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|---|---|---|---|---|
mathematics
|
A dishonest dealer uses a scale of 97 cm instead of a metre scale and claims to sell at cost price. His profit is
|
[
"9%",
"10%",
"12%",
"3.1%",
"Cannot be determined"
] |
Solution
Gain% = (3 / 97 x 100)%
= 3.1%
Answer D
The answer is: D
|
D
|
mathematics
|
If 60 men can do a piece of work in 25 hours, in how many hours will 15 men
do it ?
|
[
"100 hours",
"90 hours",
"80 hours",
"70 hours",
"60 hours"
] |
Let the required number of hours be x. Then,
Less men, More hours (Indirect Proportion)
15 : 60 : : 25 : x<=>(15 x x) =(60 x 25)<=>(60 x 25)/15 = 100
Hence, 15 men can do it in 60 hours
Answer is A.
The answer is: A
|
A
|
mathematics
|
200 liters of a mixture contains milk and water in the ratio 4:1. If 20 liters of this mixture be replaced by 20 liters of milk, the ratio of milk to water in the new mixture would be?
|
[
"6:1",
"1:6",
"2:3",
"3:2",
"4:1"
] |
Quantity of milk in 200 liters if mix = 200*4/5 =160 liters
Quantity of milk in 210 liters of new mix = 160+20 = 180 liters
Quantity of water in it = 210-180 = 30 liters
Ratio of milk and water in new mix = 180:30 = 6:1
Answer is A
The answer is: A
|
A
|
mathematics
|
A shopkeeper buys mangoes at the rate of 4 a rupee and sells them at 3 a rupee. Find his net profit or loss percent?
|
[
"33 1/7 %",
"33 8/3 %",
"33 1/3 %",
"33 1/8 %",
"37 1/3 %"
] |
The total number of mangoes bought by the shopkeeper be 12.
If he buys 4 a rupee, his CP = 3
He selling at 3 a rupee, his SP = 4
Profit = SP - CP = 4 - 3 = 1
Profit Percent = 1/3 * 100 = 33 1/3 %
Answer: C
The answer is: C
|
C
|
mathematics
|
In a certain series, each term is m greater than the previous term. If the 19th term is 760 and the 16th term is 700, what is the first term?
|
[
"200",
"300",
"400",
"450",
"500"
] |
a + 18m = 760 (17th term)
a + 15m = 700 (16th term)
You get a = 400 and m = 20
Answer: C
The answer is: C
|
C
|
mathematics
|
In 4 years, Raj's father age twice as raj, Two years ago, Raj's mother's age twice as raj. If Raj is 32yrs old in eight yrs from now, what is the age of Raj's mother and father?
|
[
"27",
"36",
"28",
"46",
"91"
] |
Raj present age = 32 - 8 = 24.
After 4 years Raj's age is 28. and Raj's fathers age is 28 x 2 = 56, and his present age is 52.
Two years ago, Raj's age is 22. and his mother's age is 22 x 2 = 44. His mother's present age = 46
Answer:C
The answer is: C
|
C
|
mathematics
|
For a group of n people, k of whom are of the same sex, the (n-k)/n expression yields an index for a certain phenomenon in group dynamics for members of that sex. For a group that consists of 20 people, 5 of whom are females, by how much does the index for the females exceed the index for the males in the group?
|
[
"0.05",
"0.0625",
"0.5",
"0.25",
"0.6"
] |
Index for females = (20-5)/20 = 3/4 = 0.75
Index for males = (20-15/20 = 1/4 = 0.25
Index for females exceeds males by 0.75 - 0.25 = 0.5
Answer: C
The answer is: C
|
C
|
mathematics
|
A firm has 4 senior partners and 6 junior partners. How many different groups D of 3 partners can be formed in which at least one member of the group is a senior partner. (2 groups are considered different if at least one group member is different)
|
[
"48",
"100",
"120",
"288",
"600"
] |
What seems to work as well, though its tougher to come up with this solution:
(10*9*8) * 2/3 + (10*9*4)*1/3 = 600. Divided by all possible permutations (=3!) yields 100.
Explanation: For the first spot you have 10 possible canditates, for the 2nd 9. For the 3rd spot you need to differentiate if a senior partner has been picked for one of the first 2 spots or not. If yes, then you can pick one of the 8 remaining guys, so 10*9*8. If no senior partner has been picked yet, you need 10*9*4.
Now you need to weight the 2 cases with the corresponding probabilities: probability of no senior partner being picked in the first 2 draws = 6/10*5/9=1/3, so you weight 10*9*4 with 1/3. For the complementary case (senior partner was picked in the first 2 draws) you just take the complementary prob (1-1/3)= 2/3 and weight 10*9*8 with it.
Now you just need to divide the answer (600) by the number of different positions (=3!) and get D=600/6=100B
The answer is: B
|
B
|
mathematics
|
Find the average of the series : 312, 162, 132, 142 and 122?
|
[
"129",
"308",
"267",
"207",
"174"
] |
Average = (312 + 162 + 132 + 142 + 122)/5
= 870/5
= 174
Answer: E
The answer is: E
|
E
|
mathematics
|
Two years ago, Arthur gave each of his five children 20 percent of his fortune to invest in any way they saw Fit. In the first year, three of the children, Alice, Bob, and Carol, each earned a profit of 50 percent on their Investments, while two of the children, Dave and Errol, lost 40 percent on their investments. In the second Year, Alice and Bob each earned a 10 percent profit, Carol lost 60 percent, Dave earned 50 percent in profit, And Errol lost all the money he had remaining. What percentage of Arthur's fortune currently remains?
|
[
"93%",
"96%",
"100%",
"107%",
"120%"
] |
Say Arthur's fortune was $100. Then:
A = 20*1.5*1.1 = 33
B = 20*1.5*1.1 = 33
C = 20*1.5*0.4 = 12
D = 20*0.6*1.50 = 18
E = 0
Total 33 + 33 + 12 + 18 = 96.
Answer: B.
The answer is: B
|
B
|
mathematics
|
The difference between compound and simple interest on a certain sum of money for 3 years at 6 2/3% p.a is Rs.184. Find the sum?
|
[
"22887",
"28779",
"27677",
"13500",
"17971"
] |
P = (184*106) / [6 2/3 * 6 2/3 *(300*6 2/3)]
P = 13500
Answer:D
The answer is: D
|
D
|
mathematics
|
A 270 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?
|
[
"230",
"278",
"266",
"555",
"255"
] |
Relative speed = 120 + 80 = 200 km/hr.
= 200 * 5/18 = 500/9 m/sec.
Let the length of the other train be x m.
Then, (x + 270)/9 = 500/9 => x = 230.
Answer:A
The answer is: A
|
A
|
mathematics
|
Two thirds of the roads from A to B are at least 5 miles long, and 3/4 of the roads from B to C are at least 5 miles long. If you randomly pick a road from A to B and then randomly pick a road from B to C, what is the probability that at least one of the roads you pick is at least 5 miles long?
|
[
"1/6",
"1/4",
"2/3",
"3/4",
"11/12"
] |
So please:
Find the probability of the event thatnoneof the roads you pick will be at least 5 miles long and subtract from 1 to get the probability thatat least oneof the roads you pick will be at least 5 miles long: P=1-1/3*1/4=11/12.
Answer: E.
The answer is: E
|
E
|
mathematics
|
A four-character password consists of one letter of the alphabet and three different digits between 1 and 9, inclusive. The letter must appear as the second or third character of the password. How many different passwords are possible?
|
[
"5,040",
"18,720",
"26,208",
"37,440",
"52,000"
] |
4 character password: DLDD
First digit can be chosen in 9 ways.
The letter can be chosen in 26 ways.
Next digit can be chosen in 8 ways.
Next digit can be chosen in 7 ways.
This gives us 9*26*8*7ways
Now, the letter can also be DDLD so there will be another 9*26*8*7 ways
Total = 9*26*8*7*2 = 26,208 ways C
The answer is: C
|
C
|
mathematics
|
Which of the following is closest to (120!-119!)/(120!+119!)
|
[
"2",
"2.5",
"3",
"1",
"3.2"
] |
(120!-119!)/(120!+119!)
119! (120-1)/119! (120+1)
119/121 = 1 (approximately)
D is the answer
The answer is: D
|
D
|
mathematics
|
An article is sold at a profit of 14%. If both the cost price and selling price are Rs 132 less, the profit would be 12% more. Find the cost price.
|
[
"Rs276",
"Rs268",
"Rs266",
"Rs286",
"Rs296"
] |
Let cost price was X.
SP = X + 14% of X = 1.14X.
If CP and SP were Rs. 132 less, the profit would be (14 +12)%.
New, CP = ( X - 132)
SP = 1.14X - 132
SP - CP = 26% of (X - 132)
1.14X - 132 - X + 132 = [26*(X -132)]/100
0.14X * 100 = 26X – 3432
14X – 26X = - 3432
12X = 3432
X = 286.
So, CP was Rs 286.
ANSWER : OPTION C
The answer is: C
|
C
|
mathematics
|
Find the simple interest on Rs.500 for 9 months at 6 paisa per month?
|
[
"288",
"270",
"287",
"209",
"271"
] |
I = (500*9*6)/100 = 270
Answer: B
The answer is: B
|
B
|
mathematics
|
Seema took a loan of 1800 with simple interest for as many years as the rate of interest. If she paid 162 as interest at the end of the loan period, what was the rate of interest?
|
[
"4",
"3",
"5",
"Can not be determined",
"None"
] |
Explanation: Let rate = R% and time = R years.
Then, (1800 x R x R)/100 = 162
18R² = 162
R² = 9
R = 3.
Answer: B
The answer is: B
|
B
|
mathematics
|
In a class, if 50% of the boys were girls, then there would be 50% more girls than boys. What percentage of the overall class is girls?
|
[
"25%",
"33.33%",
"40%",
"20%",
"10%"
] |
DETAILED SOLUTION
For questions of this type, it is best to go from the final step. In the final state, the number of girls should be 1.5 * the number of boys.
When 50% of the boys are taken as girls, let the number of boys = x
Number of girls = 1.5x
total number of students = 2.5x
Original number of boys = 2x (50% of boys = x)
Original number of girls = 0.5x
Girls form 20% of the overall class.
CORRECT ANSWER D.
The answer is: D
|
D
|
mathematics
|
How many liters of water must be evaporated from 50 liters of a 1-percent sugar solution to get a 10-percent solution?
|
[
"35",
"40",
"42",
"45",
"48"
] |
1% of a 50 liter solution is 0.5L which is 10% of the solution at the end.
The solution at the end must be 5 L.
We need to evaporate 45 liters.
The answer is D.
The answer is: D
|
D
|
mathematics
|
81, 64, 27, 16...
|
[
"12",
"4",
"9",
"3",
"1"
] |
81/3 = 27
64/4 = 16
27/3 = 9
ANSWER: C
The answer is: C
|
C
|
mathematics
|
What is K's position with respect to P?
|
[
"Fifth to the LEFT",
"7",
"Fifth to the right",
"8",
"72"
] |
Answer: Option C
The answer is: C
|
C
|
mathematics
|
If a square and a rhombus stand on the same base, then the ratio of the areas of the square and the rhombus is?
|
[
"1:1",
"1:2",
"1:9",
"1:6",
"1:4"
] |
A square and a rhombus on the same base are equal in area
Answer: A
The answer is: A
|
A
|
mathematics
|
Solution A is 20% salt and Solution B is 70% salt. If you have 30 ounces of solution A and 60 ounces of solution B, in what ratio could you mix Solution A with Solution B to produce 50 ounces of a 50% salt solution?
|
[
"6:4",
"6:14",
"2:3",
"4:6",
"3:7"
] |
Forget the volumes for the time being.
You have to mix 20% and 80% solutions to get 50%. This is very straight forward since 50 is int he middle of 20 and 80 so we need both solutions in equal quantities. If this doesn't strike, use
w1/w2 = (A2 - Aavg)/(Aavg - A1)
w1/w2 = (70 - 50)/(50 - 20) = 2/3
So the volume of the two solutions will be equal. Answer has to be 2:3
C
The answer is: C
|
C
|
mathematics
|
We invested a total of $1,000. We invested one part of the money at 4% and the rest of the money at 6%. The total investment with interest at the end of the year was $1,046. How much money did we invest at 4%?
|
[
"$600",
"$650",
"$700",
"$750",
"$800"
] |
Let x be the money invested at 4%.
1.04x+1.06(1000-x)=1046.
0.02x=1060-1046.
0.02x=14.
2x=1400.
x=700.
The answer is C.
The answer is: C
|
C
|
mathematics
|
The probability that a computer company will get a computer hardware contract is 3/4 and the probability that it will not get a software contract is 3/5. If the probability of getting at least one contract is 4/5, what is the probability that it will get both the contracts?
|
[
"4/11",
"5/12",
"6/17",
"7/20",
"11/30"
] |
Let, A ≡ event of getting hardware contract
B ≡ event of getting software contract
AB ≡ event of getting both hardware and software contract.
P(A) = 3/4, P(~B) =5/9
=> P(B) = 1- (3/5) = 2/5.
A and B are not mutually exclusive events but independent events. So,
P(at least one of A and B ) = P(A) + P(B) - P(AB).
=> 4/5 = (3/4) + (2/5) - P(AB).
=> P(AB) = 7/20.
Hence, the required probability is 7/20.
The answer is D.
The answer is: D
|
D
|
mathematics
|
Sixty men can stitch 200 shirts in 30 days working 8 hours a day. In how many days can 45 men stitch 300 shirts working 6 hours a day?
|
[
"33",
"77",
"33",
"80",
"12"
] |
We have M1 D1 H1 / W1 = M2 D2 H2 / W2 (Variation rule)
(60 * 30 * 8)/ 200 = (45 * D2 * 6) / 300
D2 = (60 * 30 * 8 * 300) / (200 * 45 * 6) => D2 = 80.
Answer:D
The answer is: D
|
D
|
mathematics
|
The marks obtained by Polly and Sandy are in the ratio 3:5 and those obtained by Sandy and Willy are in the ratio of 3:2. The marks obtained by Polly and Willy are in the ratio of...?
|
[
"3:4",
"5:6",
"7:8",
"9:10",
"11:12"
] |
Polly : Sandy = 3:5 = 9:15
Sandy : Willy = 3:2 = 15:10
Polly : Sandy : Willy = 9:15:10
Polly : Willy = 9:10
The answer is D.
The answer is: D
|
D
|
mathematics
|
City A to city B, Andrew drove for 1hr at 40 mph and for 3 hours at 60 mph. What was the average speed for the whole trip?
|
[
"55",
"57.5",
"61",
"61.5",
"62.5"
] |
The total distance is 1×40+3×60=220
And the total time is 4 hours. Hence,
Average Speed=(Total Distance/Total Time)
=220/4=55
A
The answer is: A
|
A
|
mathematics
|
The cost of 2 books and 2 magazines is $26. The cost of 1 book and 3 magazines is $27. How much does 1 magazine cost?
|
[
"8",
"5",
"7",
"4",
"6"
] |
Let the cost of 1 book = x, let the cost of 1 magazine = y
2x + 2y = 26
x = (26 - 2y)/2
x = 13 - y
Again,
(13 - y) + 3y = 27
13 + 2y = 27
2y = 14
y = 7
Answer: C
The answer is: C
|
C
|
mathematics
|
The sum of all two digit numbers divisible by 4 is
|
[
"1242",
"1542",
"1742",
"1610",
"1842"
] |
Required numbers are 12,16,20 . . . . . 96
This is an A.P. in which a=12,d=4 and l=96.
Let the number of terms in it be n.Then t=96
So a+(n-1)d=96.
12+(n-1)*6=96,
12+4n-4=96
4+4n=96
4n=96-4
n = 92/4
then n=23.
Required sum
=n/2(a+l)
=23/2(12+96)
=1242
Answer is A
The answer is: A
|
A
|
mathematics
|
If 100 microns = 1 decimeter, and 1,000angstroms = 1 decimeter, how many angstroms equal 1 micron?
|
[
"1.0e-05",
"0.0001",
"10",
"10,000",
"100,000"
] |
100 microns = 1 decimeter
1,000 angstroms = 1 decimeter
100 microns = 1,000 angstroms
1 micron = 1,000/100 = 10
Answer : C
The answer is: C
|
C
|
mathematics
|
Find out the C.I on Rs.9000 at 4% p.a. compound half-yearly for 1 1/2 years
|
[
"550.87",
"506.07",
"506.04",
"506.03",
"306.01"
] |
A = 9000(51/50)3
= 9550.87
9000
-----------
550.87
Answer:A
The answer is: A
|
A
|
mathematics
|
How many odd factors does 250 have?
|
[
"3",
"4",
"5",
"6",
"8"
] |
Start with the prime factorization: 250 = 2*5*7
For odd factors, we put aside the factor of two, and look at the other prime factors.
set of exponents = {1, 1}
plus 1 to each = {2, 2}
product = 2*2 = 4
Therefore, there are 4 odd factors of 250.
Answer: B.
The answer is: B
|
B
|
mathematics
|
What are the number of ways to select 3 men and 2 women such that one man and one woman are always selected?
|
[
"80 ways",
"87 ways",
"30 ways",
"28 ways",
"82 ways"
] |
The number of ways to select three men and two women such that one man and one woman are always selected = Number of ways selecting two men and one woman from men and five women
= ⁴C₂ * ⁵C₁ = (4 * 3)/(2 * 1) * 5
= 30 ways.
Answer: C
The answer is: C
|
C
|
mathematics
|
If the price of 23 toys is 276, then what will the price of 12 toys ?
|
[
"144",
"361",
"117",
"287",
"112"
] |
Explanation:
Less toys, Less Price (Direct Proportion)
So, let the price be Rs. x
then,
23:12::276:x => x=(276*12)/23
=> x=144
So price of 12 toys will be Rs. 144
Answer: A
The answer is: A
|
A
|
mathematics
|
To be considered grade AB, an egg must weigh between 75 and 90 grams, including the shell. Shells of grade AB eggs weigh between 3 and 5 grams. What is the smallest possible mass, in grams, of a 12-egg omelet, assuming that only grade AB eggs are used, the shells are all discarded, and no mass is lost in the cooking process?
|
[
"800",
"840",
"864",
"900",
"1,080"
] |
We're asked for the smallest possible mass, so what could the lowest mass be per egg AB? A 75 gram egg, with a 5 gram shell, or 70 grams ofcookingmass. 12 x 70 = 840, so the answer is B.
The answer is: B
|
B
|
mathematics
|
The average amount with a group of seven numbers is Rs. 30. If the newly joined member has Rs. 50 with him, what was the average amount with the group before his joining the group?
|
[
"Rs. 25.6",
"Rs. 26.6",
"Rs. 16.6",
"Rs. 26",
"Rs. 25"
] |
Total members in the group = 7
Average amount = Rs. 30
Total amount with them = 7 * 30 = Rs. 210
One number has Rs. 50. So, the amount with remaining 6 people = 210 - 50 = Rs. 160
The average amount with them = 160/6 = Rs. 26.6
ANSWER:B
The answer is: B
|
B
|
mathematics
|
The sum of two numbers is 62, and one of them is 12 more than the other. What are the two numbers?
|
[
"36-48",
"50-34",
"60-24",
"42-42",
"25-37"
] |
In this problem, we are asked to find two numbers. Therefore, we must let x be one of them. Let x, then, be the first number.
We are told that the other number is 12 more, x + 12.
The problem states that their sum is 62:
word problem = 62
The line over x + 12 is a grouping symbol called a vinculum. It saves us writing parentheses.
We have:
2x = 62 − 12
= 50.
x = 50/2
= 25.
This is the first number. Therefore the other number is
x + 12 = 25 + 12 = 37.
The sum of 25 + 37 is 62.
E
The answer is: E
|
E
|
mathematics
|
5,7,11,19,35, (...)
|
[
"12",
"67",
"5",
"64",
"32"
] |
5
5× 2 - 3 = 7
7 × 2 - 3 = 11
11 × 2 - 3 = 19
19 × 2 - 3 = 35
35 × 2 - 3 = 67
Answer is B
The answer is: B
|
B
|
mathematics
|
Two brothers were expected to return here on the same day. Rajat returned 3 days earlier but Rohit returned 4 days later. If Rajat returned on Sunday, what was the expected day when both the brothers were to return home and when did Rohit Return?
|
[
"Thursday, Monday",
"Sunday, Thursday",
"Wednesday, Sunday",
"Monday, Friday",
"none"
] |
Rajat returned on Sunday -i.e. 3 days earlier
so actual day to return home is Wednesday.
Rohit returned after days so Sunday
ANSWER:C
The answer is: C
|
C
|
mathematics
|
P software has coding line 5% more than N, N software has coding line 4/13 more than M. M software has 78 lines of coding. find P lines.
|
[
"106",
"107",
"108",
"109",
"110"
] |
M s/w has 78 line of code
N s/w has = 78+78*4/13= 102 line of code
P s/w 5% more N' code 102+5.1=107.1
or
107 line of code
ANSWER:B
The answer is: B
|
B
|
mathematics
|
In power plant, If 36 men can do a piece of work in 25 hours, in how many hours will 15 men do it ?
|
[
"40 hours",
"50 hours",
"60 hours",
"70 hours",
"None of these"
] |
Explanation :
Let the required number of hours be x. Then,
Less men, More hours (Indirect Proportion)
15 : 36 : : 25 : x => (15 * x) = (36 * 25)
x=(36 x 25)/15 = 60
Hence, 15 men can do it in 60 hours.
Answer : C
The answer is: C
|
C
|
mathematics
|
Y can do a work in 2/3 the time it takes X. Z can do the same work in ¾ the time it takes Y.When all three are typing at the same time what fraction of their total work does Y do
|
[
"1/3",
"4/13",
"9/23",
"8/29",
"9/29"
] |
given the ratio of the time of y and x is 2/3 : 1
therefore the ratio of speed of the x and y becomes 2 : 3.
similarly the ratio of the speed of the z and y given as 4 : 3
therefore the speed of the y and z becomes 3 : 4.
now , comparing the ratio of the x,y and z
it becomes 2: 3 :: 3 : 4
hence the y is doing 3/9 hence it is doing 1/3 work.
ANSWER:A
The answer is: A
|
A
|
mathematics
|
A courtyard is 18 meter long and 16 meter board is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is?
|
[
"22877",
"27778",
"20000",
"27999",
"14400"
] |
Number of bricks =Courtyard area/1 brick area
=(1800×1600/20×10)=14400
Answer: E
The answer is: E
|
E
|
mathematics
|
A delegation of 5 members has to be formed from 3 ladies and 5 gentlemen. In how many ways the delegation can be formed, if 2 particular ladies are always included in the delegation?
|
[
"20",
"28",
"29",
"49",
"48"
] |
There are three ladies and five gentlemen and a committee of 5 members to be formed.
Number of ways such that two ladies are always included in the committee =
6C3= (6 * 5 * 4)/6 = 20.
Answer:A
The answer is: A
|
A
|
mathematics
|
The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:
|
[
"1008",
"1015",
"1022",
"1032",
"1122"
] |
Explanation :
Required number = (L.C.M. of 12,16, 18, 21, 28) + 7
= 1008 + 7
= 1015
ANSWER IS B
The answer is: B
|
B
|
mathematics
|
The average of 35 students in a class is 18 years. The average age of 25 students is 20. What is the average age of remaining 10 students?
|
[
"17 years",
"16 years",
"15 years",
"14 years",
"13 years"
] |
Sum of the ages of 14 students
= (18 * 35) - (20 * 25) = 630 - 500 = 130
Required average = (130/10) = 13 years.
Answer:E
The answer is: E
|
E
|
mathematics
|
A car is traveling 68 kilometers per hour. How many meters does the car travel in one minute?
|
[
"1250m/min",
"1133.33m/min",
"2560m/min",
"1670m/min",
"1890m/min"
] |
Convert hour into minutes ( 1 hour = 60 minutes) and kilometers into meters (1 km = 1000 m) and simplify
68 kilometers per hour = 68 km/hr
= (68 × 1000 meters) / (60 minutes) = 1,133.33 meters / minute
correct answer is B)1133.33m/min
The answer is: B
|
B
|
mathematics
|
Pradeep has to obtain 25% of the total marks to pass. He got 185 marks and failed by 25 marks. The maximum marks are
|
[
"840",
"600",
"800",
"1000",
"900"
] |
Explanation :
Let their maximum marks be x.
Then, 25% of x = 185 + 25
=>25/100x= 210
x = (210100/25)
x= 840.
Answer : A
The answer is: A
|
A
|
mathematics
|
A dishonest dealer professes to sell goods at the cost price but uses a weight of 800 grams per kg, what is his percent?
|
[
"11",
"25",
"77",
"88",
"11"
] |
800 --- 200
100 --- ? => 25%
Answer:B
The answer is: B
|
B
|
mathematics
|
In a class, 3/5 of the students are girls and rest are boys. If 2/9 of the girls and 1/4 of the boys are absent, what part of the total number of students is present ?
|
[
"17/25",
"18/49",
"23/30",
"23/36",
"29/36"
] |
Girls = 3/5, boys are 2/5
Absentees are (2/9)*(3/5) + (1/4)*(2/5) = 7/30
Present Students are 23/30
ANSWER:C
The answer is: C
|
C
|
mathematics
|
(2^2+4^2+6^2+.....+22^2)=?
|
[
"5578",
"7996",
"9964",
"2024",
"1346"
] |
=(1x2)^2+(2x2)^2,+(2x3)^3+......(2x11)^2
=2^2 x (1^2+2^2+3^2+.......+11^2)
formula is =1/6 n(n+1)(2n+1)
=(4x1/6x11x12x23)
=(4x506)=2024
Answer is D
The answer is: D
|
D
|
mathematics
|
13 sheeps and 9 pigs were bought for Rs. 1291.85.If the average price of a sheep be Rs. 74. What
is the average price of a pig.
|
[
"Rs. 26.65",
"Rs. 36.55",
"Rs. 35.65",
"Rs. 36.65",
"Rs. 33.65"
] |
Average price of a sheep = Rs. 74
: . Total price of 13 sheeps
= (74*13) = Rs. 962
But, total price of 13 sheeps and 9 pigs
= Rs. 1291.85
Total price of 9 pigs
= Rs. (1291.85-962) = Rs. 329.85
Hence, average price of a pig
= (329.85/9) = Rs. 36.65
Answer is D.
The answer is: D
|
D
|
mathematics
|
A local bank that has 9 branches uses a two-digit code to represent each of its branches. The same integer can be used for both digits of a code, and a pair of two-digit numbers that are the reverse of each other (such as 17 and 71) are considered as two separate codes. What is the fewest number of different integers required for the 9 codes?
|
[
"3",
"4",
"5",
"6",
"7"
] |
Pick any two integer.
Integers: 12
Code: 11, 12, 21, 22 = 4 Codes
Add one more integer: 3
13, 31, 33, 23, 32 = 5 Codes
Total = 9 Codes. Enough. Answer: A
The answer is: A
|
A
|
mathematics
|
38 69 22 73 31 47 13 82 66 97 41 79
Which of the following numbers is greater than three fourths of the numbers but less than one fourth of the numbers in the list above?
|
[
"71",
"76",
"81",
"92",
"97"
] |
Arrange the numbers in ascending order:
13, 22, 31, 38, 41, 47, 66, 69, 73, 79, 82, 97 (Just cross check the count to ensure that you didn't miss anything)
How many numbers do we see?
12, alright.
What's (1/4)12?
3.
What's (3/4)12?
9.
We're asked to find a number that are greater than 6 numbers in the list AND smaller than the remaining two.
13, 22, 31, 38, 41, 47, 66, 69, 73, 79, 82, 97
13, 22, 31, 38, 41, 47, 66, 69, 73: Find a number greater than any of these numbers.
79, 82, 97: Find a number smaller than any of these numbers.
Only 76 fits the description.
Ans:B
The answer is: B
|
B
|
mathematics
|
The greatest number of four digits which is divisible by 15, 25, 40 and 75 is:
|
[
"9000",
"9400",
"9600",
"9670",
"9800"
] |
Greatest number of 4-digits is 9999.
L.C.M. of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399.
Required number (9999 - 399) = 9600. Answer: Option C
The answer is: C
|
C
|
mathematics
|
The ratio between the sale price and the cost price of an article is 9:5. What is the ratio between the profit and the cost price of that article?
|
[
"23",
"1:2",
"4:5",
"3:5",
"25"
] |
C.P. = Rs. 5x and S.P. = Rs. 9x.
Then, Gain = Rs. 4x
Required ratio = 4x : 5x = 4:5
C
The answer is: C
|
C
|
mathematics
|
To get to a business meeting, John drove m miles in h hours, and arrived 1/2 hour early. At what rate should he have driven to arrive exactly on time?
|
[
"m/2h",
"2m/(2h+1)",
"2m/(2h-1)",
"2m-h/2h",
"none of these"
] |
m miles in h - 1/2 = (2h - 1)/2 hours
=> 2m/(2h - 1) miles per hours
ANSWER:C
The answer is: C
|
C
|
mathematics
|
The price of a certain product increased by the same percent from 1960 to 1970 as from 1970 to 1980. If its price of $1.80 in 1970 was 150 percent of its price in 1960, what was its price in 1980?
|
[
"a) $ 1.80",
"b) $ 2.00",
"c) $ 2.40",
"d) $ 2.70",
"e) $ 3.00"
] |
The price in 1970 was 150 percent of its price in 1960, means that the percent increase was 50% from 1960 to 1970 (and from 1970 to 1980).
Therefore the price in 1980 = $1.8*1.5 = $2.7.
Answer: D.
The answer is: D
|
D
|
mathematics
|
If a train, travelling at a speed of 90 kmph, crosses a pole in 5 sec, then the length of train is?
|
[
"281 m",
"112 m",
"117 m",
"125 m",
"123 m"
] |
D
D = 90 * 5/18 * 5 = 125 m
The answer is: D
|
D
|
mathematics
|
A train covers a distance of 12 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?
|
[
"176 m",
"178 m",
"120 m",
"187 m",
"144 m"
] |
Speed = (12/10 * 60) km/hr
= (72 * 5/18) m/sec
= 20 m/sec.
Length of the train = 20 * 6
= 120 m.
Answer: C
The answer is: C
|
C
|
mathematics
|
For any integer k > 1, the term “length of an integer” refers to the number of positive prime factors, not necessarily distinct, whose product is equal to k. For example, if k = 24, the length of k is equal to 4, since 24 = 2 × 2 × 2 × 3. If x and y are positive integers such that x > 1, y > 1, and x + 3y < 920, what is the maximum possible sum of the length of x and the length of y?
|
[
"14",
"12",
"10",
"16",
"18"
] |
we know that : x > 1, y > 1, and x + 3y < 1000,
and it is given that length means no of factors.
for any value of x and y, the max no of factors can be obtained only if factor is smallest noall factors are equal.
hence, lets start with smallest no 2.
2^1 =2
2^2 =4
2^3=8
2^4=16
2^5=32
2^6=64
2^7=128
2^8=256
2^9=512
2^10 =1024 (it exceeds 920, so, x can't be 2^10)
so, max value that X can take is 2^9 , for which has length of integer is 9.
now, since x =512 ,x+3y<920
so, 3y<408
==> y<136
so, y can take any value which is less than 136. and to get the maximum no of factors of smallest integer, we can say y=2^7
for 2^7 has length of integer is 7.
SO, combined together : 9+7 = 16.
D
The answer is: D
|
D
|
mathematics
|
A shopkeeper expects a gain of 22.5% on his cost price. If in a week, his sale was of Rs. 392, what was his profit?
|
[
"Rs. 18.20",
"Rs. 70",
"Rs. 72",
"Rs. 88.25",
"Rs. 80"
] |
Explanation:
C.P. = Rs.(100/122.5 x 392)= Rs.(1000*1225 x 392)= Rs. 320
Profit = Rs. (392 - 320) = Rs. 72.
ANSWER IS C
The answer is: C
|
C
|
mathematics
|
A peacock of flying speed 5 km/h is sitiing on a top of a wooden pole of height 10m. There is a hole in the pole downwards and a snake is approaching that hole which is 21m away from the snake.How much time it will take for the peacock to catch the snake before it enters the hole.
|
[
"14.73 seconds",
"16.73 seconds",
"15.73 seconds",
"17.73 seconds",
"18.73 seconds"
] |
Speed of the peacock = 5 km/h(given)
Distance of the pole = 10m(given)
Distance between the pole hole and snake = 21m(given)
Therefore, we have to first find the distance between the peacock and the snake.
This can be done by using Pythagora's Theorem,
Therefore, 21^2 + 10^2 = 23.26 metre(approx)
Speed of the peacock = 5 km/h or 1.39 metre/sec(approx)
Now, we know can find the time for peacock to catch the snake by,
Time = Distance/Speed
= 23.26/1.39
= 16.73 seconds(approx)
Therefore, the required time for peacock to catch the snake before it enters the hole of the pole is 16.73 seconds.
ANSWER:B
The answer is: B
|
B
|
mathematics
|
Three pipes, A, B, & C are attached to a tank. A & B can fill it in 20 & 30 minutes respectively while C can empty it in 15 minutes. If A, B & C are kept open successively for 2 minute each, how soon will the tank be filled?
|
[
"2 hours",
"4 hours",
"3 hours",
"5 hours",
"6 hours"
] |
in three minute 1/20+1/30-1/15=1/60 part is filled
6 min--------1/60 parts
x min--------- 1 part(full)
x=360 min =6 hours
ANSWER:E
The answer is: E
|
E
|
mathematics
|
Mercy's income is 10 percent more than Timothy's income, and Timothy's income is 22 percent less than Ryan's income. What percent of Ryan's income is Mary's income?
|
[
"81.5%",
"85.5%",
"82.5%",
"84.5%",
"80.5%"
] |
Ryan's income = 100 (assume);
Timothy's income = 78 (22 percent less than Ryan's income);
Mercy's income = 85.5 (60 percent more than Timothy's income).
Thus, Mercy's income (85.5) is 85.5% of Ryan's income (100).
Answer: B
The answer is: B
|
B
|
mathematics
|
A train 210 m long, running with a speed of 63 km/hr will pass a tree in?
|
[
"15 sec",
"16 sec",
"18 sec",
"12 sec",
"25 sec"
] |
Speed = 63 * 5/18 = 35/2 m/sec
Time taken = 210 * 2/35 = 12 sec
ANSWER: D
The answer is: D
|
D
|
mathematics
|
A shopkeeper wants to make a minimum net profit of 5% on a pair of jeans she is selling, which she bought for $100. If originally, she was selling the pair at 20% gain, what is the largest discount she can allow?
|
[
"12.5%",
"8%",
"8.3%",
"15%",
"4%"
] |
A
If she bought the jeans at $100, she is currently selling them at (120/100)*100 = $120.
She wants to make a profit of 5%, which means she needs to sell them at (105/100)*100 = $105
The max discount she can allow is thus ((120-105)/120)*100 = 12.5%
The answer is: A
|
A
|
mathematics
|
When a number is multiplied by 13,it will become greater to 105 by an amount with which it is lesser to105 by now. What is the number
|
[
"12",
"13",
"14",
"15",
"16"
] |
no is 105-x, then
(105-x)*13 = 105+x
1365 -13 x =105+x
14x = 1260
x= 1260/14 =90
so number is 105-90 = 15
ANSWER:D
The answer is: D
|
D
|
mathematics
|
There was a cycle race going on. 1/5th of the those in front of a person and 5/6th of those behind him
gives the total number of participants. How many people took part in the race?
|
[
"31",
"39",
"30",
"33",
"34"
] |
Explanation :
Let total participants be (x+1)
Then
=> (1 / 5) * x + (5/6) * x = x+1
=> 31x/30=x+1
=> x=30
So total participants (x+1)=31
Hence (A) is the correct answer.
Answer : A
The answer is: A
|
A
|
mathematics
|
An aircraft company has 20 planes in its fleet. Every year it retires 5 of its planes and replaces then with 6 newer planes. How many years will it take the company, starting from 2010, to reduce the number of it s old planes to less than half of its fleet?
|
[
"2",
"1",
"3",
"4",
"5"
] |
Total fleet--20
End of year 2010 -- (retires 5 and buys 6) total fleet--21(15 old 6 new).
End of year 2011 -- (retires 5 and buys 6) total fleet--22(10 old 12 new).
End of year 2012 -- (retires 5 and buys 6) total fleet--23(5 old 18 new).
Answer is A--after 2 years the company has a total of 22 planes (10 old 12 new).
The answer is: A
|
A
|
mathematics
|
An optometrist charges $150 per pair for soft contact lenses and $85 per pair for hard contact lenses. Last week she sold 5 more pairs of soft lenses than hard lenses. If her total sales for pairs of contact lenses last week were $1,455, what was the total number of pairs of contact lenses that she sold?
|
[
"11",
"13",
"15",
"17",
"19"
] |
(x+5)*150 +x*85=1455
=>x=3
total lens=3+(3+5)= 11
Answer A
The answer is: A
|
A
|
mathematics
|
A bag contains 6 red, 5 blue and 2 green balls. If 2 balls are picked at random, what is the probability that both are red?
|
[
"2/13",
"3/17",
"5/26",
"5/21",
"7/15"
] |
P(Both are red),
=6C213C2=6C213C2
=5/26
C
The answer is: C
|
C
|
mathematics
|
2 years ago, the average age of a family of 5 members was 16 years. After a baby is born, the average age of family is the same today. Find the present age of the baby.
|
[
"4 years",
"6 years",
"8 years",
"8 ½ years",
"9 years"
] |
Hint: (1) First find total age of 5 members 2 years ago (2) Present age of 5 members (3) Total age of 6 members (4) Age of baby = Total age of 6 members - Present age of 5 members
We know that,
Average =Sum of Quantities / Number of Quantities
1) First calculate total age of 5 members 2 years ago = (Average age of 5 members x number of members)
First calculate total age of 5 members 2 years ago = (16 x 5) = 80 years
2) Calculate the present age of 5 members
2 years ago, their total age was 80 years. Present age can be calculated as follows:
Present age of 5 members = [80 + (2 x 5)] = 90 years
3) Calculate total age of 6 members considering baby = (16 x 6 ) = 96 years
4) Age of baby = (96 – 90) = 6 years
ANSWER IS B
The answer is: B
|
B
|
mathematics
|
A basketball coach will select the members of a five-player team from among 11 players, including John and Peter. If the five players are chosen at random, what is the probability that the coach chooses a team that includes both John and Peter?
|
[
"1/9",
"1/6",
"2/11",
"5/18",
"1/3"
] |
straight forward way is to group J and P as always present on the team and as order does not matter so we just need to find the total number of ways to select rest three players = 9c3
total number of ways of selecting 5 players out of 11 = 11c5
probability = 9c3/11c5 =2/11
C
The answer is: C
|
C
|
mathematics
|
34 is related to 12 in the same way as 59 is related to
|
[
"45",
"66",
"77",
"88",
"61"
] |
Explanation:
The second number is the product of the digits of the first.
Answer: A) 45
The answer is: A
|
A
|
mathematics
|
A business executive and his client are charging their dinner tab on the executive's expense account.The company will only allow them to spend a total of 50$ for the meal.Assuming that they will pay 7% in sales tax for the meal and leave a 20% tip,what is the most their food can cost?
|
[
"39.55$",
"40.63$",
"38.63$",
"37.88$",
"35.15$"
] |
let x is the cost of the food
1.07x is the gross bill after including sales tax
1.20* 1.07x=50
x=37.88
Hence, the correct option is C
The answer is: C
|
C
|
mathematics
|
The radius of a semi circle is 6.3 cm then its perimeter is?
|
[
"32.5",
"32.4",
"32.1",
"32.9",
"32.3"
] |
36/7 r = 6.3 = 32.4
Answer:B
The answer is: B
|
B
|
mathematics
|
In a box, there are 10 red, 6 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green ?
|
[
"4/51",
"10/21",
"7/12",
"5/21",
"13/17"
] |
Total number of balls = 10+6+5 = 21
E = event that the ball drawn is neither red nor green
= event that the ball drawn is green
n(E) = 5
P(E) = 5/21
Answer is D
The answer is: D
|
D
|
mathematics
|
In how many different number of ways 3 boys and 4 girls can sit on a bench?
|
[
"5700",
"5710",
"5040",
"8000",
"5820"
] |
npn = n!
7p7 = 7 X 6 × 5 × 4 × 3 × 2 × 1 = 5040
C)
The answer is: C
|
C
|
mathematics
|
A man can swim in still water at 6 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is?
|
[
"2",
"1.4",
"1.2",
"1.5",
"1.1"
] |
M = 6
S = x
DS = 6 + x
US = 6 + x
6 + x = (6 - x)2
6 + x = 12 -2x
3x = 6
x = 2
Answer: A
The answer is: A
|
A
|
mathematics
|
At a supermarket, a variety of cookies was priced at 75 cents per 100 grams. Subsequently, the price was revised to 40 cents for 30 grams of the same cookies. By approximately what percent did the ratio of price to weight increase from the initial price of 75 cents per pound?
|
[
"65",
"78",
"44",
"18",
"36"
] |
Initial price/weight ratio = 75 / 100 = 225/300
Revised price/weight ratio = 40 / 30 = 400/300
Answer: B
The answer is: B
|
B
|
mathematics
|
By selling 12 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
|
[
"8",
"7",
"6",
"5",
"2"
] |
80% --- 12
120% --- ?
80/120 * 12 = 8
Answer: A
The answer is: A
|
A
|
mathematics
|
Seven people went to a restaurant for dinner. Six of them spent $9 each on their meals and the seventh person spent $12 more than the average expenditure of all seven people. What was the total amount of money that the seven people spent?
|
[
"$71",
"$73",
"$75",
"$77",
"$79"
] |
Let T be the total amount of money spent.
6*9 + (T/7 + 12) = T
66 = 6T/7
T = (7*66)/6 = 77
The answer is D.
The answer is: D
|
D
|
mathematics
|
Two horses begin running on an oval course at the same time. One runs each lap in 9 minutes; the other takes 18 minutes to run each lap. How Many minutes after the start will the faster horse have a one lap lead?
|
[
"36",
"18",
"9",
"4",
"3"
] |
The rate of the faster horse is 1/9 lap/minute;
The rate of the slower horse is 1/18 lap/minute;
Their relative rate is 1/9-1/18=1/18 lap/minute;
The faster horse to gain one full lap will need time=distance/rate=1/(1/18)=18 minutes.
Answer: B
The answer is: B
|
B
|
mathematics
|
A car runs at the speed of 50 km per hour when not serviced and runs at 60 kmph when serviced. After servicing the car covers a certain distance in 6 hours. How much time will the car take to cover the same distance when not serviced?
|
[
"8 hours 12 minutes",
"6 hours 15 minutes",
"8 hours 15 minutes",
"7 hours 12 minutes",
"None"
] |
Explanation :
Time = 60*6 / 50 = 7 hours 12 mins
Answer – D
The answer is: D
|
D
|
mathematics
|
In a river flowing at 2 km/hr, a boat travels 56 km upstream and then returns downstream to the starting point. If its speed in still water be 6 km/hr, find the total journey time.
|
[
"10 hours",
"12 hours",
"14 hours",
"21 hours",
"None of these"
] |
Explanation :
speed of the boat = 6 km/hr
Speed downstream = (6+2) = 8 km/hr
Speed upstream = (6-2) = 4 km/hr
Distance travelled downstream = Distance travelled upstream = 56 km
Total time taken = Time taken downstream + Time taken upstream
= (56/8) + (56/4) = 21 hr. Answer : Option D
The answer is: D
|
D
|
mathematics
|
If n = 8^11 – 1, what is the units digit of n?
|
[
"3",
"1",
"0",
"6",
"4"
] |
8 ^ 11 - 8 = 8 (8 ^ 10 - 1)
==> 8 (2 ^ 30 - 1)
Last digit of 2 ^ 30 is 4 based on what explanation LiveStronger is saying. 2 ^ 30 - 1 yields 4 - 1 = 3 as the unit digit. Now on multiply this with 1, we get unit digit as 3.
Answer : A
The answer is: A
|
A
|
mathematics
|
A farmer with 1,350 acres of land had planted his fields with corn, sugar cane, and tobacco in the ratio of 5:3:1, respectively, but he wanted to make more money, so he shifted the ratio to 2:4:3, respectively. How many more acres of land were planted with tobacco under the new system?
|
[
"90",
"150",
"270",
"300",
"450"
] |
We have ratio in 5:3:1 and this is shifted to 2:4:3 ( C:S:T )
If we observe the ratio of the tobacco increased by 2 times (3-1)
T = 1/9*1350 = 150.
Since tobacco increased by 2 times..we get 150*2 = 300.
Answer D is the answer..
The answer is: D
|
D
|
mathematics
|
v, q, and r are positive integers. If v, q, and r are assembled into the six-digit number vqrvqr, which one of the following must be a factor of vqrvqr?
|
[
"23",
"19",
"17",
"7",
"none of the above"
] |
One short way -
vqrvqr = 1000vqr + vqr = (1000+1)vqr = 1001vqr
Therefore any factor of 1001 is a factor of vqrvqr
7 is a factor of 1001
So D
The answer is: D
|
D
|
mathematics
|
John walking at 4 Kmph reaches his office 8 minutes late. If he walks at 6 Kmph, he reaches there 8 minutes earlier. How far is the office from his house?
|
[
"3 2/5 Km",
"3 1/5 Km",
"3 1/7 Km",
"4 1/5 Km",
"4 2/5 Km"
] |
Formula = S1*S2/S2-S1 * T1+T2/60
= 4*6/2 * 16/6
= 24/2 * 16/60
= 8 * 2/5
= 16/5 = 3 1/5 Km
B)
The answer is: B
|
B
|
mathematics
|
Amanda sees a sale for 30% off all items, she sees a dress on sale that originally cost $50. How much will it cost Amanda to buy the dress after the sale amount of 30% has been take off?
|
[
"$40",
"$35",
"$50",
"$65",
"$15"
] |
Final number = original number - 30%(original number) = 50 - 30%(50) = 50 - 15 = $35.
Answer B
The answer is: B
|
B
|
mathematics
|
A car traveling at a certain constant speed takes 15 seconds longer to travel 1 kilometer than it would take to travel 1 kilometer at 60 kilometers per hour. At what speed, in kilometers per hour, is the car traveling?
|
[
"48",
"50",
"52",
"54",
"56"
] |
60 * T = 1 km => T = 1/60 km/h
V*(T+15/3600) = 1
V (1/60 + 15/3600) = 1
V (75/3600) = 1
V = 48 km/h
The answer is A.
The answer is: A
|
A
|
mathematics
|
Lionel left his house and walked towards Walt's house, 48 miles away. Two hours later, Walt left his house and ran towards Lionel's house. If Lionel's speed was 3 miles per hour and Walt's 3 miles per hour, how many miles had Lionel walked when he met Walt?
|
[
"12",
"16",
"20",
"27",
"28"
] |
In the first 2 hours Lionel at the rate of 3 miles per hour covered distance=rate*time=3*2=6 miles. So, the distance between him and Walt was 48-6=42 miles when Walt left his house. Now, their combined rate to cover this distance was 3+3=6 miles per hour, hence they will meet (they will cover that distance) in time=distance/rate=42/6=7 hours. Total time that Lionel was walking is 2+7=9 hours, which means that he covered in that time interval distance=rate*time=3*9=27 miles.
Answer: D.
The answer is: D
|
D
|
mathematics
|
When average age of 23 members are 0, how many members greater than 0?
|
[
"17",
"22",
"21",
"24",
"25"
] |
Average of 23 numbers = 0.
Sum of 23 numbers (0 x 23) = 0.
It is quite possible that 22 of these numbers may be positive and if their sum is a then 23rd number is (-a)
Answer is 22 (B)
The answer is: B
|
B
|
mathematics
|
At a certain amateur bands rock show the ratio of freaks to nerds to geeks is 1:2:3. If these are the only types of people in the crowd, and each person in the crowd has the same chance of yelling "rock on!", what are the chances that the next person who yells "rock on!" will be a geek?
|
[
"1/6",
"1/3",
"1/2",
"2/3",
"5/6"
] |
the ratio of freaks to nerds to geeks is 1:2:3.
So, Assuming the number as x,2x and 3x for freaks , nerds and geeks respc.
Probability of next person being Geek = 3x/total
or 3x/6x= 1/2. Hence , C.
The answer is: C
|
C
|
mathematics
|
If the sum of a set of 5 different positive prime numbers is 94, what is the difference between largest and smallest prime numbers between them?
|
[
"53",
"51",
"47",
"41",
"31"
] |
All prime numbers apart from 2 are odd.
Even + Even = Even
Odd + Even = Odd
Odd + Odd = Even
We are given 5 different prime numbers, whose sum is 94 i.e even
If we include 2, we will have 4 odd prime numbers and one even.
This sum would be odd
If we exclude 2, we will have 5 odd numbers.
This sum would be even
Hence 2 is included.
The possible 5 no. are = 11+7+2+43+31 = 94
the difference between largest and smallest prime numbers between them = 43 - 2 = 41
Ans - D
The answer is: D
|
D
|
mathematics
|
The profit earned after selling an article for Rs.675 is twice the loss incurred after selling the article for Rs.435. What is the cost price of the article?
|
[
"Rs.450",
"Rs.595",
"Rs.400",
"Rs.395",
"None of these"
] |
Explanation:
Let ‘x’ be the CP of the article.
i.e. Rs.675-x = 2(x-435)
675-x = 2x-870
675+870 = 3x, therefore, x=1545/3 =Rs.515
Answer: Option E
The answer is: E
|
E
|
mathematics
|
In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
|
[
"5",
"4",
"3",
"2",
"0"
] |
= 147,000
= 147 x 1000
= (3) x (7 x 7) x (2x2x2) x (5x5x5)
= 2^3 x 3^1 x 5^3 x 7^2
red = 7^2 = 49
ANSWER:D
The answer is: D
|
D
|
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