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mathematics | A 240 meter long train crosses a man standing on the platform in 6 sec. What is the speed of the train? | [
"228",
"144",
"1266",
"188",
"211"
] | S = 240/6 * 18/5 = 144 kmph
Answer: B
The answer is: B | B |
mathematics | Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's weight. Dolly weighs 50% of Laila's weight. Laila weighs 19% of Jalal's weight. Who among these 5 persons weighs the least? | [
"Bahar",
"Dolly",
"Jalal",
"Laila",
"Meena"
] | Let Jalal weigh 100 kg.
Then Meena = 50 kg, Bahar = 83.33 kg, Laila = 19 kg, Dolly = 9.5 kg
Therefore clearly Dolly is the lightest.
ANSWER:B
The answer is: B | B |
mathematics | How many 4 digit numbers can be formed with the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 and 9? | [
"a. 220",
"b. 249",
"c. 432",
"d. 216",
"e. 288"
] | Taking Question with it's same language as given
To make number divisible by 5, the unit digit should be either 0 or 5 only
Case 1: If unit digit is fixed as zero
With two6s The choice to fill the remaining three digits = 3C2 x 5 = 15
With all remaining 3 digits different, The choice to fill the remaining three digits = 6 x 5 x 4= 120
Total Such cases = 120+15 = 135
Case 2: If unit digit is fixed as Five
With two6s and one0The choice to fill the remaining three digits = 2 [6605 or 6065]
With two6s and without0The choice to fill the remaining three digits = 3C2 x 4 = 12
With all remaining 3 digits different, and one0The choice to fill the remaining three digits = 2 (ways to place zero) x 5 x 4= 40
With all remaining 3 digits different, and without0The choice to fill the remaining three digits = 3 x 5 x 4= 60
Total Such cases = 2+12+40+60 = 114
Total numbers = 135+114 = 432
ANSWER OPTION E
The answer is: E | E |
mathematics | If x/y is an integer, which of the following must also be an integer?
I. xy
II. y/x
III. x | [
"I alone",
"II alone",
"III alone",
"I and III",
"None of the above"
] | Let's take X = 4/3 and Y = 2/3
Then X/Y = 2 which is an integer.
But XY = 4/3 * 2/3 = 8/9 --> Not an integer.
Y/X = 2/3 divided by 4/3 = 2/4 = 1/2 Not an integer.
X alone is 4/3. Not an integer.
Hence E.
None of the above.
The answer is: E | E |
mathematics | Country X imported approximately $1.44 billion of goods in 1996. If Country X imported $420 million of goods in the first two months of 1997 and continued to import goods at the same rate for the rest of the year, by how much would Country Xs 1997 imports exceed those of 1996? | [
"$214 million",
"$1120 million",
"$1144 million",
"$1240 million",
"$1080 million"
] | Convert units to millions as answer is in millions
1996 Imports = $1.44 bill = $1440 mill
i.e. 1440/12 = $120 mill/month
1997 Imports = $420 mill/2 month
i.e. $210 mill/month
Difference/month = 210-120 = 90
Difference/year = $90 mill * 12 = $1080 mill
ANSWER: E
The answer is: E | E |
mathematics | A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec. fast at 2 p.m. on the following Monday. When was it correct? | [
"2 p.m. on Tuesday",
"2 p.m. on Wednesday",
"3 p.m. on Thursday",
"1 p.m. on Friday",
"None of these"
] | Time from 12 p.m. on Monday to 2 p.m. on the following Monday = 7 days 2 hours = 170 hours.
∴ The watch gains (2 + 44⁄5) min.
or 34⁄5 min. in 170 hrs.
Now, 34⁄5 min. are gained in 170 hrs.
∴ 2 min. are gained in (170 × 5⁄34 × 2)hrs. = 50 hrs
∴ Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e. it will be correct at 2 p.m. on Wednesday.
Answer B
The answer is: B | B |
mathematics | What is the smallest five digit number that is divisible by 15, 24, 36, and 54? | [
"10320",
"10800",
"10030",
"10380",
"10460"
] | 15 = 3 * 5
24 = 2^3 * 3
36 = 2^2 * 3^2
54 = 2 * 3^3
LCM = 2^3 * 3^3 * 5 = 1080
The smallest five-digit number that is a multiple of 1080 is 10*1080 = 10,800
The answer is B.
The answer is: B | B |
mathematics | In how many different number of ways 4 boys and 3 girls can sit on a bench such that girls always sit together? | [
"720",
"740",
"760",
"790",
"800"
] | Option 'A'
The answer is: A | A |
mathematics | A dealer purchased an article at 3/4 of its list price and sold 50% more than the list price. Find his gain percent | [
"90%",
"40%",
"100%",
"75%",
"25%"
] | MP = 100
CP = 75
SP = 150
------
75 ---- 75
100 ---- ? => 100%
Answer: C
The answer is: C | C |
mathematics | Rose is two years older than Bruce who is twice as old as Chris. If the total of the age of Rose, B and Chris be 37 years, then how old is Chris ? | [
"7 years",
"10 years",
"12 years",
"13 years",
"14 years"
] | Let Chris's age be x years. Then, Bruce's age = 2x years.Rose's age = (2x + 2) years.
(2x + 2) + 2x + x = 37
5x = 35
x = 7
Hence, Chris's age =7 years.
Answer : A
The answer is: A | A |
mathematics | The banker's discount on Rs.1150 due a certain time hence is Rs.115. Find the true discount and the banker's gain. | [
"10",
"15",
"18",
"21",
"None"
] | Solution
Sum =B.D x T.D/ B.D - T.D
= B.D x T.D/ B.G
T.D / B. G =Sum / B.D
= 1650 / 165
= 10 / 1
If B.D is Rs. 11,T.D= Rs.10.
If B.D is Rs.165,
T.D = Rs.(10 / 11 x 165)
= Rs.150.
And, B.G = Rs(165 - 150)
= Rs.15.
Answer B
The answer is: B | B |
mathematics | A lady builds 12cm length, 16cm width, and 6cm height box using 3cubic cm cubes. What is the minimum number of cubes required to build the box? | [
"345",
"384",
"378",
"398",
"300"
] | Number of cubes required = Volume of box/Volume of cube
= 12*16*6/3
=384 cubes
ANSWER:B
The answer is: B | B |
mathematics | Richard has to paint a mural with seven horizontal stripes. He only has enough paint for four red stripes, four blue stripes, four white stripes. If his patron wants at most two different colors in the mural, how many different ways can he paint the wall? | [
"210",
"350",
"700",
"2,520",
"5,040"
] | Number of ways to choose 2 colors among 3 - 3c2
Number of ways that the chosen colors can be painted for 7 horizontal stripes - 2 (either (4,3) or (3,4))
Now the order,
the number of ways in which a particular color among the 2 chosen colors can be painted for 4 stripes is - 7c4
[Note: We don't need to calculate the ways for the remaining 3 stripes as they are obvious and already counted under this]
Total number of combinations - 3c2 * 2* 7c4 = 210
A
The answer is: A | A |
mathematics | The average (arithmetic mean) of 24, 35, and 58 is 6 more than the average of 19, 51, and x. What is x? | [
"26",
"27",
"28",
"29",
"30"
] | The average of 24, 35, and 58 is 39.
The average of 19, 51 and x is 33.
Then 19 + 51 + x = 99.
x = 29.
The answer is D.
The answer is: D | D |
mathematics | If three numbers are added in pairs, the sums equal 10,19 and 21. Find the numbers? | [
"5, 10, 15",
"6, 4, 15",
"2, 4, 8",
"15, 20, 25",
"None"
] | Sol.
Let the numbers be x, y and z.
Then, x + y = 10 ............(i) and
y + z = 19 ....................(II) and
x + z =21 ...............(III)
Adding (i),(ii) and (iii), we get : 2(x+y+z) = 50 or (x+y+z) = 25.
Thus, x = (25 - 19) = 6;
y = (25 - 21) = 4;
z = (25 - 10) = 15.
Hence, the required numbers are 6, 4 and 15.
Answer B
The answer is: B | B |
mathematics | How many 5's are there preceded by 2 but not followed by 6?
5 9 3 2 1 2 6 7 4 9 2 5 2 1 3 2 8 2 5 1 3 8 3 2 5 6 2 5 3 9 5 8 2 0 1 8 7 4 6 3 | [
"4",
"5",
"6",
"8",
"3"
] | 2 5 2
2 5 3
2 5 1
Only at these places 3 is preceded by 2 but not followed by 6
Answer: E
The answer is: E | E |
mathematics | In a sports club with 30 members, 16 play badminton and 19 play tennis and 2 do not play either. How many members play both badminton and tennis? | [
"7",
"8",
"9",
"10",
"11"
] | Let x play both badminton and tennis so 16-x play only badminton and 19-x play only tennis. 2 play none and there are total 30 students. hence,
(16-x)+(19-x)+x+2=30
37-2x+x=30
37-x=30
x=7
So 7 members play both badminton and tennis.
A
The answer is: A | A |
mathematics | For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum of all the integers between 100 and 200? | [
"4545",
"5050",
"6525",
"4352",
"4652"
] | sum = 100*101/2 = 50*101 = 5050
Answer is B
The answer is: B | B |
mathematics | 3/4 of a number is 19 less than the original number. The number is ? | [
"84",
"64",
"76",
"72",
"None"
] | Answer
Let the original number be N.
So from question N - 3N/4 = 19
⇒ 4N - 3N = 76
∴ N = 76
Option: C
The answer is: C | C |
mathematics | A dishonest dealer professes to sell goods at the cost price but uses a weight of 880 grams per kg, what is his percent? | [
"2%",
"25%",
"22%",
"13.63%",
"45%"
] | 880 --- 120
100 --- ? => 13.63%
Answer:D
The answer is: D | D |
mathematics | On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004? | [
"Tuesday",
"Monday",
"Sunday",
"Wednesday",
"Friday"
] | The year 2004 is a leap year. It has 2 odd days.
The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.
Hence, this day is Sunday.
Answer: Option C
The answer is: C | C |
mathematics | A work which could be finished in 9 days was finished 3 days earlier after 10 more men joined. The number of men employed was? | [
"24",
"27",
"20",
"35",
"25"
] | C
20
x ------- 9
(x + 10) ---- 6
x * 9 = (x + 10)6
x = 20
The answer is: C | C |
mathematics | In certain year in Country C, x sets of twins and y sets of triplets were born. If there were z total babies born in Country C in this year, and x and y were both greater than 0, which of the following represents the fraction Q of all babies born who were NOT part of a set of twins or triplets? | [
"z - 2x - 3y",
"(2x+3y)/z",
"(x+y)/z",
"1 - (2x+3y)/z",
"1 - (x+y)/z"
] | X set of twins implies 2x babies of twin category.
Y set of triplets means 3y babies of triplet category.
Let K be the babies other than twin or triplet category.
Total babies = z = 2x+3y+k.
or K=Z-(2x+3y)
=> Fraction of babies other than twin or triplet categories = K/Z = Z-(2x+3y)/Z.
Q= 1- (2x+3y)/Z. Hence answer is D.
The answer is: D | D |
mathematics | The average wages of a worker during a fortnight comprising 15 consecutive working days was $90 per day. During the first 7 days, his average wages was $87 per day and the average wages during the last 7 days was $94 per day. What was his wage on the 8th day? | [
"$83",
"$90",
"$92",
"$97",
"$104"
] | Average daily wage of a worker for 15 consecutive working days = 90$
During the first 7 days , the daily average daily wage = 87$
During the last 7 days , the daily average daily wage = 94$
Wage on 8th day = 90*15 -( 87*7 + 94 *7)
= 1350 - (609 + 658)
=1350 - 1267
= 83
Answer A
The answer is: A | A |
mathematics | Take number 1000 and then add 20 to it. Now add 1000 one more time. Now add 30. Now add 1000 one more time. Now add 40. Now add 1000 one more time. Now add 10. What is the total? | [
"4100",
"3590",
"2800",
"3700",
"3600"
] | A
4100
The answer is: A | A |
mathematics | A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race? | [
"111.12",
"111.18",
"131.12",
"211.12",
"111.17"
] | A runs 1000 m while B runs 900 m and C runs 800 m.
The number of meters that C runs when B runs 1000 m,
= (1000 * 800)/900 = 8000/9 = 888.88 m.
B can give C = 1000 - 888.88 = 111.12 m.
Answer:A
The answer is: A | A |
mathematics | Select Odd number:
6, 9, 15, 21, 24, 28, 30 | [
"20",
"21",
"24",
"28",
"30"
] | Each of the numbers except 28, is a multiple of 3.
answer D
The answer is: D | D |
mathematics | A truck owner will refuel his vehicle at a rate of 2 gallons of diesel fuel every 5 seconds. If diesel fuel costs $ 2 per gallon, how long will it take for the truck owner to refuel his vehicle with $ 50 worth of diesel fuel? | [
"50 seconds",
"1 minute",
"1 minute 20 seconds",
"20 minutes",
"1 hour 20 minutes"
] | 2 gal / 5 sec
$2 / gal
$40/$2 = 20 gal
2 gal / 5 sec with 20 gal = 50 sec
A. 50 seconds
The answer is: A | A |
mathematics | 9. On level farmland, two runners leave at the same time from the intersection of two country roads. One runner jogs due north at a constant rate of 6 miles per hour while the second runner jogs due east at a constant rate that is 2 miles per hour faster than the first runner's rate. How far apart, to the nearest mile, will they be after 1/2 hour ? | [
"6",
"7",
"5",
"12",
"14"
] | If runner 1 is going north and runner 2 is going east they are like two sides of a 90 degree triangle.
Side 1 = 6 m/h --> 3 m in 1/2 hr
Side 2 = 8 m/h --> 4 m in 1/2 hr
to complete this right angle triangle
d^2 = 4^2 + 3^2
d^2 = 25
= 5
Answer option C
The answer is: C | C |
mathematics | A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is? | [
"22",
"50",
"888",
"277",
"21"
] | Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 => x = 50 km/hr.
Answer: B
The answer is: B | B |
mathematics | In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 172 votes. Find the total number of valid votes? | [
"430",
"437",
"435",
"431",
"433"
] | Let the total number of valid votes be x.
70% of x = 70/100 * x = 7x/10
Number of votes secured by the other candidate = x - 7x/100 = 3x/10
Given, 7x/10 - 3x/10 = 172 => 4x/10 = 172
=> 4x = 1720 => x = 430.
Answer: A
The answer is: A | A |
mathematics | A tailor trims 6 feet from opposite edges of a square piece of cloth, and 5 feet from the other two edges. If 120 square feet of cloth remain, what was the length of a side of the original piece of cloth? | [
"20",
"22",
"24",
"26",
"28"
] | Let the original side of the square be x.
(x-12)*(x-10) = 120 = 10*12
x = 22
The answer is B.
The answer is: B | B |
mathematics | When processing flower-nectar into honey bees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 35% water? | [
"1.3 kg",
"1.5 kg",
"1.7 kg",
"1.9 kg",
"None of these"
] | Explanation :
Flower-nectar contains 50% of non-water part.
In honey this non-water part constitutes 65% (100-35).
Therefore 0.5 X Amount of flower-nectar = 0.65 X Amount of honey = 0.65 X 1 kg
Therefore amount of flower-nectar needed =
(0.65/0.51)kg=1.3 kgs
Answer : A
The answer is: A | A |
mathematics | In how many years, Rs. 200 will produce the same interest @ 5 % as Rs. 900 produce in 2 years @ 3 ½ %? | [
"6.3 years",
"8.2 years",
"9 years",
"12 years",
"None of these"
] | Explanation:
P = Rs 900, R = 3 ½ % = 7/2 %, T = 2 years.
Therefore,
S.I. = PRT/100
S.I. = Rs. (900 x 7/2 x 2/100) = Rs. 63
Now, P = Rs. 200, S.I. = Rs. 63, R = 5 %
Time = ((100 x 63) / (200 x 5) ) years = 6.3 years
ANSWER A
The answer is: A | A |
mathematics | What is the 11th term in this sequence?
1,4,5,11,18,29,49,80,129,211, | [
"352",
"442",
"345",
"342",
"362"
] | 1+4 =5 +0 =5
5+4 =9+2 =11
11+5 =16+2 =18
18+11=29+0 =29
29+18=47+2 =49
49+29=78+2 =80
80+49=129+0=129
129+80=209+2=211
211+129=340+2=342
so 11th term is 342
ANSWER:D
The answer is: D | D |
mathematics | A factory producing tennis balls stores them in either big boxes, 25 balls per box, or small boxes, with 17 balls per box. If 94 freshly manufactured balls are to be stored, what is the least number of balls that can be left unboxed? | [
"0",
"1",
"2",
"3",
"4"
] | There is no way to store 94 balls without leftovers: 94−0∗25=94- 94−2∗25=44 ,94−3∗25=19 are not divisible by 17
.93 balls can be stored successfully: 93−1∗25=68 is divisible by 17. Thus, 93=1∗25+4∗17 and we need 1 big box and 4 small boxes.
Answer: B
The answer is: B | B |
mathematics | The music class consists of 4 girls and 7 boys. How many ways can a group of 3 be formed if it has to include at least one boy? | [
"155",
"158",
"161",
"165",
"172"
] | Classic combination problem
At least 1 boy = Total - all girls
All girls = C(4,3) = 4
Total combination = C(11,3) = 165
Ans = 165-4 = 161
ANS:C
The answer is: C | C |
mathematics | A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes.How long will it take to go 5 km in stationary water ? | [
"40 minutes",
"1 hour",
"1 hr 15 min",
"1 hr 20 min",
"None of these"
] | Solution
Rate downstream =(1/10x60) km/hr = 6 km/hr, Rate upstream = 2 km/hr.
Speed in still water =1/2(6 + 2) km/hr = 4 km/hr.
∴ Required time =(5/4)hrs = 1 1/4hrs = 1 hr 15 min. Answer C
The answer is: C | C |
mathematics | City X has a population 5 times as great as the population of City Y, which has a population twice as great as the population of City Z. What is the ratio of the population of City X to the population of City Z? | [
"1:8",
"1:4",
"2:1",
"4:1",
"10:1"
] | x= 5y, y= 2*z
X : Y , Y : Z
5 : 1 , 2 : 1
10 : 2 , 2 : 1
So, X : Z = 10 : 1
(E)
The answer is: E | E |
mathematics | A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is | [
"100",
"120",
"130",
"150",
"140"
] | Let the length of the train be x meters and its speed be y m/sec.
They, x / y = 15 => y = x/15
x + 100 / 25 = x / 15
x = 150 m.
Answer: Option D
The answer is: D | D |
mathematics | A snooker tournament charges $40.00 for VIP seats and $15.00 for general admission (“regular” seats). On a certain night, a total of 320 tickets were sold, for a total cost of $7,500. How many fewer tickets were sold that night for VIP seats than for general admission seats? | [
"212",
"200",
"220",
"230",
"240"
] | let no of sits in vip enclosure is x then x*40 +15( 320-x) =7500 or 25x = 7500 -4800 , x = 2700/25 =108
vip =108 general 212
A
The answer is: A | A |
mathematics | A person spends 40% of his salary on food, 25% on house rent, 15% on entertainment and 5% on conveyance. If his savings at the end of the month is Rs. 1500, then his salary per month in rupees is: | [
"4000",
"6000",
"8000",
"10000",
"None of these"
] | Total expenditure = 40 + 25 + 15 + 5 = 85%
Saving = (100 - 85) = 15%
15/100 × Salary = 1500, Salary = 10000 Rs.
Answer:D
The answer is: D | D |
mathematics | An article is bought for Rs.675 and sold for Rs.775, find the gain percent? | [
"73%",
"14.8%",
"33 1/3%",
"93 1/3%",
"33 1/3%"
] | Explanation:
675 ---- 100
100 ---- ? => 14.8%
Answer:B
The answer is: B | B |
mathematics | Ravi and sunil are partners in a business. Ravi invests Rs.15,000 for 8 months and Sunil invested Rs.8000 for 10 months then after one year ratio of their profits will be | [
"1:3",
"2:3",
"3:2",
"3:1",
"3:4"
] | =(15000*8):(8000*10)
=120000:80000
=3:2
ANSWER:C
The answer is: C | C |
mathematics | In a race where 10 cars are running, the chance that car X will win is 1/7, that Y will win is 1/3 and that Z will win is 1/5. Assuming that a dead heat is impossible, find the chance that one of them will win. | [
"1/140",
"1/180",
"71/105",
"21/113",
"57/120"
] | Required probability = P(X) + P(Y) + P(Z) (all the events are mutually exclusive).
= 1/7 + 1/3 + 1/5
= 71/105
ANSWER:C
The answer is: C | C |
mathematics | You forgot the three digit code of your safe. But you have written some hints to calculate the code if you forgot the code.
Below are the hints that you have written
Hint-1 : One of the numbers is correct and is placed in its correct position
5 4 7
Hint-2: Nothing is correct
5 3 0
Hint-3: Two numbers are correct but not placed at its correct position.
2 5 9
Hint-4: One number is correct but not placed at its correct position.
7 0 6
Hint-5: One number is correct but not placed at its correct position.
6 4 9
What's is the code. | [
"827",
"728",
"923",
"323",
"927"
] | E
927
1) 5 4 7 : 7 is placed correctly
2) 5 3 0 : None of the numbers is in the code
3) 2 5 9 : 2 & 9 are correct number of code but placed at wrong position
4) 7 0 6: Number 7 is there but placed at wrong position
5) 6 4 9: Number 9 is there but placed at wrong position
The answer is: E | E |
mathematics | The average of 11 numbers is 12.8. If the average of the first six numbers is 12.4 and that of the last six numbers is 12.2,then the middle number is? | [
"7.8",
"7.9",
"7.1",
"7.2",
"6.8"
] | Middle number = 12.4*6 + 12.2*6 - 12.8*11 = 147.6-140.8=6.8
Answer is E
The answer is: E | E |
mathematics | The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 30 runs. Find his average in all the 30 matches? | [
"31",
"36.67",
"88",
"13",
"12"
] | Total score of the batsman in 20 matches = 800.
Total score of the batsman in the next 10 matches = 300.
Total score of the batsman in the 30 matches = 1100.
Average score of the batsman = 1100/30 = 36.67.
Answer:B
The answer is: B | B |
mathematics | If two positive numbers are in the ratio 1/8 : 1/5, then by what percent is the second number more than the first? | [
"40%",
"33 1/3%",
"60%",
"66 2/3%",
"None of these"
] | Given ratio = 1/8 : 1/5 = 5 : 8
Let first number be 5x and the second number be 8x.
The second number is more than first number by 3x.
Required percentage = 3x/5x * 100 = 60%.
ANSWER:C
The answer is: C | C |
mathematics | 7 + 7+ 7 + 7 × 7^2 + 7 × 7^3 + 7 × 7^4 + 7 × 7^5 + 7 × 7^6 + 7 × 7^7 = | [
"7^3",
"7^8",
"7^2",
"7^7",
"7^11"
] | We have the sum of 9 terms. Now, if all terms were equal to the largest term 7*7^7 we would have: sum=9*(7*7^7)=63*7^7=~7^9, so the actual sum is less than 7^9 and more than 7^7 (option D) as the last term is already more than that. So the answer is clearly B.
Answer: B
The answer is: B | B |
mathematics | A man buys an article and sells it at a profit of 20%. If he had bought it at 20% less and sold it for Rs.75 less, he could have gained 25%. What is the cost price? | [
"288",
"375",
"267",
"298",
"121"
] | CP1 = 100 SP1 = 120
CP2 = 80 SP2 = 80 * (125/100) = 100
20 ----- 100
75 ----- ? => 375
Answer: B
The answer is: B | B |
mathematics | The ratio of the area of a square to that of the square drawn on its diagonal is? | [
"4/16",
"4/13",
"4/11",
"4/19",
"4/12"
] | P(SᴜK)
= P(S) + P(K) - P(S∩K), where S denotes spade and K denotes king.
P(SᴜK)
= 13/52 + 4/52 - 1/52
= 4/13
Answer:B
The answer is: B | B |
mathematics | Two cars, Car1 and Car2 move towards each other from Q and Y respectively with respective speeds of 20 m/s and 15 m/s. After meeting each other Car1 reaches Y in 10 seconds. In how many seconds does Car 2 reach Q starting from Y? | [
"15.5 sec",
"8.4 sec",
"33.6 sec",
"31.11 sec",
"16.8 sec"
] | Q--------------------------------------|----------------------------Y
Car A(20mps)------------------------->P<---------------Car B(15mps)
Let 2 cars meet each other at point P in t seconds.
Car1 covers distance= 20t. Car2 covers distance=15t. So, total distance QY= 35t.
From P, Car 1 reaches onto Y in 10 secs. So it covers 15t further.
so, 15t/20 = 10
So t=40/3 sec and total distance = (35*40)/3
Hence Car2 will cover total distance in (35*40)/(3*15) = 31.11 sec approx.
Answer D
The answer is: D | D |
mathematics | 108. Triangle A’s base is 20% greater than the base of triangle B, and A’s height is 20% less than the height of triangle B. The area of triangle A is what percent less or more than the area of triangle B? | [
"0.25 % less",
"1 % less",
"Equal to each other",
"1 % more",
"9 % more"
] | Wish the question specified that we are talking about corresponding height.
Base of A = 21/20 * Base of B
Height of A = 19/20 * Height of B
Area of A = (1/2) * Base of A * Height of A = 21/20 * 19/20 * Area of B = 399/400 * Area of B
Area of A is 0.25% less than the area of B.
Answer (A)
The answer is: A | A |
mathematics | The speed of a boat in upstream is 50 kmph and the speed of the boat downstream is 60 kmph. Find the speed of the boat in still water and the speed of the stream? | [
"5 kmph",
"4 kmph",
"9 kmph",
"8 kmph",
"6 kmph"
] | Speed of the boat in still water = (50+60)/2 = 55 kmph. Speed of the stream
= (60-50)/2
= 5 kmph.
Answer:A
The answer is: A | A |
mathematics | Of the goose eggs laid at a certain pond, 1/3 hatched and 4/5 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 120 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond? | [
"1025",
"1075",
"1125",
"1175",
"1225"
] | Let x be the number of eggs that were laid.
(2/5)(4/5)(1/3)x = 120
(8/75)x = 120
x = 1125
The answer is C.
The answer is: C | C |
mathematics | 50 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is 4 m3, then the rise in the water level in the tank will be: | [
"20 cm",
"23 cm",
"25 cm",
"30 cm",
"32 cm"
] | L*b*h=Total water displaced=200(given)
To find height i.e rise in the water level
h=200/L*B
H=25cm
answer :C
The answer is: C | C |
mathematics | A meal cost $ 35.50 and there was no tax. If the tip was more than 10 pc but less than 15pc of the price, then the total amount paid should be: | [
"40-42",
"39-41",
"38-40",
"37-39",
"36-37"
] | 10%(35.5) = 3.55
15%(35.5) = 5.325
total amount could have been 35.5+3.55 and 35.5+5.325
=> could have been between 39.05 and 40.625
=> approximately between 39 and 41
Answer is B.
The answer is: B | B |
mathematics | A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's age is | [
"23 years",
"34 years",
"45 years",
"54 years",
"None of these"
] | Explanation:
Let x and y be the ten's and unit's digits respectively of the numeral denoting the woman's age.
Then, woman's age = (10X + y) years; husband's age = (10y + x) years.
Therefore (10y + x)- (10X + y) = (1/11) (10y + x + 10x + y)
(9y-9x) = (1/11)(11y + 11x) = (x + y) 10x = 8y x = (4/5)y
Clearly, y should be a single-digit multiple of 5, which is 5.
So, x = 4, y = 5.
Hence, woman's age = 10x + y = 45 years.
Answer: C
The answer is: C | C |
mathematics | If a man lost 4% by selling oranges at the rate of 24 a rupee at how many a rupee must he sell them to gain 44%? | [
"16",
"8",
"9",
"4",
"3"
] | 96% ---- 24
144% ---- ?
96/144 * 24 = 16
Answer: A
The answer is: A | A |
mathematics | The average salary/head of all the workers in a workshop is Rs.1100, if the average salary/head of 9 technician is Rs.1300 and the average salary/head of the rest is Rs.880, the total no. of workers in the work-shop is ? | [
"18",
"20",
"22",
"17",
"26"
] | Let the total number of workers be y.
So sum of salary for all workers = sum of salary of 9 technician + sum of salary for other y -9 workers.
9 x 1300 + 880(y -9) = 1100 y
⇒ 11700 + 880y - 7920 = 1100y
⇒ 220y = 3780
∴ y = 17 So total number of workers = 17 D
The answer is: D | D |
mathematics | A certain sum of money at simple interest amounted Rs.840 in 10 years at 3% per annum, find the sum? | [
"277",
"262",
"298",
"646",
"267"
] | 840 = P [1 + (10*3)/100]
P = 646
Answer: D
The answer is: D | D |
mathematics | Given distinct positive integers 1, 12, 3, x, 2, and 9, which of the following could be the median? | [
"1",
"3",
"6",
"8",
"9"
] | The median of a set with even number of terms is the average of two middle terms when arranged in ascending (or descending) order.
Arrange numbers in ascending order: 1, 2, 3, 9, 11, and x.
Now, x can not possibly be less than 3 as given that all integers are positive and distinct (and we already have 1, 2, and 3).
Next, if x is 3<x<9 then the median will be the average of 3 and x. As all answers for the median are integers, then try odd values for x:
If x=5, then median=(3+5)/2=4 --> not among answer choices;
If x=7, then median=(3+7)/2=5 --> not among answer choices;;
If x is more than 9 so 10 or more then the median will be the average of 3 and 9 so (3+9)/2=6 (the maximum median possible).
Answer: C
The answer is: C | C |
mathematics | If a positive integer n is divisible by both 3 and 5, then n must also be divisible by which of the following?
I. 15
II. 8
III. 45 | [
"None",
"I only",
"II only",
"I and II",
"II and III"
] | A multiple of 3 and 5 is also a multiple of 15, but not necessarily a multiple of 8 or 45.
The answer is B.
The answer is: B | B |
mathematics | The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle? | [
"432 sq m",
"356 sq m",
"452 sq m",
"428 sq m",
"528 sq m"
] | 2(3x + x) = 96
l = 36 b = 12
lb = 36 * 12 = 432
ANSWER:A
The answer is: A | A |
mathematics | A man sells a horse for Rs.800 and loses something, if he had sold it for Rs.980, his gain would have been double the former loss. Find the cost price of the horse? | [
"337",
"278",
"288",
"860",
"721"
] | CP = SP + 1CP = SP - g
800 + x = 980 - 2x
3x = 180 => x = 60
CP = 800 + 60 = 860
Answer: D
The answer is: D | D |
mathematics | In a friendship gang Andrew has 8 gang, in how many ways can he invite one or more of the gang to his house? | [
"243",
"255",
"256",
"287",
"300"
] | Andrew can select one or more than one of his 8 gang.
=> Required number of ways = 28 – 1= 255.
B
The answer is: B | B |
mathematics | A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are drawn at random, what is the probability that at least one is green? | [
"23/35",
"23/37",
"23/39",
"23/32",
"23/31"
] | Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green
= (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7
= 46/70 = 23/35
Answer: A
The answer is: A | A |
mathematics | The expression rs+r is odd when the r and s are integers. Which of the following expressions must be even? | [
"r",
"s",
"r + s",
"rs - r",
"r + s^2"
] | rs+r is odd
r and s are integers
If r were even rs+r would be even despite any value of s.
s can't be odd, so s must be even.
Ans : B
The answer is: B | B |
mathematics | John is three times as old as Sam. If John will be twice as old as Sam in five years, how old was Sam two years ago? | [
"2",
"4",
"6",
"3",
"16"
] | j= 3s
after 5 years
j +5 = 2(s+5)
j= 2s+5
2s +5 = 3s
s= 5
two years ago
s= 5-2= 3
D is the answer
The answer is: D | D |
mathematics | Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? | [
"17.9 sec",
"11.8 sec",
"27.7 sec",
"10.8 sec",
"17.8 sec"
] | Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 160 = 300 m.
Required time = 300 * 9/250 = 54/5 = 10.8 sec.
Answer: D
The answer is: D | D |
mathematics | A alone can finish a work in 10 days which B alone can finish in 15 days. If they work together and finish it, then out of a total wages of Rs.3400, A will get: | [
"Rs.1200",
"Rs.1500",
"Rs. 2040",
"Rs.2000",
"None of these"
] | Explanation:
Ratio of working days of A : B = 10 : 15
Therefore, their wages ratio = reverse ratio = 15 : 10
Therefore, A will get 15 units of ratio
Total ratio = 25
1 unit of ratio =3000/25 = 136
So, A’s amount = 120 × 15 = Rs.2040.
Answer: Option C
The answer is: C | C |
mathematics | What is the value of 27^2 + 28^2 + 29^2 + 30^2 + 31^2 + 32^2 + 33^2 ? | [
"6298",
"6308",
"6318",
"6328",
"6338"
] | the method would seem to be lengthy as it is being explained but is very short actually
second would be to take advantage of proximity to 30 and a set of two numbers giving us 60 as sum..
(27^2 + 33^2) + (29^2 + 31^2) + (32^2 + 28^2)+ 30^2
(60^2-2*27*33) +(60^2-2*29*31)+ (60^2-2*28*32)+ 30^2
3*60^2+30^2-2(27*33+29*31+28*32)
3*60^2+30^2-2((30-3)*(30+3)+(30-1)*(30+1)+(30-2)*(30+2))
3*60^2+30^2-2((30^2-3^2)+(30^2-1^2)+(30^2-2^2))
3*60^2+30^2-6(30^2)+2(3^2+1^2+2^2)
we are interested only in terms where square of multiple of 10 is not involved..
2(9+1+4)=28 so the answer should be something*100+28....this gives us the answer as 6328
ANSWER:D
The answer is: D | D |
mathematics | A motorist travel to a place 150 km away at an average speed of 90 km/hr and returns at 30 km/hr.His average speed for the whole journey in km/hr is | [
"36km/hr",
"37 km/hr",
"35 km/hr",
"45 km/hr",
"None of these"
] | Explanation:
Average speed will be
2xy/x+y km/hr
= {2(90)(30)}/{90+30} km/hr
= 45 km/hr
Answer: Option D
The answer is: D | D |
mathematics | There is food for 760 men for 22 days. How many more men should join after two days so that the same food may last for 19 days more? | [
"38",
"40",
"83",
"87",
"81"
] | 760 ---- 22
760 ---- 20
x ----- 19
x*19 = 760*20
x = 800
760
-------
40
Answer: B
The answer is: B | B |
mathematics | If the circus were to sell all of its 220 tickets for this month's performance at its usual price, the revenue from sales would be 10% greater than that collected last month. If the circus raised the ticket price by 7% and sold only 200 tickets as a result, what percent less would last month's revenue be compared to this month's revenue? | [
"2",
"5",
"700/107",
"110/20",
"9/4"
] | Let price be 10/ticket
then 220 tickets for this month's performance at its usual price=2200
which is 10%greater than last month(let X)---->x(1+10/100)=2200----->x=2000
now new revenue this month=200*10.7=2140
as per question asked 2000=2140(1-A/100)----->A=700/107%
Ans C
The answer is: C | C |
mathematics | In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit? | [
"30%",
"70%",
"100%",
"120%",
"None"
] | Solution
Let C.P. = Rs. 100. Then, Profit = Rs.320,
S.P. = 420.
Let C.P. = Rs. 125% of Rs. 100 = Rs.125.
New S.P. = Rs.420.
Profit = Rs. (420 - 125) = Rs.295.
∴ Required percentage = (295 / 420 x 100)%
= 1475 / 21%
= 70%.
Answer B
The answer is: B | B |
mathematics | The sale price of an article including the sales tax is Rs. 616. The rate of sales tax is 10%. If the shopkeeper has made a profit of 12%, then the cost price of the article is: | [
"500",
"277",
"222",
"297",
"111"
] | Explanation:
110% of S.P. = 616
S.P. = (616 * 100)/110 = Rs. 560
C.P = (110 * 560)/112 = Rs. 500
Answer:A
The answer is: A | A |
mathematics | Seven children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Child A has to sit next to both B & G, with these two children immediately adjacent to Child A on either side. The other four children can sit in any order in any of the remaining seats. How many possible configurations are there for the children? | [
"240",
"480",
"720",
"1440",
"3600"
] | First we can imagine the trio ABG as one item to arrange along with four other items: C , D, E, F.
This can be done in 5! = 120 ways
However the trio can be arranged in 2 ways: BAG or GAB.
So, total number of ways to sit the seven children is equal to 2*120 = 240 (option A)
The answer is: A | A |
mathematics | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform? | [
"288",
"350",
"889",
"276",
"234"
] | Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.
Answer:B
The answer is: B | B |
mathematics | (128.5 x 25) + (13.8 x 50) = ? x 50 | [
"78.05",
"556.02",
"574.36",
"585.64",
"595.46"
] | Explanation :
? = (128.5 x 25) + (13.8 x 50)/50
= 3212.5 + 690/50 = 78.05
Answer : Option A
The answer is: A | A |
mathematics | Replace X with the appropriate number in
4 , 5 , 14 , 15 , 24 , 25 , X | [
"30",
"29",
"34",
"21",
"20"
] | C
list of consecutive numbers that has an 'f' in the spelling
The answer is: C | C |
mathematics | A train running at the speed of 54 km/hr crosses a pole in 9 sec. What is the length of the train? | [
"135 m",
"786 m",
"566 m",
"546 m",
"445 m"
] | Speed = 54 * 5/18 = 15 m/sec
Length of the train = speed * time = 15 * 9
= 135 m
Answer: A
The answer is: A | A |
mathematics | A fair coin is tossed 3 times. What is the probability of getting at least 2 heads? | [
"3/4",
"3/2",
"1/4",
"1/2",
"1/5"
] | Let's find the probability of 2 heads , 3 heads
P(HHH)=((1/2)^3=1/8.
P(HHT)=(3!/2!)*(1/2)^3=3/8
Total Probablity = 1/8 + 3/8
=1/2
Answer(D)
The answer is: D | D |
mathematics | What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit? | [
"12 %",
"16 %",
"18 %",
"20 %",
"22 %"
] | Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such number =14
Required % = (14/70)x100 % =20 %
answer : D
The answer is: D | D |
mathematics | In a sports club with 40 members, 20 play badminton and 18 play tennis and 5 do not play either. How many members play both badminton and tennis? | [
"3",
"5",
"6",
"7",
"3"
] | 20+18=38
but where as total number is 40-5=35
therefore answer is 38-35=3
Hence Answer is E
The answer is: E | E |
mathematics | A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that all the four bulbs are defective. | [
"1/127",
"1/191",
"1/138",
"1/132",
"1/126"
] | Out of nine, five are good and four are defective. Required probability
= ⁴C₄/⁹C₄ = 1/126
Answer: E
The answer is: E | E |
mathematics | The tax on a commodity is diminished by 20% and its consumption increased by 15%. The effect on revenue is? | [
"6%",
"8%",
"9%",
"2%",
"1%"
] | 100 * 100 = 10000
80 * 115 = 9200
-----------
10000-----------800
100-----------? => 8% decrease
Answer: B
The answer is: B | B |
mathematics | up to 20,how many no. are odd and prime both? | [
"9",
"5",
"6",
"7",
"8"
] | we have to calculate it manually.
odd 1,3,5,7,9,11,13,15,17,19
prime 2,3,5,7,11,13,17,19
common 3,5,7,11,13,17,19
total no. 7
answer D
The answer is: D | D |
mathematics | A child must place 2 different toys in 4 different bins. If any of the toys can go in any of the bins, in how many ways can the child place the toys into the bins? | [
"6^6",
"6^4",
"4^6",
"4^4",
"4^2"
] | there are 4 different bins and each of the toy can go to any of these bins..
so answer 4∗4=4^2
ANSWER:E
The answer is: E | E |
mathematics | 1398 x 1398 | [
"1954404",
"1981709",
"18362619",
"2031719",
"None of these"
] | 1398 x 1398 = (1398)2
= (1400 - 2)2
= (1400)2 + (2)2 - (2 x 1400 x 2)
= 1954404.
Answer: Option A
The answer is: A | A |
mathematics | Arun, Kamal and Vinay invested Rs. 8000, Rs. 4000 and Rs. 8000 respectively in a business. Arun left after six months. If after eight months, there was a gain of Rs. 4005, then what will be the share of Kamal? | [
"Rs 870",
"Rs 880",
"Rs 890",
"Rs 900",
"None of these"
] | Explanation:
Arun : Kamal : Vinay = (8,000 x 6) : (4,000 x 8) : (8,000 x 8)
= 48 : 32 : 64
= 3 : 2 : 4
Kamal's share=4005∗2/9=Rs890
Option C
The answer is: C | C |
mathematics | In an exam, students need to answer 120 multiple choice questions. If the question paper is divided into 10 sections, how many questions are there in a section? | [
"6",
"12",
"10",
"4",
"50"
] | 120 questions divided into 10 sections means each section containing 120/10=12 questions. Answer B.
The answer is: B | B |
mathematics | Jerry’s average (arithmetic mean) score on the first 3 of 4 tests is 85. If Jerry wants to raise his average by 3 points, what score must he earn on the fourth test? | [
"97",
"89",
"90",
"93",
"95"
] | Total score on 3 tests = 85*3 = 255
Jerry wants the average to be = 88
Hence total score on 4 tests should be = 88*4 = 352
Score required on the fourth test = 352 - 255 = 97
Option A
The answer is: A | A |
mathematics | The area of the maximum size of the circle described from the 10 inch square? | [
"75.5 sq inch",
"76.5 sq inch",
"77.5 sq inch",
"78.5 sq inch",
"79.5 sq inch"
] | 10 inch square means sides of sq are 10inch
then circle is within square so diameter would be 10 inch maximum and radius is 5inch
so area of the circle is = pi*r*r=3.14*5*5=78.5 sq inch
ANSWER:D
The answer is: D | D |
mathematics | The cost of water in the area where the Jones family lives is scheduled to increase by 35% next year. Since the Jones family cannot afford an increase in their water bill, how much will they have to reduce consumption to keep their cost the same? | [
"None",
"25.9%",
"10.2%",
"45%",
"15.5%"
] | Solution: Let the current water expense be represented by Rs. 100.
The cost of water rises 35%. So, to buy same amount of water, they need to increase their expense,
= (100 + 35% of 100) = Rs. 135.
But, they want to keep water expense the same, so they have to cut Rs. by 35 to keep it to Rs. =100.
The % decrease in consumption is,
(35/135)*100 = 25.9%.
Mental Calculation Method;
100-----35%↑---→135------X%↓---→100.
Here, X = (35/135)*100 = 25.9%.
Answer: Option B
The answer is: B | B |
mathematics | If r and s are positive integers and r-s=6, which of the following has the greatest value T? | [
"2r",
"2s",
"r +s",
"2r-s",
"2s-r"
] | The simplest way to do this is to assume values.
We are told that r and s are positive integers T.
Also, r-s = 6 => r = 6+s
Hence r is 6 more than s.
Let s be 10. Hence r = 16.
Option A: 2r = 2*16 = 32
Option B: 2s = 2 * 10 = 20
Option C: r + s = 16 + 10 = 26
Option D: 2r - s = 2(16) - 10 = 32 - 10 = 22
Option E: 2s - r = 2(10) - 16 = 20 - 16 = 4
Hence option A is the greatest.
The answer is: A | A |
mathematics | In the manufacture of a certain product, 8 percent of the units produced are defective and 4 percent of the defective units are shipped for sale. What percent of the units produced are defective units that are shipped for sale? | [
"0.125%",
"0.32%",
"0.8%",
"1.25%",
"2.0%"
] | Percent of defective produced = 8%
Percent of the defective units that are shipped for sale = 4%
Percent of units produced are defective units that are shipped for sale = (4/100)*(8/100)*100%
= (32/10000)*100%
= (32/100)%
= .32 %
Answer B
The answer is: B | B |
mathematics | A departmental store has 6 managers and 36 associates. The 6 managers have an average salary of $700. The 36 associates have an average salary of $1500. What is the average salary for the departmental store? | [
"$1400",
"$1385.71",
"$1500.25",
"$1466.58",
"$1650.56"
] | Number of managers is 6
Their average salary is $700
Number of associates is 36
Their average salary is $1500
Total salary of managers is 6*700=$4200
Total salary of associates is 36*1500=$54,000
Total salary for the departmental store is 54000+4200=58200
Average salary for the departmental store is 58200/6+36=1385.71
Answer is B
The answer is: B | B |
mathematics | In a camp,there is a meal for 120 men or 200 children.If 120 children have taken the meal,how many men will be catered to with the remaining meal ? | [
"20",
"30",
"40",
"48",
"60"
] | Solution
There is a metal for 200 children. 120 children have taken the meal.
Remaining meal is to be catered to 80 children.
Now, 200 children = 120 men
80 children =( 120/200x80)men= 48 men. Answer D
The answer is: D | D |