query_id
int64 0
2.15k
| database_id
stringclasses 40
values | table_id
sequencelengths 1
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stringlengths 22
185
| answer
stringlengths 22
608
| difficulty
stringclasses 4
values |
|---|---|---|---|---|---|
300 | customers_and_orders | [
"Customer_orders"
] | Give the order status code that is most frequent across customer orders. | SELECT order_status_code FROM Customer_orders GROUP BY order_status_code ORDER BY count(*) DESC LIMIT 1 | hard |
301 | customers_and_orders | [
"Customer_orders",
"Customers"
] | How many customers do not have an order? | SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_orders) | extra |
302 | customers_and_orders | [
"Customer_orders",
"Customers"
] | Count the number of customers who have not made an order. | SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_orders) | extra |
303 | customers_and_orders | [
"Order_items",
"Products"
] | Show all product names without an order. | SELECT product_name FROM Products EXCEPT SELECT T1.product_name FROM Products AS t1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id | hard |
304 | customers_and_orders | [
"Order_items",
"Products"
] | What are the names of products that have not been ordered? | SELECT product_name FROM Products EXCEPT SELECT T1.product_name FROM Products AS t1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id | hard |
305 | customers_and_orders | [
"Order_items",
"Products"
] | How many products named Monitor have been ordered? | SELECT sum(order_quantity) FROM Order_items AS T1 JOIN Products AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "Monitor" | medium |
306 | customers_and_orders | [
"Order_items",
"Products"
] | What is the total number of Monitor products that have been ordered? | SELECT sum(order_quantity) FROM Order_items AS T1 JOIN Products AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "Monitor" | medium |
307 | customers_and_orders | [
"Order_items",
"Customer_orders",
"Products"
] | How many customers have ordered the product named Monitor? | SELECT count(DISTINCT T3.customer_id) FROM Order_items AS T1 JOIN Products AS T2 ON T1.product_id = T2.product_id JOIN Customer_orders AS T3 ON T3.order_id = T1.order_id WHERE T2.product_name = "Monitor" | hard |
308 | customers_and_orders | [
"Order_items",
"Customer_orders",
"Products"
] | Count the number of different customers who have bought a Monitor Product. | SELECT count(DISTINCT T3.customer_id) FROM Order_items AS T1 JOIN Products AS T2 ON T1.product_id = T2.product_id JOIN Customer_orders AS T3 ON T3.order_id = T1.order_id WHERE T2.product_name = "Monitor" | hard |
309 | customers_and_orders | [
"Customer_orders"
] | How many customers have an order? | SELECT count(DISTINCT customer_id) FROM Customer_orders | easy |
310 | customers_and_orders | [
"Customer_orders"
] | Count the number of differnt customers who have made an order. | SELECT count(DISTINCT customer_id) FROM Customer_orders | easy |
311 | customers_and_orders | [
"Customer_orders",
"Customers"
] | Show all customer ids without an order. | SELECT customer_id FROM Customers EXCEPT SELECT customer_id FROM Customer_orders | hard |
312 | customers_and_orders | [
"Customer_orders",
"Customers"
] | What are the ids of customers who have not made an order? | SELECT customer_id FROM Customers EXCEPT SELECT customer_id FROM Customer_orders | hard |
313 | customers_and_orders | [
"Order_items",
"Customer_Orders"
] | Show all the order dates and ids of the orders with quantity of any product larger than 6 or with more than 3 products. | SELECT T1.order_date , T1.order_id FROM Customer_Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id WHERE T2.order_quantity > 6 UNION SELECT T1.order_date , T1.order_id FROM Customer_Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id HAVING count(*) > 3; | extra |
314 | customers_and_orders | [
"Order_items",
"Customer_Orders"
] | What are the order ids and corresponding order dates for orders with a quantity greater than 6 or consisting of more than 3 products? | SELECT T1.order_date , T1.order_id FROM Customer_Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id WHERE T2.order_quantity > 6 UNION SELECT T1.order_date , T1.order_id FROM Customer_Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id HAVING count(*) > 3; | extra |
315 | region_building | [
"building"
] | How many buildings are there? | SELECT count(*) FROM building | easy |
316 | region_building | [
"building"
] | Count the number of buildings. | SELECT count(*) FROM building | easy |
317 | region_building | [
"building"
] | List the names of buildings in ascending order of number of stories. | SELECT Name FROM building ORDER BY Number_of_Stories ASC | easy |
318 | region_building | [
"building"
] | What is the list of building names, sorted by the number of stories of each building in ascending order? | SELECT Name FROM building ORDER BY Number_of_Stories ASC | easy |
319 | region_building | [
"building"
] | List the addresses of buildings in descending order of building completion year. | SELECT Address FROM building ORDER BY Completed_Year DESC | easy |
320 | region_building | [
"building"
] | Sort the buildings in descending order of building completion year, and return the building addresses. | SELECT Address FROM building ORDER BY Completed_Year DESC | easy |
321 | region_building | [
"building"
] | What is the maximum number of stories of buildings not completed in 1980? | SELECT max(Number_of_Stories) FROM building WHERE Completed_Year != "1980" | easy |
322 | region_building | [
"building"
] | Among the buildings not completed in 1980, what is the maximum number of stories? | SELECT max(Number_of_Stories) FROM building WHERE Completed_Year != "1980" | easy |
323 | region_building | [
"region"
] | What is the average population for all regions? | SELECT avg(Population) FROM region | easy |
324 | region_building | [
"region"
] | Compute the average population of a region. | SELECT avg(Population) FROM region | easy |
325 | region_building | [
"region"
] | What are the names of regions in ascending alphabetical order? | SELECT Name FROM region ORDER BY Name ASC | easy |
326 | region_building | [
"region"
] | List the names of regions in alphabetical order. | SELECT Name FROM region ORDER BY Name ASC | easy |
327 | region_building | [
"region"
] | What are the capitals of the regions with area bigger than 10000? | SELECT Capital FROM region WHERE Area > 10000 | easy |
328 | region_building | [
"region"
] | Give me the capitals of the regions whose area is larger than 10000. | SELECT Capital FROM region WHERE Area > 10000 | easy |
329 | region_building | [
"region"
] | List the capital of the region with the largest population. | SELECT Capital FROM region ORDER BY Population DESC LIMIT 1 | medium |
330 | region_building | [
"region"
] | Which region has the largest population? Give me the capital of the region. | SELECT Capital FROM region ORDER BY Population DESC LIMIT 1 | medium |
331 | region_building | [
"region"
] | List the names of the regions with the top 5 largest areas. | SELECT Name FROM region ORDER BY Area DESC LIMIT 5 | medium |
332 | region_building | [
"region"
] | What are the names of the 5 largest regions in terms of area? | SELECT Name FROM region ORDER BY Area DESC LIMIT 5 | medium |
333 | region_building | [
"region",
"building"
] | Show the names of buildings and the names of regions they are in. | SELECT T1.Name , T2.Name FROM building AS T1 JOIN region AS T2 ON T1.Region_ID = T2.Region_ID | medium |
334 | region_building | [
"region",
"building"
] | For each building, return the name of the building and the name of the region it belongs to. | SELECT T1.Name , T2.Name FROM building AS T1 JOIN region AS T2 ON T1.Region_ID = T2.Region_ID | medium |
335 | region_building | [
"region",
"building"
] | Show the names of regions that have more than one building. | SELECT T2.Name FROM building AS T1 JOIN region AS T2 ON T1.Region_ID = T2.Region_ID GROUP BY T1.Region_ID HAVING COUNT(*) > 1 | medium |
336 | region_building | [
"region",
"building"
] | Which regions have more than one building? Give me the names of the regions. | SELECT T2.Name FROM building AS T1 JOIN region AS T2 ON T1.Region_ID = T2.Region_ID GROUP BY T1.Region_ID HAVING COUNT(*) > 1 | medium |
337 | region_building | [
"region",
"building"
] | Show the capital of the region that has the most buildings. | SELECT T2.capital FROM building AS T1 JOIN region AS T2 ON T1.Region_ID = T2.Region_ID GROUP BY T1.Region_ID ORDER BY COUNT(*) DESC LIMIT 1 | extra |
338 | region_building | [
"region",
"building"
] | Which region has the largest number of buildings? Show me the capital of the region. | SELECT T2.capital FROM building AS T1 JOIN region AS T2 ON T1.Region_ID = T2.Region_ID GROUP BY T1.Region_ID ORDER BY COUNT(*) DESC LIMIT 1 | extra |
339 | region_building | [
"region",
"building"
] | Show addresses of buildings and the capitals of regions they are in. | SELECT T1.Address , T2.Capital FROM building AS T1 JOIN region AS T2 ON T1.Region_ID = T2.Region_ID | medium |
340 | region_building | [
"region",
"building"
] | For each building, return the address of the building and the name of the region it belongs to. | SELECT T1.Address , T2.Capital FROM building AS T1 JOIN region AS T2 ON T1.Region_ID = T2.Region_ID | medium |
341 | region_building | [
"region",
"building"
] | Show the number of stories of buildings in the region with name "Abruzzo". | SELECT T1.Number_of_Stories FROM building AS T1 JOIN region AS T2 ON T1.Region_ID = T2.Region_ID WHERE T2.Name = "Abruzzo" | medium |
342 | region_building | [
"region",
"building"
] | Return the number of stories for each building in the region named "Abruzzo". | SELECT T1.Number_of_Stories FROM building AS T1 JOIN region AS T2 ON T1.Region_ID = T2.Region_ID WHERE T2.Name = "Abruzzo" | medium |
343 | region_building | [
"building"
] | Please show each completion year and the number of buildings completed in that year. | SELECT Completed_Year , COUNT(*) FROM building GROUP BY Completed_Year | medium |
344 | region_building | [
"building"
] | For completion year, return the year and the number of buildings completed. | SELECT Completed_Year , COUNT(*) FROM building GROUP BY Completed_Year | medium |
345 | region_building | [
"building"
] | List the year in which the most buildings are completed. | SELECT Completed_Year FROM building GROUP BY Completed_Year ORDER BY COUNT(*) DESC LIMIT 1 | hard |
346 | region_building | [
"building"
] | In which year did the most building constructions complete? | SELECT Completed_Year FROM building GROUP BY Completed_Year ORDER BY COUNT(*) DESC LIMIT 1 | hard |
347 | region_building | [
"region",
"building"
] | List the names of regions that do not have any buildings. | SELECT Name FROM region WHERE Region_ID NOT IN (SELECT Region_ID FROM building) | hard |
348 | region_building | [
"region",
"building"
] | What are the names of regions in which there are no buildings? | SELECT Name FROM region WHERE Region_ID NOT IN (SELECT Region_ID FROM building) | hard |
349 | region_building | [
"building"
] | Show the completed years shared by buildings with more than 20 stories and buildings with less than 15 stories. | SELECT Completed_Year FROM building WHERE Number_of_Stories > 20 INTERSECT SELECT Completed_Year FROM building WHERE Number_of_Stories < 15 | hard |
350 | region_building | [
"building"
] | In which years did both buildings with more than 20 stories and buildings with less than 15 stories were completed? | SELECT Completed_Year FROM building WHERE Number_of_Stories > 20 INTERSECT SELECT Completed_Year FROM building WHERE Number_of_Stories < 15 | hard |
351 | region_building | [
"building"
] | Show the distinct addresses of buildings. | SELECT DISTINCT Address FROM building | easy |
352 | region_building | [
"building"
] | Give me a list of distinct building addresses. | SELECT DISTINCT Address FROM building | easy |
353 | region_building | [
"building"
] | Show the completed years of buildings in descending order of the number of stories. | SELECT Completed_Year FROM building ORDER BY Number_of_Stories DESC | easy |
354 | region_building | [
"building"
] | Sort buildings in descending order of the number of stories, and return their completion years. | SELECT Completed_Year FROM building ORDER BY Number_of_Stories DESC | easy |
355 | government_shift | [
"channels"
] | List details of all the channel in alphabetical order . | select channel_details from channels order by channel_details | easy |
356 | government_shift | [
"channels"
] | What is the list of channel details ordered alphabetically ? | select channel_details from channels order by channel_details | easy |
357 | government_shift | [
"services"
] | How many services are there? | SELECT count(*) FROM services | easy |
358 | government_shift | [
"services"
] | Count the number of services. | SELECT count(*) FROM services | easy |
359 | government_shift | [
"analytical_layer"
] | What is the most common analytical layer type code? | SELECT analytical_layer_type_code FROM analytical_layer GROUP BY analytical_layer_type_code ORDER BY count(*) DESC LIMIT 1 | hard |
360 | government_shift | [
"analytical_layer"
] | Find the analytical layer type code that appears most often. | SELECT analytical_layer_type_code FROM analytical_layer GROUP BY analytical_layer_type_code ORDER BY count(*) DESC LIMIT 1 | hard |
361 | government_shift | [
"services",
"customers",
"customers_and_services"
] | Find all the services that has been used by the customer with details "Hardy Kutch". | SELECT t3.service_details FROM customers AS t1 JOIN customers_and_services AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t1.customer_details = "Hardy Kutch" | hard |
362 | government_shift | [
"services",
"customers",
"customers_and_services"
] | Which services were used by the customer with details "Hardy Kutch"? Give me the service details. | SELECT t3.service_details FROM customers AS t1 JOIN customers_and_services AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t1.customer_details = "Hardy Kutch" | hard |
363 | government_shift | [
"services",
"customers_and_services"
] | Find the details of the services that have been used by more than 3 times . | select t1.service_details from services as t1 join customers_and_services as t2 on t1.service_id = t2.service_id group by t1.service_details having count(*) > 3 | medium |
364 | government_shift | [
"services",
"customers_and_services"
] | Which services were used by customers by more than 3 times? Give me the service details. | SELECT t1.service_details FROM services AS t1 JOIN customers_and_services AS t2 ON t1.service_id = t2.service_id GROUP BY t1.service_details HAVING count(*) > 3 | medium |
365 | government_shift | [
"customers",
"customers_and_services"
] | Find the details of the customer who has used services the most times. | SELECT t1.customer_details FROM customers AS t1 JOIN customers_and_services AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_details ORDER BY count(*) DESC LIMIT 1 | extra |
366 | government_shift | [
"customers",
"customers_and_services"
] | return the details of the customer with largest count of used services. | select t1.customer_details from customers as t1 join customers_and_services as t2 on t1.customer_id = t2.customer_id group by t1.customer_details order by count(*) desc limit 1 | extra |
367 | government_shift | [
"customers",
"customers_and_services"
] | Find the name of the customer who has used the most types of services . | select t1.customer_details from customers as t1 join customers_and_services as t2 on t1.customer_id = t2.customer_id group by t1.customer_details order by count(*) desc limit 1 | extra |
368 | government_shift | [
"customers",
"customers_and_services"
] | Which customer has used the most types of services ? Give me the customer details . | select t1.customer_details from customers as t1 join customers_and_services as t2 on t1.customer_id = t2.customer_id group by t1.customer_details order by count(*) desc limit 1 | extra |
369 | government_shift | [
"customers",
"customers_and_services"
] | Find the details of the customer who has never used any services . | select customer_details from customers where customer_id not in (select customer_id from customers_and_services) | hard |
370 | government_shift | [
"customers",
"customers_and_services"
] | Which customers never used any services ? Give me the customer details . | select customer_details from customers where customer_id not in (select customer_id from customers_and_services) | hard |
371 | government_shift | [
"customers",
"services",
"customers_and_services"
] | Find the details of the customers who have used the least-used service . | select distinct t1.customer_details from customers as t1 join customers_and_services as t2 on t1.customer_id = t2.customer_id where t2.service_id = (select service_id from services group by service_id order by count(*) asc limit 1) | extra |
372 | government_shift | [
"customers",
"services",
"customers_and_services"
] | Which customers used the least commonly-used service ? Give me the distinct customer details . | select distinct t1.customer_details from customers as t1 join customers_and_services as t2 on t1.customer_id = t2.customer_id where t2.service_id = (select service_id from services group by service_id order by count(*) asc limit 1) | extra |
373 | government_shift | [
"customers_and_services"
] | How many distinct customer and services details are there? | SELECT count(DISTINCT customers_and_services_details) FROM customers_and_services | easy |
374 | government_shift | [
"customers_and_services"
] | Count the total number of available customers and services details. | SELECT count(DISTINCT customers_and_services_details) FROM customers_and_services | easy |
375 | government_shift | [
"customers"
] | Find all the customers whose name contains "Kutch". | SELECT customer_details FROM customers WHERE customer_details LIKE "%Kutch%" | medium |
376 | government_shift | [
"customers"
] | What are the details of the customers who have "Kutch" in part of their details? | SELECT customer_details FROM customers WHERE customer_details LIKE "%Kutch%" | medium |
377 | government_shift | [
"services",
"customer_interactions",
"customers",
"customers_and_services"
] | Find the name of all the services which either have been used by customer "Hardy Kutch" or have been rated as "good" in one of the customer interactions. | SELECT DISTINCT t3.service_details FROM customers AS t1 JOIN customers_and_services AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id JOIN customer_interactions AS t4 ON t3.service_id = t4.service_id WHERE t1.customer_details = "Hardy Kutch" OR t4.services_and_channels_details = "good" | extra |
378 | government_shift | [
"services",
"customer_interactions",
"customers",
"customers_and_services"
] | Which services are used by the customer "Hardy Kutch" or are rated as "good" in a customer interaction? Give me the service details. | SELECT DISTINCT t3.service_details FROM customers AS t1 JOIN customers_and_services AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id JOIN customer_interactions AS t4 ON t3.service_id = t4.service_id WHERE t1.customer_details = "Hardy Kutch" OR t4.services_and_channels_details = "good" | extra |
379 | government_shift | [
"services",
"customer_interactions",
"customers",
"customers_and_services"
] | Find the names of all the services which both have been used by customer "Hardy Kutch" and have been rated "bad" in one of the customer interactions. | SELECT DISTINCT t3.service_details FROM customers AS t1 JOIN customers_and_services AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id JOIN customer_interactions AS t4 ON t3.service_id = t4.service_id WHERE t1.customer_details = "Hardy Kutch" AND t4.services_and_channels_details = "bad" | extra |
380 | government_shift | [
"services",
"customer_interactions",
"customers",
"customers_and_services"
] | Which services are both used by the customer "Hardy Kutch" and are rated as "bad" in a customer interaction? Give me the service details. | SELECT DISTINCT t3.service_details FROM customers AS t1 JOIN customers_and_services AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id JOIN customer_interactions AS t4 ON t3.service_id = t4.service_id WHERE t1.customer_details = "Hardy Kutch" AND t4.services_and_channels_details = "bad" | extra |
381 | government_shift | [
"customer_interactions",
"channels",
"services"
] | Find details of all the services that have interacted with `` 15 ij '' for the the channel details. | select distinct t1.service_details from services as t1 join customer_interactions as t2 on t1.service_id = t2.service_id join channels as t3 on t2.channel_id = t3.channel_id where t3.channel_details = "15 ij" | hard |
382 | government_shift | [
"customer_interactions",
"channels",
"services"
] | Give me the details of all the services that have interacted with the channel with detail "15 ij". | SELECT DISTINCT t1.service_details FROM services AS t1 JOIN customer_interactions AS t2 ON t1.service_id = t2.service_id JOIN channels AS t3 ON t2.channel_id = t3.channel_id WHERE t3.channel_details = "15 ij" | hard |
383 | government_shift | [
"customer_interactions",
"customers"
] | Find all the details of the customers who have been involved in an interaction with status `` Stuck '' and service and channel detail `` bad '' . | select t1.customer_details from customers as t1 join customer_interactions as t2 on t1.customer_id = t2.customer_id where t2.status_code = "stuck" and services_and_channels_details = "bad" | medium |
384 | government_shift | [
"customer_interactions",
"customers"
] | Which customers have experienced status "Stuck" and service and channel detail "bad" in an interaction? Give me the customer details. | SELECT t1.customer_details FROM customers AS t1 JOIN customer_interactions AS t2 ON t1.customer_id = t2.customer_id WHERE t2.status_code = "Stuck" AND services_and_channels_details = "bad" | medium |
385 | government_shift | [
"integration_platform"
] | How many integration platforms are successful? | SELECT count(*) FROM integration_platform WHERE integration_platform_details = "Success" | easy |
386 | government_shift | [
"integration_platform"
] | Count the number of integration platforms that have "Success" in the details. | SELECT count(*) FROM integration_platform WHERE integration_platform_details = "Success" | easy |
387 | government_shift | [
"customer_interactions",
"customers",
"integration_platform"
] | List the details of all the customers who are associated with a failed integration platform . | select distinct t1.customer_details from customers as t1 join customer_interactions as t2 on t1.customer_id = t2.customer_id join integration_platform as t3 where t3.integration_platform_details = "fail" | hard |
388 | government_shift | [
"customer_interactions",
"customers",
"integration_platform"
] | Which customers have integration platform details "Fail" in interactions? Give me the customer details. | SELECT DISTINCT t1.customer_details FROM customers AS t1 JOIN customer_interactions AS t2 ON t1.customer_id = t2.customer_id JOIN integration_platform AS t3 WHERE t3.integration_platform_details = "Fail" | hard |
389 | government_shift | [
"services",
"customers_and_services"
] | Which service ( s ) has never been used by any customer ? List their details . | select service_details from services except select t2.service_details from customers_and_services as t1 join services as t2 on t1.service_id = t2.service_id | hard |
390 | government_shift | [
"services",
"customers_and_services"
] | Find details of the services that no customer has ever used . Return the service details . | select service_details from services except select t2.service_details from customers_and_services as t1 join services as t2 on t1.service_id = t2.service_id | hard |
391 | government_shift | [
"analytical_layer"
] | Find all the layer type codes with their corresponding usage count. | SELECT analytical_layer_type_code , count(*) FROM analytical_layer GROUP BY analytical_layer_type_code | medium |
392 | government_shift | [
"analytical_layer"
] | For each analytical layer, return the analytical layer type code and the number of times it was used. | SELECT analytical_layer_type_code , count(*) FROM analytical_layer GROUP BY analytical_layer_type_code | medium |
393 | government_shift | [
"services",
"customers_and_services"
] | Find details of all the services that have been marked as `` unsatisfied '' in customers and services details . | select distinct t1.service_details from services as t1 join customers_and_services as t2 on t1.service_id = t2.service_id where t2.customers_and_services_details = "unsatisfied" | medium |
394 | government_shift | [
"services",
"customers_and_services"
] | Which services have been rated as "unsatisfied" in customers and services details? Give me the service_details. | SELECT DISTINCT t1.service_details FROM services AS t1 JOIN customers_and_services AS t2 ON t1.service_id = t2.service_id WHERE t2.customers_and_services_details = "Unsatisfied" | medium |
395 | vehicle_rent | [
"vehicles"
] | How many vehicles do we have? | SELECT count(*) FROM vehicles | easy |
396 | vehicle_rent | [
"vehicles"
] | Count the number of vehicles. | SELECT count(*) FROM vehicles | easy |
397 | vehicle_rent | [
"vehicles"
] | Show names for all vehicles in descending order of model year. | SELECT name FROM vehicles ORDER BY model_year DESC | easy |
398 | vehicle_rent | [
"vehicles"
] | What are the names of all vehicles, ordered by model year descending? | SELECT name FROM vehicles ORDER BY model_year DESC | easy |
399 | vehicle_rent | [
"vehicles"
] | List all distinct types of powertrain of vehicles. | SELECT DISTINCT type_of_powertrain FROM vehicles | easy |
Subsets and Splits