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Find the titles of items whose rating is higher than the average review rating of all items.
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating > (SELECT avg(rating) FROM review)
Find the titles of items that received any rating below 5.
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating < 5
Find the titles of items that received both a rating higher than 8 and a rating below 5.
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating > 8 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating < 5
Find the names of items whose rank is higher than 3 and whose average rating is above 5.
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rank > 3 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id HAVING avg(T2.rating) > 5
Find the name of the item with the lowest average rating.
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rating) LIMIT 1
List the titles of all items in alphabetic order .
SELECT title FROM item ORDER BY title
Find the name of the user who gives the most reviews.
SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id ORDER BY count(*) DESC LIMIT 1
Find the name and id of the item with the highest average rating.
SELECT T1.title , T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rating) DESC LIMIT 1
Find the name and id of the good with the highest average rank.
SELECT T1.title , T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rank) DESC LIMIT 1
For each user, return the name and the average rating of reviews given by them.
SELECT T1.name , avg(T2.rating) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id
For each user, find their name and the number of reviews written by them.
SELECT T1.name , count(*) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id
Find the name of the user who gave the highest rating.
SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id ORDER BY T2.rating DESC LIMIT 1
Find the name of the source user with the highest average trust score.
SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.source_u_id GROUP BY T2.source_u_id ORDER BY avg(trust) DESC LIMIT 1
Find each target user's name and average trust score.
SELECT T1.name , avg(trust) FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.target_u_id GROUP BY T2.target_u_id
Find the name of the target user with the lowest trust score.
SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.target_u_id ORDER BY trust LIMIT 1
Find the names of the items that did not receive any review.
SELECT title FROM item WHERE i_id NOT IN (SELECT i_id FROM review)
Find the names of users who did not leave any review.
SELECT name FROM useracct WHERE u_id NOT IN (SELECT u_id FROM review)
Find the number of users who did not write any review.
SELECT count(*) FROM useracct WHERE u_id NOT IN (SELECT u_id FROM review)
Find the number of items without any review.
SELECT count(*) FROM item WHERE i_id NOT IN (SELECT i_id FROM review)
How many players are there?
SELECT count(*) FROM player
List the names of players in ascending order of votes.
SELECT Player_name FROM player ORDER BY Votes ASC
What are the gender and occupation of players?
SELECT Gender , Occupation FROM player
List the name and residence for players whose occupation is not "Researcher".
SELECT Player_name , residence FROM player WHERE Occupation != "Researcher"
Show the names of sponsors of players whose residence is either "Brandon" or "Birtle".
SELECT Sponsor_name FROM player WHERE Residence = "Brandon" OR Residence = "Birtle"
What is the name of the player with the largest number of votes?
SELECT Player_name FROM player ORDER BY Votes DESC LIMIT 1
Show different occupations along with the number of players in each occupation.
SELECT Occupation , COUNT(*) FROM player GROUP BY Occupation
Please show the most common occupation of players.
SELECT Occupation FROM player GROUP BY Occupation ORDER BY COUNT(*) DESC LIMIT 1
Show the residences that have at least two players.
SELECT Residence FROM player GROUP BY Residence HAVING COUNT(*) >= 2
Show the names of players and names of their coaches.
SELECT T3.Player_name , T2.coach_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID
Show the names of players coached by the rank 1 coach.
SELECT T3.Player_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID WHERE T2.Rank = 1
Show the names and genders of players with a coach starting after 2011.
SELECT T3.Player_name , T3.gender FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID WHERE T1.Starting_year > 2011
Show the names of players and names of their coaches in descending order of the votes of players.
SELECT T3.Player_name , T2.coach_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID ORDER BY T3.Votes DESC
List the names of players that do not have coaches.
SELECT Player_name FROM player WHERE Player_ID NOT IN (SELECT Player_ID FROM player_coach)
Show the residences that have both a player of gender "M" and a player of gender "F".
SELECT Residence FROM player WHERE gender = "M" INTERSECT SELECT Residence FROM player WHERE gender = "F"
How many coaches does each club has? List the club id, name and the number of coaches.
SELECT T1.club_id , T1.club_name, count(*) FROM club AS T1 JOIN coach AS T2 ON T1.club_id = T2.club_id GROUP BY T1.club_id
How many gold medals has the club with the most coaches won?
SELECT T1.club_id , T1.gold FROM match_result AS T1 JOIN coach AS T2 ON T1.club_id = T2.club_id GROUP BY T1.club_id ORDER BY count(*) DESC LIMIT 1
How many gymnasts are there?
SELECT count(*) FROM gymnast
Count the number of gymnasts.
SELECT count(*) FROM gymnast
List the total points of gymnasts in descending order.
SELECT Total_Points FROM gymnast ORDER BY Total_Points DESC
What are the total points for all gymnasts, ordered by total points descending?
SELECT Total_Points FROM gymnast ORDER BY Total_Points DESC
List the total points of gymnasts in descending order of floor exercise points.
SELECT Total_Points FROM gymnast ORDER BY Floor_Exercise_Points DESC
What are the total points of gymnasts, ordered by their floor exercise points descending?
SELECT Total_Points FROM gymnast ORDER BY Floor_Exercise_Points DESC
What is the average horizontal bar points for all gymnasts?
SELECT avg(Horizontal_Bar_Points) FROM gymnast
Return the average horizontal bar points across all gymnasts.
SELECT avg(Horizontal_Bar_Points) FROM gymnast
What are the names of people in ascending alphabetical order?
SELECT Name FROM People ORDER BY Name ASC
Return the names of people, ordered alphabetically.
SELECT Name FROM People ORDER BY Name ASC
What are the names of gymnasts?
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
Return the names of the gymnasts.
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
What are the names of gymnasts whose hometown is not "Santo Domingo"?
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T2.Hometown != "Santo Domingo"
Return the names of gymnasts who did not grow up in Santo Domingo.
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T2.Hometown != "Santo Domingo"
What is the age of the tallest person?
SELECT Age FROM people ORDER BY Height DESC LIMIT 1
Return the age of the person with the greatest height.
SELECT Age FROM people ORDER BY Height DESC LIMIT 1
List the names of the top 5 oldest people.
SELECT Name FROM People ORDER BY Age DESC LIMIT 5
What are the names of the five oldest people?
SELECT Name FROM People ORDER BY Age DESC LIMIT 5
What is the total point count of the youngest gymnast?
SELECT T1.Total_Points FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Age ASC LIMIT 1
Return the total points of the gymnast with the lowest age.
SELECT T1.Total_Points FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Age ASC LIMIT 1
What is the average age of all gymnasts?
SELECT avg(T2.Age) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
Return the average age across all gymnasts.
SELECT avg(T2.Age) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
What are the distinct hometowns of gymnasts with total points more than 57.5?
SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T1.Total_Points > 57.5
Give the different hometowns of gymnasts that have a total point score of above 57.5.
SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T1.Total_Points > 57.5
What are the hometowns of gymnasts and the corresponding number of gymnasts?
SELECT T2.Hometown , COUNT(*) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown
How many gymnasts are from each hometown?
SELECT T2.Hometown , COUNT(*) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown
What is the most common hometown of gymnasts?
SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown ORDER BY COUNT(*) DESC LIMIT 1
Return the hometown that is most common among gymnasts.
SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown ORDER BY COUNT(*) DESC LIMIT 1
What are the hometowns that are shared by at least two gymnasts?
SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown HAVING COUNT(*) >= 2
Give the hometowns from which two or more gymnasts are from.
SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown HAVING COUNT(*) >= 2
List the names of gymnasts in ascending order by their heights.
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Height ASC
What are the names of gymnasts, ordered by their heights ascending?
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Height ASC
List the distinct hometowns that are not associated with any gymnast.
SELECT DISTINCT Hometown FROM people EXCEPT SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
From which hometowns did no gymnasts come from?
SELECT DISTINCT Hometown FROM people EXCEPT SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
Show the hometowns shared by people older than 23 and younger than 20.
SELECT Hometown FROM people WHERE Age > 23 INTERSECT SELECT Hometown FROM people WHERE Age < 20
From which hometowns did both people older than 23 and younger than 20 come from?
SELECT Hometown FROM people WHERE Age > 23 INTERSECT SELECT Hometown FROM people WHERE Age < 20
How many distinct hometowns did these people have?
SELECT count(DISTINCT Hometown) FROM people
Count the number of different hometowns of these people.
SELECT count(DISTINCT Hometown) FROM people
Show the ages of gymnasts in descending order of total points.
SELECT T2.Age FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T1.Total_Points DESC
What are the ages of the gymnasts, ordered descending by their total points?
SELECT T2.Age FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T1.Total_Points DESC
Find the total savings balance of all accounts except the account with name ‘Brown’.
SELECT sum(T2.balance) FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T1.name != 'Brown'
What is the total balance of savings accounts not belonging to someone with the name Brown?
SELECT sum(T2.balance) FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T1.name != 'Brown'
How many accounts are there in total?
SELECT count(*) FROM accounts
Count the number of accounts.
SELECT count(*) FROM accounts
What is the total checking balance in all accounts?
SELECT sum(balance) FROM checking
Find the total balance across checking accounts.
SELECT sum(balance) FROM checking
Find the average checking balance.
SELECT avg(balance) FROM checking
What is the average balance in checking accounts?
SELECT avg(balance) FROM checking
How many accounts have a savings balance above the average savings balance?
SELECT count(*) FROM savings WHERE balance > (SELECT avg(balance) FROM savings)
Find the number of accounts with a savings balance that is higher than the average savings balance.
SELECT count(*) FROM savings WHERE balance > (SELECT avg(balance) FROM savings)
Find the name and id of accounts whose checking balance is below the maximum checking balance.
SELECT T1.custid , T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT max(balance) FROM checking)
What are the customer id and name corresponding to accounts with a checking balance less than the largest checking balance?
SELECT T1.custid , T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT max(balance) FROM checking)
What is the checking balance of the account whose owner’s name contains the substring ‘ee’?
SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name LIKE '%ee%'
Find the balance of the checking account belonging to an owner whose name contains 'ee'.
SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name LIKE '%ee%'
Find the checking balance and saving balance in the Brown’s account.
SELECT T2.balance , T3.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid WHERE T1.name = 'Brown'
What are the checking and savings balances in accounts belonging to Brown?
SELECT T2.balance , T3.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid WHERE T1.name = 'Brown'
Find the names of accounts whose checking balance is above the average checking balance, but savings balance is below the average savings balance.
SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM checking) INTERSECT SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT avg(balance) FROM savings)
What are the names of accounts with checking balances greater than the average checking balance and savings balances below the average savings balance?
SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM checking) INTERSECT SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT avg(balance) FROM savings)
Find the checking balance of the accounts whose savings balance is higher than the average savings balance.
SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name IN (SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM savings))
What are the balances of checking accounts belonging to people with savings balances greater than the average savings balance?
SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name IN (SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM savings))
List all customers’ names in the alphabetical order.
SELECT name FROM accounts ORDER BY name
What are the names of all the customers in alphabetical order?
SELECT name FROM accounts ORDER BY name
Find the name of account that has the lowest total checking and saving balance.
SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid ORDER BY T2.balance + T3.balance LIMIT 1
What is the name corresponding to the accoung with the lowest sum of checking and savings balances?
SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid ORDER BY T2.balance + T3.balance LIMIT 1