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Show the name, location, and number of platforms for all stations.
SELECT name , LOCATION , number_of_platforms FROM station
What are all locations of train stations?
SELECT DISTINCT LOCATION FROM station
Show the names and total passengers for all train stations not in London.
SELECT name , total_passengers FROM station WHERE LOCATION != 'London'
Show the names and main services for train stations that have the top three total number of passengers.
SELECT name , main_services FROM station ORDER BY total_passengers DESC LIMIT 3
What is the average and maximum number of total passengers for train stations in London or Glasgow?
SELECT avg(total_passengers) , max(total_passengers) FROM station WHERE LOCATION = 'London' OR LOCATION = 'Glasgow'
Show all locations and the total number of platforms and passengers for all train stations in each location.
SELECT LOCATION , sum(number_of_platforms) , sum(total_passengers) FROM station GROUP BY LOCATION
Show all locations that have train stations with at least 15 platforms and train stations with more than 25 total passengers.
SELECT DISTINCT LOCATION FROM station WHERE number_of_platforms >= 15 AND total_passengers > 25
Show all locations which don't have a train station with at least 15 platforms.
SELECT LOCATION FROM station EXCEPT SELECT LOCATION FROM station WHERE number_of_platforms >= 15
Show the location with most number of train stations.
SELECT LOCATION FROM station GROUP BY LOCATION ORDER BY count(*) DESC LIMIT 1
Show the name, time, and service for all trains.
SELECT name , TIME , service FROM train
Show the number of trains
SELECT count(*) FROM train
Show the name and service for all trains in order by time.
SELECT name , service FROM train ORDER BY TIME
Show the station name and number of trains in each station.
SELECT T2.name , count(*) FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id
show the train name and station name for each train.
SELECT T2.name , T3.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id
Show all train names and times in stations in London in descending order by train time.
SELECT T3.name , T3.time FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T2.location = 'London' ORDER BY T3.time DESC
Show the station name with greatest number of trains.
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id ORDER BY count(*) DESC LIMIT 1
Show the station name with at least two trains.
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id HAVING count(*) >= 2
Show all locations with only 1 station.
SELECT LOCATION FROM station GROUP BY LOCATION HAVING count(*) = 1
Show station names without any trains.
SELECT name FROM station WHERE station_id NOT IN (SELECT station_id FROM train_station)
What are the names of the stations which serve both "Ananthapuri Express" and "Guruvayur Express" trains?
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T3.Name = "Ananthapuri Express" INTERSECT SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T3.Name = "Guruvayur Express"
Find the names of the trains that do not pass any station located in London.
SELECT T2.name FROM train_station AS T1 JOIN train AS T2 ON T1.train_id = T2.train_id WHERE T1.station_id NOT IN (SELECT T4.station_id FROM train_station AS T3 JOIN station AS T4 ON T3.station_id = T4.station_id WHERE t4.location = "London")
List the names and locations of all stations ordered by their yearly entry exit and interchange amounts.
SELECT name , LOCATION FROM station ORDER BY Annual_entry_exit , Annual_interchanges
List all vehicle id
SELECT vehicle_id FROM Vehicles;
What are the ids of all vehicles?
SELECT vehicle_id FROM Vehicles;
How many vehicle in total?
SELECT count(*) FROM Vehicles;
How many vehicles exist?
SELECT count(*) FROM Vehicles;
Show the detail of vehicle with id 1.
SELECT vehicle_details FROM Vehicles WHERE vehicle_id = 1;
What are the details of the car with id 1?
SELECT vehicle_details FROM Vehicles WHERE vehicle_id = 1;
List the first name middle name and last name of all staff.
SELECT first_name , middle_name , last_name FROM Staff;
What are the first, middle, and last names of all staff?
SELECT first_name , middle_name , last_name FROM Staff;
What is the birthday of the staff member with first name as Janessa and last name as Sawayn?
SELECT date_of_birth FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
What is the date of birth for the staff member named Janessa Sawayn?
SELECT date_of_birth FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
When did the staff member with first name as Janessa and last name as Sawayn join the company?
SELECT date_joined_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
When did the staff member named Janessa Sawayn join the company?
SELECT date_joined_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
When did the staff member with first name as Janessa and last name as Sawayn leave the company?
SELECT date_left_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
When did the staff member Janessa Sawayn leave the company?
SELECT date_left_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
How many staff have the first name Ludie?
SELECT count(*) FROM Staff WHERE first_name = "Ludie";
How many employees have a first name of Ludie?
SELECT count(*) FROM Staff WHERE first_name = "Ludie";
What is the nickname of staff with first name as Janessa and last name as Sawayn?
SELECT nickname FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
What is the nickname of the employee named Janessa Sawayn?
SELECT nickname FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
How many staff in total?
SELECT count(*) FROM Staff;
How many employees are there?
SELECT count(*) FROM Staff;
Which city does staff with first name as Janessa and last name as Sawayn live?
SELECT T1.city FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
In what city does Janessa Sawayn live?
SELECT T1.city FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
Which country and state does staff with first name as Janessa and last name as Sawayn lived?
SELECT T1.country , T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
In which country and state does Janessa Sawayn live?
SELECT T1.country , T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
How long is the total lesson time took by customer with first name as Rylan and last name as Goodwin?
SELECT sum(T1.lesson_time) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin";
How long is the total lesson time took by the customer named Rylan Goodwin?
SELECT sum(T1.lesson_time) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin";
What is the zip code of staff with first name as Janessa and last name as Sawayn lived?
SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
What is the zip code of the hosue of the employee named Janessa Sawayn?
SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
How many staff live in state Georgia?
SELECT count(*) FROM Addresses WHERE state_province_county = "Georgia";
How many employees live in Georgia?
SELECT count(*) FROM Addresses WHERE state_province_county = "Georgia";
Find out the first name and last name of staff lived in city Damianfort.
SELECT T2.first_name , T2.last_name FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T1.city = "Damianfort";
What is the first and last name of all employees who live in the city Damianfort?
SELECT T2.first_name , T2.last_name FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T1.city = "Damianfort";
Which city lives most of staffs? List the city name and number of staffs.
SELECT T1.city , count(*) FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.city ORDER BY count(*) DESC LIMIT 1;
In which city do the most employees live and how many of them live there?
SELECT T1.city , count(*) FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.city ORDER BY count(*) DESC LIMIT 1;
List the states which have between 2 to 4 staffs living there.
SELECT T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.state_province_county HAVING count(*) BETWEEN 2 AND 4;
What are the names of the states that have 2 to 4 employees living there?
SELECT T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.state_province_county HAVING count(*) BETWEEN 2 AND 4;
List the first name and last name of all customers.
SELECT first_name , last_name FROM Customers;
What are the first and last names for all customers?
SELECT first_name , last_name FROM Customers;
List email address and birthday of customer whose first name as Carole.
SELECT email_address , date_of_birth FROM Customers WHERE first_name = "Carole"
What are the email addresses and date of births for all customers who have a first name of Carole?
SELECT email_address , date_of_birth FROM Customers WHERE first_name = "Carole"
List phone number and email address of customer with more than 2000 outstanding balance.
SELECT phone_number , email_address FROM Customers WHERE amount_outstanding > 2000;
What are the phone numbers and email addresses of all customers who have an outstanding balance of more than 2000?
SELECT phone_number , email_address FROM Customers WHERE amount_outstanding > 2000;
What is the status code, mobile phone number and email address of customer with last name as Kohler or first name as Marina?
SELECT customer_status_code , cell_mobile_phone_number , email_address FROM Customers WHERE first_name = "Marina" OR last_name = "Kohler"
What is the status code, phone number, and email address of the customer whose last name is Kohler or whose first name is Marina?
SELECT customer_status_code , cell_mobile_phone_number , email_address FROM Customers WHERE first_name = "Marina" OR last_name = "Kohler"
When are the birthdays of customer who are classified as 'Good Customer' status?
SELECT date_of_birth FROM Customers WHERE customer_status_code = 'Good Customer'
What is the date of birth of every customer whose status code is 'Good Customer'?
SELECT date_of_birth FROM Customers WHERE customer_status_code = 'Good Customer'
When did customer with first name as Carole and last name as Bernhard became a customer?
SELECT date_became_customer FROM Customers WHERE first_name = "Carole" AND last_name = "Bernhard";
When did Carole Bernhard first become a customer?
SELECT date_became_customer FROM Customers WHERE first_name = "Carole" AND last_name = "Bernhard";
How many customers in total?
SELECT count(*) FROM Customers;
How many customers are there?
SELECT count(*) FROM Customers;
List all customer status codes and the number of customers having each status code.
SELECT customer_status_code , count(*) FROM Customers GROUP BY customer_status_code;
For each customer status code, how many customers are classified that way?
SELECT customer_status_code , count(*) FROM Customers GROUP BY customer_status_code;
Which customer status code has least number of customers?
SELECT customer_status_code FROM Customers GROUP BY customer_status_code ORDER BY count(*) ASC LIMIT 1;
What is the status code with the least number of customers?
SELECT customer_status_code FROM Customers GROUP BY customer_status_code ORDER BY count(*) ASC LIMIT 1;
How many lessons taken by customer with first name as Rylan and last name as Goodwin were completed?
SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin" AND T1.lesson_status_code = "Completed";
How many lessons did the customer Ryan Goodwin complete?
SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin" AND T1.lesson_status_code = "Completed";
What is maximum, minimum and average amount of outstanding of customer?
SELECT max(amount_outstanding) , min(amount_outstanding) , avg(amount_outstanding) FROM Customers;
What is the maximum, minimum, and average amount of money outsanding for all customers?
SELECT max(amount_outstanding) , min(amount_outstanding) , avg(amount_outstanding) FROM Customers;
List the first name and last name of customers have the amount of outstanding between 1000 and 3000.
SELECT first_name , last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000;
What are the first and last names of all customers with between 1000 and 3000 dollars outstanding?
SELECT first_name , last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000;
List first name and last name of customers lived in city Lockmanfurt.
SELECT T1.first_name , T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "Lockmanfurt";
What are the first and last names of all customers who lived in Lockmanfurt?
SELECT T1.first_name , T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "Lockmanfurt";
Which country does customer with first name as Carole and last name as Bernhard lived in?
SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
What is the country in which the customer Carole Bernhard lived?
SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
What is zip code of customer with first name as Carole and last name as Bernhard?
SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
What is the zip code of the customer Carole Bernhard?
SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
Which city does has most number of customers?
SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1;
What is the city with the most customers?
SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1;
How much in total does customer with first name as Carole and last name as Bernhard paid?
SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Carole" AND T2.last_name = "Bernhard"
What is the total amount of moeny paid by the customer Carole Bernhard?
SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Carole" AND T2.last_name = "Bernhard"
List the number of customers that did not have any payment history.
SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments );
How many customers have no payment histories?
SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments );
List first name and last name of customers that have more than 2 payments.
SELECT T2.first_name , T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2;
What are the first and last names of all customers with more than 2 payments?
SELECT T2.first_name , T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2;
List all payment methods and number of payments using each payment methods.
SELECT payment_method_code , count(*) FROM Customer_Payments GROUP BY payment_method_code;
For each payment method, how many payments were made?
SELECT payment_method_code , count(*) FROM Customer_Payments GROUP BY payment_method_code;
How many lessons were in cancelled state?
SELECT count(*) FROM Lessons WHERE lesson_status_code = "Cancelled";
How many lessons have been cancelled?
SELECT count(*) FROM Lessons WHERE lesson_status_code = "Cancelled";