untrusted-test-only / solutions /bonus /02_theEmptyRoom.md
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02_theEmptyRoom.md

Iterative Approach

Oh, just classic Fibonacci number formula

        var sum = 1;
        var last = 1;
        var last2 = 1;
        for (var i = 3; i <= input; i++) {
            sum = last + last2;
            last2 = last;
            last = sum;
        }
        return sum;

urandon: admin's privilege

What if you are an admin?

        throw 'root#term: access granted';