query_id
int64
0
7k
database_id
stringclasses
140 values
table_id
sequencelengths
1
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query
stringlengths
16
224
answer
stringlengths
18
577
difficulty
stringclasses
4 values
4,600
entertainment_awards
[ "festival_detail" ]
What is the location of the festival with the largest number of audience?
SELECT LOCATION FROM festival_detail ORDER BY Num_of_Audience DESC LIMIT 1
medium
4,601
entertainment_awards
[ "festival_detail" ]
What are the names of festivals held in year 2007?
SELECT Festival_Name FROM festival_detail WHERE YEAR = 2007
easy
4,602
entertainment_awards
[ "festival_detail" ]
What is the average number of audience for festivals?
SELECT avg(Num_of_Audience) FROM festival_detail
easy
4,603
entertainment_awards
[ "festival_detail" ]
Show the names of the three most recent festivals.
SELECT Festival_Name FROM festival_detail ORDER BY YEAR DESC LIMIT 3
medium
4,604
entertainment_awards
[ "festival_detail", "artwork", "nomination" ]
For each nomination, show the name of the artwork and name of the festival where it is nominated.
SELECT T2.Name , T3.Festival_Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID = T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID = T3.Festival_ID
medium
4,605
entertainment_awards
[ "festival_detail", "artwork", "nomination" ]
Show distinct types of artworks that are nominated in festivals in 2007.
SELECT DISTINCT T2.Type FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID = T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID = T3.Festival_ID WHERE T3.Year = 2007
hard
4,606
entertainment_awards
[ "festival_detail", "artwork", "nomination" ]
Show the names of artworks in ascending order of the year they are nominated in.
SELECT T2.Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID = T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID = T3.Festival_ID ORDER BY T3.Year
hard
4,607
entertainment_awards
[ "festival_detail", "artwork", "nomination" ]
Show the names of festivals that have nominated artworks of type "Program Talent Show".
SELECT T3.Festival_Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID = T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID = T3.Festival_ID WHERE T2.Type = "Program Talent Show"
hard
4,608
entertainment_awards
[ "festival_detail", "artwork", "nomination" ]
Show the ids and names of festivals that have at least two nominations for artworks.
SELECT T1.Festival_ID , T3.Festival_Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID = T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID = T3.Festival_ID GROUP BY T1.Festival_ID HAVING COUNT(*) >= 2
hard
4,609
entertainment_awards
[ "festival_detail", "artwork", "nomination" ]
Show the id, name of each festival and the number of artworks it has nominated.
SELECT T1.Festival_ID , T3.Festival_Name , COUNT(*) FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID = T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID = T3.Festival_ID GROUP BY T1.Festival_ID
hard
4,610
entertainment_awards
[ "artwork" ]
Please show different types of artworks with the corresponding number of artworks of each type.
SELECT TYPE , COUNT(*) FROM artwork GROUP BY TYPE
medium
4,611
entertainment_awards
[ "artwork" ]
List the most common type of artworks.
SELECT TYPE FROM artwork GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1
hard
4,612
entertainment_awards
[ "festival_detail" ]
List the year in which there are more than one festivals.
SELECT YEAR FROM festival_detail GROUP BY YEAR HAVING COUNT(*) > 1
easy
4,613
entertainment_awards
[ "Artwork", "nomination" ]
List the name of artworks that are not nominated.
SELECT Name FROM Artwork WHERE Artwork_ID NOT IN (SELECT Artwork_ID FROM nomination)
hard
4,614
entertainment_awards
[ "festival_detail" ]
Show the number of audience in year 2008 or 2010.
SELECT Num_of_Audience FROM festival_detail WHERE YEAR = 2008 OR YEAR = 2010
medium
4,615
entertainment_awards
[ "festival_detail" ]
What are the total number of the audiences who visited any of the festivals?
SELECT sum(Num_of_Audience) FROM festival_detail
easy
4,616
entertainment_awards
[ "festival_detail" ]
In which year are there festivals both inside the 'United States' and outside the 'United States'?
SELECT YEAR FROM festival_detail WHERE LOCATION = 'United States' INTERSECT SELECT YEAR FROM festival_detail WHERE LOCATION != 'United States'
hard
4,617
customers_campaigns_ecommerce
[ "premises" ]
How many premises are there?
SELECT count(*) FROM premises
easy
4,618
customers_campaigns_ecommerce
[ "premises" ]
What are all the distinct premise types?
SELECT DISTINCT premises_type FROM premises
easy
4,619
customers_campaigns_ecommerce
[ "premises" ]
Find the types and details for all premises and order by the premise type.
SELECT premises_type , premise_details FROM premises ORDER BY premises_type
medium
4,620
customers_campaigns_ecommerce
[ "premises" ]
Show each premise type and the number of premises in that type.
SELECT premises_type , count(*) FROM premises GROUP BY premises_type
medium
4,621
customers_campaigns_ecommerce
[ "mailshot_campaigns" ]
Show all distinct product categories along with the number of mailshots in each category.
SELECT product_category , count(*) FROM mailshot_campaigns GROUP BY product_category
medium
4,622
customers_campaigns_ecommerce
[ "customers", "mailshot_customers" ]
Show the name and phone of the customer without any mailshot.
SELECT customer_name , customer_phone FROM customers WHERE customer_id NOT IN (SELECT customer_id FROM mailshot_customers)
extra
4,623
customers_campaigns_ecommerce
[ "mailshot_customers", "customers" ]
Show the name and phone for customers with a mailshot with outcome code 'No Response'.
SELECT T1.customer_name , T1.customer_phone FROM customers AS T1 JOIN mailshot_customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.outcome_code = 'No Response'
medium
4,624
customers_campaigns_ecommerce
[ "mailshot_customers" ]
Show the outcome code of mailshots along with the number of mailshots in each outcome code.
SELECT outcome_code , count(*) FROM mailshot_customers GROUP BY outcome_code
medium
4,625
customers_campaigns_ecommerce
[ "customers", "mailshot_customers" ]
Show the names of customers who have at least 2 mailshots with outcome code 'Order'.
SELECT T2.customer_name FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id WHERE outcome_code = 'Order' GROUP BY T1.customer_id HAVING count(*) >= 2
hard
4,626
customers_campaigns_ecommerce
[ "customers", "mailshot_customers" ]
Show the names of customers who have the most mailshots.
SELECT T2.customer_name FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1
extra
4,627
customers_campaigns_ecommerce
[ "customers", "mailshot_customers" ]
What are the name and payment method of customers who have both mailshots in 'Order' outcome and mailshots in 'No Response' outcome.
SELECT T2.customer_name , T2.payment_method FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.outcome_code = 'Order' INTERSECT SELECT T2.customer_name , T2.payment_method FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.outcome_code = 'No Response'
extra
4,628
customers_campaigns_ecommerce
[ "customer_addresses", "premises" ]
Show the premise type and address type code for all customer addresses.
SELECT T2.premises_type , T1.address_type_code FROM customer_addresses AS T1 JOIN premises AS T2 ON T1.premise_id = T2.premise_id
medium
4,629
customers_campaigns_ecommerce
[ "customer_addresses" ]
What are the distinct address type codes for all customer addresses?
SELECT DISTINCT address_type_code FROM customer_addresses
easy
4,630
customers_campaigns_ecommerce
[ "customer_orders" ]
Show the shipping charge and customer id for customer orders with order status Cancelled or Paid.
SELECT order_shipping_charges , customer_id FROM customer_orders WHERE order_status_code = 'Cancelled' OR order_status_code = 'Paid'
extra
4,631
customers_campaigns_ecommerce
[ "customer_orders", "customers" ]
Show the names of customers having an order with shipping method FedEx and order status Paid.
SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE shipping_method_code = 'FedEx' AND order_status_code = 'Paid'
medium
4,632
college_3
[ "COURSE" ]
How many courses are there in total?
SELECT count(*) FROM COURSE
easy
4,633
college_3
[ "COURSE" ]
Count the number of courses.
SELECT count(*) FROM COURSE
easy
4,634
college_3
[ "COURSE" ]
How many courses have more than 2 credits?
SELECT count(*) FROM COURSE WHERE Credits > 2
easy
4,635
college_3
[ "COURSE" ]
Count the number of courses with more than 2 credits.
SELECT count(*) FROM COURSE WHERE Credits > 2
easy
4,636
college_3
[ "COURSE" ]
List all names of courses with 1 credit?
SELECT CName FROM COURSE WHERE Credits = 1
easy
4,637
college_3
[ "COURSE" ]
What are the names of courses with 1 credit?
SELECT CName FROM COURSE WHERE Credits = 1
easy
4,638
college_3
[ "COURSE" ]
Which courses are taught on days MTW?
SELECT CName FROM COURSE WHERE Days = "MTW"
easy
4,639
college_3
[ "COURSE" ]
What are the course names for courses taught on MTW?
SELECT CName FROM COURSE WHERE Days = "MTW"
easy
4,640
college_3
[ "DEPARTMENT" ]
What is the number of departments in Division "AS"?
SELECT count(*) FROM DEPARTMENT WHERE Division = "AS"
easy
4,641
college_3
[ "DEPARTMENT" ]
How many departments are in the division AS?
SELECT count(*) FROM DEPARTMENT WHERE Division = "AS"
easy
4,642
college_3
[ "DEPARTMENT" ]
What are the phones of departments in Room 268?
SELECT DPhone FROM DEPARTMENT WHERE Room = 268
easy
4,643
college_3
[ "DEPARTMENT" ]
Give the phones for departments in room 268.
SELECT DPhone FROM DEPARTMENT WHERE Room = 268
easy
4,644
college_3
[ "ENROLLED_IN" ]
Find the number of students that have at least one grade "B".
SELECT COUNT(DISTINCT StuID) FROM ENROLLED_IN WHERE Grade = "B"
easy
4,645
college_3
[ "ENROLLED_IN" ]
How many students have had at least one "B" grade?
SELECT COUNT(DISTINCT StuID) FROM ENROLLED_IN WHERE Grade = "B"
easy
4,646
college_3
[ "GRADECONVERSION" ]
Find the max and min grade point for all letter grade.
SELECT max(gradepoint) , min(gradepoint) FROM GRADECONVERSION
medium
4,647
college_3
[ "GRADECONVERSION" ]
What are the maximum and minumum grade points?
SELECT max(gradepoint) , min(gradepoint) FROM GRADECONVERSION
medium
4,648
college_3
[ "STUDENT" ]
Find the first names of students whose first names contain letter "a".
SELECT DISTINCT Fname FROM STUDENT WHERE Fname LIKE '%a%'
medium
4,649
college_3
[ "STUDENT" ]
What are the first names for students who have an "a" in their first name?
SELECT DISTINCT Fname FROM STUDENT WHERE Fname LIKE '%a%'
medium
4,650
college_3
[ "FACULTY" ]
Find the first names and last names of male (sex is M) faculties who live in building NEB.
SELECT Fname , Lname FROM FACULTY WHERE sex = "M" AND Building = "NEB"
medium
4,651
college_3
[ "FACULTY" ]
What are the full names of faculties with sex M and who live in building NEB?
SELECT Fname , Lname FROM FACULTY WHERE sex = "M" AND Building = "NEB"
medium
4,652
college_3
[ "FACULTY" ]
Find the rooms of faculties with rank professor who live in building NEB.
SELECT Room FROM FACULTY WHERE Rank = "Professor" AND Building = "NEB"
medium
4,653
college_3
[ "FACULTY" ]
What are the rooms for members of the faculty who are professors and who live in building NEB?
SELECT Room FROM FACULTY WHERE Rank = "Professor" AND Building = "NEB"
medium
4,654
college_3
[ "DEPARTMENT" ]
Find the department name that is in Building "Mergenthaler".
SELECT DName FROM DEPARTMENT WHERE Building = "Mergenthaler"
easy
4,655
college_3
[ "DEPARTMENT" ]
What is the name of the department in the Building Mergenthaler?
SELECT DName FROM DEPARTMENT WHERE Building = "Mergenthaler"
easy
4,656
college_3
[ "COURSE" ]
List all information about courses sorted by credits in the ascending order.
SELECT * FROM COURSE ORDER BY Credits
easy
4,657
college_3
[ "COURSE" ]
What is all the information about courses, ordered by credits ascending?
SELECT * FROM COURSE ORDER BY Credits
easy
4,658
college_3
[ "COURSE" ]
List the course name of courses sorted by credits.
SELECT CName FROM COURSE ORDER BY Credits
easy
4,659
college_3
[ "COURSE" ]
What are the course names, ordered by credits?
SELECT CName FROM COURSE ORDER BY Credits
easy
4,660
college_3
[ "STUDENT" ]
Find the first name of students in the descending order of age.
SELECT Fname FROM STUDENT ORDER BY Age DESC
easy
4,661
college_3
[ "STUDENT" ]
What are the first names of students, ordered by age from greatest to least?
SELECT Fname FROM STUDENT ORDER BY Age DESC
easy
4,662
college_3
[ "STUDENT" ]
Find the last name of female (sex is F) students in the descending order of age.
SELECT LName FROM STUDENT WHERE Sex = "F" ORDER BY Age DESC
medium
4,663
college_3
[ "STUDENT" ]
What are the last names of female students, ordered by age descending?
SELECT LName FROM STUDENT WHERE Sex = "F" ORDER BY Age DESC
medium
4,664
college_3
[ "FACULTY" ]
Find the last names of faculties in building Barton in alphabetic order.
SELECT Lname FROM FACULTY WHERE Building = "Barton" ORDER BY Lname
medium
4,665
college_3
[ "FACULTY" ]
What are the last names of faculty in building Barton, sorted by last name?
SELECT Lname FROM FACULTY WHERE Building = "Barton" ORDER BY Lname
medium
4,666
college_3
[ "FACULTY" ]
Find the first names of faculties of rank Professor in alphabetic order.
SELECT Fname FROM FACULTY WHERE Rank = "Professor" ORDER BY Fname
medium
4,667
college_3
[ "FACULTY" ]
What are the first names for all faculty professors, ordered by first name?
SELECT Fname FROM FACULTY WHERE Rank = "Professor" ORDER BY Fname
medium
4,668
college_3
[ "DEPARTMENT", "MINOR_IN" ]
Find the name of the department that has the biggest number of students minored in?
SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO = T2.DNO GROUP BY T2.DNO ORDER BY count(*) DESC LIMIT 1
extra
4,669
college_3
[ "DEPARTMENT", "MINOR_IN" ]
What is the name of the department with the most students minoring in it?
SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO = T2.DNO GROUP BY T2.DNO ORDER BY count(*) DESC LIMIT 1
extra
4,670
college_3
[ "DEPARTMENT", "MINOR_IN" ]
Find the name of the department that has no students minored in?
SELECT DName FROM DEPARTMENT EXCEPT SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO = T2.DNO
hard
4,671
college_3
[ "DEPARTMENT", "MINOR_IN" ]
What is the name of the department htat has no students minoring in it?
SELECT DName FROM DEPARTMENT EXCEPT SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO = T2.DNO
hard
4,672
college_3
[ "DEPARTMENT", "MEMBER_OF" ]
Find the name of the department that has the fewest members.
SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MEMBER_OF AS T2 ON T1.DNO = T2.DNO GROUP BY T2.DNO ORDER BY count(*) ASC LIMIT 1
extra
4,673
college_3
[ "DEPARTMENT", "MEMBER_OF" ]
What is the name of the department with the fewest members?
SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MEMBER_OF AS T2 ON T1.DNO = T2.DNO GROUP BY T2.DNO ORDER BY count(*) ASC LIMIT 1
extra
4,674
college_3
[ "FACULTY" ]
Find the rank of the faculty that the fewest faculties belong to.
SELECT Rank FROM FACULTY GROUP BY Rank ORDER BY count(*) ASC LIMIT 1
hard
4,675
college_3
[ "FACULTY" ]
What is the least common faculty rank?
SELECT Rank FROM FACULTY GROUP BY Rank ORDER BY count(*) ASC LIMIT 1
hard
4,676
college_3
[ "COURSE", "FACULTY" ]
What are the first and last names of the instructors who teach the top 3 number of courses?
SELECT T2.Fname , T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3
extra
4,677
college_3
[ "COURSE", "FACULTY" ]
What are the full names of the 3 instructors who teach the most courses?
SELECT T2.Fname , T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3
extra
4,678
college_3
[ "COURSE", "FACULTY" ]
Which building does the instructor who teaches the most number of courses live in?
SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1
extra
4,679
college_3
[ "COURSE", "FACULTY" ]
Give the building that the instructor who teaches the greatest number of courses lives in.
SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1
extra
4,680
college_3
[ "COURSE", "ENROLLED_IN" ]
What are the name of courses that have at least five enrollments?
SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID = T2.CID GROUP BY T2.CID HAVING COUNT(*) >= 5
medium
4,681
college_3
[ "COURSE", "ENROLLED_IN" ]
Give the names of the courses with at least five enrollments.
SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID = T2.CID GROUP BY T2.CID HAVING COUNT(*) >= 5
medium
4,682
college_3
[ "COURSE", "FACULTY" ]
Find the first name and last name of the instructor of course that has course name
SELECT T2.Fname , T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID WHERE T1.CName = "COMPUTER LITERACY"
medium
4,683
college_3
[ "COURSE", "FACULTY" ]
What is the full name of the instructor who has a course named COMPUTER LITERACY?
SELECT T2.Fname , T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID WHERE T1.CName = "COMPUTER LITERACY"
medium
4,684
college_3
[ "COURSE", "DEPARTMENT" ]
Find the department name and room of the course INTRODUCTION TO COMPUTER SCIENCE.
SELECT T2.Dname , T2.Room FROM COURSE AS T1 JOIN DEPARTMENT AS T2 ON T1.DNO = T2.DNO WHERE T1.CName = "INTRODUCTION TO COMPUTER SCIENCE"
medium
4,685
college_3
[ "COURSE", "DEPARTMENT" ]
What are the department name and room for the course INTRODUCTION TO COMPUTER SCIENCE?
SELECT T2.Dname , T2.Room FROM COURSE AS T1 JOIN DEPARTMENT AS T2 ON T1.DNO = T2.DNO WHERE T1.CName = "INTRODUCTION TO COMPUTER SCIENCE"
medium
4,686
college_3
[ "GRADECONVERSION", "ENROLLED_IN", "STUDENT" ]
Find the student first and last names and grade points of all enrollments.
SELECT T3.Fname , T3.LName , T2.gradepoint FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID
medium
4,687
college_3
[ "GRADECONVERSION", "ENROLLED_IN", "STUDENT" ]
What are the full names and gradepoints for all enrollments?
SELECT T3.Fname , T3.LName , T2.gradepoint FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID
medium
4,688
college_3
[ "GRADECONVERSION", "ENROLLED_IN", "STUDENT" ]
Find the distinct student first names of all students that have grade point at least 3.8 in one course.
SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID WHERE T2.gradepoint >= 3.8
hard
4,689
college_3
[ "GRADECONVERSION", "ENROLLED_IN", "STUDENT" ]
What are the distinct first names for students with a grade point of 3.8 or above in at least one course?
SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID WHERE T2.gradepoint >= 3.8
hard
4,690
college_3
[ "MEMBER_OF", "FACULTY" ]
Find the full names of faculties who are members of department with department number 520.
SELECT T1.Fname , T1.Lname FROM FACULTY AS T1 JOIN MEMBER_OF AS T2 ON T1.FacID = T2.FacID WHERE T2.DNO = 520
medium
4,691
college_3
[ "MEMBER_OF", "FACULTY" ]
What are the full names of faculty members who are a part of department 520?
SELECT T1.Fname , T1.Lname FROM FACULTY AS T1 JOIN MEMBER_OF AS T2 ON T1.FacID = T2.FacID WHERE T2.DNO = 520
medium
4,692
college_3
[ "MINOR_IN", "STUDENT" ]
What are the first names and last names of the students that minor in the department with DNO 140.
SELECT T2.Fname , T2.Lname FROM MINOR_IN AS T1 JOIN STUDENT AS T2 ON T1.StuID = T2.StuID WHERE T1.DNO = 140
medium
4,693
college_3
[ "MINOR_IN", "STUDENT" ]
What are the full names of students minoring in department 140?
SELECT T2.Fname , T2.Lname FROM MINOR_IN AS T1 JOIN STUDENT AS T2 ON T1.StuID = T2.StuID WHERE T1.DNO = 140
medium
4,694
college_3
[ "DEPARTMENT", "MEMBER_OF", "FACULTY" ]
Find the last names of faculties who are members of computer science department.
SELECT T2.Lname FROM DEPARTMENT AS T1 JOIN FACULTY AS T2 ON T1.DNO = T3.DNO JOIN MEMBER_OF AS T3 ON T2.FacID = T3.FacID WHERE T1.DName = "Computer Science"
hard
4,695
college_3
[ "DEPARTMENT", "MEMBER_OF", "FACULTY" ]
What are the last names of faculty who are part of the computer science department?
SELECT T2.Lname FROM DEPARTMENT AS T1 JOIN FACULTY AS T2 ON T1.DNO = T3.DNO JOIN MEMBER_OF AS T3 ON T2.FacID = T3.FacID WHERE T1.DName = "Computer Science"
hard
4,696
college_3
[ "GRADECONVERSION", "ENROLLED_IN", "STUDENT" ]
Find the average grade point of student whose last name is Smith.
SELECT avg(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID WHERE T3.LName = "Smith"
hard
4,697
college_3
[ "GRADECONVERSION", "ENROLLED_IN", "STUDENT" ]
What is the average gradepoint for students with the last name Smith?
SELECT avg(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID WHERE T3.LName = "Smith"
hard
4,698
college_3
[ "GRADECONVERSION", "ENROLLED_IN", "STUDENT" ]
What is the maximum and minimum grade point of students who live in NYC?
SELECT max(T2.gradepoint) , min(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID WHERE T3.city_code = "NYC"
hard
4,699
college_3
[ "GRADECONVERSION", "ENROLLED_IN", "STUDENT" ]
Give the maximum and minimum gradepoints for students living in NYC?
SELECT max(T2.gradepoint) , min(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID WHERE T3.city_code = "NYC"
hard