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mathematics
|
A boy runs 200 metres in 72 seconds. What is his speed ?
|
[
"10 km/hr",
"14 km/hr",
"20 km/hr",
"12 km/hr",
"24 km/hr"
] |
200/72 * 18/5 = 10 km/hr
ANSWER:A
The answer is: A
|
A
|
mathematics
|
The area of a square is 4096 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square.
|
[
"5 : 12",
"5 : 13",
"5 : 167",
"5 : 19",
"5 : 16"
] |
Let the length and the breadth of the rectangle be l cm and b cm respectively. Let the side of the square be a cm.
a2 = 4096 = 212
a = (212)1/2 = 26 = 64
L = 2a and b = a - 24
b : l = a - 24 : 2a = 40 : 128 = 5 : 16
Answer: Option E
The answer is: E
|
E
|
mathematics
|
A train with a length of 100 meters, is traveling at a speed of 72 km/hr. The train enters a tunnel 2.3 km long. How many minutes does it take the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
|
[
"2.0",
"2.5",
"3.0",
"3.5",
"4.0"
] |
72 km/hr = 1.2 km/min
The total distance is 2.4 km.
2.4 / 1.2 = 2 minutes
The answer is A.
The answer is: A
|
A
|
mathematics
|
A candidate who gets 30% of the marks fails by 50 marks. But another candidate who gets 45% marks gets 25 marks more than necessary for passing. Find the number of marks for passing?
|
[
"200",
"150",
"275",
"300",
"350"
] |
30% ------------ 50
45% ------------ 25
----------------------
15% ------------- 75
30% -------------- ?
150 + 50 = 200 Marks
ANSWER A
The answer is: A
|
A
|
mathematics
|
How many liters of water must be evaporated from 50 liters of a 3 percent sugar solution to get a 4 percent sugar solution?
|
[
"12.5",
"15.5",
"17.5",
"21.5",
"24.5"
] |
Let x be the amount that needs to be evaporated.
0.03(50) = 0.04(50-x)
0.04x = 2 - 1.5
x = 0.5/0.04 = 12.5 liters
The answer is A.
The answer is: A
|
A
|
mathematics
|
Before leaving home for the town of Madison, Pete checks a map which shows that Madison is 5 inches from his current location, Gardensquare. Pete arrives in Madison 1.5 hours later and drove at an average speed of 60 miles per hour. At what scale, in inches per mile, is the map drawn?
|
[
"1/3",
"1/18",
"1/10",
"2",
"30"
] |
Pete covered 1.5*60=90 miles which correspond to 5 inches on the map --> scale in inches per mile is 5/90=1/18.
Answer: B.
The answer is: B
|
B
|
mathematics
|
Find odd one among 2,3, 4, 4, 6, 8, 9,12, 16 ?
|
[
"9",
"8",
"77",
"65",
"212"
] |
ANSWER: A
The answer is: A
|
A
|
mathematics
|
Employees of a certain company are each to receive a unique 9-digit identification code consisting of the digits 0, 1, 2, 3, 4, 5, 6, 7, and 8 such that no digit is used more than once in any given code. In valid codes, the second digit in the code is exactly twice the first digit. How many valid codes are there?
|
[
"14,720",
"16,240",
"18,320",
"20,160",
"22,480"
] |
There are 7! ways to make codes starting with 12.
There are 7! ways to make codes starting with 24.
There are 7! ways to make codes starting with 36.
There are 7! ways to make codes starting with 48.
The number of codes is 4*7! = 20,160.
The answer is D.
The answer is: D
|
D
|
mathematics
|
The ratio of the age of a man and his women is 4:3. At the time of first meet theratio was 5:3 and After 4 years this ratio will become 9:7. How many yrs ago were they met?
|
[
"10",
"12",
"15",
"16",
"20"
] |
Let the present age of the man and his wife be 4x and 3x respectively.
After 4 years this ratio will become 9:7
β(4x+4):(3x+4)=9:7β7(4x+4)=9(3x+4)β28x+28=27x+36βx=8
Present age of the man =4x=4Γ8=32
Present age of his wife =3x=3Γ8=24
Assume that they got married before t years. Then,
(32βt):(24βt)=5:3β3(32βt)=5(24βt)β96β3t=120β5tβ2t=24βt=242=12
B
The answer is: B
|
B
|
mathematics
|
In a fuel station the service costs $1.75 per car, every liter of fuel costs 0.65$. Assuming that a company owns 12 cars and that every fuel tank contains 57 liters and they are all empty, how much money total will it cost to fuel all cars?
|
[
"320.50$",
"380.50$",
"425.50$",
"450.50$",
"465.60$"
] |
Total Cost = ( 1.75*12 ) + ( 0.65 * 12 * 57 ) = 465.60
Hence answer will be (E)
The answer is: E
|
E
|
mathematics
|
8 couples (husband and wife) attend a dance show "Nach Baliye' in a popular TV channel ; A lucky draw in which 4 persons picked up for a prize is held, then the probability that there is atleast one couple will be selected is ?
|
[
"8/39",
"15/39",
"12/13",
"11/13",
"None of these"
] |
P( selecting atleast one couple) = 1 - P(selecting none of the couples for the prize)
= 1 - [16C1x14C1x12C1x10C1/16C4] = 15/39
Answer is B
The answer is: B
|
B
|
mathematics
|
A Man can row upstream at 95kmph and downward stream at 47 kmph. Find Man's rate of the current
|
[
"87km/hr",
"20km/hr",
"24km/hr",
"2.8km/hr",
"4.4km/hr"
] |
Rate of the current=1/2(95-47)km/hr
=24km/hr
correct option is :C
The answer is: C
|
C
|
mathematics
|
How many integers between 362,855 and 852,755have tens digit 1 and units digit 3?
|
[
"4,888",
"4,898",
"4,889",
"4,869",
"4,896"
] |
There is one number in hundred with 1 in the tens digit and 3 in the units digit: 13, 113, 213, 313, ...
The difference between 362,855 and 852,755 is 852,755-362,855=489,900 - one number per each hundred gives 133,900/100=4,889 numbers.
Answer: C.
The answer is: C
|
C
|
mathematics
|
The simple interest accrued on an amount Rs.10,000 at the end of two years is same as the compound interest on Rs.8,000 at the end of two years. The rate of interest is same in both the cases. What is the rate of interest?
|
[
"80% p.a",
"100% p.a.",
"40% p.a",
"44% p.a",
"50% p.a"
] |
Given that Rs.10,000 is invested in S.I for two years and Rs.8,000 in C.I for two years
=> C.I - S.I
=>9,000 { [1 + r/100]2 - 1} = (10,000)2r /100
=> 9{ 1 + 2r/100 + r2 / (100)2 - 1} = r/5
=> r = 0% of 40%
Since r!= 0%, r =40%
ANSWER:C
The answer is: C
|
C
|
mathematics
|
What is the simplified result of following the steps below in order?
(1) add 5y to 2q
(2) multiply the sum by 3
(3) subtract q + y from the product
|
[
"5q + 14y",
"5x + 16y",
"5x + 5y",
"6x + 4y",
"3x + 12y"
] |
3(5Y+2Q) -Q-Y= 14Y+5Q
'A' is the answer
The answer is: A
|
A
|
mathematics
|
Calculate the number of urns of water needed to fill a tank of dimensions of 10x10x5m to 90% full, if the volume of the urn is 0.8m3 and can only be filled to 80%.
|
[
"520",
"650.2",
"685.5",
"703.1",
"712.2"
] |
Volume of the tank that needed to be filled=10x10x5x0.9=450
Volume of the urn that can be filled=0.8x0.8=0.64
No. of urns of water needed to fill the tank=450/0.64= 703.1
Answer: D
The answer is: D
|
D
|
mathematics
|
An empty pool being filled with water at a constant rate takes 8hours to fill to 2/5 of its capacity.how much more time will it take to finish filling the pool?
|
[
"5hr 30min",
"5hr 20min",
"4hr 48min",
"3 hr 12min",
"2hr 40 min"
] |
As pool is filled to 2/5 of its capacity then 2/5 of its capacity is left to fill.
To fill 3/5 of the pool took 8 hours --> to fill 2/5 of the pool will take 8/(3/5)*2/5=16/3 hours = 5 hours 20 minutes (because if t is the time needed to fill the pool then t*3/5=8 --> t=8*5/3 hours --> to fill 2/5 of the pool 8*5/3*2/5=16/3 hours will be needed).
Or plug values: take the capacity of the pool to be 5 liters --> 3/5 of the pool or 3 liters is filled in 8 hours, which gives the rate of 3/8 liters per hour --> remaining 2 liters will require: time = job/rate = 2/(3/8) = 16/3 hours = 5 hours 30 minutes.
Answer: A.
The answer is: A
|
A
|
mathematics
|
A rectangular-shaped carpet that measures x feet by y feet is priced at $9. What is the cost of the carpet, in dollars per square yard? (1 square yard = 9 square feet)
|
[
"90/(xy)",
"90xy",
"xy/90",
"xy/10",
"81/(xy)"
] |
The area of the carpet in feet is xy.
The area in square yards is xy / 9.
The price per square yard is 9 / (xy/9) = 81/(xy).
The answer is E.
The answer is: E
|
E
|
mathematics
|
John and Jane went out for a dinner and they ordered the same dish. Both used a 10% discount coupon. John paid a 15% tip over the original price of the dish, while Jane paid the tip over the discounted price for the coupon. If John paid $0.54 more than Jane, what was the original price of the dish?
|
[
"24",
"34.8",
"36",
"42",
"84"
] |
The difference between the amounts John paid and Jane paid is the deference between 15% of p and 15% of 0.9p:
0.15p - 0.15*0.9p = 0.54 --> 15p - 13.5p = 54 --> p = 36.
Answer: C.
The answer is: C
|
C
|
mathematics
|
The average marks of a class of 30 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students?
|
[
"52.3",
"52.2",
"52.1",
"52.5",
"52.4"
] |
Sum of the marks for the class of 30 students = 30 * 40 = 1200
Sum of the marks for the class of 50 students = 50 * 60 = 3000
Sum of the marks for the class of 80 students =
1200 + 3000 = 4200
Average marks of all the students = 4200/80
= 52.5
Answer:D
The answer is: D
|
D
|
mathematics
|
Two vessels having volumes in the ratio 3:5 are filled with water and milk solutions. The ratio of milk and water in the two vessels are 1:2 and 6:4 respectively. If the contents of both the vessel are empties into a larger vessel, find the ratio of milk and water in the larger vessel.
|
[
"1:1",
"2:1",
"3:1",
"5:1",
"6:1"
] |
Vessel A = 300 gallons --> milk = 100, water = 200;
Vessel B = 500 gallons --> milk = 300, water = 200;
Vessel A + B = 800 gallons --> milk = 400, water 400
The ratio =400/400 --> 1:1
Answer: A
The answer is: A
|
A
|
mathematics
|
How many four digit numbers have no repeat digits, do not contain zero, and have a sum of digits A equal to 28?
|
[
"14",
"24",
"28",
"48",
"96"
] |
First, look for all 4 digits without repeat that add up to 28. To avoid repetition, start with the highest numbers first.
Start from the largest number possible 9874.
Then the next largest number possible is 9865.
After this, you'll realize no other solution. Clearly the solution needs to start with a 9 (cuz otherwise 8765 is the largest possible, but only equals 26). With a 9, you also need an 8 (cuz otherwise 9765 is the largest possible, but only equals 27). With 98__ only 74 and 65 work.
So you have two solutions. Each can be rearranged in 4!=24 ways. So A=24+24=48.D
The answer is: D
|
D
|
mathematics
|
If 5 (A's capital) = 10 (B's capital) = 15 (C's capital). Then the ratio of their capitals is?
|
[
"5:3:2",
"7:3:2",
"6:3:3",
"6:3:2",
"5:3:2"
] |
5A = 10B = 15 C
A:B:C = 1/5:1/10:1/15
= 6:3:2
Answer: D
The answer is: D
|
D
|
mathematics
|
If x is an integer and y = 3x + 5, which of the following CANNOT be a divisor of y?
|
[
"4",
"12",
"2",
"7",
"6"
] |
For any value of x, the expression 3x + 5 would never be divisible by 3,6,9...... onwards
So answer = 6 = E
The answer is: E
|
E
|
mathematics
|
A, B, C together started a business. A invested Rs.6000 for 5 months B invested Rs.3600 for 6 months and C Rs.7500 for 3 months. If they get a total profit of Rs.7410. Find the share of A?
|
[
"3999",
"3000",
"3882",
"2661",
"1234"
] |
60*5:36*6:75*3
100: 72: 75
100/247 * 7410
= 3000
Answer: B
The answer is: B
|
B
|
mathematics
|
On a trip, a cyclist averaged 11 miles per hour for the first 22 miles and 10 miles per hour for the remaining 20 miles. If the cyclist returned immediately via the same route and took a total of 9 hours for the round trip, what was the average speed (in miles per hour) for the return trip?
|
[
"7.6",
"7.8",
"8",
"8.2",
"8.4"
] |
The time to go 42 miles was 22/11+20/10=2+2=4 hours.
The average speed for the return trip was 42 miles/5 hours= 8.4 mph.
The answer is E.
The answer is: E
|
E
|
mathematics
|
A large delicatessen purchased p pounds of cheese for K dollars per pound. If d pounds of the cheese had to be discarded due to spoilage and the delicatessen sold the rest for s dollars per pound, which of the following represents the gross profit on the sale of the purchase? (gross profitequalssales revenueminusproduct cost)
|
[
"(p β d)(s β c)",
"s(p-d) - Kp",
"c(p β d) β ds",
"d(s β c) β pc",
"pc β ds"
] |
Total cost price = K*p ............... (1)
Wastage = d pounds
Quantity sold = p-d
Selling price per pound = s
Total selling price = s(p-d) ........... (2)
Profit = (2) - (1)
= s(p-d) - Kp
B
The answer is: B
|
B
|
mathematics
|
Find large number from below question The difference of two numbers is 1000. On dividing the larger number by the smaller, we get 10 as quotient and the 10 as remainder
|
[
"1234",
"1110",
"1456",
"1200",
"1600"
] |
Let the smaller number be x. Then larger number = (x + 1365).
x + 1000 = 10x + 10
9x = 990
x = 110
Large number = 110+1000=1110
B
The answer is: B
|
B
|
mathematics
|
The average weight of a group of boys is 30 kg. After a boy of weight 37 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?
|
[
"A)4",
"B)8",
"C)6",
"D)2",
"E)1"
] |
Let the number off boys in the group originally be x.
Total weight of the boys = 30x
After the boy weighing 37 kg joins the group, total weight of boys = 30x + 37
So 30x + 37 = 31(x + 1) = > x = 6.
Answer:C
The answer is: C
|
C
|
mathematics
|
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
|
[
"3.6 sec",
"18 sec",
"36 sec",
"72 sec",
"84 sec"
] |
Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
= 36 x 5/18 m/sec
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m. Answer: Option C
Time taken = 360/10 sec = 36 sec.
The answer is: C
|
C
|
mathematics
|
Subtracting 10% from X is the same as multiplying X by what number?
|
[
"97%",
"90%",
"80%",
"98%",
"20%"
] |
X - (10/100) X = X * ?
? = 90%
Answer: B
The answer is: B
|
B
|
mathematics
|
The average of 9 observations was 9, that of the 1st of 5 being 10 and that of the last 5 being 8. What was the 5th observation?
|
[
"9",
"8",
"7",
"6",
"3"
] |
1 to 9 = 9 * 9 = 81
1 to 5 = 5 * 10 = 50
5 to 9 = 5 * 8 = 40
5th = 50 + 40 = 90 β 81 = 9
Answer: A
The answer is: A
|
A
|
mathematics
|
The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:9. If P invested the money for 5 months, find for how much time did Q invest the money?
|
[
"9",
"17",
"13",
"10",
"12"
] |
7*5: 5*x = 7:9
x = 9
Answer: A
The answer is: A
|
A
|
mathematics
|
Rice weighing 33/4 pounds was divided equally and placed in 4 containers. How many ounces of rice were in each?
|
[
"18 ounces",
"15 ounces",
"19 ounces",
"17 ounces",
"14 ounces"
] |
33/4 Γ· 4 pounds.
= (4 Γ 3 + 3)/4 Γ· 4 pounds.
= 15/4 Γ· 4 pounds.
= 15/4 Γ 1/4 pounds.
= 15/16 pounds.
Now we know that, 1 pound = 16 ounces.
Therefore, 15/16 pounds = 15/16 Γ 16 ounces.
= 15 ounces.
Answer: (B)15 ounces.
The answer is: B
|
B
|
mathematics
|
IF x is an integer greater than 6, then all the following must be divisible by 3 EXCEPT
|
[
"9x/3",
"9x^2",
"x(x+1)(x+2)",
"x+1",
"3x^3"
] |
*any number multiplied by 3, will be divided by 3
for option D if we put value x=7, 7+1=8 is not divisible by 3
Answer : E
The answer is: E
|
E
|
mathematics
|
A certain city with population of 132,000 is to be divided into 11 voting districts, and no district is to have a population that is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have?
|
[
"10,700",
"10,800",
"10,900",
"11,000",
"11,100"
] |
population that is 10% greater than the population of any other district..
11000.. 10% of 11000 = 1100.. so the next population will be 12100..
10*12,100 + 11000 = 132000. D
The answer is: D
|
D
|
mathematics
|
A boat travels 72 km downstream in 8 hours and 84 km upstream in 12 hours. Find the speed of the boat in still water and the speed of the water current ?
|
[
"6 and 1 kmph",
"8 and 2 kmph",
"8 and 1 kmph",
"9 and 1 kmph",
"2 and 1 kmph"
] |
Explanation:
Downstream speed = 72km/8hrs = 9 kmph
upstream speed = 84km/12hrs = 7 kmph
speed of boat = avg of downstream and upstream speeds
speed of boat = (9+7)/2kmph = 8 kmph.
current speed = half of the difference of downstream and upstream speeds
currend speed = (9-7)/2kmph = 1 kmph
Answer: C
The answer is: C
|
C
|
mathematics
|
Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 1% more. She would get how much?
|
[
"9440",
"96288",
"26667",
"1662",
"2882"
] |
(8000*3*1)/100 = 240
9200
--------
9440
Answer:A
The answer is: A
|
A
|
mathematics
|
What will come in place of the x in the following Number series? 279936, 46656, 7776, 1296, 216, x
|
[
"124",
"165",
"36",
"178",
"215"
] |
Go on dividing by 6 to the next number
C)
The answer is: C
|
C
|
mathematics
|
A train 100 meters long completely crosses a 300 meters long bridge in 36 seconds. What is the speed of the train is?
|
[
"32 kmph",
"76 kmph",
"34 kmph",
"43 kmph",
"40 kmph"
] |
S = (100 + 300)/36
= 400/36 * 18/5
= 40
Answer:E
The answer is: E
|
E
|
mathematics
|
A man buys Rs. 52 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is:
|
[
"s. 12",
"s. 15",
"s. 18",
"s. 21",
"s. 39"
] |
Dividend on Rs. 52 = Rs. 9/100 x 52 =Rs. 4.68 .
Rs. 12 is an income on Rs. 100.
Rs. 4.68 is an income on Rs.100/12 x 4.68 = Rs. 39.
Answer: Option E
The answer is: E
|
E
|
mathematics
|
A thief is spotted by a policeman from a distance of 100metres. When the policeman starts the chase, the thief also starts running. If the speed of the thief be 15km/hr and that of the policeman 20km/hr, how far the thief will have run before he is overtaken ?
|
[
"A)1km",
"B)300m",
"C)650m",
"D)750m",
"E)800m"
] |
Relative speed of the policeman = 20-15 = 5 km/hr
time taken by policeman to cover 100m = (100/1000)*(1/5) = 1/50 hr
In 1/50 hr the thief covers a distance of 15/50 km = 3/10 km = 300m
Answer is B
The answer is: B
|
B
|
mathematics
|
In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?
|
[
"80",
"90",
"15",
"209",
"105"
] |
We may have (1 boy and 3 girls) or (2 boys and 2 girls) or (3 boys and 1 girl) or (4 boys).
Required number
of ways = (6C1 x 4C3) + (6C2 x 4C2) + (6C3 x 4C1) + (6C4)
= (6C1 x 4C1) + (6C2 x 4C2) + (6C3 x 4C1) + (6C2)
= (24 + 90 + 80 + 15)
= 209.
ANSWER D 209
The answer is: D
|
D
|
mathematics
|
Tom can hit a target 3 times in 6 shots, Karan can hit the target 2 times in 6 shots & Ashwini can hit 4 times in 4shots. What is the probability that at least 2 shots hit the target ?
|
[
"1/2",
"2/5",
"2/3",
"3/7",
"3/11"
] |
Ashwini hits the target definitely, hence required probability that atleast 2 shots hit the target is given by
Karan hits tha target and Raja not hit the target.
or
Karan does not hit the target and Raja hits the target.
or.
Karan hits the target and Raja hits the target
= 2/6 x 3/6 + 4/6 x 3/6 + 2/6 x 3/6
= 24/36 = 2/3
C
The answer is: C
|
C
|
mathematics
|
A group of 4 students bought movie tickets in one row next to each other. If Bob and Lia are in this group, what is the probability that Bob and Lia will each sit next to only one of the three other students from the group?
|
[
"5.67%",
"16.67%",
"15.57%",
"20.25%",
"25.75%"
] |
The question basically asks about the probability that Bob and Lisa sit at the ends.
The total # of sitting arrangements is 4!.
Desired arrangement is either BYZL or LYZB. Now, YZ can be arranged in 2! ways, therefore total # of favorable arrangements is 2*2!.
P=(favorable)/(total)=(2*2!)/4!=1/6.
Answer: B.
The answer is: B
|
B
|
mathematics
|
A basket has 5 apples and 4 oranges. Three fruits are picked at random. The probability that at least 2 apples are picked is
|
[
"25/42",
"25/44",
"25/409",
"25/45",
"25/41"
] |
Total fruits = 9
Since there must be at least two apples,
(5C2 * 4C1)/8C1 +2C2/2C2 = 25/42.
Answer:A
The answer is: A
|
A
|
mathematics
|
A table is bought for Rs.400/- and sold at Rs.550/- find gain or loss percentage
|
[
"l10%oss",
"30%gain",
"37.5%gain",
"10%loss",
"25% loss"
] |
Formula = (Selling price ~ Cost price)/Cost price * 100
= (550 - 400)/400 = 37.5% gain
C
The answer is: C
|
C
|
mathematics
|
In a stockpile of products produced by three machines M1, M2 and M3, 40% and 30% were manufactured by M1 and M2 respectively. 3% of the products of M1 are defective, 1% of products of M2 defective, while 91% of the products of M3 III are not defective. What is the percentage of defective in the stockpile?
|
[
"3%",
"5%",
"2.5%",
"4.2%",
"6%"
] |
Explanation :
Let there be 100 products in the stockpile. 40% and 30% were manufactured by M1 and M2 respectively. So, 30% are manufactured by M3.
Products from M1 = 40, from M2 = 30 and from M3 = 30.
Number of defective products from M1 = 0.03 x 40 = 1.2, from M2 = 0.01 x 30 = 0.3 and from M3 = 0.09 x 30 = 2.7
Therefore, total number of defective products = 4.2.
Answer : D
The answer is: D
|
D
|
mathematics
|
How long does a train 150 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length?
|
[
"14.1 sec",
"12.1 sec",
"16.1 sec",
"13.1 sec",
"12.15sec"
] |
Speed = 72 * 5/18 = 20 m/sec
Total distance covered = 150 + 132 = 282 m.
Required time = 282/20 = 14.1 sec.
Answer:A
The answer is: A
|
A
|
mathematics
|
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
|
[
"20%",
"30%",
"35%",
"40%",
"50%"
] |
Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = 0.59x x 100 % = 30% (approx.)
2x
B)
The answer is: B
|
B
|
mathematics
|
At what price must an article costing Rs.47.50 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price?
|
[
"62.5",
"62.3",
"62.7",
"62.2",
"62.9"
] |
CP = 47.50
SP = 47.50*(125/100)
= 59.375
MP*(95/100)
= 59.375
MP = 62.5
Answer:A
The answer is: A
|
A
|
mathematics
|
A container holding 12 ounces of a solution that is 1 part alcohol to 2 parts water is added to a container holding 9 ounces of a solution that is 1 part alcohol to 2 parts water. What is the ratio of alcohol to water in the resulting solution?
|
[
"1:2",
"3:7",
"3: 5",
"4:7",
"7:3"
] |
Container 1 has 12 ounces in the ratio 1:2
or,
x+2x=12 gives x(alcohol)=4 and remaining water =8
container 2 has 9 ounces in the ratio 1:2
or,
x+2x=9 gives x(alcohol)=3 and remaining water =6
mixing both we have alcohol=4+3 and water =8+6
ratio thus alcohol/water =7/14=1/2
Answer A
The answer is: A
|
A
|
mathematics
|
which one is odd?
4377
3954
9865
8454
9831
|
[
"4377",
"3954",
"9865",
"8454",
"None"
] |
Correct Answer : C
sum of digit of all other number is 21, but sum of digit of 9865 is 28
The answer is: C
|
C
|
mathematics
|
54671 - 14456 - 33466 = ?
|
[
"2449",
"5449",
"6749",
"6449",
"6468"
] |
C
If we calculate we will get 6749
The answer is: C
|
C
|
mathematics
|
A car traveled 340 miles per tankful of gasoline on the highway and 336 miles per tankful of gasoline in the city. If the car traveled 6 fewer miles per gallon in the city than on the highway, how many miles per gallon did the car travel in the city?
|
[
"504",
"416",
"321",
"220",
"170"
] |
Let the speed in highway be h mpg and in city be c mpg.
h = c+6
h miles are covered in 1 gallon
340 miles will be covered in 340/h.
Similarly c miles are covered in 1 gallon
336 miles will be covered in 336/c.
Both should be same (as car's fuel capacity does not change with speed)
=> 336/c = 340/h
=> 336/c = 340/(c+6)
=> 336c+336*6=340c
=>c=336*6/4=504
Answer A.
The answer is: A
|
A
|
mathematics
|
Two boats are heading towards each other at constant speeds of 4 miles/hr and 20 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide ?
|
[
"1/12",
"6/15",
"1/6",
"1/3",
"1/5"
] |
The question asks: how far apart will they be 1 minute=1/60 hours before they collide?
Since the combined rate of the boats is 4+20=25 mph then 1/60 hours before they collide they'll be rate*time=distance --> 24*1/60=6/15miles apart.
Answer: B.
The answer is: B
|
B
|
mathematics
|
Each shelf of a bookcase contained 12 books. If the librarian took out 21 books and rearranged the remaining books so that all shelves but the last one contained 8 books and that last shelf contained 7 books, how many shelves does the bookcase have?
|
[
"5",
"6",
"7",
"8",
"9"
] |
Let x be the number of shelves.
12x - 21 = 8(x-1) + 7
4x = 20
x= 5
The answer is A.
The answer is: A
|
A
|
mathematics
|
15 different biology books and 8 different chemistry books lie on a shelf. In how many ways can a student pick 2 books of each type?
|
[
"80",
"160",
"720",
"2100",
"2940"
] |
No. of ways of picking 2 biology books(from 15 books) = 15c2 = (15*14)/2 = 105
No. of ways of picking 2 chemistry books(from 8 books) = 8c2 = (8*7)/2 = 28
Total ways of picking 2 books of each type = 105*28 =2940
(Option E)
The answer is: E
|
E
|
mathematics
|
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are drawn at random, what is the probability that at least one is green?
|
[
"23/35",
"23/32",
"23/31",
"23/30",
"63/35"
] |
Explanation:
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green
= (Γ’ΒΒΆCΓ’βΒ * Γ’ΒΒΉCΓ’βΒ)/ΓΒΉΓ’ΒΒ΅CΓ’ββ + Γ’ΒΒΆCΓ’ββ/ΓΒΉΓ’ΒΒ΅CΓ’ββ
= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7
= 46/70 = 23/35
Answer: A
The answer is: A
|
A
|
mathematics
|
Kim bought a total of $2.65 worth of postage stamps in four denominations. If she bought an equal number of 5-cent and 25-cent stamps and twice as many 10-cent stamps as 5-cent stamps, what is the least number of 2-cent stamps she could have bought ?
|
[
"5",
"10",
"7.5",
"20",
"25"
] |
2.65 = 0.05x + 0.25x + 2 * 0.10x + 0.02y
=> 2.65 = 0.30x + 0.20x + 0.02y
=> 265 = 50x + 2y
So Max value of 50x < 265 = 250
Hence y = 7.5
Answer - C
The answer is: C
|
C
|
mathematics
|
Some times small town drivers can be very rude. One taxi driver I had the occasion to travel with was particularly lacking in courtesy, and so I asked for his number.
The driver gave me a sardonical smile and said. 'Well, if you divide my number by 2, 3, 4, 5 or 6 you will find there is always 1 remaining. But if you divide it by 11 there is no remainder. Do you want to know something more? There is no other cabby in this town with a lower number than---who can say the same.,' and he drove off, while I stood there completely baffled.
What was the man's number?
|
[
"121",
"143",
"165",
"133",
"117"
] |
A
The driver's number was 121.
The answer is: A
|
A
|
mathematics
|
Three numbers are in the ratio 5 : 6 : 7. The sum of its longest and smallest numbers equals the sum of the third number and 84. Find the third number?
|
[
"A)37",
"B)85",
"C)48",
"D)43",
"E)84"
] |
Let the numbers be 5x, 6x, 7x.
Largest number = 7x.
Smallest number = 5x.
Third number = 6x.
7x + 5x = 6x + 84
6x = 84 => third number is 84.
Answer: Option E
The answer is: E
|
E
|
mathematics
|
A boat goes 8 km upstream in 24 minutes. The speed of stream is 4 km/hr. The speed of boat in still water is:
|
[
"24 km/hr",
"25 km/hr",
"26 km/hr",
"23 km/hr",
"22 km/hr"
] |
Speed upstream =8/(24/60) = 20 km/hr
Speed of the stream = 4 km/hr
speed of boat in still water = (20+4) = 24 km/hr
Answer : Option A
The answer is: A
|
A
|
mathematics
|
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?
|
[
"28",
"50",
"88",
"22",
"12"
] |
Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 45 ==> x
= 50 km/hr.Answer:B
The answer is: B
|
B
|
mathematics
|
A 240 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
|
[
"260",
"250",
"240",
"230",
"220"
] |
Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 240)/9 = 500/9 => x = 260.
Answer: Option A
The answer is: A
|
A
|
mathematics
|
Sandy bought 65 books for $1080 from one shop and 55 books for $840 from another shop. What is the average price that Sandy paid per book?
|
[
"$14",
"$16",
"$18",
"$20",
"$22"
] |
average price per book = (1080 + 840) / (65 + 55) = 1920 / 120 = $16
The answer is B.
The answer is: B
|
B
|
mathematics
|
Frances can complete a job in 10 hours, and Joan can complete the same job in 10 hours. Frances starts the job at 9 a.m., and stops working at 3 p.m. If Joan starts working at 6 p.m. to complete the job, at what time is the job finished?
|
[
"6 p.m.",
"7 p.m.",
"8 p.m.",
"10 p.m.",
"12 p.m."
] |
Let the total work be 24 units.
Frances can complete 2.4 units/hr
Joan can complete 2.4 units/hr
Work done by Frances in 6 hours is 14.4 units ; work left for Joan is 9.6 units ( 24 - 14.4)
Time required by Jones to complete the remaining work will be 14.4/2.4 => 4 hours
Given Jones starts at 6 PM , so she would complete the work at 10 PM
Answer will be (D)
The answer is: D
|
D
|
mathematics
|
Kamal started a business with Rs.25000 and after 4 months, Kiran joined him with Rs.60000. Kamal received Rs.58000 including 10% of profit as commission for managing the business. What amount did Kiran receive?
|
[
"75000",
"70000",
"72000",
"78000",
"None of these"
] |
Explanation :
Ratio of the profits = 25000*12 : 60000*8
= 25*12 : 60*8 = 5*3 : 12:2 = 5 : 4*2
= 5:8
Let the total profit = x.
Then Kamal received 10x/100 = x/10 as commission for managing the business
Remaining profit = x- x/10 = 9x/10 which is shared in the ration 5:8
Kamal's share = x/10 + (9x/10) * (5/13) = 58000
=> x + 9x(5/13) = 580000
=> x(1 + 45/13) = 580000
=> x ( 58/13) = 580000
=> x ( 1/13) = 10000
=> x = 130000
Kiran's share = 130000 - 58000 = 72000. Answer : Option C
The answer is: C
|
C
|
mathematics
|
A starts business with a capital of Rs.1200 B and C join with some investments after 3 and 6 months respectively. If the end of a year, the profit is divided in the ratio 2:3:5 respectively. What is B's investment in the business?
|
[
"2400",
"2882",
"2277",
"2656",
"2778"
] |
1200 * 12: x * 9 = 2:3
x = 2400
Answer: A
The answer is: A
|
A
|
mathematics
|
A and B started a business with initial investments in the ratio 14 : 15 and their annual profits were in the ratio 7 : 6. If A invested the money for 10 months, for how many months did B invest his money?
|
[
"2",
"4",
"6",
"8",
"9"
] |
Sol.
Suppose A invested Rs. 14x for 10 months and B invested Rs. 15x for y months. Then,
14x * 10 / 15x * y = 7/6 β y = 840 / 105 = 8
Hence, B invested the money for 8 months.
Answer D
The answer is: D
|
D
|
mathematics
|
The circumference of the front wheel of a cart is 30 ft long and that of the back wheel is 40 ft long. What is the distance traveled by the cart, when the front wheel has done five more revolutions than the rear wheel?
|
[
"20 ft",
"25 ft",
"600ft",
"900 ft",
"1000 ft"
] |
Point to note: Both the wheels would have traveled the same distance.
Now consider, no. of revolutions made by back wheel as x, which implies that the number of revolutions made by the front wheel is (x+5).
Equating the distance traveled by front wheel to back wheel: (x+5)*30 = x * 40. (Formula for calculating the distance traveled by each wheel is: # of revolutions * circumference.)
Solving this eqn. gives x=15.
Sub x=15 either in (x+5)*30 or in x * 40 to get the distance, which is 600. So the correct choice is C.
The answer is: C
|
C
|
mathematics
|
X and Y are two towns. Ganesh covers the distance from X to Y at an average speed of 43 Km/hr. However, he covers the distance from Y to X at an average speed of 34 Km/hr. His average speed during the whole journey in km/hr. is :
|
[
"34",
"43",
"40",
"38",
"29"
] |
Solution: Average speed = 2XY / X+Y
= 2*43*34 / 43+34
= 2924 / 77
= 37.974... = 38
Answer : D
The answer is: D
|
D
|
mathematics
|
2 oranges, 3 bananas and 4 apples cost Rs.15. 3 oranges 2 bananas 1 apple costs Rs.10. what is the cost of 3 oranges, 3 bananas and 3 apples?
|
[
"30",
"15",
"10",
"20",
"40"
] |
2or+3ba+4ap=15--->(1)
3or+2ba+1ap=10---->(2)
(1)+(2)
5or+5ba+5ap=15+10
5(or+ba+ap)=25
or+ba+ap=25/5
or+ba+ap=5
therefore 3or+3ba+3ap===>3(or+ba+ap);
3(5)=15;
ANSWER:B
The answer is: B
|
B
|
mathematics
|
In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.60 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?
|
[
"165",
"175",
"190",
"200",
"210"
] |
Suppose the man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.60 + X x 3.20 = 432
X = 5.
Hence, total hours of work = (160 + 5) = 165.
answer :A
The answer is: A
|
A
|
mathematics
|
What will come in place of the x in the following Number series? 49920, 4160, 416, 52, x
|
[
"8.67",
"7.67",
"6.67",
"5.67",
"4.67"
] |
49920 /12 = 4160
3840 /10 = 416
416 /8 = 52
52/6 = 8.67
A
The answer is: A
|
A
|
mathematics
|
Twenty percent of Country Y's yearly exports come from fruit exports. One-sixth of all fruit exports from Country Y are orange exports. If country Y generates $5 million from its orange exports, how much money does it generate from its yearly total of exports?
|
[
"$21.25m",
"$25.5m",
"$106.25m",
"$127.5m",
"$150m"
] |
2/10*1/6*(total) = 5
1/30*(total) = 5
(total) = 5*30 = 150
Answer: E.
The answer is: E
|
E
|
mathematics
|
In a hostel there were 100 students. To accommodate 25 more students the average is decreased by rupees 5. But total expenditure increased by Rs.400. Find the total expenditure of the hostel now?
|
[
"A)Rs.5800",
"B)Rs.5480",
"C)Rs.5400",
"D)Rs.4500",
"E)Rs.5430"
] |
100x + 400
= 125(x β 5)
x = 41
100 * 41 + 400
= 4500
Answer:D
The answer is: D
|
D
|
mathematics
|
How to additions fast. For example we have to do a simple addition like 234 + 563+ 985 + 349.
|
[
"2131",
"7399",
"2997",
"2769",
"2771"
] |
Instead of doing like this we first add all the digits in the hundred's place. 2 + 5 + 9 + 3 = 19. Put 2 zero's to the right hand side so we get 1900.
Now add the digits in the tenth's place. 3 + 6 + 8 + 4 = 21. Put 1 zero to the right hand side so we get 210.
Now add the digits in the units place 4 + 3 + 5 + 9 = 21.
Now 1900 + 210 + 21 = 2131
Answer:A
The answer is: A
|
A
|
mathematics
|
If 4 boys can color 60 m long cloth in 3 days, then 6 boys can color 36 m long cloth in
|
[
"day",
"days",
"days",
"days",
"days"
] |
The length of cloth painted by one boy in one day = 60 / 4 Γ 3 =5 m
No. of days required to paint 36 m cloth by 6 boys = 36/ 5 Γ 6 = 6/5 day.
A)
The answer is: A
|
A
|
mathematics
|
Of the 24 participants in a certain competition, half are male, and half of the males are younger than 18 years of age. If half of the female competitors are also younger than 18 years of age, into how many distinct groups of 4 competitors could the participants be divided if each group must contain two males under 18 years of age and 2 females over 18 years of age?
|
[
"225",
"45",
"65",
"95",
"200"
] |
M under 18 - 6
F above 18 - 6
How many distinct groups can be formed now: 6c2 * 6c2 = 225
Answer : A
The answer is: A
|
A
|
mathematics
|
If the area of a square with sides of length 3 centimeters is equal to the area of a rectangle with a width of 4 centimeters, what is the length of the rectangle, in centimeters?
|
[
"4",
"8",
"12",
"3",
"18"
] |
Let length of rectangle = L
3^2 = L*4
=> L = 9/4 = 3
Answer D
The answer is: D
|
D
|
mathematics
|
10 men, working 7 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the work in 12 days ?
|
[
"4 hours a day",
"5 hours a day",
"6 hours a day",
"7 hours a day",
"8 hours a day"
] |
Explanation:
More Men, Less Hours {Indirect Proportion}
Less Days, More Hours {Indirect Proportion}
[men 15 10
days 12 18] ::7:x
=>xΓ’Λβ15Γ’Λβ12=10Γ’Λβ18Γ’Λβ7
=>x=10Γ’Λβ18Γ’Λβ7/ 15Γ’Λβ12
=>x=7
Option D
The answer is: D
|
D
|
mathematics
|
What is the units digit of 16^83 Γ 13^82 Γ 11^87?
|
[
"4",
"5",
"6",
"7",
"8"
] |
To find : the units digit of 17^83 Γ 13^82 Γ 11^87
Let's reduce the clutter and simplify the product
(7^83) (3^82) (1^87)
7 has a cyclicity of 4 : the last digit of any positive power of 7 repeats itself after every 4th power
so 7^5 has the same last digit as 7^1, 7^9, 7^13
Thus , 7^83 has the same last digit as 7^3, 7^7, 7^11 i.e.3
3 has a cyclicity of 4 : exactly the same routine as above
Thus , 3^82 has the same last digit as 3^2, 3^6, 3^10 i.e.9
Any power of 1 will result in1as the last digit
So, product of our last digits = 3 x 9 x 1 = 27....last digit is 6
Correct Option : C
The answer is: C
|
C
|
mathematics
|
A, B, C together started a business. A invested Rs.6000 for 5 months B invested Rs.3600 for 6 months and C Rs.7500 for 3 months. If they get a total profit of Rs.7410. Find the share of A?
|
[
"9179",
"3000",
"2997",
"2678",
"2682"
] |
60*5:36*6:75*3
100: 72: 75
100/247 * 7410 = 3000
Answer: B
The answer is: B
|
B
|
mathematics
|
Sari and Ken climb up a mountain. At night, they camp together. On the day they are supposed to reach the summit, Sari wakes up at 08:00 and starts climbing at a constant pace. Ken starts climbing only at 10:00, when Sari is already 700 meters ahead of him. Nevertheless, Ken climbs at a constant pace of 500 meters per hour, and reaches the summit before Sari. If Sari is 50 meters behind Ken when he reaches the summit, at what time did Ken reach the summit?
|
[
"13:00",
"13:30",
"14:00",
"15:00",
"15:30"
] |
Both Sari and Ken climb in the same direction.
Speed of Sari = 700/2 = 350 meters/hr (since she covers 700 meters in 2 hrs)
Speed of Ken = 500 meters/hr
At 8:00, distance between Ken and Sari is 700 meters. Ken needs to cover this and another 50 meters.
Time he will take = Total distance to be covered/Relative Speed = (700 + 50)/(500 - 350) = 5 hrs
Starting from 10:00, in 5 hrs, the time will be 15:00
Answer (D)
The answer is: D
|
D
|
mathematics
|
Which of the following is closest to the difference between sum Z of all proper fractions (fractions less than 1) in the form 1/x , where x is a positive digit, and the product of all proper fractions in the form y/(y+1), where y is a positive digit?
|
[
"2.82",
"2.72",
"1.82",
"1.72",
"0.82"
] |
Sum Z of all proper fractions (fractions less than 1) in the form 1/x, where x is a positive digit:
1/1 + 1/2 + 1/3 +.....+ 1/9
This is a harmonic progression. Harmonic progression is inverse of arithmetic progression.
Approximate sum of a harmonic progression with even number of terms = number of terms * (average of middle 2 terms)
Approximate sum of a harmonic progression with odd number of terms = number of terms * (middle term)
The actual sum will be slightly more than the approximation.
Here we have 9 terms (odd).
Sum = 9 * 1/5
= 9/5
Product of all proper fractions in the form y/(y+1), where y is a positive digit:
1/2 * 2/3 * 3/4 *.....*9/10
We will be left with 1/10.
Required = 9/5 - 1/10
= 1.8 - 0.1
= 1.7
Closest is 1.72
Answer (D).
The answer is: D
|
D
|
mathematics
|
A and B together can do a work in 6 days. If A alone can do it in 15 days. In how many days can B alone do it?
|
[
"15",
"10",
"20",
"18",
"12"
] |
1/6 Γ’β¬β 1/15 = 1/10 => 10
ANSWER B
The answer is: B
|
B
|
mathematics
|
A circular mat with diameter 12 inches is placed on a square tabletop, each of whose sides is 24 inches long. Which of the following is closest to the fraction of the tabletop covered by the mat?
|
[
"5/12",
"2/5",
"1/5",
"3/4",
"5/6"
] |
SO we are looking for the area of the cloth over the area of the table
Area of the Cloth = (pi)(r)^2 which is about (3)(6)(6)
Area of the Table = (24)(24)
So the quick way to estimate is looking at the fraction like this: (3/24)(36/24)
I hope this is easy to follow, so with some simplification i get (1/8)(3/2) =3/16= (1/5) Answer is C
The answer is: C
|
C
|
mathematics
|
What is the sum of the greatest common factor and the lowest common multiple of 45 and 125?
|
[
"1920",
"2201",
"3240",
"1130",
"3840"
] |
Prime factorization of the given numbers
45= 3^2
125= 5^3
Greatest common factor =5
Lowest common multiple = 3^2*5^2 *5 =1125
Sum = 5+ 1125 = 1130
Answer D
The answer is: D
|
D
|
mathematics
|
Five kids were walking down the street. At a shop, they saw three brands of chocolates viz. Cadbury, Nestle and Ferrero being displayed. The shopkeeper has three chocolates which are of three different flavors of each brand. The kids bought all the chocolates available and decided to play a game. The chocolates will be distributed only to the winners of that game. Also they have decided that any winner cannot have all three brands of chocolates as his prize. Find the number of ways in which the chocolates can be distributed when there are four winners of the game and the best of them gets at least 4 chocolates?
|
[
"12312",
"22536",
"4320",
"11268",
"45072"
] |
Since, one child cannot have more than two brands of chocolates, therefore, one child can get a maximum of six chocolates.
When there are four winners, the winners can have the chocolates in the following possible way
Case I
One of them gets six chocolates and the other three get one each.
The one who gets six chocolates can be selected in 4C1 ways and he will get any two brands out of three in 3C2 ways.
The three chocolates of the same brand will be distributed among the other three in 3! ways.
Hence, the total number of ways = 4 Γ 3 Γ 6 = 72
Case II
One of them gets 5 chocolates, one of them gets 2 chocolates and the other two get 1 each.
Kid with 5 chocolates:
The one who gets five chocolates can be selected in 4C1 ways and he will get any two brands out of three in 3C2 ways.
After choosing the two brands (say AB), he can get all three chocolates of one brand in 2 ways (i.e. either A or B). The other two chocolates can be chosen from the second brand in 3 ways. Thus, there are 4 Γ 3 Γ 2 Γ 3 = 36 ways
Kid with 2 chocolates:
This person can be chosen in 3 ways. Now, he can either get two chocolates from the same brand or from two different brands.
Thus, there are 6 Γ 3 = 18 ways
Kids with 1 chocolate each
The remaining chocolates can be distributed between the two remaining winners in 2 ways.
Therefore, total number of ways = 36 Γ 18 Γ 2 = 1296 ways.
Case III
Similarly for four chocolates the following combinations are possible:
a) 4 3 1 1
The number of ways = 4 Γ 3 Γ [{6 Γ 3(1 + ( 6 + 3))} + {1 Γ 9 Γ 3 (1 + 6)}] Γ 2 = 8856
b) 4 2 2 1
The number of ways = 4 Γ 3 Γ [{6 Γ 3(2 Γ 6 Γ 3 + (3 + 9))} + {9 Γ (9 + 9)}] = 12312
Since, the best of them canβt have less than 4 chocolates the above are the only cases applicable.
Hence, the total number of ways = 72 + 1296 + (8856 + 12312) = 22536.
Option B
The answer is: B
|
B
|
mathematics
|
Jill is dividing her 12-person class into two teams of equal size for a basketball game. If no one will sit out, how many different match-ups between the two teams are possible?
|
[
"10",
"25",
"462",
"252",
"630"
] |
With 12 players, the process of figuring out how many groups of 6 can be formed is pretty straight-forward....
12C6 = 12!/(6!6!) = 924 possible groups of 6
Once forming that first group of 6, the remaining 6 players would all be placed on the second team by default.
The 'twist' is that the two teams of 6 canshow upin either order:
C
The answer is: C
|
C
|
mathematics
|
Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
|
[
"4",
"5",
"6",
"7",
"8"
] |
N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)
= H.C.F. of 3360, 2240 and 5600 = 1120.
Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4
Answer: Option A
The answer is: A
|
A
|
mathematics
|
The C.P of 15 books is equal to the S.P of 18 books. Find his gain% or loss%?
|
[
"16 2/3% loss",
"16 8/3% loss",
"19 2/3% loss",
"13 2/3% loss",
"26 2/3% loss"
] |
15 CP = 18 SP
18 --- 3 CP loss
100 --- ? => 16 2/3% loss
Answer: A
The answer is: A
|
A
|
mathematics
|
3^b + 3^b + 3^b =
|
[
"7^b",
"7^(b + 1)",
"7^(7b)",
"3^(b + 1)",
"49^B"
] |
Easy one.
3*3^b = 3^(b+1)
Ans. D
The answer is: D
|
D
|
mathematics
|
If a Γβ b = 2a - 3b + ab, then 2 Γβ 5 + 5 Γβ 2 is equal to :
|
[
"18",
"23",
"24",
"25",
"26"
] |
Explanation:
2 Γβ 5 + 5 Γβ 2 = (2 Γβ 2 - 3 Γβ 5 + 2 Γβ 5) + ( 2 Γβ 5 - 3 Γβ 2 + 5 Γβ 3)
= (4 -15 + 10 + 10 - 6 + 15) = 18.
Answer: A
The answer is: A
|
A
|
mathematics
|
A car is running at a speed of 80kmph. What distance will it cover in 20sec?
|
[
"100m",
"440m",
"180m",
"200m",
"250m"
] |
Speed = 80kmph = 80*5/18 = 22 m/s
Distance covered in 20sec = 22*10 = 440m
Answer is B
The answer is: B
|
B
|
mathematics
|
The sector of a circle has radius of 21 cm and central angle 135o. Find its perimeter?
|
[
"91.5 cm",
"23.9 cm",
"62.9 cm",
"27.8 cm",
"21.2 cm"
] |
Perimeter of the sector = length of the arc + 2(radius)
= (135/360 * 2 * 22/7 * 21) + 2(21)
= 49.5 + 42
= 91.5 cm
Answer:A
The answer is: A
|
A
|
mathematics
|
Train R leaves New York at 7:00 am traveling to Boston at 80mph. Train B leaves Boston at 7:45 am traveling to New York at 70 mph on a parallel track. If the distance between New York and Boston is 210 miles, at what time will the two trains pass each other?
|
[
"8:15 am",
"8:45 am",
"9:00 am",
"9:30 am",
"Cannot be determined from the information given"
] |
train R will cover 60 kms in 45 min at 7:45, the time when train B starts...
distance left to cover is 210-60=150..
combined speed=80+70=150..
so the trains meet in 1 hour i.e. 7:45 + 1 hr=8:45
B
The answer is: B
|
B
|
mathematics
|
If the selling price of 100 articles is equal to the cost price of 63 articles, then the loss or gain percent is:
|
[
"39%",
"36%",
"35%",
"40%",
"37%"
] |
Let C.P. of each article be Re. 1.
Then, C.P. of 100 articles = Rs. 100;
S.P. of 100 articles = Rs. 63.
Loss % = 37/100 * 100 = 37%
ANSWER:E
The answer is: E
|
E
|
mathematics
|
Find the area of the quadrilateral of one of its diagonals is 20 cm and its off sets 5 cm and 4 cm?
|
[
"189 cm2",
"150 cm2",
"127 cm2",
"177 cm2",
"90 cm2"
] |
1/2 * 20(5 + 4)
= 90 cm2
Answer: E
The answer is: E
|
E
|
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