query_id
int64 0
7k
| database_id
stringclasses 140
values | table_id
listlengths 1
5
| query
stringlengths 16
224
| answer
stringlengths 18
577
| difficulty
stringclasses 4
values |
|---|---|---|---|---|---|
5,600 |
swimming
|
[
"event"
] |
List all the event names by year from the most recent to the oldest.
|
SELECT name FROM event ORDER BY YEAR DESC
|
easy
|
5,601 |
swimming
|
[
"event"
] |
What is the name of the event that happened in the most recent year?
|
SELECT name FROM event ORDER BY YEAR DESC LIMIT 1
|
medium
|
5,602 |
swimming
|
[
"stadium"
] |
How many stadiums are there?
|
SELECT count(*) FROM stadium
|
easy
|
5,603 |
swimming
|
[
"stadium"
] |
Find the name of the stadium that has the maximum capacity.
|
SELECT name FROM stadium ORDER BY capacity DESC LIMIT 1
|
medium
|
5,604 |
swimming
|
[
"stadium"
] |
Find the names of stadiums whose capacity is smaller than the average capacity.
|
SELECT name FROM stadium WHERE capacity < (SELECT avg(capacity) FROM stadium)
|
hard
|
5,605 |
swimming
|
[
"stadium"
] |
Find the country that has the most stadiums.
|
SELECT country FROM stadium GROUP BY country ORDER BY count(*) DESC LIMIT 1
|
hard
|
5,606 |
swimming
|
[
"stadium"
] |
Which country has at most 3 stadiums listed?
|
SELECT country FROM stadium GROUP BY country HAVING count(*) <= 3
|
easy
|
5,607 |
swimming
|
[
"stadium"
] |
Which country has both stadiums with capacity greater than 60000 and stadiums with capacity less than 50000?
|
SELECT country FROM stadium WHERE capacity > 60000 INTERSECT SELECT country FROM stadium WHERE capacity < 50000
|
hard
|
5,608 |
swimming
|
[
"stadium"
] |
How many cities have a stadium that was opened before the year of 2006?
|
SELECT count(DISTINCT city) FROM stadium WHERE opening_year < 2006
|
easy
|
5,609 |
swimming
|
[
"stadium"
] |
How many stadiums does each country have?
|
SELECT country , count(*) FROM stadium GROUP BY country
|
medium
|
5,610 |
swimming
|
[
"stadium"
] |
Which countries do not have a stadium that was opened after 2006?
|
SELECT country FROM stadium EXCEPT SELECT country FROM stadium WHERE opening_year > 2006
|
hard
|
5,611 |
swimming
|
[
"stadium"
] |
How many stadiums are not in country "Russia"?
|
SELECT count(*) FROM stadium WHERE country != 'Russia'
|
easy
|
5,612 |
swimming
|
[
"swimmer"
] |
Find the names of all swimmers, sorted by their 100 meter scores in ascending order.
|
SELECT name FROM swimmer ORDER BY meter_100
|
easy
|
5,613 |
swimming
|
[
"swimmer"
] |
How many different countries are all the swimmers from?
|
SELECT count(DISTINCT nationality) FROM swimmer
|
easy
|
5,614 |
swimming
|
[
"swimmer"
] |
List countries that have more than one swimmer.
|
SELECT nationality , count(*) FROM swimmer GROUP BY nationality HAVING count(*) > 1
|
medium
|
5,615 |
swimming
|
[
"swimmer"
] |
Find all 200 meter and 300 meter results of swimmers with nationality "Australia".
|
SELECT meter_200 , meter_300 FROM swimmer WHERE nationality = 'Australia'
|
medium
|
5,616 |
swimming
|
[
"swimmer",
"record"
] |
Find the names of swimmers who has a result of "win".
|
SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = 'Win'
|
medium
|
5,617 |
swimming
|
[
"stadium",
"event"
] |
What is the name of the stadium which held the most events?
|
SELECT t1.name FROM stadium AS t1 JOIN event AS t2 ON t1.id = t2.stadium_id GROUP BY t2.stadium_id ORDER BY count(*) DESC LIMIT 1
|
extra
|
5,618 |
swimming
|
[
"stadium",
"event"
] |
Find the name and capacity of the stadium where the event named "World Junior" happened.
|
SELECT t1.name , t1.capacity FROM stadium AS t1 JOIN event AS t2 ON t1.id = t2.stadium_id WHERE t2.name = 'World Junior'
|
medium
|
5,619 |
swimming
|
[
"stadium",
"event"
] |
Find the names of stadiums which have never had any event.
|
SELECT name FROM stadium WHERE id NOT IN (SELECT stadium_id FROM event)
|
hard
|
5,620 |
swimming
|
[
"swimmer",
"record"
] |
Find the name of the swimmer who has the most records.
|
SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id GROUP BY t2.swimmer_id ORDER BY count(*) DESC LIMIT 1
|
extra
|
5,621 |
swimming
|
[
"swimmer",
"record"
] |
Find the name of the swimmer who has at least 2 records.
|
SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id GROUP BY t2.swimmer_id HAVING count(*) >= 2
|
medium
|
5,622 |
swimming
|
[
"swimmer",
"record"
] |
Find the name and nationality of the swimmer who has won (i.e., has a result of "win") more than 1 time.
|
SELECT t1.name , t1.nationality FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = 'Win' GROUP BY t2.swimmer_id HAVING count(*) > 1
|
hard
|
5,623 |
swimming
|
[
"swimmer",
"record"
] |
Find the names of the swimmers who have no record.
|
SELECT name FROM swimmer WHERE id NOT IN (SELECT swimmer_id FROM record)
|
hard
|
5,624 |
swimming
|
[
"swimmer",
"record"
] |
Find the names of the swimmers who have both "win" and "loss" results in the record.
|
SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = 'Win' INTERSECT SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = 'Loss'
|
extra
|
5,625 |
swimming
|
[
"swimmer",
"record",
"stadium",
"event"
] |
Find the names of stadiums that some Australian swimmers have been to.
|
SELECT t4.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id JOIN event AS t3 ON t2.event_id = t3.id JOIN stadium AS t4 ON t4.id = t3.stadium_id WHERE t1.nationality = 'Australia'
|
extra
|
5,626 |
swimming
|
[
"stadium",
"record",
"event"
] |
Find the names of stadiums that the most swimmers have been to.
|
SELECT t3.name FROM record AS t1 JOIN event AS t2 ON t1.event_id = t2.id JOIN stadium AS t3 ON t3.id = t2.stadium_id GROUP BY t2.stadium_id ORDER BY count(*) DESC LIMIT 1
|
extra
|
5,627 |
swimming
|
[
"swimmer"
] |
Find all details for each swimmer.
|
SELECT * FROM swimmer
|
easy
|
5,628 |
swimming
|
[
"stadium"
] |
What is the average capacity of the stadiums that were opened in year 2005?
|
SELECT avg(capacity) FROM stadium WHERE opening_year = 2005
|
easy
|
5,629 |
railway
|
[
"railway"
] |
How many railways are there?
|
SELECT count(*) FROM railway
|
easy
|
5,630 |
railway
|
[
"railway"
] |
List the builders of railways in ascending alphabetical order.
|
SELECT Builder FROM railway ORDER BY Builder ASC
|
easy
|
5,631 |
railway
|
[
"railway"
] |
List the wheels and locations of the railways.
|
SELECT Wheels , LOCATION FROM railway
|
medium
|
5,632 |
railway
|
[
"manager"
] |
What is the maximum level of managers in countries that are not "Australia"?
|
SELECT max(LEVEL) FROM manager WHERE Country != "Australia "
|
easy
|
5,633 |
railway
|
[
"manager"
] |
What is the average age for all managers?
|
SELECT avg(Age) FROM manager
|
easy
|
5,634 |
railway
|
[
"manager"
] |
What are the names of managers in ascending order of level?
|
SELECT Name FROM manager ORDER BY LEVEL ASC
|
easy
|
5,635 |
railway
|
[
"train"
] |
What are the names and arrival times of trains?
|
SELECT Name , Arrival FROM train
|
medium
|
5,636 |
railway
|
[
"manager"
] |
What is the name of the oldest manager?
|
SELECT Name FROM manager ORDER BY Age DESC LIMIT 1
|
medium
|
5,637 |
railway
|
[
"train",
"railway"
] |
Show the names of trains and locations of railways they are in.
|
SELECT T2.Name , T1.Location FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID
|
medium
|
5,638 |
railway
|
[
"train",
"railway"
] |
Show the builder of railways associated with the trains named "Andaman Exp".
|
SELECT T1.Builder FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID WHERE T2.Name = "Andaman Exp"
|
medium
|
5,639 |
railway
|
[
"train",
"railway"
] |
Show id and location of railways that are associated with more than one train.
|
SELECT T2.Railway_ID , T1.Location FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID GROUP BY T2.Railway_ID HAVING COUNT(*) > 1
|
medium
|
5,640 |
railway
|
[
"train",
"railway"
] |
Show the id and builder of the railway that are associated with the most trains.
|
SELECT T2.Railway_ID , T1.Builder FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID GROUP BY T2.Railway_ID ORDER BY COUNT(*) DESC LIMIT 1
|
extra
|
5,641 |
railway
|
[
"railway"
] |
Show different builders of railways, along with the corresponding number of railways using each builder.
|
SELECT Builder , COUNT(*) FROM railway GROUP BY Builder
|
medium
|
5,642 |
railway
|
[
"railway"
] |
Show the most common builder of railways.
|
SELECT Builder FROM railway GROUP BY Builder ORDER BY COUNT(*) DESC LIMIT 1
|
hard
|
5,643 |
railway
|
[
"railway"
] |
Show different locations of railways along with the corresponding number of railways at each location.
|
SELECT LOCATION , COUNT(*) FROM railway GROUP BY LOCATION
|
medium
|
5,644 |
railway
|
[
"railway"
] |
Show the locations that have more than one railways.
|
SELECT LOCATION FROM railway GROUP BY LOCATION HAVING COUNT(*) > 1
|
easy
|
5,645 |
railway
|
[
"train",
"railway"
] |
List the object number of railways that do not have any trains.
|
SELECT ObjectNumber FROM railway WHERE Railway_ID NOT IN (SELECT Railway_ID FROM train)
|
hard
|
5,646 |
railway
|
[
"manager"
] |
Show the countries that have both managers of age above 50 and managers of age below 46.
|
SELECT Country FROM manager WHERE Age > 50 INTERSECT SELECT Country FROM manager WHERE Age < 46
|
hard
|
5,647 |
railway
|
[
"manager"
] |
Show the distinct countries of managers.
|
SELECT DISTINCT Country FROM manager
|
easy
|
5,648 |
railway
|
[
"manager"
] |
Show the working years of managers in descending order of their level.
|
SELECT Working_year_starts FROM manager ORDER BY LEVEL DESC
|
easy
|
5,649 |
railway
|
[
"manager"
] |
Show the countries that have managers of age above 50 or below 46.
|
SELECT Country FROM manager WHERE Age > 50 OR Age < 46
|
medium
|
5,650 |
customers_and_products_contacts
|
[
"addresses"
] |
How many addresses are there in country USA?
|
SELECT count(*) FROM addresses WHERE country = 'USA'
|
easy
|
5,651 |
customers_and_products_contacts
|
[
"addresses"
] |
Show all distinct cities in the address record.
|
SELECT DISTINCT city FROM addresses
|
easy
|
5,652 |
customers_and_products_contacts
|
[
"addresses"
] |
Show each state and the number of addresses in each state.
|
SELECT state_province_county , count(*) FROM addresses GROUP BY state_province_county
|
medium
|
5,653 |
customers_and_products_contacts
|
[
"customer_address_history",
"customers"
] |
Show names and phones of customers who do not have address information.
|
SELECT customer_name , customer_phone FROM customers WHERE customer_id NOT IN (SELECT customer_id FROM customer_address_history)
|
extra
|
5,654 |
customers_and_products_contacts
|
[
"customer_orders",
"customers"
] |
Show the name of the customer who has the most orders.
|
SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1
|
extra
|
5,655 |
customers_and_products_contacts
|
[
"products"
] |
Show the product type codes which have at least two products.
|
SELECT product_type_code FROM products GROUP BY product_type_code HAVING count(*) >= 2
|
easy
|
5,656 |
customers_and_products_contacts
|
[
"customer_orders",
"customers"
] |
Show the names of customers who have both an order in completed status and an order in part status.
|
SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status_code = 'Completed' INTERSECT SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status_code = 'Part'
|
extra
|
5,657 |
customers_and_products_contacts
|
[
"customers"
] |
Show the name, phone, and payment method code for all customers in descending order of customer number.
|
SELECT customer_name , customer_phone , payment_method_code FROM customers ORDER BY customer_number DESC
|
medium
|
5,658 |
customers_and_products_contacts
|
[
"products",
"order_items"
] |
Show the product name and total order quantity for each product.
|
SELECT T1.product_name , sum(T2.order_quantity) FROM products AS T1 JOIN order_items AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_id
|
medium
|
5,659 |
customers_and_products_contacts
|
[
"products"
] |
Show the minimum, maximum, average price for all products.
|
SELECT min(product_price) , max(product_price) , avg(product_price) FROM products
|
medium
|
5,660 |
customers_and_products_contacts
|
[
"products"
] |
How many products have a price higher than the average?
|
SELECT count(*) FROM products WHERE product_price > (SELECT avg(product_price) FROM products)
|
hard
|
5,661 |
customers_and_products_contacts
|
[
"addresses",
"customer_address_history",
"customers"
] |
Show the customer name, customer address city, date from, and date to for each customer address history.
|
SELECT T2.customer_name , T3.city , T1.date_from , T1.date_to FROM customer_address_history AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id JOIN addresses AS T3 ON T1.address_id = T3.address_id
|
medium
|
5,662 |
customers_and_products_contacts
|
[
"customer_orders",
"customers"
] |
Show the names of customers who use Credit Card payment method and have more than 2 orders.
|
SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T1.payment_method_code = 'Credit Card' GROUP BY T1.customer_id HAVING count(*) > 2
|
hard
|
5,663 |
customers_and_products_contacts
|
[
"customer_orders",
"customers",
"order_items"
] |
What are the name and phone of the customer with the most ordered product quantity?
|
SELECT T1.customer_name , T1.customer_phone FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id JOIN order_items AS T3 ON T3.order_id = T2.order_id GROUP BY T1.customer_id ORDER BY sum(T3.order_quantity) DESC LIMIT 1
|
extra
|
5,664 |
customers_and_products_contacts
|
[
"products"
] |
Show the product type and name for the products with price higher than 1000 or lower than 500.
|
SELECT product_type_code , product_name FROM products WHERE product_price > 1000 OR product_price < 500
|
extra
|
5,665 |
dorm_1
|
[
"dorm"
] |
Find the name of dorms only for female (F gender).
|
SELECT dorm_name FROM dorm WHERE gender = 'F'
|
easy
|
5,666 |
dorm_1
|
[
"dorm"
] |
What are the names of the all-female dorms?
|
SELECT dorm_name FROM dorm WHERE gender = 'F'
|
easy
|
5,667 |
dorm_1
|
[
"dorm"
] |
Find the name of dorms that can accommodate more than 300 students.
|
SELECT dorm_name FROM dorm WHERE student_capacity > 300
|
easy
|
5,668 |
dorm_1
|
[
"dorm"
] |
What are the names of all the dorms that can accomdate more than 300 students?
|
SELECT dorm_name FROM dorm WHERE student_capacity > 300
|
easy
|
5,669 |
dorm_1
|
[
"student"
] |
How many female students (sex is F) whose age is below 25?
|
SELECT count(*) FROM student WHERE sex = 'F' AND age < 25
|
medium
|
5,670 |
dorm_1
|
[
"student"
] |
How many girl students who are younger than 25?
|
SELECT count(*) FROM student WHERE sex = 'F' AND age < 25
|
medium
|
5,671 |
dorm_1
|
[
"student"
] |
Find the first name of students who is older than 20.
|
SELECT fname FROM student WHERE age > 20
|
easy
|
5,672 |
dorm_1
|
[
"student"
] |
What are the first names of all students who are older than 20?
|
SELECT fname FROM student WHERE age > 20
|
easy
|
5,673 |
dorm_1
|
[
"student"
] |
Find the first name of students living in city PHL whose age is between 20 and 25.
|
SELECT fname FROM student WHERE city_code = 'PHL' AND age BETWEEN 20 AND 25
|
medium
|
5,674 |
dorm_1
|
[
"student"
] |
What is the first name of the students who are in age 20 to 25 and living in PHL city?
|
SELECT fname FROM student WHERE city_code = 'PHL' AND age BETWEEN 20 AND 25
|
medium
|
5,675 |
dorm_1
|
[
"dorm"
] |
How many dorms are there?
|
SELECT count(*) FROM dorm
|
easy
|
5,676 |
dorm_1
|
[
"dorm"
] |
How many dorms are in the database?
|
SELECT count(*) FROM dorm
|
easy
|
5,677 |
dorm_1
|
[
"dorm_amenity"
] |
Find the number of distinct amenities.
|
SELECT count(*) FROM dorm_amenity
|
easy
|
5,678 |
dorm_1
|
[
"dorm_amenity"
] |
How many diffrent dorm amenities are there?
|
SELECT count(*) FROM dorm_amenity
|
easy
|
5,679 |
dorm_1
|
[
"dorm"
] |
Find the total capacity of all dorms.
|
SELECT sum(student_capacity) FROM dorm
|
easy
|
5,680 |
dorm_1
|
[
"dorm"
] |
What is the total student capacity of all dorms?
|
SELECT sum(student_capacity) FROM dorm
|
easy
|
5,681 |
dorm_1
|
[
"student"
] |
How many students are there?
|
SELECT count(*) FROM student
|
easy
|
5,682 |
dorm_1
|
[
"student"
] |
How many students exist?
|
SELECT count(*) FROM student
|
easy
|
5,683 |
dorm_1
|
[
"student"
] |
Find the average age of all students living in the each city.
|
SELECT avg(age) , city_code FROM student GROUP BY city_code
|
medium
|
5,684 |
dorm_1
|
[
"student"
] |
What is the average age for each city and what are those cities?
|
SELECT avg(age) , city_code FROM student GROUP BY city_code
|
medium
|
5,685 |
dorm_1
|
[
"dorm"
] |
Find the average and total capacity of dorms for the students with gender X.
|
SELECT avg(student_capacity) , sum(student_capacity) FROM dorm WHERE gender = 'X'
|
medium
|
5,686 |
dorm_1
|
[
"dorm"
] |
What is the average and total capacity for all dorms who are of gender X?
|
SELECT avg(student_capacity) , sum(student_capacity) FROM dorm WHERE gender = 'X'
|
medium
|
5,687 |
dorm_1
|
[
"has_amenity"
] |
Find the number of dorms that have some amenity.
|
SELECT count(DISTINCT dormid) FROM has_amenity
|
easy
|
5,688 |
dorm_1
|
[
"has_amenity"
] |
How many dorms have amenities?
|
SELECT count(DISTINCT dormid) FROM has_amenity
|
easy
|
5,689 |
dorm_1
|
[
"has_amenity",
"dorm"
] |
Find the name of dorms that do not have any amenity
|
SELECT dorm_name FROM dorm WHERE dormid NOT IN (SELECT dormid FROM has_amenity)
|
hard
|
5,690 |
dorm_1
|
[
"has_amenity",
"dorm"
] |
What are the names of all the dorms that don't have any amenities?
|
SELECT dorm_name FROM dorm WHERE dormid NOT IN (SELECT dormid FROM has_amenity)
|
hard
|
5,691 |
dorm_1
|
[
"dorm"
] |
Find the number of distinct gender for dorms.
|
SELECT count(DISTINCT gender) FROM dorm
|
easy
|
5,692 |
dorm_1
|
[
"dorm"
] |
How many different genders are there in the dorms?
|
SELECT count(DISTINCT gender) FROM dorm
|
easy
|
5,693 |
dorm_1
|
[
"dorm"
] |
Find the capacity and gender type of the dorm whose name has substring ‘Donor’.
|
SELECT student_capacity , gender FROM dorm WHERE dorm_name LIKE '%Donor%'
|
medium
|
5,694 |
dorm_1
|
[
"dorm"
] |
What is the student capacity and type of gender for the dorm whose name as the phrase Donor in it?
|
SELECT student_capacity , gender FROM dorm WHERE dorm_name LIKE '%Donor%'
|
medium
|
5,695 |
dorm_1
|
[
"dorm"
] |
Find the name and gender type of the dorms whose capacity is greater than 300 or less than 100.
|
SELECT dorm_name , gender FROM dorm WHERE student_capacity > 300 OR student_capacity < 100
|
extra
|
5,696 |
dorm_1
|
[
"dorm"
] |
What are the names and types of the dorms that have a capacity greater than 300 or less than 100?
|
SELECT dorm_name , gender FROM dorm WHERE student_capacity > 300 OR student_capacity < 100
|
extra
|
5,697 |
dorm_1
|
[
"student"
] |
Find the numbers of different majors and cities.
|
SELECT count(DISTINCT major) , count(DISTINCT city_code) FROM student
|
medium
|
5,698 |
dorm_1
|
[
"student"
] |
How many different majors are there and how many different city codes are there for each student?
|
SELECT count(DISTINCT major) , count(DISTINCT city_code) FROM student
|
medium
|
5,699 |
dorm_1
|
[
"has_amenity",
"dorm",
"dorm_amenity"
] |
Find the name of dorms which have both TV Lounge and Study Room as amenities.
|
SELECT T1.dorm_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T3.amenity_name = 'TV Lounge' INTERSECT SELECT T1.dorm_name FROM dorm AS T1 JOIN has_amenity AS T2 ON T1.dormid = T2.dormid JOIN dorm_amenity AS T3 ON T2.amenid = T3.amenid WHERE T3.amenity_name = 'Study Room'
|
extra
|
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