query_id
int64 0
2.15k
| database_id
stringclasses 40
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sequencelengths 1
4
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stringlengths 22
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| answer
stringlengths 22
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| difficulty
stringclasses 4
values |
|---|---|---|---|---|---|
2,000 | book_press | [
"author",
"book"
] | Which authors in the record have not published any books ? Give me their names . | select name from author where author_id not in (select author_id from book) | hard |
2,001 | book_press | [
"author",
"book"
] | Find the names of authors who have more than one book in the database. | SELECT t1.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id GROUP BY t2.author_id HAVING count(*) > 1 | medium |
2,002 | book_press | [
"author",
"book"
] | Which authors have published more than 1 book according to the database? Give me their names. | SELECT t1.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id GROUP BY t2.author_id HAVING count(*) > 1 | medium |
2,003 | book_press | [
"author",
"book",
"press"
] | Find the title, author name, and publisher name for the top 3 best sales books. | SELECT t1.name , t2.title , t3.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id JOIN press AS t3 ON t2.press_id = t3.press_id ORDER BY t2.sale_amount DESC LIMIT 3 | extra |
2,004 | book_press | [
"author",
"book",
"press"
] | What are the 3 best selling books? Show their titles, author names, and press names. | SELECT t1.name , t2.title , t3.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id JOIN press AS t3 ON t2.press_id = t3.press_id ORDER BY t2.sale_amount DESC LIMIT 3 | extra |
2,005 | book_press | [
"book",
"press"
] | Find the name and total book sale amount of each press. | SELECT sum(t1.sale_amount) , t2.name FROM book AS t1 JOIN press AS t2 ON t1.press_id = t2.press_id GROUP BY t1.press_id | medium |
2,006 | book_press | [
"book",
"press"
] | What are the name and total book sale amount of each press? | SELECT sum(t1.sale_amount) , t2.name FROM book AS t1 JOIN press AS t2 ON t1.press_id = t2.press_id GROUP BY t1.press_id | medium |
2,007 | book_press | [
"book",
"press"
] | Find the number of books that are sold more than 1000 for each publisher. List the press name as well. | SELECT count(*) , t2.name FROM book AS t1 JOIN press AS t2 ON t1.press_id = t2.press_id WHERE sale_amount > 1000 GROUP BY t2.name | hard |
2,008 | book_press | [
"book",
"press"
] | For each press, return its name and the number of books that have sale amount above 1000. | SELECT count(*) , t2.name FROM book AS t1 JOIN press AS t2 ON t1.press_id = t2.press_id WHERE sale_amount > 1000 GROUP BY t2.name | hard |
2,009 | book_press | [
"author",
"book"
] | What is the name of the author of best selling book? | SELECT t1.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id ORDER BY t2.sale_amount DESC LIMIT 1 | hard |
2,010 | book_press | [
"author",
"book"
] | Who wrote the best selling book? Give me the author name. | SELECT t1.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id ORDER BY t2.sale_amount DESC LIMIT 1 | hard |
2,011 | book_press | [
"author",
"book"
] | find the name and gender of the author who published the most books. | SELECT t1.name , t1.gender FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id GROUP BY t2.author_id ORDER BY count(*) DESC LIMIT 1 | extra |
2,012 | book_press | [
"author",
"book"
] | Who wrote the largest number of books? Give me the author name and gender. | SELECT t1.name , t1.gender FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id GROUP BY t2.author_id ORDER BY count(*) DESC LIMIT 1 | extra |
2,013 | book_press | [
"author",
"book",
"press"
] | Find the names of the authors who did not have any book with the "Accor" press. | SELECT name FROM author EXCEPT SELECT t1.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id JOIN press AS t3 ON t2.press_id = t3.press_id WHERE t3.name = 'Accor' | hard |
2,014 | book_press | [
"author",
"book",
"press"
] | Which authors have never published under the "Accor" press? Give me their names. | SELECT name FROM author EXCEPT SELECT t1.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id JOIN press AS t3 ON t2.press_id = t3.press_id WHERE t3.name = 'Accor' | hard |
2,015 | book_press | [
"book",
"press"
] | Find the name and the yearly profit in billion for press that published more than two books. | SELECT t2.name , t2.Year_Profits_billion FROM book AS t1 JOIN press AS t2 ON t1.press_id = t2.press_id GROUP BY t2.press_id HAVING count(*) > 2 | medium |
2,016 | book_press | [
"book",
"press"
] | Find the press that published more than two books, and return its name and yearly profit in billion. | SELECT t2.name , t2.Year_Profits_billion FROM book AS t1 JOIN press AS t2 ON t1.press_id = t2.press_id GROUP BY t2.press_id HAVING count(*) > 2 | medium |
2,017 | cre_Doc_Workflow | [
"Authors"
] | How many authors do we have? | SELECT count(*) FROM Authors | easy |
2,018 | cre_Doc_Workflow | [
"Authors"
] | Show all author names. | SELECT author_name FROM Authors | easy |
2,019 | cre_Doc_Workflow | [
"Authors"
] | Show the names and other details for all authors. | SELECT author_name , other_details FROM Authors | medium |
2,020 | cre_Doc_Workflow | [
"Authors"
] | Show the other details for the author Addison Denesik. | SELECT other_details FROM Authors WHERE author_name = "Addison Denesik" | easy |
2,021 | cre_Doc_Workflow | [
"Documents"
] | Show the number of documents. | SELECT count(*) FROM Documents | easy |
2,022 | cre_Doc_Workflow | [
"Documents"
] | Who is the author of the document with id 4? | SELECT author_name FROM Documents WHERE document_id = 4 | easy |
2,023 | cre_Doc_Workflow | [
"Documents"
] | Who is the author of the document "Travel to Brazil"? | SELECT author_name FROM Documents WHERE document_name = "Travel to Brazil" | easy |
2,024 | cre_Doc_Workflow | [
"Documents"
] | How many documents does has the author Era Kerluke written? | SELECT count(*) FROM Documents WHERE author_name = "Era Kerluke" | easy |
2,025 | cre_Doc_Workflow | [
"Documents"
] | Show the names and descriptions for all documents. | SELECT document_name , document_description FROM Documents | medium |
2,026 | cre_Doc_Workflow | [
"Documents"
] | Show the ids and names for all documents by author Bianka Cummings. | SELECT document_id , document_name FROM Documents WHERE author_name = "Bianka Cummings" | medium |
2,027 | cre_Doc_Workflow | [
"Documents",
"Authors"
] | Show the author name and details for the document "Travel to China". | SELECT T2.author_name , T2.other_details FROM Documents AS T1 JOIN Authors AS T2 ON T1.author_name = T2.author_name WHERE document_name = "Travel to China" | medium |
2,028 | cre_Doc_Workflow | [
"Documents"
] | Show all author names and number of documents corresponding to each. | SELECT author_name , count(*) FROM Documents GROUP BY author_name | medium |
2,029 | cre_Doc_Workflow | [
"Documents"
] | What is the name of the author with most number of documents? | SELECT author_name FROM Documents GROUP BY author_name ORDER BY count(*) DESC LIMIT 1 | hard |
2,030 | cre_Doc_Workflow | [
"Documents"
] | Show the names for authors with at least two documents. | SELECT author_name FROM Documents GROUP BY author_name HAVING count(*) >= 2 | easy |
2,031 | cre_Doc_Workflow | [
"Business_processes"
] | How many business processes do we have? | SELECT count(*) FROM Business_processes | easy |
2,032 | cre_Doc_Workflow | [
"Business_processes"
] | Show the next process id, process name, process description for process with id 9. | SELECT next_process_id , process_name , process_description FROM Business_processes WHERE process_id = 9 | medium |
2,033 | cre_Doc_Workflow | [
"Business_processes"
] | What is the process name for the next process of the process with id 9? | SELECT process_name FROM Business_processes WHERE process_id = (SELECT next_process_id FROM Business_processes WHERE process_id = 9) | hard |
2,034 | cre_Doc_Workflow | [
"Process_outcomes"
] | Show the number of process outcomes. | SELECT count(*) FROM Process_outcomes | easy |
2,035 | cre_Doc_Workflow | [
"Process_outcomes"
] | List the codes and descriptions for all process outcomes. | SELECT process_outcome_code , process_outcome_description FROM Process_outcomes | medium |
2,036 | cre_Doc_Workflow | [
"Process_outcomes"
] | What is the description for the process outcome code working? | SELECT process_outcome_description FROM Process_outcomes WHERE process_outcome_code = "working" | easy |
2,037 | cre_Doc_Workflow | [
"Process_status"
] | Show the number of process status. | SELECT count(*) FROM Process_status | easy |
2,038 | cre_Doc_Workflow | [
"Process_status"
] | List the codes and descriptions for all process status. | SELECT process_status_code , process_status_description FROM Process_status | medium |
2,039 | cre_Doc_Workflow | [
"Process_status"
] | What is the description for process status code ct? | SELECT process_status_description FROM Process_status WHERE process_status_code = "ct" | easy |
2,040 | cre_Doc_Workflow | [
"Staff"
] | How many staff do we have? | SELECT count(*) FROM Staff | easy |
2,041 | cre_Doc_Workflow | [
"Staff"
] | Show the ids and details for all staff. | SELECT staff_id , staff_details FROM Staff | medium |
2,042 | cre_Doc_Workflow | [
"Staff"
] | What are the details for the staff member with id 100. | SELECT staff_details FROM Staff WHERE staff_id = 100 | easy |
2,043 | cre_Doc_Workflow | [
"Ref_staff_roles"
] | Show the number of staff roles. | SELECT count(*) FROM Ref_staff_roles | easy |
2,044 | cre_Doc_Workflow | [
"Ref_staff_roles"
] | List the codes and descriptions for all staff roles. | SELECT staff_role_code , staff_role_description FROM Ref_staff_roles | medium |
2,045 | cre_Doc_Workflow | [
"Ref_staff_roles"
] | What is the description for staff role code HR? | SELECT staff_role_description FROM Ref_staff_roles WHERE staff_role_code = "HR" | easy |
2,046 | cre_Doc_Workflow | [
"Documents_processes"
] | How many documents have a process? | SELECT count(DISTINCT document_id) FROM Documents_processes | easy |
2,047 | cre_Doc_Workflow | [
"Documents_processes"
] | List all process ids with a document. | SELECT DISTINCT process_id FROM Documents_processes | easy |
2,048 | cre_Doc_Workflow | [
"Documents",
"Documents_processes"
] | Show all document ids without a process. | SELECT document_id FROM Documents EXCEPT SELECT document_id FROM Documents_processes | hard |
2,049 | cre_Doc_Workflow | [
"Business_processes",
"Documents_processes"
] | List all process ids with no document. | SELECT process_id FROM Business_processes EXCEPT SELECT process_id FROM Documents_processes | hard |
2,050 | cre_Doc_Workflow | [
"Process_Status",
"Documents_processes",
"Process_outcomes"
] | What is the process outcome description and process status description for the document with id 0? | SELECT T2.process_outcome_description , T3.process_status_description FROM Documents_processes AS T1 JOIN Process_outcomes AS T2 ON T1.process_outcome_code = T2.process_outcome_code JOIN Process_Status AS T3 ON T1.process_status_code = T3.process_status_code WHERE T1.document_id = 0 | hard |
2,051 | cre_Doc_Workflow | [
"Business_processes",
"Documents",
"Documents_processes"
] | What is the process name for the document "Travel to Brazil"? | SELECT T3.process_name FROM Documents_processes AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id JOIN Business_processes AS T3 ON T1.process_id = T3.process_id WHERE T2.document_name = "Travel to Brazil" | hard |
2,052 | cre_Doc_Workflow | [
"Documents_processes"
] | Show all process ids and the number of documents in each process. | SELECT process_id , count(*) FROM Documents_processes GROUP BY process_id | medium |
2,053 | cre_Doc_Workflow | [
"Staff_in_processes"
] | How many staff are the document with id 0 and process with id 9. | SELECT count(*) FROM Staff_in_processes WHERE document_id = 0 AND process_id = 9 | medium |
2,054 | cre_Doc_Workflow | [
"Staff_in_processes"
] | Show all staff ids and the number of document processes for each staff. | SELECT staff_id , count(*) FROM Staff_in_processes GROUP BY staff_id | medium |
2,055 | cre_Doc_Workflow | [
"Staff_in_processes"
] | Show all staff role codes and the number of document processes for each role. | SELECT staff_role_code , count(*) FROM Staff_in_processes GROUP BY staff_role_code | medium |
2,056 | cre_Doc_Workflow | [
"Staff_in_processes"
] | How many different roles does the staff with id 3 have? | SELECT count(DISTINCT staff_role_code) FROM Staff_in_processes WHERE staff_id = 3 | easy |
2,057 | advertising_agencies | [
"Agencies"
] | How many agencies do we have? | SELECT count(*) FROM Agencies | easy |
2,058 | advertising_agencies | [
"Agencies"
] | Count the number of agencies. | SELECT count(*) FROM Agencies | easy |
2,059 | advertising_agencies | [
"Agencies"
] | Show all agency ids and details. | SELECT agency_id , agency_details FROM Agencies | medium |
2,060 | advertising_agencies | [
"Agencies"
] | What are all the agency ids and details? | SELECT agency_id , agency_details FROM Agencies | medium |
2,061 | advertising_agencies | [
"Clients"
] | Show the number of clients. | SELECT count(*) FROM Clients | easy |
2,062 | advertising_agencies | [
"Clients"
] | How many clients are there? | SELECT count(*) FROM Clients | easy |
2,063 | advertising_agencies | [
"Clients"
] | List all client ids and client details. | SELECT client_id , client_details FROM Clients | medium |
2,064 | advertising_agencies | [
"Clients"
] | What are all the client ids and details? | SELECT client_id , client_details FROM Clients | medium |
2,065 | advertising_agencies | [
"Clients"
] | Show agency ids and the number of clients for each agency. | SELECT agency_id , count(*) FROM Clients GROUP BY agency_id | medium |
2,066 | advertising_agencies | [
"Clients"
] | How many clients does each agency have? | SELECT agency_id , count(*) FROM Clients GROUP BY agency_id | medium |
2,067 | advertising_agencies | [
"Agencies",
"Clients"
] | What is the agency id and details with most number of clients? | SELECT T1.agency_id , T1.agency_details FROM Agencies AS T1 JOIN Clients AS T2 ON T1.agency_id = T2.agency_id GROUP BY T1.agency_id ORDER BY count(*) DESC LIMIT 1 | extra |
2,068 | advertising_agencies | [
"Agencies",
"Clients"
] | Return the agency id and details for the agency with the greatest number of clients. | SELECT T1.agency_id , T1.agency_details FROM Agencies AS T1 JOIN Clients AS T2 ON T1.agency_id = T2.agency_id GROUP BY T1.agency_id ORDER BY count(*) DESC LIMIT 1 | extra |
2,069 | advertising_agencies | [
"Agencies",
"Clients"
] | Show agency ids and details with at least 2 clients. | SELECT T1.agency_id , T1.agency_details FROM Agencies AS T1 JOIN Clients AS T2 ON T1.agency_id = T2.agency_id GROUP BY T1.agency_id HAVING count(*) >= 2 | medium |
2,070 | advertising_agencies | [
"Agencies",
"Clients"
] | What are the agency ids and details agencies with at least 2 clients? | SELECT T1.agency_id , T1.agency_details FROM Agencies AS T1 JOIN Clients AS T2 ON T1.agency_id = T2.agency_id GROUP BY T1.agency_id HAVING count(*) >= 2 | medium |
2,071 | advertising_agencies | [
"Agencies",
"Clients"
] | Show agency details for client with detail 'Mac'. | SELECT T2.agency_details FROM Clients AS T1 JOIN Agencies AS T2 ON T1.agency_id = T2.agency_id WHERE T1.client_details = 'Mac' | medium |
2,072 | advertising_agencies | [
"Agencies",
"Clients"
] | What are the agency details for clients with the detail Mac? | SELECT T2.agency_details FROM Clients AS T1 JOIN Agencies AS T2 ON T1.agency_id = T2.agency_id WHERE T1.client_details = 'Mac' | medium |
2,073 | advertising_agencies | [
"Agencies",
"Clients"
] | Show details for all clients and the details of their corresponding agents. | SELECT T1.client_details , T2.agency_details FROM Clients AS T1 JOIN Agencies AS T2 ON T1.agency_id = T2.agency_id | medium |
2,074 | advertising_agencies | [
"Agencies",
"Clients"
] | What are the client details for each client and the corresponding details of their agencies? | SELECT T1.client_details , T2.agency_details FROM Clients AS T1 JOIN Agencies AS T2 ON T1.agency_id = T2.agency_id | medium |
2,075 | advertising_agencies | [
"Clients"
] | Show all sic codes and the number of clients with each code. | SELECT sic_code , count(*) FROM Clients GROUP BY sic_code | medium |
2,076 | advertising_agencies | [
"Clients"
] | How many clients are there for each sic code? | SELECT sic_code , count(*) FROM Clients GROUP BY sic_code | medium |
2,077 | advertising_agencies | [
"Clients"
] | Show all client ids and details with sic code "Bad". | SELECT client_id , client_details FROM Clients WHERE sic_code = "Bad"; | medium |
2,078 | advertising_agencies | [
"Clients"
] | What are the client ideas and details for clients with the sic code Bad? | SELECT client_id , client_details FROM Clients WHERE sic_code = "Bad"; | medium |
2,079 | advertising_agencies | [
"Agencies",
"Clients"
] | Show all agency ids and details for agencies with a client. | SELECT T1.agency_id , T1.agency_details FROM Agencies AS T1 JOIN Clients AS T2 ON T1.agency_id = T2.agency_id | medium |
2,080 | advertising_agencies | [
"Agencies",
"Clients"
] | What are the agency ids and agency details for all agencies who have a client? | SELECT T1.agency_id , T1.agency_details FROM Agencies AS T1 JOIN Clients AS T2 ON T1.agency_id = T2.agency_id | medium |
2,081 | advertising_agencies | [
"Agencies",
"Clients"
] | Show all agency ids without any client. | SELECT agency_id FROM Agencies EXCEPT SELECT agency_id FROM Clients | hard |
2,082 | advertising_agencies | [
"Agencies",
"Clients"
] | What are ids of agencies that do not have any clients? | SELECT agency_id FROM Agencies EXCEPT SELECT agency_id FROM Clients | hard |
2,083 | advertising_agencies | [
"Invoices"
] | How many invoices do we have? | SELECT count(*) FROM Invoices | easy |
2,084 | advertising_agencies | [
"Invoices"
] | Count the number of invoices. | SELECT count(*) FROM Invoices | easy |
2,085 | advertising_agencies | [
"Invoices"
] | Show ids, status codes, and details for all invoices for clients. | SELECT invoice_id , invoice_status , invoice_details FROM Invoices | medium |
2,086 | advertising_agencies | [
"Invoices"
] | What are the ids, statuses, and details for all invoices? | SELECT invoice_id , invoice_status , invoice_details FROM Invoices | medium |
2,087 | advertising_agencies | [
"Invoices"
] | Show all client ids and the number of invoices for each client. | SELECT client_id , count(*) FROM Invoices GROUP BY client_id | medium |
2,088 | advertising_agencies | [
"Invoices"
] | How many invoices are there for each client id? | SELECT client_id , count(*) FROM Invoices GROUP BY client_id | medium |
2,089 | advertising_agencies | [
"Clients",
"Invoices"
] | List the client id and detail with most number of invoices. | SELECT T1.client_id , T2.client_details FROM Invoices AS T1 JOIN Clients AS T2 ON T1.client_id = T2.client_id GROUP BY T1.client_id ORDER BY count(*) DESC LIMIT 1 | extra |
2,090 | advertising_agencies | [
"Clients",
"Invoices"
] | What are the client id and details for the client with the most invoices? | SELECT T1.client_id , T2.client_details FROM Invoices AS T1 JOIN Clients AS T2 ON T1.client_id = T2.client_id GROUP BY T1.client_id ORDER BY count(*) DESC LIMIT 1 | extra |
2,091 | advertising_agencies | [
"Invoices"
] | What are client ids for clients with at least 2 invoices. | SELECT client_id FROM Invoices GROUP BY client_id HAVING count(*) >= 2 | easy |
2,092 | advertising_agencies | [
"Invoices"
] | Return the client ids for clients with two or more invoices? | SELECT client_id FROM Invoices GROUP BY client_id HAVING count(*) >= 2 | easy |
2,093 | advertising_agencies | [
"Invoices"
] | Show all invoice status codes and the number of invoices with each status. | SELECT invoice_status , count(*) FROM Invoices GROUP BY invoice_status | medium |
2,094 | advertising_agencies | [
"Invoices"
] | How many invoices are there for each status code? | SELECT invoice_status , count(*) FROM Invoices GROUP BY invoice_status | medium |
2,095 | advertising_agencies | [
"Invoices"
] | What is the invoice status code with most number of invoices. | SELECT invoice_status FROM Invoices GROUP BY invoice_status ORDER BY count(*) DESC LIMIT 1 | hard |
2,096 | advertising_agencies | [
"Invoices"
] | Return the invoice status that has the most invoices. | SELECT invoice_status FROM Invoices GROUP BY invoice_status ORDER BY count(*) DESC LIMIT 1 | hard |
2,097 | advertising_agencies | [
"Agencies",
"Clients",
"Invoices"
] | Show all invoice status codes and details and the corresponding client id and details and agency id and details. | SELECT T1.invoice_status , T1.invoice_details , T2.client_id , T2.client_details , T3.agency_id , T3.agency_details FROM Invoices AS T1 JOIN Clients AS T2 ON T1.client_id = T2.client_id JOIN Agencies AS T3 ON T2.agency_id = T3.agency_id | medium |
2,098 | advertising_agencies | [
"Agencies",
"Clients",
"Invoices"
] | What are the invoice status, invoice details, and corresponding client ids and details and agency id and details? | SELECT T1.invoice_status , T1.invoice_details , T2.client_id , T2.client_details , T3.agency_id , T3.agency_details FROM Invoices AS T1 JOIN Clients AS T2 ON T1.client_id = T2.client_id JOIN Agencies AS T3 ON T2.agency_id = T3.agency_id | medium |
2,099 | advertising_agencies | [
"meetings"
] | List all meeting type codes and details. | SELECT meeting_type , other_details FROM meetings | medium |
Subsets and Splits