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Find the id and number of shops for the company that produces the most expensive furniture. | SELECT t1.manufacturer_id , t1.num_of_shops FROM manufacturer AS t1 JOIN furniture_manufacte AS t2 ON t1.manufacturer_id = t2.manufacturer_id ORDER BY t2.Price_in_Dollar DESC LIMIT 1 |
Find the number of funiture types produced by each manufacturer as well as the company names. | SELECT count(*) , t1.name FROM manufacturer AS t1 JOIN furniture_manufacte AS t2 ON t1.manufacturer_id = t2.manufacturer_id GROUP BY t1.manufacturer_id |
Give me the names and prices of furnitures which some companies are manufacturing. | SELECT t1.name , t2.price_in_dollar FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID = t2.Furniture_ID |
Find the market shares and names of furnitures which no any company is producing in our records. | SELECT Market_Rate , name FROM furniture WHERE Furniture_ID NOT IN (SELECT Furniture_ID FROM furniture_manufacte) |
Find the name of the company that produces both furnitures with less than 6 components and furnitures with more than 10 components. | SELECT t3.name FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID = t2.Furniture_ID JOIN manufacturer AS t3 ON t2.manufacturer_id = t3.manufacturer_id WHERE t1.num_of_component < 6 INTERSECT SELECT t3.name FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID = t2.Furniture_ID JOIN manufacturer AS t3 ON t2.manufacturer_id = t3.manufacturer_id WHERE t1.num_of_component > 10 |
Display the first name and department name for each employee. | SELECT T1.first_name , T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id |
What are the first name and department name of all employees? | SELECT T1.first_name , T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id |
List the full name (first and last name), and salary for those employees who earn below 6000. | SELECT first_name , last_name , salary FROM employees WHERE salary < 6000 |
What are the full names and salaries for any employees earning less than 6000? | SELECT first_name , last_name , salary FROM employees WHERE salary < 6000 |
Display the first name, and department number for all employees whose last name is "McEwen". | SELECT first_name , department_id FROM employees WHERE last_name = 'McEwen' |
What are the first names and department numbers for employees with last name McEwen? | SELECT first_name , department_id FROM employees WHERE last_name = 'McEwen' |
Return all the information for all employees without any department number. | SELECT * FROM employees WHERE department_id = "null" |
What are all the employees without a department number? | SELECT * FROM employees WHERE department_id = "null" |
Display all the information about the department Marketing. | SELECT * FROM departments WHERE department_name = 'Marketing' |
What is all the information about the Marketing department? | SELECT * FROM departments WHERE department_name = 'Marketing' |
when is the hire date for those employees whose first name does not containing the letter M? | SELECT hire_date FROM employees WHERE first_name NOT LIKE '%M%' |
On what dates were employees without the letter M in their first names hired? | SELECT hire_date FROM employees WHERE first_name NOT LIKE '%M%' |
display the full name (first and last), hire date, salary, and department number for those employees whose first name does not containing the letter M. | SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE '%M%' |
What are the full name, hire date, salary, and department id for employees without the letter M in their first name? | SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE '%M%' |
display the full name (first and last), hire date, salary, and department number for those employees whose first name does not containing the letter M and make the result set in ascending order by department number. | SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE '%M%' ORDER BY department_id |
What are the full name, hire data, salary and department id for employees without the letter M in their first name, ordered by ascending department id? | SELECT first_name , last_name , hire_date , salary , department_id FROM employees WHERE first_name NOT LIKE '%M%' ORDER BY department_id |
what is the phone number of employees whose salary is in the range of 8000 and 12000? | SELECT phone_number FROM employees WHERE salary BETWEEN 8000 AND 12000 |
Return the phone numbers of employees with salaries between 8000 and 12000. | SELECT phone_number FROM employees WHERE salary BETWEEN 8000 AND 12000 |
display all the information of employees whose salary is in the range of 8000 and 12000 and commission is not null or department number does not equal to 40. | SELECT * FROM employees WHERE salary BETWEEN 8000 AND 12000 AND commission_pct != "null" OR department_id != 40 |
Return all information about employees with salaries between 8000 and 12000 for which commission is not null or where their department id is not 40. | SELECT * FROM employees WHERE salary BETWEEN 8000 AND 12000 AND commission_pct != "null" OR department_id != 40 |
What are the full name (first and last name) and salary for all employees who does not have any value for commission? | SELECT first_name , last_name , salary FROM employees WHERE commission_pct = "null" |
Return the full names and salaries of employees with null commissions. | SELECT first_name , last_name , salary FROM employees WHERE commission_pct = "null" |
Display the first and last name, and salary for those employees whose first name is ending with the letter m. | SELECT first_name , last_name , salary FROM employees WHERE first_name LIKE '%m' |
Return the full names and salaries for employees with first names that end with the letter m. | SELECT first_name , last_name , salary FROM employees WHERE first_name LIKE '%m' |
Find job id and date of hire for those employees who was hired between November 5th, 2007 and July 5th, 2009. | SELECT job_id , hire_date FROM employees WHERE hire_date BETWEEN '2007-11-05' AND '2009-07-05' |
What are the job ids and dates of hire for employees hired after November 5th, 2007 and before July 5th, 2009? | SELECT job_id , hire_date FROM employees WHERE hire_date BETWEEN '2007-11-05' AND '2009-07-05' |
What are the first and last name for those employees who works either in department 70 or 90? | SELECT first_name , last_name FROM employees WHERE department_id = 70 OR department_id = 90 |
What are the full names of employees who with in department 70 or 90? | SELECT first_name , last_name FROM employees WHERE department_id = 70 OR department_id = 90 |
Find the salary and manager number for those employees who is working under a manager. | SELECT salary , manager_id FROM employees WHERE manager_id != "null" |
What are the salaries and manager ids for employees who have managers? | SELECT salary , manager_id FROM employees WHERE manager_id != "null" |
display all the details from Employees table for those employees who was hired before 2002-06-21. | SELECT * FROM employees WHERE hire_date < '2002-06-21' |
What is all the information about employees hired before June 21, 2002? | SELECT * FROM employees WHERE hire_date < '2002-06-21' |
display all the information for all employees who have the letters D or S in their first name and also arrange the result in descending order by salary. | SELECT * FROM employees WHERE first_name LIKE '%D%' OR first_name LIKE '%S%' ORDER BY salary DESC |
What is all the information about employees with D or S in their first name, ordered by salary descending? | SELECT * FROM employees WHERE first_name LIKE '%D%' OR first_name LIKE '%S%' ORDER BY salary DESC |
display those employees who joined after 7th September, 1987. | SELECT * FROM employees WHERE hire_date > '1987-09-07' |
Which employees were hired after September 7th, 1987? | SELECT * FROM employees WHERE hire_date > '1987-09-07' |
display the job title of jobs which minimum salary is greater than 9000. | SELECT job_title FROM jobs WHERE min_salary > 9000 |
Which job titles correspond to jobs with salaries over 9000? | SELECT job_title FROM jobs WHERE min_salary > 9000 |
display job Title, the difference between minimum and maximum salaries for those jobs which max salary within the range 12000 to 18000. | SELECT job_title , max_salary - min_salary FROM jobs WHERE max_salary BETWEEN 12000 AND 18000 |
What are the job titles, and range of salaries for jobs with maximum salary between 12000 and 18000? | SELECT job_title , max_salary - min_salary FROM jobs WHERE max_salary BETWEEN 12000 AND 18000 |
display the emails of the employees who have no commission percentage and salary within the range 7000 to 12000 and works in that department which number is 50. | SELECT email FROM employees WHERE commission_pct = "null" AND salary BETWEEN 7000 AND 12000 AND department_id = 50 |
What are the emails of employees with null commission, salary between 7000 and 12000, and who work in department 50? | SELECT email FROM employees WHERE commission_pct = "null" AND salary BETWEEN 7000 AND 12000 AND department_id = 50 |
display the employee ID for each employee and the date on which he ended his previous job. | SELECT employee_id , MAX(end_date) FROM job_history GROUP BY employee_id |
What are the employee ids for each employee and final dates of employment at their last job? | SELECT employee_id , MAX(end_date) FROM job_history GROUP BY employee_id |
display those departments where more than ten employees work who got a commission percentage. | SELECT department_id FROM employees GROUP BY department_id HAVING COUNT(commission_pct) > 10 |
What are the department ids for which more than 10 employees had a commission? | SELECT department_id FROM employees GROUP BY department_id HAVING COUNT(commission_pct) > 10 |
Find the ids of the departments where any manager is managing 4 or more employees. | SELECT DISTINCT department_id FROM employees GROUP BY department_id , manager_id HAVING COUNT(employee_id) >= 4 |
What are department ids for departments with managers managing more than 3 employees? | SELECT DISTINCT department_id FROM employees GROUP BY department_id , manager_id HAVING COUNT(employee_id) >= 4 |
display the average salary of employees for each department who gets a commission percentage. | SELECT department_id , AVG(salary) FROM employees WHERE commission_pct != "null" GROUP BY department_id |
What is the average salary of employees who have a commission percentage that is not null? | SELECT department_id , AVG(salary) FROM employees WHERE commission_pct != "null" GROUP BY department_id |
display the country ID and number of cities for each country. | SELECT country_id , COUNT(*) FROM locations GROUP BY country_id |
Give the country id and corresponding count of cities in each country. | SELECT country_id , COUNT(*) FROM locations GROUP BY country_id |
display job ID for those jobs that were done by two or more for more than 300 days. | SELECT job_id FROM job_history WHERE end_date - start_date > 300 GROUP BY job_id HAVING COUNT(*) >= 2 |
What are the job ids for jobs done more than once for a period of more than 300 days? | SELECT job_id FROM job_history WHERE end_date - start_date > 300 GROUP BY job_id HAVING COUNT(*) >= 2 |
display the ID for those employees who did two or more jobs in the past. | SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*) >= 2 |
What are the employee ids for employees who have held two or more jobs? | SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*) >= 2 |
Find employee with ID and name of the country presently where (s)he is working. | SELECT T1.employee_id , T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id JOIN countries AS T4 ON T3.country_id = T4.country_id |
What are all the employee ids and the names of the countries in which they work? | SELECT T1.employee_id , T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id JOIN countries AS T4 ON T3.country_id = T4.country_id |
display the department name and number of employees in each of the department. | SELECT T2.department_name , COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id GROUP BY T2.department_name |
Give the name of each department and the number of employees in each. | SELECT T2.department_name , COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id GROUP BY T2.department_name |
Can you return all detailed info of jobs which was done by any of the employees who is presently earning a salary on and above 12000? | SELECT * FROM job_history AS T1 JOIN employees AS T2 ON T1.employee_id = T2.employee_id WHERE T2.salary >= 12000 |
What is all the job history info done by employees earning a salary greater than or equal to 12000? | SELECT * FROM job_history AS T1 JOIN employees AS T2 ON T1.employee_id = T2.employee_id WHERE T2.salary >= 12000 |
display job title and average salary of employees. | SELECT job_title , AVG(salary) FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id = T2.job_id GROUP BY T2.job_title |
What is the average salary for each job title? | SELECT job_title , AVG(salary) FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id = T2.job_id GROUP BY T2.job_title |
What is the full name ( first name and last name ) for those employees who gets more salary than the employee whose id is 163? | SELECT first_name , last_name FROM employees WHERE salary > (SELECT salary FROM employees WHERE employee_id = 163 ) |
Provide the full names of employees earning more than the employee with id 163. | SELECT first_name , last_name FROM employees WHERE salary > (SELECT salary FROM employees WHERE employee_id = 163 ) |
return the smallest salary for every departments. | SELECT MIN(salary) , department_id FROM employees GROUP BY department_id |
What is the minimum salary in each department? | SELECT MIN(salary) , department_id FROM employees GROUP BY department_id |
Find the first name and last name and department id for those employees who earn such amount of salary which is the smallest salary of any of the departments. | SELECT first_name , last_name , department_id FROM employees WHERE salary IN (SELECT MIN(salary) FROM employees GROUP BY department_id) |
What are the full names and department ids for the lowest paid employees across all departments. | SELECT first_name , last_name , department_id FROM employees WHERE salary IN (SELECT MIN(salary) FROM employees GROUP BY department_id) |
Find the employee id for all employees who earn more than the average salary. | SELECT employee_id FROM employees WHERE salary > (SELECT AVG(salary) FROM employees) |
What are the employee ids for employees who make more than the average? | SELECT employee_id FROM employees WHERE salary > (SELECT AVG(salary) FROM employees) |
display the employee id and salary of all employees who report to Payam (first name). | SELECT employee_id , salary FROM employees WHERE manager_id = (SELECT employee_id FROM employees WHERE first_name = 'Payam' ) |
What are the employee ids of employees who report to Payam, and what are their salaries? | SELECT employee_id , salary FROM employees WHERE manager_id = (SELECT employee_id FROM employees WHERE first_name = 'Payam' ) |
find the name of all departments that do actually have one or more employees assigned to them. | SELECT DISTINCT T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id |
What are the names of departments that have at least one employee. | SELECT DISTINCT T2.department_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id |
get the details of employees who manage a department. | SELECT DISTINCT * FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T1.employee_id = T2.manager_id |
What is all the information regarding employees who are managers? | SELECT DISTINCT * FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T1.employee_id = T2.manager_id |
display all the information about the department Marketing. | SELECT * FROM departments WHERE department_name = 'Marketing' |
What is all the information about the Marketing department? | SELECT * FROM departments WHERE department_name = 'Marketing' |
display the ID for those employees who did two or more jobs in the past. | SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*) >= 2 |
What are the employee ids for those who had two or more jobs. | SELECT employee_id FROM job_history GROUP BY employee_id HAVING COUNT(*) >= 2 |
What are the unique ids of those departments where any manager is managing 4 or more employees. | SELECT DISTINCT department_id FROM employees GROUP BY department_id , manager_id HAVING COUNT(employee_id) >= 4 |
Give the distinct department ids of departments in which a manager is in charge of 4 or more employees? | SELECT DISTINCT department_id FROM employees GROUP BY department_id , manager_id HAVING COUNT(employee_id) >= 4 |
Find the job ID for those jobs which average salary is above 8000. | SELECT job_id FROM employees GROUP BY job_id HAVING AVG(salary) > 8000 |
What are the job ids corresponding to jobs with average salary above 8000? | SELECT job_id FROM employees GROUP BY job_id HAVING AVG(salary) > 8000 |
display the employee ID and job name for all those jobs in department 80. | SELECT T1.employee_id , T2.job_title FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id = T2.job_id WHERE T1.department_id = 80 |
what are the employee ids and job titles for employees in department 80? | SELECT T1.employee_id , T2.job_title FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id = T2.job_id WHERE T1.department_id = 80 |
What is the first name and job id for all employees in the Finance department? | SELECT T1.first_name , T1.job_id FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T2.department_name = 'Finance' |
Give the first name and job id for all employees in the Finance department. | SELECT T1.first_name , T1.job_id FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T2.department_name = 'Finance' |
display all the information of the employees whose salary if within the range of smallest salary and 2500. | SELECT * FROM employees WHERE salary BETWEEN (SELECT MIN(salary) FROM employees) AND 2500 |
What is all the information regarding employees with salaries above the minimum and under 2500? | SELECT * FROM employees WHERE salary BETWEEN (SELECT MIN(salary) FROM employees) AND 2500 |
Find the ids of the employees who does not work in those departments where some employees works whose manager id within the range 100 and 200. | SELECT * FROM employees WHERE department_id NOT IN (SELECT department_id FROM departments WHERE manager_id BETWEEN 100 AND 200) |
What are the ids for employees who do not work in departments with managers that have ids between 100 and 200? | SELECT * FROM employees WHERE department_id NOT IN (SELECT department_id FROM departments WHERE manager_id BETWEEN 100 AND 200) |
display the employee name ( first name and last name ) and hire date for all employees in the same department as Clara. | SELECT first_name , last_name , hire_date FROM employees WHERE department_id = (SELECT department_id FROM employees WHERE first_name = "Clara") |
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