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pythondev
help
it seems that your editor may treat tabs and spaces the same <@Walton>
2019-05-14T17:48:52.179600
Lawrence
pythondev_help_Lawrence_2019-05-14T17:48:52.179600
1,557,856,132.1796
23,821
pythondev
help
`linter-flake8`?
2019-05-14T17:48:53.179700
Maricruz
pythondev_help_Maricruz_2019-05-14T17:48:53.179700
1,557,856,133.1797
23,822
pythondev
help
yep!
2019-05-14T17:49:09.180000
Lawrence
pythondev_help_Lawrence_2019-05-14T17:49:09.180000
1,557,856,149.18
23,823
pythondev
help
<@Lawrence> thank you :taco:!
2019-05-14T17:49:16.180400
Maricruz
pythondev_help_Maricruz_2019-05-14T17:49:16.180400
1,557,856,156.1804
23,824
pythondev
help
well i'll try it again, but thank you for confirming that my logic was sound
2019-05-14T17:49:22.180500
Walton
pythondev_help_Walton_2019-05-14T17:49:22.180500
1,557,856,162.1805
23,825
pythondev
help
do you use VS Code as your main editor?
2019-05-14T17:49:43.180900
Lawrence
pythondev_help_Lawrence_2019-05-14T17:49:43.180900
1,557,856,183.1809
23,826
pythondev
help
these are some helpful settings for setting tabs to spaces ```// The number of spaces a tab is equal to. "editor.tabSize": 4, // Insert spaces when pressing Tab. "editor.insertSpaces": true, // When opening a file, `editor.tabSize` and `editor.insertSpaces` will be detected based on the file contents. "editor.detectIndentation": true```
2019-05-14T17:50:34.181400
Lawrence
pythondev_help_Lawrence_2019-05-14T17:50:34.181400
1,557,856,234.1814
23,827
pythondev
help
well you were write about the spaces
2019-05-14T18:17:36.181700
Walton
pythondev_help_Walton_2019-05-14T18:17:36.181700
1,557,857,856.1817
23,828
pythondev
help
however it started counting to infinity
2019-05-14T18:17:45.182000
Walton
pythondev_help_Walton_2019-05-14T18:17:45.182000
1,557,857,865.182
23,829
pythondev
help
i'll have to address that tomorrow
2019-05-14T18:18:03.182200
Walton
pythondev_help_Walton_2019-05-14T18:18:03.182200
1,557,857,883.1822
23,830
pythondev
help
i'll add those settings in, thank you for that
2019-05-14T18:18:29.183100
Walton
pythondev_help_Walton_2019-05-14T18:18:29.183100
1,557,857,909.1831
23,831
pythondev
help
I also found it handy to turn on displaying whitespace in vscode (especially if I'm troubleshooting something that seems to be just that). If you File --&gt; Preferences --&gt; Settings (or `CTRL + ,` ) and then search for whitespace, you can change it from `none` (which is default) to `all`
2019-05-14T18:19:39.184300
Marth
pythondev_help_Marth_2019-05-14T18:19:39.184300
1,557,857,979.1843
23,832
pythondev
help
ah, thanks Dan I'll check that out as well
2019-05-14T18:29:13.184700
Walton
pythondev_help_Walton_2019-05-14T18:29:13.184700
1,557,858,553.1847
23,833
pythondev
help
What is the best way to add an image that can be chosen by a novice in tkinter, my idea is to put a thermometer on one side, as a static image and an image of a degree selector that changes the image every time they click
2019-05-14T18:49:41.185800
Melia
pythondev_help_Melia_2019-05-14T18:49:41.185800
1,557,859,781.1858
23,834
pythondev
help
could you elaborate?
2019-05-14T19:17:21.186500
Nenita
pythondev_help_Nenita_2019-05-14T19:17:21.186500
1,557,861,441.1865
23,835
pythondev
help
<@Melia>
2019-05-14T19:18:07.186700
Nenita
pythondev_help_Nenita_2019-05-14T19:18:07.186700
1,557,861,487.1867
23,836
pythondev
help
like just adding an image that the person can actually click on?
2019-05-14T19:18:30.187000
Nenita
pythondev_help_Nenita_2019-05-14T19:18:30.187000
1,557,861,510.187
23,837
pythondev
help
<@Nenita> this image will be static
2019-05-14T19:20:32.187100
Melia
pythondev_help_Melia_2019-05-14T19:20:32.187100
1,557,861,632.1871
23,838
pythondev
help
and this will change
2019-05-14T19:20:55.187400
Melia
pythondev_help_Melia_2019-05-14T19:20:55.187400
1,557,861,655.1874
23,839
pythondev
help
when click i want to change the image and will return de temperture depending if image is C or F
2019-05-14T19:22:18.189600
Melia
pythondev_help_Melia_2019-05-14T19:22:18.189600
1,557,861,738.1896
23,840
pythondev
help
oh i see. Ive only worked with icons when it comes to images in tkinter. but i dont use images in tkinter anymore because sadly when you run/compile-then-run on a computer using pyinstaller or auto py to exe, it will always look for the exact directory the image is in. in otherwords, it doesn't really compile the image into the exe.
2019-05-14T19:23:06.190400
Nenita
pythondev_help_Nenita_2019-05-14T19:23:06.190400
1,557,861,786.1904
23,841
pythondev
help
but as far as what your looking to do
2019-05-14T19:23:12.190700
Nenita
pythondev_help_Nenita_2019-05-14T19:23:12.190700
1,557,861,792.1907
23,842
pythondev
help
you will need to create your image object then bind it using "&lt;&lt;Button-1&gt;&gt;" or something similar
2019-05-14T19:23:34.191300
Nenita
pythondev_help_Nenita_2019-05-14T19:23:34.191300
1,557,861,814.1913
23,843
pythondev
help
I'm going to try, thank you
2019-05-14T19:25:02.191500
Melia
pythondev_help_Melia_2019-05-14T19:25:02.191500
1,557,861,902.1915
23,844
pythondev
help
not sure if there is a hover bind and even searching google right now, it looks like there may not be :shrug:
2019-05-14T19:25:27.192000
Nenita
pythondev_help_Nenita_2019-05-14T19:25:27.192000
1,557,861,927.192
23,845
pythondev
help
here is a good example
2019-05-14T19:26:57.192200
Nenita
pythondev_help_Nenita_2019-05-14T19:26:57.192200
1,557,862,017.1922
23,846
pythondev
help
<https://www.c-sharpcorner.com/blogs/basics-for-displaying-image-in-tkinter-python>
2019-05-14T19:26:59.192400
Nenita
pythondev_help_Nenita_2019-05-14T19:26:59.192400
1,557,862,019.1924
23,847
pythondev
help
then add this
2019-05-14T19:28:34.192700
Nenita
pythondev_help_Nenita_2019-05-14T19:28:34.192700
1,557,862,114.1927
23,848
pythondev
help
if your looking to change those other images, then i suggest making a function that would use attributes based on what is changing those images and then change the images based on those inputed attributes. call that function with the bind line above
2019-05-14T19:31:23.194400
Nenita
pythondev_help_Nenita_2019-05-14T19:31:23.194400
1,557,862,283.1944
23,849
pythondev
help
Hi, is there a faster way of getting a `sqlalchemy` relationship count? ``` from app import db class Account(db.Model): id = db.Column(db.Integer, primary_key=True) email = db.Column(db.String(200), nullable=False) class Address(db.Model): id = db.Column(db.Integer, primary_key=True) account_id = db.Column(db.Integer, db.ForeignKey('account.id'), nullable=False, primary_key=True) account = db.relationship('Account', backref=db.backref('address', lazy=True)) account_list = db.session.query(Account).all() for account in account_list: address_count = len(account.address) ``` I feel like using `len` is not efficient.
2019-05-14T23:34:21.195900
Philip
pythondev_help_Philip_2019-05-14T23:34:21.195900
1,557,876,861.1959
23,850
pythondev
help
<https://docs.sqlalchemy.org/en/13/orm/query.html#sqlalchemy.orm.query.Query.count>
2019-05-14T23:35:39.196100
Chester
pythondev_help_Chester_2019-05-14T23:35:39.196100
1,557,876,939.1961
23,851
pythondev
help
I see, so its much better to do a count query rather than getting the count from the relationship?
2019-05-14T23:36:39.196300
Philip
pythondev_help_Philip_2019-05-14T23:36:39.196300
1,557,876,999.1963
23,852
pythondev
help
A count query is being made on the database side, while `len()` is being made on the client side; the database side is more performant, as usual
2019-05-14T23:37:24.196500
Chester
pythondev_help_Chester_2019-05-14T23:37:24.196500
1,557,877,044.1965
23,853
pythondev
help
Noted, thank you <@Chester> ! :taco:
2019-05-14T23:38:22.196700
Philip
pythondev_help_Philip_2019-05-14T23:38:22.196700
1,557,877,102.1967
23,854
pythondev
help
```TypeError: the JSON object must be str, bytes or bytearray, not dict```
2019-05-14T23:40:37.197200
Conchita
pythondev_help_Conchita_2019-05-14T23:40:37.197200
1,557,877,237.1972
23,855
pythondev
help
&gt; `request_json = request.get_json(silent=True)` This already returns a parsed dictionary, you don't need to `json.loads` it again
2019-05-14T23:41:56.198400
Chester
pythondev_help_Chester_2019-05-14T23:41:56.198400
1,557,877,316.1984
23,856
pythondev
help
Aha - so this is simply fixed by removing `obj = json.loads(request_json)`?
2019-05-14T23:42:29.199000
Conchita
pythondev_help_Conchita_2019-05-14T23:42:29.199000
1,557,877,349.199
23,857
pythondev
help
And `targets = request_json['targets']`?
2019-05-14T23:43:28.199900
Conchita
pythondev_help_Conchita_2019-05-14T23:43:28.199900
1,557,877,408.1999
23,858
pythondev
help
Yes, it should work
2019-05-14T23:44:34.200200
Chester
pythondev_help_Chester_2019-05-14T23:44:34.200200
1,557,877,474.2002
23,859
pythondev
help
Try it
2019-05-14T23:44:36.200400
Chester
pythondev_help_Chester_2019-05-14T23:44:36.200400
1,557,877,476.2004
23,860
pythondev
help
Tested, works!
2019-05-14T23:46:29.200600
Conchita
pythondev_help_Conchita_2019-05-14T23:46:29.200600
1,557,877,589.2006
23,861
pythondev
help
Thanks <@Chester> :taco:
2019-05-14T23:46:40.200900
Conchita
pythondev_help_Conchita_2019-05-14T23:46:40.200900
1,557,877,600.2009
23,862
pythondev
help
Yes, I have two cluster hosted on different server, i want to call a service from cluster1 in cluster2.
2019-05-15T02:46:09.201500
Darcie
pythondev_help_Darcie_2019-05-15T02:46:09.201500
1,557,888,369.2015
23,863
pythondev
help
Could anyone recommend a library for auto retrying aiohttp requests?
2019-05-15T04:46:31.202400
Pura
pythondev_help_Pura_2019-05-15T04:46:31.202400
1,557,895,591.2024
23,864
pythondev
help
could just wrap it in a try / catch and a while
2019-05-15T05:01:59.202800
Mica
pythondev_help_Mica_2019-05-15T05:01:59.202800
1,557,896,519.2028
23,865
pythondev
help
None
2019-05-15T05:04:06.202900
Mica
pythondev_help_Mica_2019-05-15T05:04:06.202900
1,557,896,646.2029
23,866
pythondev
help
that should work i think?
2019-05-15T05:04:16.203300
Mica
pythondev_help_Mica_2019-05-15T05:04:16.203300
1,557,896,656.2033
23,867
pythondev
help
then you could create a decorator from it
2019-05-15T05:04:22.203500
Mica
pythondev_help_Mica_2019-05-15T05:04:22.203500
1,557,896,662.2035
23,868
pythondev
help
I just committed to git, but I can't see my master branch. What should I do?
2019-05-15T06:14:29.204200
Javier
pythondev_help_Javier_2019-05-15T06:14:29.204200
1,557,900,869.2042
23,869
pythondev
help
That's very useful
2019-05-15T06:16:35.204300
Valeri
pythondev_help_Valeri_2019-05-15T06:16:35.204300
1,557,900,995.2043
23,870
pythondev
help
Thanks <@Neely> :taco:
2019-05-15T06:16:42.204500
Valeri
pythondev_help_Valeri_2019-05-15T06:16:42.204500
1,557,901,002.2045
23,871
pythondev
help
Did you push to `remote` after commiting?
2019-05-15T06:20:42.205700
Madonna
pythondev_help_Madonna_2019-05-15T06:20:42.205700
1,557,901,242.2057
23,872
pythondev
help
no
2019-05-15T06:22:50.206300
Javier
pythondev_help_Javier_2019-05-15T06:22:50.206300
1,557,901,370.2063
23,873
pythondev
help
<@Madonna> :taco:
2019-05-15T06:23:10.206600
Javier
pythondev_help_Javier_2019-05-15T06:23:10.206600
1,557,901,390.2066
23,874
pythondev
help
thanks i was looking for a library that had some backoff strategy implemented
2019-05-15T07:39:52.207500
Pura
pythondev_help_Pura_2019-05-15T07:39:52.207500
1,557,905,992.2075
23,875
pythondev
help
ah right, not too sure :confused:
2019-05-15T08:06:57.207700
Mica
pythondev_help_Mica_2019-05-15T08:06:57.207700
1,557,907,617.2077
23,876
pythondev
help
def requests_retry_session( retries=3, backoff_factor=0.3, status_forcelist=(500, 502, 504), session=None, :disappointed: session = session or requests.Session() retry = Retry( total=retries, read=retries, connect=retries, backoff_factor=backoff_factor, status_forcelist=status_forcelist, ) adapter = HTTPAdapter(max_retries=retry) session.mount('http://', adapter) session.mount('https://', adapter) return session
2019-05-15T08:08:03.208100
Harley
pythondev_help_Harley_2019-05-15T08:08:03.208100
1,557,907,683.2081
23,877
pythondev
help
I am using this HTTP request Adapter to try when i have got 5XX errors from requests library
2019-05-15T08:08:37.208800
Harley
pythondev_help_Harley_2019-05-15T08:08:37.208800
1,557,907,717.2088
23,878
pythondev
help
None
2019-05-15T08:09:31.208900
Harley
pythondev_help_Harley_2019-05-15T08:09:31.208900
1,557,907,771.2089
23,879
pythondev
help
I have using this HTTPAdaptor to getting from HTTPS endpoint using requests_retry_session <http://function.It|function.It> works well ben when i want to getting 5XX error when i remove http rule at ELB Security Group from backend.I can not get any timeout or connection error exception.
2019-05-15T08:12:30.209300
Harley
pythondev_help_Harley_2019-05-15T08:12:30.209300
1,557,907,950.2093
23,880
pythondev
help
Why I can not getting any exception when i break communication between this lambda function and backend endpoint
2019-05-15T08:13:11.210400
Harley
pythondev_help_Harley_2019-05-15T08:13:11.210400
1,557,907,991.2104
23,881
pythondev
help
your question is quite unclear
2019-05-15T08:14:01.210600
Jonas
pythondev_help_Jonas_2019-05-15T08:14:01.210600
1,557,908,041.2106
23,882
pythondev
help
are you saying that there is no exception thrown, *and* no response returned? How can this be true?
2019-05-15T08:14:16.211000
Jonas
pythondev_help_Jonas_2019-05-15T08:14:16.211000
1,557,908,056.211
23,883
pythondev
help
are you saying that it will just hang forever?
2019-05-15T08:14:28.211600
Jonas
pythondev_help_Jonas_2019-05-15T08:14:28.211600
1,557,908,068.2116
23,884
pythondev
help
Sorry i think i paste wrong code.Yes exactly when i append my code with try except block but although there has been occured connection error between lambda and backend http endpoint the code did not raise an exception and getting lambda execution timeout (60 second)
2019-05-15T08:17:13.214100
Harley
pythondev_help_Harley_2019-05-15T08:17:13.214100
1,557,908,233.2141
23,885
pythondev
help
I write correct code block again now
2019-05-15T08:17:21.214400
Harley
pythondev_help_Harley_2019-05-15T08:17:21.214400
1,557,908,241.2144
23,886
pythondev
help
None
2019-05-15T08:17:57.214500
Harley
pythondev_help_Harley_2019-05-15T08:17:57.214500
1,557,908,277.2145
23,887
pythondev
help
None
2019-05-15T08:18:26.214800
Harley
pythondev_help_Harley_2019-05-15T08:18:26.214800
1,557,908,306.2148
23,888
pythondev
help
The below execption block do not raise any exception when i remove SG rule between lambda and backend API so lambda execute code and goes down to the lambda timeout without any exeception.I have increase lambda timeout value from 60 to 600 step by step each test but everytime i have got only lambda timeout so it did not hang and raise any exception.
2019-05-15T08:33:16.218200
Harley
pythondev_help_Harley_2019-05-15T08:33:16.218200
1,557,909,196.2182
23,889
pythondev
help
Is it possible to use list comprehension to "extend" a list during creation? Something like: ``` a_list = ['three', 'four'] awesome_list = ['one', 'two', x for x in a_list] ```
2019-05-15T09:04:35.219600
Jolynn
pythondev_help_Jolynn_2019-05-15T09:04:35.219600
1,557,911,075.2196
23,890
pythondev
help
Such that `awesome_list == ['one', 'two', 'three', 'four']`
2019-05-15T09:05:06.220300
Jolynn
pythondev_help_Jolynn_2019-05-15T09:05:06.220300
1,557,911,106.2203
23,891
pythondev
help
``` &gt;&gt;&gt; a_list = ['three', 'four'] &gt;&gt;&gt; awesome_list = ['one', 'two', *[x for x in a_list]] &gt;&gt;&gt; awesome_list ['one', 'two', 'three', 'four'] ```
2019-05-15T09:08:59.220500
Chester
pythondev_help_Chester_2019-05-15T09:08:59.220500
1,557,911,339.2205
23,892
pythondev
help
``` &gt;&gt;&gt; ['one', 'two'] + [x for x in a_list] ['one', 'two', 'three', 'four'] ``` works too
2019-05-15T09:09:35.220800
Chester
pythondev_help_Chester_2019-05-15T09:09:35.220800
1,557,911,375.2208
23,893
pythondev
help
Does anyone have any info about the memory cost of `print()` vs using `logging` module? I have a project with TONS of `print()` calls, and wondering if switching to `logging` will reduce the overall memory footprint of the program.
2019-05-15T09:36:53.222100
Clarita
pythondev_help_Clarita_2019-05-15T09:36:53.222100
1,557,913,013.2221
23,894
pythondev
help
if anything, I think logging would be much more flexible
2019-05-15T09:41:28.222500
Hiroko
pythondev_help_Hiroko_2019-05-15T09:41:28.222500
1,557,913,288.2225
23,895
pythondev
help
because you can then route your log output to a handler which can execute different things
2019-05-15T09:41:42.222900
Hiroko
pythondev_help_Hiroko_2019-05-15T09:41:42.222900
1,557,913,302.2229
23,896
pythondev
help
eg, send an email with too many ERRORs occurring
2019-05-15T09:41:56.223200
Hiroko
pythondev_help_Hiroko_2019-05-15T09:41:56.223200
1,557,913,316.2232
23,897
pythondev
help
post to a log aggregator
2019-05-15T09:42:01.223400
Hiroko
pythondev_help_Hiroko_2019-05-15T09:42:01.223400
1,557,913,321.2234
23,898
pythondev
help
etc
2019-05-15T09:42:03.223600
Hiroko
pythondev_help_Hiroko_2019-05-15T09:42:03.223600
1,557,913,323.2236
23,899
pythondev
help
in other words, <@Clarita> I would kill print in favor of logging just because
2019-05-15T09:42:33.224300
Hiroko
pythondev_help_Hiroko_2019-05-15T09:42:33.224300
1,557,913,353.2243
23,900
pythondev
help
using lots of print statements over logging in a project is a major code smell to me
2019-05-15T09:42:51.224900
Hiroko
pythondev_help_Hiroko_2019-05-15T09:42:51.224900
1,557,913,371.2249
23,901
pythondev
help
undoubtedly logging is superior for flexibility, can’t argue that. but i’m trying to reduce memory use first and foremost, and since I don’t really know the internals of `print` just wondering if it is somehow a very costly process
2019-05-15T09:44:53.226700
Clarita
pythondev_help_Clarita_2019-05-15T09:44:53.226700
1,557,913,493.2267
23,902
pythondev
help
print uses the OS system calls, IIRC
2019-05-15T09:45:18.227300
Hiroko
pythondev_help_Hiroko_2019-05-15T09:45:18.227300
1,557,913,518.2273
23,903
pythondev
help
so its pretty low level
2019-05-15T09:45:24.227600
Hiroko
pythondev_help_Hiroko_2019-05-15T09:45:24.227600
1,557,913,524.2276
23,904
pythondev
help
certainly in terms of time print is killing our program
2019-05-15T09:45:33.227900
Clarita
pythondev_help_Clarita_2019-05-15T09:45:33.227900
1,557,913,533.2279
23,905
pythondev
help
FWIW, you really should be using levels in output
2019-05-15T09:45:47.228400
Hiroko
pythondev_help_Hiroko_2019-05-15T09:45:47.228400
1,557,913,547.2284
23,906
pythondev
help
eg, INFO, WARN, ERROR, DEBUG
2019-05-15T09:45:53.228800
Hiroko
pythondev_help_Hiroko_2019-05-15T09:45:53.228800
1,557,913,553.2288
23,907
pythondev
help
sounds like lots of your output is debug and could be avoided with proper logging levels
2019-05-15T09:46:14.229300
Hiroko
pythondev_help_Hiroko_2019-05-15T09:46:14.229300
1,557,913,574.2293
23,908
pythondev
help
eg, you want one env to have debug output, but not another. just change the log level in the env config
2019-05-15T09:46:34.230100
Hiroko
pythondev_help_Hiroko_2019-05-15T09:46:34.230100
1,557,913,594.2301
23,909
pythondev
help
thanks <@Hiroko>, unfortunately I work with a bunch of non-engineers who built this code base who didn’t about logging, and this is what I’m working with now :disappointed:
2019-05-15T09:47:48.231100
Clarita
pythondev_help_Clarita_2019-05-15T09:47:48.231100
1,557,913,668.2311
23,910
pythondev
help
gotcha
2019-05-15T09:48:59.231300
Hiroko
pythondev_help_Hiroko_2019-05-15T09:48:59.231300
1,557,913,739.2313
23,911
pythondev
help
you have my sympathies :slightly_smiling_face:
2019-05-15T09:49:09.231700
Hiroko
pythondev_help_Hiroko_2019-05-15T09:49:09.231700
1,557,913,749.2317
23,912
pythondev
help
and re: logging. I can’t recall if you have log level set to ERROR will a statement like `<http://logging.INFO|logging.INFO>(f'{calculate_string()}')` actually execute and compile that string and not print it? or does it skip the entire line like a no-op?
2019-05-15T09:55:50.233400
Clarita
pythondev_help_Clarita_2019-05-15T09:55:50.233400
1,557,914,150.2334
23,913
pythondev
help
logging is a heriarchy
2019-05-15T09:57:09.233700
Hiroko
pythondev_help_Hiroko_2019-05-15T09:57:09.233700
1,557,914,229.2337
23,914
pythondev
help
if you just wanted to test the effect, you could assign like `<http://logging.info|logging.info>` to `print` globally and run your application and observe the difference
2019-05-15T09:58:09.234500
Karoline
pythondev_help_Karoline_2019-05-15T09:58:09.234500
1,557,914,289.2345
23,915
pythondev
help
I'd be shocked if it really made a noticeable difference but maybe in some tight loops.
2019-05-15T09:58:26.235000
Karoline
pythondev_help_Karoline_2019-05-15T09:58:26.235000
1,557,914,306.235
23,916
pythondev
help
ahhhhh that’s brilliant. I’ll try this
2019-05-15T09:58:38.235100
Clarita
pythondev_help_Clarita_2019-05-15T09:58:38.235100
1,557,914,318.2351
23,917
pythondev
help
Thank you!
2019-05-15T10:02:26.235800
Jolynn
pythondev_help_Jolynn_2019-05-15T10:02:26.235800
1,557,914,546.2358
23,918
pythondev
help
hey guys, supposed I have a list of datetime.times... ``` times = ['9:00', '9:30', '9:45', '10:15', '10:30', '10:30'] ``` and I want to sort them into buckets 9:00-10:00 and 10:00-11:00. Is there a cleaner/more pythonic way to do this than: ``` time_9am = [] time_10am = [] for a_time in times: if a_time &gt;= '9:00' and a_time &lt; '10:00': time_9am.append(a_time) elif a_time &gt;= '10:00' and a_time &lt; '11:00': time_10am.append(a_time) ```
2019-05-15T11:28:34.239100
Magdalena
pythondev_help_Magdalena_2019-05-15T11:28:34.239100
1,557,919,714.2391
23,919
pythondev
help
you can bucket them by the value in `x.split(':')[0]` which will give you the hour portion of each string
2019-05-15T11:30:46.240700
Clemmie
pythondev_help_Clemmie_2019-05-15T11:30:46.240700
1,557,919,846.2407
23,920