subject
stringclasses 1
value | question
stringlengths 3
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listlengths 5
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stringlengths 18
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stringclasses 5
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|---|---|---|---|---|
mathematics
|
The true discount on Rs. 2562 due 4 months hence is Rs. 122. The rate percent is?
|
[
"12%",
"13%",
"15%",
"14%",
"18%"
] |
Explanation:
P.W = 2562 - 122 = Rs.2440
Rate=100×122/2440×13Rate=100×1222440×13
=15%
Answer: C
The answer is: C
|
C
|
mathematics
|
How many alphabets need to be there in a language if one were to make 1 million distinct 3 digit initials using the alphabets of the language?
|
[
"254",
"100",
"132",
"503",
"50"
] |
1 million distinct 3 digit initials are needed.
Let the number of required alphabets in the language be ‘n’.
Therefore, using ‘n’ alphabets we can form n * n * n = n^3 distinct 3 digit initials.
Note distinct initials is different from initials where the digits are different.
For instance, AAA and BBB are acceptable combinations in the case of distinct initials while they are not permitted when the digits of the initials need to be different.
This n^3 different initials = 1 million
i.e. n^3 = 106 (1 million = 106)
=> n^3 = (102)^3 => n = 102 = 100
Hence, the language needs to have a minimum of 100 alphabets to achieve the objective.
Ans:B
The answer is: B
|
B
|
mathematics
|
If two dice are thrown together, the probability of getting an even number on both dice is
|
[
"1/4",
"1/5",
"1/6",
"1/3",
"1/2"
] |
The number of exhaustive outcomes is 36.
Let E be the event of getting an even number on both dies is 9/36 = 1/4
P(E) = 1/4.
A)
The answer is: A
|
A
|
mathematics
|
If a = -0.4, which of the following is true?
|
[
"a < a^2 < a^3",
"a^2 < a^3 < a",
"a^2 < a < a^3",
"a < a^3 < a^2",
"a^3 < a < a^2"
] |
a=-0.4;
a^2=0.16;
a^3=-0.064;
Answer : D
The answer is: D
|
D
|
mathematics
|
A single discount equivalent to the discount series of 20%, 10% and 5% is?
|
[
"20",
"99",
"7878",
"656",
"27"
] |
SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20% Answer: A
The answer is: A
|
A
|
mathematics
|
Which of the following is closest to the difference between sum E of all proper fractions (fractions less than 1) in the form 1/x , where x is a positive digit, and the product of all proper fractions in the form y/(y+1), where y is a positive digit?
|
[
"2.82",
"2.72",
"1.82",
"1.72",
"0.82"
] |
Sum E of all proper fractions (fractions less than 1) in the form 1/x, where x is a positive digit:
1/1 + 1/2 + 1/3 +.....+ 1/9
This is a harmonic progression. Harmonic progression is inverse of arithmetic progression.
Approximate sum of a harmonic progression with even number of terms = number of terms * (average of middle 2 terms)
Approximate sum of a harmonic progression with odd number of terms = number of terms * (middle term)
The actual sum will be slightly more than the approximation.
Here we have 9 terms (odd).
Sum = 9 * 1/5
= 9/5
Product of all proper fractions in the form y/(y+1), where y is a positive digit:
1/2 * 2/3 * 3/4 *.....*9/10
We will be left with 1/10.
Required = 9/5 - 1/10
= 1.8 - 0.1
= 1.7
Closest is 1.72
Answer (D).
The answer is: D
|
D
|
mathematics
|
The cost price of a radio is Rs.1500 and it was sold for Rs.1230, find the loss %?
|
[
"18%",
"19%",
"28%",
"38%",
"16%"
] |
1500 ---- 270
100 ---- ? => 18%
Answer:A
The answer is: A
|
A
|
mathematics
|
A and B start a business with Rs.6000 and Rs.8000 respectively. Hoe should they share their profits at the end of one year?
|
[
"3:3",
"3:4",
"3:8",
"3:1",
"3:2"
] |
They should share the profits in the ratio of their investments.
The ratio of the investments made by A and B =
6000 : 8000 => 3:4.Answer: B
The answer is: B
|
B
|
mathematics
|
Shekhar started a business investing Rs.25,000 in 1999.In 2000,he invested an additional amount of Rs.10,000 and Rajeev joined him with an amount of Rs.35,000.In 2001,Shekhar invested another additional amount of Rs.10,000 and Jatin joined them with an amount of Rs.35,000.What will be Rajeev’s share in the profit of Rs.1,50,000 earned at the end of 3 years from the start of the business in 1999 ?
|
[
"Rs.45,000",
"Rs.50,000",
"Rs.70,000",
"Rs.75,000",
"None of these"
] |
Solution
Shekhar : Rajeev : Jatin
= (25000x12+35000x12+45000x12) :(35000x24) : (35000x12)
= 1260000 : 840000 : 420000 = 3 : 2 : 1.
∴ Rajeev’s share = Rs.(15000x2/6) = Rs. 50,000. Answer B
The answer is: B
|
B
|
mathematics
|
Lloyd normally works 7.5 hours per day and earns $4.00 per hour. For each hour he works in excess of 7.5 hours on a given day, he is paid 1.5 times his regular rate. If Lloyd works 10.5 hours on a given day, how much does he earn for that day?
|
[
"$33.75",
"$48.00",
"$51.75",
"$54.00",
"$70.00"
] |
Daily working hour*Regular Rate + Overtime*Increased Rate
7.5*4.0+ 3*4.0*1.5=48
Answer B
The answer is: B
|
B
|
mathematics
|
A pipe can fill a cistern in 20 minutes whereas the cistern when fill can be emptied by a leak in 70 minutes. When both pipes are opened, find when the cistern will be full?
|
[
"17 minutes",
"87 minutes",
"70 minutes",
"28 minutes",
"11 minutes"
] |
1/20 - 1/70 = 1/28
28 minutes
Answer:D
The answer is: D
|
D
|
mathematics
|
A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years.What is the sum ?
|
[
"Rs. 4462.50",
"Rs. 8032.50",
"Rs. 8900",
"Rs. 8925",
"None of these"
] |
Solution
Principal = Rs. (100x4016.25/9x5)= Rs.401625/25= Rs. 8925.
Answer D
The answer is: D
|
D
|
mathematics
|
A fair price shopkeeper takes 10% profit on his goods. He lost 20% goods during theft. His loss percent is:
|
[
"8",
"10",
"11",
"12",
"13"
] |
Explanation:
Suppose he has 100 items. Let C.P. of each item be Re. 1.
Total cost = Rs. 100. Number of items left after theft = 80.
S.P. of each item = Rs. 1.10
Total sale = 1.10 * 80 = Rs. 88
Hence, loss % = 12/100 * 100 = 12%
Answer is D
The answer is: D
|
D
|
mathematics
|
The harmonic mean of two numbers xx and yy, symbolized as h(x,y)h(x,y), is defined as 2 divided by the sum of the reciprocals of xx and yy, whereas the geometric mean g(x,y)g(x,y) is defined as the square root of the product of xx and yy (when this square root exists), and the arithmetic mean m(x,y)m(x,y) is defined as x+y2x+y2. For which of the following pairs of values for xx and yy is g(x,y)g(x,y) equal to the arithmetic mean of h(x,y)h(x,y) and m(x,y)m(x,y)?
|
[
"x=−2 y=−1",
"x=−1, y=2",
"x=2, y=8",
"x=8, y=8",
"x=8, y=64"
] |
A. x=−2 , y=−1
B. x=−1 , y=2
C. x=2 , y=8
D. x=8 , y=8
E. x=8 , y=64
The arithmetic mean, the geometric mean and the harmonic mean of two equal numbers are equal((x+x)/2=x, sqrt(x*x)=x, (2x*x)/(x+x)=x).
So without tedious calculation, (D) should be answer.
The answer is: D
|
D
|
mathematics
|
Enrollment in City College in 1980 was 85/3 percent of enrollment in 1990. What was the percent increase in the college’s enrollment from 1980 to 1990?
|
[
"100%",
"16 2/3 %",
"200%",
"253%",
"183 1/3%"
] |
Assume 100 enrollments present in 1990
85/3 % of 1990 = enrollments on 1980
enrollments on 1980 = 28.33
% change = (enrollment in 1990 - enrollment in 1980)*100/(enrollment in 1980)
=(100 - 28.33) *100 / 28.333
= 7166.67 / 28.333
= 253 %
Ans - D
The answer is: D
|
D
|
mathematics
|
If Rs. 782 is divided into three parts, proportional to
1/2:2/3:3/4
|
[
"190",
"204",
"220",
"230",
"250"
] |
Explanation:
1/2:2/3:3/4
=6:8:9
First part =782∗6/23
=204
ANSWER IS B
The answer is: B
|
B
|
mathematics
|
5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3553, how much was it in the beginning?
|
[
"4400",
"3000",
"4200",
"5000",
"5500"
] |
X * (95/100) * (85/100) = 3553
X = 4400
ANSWER A
The answer is: A
|
A
|
mathematics
|
If 85 percent of the test takers taking an old paper and pencil GMAT exam answered the first question on a given math section correctly, and 70 percent of the test takers answered the second question correctly, and 5 percent of the test takers answered neither question correctly, what percent answered both correctly?
|
[
"60 %",
"65 %",
"70%",
"75%",
"80%"
] |
{Total} = {First correctly} + {Second correctly} - {Both correctly} + {Neither correctly}
100 = 85 + 70 - {Both correctly} + 5
{Both correctly} = 60.
Answer: A.
The answer is: A
|
A
|
mathematics
|
A certain industrial loom weaves 0.128 meters of cloth every second. Approximately how many seconds will it take for the loom to weave 25 meters of cloth?
|
[
"205",
"200",
"180",
"195",
"None of these"
] |
Explanation :
Let the required number of seconds be x
More cloth, More time, (direct proportion)
Hence we can write as
Cloth0.128:25}::1:x
⇒0.128x=25
⇒x = 25/128 = 25000/128 = 3125/16 ≈ 195. Answer : Option D
The answer is: D
|
D
|
mathematics
|
in base 7, a number is written only using digits 0,1,2,3,4,5,6. the number 135 in base 7 is 1*72+3*7+5=75 in base 10. what is the sum of the base 7 numbers 1234 & 6543 in base 7?
|
[
"11101",
"11110",
"10111",
"11011",
"11010"
] |
4+3=7 since base is 7 so it will become 0 giving 1 carry to next digits(so 4+7=0)
3+4 + 1 carry from above step= 1 and 1 carry to next digit
2+5 + 1 carry to next digit= 1 and 1 carry
1+6= 11
so ans=11110
ANSWER:B
The answer is: B
|
B
|
mathematics
|
The rate of increase of the price of sugar is observed to be two percent more than the inflation rate expressed in percentage. The price of sugar, on January 1, 1994, is Rs. 18 per kg. The inflation rate for the years 1994 and 1995 are expected to be 6% each. The expected price of sugar on January 1, 1996 would be
|
[
"20.99",
"21.9",
"25.4",
"20.19",
"None of these"
] |
Explanation :
Increase in the price of sugar = (6+2)= 8%
Hence, price of the sugar on Jan 1, 1996
=> (18 * 108 * 108)/( 100 * 100 ) = Rs 20.99.
Answer : A
The answer is: A
|
A
|
mathematics
|
A small beaker is 1/2 filled with salt water. Another beaker, which has five times the capacity of the small beaker, is 2/5 filled with fresh water. After dumping all of the salt water from the small beaker into the large beaker, to what fraction of its capacity will the large beaker be filled?
|
[
"5/6",
"4/5",
"3/4",
"2/3",
"1/2"
] |
1/2 of the small beaker is 1/10 of the large beaker.
1/10 + 2/5 = 1/2
The answer is E.
The answer is: E
|
E
|
mathematics
|
A 150 meter long train crosses a man standing on the platform in 3 sec. What is the speed of the train?
|
[
"176 kmph",
"108 kmph",
"176 kmph",
"134 kmph",
"180 kmph"
] |
S = 150/3 * 18/5
= 180 kmph
Answer: E
The answer is: E
|
E
|
mathematics
|
If a die has 3,4 and 1,6 and 2,5 opposite each other, then how many such dies can be made.
|
[
"13",
"3",
"5",
"12",
"11"
] |
there are 3 pairs . consider it A,B,C
A-(1,6)
B-(3,4)
C-(2,5)
Now the possible combinations to place A B C is 6.
because for A - 3 possible place
B- 2 POSSIBLE PLACE
C-1 POSSIBLE PLACE
3*2*1=6
NOW A HAS TWO PAIR SO POSSIBLE COMBO FOR 1 AND 6 IS 2 ..SAME FOR B AND C
2+2+2=6
SO 6+6=12
ANSWER:D
The answer is: D
|
D
|
mathematics
|
If A is thrice as fast as B and together can do a work in 18 days. In how many days A alone can do the work?
|
[
"36",
"42",
"24",
"54",
"45"
] |
A’s one day’s work= 1/X
B’s one day’s work= 1/3x
A + B’s one day’s work= 1/x + 1/3x = 1/18
= 3+1/3x = 4/3x = 1/18
x = 18*4/3 = 24
ANSWER:C
The answer is: C
|
C
|
mathematics
|
Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was
|
[
"three times as much",
"twice as much",
"the same",
"half as much",
"a third as much"
] |
Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.
We know that
Speed = Distance/Time.
Or, Time = Distance/Speed.
So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.
And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.
= 100/x hr.
So we can clearly see that his new time compared with the old time was: twice as much.
Answer: (B)
The answer is: B
|
B
|
mathematics
|
Machines X and Y produce bottles at their respective constant rates. Machine X produces k bottles in 4 hours and machine Y produces k bottles in 5 hours. How many hours does it take machines X and Y , working simultaneously , to produce 10k bottles?
|
[
"8 2/3",
"12 5/3",
"15",
"18",
"22 2/9"
] |
x rate = k/4
y rate = k/5
k/4 + k/5 = 10k / T
solving T = 200/9 = 22 (2/9)
Answer E
The answer is: E
|
E
|
mathematics
|
The present population of a town is 300. Population increase rate is 10% p.a. Find the population of town after 1 years?
|
[
"100",
"120",
"200",
"220",
"330"
] |
P = 300
R = 10%
Required population of town = P*(1 + R/100)^T
= 300*(1 + 10/100)
= 300*(11/10)
= 330
Answer is E
The answer is: E
|
E
|
mathematics
|
The HCF of two numbers is 52 and the other two factors of their LCM are 11 and 12. What is the largest number.
|
[
"624",
"450",
"480",
"504",
"555"
] |
Explanation:
HCF of the two numbers = 52
HCF will be always a factor of LCM
52 is factor of LCM
other two factors are 11 & 12
Then the numbers are (52 *11) and (52 x 12)
= 572 and 624
Answer: Option A
The answer is: A
|
A
|
mathematics
|
A mixture of 150 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture?
|
[
"65 liters",
"88 liters",
"10 liters water",
"45 liters",
"8 liters"
] |
Number of liters of water in150 liters of the mixture = 20% of 150 = 20/100 * 150 = 30 liters.
P liters of water added to the mixture to make water 25% of the new mixture.
Total amount of water becomes (30 + P) and total volume of mixture is (150 + P).
(30 + P) = 25/100 * (150 + P)
120 + 4P = 150 + P => P = 10 liters. Answer: C
The answer is: C
|
C
|
mathematics
|
A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.14200 after a year?
|
[
"3630",
"9232",
"4260",
"2387",
"2813"
] |
6300:4200:10500
3:2:5
3/10 * 14200 = 4260
Answer: C
The answer is: C
|
C
|
mathematics
|
The average (arithmetic mean) of the even integers from 0 to 40 inclusive is how much greater than the average (arithmetic mean) of the even integers from 0 to 20 inclusive?
|
[
"10",
"20",
"5",
"30",
"15"
] |
So, according to A mean of a set of even numbers from 0 to 40 =(0+40)/2=20 and mean of a set of even numbers from 0 to 20 =(0+20)/2=10
Difference=20-10=10
Answer: A.
The answer is: A
|
A
|
mathematics
|
A man buy a book in Rs50 & sale it Rs80. What is the rate of profit ???
|
[
"10%",
"60%",
"30%",
"25%",
"28%"
] |
cp=50
sp=80
profit=80-50=30
%=30/50*100=60%
ANSWER:B
The answer is: B
|
B
|
mathematics
|
One day, Connie plays a game with a fair 6-sided die. Connie rolls the die until she rolls a 6, at
which point the game ends. If she rolls a 6 on her first turn, Connie wins 6 dollars. For each
subsequent turn, Connie wins 1
6 of the amount she would have won the previous turn. What is
Connie's expected earnings from the game?
|
[
"32/31",
"33/31",
"34/31",
"36/31",
"0/31"
] |
Connie has a 1
6 chance of winning 6 dollars her first turn. She has a 5/6
1/6 chance of
winning 1 dollar her second turn. Next, she has a 25
36
1/6 chance of winning 1/6 dollars her third turn.
Generalizing, Connie's expected earnings form a geometric series with initial term 1/6 *6 = 1 and
common ratio 5/6* 1/6 = 5/36 . Hence, Connie's expected earnings are
1/1- 5/36
=
36/31
correct answer D
The answer is: D
|
D
|
mathematics
|
If a man can cover 14 metres in one second, how many kilometres can he cover in 3 hours 30 minutes?
|
[
"165km",
"170km",
"176.4km",
"180km",
"190km"
] |
14 m/s = 14 * 18/5 kmph
3 hours 30 minutes = 3 1/2 hours = 7/2 hours
Distance = speed * time = 14 * 18/5 * 7/2 km = 176.4 km.
Answer:C
The answer is: C
|
C
|
mathematics
|
How many such 3's are there in the following number sequence which are immediately Preceded by an odd number and immediately f ollowed by an even number? 5 3 8 9 4 3 7 2 3 8 1 3 8 4 2 3 5 7 3 4 2 3 6
|
[
"1",
"2",
"3 three",
"4",
"More than four"
] |
A is followed by B means : A comes first,B comes next
A preceded by B means : B comes first, A comes next
The sets which satisfy the condition is: 5 3 8
1 3 8
7 3 4
ANSWER:C
The answer is: C
|
C
|
mathematics
|
597**6 is divisible by both 3 and 11. The non-zero digits in the Hundred’s and ten’s places are respectively:
|
[
"3 and 6",
"7 and 9",
"2 and 6",
"4 and 7",
"None"
] |
Solution : Let the given number be 597xy6.
Then (5+9+7+x+y+6)=(27+x+y) must be divisible by 3
And, (6+x+9)-(y+7+5)=(x-y+3) must be either 0 or divisible by 11. x-y+3=0
=> y=x+3 27+x+y)
=>(27+x+x+3)
=>(30+2x)
=> x = 3 and y = 6.
Answer A
The answer is: A
|
A
|
mathematics
|
For what values of k will the pair of equations 6x + 8y = 24 and kx + 12y = 30 does not have a unique solution?
|
[
"12",
"9",
"3",
"7.5",
"2.5"
] |
we have 2 equations
1. 6x + 8y = 24 --> 3x + 4y = 12 -- > 9x + 12y = 36
2. kx + 12y = 30
substract 1-2, we get (9-K)x = 6
i.e. x = 6/(9-k)
then, by looking at options, we get some value of x except for B. When we put k=9, x becomes 6/0 and hence answer is B
The answer is: B
|
B
|
mathematics
|
The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.7 years. The ration of the number of boys to the number of girls in the class is?
|
[
"1:6",
"2:3",
"2:5",
"2:1",
"2:4"
] |
Let the ratio be k : 1. Then,
k * 16.4 + 1 * 15.7 = (k + 1) * 15.8
= (16.4 - 15.8)k = (15.8 - 15.7)
= k = 0.1/0.6 = 1/6
Required ratio = 1/6 : 1 = 1:6.
Answer:A
The answer is: A
|
A
|
mathematics
|
A boat crossed a lake from East to West at the speed of 5 km/h, entered a river and covered twice as much distance going upstream at 4 km/h. It then turned around and stopped at the south shore of the lake. If it averaged 3.6 km/h that day, what was its approximate downstream speed?
|
[
"4",
"5",
"6",
"7",
"8"
] |
One way of solving this is:
Speed of boat on still water (lake)=5kmph
Speed upstream = 4kmph = speed in still water - speed of river => speed of river = 1kmph
=>Speed downstream = speed in still water + speed of river = 5+1 =6kmph
Ans is C
The answer is: C
|
C
|
mathematics
|
The total of the ages of Amar, Akbar and Anthony is 66 years. What was the total of their ages four years ago ?
|
[
"71",
"44",
"54",
"16",
"18"
] |
Explanation:
Required sum = (66 - 3 x 4) years = (66 - 12) years = 54 years.
Answer: C
The answer is: C
|
C
|
mathematics
|
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
|
[
"29",
"77",
"28",
"10",
"12"
] |
lb = 150
2(l + b) = 50 => l + b = 25
l – b = 5
l = 15 b = 10
Answer:D
The answer is: D
|
D
|
mathematics
|
If (2 to the x) - (2 to the (x-2)) = 3 (2 to the 12), what is the value of x?
|
[
"9",
"11",
"13",
"15",
"14"
] |
I am guessing the question is:
(2 to the power x) - (2 to the power (x-2)) = 3 (2 to the power 12)
2^x - 2^(x-2) = 3. 2^12
Hence x = 14.
Answer is E
The answer is: E
|
E
|
mathematics
|
50% of a number is added to 120, the result is the same number. Find the number?
|
[
"300",
"277",
"240",
"99",
"121"
] |
:
(50/100) * X + 120 = X
2X = 480
X = 240
Answer: C
The answer is: C
|
C
|
mathematics
|
Joshua and Jose work at an auto repair center with 2 other workers. For a survey on health care insurance, 2 of the 6 workers will be randomly chosen to be interviewed. What is the probability that Joshua and Jose will both be chosen?
|
[
"1/15",
"1/12",
"1/9",
"1/6",
"1/3"
] |
Two Methods
1) Probability of chosing Josh first = 1/4
Probability of chosing Jose second = 1/3
total = 1/12
Probability of chosing Jose first = 1/4
Probability of chosing Josh second = 1/3
Total = 1/12
Final = 1/12 + 1/12 = 1/6
D
The answer is: D
|
D
|
mathematics
|
10 men and 15 women together can complete a work in 7 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work?
|
[
"127 days",
"667 days",
"177 days",
"187 days",
"350 days"
] |
1 man's 1 day work = 1/100
(10 men + 15 women)'s 1 day work = 1/7
15 women's 1 day work = (1/7 - 10/100) = 3/70
1 woman's 1 day work = 1/350
1 woman alone can complete the work in 350 days.
Answer:E
The answer is: E
|
E
|
mathematics
|
A certain car can travel 40 minutes on a gallon of gasoline at 60 miles per hour. If the car had started with a full tank and had 8 gallons of gasoline left in its tank at the end, then what percent of the tank was used to travel 120 miles at 60 mph?
|
[
"15%",
"20%",
"25%",
"27%",
"40%"
] |
Total time for travelling 120 miles @ 60 mph = 120/60 = 2 hour = 120 minutes.
Given, the car uses 1 gallon for every 40 minutes of driving @ 60 mph. Thus in 120 minutes it will use = 3 gallons. Thus, full tank = 3+8 = 11 gallons --->3/11= 27% of the fuel used. D is the correct answer.
The answer is: D
|
D
|
mathematics
|
If the average (arithmetic mean) of (2a+16) and (3a-8) is 74, what is the value of a?
|
[
"25",
"30",
"28",
"36",
"42"
] |
((2a+16) + (3a-8)) / 2 = (5a+8)/2 = 74
a= 28
The answer is C.
The answer is: C
|
C
|
mathematics
|
Shawn and Raquel want to have gardens that are the same size. Shawn plants a garden 25 feet by 24 feet. Raquel wants one side of his garden to be 30 feet. How long should the other side be?
|
[
"22",
"29",
"20",
"15",
"18"
] |
S1 S2 = R1 R2
So 25*24 = 30*R2=> R2 = 20
Answer:C
The answer is: C
|
C
|
mathematics
|
If X is invested in a bank at a rate of simple interest of y% p.a. for two years, then the interest earned is 400. if X is invested at y% p.a., for two years when the interest is compounded annually, the interest is 410. What is the value of X?
|
[
"8000",
"6000",
"5000",
"4000",
"3000"
] |
Simple way to solve this question is to use options.
From SI, we know that X*y=20,000.
Now, put the value of X = 4000, we will have y = 5%
To calculate CI,
Now, we know 1st year Amount= 4000+5% of 4000= 4200.
2nd year, Amount = 4200 + 5% of 4200 = 4410.
We can see after 2 years Interest = 4410-4000= 410. hence, it satisfies the question. Hence D is the correct answer
The answer is: D
|
D
|
mathematics
|
How many integers from 101 to 900, inclusive, remains the value unchanged when the digits were reversed?
|
[
"50",
"60",
"70",
"80",
"90"
] |
question is asking for palindrome
first digit possibilities - 1 through 8 = 8
9 is not possible here because it would result in a number greater than 9 (i.e 909 , 919..)
second digit possibilities - 0 though 9 = 10
third digit is same as first digit
=>total possible number meeting the given conditions = 8 *10 = 80
Answer is D.
The answer is: D
|
D
|
mathematics
|
A and B complete a work in 10 days. A alone can do it in 40 days. If both together can do the work in how many days?
|
[
"1.0875 days",
"0.125 days",
"0.0675 days",
"0.0875 days",
"0.0775 days"
] |
1/10 + 1/40 = 0.125 days
ANSWER:B
The answer is: B
|
B
|
mathematics
|
50, 47, 45, 42, 40, 37, 35, 32, ?
|
[
"31",
"30",
"29",
"28",
"27"
] |
This is an alternating number subtraction series. The pattern is -3, -2, -3, -2, ....
The answer is B.
The answer is: B
|
B
|
mathematics
|
at a special sale 5 ticket can be purchased as a price of 3 ticket, if 5 ticket are purchased at the sale, the amount saved will be what % of the original price of the 5 ticket.
|
[
"10%",
"20%",
"30%",
"40%",
"50%"
] |
let the price of 1 ticket be Rs.10
Original C.P. of 5 tickets = Rs.50
After sale 5 Tickets were bought for Rs. 30
%amount saved = ((50-30)/50)*100 = 40%
ANSWER:D
The answer is: D
|
D
|
mathematics
|
The ratio between the sale price and the cost price of an article is 4:3. What is the ratio between the profit and the cost price of that article?
|
[
"2:9",
"2:5",
"3:6",
"2:0",
"1:3"
] |
Let C.P. = Rs. 3x and S.P. = Rs. 4x.
Then, Gain = Rs. x
Required ratio = x : 3x = 1:3
Answer:E
The answer is: E
|
E
|
mathematics
|
Rs. 6000 is lent out in two parts. One part is lent at 5% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest?
|
[
"5:1",
"5:5",
"5:8",
"5:4",
"5:2"
] |
Let the amount lent at 5% be Rs. x
Amount lent at 10% is Rs. (6000 - x)
Total interest for one year on the two sums lent
= 5/100 x + 10/100 (6000 - x) = 600 - 1x/20
=> 600 - 1/20 x = 450 => x = 3000
Amount lent at 10% = 3000
Required ratio = 3000 : 3000 = 5:5
Answer:B
The answer is: B
|
B
|
mathematics
|
A type Q machine can complete a job in 5 hours and a type B machine can complete the job in 7 hours. How many hours will it take 2 type Q machines and 3 type B machines working together and independently to complete the job?
|
[
"1/5",
"29/35",
"5/6",
"35/29",
"35/12"
] |
now D should be the answer.
Q need 5 hours to complete
and B needs 7 hours to compete
so 2Q + 3B will complete 2/5 + 3/7 or 29/35 portion of the job in 1 hour
so the whole job will take 35/29 hours....=D
The answer is: D
|
D
|
mathematics
|
Anne and Katherine are both saving money
from their summer jobs to buy bicycles. If
Anne had $150 less, she would have exactly 1/3
as much as Katherine. And if Katherine
had twice as much, she would have exactly
3 times as much as Anne. How much
money have they saved together?
(
|
[
"$300",
"$400",
"$450",
"$625",
"$750"
] |
If Anne had $150 less, Katherine would have three times more than Anne. Make this
statement into an equation and simplify:
3(a – 150) = k
3a – 450 = k
And if Katherine had twice as much, she would have three times more than Anne:
2k = 3a
Substitute 3a – 450 for k into the last equation and solve for a
2(3a – 450) = 3a
6a – 900 = 3a
–900 = –3a
300 = a
Now substitute 300 for a into the same equation and solve for k:
2k = 3(300)
2k = 900
k = 450
Thus, together Anne and Katherine have 300 + 450 = 750
correct answer E)$750
The answer is: E
|
E
|
mathematics
|
P is four times as fast as Q and working together, they can complete a work in 20 days. In how many days can Q alone complete the work?
|
[
"35 days",
"15 days",
"16 days",
"25 days",
"18 days"
] |
P = 4Q
P + Q = 4Q + Q = 5Q
These 5Q people can do the work in 20 days, which means Q can do the work in 100 days.
Hence, P can do the work in 25 days.
ANSWER:D
The answer is: D
|
D
|
mathematics
|
If 85 percent of the test takers taking an old paper and pencil GMAT exam answered the first question on a given math section correctly, and 80 percent of the test takers answered the second question correctly, and 5 percent of the test takers answered neither question correctly, what percent answered both correctly?
|
[
"60 %",
"65 %",
"70%",
"75%",
"80%"
] |
{Total} = {First correctly} + {Second correctly} - {Both correctly} + {Neither correctly}
100 = 85 + 80 - {Both correctly} + 5
{Both correctly} = 70.
Answer: C.
The answer is: C
|
C
|
mathematics
|
Sreenivas sells a table to Shiva at 10% profit and Shiva sells it to Mahesh at 10% loss. At what price did Sreenivas purchase the table if Mahesh paid Rs. 2772?
|
[
"2277",
"2669",
"2200",
"2800",
"2998"
] |
Let the cost price of table for Sreenivas be Rs. x and given that, cost price of table for Mahesh = Rs. 2772.
=> (90%) of (110%) of x = Rs. 2772.
=> (90/100)(110/100)x = 2772
=> x = (2772 * 100)/(9 * 11)
=> x = Rs. 2800
Answer: D
The answer is: D
|
D
|
mathematics
|
A cistern is filled by a tap in 6 1/2 hours. Due to leak in the bottom of the cistern, it takes half an hour longer to fill the cistern. If the cistern is full how many hours will it take the leak to empty it?
|
[
"81",
"85",
"88",
"91",
"95"
] |
filling rate - leak rate = net rate
1/6.5 - leak rate = 1/7
leak rate = 2/13 - 1/7 = 1/91
The answer is D.
The answer is: D
|
D
|
mathematics
|
it is a small town railway station and there are 25 stations on that line.at each of the 25 stations the passengers can get tickets for any other 24 stations.how many different kind of tickets do you think the booking clerk has to keep?
|
[
"24",
"25",
"26",
"27",
"28"
] |
600 different kind of tickets booking clerk has to keep.
24 type of tickets are to be issued from each originating station.
Therefore, 25*24 = 600 tickets
ANSWER:A
The answer is: A
|
A
|
mathematics
|
Solve the inequality
{(x^2)-7|x|+10}/{(x^2)-6x+9}
|
[
"-3",
"-5",
"3",
"5",
"0"
] |
taking one time |x| as +ve we get x=5 while
taking |x| as -ve we get x= -5
ANSWER:B
The answer is: B
|
B
|
mathematics
|
Gopi gives Rs. 90 plus one turban as salary to his servant for one year. The servant leaves after 9 months and receives Rs. 60 and the turban. Find the price of the turban.
|
[
"27",
"30",
"29",
"10",
"11"
] |
Let the price of turban be x.
Thus, for one year the salary = (90 + x)
For 9 months he should earn 3434 (90 + x).
Now he gets one turban and Rs. 60.
Thus, 3434 (90 + x) = 60 + x or 270 + 3x = 240 + 4x or x = 30
Answer:B
The answer is: B
|
B
|
mathematics
|
Mr. Wayne bungee jumps from the top of a building straight to the ground at a constant speed. 3 seconds after he starts plummeting he passes the 20th floor. 15 seconds after he starts plummeting he passes the 5th floor. Each floor is 3.6 meters high. What is Mr. Wayne's speed in meters per second?
|
[
"3",
"3.75",
"4.5",
"4.25",
"5"
] |
IMO: C
15 Floors * 3.6 Meter/Floor = 54 Meters
Time= 12 sec
Rate * 12 = 54
Rate= 54/12
=4.5
Answer C
The answer is: C
|
C
|
mathematics
|
After allowing a discount of 15% on the marked price, the selling price is Rs. 6800 for an article. If it was sold at marked price, there would have been a profit of 60%. The cost price of the article is?
|
[
"2338",
"2298",
"5000",
"2871",
"1171"
] |
Explanation:
Given SP = Rs. 6800
Marked price = [SP(100)]/(100 - d%) = (6800 * 100)/(100 - 15) = Rs. 8000
If SP = Rs. 8000, profit = 60%
CP = [SP(100)]/(100 + 60) = (8000 * 100)/160 = Rs. 5000
Answer:C
The answer is: C
|
C
|
mathematics
|
A polling company surveyed a certain country, and it found that 35% of that country’s registered voters had an unfavorable impression of both of that state’s major political parties and that 20% had a favorable impression only of Party Q. If one registered voter has a favorable impression of both parties for every two registered voters who have a favorable impression only of Party B, then what percentage of the country’s registered voters have a favorable impression of both parties (assuming that respondents to the poll were given a choice between favorable and unfavorable impressions only)?
|
[
"15",
"20",
"30",
"35",
"45"
] |
S=100
not( Q and B ) =35
only Q=20
(Q and B)/B=1/2
let ( Q and B ) =x
only B =2x
so now, 20+35+x+2x=100
x= 15
A ans
The answer is: A
|
A
|
mathematics
|
The product of x and y is a constant. If the value of x is increased by 50%, by what percentage must the value of y be decreased?
|
[
"50%",
"40%",
"33 1⁄3%",
"25%",
"12 1⁄2%"
] |
Product of x and y = xy
If the value of x is increased by 50% , value of y needs to be = xy/(1.5 x ) = 2/3 y
Decrease in value of y = y - 2/3 y = 1/3 y
% decrease in value of y = (1/3 y)/y * 100%
=33 1⁄3%
Answer C
The answer is: C
|
C
|
mathematics
|
Ajay spends 25 per cent of his salary on house rent, 5 percent on food, 15 percent travel, 10 percent on clothes and the remaining amount of Rs.27000 is saved. What is Ajay’s income?
|
[
"Rs.60000",
"Rs.80500",
"Rs.60700",
"Rs.70500",
"None of these"
] |
Explanation:
Savings = Income – expenditure
100 – (25+5+15+10) = 45%
45% of income = Rs.27000
:. Income = 27000 x 100/45 = Rs. 60000.
Answer: Option A
The answer is: A
|
A
|
mathematics
|
Which is better investment: 11% stock at 143 or 9% stock at 117?
|
[
"9 3/4% stock at 119",
"9 3/4% stock at 117",
"9 3/4% stock at 112",
"9 3/4% stock at 118",
"9 3/4% stock at 111"
] |
Let investment in each case be Rs. (143 x 117).
Income in 1st case = Rs. 11 x 143 x 117 = Rs. 1287.
143
Income in 2nd case = Rs. 39 x 143 x 117 = Rs. 1394.25
4 x 117
Clearly, 9 3 % stock at 117 is better.
4
Answer:B
The answer is: B
|
B
|
mathematics
|
The average age 10 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
|
[
"14 years",
"17 years",
"20 years",
"12 years",
"11 years"
] |
10 * 2
= 20
Answer:C
The answer is: C
|
C
|
mathematics
|
If n = 8^9 – 8, what is the units digit of n?
|
[
"4",
"0",
"1",
"2",
"3"
] |
8 ^ 9 - 8 = 8 (8 ^ 8 - 1)
==> 8 (2 ^ 24 - 1)
Last digit of 2 ^ 24 is 6 based on what explanation LiveStronger is saying. 2 ^ 24 - 1 yields 6 - 1 = 5 as the unit digit. Now on multiply this with 8, we get unit digit as 0
Answer : B
The answer is: B
|
B
|
mathematics
|
In a group of cows and hens, the number of legs are 20 more than twice the number of heads. The number of cows is :
|
[
"5",
"6",
"7",
"10",
"12"
] |
Let no of cows be x, no of hens be y.
So heads=x+y
Legs=4x+2y
Now, 4x+2y = 2(x+y)+ 20
2x = 20
x = 10.
ANSWER:D
The answer is: D
|
D
|
mathematics
|
A pipe can fill a cistern in 20 minutes whereas the cistern when fill can be emptied by a leak in 60 minutes. When both pipes are opened, find when the cistern will be full?
|
[
"17 minutes",
"87 minutes",
"30 minutes",
"27 minutes",
"11 minutes"
] |
1/20 - 1/60 = 1/30
30 minutes
Answer:C
The answer is: C
|
C
|
mathematics
|
A fence consists of m lengths of fence that are each n feet long. A fence post separates each length of fence by its width of x feet. What is the total length Q of the fence including the fence posts on each end?
|
[
"mn",
"m(n + x)",
"Q=m(n + x) + x",
"m(n + x) + 2x",
"2mn"
] |
Notice that since a fence post separates each length of fence, then there will be m+1 posts, for example if there are m=2 fences, then there will be 3 posts: PFPFP. Thus the total length of the posts is (m+1)x.
The total length Q of the fence is mn, therefore the total length of the fence including the fence posts on each end is (m+1)x+mn=mx+x+mn=m(n+x)+x.
Answer: C.
The answer is: C
|
C
|
mathematics
|
x/(y/z)
In the expression above, x, y, and z are different numbers and each is one of the numbers 1, 5, or 6. What is the least possible value of the expression?
|
[
"6/5",
"2/15",
"5/6",
"3/10",
"6/6"
] |
x/(y/z)
= (x*z)/y
The expression will have the least value when numerator (x*z) is the smallest.
= (1*5)/6
=5/6
Answer C
The answer is: C
|
C
|
mathematics
|
M = {-6, -5, -4, -3, -2, -1}
T = {-4, -3, -2, -1, 0, 1, 2, 3, 4, 5}
If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above, what is the probability that the product of the two integers will be negative?
|
[
"0",
"1/3",
"2/5",
"1/2",
"3/5"
] |
We will have a negative product only if 1, 2, 3, 4, or 5 are selected from set T.
P(negative product) = 5/10 = 1/2
The answer is D.
The answer is: D
|
D
|
mathematics
|
5 goats’s and 10 hens are brought for Rs.2500. If the average price of a hen be Rs.50. What is the average price of a goat.
|
[
"425",
"375",
"350",
"400",
"500"
] |
Explanation:
Average price of a hen = Rs.50
total price of 10 hens = 10*50 = Rs.500
But total price of 5 goats and 10 hens = Rs. 2500
Total price of 5 goats is = 2500 - 500
= 2000
Average price of a goat = 2000/5
= Rs. 400
Answer: D
The answer is: D
|
D
|
mathematics
|
How many different arrangements are possible to place seven different books on a shelf if all three math books must be placed next to each other?
|
[
"120",
"148",
"360",
"540",
"720"
] |
Let the 3 math books be M1,M2,M3 while the rest be A,B,C,D for a total of 7 different books.
Consider 3 math books to be 1 collective item (=M1M2M3 = M , as they need to be together). Thus, number of arrangements of 3 different books (M1M2M3)= 3P3 = 3!
Total number of arrangements of M,A,B,C,D = 5P5= 5!
Thus, The total possible arrangements will be : M1M2M3 ABCD = 5!*3! = 720, E is the correct answer
The answer is: E
|
E
|
mathematics
|
If radius of a circle is diminished by 10% then its area is diminished by
|
[
"22",
"19",
"877",
"26",
"271"
] |
Explanation:
Let old radius = 10 units.
New radius is diminshed by 10%. So new radius = 90% (10) = 9 units.
Old area = π × r2 = 100π
New area = π × 92 = 81π
Change = 19π/100π ×100 = 19%
Answer: B
The answer is: B
|
B
|
mathematics
|
Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 3x boxes?
|
[
"3 minutes",
"4 minutes",
"10 minutes",
"6 minutes",
"12 minutes"
] |
Rate = Work / Time
Given Rate of Machine A = X / 10 min
Machine B Produces 2x boxes in 5 min hence , Machine B produces 4x boxes in 10 min .
Rate of Machine B = 2x / 10
we need tofind the combined time that machines A and B, working simultaneouslytakeat their respective constant rates
let's first find the combined Rate of Machine A and B
Rate of Machine A = X / 10 min + Rate of Machine B = 2x / 10 = 3X/10
Now combine Time = combine work needs to be done / Combine Rate = 3x/3x * 10 = 10 Min
Ans: C
The answer is: C
|
C
|
mathematics
|
A train running at the speed of 60 km/hr crosses a pole in 18 seconds. Find the length of the train?
|
[
"150 meter",
"876 meter",
"300 meter",
"719 meter",
"169 meter"
] |
Speed = 60*(5/18) m/sec = 50/3 m/sec
Length of Train (Distance) = Speed * Time
(50/3) * 18
= 300 meter
Answer: C
The answer is: C
|
C
|
mathematics
|
A fraction bears the same ratio to 1/27 as 3/7 does to 5/9. The fraction is?
|
[
"1/35",
"2/35",
"3/45",
"4/25",
"4/27"
] |
Let the fraction be x. Then,
x:1/27 = 3/7 : 5/9
x × 5/9 = 1/27 × 3/7
x × 5/9 = 1/9 × 1/7
x × 5/9 = 1/63
x × 5 = 9/63
5x = 1/7 = 1/35
A)
The answer is: A
|
A
|
mathematics
|
Evaluate the expression
[x : (y - 3)] ⋅ (-4) - [xy + (-3)] : -1 = ?
when x = -5 and y = -2
|
[
"3",
"4",
"5",
"6",
"None"
] |
Solution:
Evaluate the expression
[x : (y - 3)] ⋅ (-4) - [xy + (-3)] : -1 =
[(-5) : (-2 - 3)] ⋅ (-4) - [(-5) ⋅ (-2) + (-3)] : -1 =
[(-5) : (-5)] ⋅ (-4) - [10 + (-3)] : -1 =
(+1) ⋅ (-4) - (+7) : -1 = -4 - (-7) = -4 + 7 = 3
Answer A
The answer is: A
|
A
|
mathematics
|
In a certain mathematical activity, we have five cards with five different prime numbers on them. We will distribute these five cards among three envelope: all could go in any envelope, or they could be broken up in any way among the envelopes. Then in each envelop, we find the product of all the cards in that envelope: that is the “number” of the envelope. An envelope containing no cards has the number 1. We then put the three envelope numbers in order, from lowest to highest, and that is our set. How many different W sets can be produced by this process?
|
[
"41",
"89",
"125",
"243",
"512"
] |
Case 1: 1 used envelope => 1 way
Case 2: 2 used envelopes
- 4-1-0: Choose 4 from 5 cards: 5 ways
- 3-2-0: Choose 3 from 5 cards: 10 ways
Case 3: All envelopes used
- 3-1-1: Choose 3 from 5 andno need to choose 1 from 2: 10 ways
- 2-2-1: Choose 2 from 5 and choose 2 from 3, but two groups are the same => (10X3):2 = 15
Total W: 1+5+10+10+15=41 => Answer: A
The answer is: A
|
A
|
mathematics
|
Can anyhow help me with an easy solution for this
2, 3, 9, 5, 6, 81, 6, 7, ?
|
[
"256",
"221",
"121",
"144",
"169"
] |
2, 3, 9, 5, 6, 81, 6, 7, ?
2+73=5 and 5-2=3 and 3^2=9
5+6=11 and 11-2=9 and 9^2=81
6+7=13 and 13-2=11 and 11^2=121
ANSWER:C
The answer is: C
|
C
|
mathematics
|
A cistern which could be filled in 8 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it?
|
[
"76 hrs",
"99 hrs",
"55 hrs",
"90 hrs",
"40 hrs"
] |
1/8 - 1/x = 1/10
=> 40 hrs
Answer: E
The answer is: E
|
E
|
mathematics
|
Sudesh was standing in the garden early in the morning after sunrise. His sister Gauri, who was coming from the opposite directions, saw that Sudesh's shadow had fallen to his right. Which directions was Gauri facing?
|
[
"North",
"South",
"South-West",
"North-East",
"None of these"
] |
as sun rises from east so the boy's shadow must be fall behind him that means toward west ......if the boy is facing towards north then and only then his sister is able to see a shadow had fallen to his right side
ANSWER:B
The answer is: B
|
B
|
mathematics
|
If A,B,C,D,E,F,G,H,I,J are in an decreasing Arithmetic Progression as such. Then Which of the following operations will result in either mean or the median being modified.
A) A is replaced by J
B) A and H are removed
C) B and I are removed
D) A,B,C,H,I,J are removed
E) A and D are removed
|
[
"1) A and B",
"2) A and E",
"3) A,B,E",
"4) All of them",
"5) None of them"
] |
Here answer will be (C).
There are 10 equidistant numbers on the number line.
Mean and median will be the average of middle two numbers.
If you remove two numbers which is equidistant from either extreme (e.g. B and I), the total deviation on either side of the mean stays the same so mean stays the same. Also, the median is still the average of middle two numbers. Other changes will affect the mean and median.
Answer: C
The answer is: C
|
C
|
mathematics
|
From a vessel on the first day, 1/3rd of the liquid evaporates. On the second day 3/4th of the remaining liquid evaporates. what fraction of the volume is present at the end of the 2 day
|
[
"1/3",
"1/4",
"1/5",
"1/6",
"1/7"
] |
let x be the volume...
after 1st day volume remaining=(x-x/3)=2x/3
after 2st day volume remaining=(2x/3)-((2x/3)*(3/4))
=(2x/3)(1-3/4)=(2x/3)*(1/4)=x/6
ANSWER:D
The answer is: D
|
D
|
mathematics
|
The average weight of 5 person's increases by 5.5 kg when a new person comes in place of one of them weighing 68 kg. What might be the weight of the new person?
|
[
"60 kg",
"95.5 kg",
"80 kg",
"85 kg",
"90 kg"
] |
Total weight increased = (5 x 5.5) kg = 27.5 kg.
Weight of new person = (68 + 27.5) kg = 95.5 kg
Option B
The answer is: B
|
B
|
mathematics
|
A student was asked to find 4/5 of a number. But the student divided the number by 4/5, thus the student got 9 more than the correct answer. Find the number.
|
[
"16",
"18",
"20",
"22",
"24"
] |
Let the number be x.
(5/4) * x = (4/5)*x + 9
25x = 16x + 180
9x = 180
x = 20
The answer is C.
The answer is: C
|
C
|
mathematics
|
Which of the following correctly lists the data sets in order of greatest to least standard deviation?
I. 8, 9, 10, 11, 12, 13
II. 12, 12, 12, 12, 12, 12
III. 47, 56, 58, 60, 64, 69
|
[
"I, II, III",
"I, III, II",
"III, I, II",
"II, III, I",
"II, I, III"
] |
out of three given sets,
II has all numbers same, so it has zero standard deviation hence it is Least
I has consecutive numbers , hence all are closedly spaced hence std deviation will be less
while in III,numbers are spread widely hence std deviation should be more than II
hence order should be II, I,III
IMO E
The answer is: E
|
E
|
mathematics
|
A woman has $133,982 in her savings account. What is the least amount of money (in whole number of dollars) that she must add to her account if she wants to split this money evenly among her Three children?
|
[
"$1",
"$11",
"$3",
"$2",
"none"
] |
To find the least amount the woman should add to her saving account to split the money evenly among her 3 children,
she needs to make the total divisible by 3
Simply add the individual digits of the total = 1+3+3+9+8+2=26
If you add 1 , the number is divisible by 3 (26+ 1)
Correct Option : A
The answer is: A
|
A
|
mathematics
|
The GDP of a country is $13.8 billion, and the total production of one of its industries is $3.3 billion. If the GDP were to grow by 5% per year in the future, which of the following would be the MINIMUM required annual growth in this industry that would it represent more than half of the GDP in ten years?
|
[
"10%",
"15%",
"20%",
"25%",
"35%"
] |
GDP in 10 years with this rate would be - 13.8 (1+0.05)^10
Half of the above value - 6.9 (1.05)^10
Industry's annual growth (say x is the rate of growth of the industry annually) = 3.3 (1+(x/100))^10
Now, the minimum of above value has to be greater than the half of the value of GDP.
3.3 (1+(x/100))^10 > 6.9 (1.05)^10
((1+(x/100))/1.05)^10 > 2 (approx)
Minimum value of x to satisfy this equation is 15
Hence B
The answer is: B
|
B
|
mathematics
|
If A and B get profits of Rs.5,000 and Rs.2,000 respectively at the end of year then ratio of their investments are
|
[
"4:1",
"1:4",
"5:2",
"2:3",
"2:5"
] |
Ratio = 5000/2000 = 5 : 2
Answer : C
The answer is: C
|
C
|
mathematics
|
If -4 < x < 8 and -6 < y < 3, which of the following specifies all the possible values of xy?
|
[
"-42 < xy < 21",
"-42 < xy < 24",
"-48 < xy < 24",
"-24 < xy < 21",
"-24 < xy < 24"
] |
The least value of xy is a bit more than 8*(-6)=-48 and the largest value of xy is a bit less than (-4)*(-6)=24.
Therefore -48 < xy < 24.
Answer: C.
The answer is: C
|
C
|
mathematics
|
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
|
[
"1",
"2",
"3",
"4",
"5"
] |
B
2
If the number 1056 is completely divisible by 23 means, remainder should come zero.
But if we divide 1056 by 23, the remainder is 2.
So if 2 is added to the 1056, we get remainder 0.
Therefore solution is 2
The answer is: B
|
B
|
mathematics
|
What is the sum of the odd integers from 35 to 65, inclusive?
|
[
"800",
"550",
"555",
"600",
"605"
] |
The mean is 50.
Sum=Mean(# of elements)
There are 16 odd numbers between 35-65 inclusive. 16*50=800
A
The answer is: A
|
A
|
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