + 1; s[E[k].s] = s[x] ^ E[k].v; dfs(E[k].s); } else { if (dp[E[k].s] < dp[x]) { long long t = s[x] ^ s[E[k].s] ^ E[k].v; if (t) a[++na] = t; } } } } int main() { R(n); R(m); for (i = 1; i <= m; i++) { R(x); R(y); R(v); E_add(x, y, v); if (v > ma) ma = v; } nn = 0; while ((1ll << nn + 1) <= ma) nn++; pw2[0] = 1; for (i = 1; i <= nn; i++) pw2[i] = (pw2[i - 1] << 1) % P; for (ii = 1; ii <= n; ii++) if (!z[ii]) { np = na = 0; sum = 0; dfs(ii); for (i = 1; i <= na; i++) { for (j = i + 1; j <= na; j++) if (a[i] < a[j]) { t = a[i]; a[i] = a[j]; a[j] = t; } if (!a[i]) break; k = nn; while (!(a[i] & 1ll << k)) k--; for (j = 1; j <= na; j++) if (j != i && (a[j] & 1ll << k)) a[j] ^= a[i]; } na = i - 1; for (i = 1; i <= na; i++) sum |= a[i]; for (i = nn; i >= 0; i--) { if (sum & 1ll << i) { ans = ((long long)np * (np - 1) / 2 % P * pw2[na - 1] % P * pw2[i] + ans) % P; continue; } n1 = 0; for (j = 1; j <= np; j++) if (s[p[j]] & 1ll << i) n1++; ans = ((long long)(np - n1) * n1 % P * pw2[na] % P * pw2[i] + ans) % P; } } printf("%d\n", ans); }
13
CPP
#include <bits/stdc++.h> using namespace std; int dx4[] = {0, 0, 1, -1}; int dy4[] = {1, -1, 0, 0}; int dx8[] = {0, 0, 1, -1, 1, 1, -1, -1}; int dy8[] = {1, -1, 0, 0, 1, -1, 1, -1}; int dxH[] = {2, 2, -2, -2, 1, 1, -1, -1}; int dyH[] = {1, -1, 1, -1, 2, -2, 2, -2}; const double GRS = (1 + sqrt(5)) / 2; template <typename T> T power(T X, T P) { T ans = (T)1; for (T i = 1; i <= P; i++) { ans = ans * X; } return ans; } template <typename T> T ABS(T A, T B) { T ret = A - B; if (ret < 0) return -ret; return ret; } const long long MOD = 1000000007; const long long BIGMAX = power(2, 63) - 1; template <typename T> T ADD(T X, T Y, T M) { if (X + Y < 0) return (X - M) + Y; else if (X + Y >= M) return X + Y - M; else return X + Y; } template <typename T> T prod(T a, T b, T c) { T x = 0, y = a % c; while (b > 0) { if (b % 2 == 1) { x = ADD(x, y, c); } y = (y * 2) % c; b /= 2; } return x % c; } template <typename T> T bigmod(T a, T b, T c) { T x = (T)1, y = a % c; while (b > 0) { if (b % (T)2 == (T)1) { x = (x * y) % c; } y = (y * y) % c; b /= (T)2; } return x; } template <typename T> T MODINVERSE(T a) { return bigmod(a, MOD - 2); } template <typename T> T GCD(T x, T y) { while (y != 0) { T z = x % y; x = y; y = z; } return x; } bool isvowel(char ch) { ch = toupper(ch); if (ch == 'A' || ch == 'E' || ch == 'I' || ch == 'O' || ch == 'U' || ch == 'Y') return true; return false; } template <typename T> T isleap(T year) { if (year % (T)400 == (T)0 || (year % (T)100 != (T)0 && year % (T)4 == (T)0)) return true; return false; } int main() { int test; scanf("%d", &test); for (int caseno = 1; caseno <= test; caseno++) { long long x, y, p, q; scanf("%lld %lld %lld %lld", &x, &y, &p, &q); long long lo = 0, hi = 1000000000LL, mid, ans = -1; int cnt = 200; while (cnt--) { mid = (lo + hi) / 2; long long Xval = p * mid; long long Yval = q * mid; long long needX = Xval - x; long long needY = Yval - y; if (needX >= 0 && needY >= 0 && needX <= needY) { hi = mid - 1; ans = Yval - y; } else { lo = mid + 1; } } printf("%lld\n", ans); } }
9
CPP
import math def prime(p): if p==1: return 0 if p==2 or p==3: return 1 if p%2==0 or p%3==0: return 0 for i in range(5,int(math.sqrt(p))+1,6): if p%i==0 or p%(i+2)==0: return 0 return 1 for _ in range(int(input())): n,k=map(int,input().split()) if n<=k: print(1) elif prime(n): print(n) else: minipack=math.inf for i in range(1,min(int(math.sqrt(n))+1,k+1)): if n%i==0: minipack=n//i if n//i<=k: minipack=i break print(minipack)
10
PYTHON3
input() a = list(map(int,input().split())) input() b = list(map(int,input().split())) A = set(a) B = set(b) print(1 if B <= A else 0)
0
PYTHON3
#include <bits/stdc++.h> using namespace std; int T, n, ans[100010]; int a[100010]; struct node { int x, id; node(int _x, int _i) { x = _x; id = _i; } bool operator<(const node &a) const { if (x == a.x) return id > a.id; else return x < a.x; } }; priority_queue<node> q; int main() { scanf("%d", &n); for (register int i = 1; i <= n; ++i) scanf("%d", &a[i]); for (register int i = 1; i <= n; ++i) q.push(node(a[i], i)); for (register int i = 1; i <= n; ++i) ans[i] = -1; for (int i = n; i; --i) { while (!q.empty() && q.top().x > a[i]) { ans[q.top().id] = max(ans[q.top().id], i - q.top().id - 1); q.pop(); } } for (register int i = 1; i <= n; ++i) cout << ans[i] << " "; return 0; }
8
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; int x; cin >> x; int p; int a[n]; for (int i = 0; i < n; i++) cin >> a[i]; sort(a, a + n); int f = 0; int flag = 1; int t; int min1 = 501; if (a[(n + 1) / 2 - 1] == x) { t = (n + 1) / 2; flag = 0; } else { for (int i = 0; i < n; i++) { if (a[i] == x) { if (abs((i + 1) - (n + 1) / 2) < min1) { min1 = abs((i + 1) - (n + 1) / 2); t = i + 1; } flag = 0; } } if (flag) { p = upper_bound(a, a + n, x) - a; if (p > n - 1) { cout << n + 1; f = 1; } else { t = p + 1; n = n + 1; } } } if (f == 0 and flag == 0) cout << min(abs((n - t) - t), abs((t - 1) - (n - t))); else if (f == 0 and flag == 1) cout << 1 + min(abs((n - t) - t), abs((t - 1) - (n - t))); return 0; }
9
CPP
n=input() count=len(set(n)) if(count%2==0): print("CHAT WITH HER!") else: print("IGNORE HIM!")
7
PYTHON3
#!/usr/bin/python3 d1,d2,d3 = [int(x) for x in input().strip().split()] print(min(d1+d2+d3,2*d1+2*d2,2*(d1+d3),2*(d2+d3)))
7
PYTHON3
#include <bits/stdc++.h> using namespace std; int q, n, m; pair<int, int> row[50001], col[50001]; set<int> row_white[50001]; char c; int main() { ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); cin >> q; for (int st = 1; st <= q; st++) { cin >> n >> m; for (int i = 1; i <= n; i++) row[i] = {0, i}; for (int i = 1; i <= m; i++) col[i] = {0, i}; for (int i = 1; i <= n; i++) { row_white[i].clear(); for (int j = 1; j <= m; j++) { cin >> c; if (c == '*') { row[i].first++; col[j].first++; } else row_white[i].insert(j); } } sort(row + 1, row + n + 1); sort(col + 1, col + m + 1); int ans = m - row[n].first + n - col[m].first; if (row[n].first == m || col[m].first == n) { cout << ans << endl; continue; } bool found = false; for (int i = n; i >= 1; i--) { if (row[i].first != row[n].first) break; for (int j = m; j >= 1; j--) { if (col[j].first != col[m].first) break; if (row_white[row[i].second].find(col[j].second) != row_white[row[i].second].end()) { ans--; found = true; break; } } if (found) break; } cout << ans << endl; } }
8
CPP
dico = {"R":(1,0),"L":(-1,0),"U":(0,1),"D":(0,-1)} rdico = {"R":(-1,0),"L":(1,0),"U":(0,-1),"D":(0,1)} def make_move(x,y,m,fn = False): if not fn: return (x+dico[m][0],y+dico[m][1]) return (x+rdico[m][0],y+rdico[m][1]) def main(): q = int(input()) for _ in range(q): n = int(input()) s = input() dico = {"0:0":0} x,y = 0,0 sols = [] for xi in range(n): x,y = make_move(x,y,s[xi]) o = str(x) + ":" + str(y) if o in dico: sols.append((xi-dico[o]+1,dico[o],xi)) dico[o] = xi+1 sols.sort(key = lambda x: x[0]) if len(sols) == 0: print(-1) continue print(sols[0][1]+1,sols[0][2]+1) main()
9
PYTHON3
#include <bits/stdc++.h> using namespace std; const long double epsilon = 1e-9; void func(double n, double mu) { map<double, int> m; for (double i = 1.0; i < n + epsilon; i++) for (double j = 1.0; j < mu + epsilon; j++) { if (i * i - j > -epsilon) { m[-i - sqrt(i * i - j)]++; m[-i + sqrt(i * i - j)]++; } } cout << "Size: " << +m.size() << endl; for (map<double, int>::iterator itr = m.begin(); itr != m.end(); ++itr) { if (itr->second > 1) { cout << itr->first << ": " << itr->second << endl; } } } int main() { long long b, c; cin >> b >> c; long long lim = min(2 * b - 1, c); long long ans = 0; long long t; for (long long a = 1; a <= b; a++) { ans += min(a * a, c) * 2; } long long p; bool bu; int odd; for (long long a = 1; a <= lim; a++) { odd = (a % 2 == 1); bu = false; if (a * a <= c && (a + a) <= 2 * b) { bu = true; ans -= 1; } p = min((2 * b - a + odd) / 2, (c / a + odd) / 2); if (p > 0) { ans -= p; bu = true; } if (bu) ans += 1; } cout << ans << endl; return 0; }
11
CPP
#include <bits/stdc++.h> using namespace std; int main() { int n, m, a[50], b, max(0), count(1); cin >> n; for (int i = 0; i < n; ++i) { cin >> a[i]; } cin >> m; for (int i = 0; i < m; ++i) { cin >> b; for (int j = 0; j < n; ++j) { if (b % a[j] == 0) { int x = b / a[j]; if (x > max) { max = x; count = 1; } else if (x == max) { count += 1; } break; } } } cout << count << endl; return 0; }
7
CPP
#include <bits/stdc++.h> using namespace std; const int N = 9; int dx[9] = {-1, -1, -1, 0, 0, 0, 1, 1, 1}; int dy[9] = {-1, 0, 1, -1, 0, 1, -1, 0, 1}; char mp[N][N]; int dfs(int x, int y, int dep) { int i; if (dep == 9) return 1; for (i = 0; i < 9; i++) { int xx = x + dx[i]; int yy = y + dy[i]; if (xx < 1 || xx > 8 || yy < 1 || yy > 8 || xx >= dep && mp[xx - dep + 1][yy] == 'S' || xx >= dep - 1 && mp[xx - dep][yy] == 'S') continue; if (dfs(xx, yy, dep + 1)) return 1; } return 0; } int main() { int i, j; for (i = 1; i <= 8; i++) scanf("%s", mp[i] + 1); if (dfs(8, 1, 1)) printf("WIN\n"); else printf("LOSE\n"); }
7
CPP