query_id
int64
0
7k
database_id
stringclasses
140 values
table_id
sequencelengths
1
5
query
stringlengths
16
224
answer
stringlengths
18
577
difficulty
stringclasses
4 values
3,900
hospital_1
[ "department" ]
Tell me the employee id of the head of the department with the least employees.
SELECT head FROM department GROUP BY departmentID ORDER BY count(departmentID) LIMIT 1;
hard
3,901
hospital_1
[ "department", "physician" ]
what is the name and position of the head whose department has least number of employees?
SELECT T2.name , T2.position FROM department AS T1 JOIN physician AS T2 ON T1.head = T2.EmployeeID GROUP BY departmentID ORDER BY count(departmentID) LIMIT 1;
extra
3,902
hospital_1
[ "department", "physician" ]
Find the name and position of the head of the department with the least employees.
SELECT T2.name , T2.position FROM department AS T1 JOIN physician AS T2 ON T1.head = T2.EmployeeID GROUP BY departmentID ORDER BY count(departmentID) LIMIT 1;
extra
3,903
hospital_1
[ "patient", "appointment" ]
What are names of patients who made an appointment?
SELECT name FROM appointment AS T1 JOIN patient AS T2 ON T1.patient = T2.ssn
easy
3,904
hospital_1
[ "patient", "appointment" ]
List the names of patients who have made appointments.
SELECT name FROM appointment AS T1 JOIN patient AS T2 ON T1.patient = T2.ssn
easy
3,905
hospital_1
[ "patient", "appointment" ]
what are name and phone number of patients who had more than one appointment?
SELECT name , phone FROM appointment AS T1 JOIN patient AS T2 ON T1.patient = T2.ssn GROUP BY T1.patient HAVING count(*) > 1
medium
3,906
hospital_1
[ "patient", "appointment" ]
Which patients made more than one appointment? Tell me the name and phone number of these patients.
SELECT name , phone FROM appointment AS T1 JOIN patient AS T2 ON T1.patient = T2.ssn GROUP BY T1.patient HAVING count(*) > 1
medium
3,907
hospital_1
[ "appointment" ]
Find the id of the appointment with the most recent start date?
SELECT appointmentid FROM appointment ORDER BY START DESC LIMIT 1
medium
3,908
hospital_1
[ "appointment" ]
What is the id of the appointment that started most recently?
SELECT appointmentid FROM appointment ORDER BY START DESC LIMIT 1
medium
3,909
hospital_1
[ "appointment", "physician" ]
List the name of physicians who took some appointment.
SELECT T2.name FROM appointment AS T1 JOIN physician AS T2 ON T1.Physician = T2.EmployeeID
easy
3,910
hospital_1
[ "appointment", "physician" ]
What are the names of all the physicians who took appointments.
SELECT T2.name FROM appointment AS T1 JOIN physician AS T2 ON T1.Physician = T2.EmployeeID
easy
3,911
hospital_1
[ "appointment", "physician" ]
List the name of physicians who never took any appointment.
SELECT name FROM physician EXCEPT SELECT T2.name FROM appointment AS T1 JOIN physician AS T2 ON T1.Physician = T2.EmployeeID
hard
3,912
hospital_1
[ "appointment", "physician" ]
Which physicians have never taken any appointment? Find their names.
SELECT name FROM physician EXCEPT SELECT T2.name FROM appointment AS T1 JOIN physician AS T2 ON T1.Physician = T2.EmployeeID
hard
3,913
hospital_1
[ "affiliated_with", "department", "physician" ]
Find the names of all physicians and their primary affiliated departments' names.
SELECT T1.name , T3.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T2.PrimaryAffiliation = 1
hard
3,914
hospital_1
[ "affiliated_with", "department", "physician" ]
What are the name and primarily affiliated department name of each physician?
SELECT T1.name , T3.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T2.PrimaryAffiliation = 1
hard
3,915
hospital_1
[ "patient", "appointment" ]
What is the name of the patient who made the most recent appointment?
SELECT T1.name FROM patient AS T1 JOIN appointment AS T2 ON T1.ssn = T2.patient ORDER BY T2.start DESC LIMIT 1
hard
3,916
hospital_1
[ "patient", "appointment" ]
Find the name of the patient who made the appointment with the most recent start date.
SELECT T1.name FROM patient AS T1 JOIN appointment AS T2 ON T1.ssn = T2.patient ORDER BY T2.start DESC LIMIT 1
hard
3,917
hospital_1
[ "stay" ]
How many patients stay in room 112?
SELECT count(patient) FROM stay WHERE room = 112
easy
3,918
hospital_1
[ "stay" ]
Count the number of patients who stayed in room 112.
SELECT count(patient) FROM stay WHERE room = 112
easy
3,919
hospital_1
[ "patient", "prescribes", "physician" ]
How many patients' prescriptions are made by physician John Dorian?
SELECT count(T1.SSN) FROM patient AS T1 JOIN prescribes AS T2 ON T1.SSN = T2.patient JOIN physician AS T3 ON T2.physician = T3.employeeid WHERE T3.name = "John Dorian"
hard
3,920
hospital_1
[ "patient", "prescribes", "physician" ]
Find the number of patients' prescriptions physician John Dorian made.
SELECT count(T1.SSN) FROM patient AS T1 JOIN prescribes AS T2 ON T1.SSN = T2.patient JOIN physician AS T3 ON T2.physician = T3.employeeid WHERE T3.name = "John Dorian"
hard
3,921
hospital_1
[ "patient", "stay", "Prescribes", "Medication" ]
Find the name of medication used on the patient who stays in room 111?
SELECT T4.name FROM stay AS T1 JOIN patient AS T2 ON T1.Patient = T2.SSN JOIN Prescribes AS T3 ON T3.Patient = T2.SSN JOIN Medication AS T4 ON T3.Medication = T4.Code WHERE room = 111
extra
3,922
hospital_1
[ "patient", "stay", "Prescribes", "Medication" ]
What is the name of the medication used for the patient staying in room 111?
SELECT T4.name FROM stay AS T1 JOIN patient AS T2 ON T1.Patient = T2.SSN JOIN Prescribes AS T3 ON T3.Patient = T2.SSN JOIN Medication AS T4 ON T3.Medication = T4.Code WHERE room = 111
extra
3,923
hospital_1
[ "stay" ]
Find the patient who most recently stayed in room 111.
SELECT patient FROM stay WHERE room = 111 ORDER BY staystart DESC LIMIT 1
hard
3,924
hospital_1
[ "stay" ]
What is the id of the patient who stayed in room 111 most recently?
SELECT patient FROM stay WHERE room = 111 ORDER BY staystart DESC LIMIT 1
hard
3,925
hospital_1
[ "appointment", "nurse" ]
What is the name of the nurse has the most appointments?
SELECT T1.name FROM nurse AS T1 JOIN appointment AS T2 ON T1.employeeid = T2.prepnurse GROUP BY T1.employeeid ORDER BY count(*) DESC LIMIT 1
extra
3,926
hospital_1
[ "appointment", "nurse" ]
Find the name of the nurse who has the largest number of appointments.
SELECT T1.name FROM nurse AS T1 JOIN appointment AS T2 ON T1.employeeid = T2.prepnurse GROUP BY T1.employeeid ORDER BY count(*) DESC LIMIT 1
extra
3,927
hospital_1
[ "patient", "physician" ]
How many patients do each physician take care of? List their names and number of patients they take care of.
SELECT T1.name , count(*) FROM physician AS T1 JOIN patient AS T2 ON T1.employeeid = T2.PCP GROUP BY T1.employeeid
medium
3,928
hospital_1
[ "patient", "physician" ]
Return the name of each physician and the number of patients he or she treats.
SELECT T1.name , count(*) FROM physician AS T1 JOIN patient AS T2 ON T1.employeeid = T2.PCP GROUP BY T1.employeeid
medium
3,929
hospital_1
[ "patient", "physician" ]
Find the name of physicians who are in charge of more than one patient.
SELECT T1.name FROM physician AS T1 JOIN patient AS T2 ON T1.employeeid = T2.PCP GROUP BY T1.employeeid HAVING count(*) > 1
medium
3,930
hospital_1
[ "patient", "physician" ]
Which physicians are in charge of more than one patient? Give me their names.
SELECT T1.name FROM physician AS T1 JOIN patient AS T2 ON T1.employeeid = T2.PCP GROUP BY T1.employeeid HAVING count(*) > 1
medium
3,931
hospital_1
[ "room", "BLOCK" ]
Find the number of rooms located on each block floor.
SELECT count(*) , T1.blockfloor FROM BLOCK AS T1 JOIN room AS T2 ON T1.blockfloor = T2.blockfloor AND T1.blockcode = T2.blockcode GROUP BY T1.blockfloor
medium
3,932
hospital_1
[ "room", "BLOCK" ]
How many rooms does each block floor have?
SELECT count(*) , T1.blockfloor FROM BLOCK AS T1 JOIN room AS T2 ON T1.blockfloor = T2.blockfloor AND T1.blockcode = T2.blockcode GROUP BY T1.blockfloor
medium
3,933
hospital_1
[ "room", "BLOCK" ]
Find the number of rooms for different block code?
SELECT count(*) , T1.blockcode FROM BLOCK AS T1 JOIN room AS T2 ON T1.blockfloor = T2.blockfloor AND T1.blockcode = T2.blockcode GROUP BY T1.blockcode
medium
3,934
hospital_1
[ "room", "BLOCK" ]
How many rooms are located for each block code?
SELECT count(*) , T1.blockcode FROM BLOCK AS T1 JOIN room AS T2 ON T1.blockfloor = T2.blockfloor AND T1.blockcode = T2.blockcode GROUP BY T1.blockcode
medium
3,935
hospital_1
[ "room" ]
What are the unique block codes that have available rooms?
SELECT DISTINCT blockcode FROM room WHERE unavailable = 0
easy
3,936
hospital_1
[ "room" ]
Tell me the distinct block codes where some rooms are available.
SELECT DISTINCT blockcode FROM room WHERE unavailable = 0
easy
3,937
hospital_1
[ "room" ]
How many different types of rooms are there?
SELECT count(DISTINCT roomtype) FROM room
easy
3,938
hospital_1
[ "room" ]
Find the number of distinct room types available.
SELECT count(DISTINCT roomtype) FROM room
easy
3,939
hospital_1
[ "medication", "prescribes", "physician" ]
What is the names of the physicians who prescribe medication Thesisin?
SELECT DISTINCT T1.name FROM physician AS T1 JOIN prescribes AS T2 ON T1.employeeid = T2.physician JOIN medication AS T3 ON T3.code = T2.medication WHERE T3.name = "Thesisin"
hard
3,940
hospital_1
[ "medication", "prescribes", "physician" ]
List the names of all the physicians who prescribe Thesisin as medication.
SELECT DISTINCT T1.name FROM physician AS T1 JOIN prescribes AS T2 ON T1.employeeid = T2.physician JOIN medication AS T3 ON T3.code = T2.medication WHERE T3.name = "Thesisin"
hard
3,941
hospital_1
[ "medication", "prescribes", "physician" ]
Find the name and position of physicians who prescribe some medication whose brand is X?
SELECT DISTINCT T1.name , T1.position FROM physician AS T1 JOIN prescribes AS T2 ON T1.employeeid = T2.physician JOIN medication AS T3 ON T3.code = T2.medication WHERE T3.Brand = "X"
hard
3,942
hospital_1
[ "medication", "prescribes", "physician" ]
Which physicians prescribe a medication of brand X? Tell me the name and position of those physicians.
SELECT DISTINCT T1.name , T1.position FROM physician AS T1 JOIN prescribes AS T2 ON T1.employeeid = T2.physician JOIN medication AS T3 ON T3.code = T2.medication WHERE T3.Brand = "X"
hard
3,943
hospital_1
[ "medication", "prescribes" ]
Find the number of medications prescribed for each brand.
SELECT count(*) , T1.name FROM medication AS T1 JOIN prescribes AS T2 ON T1.code = T2.medication GROUP BY T1.brand
medium
3,944
hospital_1
[ "medication", "prescribes" ]
How many medications are prescribed for each brand?
SELECT count(*) , T1.name FROM medication AS T1 JOIN prescribes AS T2 ON T1.code = T2.medication GROUP BY T1.brand
medium
3,945
hospital_1
[ "physician" ]
Find the name of physicians whose position title contains the word 'senior'.
SELECT name FROM physician WHERE POSITION LIKE '%senior%'
medium
3,946
hospital_1
[ "physician" ]
What are the names of the physicians who have 'senior' in their titles.
SELECT name FROM physician WHERE POSITION LIKE '%senior%'
medium
3,947
hospital_1
[ "undergoes" ]
Find the patient who has the most recent undergoing treatment?
SELECT patient FROM undergoes ORDER BY dateundergoes LIMIT 1
medium
3,948
hospital_1
[ "undergoes" ]
Which patient is undergoing the most recent treatment?
SELECT patient FROM undergoes ORDER BY dateundergoes LIMIT 1
medium
3,949
hospital_1
[ "undergoes", "stay", "patient" ]
Find the names of all patients who have an undergoing treatment and are staying in room 111.
SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN patient AS T2 ON T1.patient = T2.SSN JOIN stay AS T3 ON T1.Stay = T3.StayID WHERE T3.room = 111
hard
3,950
hospital_1
[ "undergoes", "stay", "patient" ]
What are the names of patients who are staying in room 111 and have an undergoing treatment?
SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN patient AS T2 ON T1.patient = T2.SSN JOIN stay AS T3 ON T1.Stay = T3.StayID WHERE T3.room = 111
hard
3,951
hospital_1
[ "nurse" ]
List the names of all distinct nurses ordered by alphabetical order?
SELECT DISTINCT name FROM nurse ORDER BY name
easy
3,952
hospital_1
[ "nurse" ]
What is the alphabetically ordered list of all the distinct names of nurses?
SELECT DISTINCT name FROM nurse ORDER BY name
easy
3,953
hospital_1
[ "undergoes", "nurse" ]
Find the names of nurses who are nursing an undergoing treatment.
SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN nurse AS T2 ON T1.AssistingNurse = T2.EmployeeID
easy
3,954
hospital_1
[ "undergoes", "nurse" ]
Which nurses are in charge of patients undergoing treatments?
SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN nurse AS T2 ON T1.AssistingNurse = T2.EmployeeID
easy
3,955
hospital_1
[ "medication" ]
List the names of all distinct medications, ordered in an alphabetical order.
SELECT DISTINCT name FROM medication ORDER BY name
easy
3,956
hospital_1
[ "medication" ]
What is the alphabetically ordered list of all distinct medications?
SELECT DISTINCT name FROM medication ORDER BY name
easy
3,957
hospital_1
[ "prescribes", "physician" ]
What are the names of the physician who prescribed the highest dose?
SELECT T1.name FROM physician AS T1 JOIN prescribes AS T2 ON T1.employeeid = T2.physician ORDER BY T2.dose DESC LIMIT 1
hard
3,958
hospital_1
[ "prescribes", "physician" ]
Find the physician who prescribed the highest dose. What is his or her name?
SELECT T1.name FROM physician AS T1 JOIN prescribes AS T2 ON T1.employeeid = T2.physician ORDER BY T2.dose DESC LIMIT 1
hard
3,959
hospital_1
[ "affiliated_with" ]
List the physicians' employee ids together with their primary affiliation departments' ids.
SELECT physician , department FROM affiliated_with WHERE primaryaffiliation = 1
medium
3,960
hospital_1
[ "affiliated_with" ]
What are each physician's employee id and department id primarily affiliated.
SELECT physician , department FROM affiliated_with WHERE primaryaffiliation = 1
medium
3,961
hospital_1
[ "affiliated_with", "department" ]
List the names of departments where some physicians are primarily affiliated with.
SELECT DISTINCT T2.name FROM affiliated_with AS T1 JOIN department AS T2 ON T1.department = T2.departmentid WHERE PrimaryAffiliation = 1
medium
3,962
hospital_1
[ "affiliated_with", "department" ]
What are the names of departments that have primarily affiliated physicians.
SELECT DISTINCT T2.name FROM affiliated_with AS T1 JOIN department AS T2 ON T1.department = T2.departmentid WHERE PrimaryAffiliation = 1
medium
3,963
hospital_1
[ "on_call" ]
What nurses are on call with block floor 1 and block code 1? Tell me their names.
SELECT nurse FROM on_call WHERE blockfloor = 1 AND blockcode = 1
medium
3,964
hospital_1
[ "on_call" ]
Find the ids of the nurses who are on call in block floor 1 and block code 1.
SELECT nurse FROM on_call WHERE blockfloor = 1 AND blockcode = 1
medium
3,965
hospital_1
[ "procedures" ]
What are the highest cost, lowest cost and average cost of procedures?
SELECT MAX(cost) , MIN(cost) , AVG(cost) FROM procedures
medium
3,966
hospital_1
[ "procedures" ]
Tell me the highest, lowest, and average cost of procedures.
SELECT MAX(cost) , MIN(cost) , AVG(cost) FROM procedures
medium
3,967
hospital_1
[ "procedures" ]
List the name and cost of all procedures sorted by the cost from the highest to the lowest.
SELECT name , cost FROM procedures ORDER BY cost DESC
medium
3,968
hospital_1
[ "procedures" ]
Sort the list of names and costs of all procedures in the descending order of cost.
SELECT name , cost FROM procedures ORDER BY cost DESC
medium
3,969
hospital_1
[ "procedures" ]
Find the three most expensive procedures.
SELECT name FROM procedures ORDER BY cost LIMIT 3
medium
3,970
hospital_1
[ "procedures" ]
What are the three most costly procedures?
SELECT name FROM procedures ORDER BY cost LIMIT 3
medium
3,971
hospital_1
[ "trained_in", "procedures", "physician" ]
Find the physicians who are trained in a procedure that costs more than 5000.
SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T3.cost > 5000
hard
3,972
hospital_1
[ "trained_in", "procedures", "physician" ]
Which physicians are trained in procedures that are more expensive than 5000?
SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T3.cost > 5000
hard
3,973
hospital_1
[ "trained_in", "procedures", "physician" ]
Find the physician who was trained in the most expensive procedure?
SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment ORDER BY T3.cost DESC LIMIT 1
extra
3,974
hospital_1
[ "trained_in", "procedures", "physician" ]
Which physician was trained in the procedure that costs the most.
SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment ORDER BY T3.cost DESC LIMIT 1
extra
3,975
hospital_1
[ "trained_in", "procedures", "physician" ]
What is the average cost of procedures that physician John Wen was trained in?
SELECT avg(T3.cost) FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
hard
3,976
hospital_1
[ "trained_in", "procedures", "physician" ]
Compute the mean price of procedures physician John Wen was trained in.
SELECT avg(T3.cost) FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
hard
3,977
hospital_1
[ "trained_in", "procedures", "physician" ]
Find the names of procedures which physician John Wen was trained in.
SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
hard
3,978
hospital_1
[ "trained_in", "procedures", "physician" ]
What are the names of procedures physician John Wen was trained in?
SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
hard
3,979
hospital_1
[ "trained_in", "procedures", "physician" ]
Find all procedures which cost more than 1000 or which physician John Wen was trained in.
SELECT name FROM procedures WHERE cost > 1000 UNION SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
hard
3,980
hospital_1
[ "trained_in", "procedures", "physician" ]
What are the procedures that cost more than 1000 or are specialized in by physician John Wen?
SELECT name FROM procedures WHERE cost > 1000 UNION SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
hard
3,981
hospital_1
[ "trained_in", "procedures", "physician" ]
Find the names of all procedures which cost more than 1000 but which physician John Wen was not trained in?
SELECT name FROM procedures WHERE cost > 1000 EXCEPT SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
hard
3,982
hospital_1
[ "trained_in", "procedures", "physician" ]
Among the procedures that cost more than 1000, which were not specialized in by physician John Wen?
SELECT name FROM procedures WHERE cost > 1000 EXCEPT SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
hard
3,983
hospital_1
[ "trained_in", "procedures", "physician" ]
Find the names of all procedures such that the cost is less than 5000 and physician John Wen was trained in.
SELECT name FROM procedures WHERE cost < 5000 INTERSECT SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
hard
3,984
hospital_1
[ "trained_in", "procedures", "physician" ]
What procedures cost less than 5000 and have John Wen as a trained physician?
SELECT name FROM procedures WHERE cost < 5000 INTERSECT SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
hard
3,985
hospital_1
[ "affiliated_with", "department", "physician" ]
Find the name of physicians who are affiliated with both Surgery and Psychiatry departments.
SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' INTERSECT SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Psychiatry'
extra
3,986
hospital_1
[ "affiliated_with", "department", "physician" ]
Which physicians are affiliated with both Surgery and Psychiatry departments? Tell me their names.
SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' INTERSECT SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Psychiatry'
extra
3,987
hospital_1
[ "affiliated_with", "department", "physician" ]
Find the name of physicians who are affiliated with Surgery or Psychiatry department.
SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' OR T3.name = 'Psychiatry'
extra
3,988
hospital_1
[ "affiliated_with", "department", "physician" ]
Which physicians are affiliated with either Surgery or Psychiatry department? Give me their names.
SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' OR T3.name = 'Psychiatry'
extra
3,989
hospital_1
[ "patient", "Prescribes", "Medication" ]
Find the names of patients who are not using the medication of Procrastin-X.
SELECT name FROM patient EXCEPT SELECT T1.name FROM patient AS T1 JOIN Prescribes AS T2 ON T2.Patient = T1.SSN JOIN Medication AS T3 ON T2.Medication = T3.Code WHERE T3.name = 'Procrastin-X'
hard
3,990
hospital_1
[ "patient", "Prescribes", "Medication" ]
What are the names of patients who are not taking the medication of Procrastin-X.
SELECT name FROM patient EXCEPT SELECT T1.name FROM patient AS T1 JOIN Prescribes AS T2 ON T2.Patient = T1.SSN JOIN Medication AS T3 ON T2.Medication = T3.Code WHERE T3.name = 'Procrastin-X'
hard
3,991
hospital_1
[ "patient", "Prescribes", "Medication" ]
Find the number of patients who are not using the medication of Procrastin-X.
SELECT count(*) FROM patient WHERE SSN NOT IN ( SELECT T1.patient FROM Prescribes AS T1 JOIN Medication AS T2 ON T1.Medication = T2.Code WHERE T2.name = 'Procrastin-X' )
extra
3,992
hospital_1
[ "patient", "Prescribes", "Medication" ]
How many patients are not using Procrastin-X as medication?
SELECT count(*) FROM patient WHERE SSN NOT IN ( SELECT T1.patient FROM Prescribes AS T1 JOIN Medication AS T2 ON T1.Medication = T2.Code WHERE T2.name = 'Procrastin-X' )
extra
3,993
hospital_1
[ "appointment" ]
How many appointments are there?
SELECT count(*) FROM appointment
easy
3,994
hospital_1
[ "appointment" ]
Count how many appointments have been made in total.
SELECT count(*) FROM appointment
easy
3,995
hospital_1
[ "on_call", "nurse" ]
Find the names of nurses who are on call.
SELECT DISTINCT T1.name FROM nurse AS T1 JOIN on_call AS T2 ON T1.EmployeeID = T2.nurse
easy
3,996
hospital_1
[ "on_call", "nurse" ]
What are the distinct names of nurses on call?
SELECT DISTINCT T1.name FROM nurse AS T1 JOIN on_call AS T2 ON T1.EmployeeID = T2.nurse
easy
3,997
ship_mission
[ "ship" ]
How many ships are there?
SELECT count(*) FROM ship
easy
3,998
ship_mission
[ "ship" ]
What is the number of ships?
SELECT count(*) FROM ship
easy
3,999
ship_mission
[ "ship" ]
List the name of ships in ascending order of tonnage.
SELECT Name FROM ship ORDER BY Tonnage ASC
easy