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stringlengths 0
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61.9k
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http://rosettacode.org/wiki/Algebraic_data_types | Algebraic data types | Some languages offer direct support for algebraic data types and pattern matching on them. While this of course can always be simulated with manual tagging and conditionals, it allows for terse code which is easy to read, and can represent the algorithm directly.
Task
As an example, implement insertion in a red-black-tree.
A red-black-tree is a binary tree where each internal node has a color attribute red or black. Moreover, no red node can have a red child, and every path from the root to an empty node must contain the same number of black nodes. As a consequence, the tree is balanced, and must be re-balanced after an insertion.
Reference
Red-Black Trees in a Functional Setting
| #Erlang | Erlang |
-module(rbtree).
-export([insert/3, find/2]).
% Node structure: { Key, Value, Color, Smaller, Bigger }
find(_, nil) ->
not_found;
find(Key, { Key, Value, _, _, _ }) ->
{ found, { Key, Value } };
find(Key, { Key1, _, _, Left, _ }) when Key < Key1 ->
find(Key, Left);
find(Key, { Key1, _, _, _, Right }) when Key > Key1 ->
find(Key, Right).
insert(Key, Value, Tree) ->
make_black(ins(Key, Value, Tree)).
ins(Key, Value, nil) ->
{ Key, Value, r, nil, nil };
ins(Key, Value, { Key, _, Color, Left, Right }) ->
{ Key, Value, Color, Left, Right };
ins(Key, Value, { Ky, Vy, Cy, Ly, Ry }) when Key < Ky ->
balance({ Ky, Vy, Cy, ins(Key, Value, Ly), Ry });
ins(Key, Value, { Ky, Vy, Cy, Ly, Ry }) when Key > Ky ->
balance({ Ky, Vy, Cy, Ly, ins(Key, Value, Ry) }).
make_black({ Key, Value, _, Left, Right }) ->
{ Key, Value, b, Left, Right }.
balance({ Kx, Vx, b, Lx, { Ky, Vy, r, Ly, { Kz, Vz, r, Lz, Rz } } }) ->
{ Ky, Vy, r, { Kx, Vx, b, Lx, Ly }, { Kz, Vz, b, Lz, Rz } };
balance({ Kx, Vx, b, Lx, { Ky, Vy, r, { Kz, Vz, r, Lz, Rz }, Ry } }) ->
{ Kz, Vz, r, { Kx, Vx, b, Lx, Lz }, { Ky, Vy, b, Rz, Ry } };
balance({ Kx, Vx, b, { Ky, Vy, r, { Kz, Vz, r, Lz, Rz }, Ry }, Rx }) ->
{ Ky, Vy, r, { Kz, Vz, b, Lz, Rz }, { Kx, Vx, b, Ry, Rx } };
balance({ Kx, Vx, b, { Ky, Vy, r, Ly, { Kz, Vz, r, Lz, Rz } }, Rx }) ->
{ Kz, Vz, r, { Ky, Vy, b, Ly, Lz }, { Kx, Vx, b, Rz, Rx } };
balance(T) ->
T.
|
http://rosettacode.org/wiki/Almost_prime | Almost prime | A k-Almost-prime is a natural number
n
{\displaystyle n}
that is the product of
k
{\displaystyle k}
(possibly identical) primes.
Example
1-almost-primes, where
k
=
1
{\displaystyle k=1}
, are the prime numbers themselves.
2-almost-primes, where
k
=
2
{\displaystyle k=2}
, are the semiprimes.
Task
Write a function/method/subroutine/... that generates k-almost primes and use it to create a table here of the first ten members of k-Almost primes for
1
<=
K
<=
5
{\displaystyle 1<=K<=5}
.
Related tasks
Semiprime
Category:Prime Numbers
| #CLU | CLU | kprime = proc (n,k: int) returns (bool)
f: int := 0
p: int := 2
while f<k & p*p<=n do
while n//p=0 do
n := n/p
f := f+1
end
p := p+1
end
if n>1 then f:=f+1 end
return(f=k)
end kprime
start_up = proc ()
po: stream := stream$primary_output()
for k: int in int$from_to(1,5) do
i: int := 2
c: int := 0
stream$puts(po, "k = " || int$unparse(k) || ":")
while c<10 do
if kprime(i,k) then
stream$putright(po, int$unparse(i), 4)
c := c+1
end
i := i+1
end
stream$putl(po, "")
end
end start_up |
http://rosettacode.org/wiki/Almost_prime | Almost prime | A k-Almost-prime is a natural number
n
{\displaystyle n}
that is the product of
k
{\displaystyle k}
(possibly identical) primes.
Example
1-almost-primes, where
k
=
1
{\displaystyle k=1}
, are the prime numbers themselves.
2-almost-primes, where
k
=
2
{\displaystyle k=2}
, are the semiprimes.
Task
Write a function/method/subroutine/... that generates k-almost primes and use it to create a table here of the first ten members of k-Almost primes for
1
<=
K
<=
5
{\displaystyle 1<=K<=5}
.
Related tasks
Semiprime
Category:Prime Numbers
| #COBOL | COBOL | IDENTIFICATION DIVISION.
PROGRAM-ID. ALMOST-PRIME.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 CONTROL-VARS.
03 K PIC 9.
03 I PIC 999.
03 SEEN PIC 99.
03 N PIC 999.
03 P PIC 99.
03 P-SQUARED PIC 9(4).
03 F PIC 99.
03 N-DIV-P PIC 999V999.
03 FILLER REDEFINES N-DIV-P.
05 NEXT-N PIC 999.
05 FILLER PIC 999.
88 N-DIVS-P VALUE ZERO.
01 OUT-VARS.
03 K-LN PIC X(70).
03 K-LN-PTR PIC 99.
03 LN-HDR.
05 FILLER PIC X(4) VALUE "K = ".
05 K-OUT PIC 9.
05 FILLER PIC X VALUE ":".
03 I-FMT.
05 FILLER PIC X VALUE SPACE.
05 I-OUT PIC ZZ9.
PROCEDURE DIVISION.
BEGIN.
PERFORM K-ALMOST-PRIMES VARYING K FROM 1 BY 1
UNTIL K IS GREATER THAN 5.
STOP RUN.
K-ALMOST-PRIMES.
MOVE SPACES TO K-LN.
MOVE 1 TO K-LN-PTR.
MOVE ZERO TO SEEN.
MOVE K TO K-OUT.
STRING LN-HDR DELIMITED BY SIZE INTO K-LN
WITH POINTER K-LN-PTR.
PERFORM I-K-ALMOST-PRIME VARYING I FROM 2 BY 1
UNTIL SEEN IS EQUAL TO 10.
DISPLAY K-LN.
I-K-ALMOST-PRIME.
MOVE ZERO TO F, P-SQUARED.
MOVE I TO N.
PERFORM PRIME-FACTOR VARYING P FROM 2 BY 1
UNTIL F IS NOT LESS THAN K
OR P-SQUARED IS GREATER THAN N.
IF N IS GREATER THAN 1, ADD 1 TO F.
IF F IS EQUAL TO K,
MOVE I TO I-OUT,
ADD 1 TO SEEN,
STRING I-FMT DELIMITED BY SIZE INTO K-LN
WITH POINTER K-LN-PTR.
PRIME-FACTOR.
MULTIPLY P BY P GIVING P-SQUARED.
DIVIDE N BY P GIVING N-DIV-P.
PERFORM DIVIDE-FACTOR UNTIL NOT N-DIVS-P.
DIVIDE-FACTOR.
MOVE NEXT-N TO N.
ADD 1 TO F.
DIVIDE N BY P GIVING N-DIV-P. |
http://rosettacode.org/wiki/Anagrams | Anagrams | When two or more words are composed of the same characters, but in a different order, they are called anagrams.
Task[edit]
Using the word list at http://wiki.puzzlers.org/pub/wordlists/unixdict.txt,
find the sets of words that share the same characters that contain the most words in them.
Related tasks
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #AutoHotkey | AutoHotkey | FileRead, Contents, unixdict.txt
Loop, Parse, Contents, % "`n", % "`r"
{ ; parsing each line of the file we just read
Loop, Parse, A_LoopField ; parsing each letter/character of the current word
Dummy .= "," A_LoopField
Sort, Dummy, % "D," ; sorting those letters before removing the delimiters (comma)
StringReplace, Dummy, Dummy, % ",", % "", All
List .= "`n" Dummy " " A_LoopField , Dummy := ""
} ; at this point, we have a list where each line looks like <LETTERS><SPACE><WORD>
Count := 0, Contents := "", List := SubStr(List,2)
Sort, List
Loop, Parse, List, % "`n", % "`r"
{ ; now the list is sorted, parse it counting the consecutive lines with the same set of <LETTERS>
Max := (Count > Max) ? Count : Max
StringSplit, LinePart, A_LoopField, % " " ; (LinePart1 are the letters, LinePart2 is the word)
If ( PreviousLinePart1 = LinePart1 )
Count++ , WordList .= "," LinePart2
Else
var_Result .= ( Count <> Max ) ? "" ; don't append if the number of common words is too low
: "`n" Count "`t" PreviousLinePart1 "`t" SubStr(WordList,2)
, WordList := "" , Count := 0
PreviousLinePart1 := LinePart1
}
List := "", var_Result := SubStr(var_Result,2)
Sort, var_Result, R N ; make the higher scores appear first
Loop, Parse, var_Result, % "`n", % "`r"
If ( 1 == InStr(A_LoopField,Max) )
var_Output .= "`n" A_LoopField
Else ; output only those sets of letters that scored the maximum amount of common words
Break
MsgBox, % ClipBoard := SubStr(var_Output,2) ; the result is also copied to the clipboard |
http://rosettacode.org/wiki/Angle_difference_between_two_bearings | Angle difference between two bearings | Finding the angle between two bearings is often confusing.[1]
Task
Find the angle which is the result of the subtraction b2 - b1, where b1 and b2 are the bearings.
Input bearings are expressed in the range -180 to +180 degrees.
The result is also expressed in the range -180 to +180 degrees.
Compute the angle for the following pairs:
20 degrees (b1) and 45 degrees (b2)
-45 and 45
-85 and 90
-95 and 90
-45 and 125
-45 and 145
29.4803 and -88.6381
-78.3251 and -159.036
Optional extra
Allow the input bearings to be any (finite) value.
Test cases
-70099.74233810938 and 29840.67437876723
-165313.6666297357 and 33693.9894517456
1174.8380510598456 and -154146.66490124757
60175.77306795546 and 42213.07192354373
| #Klingphix | Klingphix | include ..\Utilitys.tlhy
:bearing sub 360 mod 540 add 360 mod 180 sub ;
20 45 bearing
-45 45 bearing
-85 90 bearing
-95 90 bearing
-45 125 bearing
-45 145 bearing
29.4803 -88.6381 bearing
-78.3251 -159.036 bearing
-70099.74233810938 29840.67437876723 bearing
-165313.6666297357 33693.9894517456 bearing
1174.8380510598456 -154146.66490124757 bearing
60175.77306795546 42213.07192354373 bearing
pstack
" " input |
http://rosettacode.org/wiki/Anagrams/Deranged_anagrams | Anagrams/Deranged anagrams | Two or more words are said to be anagrams if they have the same characters, but in a different order.
By analogy with derangements we define a deranged anagram as two words with the same characters, but in which the same character does not appear in the same position in both words.
Task[edit]
Use the word list at unixdict to find and display the longest deranged anagram.
Related tasks
Permutations/Derangements
Best shuffle
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #ooRexx | ooRexx | -- This assumes you've already downloaded the following file and placed it
-- in the current directory: http://www.puzzlers.org/pub/wordlists/unixdict.txt
-- There are several different ways of reading the file. I chose the
-- supplier method just because I haven't used it yet in any other examples.
source = .stream~new('unixdict.txt')~supplier
-- this holds our mappings of the anagrams. This is good use for the
-- relation class
anagrams = .relation~new
count = 0 -- this is used to keep track of the maximums
loop while source~available
word = source~item
-- this produces a string consisting of the characters in sorted order
-- Note: the ~~ used to invoke sort makes that message return value be
-- the target array. The sort method does not normally have a return value.
key = word~makearray('')~~sort~tostring("l", "")
-- add this to our mapping. This creates multiple entries for each
-- word that uses the same key
anagrams[key] = word
source~next
end
-- now get the set of unique keys
keys = .set~new~~putall(anagrams~allIndexes)
-- the longest count tracker
longest = 0
-- our list of the longest pairs
pairs = .array~new
loop key over keys
-- don't even bother doing the deranged checks for any key
-- shorter than our current longest
if key~length < longest then iterate
words = anagrams~allAt(key)
-- singletons aren't anagrams at all
newCount = words~items
loop i = 1 to newCount - 1
word1 = words[i]
loop j = 1 to newCount
word2 = words[j]
-- bitxor will have '00'x in every position where these
-- strings match. If found, go around and check the
-- next one
if word1~bitxor(word2)~pos('00'x) > 0 then iterate
-- we have a match
else do
if word1~length > longest then do
-- throw away anything we've gathered so far
pairs~empty
longest = word1~length
end
pairs~append(.array~of(word1, word2))
end
end
end
end
say "The longest deranged anagrams we found are:"
loop pair over pairs
say pair[1] pair[2]
end |
http://rosettacode.org/wiki/Anonymous_recursion | Anonymous recursion | While implementing a recursive function, it often happens that we must resort to a separate helper function to handle the actual recursion.
This is usually the case when directly calling the current function would waste too many resources (stack space, execution time), causing unwanted side-effects, and/or the function doesn't have the right arguments and/or return values.
So we end up inventing some silly name like foo2 or foo_helper. I have always found it painful to come up with a proper name, and see some disadvantages:
You have to think up a name, which then pollutes the namespace
Function is created which is called from nowhere else
The program flow in the source code is interrupted
Some languages allow you to embed recursion directly in-place. This might work via a label, a local gosub instruction, or some special keyword.
Anonymous recursion can also be accomplished using the Y combinator.
Task
If possible, demonstrate this by writing the recursive version of the fibonacci function (see Fibonacci sequence) which checks for a negative argument before doing the actual recursion.
| #Klingphix | Klingphix | include ..\Utilitys.tlhy
:fib %f !f
%fr
[ %n !n
$n 2 <
( [$n]
[$n 1 - $fr eval $n 2 - $fr eval +] )
if
] !fr
$f 0 <
( ["Error: number is negative"]
[$f true $fr if] )
if
;
25 fib ?
msec ?
"End " input |
http://rosettacode.org/wiki/Amicable_pairs | Amicable pairs | Two integers
N
{\displaystyle N}
and
M
{\displaystyle M}
are said to be amicable pairs if
N
≠
M
{\displaystyle N\neq M}
and the sum of the proper divisors of
N
{\displaystyle N}
(
s
u
m
(
p
r
o
p
D
i
v
s
(
N
)
)
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (N))}
)
=
M
{\displaystyle =M}
as well as
s
u
m
(
p
r
o
p
D
i
v
s
(
M
)
)
=
N
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (M))=N}
.
Example
1184 and 1210 are an amicable pair, with proper divisors:
1, 2, 4, 8, 16, 32, 37, 74, 148, 296, 592 and
1, 2, 5, 10, 11, 22, 55, 110, 121, 242, 605 respectively.
Task
Calculate and show here the Amicable pairs below 20,000; (there are eight).
Related tasks
Proper divisors
Abundant, deficient and perfect number classifications
Aliquot sequence classifications and its amicable classification.
| #GFA_Basic | GFA Basic |
OPENW 1
CLEARW 1
'
DIM f%(20001) ! sum of proper factors for each n
FOR i%=1 TO 20000
f%(i%)=@sum_proper_divisors(i%)
NEXT i%
' look for pairs
FOR i%=1 TO 20000
FOR j%=i%+1 TO 20000
IF f%(i%)=j% AND i%=f%(j%)
PRINT "Amicable pair ";i%;" ";j%
ENDIF
NEXT j%
NEXT i%
'
PRINT
PRINT "-- found all amicable pairs"
~INP(2)
CLOSEW 1
'
' Compute the sum of proper divisors of given number
'
FUNCTION sum_proper_divisors(n%)
LOCAL i%,sum%,root%
'
IF n%>1 ! n% must be 2 or larger
sum%=1 ! start with 1
root%=SQR(n%) ! note that root% is an integer
' check possible factors, up to sqrt
FOR i%=2 TO root%
IF n% MOD i%=0
sum%=sum%+i% ! i% is a factor
IF i%*i%<>n% ! check i% is not actual square root of n%
sum%=sum%+n%/i% ! so n%/i% will also be a factor
ENDIF
ENDIF
NEXT i%
ENDIF
RETURN sum%
ENDFUNC
|
http://rosettacode.org/wiki/Animation | Animation |
Animation is integral to many parts of GUIs, including both the fancy effects when things change used in window managers, and of course games. The core of any animation system is a scheme for periodically changing the display while still remaining responsive to the user. This task demonstrates this.
Task
Create a window containing the string "Hello World! " (the trailing space is significant).
Make the text appear to be rotating right by periodically removing one letter from the end of the string and attaching it to the front.
When the user clicks on the (windowed) text, it should reverse its direction.
| #Python | Python | #!/usr/bin/env python3
import sys
from PyQt5.QtCore import QBasicTimer, Qt
from PyQt5.QtGui import QFont
from PyQt5.QtWidgets import QApplication, QLabel
class Marquee(QLabel):
def __init__(self, **kwargs):
super().__init__(**kwargs)
self.right_to_left_direction = True
self.initUI()
self.timer = QBasicTimer()
self.timer.start(80, self)
def initUI(self):
self.setWindowFlags(Qt.FramelessWindowHint)
self.setAttribute(Qt.WA_TranslucentBackground)
self.setText("Hello World! ")
self.setFont(QFont(None, 50, QFont.Bold))
# make more irritating for the authenticity with <marquee> element
self.setStyleSheet("QLabel {color: cyan; }")
def timerEvent(self, event):
i = 1 if self.right_to_left_direction else -1
self.setText(self.text()[i:] + self.text()[:i]) # rotate
def mouseReleaseEvent(self, event): # change direction on mouse release
self.right_to_left_direction = not self.right_to_left_direction
def keyPressEvent(self, event): # exit on Esc
if event.key() == Qt.Key_Escape:
self.close()
app = QApplication(sys.argv)
w = Marquee()
# center widget on the screen
w.adjustSize() # update w.rect() now
w.move(QApplication.instance().desktop().screen().rect().center()
- w.rect().center())
w.show()
sys.exit(app.exec()) |
http://rosettacode.org/wiki/Animate_a_pendulum | Animate a pendulum |
One good way of making an animation is by simulating a physical system and illustrating the variables in that system using a dynamically changing graphical display.
The classic such physical system is a simple gravity pendulum.
Task
Create a simple physical model of a pendulum and animate it.
| #Liberty_BASIC | Liberty BASIC | nomainwin
WindowWidth = 400
WindowHeight = 300
open "Pendulum" for graphics_nsb_nf as #main
#main "down;fill white; flush"
#main "color black"
#main "trapclose [quit.main]"
Angle = asn(1)
DeltaT = 0.1
PendLength = 150
FixX = int(WindowWidth / 2)
FixY = 40
timer 30, [swing]
wait
[swing]
#main "cls"
#main "discard"
PlumbobX = FixX + int(sin(Angle) * PendLength)
PlumbobY = FixY + int(cos(Angle) * PendLength)
AngAccel = -9.81 / PendLength * sin(Angle)
AngVelocity = AngVelocity + AngAccel * DeltaT
Angle = Angle + AngVelocity * DeltaT
#main "backcolor black"
#main "place ";FixX;" ";FixY
#main "circlefilled 3"
#main "line ";FixX;" ";FixY;" ";PlumbobX;" ";PlumbobY
#main "backcolor red"
#main "circlefilled 10"
wait
[quit.main]
close #main
end |
http://rosettacode.org/wiki/Amb | Amb | Define and give an example of the Amb operator.
The Amb operator (short for "ambiguous") expresses nondeterminism. This doesn't refer to randomness (as in "nondeterministic universe") but is closely related to the term as it is used in automata theory ("non-deterministic finite automaton").
The Amb operator takes a variable number of expressions (or values if that's simpler in the language) and yields a correct one which will satisfy a constraint in some future computation, thereby avoiding failure.
Problems whose solution the Amb operator naturally expresses can be approached with other tools, such as explicit nested iterations over data sets, or with pattern matching. By contrast, the Amb operator appears integrated into the language. Invocations of Amb are not wrapped in any visible loops or other search patterns; they appear to be independent.
Essentially Amb(x, y, z) splits the computation into three possible futures: a future in which the value x is yielded, a future in which the value y is yielded and a future in which the value z is yielded. The future which leads to a successful subsequent computation is chosen. The other "parallel universes" somehow go away. Amb called with no arguments fails.
For simplicity, one of the domain values usable with Amb may denote failure, if that is convenient. For instance, it is convenient if a Boolean false denotes failure, so that Amb(false) fails, and thus constraints can be expressed using Boolean expressions like Amb(x * y == 8) which unless x and y add to four.
A pseudo-code program which satisfies this constraint might look like:
let x = Amb(1, 2, 3)
let y = Amb(7, 6, 4, 5)
Amb(x * y = 8)
print x, y
The output is 2 4 because Amb(1, 2, 3) correctly chooses the future in which x has value 2, Amb(7, 6, 4, 5) chooses 4 and consequently Amb(x * y = 8) produces a success.
Alternatively, failure could be represented using strictly Amb():
unless x * y = 8 do Amb()
Or else Amb could take the form of two operators or functions: one for producing values and one for enforcing constraints:
let x = Ambsel(1, 2, 3)
let y = Ambsel(4, 5, 6)
Ambassert(x * y = 8)
print x, y
where Ambassert behaves like Amb() if the Boolean expression is false, otherwise it allows the future computation to take place, without yielding any value.
The task is to somehow implement Amb, and demonstrate it with a program which chooses one word from each of the following four sets of character strings to generate a four-word sentence:
"the" "that" "a"
"frog" "elephant" "thing"
"walked" "treaded" "grows"
"slowly" "quickly"
The constraint to be satisfied is that the last character of each word (other than the last) is the same as the first character of its successor.
The only successful sentence is "that thing grows slowly"; other combinations do not satisfy the constraint and thus fail.
The goal of this task isn't to simply process the four lists of words with explicit, deterministic program flow such as nested iteration, to trivially demonstrate the correct output. The goal is to implement the Amb operator, or a facsimile thereof that is possible within the language limitations.
| #C.23 | C# | using System;
using System.Collections.Generic;
public class Amb : IDisposable
{
List<IValueSet> streams = new List<IValueSet>();
List<IAssertOrAction> assertsOrActions = new List<IAssertOrAction>();
volatile bool stopped = false;
public IAmbValue<T> DefineValues<T>(params T[] values)
{
return DefineValueSet(values);
}
public IAmbValue<T> DefineValueSet<T>(IEnumerable<T> values)
{
ValueSet<T> stream = new ValueSet<T>();
stream.Enumerable = values;
streams.Add(stream);
return stream;
}
public Amb Assert(Func<bool> function)
{
assertsOrActions.Add(new AmbAssert()
{
Level = streams.Count,
IsValidFunction = function
});
return this;
}
public Amb Perform(Action action)
{
assertsOrActions.Add(new AmbAction()
{
Level = streams.Count,
Action = action
});
return this;
}
public void Stop()
{
stopped = true;
}
public void Dispose()
{
RunLevel(0, 0);
if (!stopped)
{
throw new AmbException();
}
}
void RunLevel(int level, int actionIndex)
{
while (actionIndex < assertsOrActions.Count && assertsOrActions[actionIndex].Level <= level)
{
if (!assertsOrActions[actionIndex].Invoke() || stopped)
return;
actionIndex++;
}
if (level < streams.Count)
{
using (IValueSetIterator iterator = streams[level].CreateIterator())
{
while (iterator.MoveNext())
{
RunLevel(level + 1, actionIndex);
}
}
}
}
interface IValueSet
{
IValueSetIterator CreateIterator();
}
interface IValueSetIterator : IDisposable
{
bool MoveNext();
}
interface IAssertOrAction
{
int Level { get; }
bool Invoke();
}
class AmbAssert : IAssertOrAction
{
internal int Level;
internal Func<bool> IsValidFunction;
int IAssertOrAction.Level { get { return Level; } }
bool IAssertOrAction.Invoke()
{
return IsValidFunction();
}
}
class AmbAction : IAssertOrAction
{
internal int Level;
internal Action Action;
int IAssertOrAction.Level { get { return Level; } }
bool IAssertOrAction.Invoke()
{
Action(); return true;
}
}
class ValueSet<T> : IValueSet, IAmbValue<T>, IValueSetIterator
{
internal IEnumerable<T> Enumerable;
private IEnumerator<T> enumerator;
public T Value { get { return enumerator.Current; } }
public IValueSetIterator CreateIterator()
{
enumerator = Enumerable.GetEnumerator();
return this;
}
public bool MoveNext()
{
return enumerator.MoveNext();
}
public void Dispose()
{
enumerator.Dispose();
}
}
}
public interface IAmbValue<T>
{
T Value { get; }
}
public class AmbException : Exception
{
public AmbException() : base("AMB is angry") { }
} |
http://rosettacode.org/wiki/Aliquot_sequence_classifications | Aliquot sequence classifications | An aliquot sequence of a positive integer K is defined recursively as the first member
being K and subsequent members being the sum of the Proper divisors of the previous term.
If the terms eventually reach 0 then the series for K is said to terminate.
There are several classifications for non termination:
If the second term is K then all future terms are also K and so the sequence repeats from the first term with period 1 and K is called perfect.
If the third term would be repeating K then the sequence repeats with period 2 and K is called amicable.
If the Nth term would be repeating K for the first time, with N > 3 then the sequence repeats with period N - 1 and K is called sociable.
Perfect, amicable and sociable numbers eventually repeat the original number K; there are other repetitions...
Some K have a sequence that eventually forms a periodic repetition of period 1 but of a number other than K, for example 95 which forms the sequence 95, 25, 6, 6, 6, ... such K are called aspiring.
K that have a sequence that eventually forms a periodic repetition of period >= 2 but of a number other than K, for example 562 which forms the sequence 562, 284, 220, 284, 220, ... such K are called cyclic.
And finally:
Some K form aliquot sequences that are not known to be either terminating or periodic; these K are to be called non-terminating.
For the purposes of this task, K is to be classed as non-terminating if it has not been otherwise classed after generating 16 terms or if any term of the sequence is greater than 2**47 = 140,737,488,355,328.
Task
Create routine(s) to generate the aliquot sequence of a positive integer enough to classify it according to the classifications given above.
Use it to display the classification and sequences of the numbers one to ten inclusive.
Use it to show the classification and sequences of the following integers, in order:
11, 12, 28, 496, 220, 1184, 12496, 1264460, 790, 909, 562, 1064, 1488, and optionally 15355717786080.
Show all output on this page.
Related tasks
Abundant, deficient and perfect number classifications. (Classifications from only the first two members of the whole sequence).
Proper divisors
Amicable pairs
| #AppleScript | AppleScript | on aliquotSum(n)
if (n < 2) then return 0
set sum to 1
set sqrt to n ^ 0.5
set limit to sqrt div 1
if (limit = sqrt) then
set sum to sum + limit
set limit to limit - 1
end if
repeat with i from 2 to limit
if (n mod i is 0) then set sum to sum + i + n div i
end repeat
return sum
end aliquotSum
on aliquotSequence(k, maxLength, maxN)
-- Generate the sequence within the specified limitations.
set sequence to {k}
set n to k
repeat (maxLength - 1) times
set n to aliquotSum(n)
set repetition to (sequence contains n)
if (repetition) then exit repeat
set end of sequence to n
if ((n = 0) or (n > maxN)) then exit repeat
end repeat
-- Analyse it.
set sequenceLength to (count sequence)
if (sequenceLength is 1) then
set classification to "perfect"
else if (n is 0) then
set classification to "terminating"
else if (n = k) then
if (sequenceLength is 2) then
set classification to "amicable"
else
set classification to "sociable"
end if
else if (repetition) then
if (sequence ends with n) then
set classification to "aspiring"
else
set classification to "cyclic"
end if
else
set classification to "non-terminating"
end if
return {sequence:sequence, classification:classification}
end aliquotSequence
-- Task code:
local output, maxLength, maxN, spacing, astid, k
set output to {""}
set {maxLength, maxN} to {16, 2 ^ 47}
set spacing to " "
set astid to AppleScript's text item delimiters
set AppleScript's text item delimiters to ", "
repeat with k in {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, ¬
11, 12, 28, 496, 220, 1184, 12496, 1264460, 790, 909, 562, 1064, 1488, 1.535571778608E+13}
set thisResult to aliquotSequence(k's contents, maxLength, maxN)
set end of output to text -18 thru -1 of (spacing & k) & ": " & ¬
text 1 thru 17 of (thisResult's classification & spacing) & thisResult's sequence
end repeat
set AppleScript's text item delimiters to linefeed
set output to output as text
set AppleScript's text item delimiters to astid
return output |
http://rosettacode.org/wiki/Address_of_a_variable | Address of a variable |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
| #Arturo | Arturo | x: 2
xInfo: info.get 'x
print [
"address of x:" xInfo\address
"->" from.hex xInfo\address
] |
http://rosettacode.org/wiki/Address_of_a_variable | Address of a variable |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
| #Astro | Astro | var num = 12
var pointer = ptr(num) # get pointer
print pointer # print address
@unsafe # bad idea!
pointer.addr = 0xFFFE # set the address
|
http://rosettacode.org/wiki/Address_of_a_variable | Address of a variable |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
| #AutoHotkey | AutoHotkey | msgbox % &var |
http://rosettacode.org/wiki/AKS_test_for_primes | AKS test for primes | The AKS algorithm for testing whether a number is prime is a polynomial-time algorithm based on an elementary theorem about Pascal triangles.
The theorem on which the test is based can be stated as follows:
a number
p
{\displaystyle p}
is prime if and only if all the coefficients of the polynomial expansion of
(
x
−
1
)
p
−
(
x
p
−
1
)
{\displaystyle (x-1)^{p}-(x^{p}-1)}
are divisible by
p
{\displaystyle p}
.
Example
Using
p
=
3
{\displaystyle p=3}
:
(x-1)^3 - (x^3 - 1)
= (x^3 - 3x^2 + 3x - 1) - (x^3 - 1)
= -3x^2 + 3x
And all the coefficients are divisible by 3, so 3 is prime.
Note:
This task is not the AKS primality test. It is an inefficient exponential time algorithm discovered in the late 1600s and used as an introductory lemma in the AKS derivation.
Task
Create a function/subroutine/method that given
p
{\displaystyle p}
generates the coefficients of the expanded polynomial representation of
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
.
Use the function to show here the polynomial expansions of
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
for
p
{\displaystyle p}
in the range 0 to at least 7, inclusive.
Use the previous function in creating another function that when given
p
{\displaystyle p}
returns whether
p
{\displaystyle p}
is prime using the theorem.
Use your test to generate a list of all primes under 35.
As a stretch goal, generate all primes under 50 (needs integers larger than 31-bit).
References
Agrawal-Kayal-Saxena (AKS) primality test (Wikipedia)
Fool-Proof Test for Primes - Numberphile (Video). The accuracy of this video is disputed -- at best it is an oversimplification.
| #AArch64_Assembly | AArch64 Assembly |
/* ARM assembly AARCH64 Raspberry PI 3B or android 64 bits */
/* program AKS64.s */
/*******************************************/
/* Constantes file */
/*******************************************/
/* for this file see task include a file in language AArch64 assembly*/
.include "../includeConstantesARM64.inc"
.equ MAXI, 64
.equ NUMBERLOOP, 10
/*********************************/
/* Initialized data */
/*********************************/
.data
szMessResult: .asciz " (x-1)^@ = "
szMessResult1: .asciz " @ x^@ "
szMessResPrime: .asciz "Number @ is prime. \n"
szCarriageReturn: .asciz "\n"
/*********************************/
/* UnInitialized data */
/*********************************/
.bss
sZoneConv: .skip 24
qTabCoef: .skip 8 * MAXI
/*********************************/
/* code section */
/*********************************/
.text
.global main
main: // entry of program
mov x4,#1
1: // loop
mov x0,x4
bl computeCoef // compute coefficient
ldr x0,qAdrqTabCoef
mov x0,x4
bl displayCoef // display coefficient
add x4,x4,1
cmp x4,NUMBERLOOP
blt 1b
mov x4,1
2:
mov x0,x4
bl isPrime // is prime ?
cmp x0,1
bne 3f
mov x0,x4
ldr x1,qAdrsZoneConv
bl conversion10 // call decimal conversion
add x1,x1,x0
strb wzr,[x1]
ldr x0,qAdrszMessResPrime
ldr x1,qAdrsZoneConv // insert value conversion in message
bl strInsertAtCharInc
bl affichageMess
3:
add x4,x4,1
cmp x4,MAXI
blt 2b
100: // standard end of the program
mov x0,0 // return code
mov x8,EXIT // request to exit program
svc 0 // perform the system call
qAdrszCarriageReturn: .quad szCarriageReturn
qAdrsZoneConv: .quad sZoneConv
qAdrqTabCoef: .quad qTabCoef
qAdrszMessResPrime: .quad szMessResPrime
/***************************************************/
/* display coefficients */
/***************************************************/
// x0 contains a number
displayCoef:
stp x1,lr,[sp,-16]! // save registres
stp x2,x3,[sp,-16]! // save registres
stp x4,x5,[sp,-16]! // save registres
stp x6,x7,[sp,-16]! // save registres
mov x2,x0
ldr x1,qAdrsZoneConv //
bl conversion10 // call decimal conversion
add x1,x1,x0
strb wzr,[x1]
ldr x0,qAdrszMessResult
ldr x1,qAdrsZoneConv // insert value conversion in message
bl strInsertAtCharInc
bl affichageMess
ldr x3,qAdrqTabCoef
1:
ldr x0,[x3,x2,lsl #3]
ldr x1,qAdrsZoneConv //
bl conversion10S // call decimal conversion
2: // removing spaces
ldrb w6,[x1]
cmp x6,' '
cinc x1,x1,eq
beq 2b
ldr x0,qAdrszMessResult1
bl strInsertAtCharInc
mov x4,x0
mov x0,x2
ldr x1,qAdrsZoneConv // else display odd message
bl conversion10 // call decimal conversion
add x1,x1,x0
strb wzr,[x1]
mov x0,x4
ldr x1,qAdrsZoneConv // insert value conversion in message
bl strInsertAtCharInc
bl affichageMess
subs x2,x2,#1
bge 1b
ldr x0,qAdrszCarriageReturn
bl affichageMess
100:
ldp x6,x7,[sp],16 // restaur des 2 registres
ldp x4,x5,[sp],16 // restaur des 2 registres
ldp x2,x3,[sp],16 // restaur des 2 registres
ldp x1,lr,[sp],16 // restaur des 2 registres
ret
qAdrszMessResult: .quad szMessResult
qAdrszMessResult1: .quad szMessResult1
/***************************************************/
/* compute coefficient */
/***************************************************/
// x0 contains a number
computeCoef:
stp x1,lr,[sp,-16]! // save registres
stp x2,x3,[sp,-16]! // save registres
stp x4,x5,[sp,-16]! // save registres
stp x6,x7,[sp,-16]! // save registres
ldr x1,qAdrqTabCoef // address coefficient array
mov x2,1
str x2,[x1] // store 1 to coeff [0]
mov x3,0 // indice 1
1:
add x4,x3,1
mov x5,1
str x5,[x1,x4,lsl #3]
mov x6,x3 // indice 2 = indice 1
2:
cmp x6,0 // zero ? -> end loop
ble 3f
sub x4,x6,1
ldr x5,[x1,x4,lsl 3]
ldr x4,[x1,x6,lsl 3]
sub x5,x5,x4
str x5,[x1,x6,lsl 3]
sub x6,x6,1
b 2b
3:
ldr x2,[x1] // inversion coeff [0]
neg x2,x2
str x2,[x1]
add x3,x3,1
cmp x3,x0
blt 1b
100:
ldp x6,x7,[sp],16 // restaur des 2 registres
ldp x4,x5,[sp],16 // restaur des 2 registres
ldp x2,x3,[sp],16 // restaur des 2 registres
ldp x1,lr,[sp],16 // restaur des 2 registres
ret
/***************************************************/
/* verify number is prime */
/***************************************************/
// x0 contains a number
isPrime:
stp x1,lr,[sp,-16]! // save registres
stp x2,x3,[sp,-16]! // save registres
stp x4,x5,[sp,-16]! // save registres
bl computeCoef
ldr x4,qAdrqTabCoef // address coefficient array
ldr x2,[x4]
add x2,x2,1
str x2,[x4]
ldr x2,[x4,x0,lsl 3]
sub x2,x2,#1
str x2,[x4,x0,lsl 3]
mov x5,x0 // number start
1:
ldr x1,[x4,x5,lsl 3] // load one coeff
sdiv x2,x1,x0
msub x3,x2,x0,x1 // compute remainder
cmp x3,#0 // remainder = zéro ?
bne 99f // if <> no prime
subs x5,x5,#1 // next coef
bgt 1b // and loop
mov x0,#1 // prime
b 100f
99:
mov x0,0 // no prime
100:
ldp x4,x5,[sp],16 // restaur des 2 registres
ldp x2,x3,[sp],16 // restaur des 2 registres
ldp x1,lr,[sp],16 // restaur des 2 registres
ret
/********************************************************/
/* File Include fonctions */
/********************************************************/
/* for this file see task include a file in language AArch64 assembly */
.include "../includeARM64.inc"
|
http://rosettacode.org/wiki/Additive_primes | Additive primes | Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
the OEIS entry: A046704 additive primes.
the prime-numbers entry: additive primes.
the geeks for geeks entry: additive prime number.
the prime-numbers fandom: additive primes.
| #ALGOL_68 | ALGOL 68 | BEGIN # find additive primes - primes whose digit sum is also prime #
# sieve the primes to max prime #
PR read "primes.incl.a68" PR
[]BOOL prime = PRIMESIEVE 499;
# find the additive primes #
INT additive count := 0;
FOR n TO UPB prime DO
IF prime[ n ] THEN
# have a prime #
INT digit sum := 0;
INT v := n;
WHILE v > 0 DO
digit sum +:= v MOD 10;
v OVERAB 10
OD;
IF prime( digit sum ) THEN
# the digit sum is prime #
print( ( " ", whole( n, -3 ) ) );
IF ( additive count +:= 1 ) MOD 20 = 0 THEN print( ( newline ) ) FI
FI
FI
OD;
print( ( newline, "Found ", whole( additive count, 0 ), " additive primes below ", whole( UPB prime + 1, 0 ), newline ) )
END |
http://rosettacode.org/wiki/Algebraic_data_types | Algebraic data types | Some languages offer direct support for algebraic data types and pattern matching on them. While this of course can always be simulated with manual tagging and conditionals, it allows for terse code which is easy to read, and can represent the algorithm directly.
Task
As an example, implement insertion in a red-black-tree.
A red-black-tree is a binary tree where each internal node has a color attribute red or black. Moreover, no red node can have a red child, and every path from the root to an empty node must contain the same number of black nodes. As a consequence, the tree is balanced, and must be re-balanced after an insertion.
Reference
Red-Black Trees in a Functional Setting
| #F.23 | F# |
// Pattern Matching. Nigel Galloway: January 15th., 2021
type colour= |Red |Black
type rbT<'N>= |Empty |N of colour * rbT<'N> * rbT<'N> * 'N
let repair=function |Black,N(Red,N(Red,ll,lr,lv),rl,v),rr,rv
|Black,N(Red,ll,N(Red,lr,rl,v),lv),rr,rv
|Black,ll,N(Red,N(Red,lr,rl,v),rr,rv),lv
|Black,ll,N(Red,lr,N(Red,rl,rr,rv),v),lv->N(Red,N(Black,ll,lr,lv),N(Black,rl,rr,rv),v)
|i,g,e,l->N(i,g,e,l)
let insert item rbt = let rec insert=function
|Empty->N(Red,Empty,Empty,item)
|N(i,g,e,l) as node->if item>l then repair(i,g,insert e,l) elif item<l then repair(i,insert g,e,l) else node
match insert rbt with N(_,g,e,l)->N(Black,g,e,l) |_->Empty
|
http://rosettacode.org/wiki/Algebraic_data_types | Algebraic data types | Some languages offer direct support for algebraic data types and pattern matching on them. While this of course can always be simulated with manual tagging and conditionals, it allows for terse code which is easy to read, and can represent the algorithm directly.
Task
As an example, implement insertion in a red-black-tree.
A red-black-tree is a binary tree where each internal node has a color attribute red or black. Moreover, no red node can have a red child, and every path from the root to an empty node must contain the same number of black nodes. As a consequence, the tree is balanced, and must be re-balanced after an insertion.
Reference
Red-Black Trees in a Functional Setting
| #Go | Go | package main
import "fmt"
type Color string
const (
R Color = "R"
B = "B"
)
type Tree interface {
ins(x int) Tree
}
type E struct{}
func (_ E) ins(x int) Tree {
return T{R, E{}, x, E{}}
}
func (_ E) String() string {
return "E"
}
type T struct {
cl Color
le Tree
aa int
ri Tree
}
func (t T) balance() Tree {
if t.cl != B {
return t
}
le, leIsT := t.le.(T)
ri, riIsT := t.ri.(T)
var lele, leri, rile, riri T
var leleIsT, leriIsT, rileIsT, ririIsT bool
if leIsT {
lele, leleIsT = le.le.(T)
}
if leIsT {
leri, leriIsT = le.ri.(T)
}
if riIsT {
rile, rileIsT = ri.le.(T)
}
if riIsT {
riri, ririIsT = ri.ri.(T)
}
switch {
case leIsT && leleIsT && le.cl == R && lele.cl == R:
_, t2, z, d := t.destruct()
_, t3, y, c := t2.(T).destruct()
_, a, x, b := t3.(T).destruct()
return T{R, T{B, a, x, b}, y, T{B, c, z, d}}
case leIsT && leriIsT && le.cl == R && leri.cl == R:
_, t2, z, d := t.destruct()
_, a, x, t3 := t2.(T).destruct()
_, b, y, c := t3.(T).destruct()
return T{R, T{B, a, x, b}, y, T{B, c, z, d}}
case riIsT && rileIsT && ri.cl == R && rile.cl == R:
_, a, x, t2 := t.destruct()
_, t3, z, d := t2.(T).destruct()
_, b, y, c := t3.(T).destruct()
return T{R, T{B, a, x, b}, y, T{B, c, z, d}}
case riIsT && ririIsT && ri.cl == R && riri.cl == R:
_, a, x, t2 := t.destruct()
_, b, y, t3 := t2.(T).destruct()
_, c, z, d := t3.(T).destruct()
return T{R, T{B, a, x, b}, y, T{B, c, z, d}}
default:
return t
}
}
func (t T) ins(x int) Tree {
switch {
case x < t.aa:
return T{t.cl, t.le.ins(x), t.aa, t.ri}.balance()
case x > t.aa:
return T{t.cl, t.le, t.aa, t.ri.ins(x)}.balance()
default:
return t
}
}
func (t T) destruct() (Color, Tree, int, Tree) {
return t.cl, t.le, t.aa, t.ri
}
func (t T) String() string {
return fmt.Sprintf("T(%s, %v, %d, %v)", t.cl, t.le, t.aa, t.ri)
}
func insert(tr Tree, x int) Tree {
t := tr.ins(x)
switch t.(type) {
case T:
tt := t.(T)
_, a, y, b := tt.destruct()
return T{B, a, y, b}
case E:
return E{}
default:
return nil
}
}
func main() {
var tr Tree = E{}
for i := 1; i <= 16; i++ {
tr = insert(tr, i)
}
fmt.Println(tr)
} |
http://rosettacode.org/wiki/Almost_prime | Almost prime | A k-Almost-prime is a natural number
n
{\displaystyle n}
that is the product of
k
{\displaystyle k}
(possibly identical) primes.
Example
1-almost-primes, where
k
=
1
{\displaystyle k=1}
, are the prime numbers themselves.
2-almost-primes, where
k
=
2
{\displaystyle k=2}
, are the semiprimes.
Task
Write a function/method/subroutine/... that generates k-almost primes and use it to create a table here of the first ten members of k-Almost primes for
1
<=
K
<=
5
{\displaystyle 1<=K<=5}
.
Related tasks
Semiprime
Category:Prime Numbers
| #Common_Lisp | Common Lisp | (defun start ()
(loop for k from 1 to 5
do (format t "k = ~a: ~a~%" k (collect-k-almost-prime k))))
(defun collect-k-almost-prime (k &optional (d 2) (lst nil))
(cond ((= (length lst) 10) (reverse lst))
((= (?-primality d) k) (collect-k-almost-prime k (+ d 1) (cons d lst)))
(t (collect-k-almost-prime k (+ d 1) lst))))
(defun ?-primality (n &optional (d 2) (c 0))
(cond ((> d (isqrt n)) (+ c 1))
((zerop (rem n d)) (?-primality (/ n d) d (+ c 1)))
(t (?-primality n (+ d 1) c)))) |
http://rosettacode.org/wiki/Anagrams | Anagrams | When two or more words are composed of the same characters, but in a different order, they are called anagrams.
Task[edit]
Using the word list at http://wiki.puzzlers.org/pub/wordlists/unixdict.txt,
find the sets of words that share the same characters that contain the most words in them.
Related tasks
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #AWK | AWK | # JUMBLEA.AWK - words with the most duplicate spellings
# syntax: GAWK -f JUMBLEA.AWK UNIXDICT.TXT
{ for (i=1; i<=NF; i++) {
w = sortstr(toupper($i))
arr[w] = arr[w] $i " "
n = gsub(/ /,"&",arr[w])
if (max_n < n) { max_n = n }
}
}
END {
for (w in arr) {
if (gsub(/ /,"&",arr[w]) == max_n) {
printf("%s\t%s\n",w,arr[w])
}
}
exit(0)
}
function sortstr(str, i,j,leng) {
leng = length(str)
for (i=2; i<=leng; i++) {
for (j=i; j>1 && substr(str,j-1,1) > substr(str,j,1); j--) {
str = substr(str,1,j-2) substr(str,j,1) substr(str,j-1,1) substr(str,j+1)
}
}
return(str)
} |
http://rosettacode.org/wiki/Angle_difference_between_two_bearings | Angle difference between two bearings | Finding the angle between two bearings is often confusing.[1]
Task
Find the angle which is the result of the subtraction b2 - b1, where b1 and b2 are the bearings.
Input bearings are expressed in the range -180 to +180 degrees.
The result is also expressed in the range -180 to +180 degrees.
Compute the angle for the following pairs:
20 degrees (b1) and 45 degrees (b2)
-45 and 45
-85 and 90
-95 and 90
-45 and 125
-45 and 145
29.4803 and -88.6381
-78.3251 and -159.036
Optional extra
Allow the input bearings to be any (finite) value.
Test cases
-70099.74233810938 and 29840.67437876723
-165313.6666297357 and 33693.9894517456
1174.8380510598456 and -154146.66490124757
60175.77306795546 and 42213.07192354373
| #Kotlin | Kotlin | // version 1.1.2
class Angle(d: Double) {
val value = when {
d in -180.0 .. 180.0 -> d
d > 180.0 -> (d - 180.0) % 360.0 - 180.0
else -> (d + 180.0) % 360.0 + 180.0
}
operator fun minus(other: Angle) = Angle(this.value - other.value)
}
fun main(args: Array<String>) {
val anglePairs = arrayOf(
20.0 to 45.0,
-45.0 to 45.0,
-85.0 to 90.0,
-95.0 to 90.0,
-45.0 to 125.0,
-45.0 to 145.0,
29.4803 to -88.6381,
-78.3251 to -159.036,
-70099.74233810938 to 29840.67437876723,
-165313.6666297357 to 33693.9894517456,
1174.8380510598456 to -154146.66490124757,
60175.77306795546 to 42213.07192354373
)
println(" b1 b2 diff")
val f = "% 12.4f % 12.4f % 12.4f"
for (ap in anglePairs) {
val diff = Angle(ap.second) - Angle(ap.first)
println(f.format(ap.first, ap.second, diff.value))
}
} |
http://rosettacode.org/wiki/Anagrams/Deranged_anagrams | Anagrams/Deranged anagrams | Two or more words are said to be anagrams if they have the same characters, but in a different order.
By analogy with derangements we define a deranged anagram as two words with the same characters, but in which the same character does not appear in the same position in both words.
Task[edit]
Use the word list at unixdict to find and display the longest deranged anagram.
Related tasks
Permutations/Derangements
Best shuffle
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #PARI.2FGP | PARI/GP | dict=readstr("unixdict.txt");
len=apply(s->#s, dict);
getLen(L)=my(v=List()); for(i=1,#dict, if(len[i]==L, listput(v, dict[i]))); Vec(v);
letters(s)=vecsort(Vec(s));
getAnagrams(v)=my(u=List(),L=apply(letters,v),t,w); for(i=1,#v-1, w=List(); t=L[i]; for(j=i+1,#v, if(L[j]==t, listput(w, v[j]))); if(#w, listput(u, concat([v[i]], Vec(w))))); Vec(u);
deranged(s1,s2)=s1=Vec(s1);s2=Vec(s2); for(i=1,#s1, if(s1[i]==s2[i], return(0))); 1
getDeranged(v)=my(u=List(),w); for(i=1,#v-1, for(j=i+1,#v, if(deranged(v[i], v[j]), listput(u, [v[i], v[j]])))); Vec(u);
f(n)=my(t=getAnagrams(getLen(n))); if(#t, concat(apply(getDeranged, t)), []);
forstep(n=vecmax(len),1,-1, t=f(n); if(#t, return(t))) |
http://rosettacode.org/wiki/Anonymous_recursion | Anonymous recursion | While implementing a recursive function, it often happens that we must resort to a separate helper function to handle the actual recursion.
This is usually the case when directly calling the current function would waste too many resources (stack space, execution time), causing unwanted side-effects, and/or the function doesn't have the right arguments and/or return values.
So we end up inventing some silly name like foo2 or foo_helper. I have always found it painful to come up with a proper name, and see some disadvantages:
You have to think up a name, which then pollutes the namespace
Function is created which is called from nowhere else
The program flow in the source code is interrupted
Some languages allow you to embed recursion directly in-place. This might work via a label, a local gosub instruction, or some special keyword.
Anonymous recursion can also be accomplished using the Y combinator.
Task
If possible, demonstrate this by writing the recursive version of the fibonacci function (see Fibonacci sequence) which checks for a negative argument before doing the actual recursion.
| #Klong | Klong |
fib::{:[x<0;"error: negative":|x<2;x;.f(x-1)+.f(x-2)]}
|
http://rosettacode.org/wiki/Amicable_pairs | Amicable pairs | Two integers
N
{\displaystyle N}
and
M
{\displaystyle M}
are said to be amicable pairs if
N
≠
M
{\displaystyle N\neq M}
and the sum of the proper divisors of
N
{\displaystyle N}
(
s
u
m
(
p
r
o
p
D
i
v
s
(
N
)
)
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (N))}
)
=
M
{\displaystyle =M}
as well as
s
u
m
(
p
r
o
p
D
i
v
s
(
M
)
)
=
N
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (M))=N}
.
Example
1184 and 1210 are an amicable pair, with proper divisors:
1, 2, 4, 8, 16, 32, 37, 74, 148, 296, 592 and
1, 2, 5, 10, 11, 22, 55, 110, 121, 242, 605 respectively.
Task
Calculate and show here the Amicable pairs below 20,000; (there are eight).
Related tasks
Proper divisors
Abundant, deficient and perfect number classifications
Aliquot sequence classifications and its amicable classification.
| #Go | Go | package main
import "fmt"
func pfacSum(i int) int {
sum := 0
for p := 1; p <= i/2; p++ {
if i%p == 0 {
sum += p
}
}
return sum
}
func main() {
var a[20000]int
for i := 1; i < 20000; i++ {
a[i] = pfacSum(i)
}
fmt.Println("The amicable pairs below 20,000 are:")
for n := 2; n < 19999; n++ {
m := a[n]
if m > n && m < 20000 && n == a[m] {
fmt.Printf(" %5d and %5d\n", n, m)
}
}
} |
http://rosettacode.org/wiki/Animation | Animation |
Animation is integral to many parts of GUIs, including both the fancy effects when things change used in window managers, and of course games. The core of any animation system is a scheme for periodically changing the display while still remaining responsive to the user. This task demonstrates this.
Task
Create a window containing the string "Hello World! " (the trailing space is significant).
Make the text appear to be rotating right by periodically removing one letter from the end of the string and attaching it to the front.
When the user clicks on the (windowed) text, it should reverse its direction.
| #Quick_BASIC | Quick BASIC |
'here accordingly to the version, QB or QBX
REM $INCLUDE: 'QBX.BI'
DIM REGS AS REGTYPE
DIM C AS STRING, SIZ AS INTEGER
DIM I AS DOUBLE, DIRE AS INTEGER
C = "Hello World! "
SIZ = LEN(C)
SCREEN 12
'turn the cursor visible
REGS.AX = 1
INTERRUPT 51, REGS, REGS
DO
I = TIMER
LOCATE 1, 1
PRINT C
REGS.AX = 5 'read mouse's queue of occurred pressings
REGS.BX = 0 'the left button
INTERRUPT 51, REGS, REGS
'BX is the selected button's quantity of occurred pressings
IF REGS.BX <> 0 THEN
IF REGS.CX >= 0 AND REGS.CX < SIZ * 8 AND REGS.DX >= 0 AND REGS.DX < 16 THEN
DIRE = 1 - DIRE
END IF
END IF
'AX is all buttons' status
IF (REGS.AX AND 2) <> 0 THEN EXIT DO
IF DIRE = 0 THEN
C = RIGHT$(C, 1) + LEFT$(C, SIZ - 1)
ELSE
C = RIGHT$(C, SIZ - 1) + LEFT$(C, 1)
END IF
DO WHILE TIMER < I + .08
IF TIMER < I THEN I = I - 86400 'midnight checking
LOOP
LOOP |
http://rosettacode.org/wiki/Animate_a_pendulum | Animate a pendulum |
One good way of making an animation is by simulating a physical system and illustrating the variables in that system using a dynamically changing graphical display.
The classic such physical system is a simple gravity pendulum.
Task
Create a simple physical model of a pendulum and animate it.
| #Lingo | Lingo | global RODLEN, GRAVITY, DT
global velocity, acceleration, angle, posX, posY
on startMovie
-- window properties
_movie.stage.title = "Pendulum"
_movie.stage.titlebarOptions.visible = TRUE
_movie.stage.rect = rect(0, 0, 400, 400)
_movie.centerStage = TRUE
_movie.puppetTempo(30)
RODLEN = 180
GRAVITY = -9.8
DT = 0.03
velocity = 0.0
acceleration = 0.0
angle = PI/3
posX = 200 - sin(angle) * RODLEN
posY = 100 + cos(angle) * RODLEN
paint()
-- show the window
_movie.stage.visible = TRUE
end
on enterFrame
acceleration = GRAVITY * sin(angle)
velocity = velocity + acceleration * DT
angle = angle + velocity * DT
posX = 200 - sin(angle) * rodLen
posY = 100 + cos(angle) * rodLen
paint()
end
on paint
img = _movie.stage.image
img.fill(img.rect, rgb(255,255,255))
img.fill(point(200-5, 100-5), point(200+5, 100+5), [#shapeType:#oval,#color:rgb(0,0,0)])
img.draw(point(200, 100), point(posX, posY), [#color:rgb(0,0,0)])
img.fill(point(posX-20, posY-20), point(posX+20, posY+20), [#shapeType:#oval,#lineSize:1,#bgColor:rgb(0,0,0),#color:rgb(255,255,0)])
end |
http://rosettacode.org/wiki/Amb | Amb | Define and give an example of the Amb operator.
The Amb operator (short for "ambiguous") expresses nondeterminism. This doesn't refer to randomness (as in "nondeterministic universe") but is closely related to the term as it is used in automata theory ("non-deterministic finite automaton").
The Amb operator takes a variable number of expressions (or values if that's simpler in the language) and yields a correct one which will satisfy a constraint in some future computation, thereby avoiding failure.
Problems whose solution the Amb operator naturally expresses can be approached with other tools, such as explicit nested iterations over data sets, or with pattern matching. By contrast, the Amb operator appears integrated into the language. Invocations of Amb are not wrapped in any visible loops or other search patterns; they appear to be independent.
Essentially Amb(x, y, z) splits the computation into three possible futures: a future in which the value x is yielded, a future in which the value y is yielded and a future in which the value z is yielded. The future which leads to a successful subsequent computation is chosen. The other "parallel universes" somehow go away. Amb called with no arguments fails.
For simplicity, one of the domain values usable with Amb may denote failure, if that is convenient. For instance, it is convenient if a Boolean false denotes failure, so that Amb(false) fails, and thus constraints can be expressed using Boolean expressions like Amb(x * y == 8) which unless x and y add to four.
A pseudo-code program which satisfies this constraint might look like:
let x = Amb(1, 2, 3)
let y = Amb(7, 6, 4, 5)
Amb(x * y = 8)
print x, y
The output is 2 4 because Amb(1, 2, 3) correctly chooses the future in which x has value 2, Amb(7, 6, 4, 5) chooses 4 and consequently Amb(x * y = 8) produces a success.
Alternatively, failure could be represented using strictly Amb():
unless x * y = 8 do Amb()
Or else Amb could take the form of two operators or functions: one for producing values and one for enforcing constraints:
let x = Ambsel(1, 2, 3)
let y = Ambsel(4, 5, 6)
Ambassert(x * y = 8)
print x, y
where Ambassert behaves like Amb() if the Boolean expression is false, otherwise it allows the future computation to take place, without yielding any value.
The task is to somehow implement Amb, and demonstrate it with a program which chooses one word from each of the following four sets of character strings to generate a four-word sentence:
"the" "that" "a"
"frog" "elephant" "thing"
"walked" "treaded" "grows"
"slowly" "quickly"
The constraint to be satisfied is that the last character of each word (other than the last) is the same as the first character of its successor.
The only successful sentence is "that thing grows slowly"; other combinations do not satisfy the constraint and thus fail.
The goal of this task isn't to simply process the four lists of words with explicit, deterministic program flow such as nested iteration, to trivially demonstrate the correct output. The goal is to implement the Amb operator, or a facsimile thereof that is possible within the language limitations.
| #C.2B.2B | C++ | #include <iostream>
#include <string_view>
#include <boost/hana.hpp>
#include <boost/hana/experimental/printable.hpp>
using namespace std;
namespace hana = boost::hana;
// Define the Amb function. The first parameter is the constraint to be
// enforced followed by the potential values.
constexpr auto Amb(auto constraint, auto&& ...params)
{
// create the set of all possible solutions
auto possibleSolutions = hana::cartesian_product(hana::tuple(params...));
// find one that matches the constraint
auto foldOperation = [constraint](auto a, auto b)
{
bool meetsConstraint = constraint(a);
return meetsConstraint ? a : b;
};
return hana::fold_right(possibleSolutions, foldOperation);
}
void AlgebraExample()
{
// use a tuple to hold the possible values of each variable
constexpr hana::tuple x{1, 2, 3};
constexpr hana::tuple y{7, 6, 4, 5};
// the constraint enforcing x * y == 8
constexpr auto constraint = [](auto t)
{
return t[hana::size_c<0>] * t[hana::size_c<1>] == 8;
};
// find the solution using the Amb function
auto result = Amb(constraint, x, y);
cout << "\nx = " << hana::experimental::print(x);
cout << "\ny = " << hana::experimental::print(y);
cout << "\nx * y == 8: " << hana::experimental::print(result);
}
void StringExample()
{
// the word lists to choose from
constexpr hana::tuple words1 {"the"sv, "that"sv, "a"sv};
constexpr hana::tuple words2 {"frog"sv, "elephant"sv, "thing"sv};
constexpr hana::tuple words3 {"walked"sv, "treaded"sv, "grows"sv};
constexpr hana::tuple words4 {"slowly"sv, "quickly"sv};
// the constraint that the first letter of a word is the same as the last
// letter of the previous word
constexpr auto constraint = [](const auto t)
{
auto adjacent = hana::zip(hana::drop_back(t), hana::drop_front(t));
return hana::all_of(adjacent, [](auto t)
{
return t[hana::size_c<0>].back() == t[hana::size_c<1>].front();
});
};
// find the solution using the Amb function
auto wordResult = Amb(constraint, words1, words2, words3, words4);
cout << "\n\nWords 1: " << hana::experimental::print(words1);
cout << "\nWords 2: " << hana::experimental::print(words2);
cout << "\nWords 3: " << hana::experimental::print(words3);
cout << "\nWords 4: " << hana::experimental::print(words4);
cout << "\nSolution: " << hana::experimental::print(wordResult) << "\n";
}
int main()
{
AlgebraExample();
StringExample();
}
|
http://rosettacode.org/wiki/Aliquot_sequence_classifications | Aliquot sequence classifications | An aliquot sequence of a positive integer K is defined recursively as the first member
being K and subsequent members being the sum of the Proper divisors of the previous term.
If the terms eventually reach 0 then the series for K is said to terminate.
There are several classifications for non termination:
If the second term is K then all future terms are also K and so the sequence repeats from the first term with period 1 and K is called perfect.
If the third term would be repeating K then the sequence repeats with period 2 and K is called amicable.
If the Nth term would be repeating K for the first time, with N > 3 then the sequence repeats with period N - 1 and K is called sociable.
Perfect, amicable and sociable numbers eventually repeat the original number K; there are other repetitions...
Some K have a sequence that eventually forms a periodic repetition of period 1 but of a number other than K, for example 95 which forms the sequence 95, 25, 6, 6, 6, ... such K are called aspiring.
K that have a sequence that eventually forms a periodic repetition of period >= 2 but of a number other than K, for example 562 which forms the sequence 562, 284, 220, 284, 220, ... such K are called cyclic.
And finally:
Some K form aliquot sequences that are not known to be either terminating or periodic; these K are to be called non-terminating.
For the purposes of this task, K is to be classed as non-terminating if it has not been otherwise classed after generating 16 terms or if any term of the sequence is greater than 2**47 = 140,737,488,355,328.
Task
Create routine(s) to generate the aliquot sequence of a positive integer enough to classify it according to the classifications given above.
Use it to display the classification and sequences of the numbers one to ten inclusive.
Use it to show the classification and sequences of the following integers, in order:
11, 12, 28, 496, 220, 1184, 12496, 1264460, 790, 909, 562, 1064, 1488, and optionally 15355717786080.
Show all output on this page.
Related tasks
Abundant, deficient and perfect number classifications. (Classifications from only the first two members of the whole sequence).
Proper divisors
Amicable pairs
| #ARM_Assembly | ARM Assembly |
/* ARM assembly Raspberry PI */
/* program aliquotSeq.s */
/* REMARK 1 : this program use routines in a include file
see task Include a file language arm assembly
for the routine affichageMess conversion10
see at end of this program the instruction include */
/* for constantes see task include a file in arm assembly */
/************************************/
/* Constantes */
/************************************/
.include "../constantes.inc"
.equ MAXINUM, 10
.equ MAXI, 16
.equ NBDIVISORS, 1000
/*******************************************/
/* Initialized data */
/*******************************************/
.data
szMessStartPgm: .asciz "Program start \n"
szMessEndPgm: .asciz "Program normal end.\n"
szMessErrorArea: .asciz "\033[31mError : area divisors too small.\033[0m \n"
szMessError: .asciz "\033[31mError !!!\033[0m \n"
szMessErrGen: .asciz "Error end program.\033[0m \n"
szCarriageReturn: .asciz "\n"
szLibPerf: .asciz "Perfect \n"
szLibAmic: .asciz "Amicable \n"
szLibSoc: .asciz "Sociable \n"
szLibAspi: .asciz "Aspiring \n"
szLibCycl: .asciz "Cyclic \n"
szLibTerm: .asciz "Terminating \n"
szLibNoTerm: .asciz "No terminating\n"
/* datas message display */
szMessResult: .asciz " @ "
szMessResHead: .asciz "Number @ :"
.align 4
tbNumber: .int 11,12,28,496,220,1184,12496,1264460,790,909,562,1064,1488
.equ NBNUMBER, (. - tbNumber ) / 4
/*******************************************/
/* UnInitialized data */
/*******************************************/
.bss
.align 4
sZoneConv: .skip 24
tbZoneDecom: .skip 4 * NBDIVISORS // facteur 4 octets
tbNumberSucc: .skip 4 * MAXI
/*******************************************/
/* code section */
/*******************************************/
.text
.global main
main: @ program start
ldr r0,iAdrszMessStartPgm @ display start message
bl affichageMess
mov r4,#1
1:
mov r0,r4 @ number
bl aliquotClassif @ aliquot classification
cmp r0,#-1 @ error ?
beq 99f
add r4,r4,#1
cmp r4,#MAXINUM
ble 1b
ldr r5,iAdrtbNumber @ number array
mov r4,#0
2:
ldr r0,[r5,r4,lsl #2] @ load a number
bl aliquotClassif @ aliquot classification
cmp r0,#-1 @ error ?
beq 99f
add r4,r4,#1 @ next number
cmp r4,#NBNUMBER @ maxi ?
blt 2b @ no -> loop
ldr r0,iAdrszMessEndPgm @ display end message
bl affichageMess
b 100f
99: @ display error message
ldr r0,iAdrszMessError
bl affichageMess
100: @ standard end of the program
mov r0, #0 @ return code
mov r7, #EXIT @ request to exit program
svc 0 @ perform system call
iAdrszMessStartPgm: .int szMessStartPgm
iAdrszMessEndPgm: .int szMessEndPgm
iAdrszMessError: .int szMessError
iAdrszCarriageReturn: .int szCarriageReturn
iAdrtbZoneDecom: .int tbZoneDecom
iAdrszMessResult: .int szMessResult
iAdrsZoneConv: .int sZoneConv
iAdrtbNumber: .int tbNumber
/******************************************************************/
/* function aliquot classification */
/******************************************************************/
/* r0 contains number */
aliquotClassif:
push {r3-r8,lr} @ save registers
mov r5,r0 @ save number
ldr r1,iAdrsZoneConv
bl conversion10 @ convert ascii string
mov r2,#0
strb r2,[r1,r0]
ldr r0,iAdrszMessResHead
ldr r1,iAdrsZoneConv
bl strInsertAtCharInc @ put in head message
bl affichageMess @ and display
mov r0,r5 @ restaur number
ldr r7,iAdrtbNumberSucc @ number successif array
mov r4,#0 @ counter number successif
1:
mov r6,r0 @ previous number
ldr r1,iAdrtbZoneDecom
bl decompFact @ create area of divisors
cmp r0,#0 @ error ?
blt 99f
sub r3,r1,r6 @ sum
mov r0,r3
ldr r1,iAdrsZoneConv
bl conversion10 @ convert ascii string
mov r2,#0
strb r2,[r1,r0]
ldr r0,iAdrszMessResult
ldr r1,iAdrsZoneConv
bl strInsertAtCharInc @ and put in message
bl affichageMess
cmp r3,#0 @ sum = zero
bne 11f
ldr r0,iAdrszLibTerm @ terminating
bl affichageMess
b 100f
11:
cmp r5,r3 @ compare number and sum
bne 4f
cmp r4,#0 @ first loop ?
bne 2f
ldr r0,iAdrszLibPerf @ perfect
bl affichageMess
b 100f
2:
cmp r4,#1 @ second loop ?
bne 3f
ldr r0,iAdrszLibAmic @ amicable
bl affichageMess
b 100f
3: @ other loop
ldr r0,iAdrszLibSoc @ sociable
bl affichageMess
b 100f
4:
cmp r6,r3 @ compare sum and (sum - 1)
bne 5f
ldr r0,iAdrszLibAspi @ aspirant
bl affichageMess
b 100f
5:
cmp r3,#1 @ if one ,no search in array
beq 7f
mov r2,#0 @ search indice
6: @ search number in array
ldr r8,[r7,r2,lsl #2]
cmp r8,r3 @ equal ?
beq 8f @ yes -> cycling
add r2,r2,#1 @ increment indice
cmp r2,r4 @ end ?
blt 6b @ no -> loop
7:
cmp r4,#MAXI
blt 10f
ldr r0,iAdrszLibNoTerm @ no terminating
bl affichageMess
b 100f
8: @ cycling
ldr r0,iAdrszLibCycl
bl affichageMess
b 100f
10:
str r3,[r7,r4,lsl #2] @ store new sum in array
add r4,r4,#1 @ increment counter
mov r0,r3 @ new number = new sum
b 1b @ and loop
99: @ display error
ldr r0,iAdrszMessError
bl affichageMess
100:
pop {r3-r8,lr} @ restaur registers
bx lr
iAdrszMessResHead: .int szMessResHead
iAdrszLibPerf: .int szLibPerf
iAdrszLibAmic: .int szLibAmic
iAdrszLibSoc: .int szLibSoc
iAdrszLibCycl: .int szLibCycl
iAdrszLibAspi: .int szLibAspi
iAdrszLibNoTerm: .int szLibNoTerm
iAdrszLibTerm: .int szLibTerm
iAdrtbNumberSucc: .int tbNumberSucc
/******************************************************************/
/* factor decomposition */
/******************************************************************/
/* r0 contains number */
/* r1 contains address of divisors area */
/* r0 return divisors items in array */
/* r1 return the sum of divisors */
decompFact:
push {r3-r12,lr} @ save registers
cmp r0,#1
moveq r1,#1
beq 100f
mov r5,r1
mov r8,r0 @ save number
bl isPrime @ prime ?
cmp r0,#1
beq 98f @ yes is prime
mov r1,#1
str r1,[r5] @ first factor
mov r12,#1 @ divisors sum
mov r10,#1 @ indice divisors table
mov r9,#2 @ first divisor
mov r6,#0 @ previous divisor
mov r7,#0 @ number of same divisors
/* division loop */
2:
mov r0,r8 @ dividende
mov r1,r9 @ divisor
bl division @ r2 quotient r3 remainder
cmp r3,#0
beq 3f @ if remainder zero -> divisor
/* not divisor -> increment next divisor */
cmp r9,#2 @ if divisor = 2 -> add 1
addeq r9,#1
addne r9,#2 @ else add 2
b 2b
/* divisor compute the new factors of number */
3:
mov r8,r2 @ else quotient -> new dividende
cmp r9,r6 @ same divisor ?
beq 4f @ yes
mov r0,r5 @ table address
mov r1,r10 @ number factors in table
mov r2,r9 @ divisor
mov r3,r12 @ somme
mov r4,#0
bl computeFactors
cmp r0,#-1
beq 100f
mov r10,r1
mov r12,r0
mov r6,r9 @ new divisor
b 7f
4: @ same divisor
sub r7,r10,#1
5: @ search in table the first use of divisor
ldr r3,[r5,r7,lsl #2 ]
cmp r3,r9
subne r7,#1
bne 5b
@ and compute new factors after factors
sub r4,r10,r7 @ start indice
mov r0,r5
mov r1,r10
mov r2,r9 @ divisor
mov r3,r12
bl computeFactors
cmp r0,#-1
beq 100f
mov r12,r0
mov r10,r1
/* divisor -> test if new dividende is prime */
7:
cmp r8,#1 @ dividende = 1 ? -> end
beq 10f
mov r0,r8 @ new dividende is prime ?
mov r1,#0
bl isPrime @ the new dividende is prime ?
cmp r0,#1
bne 10f @ the new dividende is not prime
cmp r8,r6 @ else dividende is same divisor ?
beq 8f @ yes
mov r0,r5
mov r1,r10
mov r2,r8
mov r3,r12
mov r4,#0
bl computeFactors
cmp r0,#-1
beq 100f
mov r12,r0
mov r10,r1
mov r7,#0
b 11f
8:
sub r7,r10,#1
9:
ldr r3,[r5,r7,lsl #2 ]
cmp r3,r8
subne r7,#1
bne 9b
mov r0,r5
mov r1,r10
sub r4,r10,r7
mov r2,r8
mov r3,r12
bl computeFactors
cmp r0,#-1
beq 100f
mov r12,r0
mov r10,r1
b 11f
10:
cmp r9,r8 @ current divisor > new dividende ?
ble 2b @ no -> loop
/* end decomposition */
11:
mov r0,r10 @ return number of table items
mov r1,r12 @ return sum
mov r3,#0
str r3,[r5,r10,lsl #2] @ store zéro in last table item
b 100f
98: @ prime number
add r1,r8,#1
mov r0,#0 @ return code
b 100f
99:
ldr r0,iAdrszMessError
bl affichageMess
mov r0,#-1 @ error code
b 100f
100:
pop {r3-r12,pc} @ restaur registers
/******************************************************************/
/* compute all factors */
/******************************************************************/
/* r0 table factors address */
/* r1 number factors in table */
/* r2 new divisor */
/* r3 sum */
/* r4 start indice */
/* r0 return sum */
/* r1 return number factors in table */
computeFactors:
push {r2-r6,lr} @ save registers
mov r6,r1 @ number factors in table
1:
ldr r5,[r0,r4,lsl #2 ] @ load one factor
mul r5,r2,r5 @ multiply
str r5,[r0,r1,lsl #2] @ and store in the table
adds r3,r5
movcs r0,#-1 @ overflow
bcs 100f
add r1,r1,#1 @ and increment counter
add r4,r4,#1
cmp r4,r6
blt 1b
mov r0,r3 @ factors sum
100: @ fin standard de la fonction
pop {r2-r6,pc} @ restaur des registres
/***************************************************/
/* check if a number is prime */
/***************************************************/
/* r0 contains the number */
/* r0 return 1 if prime 0 else */
isPrime:
push {r1-r6,lr} @ save registers
cmp r0,#0
beq 90f
cmp r0,#17
bhi 1f
cmp r0,#3
bls 80f @ for 1,2,3 return prime
cmp r0,#5
beq 80f @ for 5 return prime
cmp r0,#7
beq 80f @ for 7 return prime
cmp r0,#11
beq 80f @ for 11 return prime
cmp r0,#13
beq 80f @ for 13 return prime
cmp r0,#17
beq 80f @ for 17 return prime
1:
tst r0,#1 @ even ?
beq 90f @ yes -> not prime
mov r2,r0 @ save number
sub r1,r0,#1 @ exposant n - 1
mov r0,#3 @ base
bl moduloPuR32 @ compute base power n - 1 modulo n
cmp r0,#1
bne 90f @ if <> 1 -> not prime
mov r0,#5
bl moduloPuR32
cmp r0,#1
bne 90f
mov r0,#7
bl moduloPuR32
cmp r0,#1
bne 90f
mov r0,#11
bl moduloPuR32
cmp r0,#1
bne 90f
mov r0,#13
bl moduloPuR32
cmp r0,#1
bne 90f
mov r0,#17
bl moduloPuR32
cmp r0,#1
bne 90f
80:
mov r0,#1 @ is prime
b 100f
90:
mov r0,#0 @ no prime
100: @ fin standard de la fonction
pop {r1-r6,pc} @ restaur des registres
/********************************************************/
/* Calcul modulo de b puissance e modulo m */
/* Exemple 4 puissance 13 modulo 497 = 445 */
/* */
/********************************************************/
/* r0 nombre */
/* r1 exposant */
/* r2 modulo */
/* r0 return result */
moduloPuR32:
push {r1-r7,lr} @ save registers
cmp r0,#0 @ verif <> zero
beq 100f
cmp r2,#0 @ verif <> zero
beq 100f @ TODO: v鲩fier les cas d erreur
1:
mov r4,r2 @ save modulo
mov r5,r1 @ save exposant
mov r6,r0 @ save base
mov r3,#1 @ start result
mov r1,#0 @ division de r0,r1 par r2
bl division32R
mov r6,r2 @ base <- remainder
2:
tst r5,#1 @ exposant even or odd
beq 3f
umull r0,r1,r6,r3
mov r2,r4
bl division32R
mov r3,r2 @ result <- remainder
3:
umull r0,r1,r6,r6
mov r2,r4
bl division32R
mov r6,r2 @ base <- remainder
lsr r5,#1 @ left shift 1 bit
cmp r5,#0 @ end ?
bne 2b
mov r0,r3
100: @ fin standard de la fonction
pop {r1-r7,pc} @ restaur des registres
/***************************************************/
/* division number 64 bits in 2 registers by number 32 bits */
/***************************************************/
/* r0 contains lower part dividende */
/* r1 contains upper part dividende */
/* r2 contains divisor */
/* r0 return lower part quotient */
/* r1 return upper part quotient */
/* r2 return remainder */
division32R:
push {r3-r9,lr} @ save registers
mov r6,#0 @ init upper upper part remainder !!
mov r7,r1 @ init upper part remainder with upper part dividende
mov r8,r0 @ init lower part remainder with lower part dividende
mov r9,#0 @ upper part quotient
mov r4,#0 @ lower part quotient
mov r5,#32 @ bits number
1: @ begin loop
lsl r6,#1 @ shift upper upper part remainder
lsls r7,#1 @ shift upper part remainder
orrcs r6,#1
lsls r8,#1 @ shift lower part remainder
orrcs r7,#1
lsls r4,#1 @ shift lower part quotient
lsl r9,#1 @ shift upper part quotient
orrcs r9,#1
@ divisor sustract upper part remainder
subs r7,r2
sbcs r6,#0 @ and substract carry
bmi 2f @ n駡tive ?
@ positive or equal
orr r4,#1 @ 1 -> right bit quotient
b 3f
2: @ negative
orr r4,#0 @ 0 -> right bit quotient
adds r7,r2 @ and restaur remainder
adc r6,#0
3:
subs r5,#1 @ decrement bit size
bgt 1b @ end ?
mov r0,r4 @ lower part quotient
mov r1,r9 @ upper part quotient
mov r2,r7 @ remainder
100: @ function end
pop {r3-r9,pc} @ restaur registers
/***************************************************/
/* ROUTINES INCLUDE */
/***************************************************/
.include "../affichage.inc"
|
http://rosettacode.org/wiki/Active_Directory/Search_for_a_user | Active Directory/Search for a user | Make sure you Connect to Active Directory
| #C | C | #include <ldap.h>
char *name, *password;
...
LDAP *ld = ldap_init("ldap.somewhere.com", 389);
ldap_simple_bind_s(ld, name, password);
LDAPMessage **result;
ldap_search_s(ld, "dc=somewhere,dc=com", LDAP_SCOPE_SUBTREE,
/* search for all persons whose names start with joe or shmoe */
"(&(objectclass=person)(|(cn=joe*)(cn=shmoe*)))",
NULL, /* return all attributes */
0, /* want both types and values of attrs */
result); /* ldap will allocate room for return messages */
/* arduously do stuff here to result, with ldap_first_message(),
ldap_parse_result(), etc. */
ldap_msgfree(*result); /* free messages */
ldap_unbind(ld); /* disconnect */ |
http://rosettacode.org/wiki/Address_of_a_variable | Address of a variable |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
| #Axe | Axe | °A→B
.B now contains the address of A |
http://rosettacode.org/wiki/Address_of_a_variable | Address of a variable |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
| #BaCon | BaCon |
'---get a variable's address
LOCAL x TYPE long
PRINT ADDRESS(x)
|
http://rosettacode.org/wiki/Address_of_a_variable | Address of a variable |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
| #BASIC | BASIC | 'get a variable's address:
DIM x AS INTEGER, y AS LONG
y = VARPTR(x)
'can't set the address, but can access a given memory location... 1 byte at a time
DIM z AS INTEGER
z = PEEK(y)
z = z + (PEEK(y) * 256) |
http://rosettacode.org/wiki/AKS_test_for_primes | AKS test for primes | The AKS algorithm for testing whether a number is prime is a polynomial-time algorithm based on an elementary theorem about Pascal triangles.
The theorem on which the test is based can be stated as follows:
a number
p
{\displaystyle p}
is prime if and only if all the coefficients of the polynomial expansion of
(
x
−
1
)
p
−
(
x
p
−
1
)
{\displaystyle (x-1)^{p}-(x^{p}-1)}
are divisible by
p
{\displaystyle p}
.
Example
Using
p
=
3
{\displaystyle p=3}
:
(x-1)^3 - (x^3 - 1)
= (x^3 - 3x^2 + 3x - 1) - (x^3 - 1)
= -3x^2 + 3x
And all the coefficients are divisible by 3, so 3 is prime.
Note:
This task is not the AKS primality test. It is an inefficient exponential time algorithm discovered in the late 1600s and used as an introductory lemma in the AKS derivation.
Task
Create a function/subroutine/method that given
p
{\displaystyle p}
generates the coefficients of the expanded polynomial representation of
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
.
Use the function to show here the polynomial expansions of
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
for
p
{\displaystyle p}
in the range 0 to at least 7, inclusive.
Use the previous function in creating another function that when given
p
{\displaystyle p}
returns whether
p
{\displaystyle p}
is prime using the theorem.
Use your test to generate a list of all primes under 35.
As a stretch goal, generate all primes under 50 (needs integers larger than 31-bit).
References
Agrawal-Kayal-Saxena (AKS) primality test (Wikipedia)
Fool-Proof Test for Primes - Numberphile (Video). The accuracy of this video is disputed -- at best it is an oversimplification.
| #Ada | Ada | with Ada.Text_IO;
procedure Test_For_Primes is
type Pascal_Triangle_Type is array (Natural range <>) of Long_Long_Integer;
function Calculate_Pascal_Triangle (N : in Natural) return Pascal_Triangle_Type is
Pascal_Triangle : Pascal_Triangle_Type (0 .. N);
begin
Pascal_Triangle (0) := 1;
for I in Pascal_Triangle'First .. Pascal_Triangle'Last - 1 loop
Pascal_Triangle (1 + I) := 1;
for J in reverse 1 .. I loop
Pascal_Triangle (J) := Pascal_Triangle (J - 1) - Pascal_Triangle (J);
end loop;
Pascal_Triangle (0) := -Pascal_Triangle (0);
end loop;
return Pascal_Triangle;
end Calculate_Pascal_Triangle;
function Is_Prime (N : Integer) return Boolean is
I : Integer;
Result : Boolean := True;
Pascal_Triangle : constant Pascal_Triangle_Type := Calculate_Pascal_Triangle (N);
begin
I := N / 2;
while Result and I > 1 loop
Result := Result and Pascal_Triangle (I) mod Long_Long_Integer (N) = 0;
I := I - 1;
end loop;
return Result;
end Is_Prime;
function Image (N : in Long_Long_Integer;
Sign : in Boolean := False) return String is
Image : constant String := N'Image;
begin
if N < 0 then
return Image;
else
if Sign then
return "+" & Image (Image'First + 1 .. Image'Last);
else
return Image (Image'First + 1 .. Image'Last);
end if;
end if;
end Image;
procedure Show (Triangle : in Pascal_Triangle_Type) is
use Ada.Text_IO;
Begin
for I in reverse Triangle'Range loop
Put (Image (Triangle (I), Sign => True));
Put ("x^");
Put (Image (Long_Long_Integer (I)));
Put (" ");
end loop;
end Show;
procedure Show_Pascal_Triangles is
use Ada.Text_IO;
begin
for N in 0 .. 9 loop
declare
Pascal_Triangle : constant Pascal_Triangle_Type := Calculate_Pascal_Triangle (N);
begin
Put ("(x-1)^" & Image (Long_Long_Integer (N)) & " = ");
Show (Pascal_Triangle);
New_Line;
end;
end loop;
end Show_Pascal_Triangles;
procedure Show_Primes is
use Ada.Text_IO;
begin
for N in 2 .. 63 loop
if Is_Prime (N) then
Put (N'Image);
end if;
end loop;
New_Line;
end Show_Primes;
begin
Show_Pascal_Triangles;
Show_Primes;
end Test_For_Primes; |
http://rosettacode.org/wiki/Additive_primes | Additive primes | Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
the OEIS entry: A046704 additive primes.
the prime-numbers entry: additive primes.
the geeks for geeks entry: additive prime number.
the prime-numbers fandom: additive primes.
| #ALGOL_W | ALGOL W | begin % find some additive primes - primes whose digit sum is also prime %
% sets p( 1 :: n ) to a sieve of primes up to n %
procedure Eratosthenes ( logical array p( * ) ; integer value n ) ;
begin
p( 1 ) := false; p( 2 ) := true;
for i := 3 step 2 until n do p( i ) := true;
for i := 4 step 2 until n do p( i ) := false;
for i := 3 step 2 until truncate( sqrt( n ) ) do begin
integer ii; ii := i + i;
if p( i ) then for pr := i * i step ii until n do p( pr ) := false
end for_i ;
end Eratosthenes ;
integer MAX_NUMBER;
MAX_NUMBER := 500;
begin
logical array prime( 1 :: MAX_NUMBER );
integer aCount;
% sieve the primes to MAX_NUMBER %
Eratosthenes( prime, MAX_NUMBER );
% find the primes that are additive primes %
aCount := 0;
for i := 1 until MAX_NUMBER - 1 do begin
if prime( i ) then begin
integer dSum, v;
v := i;
dSum := 0;
while v > 0 do begin
dSum := dSum + v rem 10;
v := v div 10
end while_v_gt_0 ;
if prime( dSum ) then begin
writeon( i_w := 4, s_w := 0, " ", i );
aCount := aCount + 1;
if aCount rem 20 = 0 then write()
end if_prime_dSum
end if_prime_i
end for_i ;
write( i_w := 1, s_w := 0, "Found ", aCount, " additive primes below ", MAX_NUMBER )
end
end. |
http://rosettacode.org/wiki/Additive_primes | Additive primes | Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
the OEIS entry: A046704 additive primes.
the prime-numbers entry: additive primes.
the geeks for geeks entry: additive prime number.
the prime-numbers fandom: additive primes.
| #APL | APL | ((+⌿(4/10)⊤P)∊P)/P←(~P∊P∘.×P)/P←1↓⍳500 |
http://rosettacode.org/wiki/Algebraic_data_types | Algebraic data types | Some languages offer direct support for algebraic data types and pattern matching on them. While this of course can always be simulated with manual tagging and conditionals, it allows for terse code which is easy to read, and can represent the algorithm directly.
Task
As an example, implement insertion in a red-black-tree.
A red-black-tree is a binary tree where each internal node has a color attribute red or black. Moreover, no red node can have a red child, and every path from the root to an empty node must contain the same number of black nodes. As a consequence, the tree is balanced, and must be re-balanced after an insertion.
Reference
Red-Black Trees in a Functional Setting
| #Haskell | Haskell | data Color = R | B
data Tree a = E | T Color (Tree a) a (Tree a)
balance :: Color -> Tree a -> a -> Tree a -> Tree a
balance B (T R (T R a x b) y c ) z d = T R (T B a x b) y (T B c z d)
balance B (T R a x (T R b y c)) z d = T R (T B a x b) y (T B c z d)
balance B a x (T R (T R b y c) z d ) = T R (T B a x b) y (T B c z d)
balance B a x (T R b y (T R c z d)) = T R (T B a x b) y (T B c z d)
balance col a x b = T col a x b
insert :: Ord a => a -> Tree a -> Tree a
insert x s = T B a y b where
ins E = T R E x E
ins s@(T col a y b)
| x < y = balance col (ins a) y b
| x > y = balance col a y (ins b)
| otherwise = s
T _ a y b = ins s |
http://rosettacode.org/wiki/Algebraic_data_types | Algebraic data types | Some languages offer direct support for algebraic data types and pattern matching on them. While this of course can always be simulated with manual tagging and conditionals, it allows for terse code which is easy to read, and can represent the algorithm directly.
Task
As an example, implement insertion in a red-black-tree.
A red-black-tree is a binary tree where each internal node has a color attribute red or black. Moreover, no red node can have a red child, and every path from the root to an empty node must contain the same number of black nodes. As a consequence, the tree is balanced, and must be re-balanced after an insertion.
Reference
Red-Black Trees in a Functional Setting
| #J | J | insert=:{{
'R';'';y;a:
:
if. 0=#y do. insert x
elseif. 0=L.y do. x insert insert y
else.
'C e K w'=. y
select. *x - K
case. _1 do. balance C;(x insert e);K;<w
case. 0 do. y
case. 1 do. balance C;e;K;<x insert w
end.
end.
}}
NB. C: color, e: east, K: key, w: west
NB. two cascaded reds under a black become two black siblings under a red
balance=: {{
'C e K w'=. y
if. #e do.
'eC ee eK ew'=. e
if. 'R'=eC do.
if. #ee do.
'eeC eee eeK eew'=. ee NB. ((eee eeK eew) eK ew) K w => (eee eeK eew) eK (ew K w)
if. 'R'=eeC do. 'R';('B';eee;eeK;<eew);eK;<'B';ew;K;<w return. end. end.
if. #ew do.
'ewC ewe ewK eww'=. ew NB. (ee ek (ewe ewK eww)) K w => (ee ek ewe) ewK (eww K w)
if. 'R'=ewC do. 'R';('B';ee;eK;<ewe);ewK;<'B';eww;K;<w return. end. end. end. end.
if. #w do.
'wC we wK ww'=. w
if. 'R'=wC do.
if. #we do.
'weC wee weK wew'=. we NB. e K ((wee weK wew) wK ww) => (e K wee) weK (wew wK ww)
if. 'R'=weC do. 'R';('B';e;K;<wee);weK;<'B';wew;wK;<ww return. end. end.
if. #ww do.
'wwC wwe wwK www'=. ww NB. e K (we wK (wwe wwK www)) => (e K we) wK (wwe wwK www)
if. 'R'=wwC do. 'R';('B';e;K;<we);wK;<'B';wwe;wwK;<www return. end. end. end. end.
y
}} |
http://rosettacode.org/wiki/Almost_prime | Almost prime | A k-Almost-prime is a natural number
n
{\displaystyle n}
that is the product of
k
{\displaystyle k}
(possibly identical) primes.
Example
1-almost-primes, where
k
=
1
{\displaystyle k=1}
, are the prime numbers themselves.
2-almost-primes, where
k
=
2
{\displaystyle k=2}
, are the semiprimes.
Task
Write a function/method/subroutine/... that generates k-almost primes and use it to create a table here of the first ten members of k-Almost primes for
1
<=
K
<=
5
{\displaystyle 1<=K<=5}
.
Related tasks
Semiprime
Category:Prime Numbers
| #Cowgol | Cowgol | include "cowgol.coh";
sub kprime(n: uint8, k: uint8): (kp: uint8) is
var p: uint8 := 2;
var f: uint8 := 0;
while f < k and p*p <= n loop
while 0 == n % p loop
n := n / p;
f := f + 1;
end loop;
p := p + 1;
end loop;
if n > 1 then
f := f + 1;
end if;
if f == k then
kp := 1;
else
kp := 0;
end if;
end sub;
var k: uint8 := 1;
while k <= 5 loop
print("k = ");
print_i8(k);
print(":");
var i: uint8 := 2;
var c: uint8 := 0;
while c < 10 loop
if kprime(i,k) != 0 then
print(" ");
print_i8(i);
c := c + 1;
end if;
i := i + 1;
end loop;
print_nl();
k := k + 1;
end loop; |
http://rosettacode.org/wiki/Almost_prime | Almost prime | A k-Almost-prime is a natural number
n
{\displaystyle n}
that is the product of
k
{\displaystyle k}
(possibly identical) primes.
Example
1-almost-primes, where
k
=
1
{\displaystyle k=1}
, are the prime numbers themselves.
2-almost-primes, where
k
=
2
{\displaystyle k=2}
, are the semiprimes.
Task
Write a function/method/subroutine/... that generates k-almost primes and use it to create a table here of the first ten members of k-Almost primes for
1
<=
K
<=
5
{\displaystyle 1<=K<=5}
.
Related tasks
Semiprime
Category:Prime Numbers
| #D | D | import std.stdio, std.algorithm, std.traits;
Unqual!T[] decompose(T)(in T number) pure nothrow
in {
assert(number > 1);
} body {
typeof(return) result;
Unqual!T n = number;
for (Unqual!T i = 2; n % i == 0; n /= i)
result ~= i;
for (Unqual!T i = 3; n >= i * i; i += 2)
for (; n % i == 0; n /= i)
result ~= i;
if (n != 1)
result ~= n;
return result;
}
void main() {
enum outLength = 10; // 10 k-th almost primes.
foreach (immutable k; 1 .. 6) {
writef("K = %d: ", k);
auto n = 2; // The "current number" to be checked.
foreach (immutable i; 1 .. outLength + 1) {
while (n.decompose.length != k)
n++;
// Now n is K-th almost prime.
write(n, " ");
n++;
}
writeln;
}
} |
http://rosettacode.org/wiki/Anagrams | Anagrams | When two or more words are composed of the same characters, but in a different order, they are called anagrams.
Task[edit]
Using the word list at http://wiki.puzzlers.org/pub/wordlists/unixdict.txt,
find the sets of words that share the same characters that contain the most words in them.
Related tasks
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #BaCon | BaCon | OPTION COLLAPSE TRUE
DECLARE idx$ ASSOC STRING
FOR w$ IN LOAD$("unixdict.txt") STEP NL$
set$ = SORT$(EXPLODE$(w$, 1))
idx$(set$) = APPEND$(idx$(set$), 0, w$)
total = AMOUNT(idx$(set$))
IF MaxCount < total THEN MaxCount = total
NEXT
PRINT "Analyzing took ", TIMER, " msecs.", NL$
LOOKUP idx$ TO n$ SIZE x
FOR y = 0 TO x-1
IF MaxCount = AMOUNT(idx$(n$[y])) THEN PRINT n$[y], ": ", idx$(n$[y])
NEXT |
http://rosettacode.org/wiki/Angle_difference_between_two_bearings | Angle difference between two bearings | Finding the angle between two bearings is often confusing.[1]
Task
Find the angle which is the result of the subtraction b2 - b1, where b1 and b2 are the bearings.
Input bearings are expressed in the range -180 to +180 degrees.
The result is also expressed in the range -180 to +180 degrees.
Compute the angle for the following pairs:
20 degrees (b1) and 45 degrees (b2)
-45 and 45
-85 and 90
-95 and 90
-45 and 125
-45 and 145
29.4803 and -88.6381
-78.3251 and -159.036
Optional extra
Allow the input bearings to be any (finite) value.
Test cases
-70099.74233810938 and 29840.67437876723
-165313.6666297357 and 33693.9894517456
1174.8380510598456 and -154146.66490124757
60175.77306795546 and 42213.07192354373
| #Lua | Lua | bearing = {degrees = 0} -- prototype object
function bearing:assign(angle)
angle = tonumber(angle) or 0
while angle > 180 do
angle = angle - 360
end
while angle < -180 do
angle = angle + 360
end
self.degrees = angle
end
function bearing:new(size)
local child_object = {}
setmetatable(child_object, {__index = self})
child_object:assign(size)
return child_object
end
function bearing:subtract(other)
local difference = self.degrees - other.degrees
return self:new(difference)
end
function bearing:list(sizes)
local bearings = {}
for index, size in ipairs(sizes) do
table.insert(bearings, self:new(size))
end
return bearings
end
function bearing:text()
return string.format("%.4f deg", self.degrees)
end
function main()
local subtrahends = bearing:list{
20, -45, -85, -95, -45, -45, 29.4803, -78.3251,
-70099.74233810938, -165313.6666297357,
1174.8380510598456, 60175.77306795546
}
local minuends = bearing:list{
45, 45, 90, 90, 125, 145, -88.6381, -159.036,
29840.67437876723, 33693.9894517456,
-154146.66490124757, 42213.07192354373
}
for index = 1, #minuends do
local b2, b1 = minuends[index], subtrahends[index]
local b3 = b2:subtract(b1)
local statement = string.format(
"%s - %s = %s\n",
b2:text(), b1:text(), b3:text()
)
io.write(statement)
end
end
main() |
http://rosettacode.org/wiki/Anagrams/Deranged_anagrams | Anagrams/Deranged anagrams | Two or more words are said to be anagrams if they have the same characters, but in a different order.
By analogy with derangements we define a deranged anagram as two words with the same characters, but in which the same character does not appear in the same position in both words.
Task[edit]
Use the word list at unixdict to find and display the longest deranged anagram.
Related tasks
Permutations/Derangements
Best shuffle
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #Pascal | Pascal | program Anagrams_Deranged;
{$IFDEF FPC}
{$MODE Delphi}
{$Optimization ON,ALL}
uses
SysUtils,
Classes;
{$ELSE}
{$APPTYPE CONSOLE}
uses
System.SysUtils,
System.Classes,
{$R *.res}
{$ENDIF}
function Sort(const s: string):string;
//insertion sort
var
pRes : pchar;
i, j, aLength: NativeInt;
tmpc: Char;
begin
aLength := s.Length;
if aLength = 0 then
exit('');
Result := s;
//without it, s will be sorted
UniqueString(Result);
//insertion sort
pRes := pChar(Result);
dec(aLength,1);
for i := 0 to aLength do
Begin
tmpc := pRes[i];
j := i-1;
while (j>=0) AND (tmpc < pRes[j]) do
Begin
pRes[j+1] := pRes[j];
dec(j);
end;
inc(j);
pRes[j]:= tmpc;
end;
end;
function CompareLength(List: TStringList; Index1, Index2: longInt): longInt;
begin
result := List[Index1].Length - List[Index2].Length;
IF result = 0 then
result := CompareStr(List[Index1],List[Index2]);
end;
function IsDerangement(const word1, word2: string): Boolean;
var
i: NativeInt;
begin
for i := word1.Length downto 1 do
if word1[i] = word2[i] then
exit(False);
Result := True;
end;
var
Dict,SortDict: TStringList;
words: string;
StopWatch: Int64;
Count, Index: NativeInt;
begin
Dict := TStringList.Create();
Dict.LoadFromFile('unixdict.txt');
StopWatch := GettickCount64;
SortDict:= TStringList.Create();
SortDict.capacity := Dict.Count;
For Index := 0 to Dict.Count - 1 do
Begin
SortDict.Add(Sort(Dict[Index]));
//remember the origin in Dict
SortDict.Objects[Index]:= TObject(Index);
end;
SortDict.CustomSort(CompareLength);
Index := Dict.Count - 1;
words := '';
Count := 1;
while Index - Count >= 0 do
begin
if SortDict[Index]= SortDict[Index - Count] then
begin
if IsDerangement(Dict[NativeInt(SortDict.Objects[Index])],
Dict[NativeInt(SortDict.Objects[Index - Count])]) then
begin
words := Dict[NativeInt(SortDict.Objects[Index])] + ' - ' +
Dict[NativeInt(SortDict.Objects[Index - Count])];
Break;
end;
Inc(Count);
end
else
begin
Dec(Index, Count);
Count := 1;
end;
end;
StopWatch := GettickCount64-StopWatch;
Writeln(Format('Time pass: %d ms [AMD 2200G-Linux Fossa]',[StopWatch]));
writeln(#10'Longest derangement words are:'#10#10, words);
SortDict.free;
Dict.Free;
end.
|
http://rosettacode.org/wiki/Anonymous_recursion | Anonymous recursion | While implementing a recursive function, it often happens that we must resort to a separate helper function to handle the actual recursion.
This is usually the case when directly calling the current function would waste too many resources (stack space, execution time), causing unwanted side-effects, and/or the function doesn't have the right arguments and/or return values.
So we end up inventing some silly name like foo2 or foo_helper. I have always found it painful to come up with a proper name, and see some disadvantages:
You have to think up a name, which then pollutes the namespace
Function is created which is called from nowhere else
The program flow in the source code is interrupted
Some languages allow you to embed recursion directly in-place. This might work via a label, a local gosub instruction, or some special keyword.
Anonymous recursion can also be accomplished using the Y combinator.
Task
If possible, demonstrate this by writing the recursive version of the fibonacci function (see Fibonacci sequence) which checks for a negative argument before doing the actual recursion.
| #Kotlin | Kotlin | fun fib(n: Int): Int {
require(n >= 0)
fun fib1(k: Int, a: Int, b: Int): Int =
if (k == 0) a else fib1(k - 1, b, a + b)
return fib1(n, 0, 1)
}
fun main(args: Array<String>) {
for (i in 0..20) print("${fib(i)} ")
println()
} |
http://rosettacode.org/wiki/Amicable_pairs | Amicable pairs | Two integers
N
{\displaystyle N}
and
M
{\displaystyle M}
are said to be amicable pairs if
N
≠
M
{\displaystyle N\neq M}
and the sum of the proper divisors of
N
{\displaystyle N}
(
s
u
m
(
p
r
o
p
D
i
v
s
(
N
)
)
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (N))}
)
=
M
{\displaystyle =M}
as well as
s
u
m
(
p
r
o
p
D
i
v
s
(
M
)
)
=
N
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (M))=N}
.
Example
1184 and 1210 are an amicable pair, with proper divisors:
1, 2, 4, 8, 16, 32, 37, 74, 148, 296, 592 and
1, 2, 5, 10, 11, 22, 55, 110, 121, 242, 605 respectively.
Task
Calculate and show here the Amicable pairs below 20,000; (there are eight).
Related tasks
Proper divisors
Abundant, deficient and perfect number classifications
Aliquot sequence classifications and its amicable classification.
| #Haskell | Haskell | divisors :: (Integral a) => a -> [a]
divisors n = filter ((0 ==) . (n `mod`)) [1 .. (n `div` 2)]
main :: IO ()
main = do
let range = [1 .. 20000 :: Int]
divs = zip range $ map (sum . divisors) range
pairs = [(n, m) | (n, nd) <- divs, (m, md) <- divs,
n < m, nd == m, md == n]
print pairs |
http://rosettacode.org/wiki/Animation | Animation |
Animation is integral to many parts of GUIs, including both the fancy effects when things change used in window managers, and of course games. The core of any animation system is a scheme for periodically changing the display while still remaining responsive to the user. This task demonstrates this.
Task
Create a window containing the string "Hello World! " (the trailing space is significant).
Make the text appear to be rotating right by periodically removing one letter from the end of the string and attaching it to the front.
When the user clicks on the (windowed) text, it should reverse its direction.
| #R | R |
rotate_string <- function(x, forwards)
{
nchx <- nchar(x)
if(forwards)
{
paste(substr(x, nchx, nchx), substr(x, 1, nchx - 1), sep = "")
} else
{
paste(substr(x, 2, nchx), substr(x, 1, 1), sep = "")
}
}
handle_rotate_label <- function(obj, interval = 100)
{
addHandlerIdle(obj,
handler = function(h, ...)
{
svalue(obj) <- rotate_string(svalue(obj), tag(obj, "forwards"))
},
interval = interval
)
}
handle_change_direction_on_click <- function(obj)
{
addHandlerClicked(obj,
handler = function(h, ...)
{
tag(h$obj, "forwards") <- !tag(h$obj, "forwards")
}
)
}
library(gWidgets)
library(gWidgetstcltk) #or library(gWidgetsRGtk2) or library(gWidgetsrJava)
lab <- glabel("Hello World! ", container = gwindow())
tag(lab, "forwards") <- TRUE
handle_rotate_label(lab)
handle_change_direction_on_click(lab)
|
http://rosettacode.org/wiki/Animation | Animation |
Animation is integral to many parts of GUIs, including both the fancy effects when things change used in window managers, and of course games. The core of any animation system is a scheme for periodically changing the display while still remaining responsive to the user. This task demonstrates this.
Task
Create a window containing the string "Hello World! " (the trailing space is significant).
Make the text appear to be rotating right by periodically removing one letter from the end of the string and attaching it to the front.
When the user clicks on the (windowed) text, it should reverse its direction.
| #Racket | Racket |
#lang racket/gui
;; One of 'left or 'right
(define direction 'left)
;; Set up the GUI
(define animation-frame%
(class frame%
(super-new [label "Animation"])
;; reverse direction on a click
(define/override (on-subwindow-event win evt)
(when (send evt button-down?)
(set! direction
(if (eq? direction 'left)
'right
'left))))))
(define frame (new animation-frame%))
(define msg (new message%
[label "Hello World! "]
[parent frame]))
;; Timer callback to adjust the message
(define (callback)
(define old-label (send msg get-label))
(define len (string-length old-label))
(if (eq? direction 'left)
(send msg set-label
(string-append (substring old-label 1)
(substring old-label 0 1)))
(send msg set-label
(string-append (substring old-label (- len 1) len)
(substring old-label 0 (- len 1))))))
;; Set a timer and go
(define timer (new timer%
[notify-callback callback]
[interval 500]))
(send frame show #t)
|
http://rosettacode.org/wiki/Animate_a_pendulum | Animate a pendulum |
One good way of making an animation is by simulating a physical system and illustrating the variables in that system using a dynamically changing graphical display.
The classic such physical system is a simple gravity pendulum.
Task
Create a simple physical model of a pendulum and animate it.
| #Logo | Logo | make "angle 45
make "L 1
make "bob 10
to draw.pendulum
clearscreen
seth :angle+180 ; down on screen is 180
forward :L*100-:bob
penup
forward :bob
pendown
arc 360 :bob
end
make "G 9.80665
make "dt 1/30
make "acc 0
make "vel 0
to step.pendulum
make "acc -:G / :L * sin :angle
make "vel :vel + :acc * :dt
make "angle :angle + :vel * :dt
wait :dt*60
draw.pendulum
end
hideturtle
until [key?] [step.pendulum] |
http://rosettacode.org/wiki/Amb | Amb | Define and give an example of the Amb operator.
The Amb operator (short for "ambiguous") expresses nondeterminism. This doesn't refer to randomness (as in "nondeterministic universe") but is closely related to the term as it is used in automata theory ("non-deterministic finite automaton").
The Amb operator takes a variable number of expressions (or values if that's simpler in the language) and yields a correct one which will satisfy a constraint in some future computation, thereby avoiding failure.
Problems whose solution the Amb operator naturally expresses can be approached with other tools, such as explicit nested iterations over data sets, or with pattern matching. By contrast, the Amb operator appears integrated into the language. Invocations of Amb are not wrapped in any visible loops or other search patterns; they appear to be independent.
Essentially Amb(x, y, z) splits the computation into three possible futures: a future in which the value x is yielded, a future in which the value y is yielded and a future in which the value z is yielded. The future which leads to a successful subsequent computation is chosen. The other "parallel universes" somehow go away. Amb called with no arguments fails.
For simplicity, one of the domain values usable with Amb may denote failure, if that is convenient. For instance, it is convenient if a Boolean false denotes failure, so that Amb(false) fails, and thus constraints can be expressed using Boolean expressions like Amb(x * y == 8) which unless x and y add to four.
A pseudo-code program which satisfies this constraint might look like:
let x = Amb(1, 2, 3)
let y = Amb(7, 6, 4, 5)
Amb(x * y = 8)
print x, y
The output is 2 4 because Amb(1, 2, 3) correctly chooses the future in which x has value 2, Amb(7, 6, 4, 5) chooses 4 and consequently Amb(x * y = 8) produces a success.
Alternatively, failure could be represented using strictly Amb():
unless x * y = 8 do Amb()
Or else Amb could take the form of two operators or functions: one for producing values and one for enforcing constraints:
let x = Ambsel(1, 2, 3)
let y = Ambsel(4, 5, 6)
Ambassert(x * y = 8)
print x, y
where Ambassert behaves like Amb() if the Boolean expression is false, otherwise it allows the future computation to take place, without yielding any value.
The task is to somehow implement Amb, and demonstrate it with a program which chooses one word from each of the following four sets of character strings to generate a four-word sentence:
"the" "that" "a"
"frog" "elephant" "thing"
"walked" "treaded" "grows"
"slowly" "quickly"
The constraint to be satisfied is that the last character of each word (other than the last) is the same as the first character of its successor.
The only successful sentence is "that thing grows slowly"; other combinations do not satisfy the constraint and thus fail.
The goal of this task isn't to simply process the four lists of words with explicit, deterministic program flow such as nested iteration, to trivially demonstrate the correct output. The goal is to implement the Amb operator, or a facsimile thereof that is possible within the language limitations.
| #Clojure | Clojure | (ns amb
(:use clojure.contrib.monads))
(defn amb [wss]
(let [valid-word (fn [w1 w2]
(if (and w1 (= (last w1) (first w2)))
(str w1 " " w2)))]
(filter #(reduce valid-word %)
(with-monad sequence-m (m-seq wss)))))
amb> (amb '(("the" "that" "a") ("frog" "elephant" "thing") ("walked" "treaded" "grows") ("slowly" "quickly")))
(("that" "thing" "grows" "slowly"))
|
http://rosettacode.org/wiki/Aliquot_sequence_classifications | Aliquot sequence classifications | An aliquot sequence of a positive integer K is defined recursively as the first member
being K and subsequent members being the sum of the Proper divisors of the previous term.
If the terms eventually reach 0 then the series for K is said to terminate.
There are several classifications for non termination:
If the second term is K then all future terms are also K and so the sequence repeats from the first term with period 1 and K is called perfect.
If the third term would be repeating K then the sequence repeats with period 2 and K is called amicable.
If the Nth term would be repeating K for the first time, with N > 3 then the sequence repeats with period N - 1 and K is called sociable.
Perfect, amicable and sociable numbers eventually repeat the original number K; there are other repetitions...
Some K have a sequence that eventually forms a periodic repetition of period 1 but of a number other than K, for example 95 which forms the sequence 95, 25, 6, 6, 6, ... such K are called aspiring.
K that have a sequence that eventually forms a periodic repetition of period >= 2 but of a number other than K, for example 562 which forms the sequence 562, 284, 220, 284, 220, ... such K are called cyclic.
And finally:
Some K form aliquot sequences that are not known to be either terminating or periodic; these K are to be called non-terminating.
For the purposes of this task, K is to be classed as non-terminating if it has not been otherwise classed after generating 16 terms or if any term of the sequence is greater than 2**47 = 140,737,488,355,328.
Task
Create routine(s) to generate the aliquot sequence of a positive integer enough to classify it according to the classifications given above.
Use it to display the classification and sequences of the numbers one to ten inclusive.
Use it to show the classification and sequences of the following integers, in order:
11, 12, 28, 496, 220, 1184, 12496, 1264460, 790, 909, 562, 1064, 1488, and optionally 15355717786080.
Show all output on this page.
Related tasks
Abundant, deficient and perfect number classifications. (Classifications from only the first two members of the whole sequence).
Proper divisors
Amicable pairs
| #AWK | AWK |
#!/bin/gawk -f
function sumprop(num, i,sum,root) {
if (num == 1) return 0
sum=1
root=sqrt(num)
for ( i=2; i < root; i++) {
if (num % i == 0 )
{
sum = sum + i + num/i
}
}
if (num % root == 0)
{
sum = sum + root
}
return sum
}
function class(k, oldk,newk,seq){
# first term
oldk = k
seq = " "
# second term
newk = sumprop(oldk)
oldk = newk
seq = seq " " newk
if (newk == 0) return "terminating " seq
if (newk == k) return "perfect " seq
# third term
newk = sumprop(oldk)
oldk = newk
seq = seq " " newk
if (newk == 0) return "terminating " seq
if (newk == k) return "amicable " seq
for (t=4; t<17; t++) {
newk = sumprop(oldk)
seq = seq " " newk
if (newk == 0) return "terminating " seq
if (newk == k) return "sociable (period " t-1 ") "seq
if (newk == oldk) return "aspiring " seq
if (index(seq," " newk " ") > 0) return "cyclic (at " newk ") " seq
if (newk > 140737488355328) return "non-terminating (term > 140737488355328) " seq
oldk = newk
}
return "non-terminating (after 16 terms) " seq
}
BEGIN{
print "Number classification sequence"
for (j=1; j < 11; j++)
{
print j,class(j)}
print 11,class(11)
print 12,class(12)
print 28,class(28)
print 496,class(496)
print 220,class(220)
print 1184,class(1184)
print 12496,class(12496)
print 1264460,class(1264460)
print 790,class(790)
print 909,class(909)
print 562,class(562)
print 1064,class(1064)
print 1488,class(1488)
print 15355717786080,class(15355717786080)
}
|
http://rosettacode.org/wiki/Active_Directory/Search_for_a_user | Active Directory/Search for a user | Make sure you Connect to Active Directory
| #D | D |
import openldap;
import std.stdio;
void main() {
// connect to server
auto ldap = LDAP("ldap://localhost");
// search for uid
auto r = ldap.search_s("dc=example,dc=com", LDAP_SCOPE_SUBTREE, "(uid=%s)".format("test"));
// show properties
writeln("Found dn: %s", r[0].dn);
foreach(k, v; r[0].entry)
writeln("%s = %s", k, v);
// bind on found entry
int b = ldap.bind_s(r[0].dn, "password");
scope(exit) ldap.unbind;
if (b)
{
writeln("error on binding");
return;
}
// do something
...
}
|
http://rosettacode.org/wiki/Active_Directory/Search_for_a_user | Active Directory/Search for a user | Make sure you Connect to Active Directory
| #Eiffel | Eiffel |
feature -- Validation
is_user_credential_valid (a_domain, a_username, a_password: READABLE_STRING_GENERAL): BOOLEAN
-- Is the pair `a_username'/`a_password' a valid credential in `a_domain'?
local
l_domain, l_username, l_password: WEL_STRING
do
create l_domain.make (a_domain)
create l_username.make (a_username)
create l_password.make (a_password)
Result := cwel_is_credential_valid (l_domain.item, l_username.item, l_password.item)
end
|
http://rosettacode.org/wiki/Active_Directory/Search_for_a_user | Active Directory/Search for a user | Make sure you Connect to Active Directory
| #Go | Go | package main
import (
"log"
"github.com/jtblin/go-ldap-client"
)
func main() {
client := &ldap.LDAPClient{
Base: "dc=example,dc=com",
Host: "ldap.example.com",
Port: 389,
GroupFilter: "(memberUid=%s)",
}
defer client.Close()
err := client.Connect()
if err != nil {
log.Fatalf("Failed to connect : %+v", err)
}
groups, err := client.GetGroupsOfUser("username")
if err != nil {
log.Fatalf("Error getting groups for user %s: %+v", "username", err)
}
log.Printf("Groups: %+v", groups)
} |
http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | Add a variable to a class instance at runtime | Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
| #ActionScript | ActionScript | var object:Object = new Object();
object.foo = "bar"; |
http://rosettacode.org/wiki/Address_of_a_variable | Address of a variable |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
| #BBC_BASIC | BBC BASIC | REM get a variable's address:
y% = ^x%
REM can't set a variable's address, but can access a given memory location (4 bytes):
x% = !y% |
http://rosettacode.org/wiki/Address_of_a_variable | Address of a variable |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
| #C_.2F_C.2B.2B | C / C++ | int i;
void* address_of_i = &i; |
http://rosettacode.org/wiki/Address_of_a_variable | Address of a variable |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
| #C.23 | C# | unsafe
{
int i = 5;
void* address_of_i = &i;
} |
http://rosettacode.org/wiki/AKS_test_for_primes | AKS test for primes | The AKS algorithm for testing whether a number is prime is a polynomial-time algorithm based on an elementary theorem about Pascal triangles.
The theorem on which the test is based can be stated as follows:
a number
p
{\displaystyle p}
is prime if and only if all the coefficients of the polynomial expansion of
(
x
−
1
)
p
−
(
x
p
−
1
)
{\displaystyle (x-1)^{p}-(x^{p}-1)}
are divisible by
p
{\displaystyle p}
.
Example
Using
p
=
3
{\displaystyle p=3}
:
(x-1)^3 - (x^3 - 1)
= (x^3 - 3x^2 + 3x - 1) - (x^3 - 1)
= -3x^2 + 3x
And all the coefficients are divisible by 3, so 3 is prime.
Note:
This task is not the AKS primality test. It is an inefficient exponential time algorithm discovered in the late 1600s and used as an introductory lemma in the AKS derivation.
Task
Create a function/subroutine/method that given
p
{\displaystyle p}
generates the coefficients of the expanded polynomial representation of
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
.
Use the function to show here the polynomial expansions of
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
for
p
{\displaystyle p}
in the range 0 to at least 7, inclusive.
Use the previous function in creating another function that when given
p
{\displaystyle p}
returns whether
p
{\displaystyle p}
is prime using the theorem.
Use your test to generate a list of all primes under 35.
As a stretch goal, generate all primes under 50 (needs integers larger than 31-bit).
References
Agrawal-Kayal-Saxena (AKS) primality test (Wikipedia)
Fool-Proof Test for Primes - Numberphile (Video). The accuracy of this video is disputed -- at best it is an oversimplification.
| #ALGOL_68 | ALGOL 68 |
BEGIN
COMMENT
Mathematical preliminaries.
First note that the homogeneous polynomial (a+b)^n is symmetrical
(to see this just swap the variables a and b). Therefore its
coefficients need be calculated only to that of (ab)^{n/2} for even
n or (ab)^{(n-1)/2} for odd n.
Second, the coefficients are the binomial coefficients C(n,k) where
the coefficient of a^k b^(n-k) is C(n,k) = n! / k! (k-1)!. This
leads to an immediate and relatively efficient implementation for
which we do not need to compute n! before dividing by k! and (k-1)!
but, rather cancel common factors as we go along. Further, the
well-known symmetry identity C(n,k) = C(n, n-k) allows a
significant reduction in computational effort.
Third, (x-1)^n is the value of (a + b)^n when a=x and b = -1. The
powers of -1 alternate between +1 and -1 so we may as well compute
(x+1)^n and negate every other coefficient when printing.
COMMENT
PR precision=300 PR
MODE LLI = LONG LONG INT; CO For brevity CO
PROC choose = (INT n, k) LLI :
BEGIN
LLI result := 1;
INT sym k := (k >= n%2 | n-k | k); CO Use symmetry CO
IF sym k > 0 THEN
FOR i FROM 0 TO sym k-1
DO
result TIMESAB (n-i);
result OVERAB (i+1)
OD
FI;
result
END;
PROC coefficients = (INT n) [] LLI :
BEGIN
[0:n] LLI a;
FOR i FROM 0 TO n%2
DO
a[i] := a[n-i] := choose (n, i) CO Use symmetry CO
OD;
a
END;
COMMENT
First print the polynomials (x-1)^n, remembering to alternate signs
and to tidy up the constant term, the x^1 term and the x^n term.
This means we must treat (x-1)^0 and (x-1)^1 specially
COMMENT
FOR n FROM 0 TO 7
DO
[0:n] LLI a := coefficients (n);
printf (($"(x-1)^", g(0), " = "$, n));
CASE n+1 IN
printf (($g(0)l$, a[0])),
printf (($"x - ", g(0)l$, a[1]))
OUT
printf (($"x^", g(0)$, n));
FOR i TO n-2
DO
printf (($xax, g(0), "x^", g(0)$, (ODD i | "-" | "+"), a[i], n-i))
OD;
printf (($xax, g(0), "x"$, (ODD (n-1) | "-" | "+"), a[n-1]));
printf (($xaxg(0)l$, (ODD n | "-" | "+"), a[n]))
ESAC
OD;
COMMENT
Finally, for the "AKS" portion of the task, the sign of the
coefficient has no effect on its divisibility by p so, once again,
we may as well use the positive coefficients. Symmetry clearly
reduces the necessary number of tests by a factor of two.
COMMENT
PROC is prime = (INT n) BOOL :
BEGIN
BOOL prime := TRUE;
FOR i FROM 1 TO n%2 WHILE prime DO prime := choose (n, i) MOD n = 0 OD;
prime
END;
print ("Primes < 50 are ");
FOR n FROM 2 TO 50 DO (is prime (n) | printf (($g(0)x$, n)) ) OD;
print (newline);
print ("And just to show off, the primes between 900 and 1000 are ");
FOR n FROM 900 TO 1000 DO IF is prime (n) THEN printf (($g(0)x$, n)) FI OD;
print (newline)
END
|
http://rosettacode.org/wiki/Additive_primes | Additive primes | Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
the OEIS entry: A046704 additive primes.
the prime-numbers entry: additive primes.
the geeks for geeks entry: additive prime number.
the prime-numbers fandom: additive primes.
| #AppleScript | AppleScript | on sieveOfEratosthenes(limit)
script o
property numberList : {missing value}
end script
repeat with n from 2 to limit
set end of o's numberList to n
end repeat
repeat with n from 2 to (limit ^ 0.5) div 1
if (item n of o's numberList is n) then
repeat with multiple from n * n to limit by n
set item multiple of o's numberList to missing value
end repeat
end if
end repeat
return o's numberList's numbers
end sieveOfEratosthenes
on sumOfDigits(n) -- n assumed to be a positive decimal integer.
set sum to n mod 10
set n to n div 10
repeat until (n = 0)
set sum to sum + n mod 10
set n to n div 10
end repeat
return sum
end sumOfDigits
on additivePrimes(limit)
script o
property primes : sieveOfEratosthenes(limit)
property additives : {}
end script
repeat with p in o's primes
if (sumOfDigits(p) is in o's primes) then set end of o's additives to p's contents
end repeat
return o's additives
end additivePrimes
-- Task code:
tell additivePrimes(499) to return {|additivePrimes<500|:it, numberThereof:count} |
http://rosettacode.org/wiki/Algebraic_data_types | Algebraic data types | Some languages offer direct support for algebraic data types and pattern matching on them. While this of course can always be simulated with manual tagging and conditionals, it allows for terse code which is easy to read, and can represent the algorithm directly.
Task
As an example, implement insertion in a red-black-tree.
A red-black-tree is a binary tree where each internal node has a color attribute red or black. Moreover, no red node can have a red child, and every path from the root to an empty node must contain the same number of black nodes. As a consequence, the tree is balanced, and must be re-balanced after an insertion.
Reference
Red-Black Trees in a Functional Setting
| #jq | jq | # bindings($x) attempts to match . and $x structurally on the
# assumption that . is free of JSON objects, and that any objects in
# $x will have distinct, singleton keys that are to be interpreted as
# variables. These variables will match the corresponding entities in
# . if . and $x can be structurally matched.
#
# If . and $x cannot be matched, then null is returned;
# otherwise, if $x contains no objects, {} is returned;
# finally, if . and $x can be structurally matched, a composite object containing the bindings
# will be returned.
# Output: null (failure to match) or a single JSON object giving the bindings if any.
def bindings($x):
if $x == . then {} # by assumption, no bindings are necessary
elif ($x|type) == "object"
then ($x|keys) as $keys
| if ($keys|length) == 1 then {($keys[0]): .} else "objects should be singletons"|error end
elif type != ($x|type) then null
elif type == "array"
then if length != ($x|length) then null
else . as $in
| reduce range(0;length) as $i ({};
if . == null then null
else ($in[$i] | bindings($x[$i]) ) as $m
| if $m == null then null else . + $m end
end)
end
else null
end ; |
http://rosettacode.org/wiki/Algebraic_data_types | Algebraic data types | Some languages offer direct support for algebraic data types and pattern matching on them. While this of course can always be simulated with manual tagging and conditionals, it allows for terse code which is easy to read, and can represent the algorithm directly.
Task
As an example, implement insertion in a red-black-tree.
A red-black-tree is a binary tree where each internal node has a color attribute red or black. Moreover, no red node can have a red child, and every path from the root to an empty node must contain the same number of black nodes. As a consequence, the tree is balanced, and must be re-balanced after an insertion.
Reference
Red-Black Trees in a Functional Setting
| #Julia | Julia | import Base.length
abstract type AbstractColoredNode end
struct RedNode <: AbstractColoredNode end; const R = RedNode()
struct BlackNode <: AbstractColoredNode end; const B = BlackNode()
struct Empty end; const E = Empty()
length(e::Empty) = 1
function balance(b::BlackNode, v::Vector, z, d)
if v[1] == R
if length(v[2]) == 4 && v[2][1] == R
return [R, [B, v[2][2], v[2][3], v[2][4]], v[3], [B, v[4], z, d]]
elseif length(v[4]) == 4 && v[4][1] == R
return [R, [B, v[2], v[3], v[4][2]], v[4][3], [B, v[4][4], z, d]]
end
end
[b, v, z, d]
end
function balance(b::BlackNode, a, x, v::Vector)
if v[1] == R
if length(v[2]) == 4 && v[2][1] == R
return [R, [B, a, x, v[2][2]], v[2][3], [B, v[2][4], v[3], v[4]]]
elseif length(v[4]) == 4 && v[4][1] == R
return [R, [B, a, x, v[2]], v[3], [B, v[4][2], v[4][3], v[4][4]]]
end
end
[b, a, x, v]
end
function balance(b::BlackNode, a::Vector, x, v::Vector)
if v[1] == R
if length(v[2]) == 4 && v[2][1] == R
return [R, [B, a, x, v[2][2]], v[2][3], [B, v[2][4], v[3], v[4]]]
elseif length(v[4]) == 4 && v[4][1] == R
return [R, [B, a, x, v[2]], v[3], [B, v[4][2], v[4][3], v[4][4]]]
end
end
[b, a, x, v]
end
balance(node, l, a, r) = [node, l, a, r]
function ins(v::Vector, x::Number)
if length(v) == 4
if x < v[3]
return balance(v[1], ins(v[2], x), v[3], v[4])
elseif x > v[3]
return balance(v[1], v[2], v[3], ins(v[4], x))
end
end
v
end
ins(t, a) = [R, E, a, E]
insert(v, a) = (t = ins(v, a); t[1] = B; t)
function testRB()
t = E
for i in rand(collect(1:20), 10)
t = insert(t, i)
end
println(replace(string(t), r"lackNode\(\)|edNode\(\)|Any|mpty\(\)" => ""))
end
testRB()
|
http://rosettacode.org/wiki/Almost_prime | Almost prime | A k-Almost-prime is a natural number
n
{\displaystyle n}
that is the product of
k
{\displaystyle k}
(possibly identical) primes.
Example
1-almost-primes, where
k
=
1
{\displaystyle k=1}
, are the prime numbers themselves.
2-almost-primes, where
k
=
2
{\displaystyle k=2}
, are the semiprimes.
Task
Write a function/method/subroutine/... that generates k-almost primes and use it to create a table here of the first ten members of k-Almost primes for
1
<=
K
<=
5
{\displaystyle 1<=K<=5}
.
Related tasks
Semiprime
Category:Prime Numbers
| #Delphi | Delphi |
program AlmostPrime;
{$APPTYPE CONSOLE}
function IsKPrime(const n, k: Integer): Boolean;
var
p, f, v: Integer;
begin
f := 0;
p := 2;
v := n;
while (f < k) and (p*p <= n) do begin
while (v mod p) = 0 do begin
v := v div p;
Inc(f);
end;
Inc(p);
end;
if v > 1 then Inc(f);
Result := f = k;
end;
var
i, c, k: Integer;
begin
for k := 1 to 5 do begin
Write('k = ', k, ':');
c := 0;
i := 2;
while c < 10 do begin
if IsKPrime(i, k) then begin
Write(' ', i);
Inc(c);
end;
Inc(i);
end;
WriteLn;
end;
end.
|
http://rosettacode.org/wiki/Anagrams | Anagrams | When two or more words are composed of the same characters, but in a different order, they are called anagrams.
Task[edit]
Using the word list at http://wiki.puzzlers.org/pub/wordlists/unixdict.txt,
find the sets of words that share the same characters that contain the most words in them.
Related tasks
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #BBC_BASIC | BBC BASIC | INSTALL @lib$+"SORTLIB"
sort% = FN_sortinit(0,0)
REM Count number of words in dictionary:
nwords% = 0
dict% = OPENIN("unixdict.txt")
WHILE NOT EOF#dict%
word$ = GET$#dict%
nwords% += 1
ENDWHILE
CLOSE #dict%
REM Create arrays big enough to contain the dictionary:
DIM dict$(nwords%), sort$(nwords%)
REM Load the dictionary and sort the characters in the words:
dict% = OPENIN("unixdict.txt")
FOR word% = 1 TO nwords%
word$ = GET$#dict%
dict$(word%) = word$
sort$(word%) = FNsortchars(word$)
NEXT word%
CLOSE #dict%
REM Sort arrays using the 'sorted character' words as a key:
C% = nwords%
CALL sort%, sort$(1), dict$(1)
REM Count the longest sets of anagrams:
max% = 0
set% = 1
FOR word% = 1 TO nwords%-1
IF sort$(word%) = sort$(word%+1) THEN
set% += 1
ELSE
IF set% > max% THEN max% = set%
set% = 1
ENDIF
NEXT word%
REM Output the results:
set% = 1
FOR word% = 1 TO nwords%-1
IF sort$(word%) = sort$(word%+1) THEN
set% += 1
ELSE
IF set% = max% THEN
FOR anagram% = word%-max%+1 TO word%
PRINT dict$(anagram%),;
NEXT
PRINT
ENDIF
set% = 1
ENDIF
NEXT word%
END
DEF FNsortchars(word$)
LOCAL C%, char&()
DIM char&(LEN(word$))
$$^char&(0) = word$
C% = LEN(word$)
CALL sort%, char&(0)
= $$^char&(0) |
http://rosettacode.org/wiki/Angle_difference_between_two_bearings | Angle difference between two bearings | Finding the angle between two bearings is often confusing.[1]
Task
Find the angle which is the result of the subtraction b2 - b1, where b1 and b2 are the bearings.
Input bearings are expressed in the range -180 to +180 degrees.
The result is also expressed in the range -180 to +180 degrees.
Compute the angle for the following pairs:
20 degrees (b1) and 45 degrees (b2)
-45 and 45
-85 and 90
-95 and 90
-45 and 125
-45 and 145
29.4803 and -88.6381
-78.3251 and -159.036
Optional extra
Allow the input bearings to be any (finite) value.
Test cases
-70099.74233810938 and 29840.67437876723
-165313.6666297357 and 33693.9894517456
1174.8380510598456 and -154146.66490124757
60175.77306795546 and 42213.07192354373
| #Maple | Maple | getDiff := proc(b1,b2)
local r:
r := frem(b2 - b1, 360):
if r >= 180 then r := r - 360: fi:
return r:
end proc:
getDiff(20,45);
getDiff(-45,45);
getDiff(-85,90);
getDiff(-95,90);
getDiff(-45,125);
getDiff(-45,145);
getDiff(29.4803, -88.6381);
getDiff(-78.3251,-159.036);
getDiff(-70099.74233810938,29840.67437876723);
getDiff(-165313.6666297357,33693.9894517456);
getDiff(1174.8380510598456,-154146.66490124757);
getDiff(60175.77306795546,42213.07192354373) |
http://rosettacode.org/wiki/Anagrams/Deranged_anagrams | Anagrams/Deranged anagrams | Two or more words are said to be anagrams if they have the same characters, but in a different order.
By analogy with derangements we define a deranged anagram as two words with the same characters, but in which the same character does not appear in the same position in both words.
Task[edit]
Use the word list at unixdict to find and display the longest deranged anagram.
Related tasks
Permutations/Derangements
Best shuffle
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #Perl | Perl | sub deranged { # only anagrams ever get here
my @a = split('', shift); # split word into letters
my @b = split('', shift);
for (0 .. $#a) {
$a[$_] eq $b[$_] and return;
}
return 1
}
sub find_deranged {
for my $i ( 0 .. $#_ ) {
for my $j ( $i+1 .. $#_ ) {
next unless deranged $_[$i], $_[$j];
print "length ", length($_[$i]), ": $_[$i] => $_[$j]\n";
return 1;
}
}
}
my %letter_list;
open my $in, 'unixdict.txt';
local $/ = undef;
for (split(' ', <$in>)) {
# store anagrams in hash table by letters they contain
push @{ $letter_list{ join('', sort split('', $_)) } }, $_
}
for ( sort { length($b) <=> length($a) } # sort by length, descending
grep { @{ $letter_list{$_} } > 1 } # take only ones with anagrams
keys %letter_list )
{
# if we find a pair, they are the longested due to the sort before
last if find_deranged(@{ $letter_list{$_} });
} |
http://rosettacode.org/wiki/Anonymous_recursion | Anonymous recursion | While implementing a recursive function, it often happens that we must resort to a separate helper function to handle the actual recursion.
This is usually the case when directly calling the current function would waste too many resources (stack space, execution time), causing unwanted side-effects, and/or the function doesn't have the right arguments and/or return values.
So we end up inventing some silly name like foo2 or foo_helper. I have always found it painful to come up with a proper name, and see some disadvantages:
You have to think up a name, which then pollutes the namespace
Function is created which is called from nowhere else
The program flow in the source code is interrupted
Some languages allow you to embed recursion directly in-place. This might work via a label, a local gosub instruction, or some special keyword.
Anonymous recursion can also be accomplished using the Y combinator.
Task
If possible, demonstrate this by writing the recursive version of the fibonacci function (see Fibonacci sequence) which checks for a negative argument before doing the actual recursion.
| #Lambdatalk | Lambdatalk |
1) defining a quasi-recursive function combined with a simple Ω-combinator:
{def fibo {lambda {:n}
{{{lambda {:f} {:f :f}}
{lambda {:f :n :a :b}
{if {< :n 0}
then the number must be positive!
else {if {< :n 1}
then :a
else {:f :f {- :n 1} {+ :a :b} :a}}}}} :n 1 0}}}
-> fibo
2) testing:
{fibo -1} -> the number must be positive!
{fibo 0} -> 1
{fibo 8} -> 34
{fibo 1000} -> 7.0330367711422765e+208
{S.map fibo {S.serie 1 20}}
-> 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181 6765 10946
We could also avoid any name and write an IIFE
{{lambda {:n}
{{{lambda {:f} {:f :f}}
{lambda {:f :n :a :b}
{if {< :n 0}
then the number must be positive!
else {if {< :n 1}
then :a
else {:f :f {- :n 1} {+ :a :b} :a}}}}} :n 1 0}}
8}
-> 34
|
http://rosettacode.org/wiki/Amicable_pairs | Amicable pairs | Two integers
N
{\displaystyle N}
and
M
{\displaystyle M}
are said to be amicable pairs if
N
≠
M
{\displaystyle N\neq M}
and the sum of the proper divisors of
N
{\displaystyle N}
(
s
u
m
(
p
r
o
p
D
i
v
s
(
N
)
)
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (N))}
)
=
M
{\displaystyle =M}
as well as
s
u
m
(
p
r
o
p
D
i
v
s
(
M
)
)
=
N
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (M))=N}
.
Example
1184 and 1210 are an amicable pair, with proper divisors:
1, 2, 4, 8, 16, 32, 37, 74, 148, 296, 592 and
1, 2, 5, 10, 11, 22, 55, 110, 121, 242, 605 respectively.
Task
Calculate and show here the Amicable pairs below 20,000; (there are eight).
Related tasks
Proper divisors
Abundant, deficient and perfect number classifications
Aliquot sequence classifications and its amicable classification.
| #J | J | factors=: [: /:~@, */&>@{@((^ i.@>:)&.>/)@q:~&__
properDivisors=: factors -. -.&1 |
http://rosettacode.org/wiki/Animation | Animation |
Animation is integral to many parts of GUIs, including both the fancy effects when things change used in window managers, and of course games. The core of any animation system is a scheme for periodically changing the display while still remaining responsive to the user. This task demonstrates this.
Task
Create a window containing the string "Hello World! " (the trailing space is significant).
Make the text appear to be rotating right by periodically removing one letter from the end of the string and attaching it to the front.
When the user clicks on the (windowed) text, it should reverse its direction.
| #Raku | Raku | use GTK::Simple;
use GTK::Simple::App;
my $app = GTK::Simple::App.new(:title<Animation>);
my $button = GTK::Simple::Button.new(label => 'Hello World! ');
my $vbox = GTK::Simple::VBox.new($button);
my $repeat = $app.g-timeout(100); # milliseconds
my $dir = 1;
$button.clicked.tap({ $dir *= -1 });
$repeat.tap( &{$button.label = $button.label.comb.List.rotate($dir).join} );
$app.set-content($vbox);
$app.run; |
http://rosettacode.org/wiki/Animate_a_pendulum | Animate a pendulum |
One good way of making an animation is by simulating a physical system and illustrating the variables in that system using a dynamically changing graphical display.
The classic such physical system is a simple gravity pendulum.
Task
Create a simple physical model of a pendulum and animate it.
| #Lua | Lua |
function degToRad( d )
return d * 0.01745329251
end
function love.load()
g = love.graphics
rodLen, gravity, velocity, acceleration = 260, 3, 0, 0
halfWid, damp = g.getWidth() / 2, .989
posX, posY, angle = halfWid
TWO_PI, angle = math.pi * 2, degToRad( 90 )
end
function love.update( dt )
acceleration = -gravity / rodLen * math.sin( angle )
angle = angle + velocity; if angle > TWO_PI then angle = 0 end
velocity = velocity + acceleration
velocity = velocity * damp
posX = halfWid + math.sin( angle ) * rodLen
posY = math.cos( angle ) * rodLen
end
function love.draw()
g.setColor( 250, 0, 250 )
g.circle( "fill", halfWid, 0, 8 )
g.line( halfWid, 4, posX, posY )
g.setColor( 250, 100, 20 )
g.circle( "fill", posX, posY, 20 )
end
|
http://rosettacode.org/wiki/Amb | Amb | Define and give an example of the Amb operator.
The Amb operator (short for "ambiguous") expresses nondeterminism. This doesn't refer to randomness (as in "nondeterministic universe") but is closely related to the term as it is used in automata theory ("non-deterministic finite automaton").
The Amb operator takes a variable number of expressions (or values if that's simpler in the language) and yields a correct one which will satisfy a constraint in some future computation, thereby avoiding failure.
Problems whose solution the Amb operator naturally expresses can be approached with other tools, such as explicit nested iterations over data sets, or with pattern matching. By contrast, the Amb operator appears integrated into the language. Invocations of Amb are not wrapped in any visible loops or other search patterns; they appear to be independent.
Essentially Amb(x, y, z) splits the computation into three possible futures: a future in which the value x is yielded, a future in which the value y is yielded and a future in which the value z is yielded. The future which leads to a successful subsequent computation is chosen. The other "parallel universes" somehow go away. Amb called with no arguments fails.
For simplicity, one of the domain values usable with Amb may denote failure, if that is convenient. For instance, it is convenient if a Boolean false denotes failure, so that Amb(false) fails, and thus constraints can be expressed using Boolean expressions like Amb(x * y == 8) which unless x and y add to four.
A pseudo-code program which satisfies this constraint might look like:
let x = Amb(1, 2, 3)
let y = Amb(7, 6, 4, 5)
Amb(x * y = 8)
print x, y
The output is 2 4 because Amb(1, 2, 3) correctly chooses the future in which x has value 2, Amb(7, 6, 4, 5) chooses 4 and consequently Amb(x * y = 8) produces a success.
Alternatively, failure could be represented using strictly Amb():
unless x * y = 8 do Amb()
Or else Amb could take the form of two operators or functions: one for producing values and one for enforcing constraints:
let x = Ambsel(1, 2, 3)
let y = Ambsel(4, 5, 6)
Ambassert(x * y = 8)
print x, y
where Ambassert behaves like Amb() if the Boolean expression is false, otherwise it allows the future computation to take place, without yielding any value.
The task is to somehow implement Amb, and demonstrate it with a program which chooses one word from each of the following four sets of character strings to generate a four-word sentence:
"the" "that" "a"
"frog" "elephant" "thing"
"walked" "treaded" "grows"
"slowly" "quickly"
The constraint to be satisfied is that the last character of each word (other than the last) is the same as the first character of its successor.
The only successful sentence is "that thing grows slowly"; other combinations do not satisfy the constraint and thus fail.
The goal of this task isn't to simply process the four lists of words with explicit, deterministic program flow such as nested iteration, to trivially demonstrate the correct output. The goal is to implement the Amb operator, or a facsimile thereof that is possible within the language limitations.
| #Common_Lisp | Common Lisp | (define-condition amb-failure () ()
(:report "No amb alternative succeeded."))
(defun invoke-ambiguously (function thunks)
"Call function with successive values produced by successive
functions in thunks until some invocation of function does not signal
an amb-failure."
(do ((thunks thunks (rest thunks)))
((endp thunks) (error 'amb-failure))
(let ((argument (funcall (first thunks))))
(handler-case (return (funcall function argument))
(amb-failure ())))))
(defmacro amblet1 ((var form) &body body)
"If form is of the form (amb {form}*) then amblet1 is a convenient
syntax for invoke-ambiguously, by which body is evaluated with var
bound the results of each form until some evaluation of body does not
signal an amb-failure. For any other form, amblet binds var the result
of form, and evaluates body."
(if (and (listp form) (eq (first form) 'amb))
`(invoke-ambiguously
#'(lambda (,var) ,@body)
(list ,@(loop for amb-form in (rest form)
collecting `#'(lambda () ,amb-form))))
`(let ((,var ,form))
,@body)))
(defmacro amblet (bindings &body body)
"Like let, except that if an init-form is of the form (amb {form}*),
then the corresponding var is bound with amblet1."
(if (endp bindings)
`(progn ,@body)
`(amblet1 ,(first bindings)
(amblet ,(rest bindings)
,@body)))) |
http://rosettacode.org/wiki/Active_Directory/Connect | Active Directory/Connect | The task is to establish a connection to an Active Directory or Lightweight Directory Access Protocol server.
| #AutoHotkey | AutoHotkey | objConn := CreateObject("ADODB.Connection")
objCmd := CreateObject("ADODB.Command")
objConn.Provider := "ADsDSOObject"
objConn.Open() |
http://rosettacode.org/wiki/Aliquot_sequence_classifications | Aliquot sequence classifications | An aliquot sequence of a positive integer K is defined recursively as the first member
being K and subsequent members being the sum of the Proper divisors of the previous term.
If the terms eventually reach 0 then the series for K is said to terminate.
There are several classifications for non termination:
If the second term is K then all future terms are also K and so the sequence repeats from the first term with period 1 and K is called perfect.
If the third term would be repeating K then the sequence repeats with period 2 and K is called amicable.
If the Nth term would be repeating K for the first time, with N > 3 then the sequence repeats with period N - 1 and K is called sociable.
Perfect, amicable and sociable numbers eventually repeat the original number K; there are other repetitions...
Some K have a sequence that eventually forms a periodic repetition of period 1 but of a number other than K, for example 95 which forms the sequence 95, 25, 6, 6, 6, ... such K are called aspiring.
K that have a sequence that eventually forms a periodic repetition of period >= 2 but of a number other than K, for example 562 which forms the sequence 562, 284, 220, 284, 220, ... such K are called cyclic.
And finally:
Some K form aliquot sequences that are not known to be either terminating or periodic; these K are to be called non-terminating.
For the purposes of this task, K is to be classed as non-terminating if it has not been otherwise classed after generating 16 terms or if any term of the sequence is greater than 2**47 = 140,737,488,355,328.
Task
Create routine(s) to generate the aliquot sequence of a positive integer enough to classify it according to the classifications given above.
Use it to display the classification and sequences of the numbers one to ten inclusive.
Use it to show the classification and sequences of the following integers, in order:
11, 12, 28, 496, 220, 1184, 12496, 1264460, 790, 909, 562, 1064, 1488, and optionally 15355717786080.
Show all output on this page.
Related tasks
Abundant, deficient and perfect number classifications. (Classifications from only the first two members of the whole sequence).
Proper divisors
Amicable pairs
| #BASIC256 | BASIC256 | # Rosetta Code problem: http://rosettacode.org/wiki/Aliquot_sequence_classifications
# by Jjuanhdez, 06/2022
global limite
limite = 20000000
dim nums = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 28, 496, 220, 1184, 12496, 1264460, 790, 909, 562, 1064, 1488}
for n = 0 to nums[?]-1
print "Number "; nums[n]; " : ";
call PrintAliquotClassifier(nums[n])
next n
print
print "Program normal end."
end
function PDtotal (n)
total = 0
for y = 2 to n
if (n mod y) = 0 then total += (n / y)
next y
return total
end function
subroutine PrintAliquotClassifier (K)
longit = 52: n = K: clase = 0: priorn = 0: inc = 0
dim Aseq(longit)
for element = 2 to longit
Aseq[element] = PDtotal(n)
n = int(Aseq[element])
print n; " ";
begin case
case n = 0
print " Terminating": clase = 1: exit for
case n = K and element = 2
print " Perfect" : clase = 2: exit for
case n = K and element = 3
print " Amicable": clase = 3: exit for
case n = K and element > 3
print " Sociable": clase = 4: exit for
case n <> K and Aseq[element - 1] = Aseq[element]
print " Aspiring": clase = 5: exit for
case n <> K and Aseq[element - 2] = n
print " Cyclic": clase = 6: exit for
end case
if n > priorn then priorn = n: inc += 1 else inc = 0: priorn = 0
if inc = 11 or n > limite then exit for
next element
if clase = 0 then print " non-terminating"
end subroutine |
http://rosettacode.org/wiki/Active_Directory/Search_for_a_user | Active Directory/Search for a user | Make sure you Connect to Active Directory
| #Haskell | Haskell | {-# LANGUAGE OverloadedStrings #-}
module Main (main) where
import Data.Foldable (for_)
import qualified Data.Text.Encoding as Text (encodeUtf8)
import Ldap.Client (Attr(..), Filter(..))
import qualified Ldap.Client as Ldap (Dn(..), Host(..), search, with, typesOnly)
main :: IO ()
main = do
entries <- Ldap.with (Ldap.Plain "localhost") 389 $ \ldap ->
Ldap.search ldap (Ldap.Dn "o=example.com") (Ldap.typesOnly True) (Attr "uid" := Text.encodeUtf8 "user") []
for_ entries $ \entry ->
print entry |
http://rosettacode.org/wiki/Active_Directory/Search_for_a_user | Active Directory/Search for a user | Make sure you Connect to Active Directory
| #Java | Java | import java.io.IOException;
import org.apache.directory.api.ldap.model.cursor.CursorException;
import org.apache.directory.api.ldap.model.cursor.EntryCursor;
import org.apache.directory.api.ldap.model.entry.Entry;
import org.apache.directory.api.ldap.model.exception.LdapException;
import org.apache.directory.api.ldap.model.message.SearchScope;
import org.apache.directory.ldap.client.api.LdapConnection;
import org.apache.directory.ldap.client.api.LdapNetworkConnection;
public class LdapSearchDemo {
public static void main(String[] args) throws IOException, LdapException, CursorException {
new LdapSearchDemo().demonstrateSearch();
}
private void demonstrateSearch() throws IOException, LdapException, CursorException {
try (LdapConnection conn = new LdapNetworkConnection("localhost", 11389)) {
conn.bind("uid=admin,ou=system", "********");
search(conn, "*mil*");
conn.unBind();
}
}
private void search(LdapConnection connection, String uid) throws LdapException, CursorException {
String baseDn = "ou=users,o=mojo";
String filter = "(&(objectClass=person)(&(uid=" + uid + ")))";
SearchScope scope = SearchScope.SUBTREE;
String[] attributes = {"dn", "cn", "sn", "uid"};
int ksearch = 0;
EntryCursor cursor = connection.search(baseDn, filter, scope, attributes);
while (cursor.next()) {
ksearch++;
Entry entry = cursor.get();
System.out.printf("Search entry %d = %s%n", ksearch, entry);
}
}
} |
http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | Add a variable to a class instance at runtime | Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
| #Ada | Ada | with Ada.Text_IO; use Ada.Text_IO;
procedure Dynamic is
package Abstract_Class is
type Class is limited interface;
function Boo (X : Class) return String is abstract;
end Abstract_Class;
use Abstract_Class;
package Base_Class is
type Base is new Class with null record;
overriding function Boo (X : Base) return String;
end Base_Class;
package body Base_Class is
function Boo (X : Base) return String is
begin
return "I am Class";
end Boo;
end Base_Class;
use Base_Class;
E : aliased Base; -- An instance of Base
begin
-- Gone run-time
declare
type Monkey_Patch (Root : access Base) is new Class with record
Foo : Integer := 1;
end record;
overriding function Boo (X : Monkey_Patch) return String;
function Boo (X : Monkey_Patch) return String is
begin -- Delegation to the base
return X.Root.Boo;
end Boo;
EE : Monkey_Patch (E'Access); -- Extend E
begin
Put_Line (EE.Boo & " with" & Integer'Image (EE.Foo));
end;
end Dynamic; |
http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | Add a variable to a class instance at runtime | Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
| #Arturo | Arturo | define :myClass [name,surname][]
myInstance: to :myClass ["John" "Doe"]
print myInstance
myInstance\age: 35
print myInstance |
http://rosettacode.org/wiki/Address_of_a_variable | Address of a variable |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
| #COBOL | COBOL | data division.
working-storage section.
01 ptr usage pointer.
01 var pic x(64).
procedure division.
set ptr to address of var. |
http://rosettacode.org/wiki/Address_of_a_variable | Address of a variable |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
| #Common_Lisp | Common Lisp | ;;; Demonstration of references by swapping two variables using a function rather than a macro
;;; Needs http://paste.lisp.org/display/71952
(defun swap (ref-left ref-right)
;; without with-refs we would have to write this:
;; (psetf (deref ref-left) (deref ref-right)
;; (deref ref-right) (deref ref-left))
(with-refs ((l ref-left) (r ref-right))
(psetf l r r l)))
(defvar *x* 42)
(defvar *y* 0)
(swap (ref *x*) (ref *y*))
;; *y* -> 42
;; *x* -> 0 |
http://rosettacode.org/wiki/Address_of_a_variable | Address of a variable |
Basic Data Operation
This is a basic data operation. It represents a fundamental action on a basic data type.
You may see other such operations in the Basic Data Operations category, or:
Integer Operations
Arithmetic |
Comparison
Boolean Operations
Bitwise |
Logical
String Operations
Concatenation |
Interpolation |
Comparison |
Matching
Memory Operations
Pointers & references |
Addresses
Task
Demonstrate how to get the address of a variable and how to set the address of a variable.
| #Component_Pascal | Component Pascal |
MODULE AddressVar;
IMPORT SYSTEM,StdLog;
VAR
x: INTEGER;
PROCEDURE Do*;
BEGIN
StdLog.String("ADR(x):> ");StdLog.IntForm(SYSTEM.ADR(x),StdLog.hexadecimal,8,'0',TRUE);StdLog.Ln
END Do;
BEGIN
x := 10;
END AddressVar.
|
http://rosettacode.org/wiki/AKS_test_for_primes | AKS test for primes | The AKS algorithm for testing whether a number is prime is a polynomial-time algorithm based on an elementary theorem about Pascal triangles.
The theorem on which the test is based can be stated as follows:
a number
p
{\displaystyle p}
is prime if and only if all the coefficients of the polynomial expansion of
(
x
−
1
)
p
−
(
x
p
−
1
)
{\displaystyle (x-1)^{p}-(x^{p}-1)}
are divisible by
p
{\displaystyle p}
.
Example
Using
p
=
3
{\displaystyle p=3}
:
(x-1)^3 - (x^3 - 1)
= (x^3 - 3x^2 + 3x - 1) - (x^3 - 1)
= -3x^2 + 3x
And all the coefficients are divisible by 3, so 3 is prime.
Note:
This task is not the AKS primality test. It is an inefficient exponential time algorithm discovered in the late 1600s and used as an introductory lemma in the AKS derivation.
Task
Create a function/subroutine/method that given
p
{\displaystyle p}
generates the coefficients of the expanded polynomial representation of
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
.
Use the function to show here the polynomial expansions of
(
x
−
1
)
p
{\displaystyle (x-1)^{p}}
for
p
{\displaystyle p}
in the range 0 to at least 7, inclusive.
Use the previous function in creating another function that when given
p
{\displaystyle p}
returns whether
p
{\displaystyle p}
is prime using the theorem.
Use your test to generate a list of all primes under 35.
As a stretch goal, generate all primes under 50 (needs integers larger than 31-bit).
References
Agrawal-Kayal-Saxena (AKS) primality test (Wikipedia)
Fool-Proof Test for Primes - Numberphile (Video). The accuracy of this video is disputed -- at best it is an oversimplification.
| #ARM_Assembly | ARM Assembly |
/* ARM assembly Raspberry PI or android 32 bits */
/* program AKS.s */
/* REMARK 1 : this program use routines in a include file
see task Include a file language arm assembly
for the routine affichageMess conversion10
see at end of this program the instruction include */
/* for constantes see task include a file in arm assembly */
/************************************/
/* Constantes */
/************************************/
.include "../constantes.inc"
.equ MAXI, 32
.equ NUMBERLOOP, 10
/*********************************/
/* Initialized data */
/*********************************/
.data
szMessResult: .asciz " (x-1)^@ = "
szMessResult1: .asciz " @ x^@ "
szMessResPrime: .asciz "Number @ is prime. \n"
szCarriageReturn: .asciz "\n"
/*********************************/
/* UnInitialized data */
/*********************************/
.bss
sZoneConv: .skip 24
iTabCoef: .skip 4 * MAXI
/*********************************/
/* code section */
/*********************************/
.text
.global main
main: @ entry of program
mov r4,#1
1: @ loop
mov r0,r4
bl computeCoef @ compute coefficient
ldr r0,iAdriTabCoef
mov r0,r4
bl displayCoef @ display coefficient
add r4,r4,#1
cmp r4,#NUMBERLOOP
blt 1b
mov r4,#1
2:
mov r0,r4
bl isPrime @ is prime ?
cmp r0,#1
bne 3f
mov r0,r4
ldr r1,iAdrsZoneConv
bl conversion10 @ call decimal conversion
add r1,r0
mov r5,#0
strb r5,[r1]
ldr r0,iAdrszMessResPrime
ldr r1,iAdrsZoneConv @ insert value conversion in message
bl strInsertAtCharInc
bl affichageMess
3:
add r4,r4,#1
cmp r4,#MAXI
blt 2b
100: @ standard end of the program
mov r0, #0 @ return code
mov r7, #EXIT @ request to exit program
svc #0 @ perform the system call
iAdrszCarriageReturn: .int szCarriageReturn
iAdrsZoneConv: .int sZoneConv
iAdriTabCoef: .int iTabCoef
iAdrszMessResPrime: .int szMessResPrime
/***************************************************/
/* display coefficients */
/***************************************************/
// r0 contains a number
displayCoef:
push {r1-r6,lr} @ save registers
mov r2,r0
ldr r1,iAdrsZoneConv @
bl conversion10 @ call decimal conversion
add r1,r0
mov r5,#0
strb r5,[r1]
ldr r0,iAdrszMessResult
ldr r1,iAdrsZoneConv @ insert value conversion in message
bl strInsertAtCharInc
bl affichageMess
ldr r3,iAdriTabCoef
1:
ldr r0,[r3,r2,lsl #2]
ldr r1,iAdrsZoneConv @
bl conversion10S @ call decimal conversion
2: @ removing spaces
ldrb r6,[r1]
cmp r6,#' '
addeq r1,#1
beq 2b
ldr r0,iAdrszMessResult1
bl strInsertAtCharInc
mov r4,r0
mov r0,r2
ldr r1,iAdrsZoneConv @ else display odd message
bl conversion10 @ call decimal conversion
add r1,r0
mov r5,#0
strb r5,[r1]
mov r0,r4
ldr r1,iAdrsZoneConv @ insert value conversion in message
bl strInsertAtCharInc
bl affichageMess
subs r2,r2,#1
bge 1b
ldr r0,iAdrszCarriageReturn
bl affichageMess
100:
pop {r1-r6,lr} @ restaur registers
bx lr @ return
iAdrszMessResult: .int szMessResult
iAdrszMessResult1: .int szMessResult1
/***************************************************/
/* compute coefficient */
/***************************************************/
// r0 contains a number
computeCoef:
push {r1-r6,lr} @ save registers
ldr r1,iAdriTabCoef @ address coefficient array
mov r2,#1
str r2,[r1] @ store 1 to coeff [0]
mov r3,#0 @ indice 1
1:
add r4,r3,#1
mov r5,#1
str r5,[r1,r4,lsl #2]
mov r6,r3 @ indice 2 = indice 1
2:
cmp r6,#0 @ zero ? -> end loop
ble 3f
sub r4,r6,#1
ldr r5,[r1,r4,lsl #2]
ldr r4,[r1,r6,lsl #2]
sub r5,r5,r4
str r5,[r1,r6,lsl #2]
sub r6,r6,#1
b 2b
3:
ldr r2,[r1] @ inversion coeff [0]
neg r2,r2
str r2,[r1]
add r3,r3,#1
cmp r3,r0
blt 1b
100:
pop {r1-r6,lr} @ restaur registers
bx lr @ return
/***************************************************/
/* verify number is prime */
/***************************************************/
// r0 contains a number
isPrime:
push {r1-r5,lr} @ save registers
bl computeCoef
ldr r4,iAdriTabCoef @ address coefficient array
ldr r2,[r4]
add r2,r2,#1
str r2,[r4]
ldr r2,[r4,r0,lsl #2]
sub r2,r2,#1
str r2,[r4,r0,lsl #2]
mov r5,r0 @ number start
mov r1,r0 @ divisor
1:
ldr r0,[r4,r5,lsl #2] @ load one coeff
cmp r0,#0 @ if negative inversion
neglt r0,r0
bl division @ because this routine is number positive only
cmp r3,#0 @ remainder = zéro ?
movne r0,#0 @ if <> no prime
bne 100f
subs r5,r5,#1 @ next coef
bgt 1b
mov r0,#1 @ prime
100:
pop {r1-r5,lr} @ restaur registers
bx lr @ return
/***************************************************/
/* ROUTINES INCLUDE */
/***************************************************/
.include "../affichage.inc"
|
http://rosettacode.org/wiki/Additive_primes | Additive primes | Definitions
In mathematics, additive primes are prime numbers for which the sum of their decimal digits are also primes.
Task
Write a program to determine (and show here) all additive primes less than 500.
Optionally, show the number of additive primes.
Also see
the OEIS entry: A046704 additive primes.
the prime-numbers entry: additive primes.
the geeks for geeks entry: additive prime number.
the prime-numbers fandom: additive primes.
| #ARM_Assembly | ARM Assembly |
/* ARM assembly Raspberry PI */
/* program additivePrime.s */
/* REMARK 1 : this program use routines in a include file
see task Include a file language arm assembly
for the routine affichageMess conversion10
see at end of this program the instruction include */
/* for constantes see task include a file in arm assembly */
/************************************/
/* Constantes */
/************************************/
.include "../constantes.inc"
.equ MAXI, 500
/*********************************/
/* Initialized data */
/*********************************/
.data
szMessResult: .asciz "Prime : @ \n"
szMessCounter: .asciz "Number found : @ \n"
szCarriageReturn: .asciz "\n"
/*********************************/
/* UnInitialized data */
/*********************************/
.bss
sZoneConv: .skip 24
TablePrime: .skip 4 * MAXI
/*********************************/
/* code section */
/*********************************/
.text
.global main
main: @ entry of program
bl createArrayPrime
mov r5,r0 @ prime number
ldr r4,iAdrTablePrime @ address prime table
mov r10,#0 @ init counter
mov r6,#0 @ indice
1:
ldr r2,[r4,r6,lsl #2] @ load prime
mov r9,r2 @ save prime
mov r7,#0 @ init digit sum
mov r1,#10 @ divisor
2: @ begin loop
mov r0,r2 @ dividende
bl division
add r7,r7,r3 @ add digit to digit sum
cmp r2,#0 @ quotient null ?
bne 2b @ no -> comppute other digit
mov r8,#1 @ indice
4: @ prime search loop
cmp r8,r5 @ maxi ?
bge 5f @ yes
ldr r0,[r4,r8,lsl #2] @ load prime
cmp r0,r7 @ prime >= digit sum ?
addlt r8,r8,#1 @ no -> increment indice
blt 4b @ and loop
bne 5f @ >
mov r0,r9 @ equal
bl displayPrime
add r10,r10,#1 @ increment counter
5:
add r6,r6,#1 @ increment first indice
cmp r6,r5 @ maxi ?
blt 1b @ and loop
mov r0,r10 @ number counter
ldr r1,iAdrsZoneConv
bl conversion10 @ call décimal conversion
ldr r0,iAdrszMessCounter
ldr r1,iAdrsZoneConv @ insert conversion in message
bl strInsertAtCharInc
bl affichageMess @ display message
100: @ standard end of the program
mov r0, #0 @ return code
mov r7, #EXIT @ request to exit program
svc #0 @ perform the system call
iAdrszCarriageReturn: .int szCarriageReturn
iAdrszMessResult: .int szMessResult
iAdrszMessCounter: .int szMessCounter
iAdrTablePrime: .int TablePrime
/******************************************************************/
/* créate prime array */
/******************************************************************/
createArrayPrime:
push {r1-r7,lr} @ save registers
ldr r4,iAdrTablePrime @ address prime table
mov r0,#1
str r0,[r4] @ store 1 in array
mov r0,#2
str r0,[r4,#4] @ store 2 in array
mov r0,#3
str r0,[r4,#8] @ store 3 in array
mov r5,#3 @ prine counter
mov r7,#5 @ first number to test
1:
mov r6,#1 @ indice
2:
mov r0,r7 @ dividende
ldr r1,[r4,r6,lsl #2] @ load divisor
bl division
cmp r3,#0 @ null remainder ?
beq 3f @ yes -> end loop
cmp r2,r1 @ quotient < divisor
strlt r7,[r4,r5,lsl #2] @ dividende is prime store in array
addlt r5,r5,#1 @ increment counter
blt 3f @ and end loop
add r6,r6,#1 @ else increment indice
cmp r6,r5 @ maxi ?
blt 2b @ no -> loop
3:
add r7,#2 @ other odd number
cmp r7,#MAXI @ maxi ?
blt 1b @ no -> loop
mov r0,r5 @ return counter
100:
pop {r1-r7,pc}
/******************************************************************/
/* Display prime table elements */
/******************************************************************/
/* r0 contains the prime */
displayPrime:
push {r1,lr} @ save registers
ldr r1,iAdrsZoneConv
bl conversion10 @ call décimal conversion
ldr r0,iAdrszMessResult
ldr r1,iAdrsZoneConv @ insert conversion in message
bl strInsertAtCharInc
bl affichageMess @ display message
100:
pop {r1,pc}
iAdrsZoneConv: .int sZoneConv
/***************************************************/
/* ROUTINES INCLUDE */
/***************************************************/
.include "../affichage.inc"
|
http://rosettacode.org/wiki/Algebraic_data_types | Algebraic data types | Some languages offer direct support for algebraic data types and pattern matching on them. While this of course can always be simulated with manual tagging and conditionals, it allows for terse code which is easy to read, and can represent the algorithm directly.
Task
As an example, implement insertion in a red-black-tree.
A red-black-tree is a binary tree where each internal node has a color attribute red or black. Moreover, no red node can have a red child, and every path from the root to an empty node must contain the same number of black nodes. As a consequence, the tree is balanced, and must be re-balanced after an insertion.
Reference
Red-Black Trees in a Functional Setting
| #Kotlin | Kotlin | // version 1.1.51
import Color.*
enum class Color { R, B }
sealed class Tree<A : Comparable<A>> {
fun insert(x: A): Tree<A> {
val t = ins(x)
return when (t) {
is T -> {
val (_, a, y, b) = t
T(B, a, y, b)
}
is E -> E()
}
}
abstract fun ins(x: A): Tree<A>
}
class E<A : Comparable<A>> : Tree<A>() {
override fun ins(x: A): Tree<A> = T(R, E(), x, E())
override fun toString() = "E"
}
data class T<A : Comparable<A>>(
val cl: Color,
val le: Tree<A>,
val aa: A,
val ri: Tree<A>
) : Tree<A>() {
private fun balance(): Tree<A> {
if (cl != B) return this
val res =
if (le is T && le.le is T && le.cl == R && le.le.cl == R) {
val (_, t, z, d) = this
val (_, t2, y, c) = t as T
val (_, a, x, b) = t2 as T
T(R, T(B, a, x, b), y, T(B, c, z, d))
}
else if (le is T && le.ri is T && le.cl == R && le.ri.cl == R) {
val (_, t, z, d) = this
val (_, a, x, t2) = t as T
val (_, b, y, c) = t2 as T
T(R, T(B, a, x, b), y, T(B, c, z, d))
}
else if (ri is T && ri.le is T && ri.cl == R && ri.le.cl == R) {
val (_, a, x, t) = this
val (_, t2, z, d) = t as T
val (_, b, y, c) = t2 as T
T(R, T(B, a, x, b), y, T(B, c, z, d))
}
else if (ri is T && ri.ri is T && ri.cl == R && ri.ri.cl == R) {
val (_, a, x, t) = this
val (_, b, y, t2) = t as T
val (_, c, z, d) = t2 as T
T(R, T(B, a, x, b), y, T(B, c, z, d))
}
else this
return res
}
override fun ins(x: A): Tree<A> = when (x.compareTo(aa)) {
-1 -> T(cl, le.ins(x), aa, ri).balance()
+1 -> T(cl, le, aa, ri.ins(x)).balance()
else -> this
}
override fun toString() = "T($cl, $le, $aa, $ri)"
}
fun main(args: Array<String>) {
var tree: Tree<Int> = E()
for (i in 1..16) {
tree = tree.insert(i)
}
println(tree)
} |
http://rosettacode.org/wiki/Almost_prime | Almost prime | A k-Almost-prime is a natural number
n
{\displaystyle n}
that is the product of
k
{\displaystyle k}
(possibly identical) primes.
Example
1-almost-primes, where
k
=
1
{\displaystyle k=1}
, are the prime numbers themselves.
2-almost-primes, where
k
=
2
{\displaystyle k=2}
, are the semiprimes.
Task
Write a function/method/subroutine/... that generates k-almost primes and use it to create a table here of the first ten members of k-Almost primes for
1
<=
K
<=
5
{\displaystyle 1<=K<=5}
.
Related tasks
Semiprime
Category:Prime Numbers
| #Draco | Draco | proc nonrec kprime(word n, k) bool:
word f, p;
f := 0;
p := 2;
while f < k and p*p <= n do
while n%p = 0 do
n := n/p;
f := f+1
od;
p := p+1
od;
if n>1 then f+1 = k
else f = k
fi
corp
proc nonrec main() void:
byte k, i, c;
for k from 1 upto 5 do
write("k = ", k:1, ":");
i := 2;
c := 0;
while c < 10 do
if kprime(i,k) then
write(i:4);
c := c+1
fi;
i := i+1
od;
writeln()
od
corp |
http://rosettacode.org/wiki/Almost_prime | Almost prime | A k-Almost-prime is a natural number
n
{\displaystyle n}
that is the product of
k
{\displaystyle k}
(possibly identical) primes.
Example
1-almost-primes, where
k
=
1
{\displaystyle k=1}
, are the prime numbers themselves.
2-almost-primes, where
k
=
2
{\displaystyle k=2}
, are the semiprimes.
Task
Write a function/method/subroutine/... that generates k-almost primes and use it to create a table here of the first ten members of k-Almost primes for
1
<=
K
<=
5
{\displaystyle 1<=K<=5}
.
Related tasks
Semiprime
Category:Prime Numbers
| #EchoLisp | EchoLisp |
(define (almost-prime? p k)
(= k (length (prime-factors p))))
(define (almost-primes k nmax)
(take (filter (rcurry almost-prime? k) [2 ..]) nmax))
(define (task (kmax 6) (nmax 10))
(for ((k [1 .. kmax]))
(write 'k= k '|)
(for-each write (almost-primes k nmax))
(writeln)))
|
http://rosettacode.org/wiki/Anagrams | Anagrams | When two or more words are composed of the same characters, but in a different order, they are called anagrams.
Task[edit]
Using the word list at http://wiki.puzzlers.org/pub/wordlists/unixdict.txt,
find the sets of words that share the same characters that contain the most words in them.
Related tasks
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #BQN | BQN | words ← •FLines "unixdict.txt"
•Show¨{𝕩/˜(⊢=⌈´)≠¨𝕩} (⊐∧¨)⊸⊔ words |
http://rosettacode.org/wiki/Angle_difference_between_two_bearings | Angle difference between two bearings | Finding the angle between two bearings is often confusing.[1]
Task
Find the angle which is the result of the subtraction b2 - b1, where b1 and b2 are the bearings.
Input bearings are expressed in the range -180 to +180 degrees.
The result is also expressed in the range -180 to +180 degrees.
Compute the angle for the following pairs:
20 degrees (b1) and 45 degrees (b2)
-45 and 45
-85 and 90
-95 and 90
-45 and 125
-45 and 145
29.4803 and -88.6381
-78.3251 and -159.036
Optional extra
Allow the input bearings to be any (finite) value.
Test cases
-70099.74233810938 and 29840.67437876723
-165313.6666297357 and 33693.9894517456
1174.8380510598456 and -154146.66490124757
60175.77306795546 and 42213.07192354373
| #Mathematica.2FWolfram_Language | Mathematica/Wolfram Language | ClearAll[AngleDifference]
AngleDifference[b1_, b2_] := Mod[b2 - b1, 360, -180]
AngleDifference[20, 45]
AngleDifference[-45, 45]
AngleDifference[-85, 90]
AngleDifference[-95, 90]
AngleDifference[-45, 125]
AngleDifference[-45, 145]
AngleDifference[29.4803, -88.6381]
AngleDifference[-78.3251, -159.036]
AngleDifference[-70099.74233810938, 29840.67437876723]
AngleDifference[-165313.6666297357, 33693.9894517456]
AngleDifference[1174.8380510598456, -154146.66490124757]
AngleDifference[60175.77306795546, 42213.07192354373] |
http://rosettacode.org/wiki/Anagrams/Deranged_anagrams | Anagrams/Deranged anagrams | Two or more words are said to be anagrams if they have the same characters, but in a different order.
By analogy with derangements we define a deranged anagram as two words with the same characters, but in which the same character does not appear in the same position in both words.
Task[edit]
Use the word list at unixdict to find and display the longest deranged anagram.
Related tasks
Permutations/Derangements
Best shuffle
Word plays
Ordered words
Palindrome detection
Semordnilap
Anagrams
Anagrams/Deranged anagrams
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #Phix | Phix | function deranged(string word1, word2)
return sum(sq_eq(word1,word2))=0
end function
integer fn = open("demo/unixdict.txt","r")
sequence words = {}, anagrams = {}, last="", letters
object word
integer maxlen = 1
while 1 do
word = trim(gets(fn))
if atom(word) then exit end if
if length(word) then
letters = sort(word)
words = append(words, {letters, word})
end if
end while
close(fn)
words = sort(words)
for i=1 to length(words) do
{letters,word} = words[i]
if letters=last then
anagrams[$] = append(anagrams[$],word)
anagrams[$][1] = length(word)
else
last = letters
anagrams = append(anagrams,{0,word})
end if
end for
anagrams = sort(anagrams)
puts(1,"\nLongest deranged anagrams:\n")
for i=length(anagrams) to 1 by -1 do
last = anagrams[i]
if last[1]<maxlen then exit end if
for j=2 to length(last) do
for k=j+1 to length(last) do
if deranged(last[j],last[k]) then
puts(1,last[j]&", "&last[k]&"\n")
maxlen = last[1]
end if
end for
end for
end for
|
http://rosettacode.org/wiki/Anonymous_recursion | Anonymous recursion | While implementing a recursive function, it often happens that we must resort to a separate helper function to handle the actual recursion.
This is usually the case when directly calling the current function would waste too many resources (stack space, execution time), causing unwanted side-effects, and/or the function doesn't have the right arguments and/or return values.
So we end up inventing some silly name like foo2 or foo_helper. I have always found it painful to come up with a proper name, and see some disadvantages:
You have to think up a name, which then pollutes the namespace
Function is created which is called from nowhere else
The program flow in the source code is interrupted
Some languages allow you to embed recursion directly in-place. This might work via a label, a local gosub instruction, or some special keyword.
Anonymous recursion can also be accomplished using the Y combinator.
Task
If possible, demonstrate this by writing the recursive version of the fibonacci function (see Fibonacci sequence) which checks for a negative argument before doing the actual recursion.
| #Lingo | Lingo | on fib (n)
if n<0 then return _player.alert("negative arguments not allowed")
-- create instance of unnamed class in memory only (does not pollute namespace)
m = new(#script)
r = RETURN
m.scriptText = "on fib (me,n)"&r&"if n<2 then return n"&r&"return me.fib(n-1)+me.fib(n-2)"&r&"end"
aux = m.script.new()
m.erase()
return aux.fib(n)
end |
http://rosettacode.org/wiki/Amicable_pairs | Amicable pairs | Two integers
N
{\displaystyle N}
and
M
{\displaystyle M}
are said to be amicable pairs if
N
≠
M
{\displaystyle N\neq M}
and the sum of the proper divisors of
N
{\displaystyle N}
(
s
u
m
(
p
r
o
p
D
i
v
s
(
N
)
)
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (N))}
)
=
M
{\displaystyle =M}
as well as
s
u
m
(
p
r
o
p
D
i
v
s
(
M
)
)
=
N
{\displaystyle \mathrm {sum} (\mathrm {propDivs} (M))=N}
.
Example
1184 and 1210 are an amicable pair, with proper divisors:
1, 2, 4, 8, 16, 32, 37, 74, 148, 296, 592 and
1, 2, 5, 10, 11, 22, 55, 110, 121, 242, 605 respectively.
Task
Calculate and show here the Amicable pairs below 20,000; (there are eight).
Related tasks
Proper divisors
Abundant, deficient and perfect number classifications
Aliquot sequence classifications and its amicable classification.
| #Java | Java | import java.util.Map;
import java.util.function.Function;
import java.util.stream.Collectors;
import java.util.stream.LongStream;
public class AmicablePairs {
public static void main(String[] args) {
int limit = 20_000;
Map<Long, Long> map = LongStream.rangeClosed(1, limit)
.parallel()
.boxed()
.collect(Collectors.toMap(Function.identity(), AmicablePairs::properDivsSum));
LongStream.rangeClosed(1, limit)
.forEach(n -> {
long m = map.get(n);
if (m > n && m <= limit && map.get(m) == n)
System.out.printf("%s %s %n", n, m);
});
}
public static Long properDivsSum(long n) {
return LongStream.rangeClosed(1, (n + 1) / 2).filter(i -> n % i == 0).sum();
}
} |
http://rosettacode.org/wiki/Animation | Animation |
Animation is integral to many parts of GUIs, including both the fancy effects when things change used in window managers, and of course games. The core of any animation system is a scheme for periodically changing the display while still remaining responsive to the user. This task demonstrates this.
Task
Create a window containing the string "Hello World! " (the trailing space is significant).
Make the text appear to be rotating right by periodically removing one letter from the end of the string and attaching it to the front.
When the user clicks on the (windowed) text, it should reverse its direction.
| #REBOL | REBOL | rebol [
Title: "Basic Animation"
URL: http://rosettacode.org/wiki/Basic_Animation
]
message: "Hello World! " how: 1
roll: func [
"Shifts a text string right or left by one character."
text [string!] "Text to shift."
direction [integer!] "Direction to shift -- right: 1, left: -1."
/local h t
][
either direction > 0 [
h: last text t: copy/part text ((length? text) - 1)
][
h: copy skip text 1 t: text/1
]
rejoin [h t]
]
; This next bit specifies the GUI panel. The window will have a
; gradient backdrop, over which will be composited the text, in a
; monospaced font with a drop-shadow. A timer (the 'rate' bit) is set
; to update 24 times per second. The 'engage' function in the 'feel'
; block listens for events on the text face. Time events update the
; animation and mouse-down change the animation's direction.
view layout [
backdrop effect [gradient 0x1 coal black]
vh1 as-is message ; 'as-is' prevents text trimming.
font [name: font-fixed]
rate 24
feel [
engage: func [f a e] [
case [
'time = a [set-face f message: roll message how] ; Animate.
'down = a [how: how * -1] ; Change direction.
]
]
]
] |
http://rosettacode.org/wiki/Animate_a_pendulum | Animate a pendulum |
One good way of making an animation is by simulating a physical system and illustrating the variables in that system using a dynamically changing graphical display.
The classic such physical system is a simple gravity pendulum.
Task
Create a simple physical model of a pendulum and animate it.
| #M2000_Interpreter | M2000 Interpreter |
Module Pendulum {
back()
degree=180/pi
THETA=Pi/2
SPEED=0
G=9.81
L=0.5
Profiler
lasttimecount=0
cc=40 ' 40 ms every draw
accold=0
Every cc {
ACCEL=G*SIN(THETA*degree)/L/50
SPEED+=ACCEL/cc
THETA+=SPEED
Pendulum(THETA)
if KeyPress(32) Then Exit
}
Sub back()
If not IsWine then Smooth On
Cls 7,0
Pen 0
Move 0, scale.y/4
Draw scale.x,0
Step -scale.x/2
circle fill #AAAAAA, scale.x/50
Hold ' hold this as background
End Sub
Sub Pendulum(x)
x+=pi/2
Release ' place stored background to screen
Width scale.x/2000 {
Draw Angle x, scale.y/2.5
Width 1 {
Circle Fill 14, scale.x/25
}
Step Angle x, -scale.y/2.5
}
Print @(1,1), lasttimecount
if sgn(accold)<>sgn(ACCEL) then lasttimecount=timecount: Profiler
accold=ACCEL
Refresh 1000
End Sub
}
Pendulum
|
http://rosettacode.org/wiki/Amb | Amb | Define and give an example of the Amb operator.
The Amb operator (short for "ambiguous") expresses nondeterminism. This doesn't refer to randomness (as in "nondeterministic universe") but is closely related to the term as it is used in automata theory ("non-deterministic finite automaton").
The Amb operator takes a variable number of expressions (or values if that's simpler in the language) and yields a correct one which will satisfy a constraint in some future computation, thereby avoiding failure.
Problems whose solution the Amb operator naturally expresses can be approached with other tools, such as explicit nested iterations over data sets, or with pattern matching. By contrast, the Amb operator appears integrated into the language. Invocations of Amb are not wrapped in any visible loops or other search patterns; they appear to be independent.
Essentially Amb(x, y, z) splits the computation into three possible futures: a future in which the value x is yielded, a future in which the value y is yielded and a future in which the value z is yielded. The future which leads to a successful subsequent computation is chosen. The other "parallel universes" somehow go away. Amb called with no arguments fails.
For simplicity, one of the domain values usable with Amb may denote failure, if that is convenient. For instance, it is convenient if a Boolean false denotes failure, so that Amb(false) fails, and thus constraints can be expressed using Boolean expressions like Amb(x * y == 8) which unless x and y add to four.
A pseudo-code program which satisfies this constraint might look like:
let x = Amb(1, 2, 3)
let y = Amb(7, 6, 4, 5)
Amb(x * y = 8)
print x, y
The output is 2 4 because Amb(1, 2, 3) correctly chooses the future in which x has value 2, Amb(7, 6, 4, 5) chooses 4 and consequently Amb(x * y = 8) produces a success.
Alternatively, failure could be represented using strictly Amb():
unless x * y = 8 do Amb()
Or else Amb could take the form of two operators or functions: one for producing values and one for enforcing constraints:
let x = Ambsel(1, 2, 3)
let y = Ambsel(4, 5, 6)
Ambassert(x * y = 8)
print x, y
where Ambassert behaves like Amb() if the Boolean expression is false, otherwise it allows the future computation to take place, without yielding any value.
The task is to somehow implement Amb, and demonstrate it with a program which chooses one word from each of the following four sets of character strings to generate a four-word sentence:
"the" "that" "a"
"frog" "elephant" "thing"
"walked" "treaded" "grows"
"slowly" "quickly"
The constraint to be satisfied is that the last character of each word (other than the last) is the same as the first character of its successor.
The only successful sentence is "that thing grows slowly"; other combinations do not satisfy the constraint and thus fail.
The goal of this task isn't to simply process the four lists of words with explicit, deterministic program flow such as nested iteration, to trivially demonstrate the correct output. The goal is to implement the Amb operator, or a facsimile thereof that is possible within the language limitations.
| #D | D | import std.stdio, std.array;
/** This amb function takes a comparison function and
the possibilities that need to be checked.*/
//string[] amb(in bool function(in string, in string) pure comp,
const(string)[] amb(in bool function(in string, in string) pure comp,
in string[][] options,
in string prev = null) pure {
if (options.empty)
return null;
foreach (immutable opt; options.front) {
// If this is the base call, prev is null and we need to
// continue.
if (!prev.empty && !comp(prev, opt))
continue;
// Take care of the case where we have no options left.
if (options.length == 1)
return [opt];
// Traverse into the tree.
const res = amb(comp, options[1 .. $], opt);
// If it was a failure, try the next one.
if (!res.empty)
return opt ~ res; // We have a match!
}
return null; // No matches.
}
void main() {
immutable sets = [["the", "that", "a"],
["frog", "elephant", "thing"],
["walked", "treaded", "grows"],
["slowly", "quickly"]];
// Pass in the comparator and the available sets.
// (The comparator is not nothrow because of UTF.)
const result = amb((s, t) => s.back == t.front, sets);
if (result.empty)
writeln("No matches found!");
else
writefln("%-(%s %)", result);
} |
http://rosettacode.org/wiki/Active_Directory/Connect | Active Directory/Connect | The task is to establish a connection to an Active Directory or Lightweight Directory Access Protocol server.
| #AutoIt | AutoIt | #include <AD.au3>
_AD_Open() |
http://rosettacode.org/wiki/Active_Directory/Connect | Active Directory/Connect | The task is to establish a connection to an Active Directory or Lightweight Directory Access Protocol server.
| #C | C | #include <ldap.h>
...
char *name, *password;
...
LDAP *ld = ldap_init("ldap.somewhere.com", 389);
ldap_simple_bind_s(ld, name, password);
... after done with it...
ldap_unbind(ld); |
http://rosettacode.org/wiki/Active_Directory/Connect | Active Directory/Connect | The task is to establish a connection to an Active Directory or Lightweight Directory Access Protocol server.
| #C.23 | C# |
// Requires adding a reference to System.DirectoryServices
var objDE = new System.DirectoryServices.DirectoryEntry("LDAP://DC=onecity,DC=corp,DC=fabrikam,DC=com");
|
http://rosettacode.org/wiki/Active_Directory/Connect | Active Directory/Connect | The task is to establish a connection to an Active Directory or Lightweight Directory Access Protocol server.
| #ColdFusion | ColdFusion |
<cfldap
server = "#someip#"
action="query"
start="somestart#"
username = "#someusername#"
password = "#somepassowrd#"
name = "results"
scope="subtree"
attributes = "#attributeslist#"
>
|
http://rosettacode.org/wiki/Aliquot_sequence_classifications | Aliquot sequence classifications | An aliquot sequence of a positive integer K is defined recursively as the first member
being K and subsequent members being the sum of the Proper divisors of the previous term.
If the terms eventually reach 0 then the series for K is said to terminate.
There are several classifications for non termination:
If the second term is K then all future terms are also K and so the sequence repeats from the first term with period 1 and K is called perfect.
If the third term would be repeating K then the sequence repeats with period 2 and K is called amicable.
If the Nth term would be repeating K for the first time, with N > 3 then the sequence repeats with period N - 1 and K is called sociable.
Perfect, amicable and sociable numbers eventually repeat the original number K; there are other repetitions...
Some K have a sequence that eventually forms a periodic repetition of period 1 but of a number other than K, for example 95 which forms the sequence 95, 25, 6, 6, 6, ... such K are called aspiring.
K that have a sequence that eventually forms a periodic repetition of period >= 2 but of a number other than K, for example 562 which forms the sequence 562, 284, 220, 284, 220, ... such K are called cyclic.
And finally:
Some K form aliquot sequences that are not known to be either terminating or periodic; these K are to be called non-terminating.
For the purposes of this task, K is to be classed as non-terminating if it has not been otherwise classed after generating 16 terms or if any term of the sequence is greater than 2**47 = 140,737,488,355,328.
Task
Create routine(s) to generate the aliquot sequence of a positive integer enough to classify it according to the classifications given above.
Use it to display the classification and sequences of the numbers one to ten inclusive.
Use it to show the classification and sequences of the following integers, in order:
11, 12, 28, 496, 220, 1184, 12496, 1264460, 790, 909, 562, 1064, 1488, and optionally 15355717786080.
Show all output on this page.
Related tasks
Abundant, deficient and perfect number classifications. (Classifications from only the first two members of the whole sequence).
Proper divisors
Amicable pairs
| #C | C |
#include<stdlib.h>
#include<string.h>
#include<stdio.h>
unsigned long long bruteForceProperDivisorSum(unsigned long long n){
unsigned long long i,sum = 0;
for(i=1;i<(n+1)/2;i++)
if(n%i==0 && n!=i)
sum += i;
return sum;
}
void printSeries(unsigned long long* arr,int size,char* type){
int i;
printf("\nInteger : %llu, Type : %s, Series : ",arr[0],type);
for(i=0;i<size-1;i++)
printf("%llu, ",arr[i]);
printf("%llu",arr[i]);
}
void aliquotClassifier(unsigned long long n){
unsigned long long arr[16];
int i,j;
arr[0] = n;
for(i=1;i<16;i++){
arr[i] = bruteForceProperDivisorSum(arr[i-1]);
if(arr[i]==0||arr[i]==n||(arr[i]==arr[i-1] && arr[i]!=n)){
printSeries(arr,i+1,(arr[i]==0)?"Terminating":(arr[i]==n && i==1)?"Perfect":(arr[i]==n && i==2)?"Amicable":(arr[i]==arr[i-1] && arr[i]!=n)?"Aspiring":"Sociable");
return;
}
for(j=1;j<i;j++){
if(arr[j]==arr[i]){
printSeries(arr,i+1,"Cyclic");
return;
}
}
}
printSeries(arr,i+1,"Non-Terminating");
}
void processFile(char* fileName){
FILE* fp = fopen(fileName,"r");
char str[21];
while(fgets(str,21,fp)!=NULL)
aliquotClassifier(strtoull(str,(char**)NULL,10));
fclose(fp);
}
int main(int argC,char* argV[])
{
if(argC!=2)
printf("Usage : %s <positive integer>",argV[0]);
else{
if(strchr(argV[1],'.')!=NULL)
processFile(argV[1]);
else
aliquotClassifier(strtoull(argV[1],(char**)NULL,10));
}
return 0;
}
|
http://rosettacode.org/wiki/Active_Directory/Search_for_a_user | Active Directory/Search for a user | Make sure you Connect to Active Directory
| #Julia | Julia | using LDAPClient
function searchLDAPusers(searchstring, uname, pword, host=["example", "com"])
conn = LDAPClient.LDAPConnection("ldap://ldap.server.net")
LDAPClient.simple_bind(conn, uname, pword)
search_string = "CN=Users,DC=$(host[1]),DC=$(host[2])"
scope = LDAPClient.LDAP_SCOPE_ONELEVEL
chain = LDAPClient.search(conn, search_string, scope, filter="(&(objectClass=person)(&(uid=$(searchstring))))")
for entry in LDAPClient.each_entry(chain)
println("Search for $searchstring found user $(entry["name"]) with attributes:")
for attr in LDAPClient.each_attribute(entry)
println(" ", attr)
end
end
LDAPClient.unbind(conn)
end
searchLDAPusers("Mario", "my-username", "my-password")
|
http://rosettacode.org/wiki/Active_Directory/Search_for_a_user | Active Directory/Search for a user | Make sure you Connect to Active Directory
| #NetRexx | NetRexx | /* NetRexx */
options replace format comments java crossref symbols binary
import org.apache.directory.ldap.client.api.LdapConnection
import org.apache.directory.ldap.client.api.LdapNetworkConnection
import org.apache.directory.shared.ldap.model.cursor.EntryCursor
import org.apache.directory.shared.ldap.model.entry.Entry
import org.apache.directory.shared.ldap.model.exception.LdapException
import org.apache.directory.shared.ldap.model.message.SearchScope
import org.slf4j.Logger
import org.slf4j.LoggerFactory
class RDirectorySearchLDAP public
properties constant
log_ = LoggerFactory.getLogger(RDirectorySearchLDAP.class)
properties private constant
ldapHostName = String 'localhost'
ldapPort = int 11389
ldapDnStr = String 'uid=admin,ou=system'
ldapCreds = String '********'
isTrue = boolean (1 == 1)
isFalse = boolean (1 \== 1)
properties private static
connection = LdapConnection
method main(args = String[]) public static
connected = isFalse
do
connected = setUp()
if connected then do
search('*mil*')
end
finally
if connected then do
tearDown()
end
end
return
method search(uid = String '*') static returns boolean
state = isTrue
cursor = EntryCursor
baseDn = 'ou=users,o=mojo'
filter = '(&(objectClass=person)(&(uid=' || uid || ')))'
scope = SearchScope.SUBTREE
attributes = String[] [String 'dn', 'cn', 'sn', 'uid']
do
if log_.isTraceEnabled() then log_.trace('LDAP search')
if log_.isInfoEnabled() then do
log_.info('Begin search')
log_.info(' search base distinguished name:' baseDn)
log_.info(' search filter:' filter)
log_.info(' search attributes:' Arrays.asList(attributes))
end
cursor = connection.search(baseDn, filter, scope, attributes)
loop ksearch = 1 while cursor.next()
ev = cursor.get()
if log_.isInfoEnabled() then log_.info('Search cursor entry count:' ksearch)
if log_.isInfoEnabled() then log_.info(ev.toString())
end ksearch
catch lex = LdapException
state = isFalse
log_.error('LDAP Error in cursor loop: Iteration' ksearch, Throwable lex)
catch ex = Exception
state = isFalse
log_.error('I/O Error in cursor loop: Iteration' ksearch, Throwable ex)
end
return state
method setUp() static returns boolean
state = isFalse
do
if log_.isInfoEnabled() then log_.info('LDAP Connection to' ldapHostName 'on port' ldapPort)
connection = LdapNetworkConnection(ldapHostName, ldapPort)
if log_.isTraceEnabled() then log_.trace('LDAP bind')
connection.bind(ldapDnStr, ldapCreds)
state = isTrue
catch lex = LdapException
state = isFalse
log_.error('LDAP Error', Throwable lex)
catch iox = IOException
state = isFalse
log_.error('I/O Error', Throwable iox)
end
return state
method tearDown() static returns boolean
state = isFalse
do
if log_.isTraceEnabled() then log_.trace('LDAP unbind')
connection.unBind()
state = isTrue
catch lex = LdapException
state = isFalse
log_.error('LDAP Error', Throwable lex)
finally
do
connection.close()
catch iox = IOException
state = isFalse
log_.error('I/O Error on connection.close()', Throwable iox)
end
end
return state
|
http://rosettacode.org/wiki/Add_a_variable_to_a_class_instance_at_runtime | Add a variable to a class instance at runtime | Demonstrate how to dynamically add variables to an object (a class instance) at runtime.
This is useful when the methods/variables of an instance are based on a data file that isn't available until runtime. Hal Fulton gives an example of creating an OO CSV parser at An Exercise in Metaprogramming with Ruby. This is referred to as "monkeypatching" by Pythonistas and some others.
| #AutoHotkey | AutoHotkey | e := {}
e.foo := 1 |
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