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stringclasses 5
values | question
stringlengths 20
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Arithmetic calculation
|
When you write the numbers from 10 to 99 in your notebook, how many times do you write the number 8?
|
19
|
10 99 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 8 [OP_LIST_FIND_NUM]
|
var_a = 10
var_b = 99
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d=""
for i in list_a:
i = str(i)
var_d = var_d + i
list_b = []
var_d = int(var_d)
while var_d//10 > 0:
list_b.append(var_d%10)
var_d = var_d//10
list_b.append(var_d%10)
list_b = list_b[::-1]
var_e = 8
var_f = 0
var_e = int(var_e)
for i in list_b:
i = int(i)
if i == var_e:
var_f = var_f + 1
print(int(var_f))
|
Comparison
|
Nine people stand in a line in order from shortest to tallest. Hoseok is the shortest, and there are 4 people standing between Yuna and Hoseok. If they line up again in order from tallest to shortest, what number will Yuna stand from the front?
|
4
|
9 1 [OP_SUB] 4 [OP_SUB] 1 [OP_SUB] 1 [OP_ADD]
|
var_a = 9
var_b = 1
var_c = var_a - var_b
var_d = 4
var_e = var_c - var_d
var_f = 1
var_g = var_e - var_f
var_h = 1
var_i = var_g + var_h
print(int(var_i))
|
Comparison
|
There are a total of 531 third and fourth graders attending an elementary school in Seoul. There are 31 more 4th graders than 3rd graders, and 22 fewer 3rd grade girls than 3rd grade boys. Among the boys attending this school, find how many are in the third grade.
|
136
|
531 31 [OP_SUB] 2 [OP_DIV] 22 [OP_SUB] 2 [OP_DIV] 22 [OP_ADD]
|
var_a = 531
var_b = 31
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
var_f = 22
var_g = var_e - var_f
var_h = 2
var_i = var_g / var_h
var_j = 22
var_k = var_i + var_j
print(int(var_k))
|
Arithmetic calculation
|
You want to place 6 flagpoles at regular intervals on a straight line that is 11.5 meters (m) long. How many meters (m) should be the distance between flagpoles?
|
2.3
|
11.5 6 1 [OP_SUB] [OP_DIV]
|
var_a = 11.5
var_b = 6
var_c = 1
var_d = var_b - var_c
var_e = var_a / var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
Correspondence
|
There is a three-digit number whose sum of each digit is 9 and is divisible by 5. How many of these three-digit numbers are there?
|
13
|
100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_NUM2SUM] 9 [OP_LIST_FIND_NUM]
|
var_a = 100
var_b = 1000
var_c = 1
var_d = var_b - var_c
var_e = 1
list_a = [i for i in range(var_a, var_d + 1, var_e)]
var_f = 5
list_b = []
var_f = int(var_f)
for i in list_a:
i = int(i)
if i % var_f == 0:
list_b.append(i)
list_c=[]
for i in list_b:
var_g = 0
i = int(i)
while i//10 > 0:
var_g = var_g + i%10
i = i//10
var_g = var_g + i%10
list_c.append(var_g)
var_h = 9
var_i = 0
var_h = int(var_h)
for i in list_c:
i = int(i)
if i == var_h:
var_i = var_i + 1
print(int(var_i))
|
Possibility
|
How many three-digit integers can be made by drawing 3 out of 4 cards with the numbers 0, 4, 5, and 7 written on them?
|
18
|
4 3 [OP_PERM] 3 3 [OP_PERM] [OP_SUB]
|
var_a = 4
var_b = 3
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
var_d = 3
var_e = 3
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
var_g = var_c - var_f
print(int(var_g))
|
Correspondence
|
When a natural number A is divided by a natural number B, the quotient is 28 and the remainder is 4. Find the smallest A among all possible numbers that can be A.
|
144
|
5 28 [OP_MUL] 4 [OP_ADD]
|
var_a = 5
var_b = 28
var_c = var_a * var_b
var_d = 4
var_e = var_c + var_d
print(int(var_e))
|
Correspondence
|
There is a number that is greater than 50 and less than 70. This number has a remainder of 3 when divided by 5 and a remainder of 2 when divided by 7. What is this number?
|
58
|
50 70 1 [OP_SUB] 1 [OP_LIST_ARANGE] 5 3 [OP_LIST_DIVIDE_AND_REMAIN] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET]
|
var_a = 50
var_b = 70
var_c = 1
var_d = var_b - var_c
var_e = 1
list_a = [i for i in range(var_a, var_d + 1, var_e)]
var_f = 5
var_g = 3
list_b = []
var_f = int(var_f)
var_g = int(var_g)
if var_g < 0:
var_g = var_g + var_f
for i in list_a:
i = int(i)
if i%var_f == var_g:
list_b.append(i)
var_h = 7
var_i = 2
list_c = []
var_h = int(var_h)
var_i = int(var_i)
if var_i < 0:
var_i = var_i + var_h
for i in list_b:
i = int(i)
if i%var_h == var_i:
list_c.append(i)
var_j = 1
var_k = list_c[var_j-1]
print(int(var_k))
|
Arithmetic calculation
|
A frog takes 5/18 minutes to jump 7/12 centimeters (cm). How many centimeters (cm) can this frog travel in 7 minutes if it runs at the same speed?
|
14.7
|
7/12 5/18 [OP_DIV] 7 [OP_MUL]
|
var_a = 0.5833333333333334
var_b = 0.2777777777777778
var_c = var_a / var_b
var_d = 7
var_e = var_c * var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
Possibility
|
There are 5 different interviewers. Find the number of cases in which two of them pass.
|
10
|
5 2 [OP_COMB]
|
var_a = 5
var_b = 2
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
print(int(var_c))
|
Comparison
|
Among the five numbers 1.4, 9/10, 1.2, 0.5, 13/10, which number is at the very front, when numbers greater than or equal to 1.1 are picked up to be lined up in order from the smallest?
|
1.2
|
[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN]
|
var_a = 1.4
var_b = 0.9
var_c = 1.2
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1.1
list_b = []
for i in list_a:
if i >= var_f:
list_b.append(i)
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[var_g-1]
print('{:.2f}'.format(round(var_h+1e-10,2)))
|
Comparison
|
Taehyung read 32 pages of fairy tales yesterday, and today he read 13 fewer pages than yesterday. Namjoon read 25 pages of fairy tales yesterday, and today he read 14 more pages than yesterday. Who read more fairy tales yesterday and today combined?
|
Namjoon
|
[OP_LIST_SOL] Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] 32 13 [OP_SUB] 32 [OP_ADD] 25 14 [OP_ADD] 25 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
|
var_a = 'Taehyung'
var_b = 'Namjoon'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 32
var_d = 13
var_e = var_c - var_d
var_f = 32
var_g = var_e + var_f
var_h = 25
var_i = 14
var_j = var_h + var_i
var_k = 25
var_l = var_j + var_k
list_b= []
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
list_b.reverse()
var_m = 1
list_c=list_b.copy()
list_c.sort()
var_n = list_c[-var_m]
var_o = list_b.index(var_n)+1
var_p = list_a[var_o-1]
print(var_p)
|
Arithmetic calculation
|
Jae-woong and Dong-hun started at the same place in opposite directions on a kickboard on a 3-kilometer (km)-long playground. If Jaewoong rides a kickboard at a speed of 100 meters (m) per minute and Donghun rides a kickboard at a speed of 150 meters (m) per minute, find out how many minutes later they will meet again for the first time.
|
12
|
3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV]
|
var_a = 3
var_b = 100
var_c = 1000
var_d = var_b / var_c
var_e = 150
var_f = 1000
var_g = var_e / var_f
var_h = var_d + var_g
var_i = var_a / var_h
print(int(var_i))
|
Possibility
|
If the number of ways to get from point A to point B is 3 and from point B to point C is 4, find how many possible ways are there to get from point A to point C via point B.
|
12
|
3 4 [OP_MUL]
|
var_a = 3
var_b = 4
var_c = var_a * var_b
print(int(var_c))
|
Geometry
|
When square-shaped tiles were laid in order to form a large square, 36 tiles were not used. I increased the width and length of the large square by one line each, and there were still 3 residual tiles left. How many tiles did I have?
|
292
|
36 3 [OP_SUB] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 36 [OP_ADD]
|
var_a = 36
var_b = 3
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
var_h = 2
var_i = var_g ** var_h
var_j = 36
var_k = var_i + var_j
print(int(var_k))
|
Possibility
|
You want to create a three-digit number using each 0, 2, 4, and 6 only once. Find the product of the largest possible number and the smallest possible number.
|
130968
|
[OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL]
|
var_a = 0
var_b = 2
var_c = 4
var_d = 6
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 1
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
var_h = 1
list_d=list_b.copy()
list_d.sort()
var_i = list_d[var_h-1]
var_j = var_g * var_i
print(int(var_j))
|
Geometry
|
If the area of a triangle when halved is in 7 square centimeters (cm2), what is the area before halving?
|
14
|
7 2 [OP_MUL]
|
var_a = 7
var_b = 2
var_c = var_a * var_b
print(int(var_c))
|
Comparison
|
The number of flowers planted in each column is the same. When a rose is planted in the 9th column from the left, the 7th row from the front, the 16th row from the back, and the 13th column from the right, how many flowers are planted?
|
462
|
7 16 [OP_ADD] 1 [OP_SUB] 9 13 [OP_ADD] 1 [OP_SUB] [OP_MUL]
|
var_a = 7
var_b = 16
var_c = var_a + var_b
var_d = 1
var_e = var_c - var_d
var_f = 9
var_g = 13
var_h = var_f + var_g
var_i = 1
var_j = var_h - var_i
var_k = var_e * var_j
print(int(var_k))
|
Arithmetic calculation
|
There are five numbers 10, 11, 12, 13, and 14. What is the product of the 3rd smallest number and the 2nd smallest number?
|
132
|
[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL]
|
var_a = 10
var_b = 11
var_c = 12
var_d = 13
var_e = 14
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b=list_a.copy()
list_b.sort()
var_g = list_b[var_f-1]
var_h = 2
list_c=list_a.copy()
list_c.sort()
var_i = list_c[var_h-1]
var_j = var_g * var_i
print(int(var_j))
|
Arithmetic calculation
|
When Woo-jun's age is 1 year less than 1/4 of his mother's age and his mother's age is 5 years less than 5 times Woo-jun's age, how old is Woo-jun now?
|
9
|
1/4 5 [OP_MUL] 1 [OP_ADD] 1/4 5 [OP_MUL] 1 [OP_SUB] [OP_DIV]
|
var_a = 0.25
var_b = 5
var_c = var_a * var_b
var_d = 1
var_e = var_c + var_d
var_f = 0.25
var_g = 5
var_h = var_f * var_g
var_i = 1
var_j = var_h - var_i
var_k = var_e / var_j
print(int(var_k))
|
Correspondence
|
For the natural numbers A, B, and C, when A is divided by 8, the quotient is B and the remainder is C. If the quotient and the remainder are equal, find the largest number of A.
|
63
|
8 8 1 [OP_SUB] [OP_MUL] 8 1 [OP_SUB] [OP_ADD]
|
var_a = 8
var_b = 8
var_c = 1
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 8
var_g = 1
var_h = var_f - var_g
var_i = var_e + var_h
print(int(var_i))
|
Arithmetic calculation
|
The length of tape A which is equal to the length of the tape B folded in half is 35 centimeters (cm). The length of tape C is 21 centimeters (cm) longer than twice the length of tape A, how many centimeters (cm) is the sum of the lengths of tape B and tape C?
|
119
|
35 2 [OP_MUL] 35 2 [OP_MUL] 21 [OP_SUB] [OP_ADD]
|
var_a = 35
var_b = 2
var_c = var_a * var_b
var_d = 35
var_e = 2
var_f = var_d * var_e
var_g = 21
var_h = var_f - var_g
var_i = var_c + var_h
print(int(var_i))
|
Geometry
|
How many faces does a tetrahedron have?
|
4
|
4
|
var_a = 4
print(int(var_a))
|
Geometry
|
Suzy has a regular hexagon shaped piece of colored paper. The length of one side of this regular hexagon is 5 centimeters (cm). Find the circumference of this colored paper.
|
30
|
5 6 [OP_MUL]
|
var_a = 5
var_b = 6
var_c = var_a * var_b
print(int(var_c))
|
Geometry
|
A box measuring 1 meter (m) in width, length, and height is stored on a rectangular piece of land measuring 44 meters (m) wide and 35 meters (m) long. If you stacked boxes in 7 layers on the first day and boxes in 3 layers on the second day, how many boxes did you get in two days?
|
15400
|
44 35 [OP_MUL] 7 3 [OP_ADD] [OP_MUL]
|
var_a = 44
var_b = 35
var_c = var_a * var_b
var_d = 7
var_e = 3
var_f = var_d + var_e
var_g = var_c * var_f
print(int(var_g))
|
Geometry
|
When I measured the length of one side of a square-shaped blackboard, it was 6 centimeters (cm). What is the area of this blackboard in square centimeters (cm2)?
|
36
|
6 2 [OP_POW]
|
var_a = 6
var_b = 2
var_c = var_a ** var_b
print(int(var_c))
|
Comparison
|
There are 60 consecutive natural numbers between 200 and this number. If the number is less than 200, how many numbers between 200 and the number are divisible by 2 and 3?
|
10
|
200 1 [OP_ADD] 60 [OP_SUB] 200 1 [OP_SUB] 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]
|
var_a = 200
var_b = 1
var_c = var_a + var_b
var_d = 60
var_e = var_c - var_d
var_f = 200
var_g = 1
var_h = var_f - var_g
var_i = 1
list_a = [i for i in range(var_e, var_h + 1, var_i)]
var_j = 2
list_b = []
var_j = int(var_j)
for i in list_a:
i = int(i)
if i % var_j == 0:
list_b.append(i)
var_k = 3
list_c = []
var_k = int(var_k)
for i in list_b:
i = int(i)
if i % var_k == 0:
list_c.append(i)
var_l = len(list_c)
print(int(var_l))
|
Arithmetic calculation
|
If you cut and used 105 millimeters (mm) from a 23.3 centimeter (cm) wire and another 4.6 centimeters (cm) the next day, how many millimeters (mm) of wire are left?
|
82
|
23.3 10 [OP_MUL] 105 [OP_SUB] 4.6 10 [OP_MUL] [OP_SUB]
|
var_a = 23.3
var_b = 10
var_c = var_a * var_b
var_d = 105
var_e = var_c - var_d
var_f = 4.6
var_g = 10
var_h = var_f * var_g
var_i = var_e - var_h
print(int(var_i))
|
Geometry
|
What is the volume, in cubic centimeters (cm3), of a cube with an edge of 7 centimeters (cm)?
|
343
|
7 3 [OP_POW]
|
var_a = 7
var_b = 3
var_c = var_a ** var_b
print(int(var_c))
|
Geometry
|
A pyramid has N bases. How much is N?
|
1
|
1
|
var_a = 1
print(int(var_a))
|
Geometry
|
The area of a trapezoid with an upper side that is 3.4 centimeters (cm) longer than the lower side and with a height of 5.2 centimeters (cm) is 100.62 square centimeters (cm2). How many centimeters (cm) is the length of the lower side?
|
17.65
|
100.62 2 [OP_MUL] 5.2 [OP_DIV] 3.4 [OP_SUB] 2 [OP_DIV]
|
var_a = 100.62
var_b = 2
var_c = var_a * var_b
var_d = 5.2
var_e = var_c / var_d
var_f = 3.4
var_g = var_e - var_f
var_h = 2
var_i = var_g / var_h
print('{:.2f}'.format(round(var_i+1e-10,2)))
|
Geometry
|
There is a box in the shape of a cuboid measuring 30 centimeters (cm) wide, 20 centimeters (cm) long, and 5 centimeters (cm) high. If this box contains all the chocolates in the shape of a cuboid measuring 6 centimeters (cm) wide, 4 centimeters (cm) long, and 1 cm (cm high) without leaving any space, how many chocolates are in the box?
|
125
|
30 20 [OP_MUL] 5 [OP_MUL] 6 4 [OP_MUL] 1 [OP_MUL] [OP_DIV]
|
var_a = 30
var_b = 20
var_c = var_a * var_b
var_d = 5
var_e = var_c * var_d
var_f = 6
var_g = 4
var_h = var_f * var_g
var_i = 1
var_j = var_h * var_i
var_k = var_e / var_j
print(int(var_k))
|
Correspondence
|
A number divided by 9 and by 7 is 13. Find this number.
|
819
|
13 7 [OP_MUL] 9 [OP_MUL]
|
var_a = 13
var_b = 7
var_c = var_a * var_b
var_d = 9
var_e = var_c * var_d
print(int(var_e))
|
Arithmetic calculation
|
I put 30 tangerines, each weighing 0.36 kilograms (kg), in a gift box. At this moment, the weight of the gift box was 11.26 kilograms (kg). How many kilograms (kg) does an empty gift box weigh?
|
0.46
|
11.26 0.36 30 [OP_MUL] [OP_SUB]
|
var_a = 11.26
var_b = 0.36
var_c = 30
var_d = var_b * var_c
var_e = var_a - var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
Geometry
|
Mijeong's cuboid box has a bottom area of 14 square centimeters (cm2) and a height of 13 centimeters (cm). Find the volume of this box.
|
182
|
14 13 [OP_MUL]
|
var_a = 14
var_b = 13
var_c = var_a * var_b
print(int(var_c))
|
Correspondence
|
While Yoongi was subtracting 57 from the two-digit number, he mistook the two-digit units digit 9 for 6. When the difference obtained by Yoongi is 39, what is the two-digit number?
|
99
|
39 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB]
|
var_a = 39
var_b = 57
var_c = var_a + var_b
var_d = 6
var_e = 9
var_f = var_d - var_e
var_g = var_c - var_f
print(int(var_g))
|
Arithmetic calculation
|
What is the second largest odd number from 1 to 9?
|
7
|
1 9 [OP_LIST_ODD] 2 [OP_LIST_MAX]
|
var_a = 1
var_b = 9
list_a = []
if var_a%2==0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c = 2
list_b=list_a.copy()
list_b.sort()
var_d = list_b[-var_c]
print(int(var_d))
|
Arithmetic calculation
|
The average height of 11 members of the Yeonju's line is 145.7 centimeters (cm). However, if the heights of the two students are equal to 142.1 centimeters (cm), find the average of the heights of the other students.
|
146.5
|
145.7 11 [OP_MUL] 142.1 2 [OP_MUL] [OP_SUB] 11 2 [OP_SUB] [OP_DIV]
|
var_a = 145.7
var_b = 11
var_c = var_a * var_b
var_d = 142.1
var_e = 2
var_f = var_d * var_e
var_g = var_c - var_f
var_h = 11
var_i = 2
var_j = var_h - var_i
var_k = var_g / var_j
print('{:.2f}'.format(round(var_k+1e-10,2)))
|
Arithmetic calculation
|
Jimin has 41 pieces of colored paper, and Seokjin has 1 less than Jimin. How many pieces of colored paper does Seokjin have?
|
40
|
41 1 [OP_SUB]
|
var_a = 41
var_b = 1
var_c = var_a - var_b
print(int(var_c))
|
Possibility
|
There are 1 red ball, 1 yellow ball, and 2 blue balls. Given that balls of the same color are indistinguishable from each other, how many different ways can you arrange them differently?
|
12
|
1 1 [OP_ADD] 2 [OP_ADD] 1 1 [OP_ADD] 2 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV]
|
var_a = 1
var_b = 1
var_c = var_a + var_b
var_d = 2
var_e = var_c + var_d
var_f = 1
var_g = 1
var_h = var_f + var_g
var_i = 2
var_j = var_h + var_i
var_k = 1
var_e = int(var_e)
var_j = int(var_j)
for i, elem in enumerate(range(var_j)):
var_k = var_k * (var_e-i)
var_l = 2
var_m = 2
var_n = 1
var_l = int(var_l)
var_m = int(var_m)
for i, elem in enumerate(range(var_m)):
var_n = var_n * (var_l-i)
var_o = var_k / var_n
print(int(var_o))
|
Correspondence
|
When a number A is divided by 8, the quotient and remainder are B and C, respectively. A, B, and C are natural numbers. If the quotient and the remainder are equal, find the largest number of A.
|
63
|
8 8 1 [OP_SUB] [OP_MUL] 8 1 [OP_SUB] [OP_ADD]
|
var_a = 8
var_b = 8
var_c = 1
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 8
var_g = 1
var_h = var_f - var_g
var_i = var_e + var_h
print(int(var_i))
|
Arithmetic calculation
|
There are three tapes: tapes A, B, and C. The length of the tape A is 35 centimeters (cm). The length of tape A is half the length of tape B, and the length of tape C is 21 centimeters (cm) less than twice the length of tape A. What is the sum of the lengths of tape B and tape C in centimeters (cm)?
|
119
|
35 2 [OP_MUL] 35 2 [OP_MUL] 21 [OP_SUB] [OP_ADD]
|
var_a = 35
var_b = 2
var_c = var_a * var_b
var_d = 35
var_e = 2
var_f = var_d * var_e
var_g = 21
var_h = var_f - var_g
var_i = var_c + var_h
print(int(var_i))
|
Arithmetic calculation
|
You want to install 24 power poles with equal space between two poles on one side of a 239.66 meters (m) long road. If you are to install one at the beginning and one at the end of the road, how long should the distance between the power poles be in meters (m)?
|
10.42
|
239.66 24 1 [OP_SUB] [OP_DIV]
|
var_a = 239.66
var_b = 24
var_c = 1
var_d = var_b - var_c
var_e = var_a / var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
Geometry
|
How many circles with a radius of 4 centimeters (cm) can be drawn in a rectangle with a width of 24 centimeters (cm) and a length of 8 centimeters (cm) without overlapping?
|
3
|
24 4 2 [OP_MUL] [OP_DIV]
|
var_a = 24
var_b = 4
var_c = 2
var_d = var_b * var_c
var_e = var_a / var_d
print(int(var_e))
|
Arithmetic calculation
|
(A) classmates planted 8 trees. (B) classmates planted 7 trees. How many trees did the students in class (A) and (B) plant?
|
15
|
8 7 [OP_ADD]
|
var_a = 8
var_b = 7
var_c = var_a + var_b
print(int(var_c))
|
Possibility
|
Donghyun can put the magnets with 1, 6, and 8 written on them in the hundreds, tens, and ones place, respectively. What is the difference between the second largest and the third smallest number Donghyun can make?
|
198
|
[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB]
|
var_a = 1
var_b = 6
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 2
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
var_g = 3
list_d=list_b.copy()
list_d.sort()
var_h = list_d[var_g-1]
var_i = var_f - var_h
print(int(var_i))
|
Comparison
|
There are five shapes: triangular-prism, quadrangular-prism, triangular-pyramid, quadrangular-pyramid, and square-frustum. If each shape's face is colored with a different color, which shape needs the fewest colors?
|
triangular-pyramid
|
[OP_LIST_SOL] triangular-prism quadrangular-prism triangular-pyramid quadrangular-pyramid square-frustum [OP_LIST_EOL] [OP_LIST_SOL] 3 2 [OP_ADD] 4 2 [OP_ADD] 3 1 [OP_ADD] 4 1 [OP_ADD] 4 2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
|
var_a = 'triangular-prism'
var_b = 'quadrangular-prism'
var_c = 'triangular-pyramid'
var_d = 'quadrangular-pyramid'
var_e = 'square-frustum'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
var_g = 2
var_h = var_f + var_g
var_i = 4
var_j = 2
var_k = var_i + var_j
var_l = 3
var_m = 1
var_n = var_l + var_m
var_o = 4
var_p = 1
var_q = var_o + var_p
var_r = 4
var_s = 2
var_t = var_r + var_s
list_b= []
if "/" in str(var_t):
var_t = eval(str(var_t))
list_b.append(var_t)
if "/" in str(var_q):
var_q = eval(str(var_q))
list_b.append(var_q)
if "/" in str(var_n):
var_n = eval(str(var_n))
list_b.append(var_n)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
list_b.reverse()
var_u = 1
list_c=list_b.copy()
list_c.sort()
var_v = list_c[var_u-1]
var_w = list_b.index(var_v)+1
var_x = list_a[var_w-1]
print(var_x)
|
Correspondence
|
Seonghyeon and Jisoo are standing on the playground. Seonghyeon ran 200 meters (m) in the direction of Ji-soo and then ran 1000 meters (m) in the opposite direction. If the distance between Seonghyeon and Jisoo is now 2000 meters (m), find the distance in meters (m) between Seonghyeon and Jisoo before Seonghyeon moved.
|
1200
|
2000 1000 [OP_SUB] 200 [OP_ADD]
|
var_a = 2000
var_b = 1000
var_c = var_a - var_b
var_d = 200
var_e = var_c + var_d
print(int(var_e))
|
Possibility
|
Jungkook wants to buy different fruits and present them to Jimin and Yoongi. If the fruits sold at the fruit shop are apples, peaches, pears, melons, and strawberries, how many numbers of cases are possible for the gift?
|
20
|
[OP_LIST_SOL] apples peaches pears melons strawberries [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM]
|
var_a = 'apples'
var_b = 'peaches'
var_c = 'pears'
var_d = 'melons'
var_e = 'strawberries'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = len(list_a)
var_g = 2
var_h = 1
var_f = int(var_f)
var_g = int(var_g)
for i, elem in enumerate(range(var_g)):
var_h = var_h * (var_f-i)
print(int(var_h))
|
Possibility
|
How many three-digit numbers can be made by using all three numbers 1, 2, and 3 once?
|
6
|
[OP_LIST_SOL] 1 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]
|
var_a = 1
var_b = 2
var_c = 3
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = len(list_b)
print(int(var_e))
|
Correspondence
|
When a number is divided by 7, the quotient is 13 and the remainder is 1. Add 9 to this number. Then, divide it by 8 to find the sum of the quotient and remainder.
|
17
|
13 7 [OP_MUL] 1 [OP_ADD] 9 [OP_ADD] 8 [OP_FDIV] 13 7 [OP_MUL] 1 [OP_ADD] 9 [OP_ADD] 8 [OP_MOD] [OP_ADD]
|
var_a = 13
var_b = 7
var_c = var_a * var_b
var_d = 1
var_e = var_c + var_d
var_f = 9
var_g = var_e + var_f
var_h = 8
var_i = var_g // var_h
var_j = 13
var_k = 7
var_l = var_j * var_k
var_m = 1
var_n = var_l + var_m
var_o = 9
var_p = var_n + var_o
var_q = 8
var_r = var_p % var_q
var_s = var_i + var_r
print(int(var_s))
|
Geometry
|
A large track in the shape of a square with a side of 20 meters (m) was divided into 3 equal parts to create 3 smaller tracks. What is the area of this small track in square meters (m2)?
|
44.44
|
20 3 [OP_DIV] 2 [OP_POW]
|
var_a = 20
var_b = 3
var_c = var_a / var_b
var_d = 2
var_e = var_c ** var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
Geometry
|
How many edges does a regular icosahedron have?
|
30
|
30
|
var_a = 30
print(int(var_a))
|
Comparison
|
What is the sum of numbers which are greater than or equal to 1.1 among five numbers 1.4, 9/10, 1.2, 0.5, and 13/10.
|
3.9
|
[OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM]
|
var_a = 1.4
var_b = 0.9
var_c = 1.2
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1.1
list_b = []
for i in list_a:
if i >= var_f:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_g = sum(list_b)
print('{:.2f}'.format(round(var_g+1e-10,2)))
|
Correspondence
|
What number must go in A to make A7B+23=695?
|
6
|
A7B+23=695 A [OP_DIGIT_UNK_SOLVER]
|
var_a = 'A7B+23=695'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c))
|
Arithmetic calculation
|
There are 15 chickens - 3 are hens and the rest are roosters. Chicks are 4 fewer than roosters. How many chicks do you have?
|
8
|
15 3 [OP_SUB] 4 [OP_SUB]
|
var_a = 15
var_b = 3
var_c = var_a - var_b
var_d = 4
var_e = var_c - var_d
print(int(var_e))
|
Arithmetic calculation
|
There are 950 stones. If there are 150 more white stones than black stones, how many black stones are there?
|
400
|
950 150 [OP_SUB] 2 [OP_DIV]
|
var_a = 950
var_b = 150
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e))
|
Possibility
|
Write the largest three-digit number that can be formed by using 2, 6, and 9 only once.
|
962
|
[OP_LIST_SOL] 2 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]
|
var_a = 2
var_b = 6
var_c = 9
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
print(int(var_f))
|
Arithmetic calculation
|
In the addition of two-digit numbers, the units digit of added number was originally 5 but was mistaken as 8. Also, when the number 7 in the tens place of the number being added was mistakenly calculated as 4, the calculated value was 111. Find the result of the correct calculation.
|
138
|
111 1 5 8 [OP_SUB] [OP_MUL] [OP_ADD] 10 7 4 [OP_SUB] [OP_MUL] [OP_ADD]
|
var_a = 111
var_b = 1
var_c = 5
var_d = 8
var_e = var_c - var_d
var_f = var_b * var_e
var_g = var_a + var_f
var_h = 10
var_i = 7
var_j = 4
var_k = var_i - var_j
var_l = var_h * var_k
var_m = var_g + var_l
print(int(var_m))
|
Possibility
|
Find the number in the hundredth place of the smallest number that can be made by using all of the given number cards 0, 5, and 8 once.
|
5
|
[OP_LIST_SOL] 0 5 8 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 100 [OP_FDIV]
|
var_a = 0
var_b = 5
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[var_e-1]
var_g = 100
var_h = var_f // var_g
print(int(var_h))
|
Possibility
|
There is one ID photo each of Seokjin, Taehyung, Namjoon, Yoojeong, and Yuna. In how many ways can these pictures be arranged in a row?
|
120
|
[OP_LIST_SOL] Seokjin Taehyung Namjoon Yoojeong Yuna [OP_LIST_EOL] [OP_LIST_LEN] 5 [OP_PERM]
|
var_a = 'Seokjin'
var_b = 'Taehyung'
var_c = 'Namjoon'
var_d = 'Yoojeong'
var_e = 'Yuna'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = len(list_a)
var_g = 5
var_h = 1
var_f = int(var_f)
var_g = int(var_g)
for i, elem in enumerate(range(var_g)):
var_h = var_h * (var_f-i)
print(int(var_h))
|
Correspondence
|
On a farm of 12 cows and 34 pigs, a few cows and three times as many pigs were sold on the market. When there are 30 remaining cows and pigs, how many cows sold?
|
4
|
12 34 [OP_ADD] 30 [OP_SUB] 1 3 [OP_ADD] [OP_DIV]
|
var_a = 12
var_b = 34
var_c = var_a + var_b
var_d = 30
var_e = var_c - var_d
var_f = 1
var_g = 3
var_h = var_f + var_g
var_i = var_e / var_h
print(int(var_i))
|
Geometry
|
How many candles are needed to place candles every 3 cm (cm) on the edge of a square table with a side of 90 centimeters (cm)?
|
120
|
90 4 [OP_MUL] 3 [OP_FDIV]
|
var_a = 90
var_b = 4
var_c = var_a * var_b
var_d = 3
var_e = var_c // var_d
print(int(var_e))
|
Correspondence
|
If there are four different natural numbers A, B, C, and D that satisfy A2B6-C97=543D, what are the possible values for A?
|
6
|
A2B6-C97=543D A [OP_DIGIT_UNK_SOLVER]
|
var_a = 'A2B6-C97=543D'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c))
|
Comparison
|
Junsu drank 0.331 liters (L) of milk, while Jimin drank 218 milliliters (㎖). Who drank more milk?
|
Junsu
|
[OP_LIST_SOL] Junsu Jimin [OP_LIST_EOL] [OP_LIST_SOL] 0.331 1000 [OP_MUL] 218 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
|
var_a = 'Junsu'
var_b = 'Jimin'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 0.331
var_d = 1000
var_e = var_c * var_d
var_f = 218
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j)
|
Possibility
|
You want to use 3 out of 0, 7, 4, and 5 allowing the repetition of digits to create a three-digit number. Find the difference between the second largest number and the third smallest number that can be made.
|
370
|
[OP_LIST_SOL] 0 7 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS]
|
var_a = 0
var_b = 7
var_c = 4
var_d = 5
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 2
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
var_h = 3
list_d=list_b.copy()
list_d.sort()
var_i = list_d[var_h-1]
var_j = var_g - var_i
var_k = abs(var_j)
print(int(var_k))
|
Comparison
|
There are several chairs inside the church. If 9 students sit per chair, one student cannot sit, and if 10 students sit per chair, 1 chair becomes vacant. How many students went to church?
|
100
|
1 10 [OP_ADD] 10 9 [OP_SUB] [OP_DIV] 9 [OP_MUL] 1 [OP_ADD]
|
var_a = 1
var_b = 10
var_c = var_a + var_b
var_d = 10
var_e = 9
var_f = var_d - var_e
var_g = var_c / var_f
var_h = 9
var_i = var_g * var_h
var_j = 1
var_k = var_i + var_j
print(int(var_k))
|
Arithmetic calculation
|
There are four numbers 10, 11, 12, and 13. What is the value of difference between the 3rd smallest number and the 2nd smallest number?
|
1
|
[OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB]
|
var_a = 10
var_b = 11
var_c = 12
var_d = 13
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b=list_a.copy()
list_b.sort()
var_f = list_b[var_e-1]
var_g = 2
list_c=list_a.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = var_f - var_h
print(int(var_i))
|
Correspondence
|
I was supposed to subtract 36 from a particular number, but mistakenly subtracted 63, and as a result, got 8 as an answer. What should be the answer to the correct calculation?
|
35
|
8 63 [OP_ADD] 36 [OP_SUB]
|
var_a = 8
var_b = 63
var_c = var_a + var_b
var_d = 36
var_e = var_c - var_d
print(int(var_e))
|
Possibility
|
Each box contains 3 red balls and 5 blue balls. When Jungkook has 2 boxes, how many red balls does Jungkook have?
|
6
|
3 2 [OP_MUL]
|
var_a = 3
var_b = 2
var_c = var_a * var_b
print(int(var_c))
|
Geometry
|
After arranging the vases in a square shape, there were 6 bottles left. So, I tried to increase the width and length by one row each, but 11 vases were insufficient. If you arrange these vases in 7 rows, how many bottles are there in 1 row?
|
10
|
6 11 [OP_ADD] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 6 [OP_ADD] 7 [OP_DIV]
|
var_a = 6
var_b = 11
var_c = var_a + var_b
var_d = 1
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
var_h = 2
var_i = var_g ** var_h
var_j = 6
var_k = var_i + var_j
var_l = 7
var_m = var_k / var_l
print(int(var_m))
|
Geometry
|
What is the sum of the lengths in centimeters (cm) of all the edges of a cube with one edge length of 15 centimeters (cm)?
|
180
|
15 4 3 [OP_MUL] [OP_MUL]
|
var_a = 15
var_b = 4
var_c = 3
var_d = var_b * var_c
var_e = var_a * var_d
print(int(var_e))
|
Possibility
|
Three cards of numbers from 1 to 9 are used to create a certain three-digit number. If the hundredth place is 7 and the tens place is 4, how many digits can be placed in the ones place?
|
7
|
1 9 1 [OP_LIST_ARANGE] [OP_LIST_SOL] 7 4 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN]
|
var_a = 1
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 7
var_e = 4
list_b= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
list_c = list(set(list_a) - set(list_b))
var_f = len(list_c)
print(int(var_f))
|
Correspondence
|
Hyungjun used half of his ribbon and 2000 centimeters (cm) of ribbon to wrap the first box, and used half of the remaining ribbon and 2000 centimeters (cm) of ribbon to wrap the second box, but there was no ribbon left. How many centimeters (cm) is the ribbon Hyeongjun had at first?
|
12000
|
0 2000 [OP_ADD] 2 [OP_MUL] 2000 [OP_ADD] 2 [OP_MUL]
|
var_a = 0
var_b = 2000
var_c = var_a + var_b
var_d = 2
var_e = var_c * var_d
var_f = 2000
var_g = var_e + var_f
var_h = 2
var_i = var_g * var_h
print(int(var_i))
|
Geometry
|
There is a box with an inside volume of 138000000 cubic centimeters (cm3), six sides each being a rectangle, equal opposite sides, twelve edges, and eight vertices. If the area of the top surface is 115 square meters (m2), find the height in meters (m).
|
12
|
1380000000 100 3 [OP_POW] [OP_DIV] 115 [OP_DIV]
|
var_a = 1380000000
var_b = 100
var_c = 3
var_d = var_b ** var_c
var_e = var_a / var_d
var_f = 115
var_g = var_e / var_f
print(int(var_g))
|
Arithmetic calculation
|
If the sum of the two pages of the book Eunji has opened is 137, what is the larger number of the two pages Eunji has opened?
|
69
|
137 2 [OP_FDIV] 1 [OP_ADD]
|
var_a = 137
var_b = 2
var_c = var_a // var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e))
|
Geometry
|
Find the number of all faces of a regular icosahedron.
|
20
|
20
|
var_a = 20
print(int(var_a))
|
Geometry
|
A park is in the shape of a square with sides measuring 10 meters (m). We want to divide the park into right triangles with a base of 1 meters (m) and a height of 3 meters (m). What is the maximum number of zones that can be divided?
|
66
|
10 2 [OP_POW] 1 3 [OP_MUL] [OP_FDIV] 2 [OP_MUL]
|
var_a = 10
var_b = 2
var_c = var_a ** var_b
var_d = 1
var_e = 3
var_f = var_d * var_e
var_g = var_c // var_f
var_h = 2
var_i = var_g * var_h
print(int(var_i))
|
Arithmetic calculation
|
You want to hand out 269 pens each of which costs 150 won to 29 students equally. If you have to buy the lacking pens, find how much money you need.
|
3150
|
29 269 29 [OP_MOD] [OP_SUB] 150 [OP_MUL]
|
var_a = 29
var_b = 269
var_c = 29
var_d = var_b % var_c
var_e = var_a - var_d
var_f = 150
var_g = var_e * var_f
print(int(var_g))
|
Correspondence
|
A prime number was supposed to be divided by 8, but multiplied by 8 by mistake, and it became 69.76. Find the correct value.
|
1.09
|
69.76 8 [OP_DIV] 8 [OP_DIV]
|
var_a = 69.76
var_b = 8
var_c = var_a / var_b
var_d = 8
var_e = var_c / var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
Comparison
|
Which is the smallest among circle A with a diameter of 10 centimeters (cm), circle B with a radius of 4 centimeters (cm), and circle C with a sum of 9 in its diameter and radius?
|
C
|
[OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 10 2 [OP_DIV] 4 9 2 1 [OP_ADD] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
|
var_a = 'A'
var_b = 'B'
var_c = 'C'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 10
var_e = 2
var_f = var_d / var_e
var_g = 4
var_h = 9
var_i = 2
var_j = 1
var_k = var_i + var_j
var_l = var_h / var_k
list_b= []
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_m = 1
list_c=list_b.copy()
list_c.sort()
var_n = list_c[var_m-1]
var_o = list_b.index(var_n)+1
var_p = list_a[var_o-1]
print(var_p)
|
Arithmetic calculation
|
There are 34 hibiscus. There are 13 fewer hibiscus than chrysanthemums. There are 23 more chrysanthemums than dandelions. How many hibiscus, chrysanthemum, and dandelion are there in total?
|
105
|
34 34 13 [OP_ADD] [OP_ADD] 34 13 [OP_ADD] 23 [OP_SUB] [OP_ADD]
|
var_a = 34
var_b = 34
var_c = 13
var_d = var_b + var_c
var_e = var_a + var_d
var_f = 34
var_g = 13
var_h = var_f + var_g
var_i = 23
var_j = var_h - var_i
var_k = var_e + var_j
print(int(var_k))
|
Correspondence
|
There are two different numbers A and B. Find B from the two-digit addition formula AB+25=B3.
|
8
|
AB+25=B3 B [OP_DIGIT_UNK_SOLVER]
|
var_a = 'AB+25=B3'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c))
|
Geometry
|
A regular octagonal fence was built using eight 2.3-meter (m) wooden poles. What is the perimeter of this fence in centimeters (cm)?
|
1840
|
2.3 8 [OP_MUL] 100 [OP_MUL]
|
var_a = 2.3
var_b = 8
var_c = var_a * var_b
var_d = 100
var_e = var_c * var_d
print(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))
|
Arithmetic calculation
|
If a ball that bounces 1/4 of its height is dropped from a height of 12.8 meters (m), how many centimeters (cm) will the third bounce be?
|
20
|
12.8 1/4 3 [OP_POW] [OP_MUL] 100 [OP_MUL]
|
var_a = 12.8
var_b = 0.25
var_c = 3
var_d = var_b ** var_c
var_e = var_a * var_d
var_f = 100
var_g = var_e * var_f
print(int(var_g))
|
Geometry
|
The circumference of a wheel is 94.2 centimeters (cm). If the diameter of this wheel is 30 centimeters (cm), how many times the circumference of the wheel is than the diameter?
|
3.14
|
94.2 30 [OP_DIV]
|
var_a = 94.2
var_b = 30
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2)))
|
Arithmetic calculation
|
How many kilograms (kg) does 1 meter (m) of marble weigh if 3/4 meter (m) of marble weighs 15/2 kilograms (kg)?
|
10
|
15/2 3/4 [OP_DIV]
|
var_a = 7.5
var_b = 0.75
var_c = var_a / var_b
print(int(var_c))
|
Arithmetic calculation
|
Seokgi and Yeseul are going to share a wire that is 1 meter (m) and 50 centimeters (cm) long. Find how many centimeters (cm) of wire must Seokgi take for him to get 16 centimeters (cm) shorter wire than Yeseul's.
|
67
|
1 100 [OP_MUL] 50 [OP_ADD] 16 [OP_SUB] 2 [OP_DIV]
|
var_a = 1
var_b = 100
var_c = var_a * var_b
var_d = 50
var_e = var_c + var_d
var_f = 16
var_g = var_e - var_f
var_h = 2
var_i = var_g / var_h
print(int(var_i))
|
Arithmetic calculation
|
The price of one onion is 200 won. How much does one bag of onions cost, if you divide 180 onions into 6 bags?
|
6000
|
180 6 [OP_DIV] 200 [OP_MUL]
|
var_a = 180
var_b = 6
var_c = var_a / var_b
var_d = 200
var_e = var_c * var_d
print(int(var_e))
|
Possibility
|
Find the sum of the largest and smallest six-digit numbers that can be formed by using 2, 0, 4, 1, 5, and 8 only once.
|
956668
|
[OP_LIST_SOL] 2 0 4 1 5 8 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]
|
var_a = 2
var_b = 0
var_c = 4
var_d = 1
var_e = 5
var_f = 8
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = 6
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_g))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_h = 1
list_c=list_b.copy()
list_c.sort()
var_i = list_c[-var_h]
var_j = 1
list_d=list_b.copy()
list_d.sort()
var_k = list_d[var_j-1]
var_l = var_i + var_k
print(int(var_l))
|
Geometry
|
A rectangular wrapping paper is 6 centimeters (cm) wide and 28 centimeters (cm) in perimeter. Find the area of the area that can be covered with this wrapping paper.
|
48
|
28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL]
|
var_a = 28
var_b = 2
var_c = var_a / var_b
var_d = 6
var_e = var_c - var_d
var_f = 6
var_g = var_e * var_f
print(int(var_g))
|
Arithmetic calculation
|
Hyeongi studies for 0.6 hours a day. For how many hours did Hyeongi study in 3 weeks?
|
12.6
|
0.6 7 [OP_MUL] 3 [OP_MUL]
|
var_a = 0.6
var_b = 7
var_c = var_a * var_b
var_d = 3
var_e = var_c * var_d
print('{:.2f}'.format(round(var_e+1e-10,2)))
|
Geometry
|
I cut 78 centimeters (cm) of wire and used all of them to make one triangle and one square. If the sum of the lengths of the three sides of the triangle is 46 centimeters (cm), how many centimeters (cm) is the side of the square?
|
8
|
78 46 [OP_SUB] 4 [OP_DIV]
|
var_a = 78
var_b = 46
var_c = var_a - var_b
var_d = 4
var_e = var_c / var_d
print(int(var_e))
|
Arithmetic calculation
|
Six friends are going to rent bikes for a ride in the park. A 30-minute rental of a bicycle is 4,000 won. How much does one person have to pay to rent 4 bicycles for 3 hours?
|
16000
|
3 60 [OP_MUL] 30 [OP_DIV] 4000 [OP_MUL] 4 [OP_MUL] 6 [OP_DIV]
|
var_a = 3
var_b = 60
var_c = var_a * var_b
var_d = 30
var_e = var_c / var_d
var_f = 4000
var_g = var_e * var_f
var_h = 4
var_i = var_g * var_h
var_j = 6
var_k = var_i / var_j
print(int(var_k))
|
Arithmetic calculation
|
It requires 30 pictures to play 1 second of the animated film called 'The Snow Prince'. How many pictures are necessary to make a 25-second screening?
|
750
|
30 25 [OP_MUL]
|
var_a = 30
var_b = 25
var_c = var_a * var_b
print(int(var_c))
|
Geometry
|
You want to create a rectangular field that has the same area as a triangular field with a base of 7.2 meters (m) and a height of 7 meters (m). If the width of a rectangular field is 4 meters (m), how many meters (m) should the length be?
|
6.3
|
7.2 7 [OP_MUL] 2 [OP_DIV] 4 [OP_DIV]
|
var_a = 7.2
var_b = 7
var_c = var_a * var_b
var_d = 2
var_e = var_c / var_d
var_f = 4
var_g = var_e / var_f
print('{:.2f}'.format(round(var_g+1e-10,2)))
|
Arithmetic calculation
|
At first, Jungkook had 8 apples. How many apples does Jungkook have in total when he is given 7 apples?
|
15
|
8 7 [OP_ADD]
|
var_a = 8
var_b = 7
var_c = var_a + var_b
print(int(var_c))
|
Arithmetic calculation
|
Jungkook tries to divide 10 balls into boxes containing 5 balls each. How many boxes does Jungkook need?
|
2
|
10 5 [OP_DIV]
|
var_a = 10
var_b = 5
var_c = var_a / var_b
print(int(var_c))
|
Geometry
|
Haechan used all the ribbon tapes he had to make a rectangle of 7 centimeters (cm) long and 5 centimeters (cm) wide. If he used this ribbon tape again to make a square, how many centimeters (cm) would each side be?
|
6
|
7 5 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV]
|
var_a = 7
var_b = 5
var_c = var_a + var_b
var_d = 2
var_e = var_c * var_d
var_f = 4
var_g = var_e / var_f
print(int(var_g))
|
Correspondence
|
If you divide a number by 1.2, subtract 22.5, multiply that number by 0.6, then add 10.5, you can get 30. Find out this number.
|
66
|
30 10.5 [OP_SUB] 0.6 [OP_DIV] 22.5 [OP_ADD] 1.2 [OP_MUL]
|
var_a = 30
var_b = 10.5
var_c = var_a - var_b
var_d = 0.6
var_e = var_c / var_d
var_f = 22.5
var_g = var_e + var_f
var_h = 1.2
var_i = var_g * var_h
print(int(var_i))
|
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