query_id
int64 0
7k
| database_id
stringclasses 140
values | table_id
listlengths 1
5
| query
stringlengths 16
224
| answer
stringlengths 18
577
| difficulty
stringclasses 4
values |
|---|---|---|---|---|---|
6,300 |
city_record
|
[
"match"
] |
What are the venues of all the matches? Sort them in the descending order of match date.
|
SELECT venue FROM MATCH ORDER BY date DESC
|
easy
|
6,301 |
city_record
|
[
"city"
] |
what is the GDP of the city with the largest population.
|
SELECT gdp FROM city ORDER BY Regional_Population DESC LIMIT 1
|
medium
|
6,302 |
city_record
|
[
"city"
] |
Find the GDP of the city with the largest regional population.
|
SELECT gdp FROM city ORDER BY Regional_Population DESC LIMIT 1
|
medium
|
6,303 |
city_record
|
[
"city",
"hosting_city"
] |
What are the GDP and population of the city that already served as a host more than once?
|
SELECT t1.gdp , t1.Regional_Population FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city GROUP BY t2.Host_City HAVING count(*) > 1
|
medium
|
6,304 |
city_record
|
[
"city",
"hosting_city"
] |
Which cities have served as host cities more than once? Return me their GDP and population.
|
SELECT t1.gdp , t1.Regional_Population FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city GROUP BY t2.Host_City HAVING count(*) > 1
|
medium
|
6,305 |
e_government
|
[
"individuals"
] |
List every individual's first name, middle name and last name in alphabetical order by last name.
|
SELECT individual_first_name , individual_middle_name , individual_last_name FROM individuals ORDER BY individual_last_name
|
medium
|
6,306 |
e_government
|
[
"individuals"
] |
What are the first, middle, and last names of all individuals, ordered by last name?
|
SELECT individual_first_name , individual_middle_name , individual_last_name FROM individuals ORDER BY individual_last_name
|
medium
|
6,307 |
e_government
|
[
"forms"
] |
List all the types of forms.
|
SELECT DISTINCT form_type_code FROM forms
|
easy
|
6,308 |
e_government
|
[
"forms"
] |
What are the different types of forms?
|
SELECT DISTINCT form_type_code FROM forms
|
easy
|
6,309 |
e_government
|
[
"forms",
"party_forms"
] |
Find the name of the most popular party form.
|
SELECT t1.form_name FROM forms AS t1 JOIN party_forms AS t2 ON t1.form_id = t2.form_id GROUP BY t2.form_id ORDER BY count(*) DESC LIMIT 1
|
extra
|
6,310 |
e_government
|
[
"forms",
"party_forms"
] |
What is the name of the party form that is most common?
|
SELECT t1.form_name FROM forms AS t1 JOIN party_forms AS t2 ON t1.form_id = t2.form_id GROUP BY t2.form_id ORDER BY count(*) DESC LIMIT 1
|
extra
|
6,311 |
e_government
|
[
"parties"
] |
Find the payment method and phone of the party with email "[email protected]".
|
SELECT payment_method_code , party_phone FROM parties WHERE party_email = "[email protected]"
|
medium
|
6,312 |
e_government
|
[
"parties"
] |
What is the payment method code and party phone of the party with the email '[email protected]'?
|
SELECT payment_method_code , party_phone FROM parties WHERE party_email = "[email protected]"
|
medium
|
6,313 |
e_government
|
[
"parties",
"party_forms"
] |
Find the emails of parties with the most popular party form.
|
SELECT t1.party_email FROM parties AS t1 JOIN party_forms AS t2 ON t1.party_id = t2.party_id WHERE t2.form_id = (SELECT form_id FROM party_forms GROUP BY form_id ORDER BY count(*) DESC LIMIT 1)
|
extra
|
6,314 |
e_government
|
[
"parties",
"party_forms"
] |
What are the party emails associated with parties that used the party form that is the most common?
|
SELECT t1.party_email FROM parties AS t1 JOIN party_forms AS t2 ON t1.party_id = t2.party_id WHERE t2.form_id = (SELECT form_id FROM party_forms GROUP BY form_id ORDER BY count(*) DESC LIMIT 1)
|
extra
|
6,315 |
e_government
|
[
"organizations"
] |
List all the name of organizations in order of the date formed.
|
SELECT organization_name FROM organizations ORDER BY date_formed ASC
|
easy
|
6,316 |
e_government
|
[
"organizations"
] |
What are the names of organizations, ordered by the date they were formed, ascending?
|
SELECT organization_name FROM organizations ORDER BY date_formed ASC
|
easy
|
6,317 |
e_government
|
[
"organizations"
] |
Find the name of the youngest organization.
|
SELECT organization_name FROM organizations ORDER BY date_formed DESC LIMIT 1
|
medium
|
6,318 |
e_government
|
[
"organizations"
] |
What is the name of the organization that was formed most recently?
|
SELECT organization_name FROM organizations ORDER BY date_formed DESC LIMIT 1
|
medium
|
6,319 |
e_government
|
[
"organizations",
"organization_contact_individuals",
"individuals"
] |
Find the last name of the latest contact individual of the organization "Labour Party".
|
SELECT t3.individual_last_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id JOIN individuals AS t3 ON t2.individual_id = t3.individual_id WHERE t1.organization_name = "Labour Party" ORDER BY t2.date_contact_to DESC LIMIT 1
|
extra
|
6,320 |
e_government
|
[
"organizations",
"organization_contact_individuals",
"individuals"
] |
What is the last name of the contact individual from the Labour party organization who was contacted most recently?
|
SELECT t3.individual_last_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id JOIN individuals AS t3 ON t2.individual_id = t3.individual_id WHERE t1.organization_name = "Labour Party" ORDER BY t2.date_contact_to DESC LIMIT 1
|
extra
|
6,321 |
e_government
|
[
"organizations",
"organization_contact_individuals",
"individuals"
] |
Find the last name of the first ever contact person of the organization with the highest UK Vat number.
|
SELECT t3.individual_last_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id JOIN individuals AS t3 ON t2.individual_id = t3.individual_id WHERE t1.uk_vat_number = (SELECT max(uk_vat_number) FROM organizations) ORDER BY t2.date_contact_to ASC LIMIT 1
|
extra
|
6,322 |
e_government
|
[
"organizations",
"organization_contact_individuals",
"individuals"
] |
What is the last name of the first individual contacted from the organization with the maximum UK Vat number across all organizations?
|
SELECT t3.individual_last_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id JOIN individuals AS t3 ON t2.individual_id = t3.individual_id WHERE t1.uk_vat_number = (SELECT max(uk_vat_number) FROM organizations) ORDER BY t2.date_contact_to ASC LIMIT 1
|
extra
|
6,323 |
e_government
|
[
"services"
] |
How many services are there?
|
SELECT count(*) FROM services
|
easy
|
6,324 |
e_government
|
[
"services"
] |
Count the number of services.
|
SELECT count(*) FROM services
|
easy
|
6,325 |
e_government
|
[
"party_services",
"services"
] |
Find name of the services that has never been used.
|
SELECT service_name FROM services EXCEPT SELECT t1.service_name FROM services AS t1 JOIN party_services AS t2 ON t1.service_id = t2.service_id
|
hard
|
6,326 |
e_government
|
[
"party_services",
"services"
] |
What are the names of the services that have never been used?
|
SELECT service_name FROM services EXCEPT SELECT t1.service_name FROM services AS t1 JOIN party_services AS t2 ON t1.service_id = t2.service_id
|
hard
|
6,327 |
e_government
|
[
"addresses"
] |
Find the name of all the cities and states.
|
SELECT town_city FROM addresses UNION SELECT state_province_county FROM addresses
|
hard
|
6,328 |
e_government
|
[
"addresses"
] |
What are the names of all cities and states?
|
SELECT town_city FROM addresses UNION SELECT state_province_county FROM addresses
|
hard
|
6,329 |
e_government
|
[
"addresses"
] |
How many cities are there in state "Colorado"?
|
SELECT count(*) FROM addresses WHERE state_province_county = "Colorado"
|
easy
|
6,330 |
e_government
|
[
"addresses"
] |
Count the number of cities in the state of Colorado.
|
SELECT count(*) FROM addresses WHERE state_province_county = "Colorado"
|
easy
|
6,331 |
e_government
|
[
"parties"
] |
Find the payment method code used by more than 3 parties.
|
SELECT payment_method_code FROM parties GROUP BY payment_method_code HAVING count(*) > 3
|
easy
|
6,332 |
e_government
|
[
"parties"
] |
What are the payment method codes that have been used by more than 3 parties?
|
SELECT payment_method_code FROM parties GROUP BY payment_method_code HAVING count(*) > 3
|
easy
|
6,333 |
e_government
|
[
"organizations"
] |
Find the name of organizations whose names contain "Party".
|
SELECT organization_name FROM organizations WHERE organization_name LIKE "%Party%"
|
medium
|
6,334 |
e_government
|
[
"organizations"
] |
What are the names of organizations that contain the word "Party"?
|
SELECT organization_name FROM organizations WHERE organization_name LIKE "%Party%"
|
medium
|
6,335 |
e_government
|
[
"parties"
] |
How many distinct payment methods are used by parties?
|
SELECT count(DISTINCT payment_method_code) FROM parties
|
easy
|
6,336 |
e_government
|
[
"parties"
] |
Count the number of different payment method codes used by parties.
|
SELECT count(DISTINCT payment_method_code) FROM parties
|
easy
|
6,337 |
e_government
|
[
"party_services",
"parties"
] |
Which is the email of the party that has used the services the most number of times?
|
SELECT t1.party_email FROM parties AS t1 JOIN party_services AS t2 ON t1.party_id = t2.customer_id GROUP BY t1.party_email ORDER BY count(*) DESC LIMIT 1
|
extra
|
6,338 |
e_government
|
[
"party_services",
"parties"
] |
Return the party email that has used party services the greatest number of times.
|
SELECT t1.party_email FROM parties AS t1 JOIN party_services AS t2 ON t1.party_id = t2.customer_id GROUP BY t1.party_email ORDER BY count(*) DESC LIMIT 1
|
extra
|
6,339 |
e_government
|
[
"addresses"
] |
Which state can address "6862 Kaitlyn Knolls" possibly be in?
|
SELECT state_province_county FROM addresses WHERE line_1_number_building LIKE "%6862 Kaitlyn Knolls%"
|
medium
|
6,340 |
e_government
|
[
"addresses"
] |
Give the state corresponding to the line number building "6862 Kaitlyn Knolls".
|
SELECT state_province_county FROM addresses WHERE line_1_number_building LIKE "%6862 Kaitlyn Knolls%"
|
medium
|
6,341 |
e_government
|
[
"organizations",
"organization_contact_individuals"
] |
What is the name of organization that has the greatest number of contact individuals?
|
SELECT t1.organization_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id GROUP BY t1.organization_name ORDER BY count(*) DESC LIMIT 1
|
extra
|
6,342 |
e_government
|
[
"organizations",
"organization_contact_individuals"
] |
Return the name of the organization which has the most contact individuals.
|
SELECT t1.organization_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id GROUP BY t1.organization_name ORDER BY count(*) DESC LIMIT 1
|
extra
|
6,343 |
e_government
|
[
"organization_contact_individuals",
"individuals"
] |
Find the last name of the individuals that have been contact individuals of an organization.
|
SELECT DISTINCT t1.individual_last_name FROM individuals AS t1 JOIN organization_contact_individuals AS t2 ON t1.individual_id = t2.individual_id
|
easy
|
6,344 |
e_government
|
[
"organization_contact_individuals",
"individuals"
] |
What are the last names of individuals who have been contact individuals for an organization?
|
SELECT DISTINCT t1.individual_last_name FROM individuals AS t1 JOIN organization_contact_individuals AS t2 ON t1.individual_id = t2.individual_id
|
easy
|
6,345 |
school_bus
|
[
"driver"
] |
How many drivers are there?
|
SELECT count(*) FROM driver
|
easy
|
6,346 |
school_bus
|
[
"driver"
] |
Show the name, home city, and age for all drivers.
|
SELECT name , home_city , age FROM driver
|
medium
|
6,347 |
school_bus
|
[
"driver"
] |
Show the party and the number of drivers in each party.
|
SELECT party , count(*) FROM driver GROUP BY party
|
medium
|
6,348 |
school_bus
|
[
"driver"
] |
Show the name of drivers in descending order of age.
|
SELECT name FROM driver ORDER BY age DESC
|
easy
|
6,349 |
school_bus
|
[
"driver"
] |
Show all different home cities.
|
SELECT DISTINCT home_city FROM driver
|
easy
|
6,350 |
school_bus
|
[
"driver"
] |
Show the home city with the most number of drivers.
|
SELECT home_city FROM driver GROUP BY home_city ORDER BY count(*) DESC LIMIT 1
|
hard
|
6,351 |
school_bus
|
[
"driver"
] |
Show the party with drivers from Hartford and drivers older than 40.
|
SELECT party FROM driver WHERE home_city = 'Hartford' AND age > 40
|
medium
|
6,352 |
school_bus
|
[
"driver"
] |
Show home city where at least two drivers older than 40 are from.
|
SELECT home_city FROM driver WHERE age > 40 GROUP BY home_city HAVING count(*) >= 2
|
medium
|
6,353 |
school_bus
|
[
"driver"
] |
Show all home cities except for those having a driver older than 40.
|
SELECT home_city FROM driver EXCEPT SELECT home_city FROM driver WHERE age > 40
|
hard
|
6,354 |
school_bus
|
[
"driver",
"school_bus"
] |
Show the names of the drivers without a school bus.
|
SELECT name FROM driver WHERE driver_id NOT IN (SELECT driver_id FROM school_bus)
|
hard
|
6,355 |
school_bus
|
[
"school"
] |
Show the types of schools that have two schools.
|
SELECT TYPE FROM school GROUP BY TYPE HAVING count(*) = 2
|
easy
|
6,356 |
school_bus
|
[
"school",
"driver",
"school_bus"
] |
Show the school name and driver name for all school buses.
|
SELECT T2.school , T3.name FROM school_bus AS T1 JOIN school AS T2 ON T1.school_id = T2.school_id JOIN driver AS T3 ON T1.driver_id = T3.driver_id
|
medium
|
6,357 |
school_bus
|
[
"school_bus"
] |
What is the maximum, minimum and average years spent working on a school bus?
|
SELECT max(years_working) , min(years_working) , avg(years_working) FROM school_bus
|
medium
|
6,358 |
school_bus
|
[
"school",
"school_bus"
] |
Show the school name and type for schools without a school bus.
|
SELECT school , TYPE FROM school WHERE school_id NOT IN (SELECT school_id FROM school_bus)
|
extra
|
6,359 |
school_bus
|
[
"school",
"school_bus"
] |
Show the type of school and the number of buses for each type.
|
SELECT T2.type , count(*) FROM school_bus AS T1 JOIN school AS T2 ON T1.school_id = T2.school_id GROUP BY T2.type
|
medium
|
6,360 |
school_bus
|
[
"driver"
] |
How many drivers are from Hartford city or younger than 40?
|
SELECT count(*) FROM driver WHERE home_city = 'Hartford' OR age < 40
|
medium
|
6,361 |
school_bus
|
[
"driver"
] |
List names for drivers from Hartford city and younger than 40.
|
SELECT name FROM driver WHERE home_city = 'Hartford' AND age < 40
|
medium
|
6,362 |
school_bus
|
[
"driver",
"school_bus"
] |
find the name of driver who is driving the school bus with the longest working history.
|
SELECT t1.name FROM driver AS t1 JOIN school_bus AS t2 ON t1.driver_id = t2.driver_id ORDER BY years_working DESC LIMIT 1
|
hard
|
6,363 |
flight_company
|
[
"flight"
] |
How many flights have a velocity larger than 200?
|
SELECT count(*) FROM flight WHERE velocity > 200
|
easy
|
6,364 |
flight_company
|
[
"flight"
] |
List the vehicle flight number, date and pilot of all the flights, ordered by altitude.
|
SELECT vehicle_flight_number , date , pilot FROM flight ORDER BY altitude ASC
|
medium
|
6,365 |
flight_company
|
[
"airport"
] |
List the id, country, city and name of the airports ordered alphabetically by the name.
|
SELECT id , country , city , name FROM airport ORDER BY name
|
medium
|
6,366 |
flight_company
|
[
"operate_company"
] |
What is maximum group equity shareholding of the companies?
|
SELECT max(group_equity_shareholding) FROM operate_company
|
easy
|
6,367 |
flight_company
|
[
"flight"
] |
What is the velocity of the pilot named 'Thompson'?
|
SELECT avg(velocity) FROM flight WHERE pilot = 'Thompson'
|
easy
|
6,368 |
flight_company
|
[
"operate_company",
"flight"
] |
What are the names and types of the companies that have ever operated a flight?
|
SELECT T1.name , T1.type FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id
|
medium
|
6,369 |
flight_company
|
[
"airport"
] |
What are the names of the airports which are not in the country 'Iceland'?
|
SELECT name FROM airport WHERE country != 'Iceland'
|
easy
|
6,370 |
flight_company
|
[
"operate_company",
"flight"
] |
What are the distinct types of the companies that have operated any flights with velocity less than 200?
|
SELECT DISTINCT T1.type FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id WHERE T2.velocity < 200
|
medium
|
6,371 |
flight_company
|
[
"operate_company",
"flight"
] |
What are the ids and names of the companies that operated more than one flight?
|
SELECT T1.id , T1.name FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id GROUP BY T1.id HAVING count(*) > 1
|
medium
|
6,372 |
flight_company
|
[
"flight",
"airport"
] |
What is the id, name and IATA code of the airport that had most number of flights?
|
SELECT T1.id , T1.name , T1.IATA FROM airport AS T1 JOIN flight AS T2 ON T1.id = T2.airport_id GROUP BY T2.id ORDER BY count(*) DESC LIMIT 1
|
extra
|
6,373 |
flight_company
|
[
"flight",
"airport"
] |
What are the different pilot names who had piloted a flight in the country 'United States' or in the airport named 'Billund Airport'?
|
SELECT DISTINCT T2.pilot FROM airport AS T1 JOIN flight AS T2 ON T1.id = T2.airport_id WHERE T1.country = 'United States' OR T1.name = 'Billund Airport'
|
hard
|
6,374 |
flight_company
|
[
"operate_company"
] |
What is the most common company type, and how many are there?
|
SELECT TYPE , count(*) FROM operate_company GROUP BY TYPE ORDER BY count(*) DESC LIMIT 1
|
hard
|
6,375 |
flight_company
|
[
"flight",
"airport"
] |
How many airports haven't the pilot 'Thompson' driven an aircraft?
|
SELECT count(*) FROM airport WHERE id NOT IN ( SELECT airport_id FROM flight WHERE pilot = 'Thompson' );
|
extra
|
6,376 |
flight_company
|
[
"operate_company",
"flight"
] |
List the name of the pilots who have flied for both a company that mainly provide 'Cargo' services and a company that runs 'Catering services' activities.
|
SELECT T2.pilot FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id WHERE T1.principal_activities = 'Cargo' INTERSECT SELECT T2.pilot FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id WHERE T1.principal_activities = 'Catering services'
|
extra
|
6,377 |
flight_company
|
[
"airport"
] |
Which of the airport names contains the word 'international'?
|
SELECT name FROM airport WHERE name LIKE '%international%'
|
medium
|
6,378 |
flight_company
|
[
"operate_company",
"flight",
"airport"
] |
How many companies operates airlines in each airport?
|
SELECT T3.id , count(*) FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id JOIN airport AS T3 ON T2.airport_id = T3.id GROUP BY T3.id
|
hard
|
6,379 |
flight_company
|
[
"airport"
] |
how many airports are there in each country?
|
SELECT count(*) , country FROM airport GROUP BY country
|
medium
|
6,380 |
flight_company
|
[
"airport"
] |
which countries have more than 2 airports?
|
SELECT country FROM airport GROUP BY country HAVING count(*) > 2
|
easy
|
6,381 |
flight_company
|
[
"flight"
] |
which pilot is in charge of the most number of flights?
|
SELECT pilot FROM flight GROUP BY pilot ORDER BY count(*) DESC LIMIT 1
|
hard
|
6,382 |
cre_Docs_and_Epenses
|
[
"accounts"
] |
How many accounts do we have?
|
SELECT count(*) FROM Accounts
|
easy
|
6,383 |
cre_Docs_and_Epenses
|
[
"accounts"
] |
Count the number of accounts.
|
SELECT count(*) FROM Accounts
|
easy
|
6,384 |
cre_Docs_and_Epenses
|
[
"accounts"
] |
Show all account ids and account details.
|
SELECT account_id , account_details FROM Accounts
|
medium
|
6,385 |
cre_Docs_and_Epenses
|
[
"accounts"
] |
What are the ids and details of all accounts?
|
SELECT account_id , account_details FROM Accounts
|
medium
|
6,386 |
cre_Docs_and_Epenses
|
[
"statements"
] |
How many statements do we have?
|
SELECT count(*) FROM Statements
|
easy
|
6,387 |
cre_Docs_and_Epenses
|
[
"statements"
] |
Count the number of statements.
|
SELECT count(*) FROM Statements
|
easy
|
6,388 |
cre_Docs_and_Epenses
|
[
"statements"
] |
List all statement ids and statement details.
|
SELECT STATEMENT_ID , statement_details FROM Statements
|
medium
|
6,389 |
cre_Docs_and_Epenses
|
[
"statements"
] |
What are the ids and details of all statements?
|
SELECT STATEMENT_ID , statement_details FROM Statements
|
medium
|
6,390 |
cre_Docs_and_Epenses
|
[
"statements",
"accounts"
] |
Show statement id, statement detail, account detail for accounts.
|
SELECT T1.statement_id , T2.statement_details , T1.account_details FROM Accounts AS T1 JOIN Statements AS T2 ON T1.statement_id = T2.statement_id
|
medium
|
6,391 |
cre_Docs_and_Epenses
|
[
"statements",
"accounts"
] |
What are the statement ids, statement details, and account details, for all accounts?
|
SELECT T1.statement_id , T2.statement_details , T1.account_details FROM Accounts AS T1 JOIN Statements AS T2 ON T1.statement_id = T2.statement_id
|
medium
|
6,392 |
cre_Docs_and_Epenses
|
[
"accounts"
] |
Show all statement id and the number of accounts for each statement.
|
SELECT STATEMENT_ID , count(*) FROM Accounts GROUP BY STATEMENT_ID
|
medium
|
6,393 |
cre_Docs_and_Epenses
|
[
"accounts"
] |
What are the different statement ids on accounts, and the number of accounts for each?
|
SELECT STATEMENT_ID , count(*) FROM Accounts GROUP BY STATEMENT_ID
|
medium
|
6,394 |
cre_Docs_and_Epenses
|
[
"statements",
"accounts"
] |
Show the statement id and the statement detail for the statement with most number of accounts.
|
SELECT T1.statement_id , T2.statement_details FROM Accounts AS T1 JOIN Statements AS T2 ON T1.statement_id = T2.statement_id GROUP BY T1.statement_id ORDER BY count(*) DESC LIMIT 1
|
extra
|
6,395 |
cre_Docs_and_Epenses
|
[
"statements",
"accounts"
] |
What are the statement id and statement detail for the statement that has the most corresponding accounts?
|
SELECT T1.statement_id , T2.statement_details FROM Accounts AS T1 JOIN Statements AS T2 ON T1.statement_id = T2.statement_id GROUP BY T1.statement_id ORDER BY count(*) DESC LIMIT 1
|
extra
|
6,396 |
cre_Docs_and_Epenses
|
[
"documents"
] |
Show the number of documents.
|
SELECT count(*) FROM Documents
|
easy
|
6,397 |
cre_Docs_and_Epenses
|
[
"documents"
] |
Count the number of documents.
|
SELECT count(*) FROM Documents
|
easy
|
6,398 |
cre_Docs_and_Epenses
|
[
"documents"
] |
List the document type code, document name, and document description for the document with name 'Noel CV' or name 'King Book'.
|
SELECT document_type_code , document_name , document_description FROM Documents WHERE document_name = 'Noel CV' OR document_name = 'King Book'
|
extra
|
6,399 |
cre_Docs_and_Epenses
|
[
"documents"
] |
What are the type come, name, and description of the document that has either the name 'Noel CV' or 'King Book'?
|
SELECT document_type_code , document_name , document_description FROM Documents WHERE document_name = 'Noel CV' OR document_name = 'King Book'
|
extra
|
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