subject
stringclasses 1
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stringlengths 3
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listlengths 5
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stringlengths 18
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stringclasses 5
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|---|---|---|---|---|
mathematics
|
How many seconds does Sandy take to cover a distance of 600 meters, if Sandy runs at a speed of 15 km/hr?
|
[
"128",
"136",
"144",
"152",
"160"
] |
15 km/hr = 15000 m / 3600 s = (150 / 36) m/s = (25 / 6) m/s
time = 600 / (25/6) = 144 seconds
The answer is C.
The answer is: C
|
C
|
mathematics
|
A certain fraction is equivalent to 2/5. If the numerator of the fraction is increased by 4 and the denominator is doubled, the new fraction is equivalent to 1/3. What is the difference of the numerator and denominator of the original fraction?
|
[
"49",
"9",
"28",
"26",
"21"
] |
x/y = 2/5 -> 1
(x+4)/2y = 1/3 -> 2
Divide 1 by 2 :
=> 2x/(x+4) = 6/5
=> 5x = 3x + 12
=> x = 6
=> y = 5/2 * 6 = 15
so x - y = 9
The answer is B
The answer is: B
|
B
|
mathematics
|
Mohan purchased 15 kgs of rice at the rate of Rs.26 per kg and 10 kgs of pulses at the rate of Rs.26 per kg. Whaat is the total amount that he paid to the shopkeeper?
|
[
"A)Rs.598",
"B)Rs.594",
"C)Rs.596",
"D)Rs.550",
"None of these"
] |
Explanation:
Price of 15 kgs of rice at Rs.26/kg = 15x26 = Rs.390
Price of 10 kgs of pulses at Rs.26/kg = 10x26 = Rs.260
Therefore, Total amount = Rs.390+Rs.260 = Rs.550
Answer: Option D
The answer is: D
|
D
|
mathematics
|
Two trains 300m and 400m long run at the speed of 36kmph and 18 kmph in opposite directions in parallel tracks. The time which they take to cross each other is?
|
[
"5.6sec",
"46.67 sec",
"10.8sec",
"12.6sec",
"15sec"
] |
Relative speed = 36+18 = 54 kmph * 5/18 = 15 m/s
Distance covered in crossing each other = 300+400 = 700m
Required time = 700*1/15=46.67 sec
Answer is B
The answer is: B
|
B
|
mathematics
|
3+33+333+33.33=?
|
[
"362.33",
"372.33",
"402.33",
"702",
"None of them"
] |
3
33
333
33.33
----------
402.33
----------
Answer is C
The answer is: C
|
C
|
mathematics
|
How many consonants are present between the first and second vowel in the sequence of English alphabet ?
|
[
"3",
"13",
"11",
"10",
"None of these"
] |
Explanation:
Ref : A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
The first and second vowels are A and E respectively. There are 3 letters between A and E; there are no vowels in between. Thus, there are 3 consonants between A and E.
ANSWER A
The answer is: A
|
A
|
mathematics
|
A train passes a station platform in 36 sec and a man standing on the platform in 24 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
|
[
"767 m",
"240 m",
"180 m",
"176 m",
"186 m"
] |
Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 24 = 360 m.
Let the length of the platform be x m . Then,
(x + 360)/36 = 15 => x = 180 m.
Answer:C
The answer is: C
|
C
|
mathematics
|
If a man can cover 16 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?
|
[
"118 km",
"162 km",
"216 km",
"1887 km",
"177 km"
] |
16 m/s = 16 * 18/5 kmph
3 hours 45 minutes = 3 3/4 hours = 15/4 hours
Distance = speed * time = 16 * 18/5 * 15/4 km = 216 km.
Answer: C
The answer is: C
|
C
|
mathematics
|
A man invested Rs. 4940 in Rs. 10 shares quoted at Rs. 9.50. If the rate of dividend be 14%, his annual income is
|
[
"Rs.728",
"Rs.648",
"Rs.720",
"Rs.622",
"Rs.722"
] |
Explanation :
Market Value of a share = Rs.9.50
Investment = Rs.4940
Number of shares = 4940/9.50 = 520
Face Value of a share = Rs.10
dividend = 14%
dividend per share = (10Γ14)100 = Rs. 1.4
His annual income = 520 Γ 1.4 = Rs.728
Answer : Option A
The answer is: A
|
A
|
mathematics
|
Diane find 6 cans of paint are just enough to paint one third of her room. How many more cans of paint will she need to finish her room and paint a second room of the same size?
|
[
"5",
"7 and a half",
"10",
"12 and a half",
"30"
] |
She will need 12 cans to paint the rest of this room and 18 for the next room for a total of 30 cans.
E
The answer is: E
|
E
|
mathematics
|
Today is Monday. After 61 days, it will be:
|
[
"SUNDAY",
"SATURSDAY",
"FRIDAY",
"THURSDAY",
"MONDAY"
] |
Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
After 61 days, it will be Saturday.
Answer: Option B
The answer is: B
|
B
|
mathematics
|
If four coins are tossed, the probability of getting two heads and two tails is?
|
[
"3/8",
"3/6",
"3/9",
"3/1",
"3/4"
] |
Since four coins are tossed, sample space = 24
Getting two heads and two tails can happen in six ways.
n(E) = six ways
p(E) = 6/24 = 3/8
Answer:A
The answer is: A
|
A
|
mathematics
|
At what rate percent on simple interest will Rs.1800 amount to Rs.2000 in 5 years?
|
[
"4 %",
"3 6/7 %",
"2 6/7 %",
"3.47%",
"6 %"
] |
Explanation:
250 = (1800x5xR)/100
R = 3.47%
Answer: Option D
The answer is: D
|
D
|
mathematics
|
In each term of a sequence, 7 is added to get the next term. If the first term is 3, what is the thirty-seventh term?
|
[
"222",
"284",
"252",
"263",
"255"
] |
1rst term + 36 terms = 3 + 7+7+7+7+7+7+7+...+7 (36 times)
3 + (7 x 36) = 3 + 252 = 255
Answer E
The answer is: E
|
E
|
mathematics
|
A total of 50 percent of the geese included in a certain migration study were male. If some of the geese migrated during the study and 20 percent of the migrating geese were male, what was the ratio of the migration rate for the male geese to the migration rate for the female geese? [Migration rate for geese of a certain sex = (number of geese of that sex migrating) / (total number of geese of that sex)]
|
[
"1/4",
"7/12",
"2/3",
"7/8",
"8/7"
] |
Let' take the Number of geese to be 100.
Male = 50. Female = 50.
Now the second part of the Q, Let's take the Number migrated to be 20.
So we have 20 geese that migrated and out of that 20% are male i.e 20/100 *20 = 4 Geese (Males)
And now we know out of the total 20 geese , 4 are male , then 16 have to be female.
Now the ratio part , Male Geese Ratios = 4/50 = 2/25. - A
Female Geese Ratios =16/50=8/25 - B
Cross Multiply Equations A and B and you get =1/4 .
Ans A
The answer is: A
|
A
|
mathematics
|
A prize of $800 is to be distributed among 20 winners, each of whom must be awarded at least $20. If 2/5 of the prize will be distributed to 3/5 of the winners, what is the greatest possible individual award?
|
[
"$200",
"$220",
"$280",
"$300",
"$340"
] |
Total value of the prize =$800
Number of people = 20
2/5 of 800 (=$320) should be distributed among 3/5 of 20 (=12 people ) with each getting $20 each. Remaining money = 800-320 = $480. Now in order to 'maximize' 1 prize, we need to minimise the others and we have been given that each should get $20. Thus, minimising the remaining 7 people (=20-12-1. '-1' to exclude 1 that needs to be maximised) = 7*20=140.
Thus the maximum award can be = 480-140 = $340, hence E is the correct answer.
The answer is: E
|
E
|
mathematics
|
How many bricks each measuring 21cm x 10cm x 8cm, will be needed to build a wall 9m x 5m x 18.5m
|
[
"4955",
"4899",
"4650",
"7200",
"None of these"
] |
Explanation:
no. of bricks= volume of the wall/volume of 1 brick = (900 x 500 x 18.5) / (21 x 10 x 8) = 4955
Answer: A
The answer is: A
|
A
|
mathematics
|
The length and breadth of a rectangle is increased by 3% and 6% respectively. What is the increase in the area?
|
[
"9.18",
"9.25",
"9.5",
"8.98",
"8.88"
] |
100*100=10000
103*106=10918
-----------
918
10000-------918
100----------9.18
Ans A
The answer is: A
|
A
|
mathematics
|
An empty container is filled with pure alcohol. The alcohol is slowly allowed to run out and when the container is 1/4 empty ,it is replaced with water . Next, when the container is half empty it is again filled with water. Finally, when it is empty, it is again filled with water. What percentage of container is alcohol now?
|
[
"81/2%",
"113/4%",
"93/8 %",
"143/8%",
"none of these"
] |
Ratio of quantity of alcohol left to total quantity
=>1/1 x (3/4)/1 x (1/2)/1 x (1/4)/1
=>3/32
Alcohol percentage=3/32 x 100 => 93/8%
ANSWER:C
The answer is: C
|
C
|
mathematics
|
Nelson borrowed some money at the rate of 6 p.c.p.a. for the first three years, 9 p.c.p.a. for the next five years and 13 p.c.p.a. for the period beyond eight years. If the total interest paid by him at the end of eleven years is 8,160, how much money did he borrow?
|
[
"12,000",
"10,000",
"8,000",
"Data inadequate",
"None of these"
] |
Let βxβ be the amount borrowed by Nelson
and xΓ6Γ3/100+xΓ9Γ5/100+xΓ13Γ3/100=8160
β 102β100x = 8,160
β΄ x = 8,160Γ100102=8000
Answer C
The answer is: C
|
C
|
mathematics
|
The number of stamps that P and Q had were in the ratio of 7:3 respectively. After P gave Q 13 stamps, the ratio of the number of P's stamps to the number of Q's stamps was 5:4. As a result of the gift, P had how many more stamps than Q?
|
[
"10",
"25",
"40",
"65",
"90"
] |
P started with 7k stamps and Q started with 3k stamps.
(7k-13)/(3k+13) = 5/4
28k - 15k = 117
k = 9
P has 7(9) - 13 = 50 stamps and Q has 3(9)+13 = 40 stamps.
The answer is A.
The answer is: A
|
A
|
mathematics
|
The no. of gift pack bought by Dexter is 1 more than the price, in rupees, of each gift pack. The amount of Rs.380 which Dexter had, fell short of the required amount. What is theamount by which he might have fallen short.
|
[
"30",
"40",
"45",
"48",
"54"
] |
Let the price of gift pack be 'aa'
Then number of packs bought =a+1=a+1
Hence total cost is a(a+1)a(a+1)
It is given that 380<a(a+1)380<a(a+1)
If a=19a=19, the total cost =19Γ20=380=19Γ20=380
Dexter would not have fallen short, If:
a=20a=20, a(a+1)=420a(a+1)=420
So he would have fallen short by Rs 40.
This is the minimum amount by which he may have fallen short.
B)
The answer is: B
|
B
|
mathematics
|
A train traveling at 72 kmph crosses a platform in 30 seconds and a man standing on the platform in 17 seconds. What is the length of the platform in meters?
|
[
"240 meters",
"260 meters",
"420 meters",
"600 meters",
"Cannot be determined"
] |
Speed of the train in metres/sec = 72000/3600 = 20
Distance travelled by train to cross the platform = 30 * 20 = 600 = Length of train + Length of platform
Distance travelled by train to cross the man = 17 * 20 = 340 = Length of train
Length of platform = 600 - 340 = 260
Answer: B
The answer is: B
|
B
|
mathematics
|
If n is a positive integer and n^2 is divisible by 62, then the largest positive integer that must divide n is
|
[
"6",
"12",
"24",
"36",
"48"
] |
The question asks aboutthe largest positive integer that MUST divide n, not COULD divide n. Since the least value of n for which n^2 is a multiple of 72 is 12 then the largest positive integer that MUST divide n is 12.
Complete solution of this question is given above. Please ask if anything remains unclear.
I spent a few hours on this one alone and I'm still not clear. I chose 12 at first, but then changed to 48.
I'm not a native speaker, so here is how I interpreted this question:the largest positive integer that must divide n=the largest positive factor of n. Since n is a variable (i.e. n is moving), so is its largest factor. Please correct if I'm wrong here.
I know that if n = 12, n^2 = 144 = 2 * 72 (satisfy the condition). When n = 12, the largest factor of n is n itself, which is 12. Check: 12 is the largest positive number that must divide 12 --> true
However if n = 48, n^2 = 48 * 48 = 32 * 72 (satisfy the condition too). When n = 48, the largest factor of n is n itself, which is 48. Check: 48 is the largest positive number that must divide 48 --> true
So, I also notice that the keyword isMUST, notCOULD. The question is, why is 48 notMUST divide 48, but instead onlyCOULD divide 48? I'm not clear right here. Why is 12MUST divide 12? What's the difference between them?
Only restriction we have on positive integer n is that n^2 is divisible by 72. The least value of n for which n^2 is divisible by 72 is 12, thus nmustbe divisible by 12 (n is in any case divisible by 12). For all other values of n, for which n^2 is divisible by 72, n will still be divisible by 12. This means that n is always divisible by 12 if n^2 is divisible by 72.
Now, ask yourself: if n=12, is n divisible by 48? No. So, n is not always divisible by 48.
B
The answer is: B
|
B
|
mathematics
|
The average of five results is 46 and that of the first four is 37. The fifth result is?
|
[
"50",
"88",
"77",
"82",
"51"
] |
5 * 46 Γ’β¬β 4 * 37
= 82
Answer: D
The answer is: D
|
D
|
mathematics
|
Walking at 5/6 of its usual speed, a train is 10 minutes too late. Find its usual time to cover the journey.
|
[
"50 min",
"20 min",
"1 hour",
"30 min",
"45 min"
] |
new speed = 5/6 of the usual speed
new time taken = 6/5 of the usual time taken
so, ( 6/5 of the usual time ) - ( usual time ) = 10min
1/5 of the usual time = 10min
usual time = 10*5 = 50 min
correct option is A
The answer is: A
|
A
|
mathematics
|
A train travels from New York to Chicago, a distance of approximately 270 miles, at an average rate of 30 miles per hour and arrives in Chicago at 6:00 in evening, Chicago time. At what hour in the morning, New York time, did the train depart for Chicago? (Note : Chicago time is one hour earlier than New York time)
|
[
"3:00",
"4:00",
"10:00",
"6:00",
"7:00"
] |
6:00 in evening in Chicago = 7:00 in evening in New York. So, the train was in Chicago 7:00 in the evening, New York time.
The trip took T=D/R=270/30=9 hours. Therefore, the train depart from New York at 7:00 - 9 hours = 10:00 in the morning, New York time.
Answer: C.
The answer is: C
|
C
|
mathematics
|
The average score of a cricketer in 6 matches is 27 and in other 4 matches is 32. Then find the average score in all the 10 matches?
|
[
"25",
"27",
"30",
"29",
"42"
] |
Average in 10 matches = (6*27 + 4*32)/6+4 = 162+128/ 10 = 290/10 = 29
Answer is D
The answer is: D
|
D
|
mathematics
|
A man bought 40 shares of Rs. 60 at 6 discount, the rate of dividend being 12 1/2%The rate of interest obtained is
|
[
"13.89%",
"15.5%",
"14%",
"14.25%",
"14.95%"
] |
Explanation :
Face Value of a share = Rs.60
He bought each share at Rs.60 - Rs.6 = Rs.54
Number of shares = 40
Dividend = 12 1/2%=25/2%
Dividend per share = 60Γ25/2Γ100=Rs.7.5
Total dividend = (40 Γ 7.5)
ie, He got a dividend of (40 Γ 7.5) for an investment of Rs.(40 Γ 54)
Interest obtained = 40Γ7.5Γ100/40Γ54=13.89%
Answer : Option A
The answer is: A
|
A
|
mathematics
|
Janey covered a distance of 340 miles between city A and city B taking a total of 5 hours. If part of the distance was covered at 60 miles per hour speed and the balance at 80 miles per hour speed, how many hours did she travel at 60 miles per hour?
|
[
"1 hour 45 minutes",
"2 hours",
"2 hours 30 minutes",
"3 hours",
"None of these"
] |
Janey covered a distance of 340 miles between city A and city B taking a total of 5 hours.time taken at 60:time taken at 80::(greater speed-average speed):(average speed-lower speed)
average speed is 340/5=68
That gives the answer 3:2=D
The answer is: D
|
D
|
mathematics
|
A train passes a man standing on the platform. If the train is 125 meters long and its speed is 90 kmph, how much time it took in doing so?
|
[
"6 sec",
"2 sec",
"9 sec",
"5 sec",
"1 sec"
] |
D = 125
S = 90 * 5/18 = 25 mps
T = 125/25 = 5 sec
Answer:D
The answer is: D
|
D
|
mathematics
|
In a certain year, the population of a certain town was 9000. If in the next year the population of males increases by 3% and that of the females by 9% and the total population increases to 9600, then what was the ratio of population of males and females in that given year?
|
[
"7 : 11",
"5 : 4",
"2 : 3",
"Data inadequate",
"None of these"
] |
Let the population of males = x; then the population of females = 9000 β x
Now, 3% of x + 9% of (9000 β x)
= (9600 β 9000 ) = 600
or 0.03x + 720 β 0.09x = 600
or 720 β 600 = 0.09x β 0.03x
or, 120 = 0.06x
x = 3500
Reqd ratio of population of males and females
3500/9000β3500=3500/5500=7:11
Answer A
The answer is: A
|
A
|
mathematics
|
The tax on a commodity is diminished by 32% but its consumption is increased by 12%. Find the decrease percent in the revenue derived from it?
|
[
"20%",
"18%",
"15%",
"12%",
"24%"
] |
100 * 100 = 10000
68 * 112 = 7616
10000------- 2384
100 ------- ? = 24%
ANSWER:E
The answer is: E
|
E
|
mathematics
|
Uncle Bruce is baking chocolate chip cookies. He has 36 ounces of dough (with no chocolate) and 13 ounces of chocolate. How many ounces of chocolate are left over if he uses all the dough but only wants the cookies to consist of 20% chocolate?
|
[
"4",
"6",
"7.2",
"7.8",
"9"
] |
Answer is A.
x/x+36=1/5
x=9
13-9=4
The answer is: A
|
A
|
mathematics
|
During the past week, a local medical clinic tested N individuals for two infections. If 1/2 of those tested had infection A and, of those with infection A, 1/6 also had infection B, how many individuals did not have both infection A and B?
|
[
"N/12",
"4N/15",
"14N/12",
"11N/12",
"4N/5"
] |
1/3 of tested had infection A, thus N/2 had infection A;
Of those with infection A, 1/6 also had infection B, thus 1/2*N/6 = N/12 had both infections A and B.
Therefore, N - N/12 = 11N/12 did not have both infection A and B.
Answer: D.
The answer is: D
|
D
|
mathematics
|
At what rate percent per annum will sum of money double in 20 years?
|
[
"1.2 %",
"2 %",
"4 %",
"5 %",
"None of these"
] |
Explanation:
Hint: If sum of money becomes (z times) in (T) years at simple interest, then rate of interest (R) can be calculated using the formula:
Rate of Interest (R) % = 100 (z β 1)/T
Here, principal amount is not given.
Hence, we can directly use the trick to calculate the rate of interest.
Rate of Interest (R) % = 100 (2 β 1)/20
Rate of Interest (R) %=5 % p.a.
ANSWER IS D
The answer is: D
|
D
|
mathematics
|
How many even integers n, such that 20<=n<=250 are of the form 3k+4, where k is any natural number?
|
[
"33",
"36",
"39",
"42",
"45"
] |
The first number is 22 = 16+6(1).
We can continue adding 6 to make a list: 22, 28, 34,...
The last number is 250 = 16+6(39)
There are 39 numbers in the list.
The answer is C.
The answer is: C
|
C
|
mathematics
|
A cylindrical tank of diameter 35 cm is full of water. If 11 litres of water is drawn off, the water level in the tank will drop by:
|
[
"11 3/7cm",
"11 2/7cm",
"11 1/7cm",
"11cm",
"None of these"
] |
Explanation:
Let the drop in the water level be h cm, then,
Volume of cylinder= Οr2h
=>22/7β35/2β35/2βh=11000
=>h=11000β7β4/ 22β35β35cm=80/7cm=11 3/7cm
Option A
The answer is: A
|
A
|
mathematics
|
A FIVE DIGIT NUMBER IS FORMED BY USING THE DIGITS 1,2,3,4,5,6 WITH OUT REPETITIONS . WHAT IS THE PROBABILITY THE NUMBER IS DIVISIBLE BY4?
|
[
"1/5",
"5/6",
"21/65",
"7/3",
"2/7"
] |
If a number is divisible by 4 the last 2 digits of the number has to be divisible by 4.
If the number ends with 12: Number of possibilities = 4*3 * 2 * 1 =24
number ends with 24: Possibilities = 4*3 * 2 * 1 = 24
number ends with 32: Possibilities =24
number ends with 52: Possibilities = 24
number ends with 36: Possibilities =24
number ends with 16: Possibilities = 24
number ends with 64: Possibilities = 24
Total number of possibilities with restriction = 7*24 = 168
Total number of possibilities without restriction = 6! = 720
Probability = 168/720 =21/65
Answer: C
The answer is: C
|
C
|
mathematics
|
The C.P of 10 pens is equal to the S.P of 20 pens. Find his gain % or loss%?
|
[
"loss 16 2/8%",
"loss 50%",
"loss 16 2/3%",
"loss 18 2/3%",
"loss 16 25%"
] |
10 CP = 20 SP
20 --- 10 CP loss
100 --- ? => 50% loss
Answer:B
The answer is: B
|
B
|
mathematics
|
A reduction of 20% in the price of salt enables a lady to obtain 5 kgs more for Rs.100, find the original price per kg?
|
[
"6",
"1",
"5",
"4",
"7"
] |
100*(20/100) = 20 --- 5
? --- 1 => Rs.4
100 --- 80
? ---4 => Rs.5
Answer: C
The answer is: C
|
C
|
mathematics
|
A, B and C are entered into a partnership. A invested Rs.6500 for 6 months, B invested Rs.8400 for 5 months and C invested for Rs.10000 for 3 months. A is a working partner and gets 5% of the total profit for the same. Find the share of C in a total profit of Rs.7400.
|
[
"2777",
"1900",
"1887",
"20989",
"2671"
] |
65 * 6 : 84 * 5 : 100 * 3
26:28:20
C share = 74000 * 95/100 = 7030 * 20/74 => 1900
Answer:B
The answer is: B
|
B
|
mathematics
|
Think of a number, divide it by 5 and add 10 to it. The result is 21. What is the number thought of?
|
[
"24",
"55",
"297",
"267",
"29"
] |
Explanation :
21-10 = 11
11 x 5 = 55
Answer : B
The answer is: B
|
B
|
mathematics
|
For a finite sequence of non zero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6 , -8?
|
[
"1",
"2",
"3",
"4",
"5"
] |
Given sequence: {1, -3, 2, 5, -4, -6, -8}
The questions basically asks: how manypairs of consecutive termsare there in the sequence such that the product of these consecutive terms is negative.
1*(-3)=-3=negative;
-3*2=-6=negative;
2*5=10=positive;
5*(-4)=-20=negative;
(-4)*(-6)=24=positive.
So there are 3 pairs of consecutive terms of the sequence for which the product is negative.
Answer: C.
The answer is: C
|
C
|
mathematics
|
Difference between the length &breadth of a rectangle is 15 m. If its perimeter is 302 m, then its area is?? We have: (l - b) = 15 and 2(l + b) = 302 or (l + b) = 151?
|
[
"5446 m^2",
"5464 m^2",
"5644 m^2",
"5434 m^2",
"5344 m^2"
] |
Solving the two equations, we get: l = 83 and b = 68.
Area = (l x b) = (83 x 68) m2 = 5644 m^2
C
The answer is: C
|
C
|
mathematics
|
An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq m?
|
[
"Rs.4082.21",
"Rs.4082.98",
"Rs.4032.40",
"Rs.4282.40",
"Rs.4082.40"
] |
Length of the first carpet
= (1.44)(6) = 8.64 cm
Area of the second carpet
= 8.64(1 + 40/100) 6 (1 + 25/100)
= 51.84(1.4)(5/4) sq m
= (12.96)(7) sq m
Cost of the second carpet = (45)(12.96 * 7)
= 315 (13 - 0.04) = 4095 - 12.6
= Rs.4082.40
Answer:E
The answer is: E
|
E
|
mathematics
|
If x>=y and y>1 , what is the maximum value of log (base x) -(x/y) + log (base y)x^2/y?
|
[
"-0.5",
"0",
"0.5",
"1",
"2"
] |
log -(x/y) + log ( x^2)/y => - log x/y + 2log (x/y)
x y x y
By Formula (i) - log x/y = log y/x (ii) log y/x = log y - log x
x x x x x
log y - log x + 2{log x - log y }
x x y y
log y -1 + 2log x - 2 ==> log y + 2log x -3
x y x y
by Sub x &y as 2 by Question Condition---> Ans 1+2-3 = 0
ANSWER:B
The answer is: B
|
B
|
mathematics
|
A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.900, what is the reduced price for kg?
|
[
"45",
"60",
"70",
"80",
"20"
] |
A
900*(25/100) = 225 ---- 5
? ---- 1 => Rs.45
The answer is: A
|
A
|
mathematics
|
Two pipes can fill a tank in 20 minutes and 15 minutes. An outlet pipe can empty the tank in 45 minutes. If all the pipes are opened when the tank is empty, then how many minutes will it take to fill the tank?
|
[
"5 minutes",
"17 minutes",
"15 minutes",
"10 minutes",
"12 minutes"
] |
Part of the filled by all the three pipes in one minute
= 1/20 + 1/15 - 1/45 = (9 + 12 - 4)/180 = 17/180
So, the tank becomes full in 5 minutes.
Answer: A
The answer is: A
|
A
|
mathematics
|
If KING is coded as 17 and MASS is coded as 29 Then DON is coded as
|
[
"21",
"20",
"18",
"16",
"None of these"
] |
KING = 11+9+14+7=41 i.e (4*4)+(1*1)=17
MASS = 13+1+19+19=52 i.e (5*5)+(2*2)=29
DON = 4+14+15=33 i.e(3*3)+(3*3)=18
ANSWER:C
The answer is: C
|
C
|
mathematics
|
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are picked at random, what is the probability that they are all blue?
|
[
"1/455",
"1/458",
"1/451",
"1/457",
"1/452"
] |
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.
Probability that all the three marbles picked at random are blue
= Β³Cβ/ΒΉβ΅Cβ = (1 * 3 * 2 * 1)/(15 * 14 * 13)
= 1/455
Answer: A
The answer is: A
|
A
|
mathematics
|
Find the next number in the series ?
2 3/4 5/7 7/10 11/13 13/16 ?
|
[
"14/19",
"15/19",
"17/19",
"16/19",
"18/19"
] |
Solution:
17/19
series is 2/1 3/4 5/7 7/10 11/13 13/16
Numerator is prime number series 2-3-5-7-11-13-17
and Denominator is +3 series 1-4-7-10-13-16-19
Answer C
The answer is: C
|
C
|
mathematics
|
The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 15000, then find the annual income of A?
|
[
"Rs. 424000",
"Rs. 484000",
"Rs. 502000",
"Rs. 503000",
"Rs. 504000"
] |
B's monthly income = 15000 * 112/100 = Rs. 16800
B's monthly income = 2 parts ----> Rs. 16800
A's monthly income = 5 parts = 5/2 * 16800 = Rs. 42000
A's annual income = Rs. 42000 * 12 = Rs. 504000
E)
The answer is: E
|
E
|
mathematics
|
If the quantity (p + 5) is 5 times the quantity (q β 5), then what is the relationship between p and q?
|
[
"p = 5q + 30",
"p = 5q β 30",
"5p = q + 20",
"p = 5q",
"p = 5q β 20"
] |
p+5=5(q-5)
p+5=5q-25
p=5q-30
option B
The answer is: B
|
B
|
mathematics
|
At a certain supplier, a machine of type A costs $20,000 and a machine of type B costs $45,000. Each machine can be purchased by making a 20 percent down payment and repaying the remainder of the cost and the finance charges over a period of time. If the finance charges are equal to 40 percent of the remainder of the cost, how much less would 2 machines of type A cost than 1 machine of type B under this arrangement?
|
[
"$10,000",
"$11,200",
"$12,000",
"$13,600",
"$13,200"
] |
1 machine of type B will cost: 20% down payment of 45,000 = 9,000plusremaining sum (50,000-9,000=41,000) with 40% of finance charges 41,000*1.4=57,400 --> 9,000+57,400=66,400;
2 machine of type A will cost: 20% down payment of 2*20,000 = 8,000plusremaining sum (40,000-8,000=32,000) with 40% of finance charges 32,000*1.4=44,800 --> 8,000+44,800=52,800;
Difference = 66,400 - 52,800 = 13,600.
Answer: D.
The answer is: D
|
D
|
mathematics
|
During the months May through October, Teddy the bear quintuples his weight, and during the months November through April, Teddy loses 100 pounds. If at the beginning of November 1973, Teddy's weight was m pounds, what was Teddy's weight in pounds by the end of April 1976?
|
[
"25m - 1300",
"25m - 1200",
"5m - 1300",
"5m - 1200",
"5m"
] |
Nov ' 73 = m
April ' 74 = m - 100
Oct ' 74 = 5m - 300
April' 75 = 5m - 400
Oct' 75 = 25m - 1200
April'76 = 25m - 1300
Hence answer will be (A) 25m - 1300
The answer is: A
|
A
|
mathematics
|
On a certain road 10% of the motorists exceed the posted speed limit and receive speeding tickets, but 50% of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on the road exceed the posted speed limit?
|
[
"10.5%",
"12.5%",
"15%",
"22%",
"20%"
] |
0.1 M = 0.50 E
=> E/M = 1/5* 100 = 20%
So answer is E.
M - # of Motorists
E - # of Motorists exceeding speed
The answer is: E
|
E
|
mathematics
|
Nine men went to a hotel. 8 of them spent 3 each over their meals and the ninth spent 3 more than the average expenditure of all the nine. The total money spent by all of them was
|
[
"26",
"40",
"29.25",
"30.375",
"None of the above"
] |
Let the average expenditure of all the ninte be x
Then, 3 Γ 8 + x + 3 = 9x
β x = 3.375
β΄ Total money spent = 9x = 9 Γ 3.375 = 30.375
Answer D
The answer is: D
|
D
|
mathematics
|
A sells a Cricket Bat to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays $231 for it, the cost price of the Cricket Bat for A is:
|
[
"150",
"120",
"154",
"160",
"210"
] |
125% of 120% of A = 231
125/100 * 120/100 * A = 231
A = 231 * 2/3 = 154.
ANSWER C
The answer is: C
|
C
|
mathematics
|
A shopkeeper buys mangoes at the rate of 4 a rupee and sells them at 1 a rupee. Find his net profit or loss percent?
|
[
"330 %",
"390 %",
"200 %",
"250 %",
"300%"
] |
The total number of mangoes bought by the shopkeeper be 12.
If he buys 4 a rupee, his CP = 1
He selling at 3 a rupee, his SP = 4
Profit = SP - CP = 4 - 1 = 3
Profit Percent = 3/1 * 100 = 300 %
Answer:E
The answer is: E
|
E
|
mathematics
|
Five bells commence tolling together and toll at intervals of 2, 4, 6, 8,10 seconds respectively. In 60 minutes, how many times do they toll together?
|
[
"41",
"10",
"31",
"16",
"17"
] |
L.C.M of 2,4,6,8,10 is 240. i.e after each 2 min they will toll together.So in 60 min they will toll 30 times.As they have initially tolled once,The answer will be 30+1=31.
ANSWER:C
The answer is: C
|
C
|
mathematics
|
The salary of a person was reduced by 20%. By what percent should his reduced salary be raised so as to bring it at par with his original salary?
|
[
"10%",
"15%",
"20%",
"25%",
"50%"
] |
Let the original salary be $100
new salary = $80
increase on 80 = 20
increase on 100 = [(20/80)100]% = 25%
Answer is D
The answer is: D
|
D
|
mathematics
|
An error 5% in excess is made while measuring the side of a square. What is the percentage of error in the calculated area of the square?
|
[
"4.05%",
"4.02%",
"4%",
"10.28%",
"2%"
] |
Percentage error in calculated area
=(5+5+(5Γβ5)/100)%
=10.25%
ANSWER:D
The answer is: D
|
D
|
mathematics
|
Which of the following numbers has more than two distinct prime factors?
|
[
"385",
"422",
"425",
"471",
"500"
] |
385=5*7*11
422=2*211
425=5^2*17
471=3*157
500=2^2 * 5^3
385 has 3 distinct prime factors
Answer A
The answer is: A
|
A
|
mathematics
|
A flagstaff 17.5 m high casts a shadow of length 40.25 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be?
|
[
"10 m",
"12.5 m",
"12m",
"13 m",
"14 m"
] |
Let the height of the building x metres.
Less lengthy shadow, Less in the height (Direct Proportion)
40.25 : 28.75 :: 17.5 : x 40.25 x x = 28.75 x 17.5
x = 28.75 x 17.5/40.25
x = 12.5
Answer:B
The answer is: B
|
B
|
mathematics
|
There are 12 points marked on the circumference of a circle. How many hexagons can be formed by connecting 6 points of the 12 points?
|
[
"908",
"912",
"916",
"920",
"924"
] |
12C6=924
The answer is E.
The answer is: E
|
E
|
mathematics
|
Grace has 18 jellybeans in her pocket. She has 9 red ones, 5 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?
|
[
"4",
"8",
"12",
"13",
"15"
] |
The worst scenario is when she takes 9 red and 5 green, total of 14 jellybeans, and still doesn't have 3 distinct colors. But the next draw (15th) will surely be the third color jellybean (blue) as there is no other color jellybeans left in pocket.
Answer: E.
The answer is: E
|
E
|
mathematics
|
The sum of two consecutive integers is 21. Find the numbers.
|
[
"17, 18",
"7, 8",
"10, 11",
"1, 2",
"8, 9"
] |
n + (n + 1) = 21
2n + 1 = 21
2n = 20
n = 10
Answer: C
The answer is: C
|
C
|
mathematics
|
Mary, Peter, and Lucy were picking chestnuts. Mary picked twice as much chestnuts than Peter. Lucy picked 4 kg more than Peter. Together the three of them picked 28 kg of chestnuts. How many kilograms of chestnuts did Mary, Peter, and Lucy pick respectively?
|
[
"6, 10 and 12",
"12, 10 and 6",
"10, 6 and 12",
"12, 6 and 10",
"6, 12 and 10"
] |
M = 2P
L = P+4
M + P + L = 28
2P + P + (P+4) = 28
P = 6, M = 12, L = 10
Therefore, Mary, Peter, and Lucy picked 12, 6, and 10 kg, respectively.
The answer is D.
The answer is: D
|
D
|
mathematics
|
Molly is rolling a number cube with faces numbered 1 to 6 repeatedly. When she receives a 2, she will stop rolling the cube. What is the probability that Molly will roll the die less than 3 times before stopping?
|
[
"11/180",
"11/36",
"25/216",
"91/216",
"27/128"
] |
The probability that Molly will roll the die less than 4 times before stopping is the sum of the following:
The probability that Molly will roll the die once: P=1/6 (she gets 2 on the first roll);
The probability that Molly will roll the die twice: P=5/6*1/6 (not 2, 2);
P = 1/6 + 5/6*1/6 = 11/36
Answer: B
The answer is: B
|
B
|
mathematics
|
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 32, then how old is B?
|
[
"17 years",
"19 years",
"29 years",
"10 years",
"12 years"
] |
Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 32
5x = 30 => x = 6
Hence, B's age = 2x = 12 years.
Answer: E
The answer is: E
|
E
|
mathematics
|
If Log 4 (x) = 12, then log 2 (x / 4) is equal to
|
[
"23",
"25",
"21",
"22",
"26"
] |
If Log 4 (x) = 12, then
x = 412
x / 4 = 411
Hence
log 2 (x / 4) = log 2 (411)
= log 2 ((22)11)
= log 2 (222)
= 22
answer D
The answer is: D
|
D
|
mathematics
|
In a group of ducks and cows, the total number of legs are 32 more than twice the number of heads. Find the total number of cows.
|
[
"12",
"14",
"16",
"18",
"20"
] |
Let the number of ducks be d
and number of cows be c
Then, total number of legs = 2d + 4c = 2(d + 2c)
total number of heads = c + d
Given that total number of legs are 32 more than twice the number of heads
=> 2(d + 2c) = 32 + 2(c + d)
=> d + 2c = 16 + c + d
=> 2c = 16 + c
=> c = 16
i.e., total number of cows = 16
Answer is C.
The answer is: C
|
C
|
mathematics
|
y selling 12 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
|
[
"8",
"9",
"7",
"5",
"4"
] |
80% --- 12
120% --- ?
80/120 * 12 = 8
Answer: A
The answer is: A
|
A
|
mathematics
|
The Carson family will purchase three used cars. There are two models of cars available, Model A and Model B, each of which is available in three colors: blue, black, red, and green. How many different combinations of three cars can the Carsons select if all the cars are to be different colors?
|
[
"24",
"32",
"8",
"60",
"192"
] |
I have no idea how you got 8C8, 7C6 and 4C1.
I could have understood 8C1*6C1*4C1 (I have explained why this doesn't work in the post above)
The best way to solve it is by first selecting 3 colors out of the given 4 in 4C3 ways. (say, you got black, red and green)
Now for each color, you have 2 choices - model A or B
So you select a model in 2 ways.
No of ways of selecting the 3 cars = 3C3 * 2 * 2 * 2 = 8
Well, my logic was
The number of ways of selecting r objects from n different objects is nCr.
We have 8 options and can select either of the 8 as the first - 8C8
One car is gone and one becomes a forbidden choice so we have 7 options and need to select either of the 6 as the first - 7C6
Two cars are gone and two becomes a forbidden choice so we have 6 options and need to select either of the 4 as the first - 6C4
C
The answer is: C
|
C
|
mathematics
|
If 4 people are selected from a group of 9 married couples, what is the probability that none of them would be married to each other?
|
[
"1/33",
"2/85",
"1/3",
"56/85",
"11/85"
] |
If we are to select 4 people from 9 couples WITHOUT any restriction, how many ways can we make the selection? 18!/4!14! = 3060
If we are to select 4 people from 9 couples WITH restriction that no married couple can both make it to the group, only a representative?
9!/4!5! = 126
But we know that to select a person from each couple, take 2 possibilities
126*2*2*2*2 = 2016
Probability = Desired/All Possibilities = 2016/3060 = 56/85
Answer: D
The answer is: D
|
D
|
mathematics
|
In a can, there is a mixture of milk and water in the ratio 4 : 5. If it is filled with an additional 12 litres of milk the can would be full and ratio of milk and water would become 6 : 5. Find the capacity of the can?
|
[
"40",
"44",
"66",
"52",
"None of these"
] |
Let the capacity of the can be T litres.
Quantity of milk in the mixture before adding milk = 4/9 (T - 12)
After adding milk, quantity of milk in the mixture = 6/11 T.
6T/11 - 12 = 4/9(T - 12)
10T = 1188 - 528 => T = 66.
ANSWER:C
The answer is: C
|
C
|
mathematics
|
How many pairs of letters in the word 'CHAIRS' have as many letters between them in the word as in the alphabet?
|
[
"2",
"5",
"6",
"8",
"3"
] |
Explanation:
Letters in the word Letters in the alphabet
Answer: A) 2
The answer is: A
|
A
|
mathematics
|
In an xy-coordinate plane, a line is defined by y = kx + 1. If (2, b), (a, 4), and (a, b+1) are three points on the line, where a and b are unknown, then k = ?
|
[
"1/2",
"1",
"3/2",
"2",
"5/2"
] |
b=2k+1...(1)
b+1=ak+1...(2)
4=ak+1...(3)
Taking (2) and (3)
4=b+1
b=3
Taking (1)
3=2k+1
k=1
Answer : B
The answer is: B
|
B
|
mathematics
|
A batsman scored 130 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
|
[
"45(4/11) %",
"45 %",
"53(11/13) %",
"44(5/11) %",
"None of these"
] |
Explanation :
Total runs scored = 130
Total runs scored from boundaries and sixes = 3 x 4 + 8 x 6 = 60
Total runs scored by running between the wickets = 130 - 60 = 70
Required % = (70/130) Γ 100 = 700/13 = 53(11/13)%
Answer : Option C
The answer is: C
|
C
|
mathematics
|
9. On level farmland, two runners leave at the same time from the intersection of two country roads. One runner jogs due north at a constant rate of 8 miles per hour while the second runner jogs due east at a constant rate that is 2 miles per hour slower than the first runner's rate. How far apart, to the nearest mile, will they be after 1/2 hour ?
|
[
"5",
"7",
"8",
"12",
"14"
] |
If runner 1 is going north and runner 2 is going east they are like two sides of a 90 degree triangle.
Side 1 = 8 m/h --> 4 m in 1/2 hr
Side 2 = 6 m/h --> 3 m in 1/2 hr
to complete this right angle triangle
d^2 = 4^2 + 3^2
d^2 = 25
= 5
Answer option A
The answer is: A
|
A
|
mathematics
|
In what ratio must a grocer mix two varieties of pulses costing Rs.15 and Rs. 20 per kg respectively to
obtain a mixture worth Rs.16.50 per Kg?
|
[
"1 : 2",
"2 : 1",
"3 : 7",
"7 : 3",
"None of these"
] |
Explanation :
By the rule of alligation,we have
CP of 1 kg of 1st variety pulse CP of 1 kg of 2nd variety pulse
15 20
Mean Price
16.5
20-16.5 = 3.5 16.5-15=1.5
Required Ratio = 3.5 : 1.5 = 35 : 15 = 7 : 3
Answer : Option D
The answer is: D
|
D
|
mathematics
|
In an old fort, If 15 spiders make 15 webs in 15 days, then 1 spider will make 1 web in how many days?
|
[
"1",
"15/2",
"15",
"225",
"None of these"
] |
Explanation :
Solution: Let the required number of days be x.. Then,
Less spiders, more days (IP)
Less webs, less days (DP)
.'. Spiders 1 : 15
} : : 15 : x
webs 15 : 1
.'. 1*15*x = 15*1*15 <=> x = 15.
Answer : C
The answer is: C
|
C
|
mathematics
|
A room contains 140 people, 15 percent of whom are women. A group of people, 30 percent of whom are women, leaves the room. Of the people remaining in the room, 10 percent are women. How many people left the room?
|
[
"10",
"35",
"40",
"60",
"80"
] |
Say group of x people left the room.
# of women in the room was 0.15*140=21;
# of women in the group that left 0.3x;
# of women in the room after the group left it is 0.1(140-x);
So, 21-0.3x= 0.1(140-x) --> x=35.
Answer: B.
The answer is: B
|
B
|
mathematics
|
If the first 200 numbers are written down and those divisible by 2 are deleted and again those divisible by 5 are deleted, how many numbers are left out ?
|
[
"80",
"150",
"200",
"160",
"None"
] |
Total numbers divisible by 2 = 100
Total numbers divisible by 5 = 40
But there is double counting. So we have to subtract Total numbers which are divisible by both 2 and 5 i.e, 200 / 10 = 20
So Total numbers which are divisible by either 2 or 5 is 100 + 40 - 20 = 120
Number of numbers which are not divisible by any of those = 200 - 120 = 80
Correct Option: A
The answer is: A
|
A
|
mathematics
|
which of the following inequalities indicates the set of all values of d for which the lengths W of the three sides of a triangle can be 3,4, and d?
|
[
"0<d<1",
"0<d<5",
"0<d<7",
"1<d<5",
"1<d<7"
] |
This question is a good way to apply one of the most basic relation between the 3 sides of a triangle. In a triangle (ANY TRIANGLE), any side MUST be greater than the positive difference of the other two sides and less than than the sum of the other 2 sides. Let the sides of a triangle be a,b,c .
Thus,
|a-b| < c < a+b
|b-c| < a < b+c
|c-a| < b < a+c
Thus, if the sides of the triangle are 3,4 and d,
4-3<d<4+3 ---> 1<d<7. Thus E is the correct answer.
The answer is: E
|
E
|
mathematics
|
An aeroplane covers a particular distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 hour, it must travel at a speed of
|
[
"300 kmph",
"720 kmph",
"700 kmph",
"450 kmph",
"500 kmph"
] |
distance=(240*5) = 1200 km
speed=dist/time
req speed = 1200/(5/3)=>720km/hr
ANSWER B
The answer is: B
|
B
|
mathematics
|
Find the surface area of a 10 cm x 4 cm x 2 cm brick.
|
[
"136 cu cm",
"124 cu cm",
"164 cu cm",
"180 cu cm",
"None"
] |
Sol.
Surface area = [2(10 x 4 + 4 x 2 + 10 x 2)]
= (2 x 68)
= 136 cu cm
Answer A
The answer is: A
|
A
|
mathematics
|
Find the value of p: 5p^2-12p+1 = 20.25
|
[
"4.5",
"3.5",
"20.25",
"6.2",
"2.1"
] |
Using the elimination method substitute options for x and find the correct option.
Answer: B
The answer is: B
|
B
|
mathematics
|
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
|
[
"1 years",
"20 years",
"10 years",
"15 years",
"25 years"
] |
Explanation:
Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years.
Answer: C
The answer is: C
|
C
|
mathematics
|
In an electric circuit, two resistors with resistances x and y are connected in parallel. If R is the combined resistance of these two resistors, then the reciprocal of R is equal to the sum of the reciprocals of x and y. What is R if x is 4 Ohms and y is 5 Ohms?
|
[
"7/9",
"20/9",
"7/20",
"9/20",
"11/20"
] |
1/R = 1/x + 1/y
1/R = 1/4+1/5 = 9/20
R = 20/9
The answer is B.
The answer is: B
|
B
|
mathematics
|
A cylinder with 6 meter radius and 12 meter height is filled to capacity with water. If the content of the cylinder is used to fill several smaller cylinders of 4 meter diameter and 8 meter height, how many smaller cylinders will be filled to capacity?
|
[
"13",
"12",
"4",
"16",
"18"
] |
Calculate the volume of the larger cylinder and divide it by the volume of the smaller cylinder.
volume of cylinder =Οr2h
larger cylinder volume=1357.17
smaller cylinder volume=100.53
therefore the number of cylinders B that can be filled to capacity=1357.17/100.53=13.5
Answer is A only 13 smaller cylinders can be filled to capacity.
The answer is: A
|
A
|
mathematics
|
In a class of 25 students, 2 students did not borrow any books from the library, 10 students each borrowed 1 book, 8 students each borrowed 2 books, and the rest of the students each borrowed at least 3 books. If the average (arithmetic mean) number of books borrowed per student was 2, what is the maximum number of books that any single student could have borrowed ?
|
[
"8",
"10",
"12",
"13",
"15"
] |
The average number of books per student was 2means that total of 2*25=50 books were borrowed;
2+10+8=20 students borrowed total of 2*0+10*1+8*2=26 books;
So 50-26=24 books are left to distribute among 25-20=5 students, these 5 arethe rest who borrowed at least 3 books;
Tomaximizethe number of books one student from above 5 could have borrowed we shouldminimizethe number of books other 4 students from 5 could have borrowed. Minimum these 4 students could have borrowed is 4 books per student, so total number of books they could have borrowed is 4*3=12 books. So the 5th student could have borrowed is 24-12=12 books.
Answer: C.
The answer is: C
|
C
|
mathematics
|
Six fencers participate in a fencing championship. Assuming all competitors have an equal chance of winning, how many possibilities are there with respect to how a first-place and second-place medal can be awarded?
|
[
"20",
"24",
"25",
"30",
"36"
] |
6*5 = 30
The answer is D.
The answer is: D
|
D
|
mathematics
|
The sum of two numbers is 22. Five times one number is equal to 6 times the other. The bigger of the two numbers is
|
[
"10",
"12",
"16",
"22",
"24"
] |
Sol.
Let the numbers be x and (22 - x).
Then, 5x = 6(22 - x)
β 11x = 132β x = 12.
So, the numbers are 12 and 10.
Answer B
The answer is: B
|
B
|
mathematics
|
A man bought 40 shares of Rs. 60 at 5 discount, the rate of dividend being 1212%The rate of interest obtained is
|
[
"13.64%",
"15.5%",
"14%",
"14.25%",
"14.95%"
] |
Explanation :
Face Value of a share = Rs.60
He bought each share at Rs.60 - Rs.5 = Rs.55
Number of shares = 40
Dividend = 12 1/2%=25/2%
Dividend per share = 60Γ25/2Γ100=Rs.7.5
Total dividend = (40 Γ 7.5)
ie, He got a dividend of (40 Γ 7.5) for an investment of Rs.(40 Γ 55)
Interest obtained = 40Γ7.5Γ100/40Γ55=13.64%
Answer : Option A
The answer is: A
|
A
|
mathematics
|
Rs 80000 is divided into two parts One part is given to a person with 10% interest and another part is given to a person with 20 % interest. At the end of first year he gets profit 9000 Find money given by 10%?
|
[
"30000",
"40000",
"50000",
"60000",
"70000"
] |
let first parrt is x and second part is y then x+y=80000----------eq1
total profit=profit on x +profit on y
9000=(x*10*1)/100 + (y*20*1)/100
90000=x+2y-----------------------------------eq2
90000=80000+y
so y=10000 then x =80000-10000=70000
first part =70000
ANSWER:E
The answer is: E
|
E
|
mathematics
|
A can complete a work in 12 days with a working of 8 hours per day. B can complete the same work in 8 days when working 10 hours a day. If A and B work together, working 8 hours a day, the work can be completed in --- days.
|
[
"5 5β11",
"4 5β11",
"6 4β11",
"6 5β11",
"7 5β11"
] |
Explanation :
A can complete the work in 12 days working 8 hours a day
=> Number of hours A can complete the work = 12Γ8 = 96 hours
=> Work done by A in 1 hour = 1/96
B can complete the work in 8 days working 10 hours a day
=> Number of hours B can complete the work = 8Γ10 = 80 hours
=> Work done by B in 1 hour = 1/80
Work done by A and B in 1 hour = 1/96 + 1/80 = 11/480
=> A and B can complete the work in 480/11 hours
A and B works 8 hours a day
Hence total days to complete the work with A and B working together
= (480/11)/ (8) = 60/11 days = 5 5β11 days
Answer : Option A
The answer is: A
|
A
|
mathematics
|
How many zeros are the end of 380! ?
|
[
"90",
"91",
"94",
"None",
"95"
] |
380! has 380/5+380/5^2+380/5^3=76+15+3=94 trailing zeros ( take only the quotient into account).
Answer: C.
The answer is: C
|
C
|
mathematics
|
The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 13 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is
|
[
"345600",
"153400",
"153600",
"154000",
"154200"
] |
Perimeter = Distance covered in 8 min. = 18000 x 8 m = 2400 m.
60
Let length = 3x metres and breadth = 2x metres.
Then, 2(3x + 2x) = 2400 or x = 240.
Length = 720 m and Breadth = 480 m.
Area = (720 x 480) m2 = 345600 m2.
A
The answer is: A
|
A
|
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