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pythondev
help
and that did it
2019-05-07T13:45:55.385800
Holly
pythondev_help_Holly_2019-05-07T13:45:55.385800
1,557,236,755.3858
22,521
pythondev
help
:taco: <@Sasha>
2019-05-07T13:46:01.386000
Holly
pythondev_help_Holly_2019-05-07T13:46:01.386000
1,557,236,761.386
22,522
pythondev
help
tacos for everyone today :slightly_smiling_face:
2019-05-07T13:46:06.386200
Holly
pythondev_help_Holly_2019-05-07T13:46:06.386200
1,557,236,766.3862
22,523
pythondev
help
Has anyone here used the pipeline feature of Heroku with django (and or python)? I am trying to automatically load fixtures in when deploying 'Review Apps'. Basically so i have some testing data and doesn't have to create it every time manually. i would also like to have some helper functionality for staging to flush as well.. not sure how. any clues any one?
2019-05-07T14:44:52.388700
Christina
pythondev_help_Christina_2019-05-07T14:44:52.388700
1,557,240,292.3887
22,524
pythondev
help
it's been a while since I put much effort into that, but you'd want to use a postdeploy script: <https://devcenter.heroku.com/articles/github-integration-review-apps#the-postdeploy-script>
2019-05-07T14:58:24.389900
Joette
pythondev_help_Joette_2019-05-07T14:58:24.389900
1,557,241,104.3899
22,525
pythondev
help
what you need to watch out for is configuration inheritance
2019-05-07T14:59:31.391000
Joette
pythondev_help_Joette_2019-05-07T14:59:31.391000
1,557,241,171.391
22,526
pythondev
help
e.g. if `DATABASE_URL` is inherited from your staging app, then your review app could end up using the staging DB which is _probably_ not what you want
2019-05-07T15:00:05.391800
Joette
pythondev_help_Joette_2019-05-07T15:00:05.391800
1,557,241,205.3918
22,527
pythondev
help
i actually found postdeploy script eventually. sorry i din't see your nice answer <@Joette>. it seems that heroku actually creates a new database instance for each review app
2019-05-07T15:57:55.393000
Christina
pythondev_help_Christina_2019-05-07T15:57:55.393000
1,557,244,675.393
22,528
pythondev
help
yes, the issue is the attached names
2019-05-07T15:58:28.393400
Joette
pythondev_help_Joette_2019-05-07T15:58:28.393400
1,557,244,708.3934
22,529
pythondev
help
oh wait you are correct yes. hmm
2019-05-07T15:58:55.393800
Christina
pythondev_help_Christina_2019-05-07T15:58:55.393800
1,557,244,735.3938
22,530
pythondev
help
do you have any clue of how to fix it. it seems like an issue a lot of people would face. so i use Jaws for my db, but it saves the environment value as 'JAWSDB_URL' but django heroku looks for 'DATABASE_URL' :3
2019-05-07T16:01:25.395100
Christina
pythondev_help_Christina_2019-05-07T16:01:25.395100
1,557,244,885.3951
22,531
pythondev
help
can i create like a relative environment value? is that a thing like DATABASE_URL = $JAWSDB_URL
2019-05-07T16:04:27.395800
Christina
pythondev_help_Christina_2019-05-07T16:04:27.395800
1,557,245,067.3958
22,532
pythondev
help
no, they're values not references - I'd probably look into some kind of conditional logic based on the environment, or fallback on `JAWSDB_URL` in your own app if `DATABASE_URL` is empty/missing
2019-05-07T16:06:14.397000
Joette
pythondev_help_Joette_2019-05-07T16:06:14.397000
1,557,245,174.397
22,533
pythondev
help
yep, i have utility function called `make_database_url` that checks for the `DATABASE_URL` and if it isn’t there builds it.
2019-05-07T16:10:05.399600
Eliana
pythondev_help_Eliana_2019-05-07T16:10:05.399600
1,557,245,405.3996
22,534
pythondev
help
``` def make_database_url(): # Check for DATABASE_URL that is provided by heroku if 'DATABASE_URL' in os.environ and os.environ['DATABASE_URL']: return os.environ.get('DATABASE_URL') else: return 'postgresql+psycopg2://{0}:{1}@{2}:{3}/{4}'.format( os.environ.get('DB_USER', 'postgres'), os.environ.get('DB_PASSWORD', ''), os.environ.get('DB_HOST', '127.0.0.1'), os.environ.get('DB_PORT', '5432'), os.environ.get('DB_NAME', 'postgres'), ) ```
2019-05-07T16:11:25.400200
Eliana
pythondev_help_Eliana_2019-05-07T16:11:25.400200
1,557,245,485.4002
22,535
pythondev
help
I have a big dumb question: what is a *handler* and how does it differ from a *controller* in Rails?
2019-05-07T16:12:13.401300
Ann
pythondev_help_Ann_2019-05-07T16:12:13.401300
1,557,245,533.4013
22,536
pythondev
help
do you use `django_heroku` then? does it check the constant values as well? :slightly_smiling_face:
2019-05-07T16:12:36.401500
Christina
pythondev_help_Christina_2019-05-07T16:12:36.401500
1,557,245,556.4015
22,537
pythondev
help
no i use flask but the concept is the same.
2019-05-07T16:12:53.401700
Eliana
pythondev_help_Eliana_2019-05-07T16:12:53.401700
1,557,245,573.4017
22,538
pythondev
help
oh yeah i see now
2019-05-07T16:13:02.401900
Christina
pythondev_help_Christina_2019-05-07T16:13:02.401900
1,557,245,582.4019
22,539
pythondev
help
django_heroku use `locals()`
2019-05-07T16:13:15.402100
Christina
pythondev_help_Christina_2019-05-07T16:13:15.402100
1,557,245,595.4021
22,540
pythondev
help
what’s the context?
2019-05-07T16:13:41.402600
Hiroko
pythondev_help_Hiroko_2019-05-07T16:13:41.402600
1,557,245,621.4026
22,541
pythondev
help
Writing handlers in Tornado
2019-05-07T16:13:58.402900
Ann
pythondev_help_Ann_2019-05-07T16:13:58.402900
1,557,245,638.4029
22,542
pythondev
help
Is it just a function that "handles" routes, i.e. receives requests and does things based on them, including generating responses?
2019-05-07T16:14:38.403600
Ann
pythondev_help_Ann_2019-05-07T16:14:38.403600
1,557,245,678.4036
22,543
pythondev
help
For extremely specific context, I'm going through a tutorial that contains this code block:
2019-05-07T16:16:28.404000
Ann
pythondev_help_Ann_2019-05-07T16:16:28.404000
1,557,245,788.404
22,544
pythondev
help
```class AltimeterHandler(web.RequestHandler): SUPPORTED_METHODS = ("GET") ALTIMETER_ID = 1 def get(self, id): if int(id) is not self.__class__.ALTIMETER_ID: self.set_status(HTTPStatus.NOT_FOUND) return unit = self.get_arguments('unit') if 'meters' in unit: altitude_multiplier = 0.3048 response_unit = 'meters' else: altitude_multiplier = 1 response_unit = 'feet' print("I've started retrieving the altitude") altitude = round(drone.altimeter.altitude * altitude_multiplier, 4) print("I've finished retrieving the altitude") response = { 'altitude': altitude, 'unit': response_unit} self.set_status(HTTPStatus.OK) self.write(response) ```
2019-05-07T16:16:30.404200
Ann
pythondev_help_Ann_2019-05-07T16:16:30.404200
1,557,245,790.4042
22,545
pythondev
help
Just want to understand what Handler means in this context
2019-05-07T16:16:51.404600
Ann
pythondev_help_Ann_2019-05-07T16:16:51.404600
1,557,245,811.4046
22,546
pythondev
help
seems like they’re pretty similar
2019-05-07T16:18:56.404800
Hiroko
pythondev_help_Hiroko_2019-05-07T16:18:56.404800
1,557,245,936.4048
22,547
pythondev
help
eg, handler in tornado is similar to a view in django/flask and controller in rails
2019-05-07T16:19:14.405600
Hiroko
pythondev_help_Hiroko_2019-05-07T16:19:14.405600
1,557,245,954.4056
22,548
pythondev
help
```A Tornado web application generally consists of one or more RequestHandler subclasses, an Application object which routes incoming requests to handlers```
2019-05-07T16:19:28.405800
Hiroko
pythondev_help_Hiroko_2019-05-07T16:19:28.405800
1,557,245,968.4058
22,549
pythondev
help
:thinking_face: Thanks <@Hiroko>!
2019-05-07T16:52:27.406500
Ann
pythondev_help_Ann_2019-05-07T16:52:27.406500
1,557,247,947.4065
22,550
pythondev
help
I'm kinda stuck. I was trying to write something clean in an excel doc with Openpyxl. in order to shorten my code instead of saying ,
2019-05-07T17:17:25.407900
Walton
pythondev_help_Walton_2019-05-07T17:17:25.407900
1,557,249,445.4079
22,551
pythondev
help
What do you mean by cleaner? The loop looks like covers your needs (unless you need to cover more then one row). I don't exactly understand the significance of the top portion (`sheet['A1'].value == one fish` etc)
2019-05-07T17:22:48.408200
Krista
pythondev_help_Krista_2019-05-07T17:22:48.408200
1,557,249,768.4082
22,552
pythondev
help
Well, with the first four lines, thats me writing every entry manually. with lines 7,8 i'd like it to just take an array of values and write it across the row.
2019-05-07T17:24:11.408400
Walton
pythondev_help_Walton_2019-05-07T17:24:11.408400
1,557,249,851.4084
22,553
pythondev
help
it should give the same result as lines 1-4, but all be done in 2 lines by looping through the array
2019-05-07T17:24:54.408600
Walton
pythondev_help_Walton_2019-05-07T17:24:54.408600
1,557,249,894.4086
22,554
pythondev
help
i'll have to apply a similar logic when I copy a list of results out of one excel document and start writing it to another
2019-05-07T17:26:21.408800
Walton
pythondev_help_Walton_2019-05-07T17:26:21.408800
1,557,249,981.4088
22,555
pythondev
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Ok, I'm with you. Is the data you are writing in each row the same. i.e. are you always writing "one fish" in the first column, "two fish" in the second column, etc.?
2019-05-07T17:28:46.409000
Krista
pythondev_help_Krista_2019-05-07T17:28:46.409000
1,557,250,126.409
22,556
pythondev
help
For this i'm establishing all the headers for Row 1, First Name, Last Name, Organization, Email For the other portions, i'll be importing the columns of data from row 2 to max row.
2019-05-07T17:30:20.409200
Walton
pythondev_help_Walton_2019-05-07T17:30:20.409200
1,557,250,220.4092
22,557
pythondev
help
I just used one fish, two fish as an example
2019-05-07T17:30:32.409400
Walton
pythondev_help_Walton_2019-05-07T17:30:32.409400
1,557,250,232.4094
22,558
pythondev
help
Do you need to write all the imported data using the same code, or is that being handled somewhere else?
2019-05-07T17:32:00.409600
Krista
pythondev_help_Krista_2019-05-07T17:32:00.409600
1,557,250,320.4096
22,559
pythondev
help
I'll do a variation of this solution elsewhere to import the data
2019-05-07T17:33:10.409800
Walton
pythondev_help_Walton_2019-05-07T17:33:10.409800
1,557,250,390.4098
22,560
pythondev
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The most straightfoward way to do this is with a list of lists: `[['one fish', 'two fish', 'red fish', 'blue fish'], ['next rowA', 'next rowB', 'next rowC', 'next rowD'] , etc]`
2019-05-07T17:35:59.410000
Krista
pythondev_help_Krista_2019-05-07T17:35:59.410000
1,557,250,559.41
22,561
pythondev
help
When writing, you will use a nested loop to grab each value that you need,
2019-05-07T17:36:21.410200
Krista
pythondev_help_Krista_2019-05-07T17:36:21.410200
1,557,250,581.4102
22,562
pythondev
help
huh
2019-05-07T17:37:01.410400
Walton
pythondev_help_Walton_2019-05-07T17:37:01.410400
1,557,250,621.4104
22,563
pythondev
help
i mean i get it, it's jsut weird to me.
2019-05-07T17:37:13.410600
Walton
pythondev_help_Walton_2019-05-07T17:37:13.410600
1,557,250,633.4106
22,564
pythondev
help
''' data = [[], []] # the list of lists for row_index in range(0, len(data)): current_row = data[row_index] for column_index in range(0, len(current_row)): data_for_cell = current_row[column_index] # Write the data to the document using row_index and column_index '''
2019-05-07T17:39:03.411000
Krista
pythondev_help_Krista_2019-05-07T17:39:03.411000
1,557,250,743.411
22,565
pythondev
help
Yeah, it can be a little strange, but I don't think there's a more efficient way to handle spreadsheet data
2019-05-07T17:39:37.411200
Krista
pythondev_help_Krista_2019-05-07T17:39:37.411200
1,557,250,777.4112
22,566
pythondev
help
I get no errors witht he logic, but I see no values entered.
2019-05-07T17:46:44.411400
Walton
pythondev_help_Walton_2019-05-07T17:46:44.411400
1,557,251,204.4114
22,567
pythondev
help
I see it says range 0. shouldn't it be 1 for openpyxl?
2019-05-07T17:47:00.411600
Walton
pythondev_help_Walton_2019-05-07T17:47:00.411600
1,557,251,220.4116
22,568
pythondev
help
Probably, based on your example. Things are typically zero-indexed, but they might not be for openpyxl, I've never used the library
2019-05-07T17:51:26.411800
Krista
pythondev_help_Krista_2019-05-07T17:51:26.411800
1,557,251,486.4118
22,569
pythondev
help
And you will need to populate `data` with the actual information you are trying to put in
2019-05-07T17:51:49.412000
Krista
pythondev_help_Krista_2019-05-07T17:51:49.412000
1,557,251,509.412
22,570
pythondev
help
Try ` data = [['one fish', 'two fish', 'red fish', 'blue fish']]` for a POC
2019-05-07T17:52:15.412200
Krista
pythondev_help_Krista_2019-05-07T17:52:15.412200
1,557,251,535.4122
22,571
pythondev
help
oh I did do that
2019-05-07T17:53:43.412400
Walton
pythondev_help_Walton_2019-05-07T17:53:43.412400
1,557,251,623.4124
22,572
pythondev
help
basically I have this: data = [['One Fish'],['Two Fish'],['Red Fish'],['Blue Fish']] # the list of lists for row_index in range(1, len(data)): current_row = data[row_index] for column_index in range(1, len(current_row)): data_for_cell = current_row[column_index] # Write the data to the document using row_index and column_index
2019-05-07T17:54:15.412600
Walton
pythondev_help_Walton_2019-05-07T17:54:15.412600
1,557,251,655.4126
22,573
pythondev
help
You need to change the indexing to `in range(1, len(data)+1)`
2019-05-07T17:57:42.412800
Krista
pythondev_help_Krista_2019-05-07T17:57:42.412800
1,557,251,862.4128
22,574
pythondev
help
The `range` operator assumes zero based indexing as well, my bad, didn't think of that
2019-05-07T17:58:03.413000
Krista
pythondev_help_Krista_2019-05-07T17:58:03.413000
1,557,251,883.413
22,575
pythondev
help
oh, ok lemme try that
2019-05-07T17:58:34.413200
Walton
pythondev_help_Walton_2019-05-07T17:58:34.413200
1,557,251,914.4132
22,576
pythondev
help
Nothing's happening because with the outer loop you are basically saying `for row_index in range(1, 1)` which just exits immediately
2019-05-07T17:58:49.413400
Krista
pythondev_help_Krista_2019-05-07T17:58:49.413400
1,557,251,929.4134
22,577
pythondev
help
Do it with the inner row as well
2019-05-07T17:59:22.413600
Krista
pythondev_help_Krista_2019-05-07T17:59:22.413600
1,557,251,962.4136
22,578
pythondev
help
got an error of : List index out of range
2019-05-07T18:00:44.413800
Walton
pythondev_help_Walton_2019-05-07T18:00:44.413800
1,557,252,044.4138
22,579
pythondev
help
i found an openpyxl doc... but it references something called lista... but openpyxl doesn't know what lista is... and its documentation written by openpyxl
2019-05-07T18:01:43.414000
Walton
pythondev_help_Walton_2019-05-07T18:01:43.414000
1,557,252,103.414
22,580
pythondev
help
Can you show me?
2019-05-07T18:05:02.414200
Krista
pythondev_help_Krista_2019-05-07T18:05:02.414200
1,557,252,302.4142
22,581
pythondev
help
Bottom Example: <http://www.pythonexcel.com/openpyxl-write-to-cell.php>
2019-05-07T18:05:17.414400
Walton
pythondev_help_Walton_2019-05-07T18:05:17.414400
1,557,252,317.4144
22,582
pythondev
help
with that i tried: for i in range (1,4): cellref=exSheet.cell(row=1,column=i) cellref.value=list [data]
2019-05-07T18:05:58.414700
Walton
pythondev_help_Walton_2019-05-07T18:05:58.414700
1,557,252,358.4147
22,583
pythondev
help
sorry...I haven't read the whole conversation here...but I think have you tried creating a list from your values. So `data = ['one fish', 'two fish', 'red fish', 'blue fish']`
2019-05-07T18:06:50.414900
Marth
pythondev_help_Marth_2019-05-07T18:06:50.414900
1,557,252,410.4149
22,584
pythondev
help
then in your for loop doing something like
2019-05-07T18:06:59.415100
Marth
pythondev_help_Marth_2019-05-07T18:06:59.415100
1,557,252,419.4151
22,585
pythondev
help
`Sheet['(row=1, column=headers)'].value = data[header]`
2019-05-07T18:07:23.415300
Marth
pythondev_help_Marth_2019-05-07T18:07:23.415300
1,557,252,443.4153
22,586
pythondev
help
also notice `==` is to check if something equals something you want to use one `=` to set a value
2019-05-07T18:07:53.415500
Marth
pythondev_help_Marth_2019-05-07T18:07:53.415500
1,557,252,473.4155
22,587
pythondev
help
^ Good catch with the `==`
2019-05-07T18:08:08.415700
Krista
pythondev_help_Krista_2019-05-07T18:08:08.415700
1,557,252,488.4157
22,588
pythondev
help
shoot that should be `= data[headers]` with an "s" since that your for iterator
2019-05-07T18:09:14.415900
Marth
pythondev_help_Marth_2019-05-07T18:09:14.415900
1,557,252,554.4159
22,589
pythondev
help
And the `lista` appears to be a variable name in their example, replace it with `data[row_index][column_index]` for your process
2019-05-07T18:09:20.416100
Krista
pythondev_help_Krista_2019-05-07T18:09:20.416100
1,557,252,560.4161
22,590
pythondev
help
hey Dan. all great advice. here is my output with your suggestion though :disappointed: ValueError: (row=1, column=headers) is not a valid coordinate or range
2019-05-07T18:10:58.416300
Walton
pythondev_help_Walton_2019-05-07T18:10:58.416300
1,557,252,658.4163
22,591
pythondev
help
cstarner, going to try that edit
2019-05-07T18:11:07.416500
Walton
pythondev_help_Walton_2019-05-07T18:11:07.416500
1,557,252,667.4165
22,592
pythondev
help
ah...ok, I hadn't checked the syntax, maybe try something like...
2019-05-07T18:12:11.416700
Marth
pythondev_help_Marth_2019-05-07T18:12:11.416700
1,557,252,731.4167
22,593
pythondev
help
also IndexError: list index out of range
2019-05-07T18:12:21.416900
Walton
pythondev_help_Walton_2019-05-07T18:12:21.416900
1,557,252,741.4169
22,594
pythondev
help
data = [['One Fish'],['Two Fish'],['Red Fish'],['Blue Fish']] # the list of lists for row_index in range(0, len(data)): current_row = data[row_index] for column_index in range(0, len(current_row)): column_index_for_write = column_index + 1 row_index_for_write = row_index + 1 data_for_cell = current_row[column_index] # Write the data to the document using row_index_for_write and column_index_for_write
2019-05-07T18:13:15.417100
Krista
pythondev_help_Krista_2019-05-07T18:13:15.417100
1,557,252,795.4171
22,595
pythondev
help
`Sheet.cell(row=1, column=headers).value = data[headers]`
2019-05-07T18:13:16.417300
Marth
pythondev_help_Marth_2019-05-07T18:13:16.417300
1,557,252,796.4173
22,596
pythondev
help
you had `'(row=1, column=headers)'` in single quotes, so python was reading it as a string
2019-05-07T18:13:53.417500
Marth
pythondev_help_Marth_2019-05-07T18:13:53.417500
1,557,252,833.4175
22,597
pythondev
help
without the apostropes I get a syntax error
2019-05-07T18:14:05.417800
Walton
pythondev_help_Walton_2019-05-07T18:14:05.417800
1,557,252,845.4178
22,598
pythondev
help
can you post that line as you now have it written and the entire error
2019-05-07T18:14:56.418000
Marth
pythondev_help_Marth_2019-05-07T18:14:56.418000
1,557,252,896.418
22,599
pythondev
help
I'll also need to look back at some of my code where I used openpyxl...I don't remember using the references that way (but there could easily be more than one way to reference a cell)
2019-05-07T18:15:32.418200
Marth
pythondev_help_Marth_2019-05-07T18:15:32.418200
1,557,252,932.4182
22,600
pythondev
help
&gt;&gt;&gt; for headers in range (1,4): exSheet[(row=1, column=headers)].value = data[headers] SyntaxError: invalid syntax
2019-05-07T18:16:00.418400
Walton
pythondev_help_Walton_2019-05-07T18:16:00.418400
1,557,252,960.4184
22,601
pythondev
help
can you remove the square brackets?
2019-05-07T18:16:35.418600
Marth
pythondev_help_Marth_2019-05-07T18:16:35.418600
1,557,252,995.4186
22,602
pythondev
help
my sheet is called exSheet, as i'll be working with multiple sheets and this is the export sheet of data
2019-05-07T18:16:38.418800
Walton
pythondev_help_Walton_2019-05-07T18:16:38.418800
1,557,252,998.4188
22,603
pythondev
help
that may work
2019-05-07T18:16:47.419000
Walton
pythondev_help_Walton_2019-05-07T18:16:47.419000
1,557,253,007.419
22,604
pythondev
help
TypeError: 'Worksheet' object is not callable
2019-05-07T18:17:26.419200
Walton
pythondev_help_Walton_2019-05-07T18:17:26.419200
1,557,253,046.4192
22,605
pythondev
help
we may need you to post more of your code (like where how your creating the exSheet object, etc. Also, when you post code, can you use the snippet feature (it's under the :heavy_plus_sign: sign to the left of the dialog box where we're typing)
2019-05-07T18:18:59.419400
Marth
pythondev_help_Marth_2019-05-07T18:18:59.419400
1,557,253,139.4194
22,606
pythondev
help
it'll make reading the code easier
2019-05-07T18:19:06.419600
Marth
pythondev_help_Marth_2019-05-07T18:19:06.419600
1,557,253,146.4196
22,607
pythondev
help
you got it
2019-05-07T18:20:08.419800
Walton
pythondev_help_Walton_2019-05-07T18:20:08.419800
1,557,253,208.4198
22,608
pythondev
help
oh shoot....I might be wrong, in threads, code might not be supported
2019-05-07T18:20:19.420000
Marth
pythondev_help_Marth_2019-05-07T18:20:19.420000
1,557,253,219.42
22,609
pythondev
help
just noticed that myself
2019-05-07T18:20:28.420200
Walton
pythondev_help_Walton_2019-05-07T18:20:28.420200
1,557,253,228.4202
22,610
pythondev
help
if not, I'd post the code in the main part of the channel and use the code thing there :slightly_smiling_face:
2019-05-07T18:20:49.420500
Marth
pythondev_help_Marth_2019-05-07T18:20:49.420500
1,557,253,249.4205
22,611
pythondev
help
Code i'm workign on to try and get a list of headers written to Excel via an array
2019-05-07T18:26:02.420700
Walton
pythondev_help_Walton_2019-05-07T18:26:02.420700
1,557,253,562.4207
22,612
pythondev
help
posted
2019-05-07T18:26:05.421000
Walton
pythondev_help_Walton_2019-05-07T18:26:05.421000
1,557,253,565.421
22,613
pythondev
help
4 different attempts
2019-05-07T18:26:12.421200
Walton
pythondev_help_Walton_2019-05-07T18:26:12.421200
1,557,253,572.4212
22,614
pythondev
help
Sorry didn't read the rest of the above chain but ``` #attempt 1 for headers in range (1,4): cellref.value = data[headers] ``` should be: ``` for headers in range(0,4): cellref.value = data[headers][0] ```
2019-05-07T18:30:16.422400
Maricruz
pythondev_help_Maricruz_2019-05-07T18:30:16.422400
1,557,253,816.4224
22,615
pythondev
help
i thought openpyxl doesn't use 0
2019-05-07T18:30:46.423200
Walton
pythondev_help_Walton_2019-05-07T18:30:46.423200
1,557,253,846.4232
22,616
pythondev
help
Although I think you can just write `data` as a regular list rather than a list of lists? `data = ['One Fish', 'Two Fish', etc]`
2019-05-07T18:30:57.423400
Maricruz
pythondev_help_Maricruz_2019-05-07T18:30:57.423400
1,557,253,857.4234
22,617
pythondev
help
yeah I JUST made the change in value for data, and I now get no error, but only thing listed is in A1, and it's Blue Fish
2019-05-07T18:31:44.424700
Walton
pythondev_help_Walton_2019-05-07T18:31:44.424700
1,557,253,904.4247
22,618
pythondev
help
None
2019-05-07T18:32:04.425000
Walton
pythondev_help_Walton_2019-05-07T18:32:04.425000
1,557,253,924.425
22,619
pythondev
help
You need to loop through the row you want your headers in
2019-05-07T18:32:23.425700
Maricruz
pythondev_help_Maricruz_2019-05-07T18:32:23.425700
1,557,253,943.4257
22,620