target-benchmark/spider-queries · Datasets at Hugging Face

query_id int64 0 2.15k	database_id stringclasses 40 values	table_id listlengths 1 4	query stringlengths 22 185	answer stringlengths 22 608	difficulty stringclasses 4 values
0	soccer_3	[ "club" ]	How many clubs are there?	SELECT count(*) FROM club	easy
1	soccer_3	[ "club" ]	Count the number of clubs.	SELECT count(*) FROM club	easy
2	soccer_3	[ "club" ]	List the name of clubs in ascending alphabetical order.	SELECT Name FROM club ORDER BY Name ASC	easy
3	soccer_3	[ "club" ]	What are the names of clubs, ordered alphabetically?	SELECT Name FROM club ORDER BY Name ASC	easy
4	soccer_3	[ "club" ]	What are the managers and captains of clubs?	SELECT Manager , Captain FROM club	medium
5	soccer_3	[ "club" ]	Return the managers and captains of all clubs.	SELECT Manager , Captain FROM club	medium
6	soccer_3	[ "club" ]	List the name of clubs whose manufacturer is not "Nike"	SELECT Name FROM club WHERE Manufacturer != "Nike"	easy
7	soccer_3	[ "club" ]	What are the names of clubs who do not have the manufacturer Nike?	SELECT Name FROM club WHERE Manufacturer != "Nike"	easy
8	soccer_3	[ "player" ]	What are the names of players in ascending order of wins count?	SELECT Name FROM player ORDER BY Wins_count ASC	easy
9	soccer_3	[ "player" ]	Return the names of players in order of count of wins, ascending.	SELECT Name FROM player ORDER BY Wins_count ASC	easy
10	soccer_3	[ "player" ]	What is the name of the player with the highest earnings?	SELECT Name FROM player ORDER BY Earnings DESC LIMIT 1	medium
11	soccer_3	[ "player" ]	Return the name of the player who earns the most money.	SELECT Name FROM player ORDER BY Earnings DESC LIMIT 1	medium
12	soccer_3	[ "player" ]	What are the distinct countries of players with earnings higher than 1200000?	SELECT DISTINCT Country FROM player WHERE Earnings > 1200000	easy
13	soccer_3	[ "player" ]	From which countries are players who make more than 1200000 from?	SELECT DISTINCT Country FROM player WHERE Earnings > 1200000	easy
14	soccer_3	[ "player" ]	What is the country of the player with the highest earnings among players that have more than 2 win counts?	SELECT Country FROM player WHERE Wins_count > 2 ORDER BY Earnings DESC LIMIT 1	hard
15	soccer_3	[ "player" ]	Of players who have more than 2 wins, what is the country of the player who makes the most?	SELECT Country FROM player WHERE Wins_count > 2 ORDER BY Earnings DESC LIMIT 1	hard
16	soccer_3	[ "club", "player" ]	Show names of players and names of clubs they are in.	SELECT T2.Name , T1.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID	medium
17	soccer_3	[ "club", "player" ]	What are the names of players and the corresponding clubs that they are in?	SELECT T2.Name , T1.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID	medium
18	soccer_3	[ "club", "player" ]	Show names of clubs that have players with more than 2 win counts.	SELECT T1.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID WHERE T2.Wins_count > 2	medium
19	soccer_3	[ "club", "player" ]	What are the names of clubs that have players who have won more than twice?	SELECT T1.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID WHERE T2.Wins_count > 2	medium
20	soccer_3	[ "club", "player" ]	Show names of players from the club with manager "Sam Allardyce".	SELECT T2.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID WHERE T1.Manager = "Sam Allardyce"	medium
21	soccer_3	[ "club", "player" ]	What are the names of players from the club managed by Sam Allardyce?	SELECT T2.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID WHERE T1.Manager = "Sam Allardyce"	medium
22	soccer_3	[ "club", "player" ]	Show names of clubs in descending order of average earnings of players belonging.	SELECT T1.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID GROUP BY T1.Club_ID ORDER BY avg(T2.Earnings) DESC	hard
23	soccer_3	[ "club", "player" ]	What are the names of clubs, ordered descending by the average earnings of players within each?	SELECT T1.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID GROUP BY T1.Club_ID ORDER BY avg(T2.Earnings) DESC	hard
24	soccer_3	[ "club" ]	Show different manufacturers and the number of clubs they are associated with.	SELECT Manufacturer , COUNT(*) FROM club GROUP BY Manufacturer	medium
25	soccer_3	[ "club" ]	How many clubs use each manufacturer?	SELECT Manufacturer , COUNT(*) FROM club GROUP BY Manufacturer	medium
26	soccer_3	[ "club" ]	Please show the most common manufacturer of clubs.	SELECT Manufacturer FROM club GROUP BY Manufacturer ORDER BY COUNT(*) DESC LIMIT 1	hard
27	soccer_3	[ "club" ]	Which manufacturer is most common among clubs?	SELECT Manufacturer FROM club GROUP BY Manufacturer ORDER BY COUNT(*) DESC LIMIT 1	hard
28	soccer_3	[ "club" ]	List the manufacturers that are associated with more than one club.	SELECT Manufacturer FROM club GROUP BY Manufacturer HAVING COUNT(*) > 1	easy
29	soccer_3	[ "club" ]	Which manufacturers work for more than 1 club?	SELECT Manufacturer FROM club GROUP BY Manufacturer HAVING COUNT(*) > 1	easy
30	soccer_3	[ "player" ]	List the country that have more than one player.	SELECT Country FROM player GROUP BY Country HAVING COUNT(*) > 1	easy
31	soccer_3	[ "player" ]	Which countries have produced more than one player?	SELECT Country FROM player GROUP BY Country HAVING COUNT(*) > 1	easy
32	soccer_3	[ "club", "player" ]	List the name of clubs that do not have players.	SELECT Name FROM club WHERE Club_ID NOT IN (SELECT Club_ID FROM player)	hard
33	soccer_3	[ "club", "player" ]	What are the names of clubs that do not have any players?	SELECT Name FROM club WHERE Club_ID NOT IN (SELECT Club_ID FROM player)	hard
34	soccer_3	[ "player" ]	Show the country of players with earnings more than 1400000 and players with earnings less than 1100000.	SELECT Country FROM player WHERE Earnings > 1400000 INTERSECT SELECT Country FROM player WHERE Earnings < 1100000	hard
35	soccer_3	[ "player" ]	Which country has produced both players with earnings over 1400000 and players with earnings below 1100000?	SELECT Country FROM player WHERE Earnings > 1400000 INTERSECT SELECT Country FROM player WHERE Earnings < 1100000	hard
36	soccer_3	[ "player" ]	What is the number of distinct countries of all players?	SELECT COUNT (DISTINCT Country) FROM player	easy
37	soccer_3	[ "player" ]	How many different countries are players from?	SELECT COUNT (DISTINCT Country) FROM player	easy
38	soccer_3	[ "player" ]	Show the earnings of players from country "Australia" or "Zimbabwe".	SELECT Earnings FROM player WHERE Country = "Australia" OR Country = "Zimbabwe"	medium
39	soccer_3	[ "player" ]	What are the earnings of players from either of the countries of Australia or Zimbabwe?	SELECT Earnings FROM player WHERE Country = "Australia" OR Country = "Zimbabwe"	medium
40	e_commerce	[ "order_items", "orders", "customers" ]	List the id, first name and last name of the customers who both have placed more than 2 orders and have bought at least 3 items.	SELECT T1.customer_id , T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count() > 2 INTERSECT SELECT T1.customer_id , T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id JOIN Order_items AS T3 ON T2.order_id = T3.order_id GROUP BY T1.customer_id HAVING count() >= 3	extra
41	e_commerce	[ "order_items", "orders", "customers" ]	What are the ids, first and last names of the customers who have ordered more than twice and have bought at least 3 items?	SELECT T1.customer_id , T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count() > 2 INTERSECT SELECT T1.customer_id , T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id JOIN Order_items AS T3 ON T2.order_id = T3.order_id GROUP BY T1.customer_id HAVING count() >= 3	extra
42	e_commerce	[ "order_items", "orders" ]	For the orders with any produts, how many products does each orders contain ? List the order id, status and the number.	SELECT T1.order_id , T1.order_status_code , count(*) FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id	medium
43	e_commerce	[ "order_items", "orders" ]	For every order, how many products does it contain, and what are the orders' statuses and ids?	SELECT T1.order_id , T1.order_status_code , count(*) FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id	medium
44	e_commerce	[ "order_items", "orders" ]	List the dates of the orders which were placed at the earliest time or have more than 1 items.	SELECT min(date_order_placed) FROM Orders UNION SELECT T1.date_order_placed FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id HAVING count(*) > 1	hard
45	e_commerce	[ "order_items", "orders" ]	What are the dates of the earliest order and the dates of all orders with more than 1 item?	SELECT min(date_order_placed) FROM Orders UNION SELECT T1.date_order_placed FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id HAVING count(*) > 1	hard
46	e_commerce	[ "orders", "customers" ]	Which customers did not make any orders? List the first name, middle initial and last name.	SELECT customer_first_name , customer_middle_initial , customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name , T1.customer_middle_initial , T1.customer_last_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id	extra
47	e_commerce	[ "orders", "customers" ]	WHat are the first and last names, and middle initials of all customers who did not make any orders?	SELECT customer_first_name , customer_middle_initial , customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name , T1.customer_middle_initial , T1.customer_last_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id	extra
48	e_commerce	[ "order_items", "orders", "products" ]	What are the id, name, price and color of the products which have not been ordered for at least twice?	SELECT product_id , product_name , product_price , product_color FROM Products EXCEPT SELECT T1.product_id , T1.product_name , T1.product_price , T1.product_color FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Orders AS T3 ON T2.order_id = T3.order_id GROUP BY T1.product_id HAVING count(*) >= 2	extra
49	e_commerce	[ "orders", "products", "order_items" ]	What are the ids , names , prices , and colors of all products that have been listed in less than two orders ?	select t1.product_id , t1.product_name , t1.product_price , t1.product_color from products as t1 join order_items as t2 on t1.product_id = t2.product_id join orders as t3 on t2.order_id = t3.order_id group by t1.product_id having count(*) < 2	hard
50	e_commerce	[ "order_items", "orders" ]	Which orders have at least 2 products on it? List the order id and date.	SELECT T1.order_id , T1.date_order_placed FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id HAVING count(*) >= 2	medium
51	e_commerce	[ "order_items", "orders" ]	What are the ids and dates of the orders with at least two products?	SELECT T1.order_id , T1.date_order_placed FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id HAVING count(*) >= 2	medium
52	e_commerce	[ "order_items", "products" ]	Which product are listed in orders most frequently? List the id, product name and price.	SELECT T1.product_id , T1.product_name , T1.product_price FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_id ORDER BY count(*) DESC LIMIT 1	extra
53	e_commerce	[ "order_items", "products" ]	What are the ids, names, and prices of all products that are ordered most frequently?	SELECT T1.product_id , T1.product_name , T1.product_price FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_id ORDER BY count(*) DESC LIMIT 1	extra
54	e_commerce	[ "order_items", "products" ]	Which order have the least sum of the product prices. List the order id and sum.	SELECT T1.order_id , sum(T2.product_price) FROM Order_items AS T1 JOIN Products AS T2 ON T1.product_id = T2.product_id GROUP BY T1.order_id ORDER BY sum(T2.product_price) ASC LIMIT 1	extra
55	e_commerce	[ "products", "order_items" ]	What is the order that total cost the least , and how much is the total cost ?	select t1.order_id , sum(t2.product_price) from order_items as t1 join products as t2 on t1.product_id = t2.product_id group by t1.order_id order by sum(t2.product_price) asc limit 1	extra
56	e_commerce	[ "customer_payment_methods" ]	What is the most popular payment method?	SELECT Payment_method_code FROM Customer_Payment_Methods GROUP BY Payment_method_code ORDER BY count(*) DESC LIMIT 1	hard
57	e_commerce	[ "customer_payment_methods" ]	What is the payment method that most customers use?	SELECT Payment_method_code FROM Customer_Payment_Methods GROUP BY Payment_method_code ORDER BY count(*) DESC LIMIT 1	hard
58	e_commerce	[ "order_items", "orders", "customers" ]	How many number of products does each gender of customers buy? List the gender and the number	SELECT T1.gender_code , count(*) FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id JOIN Order_items AS T3 ON T2.order_id = T3.order_id GROUP BY T1.gender_code	hard
59	e_commerce	[ "order_items", "orders", "customers" ]	How many products does each gender buy?	SELECT T1.gender_code , count(*) FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id JOIN Order_items AS T3 ON T2.order_id = T3.order_id GROUP BY T1.gender_code	hard
60	e_commerce	[ "orders", "customers" ]	How many orders has each gender of customers placed?	SELECT T1.gender_code , count(*) FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.gender_code	medium
61	e_commerce	[ "orders", "customers" ]	How many orders has each gender placed?	SELECT T1.gender_code , count(*) FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.gender_code	medium
62	e_commerce	[ "customer_payment_methods", "customers" ]	List the customers' first name, middle initial, last name and payment methods.	SELECT T1.customer_first_name , T1.customer_middle_initial , T1.customer_last_name , T2.Payment_method_code FROM Customers AS T1 JOIN Customer_Payment_Methods AS T2 ON T1.customer_id = T2.customer_id	medium
63	e_commerce	[ "customer_payment_methods", "customers" ]	What are the first names, middle initials, last names, and payment methods of all customers?	SELECT T1.customer_first_name , T1.customer_middle_initial , T1.customer_last_name , T2.Payment_method_code FROM Customers AS T1 JOIN Customer_Payment_Methods AS T2 ON T1.customer_id = T2.customer_id	medium
64	e_commerce	[ "shipments", "invoices" ]	List the invoices' status, date and the date of shipment.	SELECT T1.invoice_status_code , T1.invoice_date , T2.shipment_date FROM Invoices AS T1 JOIN Shipments AS T2 ON T1.invoice_number = T2.invoice_number	medium
65	e_commerce	[ "shipments", "invoices" ]	What are the statuses, dates, and shipment dates for all invoices?	SELECT T1.invoice_status_code , T1.invoice_date , T2.shipment_date FROM Invoices AS T1 JOIN Shipments AS T2 ON T1.invoice_number = T2.invoice_number	medium
66	e_commerce	[ "order_items", "products", "shipments", "shipment_items" ]	List the names of the products being shipped and the corresponding shipment date.	SELECT T1.product_name , T4.shipment_date FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Shipment_Items AS T3 ON T2.order_item_id = T3.order_item_id JOIN Shipments AS T4 ON T3.shipment_id = T4.shipment_id	hard
67	e_commerce	[ "order_items", "products", "shipments", "shipment_items" ]	What are the names of the products tht have been shipped, and on what days were they shipped?	SELECT T1.product_name , T4.shipment_date FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Shipment_Items AS T3 ON T2.order_item_id = T3.order_item_id JOIN Shipments AS T4 ON T3.shipment_id = T4.shipment_id	hard
68	e_commerce	[ "order_items", "shipments", "shipment_items" ]	What is the status code of the items being ordered and shipped and its corresponding shipment tracking number?	SELECT T1.order_item_status_code , T3.shipment_tracking_number FROM Order_items AS T1 JOIN Shipment_Items AS T2 ON T1.order_item_id = T2.order_item_id JOIN Shipments AS T3 ON T2.shipment_id = T3.shipment_id	medium
69	e_commerce	[ "order_items", "shipments", "shipment_items" ]	What is the status code of the items have been ordered and shipped, and also what are their shipment tracking numbers?	SELECT T1.order_item_status_code , T3.shipment_tracking_number FROM Order_items AS T1 JOIN Shipment_Items AS T2 ON T1.order_item_id = T2.order_item_id JOIN Shipments AS T3 ON T2.shipment_id = T3.shipment_id	medium
70	e_commerce	[ "order_items", "products", "shipments", "shipment_items" ]	What is the product name and the color of the ordered items which have been shipped?	SELECT T1.product_name , T1.product_color FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Shipment_Items AS T3 ON T2.order_item_id = T3.order_item_id JOIN Shipments AS T4 ON T3.shipment_id = T4.shipment_id	hard
71	e_commerce	[ "order_items", "products", "shipments", "shipment_items" ]	What are the names and colors of all products that have been shipped?	SELECT T1.product_name , T1.product_color FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Shipment_Items AS T3 ON T2.order_item_id = T3.order_item_id JOIN Shipments AS T4 ON T3.shipment_id = T4.shipment_id	hard
72	e_commerce	[ "order_items", "orders", "products", "customers" ]	List all the distinct product names, price and descriptions which are bought by female customers.	SELECT DISTINCT T1.product_name , T1.product_price , T1.product_description FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Orders AS T3 ON T2.order_id = T3.order_id JOIN Customers AS T4 ON T3.customer_id = T4.customer_id WHERE T4.gender_code = 'Female'	extra
73	e_commerce	[ "order_items", "orders", "products", "customers" ]	What are the different names, prices, and descriptions for all products bought by female customers?	SELECT DISTINCT T1.product_name , T1.product_price , T1.product_description FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Orders AS T3 ON T2.order_id = T3.order_id JOIN Customers AS T4 ON T3.customer_id = T4.customer_id WHERE T4.gender_code = 'Female'	extra
74	e_commerce	[ "shipments", "invoices" ]	What are invoices status of all the orders which have not been shipped?	SELECT invoice_status_code FROM Invoices WHERE invoice_number NOT IN ( SELECT invoice_number FROM Shipments )	hard
75	e_commerce	[ "shipments", "invoices" ]	What are the invoice statuses for all orderes that have not been shipped out yet?	SELECT invoice_status_code FROM Invoices WHERE invoice_number NOT IN ( SELECT invoice_number FROM Shipments )	hard
76	e_commerce	[ "orders", "products", "order_items" ]	What are the total cost of all the orders ? List the order id , date , and total cost .	select t1.order_id , t1.date_order_placed , sum(t3.product_price) from orders as t1 join order_items as t2 on t1.order_id = t2.order_id join products as t3 on t2.product_id = t3.product_id group by t1.order_id	hard
77	e_commerce	[ "order_items", "orders", "products" ]	For each order, what is its id, date, and total amount paid?	SELECT T1.order_id , T1.date_order_placed , sum(T3.product_price) FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id JOIN Products AS T3 ON T2.product_id = T3.product_id GROUP BY T1.order_id	hard
78	e_commerce	[ "orders" ]	How many customers have placed any order?	SELECT count(DISTINCT customer_id) FROM Orders	easy
79	e_commerce	[ "orders" ]	How many different customers have ordered things?	SELECT count(DISTINCT customer_id) FROM Orders	easy
80	e_commerce	[ "order_items" ]	How many item states are there in the orders?	SELECT count(DISTINCT order_item_status_code) FROM Order_items	easy
81	e_commerce	[ "order_items" ]	How many different item status codes are there listed in ordered items?	SELECT count(DISTINCT order_item_status_code) FROM Order_items	easy
82	e_commerce	[ "customer_payment_methods" ]	How many different payment methods are there?	SELECT count(DISTINCT Payment_method_code) FROM Customer_Payment_Methods	easy
83	e_commerce	[ "customer_payment_methods" ]	How many different payment methods can customers choose from?	SELECT count(DISTINCT Payment_method_code) FROM Customer_Payment_Methods	easy
84	e_commerce	[ "customers" ]	What are the login names and passwords of the customers whose phone number have the prefix '+12'?	SELECT login_name , login_password FROM Customers WHERE phone_number LIKE '+12%'	medium
85	e_commerce	[ "customers" ]	What are the usernames and passwords of all customers whose phone number starts with '+12'?	SELECT login_name , login_password FROM Customers WHERE phone_number LIKE '+12%'	medium
86	e_commerce	[ "products" ]	What are the product sizes of the products whose name has the substring 'Dell'?	SELECT product_size FROM Products WHERE product_name LIKE '%Dell%'	medium
87	e_commerce	[ "products" ]	What are the sizes of all products whose name includes the word 'Dell'?	SELECT product_size FROM Products WHERE product_name LIKE '%Dell%'	medium
88	e_commerce	[ "products" ]	What are the product price and the product size of the products whose price is above average?	SELECT product_price , product_size FROM Products WHERE product_price > ( SELECT avg(product_price) FROM Products )	extra
89	e_commerce	[ "products" ]	What are the prices and sizes of all products whose price is above the mean?	SELECT product_price , product_size FROM Products WHERE product_price > ( SELECT avg(product_price) FROM Products )	extra
90	e_commerce	[ "order_items", "products" ]	How many kinds of products have not been sold?	SELECT count(*) FROM Products WHERE product_id NOT IN ( SELECT product_id FROM Order_items )	extra
91	e_commerce	[ "order_items", "products" ]	What is the number of products that have not been ordered yet?	SELECT count(*) FROM Products WHERE product_id NOT IN ( SELECT product_id FROM Order_items )	extra
92	e_commerce	[ "customer_payment_methods", "customers" ]	How many customers do not have any payment method?	SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payment_Methods )	extra
93	e_commerce	[ "customer_payment_methods", "customers" ]	How many customers do not have a listed payment method?	SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payment_Methods )	extra
94	e_commerce	[ "orders" ]	What are all the order status and all the dates of orders?	SELECT order_status_code , date_order_placed FROM Orders	medium
95	e_commerce	[ "orders" ]	What are the status codes and dates placed for all of the orders?	SELECT order_status_code , date_order_placed FROM Orders	medium
96	e_commerce	[ "customers" ]	List the address, town and county information of the customers who live in the USA.	SELECT address_line_1 , town_city , county FROM Customers WHERE Country = 'USA'	medium
97	e_commerce	[ "customers" ]	What are the addresses, towns, and county information for all customers who live in the United States?	SELECT address_line_1 , town_city , county FROM Customers WHERE Country = 'USA'	medium
98	e_commerce	[ "order_items", "orders", "products", "customers" ]	List all the pairs of buyer first names and product names.	SELECT T1.customer_first_name , T4.product_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id JOIN Order_items AS T3 ON T2.order_id = T3.order_id JOIN Products AS T4 ON T3.product_id = T4.product_id	hard
99	e_commerce	[ "order_items", "orders", "products", "customers" ]	What are the first names of all buyers and what products did they buy? List them in pairs.	SELECT T1.customer_first_name , T4.product_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id JOIN Order_items AS T3 ON T2.order_id = T3.order_id JOIN Products AS T4 ON T3.product_id = T4.product_id	hard

0

soccer_3

[ "club" ]

How many clubs are there?

SELECT count(*) FROM club

easy

1

soccer_3

[ "club" ]

Count the number of clubs.

SELECT count(*) FROM club

easy

2

soccer_3

[ "club" ]

List the name of clubs in ascending alphabetical order.

SELECT Name FROM club ORDER BY Name ASC

easy

3

soccer_3

[ "club" ]

What are the names of clubs, ordered alphabetically?

SELECT Name FROM club ORDER BY Name ASC

easy

4

soccer_3

[ "club" ]

What are the managers and captains of clubs?

SELECT Manager , Captain FROM club

medium

5

soccer_3

[ "club" ]

Return the managers and captains of all clubs.

SELECT Manager , Captain FROM club

medium

6

soccer_3

[ "club" ]

List the name of clubs whose manufacturer is not "Nike"

SELECT Name FROM club WHERE Manufacturer != "Nike"

easy

7

soccer_3

[ "club" ]

What are the names of clubs who do not have the manufacturer Nike?

SELECT Name FROM club WHERE Manufacturer != "Nike"

easy

8

soccer_3

[ "player" ]

What are the names of players in ascending order of wins count?

SELECT Name FROM player ORDER BY Wins_count ASC

easy

9

soccer_3

[ "player" ]

Return the names of players in order of count of wins, ascending.

SELECT Name FROM player ORDER BY Wins_count ASC

easy

10

soccer_3

[ "player" ]

What is the name of the player with the highest earnings?

SELECT Name FROM player ORDER BY Earnings DESC LIMIT 1

medium

11

soccer_3

[ "player" ]

Return the name of the player who earns the most money.

SELECT Name FROM player ORDER BY Earnings DESC LIMIT 1

medium

12

soccer_3

[ "player" ]

What are the distinct countries of players with earnings higher than 1200000?

SELECT DISTINCT Country FROM player WHERE Earnings > 1200000

easy

13

soccer_3

[ "player" ]

From which countries are players who make more than 1200000 from?

SELECT DISTINCT Country FROM player WHERE Earnings > 1200000

easy

14

soccer_3

[ "player" ]

What is the country of the player with the highest earnings among players that have more than 2 win counts?

SELECT Country FROM player WHERE Wins_count > 2 ORDER BY Earnings DESC LIMIT 1

hard

15

soccer_3

[ "player" ]

Of players who have more than 2 wins, what is the country of the player who makes the most?

SELECT Country FROM player WHERE Wins_count > 2 ORDER BY Earnings DESC LIMIT 1

hard

16

soccer_3

[ "club", "player" ]

Show names of players and names of clubs they are in.

SELECT T2.Name , T1.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID

medium

17

soccer_3

[ "club", "player" ]

What are the names of players and the corresponding clubs that they are in?

SELECT T2.Name , T1.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID

medium

18

soccer_3

[ "club", "player" ]

Show names of clubs that have players with more than 2 win counts.

SELECT T1.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID WHERE T2.Wins_count > 2

medium

19

soccer_3

[ "club", "player" ]

What are the names of clubs that have players who have won more than twice?

SELECT T1.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID WHERE T2.Wins_count > 2

medium

20

soccer_3

[ "club", "player" ]

Show names of players from the club with manager "Sam Allardyce".

SELECT T2.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID WHERE T1.Manager = "Sam Allardyce"

medium

21

soccer_3

[ "club", "player" ]

What are the names of players from the club managed by Sam Allardyce?

SELECT T2.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID WHERE T1.Manager = "Sam Allardyce"

medium

22

soccer_3

[ "club", "player" ]

Show names of clubs in descending order of average earnings of players belonging.

SELECT T1.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID GROUP BY T1.Club_ID ORDER BY avg(T2.Earnings) DESC

hard

23

soccer_3

[ "club", "player" ]

What are the names of clubs, ordered descending by the average earnings of players within each?

SELECT T1.Name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID GROUP BY T1.Club_ID ORDER BY avg(T2.Earnings) DESC

hard

24

soccer_3

[ "club" ]

Show different manufacturers and the number of clubs they are associated with.

SELECT Manufacturer , COUNT(*) FROM club GROUP BY Manufacturer

medium

25

soccer_3

[ "club" ]

How many clubs use each manufacturer?

SELECT Manufacturer , COUNT(*) FROM club GROUP BY Manufacturer

medium

26

soccer_3

[ "club" ]

Please show the most common manufacturer of clubs.

SELECT Manufacturer FROM club GROUP BY Manufacturer ORDER BY COUNT(*) DESC LIMIT 1

hard

27

soccer_3

[ "club" ]

Which manufacturer is most common among clubs?

SELECT Manufacturer FROM club GROUP BY Manufacturer ORDER BY COUNT(*) DESC LIMIT 1

hard

28

soccer_3

[ "club" ]

List the manufacturers that are associated with more than one club.

SELECT Manufacturer FROM club GROUP BY Manufacturer HAVING COUNT(*) > 1

easy

29

soccer_3

[ "club" ]

Which manufacturers work for more than 1 club?

SELECT Manufacturer FROM club GROUP BY Manufacturer HAVING COUNT(*) > 1

easy

30

soccer_3

[ "player" ]

List the country that have more than one player.

SELECT Country FROM player GROUP BY Country HAVING COUNT(*) > 1

easy

31

soccer_3

[ "player" ]

Which countries have produced more than one player?

SELECT Country FROM player GROUP BY Country HAVING COUNT(*) > 1

easy

32

soccer_3

[ "club", "player" ]

List the name of clubs that do not have players.

SELECT Name FROM club WHERE Club_ID NOT IN (SELECT Club_ID FROM player)

hard

33

soccer_3

[ "club", "player" ]

What are the names of clubs that do not have any players?

SELECT Name FROM club WHERE Club_ID NOT IN (SELECT Club_ID FROM player)

hard

34

soccer_3

[ "player" ]

Show the country of players with earnings more than 1400000 and players with earnings less than 1100000.

SELECT Country FROM player WHERE Earnings > 1400000 INTERSECT SELECT Country FROM player WHERE Earnings < 1100000

hard

35

soccer_3

[ "player" ]

Which country has produced both players with earnings over 1400000 and players with earnings below 1100000?

SELECT Country FROM player WHERE Earnings > 1400000 INTERSECT SELECT Country FROM player WHERE Earnings < 1100000

hard

36

soccer_3

[ "player" ]

What is the number of distinct countries of all players?

SELECT COUNT (DISTINCT Country) FROM player

easy

37

soccer_3

[ "player" ]

How many different countries are players from?

SELECT COUNT (DISTINCT Country) FROM player

easy

38

soccer_3

[ "player" ]

Show the earnings of players from country "Australia" or "Zimbabwe".

SELECT Earnings FROM player WHERE Country = "Australia" OR Country = "Zimbabwe"

medium

39

soccer_3

[ "player" ]

What are the earnings of players from either of the countries of Australia or Zimbabwe?

SELECT Earnings FROM player WHERE Country = "Australia" OR Country = "Zimbabwe"

medium

40

e_commerce

[ "order_items", "orders", "customers" ]

List the id, first name and last name of the customers who both have placed more than 2 orders and have bought at least 3 items.

SELECT T1.customer_id , T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2 INTERSECT SELECT T1.customer_id , T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id JOIN Order_items AS T3 ON T2.order_id = T3.order_id GROUP BY T1.customer_id HAVING count(*) >= 3

extra

41

e_commerce

[ "order_items", "orders", "customers" ]

What are the ids, first and last names of the customers who have ordered more than twice and have bought at least 3 items?

SELECT T1.customer_id , T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2 INTERSECT SELECT T1.customer_id , T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id JOIN Order_items AS T3 ON T2.order_id = T3.order_id GROUP BY T1.customer_id HAVING count(*) >= 3

extra

42

e_commerce

[ "order_items", "orders" ]

For the orders with any produts, how many products does each orders contain ? List the order id, status and the number.

SELECT T1.order_id , T1.order_status_code , count(*) FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id

medium

43

e_commerce

[ "order_items", "orders" ]

For every order, how many products does it contain, and what are the orders' statuses and ids?

SELECT T1.order_id , T1.order_status_code , count(*) FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id

medium

44

e_commerce

[ "order_items", "orders" ]

List the dates of the orders which were placed at the earliest time or have more than 1 items.

SELECT min(date_order_placed) FROM Orders UNION SELECT T1.date_order_placed FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id HAVING count(*) > 1

hard

45

e_commerce

[ "order_items", "orders" ]

What are the dates of the earliest order and the dates of all orders with more than 1 item?

SELECT min(date_order_placed) FROM Orders UNION SELECT T1.date_order_placed FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id HAVING count(*) > 1

hard

46

e_commerce

[ "orders", "customers" ]

Which customers did not make any orders? List the first name, middle initial and last name.

SELECT customer_first_name , customer_middle_initial , customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name , T1.customer_middle_initial , T1.customer_last_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id

extra

47

e_commerce

[ "orders", "customers" ]

WHat are the first and last names, and middle initials of all customers who did not make any orders?

SELECT customer_first_name , customer_middle_initial , customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name , T1.customer_middle_initial , T1.customer_last_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id

extra

48

e_commerce

[ "order_items", "orders", "products" ]

What are the id, name, price and color of the products which have not been ordered for at least twice?

SELECT product_id , product_name , product_price , product_color FROM Products EXCEPT SELECT T1.product_id , T1.product_name , T1.product_price , T1.product_color FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Orders AS T3 ON T2.order_id = T3.order_id GROUP BY T1.product_id HAVING count(*) >= 2

extra

49

e_commerce

[ "orders", "products", "order_items" ]

What are the ids , names , prices , and colors of all products that have been listed in less than two orders ?

select t1.product_id , t1.product_name , t1.product_price , t1.product_color from products as t1 join order_items as t2 on t1.product_id = t2.product_id join orders as t3 on t2.order_id = t3.order_id group by t1.product_id having count(*) < 2

hard

50

e_commerce

[ "order_items", "orders" ]

Which orders have at least 2 products on it? List the order id and date.

SELECT T1.order_id , T1.date_order_placed FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id HAVING count(*) >= 2

medium

51

e_commerce

[ "order_items", "orders" ]

What are the ids and dates of the orders with at least two products?

SELECT T1.order_id , T1.date_order_placed FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id HAVING count(*) >= 2

medium

52

e_commerce

[ "order_items", "products" ]

Which product are listed in orders most frequently? List the id, product name and price.

SELECT T1.product_id , T1.product_name , T1.product_price FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_id ORDER BY count(*) DESC LIMIT 1

extra

53

e_commerce

[ "order_items", "products" ]

What are the ids, names, and prices of all products that are ordered most frequently?

SELECT T1.product_id , T1.product_name , T1.product_price FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_id ORDER BY count(*) DESC LIMIT 1

extra

54

e_commerce

[ "order_items", "products" ]

Which order have the least sum of the product prices. List the order id and sum.

SELECT T1.order_id , sum(T2.product_price) FROM Order_items AS T1 JOIN Products AS T2 ON T1.product_id = T2.product_id GROUP BY T1.order_id ORDER BY sum(T2.product_price) ASC LIMIT 1

extra

55

e_commerce

[ "products", "order_items" ]

What is the order that total cost the least , and how much is the total cost ?

select t1.order_id , sum(t2.product_price) from order_items as t1 join products as t2 on t1.product_id = t2.product_id group by t1.order_id order by sum(t2.product_price) asc limit 1

extra

56

e_commerce

[ "customer_payment_methods" ]

What is the most popular payment method?

SELECT Payment_method_code FROM Customer_Payment_Methods GROUP BY Payment_method_code ORDER BY count(*) DESC LIMIT 1

hard

57

e_commerce

[ "customer_payment_methods" ]

What is the payment method that most customers use?

SELECT Payment_method_code FROM Customer_Payment_Methods GROUP BY Payment_method_code ORDER BY count(*) DESC LIMIT 1

hard

58

e_commerce

[ "order_items", "orders", "customers" ]

How many number of products does each gender of customers buy? List the gender and the number

SELECT T1.gender_code , count(*) FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id JOIN Order_items AS T3 ON T2.order_id = T3.order_id GROUP BY T1.gender_code

hard

59

e_commerce

[ "order_items", "orders", "customers" ]

How many products does each gender buy?

SELECT T1.gender_code , count(*) FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id JOIN Order_items AS T3 ON T2.order_id = T3.order_id GROUP BY T1.gender_code

hard

60

e_commerce

[ "orders", "customers" ]

How many orders has each gender of customers placed?

SELECT T1.gender_code , count(*) FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.gender_code

medium

61

e_commerce

[ "orders", "customers" ]

How many orders has each gender placed?

SELECT T1.gender_code , count(*) FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.gender_code

medium

62

e_commerce

[ "customer_payment_methods", "customers" ]

List the customers' first name, middle initial, last name and payment methods.

SELECT T1.customer_first_name , T1.customer_middle_initial , T1.customer_last_name , T2.Payment_method_code FROM Customers AS T1 JOIN Customer_Payment_Methods AS T2 ON T1.customer_id = T2.customer_id

medium

63

e_commerce

[ "customer_payment_methods", "customers" ]

What are the first names, middle initials, last names, and payment methods of all customers?

SELECT T1.customer_first_name , T1.customer_middle_initial , T1.customer_last_name , T2.Payment_method_code FROM Customers AS T1 JOIN Customer_Payment_Methods AS T2 ON T1.customer_id = T2.customer_id

medium

64

e_commerce

[ "shipments", "invoices" ]

List the invoices' status, date and the date of shipment.

SELECT T1.invoice_status_code , T1.invoice_date , T2.shipment_date FROM Invoices AS T1 JOIN Shipments AS T2 ON T1.invoice_number = T2.invoice_number

medium

65

e_commerce

[ "shipments", "invoices" ]

What are the statuses, dates, and shipment dates for all invoices?

SELECT T1.invoice_status_code , T1.invoice_date , T2.shipment_date FROM Invoices AS T1 JOIN Shipments AS T2 ON T1.invoice_number = T2.invoice_number

medium

66

e_commerce

[ "order_items", "products", "shipments", "shipment_items" ]

List the names of the products being shipped and the corresponding shipment date.

SELECT T1.product_name , T4.shipment_date FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Shipment_Items AS T3 ON T2.order_item_id = T3.order_item_id JOIN Shipments AS T4 ON T3.shipment_id = T4.shipment_id

hard

67

e_commerce

[ "order_items", "products", "shipments", "shipment_items" ]

What are the names of the products tht have been shipped, and on what days were they shipped?

SELECT T1.product_name , T4.shipment_date FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Shipment_Items AS T3 ON T2.order_item_id = T3.order_item_id JOIN Shipments AS T4 ON T3.shipment_id = T4.shipment_id

hard

68

e_commerce

[ "order_items", "shipments", "shipment_items" ]

What is the status code of the items being ordered and shipped and its corresponding shipment tracking number?

SELECT T1.order_item_status_code , T3.shipment_tracking_number FROM Order_items AS T1 JOIN Shipment_Items AS T2 ON T1.order_item_id = T2.order_item_id JOIN Shipments AS T3 ON T2.shipment_id = T3.shipment_id

medium

69

e_commerce

[ "order_items", "shipments", "shipment_items" ]

What is the status code of the items have been ordered and shipped, and also what are their shipment tracking numbers?

SELECT T1.order_item_status_code , T3.shipment_tracking_number FROM Order_items AS T1 JOIN Shipment_Items AS T2 ON T1.order_item_id = T2.order_item_id JOIN Shipments AS T3 ON T2.shipment_id = T3.shipment_id

medium

70

e_commerce

[ "order_items", "products", "shipments", "shipment_items" ]

What is the product name and the color of the ordered items which have been shipped?

SELECT T1.product_name , T1.product_color FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Shipment_Items AS T3 ON T2.order_item_id = T3.order_item_id JOIN Shipments AS T4 ON T3.shipment_id = T4.shipment_id

hard

71

e_commerce

[ "order_items", "products", "shipments", "shipment_items" ]

What are the names and colors of all products that have been shipped?

SELECT T1.product_name , T1.product_color FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Shipment_Items AS T3 ON T2.order_item_id = T3.order_item_id JOIN Shipments AS T4 ON T3.shipment_id = T4.shipment_id

hard

72

e_commerce

[ "order_items", "orders", "products", "customers" ]

List all the distinct product names, price and descriptions which are bought by female customers.

SELECT DISTINCT T1.product_name , T1.product_price , T1.product_description FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Orders AS T3 ON T2.order_id = T3.order_id JOIN Customers AS T4 ON T3.customer_id = T4.customer_id WHERE T4.gender_code = 'Female'

extra

73

e_commerce

[ "order_items", "orders", "products", "customers" ]

What are the different names, prices, and descriptions for all products bought by female customers?

SELECT DISTINCT T1.product_name , T1.product_price , T1.product_description FROM Products AS T1 JOIN Order_items AS T2 ON T1.product_id = T2.product_id JOIN Orders AS T3 ON T2.order_id = T3.order_id JOIN Customers AS T4 ON T3.customer_id = T4.customer_id WHERE T4.gender_code = 'Female'

extra

74

e_commerce

[ "shipments", "invoices" ]

What are invoices status of all the orders which have not been shipped?

SELECT invoice_status_code FROM Invoices WHERE invoice_number NOT IN ( SELECT invoice_number FROM Shipments )

hard

75

e_commerce

[ "shipments", "invoices" ]

What are the invoice statuses for all orderes that have not been shipped out yet?

SELECT invoice_status_code FROM Invoices WHERE invoice_number NOT IN ( SELECT invoice_number FROM Shipments )

hard

76

e_commerce

[ "orders", "products", "order_items" ]

What are the total cost of all the orders ? List the order id , date , and total cost .

select t1.order_id , t1.date_order_placed , sum(t3.product_price) from orders as t1 join order_items as t2 on t1.order_id = t2.order_id join products as t3 on t2.product_id = t3.product_id group by t1.order_id

hard

77

e_commerce

[ "order_items", "orders", "products" ]

For each order, what is its id, date, and total amount paid?

SELECT T1.order_id , T1.date_order_placed , sum(T3.product_price) FROM Orders AS T1 JOIN Order_items AS T2 ON T1.order_id = T2.order_id JOIN Products AS T3 ON T2.product_id = T3.product_id GROUP BY T1.order_id

hard

78

e_commerce

[ "orders" ]

How many customers have placed any order?

SELECT count(DISTINCT customer_id) FROM Orders

easy

79

e_commerce

[ "orders" ]

How many different customers have ordered things?

SELECT count(DISTINCT customer_id) FROM Orders

easy

80

e_commerce

[ "order_items" ]

How many item states are there in the orders?

SELECT count(DISTINCT order_item_status_code) FROM Order_items

easy

81

e_commerce

[ "order_items" ]

How many different item status codes are there listed in ordered items?

SELECT count(DISTINCT order_item_status_code) FROM Order_items

easy

82

e_commerce

[ "customer_payment_methods" ]

How many different payment methods are there?

SELECT count(DISTINCT Payment_method_code) FROM Customer_Payment_Methods

easy

83

e_commerce

[ "customer_payment_methods" ]

How many different payment methods can customers choose from?

SELECT count(DISTINCT Payment_method_code) FROM Customer_Payment_Methods

easy

84

e_commerce

[ "customers" ]

What are the login names and passwords of the customers whose phone number have the prefix '+12'?

SELECT login_name , login_password FROM Customers WHERE phone_number LIKE '+12%'

medium

85

e_commerce

[ "customers" ]

What are the usernames and passwords of all customers whose phone number starts with '+12'?

SELECT login_name , login_password FROM Customers WHERE phone_number LIKE '+12%'

medium

86

e_commerce

[ "products" ]

What are the product sizes of the products whose name has the substring 'Dell'?

SELECT product_size FROM Products WHERE product_name LIKE '%Dell%'

medium

87

e_commerce

[ "products" ]

What are the sizes of all products whose name includes the word 'Dell'?

SELECT product_size FROM Products WHERE product_name LIKE '%Dell%'

medium

88

e_commerce

[ "products" ]

What are the product price and the product size of the products whose price is above average?

SELECT product_price , product_size FROM Products WHERE product_price > ( SELECT avg(product_price) FROM Products )

extra

89

e_commerce

[ "products" ]

What are the prices and sizes of all products whose price is above the mean?

SELECT product_price , product_size FROM Products WHERE product_price > ( SELECT avg(product_price) FROM Products )

extra

90

e_commerce

[ "order_items", "products" ]

How many kinds of products have not been sold?

SELECT count(*) FROM Products WHERE product_id NOT IN ( SELECT product_id FROM Order_items )

extra

91

e_commerce

[ "order_items", "products" ]

What is the number of products that have not been ordered yet?

SELECT count(*) FROM Products WHERE product_id NOT IN ( SELECT product_id FROM Order_items )

extra

92

e_commerce

[ "customer_payment_methods", "customers" ]

How many customers do not have any payment method?

SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payment_Methods )

extra

93

e_commerce

[ "customer_payment_methods", "customers" ]

How many customers do not have a listed payment method?

SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payment_Methods )

extra

94

e_commerce

[ "orders" ]

What are all the order status and all the dates of orders?

SELECT order_status_code , date_order_placed FROM Orders

medium

95

e_commerce

[ "orders" ]

What are the status codes and dates placed for all of the orders?

SELECT order_status_code , date_order_placed FROM Orders

medium

96

e_commerce

[ "customers" ]

List the address, town and county information of the customers who live in the USA.

SELECT address_line_1 , town_city , county FROM Customers WHERE Country = 'USA'

medium

97

e_commerce

[ "customers" ]

What are the addresses, towns, and county information for all customers who live in the United States?

SELECT address_line_1 , town_city , county FROM Customers WHERE Country = 'USA'

medium

98

e_commerce

[ "order_items", "orders", "products", "customers" ]

List all the pairs of buyer first names and product names.

SELECT T1.customer_first_name , T4.product_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id JOIN Order_items AS T3 ON T2.order_id = T3.order_id JOIN Products AS T4 ON T3.product_id = T4.product_id

hard

99

e_commerce

[ "order_items", "orders", "products", "customers" ]

What are the first names of all buyers and what products did they buy? List them in pairs.

SELECT T1.customer_first_name , T4.product_name FROM Customers AS T1 JOIN Orders AS T2 ON T1.customer_id = T2.customer_id JOIN Order_items AS T3 ON T2.order_id = T3.order_id JOIN Products AS T4 ON T3.product_id = T4.product_id

hard