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pythondev
help
ahhh, thank you <@Carlo>
2019-04-01T15:49:52.017400
Virgie
pythondev_help_Virgie_2019-04-01T15:49:52.017400
1,554,133,792.0174
16,321
pythondev
help
I have some json-formatted data within a non-json file (there are other ascii content within). I’m trying to parse out the json content with python’s regular expressions. essentially, we have nested data, and I’m trying to simply matches braces over multiple lines.
2019-04-01T15:51:18.018900
Virgie
pythondev_help_Virgie_2019-04-01T15:51:18.018900
1,554,133,878.0189
16,322
pythondev
help
for instance:
2019-04-01T15:51:24.019100
Virgie
pythondev_help_Virgie_2019-04-01T15:51:24.019100
1,554,133,884.0191
16,323
pythondev
help
`{ ‘data’: [ ‘example’, ‘example’ ] }`
2019-04-01T15:52:25.020100
Virgie
pythondev_help_Virgie_2019-04-01T15:52:25.020100
1,554,133,945.0201
16,324
pythondev
help
why do you have a mixed-format file?
2019-04-01T15:52:55.020900
Hiroko
pythondev_help_Hiroko_2019-04-01T15:52:55.020900
1,554,133,975.0209
16,325
pythondev
help
it’s a malware config file
2019-04-01T15:53:05.021300
Virgie
pythondev_help_Virgie_2019-04-01T15:53:05.021300
1,554,133,985.0213
16,326
pythondev
help
I’ve used the `re.S` flag to match the newline character, but it still doesn’t seem to work
2019-04-01T15:53:59.022200
Virgie
pythondev_help_Virgie_2019-04-01T15:53:59.022200
1,554,134,039.0222
16,327
pythondev
help
<@Sasha> no, and i did get it figured out. by your response, it confirmed my resolution. because i have no __init__, im having to declare (at least for the moment) my class.
2019-04-01T15:56:08.024000
Nenita
pythondev_help_Nenita_2019-04-01T15:56:08.024000
1,554,134,168.024
16,328
pythondev
help
HELLO!&gt;?!?&gt;!?!
2019-04-01T15:56:26.024500
Claudine
pythondev_help_Claudine_2019-04-01T15:56:26.024500
1,554,134,186.0245
16,329
pythondev
help
there are only two braces in the file, but `re.search('\{.*\}', file, re.S).group(0)` doesn’t seem to work.
2019-04-01T15:56:30.024700
Virgie
pythondev_help_Virgie_2019-04-01T15:56:30.024700
1,554,134,190.0247
16,330
pythondev
help
<@Claudine> :wave:
2019-04-01T15:56:53.025100
Nenita
pythondev_help_Nenita_2019-04-01T15:56:53.025100
1,554,134,213.0251
16,331
pythondev
help
does `re.MULTILINE` do anything for you instead of `re.S`?
2019-04-01T15:57:27.025600
Claudine
pythondev_help_Claudine_2019-04-01T15:57:27.025600
1,554,134,247.0256
16,332
pythondev
help
unfortunately not. I tried that, and both ( `re.M | re.S` ), and neither worked
2019-04-01T15:58:06.026200
Virgie
pythondev_help_Virgie_2019-04-01T15:58:06.026200
1,554,134,286.0262
16,333
pythondev
help
`\{.*|\n\}` that do anything for ya?
2019-04-01T15:58:55.026400
Claudine
pythondev_help_Claudine_2019-04-01T15:58:55.026400
1,554,134,335.0264
16,334
pythondev
help
negative =/
2019-04-01T16:01:03.026600
Virgie
pythondev_help_Virgie_2019-04-01T16:01:03.026600
1,554,134,463.0266
16,335
pythondev
help
Do you need a raw string for the backslashes?
2019-04-01T16:02:12.027000
Sasha
pythondev_help_Sasha_2019-04-01T16:02:12.027000
1,554,134,532.027
16,336
pythondev
help
how about this bad larry? `{[^}]*`
2019-04-01T16:03:25.027300
Claudine
pythondev_help_Claudine_2019-04-01T16:03:25.027300
1,554,134,605.0273
16,337
pythondev
help
that should match an opening brace, and then everything else that is not a closing brace
2019-04-01T16:03:56.027700
Claudine
pythondev_help_Claudine_2019-04-01T16:03:56.027700
1,554,134,636.0277
16,338
pythondev
help
if there is a stray closing brace in your file it will jack up the regex
2019-04-01T16:04:06.028000
Claudine
pythondev_help_Claudine_2019-04-01T16:04:06.028000
1,554,134,646.028
16,339
pythondev
help
you can pop an extra `}` on the end if you want to capture the braces
2019-04-01T16:04:57.028400
Claudine
pythondev_help_Claudine_2019-04-01T16:04:57.028400
1,554,134,697.0284
16,340
pythondev
help
*hungrily awaits taco*
2019-04-01T16:05:46.028700
Claudine
pythondev_help_Claudine_2019-04-01T16:05:46.028700
1,554,134,746.0287
16,341
pythondev
help
here you are, sir
2019-04-01T16:06:14.029000
Virgie
pythondev_help_Virgie_2019-04-01T16:06:14.029000
1,554,134,774.029
16,342
pythondev
help
that worked! :raised_hands:
2019-04-01T16:06:44.029600
Virgie
pythondev_help_Virgie_2019-04-01T16:06:44.029600
1,554,134,804.0296
16,343
pythondev
help
dope
2019-04-01T16:06:47.029800
Claudine
pythondev_help_Claudine_2019-04-01T16:06:47.029800
1,554,134,807.0298
16,344
pythondev
help
actually if you wanna type `@kraete :taco:` for me that'd be squanchy
2019-04-01T16:07:05.030400
Claudine
pythondev_help_Claudine_2019-04-01T16:07:05.030400
1,554,134,825.0304
16,345
pythondev
help
`squanchy`
2019-04-01T16:07:20.031100
Hiroko
pythondev_help_Hiroko_2019-04-01T16:07:20.031100
1,554,134,840.0311
16,346
pythondev
help
it'll give me a taco credit, there's a taco bot
2019-04-01T16:07:27.031500
Claudine
pythondev_help_Claudine_2019-04-01T16:07:27.031500
1,554,134,847.0315
16,347
pythondev
help
`re.search('{[^}]*', file, re.M).group(0)` was the query, for anyone else wondering
2019-04-01T16:07:37.031800
Virgie
pythondev_help_Virgie_2019-04-01T16:07:37.031800
1,554,134,857.0318
16,348
pythondev
help
<@Claudine> :taco:
2019-04-01T16:07:59.032200
Virgie
pythondev_help_Virgie_2019-04-01T16:07:59.032200
1,554,134,879.0322
16,349
pythondev
help
perfect thanks
2019-04-01T16:08:10.032600
Claudine
pythondev_help_Claudine_2019-04-01T16:08:10.032600
1,554,134,890.0326
16,350
pythondev
help
I’ll squanch a taco at yu any time. much appreciated!
2019-04-01T16:08:18.032900
Virgie
pythondev_help_Virgie_2019-04-01T16:08:18.032900
1,554,134,898.0329
16,351
pythondev
help
i'll squanch your regexes anytime, you're quite welcome
2019-04-01T16:08:32.033200
Claudine
pythondev_help_Claudine_2019-04-01T16:08:32.033200
1,554,134,912.0332
16,352
pythondev
help
actually, if you don’t quite mind helping me understand that regex you gave me…
2019-04-01T16:09:02.033600
Virgie
pythondev_help_Virgie_2019-04-01T16:09:02.033600
1,554,134,942.0336
16,353
pythondev
help
sure
2019-04-01T16:09:36.033800
Claudine
pythondev_help_Claudine_2019-04-01T16:09:36.033800
1,554,134,976.0338
16,354
pythondev
help
`{[^}]*` the first character is `{`, so that will match your opening curly brace this is followed by a character group `[]`, but those `[` `]` have things inside them the things inside are `^}`, inside a character group `^` is a negation and `}` is the character being negating, so this character group matches any character that is not a `}` (including newlines) and then we have `*` at the end, which means match as many of the previous negation as possible
2019-04-01T16:11:32.036100
Claudine
pythondev_help_Claudine_2019-04-01T16:11:32.036100
1,554,135,092.0361
16,355
pythondev
help
then eventually we hit your closing `}` which terminations the previous matchy bit there
2019-04-01T16:11:52.036600
Claudine
pythondev_help_Claudine_2019-04-01T16:11:52.036600
1,554,135,112.0366
16,356
pythondev
help
so like `[a]` will match one lower case `a` [^a]` will match anything that isn't a lowercase `a`
2019-04-01T16:12:35.037500
Claudine
pythondev_help_Claudine_2019-04-01T16:12:35.037500
1,554,135,155.0375
16,357
pythondev
help
ahhh, okay. dsylexia makes regex a headache to read correctly :facepalm:
2019-04-01T16:12:43.037900
Virgie
pythondev_help_Virgie_2019-04-01T16:12:43.037900
1,554,135,163.0379
16,358
pythondev
help
if you wanted to match anything that is not a digit you could do `[^0-9]`
2019-04-01T16:12:52.038200
Claudine
pythondev_help_Claudine_2019-04-01T16:12:52.038200
1,554,135,172.0382
16,359
pythondev
help
haha yea i could see that making it much harder than it already is
2019-04-01T16:13:13.038900
Claudine
pythondev_help_Claudine_2019-04-01T16:13:13.038900
1,554,135,193.0389
16,360
pythondev
help
I was reading the braces and brackets as their actual regex interpretations for grouping, instead of their literals
2019-04-01T16:13:16.039100
Virgie
pythondev_help_Virgie_2019-04-01T16:13:16.039100
1,554,135,196.0391
16,361
pythondev
help
ahh yea that can get dicey
2019-04-01T16:13:38.039400
Claudine
pythondev_help_Claudine_2019-04-01T16:13:38.039400
1,554,135,218.0394
16,362
pythondev
help
oh well. that’s cleared up, so another is in order
2019-04-01T16:14:03.039900
Virgie
pythondev_help_Virgie_2019-04-01T16:14:03.039900
1,554,135,243.0399
16,363
pythondev
help
<@Claudine> :taco:
2019-04-01T16:14:12.040200
Virgie
pythondev_help_Virgie_2019-04-01T16:14:12.040200
1,554,135,252.0402
16,364
pythondev
help
thanks again! very clever regex :wink:
2019-04-01T16:15:42.040600
Virgie
pythondev_help_Virgie_2019-04-01T16:15:42.040600
1,554,135,342.0406
16,365
pythondev
help
no problem! the only thing i'd be worried about is if the contents of your file happens to have another `}` somewhere in it because it'd cut the match of there
2019-04-01T16:16:34.041400
Claudine
pythondev_help_Claudine_2019-04-01T16:16:34.041400
1,554,135,394.0414
16,366
pythondev
help
it’s unlikely, but certainly possible. it’ll be noticeable if it does, and I’ll address it then.
2019-04-01T16:17:45.042000
Virgie
pythondev_help_Virgie_2019-04-01T16:17:45.042000
1,554,135,465.042
16,367
pythondev
help
Hey all, I'm having issues with handling csv files. the problem is that the delimiter and the lineterminator uses the same character(';'). I'm using the lineterminator argument from pandas.to_csv to append the rows with a ';'. This is done so that the column count of two files are equal(one was missing ; at the end and therefore didn't count as column)
2019-04-01T17:19:12.045300
Kathline
pythondev_help_Kathline_2019-04-01T17:19:12.045300
1,554,139,152.0453
16,368
pythondev
help
Do you know ahead of time the number of columns?
2019-04-01T17:20:07.046700
Bethany
pythondev_help_Bethany_2019-04-01T17:20:07.046700
1,554,139,207.0467
16,369
pythondev
help
yes
2019-04-01T17:20:12.047000
Kathline
pythondev_help_Kathline_2019-04-01T17:20:12.047000
1,554,139,212.047
16,370
pythondev
help
You could split on `;` and reshape the resulting list since you know what the shape should be
2019-04-01T17:21:37.048200
Bethany
pythondev_help_Bethany_2019-04-01T17:21:37.048200
1,554,139,297.0482
16,371
pythondev
help
But there's no line ending character `\n`?
2019-04-01T17:22:17.049100
Bethany
pythondev_help_Bethany_2019-04-01T17:22:17.049100
1,554,139,337.0491
16,372
pythondev
help
alright, thanks I will look into that. there isn't a line ending character as it's a excel file converted into a csv using pandas(it looked easier to use and flexible)
2019-04-01T17:24:44.051500
Kathline
pythondev_help_Kathline_2019-04-01T17:24:44.051500
1,554,139,484.0515
16,373
pythondev
help
In the original `to_csv()`, can you use `";\n"` as the line terminator?
2019-04-01T17:25:31.052400
Sasha
pythondev_help_Sasha_2019-04-01T17:25:31.052400
1,554,139,531.0524
16,374
pythondev
help
<@Sasha>, <@Bethany>. ':\n' worked, didn't know you could use regex as line terminator. Thank you :smile:
2019-04-01T17:29:45.053700
Kathline
pythondev_help_Kathline_2019-04-01T17:29:45.053700
1,554,139,785.0537
16,375
pythondev
help
It's not a regex, just a multi-character string.
2019-04-01T17:30:11.054000
Sasha
pythondev_help_Sasha_2019-04-01T17:30:11.054000
1,554,139,811.054
16,376
pythondev
help
HELLO!?!?!?
2019-04-01T17:32:10.054400
Claudine
pythondev_help_Claudine_2019-04-01T17:32:10.054400
1,554,139,930.0544
16,377
pythondev
help
Hello
2019-04-01T17:32:18.054800
Genesis
pythondev_help_Genesis_2019-04-01T17:32:18.054800
1,554,139,938.0548
16,378
pythondev
help
False alarm, sorry <@Claudine>
2019-04-01T17:32:42.055400
Sasha
pythondev_help_Sasha_2019-04-01T17:32:42.055400
1,554,139,962.0554
16,379
pythondev
help
Haha no worries
2019-04-01T17:41:37.055900
Claudine
pythondev_help_Claudine_2019-04-01T17:41:37.055900
1,554,140,497.0559
16,380
pythondev
help
:joy: The amount I laughed at that says a lot about me
2019-04-01T20:09:20.058300
Clemmie
pythondev_help_Clemmie_2019-04-01T20:09:20.058300
1,554,149,360.0583
16,381
pythondev
help
note - excel new lines are either `\r\n` or `\n\r` i cant remember which order - but those 2 together make a hard csv new line row in weird cases i have also seen `\m` which is damn near invisible unless you view it on terminal lol and has been known to throw wrenches on occasion :face_with_rolling_eyes:
2019-04-01T20:10:50.058800
Sparkle
pythondev_help_Sparkle_2019-04-01T20:10:50.058800
1,554,149,450.0588
16,382
pythondev
help
Hello. I have a list that contains data like this: ``` [{'broker': 0, 'leader': True, 'in_sync': True}, {'broker': 1, 'leader': False, 'in_sync': True}] [{'broker': 1, 'leader': True, 'in_sync': True}, {'broker': 2, 'leader': False, 'in_sync': True}] [{'broker': 2, 'leader': True, 'in_sync': True}, {'broker': 0, 'leader': False, 'in_sync': True}] ``` That data above is generated by this: `broker = [ x[i]['broker'] for x in lc_replicas ]` My output code is like so: ``` lc_partitions = [ p['partition'] for p in output['partitions'] ] lc_leader = [ l['leader'] for l in output['partitions'] ] lc_replicas = [ r['replicas'] for r in output['partitions'] ] for i in range(slice): print(i) broker = [ x[i]['broker'] for x in lc_replicas ] leader = [ x[i]['leader'] for x in lc_replicas ] in_sync = [ x[i]['in_sync'] for x in lc_replicas ] for lc_p,lc_l,b,l,i in zip(lc_partitions, lc_leader, broker, leader, in_sync): print('Partitions: Partition - {0} Leader - {1} Replicas: Broker - {2} Leader - {3} In_Sync - {4}'.format(lc_p, lc_l, b, l, i)) ``` The issue is that it prints the formatted data for each loop, when I only want to print part of the output once, and concatenate/zip/? the replica data (which requires the looping, at least how I'm doing it currently) to each Partitions line. So it currently does this: ``` 0 #loop count Partitions: Partition - 0 Leader - 0 Replicas: Broker - 0 Leader - True In_Sync - True Partitions: Partition - 1 Leader - 1 Replicas: Broker - 1 Leader - True In_Sync - True Partitions: Partition - 2 Leader - 2 Replicas: Broker - 2 Leader - True In_Sync - True ``` ``` 1 #loop Partitions: Partition - 0 Leader - 0 Replicas: Broker - 1 Leader - False In_Sync - True Partitions: Partition - 1 Leader - 1 Replicas: Broker - 2 Leader - False In_Sync - True Partitions: Partition - 2 Leader - 2 Replicas: Broker - 0 Leader - False In_Sync - True ``` I want the lines to look like this: `Partitions: Partition - 0 Leader - 0 Replicas: Broker - 0 Leader - True In_Sync - True, Broker - 1 Leader - False In_Sync - True` `Partitions: Partition - 1 Leader - 1 Replicas: Broker - 1 Leader - True In_Sync - True, Broker - 2 Leader - False In_Sync - True` `Partitions: Partition - 2 Leader - 2 Replicas: Broker - 2 Leader - True In_Sync - True, Broker - 0 Leader - False In_Sync - True` Hopefully this makes sense.
2019-04-01T21:28:25.059500
Stacy
pythondev_help_Stacy_2019-04-01T21:28:25.059500
1,554,154,105.0595
16,383
pythondev
help
It's not completely clear what you want. What data should be associated with partition 0? From the example, it looks like you just want the two broker entries in the first entry of the replicas list. So I'm not sure why you're trying to zip across records.
2019-04-02T00:38:05.061400
Sasha
pythondev_help_Sasha_2019-04-02T00:38:05.061400
1,554,165,485.0614
16,384
pythondev
help
<@Sasha> so the lines that i want it to look like combine sections of both loop 0 and loop1 because `lc_replicas` contains two dictionaries within one list, so I have to loop through those keys with these: ``` broker = [ x[i]['broker'] for x in lc_replicas ] leader = [ x[i]['leader'] for x in lc_replicas ] in_sync = [ x[i]['in_sync'] for x in lc_replicas ] ``` I'm doing this because I believe these show the results of partitions that have 2 replicas - it could be 1 to 3 so I'm trying to take that into account, in which case the line i want it to look like could potentially be `Partitions: Partition - 0 Leader - 0 Replicas: Broker - 0 Leader - True In_Sync - True, Broker - 1 Leader - False In_Sync - True, ****Broker - 2, Leader - False, In_Sync - True****` where the third loop adds the content contained within asterisks. Does that help? Without the loops the output would simply be `Partitions: Partition - 0 Leader - 0` which requires no loops, just a matter of zipping the results together so they match up.
2019-04-02T00:47:10.065800
Stacy
pythondev_help_Stacy_2019-04-02T00:47:10.065800
1,554,166,030.0658
16,385
pythondev
help
I basically want to concat the content from the loops of the dictionaries together so they're contained on the same line when I zip everything together.
2019-04-02T00:48:13.066400
Stacy
pythondev_help_Stacy_2019-04-02T00:48:13.066400
1,554,166,093.0664
16,386
pythondev
help
From your original list:
2019-04-02T00:49:06.066800
Sasha
pythondev_help_Sasha_2019-04-02T00:49:06.066800
1,554,166,146.0668
16,387
pythondev
help
i'm not sure if leveraging itertools / chain would help in this case. haven't used it before.
2019-04-02T00:49:18.067300
Stacy
pythondev_help_Stacy_2019-04-02T00:49:18.067300
1,554,166,158.0673
16,388
pythondev
help
so there's a total of 47 partitions total (contained within `lc_partitions = [ p['partition'] for p in output['partitions'] ]` - i only need to loop those once. the way the current code works is it adds the replicas details to the partitions in two separate loops because i'm looping broker/leader/in_sync list comprehensions twice in this example....it could potentially be 1-3. so in the snippets where it shows `#loop 0`, it goes from 0 to 47, with the first slice/element of dictionaries in the list : ``` broker = [ x[i]['broker'] for x in lc_replicas ] leader = [ x[i]['leader'] for x in lc_replicas ] in_sync = [ x[i]['in_sync'] for x in lc_replicas ] ``` loop 1 then goes through partitions 0-47 again, appending the second element of the list. i want both `x[0]['broker'],x[0]['leader'],x[0]['in_sync'] and x[1]['broker'],x[1]['leader'],x[1]['in_sync']` printed on the same line.
2019-04-02T00:56:45.072700
Stacy
pythondev_help_Stacy_2019-04-02T00:56:45.072700
1,554,166,605.0727
16,389
pythondev
help
Let me sketch out what I think you want, and you correct me... Give me a sec.
2019-04-02T00:57:48.073500
Sasha
pythondev_help_Sasha_2019-04-02T00:57:48.073500
1,554,166,668.0735
16,390
pythondev
help
i'm probably complicating by just doing snippets vs the whole thing, i can try to provide more if that would help
2019-04-02T00:59:12.074700
Stacy
pythondev_help_Stacy_2019-04-02T00:59:12.074700
1,554,166,752.0747
16,391
pythondev
help
I think you just want a nested loop like this, if I understand which data you want where.
2019-04-02T01:01:44.074800
Sasha
pythondev_help_Sasha_2019-04-02T01:01:44.074800
1,554,166,904.0748
16,392
pythondev
help
Doesn't do the commas correctly, but meh, you get the idea.
2019-04-02T01:03:12.075600
Sasha
pythondev_help_Sasha_2019-04-02T01:03:12.075600
1,554,166,992.0756
16,393
pythondev
help
Yes!!!!!
2019-04-02T01:07:03.075900
Stacy
pythondev_help_Stacy_2019-04-02T01:07:03.075900
1,554,167,223.0759
16,394
pythondev
help
Ok, so this strips out the need of me needing to my slice logic to take into account how many dictionaries there might be in the replicas because well....it's already provided. That's apparent now
2019-04-02T01:08:39.076700
Stacy
pythondev_help_Stacy_2019-04-02T01:08:39.076700
1,554,167,319.0767
16,395
pythondev
help
i knew at some point i'd have to end with a space in attempt to concat the two lines together also. i had this commented out from previous troubleshooting `#print(lc_p, lc_l, l, b, i, end=' ')`
2019-04-02T01:09:49.077500
Stacy
pythondev_help_Stacy_2019-04-02T01:09:49.077500
1,554,167,389.0775
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pythondev
help
my confusion was how to iterate those dictionaries within the replicas list.
2019-04-02T01:10:28.077800
Stacy
pythondev_help_Stacy_2019-04-02T01:10:28.077800
1,554,167,428.0778
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pythondev
help
this is great. thank you <@Sasha> at some point i'm going to have to buy you beers instead of tacos (if you're in to that.) :slightly_smiling_face:
2019-04-02T01:11:05.078600
Stacy
pythondev_help_Stacy_2019-04-02T01:11:05.078600
1,554,167,465.0786
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pythondev
help
Heh, no problem. Happy to help, and glad it wasn't as complicated as it seemed.
2019-04-02T01:12:04.079300
Sasha
pythondev_help_Sasha_2019-04-02T01:12:04.079300
1,554,167,524.0793
16,399
pythondev
help
still getting a hang of python data structures. i always seem to over complicate it and have to strip things down.. need to quit making things so hard.
2019-04-02T01:13:09.080000
Stacy
pythondev_help_Stacy_2019-04-02T01:13:09.080000
1,554,167,589.08
16,400
pythondev
help
can't wait till rhel8 when i can start using f-strings all the time. using .format to be compatible on my servers for now.
2019-04-02T01:16:07.080700
Stacy
pythondev_help_Stacy_2019-04-02T01:16:07.080700
1,554,167,767.0807
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pythondev
help
Oh hey <@Sasha> I'm trying to understand a problem conceptually, could we talk through it?
2019-04-02T01:18:33.081300
Demetrice
pythondev_help_Demetrice_2019-04-02T01:18:33.081300
1,554,167,913.0813
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pythondev
help
Sure, go for it.
2019-04-02T01:19:17.081600
Sasha
pythondev_help_Sasha_2019-04-02T01:19:17.081600
1,554,167,957.0816
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pythondev
help
So i'm trying to help a friend with a coding challenge. and i realized that i can't quite conceptualize it myself
2019-04-02T01:20:26.082100
Demetrice
pythondev_help_Demetrice_2019-04-02T01:20:26.082100
1,554,168,026.0821
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pythondev
help
None
2019-04-02T01:21:03.082300
Demetrice
pythondev_help_Demetrice_2019-04-02T01:21:03.082300
1,554,168,063.0823
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pythondev
help
So i first i thought it would just be a series of if statements and that would be simple enough. But then i realized it will probably incorporate some concepts i'm not familiar with
2019-04-02T01:22:12.083500
Demetrice
pythondev_help_Demetrice_2019-04-02T01:22:12.083500
1,554,168,132.0835
16,406
pythondev
help
I mean i don't actually have to write it. Just conceptualizing it successfully is the goal.
2019-04-02T01:23:36.084100
Demetrice
pythondev_help_Demetrice_2019-04-02T01:23:36.084100
1,554,168,216.0841
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pythondev
help
If it's too long to read i can do a tl;dr
2019-04-02T01:23:44.084400
Demetrice
pythondev_help_Demetrice_2019-04-02T01:23:44.084400
1,554,168,224.0844
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pythondev
help
I understand the problem, but it's not immediately obvious how to solve it. My first point of slight confusion is even to figure out what the brackets look like for tournaments that don't have a power-of-two number of teams, since some teams will have to skip a round, and maybe we want our favored team to do that.
2019-04-02T01:26:43.086800
Sasha
pythondev_help_Sasha_2019-04-02T01:26:43.086800
1,554,168,403.0868
16,409
pythondev
help
I thought the implication was that there's any number of teams
2019-04-02T01:27:59.088300
Demetrice
pythondev_help_Demetrice_2019-04-02T01:27:59.088300
1,554,168,479.0883
16,410
pythondev
help
but i don't think odd numbers are allowed. I think it has to be a logical bracket
2019-04-02T01:28:11.088800
Demetrice
pythondev_help_Demetrice_2019-04-02T01:28:11.088800
1,554,168,491.0888
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pythondev
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For our team to advance to a slot in the bracket, it will have to be the highest-ranked team in that subtree, but the exact ordering of other teams doesn't matter within that tree.
2019-04-02T01:28:15.089000
Sasha
pythondev_help_Sasha_2019-04-02T01:28:15.089000
1,554,168,495.089
16,412
pythondev
help
I mean that's an assumption, but i don't know how that wouldn't be the case
2019-04-02T01:28:22.089300
Demetrice
pythondev_help_Demetrice_2019-04-02T01:28:22.089300
1,554,168,502.0893
16,413
pythondev
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Ohh you're right
2019-04-02T01:28:33.089600
Demetrice
pythondev_help_Demetrice_2019-04-02T01:28:33.089600
1,554,168,513.0896
16,414
pythondev
help
You know i've been trying to make the bracket from the bottom up
2019-04-02T01:28:46.090000
Demetrice
pythondev_help_Demetrice_2019-04-02T01:28:46.090000
1,554,168,526.09
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pythondev
help
But i think just &gt; statements might work?
2019-04-02T01:29:01.090600
Demetrice
pythondev_help_Demetrice_2019-04-02T01:29:01.090600
1,554,168,541.0906
16,416
pythondev
help
I'm not sure
2019-04-02T01:29:08.090800
Demetrice
pythondev_help_Demetrice_2019-04-02T01:29:08.090800
1,554,168,548.0908
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pythondev
help
No it's not that easy. Hmm
2019-04-02T01:29:13.091000
Demetrice
pythondev_help_Demetrice_2019-04-02T01:29:13.091000
1,554,168,553.091
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pythondev
help
Waaaait... in the pasted text, it says "2N" teams. Is that actually "2^N" with an exponent?
2019-04-02T01:32:56.093800
Sasha
pythondev_help_Sasha_2019-04-02T01:32:56.093800
1,554,168,776.0938
16,419
pythondev
help
So i was thinking and i'm not sure if this makes sense but i was thinking we'd want to try to sort it top to bottom x number of times
2019-04-02T01:33:08.094000
Demetrice
pythondev_help_Demetrice_2019-04-02T01:33:08.094000
1,554,168,788.094
16,420