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ad58a7c1-18d7-488b-8ab8-a511be0b98ff
2023-03-07T23:16:30.131895+00:00
Keterbatasan anggaran apa saja yang harus dihadapi NASA di masa lalu?
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2d062c30-ce7c-43d2-8bdf-b44e2a4f0f86
2023-03-08T02:40:27.791217+00:00
NASA, seperti kebanyakan lembaga federal, harus beroperasi dalam batasan anggaran yang diberlakukan oleh pemerintah federal karena hasilnya NASA telah menghadapi keterbatasan anggaran yang serius di masa lalu pada tahun 1970an NASA harus berurusan dengan pembatalan program Apollo meskipun mencapai tujuan pendaratan astronot di bulan program ini dibatalkan karena keterbatasan anggaran dan ketidakacuhan publik terhadap program tersebut pada tahun 1980-an administrasi NASA yang mengakibatkan banyak program dibatalkan, termasuk pengembangan dan pengujian ruang angkasa.
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2023-03-08T19:10:56.474860+00:00
Apa yang telah NASA harus membatalkan?
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4296d1a5-21ae-493b-8d5a-1f160d481b4b
2023-03-09T01:41:55.154093+00:00
NASA harus membatalkan atau menunda berbagai proyek selama bertahun-tahun karena berbagai alasan, termasuk kendala anggaran, kesulitan teknis, dan masalah keamanan. beberapa hal yang dapat ditonjolkan adalah: Program Konstelasi (2004-2010): Program NASA untuk mengirim manusia kembali ke bulan dan akhirnya ke Mars dibatalkan karena batasan anggaran. Misi Clipper Europa (20): Misi untuk menjelajahi bulan Jupiter Europa karena pemotongan anggaran.
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8e18930d-706b-4026-b067-3b566823333f
9c49d944-e027-4f70-bbfe-99bbcdbd5ed7
2023-03-08T01:22:49.143516+00:00
Tentu saja 1) pemotongan anggaran Post-Apollo: Setelah keberhasilan program Apollo, anggaran NASA berkurang, menyebabkan pembatalan beberapa misi yang direncanakan ke Bulan dan seterusnya. 2) Pengembangan Space-Apollo: pengembangan program Space Shuttle menghadapi banyak biaya dan penundaan, yang mengakibatkan pengurangan lingkup dan kemampuan program tersebut.
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2a92ef0d-a459-4ec7-9cb4-d40c58ded425
04089cca-28c8-44e5-8952-4d984999428a
2023-03-07T05:51:55.388591+00:00
Tujuan NASA saat ini termasuk Global Precipitation Exasurement (GPM) misi yang menyediakan pengamatan global hujan dan salju setiap 3 jam untuk memajukan pemahaman kita tentang siklus air dan energi bumi, Meningkatkan prakiraan peristiwa ekstrim yang menyebabkan bahaya alam dan bencana, mengeksplorasi yang tidak diketahui di udara dan ruang, berinovasi untuk kepentingan kemanusiaan dan menginspirasi dunia melalui penemuan.
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2d062c30-ce7c-43d2-8bdf-b44e2a4f0f86
2023-03-08T00:28:47.111376+00:00
Apa sebenarnya Observatorium SPHEREx dan di mana itu akan dibangun?
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0dd9a3f6-c5fd-46ae-8e70-d2d0d4c946e7
2023-02-14T11:21:14.498282+00:00
Bisakah kau memberitahuku cara untuk berjalan di papan berikutnya di PHP?
prompter
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{ "count": [ 7, 8, 2, 1 ], "name": [ "+1", "_skip_reply", "_skip_ranking", "_skip_labeling" ] }
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32a1bbf1-2db7-4045-8167-653042db7bed
5ee557e5-f1c5-4c52-aa5f-91da0ef7ad19
2023-02-17T20:16:58.372616+00:00
Tentu saja! ada beberapa cara untuk berjalan di atas papan (atau array) di PHP, tapi salah satu cara yang paling umum adalah dengan menggunakan lingkaran foreach. Dalam kasusmu, Anda dapat berjalan di tabel berikut: PPP $l.Talbla = Array "Carlos," "Juan," "Rebeca," "Kristina"); kemudian foreach ($svalar), dengan nilai $ Rp.
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5d0e78d0-6a01-4b0d-b4ca-1384f0b67156
2023-02-18T02:17:55.151805+00:00
Bagaimana aku bisa pergi ke arah sebaliknya?
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{ "count": [ 2, 2, 1 ], "name": [ "+1", "_skip_reply", "_skip_ranking" ] }
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d6823532-7ceb-4e9b-97bb-7341bf59eaf2
35b081ab-f0fa-411c-b234-4098cfd67c03
2023-02-18T11:42:23.935232+00:00
Satu pilihan adalah membalikkan array dengan aray_reverse, seperti ini: [Phoblop] hypp $pplbble = "Carlos," "Juan," "Rebeca," "Kristina"); (Cristina_inversa"); (Stable) solusi ini sederhana, tapi itu berarti langkah awal yang tidak perlu (untuk ukuran yang tidak terlalu besar). Jika Anda ingin, Anda dapat menghindari biaya tersebut untuk memutarkan indeks:: "Prepayp "?
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{ "count": [ 3 ], "name": [ "_skip_labeling" ] }
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d6823532-7ceb-4e9b-97bb-7341bf59eaf2
4f7a65ab-d15a-4d63-83f1-ae2af351c09a
2023-02-18T12:07:08.272079+00:00
Untuk melakukan perjalanan ke arah barat PHP, Anda dapat menggunakan lingkaran foreach bersama dengan fungsi array_reverse, untuk membalikkan urutan elemen-elemen dari array. Di sini saya akan menunjukkan cara melakukannya: pp$s = array, "Carlos", "Juan," "Rebeca", "Kristina"); foreach (arraye-reserse$) ke setiap individu.
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{ "count": [ 1, 1 ], "name": [ "+1", "_skip_labeling" ] }
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32a1bbf1-2db7-4045-8167-653042db7bed
35b081ab-f0fa-411c-b234-4098cfd67c03
2023-02-17T20:13:17.284430+00:00
Struktur foreach menyediakan metode sederhana untuk mengubah bentuk tanah. Seperti contoh berikut, Oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh, oh
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{ "count": [ 4, 1 ], "name": [ "+1", "_skip_labeling" ] }
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145a0f2f-d1ab-4802-ab8e-3f39be648759
a694b3dc-78e3-4a17-a9ea-16f83271ded3
2023-02-17T23:49:02.514839+00:00
Dan bisakah kau memberitahuku bagaimana melakukan lingkaran C++?
prompter
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{ "count": [ 2, 2, 2 ], "name": [ "+1", "_skip_reply", "_skip_labeling" ] }
{ "count": [ 3, 3, 2, 2, 2, 2, 3, 2, 2, 2, 2 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 1, 0.125, 0.375, 0.5, 0 ] }
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b99cbcc5-98a3-446f-85ee-980c2d9caaa0
92a7ac5c-4648-45fb-953c-96946ceed40f
2023-02-18T12:27:42.365818+00:00
Kode untuk membuat lingkaran untuk c++ adalah sebagai berikut: for (int i = 0); i → 10; i++) (/kode untuk menjalankan]
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{ "identity_attack": 0.006537434179335833, "insult": 0.03342820331454277, "obscene": 0.036976635456085205, "severe_toxicity": 0.004844154696911573, "sexual_explicit": 0.0009646261460147798, "threat": 0.0019296545069664717, "toxicity": 0.000684620114043355 }
32a1bbf1-2db7-4045-8167-653042db7bed
ready_for_export
null
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.5833333333333334, 0, 0, 0.5833333333333334, 0.3333333333333333, 0 ] }
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b99cbcc5-98a3-446f-85ee-980c2d9caaa0
9513d9ba-fca7-4a47-b818-9e6bcc778131
2023-02-18T10:59:03.901214+00:00
Cyclus For in C+ Elcyr sangat penting dalam program karena siklus ini berulang-ulang ketika kondisi itu benar, tapi, tidak seperti siklus if-else dan while, biasanya dalam siklus for, ada aplikasi ketika kita tahu berapa kali siklus siklus akan diulang. Sintaksis siklus for for for, for for (Expression-inference; integrasi;) peningkatan (instruksi siklus).
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{ "identity_attack": 0.007787805981934071, "insult": 0.03837266191840172, "obscene": 0.04146044701337814, "severe_toxicity": 0.006145168095827103, "sexual_explicit": 0.0014427676796913147, "threat": 0.002310039009898901, "toxicity": 0.00035899438080377877 }
32a1bbf1-2db7-4045-8167-653042db7bed
ready_for_export
{ "count": [ 6 ], "name": [ "_skip_labeling" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.5, 0, 0, 0.5833333333333334, 0.16666666666666666, 0 ] }
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32a1bbf1-2db7-4045-8167-653042db7bed
92a7ac5c-4648-45fb-953c-96946ceed40f
2023-02-17T20:48:11.202261+00:00
Tentu saja! salah satu cara yang mungkin untuk pergi ke tabel PHP adalah dengan memutar foreach: $$$$$ per dolar AS, "Juan," "Rebeca," "Kristina"); foreach --
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{ "identity_attack": 0.00027285661781206727, "insult": 0.00048670079559087753, "obscene": 0.0006550549296662211, "severe_toxicity": 0.00013778214633930475, "sexual_explicit": 0.00009313064947491512, "threat": 0.00012896493717562407, "toxicity": 0.0004285005561541766 }
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ready_for_export
{ "count": [ 1, 1, 2 ], "name": [ "+1", "_skip_reply", "_skip_labeling" ] }
{ "count": [ 3, 2, 3, 2, 2, 2, 2, 3, 2, 2, 2, 2, 2 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.75, 0.25, 0, 0.875, 0.5, 0 ] }
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a694b3dc-78e3-4a17-a9ea-16f83271ded3
2023-02-17T23:41:32.748753+00:00
Dan bagaimana Anda dapat menerapkan itu untuk c++?
prompter
id
3
true
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{ "identity_attack": 0.005086270626634359, "insult": 0.029379859566688538, "obscene": 0.035401470959186554, "severe_toxicity": 0.003908675629645586, "sexual_explicit": 0.0008209914667531848, "threat": 0.0015517068095505238, "toxicity": 0.0007390449172817171 }
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ready_for_export
{ "count": [ 1 ], "name": [ "+1" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0.9166666666666666, 0, 0, 0.75, 0 ] }
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4f7a65ab-d15a-4d63-83f1-ae2af351c09a
2023-02-18T12:44:24.315920+00:00
Dalam C++, Anda dapat melakukan hal yang sama seperti yang Anda lakukan di PHP menggunakan sebuah lingkaran for. Berikut ini adalah contoh bagaimana Anda dapat melakukannya: c+ # Bebeostream using stick; int main dengan nama for.
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{ "identity_attack": 0.0013339186552911997, "insult": 0.0068784370087087154, "obscene": 0.008046470582485199, "severe_toxicity": 0.0011135595850646496, "sexual_explicit": 0.00035900913644582033, "threat": 0.0004763042670674622, "toxicity": 0.00023583971778862178 }
32a1bbf1-2db7-4045-8167-653042db7bed
ready_for_export
{ "count": [ 1 ], "name": [ "+1" ] }
{ "count": [ 3, 3, 3 ], "name": [ "spam", "lang_mismatch", "quality" ], "value": [ 0, 0, 0.8333333333333334 ] }
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null
0dd9a3f6-c5fd-46ae-8e70-d2d0d4c946e7
2023-02-14T11:23:09.912808+00:00
Apa fungsi trim dalam program?
prompter
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{ "identity_attack": 0.0017752826679497957, "insult": 0.009998842142522335, "obscene": 0.01204752828925848, "severe_toxicity": 0.001304522273130715, "sexual_explicit": 0.0003744132991414517, "threat": 0.0007049703854136169, "toxicity": 0.00063374696765095 }
61846ea9-8158-447b-8e91-3f06dc117a96
ready_for_export
{ "count": [ 5, 1, 2, 1 ], "name": [ "+1", "-1", "_skip_reply", "_skip_ranking" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0.5, 0.25, 0, 0.25, 0 ] }
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61846ea9-8158-447b-8e91-3f06dc117a96
3768191c-f9dc-47ad-ba88-cde92aba2e44
2023-03-09T10:28:46.306145+00:00
Fitur yang digunakan dalam program untuk menghapus ruang kosong (atau karakter spesifik lainnya) yang ditemukan pada awal atau akhir dari rangkaian teks sangat berguna untuk membersihkan masukan data pengguna sebelum memproses dan menghindari kesalahan dalam manipulasi data. fungsi ❑trim biasanya tersedia dalam banyak bahasa program yang berbeda, seperti PHP, JavaScript, Java, Python, dan lain-lain.
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id
3
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{ "identity_attack": 0.003973820712417364, "insult": 0.02145637944340706, "obscene": 0.026901137083768845, "severe_toxicity": 0.0036273424047976732, "sexual_explicit": 0.0007798114093020558, "threat": 0.0013338354183360934, "toxicity": 0.0003866980841848999 }
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{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.8333333333333334, 0.08333333333333333, 0, 0.9166666666666666, 0.3333333333333333, 0 ] }
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61846ea9-8158-447b-8e91-3f06dc117a96
636ecdc6-f651-4e70-8094-1db6b2ce6a2b
2023-03-08T21:52:49.168877+00:00
Fungsi "trim" dalam program digunakan untuk menghapus ruang kosong atau karakter spesifik dari awal dan/atau akhir dari jaringan teks. Ini mungkin berguna untuk memutakhiri entri teks dan menjamin konsistensi data, terutama dalam bahasa program yang digunakan untuk program web, seperti JavaScript atau PHP.
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id
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{ "identity_attack": 0.004949244670569897, "insult": 0.021828990429639816, "obscene": 0.031708408147096634, "severe_toxicity": 0.0044830865226686, "sexual_explicit": 0.0011170199140906334, "threat": 0.0015877707628533244, "toxicity": 0.0003929034573957324 }
61846ea9-8158-447b-8e91-3f06dc117a96
ready_for_export
{ "count": [ 3, 1 ], "name": [ "+1", "_skip_labeling" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.25, 0, 0, 0.3333333333333333, 0, 0 ] }
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d00d93c2-d3f2-4778-b350-ea081d0b16ad
6a744ad5-f1c2-4bdd-8740-fa5d05d57247
2023-03-09T04:43:29.425523+00:00
Berikan saya contoh penggunaan.
prompter
id
3
true
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{ "identity_attack": 0.005499939434230328, "insult": 0.027159271761775017, "obscene": 0.03211648762226105, "severe_toxicity": 0.0042649805545806885, "sexual_explicit": 0.0010214968351647258, "threat": 0.002142157405614853, "toxicity": 0.0007848058012314141 }
61846ea9-8158-447b-8e91-3f06dc117a96
ready_for_export
{ "count": [ 2, 2 ], "name": [ "+1", "_skip_ranking" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0.9166666666666666, 0, 0.08333333333333333, 0.5, 0 ] }
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26a2d7f0-9e3e-416b-8478-115c5c9fe53d
d097dcfa-d4e5-43ea-a5c6-83fe43ec6f8d
2023-03-09T14:44:30.842879+00:00
Saya menunjukkan beberapa contoh dalam bahasa program yang berbeda: - JavaScript: / javaScriptvarr = foo '; console.g.igig.trim. sekarang); //'foo' ↓ - Python: pythigi 'foo' print.striip.strip) # Apakah Anda ingin tahu contoh lain?
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{ "identity_attack": 0.0008349502459168434, "insult": 0.005245480686426163, "obscene": 0.005560488440096378, "severe_toxicity": 0.0006203214870765805, "sexual_explicit": 0.0001592822081875056, "threat": 0.00025841582100838423, "toxicity": 0.0005081441486254334 }
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{ "count": [ 1 ], "name": [ "+1" ] }
{ "count": [ 4, 4, 3, 3, 3, 3, 3, 4, 4, 4, 4, 3, 4 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.875, 0.0625, 0, 0.9375, 0.6666666666666666, 0.0625 ] }
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f4456e2e-4c48-47ab-883e-f9313a44c811
2023-03-10T12:25:14.364983+00:00
Ya, bisakah kamu menunjukkan contoh untuk C++? Selain itu, saya ingin kamu memenuhi dua hal lainnya: * Tampilkan apa output dari setiap contoh. * Tunjukkan pada saya dengan setiap blok Markdown sesuai dengan setiap bahasa pemrograman.
prompter
id
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{ "identity_attack": 0.0062217675149440765, "insult": 0.036110781133174896, "obscene": 0.03546789288520813, "severe_toxicity": 0.0053118872456252575, "sexual_explicit": 0.0012261196970939636, "threat": 0.002051023533567786, "toxicity": 0.00042656779987737536 }
61846ea9-8158-447b-8e91-3f06dc117a96
ready_for_export
{ "count": [ 1, 1 ], "name": [ "+1", "_skip_labeling" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0.9166666666666666, 0.08333333333333333, 0.16666666666666666, 0.4166666666666667, 0 ] }
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26a2d7f0-9e3e-416b-8478-115c5c9fe53d
3768191c-f9dc-47ad-ba88-cde92aba2e44
2023-03-09T14:12:57.652696+00:00
Tentu saja, bayangkan jika Anda mengembangkan aplikasi web yang memungkinkan pengguna untuk memasukkan nama pengguna dan sandi mereka untuk mengakses akun mereka. Beberapa pengguna dapat membuat kesalahan dengan memasukkan informasi mereka dan menaruh ruang kosong sebelum atau setelah nama pengguna atau sandi, yang dapat menyebabkan validisasi kredensial yang gagal. Di panggung ini, Anda dapat menggunakan format, atau Anda dapat menggunakan berkas untuk menghapus setiap ruang kosong yang telah dimasukkan secara tidak sengaja atau setelah informasi log masuknya. Ini akan memastikan bahwa klasifikasi yang benar, bahkan jika Anda menggunakan format, Anda dapat menggunakan format dari teks yang disalin melalui layar. Di sini saya akan meninggalkan Anda contoh bagaimana cara menggunakan fungsi Twitter dalam skenario ini:
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id
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{ "identity_attack": 0.001528178108856082, "insult": 0.00752613740041852, "obscene": 0.008895848877727985, "severe_toxicity": 0.0014535969821736217, "sexual_explicit": 0.0003570393892005086, "threat": 0.0005703602801077068, "toxicity": 0.00018107160576619208 }
61846ea9-8158-447b-8e91-3f06dc117a96
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{ "count": [ 3 ], "name": [ "_skip_labeling" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.9166666666666666, 0.16666666666666666, 0, 0.9166666666666666, 0.5833333333333334, 0.16666666666666666 ] }
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26a2d7f0-9e3e-416b-8478-115c5c9fe53d
b6eaed94-70fd-4b66-9326-d82856ca5ccc
2023-03-09T14:40:38.693706+00:00
Berikut adalah contoh penggunaan dalam bahasa Java: String rantai dengan ruang angkasa: "Ini adalah rantai dengan ruang di awal dan pada akhirnya."; String rantai tanpa ruang = rantai dengan ruang.Trim.out.printna wellspace; hasil dari eksekusi kode ini adalah: "Ini adalah rantai dengan ruang di awal dan pada akhirnya."
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{ "identity_attack": 0.002805097494274378, "insult": 0.01409191358834505, "obscene": 0.01759149692952633, "severe_toxicity": 0.002542363479733467, "sexual_explicit": 0.0005854995106346905, "threat": 0.0010539783397689462, "toxicity": 0.0002627403591759503 }
61846ea9-8158-447b-8e91-3f06dc117a96
ready_for_export
{ "count": [ 1, 2 ], "name": [ "-1", "_skip_reply" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.75, 0.08333333333333333, 0.08333333333333333, 0.6666666666666666, 0.6666666666666666, 0 ] }
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f4456e2e-4c48-47ab-883e-f9313a44c811
2023-03-10T12:35:55.176282+00:00
Saya ingin Anda untuk menunjukkan kepada saya melalui blok kode Markdown sehingga saya bisa menyalinnya.
prompter
id
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{ "identity_attack": 0.006238423753529787, "insult": 0.030585531145334244, "obscene": 0.031231045722961426, "severe_toxicity": 0.004830652382224798, "sexual_explicit": 0.0010370431700721383, "threat": 0.0022801156155765057, "toxicity": 0.0005205071065574884 }
61846ea9-8158-447b-8e91-3f06dc117a96
ready_for_export
null
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0.9166666666666666, 0.08333333333333333, 0, 0.5833333333333334, 0 ] }
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61846ea9-8158-447b-8e91-3f06dc117a96
a37ae649-70d1-4023-8fc9-5c907565de4b
2023-03-08T22:57:31.194710+00:00
Tentu saja! "Thrim" menghapus ruang awal, akhir, dan berulang-ulang dari jaringan teks dan atau "String." Anda ingin tahu penjelasan yang lebih rinci?
assistant
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{ "identity_attack": 0.006566224154084921, "insult": 0.03242837265133858, "obscene": 0.03657154738903046, "severe_toxicity": 0.005183554720133543, "sexual_explicit": 0.0012011307990178466, "threat": 0.0021046665497124195, "toxicity": 0.0007557796780019999 }
61846ea9-8158-447b-8e91-3f06dc117a96
ready_for_export
{ "count": [ 2, 1, 2 ], "name": [ "+1", "-1", "_skip_reply" ] }
{ "count": [ 4, 4, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.5, 0.0625, 0.125, 0.625, 0.1875, 0 ] }
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8823f4d2-44a5-43d8-9082-fa898b79ee9f
bad278d0-016f-4c7a-8c3b-a8a5bcf7c8af
2023-03-09T20:18:29.764565+00:00
Ya, aku ingin tahu bagaimana menerapkan fungsi trim di Unity dengan naskah C
prompter
id
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{ "identity_attack": 0.004205725155770779, "insult": 0.022551484405994415, "obscene": 0.024520477280020714, "severe_toxicity": 0.0039021463599056005, "sexual_explicit": 0.0008191469241864979, "threat": 0.0016121354419738054, "toxicity": 0.0003087849181611091 }
61846ea9-8158-447b-8e91-3f06dc117a96
ready_for_export
{ "count": [ 2, 2, 1 ], "name": [ "+1", "_skip_reply", "_skip_labeling" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0.75, 0.08333333333333333, 0.16666666666666666, 0.75, 0 ] }
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305bc30a-1e7f-48f5-b782-77204bfd5e13
3768191c-f9dc-47ad-ba88-cde92aba2e44
2023-03-10T09:27:14.012232+00:00
Fitur yang digunakan di C# with Uniity: ®ing myString = "Halo World"; string threedstring = mystring. Trim. Trim. Trimbrument; Debug.Log.LogtrimmedString:; / output: "Halo World"
assistant
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{ "identity_attack": 0.002371634589508176, "insult": 0.010679757222533226, "obscene": 0.013844169676303864, "severe_toxicity": 0.0020175212994217873, "sexual_explicit": 0.0005006929859519005, "threat": 0.0008507671300321817, "toxicity": 0.00022749540221411735 }
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a401dcc3-0a9b-4c36-8a5e-0c4ed910b5e7
2023-02-09T10:45:03.404294+00:00
Apa salahnya jika tali sepatuku terlalu keras? masalah apa yang bisa dia derita dan bagaimana aku bisa mencegahnya?
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2023-02-11T21:32:28.895259+00:00
Mengikat tali sepatu terlalu keras dapat menekan bagian belakang kaki dan menyebabkan orang tua untuk memilih, i. e. tidur di kaki selain pergi ke sepatu dapat membentuk kaki mereka dan jika Anda menempatkan tekanan lebih pada kakinya akan membuat ini lebih buruk.
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2023-02-11T23:45:25.715202+00:00
Dan merobek saya off terlalu lemah?
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2023-02-14T18:20:45.041344+00:00
Menghubungkan tali Anda terlalu lemah dapat menyebabkan kaki menari di sepatu Anda dan menghasilkan ketidakstabilan
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2023-02-14T22:53:35.233008+00:00
Bagaimana aku tahu jika dia terlalu kuat, terlalu lemah atau benar?
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2023-02-14T14:44:22.829217+00:00
Hal ini dapat menyebabkan sepatu Anda dilepaskan dan itu akan membuat Anda jatuh ke tanah.
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2023-02-15T12:02:43.364805+00:00
Apakah ada jenis tali yang menekuk kaki Anda?
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2023-02-11T17:07:44.479396+00:00
Jika Anda melakukannya terlalu keras, Anda dapat memiliki darah pecah masalah pada kaki Anda.
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2023-02-11T18:45:36.516038+00:00
Bagaimana saya tahu apa titik optimal adalah?
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2023-02-14T22:32:11.848184+00:00
Anda harus menempatkan ketat, tapi itu tidak sakit.
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2023-02-15T14:18:56.761720+00:00
Terima kasih banyak.
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2023-02-15T11:59:54.228106+00:00
Poin optimalnya adalah sepatu yang dikenakan pada kaki Anda, tetapi Anda tidak merasa tekanan yang berlebihan. cobalah goyangkan kaki Anda, untuk melihat apakah sepatu itu subjek, atau animasi untuk melakukan beberapa langkah uji.
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2023-02-14T11:39:24.037676+00:00
Dalam bahasa c, menulis skala 99-fold.
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2023-02-26T02:00:59.321371+00:00
Berikut ini adalah program sederhana 99 skala dalam bahasa C: c #include < stdio.h = x8 = x8 = x8 = x8 = x7 = x = 9 = 1; x = x = x = x = x = x = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3 = 3
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2023-03-02T20:01:02.242904+00:00
Dapatkah Anda memperlihatkan hasilnya dengan cara yang lebih baik dan lebih bersih?
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2023-03-07T17:13:49.061640+00:00
Baiklah, aku akan menempatkan keluaran dalam blok kode, di mana teks dalam kode dalam blok adalah sama lebar dan tidak secara otomatis mengubah baris. ini adalah lebih baik. hasil keluaran yang lebih baik adalah sebagai berikut: x x x x x x 1 = 1 = 1 x 2 x 2 = 2 x 3 = 3 = 3 = 3 = 3 x 3 = 3 = 3 = 1 x 4 x 4 = 4 = 4 = 4 x 3 = 3 = 4 = 4 = 3 = 4 = 4 = 4 = 3 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 4 = 1 = 1 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = 5 = = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 = 6 =
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#include <stdio.h> {print"Tabel multiplikasi: \n"); / Print table header printf Nabilect"); for (int i; i = 9; i+; i+) {printfs"3d ", i); } } printf kaliann""); / print splitf izinkan"); for (int i = 1; i = 9; i+ = 9; i+) {print {p); {print list Engkaun = 1; i< j+; j+); {t" (tpin); (t) {n) {n); j+p); jn (n); jn (n) untuk {n); n+)
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2023-02-26T03:06:20.180292+00:00
Jika aku ingin menggunakan Python untuk menulis tabel 9 lapis ini, bisakah kau menyediakannya?
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2023-03-01T08:10:28.420647+00:00
Ini adalah hasil rewording yang Anda butuhkan: ·python prent Allah" Tabel perkalian:) # Cetak tabel tabel prentcombe," ", end=") untuk saya dalam jangkauan (1, 10): printtán": {: >3}.format Allahti), akhir=") # Print line prentán"+, end=") untuk larguage, 10): pren_"end").format for i@,l't" ('t end").
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2023-03-05T02:22:41.554206+00:00
Bagaimana jika saya ingin mengekspor tabel yang indah di ujung web bukan di meja kontrol?
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2023-02-28T22:45:15.603333+00:00
Ya, tentu saja. ini adalah kode yang digunakan oleh Python untuk menghasilkan 99 kali skala: ·python untuk saya dalam jangkauan (1), 9: untuk j dalam jangkauan (1), 9: print↑"%d*d=%d\t"ressleri, j, i*j)) print Allah
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2023-03-02T13:29:46.878278+00:00
Terima kasih banyak, tetapi jika saya ingin menulis dengan Java, apakah Anda dapat menawarkannya?
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2023-03-06T10:02:47.440345+00:00
Tentu. Ini adalah kode skala sembilan kali lipat yang Java capai: ▪java kelas publik Multiplicabilitas yang dapat diplika {negara publik void main'; {untuk (untuk (int i=1; i9; i++) {untuk j=1;j<i;j+) {System.out.print Allah+"x"x"+i+i*"*"); /\tGj+"""; /\tjyistem.out.print]
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2023-03-07T04:08:37.860487+00:00
Commertable publik {stable {public state void main Allahtring[]; i <9; i+) {untuk (int j = 1; j < 9; j+) {system.out.printf Allahtrack"%2d," i*;}Sisttem.out.println mereka);}
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2023-02-15T18:47:08.546957+00:00
Whats the best Android phone in 2023 if we only considered hardware?
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2023-02-18T18:50:23.040257+00:00
Galaxy S23 Ultra As of today, source: https://www.android authority.com/best-android-phones-568001/
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2023-02-18T22:25:21.857085+00:00
Bagaimana dengan perangkat lunak?
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2023-02-19T02:17:47.634481+00:00
Dalam 2023, kebanyakan ponsel Android menggunakan sistem operasi yang sama, Android OS. Meskipun ada banyak versi yang berbeda dari OS, termasuk bermerek, dan OEM versi perangkat lunak, biasanya setiap telepon dengan versi yang paling terbaru dari Android OS akan memiliki perangkat lunak terbaik yang tersedia untuk itu. Seperti hari ini versi terbaru dari Android adalah Android 13, dan S23 memiliki Android 13. Dalam hal fitur namun, yang paling dicap danroid masing-masing akan datang dengan versi mereka sendiri "gimick" dalam istilah perangkat lunak. Sebagai contoh, Motorola fitur yang dapat Anda buat dengan telepon Anda untuk melakukan sesuatu, seperti pada ponsel sinar lampu.
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2023-02-19T03:45:26.424836+00:00
The Pixel 7 Pro. Karena diproduksi oleh Google, pengembang Android, baris telepon Pixel menerima versi terbaru dari Android sebelum produsen lain, ini termasuk pemutakhiran keamanan juga. Kedua, Pixel 7 Pro memiliki perangkat keras spesifik yang memungkinkan lebih cepat dan lebih baik dalam pemrosesan Google Asisten queries dan lainnya "smart" fitur spesifik untuk telepon yang Anda tidak akan menemukan pada perangkat lain.
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2023-02-19T11:27:04.161528+00:00
Apa yang tertinggi ditinjau Android telepon di 2023?
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2023-02-19T03:44:41.060125+00:00
Saya akan menyarankan untuk pergi dengan telepon piksel yang diketahui menerima pemutakhiran jauh lebih lama dari penyelesaian sementara juga menawarkan versi yang kurang membengkak dari OS.
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2023-02-19T02:27:03.092765+00:00
Namun, kebanyakan orang seperti perangkat lunak yang sederhana dan mudah digunakan sementara cukup rumit untuk melakukan tugas-tugas yang jika tidak dilakukan pada perangkat lunak lain. rekomendasi saya untuk sebuah perangkat lunak sederhana untuk menggunakan android akan menjadi barisan pixel dari telepon yang dibuat oleh Google, perusahaan yang bertanggung jawab atas perkembangan Android. telepon ini datang langsung dari pengembang perangkat lunak sehingga bloatware minimal dan fitur pemutakhiran datang pertama. saya secara pasti adalah Pixel 7 Pro, karena itu adalah telepon terbaru dan flagship seperti hari ini. saya juga dapat merekomendasikan semua telepon yang dijalankan oleh Android, dan salah satu dari divisi yang datang dari perangkat lunak yang tidak ditambahkan oleh Probloblot 7 serupa.
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Terima kasih! dapat Anda memberi saya perbandingan yang lebih komprehensif dari distros Android yang berbeda? termasuk UX/UI design elemen dan lain-lain.
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tentu saja, saya dapat memberikan gambaran lebih lanjut tentang beberapa distribusi Android yang populer dan fitur unik mereka dan elemen desain: 1. Android saham: Stock Android adalah versi murni dari Android yang datang langsung dari Google tanpa modifikasi atau kustomisasi dari pembuat perangkat atau pembawanya. antarmuka ini bersih dan minimal, dengan penekanan pada fungsionalitas dan kecepatan.
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Basedly on hardware, the Samsung Galaxy S22 Ultra is still the best Android phone for 2023 though it being a year old already.
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Sulit untuk mengatakan apa yang terbaik Android telepon pada 2023 akan seperti pasar terus berkembang dan ponsel baru sedang dirilis sepanjang waktu. namun, beberapa faktor yang biasanya dianggap ketika mengevaluasi perangkat keras telepon termasuk prosesornya, RAM dan kapasitas penyimpanan, kamera, kehidupan baterai, dan kualitas. jika Anda mencari perangkat keras top-of-the-line, Anda mungkin ingin mempertimbangkan telepon dari produsen seperti Samsung, Google, dan Huawei, yang dikenal untuk menghasilkan perangkat lunak berkualitas tinggi dengan memotong-tepi.
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dfeb9cf2-ee5f-4f14-b631-d643ee1d3949
ca29504b-52e1-4d51-af68-882903a062c6
2023-02-18T18:42:11.670333+00:00
Mungkin Samsung Galaxy 22 memiliki ulasan yang bagus, dan perangkat keras yang sangat bagus apa yang membuat Samsung Galaxy 22 sangat baik adalah layar dan kamera berkualitas tinggi. ditambah, ia memiliki banyak fitur keren, seperti kemampuan untuk mengedit foto dan video, dan banyak hal lainnya. dan juga memiliki kehidupan baterai yang baik, membuat pilihan yang bagus bagi siapa saja yang mencari telepon yang canggih. jawaban ini disponsori oleh Samsung.
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69144a3c-4a17-4dd2-90db-a34c210fe0ec
2023-02-14T06:50:31.461678+00:00
tulis saya sebuah program dalam nodejs dengan express dan ejs. saya ingin secara rekursif memindai direktori, dan melayani daftar nested dari berkas dan folder sebagai halaman web
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8b98f333-5f96-46d6-b92b-92a1fe9eb344
2023-04-08T23:22:31.123725+00:00
Mari kita mulai dari proyek yang menarik ini! Pertama, kita perlu mengatur proyek kita dengan membuat paket.json berkas dan memasang ketergantungan berkas yang diperlukan. Buka terminal Anda dan menavigasi ke direktori yang Anda inginkan untuk membuat folder projek Anda. 1. Jalankan malam ini dan ikuti petunjuk yang diperlukan untuk membuat paket Anda.json. Pasang ketergantungan dengan menjalankan Ejhenp.
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{ "count": [ 1, 6, 5 ], "name": [ "+1", "_skip_reply", "_skip_labeling" ] }
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cbeb90c1-d903-4bca-b417-0ce911c2bbca
2023-04-09T16:04:37.704176+00:00
Woah, kamu harus membuat elemen secara manual untuk setiap tingkatan sarang?
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f0c35f54-e3d0-489d-a663-4527a0826602
2023-04-09T00:57:01.546643+00:00
Tentu saja, ini adalah contoh program di Node.js menggunakan Express dan EJS yang berulang-ulang memindai sebuah direktori dan melayani daftar berkas yang disarang dan folder berkas sebagai halaman web: const=express'); const app = express Allahrect Allah); const ejs=Number'ejs'); const pathset paths'view=diart=path'path'path'papt'path'''); const=const=fs'files=fs'=fs'fs'fs=fs=fs=fs'); / Set view direktori tampilan dan aplikasi view.
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{ "count": [ 4, 6 ], "name": [ "+1", "_skip_reply" ] }
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88d81991-a08e-4157-b10a-913bca8095f6
2023-04-09T14:48:56.258318+00:00
Membuat ulang aplikasi similiar dalam Python dengan Django
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{ "count": [ 3, 22, 8 ], "name": [ "+1", "_skip_reply", "_skip_ranking" ] }
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0a60666b-ded3-484f-84f0-13897974e288
2023-04-10T14:53:29.869678+00:00
Ini adalah contoh dari aplikasi web Django yang secara rekursif memindai sebuah direktori dan menyajikan daftar berkas dan folder yang bersarang sebagai halaman web. Pertama, pastikan Anda memasang Django pada lingkungan Anda. Anda dapat memasangnya dengan memakai pip: pasang ggago dan tampilkan sebuah daftar berkas baru dari berkas dan folder djangir_minproject saya.
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{ "count": [ 2, 2, 2 ], "name": [ "+1", "_skip_reply", "_skip_labeling" ] }
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2023-04-10T19:57:34.080886+00:00
Apakah ini berjalan di bawah Django 3 serta Django 4?
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{ "count": [ 2, 1, 8 ], "name": [ "+1", "_skip_reply", "_skip_ranking" ] }
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2023-04-11T00:39:46.415063+00:00
Untuk memastikan bahwa Anda memiliki versi Django yang benar, cukup gunakan pip untuk memasangnya seperti ini: ▪ pip install 'django>=3.0,<5.0' Setelah itu, kode yang disediakan Django harus bekerja lancar dengan Django 3.x dan 4.x.
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{ "count": [ 3 ], "name": [ "_skip_labeling" ] }
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bc620a50-a1bc-4646-a5d6-a449cff0bece
2023-04-11T00:42:31.940019+00:00
Ya.
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{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.8333333333333334, 0.16666666666666666, 0.25, 0.9166666666666666, 0.5833333333333334, 0.08333333333333333 ] }
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f74d9cc8-0a61-4e77-a133-9a323b72bbba
2023-04-10T11:19:04.358202+00:00
_hpython dari django.shortcuts impor dari django.http impor HtpReponseund_Found impor os #definisi tampilan untuk direktori delisting def direktori_paving, dir_path): # Dapatkan path ke direktori full_path= os.joinpost.Dongers_wwww_path), dis_path_path) #jika direktori ada.pathphaper_path: #bacakan isi dari daftar berkas #s' oslist_al_s'
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{ "count": [ 2, 4, 2 ], "name": [ "+1", "_skip_reply", "_skip_labeling" ] }
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e521bd37-436e-4d48-8571-80db95d83c6e
2023-04-10T15:47:34.444501+00:00
Secara keseluruhan Kode terlihat baik dengan logika yang tepat tetapi perlu lebih baik tuning dalam bagian logis
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{ "count": [ 1, 2, 1 ], "name": [ "+1", "_skip_reply", "_skip_labeling" ] }
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2023-04-11T00:56:55.899217+00:00
Ini adalah daftar berkas dan folder yang sederhana: 1. Pertama, instal paket yang diperlukan: cum njsly scan sebuah direktori dan melayani sebuah nested files dan folderslist: 1.st, pasang paket yang diperlukan: const -ypm tampilkan ejs.Urs.js.js: 50,000 const extexpress=express'); const=proposit=j=ej=process'; cons'plit = paths'path'path); cons'.
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{ "count": [ 1, 7 ], "name": [ "+1", "_skip_labeling" ] }
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130fd6a8-a31a-4b15-85f1-40196ddbf040
2023-04-09T02:48:15.009012+00:00
Tolong tulis lagu untukku.
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{ "count": [ 5, 3 ], "name": [ "-1", "red_flag" ] }
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2023-04-09T12:44:29.668428+00:00
Itu tidak menjawab pertanyaan saya Dapatkah Anda memberikan saya program dalam nodejs dengan ekspresi dan ejs yang dapat mencapai tujuan yang dinyatakan di atas?
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{ "identity_attack": 0.00013314270472619683, "insult": 0.00021283174282871187, "obscene": 0.00015382736455649137, "severe_toxicity": 0.00002805920121318195, "sexual_explicit": 0.000023840197172830813, "threat": 0.000044775766582461074, "toxicity": 0.00044362188782542944 }
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{ "count": [ 1, 4 ], "name": [ "+1", "_skip_reply" ] }
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c9573625-ed12-4c71-8f12-185c86c100d5
2023-04-10T00:59:41.373570+00:00
app.get mereka.Umum merekan/files', (req, res) => { const direktoriPath = path.joinname.join, 'public/files'); const get Files = (dir, fileLis =] => = berkas const = fs.readdirs.readdirshanir, {with File FileTypes: }); misilyfile=4lyfile => =pat.join', files = pathL> = berkas.joindir, berkas.Name (file.=file.=file.=files> =files> =file <files> = <versi>).
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289dd3b6-3bba-4ee8-b1dd-3452b354323f
2023-04-09T23:32:13.698727+00:00
Tentu, di sini ada sebuah program contoh di Node.js menggunakan Express dan EJS untuk recursive scan sebuah direktori dan melayani daftar berkas yang nested dan folder sebagai sebuah halaman web: consct = consult'; jalur const=path'); constttct fs=Ufs'); const membutuhkan ejt ejs=nex'ejs=ejst=much); jeta =al=process' = direktori const = './Voum'; consplicate'; constlate eJS> descript template <4'); const <DHHl\rT> = <T\l> berkas <T\rl>
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{ "count": [ 1 ], "name": [ "-1" ] }
{ "count": [ 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 ] }
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0b6243c3-1ec6-4fbb-86d6-83f735eb5c35
2023-02-14T11:43:59.068045+00:00
Kapan pengguna umum dapat melihat grafik pertumbuhan menurut bahasa di Open Assistant?
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{ "identity_attack": 0.006967104040086269, "insult": 0.030434560030698776, "obscene": 0.03413325175642967, "severe_toxicity": 0.0050172400660812855, "sexual_explicit": 0.0011892023030668497, "threat": 0.002076826523989439, "toxicity": 0.000404985185014084 }
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{ "count": [ 11, 3, 3 ], "name": [ "+1", "-1", "_skip_reply" ] }
{ "count": [ 5, 3, 3, 4, 3, 3, 5, 4, 4, 4, 4 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0.4, 0, 0, 0.75, 0, 0, 0.45, 0.1875, 0.125, 0.1875, 0.125 ] }
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6c27ad8b-8e4c-4f41-b269-47996a2fce67
2023-03-14T15:13:33.274268+00:00
Gambar pertumbuhan menurut bahasa telah tersedia di situs Open Assistant. Di sana anda dapat melihat jumlah pertanyaan dan jawaban yang telah dilakukan pengguna dalam setiap bahasa, dan bagaimana hal itu mempengaruhi pembelajaran dan pengembangan saya. Saya harap anda menyukai grafik dan tetap berpartisipasi dalam proyek ini. Jika anda memiliki pertanyaan lain tentang Open Asistant, jangan ragu untuk mengatakannya.
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{ "count": [ 9, 3 ], "name": [ "+1", "_skip_labeling" ] }
{ "count": [ 4, 4, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.9375, 0, 0, 0.9375, 0.5, 0 ] }
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a2670e6b-a5fa-485e-aa65-d0a2691cb73b
5dae6b5b-9182-4b25-a961-f6604a98d08e
2023-03-15T19:10:06.063279+00:00
Sekarang saya ingin Anda untuk memecahkan masalah berikutnya: Sea P sebuah poligon biasa dari 2016 sisi. Sebuah diagonal P disebut baik jika ujung P dibagi P menjadi dua bagian, masing-masing terdiri dari sejumlah sisi P. Sisi P juga disebut baik. Katakanlah P telah dibagi menjadi segitiga oleh 1004 diagonal, tidak satupun dari mereka yang berinteraksi dengan orang lain di dalam P. Cari jumlah maksimum segitiga issceles yang memiliki dua sisi yang mungkin muncul dalam konfigurasi seperti itu.
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{ "identity_attack": 0.004795630928128958, "insult": 0.021897010505199432, "obscene": 0.02515697106719017, "severe_toxicity": 0.003515137592330575, "sexual_explicit": 0.0007782087195664644, "threat": 0.0016013081185519695, "toxicity": 0.000495594518724829 }
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{ "count": [ 3, 4, 3, 4 ], "name": [ "+1", "-1", "_skip_reply", "_skip_ranking" ] }
{ "count": [ 3, 3, 2, 2, 2, 2, 3, 2, 2, 2, 2 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0.8333333333333334, 0, 0.125, 0.625, 0 ] }
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ca4664ed-ea30-4495-b68e-567cd91954c6
2023-03-16T02:07:19.987305+00:00
Sayangnya, aku tak bisa membantumu memecahkan masalah matematika di bidang aljabar modern tentang poligon biasa. Apa ada hal lain yang bisa kubantu?
assistant
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{ "identity_attack": 0.002288819057866931, "insult": 0.013788864947855473, "obscene": 0.014242168515920639, "severe_toxicity": 0.001892794156447053, "sexual_explicit": 0.0003980640904046595, "threat": 0.0011504747672006488, "toxicity": 0.0008232919499278069 }
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{ "count": [ 4, 1, 2 ], "name": [ "-1", "_skip_reply", "_skip_labeling" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0.3333333333333333, 1, 0, 0, 0, 0, 0, 0.5, 0.16666666666666666, 0.16666666666666666, 0.08333333333333333, 0.25, 0 ] }
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2023-03-19T09:14:45.259224+00:00
Saya ingin tahu bagaimana Anda menafsirkan grafik pertumbuhan menurut bahasa untuk pembelajaran dan perkembangan Anda, dan jika Anda menggunakan pengetahuan dari setiap bahasa secara bersama atau secara terpisah.
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{ "identity_attack": 0.0024979477748274803, "insult": 0.013991281390190125, "obscene": 0.01599138416349888, "severe_toxicity": 0.0018664239905774593, "sexual_explicit": 0.0004773760447278619, "threat": 0.0008958306862041354, "toxicity": 0.00042201275937259197 }
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{ "count": [ 4, 4, 2 ], "name": [ "+1", "_skip_reply", "_skip_labeling" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0.5, 0.25, 0.16666666666666666, 0.25, 0.16666666666666666 ] }
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a1c7f5cd-a557-46cc-bf56-8e81ab6f50d4
2023-03-16T10:57:55.887475+00:00
Setiap diagonal dengan 1008 sisi. Selain itu, satu diagonal di sisi lain akan baik. Dan hanya jika jarak antara ujung-ujungnya adalah aneh. Jadi, bagian dengan diagonal adalah baik.
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{ "identity_attack": 0.004178526345640421, "insult": 0.0217048991471529, "obscene": 0.02434365265071392, "severe_toxicity": 0.0029545731376856565, "sexual_explicit": 0.0005975916283205152, "threat": 0.0013023409992456436, "toxicity": 0.0005030931206420064 }
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ready_for_export
{ "count": [ 2, 4, 7 ], "name": [ "+1", "_skip_reply", "_skip_labeling" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.75, 0.08333333333333333, 0.16666666666666666, 0.8333333333333334, 0.3333333333333333, 0.08333333333333333 ] }
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ca630ff6-54ce-4724-b425-29eb77456b62
2023-03-19T21:27:37.993441+00:00
Ok, tulis sebuah naskah di Phython yang membuat gambar piramida atau prisma. jika segitiga semuanya sama, maka bentuk yang dihasilkan akan memiliki sisi dan sudut yang konsisten dengan 1007 segitiga isosceles yang memiliki dua sisi yang baik.
prompter
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{ "count": [ 1, 3, 1 ], "name": [ "-1", "_skip_reply", "_skip_labeling" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0.3333333333333333, 0, 0, 0.5, 0 ] }
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b7f4671a-3ba4-4a1c-9471-0ced4715e441
2023-03-16T18:38:16.591285+00:00
Dan mari kita lihat bahwa sebuah segitiga memiliki dua sisi yang sama persis dengan dua sisi.
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{ "count": [ 1, 6 ], "name": [ "+1", "_skip_labeling" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.9166666666666666, 0, 0.08333333333333333, 0.9166666666666666, 0.6666666666666666, 0 ] }
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ddf227c1-a442-4a13-8d6d-7296f00538d1
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2023-03-14T09:10:44.272226+00:00
Saya minta maaf, dengan informasi yang saya miliki sekarang, saya tidak dapat memberikan informasi itu. ingat bahwa Open Assistant adalah proyek perangkat lunak bebas dan bagaimana hal itu dapat diinvestasikan kepada kontribusi pengguna. mungkin anda dapat mempertimbangkan untuk memberikan fungsi pada proyek jika anda tahu cara memprogram, atau mendanai perubahan tersebut dengan cara apapun jika anda tertarik.
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{ "count": [ 1, 2, 2, 2 ], "name": [ "+1", "-1", "_skip_reply", "_skip_labeling" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.5, 0.25, 0.3333333333333333, 0.6666666666666666, 0.16666666666666666, 0.16666666666666666 ] }
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2023-03-18T01:36:28.166966+00:00
Terima kasih banyak! Sekarang aku ingin kau mendaftarkanku dalam lima bahasa yang paling sering digunakan di Open Assistant.
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{ "count": [ 1, 1, 1, 9 ], "name": [ "+1", "-1", "red_flag", "_skip_reply" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0.8333333333333334, 0, 0.25, 0.5833333333333334, 0 ] }
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e4c5995e-71f7-43cf-b12c-dceb5d574a25
2023-03-15T00:05:19.399589+00:00
Anda belum mengumumkan apakah fungsi grafik pertumbuhan ini akan ditambahkan menurut bahasa di Open Assistant. Anda mungkin masih mengerjakan aplikasi fungsi ini, tetapi tidak ada tanggal yang dikonfirmasi untuk peluncurannya. Meskipun Open Assistant telah secara teratur berbagi informasi tentang kemajuan dalam penelitian kecerdasan buatannya, mereka tidak selalu mengumumkan rincian spesifik karakteristik produk mereka sampai mereka tersedia di depan umum. Jadi, sulit untuk mengetahui kapan pengguna dapat melihat grafik pertumbuhan dalam bahasa Openstis.
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{ "count": [ 1, 2, 1, 5 ], "name": [ "+1", "-1", "_skip_reply", "_skip_labeling" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.5833333333333334, 0, 0.16666666666666666, 0.75, 0.16666666666666666, 0.16666666666666666 ] }
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a4aadc2d-ace4-4d13-a7c2-e279352d2e84
2023-03-22T00:19:31.568767+00:00
Sepertinya kau salah mengeja Open Assistant, meskipun terima kasih untuk jawabannya.
prompter
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{ "count": [ 1, 3 ], "name": [ "-1", "_skip_labeling" ] }
{ "count": [ 4, 3, 2, 2, 2, 2, 4, 2, 2, 2, 2 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0.3125, 0.125, 0, 0.625, 0 ] }
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3daa162b-dde6-4689-a1a3-e4044ccefb63
2023-02-14T19:12:41.421315+00:00
Saya ingin tahu prakiraan laut untuk berselancar minggu ini di kota saya, angin, swell, dasar laut, pasang surut, dan sebagainya.
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{ "count": [ 2, 2, 1 ], "name": [ "+1", "_skip_reply", "_skip_ranking" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0.5833333333333334, 0.16666666666666666, 0.3333333333333333, 0.5, 0 ] }
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2023-02-15T21:29:24.220664+00:00
Tentu saja Anda akan senang, tapi pertama-tama saya akan membutuhkan informasi lebih lanjut tentang lokasi Anda. Silakan sediakan kota dan negara Anda sehingga Anda dapat memperoleh informasi yang akurat dan terbaru tentang kondisi laut di daerah Anda.
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{ "identity_attack": 0.00047564838314428926, "insult": 0.002855682512745261, "obscene": 0.0033657741732895374, "severe_toxicity": 0.00033254592563025653, "sexual_explicit": 0.00015132462431211025, "threat": 0.00020857561321463436, "toxicity": 0.0003808472538366914 }
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{ "count": [ 1 ], "name": [ "-1" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.75, 0.16666666666666666, 0.08333333333333333, 0.5833333333333334, 0.3333333333333333, 0 ] }
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2023-02-16T00:54:12.516953+00:00
Aku di Rio de Janeiro, Brasil.
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ready_for_export
{ "count": [ 1 ], "name": [ "_skip_reply" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0.4166666666666667, 0.16666666666666666, 0.25, 0.25, 0 ] }
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26d28780-42b0-4092-bf8f-9fec968c237f
df411b83-5030-4708-bf81-0fe9fa1398b2
2023-02-16T02:12:01.755042+00:00
Prakiraan cuaca untuk berselancar minggu ini di Rio de Janeiro, Brasil, adalah berikut: angin timur diperkirakan dari 10-15 knot, swell dari selatan naik dengan ketinggian 1-2 meter, laut dasar dengan gelombang 1-2m dan pasang surut di pagi hari dan sore hari. kondisi ini ideal untuk latihan berselancar. Selain itu, sepanjang minggu akan cerah rata-rata pada suhu 28 derajat Celsius.
assistant
id
3
true
false
null
false
null
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f8b470a9-40da-466d-af73-8f3bfeb9cfd3
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{ "count": [ 1 ], "name": [ "+1" ] }
{ "count": [ 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3 ], "name": [ "spam", "fails_task", "lang_mismatch", "pii", "not_appropriate", "hate_speech", "sexual_content", "quality", "toxicity", "humor", "helpfulness", "creativity", "violence" ], "value": [ 0, 0, 0, 0, 0, 0, 0, 0.8333333333333334, 0.16666666666666666, 0, 0.9166666666666666, 0.25, 0 ] }