target-benchmark/spider-queries-validation

query_id int64 0 1.03k	database_id stringclasses 20 values	table_id listlengths 1 4	query stringlengths 18 174	answer stringlengths 20 422	difficulty stringclasses 4 values
800	world_1	[ "country" ]	What are the names and areas of countries with the top 5 largest area?	SELECT Name , SurfaceArea FROM country ORDER BY SurfaceArea DESC LIMIT 5	medium
801	world_1	[ "country" ]	Return the names and surface areas of the 5 largest countries.	SELECT Name , SurfaceArea FROM country ORDER BY SurfaceArea DESC LIMIT 5	medium
802	world_1	[ "country" ]	What are names of countries with the top 3 largest population?	SELECT Name FROM country ORDER BY Population DESC LIMIT 3	medium
803	world_1	[ "country" ]	Return the names of the 3 most populated countries.	SELECT Name FROM country ORDER BY Population DESC LIMIT 3	medium
804	world_1	[ "country" ]	What are the names of the nations with the 3 lowest populations?	SELECT Name FROM country ORDER BY Population ASC LIMIT 3	medium
805	world_1	[ "country" ]	Return the names of the 3 countries with the fewest people.	SELECT Name FROM country ORDER BY Population ASC LIMIT 3	medium
806	world_1	[ "country" ]	how many countries are in Asia?	SELECT count(*) FROM country WHERE continent = "Asia"	easy
807	world_1	[ "country" ]	Count the number of countries in Asia.	SELECT count(*) FROM country WHERE continent = "Asia"	easy
808	world_1	[ "country" ]	What are the names of the countries that are in the continent of Europe and have a population of 80000?	SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000"	medium
809	world_1	[ "country" ]	Give the names of countries that are in Europe and have a population equal to 80000.	SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000"	medium
810	world_1	[ "country" ]	What is the total population and average area of countries in the continent of North America whose area is bigger than 3000 ?	select sum(population) , avg(surfacearea) from country where continent = "north america" and surfacearea > 3000	hard
811	world_1	[ "country" ]	Give the total population and average surface area corresponding to countries in North America that have a surface area greater than 3000 .	select sum(population) , avg(surfacearea) from country where continent = "north america" and surfacearea > 3000	hard
812	world_1	[ "city" ]	What are the cities whose population is between 160000 and 900000?	SELECT name FROM city WHERE Population BETWEEN 160000 AND 900000	easy
813	world_1	[ "city" ]	Return the names of cities that have a population between 160000 and 900000 .	select name from city where population between 160000 and 900000	easy
814	world_1	[ "countrylanguage" ]	Which language is spoken by the largest number of countries?	SELECT LANGUAGE FROM countrylanguage GROUP BY LANGUAGE ORDER BY count(*) DESC LIMIT 1	hard
815	world_1	[ "countrylanguage" ]	Give the language that is spoken in the most countries.	SELECT LANGUAGE FROM countrylanguage GROUP BY LANGUAGE ORDER BY count(*) DESC LIMIT 1	hard
816	world_1	[ "countrylanguage" ]	What is the language spoken by the largest percentage of people in each country?	SELECT LANGUAGE , CountryCode , max(Percentage) FROM countrylanguage GROUP BY CountryCode	medium
817	world_1	[ "countrylanguage" ]	What are the country codes of the different countries, and what are the languages spoken by the greatest percentage of people for each?	SELECT LANGUAGE , CountryCode , max(Percentage) FROM countrylanguage GROUP BY CountryCode	medium
818	world_1	[ "countrylanguage" ]	What is the total number of countries where Spanish is spoken by the largest percentage of people?	SELECT count(*) , max(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode	extra
819	world_1	[ "countrylanguage" ]	Count the number of countries for which Spanish is the predominantly spoken language.	SELECT count(*) , max(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode	extra
820	world_1	[ "countrylanguage" ]	What are the codes of countries where Spanish is spoken by the largest percentage of people?	SELECT CountryCode , max(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode	medium
821	world_1	[ "countrylanguage" ]	Return the codes of countries for which Spanish is the predominantly spoken language.	SELECT CountryCode , max(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode	medium
822	orchestra	[ "conductor" ]	How many conductors are there?	SELECT count(*) FROM conductor	easy
823	orchestra	[ "conductor" ]	Count the number of conductors.	SELECT count(*) FROM conductor	easy
824	orchestra	[ "conductor" ]	List the names of conductors in ascending order of age.	SELECT Name FROM conductor ORDER BY Age ASC	easy
825	orchestra	[ "conductor" ]	What are the names of conductors, ordered by age?	SELECT Name FROM conductor ORDER BY Age ASC	easy
826	orchestra	[ "conductor" ]	What are the names of conductors whose nationalities are not "USA"?	SELECT Name FROM conductor WHERE Nationality != 'USA'	easy
827	orchestra	[ "conductor" ]	Return the names of conductors that do not have the nationality "USA".	SELECT Name FROM conductor WHERE Nationality != 'USA'	easy
828	orchestra	[ "orchestra" ]	What are the record companies of orchestras in descending order of years in which they were founded?	SELECT Record_Company FROM orchestra ORDER BY Year_of_Founded DESC	easy
829	orchestra	[ "orchestra" ]	Return the record companies of orchestras, sorted descending by the years in which they were founded.	SELECT Record_Company FROM orchestra ORDER BY Year_of_Founded DESC	easy
830	orchestra	[ "SHOW" ]	What is the average attendance of shows?	SELECT avg(Attendance) FROM SHOW	easy
831	orchestra	[ "SHOW" ]	Return the average attendance across all shows.	SELECT avg(Attendance) FROM SHOW	easy
832	orchestra	[ "performance" ]	What are the maximum and minimum share of performances whose type is not "Live final".	SELECT max(SHARE) , min(SHARE) FROM performance WHERE TYPE != "Live final"	medium
833	orchestra	[ "performance" ]	Return the maximum and minimum shares for performances that do not have the type "Live final".	SELECT max(SHARE) , min(SHARE) FROM performance WHERE TYPE != "Live final"	medium
834	orchestra	[ "conductor" ]	How many different nationalities do conductors have?	SELECT count(DISTINCT Nationality) FROM conductor	easy
835	orchestra	[ "conductor" ]	Count the number of different nationalities of conductors.	SELECT count(DISTINCT Nationality) FROM conductor	easy
836	orchestra	[ "conductor" ]	List names of conductors in descending order of years of work.	SELECT Name FROM conductor ORDER BY Year_of_Work DESC	easy
837	orchestra	[ "conductor" ]	What are the names of conductors, sorted descending by the number of years they have worked?	SELECT Name FROM conductor ORDER BY Year_of_Work DESC	easy
838	orchestra	[ "conductor" ]	List the name of the conductor with the most years of work.	SELECT Name FROM conductor ORDER BY Year_of_Work DESC LIMIT 1	medium
839	orchestra	[ "conductor" ]	What is the name of the conductor who has worked the greatest number of years?	SELECT Name FROM conductor ORDER BY Year_of_Work DESC LIMIT 1	medium
840	orchestra	[ "conductor", "orchestra" ]	Show the names of conductors and the orchestras they have conducted.	SELECT T1.Name , T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID	medium
841	orchestra	[ "conductor", "orchestra" ]	What are the names of conductors as well as the corresonding orchestras that they have conducted?	SELECT T1.Name , T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID	medium
842	orchestra	[ "conductor", "orchestra" ]	Show the names of conductors that have conducted more than one orchestras.	SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1	medium
843	orchestra	[ "conductor", "orchestra" ]	What are the names of conductors who have conducted at more than one orchestra?	SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1	medium
844	orchestra	[ "conductor", "orchestra" ]	Show the name of the conductor that has conducted the most number of orchestras.	SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1	extra
845	orchestra	[ "conductor", "orchestra" ]	What is the name of the conductor who has conducted the most orchestras?	SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1	extra
846	orchestra	[ "conductor", "orchestra" ]	Please show the name of the conductor that has conducted orchestras founded after 2008.	SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008	medium
847	orchestra	[ "conductor", "orchestra" ]	What are the names of conductors who have conducted orchestras founded after the year 2008?	SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008	medium
848	orchestra	[ "orchestra" ]	Please show the different record companies and the corresponding number of orchestras.	SELECT Record_Company , COUNT(*) FROM orchestra GROUP BY Record_Company	medium
849	orchestra	[ "orchestra" ]	How many orchestras does each record company manage?	SELECT Record_Company , COUNT(*) FROM orchestra GROUP BY Record_Company	medium
850	orchestra	[ "orchestra" ]	Please show the record formats of orchestras in ascending order of count.	SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC	medium
851	orchestra	[ "orchestra" ]	What are the major record formats of orchestras, sorted by their frequency?	SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC	medium
852	orchestra	[ "orchestra" ]	List the record company shared by the most number of orchestras.	SELECT Record_Company FROM orchestra GROUP BY Record_Company ORDER BY COUNT(*) DESC LIMIT 1	hard
853	orchestra	[ "orchestra" ]	What is the record company used by the greatest number of orchestras?	SELECT Record_Company FROM orchestra GROUP BY Record_Company ORDER BY COUNT(*) DESC LIMIT 1	hard
854	orchestra	[ "orchestra", "performance" ]	List the names of orchestras that have no performance.	SELECT Orchestra FROM orchestra WHERE Orchestra_ID NOT IN (SELECT Orchestra_ID FROM performance)	hard
855	orchestra	[ "orchestra", "performance" ]	What are the orchestras that do not have any performances?	SELECT Orchestra FROM orchestra WHERE Orchestra_ID NOT IN (SELECT Orchestra_ID FROM performance)	hard
856	orchestra	[ "orchestra" ]	Show the record companies shared by orchestras founded before 2003 and after 2003.	SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003	hard
857	orchestra	[ "orchestra" ]	What are the record companies that are used by both orchestras founded before 2003 and those founded after 2003?	SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003	hard
858	orchestra	[ "orchestra" ]	Find the number of orchestras whose record format is "CD" or "DVD".	SELECT COUNT(*) FROM orchestra WHERE Major_Record_Format = "CD" OR Major_Record_Format = "DVD"	medium
859	orchestra	[ "orchestra" ]	Count the number of orchestras that have CD or DVD as their record format.	SELECT COUNT(*) FROM orchestra WHERE Major_Record_Format = "CD" OR Major_Record_Format = "DVD"	medium
860	orchestra	[ "orchestra", "performance" ]	Show the years in which orchestras that have given more than one performance are founded.	SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1	medium
861	orchestra	[ "orchestra", "performance" ]	What are years of founding for orchestras that have had more than a single performance?	SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1	medium
862	network_1	[ "Highschooler" ]	How many high schoolers are there?	SELECT count(*) FROM Highschooler	easy
863	network_1	[ "Highschooler" ]	Count the number of high schoolers.	SELECT count(*) FROM Highschooler	easy
864	network_1	[ "Highschooler" ]	Show the names and grades of each high schooler.	SELECT name , grade FROM Highschooler	medium
865	network_1	[ "Highschooler" ]	What are the names and grades for each high schooler?	SELECT name , grade FROM Highschooler	medium
866	network_1	[ "Highschooler" ]	Show all the grades of the high schoolers.	SELECT grade FROM Highschooler	easy
867	network_1	[ "Highschooler" ]	What is the grade of each high schooler?	SELECT grade FROM Highschooler	easy
868	network_1	[ "Highschooler" ]	What grade is Kyle in?	SELECT grade FROM Highschooler WHERE name = "Kyle"	easy
869	network_1	[ "Highschooler" ]	Return the grade for the high schooler named Kyle.	SELECT grade FROM Highschooler WHERE name = "Kyle"	easy
870	network_1	[ "Highschooler" ]	Show the names of all high schoolers in grade 10.	SELECT name FROM Highschooler WHERE grade = 10	easy
871	network_1	[ "Highschooler" ]	What are the names of all high schoolers in grade 10?	SELECT name FROM Highschooler WHERE grade = 10	easy
872	network_1	[ "Highschooler" ]	Show the ID of the high schooler named Kyle.	SELECT ID FROM Highschooler WHERE name = "Kyle"	easy
873	network_1	[ "Highschooler" ]	What is Kyle's id?	SELECT ID FROM Highschooler WHERE name = "Kyle"	easy
874	network_1	[ "Highschooler" ]	How many high schoolers are there in grade 9 or 10?	SELECT count(*) FROM Highschooler WHERE grade = 9 OR grade = 10	medium
875	network_1	[ "Highschooler" ]	Count the number of high schoolers in grades 9 or 10.	SELECT count(*) FROM Highschooler WHERE grade = 9 OR grade = 10	medium
876	network_1	[ "Highschooler" ]	Show the number of high schoolers for each grade.	SELECT grade , count(*) FROM Highschooler GROUP BY grade	medium
877	network_1	[ "Highschooler" ]	How many high schoolers are in each grade?	SELECT grade , count(*) FROM Highschooler GROUP BY grade	medium
878	network_1	[ "Highschooler" ]	Which grade has the most high schoolers?	SELECT grade FROM Highschooler GROUP BY grade ORDER BY count(*) DESC LIMIT 1	hard
879	network_1	[ "Highschooler" ]	Return the grade that has the greatest number of high schoolers.	SELECT grade FROM Highschooler GROUP BY grade ORDER BY count(*) DESC LIMIT 1	hard
880	network_1	[ "Highschooler" ]	Show me all grades that have at least 4 students.	SELECT grade FROM Highschooler GROUP BY grade HAVING count(*) >= 4	easy
881	network_1	[ "Highschooler" ]	Which grades have 4 or more high schoolers?	SELECT grade FROM Highschooler GROUP BY grade HAVING count(*) >= 4	easy
882	network_1	[ "Friend" ]	Show the student IDs and numbers of friends corresponding to each.	SELECT student_id , count(*) FROM Friend GROUP BY student_id	medium
883	network_1	[ "Friend" ]	How many friends does each student have?	SELECT student_id , count(*) FROM Friend GROUP BY student_id	medium
884	network_1	[ "Friend", "Highschooler" ]	Show the names of high school students and their corresponding number of friends.	SELECT T2.name , count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id	medium
885	network_1	[ "Friend", "Highschooler" ]	What are the names of the high schoolers and how many friends does each have?	SELECT T2.name , count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id	medium
886	network_1	[ "Friend", "Highschooler" ]	What is the name of the high schooler who has the greatest number of friends?	SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1	extra
887	network_1	[ "Friend", "Highschooler" ]	Return the name of the high school student with the most friends.	SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1	extra
888	network_1	[ "Friend", "Highschooler" ]	Show the names of high schoolers who have at least 3 friends.	SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING count(*) >= 3	medium
889	network_1	[ "Friend", "Highschooler" ]	What are the names of high schoolers who have 3 or more friends?	SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING count(*) >= 3	medium
890	network_1	[ "Friend", "Highschooler" ]	Show the names of all of the high schooler Kyle's friends.	SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle"	hard
891	network_1	[ "Friend", "Highschooler" ]	Return the names of friends of the high school student Kyle.	SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle"	hard
892	network_1	[ "Friend", "Highschooler" ]	How many friends does the high school student Kyle have?	SELECT count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"	medium
893	network_1	[ "Friend", "Highschooler" ]	Count the number of friends Kyle has.	SELECT count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"	medium
894	network_1	[ "Friend", "Highschooler" ]	Show ids of all students who do not have any friends.	SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend	hard
895	network_1	[ "Friend", "Highschooler" ]	What are the ids of high school students who do not have friends?	SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend	hard
896	network_1	[ "Friend", "Highschooler" ]	Show names of all high school students who do not have any friends.	SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id	hard
897	network_1	[ "Friend", "Highschooler" ]	What are the names of students who have no friends?	SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id	hard
898	network_1	[ "Likes", "Friend" ]	Show the ids of high schoolers who have friends and are also liked by someone else.	SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes	hard
899	network_1	[ "Likes", "Friend" ]	What are the ids of students who both have friends and are liked?	SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes	hard

800

world_1

[ "country" ]

What are the names and areas of countries with the top 5 largest area?

SELECT Name , SurfaceArea FROM country ORDER BY SurfaceArea DESC LIMIT 5

medium

801

world_1

[ "country" ]

Return the names and surface areas of the 5 largest countries.

SELECT Name , SurfaceArea FROM country ORDER BY SurfaceArea DESC LIMIT 5

medium

802

world_1

[ "country" ]

What are names of countries with the top 3 largest population?

SELECT Name FROM country ORDER BY Population DESC LIMIT 3

medium

803

world_1

[ "country" ]

Return the names of the 3 most populated countries.

SELECT Name FROM country ORDER BY Population DESC LIMIT 3

medium

804

world_1

[ "country" ]

What are the names of the nations with the 3 lowest populations?

SELECT Name FROM country ORDER BY Population ASC LIMIT 3

medium

805

world_1

[ "country" ]

Return the names of the 3 countries with the fewest people.

SELECT Name FROM country ORDER BY Population ASC LIMIT 3

medium

806

world_1

[ "country" ]

how many countries are in Asia?

SELECT count(*) FROM country WHERE continent = "Asia"

easy

807

world_1

[ "country" ]

Count the number of countries in Asia.

SELECT count(*) FROM country WHERE continent = "Asia"

easy

808

world_1

[ "country" ]

What are the names of the countries that are in the continent of Europe and have a population of 80000?

SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000"

medium

809

world_1

[ "country" ]

Give the names of countries that are in Europe and have a population equal to 80000.

SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000"

medium

810

world_1

[ "country" ]

What is the total population and average area of countries in the continent of North America whose area is bigger than 3000 ?

select sum(population) , avg(surfacearea) from country where continent = "north america" and surfacearea > 3000

hard

811

world_1

[ "country" ]

Give the total population and average surface area corresponding to countries in North America that have a surface area greater than 3000 .

select sum(population) , avg(surfacearea) from country where continent = "north america" and surfacearea > 3000

hard

812

world_1

[ "city" ]

What are the cities whose population is between 160000 and 900000?

SELECT name FROM city WHERE Population BETWEEN 160000 AND 900000

easy

813

world_1

[ "city" ]

Return the names of cities that have a population between 160000 and 900000 .

select name from city where population between 160000 and 900000

easy

814

world_1

[ "countrylanguage" ]

Which language is spoken by the largest number of countries?

SELECT LANGUAGE FROM countrylanguage GROUP BY LANGUAGE ORDER BY count(*) DESC LIMIT 1

hard

815

world_1

[ "countrylanguage" ]

Give the language that is spoken in the most countries.

SELECT LANGUAGE FROM countrylanguage GROUP BY LANGUAGE ORDER BY count(*) DESC LIMIT 1

hard

816

world_1

[ "countrylanguage" ]

What is the language spoken by the largest percentage of people in each country?

SELECT LANGUAGE , CountryCode , max(Percentage) FROM countrylanguage GROUP BY CountryCode

medium

817

world_1

[ "countrylanguage" ]

What are the country codes of the different countries, and what are the languages spoken by the greatest percentage of people for each?

SELECT LANGUAGE , CountryCode , max(Percentage) FROM countrylanguage GROUP BY CountryCode

medium

818

world_1

[ "countrylanguage" ]

What is the total number of countries where Spanish is spoken by the largest percentage of people?

SELECT count(*) , max(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode

extra

819

world_1

[ "countrylanguage" ]

Count the number of countries for which Spanish is the predominantly spoken language.

SELECT count(*) , max(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode

extra

820

world_1

[ "countrylanguage" ]

What are the codes of countries where Spanish is spoken by the largest percentage of people?

SELECT CountryCode , max(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode

medium

821

world_1

[ "countrylanguage" ]

Return the codes of countries for which Spanish is the predominantly spoken language.

SELECT CountryCode , max(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode

medium

822

orchestra

[ "conductor" ]

How many conductors are there?

SELECT count(*) FROM conductor

easy

823

orchestra

[ "conductor" ]

Count the number of conductors.

SELECT count(*) FROM conductor

easy

824

orchestra

[ "conductor" ]

List the names of conductors in ascending order of age.

SELECT Name FROM conductor ORDER BY Age ASC

easy

825

orchestra

[ "conductor" ]

What are the names of conductors, ordered by age?

SELECT Name FROM conductor ORDER BY Age ASC

easy

826

orchestra

[ "conductor" ]

What are the names of conductors whose nationalities are not "USA"?

SELECT Name FROM conductor WHERE Nationality != 'USA'

easy

827

orchestra

[ "conductor" ]

Return the names of conductors that do not have the nationality "USA".

SELECT Name FROM conductor WHERE Nationality != 'USA'

easy

828

orchestra

[ "orchestra" ]

What are the record companies of orchestras in descending order of years in which they were founded?

SELECT Record_Company FROM orchestra ORDER BY Year_of_Founded DESC

easy

829

orchestra

[ "orchestra" ]

Return the record companies of orchestras, sorted descending by the years in which they were founded.

SELECT Record_Company FROM orchestra ORDER BY Year_of_Founded DESC

easy

830

orchestra

[ "SHOW" ]

What is the average attendance of shows?

SELECT avg(Attendance) FROM SHOW

easy

831

orchestra

[ "SHOW" ]

Return the average attendance across all shows.

SELECT avg(Attendance) FROM SHOW

easy

832

orchestra

[ "performance" ]

What are the maximum and minimum share of performances whose type is not "Live final".

SELECT max(SHARE) , min(SHARE) FROM performance WHERE TYPE != "Live final"

medium

833

orchestra

[ "performance" ]

Return the maximum and minimum shares for performances that do not have the type "Live final".

SELECT max(SHARE) , min(SHARE) FROM performance WHERE TYPE != "Live final"

medium

834

orchestra

[ "conductor" ]

How many different nationalities do conductors have?

SELECT count(DISTINCT Nationality) FROM conductor

easy

835

orchestra

[ "conductor" ]

Count the number of different nationalities of conductors.

SELECT count(DISTINCT Nationality) FROM conductor

easy

836

orchestra

[ "conductor" ]

List names of conductors in descending order of years of work.

SELECT Name FROM conductor ORDER BY Year_of_Work DESC

easy

837

orchestra

[ "conductor" ]

What are the names of conductors, sorted descending by the number of years they have worked?

SELECT Name FROM conductor ORDER BY Year_of_Work DESC

easy

838

orchestra

[ "conductor" ]

List the name of the conductor with the most years of work.

SELECT Name FROM conductor ORDER BY Year_of_Work DESC LIMIT 1

medium

839

orchestra

[ "conductor" ]

What is the name of the conductor who has worked the greatest number of years?

SELECT Name FROM conductor ORDER BY Year_of_Work DESC LIMIT 1

medium

840

orchestra

[ "conductor", "orchestra" ]

Show the names of conductors and the orchestras they have conducted.

SELECT T1.Name , T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID

medium

841

orchestra

[ "conductor", "orchestra" ]

What are the names of conductors as well as the corresonding orchestras that they have conducted?

SELECT T1.Name , T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID

medium

842

orchestra

[ "conductor", "orchestra" ]

Show the names of conductors that have conducted more than one orchestras.

SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1

medium

843

orchestra

[ "conductor", "orchestra" ]

What are the names of conductors who have conducted at more than one orchestra?

SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1

medium

844

orchestra

[ "conductor", "orchestra" ]

Show the name of the conductor that has conducted the most number of orchestras.

SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1

extra

845

orchestra

[ "conductor", "orchestra" ]

What is the name of the conductor who has conducted the most orchestras?

SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1

extra

846

orchestra

[ "conductor", "orchestra" ]

Please show the name of the conductor that has conducted orchestras founded after 2008.

SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008

medium

847

orchestra

[ "conductor", "orchestra" ]

What are the names of conductors who have conducted orchestras founded after the year 2008?

SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008

medium

848

orchestra

[ "orchestra" ]

Please show the different record companies and the corresponding number of orchestras.

SELECT Record_Company , COUNT(*) FROM orchestra GROUP BY Record_Company

medium

849

orchestra

[ "orchestra" ]

How many orchestras does each record company manage?

SELECT Record_Company , COUNT(*) FROM orchestra GROUP BY Record_Company

medium

850

orchestra

[ "orchestra" ]

Please show the record formats of orchestras in ascending order of count.

SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC

medium

851

orchestra

[ "orchestra" ]

What are the major record formats of orchestras, sorted by their frequency?

SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC

medium

852

orchestra

[ "orchestra" ]

List the record company shared by the most number of orchestras.

SELECT Record_Company FROM orchestra GROUP BY Record_Company ORDER BY COUNT(*) DESC LIMIT 1

hard

853

orchestra

[ "orchestra" ]

What is the record company used by the greatest number of orchestras?

SELECT Record_Company FROM orchestra GROUP BY Record_Company ORDER BY COUNT(*) DESC LIMIT 1

hard

854

orchestra

[ "orchestra", "performance" ]

List the names of orchestras that have no performance.

SELECT Orchestra FROM orchestra WHERE Orchestra_ID NOT IN (SELECT Orchestra_ID FROM performance)

hard

855

orchestra

[ "orchestra", "performance" ]

What are the orchestras that do not have any performances?

SELECT Orchestra FROM orchestra WHERE Orchestra_ID NOT IN (SELECT Orchestra_ID FROM performance)

hard

856

orchestra

[ "orchestra" ]

Show the record companies shared by orchestras founded before 2003 and after 2003.

SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003

hard

857

orchestra

[ "orchestra" ]

What are the record companies that are used by both orchestras founded before 2003 and those founded after 2003?

SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003

hard

858

orchestra

[ "orchestra" ]

Find the number of orchestras whose record format is "CD" or "DVD".

SELECT COUNT(*) FROM orchestra WHERE Major_Record_Format = "CD" OR Major_Record_Format = "DVD"

medium

859

orchestra

[ "orchestra" ]

Count the number of orchestras that have CD or DVD as their record format.

SELECT COUNT(*) FROM orchestra WHERE Major_Record_Format = "CD" OR Major_Record_Format = "DVD"

medium

860

orchestra

[ "orchestra", "performance" ]

Show the years in which orchestras that have given more than one performance are founded.

SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1

medium

861

orchestra

[ "orchestra", "performance" ]

What are years of founding for orchestras that have had more than a single performance?

SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1

medium

862

network_1

[ "Highschooler" ]

How many high schoolers are there?

SELECT count(*) FROM Highschooler

easy

863

network_1

[ "Highschooler" ]

Count the number of high schoolers.

SELECT count(*) FROM Highschooler

easy

864

network_1

[ "Highschooler" ]

Show the names and grades of each high schooler.

SELECT name , grade FROM Highschooler

medium

865

network_1

[ "Highschooler" ]

What are the names and grades for each high schooler?

SELECT name , grade FROM Highschooler

medium

866

network_1

[ "Highschooler" ]

Show all the grades of the high schoolers.

SELECT grade FROM Highschooler

easy

867

network_1

[ "Highschooler" ]

What is the grade of each high schooler?

SELECT grade FROM Highschooler

easy

868

network_1

[ "Highschooler" ]

What grade is Kyle in?

SELECT grade FROM Highschooler WHERE name = "Kyle"

easy

869

network_1

[ "Highschooler" ]

Return the grade for the high schooler named Kyle.

SELECT grade FROM Highschooler WHERE name = "Kyle"

easy

870

network_1

[ "Highschooler" ]

Show the names of all high schoolers in grade 10.

SELECT name FROM Highschooler WHERE grade = 10

easy

871

network_1

[ "Highschooler" ]

What are the names of all high schoolers in grade 10?

SELECT name FROM Highschooler WHERE grade = 10

easy

872

network_1

[ "Highschooler" ]

Show the ID of the high schooler named Kyle.

SELECT ID FROM Highschooler WHERE name = "Kyle"

easy

873

network_1

[ "Highschooler" ]

What is Kyle's id?

SELECT ID FROM Highschooler WHERE name = "Kyle"

easy

874

network_1

[ "Highschooler" ]

How many high schoolers are there in grade 9 or 10?

SELECT count(*) FROM Highschooler WHERE grade = 9 OR grade = 10

medium

875

network_1

[ "Highschooler" ]

Count the number of high schoolers in grades 9 or 10.

SELECT count(*) FROM Highschooler WHERE grade = 9 OR grade = 10

medium

876

network_1

[ "Highschooler" ]

Show the number of high schoolers for each grade.

SELECT grade , count(*) FROM Highschooler GROUP BY grade

medium

877

network_1

[ "Highschooler" ]

How many high schoolers are in each grade?

SELECT grade , count(*) FROM Highschooler GROUP BY grade

medium

878

network_1

[ "Highschooler" ]

Which grade has the most high schoolers?

SELECT grade FROM Highschooler GROUP BY grade ORDER BY count(*) DESC LIMIT 1

hard

879

network_1

[ "Highschooler" ]

Return the grade that has the greatest number of high schoolers.

SELECT grade FROM Highschooler GROUP BY grade ORDER BY count(*) DESC LIMIT 1

hard

880

network_1

[ "Highschooler" ]

Show me all grades that have at least 4 students.

SELECT grade FROM Highschooler GROUP BY grade HAVING count(*) >= 4

easy

881

network_1

[ "Highschooler" ]

Which grades have 4 or more high schoolers?

SELECT grade FROM Highschooler GROUP BY grade HAVING count(*) >= 4

easy

882

network_1

[ "Friend" ]

Show the student IDs and numbers of friends corresponding to each.

SELECT student_id , count(*) FROM Friend GROUP BY student_id

medium

883

network_1

[ "Friend" ]

How many friends does each student have?

SELECT student_id , count(*) FROM Friend GROUP BY student_id

medium

884

network_1

[ "Friend", "Highschooler" ]

Show the names of high school students and their corresponding number of friends.

SELECT T2.name , count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id

medium

885

network_1

[ "Friend", "Highschooler" ]

What are the names of the high schoolers and how many friends does each have?

SELECT T2.name , count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id

medium

886

network_1

[ "Friend", "Highschooler" ]

What is the name of the high schooler who has the greatest number of friends?

SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1

extra

887

network_1

[ "Friend", "Highschooler" ]

Return the name of the high school student with the most friends.

SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1

extra

888

network_1

[ "Friend", "Highschooler" ]

Show the names of high schoolers who have at least 3 friends.

SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING count(*) >= 3

medium

889

network_1

[ "Friend", "Highschooler" ]

What are the names of high schoolers who have 3 or more friends?

SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING count(*) >= 3

medium

890

network_1

[ "Friend", "Highschooler" ]

Show the names of all of the high schooler Kyle's friends.

SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle"

hard

891

network_1

[ "Friend", "Highschooler" ]

Return the names of friends of the high school student Kyle.

SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle"

hard

892

network_1

[ "Friend", "Highschooler" ]

How many friends does the high school student Kyle have?

SELECT count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"

medium

893

network_1

[ "Friend", "Highschooler" ]

Count the number of friends Kyle has.

SELECT count(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"

medium

894

network_1

[ "Friend", "Highschooler" ]

Show ids of all students who do not have any friends.

SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend

hard

895

network_1

[ "Friend", "Highschooler" ]

What are the ids of high school students who do not have friends?

SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend

hard

896

network_1

[ "Friend", "Highschooler" ]

Show names of all high school students who do not have any friends.

SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id

hard

897

network_1

[ "Friend", "Highschooler" ]

What are the names of students who have no friends?

SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id

hard

898

network_1

[ "Likes", "Friend" ]

Show the ids of high schoolers who have friends and are also liked by someone else.

SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes

hard

899

network_1

[ "Likes", "Friend" ]

What are the ids of students who both have friends and are liked?

SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes

hard