Datasets:
target-benchmark
/
spider-queries

Dataset card Data Studio Files Community
3
query_id
int64
0
7k
database_id
stringclasses
140 values
table_id
listlengths
1
5
query
stringlengths
16
224
answer
stringlengths
18
577
difficulty
stringclasses
4 values
6,600
train_station
[ "station" ]
Show the names and main services for train stations that have the top three total number of passengers.
SELECT name , main_services FROM station ORDER BY total_passengers DESC LIMIT 3
medium
6,601
train_station
[ "station" ]
What is the average and maximum number of total passengers for train stations in London or Glasgow?
SELECT avg(total_passengers) , max(total_passengers) FROM station WHERE LOCATION = 'London' OR LOCATION = 'Glasgow'
hard
6,602
train_station
[ "station" ]
Show all locations and the total number of platforms and passengers for all train stations in each location.
SELECT LOCATION , sum(number_of_platforms) , sum(total_passengers) FROM station GROUP BY LOCATION
medium
6,603
train_station
[ "station" ]
Show all locations that have train stations with at least 15 platforms and train stations with more than 25 total passengers.
SELECT DISTINCT LOCATION FROM station WHERE number_of_platforms >= 15 AND total_passengers > 25
medium
6,604
train_station
[ "station" ]
Show all locations which don't have a train station with at least 15 platforms.
SELECT LOCATION FROM station EXCEPT SELECT LOCATION FROM station WHERE number_of_platforms >= 15
hard
6,605
train_station
[ "station" ]
Show the location with most number of train stations.
SELECT LOCATION FROM station GROUP BY LOCATION ORDER BY count(*) DESC LIMIT 1
hard
6,606
train_station
[ "train" ]
Show the name, time, and service for all trains.
SELECT name , TIME , service FROM train
medium
6,607
train_station
[ "train" ]
Show the number of trains
SELECT count(*) FROM train
easy
6,608
train_station
[ "train" ]
Show the name and service for all trains in order by time.
SELECT name , service FROM train ORDER BY TIME
medium
6,609
train_station
[ "station", "train_station" ]
Show the station name and number of trains in each station.
SELECT T2.name , count(*) FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id
medium
6,610
train_station
[ "train", "station", "train_station" ]
show the train name and station name for each train.
SELECT T2.name , T3.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id
medium
6,611
train_station
[ "train", "station", "train_station" ]
Show all train names and times in stations in London in descending order by train time.
SELECT T3.name , T3.time FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T2.location = 'London' ORDER BY T3.time DESC
extra
6,612
train_station
[ "station", "train_station" ]
Show the station name with greatest number of trains.
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id ORDER BY count(*) DESC LIMIT 1
extra
6,613
train_station
[ "station", "train_station" ]
Show the station name with at least two trains.
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id HAVING count(*) >= 2
medium
6,614
train_station
[ "station" ]
Show all locations with only 1 station.
SELECT LOCATION FROM station GROUP BY LOCATION HAVING count(*) = 1
easy
6,615
train_station
[ "station", "train_station" ]
Show station names without any trains.
SELECT name FROM station WHERE station_id NOT IN (SELECT station_id FROM train_station)
hard
6,616
train_station
[ "train", "station", "train_station" ]
What are the names of the stations which serve both "Ananthapuri Express" and "Guruvayur Express" trains?
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T3.Name = "Ananthapuri Express" INTERSECT SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T3.Name = "Guruvayur Express"
extra
6,617
train_station
[ "train", "station", "train_station" ]
Find the names of the trains that do not pass any station located in London.
SELECT T2.name FROM train_station AS T1 JOIN train AS T2 ON T1.train_id = T2.train_id WHERE T1.station_id NOT IN (SELECT T4.station_id FROM train_station AS T3 JOIN station AS T4 ON T3.station_id = T4.station_id WHERE t4.location = "London")
extra
6,618
train_station
[ "station" ]
List the names and locations of all stations ordered by their yearly entry exit and interchange amounts.
SELECT name , LOCATION FROM station ORDER BY Annual_entry_exit , Annual_interchanges
medium
6,619
driving_school
[ "vehicles" ]
List all vehicle id
SELECT vehicle_id FROM Vehicles;
easy
6,620
driving_school
[ "vehicles" ]
What are the ids of all vehicles?
SELECT vehicle_id FROM Vehicles;
easy
6,621
driving_school
[ "vehicles" ]
How many vehicle in total?
SELECT count(*) FROM Vehicles;
easy
6,622
driving_school
[ "vehicles" ]
How many vehicles exist?
SELECT count(*) FROM Vehicles;
easy
6,623
driving_school
[ "vehicles" ]
Show the detail of vehicle with id 1.
SELECT vehicle_details FROM Vehicles WHERE vehicle_id = 1;
easy
6,624
driving_school
[ "vehicles" ]
What are the details of the car with id 1?
SELECT vehicle_details FROM Vehicles WHERE vehicle_id = 1;
easy
6,625
driving_school
[ "staff" ]
List the first name middle name and last name of all staff.
SELECT first_name , middle_name , last_name FROM Staff;
medium
6,626
driving_school
[ "staff" ]
What are the first, middle, and last names of all staff?
SELECT first_name , middle_name , last_name FROM Staff;
medium
6,627
driving_school
[ "staff" ]
What is the birthday of the staff member with first name as Janessa and last name as Sawayn?
SELECT date_of_birth FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
medium
6,628
driving_school
[ "staff" ]
What is the date of birth for the staff member named Janessa Sawayn?
SELECT date_of_birth FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
medium
6,629
driving_school
[ "staff" ]
When did the staff member with first name as Janessa and last name as Sawayn join the company?
SELECT date_joined_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
medium
6,630
driving_school
[ "staff" ]
When did the staff member named Janessa Sawayn join the company?
SELECT date_joined_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
medium
6,631
driving_school
[ "staff" ]
When did the staff member with first name as Janessa and last name as Sawayn leave the company?
SELECT date_left_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
medium
6,632
driving_school
[ "staff" ]
When did the staff member Janessa Sawayn leave the company?
SELECT date_left_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
medium
6,633
driving_school
[ "staff" ]
How many staff have the first name Ludie?
SELECT count(*) FROM Staff WHERE first_name = "Ludie";
easy
6,634
driving_school
[ "staff" ]
How many employees have a first name of Ludie?
SELECT count(*) FROM Staff WHERE first_name = "Ludie";
easy
6,635
driving_school
[ "staff" ]
What is the nickname of staff with first name as Janessa and last name as Sawayn?
SELECT nickname FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
medium
6,636
driving_school
[ "staff" ]
What is the nickname of the employee named Janessa Sawayn?
SELECT nickname FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
medium
6,637
driving_school
[ "staff" ]
How many staff in total?
SELECT count(*) FROM Staff;
easy
6,638
driving_school
[ "staff" ]
How many employees are there?
SELECT count(*) FROM Staff;
easy
6,639
driving_school
[ "addresses", "staff" ]
Which city does staff with first name as Janessa and last name as Sawayn live?
SELECT T1.city FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
medium
6,640
driving_school
[ "addresses", "staff" ]
In what city does Janessa Sawayn live?
SELECT T1.city FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
medium
6,641
driving_school
[ "addresses", "staff" ]
Which country and state does staff with first name as Janessa and last name as Sawayn lived?
SELECT T1.country , T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
extra
6,642
driving_school
[ "addresses", "staff" ]
In which country and state does Janessa Sawayn live?
SELECT T1.country , T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
extra
6,643
driving_school
[ "lessons", "customers" ]
How long is the total lesson time took by customer with first name as Rylan and last name as Goodwin?
SELECT sum(T1.lesson_time) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin";
medium
6,644
driving_school
[ "lessons", "customers" ]
How long is the total lesson time took by the customer named Rylan Goodwin?
SELECT sum(T1.lesson_time) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin";
medium
6,645
driving_school
[ "addresses", "staff" ]
What is the zip code of staff with first name as Janessa and last name as Sawayn lived?
SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
medium
6,646
driving_school
[ "addresses", "staff" ]
What is the zip code of the hosue of the employee named Janessa Sawayn?
SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
medium
6,647
driving_school
[ "addresses" ]
How many staff live in state Georgia?
SELECT count(*) FROM Addresses WHERE state_province_county = "Georgia";
easy
6,648
driving_school
[ "addresses" ]
How many employees live in Georgia?
SELECT count(*) FROM Addresses WHERE state_province_county = "Georgia";
easy
6,649
driving_school
[ "addresses", "staff" ]
Find out the first name and last name of staff lived in city Damianfort.
SELECT T2.first_name , T2.last_name FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T1.city = "Damianfort";
medium
6,650
driving_school
[ "addresses", "staff" ]
What is the first and last name of all employees who live in the city Damianfort?
SELECT T2.first_name , T2.last_name FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T1.city = "Damianfort";
medium
6,651
driving_school
[ "addresses", "staff" ]
Which city lives most of staffs? List the city name and number of staffs.
SELECT T1.city , count(*) FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.city ORDER BY count(*) DESC LIMIT 1;
extra
6,652
driving_school
[ "addresses", "staff" ]
In which city do the most employees live and how many of them live there?
SELECT T1.city , count(*) FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.city ORDER BY count(*) DESC LIMIT 1;
extra
6,653
driving_school
[ "addresses", "staff" ]
List the states which have between 2 to 4 staffs living there.
SELECT T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.state_province_county HAVING count(*) BETWEEN 2 AND 4;
medium
6,654
driving_school
[ "addresses", "staff" ]
What are the names of the states that have 2 to 4 employees living there?
SELECT T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.state_province_county HAVING count(*) BETWEEN 2 AND 4;
medium
6,655
driving_school
[ "customers" ]
List the first name and last name of all customers.
SELECT first_name , last_name FROM Customers;
medium
6,656
driving_school
[ "customers" ]
What are the first and last names for all customers?
SELECT first_name , last_name FROM Customers;
medium
6,657
driving_school
[ "customers" ]
List email address and birthday of customer whose first name as Carole.
SELECT email_address , date_of_birth FROM Customers WHERE first_name = "Carole"
medium
6,658
driving_school
[ "customers" ]
What are the email addresses and date of births for all customers who have a first name of Carole?
SELECT email_address , date_of_birth FROM Customers WHERE first_name = "Carole"
medium
6,659
driving_school
[ "customers" ]
List phone number and email address of customer with more than 2000 outstanding balance.
SELECT phone_number , email_address FROM Customers WHERE amount_outstanding > 2000;
medium
6,660
driving_school
[ "customers" ]
What are the phone numbers and email addresses of all customers who have an outstanding balance of more than 2000?
SELECT phone_number , email_address FROM Customers WHERE amount_outstanding > 2000;
medium
6,661
driving_school
[ "customers" ]
What is the status code, mobile phone number and email address of customer with last name as Kohler or first name as Marina?
SELECT customer_status_code , cell_mobile_phone_number , email_address FROM Customers WHERE first_name = "Marina" OR last_name = "Kohler"
extra
6,662
driving_school
[ "customers" ]
What is the status code, phone number, and email address of the customer whose last name is Kohler or whose first name is Marina?
SELECT customer_status_code , cell_mobile_phone_number , email_address FROM Customers WHERE first_name = "Marina" OR last_name = "Kohler"
extra
6,663
driving_school
[ "customers" ]
When are the birthdays of customer who are classified as 'Good Customer' status?
SELECT date_of_birth FROM Customers WHERE customer_status_code = 'Good Customer'
easy
6,664
driving_school
[ "customers" ]
What is the date of birth of every customer whose status code is 'Good Customer'?
SELECT date_of_birth FROM Customers WHERE customer_status_code = 'Good Customer'
easy
6,665
driving_school
[ "customers" ]
When did customer with first name as Carole and last name as Bernhard became a customer?
SELECT date_became_customer FROM Customers WHERE first_name = "Carole" AND last_name = "Bernhard";
medium
6,666
driving_school
[ "customers" ]
When did Carole Bernhard first become a customer?
SELECT date_became_customer FROM Customers WHERE first_name = "Carole" AND last_name = "Bernhard";
medium
6,667
driving_school
[ "customers" ]
How many customers in total?
SELECT count(*) FROM Customers;
easy
6,668
driving_school
[ "customers" ]
How many customers are there?
SELECT count(*) FROM Customers;
easy
6,669
driving_school
[ "customers" ]
List all customer status codes and the number of customers having each status code.
SELECT customer_status_code , count(*) FROM Customers GROUP BY customer_status_code;
medium
6,670
driving_school
[ "customers" ]
For each customer status code, how many customers are classified that way?
SELECT customer_status_code , count(*) FROM Customers GROUP BY customer_status_code;
medium
6,671
driving_school
[ "customers" ]
Which customer status code has least number of customers?
SELECT customer_status_code FROM Customers GROUP BY customer_status_code ORDER BY count(*) ASC LIMIT 1;
hard
6,672
driving_school
[ "customers" ]
What is the status code with the least number of customers?
SELECT customer_status_code FROM Customers GROUP BY customer_status_code ORDER BY count(*) ASC LIMIT 1;
hard
6,673
driving_school
[ "lessons", "customers" ]
How many lessons taken by customer with first name as Rylan and last name as Goodwin were completed?
SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin" AND T1.lesson_status_code = "Completed";
medium
6,674
driving_school
[ "lessons", "customers" ]
How many lessons did the customer Ryan Goodwin complete?
SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin" AND T1.lesson_status_code = "Completed";
medium
6,675
driving_school
[ "customers" ]
What is maximum, minimum and average amount of outstanding of customer?
SELECT max(amount_outstanding) , min(amount_outstanding) , avg(amount_outstanding) FROM Customers;
medium
6,676
driving_school
[ "customers" ]
What is the maximum, minimum, and average amount of money outsanding for all customers?
SELECT max(amount_outstanding) , min(amount_outstanding) , avg(amount_outstanding) FROM Customers;
medium
6,677
driving_school
[ "customers" ]
List the first name and last name of customers have the amount of outstanding between 1000 and 3000.
SELECT first_name , last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000;
medium
6,678
driving_school
[ "customers" ]
What are the first and last names of all customers with between 1000 and 3000 dollars outstanding?
SELECT first_name , last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000;
medium
6,679
driving_school
[ "addresses", "customers" ]
List first name and last name of customers lived in city Lockmanfurt.
SELECT T1.first_name , T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "Lockmanfurt";
medium
6,680
driving_school
[ "addresses", "customers" ]
What are the first and last names of all customers who lived in Lockmanfurt?
SELECT T1.first_name , T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "Lockmanfurt";
medium
6,681
driving_school
[ "addresses", "customers" ]
Which country does customer with first name as Carole and last name as Bernhard lived in?
SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
medium
6,682
driving_school
[ "addresses", "customers" ]
What is the country in which the customer Carole Bernhard lived?
SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
medium
6,683
driving_school
[ "addresses", "customers" ]
What is zip code of customer with first name as Carole and last name as Bernhard?
SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
medium
6,684
driving_school
[ "addresses", "customers" ]
What is the zip code of the customer Carole Bernhard?
SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
medium
6,685
driving_school
[ "addresses", "customers" ]
Which city does has most number of customers?
SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1;
extra
6,686
driving_school
[ "addresses", "customers" ]
What is the city with the most customers?
SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1;
extra
6,687
driving_school
[ "customer_payments", "customers" ]
How much in total does customer with first name as Carole and last name as Bernhard paid?
SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Carole" AND T2.last_name = "Bernhard"
medium
6,688
driving_school
[ "customer_payments", "customers" ]
What is the total amount of moeny paid by the customer Carole Bernhard?
SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Carole" AND T2.last_name = "Bernhard"
medium
6,689
driving_school
[ "customer_payments", "customers" ]
List the number of customers that did not have any payment history.
SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments );
extra
6,690
driving_school
[ "customer_payments", "customers" ]
How many customers have no payment histories?
SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments );
extra
6,691
driving_school
[ "customer_payments", "customers" ]
List first name and last name of customers that have more than 2 payments.
SELECT T2.first_name , T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2;
medium
6,692
driving_school
[ "customer_payments", "customers" ]
What are the first and last names of all customers with more than 2 payments?
SELECT T2.first_name , T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2;
medium
6,693
driving_school
[ "customer_payments" ]
List all payment methods and number of payments using each payment methods.
SELECT payment_method_code , count(*) FROM Customer_Payments GROUP BY payment_method_code;
medium
6,694
driving_school
[ "customer_payments" ]
For each payment method, how many payments were made?
SELECT payment_method_code , count(*) FROM Customer_Payments GROUP BY payment_method_code;
medium
6,695
driving_school
[ "lessons" ]
How many lessons were in cancelled state?
SELECT count(*) FROM Lessons WHERE lesson_status_code = "Cancelled";
easy
6,696
driving_school
[ "lessons" ]
How many lessons have been cancelled?
SELECT count(*) FROM Lessons WHERE lesson_status_code = "Cancelled";
easy
6,697
driving_school
[ "staff", "lessons" ]
List lesson id of all lessons taught by staff with first name as Janessa, last name as Sawayn and nickname containing letter 's'.
SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" AND nickname LIKE "%s%";
hard
6,698
driving_school
[ "staff", "lessons" ]
What are the the lesson ids of all staff taught by Janessa Sawayn whose nickname has the letter s?
SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" AND nickname LIKE "%s%";
hard
6,699
driving_school
[ "staff", "lessons" ]
How many lessons taught by staff whose first name has letter 'a' in it?
SELECT count(*) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name LIKE "%a%"
hard