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2ea23abd8086888898e9990be20ba11ebadd02e2
rostam/Experiments
/python/python-code-samples/TestingEvaluationML/anotherTest.py
5,977
4.125
4
#!/usr/bin/env python # coding: utf-8 # ### Diabetes Case Study # # You now have had the opportunity to work with a range of supervised machine learning techniques for both classification and regression. Before you apply these in the project, let's do one more example to see how the machine learning process works from beginning to end with another popular dataset. # # We will start out by reading in the dataset and our necessary libraries. You will then gain an understanding of how to optimize a number of models using grid searching as you work through the notebook. # Import our libraries import pandas as pd import numpy as np from sklearn.datasets import load_diabetes from sklearn.model_selection import train_test_split, RandomizedSearchCV from sklearn.metrics import accuracy_score, precision_score, recall_score, f1_score from sklearn.ensemble import RandomForestClassifier, AdaBoostClassifier import matplotlib.pyplot as plt from sklearn.svm import SVC import seaborn as sns sns.set(style="ticks") # Read in our dataset diabetes = pd.read_csv('diabetes.csv') # Take a look at the first few rows of the dataset diabetes.head() # Because this course has been aimed at understanding machine learning techniques, we have largely ignored items related to parts of the data analysis process that come before building machine learning models - exploratory data analysis, feature engineering, data cleaning, and data wrangling. # # > **Step 1:** Let's do a few steps here. Take a look at some of usual summary statistics calculated to accurately match the values to the appropriate key in the dictionary below. # In[2]: # Cells for work diabetes.describe() # In[3]: sns.pairplot(diabetes, hue="Outcome"); # In[4]: sns.heatmap(diabetes.corr(), annot=True, cmap="YlGnBu"); # In[5]: diabetes.hist(); # In[6]: # Possible keys for the dictionary a = '0.65' b = '0' c = 'Age' d = '0.35' e = 'Glucose' f = '0.5' g = "More than zero" # Fill in the dictionary with the correct values here answers_one = { 'The proportion of diabetes outcomes in the dataset': d, 'The number of missing data points in the dataset': b, 'A dataset with a symmetric distribution': e, 'A dataset with a right-skewed distribution': c, 'This variable has the strongest correlation with the outcome': e } y = diabetes['Outcome'] X = diabetes[['Pregnancies','Glucose', 'BloodPressure', 'SkinThickness','Insulin', 'BMI', 'DiabetesPedigreeFunction', 'Age']] X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.2, random_state=42) # build a classifier clf_rf = RandomForestClassifier() # Set up the hyperparameter search param_dist = {"max_depth": [3, None], "n_estimators": list(range(10, 200)), "max_features": list(range(1, X_test.shape[1]+1)), "min_samples_split": list(range(2, 11)), "min_samples_leaf": list(range(1, 11)), "bootstrap": [True, False], "criterion": ["gini", "entropy"]} # Run a randomized search over the hyperparameters random_search = RandomizedSearchCV(clf_rf, param_distributions=param_dist) # Fit the model on the training data random_search.fit(X_train, y_train) # Make predictions on the test data rf_preds = random_search.best_estimator_.predict(X_test) # build a classifier for ada boost clf_ada = AdaBoostClassifier() # Set up the hyperparameter search # look at setting up your search for n_estimators, learning_rate # http://scikit-learn.org/stable/modules/generated/sklearn.ensemble.AdaBoostClassifier.html param_dist = {"n_estimators": [10, 100, 200, 400], "learning_rate": [0.001, 0.005, .01, 0.05, 0.1, 0.2, 0.3, 0.4, 0.5, 1, 2, 10, 20]} # Run a randomized search over the hyperparameters ada_search = RandomizedSearchCV(clf_ada, param_distributions=param_dist) # Fit the model on the training data ada_search.fit(X_train, y_train) # Make predictions on the test data ada_preds = ada_search.best_estimator_.predict(X_test) ch.print_metrics(y_test, ada_preds, 'adaboost') # In[10]: # build a classifier for support vector machines clf_svc = SVC() # Set up the hyperparameter search # look at setting up your search for C (recommend 0-10 range), # kernel, and degree # http://scikit-learn.org/stable/modules/generated/sklearn.svm.SVC.html param_dist = {"C": [0.1, 0.5, 1, 3, 5], "kernel": ['linear','rbf'] } # Run a randomized search over the hyperparameters svc_search = RandomizedSearchCV(clf_svc, param_distributions=param_dist) # Fit the model on the training data svc_search.fit(X_train, y_train) # Make predictions on the test data svc_preds = svc_search.best_estimator_.predict(X_test) ch.print_metrics(y_test, svc_preds, 'svc') # > **Step 5**: Use the test below to see if your best model matched, what we found after running the grid search. # In[11]: a = 'randomforest' b = 'adaboost' c = 'supportvector' best_model = b # put your best model here as a string or variable # Show your work here - the plot below was helpful for me # https://stackoverflow.com/questions/44101458/random-forest-feature-importance-chart-using-python features = diabetes.columns[:diabetes.shape[1]] importances = random_search.best_estimator_.feature_importances_ indices = np.argsort(importances) plt.title('Feature Importances') plt.barh(range(len(indices)), importances[indices], color='b', align='center') plt.yticks(range(len(indices)), features[indices]) plt.xlabel('Relative Importance'); # and running this cell a = 'Age' b = 'BloodPressure' c = 'BMI' d = 'DiabetesPedigreeFunction' e = 'Insulin' f = 'Glucose' g = 'Pregnancy' h = 'SkinThickness' sol_seven = { 'The variable that is most related to the outcome of diabetes' : f, 'The second most related variable to the outcome of diabetes' : c, 'The third most related variable to the outcome of diabetes' : a, 'The fourth most related variable to the outcome of diabetes' : d }
4d09c4c6782c12470c7ad19b72fb89443acdd978
QinmengLUAN/Daily_Python_Coding
/wk11_HT_uniqueOccurrences_LC1207.py
1,056
3.953125
4
""" 1207. Unique Number of Occurrences Easy: Hash Table Given an array of integers arr, write a function that returns true if and only if the number of occurrences of each value in the array is unique. Example 1: Input: arr = [1,2,2,1,1,3] Output: true Explanation: The value 1 has 3 occurrences, 2 has 2 and 3 has 1. No two values have the same number of occurrences. Example 2: Input: arr = [1,2] Output: false Example 3: Input: arr = [-3,0,1,-3,1,1,1,-3,10,0] Output: true """ class Solution: def uniqueOccurrences(self, arr: List[int]) -> bool: arr_counter = Counter(arr) arr_unique = set(arr_counter.values()) return len(arr_counter) == len(arr_unique) def uniqueOccurrences1(self, arr: List[int]) -> bool: arr_counter = Counter(arr) # print(arr_counter) appeared_occur = set() for item in set(arr): if arr_counter[item] in appeared_occur: return False else: appeared_occur.add(arr_counter[item]) return True
0209d97e93a70d10bdb739783605bba86104327d
marioleonardo/informatica_1_lab
/laib3/es6.py
321
3.71875
4
import math num = float(input("Qual è il numero?\n")) num = math.ceil(num) if (num <= 4 and num >= 0): print("A" if num == 4 else "", end="") print("B" if num == 3 else "", end="") print("C" if num == 2 else "", end="") print("D" if num == 1 else "", end="") print("F" if num == 0 else "", end="")
9006f0371809f41105ebb23c3ca395ee86772882
qzying/leetcode-private
/python/best-time-to-buy-and-sell-stock-iii.py
1,870
3.75
4
r""" 给定一个数组,它的第i个元素是一支给定的股票在第i天的价格。 设计一个算法来计算你所能获取的最大利润,你最多可以完成两笔交易。 注意:你不能同时参与多笔交易(你必须在再次购买前出售掉之前的股票)。 示例 1: 输入:prices = [3,3,5,0,0,3,1,4] 输出:6 解释:在第4天(股票价格 = 0)的时候买入,在第6天(股票价格 = 3)的时候卖出,这笔交易所能获得利润 = 3-0 = 3。   随后,在第7天(股票价格 = 1)的时候买入,在第8天(股票价格 = 4)的时候卖出,这笔交易所能获得利润 = 4-1 = 3。 示例 2: 输入:prices = [1,2,3,4,5] 输出:4 解释:在第1天(股票价格 = 1)的时候买入,在第5天(股票价格 = 5)的时候卖出, 这笔交易所能获得利润 = 5-1 = 4。     注意你不能在第1天和第2天接连购买股票,之后再将它们卖出。因为这样属于同时参与了多笔交易,你必须在再次购买前出售掉之前的股票。 示例 3: 输入:prices = [7,6,4,3,1] 输出:0 解释:在这个情况下, 没有交易完成, 所以最大利润为0。 示例 4: 输入:prices = [1] 输出:0   提示: (1) 1 <= prices.length <= 105 (2) 0 <= prices[i] <= 105 """ import numpy as np class Solution: def maxProfit(self, prices: List[int]) -> int: n = len(prices) dp = np.zeros((n + 1, 2 + 1, 2)) dp[0, :, 0] = 0 dp[0, :, 1] = -sys.maxsize dp[:, 0, 0] = 0 dp[:, 0, 1] = -sys.maxsize for i in range(1, n + 1): for j in range(2, 0, -1): dp[i][j][0] = max(dp[i - 1][j][0], dp[i - 1][j][1] + prices[i - 1]) dp[i][j][1] = max(dp[i - 1][j][1], dp[i - 1][j - 1][0] - prices[i - 1]) return int(dp[n][2][0])
edcf8b46cb6b094d6bb14c1f55a68230c42a7aaa
BackupTheBerlios/elisa-svn
/trunk/elisa/utils/misc.py
438
3.515625
4
import os def file_extension_matches(filename, pattern_list): path, extension = os.path.splitext(filename) # strip ext separator extension = extension[1:] extension = extension.lower() return extension in pattern_list def file_is_picture(filename): return file_extension_matches(filename,('jpg', 'png', 'jpeg', 'gif')) def file_is_movie(filename): return file_extension_matches(filename,('avi','mov'))
670a71dd45009dd3cc1b73174c4b093c0a90805a
tcandzq/LeetCode
/Stack/ReverseSubstringsBetweenEachPairOfParentheses.py
1,202
3.609375
4
# -*- coding: utf-8 -*- # @File : ReverseSubstringsBetweenEachPairOfParentheses.py # @Date : 2020-02-25 # @Author : tc """ 题号 1190. 反转每对括号间的子串 给出一个字符串 s(仅含有小写英文字母和括号)。 请你按照从括号内到外的顺序,逐层反转每对匹配括号中的字符串,并返回最终的结果。 注意,您的结果中 不应 包含任何括号。 示例 1: 输入:s = "(abcd)" 输出:"dcba" 示例 2: 输入:s = "(u(love)i)" 输出:"iloveu" 示例 3: 输入:s = "(ed(et(oc))el)" 输出:"leetcode" 示例 4: 输入:s = "a(bcdefghijkl(mno)p)q" 输出:"apmnolkjihgfedcbq" """ class Solution: def reverseParentheses(self, s: str) -> str: s = list(s) stack = [] n = len(s) for i in range(n): if s[i] == '(': stack.append(i) s[i] = '' if s[i] == ')' and stack: s[i] = '' start = stack.pop() s[start:i] = s[start:i][::-1] return ''.join(s) if __name__ == '__main__': s = "(ed(et(oc))el)" solution = Solution() print(solution.reverseParentheses(s))
b1928474f0b8fca4f0cb0ac1705b8c58c8b09e6c
gohst9/misc
/my_queue.py
1,412
4.21875
4
class Queue_item: #キュー内の要素にはそれ自体の値と次の値へのリンクがある def __init__(self,v,next=None): self.value = v self.next = next class Queue: def __init__(self,v=0): self.first = None self.last = None def push(self,v): #キューの一番後ろに値を付け足す if self.first == None: self.first = Queue_item(v) self.last = self.first else: #キューの一番最後の要素に新しい要素へのリンクを追加した後、 #一番最後を新しい要素に変える self.last.next = Queue_item(v) self.last = self.last.next def pop(self): if self.first == None: return None #一番最初の要素を取り出した後、 #Queue_Item内の次の要素へのリンク(next)をつかって #一番最初の要素を次の要素に変える temp = self.first.value if self.first.next != None: self.first = self.first.next else: self.first = None self.last = None return temp def main(): q = Queue() for i in [1,2,3]: q.push(i) for i in range(3): print(q.pop()) #先入れ先出しで「1,2,3」の順番で出力される if __name__ == '__main__': main()
ac5d146845124c159ccee1090552add807fd87eb
jmaitoza/ECE256_Lab2
/Lab2/caesar_encrypt.py
1,248
4.09375
4
#!/usr/bin/env python3 import os import sys shift = int(sys.argv[1]) plaintext = open("plaintext.txt", "r") #opens plaintext file plntxt = plaintext.read().strip() encrypted = "" for c in plntxt: # if not c.isalpha(): # pass # continue #if c.isupper(): # checks if plain text is capital letters c_uni = ord(c) #turns char into unicode c_index = ord(c) - ord(" ") #creates new index new_index = (c_index + shift) % 94 #shifts each char based on shift value new_uni = new_index + ord(" ") #converts unicode back to char new_char = chr(new_uni) encrypted = encrypted + new_char # creates new string based on encrypted characters # else: # c_uni = ord(c) # c_index = ord(c) - ord("a") # new_index = (c_index + shift) % 26 # # new_uni = new_index + ord("a") # new_char = chr(new_uni) # # encrypted = encrypted + new_char print("Plain text: ", plntxt) print("Encrypted text: ", encrypted) ciptext = open("ciphertext_file.txt", "r+") #opens ciphertext file contents = ciptext.read().split("\n") #following code checks if file is empty and if not empties the file to write new text to it ciptext.seek(0) ciptext.truncate() ciptext.write(encrypted) #writes encryped text to file plaintext.close() #closes files ciptext.close()
70167c3c529371165544332fd791aa5ddf66cec0
plenari/omfPython
/mpy0.0/fit_circle.py
2,952
3.796875
4
# -*- coding: utf-8 -*- ''' 计算excel文件里铁磁斯格明子的直径,只能含有一个斯格明子 >>>main(path,length=[0,1000],step=2e-9,name='M%d.xlsx',dname=3): >>>length[start,stop], >>>这个只能处理方格的情况,每隔格子的长度为step >>>dname:希望用输入路径中倒数第几个来命名结果,比如: >>>D:\\relax700\\relax250Hz700\\txt\\excel,倒数第三个,所以dname=3 >>>step,保存到excel的直径将乘以这个数字 >>>name,文件的格式,数字用%d代替。 ''' import pandas as pd import numpy as np import math import os def circle(x,y):#拟合圆形,最小二乘法 if len(x)==0: return 0,0,0 x1,x2,x3,y1,y2,y3=0.,0.,0.,0.,0.,0. x1y1,x1y2,x2y1=0.,0.,0. N=len(x) for i in range(N): x1=x1+x[i] x2=x2+x[i]**2 x3=x3+x[i]**3 y1=y1+y[i] y2=y2+y[i]**2 y3=y3+y[i]**3 x1y1=x1y1+x[i]*y[i] x1y2=x1y2+x[i]*y[i]*y[i] x2y1=x2y1+x[i]*x[i]*y[i] C=N*x2-x1**2 D=N*x1y1-x1*y1 E=N*x3+N*x1y2-(x2+y2)*x1 G=N*y2-y1**2 H=N*x2y1+N*y3-(x2+y2)*y1 a=(H*D-E*G)/(C*G-D*D) b=(H*C-E*D)/(D*D-G*C) c=-(a*x1+b*y1+x2+y2)/N A=-a/2 B=-b/2 D=math.sqrt(a**2+b**2-4*c) return D,A,B def main(pdir,pfiles,step=2e-9,dname=3,save=True,save_path=None): indexs,D,A,B=[],[],[],[] for i in pfiles: x,y=getxy(os.path.join(pdir,i)) d,a,b=circle(x,y) D.append(d*step) A.append(a*step) B.append(b*step) indexs.append(i) print(i,d) re=np.array([D,A,B]) name=pdir.split(os.sep)[-dname] result1=pd.DataFrame(re.T,columns=['Dia','X','Y'],index=indexs) if save==True: result1.to_excel(os.path.join(save_path,'Position-%s.xlsx'%name)) return result1 def getxy(path): ''' 输入数据的列是x轴,行是y轴. ''' data=np.array(pd.read_excel(path)) data_mul=data[:,:-1]*data[:,1:] loc=np.where(data_mul<0) locx,locy=loc[1],loc[0]#分别是第几列x,第几行y m0,m1=data[loc],data[locy,locx+1]# calx=(-m0)/(m1-m0)+locx return calx,locy if __name__=='__main__': #如果需要更改数据,都在下边这行更改,在上边更改无效。 step=2e-9 #cellsize dname=1 #用倒数第三个名字命名新的excel pdir=input(r'请输入计算直径excel所在的文件夹:') pfiles=[i for i in os.listdir(pdir) if i.split('.')[-1]=='xlsx'] pfiles=sorted(pfiles) ###########以下不需要更改 name=pdir.split(os.sep)[-dname]# save_path=pdir.split(pdir.split(os.sep)[-dname])[0] print('''当前使用的参数如下:\n1,计算文件夹:{} \n2,cellsize:{}\n3,excel名字:{}\n4,保存路径:{}'''.format(pdir,step,name,save_path)) main(pdir,pfiles,step=step,dname=dname,save_path=save_path)
0a25cecdfdf8f6eae74ce90af5971649d0da15d0
SalahCoder/Rock-Paper-Scissors
/main.py
1,488
4.09375
4
import random option_choosen = int(input("what do u choose \n type\n 0 for Rock ⚫️ \n 1 for paper 📄\n 2 for scissors ✂️ : ")) rock = ''' _______ ---' ____) (_____) (_____) (____) ---.__(___) ''' paper = ''' _______ ---' ____)____ ______) _______) _______) ---.__________) ''' scissors = ''' _______ ---' ____)____ ______) __________) (____) ---.__(___) ''' if option_choosen == 0: print(rock) elif option_choosen == 1: print(paper) elif option_choosen == 2: print (scissors) else: print("invalid entry") computer_choice = random.randint(0 , 2) print("computer chose: \n") if computer_choice == 0: print(rock) elif computer_choice == 1: print(paper) elif computer_choice == 2: print (scissors) else: print("ops the Computer is cheater") if computer_choice == option_choosen : print("Drow") elif option_choosen == 0 and computer_choice == 1: print("computer win😂 .. You loss🥺") elif option_choosen == 1 and computer_choice == 2: print("computer win😂 .. You loss🥺") elif option_choosen == 2 and computer_choice == 0: print("computer win😂 .. You loss🥺") elif option_choosen == 0 and computer_choice == 2: print("You win 😍 .. computer loss🥺") elif option_choosen == 1 and computer_choice == 0: print("You win 😍 .. computer loss🥺") elif option_choosen == 2 and computer_choice == 1: print("You win 😍 .. computer loss🥺")
7d39b12fb86bfcf572329dca9ae91c83da28c75e
ElshadaiK/Competitive-Programming
/red_and_blue.py
687
3.65625
4
def maximizer(reds, blues): red_sum = 0 blue_sum = 0 max_red = 0 max_blue = 0 for red in reds: red_sum += int(red) max_red = max(max_red, red_sum) for blue in blues: blue_sum += int(blue) max_blue = max(max_blue, blue_sum) return max_blue+max_red if __name__ == '__main__': t = int(input().rstrip()) temp = [] for i in range(t): red_count = int(input().rstrip()) reds = input().rstrip().split() blue_count = int(input().rstrip()) blues = input().rstrip().split() temp.append([reds, blues]) for inputs in temp: print(maximizer(inputs[0], inputs[1]))
d4e5b77c4a5c8e22ed20ca0e6c80a74e1dbf0780
jjlicky/python-basic
/파이썬 기초(조건문,반복문,복합자료형,함수)/함수예제 sumAll3.py
157
3.5
4
def sumAll(*values): sum=0 for i in values: sum+=i print("1부터 10까지의 합은 %d 입니다."%(sum)) sumAll(1,2,3,4,5,6,7,8,9,10)
e4ed7b98a241eedea5d0dc9420c788c52419a833
Prakashchater/Daily-Practice-questions
/largest.py
1,167
3.859375
4
# def large1(arr): # mx = arr[0] # for i in range(len(arr)): # if arr[i] > mx: # mx = arr[i] # return mx # # if __name__ == '__main__': # arr = [70, 11, 20, 4, 100] # print(large1(arr)) # def large2(arr): # mx = max(arr[0], arr[1]) # secmx = min(arr[0],arr[1]) # # for i in range(2,len(arr)): # if arr[i]>mx: # secmx = mx # mx = arr[i] # elif arr[i] > secmx and mx != arr: # secmx = arr[i] # return secmx # # if __name__ == '__main__': # arr = [70, 11, 20, 4, 100] # print(large2(arr)) import sys def large3(arr): if len(arr) < 3: print("Invalid") return first = arr[0] for i in range(1,len(arr)): if arr[i] > first: first = arr[i] second = -sys.maxsize for i in range(0,len(arr)): if arr[i] > second and arr[i] < first: second = arr[i] third = -sys.maxsize for i in range(0,len(arr)): if arr[i] > third and arr[i] < second: third = arr[i] return third if __name__ == '__main__': arr = [70, 11, 20, 4, 90,100] print(large3(arr))
3c313bd2c0d10b1ffa8686c3c9fe523b28a43a75
aswaniramachandran/programming-lab-aswani
/CO1 PG 13.py
176
3.65625
4
n=int(input("Enter a limit:")) print(f"Enter {n} colour names:") c=[] for i in range(0,n): c.append(input()) for i in range(0, n): print(c[0],c[n-1]) break
a9f37012ed908abdc5db839bc1d9a2ea4156dcd2
ahatzz11/advent-of-code
/2019/02/two.py
1,477
3.59375
4
#!/usr/bin/env python # part one: 3402634 # part two: 5101069 import sys def main(args): f = open("input.txt","r") instructions = f.read().split(",") i = 0 for instruction in instructions: instructions[i] = int(instruction) i += 1 current_index_offset = 0 while(instructions[current_index_offset]): if(instructions[0 + current_index_offset] == 1): print('adding!') noun = instructions[instructions[1 + current_index_offset]] verb = instructions[instructions[2 + current_index_offset]] new_position = instructions[3 + current_index_offset] instructions[new_position] = noun + verb elif(instructions[0 + current_index_offset] == 2): print('multiplying!') noun = instructions[instructions[1 + current_index_offset]] verb = instructions[instructions[2 + current_index_offset]] new_position = instructions[3 + current_index_offset] instructions[new_position] = noun * verb elif(instructions[0 + current_index_offset] == 99): print('dead!') sys.exit(0) current_index_offset += 4 print(instructions) print(instructions) def part2(data): for noun in range(100): for verb in range(100): if part1(data, noun, verb) == 19690720: return 100 * noun + verb if __name__ == '__main__': main(sys.argv)
cf912e0a6b85487110eca93a0be942a8185c33a4
LucasMaiale/Libro1-python
/Cap3/Programa 3_29.py
1,329
3.90625
4
# -*- coding: utf-8 -*- """ @author: guardati Solución del problema 3.29 Calcula e imprime el costo de un paquete turístico de acuerdo con el destino, el nivel y la cantidad de días de duración. """ destino = input('Ingrese el tipo de destino (playa/colonial/arqueológica): ') nivel_paquete = input('Ingrese nivel de paquete (exclusivo/lujo/estándar): ') numero_dias = int(input('Ingrese los días de duración del viaje: ')) ''' Se asigna el valor del costo diario de acuerdo con el destino. Observe que,si el usuario se equivoca e ingresa un destino diferente a los 3 previstos, el programa asignará el valor de $900, y calculará e imprimirá un resultado inconsistente. A pesar de que existen maneras de evitar este tipo de errores, en esta solución no se hace. ''' if destino == 'playa': costo_dia = 1200 elif destino == 'colonial': costo_dia = 1000 else: costo_dia = 900 costo_paquete = costo_dia * numero_dias # Se aplica un recargo si el nivel es exxclusivo o lujo. if nivel_paquete == 'exclusivo': costo_paquete *= 1.3 elif nivel_paquete == 'lujo': costo_paquete *= 1.1 if numero_dias > 10: costo_paquete *= 0.92 # Se aplica el descuento del 8% para estadías > 10 días. print(f'\nEl costo del paquete elegido es ${costo_paquete:.2f}')
d379cfc6f12a7bfe6edc398c146dbf16fc86c578
katesem/sololearn
/us_date_to_eu.py
461
3.78125
4
s = input() if '/' in s: s = s.split('/') print(('/').join([s[1],s[0],s[2]])) else: d = { "January": 1, "February": 2, "March": 3, "April": 4, "May": 5, "June": 6, "July": 7, "August": 8, "September": 9, "October": 10, "November": 11, "December": 12 } s = s.replace(',','').split(' ') print(('/').join([s[1], str(d[s[0]]), s[2]]))
042d46b3933a28a92448696bf6fffe96a648d9a1
BurlaSaiTeja/Python-Codes
/Lists/Lists06.py
228
4.28125
4
""" Write a Python program to generate all permutations of a list in Python. """ import itertools print(list(itertools.permutations([1,2,3]))) """ Output: [(1, 2, 3), (1, 3, 2), (2, 1, 3), (2, 3, 1), (3, 1, 2), (3, 2, 1)] """
a1dcfdcf71ead60e6957be78bf81baeecd27b3a9
Abhijit2505/Survival-Analysis
/Abhijit/Nelson Aalen Estimator/NA_estimator.py
2,684
3.609375
4
# importing the required python libraries import numpy as np import pandas as pd import matplotlib.pyplot as plt import seaborn as sns from lifelines import NelsonAalenFitter # reading the data into python dataframe telco_data = pd.read_csv('telco_customer.csv') # filtering and preparing the data to the required format telco_data['TotalCharges']=pd.to_numeric(telco_data['TotalCharges'],errors='coerce') telco_data['Churn']=telco_data['Churn'].apply(lambda x: 1 if x == 'Yes' else 0 ) # the duration varaiable column T = telco_data['tenure'] # the target event(occures/not occured) column E = telco_data['Churn'] # creating a NelsonAalenFitter object and fitting the duration and event colum data to it naf = NelsonAalenFitter() naf.fit(T,event_observed=E) # printing out the NA Estimations (cummulative hazard rates) print(naf.cumulative_hazard_.head()) print(naf.cumulative_hazard_.tail()) # utility function to plot the NA Estimator def plot_estimator(): naf.plot(figsize=(12,10),label="NA Estimator") plt.xlabel('Tenure',size=15) plt.ylabel('NA Estimate(Commulative Hazard Function Estimator)',size=13) plt.title('Plotting NA Estimate against the churning tenure of a customer',size=15) plt.legend(prop={'size': 16}) # utility function to smoothen the curve and compare between the plots def plot_function(category1,category2,bandwidth,column_name): small_ans = (telco_data[column_name] == category1) naf.fit(T[small_ans], event_observed=E[small_ans], label= category1) ax = naf.plot_hazard(bandwidth=bandwidth,figsize=(10,8)) naf.fit(T[~small_ans], event_observed=E[~small_ans], label= category2) naf.plot_hazard(ax=ax, bandwidth=bandwidth,figsize=(10,8)) plt.legend(title = column_name,prop={'size': 12}) plt.title('Curve Smoothening and Comparing({})'.format(column_name),size=12) # utility function for a plot generation to explain the smoothness and bandwidth factor visually def smooth_analysis(): n = 10 while(n<=100): naf.plot_hazard(bandwidth=n,figsize=(15,13),label=n) n+=10 plt.tight_layout() plt.legend(title= 'Bandwidth',prop={'size': 12}) # plotting the NA Estimator plot_estimator() # getting a visualization of bandwidth and smoothness of the NA Estimator smooth_analysis() # smoothing the NA Estimator naf.plot_hazard(bandwidth=10,figsize=(12,10),title="Smoother NA Estimator",label="NA Estimator") # smoothing and comparing according to the column's entry plot_function('Male','Female',3,'gender') plot_function('Yes','No',3,'PhoneService') plot_function('Yes','No',3,'Partner') plot_function('Yes','No',3,'Dependents') plot_function('Yes','No',3,'PaperlessBilling')
bfb6ba4f9b944beee17cf3609107882c7a3c1c96
ataylor89/leetcode
/problem0110.py
1,476
3.546875
4
class Solution(object): def isBalanced(self, root): if root == None: return True self.assignHeight(root) if root.left == None and root.right == None: return True elif root.left != None and root.right == None: return root.left.height == 0 elif root.right != None and root.left == None: return root.right.height == 0 else: lh = root.left.height rh = root.right.height bl = self.isBalanced(root.left) br = self.isBalanced(root.right) return abs(lh - rh) <= 1 and bl and br def assignHeight(self, node): if node == None: return node.height = None if node.left == None and node.right == None: node.height = 0 if node.left != None and node.right == None: self.assignHeight(node.left) node.height = 1 + node.left.height elif node.right != None and node.left == None: self.assignHeight(node.right) node.height = 1 + node.right.height elif node.left != None and node.right != None: self.assignHeight(node.left) self.assignHeight(node.right) node.height = 1 + max(node.left.height, node.right.height)
c157ab69c10a9d670ff2a28653ad592e22d00fa7
avinash-mishra/codeInPython
/pythonConcepts/os_module.py
1,361
4.46875
4
# Creating and removing files and directories with Python os module """This is done with the os module, which has lots of methods for handling files and dirs""" import os # this line will import os module # Make a new file. # Simply opening a file in write mode will create it at specified location, if it doesn't exist. ( If file does exist, # the act of opening # it in write mode will completely overwrite its contents.) try: f = open("file.txt", "w") # It will create file.txt in current location except IOError as e: print(e.errno) print(e) # Remove a file try: os.remove("file.txt") except os.error as e: print(e.errno) print(e) # Make a directory os.mkdir('dirname') # Recursive directory creation: creates die_c and if necessary dir_b and dir_a os.mkdir('dir_a/dir_b/dir_c') # Remove an empty directory os.rmdir('dirname') os.rmdir('dir_a/dir_b/dir_c') # Removes dir_c only ######################################################################################################33 # Create a directory and set user:group with python's os module import pwd file_path = 'example' if not os.path.exists(file_path): os.makedirs(file_path) # Creates with default permission of 0777 uid, gid = pwd.getpwnam('root').pw_uid, pwd.getpwnam('avi').pw_uid os.chown(file_path, uid, gid) # set user:group as root:avi
659fca32acee07d20c8ef117512d6f06d238fe16
BROjohnny/Python-A-Z-and-BasicPrograms-
/10 Dictionary/dictionary.py
515
4.15625
4
#this is how to define dictionary in python pythonDic = {} #this is how add values for dictionary pythonDic = {'janidu' : 'most kind person i ever met' , 'yoshini' : 'most angryful girl i ever met'} print(pythonDic.items()) print(pythonDic.keys()) print(pythonDic.values()) pythonDic['hansika'] = 'she is pretty but high class,cant reach from in my level' print(pythonDic.items()) #delete items from the dictionary del(pythonDic['hansika']) print(pythonDic.items()) pythonDic.clear() print(pythonDic.items())
21a1707916b1019e4d08fa2d0c028edb7a6fed00
jasonlingo/RoadSafety
/Map/Shapefile.py
879
3.71875
4
import shapefile as shp def ParseShapefile(filename): """ Extract GPS points from a shapefile. Args; (String) filename: the address of a shapefile. Return: (list) shapePoint: a list of GPS point in the given shapefile. """ # Read the shapefile and get its shape records. ctr = shp.Reader(filename) ShapeRecords = ctr.iterShapeRecords() # For storing GPS data of roads. shapePoint = [] # Extract GPS data of major roads that are the types of # 'trunk' and 'primary'. for sr in ShapeRecords: if sr.record[0] in ['trunk', 'primary']: shapePoint.append([]) for point in sr.shape.points: shapePoint[-1].append((point[1], point[0])) return shapePoint #ParseShapefile("/Users/Jason/GitHub/RoadSeftey/RoadSafety/Data/shapefile/delhi_highway/delhi_highway.shp")
2b079fa9f884419fba9061341f0e8200390dbcdd
jack-x/HackerEarthCode
/E_NotInRange.py
2,388
3.625
4
''' # Sample code to perform I/O: name = input() # Reading input from STDIN print('Hi, %s.' % name) # Writing output to STDOUT # Warning: Printing unwanted or ill-formatted data to output will cause the test cases to fail ''' # Write your code here def sumNatural(num): return int(num*(num+1)/2) def main(): x = 1000000 sum = int(x*(x+1)/2) #print(sum) N = int(input()) for case in range(0,N): i = input().split(' ') l = int(i[0]) r = int(i[1]) #print("L: {} and R: {}".format(l,r)) addition = sumNatural(r) - sumNatural(l-1) #print("Sum of numbers from L to R: {}".format(addition)) sum -= addition #print("Sum Remaining: {}".format(sum)) print(sum) def findPosition(arr,x): a = 0 b = len(arr) while a!=b and (b-a) > 1: mid = int((a+b)/2) if arr[mid] == x: return mid else: if arr[mid] > x: b = mid elif arr[mid] < x: a = mid return a def main2(): x = 1000000 sum = int(x*(x+1)/2) removekey = [0] * 1000001 N = int(input()) if N == 0: print(sum) return ranges = [] #initializing case 1 i = input().split(' ') l = int(i[0]) r = int(i[1]) LRarray = [[l,r]] Larray = [l] for case in range(1,N): i = input().split(' ') l = int(i[0]) r = int(i[1]) #find position index = findPosition(Larray,l) #binarySearch for x in range(index,index-1,-1): LR = LRarray[x] #print(LRarray) #print(Larray) #print(x) if l <= LR[0] and r>= LR[1]: LRarray[x] = [l,r] Larray[x] = l break if ( l >=LR[0] and l<=LR[1] ) and r>= LR[1]: LRarray[x][1] = r break if l == LR[1] : LRarray[x][1] = r break if l>LR[1]: LRarray.insert(x+1,[l,r]) Larray.insert(x+1,l) break for y in LRarray: for x in range(y[0],y[1]+1): removekey[x] = x removekey.pop(0) for x in removekey: sum -= x print(sum) main2()
13fbaa6dc28208e99f2c170776df929d28a40ede
jineshpaloor/ProjectEuler
/p07.py
841
3.953125
4
""" By listing the first six prime numbers: 2, 3, 5, 7, 11, and 13, we can see that the 6th prime is 13. What is the 10 001st prime number? """ def main(): # n = 6 # p = 13 # while n < 10001: # p = p + 2 # is_prime = True # for i in range(2,p/2 + 1): # if p % i == 0: # is_prime = False # break # if is_prime: # n = n + 1 # # print p MAX = 105000 numbers = [True] * MAX numbers[0] = numbers[1] = False primes = [] for number,is_prime in enumerate(numbers): if is_prime: primes.append(number) if len(primes) == 10001: break for i in range(number+number, MAX, number): numbers[i] = False print primes[10000] if __name__ == "__main__": main()
6b3820b099a6d33c188d8441145dbdf2a7d52bec
liorbraun/wordplay
/Functions_Logic.py
2,040
3.625
4
import random import pandas as pd from player import add_player from wordgame import listofplayers def add_player_func(playername, word, opponent): try: add_player(playername, word, opponent) except: pass def get_random_word(): try: for player_word in listofplayers: listofwords = pd.read_csv("word.csv") player_word.word = listofwords["word"][random.randint(1, 10)] except: pass def print_list(): for print_player in listofplayers: print("player name: " + print_player.name + " player opponent : " + print_player.opponent_name + " word :" + print_player.word + "\n") def get_opponent(): try: list_op = [] for player in listofplayers: list_op.append(player) for player in listofplayers: while list_op: player_op = random.choice(list_op) if player != player_op: player.opponent_name = player_op.name list_op.remove(player_op) break except: pass def kill_opponent(): try: print("kill opponent") player_name = input("Enter your name : ") for player in listofplayers: if player.name == player_name: ans = input("Are you really {} ? y/n ".format(player_name)) if str.lower(ans) == "y": kill_ans = input( "Did you kill {} : y/n ".format(player.opponent_name)) if kill_ans == "y": for opponent in listofplayers: if opponent.name == player.opponent_name: player.opponent_name = opponent.opponent_name player.word = opponent.word listofplayers.remove(opponent) break else: print("So go kill him!") except: pass
1a6dd83c2de641d61f367260cbd1e381956f5034
jgarte/Python
/Chapter 03/substitutecrypt.py
263
3.8125
4
def substitutionEncrypt(plainText,key): alphabet = "abcdefghijklmnopqrstuvwxyz " plainText = plainText.lower() cipherText = "" for ch in plainText: idx = alphabet.find(ch) chipherText = cipherText + key[idx] return cipherText
458aa7b7e8015db201c1c8563d93c48d849cd634
moodycam/MARS-5470-4470
/Hopkins/Homeworks/Week 3/Hopkins_Exercises_WK3.py
4,235
3.875
4
# -*- coding: utf-8 -*- """ Created on Mon Feb 4 14:52:51 2019 @author: srv_veralab """ # -*- coding: utf-8 -*- """ Spyder Editor This is a temporary script file. """ person = input('Enter your name:') #%% """ Exercise 1 """ def scary(): person = input('Enter your name: ') # Creates an input to place your name. age = input('Enter your age: ') # Creates an input to place your age. old = 2019 - int(age) + 100 # Gives the ouput of the current year minus input age plus 100 years. old = str(old) # Converts the variable of 'old' to a string so it can be concatenated return('Hello ' + person + ". " + "In " + old + " you will be 100 years old.") # Returns the ouput: Hello [inputted name]. In [outputted year] you will # be 100 years old. scary() #%% """ Exercise 2 """ def divide(): number = input('Enter your number: ') # Creates a prompt to enter a number number = int(number) # Turns the number into an integer m = number % 2 # Returns the remainder after dividing number by 2 if m > 0: print("Odd.") # If "m" is greater than 0 than the number is odd, otherwise it is even. else: print("Even.") divide() #%% """ Exercise 9 """ def guess(): import random a = random.randint(1,9) # Chooses a random number between (and including) 1 and 9 number = int(input('Give me a number between 1 and 9: ')) # Asks the user to input a number between 1 and 9 as an attempted guess # for the random number chosen by the program if a > number: print("Too Low!") # If the generated number is greater than the chosen number. elif a < number: print("Too High!") # If the generated number is lower than the chosen number. else: print("Perfect!") # If you're exactly right. guess() #%% """ Exercies 13 """ def gen_fib(): count = int(input("How many fibonacci numbers would you like to generate?")) i = 1 if count == 0: fib = [] # If the input is '0' print nothing elif count == 1: fib = [1] # Otherwise, if the input is '1' print '1' elif count == 2: fib = [1,1] # If the input is '2' print '1, 1' elif count > 2: fib = [1,1] while i < (count - 1): fib.append(fib[i] + fib[i-1]) i += 1 # Else if the input is greater than '2', first print '1,1' to get # started, then take the count and count-1 and add them # together to create a new variable 'i' # Eventual return is 'fib', which is the final elif return if the # input is greater than '2' return fib gen_fib() #%% """ Dr. Harrison's Answer for Exercise 13 """ fib1 = 0; fib2 = 1; counter = 5 print(fib2) while counter>1: print(fib2+fib1) temp = fib2 + fib1 fib1 = fib2 fib2 = temp counter -= 1 """ Changing Dr. Harrison's code into a function """ def gen_fib2(): count = int(input("How many fibonacci numbers would you like to generate?")) fib1 = 0; fib2 = 1 while count>1: print(fib2+fib1) temp = fib2 + fib1 fib1 = fib2 fib2 = temp count -= 1 return gen_fib2() #%% """ Exercise 25 """ import random def guess1(): ans2 = input("Is your answer 50? ") ans3 = 0 guess = 50 count = 1 while ans2 != "yes": count += 1 # If yes => done if ans2 == "yes": print("Great! I solved it in "+str(count)+"tries!") # If no else: # Is it high or low? ans3 = input("higher or lower? ") # If High if ans3 == "higher": guess += random.randint(1, 5) ans2 = input("Ok. Is it " + str(guess) + "? ") # If Low elif ans3 == "lower": guess -= random.randint(1, 5) ans2 = input("Ok. Is it " + str(guess) + "? ") return print("Great! I solved it in "+str(count)+" tries!") guess1()
9bb843ef70a895d700911c9e0bddb50f661e8af4
laxur1312/py4e
/ex_07_01.py
244
3.765625
4
print('python shout.py') fname=input('Enter a file name: ') try: fhandle=open(fname) except: print('Archivo no encontrado') exit() for line in fhandle: rline=line.rstrip() rline=rline.upper() print(rline)
f71986ca7dd932abde2d6f7f95646ee246375328
shehryarbajwa/Algorithms--Datastructures
/Algorithms-Project 1/Task3.py
2,893
4.1875
4
""" Read file into texts and calls. It's ok if you don't understand how to read files. """ import csv with open('/Users/shehryarbajwa/algorithms-challenges/texts.csv', 'r') as f: reader = csv.reader(f) texts = list(reader) with open('/Users/shehryarbajwa/algorithms-challenges/calls.csv', 'r') as f: reader = csv.reader(f) calls = list(reader) """ TASK 3: (080) is the area code for fixed line telephones in Bangalore. Fixed line numbers include parentheses, so Bangalore numbers have the form (080)xxxxxxx.) Part A: Find all of the area codes and mobile prefixes called by people in Bangalore. - Fixed lines start with an area code enclosed in brackets. The area codes vary in length but always begin with 0. - Mobile numbers have no parentheses, but have a space in the middle of the number to help readability. The prefix of a mobile number is its first four digits, and they always start with 7, 8 or 9. - Telemarketers' numbers have no parentheses or space, but they start with the area code 140. Print the answer as part of a message: "The numbers called by people in Bangalore have codes:" <list of codes> The list of codes should be print out one per line in lexicographic order with no duplicates. Part B: What percentage of calls from fixed lines in Bangalore are made to fixed lines also in Bangalore? In other words, of all the calls made from a number starting with "(080)", what percentage of these calls were made to a number also starting with "(080)"? Print the answer as a part of a message:: "<percentage> percent of calls from fixed lines in Bangalore are calls to other fixed lines in Bangalore." The percentage should have 2 decimal digits """ """Check if the number belongs to Bangalore""" def numberFromBangalore(num): isFromBangalore = num.startswith('(080)') return isFromBangalore """Check area codes""" def checkAreacodes(num): if num.startswith('('): fixedLine = num.split(')')[0].strip('()') return fixedLine if num.find(' ') and num[0] == '7' or num[0] == '8' or num[0] == '9': return num[0:4] if num.startswith('140'): return num.startswith('140') """Keep track of local calls to Bangalore numbers and all other calls""" count_bangalore_calls = 0 count_all_calls = 0 areaCodesList = [] for call in calls: if numberFromBangalore(call[0]): count_all_calls += 1 get_area_codes = checkAreacodes(call[1]) if get_area_codes not in areaCodesList: areaCodesList.append(get_area_codes) if numberFromBangalore(call[1]): count_bangalore_calls += 1 areaCodesList.sort() print('The numbers called by people in Bangalore have codes:') for code in areaCodesList: print(code) percentage = ((count_bangalore_calls / count_all_calls) * 100) print(f"{round(percentage,2)} percent of calls from fixed lines in Bangalore are calls to other fixed lines in Bangalore.")
2cfa7b3b6a9288d3b6ce7f68943ddc1ec0d38b10
abhicse32/SPOJ_codes
/DIVCHK.py
280
3.96875
4
num= input() for i in range(num): str_=raw_input() div=input(); len_=len(str_)-1; two=1; num_=0; while len_ >=0: num_+=int(str_[len_])*two; two*=2; len_-=1 #print (num_) if num_%div==0: print ("\nDivisible By %d"%div) else: print ("\nNot Divisible By %d"%div)
6ff46cb8e308a6981806070bae61917799e420b2
Anirban2404/LeetCodePractice
/621_leastInterval.py
2,048
3.9375
4
#!/usr/bin/env python3 # -*- coding: utf-8 -*- """ Created on Sun Apr 21 14:38:35 2019 @author: anirban-mac """ """ Given a char array representing tasks CPU need to do. It contains capital letters A to Z where different letters represent different tasks. Tasks could be done without original order. Each task could be done in one interval. For each interval, CPU could finish one task or just be idle. However, there is a non-negative cooling interval n that means between two same tasks, there must be at least n intervals that CPU are doing different tasks or just be idle. You need to return the least number of intervals the CPU will take to finish all the given tasks. Example: Input: tasks = ["A","A","A","B","B","B"], n = 2 Output: 8 Explanation: A -> B -> idle -> A -> B -> idle -> A -> B. Note: The number of tasks is in the range [1, 10000]. The integer n is in the range [0, 100]. """ import collections class Solution: def leastInterval(self, tasks, n): """ :type tasks: List[str] :type n: int :rtype: int """ d = collections.Counter(tasks) counts = d.values() longest = max(counts) interval = (longest - 1) * (n + 1) for count in counts: interval += count == longest and 1 or 0 return max(len(tasks), interval) """ n += 1 ans = 0 d = collections.Counter(tasks) heap = [-c for c in d.values()] heapq.heapify(heap) while heap: stack = [] cnt = 0 for _ in range(n): if heap: c = heapq.heappop(heap) cnt += 1 if c < -1: stack.append(c + 1) for item in stack: heapq.heappush(heap, item) ans += heap and n or cnt # == if heap then n else cnt return ans """ tasks = ["A","A","A","B","B","B"] n = 2 print(Solution().leastInterval(tasks,n))
6b54d7ae0e3df857db649e5616523be341eefd2e
fabiovpcaumo/curso-de-python
/semana04/aula02/exercicio_10.py
3,384
3.796875
4
""" Classe Bomba de Combustível: Faça um programa completo utilizando classes e métodos que: Possua uma classe chamada bombaCombustível, com no mínimo esses atributos: tipoCombustivel. valorLitro quantidadeCombustivel Possua no mínimo esses métodos: abastecerPorValor( ) – método onde é informado o valor a ser abastecido e mostra a quantidade de litros que foi colocada no veículo abastecerPorLitro( ) – método onde é informado a quantidade em litros de combustível e mostra o valor a ser pago pelo cliente. alterarValor( ) – altera o valor do litro do combustível. alterarCombustivel( ) – altera o tipo do combustível. alterarQuantidadeCombustivel( ) – altera a quantidade de combustível restante na bomba. OBS: Sempre que acontecer um abastecimento é necessário atualizar a quantidade de combustível total na bomba. """ class BombaDeCombustivel: def __init__(self, tipo_combustivel: str, valor_litro: int, quantidade_combustivel: int): self.tipo_combustivel = tipo_combustivel self.valor_litro = valor_litro self.quantidade_combustivel = quantidade_combustivel def abastecerPorValor(self, valor_a_abastecer): total_litros = valor_a_abastecer/self.valor_litro if total_litros <= self.quantidade_combustivel: print(f'Abastecidos {total_litros} com R$ {valor_a_abastecer}') self.alterarQuantidadeCombustivel(-total_litros) self.mostrarQuantidadeNaBomba() else: print(f'Foram abastecidos apenas {self.quantidade_combustivel} litros pois não há mais combustível na bomba. \ \nTotal: R$ {self.quantidade_combustivel * self.valor_litro} \ \nFaltaram: {total_litros - self.quantidade_combustivel}L de {self.tipo_combustivel}.') self.alterarQuantidadeCombustivel(-self.quantidade_combustivel) self.mostrarQuantidadeNaBomba() def abastecerPorLitro(self, quantidade_de_litros): valor_total = quantidade_de_litros * self.valor_litro if valor_total <= self.quantidade_combustivel: print(f'Abastecidos {quantidade_de_litros} a R$ {valor_total}') self.alterarQuantidadeCombustivel(-quantidade_de_litros) print(f'Total de combustível na bomba: {self.quantidade_combustivel}') self.mostrarQuantidadeNaBomba() else: print(f'Foram abastecidos apenas {self.quantidade_combustivel} litros pois não há mais combustível na bomba. \ \nTotal: R$ {self.quantidade_combustivel * self.valor_litro} \ \nFaltaram: {quantidade_de_litros - self.quantidade_combustivel}L de {self.tipo_combustivel}.') self.alterarQuantidadeCombustivel(-self.quantidade_combustivel) self.mostrarQuantidadeNaBomba() def alterarValor(self, novo_valor): self.valor_litro = novo_valor def alterarCombustivel(self, novo_combustivel): self.tipo_combustivel = novo_combustivel def alterarQuantidadeCombustivel(self, qtde_combustivel): self.quantidade_combustivel += qtde_combustivel def mostrarQuantidadeNaBomba(self): print (f'Quantidade de {self.tipo_combustivel} na bomba: {self.quantidade_combustivel}') if __name__ == "__main__": b1 = BombaDeCombustivel("gasolina", 3.75, 100) b1.abastecerPorLitro(101)
d0cb8cf48b393d29401b23dd7a098329029e64bb
Sewez/projecteulersol
/prob4.py
1,327
3.953125
4
# Problem 4 # Find the largest palindrome made from the product of two 3-digit numbers. # Function to check palindomic numbers def check_palin(int_list): j = 0 # Simple loops to compare the current value for it's mirror in the list for i, x in enumerate(int_list): if i == (len(int_list) - 1 - i): break if x == int_list[len(int_list) - 1 - i]: continue else: return False # return T or F return True # Breaks down a number into a list of it's digitsy def breakdown_int(num): i = 1 y = [] # extract matching factors while i <= num: y.insert(0, i) i *= 10 # extract division values div = [num / i for i in y] # create a copy to update with extractions from factors copy = [i for i in div] # loop and extract each number indvidually in a list for i, v in enumerate(div): if i > 0: copy[i] = v - (div[i-1] * 10) return copy def run_test(rev_list): for x in rev_list_gen: for y in rev_list_gen: check_list = breakdown_int(x * y) if check_palin(check_list): return x, y, x * y # Creat reversed list of all 3 digit number rev_list_gen = range(999,99, -1) print run_test(rev_list_gen)
64bdffc88dd3b3fc3ea5f967d016477141ee9643
abrosen/classroom
/itp/spring2021/gobbler.py
4,489
3.921875
4
class Player: def __init__(self, color): self.color = color self.pieces = [] self.pieces.append(Piece(color,3)) self.pieces.append(Piece(color,3)) self.pieces.append(Piece(color,2)) self.pieces.append(Piece(color,2)) self.pieces.append(Piece(color,1)) self.pieces.append(Piece(color,1)) def __str__(self) -> str: output = str(self.color) + " Player has " for index,piece in enumerate(self.pieces): output = output + str(index)+": " +str(piece) + ", " return output[:-2] +"]" #output = str(self.color) + " Player has [" #for piece in self.pieces: # output = output + str(piece) + ", " #return output[:-2] +"]" class Piece: def __init__(self,color,size): self.color= color # blue or orange self.size = size # size is int, either 1 2 or 3 self.eaten = None def can_gobble(self, other): if self.size > other.size: return True else: return False def gobble(self, other): self.eaten = other def __str__(self): return str(self.color).lower()[0]+str(self.size) #return str(self.color) + " " + str(self.size) class Board: def __init__(self): self.grid = [[None,None,None],[None,None,None],[None,None,None]] # player places a piece def place(self, piece, row, col): piece.gobble(self.grid[row][col]) self.grid[row][col] = piece # player moves a piece def move(self, piece, oldRow, oldCol, row, col): self.grid[oldRow][oldCol] = piece.eaten self.place(piece, row, col) # check for winner def is_winner(self): return self.winner_in_rows() or self.winner_in_cols() or self.winner_in_diagonal() def winner_in_rows(self): for row in self.grid: if None not in row and row[0].color == row[1].color == row[2].color: return True return False # col 0 1 2 # row 0 # # row 1 # # row 2 # def winner_in_cols(self): for colNum in range(3): if self.grid[0][colNum] != None and self.grid[1][colNum] != None and self.grid[2][colNum] != None: if self.grid[0][colNum].color == self.grid[1][colNum] == self.grid[2][colNum]: return True return False def winner_in_diagonal(self): if self.grid[0][0] != None and self.grid[1][1] != None and self.grid[2][2] != None: if self.grid[0][0].color == self.grid[1][1].color == self.grid[2][2].color: return True if self.grid[0][2] != None and self.grid[1][1] != None and self.grid[2][0] != None: if self.grid[0][2].color == self.grid[1][1].color == self.grid[2][0].color: return True return False # check if proposed move is valid def is_valid_place(self, piece, row,col): if row < 0 or row > 2 : return False if col <0 or col > 2: return False if self.grid[row][col] == None: return True else: return piece.can_gobble(self.grid[row][col]) # print board status def printBoard(self): for row in self.grid: output = "" for piece in row: output += str(piece) + "\t" print(output) def getInput(self, player): choice = "" if len(player.pieces) == 0: choice == "move" while "m" not in choice and "p" not in choice: choice = input("Please whether you want to place or move") # place if "p" in choice: index = -54892789 while not 0 <= index < len(player.pieces): print(player) index = int(input("Please enter the number of the piece you want to play")) piece = player.pieces[index] player.pieces.remove(piece) row = 70 col = 100 while not self.is_valid_place(piece,row,col): row = int(input("Enter a row: ")) col = int(input("Enter a col: ")) self.place(piece,row,col) else: pass o = Player("Orange") b = Player("Blue") board = Board() board.getInput(o) board.printBoard() board.getInput(b) board.printBoard() board.getInput(o) board.printBoard()
18bff0d9c0ee4fb8b6609bdddac547a8d5172fbc
Rajan-Chaurasiya/Python-Practice
/splitex.py
116
3.703125
4
filename = input("enter a file name: ") f_exten = filename.split(".") print("the extension is: " +repr(f_exten[-1]))
653545660ac6e8f2707ac4d1c913812c19626edd
aymane081/python_algo
/arrays/contains_duplicates.py
531
3.640625
4
class Solution(object): def contains_duplicates(self, numbers): number_set = set(numbers) return len(numbers) != len(number_set) def contains_duplicates2(self, numbers): """ :type numbers: list :rtype : Boolean """ numbers.sort() for i in range(1, len(numbers)): if numbers[i] == numbers[i - 1]: return True return False numbers = [1, 2, 1, 4] solution = Solution() print(solution.contains_duplicates(numbers))
deed9b7d5cb6bdb260cfba2165767bd8f0061878
shangjiadong/algorithm
/numBitStrings/bitstrings.py
896
3.96875
4
""" 3. Number of bit strings of length n that has 1) no two consecutive 0s. 2) two consecutive 0s. >>> num_no(3) 5 >>> num_yes(3) 3 [HINT] There are three 3-bit 0/1-strings that have two consecutive 0s. 001 100 000 The other five 3-bit 0/1-strings have no two consecutive 0s: 010 011 101 110 111 Feel free to choose any implementation style. Filename: bitstrings.py """ def num_no(n): no = {1: 2, 2: 3} if n in no: return no[n] else: no[n] = num_no(n-1) + num_no(n-2) return no[n] def num_yes(n): yes = {1: 0, 2: 1, 3: 3} if n in yes: return yes[n] else: yes[n] = 2**(n-2) + num_yes(n-2) + num_yes(n-1) return yes[n] def main(): print(num_yes(10)) print(num_no(10)) if __name__ == '__main__': main()
421053db4de77630c3aeb7309ae830896bf46deb
vishalagrawalit/Competitive-Programming
/Codechef-June_Challange-2017/Triplets.py
1,716
3.546875
4
def binarySearch(arr, l, r, x): if l>r: return -1 if x>=arr[r]: return r mid = (l+r)//2 if arr[mid]==x: return mid if mid>0 and arr[mid-1]<= x and x<arr[mid]: return mid-1 if x<arr[mid]: return binarySearch(arr, l, mid-1, x) return binarySearch(arr, mid+1, r, x) M = 10**9 + 7 for _ in range(int(input())): array = list(map(int,input().split())) s_one,s_three = [],[] p = list(map(int,input().split())) p.sort() add = 0 for x in range(array[0]): add = (add+p[x])%M s_one.append(add) q = list(map(int,input().split())) q.sort() r = list(map(int,input().split())) r.sort() add = 0 for x in range(array[2]): add = (add+r[x])%M s_three.append(add) ans = 0 for i in range(array[1]): index_p = binarySearch(p,0, array[0]-1, q[i]) index_r = binarySearch(r,0, array[2]-1, q[i]) if index_p < array[0] and index_p!=-1 and p[index_p+1]==q[i]: for j in range(index_p+1,array[0]-1): if p[j]==q[i]: index_p+=1 else: break if index_r < array[2] and index_r!=-1 and r[index_r+1]==q[i]: for k in range(index_r+1,array[2]-1): if r[k]==q[i]: index_r+=1 else: break if index_p!=-1 and index_r!=-1: res = (q[i] * q[i] * (index_p+1) * (index_r+1)) + (s_one[index_p] * s_three[index_r]) + (s_one[index_p] * (index_r+1) + s_three[index_r] * (index_p+1)) * q[i] ans = (ans + (res%M))%M print(ans)
ac1350ea905e0fd409f24e4542cd661bf014fb6d
kayvera/random_python_files
/name_cases.py
601
3.765625
4
full_name = "Mikayla Rivera" message = "Hello " + full_name + "," + " is the coolest ever!" print(message) print(full_name.title()) print(full_name.upper()) print(full_name.lower()) print('\tWarren Buffett once said,"Price is what you pay.\n\tValue is what you get."') famous_person = "Warren Buffett" message = "\t" + famous_person + ' once said,"Price is what you pay.\n\tValue is what you get."' print(message) persons_name = " Kelly Green " print(persons_name) print('\n' + persons_name) print('\t' + persons_name) print(persons_name.lstrip()) print(persons_name.rstrip()) print(persons_name.strip())
aebcdc6d32100c50f30dc123668b20850e6559b3
MrHamdulay/csc3-capstone
/examples/data/Assignment_1/shmken002/question2.py
414
4.1875
4
# program to check the validity of a time entered by the user as a set of three integers #shimabukuro kenneth #28 february 2014 hours = eval(input("Enter the hours:""\n")) minutes = eval(input("Enter the minutes:""\n")) seconds = eval(input("Enter the seconds:""\n")) if (0 <= hours <= 23) and (0 <= minutes <= 59) and (0 <= seconds <= 59): print ("Your time is valid.") else: print ("Your time is invalid.")
2528eef32d526d21201252ed2256a842c5f2216c
NikheelP/Spark_
/spark/widget/sample/sample_color_variable.py
9,494
3.625
4
class COLOR_VARIABLE_CHILD(): def __init__(self, value): self._color_value = value @property def set_value(self): ''' return the color value ''' return self._color_value def get_value(self): ''' return the color value ''' return self._color_value @set_value.setter def set_value(self, value): ''' setting up the new value @param value: list value @type value: list ''' if not isinstance(value, list): raise Exception('value is not a list please Define the List') self._color_value = value return self._color_value class COLOR_VARIABLE(): ''' this is the color variable which will be include all the related to color in the widget can be get and set new value to change the widget color ''' def __init__(self): # 18color self.red_color = COLOR_VARIABLE_CHILD(value=[254, 0, 2]) self.blue_color = COLOR_VARIABLE_CHILD(value=[1, 0, 254]) self.green_color = COLOR_VARIABLE_CHILD(value=[1, 154, 1]) self.orange_color = COLOR_VARIABLE_CHILD(value=[255, 154, 0]) self.yellow_color = COLOR_VARIABLE_CHILD(value=[255, 255, 1]) self.pink_color = COLOR_VARIABLE_CHILD(value=[255, 205, 208]) self.purple_color = COLOR_VARIABLE_CHILD(value=[152, 0, 134]) self.violet_color = COLOR_VARIABLE_CHILD(value=[255, 131, 243]) self.turquoise_color = COLOR_VARIABLE_CHILD(value=[0, 225, 209]) self.gold_color = COLOR_VARIABLE_CHILD(value=[255, 216, 1]) self.lime_color = COLOR_VARIABLE_CHILD(value=[1, 255, 1]) self.aqua_color = COLOR_VARIABLE_CHILD(value=[99, 255, 255]) self.navy_color = COLOR_VARIABLE_CHILD(value=[2, 0, 133]) self.coral_color = COLOR_VARIABLE_CHILD(value=[255, 128, 77]) self.teal_color = COLOR_VARIABLE_CHILD(value=[1, 129, 132]) self.brown_color = COLOR_VARIABLE_CHILD(value=[193, 37, 40]) self.white_color = COLOR_VARIABLE_CHILD(value=[255, 255, 255]) self.black_color = COLOR_VARIABLE_CHILD(value=[80, 80, 80]) basic_font_radius_size = 10 basic_font_weight = 'bold' #make a object color self.nurbsCurve_color = self.orange_color self.dynamicConstraint_color = self.green_color self.transform_color = self.blue_color self.mesh_color = self.yellow_color self.ncloth_color = self.pink_color self.locator_color = self.pink_color self.camera_color = self.violet_color self.nucleus_color = self.red_color self.clusterHandle_color = self.lime_color self.light_color = self.brown_color #CFX COLOR self.nCloth_color = self.lime_color self.nRigit_color = self.orange_color self.nConstraint_color = self.yellow_color self.nHair_color = self.red_color self.folical_color = self.gold_color # PUSHBUTTON BASIC 1 COLOR self.pushbutton_basic_1_background_color = COLOR_VARIABLE_CHILD(value=[117, 138, 255]) self.pushbutton_basic_1_color = COLOR_VARIABLE_CHILD(value=[255, 255, 255]) self.pushbutton_basic_1_font_size = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_1_font_weight = COLOR_VARIABLE_CHILD(value=basic_font_weight) self.pushbutton_basic_1_font_radius = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_1_background_hover_color = COLOR_VARIABLE_CHILD(value=[0, 145, 80]) # PUSHBUTTON BASIC 2 COLOR self.pushbutton_basic_2_background_color = COLOR_VARIABLE_CHILD(value=[254, 82, 147]) self.pushbutton_basic_2_color = COLOR_VARIABLE_CHILD(value=[255, 255, 255]) self.pushbutton_basic_2_font_size = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_2_font_weight = COLOR_VARIABLE_CHILD(value=basic_font_weight) self.pushbutton_basic_2_font_radius = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_2_background_hover_color = COLOR_VARIABLE_CHILD(value=[189, 61, 110]) # PUSHBUTTON BASIC 3 COLOR self.pushbutton_basic_3_background_color = COLOR_VARIABLE_CHILD(value=[250, 37, 71]) self.pushbutton_basic_3_color = COLOR_VARIABLE_CHILD(value=[255, 255, 255]) self.pushbutton_basic_3_font_size = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_3_font_weight = COLOR_VARIABLE_CHILD(value=basic_font_weight) self.pushbutton_basic_3_font_radius = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_3_background_hover_color = COLOR_VARIABLE_CHILD(value=[198, 28, 57]) # PUSHBUTTON BASIC 4 COLOR self.pushbutton_basic_4_background_color = COLOR_VARIABLE_CHILD(value=[255, 132, 61]) self.pushbutton_basic_4_color = COLOR_VARIABLE_CHILD(value=[255, 255, 255]) self.pushbutton_basic_4_font_size = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_4_font_weight = COLOR_VARIABLE_CHILD(value=basic_font_weight) self.pushbutton_basic_4_font_radius = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_4_background_hover_color = COLOR_VARIABLE_CHILD(value=[202, 102, 48]) # PUSHBUTTON BASIC 5 COLOR self.pushbutton_basic_5_background_color = COLOR_VARIABLE_CHILD(value=[104, 99, 160]) self.pushbutton_basic_5_color = COLOR_VARIABLE_CHILD(value=[255, 255, 255]) self.pushbutton_basic_5_font_size = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_5_font_weight = COLOR_VARIABLE_CHILD(value=basic_font_weight) self.pushbutton_basic_5_font_radius = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_5_background_hover_color = COLOR_VARIABLE_CHILD(value=[136, 131, 211]) # PUSHBUTTON BASIC 6 COLOR self.pushbutton_basic_6_background_color = COLOR_VARIABLE_CHILD(value=[0, 143, 254]) self.pushbutton_basic_6_color = COLOR_VARIABLE_CHILD(value=[255, 255, 255]) self.pushbutton_basic_6_font_size = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_6_font_weight = COLOR_VARIABLE_CHILD(value=basic_font_weight) self.pushbutton_basic_6_font_radius = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_6_background_hover_color = COLOR_VARIABLE_CHILD(value=[0, 105, 186]) # PUSHBUTTON BASIC 7 COLOR self.pushbutton_basic_7_background_color = COLOR_VARIABLE_CHILD(value=[188, 188, 188]) self.pushbutton_basic_7_color = COLOR_VARIABLE_CHILD(value=[255, 255, 255]) self.pushbutton_basic_7_font_size = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_7_font_weight = COLOR_VARIABLE_CHILD(value=basic_font_weight) self.pushbutton_basic_7_font_radius = COLOR_VARIABLE_CHILD(value=basic_font_radius_size) self.pushbutton_basic_7_background_hover_color = COLOR_VARIABLE_CHILD(value=[220, 220, 220]) self.background_color = COLOR_VARIABLE_CHILD(value=[0, 255, 132]) self.new_background_color = COLOR_VARIABLE_CHILD(value=[0, 39, 46]) self.background_another_color = COLOR_VARIABLE_CHILD(value=[43, 82, 112]) self.color = COLOR_VARIABLE_CHILD(value=[0, 255, 0]) # TITLE LABEL self.title_label = COLOR_VARIABLE_CHILD(value=[0, 255, 0]) # MINIMIZE COLOR self.minimize_color = COLOR_VARIABLE_CHILD(value=[0, 255, 0]) self.minimize_hover_color = COLOR_VARIABLE_CHILD(value=[20, 145, 1]) # MAXIMIZE COLOR self.maximize_color = COLOR_VARIABLE_CHILD(value=[255, 255, 0]) self.maximize_hover_color = COLOR_VARIABLE_CHILD(value=[166, 166, 0]) # CLOSE COLOR self.close_color = COLOR_VARIABLE_CHILD(value=[255, 0, 0]) self.close_hover_color = COLOR_VARIABLE_CHILD(value=[171, 0, 0]) # DOCK WIDGET COLOR self.dockwidget_color = COLOR_VARIABLE_CHILD(value=[0, 255, 0]) self.dockwidget_hover_color = COLOR_VARIABLE_CHILD(value=[255, 85, 0]) self.splitter_background_color = COLOR_VARIABLE_CHILD(value=[255, 85, 0]) # USER TOOL COLOR self.user_tool_color = COLOR_VARIABLE_CHILD(value=[74, 74, 74]) self.user_help_color = COLOR_VARIABLE_CHILD(value=[74, 74, 74]) def color_list(self): color_list = [[255, 0, 0], (0,255,0), (0,0,255), (255,255,0), (0,255,255), (255,0,255), (192,192,192), (128,128,128), (128,0,0), (128,128,0), (0,128,0), (128,0,128), (0,128,128), (0,0,128), (128,0,0), (139,0,0), (165,42,42), (178,34,34), (220,20,60), (255,0,0), (255,99,71), (255,127,80), (205,92,92), (240,128,128), (233,150,122), (250,128,114), (255,160,122), (255,69,0), (255,140,0), (255,165,0), (255,215,0)] return color_list def bright_color(self): return [self.red_color, self.blue_color, self.green_color, self.orange_color, self.yellow_color, self.pink_color, self.purple_color, self.violet_color, self.turquoise_color, self.gold_color, self.lime_color, self.aqua_color, self.navy_color, self.coral_color, self.teal_color, self.brown_color, self.white_color, self.black_color]
96729bbbf26ddbb2c41a592e8bd426523f3d4b9b
Arthurmf01/PROGRAMING-WITH-PYTHON-
/Exercices
347
3.8125
4
#!/usr/bin/env python3 # -*- coding: utf-8 -*- """ Created on Fri Oct 26 14:35:38 2018 @author: arthurmaroquenefroissart """ #%% def linear(number, lst): for i in range(len(lst)): if number == lst[i]: return i return None def hello(): name = input("What's your name ? ") print("Hello " + name) #%%
e20ca2cb2b36e99f94bb9ef206851cd49793915c
vilaron/Complejidad2020II
/clase_2/bfs.py
779
3.625
4
#cada posicion de la lista representa a un nodo y lo que hay en esa posicion representa los nodos adyacentes a ese nodo #lista de adj, visitados y cola o queue #grafo no dirigido adj = [ [1,2], [0, 3 , 4], [0 ,4 , 5], [1, 6], [1 , 2 , 6 ], [2 ,6], [3 , 4 , 5] ] visitados = [False] * len(adj) #FiFo (First in , First out) #se comporta como cola queue = [] #punto de inicio start = 0 #se lee por niveles def bfs(): visitados[start] = True queue.append(start) while queue: #se borra el elemento del principio y lo guardas a la misma vez en v v = queue.pop(0) print(v) for u in adj[v]: if visitados[u] == False: visitados[u] = True queue.append(u) bfs()
27c7733ac3ab2c6ee367eb537c65b76ffb73a5c3
ryzzhov-al/TaskStepik
/Taskstepik.py
3,122
4.09375
4
""" Напишите программу, которая выводит часть последовательности 1 2 2 3 3 3 4 4 4 4 5 5 5 5 5 ... (число повторяется столько раз, чему равно). На вход программе передаётся неотрицательное целое число n — столько элементов последовательности должна отобразить программа. На выходе ожидается последовательность чисел, записанных через пробел в одну строку. Например, если n = 7, то программа должна вывести 1 2 2 3 3 3 4. n = int(input()) a = [] i = 0 while len(a) < n: a += [i] * i print("Выводим а:",a) i += 1 print('Выводим i:',i) print("Выводим итог",*a[:n]) ''' L = [1, 2, 3, 4, 5] -- *выыодит все элементы списка через пробел print(*L) print(*L, sep=', ') print(*L, sep=' -> ') ''' """ #-----------------------# """ Напишите функцию modify_list(l), которая принимает на вход список целых чисел, удаляет из него все нечётные значения, а чётные нацело делит на два. Функция не должна ничего возвращать, требуется только изменение переданного списка, например: lst = [1, 2, 3, 4, 5, 6] print(modify_list(lst)) # None print(lst) # [1, 2, 3] modify_list(lst) print(lst) # [1] lst = [10, 5, 8, 3] modify_list(lst) print(lst) # [5, 4] Также функция не должна осуществлять ввод/вывод информации. """ """ def modify_list(l): i = 0 while i < len(l): if l[i]%2 != 0: l.remove(l[i]) else: l[i] = l[i]//2 i += 1 return (l) lst = [0, 1, 2,7,8] print(modify_list(lst)) """ """ Напишите программу, которая принимает на вход список чисел и число, после чего выводит все позиции, на которых это число встречается в переданном списке. Позиции в списке нумеруются с нуля. Если число x не найдено в списке, нужно вывести строку "None" (без кавычек, с большой буквы). """ """ a = input().split() #пользовательски ввод разбиваем методом split(разбивает строку с помощью указанного спецсимвола и возвращает список подстрок) b = input() if b not in a: print("None") else: for i in range(len(a)): #проверям число по позиции в списке if a[i] == b: print(i) """
26116f1b8924c50c70a09e215e4386f5fc81edb3
scrypti/Udacity
/ArtificialIntelligence/Localization/kalman_filters.py
1,931
3.703125
4
from math import * import warnings # make predictions about future positions # measurement meant updating our belief (and renormalizing our distribution). # motion meant keeping track of where all of our probability "went" when we moved # Kalman Filter: # measurement update: bayes rule (multiplication) # motion update prediction: total probability (addition) def f(m, v, x): """ gaussian computation (deprecated) :param m: mean (mu) :param v: variance (sigma squared) :param x: x """ return 1 / sqrt(2.0 * pi * v) * exp(-0.5 * (x - m)**2 / v) def update(m1, v1, m2, v2): """ measurement update step (kalman filter) updates mean and variance based on previous measurement and new observation :param m1: previous mean (mu) :param v1: previous variance (sigma^2) :param m2: observed mean (mu) :param v2: observed variance (sigma^2) :return: new mean and variance [m, v] """ m = (v1 * m2 + v2 * m1) / (v1 + v2) v = 1. / (1. / v1 + 1. / v2) return [m, v] def predict(m1, v1, m2, v2): """ predicts mean and variance based on movement :param m1: previous mean (mu) :param v1: previous variance (sigma^2) :param m2: observed mean (mu) :param v2: observed variance (sigma^2) :return: new mean and variance [m, v] """ m = m1 + m2 v = v1 + v2 return [m, v] def main(): measurements = [5., 6., 7., 9., 10.] motion = [1., 1., 2., 1., 1.] measurement_sig = 4. motion_sig = 2. mu = 0. sig = 10000. result = [mu, sig] for i in range(len(measurements)): # sense result = update(result[0], result[1], measurements[i], measurement_sig) print('update: ', result) # move result = predict(result[0], result[1], motion[i], motion_sig) print('predict: ', result) # print(update(10, 4, 12, 4)) if __name__ == "__main__": main()
2bab9a82b515cff5eaa7f1e179987b026f2f3d09
Liza333/Python
/laba 1/Task9.py
1,508
3.625
4
# Напишите программу, имитирующую работу банкомата. Выберите # структуру данных для хранения купюр разного достоинства в заданном # количестве. При вводе пользователем запрашиваемой суммы денег, # скрипт должен вывести на консоль количество купюр подходящего # достоинства. Если имеющихся денег не хватает, то необходимо # напечатать сообщение «Операция не может быть выполнена!». # Например, при сумме 5370 рублей на консоль должно быть выведено # «5*1000 + 3*100 + 1*50 + 2*10». import os os.startfile(r'say_hi.jpg') money_in_stock = {1000: 2, 500: 2, 200: 10, 100: 5, 50: 5, 10: 20} result = {1000: 0, 500: 0, 200: 0, 100: 0, 50: 0, 10: 0} money = int(input('Введите сумму, которую хотите снять: ')) for key in money_in_stock.keys(): current = money // key # деление без остатка if current > money_in_stock[key]: money = money - (money_in_stock[key] * key) result[key] = money_in_stock[key] else: money = money % key result[key] = current print("Your money : " + str(sum([k * v for k, v in zip(result.keys(), result.values())]))) print(result)
1110db582484a26a41aa336f6dfb3d0b3f912b3d
sross1418/PythonExamples
/Turtle Example.py
3,579
4.625
5
# turtle documentation: https://docs.python.org/3/library/turtle.html # Challenges: add a command to make the turtle draw a circle of a specified diameter # add a command to change the turtle's color # add a command to tell the turtle to move to a certain set of coordinates import turtle t = turtle.Turtle() def turtleStar(size): for i in range(5): t.forward(size) t.right(144) def turtleSquare(sideLength): for i in range(4): t.forward(sideLength) t.right(90) def turtleCircle(radius): circleConstant = 0.00873438728 t.speed(0) for i in range(360): t.forward(radius * circleConstant) t.right(1) if i == 180: print(t.position()) t.speed(6) def askInput(): # Keep asking for input until they give us valid input # we exit the function when we return some value, which will only happen when the input is validated. while True: print("What should the turtle do?: ") # Ask for user input, change it to all lowercase, and split wherever there's a space, leaving us with a list # of the words or numbers that the user entered userInput = input().lower().split() # limit them to only 2 words, a command and an argument if len(userInput) > 2: print("Too many arguments. Please type a command and a number") else: # if they only say exit, provide a blank argument and return the pair if len(userInput) == 1: return (userInput[0], "") # otherwise save the first element of their input as the command and the second as the argument else: # we need to try to convert the argument from a string to a float. # if we don't, we will get an error if we try something like t.forward("apple") down the line try: return (userInput[0], float(userInput[1])) # this happens if the above 'try' block fails # meaning they put an argument that could not be converted properly to a float. # if we don't do this and they enter something that can't be converted, the program will crash except: print("Please enter a number after the command.") # call the appropriate function based on the user's command, using the argument that they gave us as well def doCommand(command, argument): if command == "exit" or command == "quit": exit() elif command == "left" or command == "l": t.left(int(argument)) elif command == "right" or command == "r": t.right(int(argument)) elif command == "forward" or command == "f": t.forward(int(argument)) elif command == "star" or command == "s": turtleStar(int(argument)) elif command == "circle": t.circle(int(argument)) elif command == "square": turtleSquare(int(argument)) else: print("Please say 'forward', 'left', 'right', or 'star' in addition to a number. Or say 'exit' to quit.") def welcome(): print("""Welcome to the interactive turtle program! Please give the turtle instructions You can tell the turtle to move forward, turn left or right, or draw a star of a certain size For example, you can say 'forward 15' 'left 90' or 'star 50'""") welcome() # repeat the input -> command loop until they quit while True: userInput = askInput() # pass the command and argument we got to the doCommand function doCommand(userInput[0], userInput[1])
9870fde109c97a853ccb0268a165038bf2e6cc3c
evad37/python-bits-and-pieces
/Calculator.py
3,415
3.8125
4
""" Calculator.py A calculator that takes input as a string from the user, and recursively solves the given problem. Reports "divide by zero" errors and bracket mismatch errors. """ def add(a,b): if a is None or b is None: return None return a + b def minus(a,b): if a is None or b is None: return None return a - b def times(a,b): if a is None or b is None: return None return a * b def divide(a,b): if b == 0: print("Divide by zero error!") return None elif a is None or b is None: return None return a / b def power(a,b): if a is None or b is None: return None return pow(a, b) def calculator(problem): if problem.count("(") != problem.count(")"): print("Bracket count mismatch error!") return None elif "(" in problem: lastOpenBracket = problem.rindex("(") nextCloseBracket = problem.find(")", lastOpenBracket) if nextCloseBracket == -1: print("Bracket order mismatch error!") return None innerTotal = calculator(problem[lastOpenBracket+1:nextCloseBracket]) if innerTotal is None: return None # Convert to string as a float (not exponential for small numbers) innerPart = format(innerTotal, 'f') leftPart = problem[0:lastOpenBracket] if len(leftPart) > 0 and not leftPart[-1] in "+-*/^(": leftPart += "*" rightPart = problem[nextCloseBracket+1:] if len(rightPart) > 0 and not rightPart[0] in "+-*/^)": rightPart = "*" + rightPart return calculator(leftPart+innerPart+rightPart) elif "+" in problem: parts = problem.split("+") subtotal = calculator(parts[0]) for i in range(1, len(parts)): subtotal = add(subtotal, calculator(parts[i])) return subtotal elif "-" in problem: parts = problem.split("-") subtotal = calculator(parts[0]) for i in range(1, len(parts)): subtotal = minus(subtotal, calculator(parts[i])) return subtotal elif "*" in problem: parts = problem.split("*") subtotal = calculator(parts[0]) for i in range(1, len(parts)): subtotal = times(subtotal, calculator(parts[i])) return subtotal elif "/" in problem: parts = problem.split("/") subtotal = calculator(parts[0]) for i in range(1, len(parts)): subtotal = divide(subtotal, calculator(parts[i])) return subtotal elif "^" in problem: parts = problem.split("^") subtotal = calculator(parts[0]) for i in range(1, len(parts)): subtotal = power(subtotal, calculator(parts[i])) return subtotal elif problem == "": print("Error! Operators must be used between numbers.") else: return float(problem) result = None print("Enter problem(s), or 'Q' to quit. Use numbers and the symbols + - * / ^ ( ) only.") while True: calculation = input("> ") if calculation.upper() == 'Q': break if not(result is None) and calculation[0] in "+-*/^": calculation = format(result, 'f') + calculation result = calculator(calculation) if not(result is None): print("=", result)
a0a054eee73c04771deffdad9b789a80883b2bac
RavikrianGoru/py_durga
/telsuko_one/py_basics/10_prime_check.py
206
3.96875
4
# num = int(input("Enter positive number: ")) num = 83 num = int(num/2) for i in range(2, num): if num % i == 0: print("Not prime") break else: print("Prime") print("Bye")
ca7f48d6367d4eabc5706b88f3b30b12852a8921
apitman91/problem-solving
/project-euler/p1.py
160
3.859375
4
def p1(n): """Sums all multiples of 3 and 5 less than n""" set = [i for i in range(1, n) if i % 3 == 0 or i% 5 ==0] return sum(set) print(p1(1000))
419b22f3679fcda55083a82c19a35b034b235352
hyphenliu/TensorFlow_Google_Practice
/Deep_Learning_with_TensorFlow/1.4.0/Chapter04/2. 学习率的设置.py
3,524
3.734375
4
# #### 假设我们要最小化函数 $y=x^2$, 选择初始点 $x_0=5$ # #### 1. 学习率为1的时候,x在5和-5之间震荡。 import tensorflow as tf TRAINING_STEPS = 10 LEARNING_RATE = 1 x = tf.Variable(tf.constant(5, dtype=tf.float32), name="x") y = tf.square(x) train_op = tf.train.GradientDescentOptimizer(LEARNING_RATE).minimize(y) with tf.Session() as sess: sess.run(tf.global_variables_initializer()) for i in range(TRAINING_STEPS): sess.run(train_op) x_value = sess.run(x) print("After %s iteration(s): x%s is %f."% (i+1, i+1, x_value)) # #### 2. 学习率为0.001的时候,下降速度过慢,在901轮时才收敛到0.823355。 TRAINING_STEPS = 1000 LEARNING_RATE = 0.001 x = tf.Variable(tf.constant(5, dtype=tf.float32), name="x") y = tf.square(x) train_op = tf.train.GradientDescentOptimizer(LEARNING_RATE).minimize(y) with tf.Session() as sess: sess.run(tf.global_variables_initializer()) for i in range(TRAINING_STEPS): sess.run(train_op) if i % 100 == 0: x_value = sess.run(x) print("After %s iteration(s): x%s is %f."% (i+1, i+1, x_value)) # #### 3. 使用指数衰减的学习率,在迭代初期得到较高的下降速度,可以在较小的训练轮数下取得不错的收敛程度。 TRAINING_STEPS = 100 global_step = tf.Variable(0) LEARNING_RATE = tf.train.exponential_decay(0.1, global_step, 1, 0.96, staircase=True) x = tf.Variable(tf.constant(5, dtype=tf.float32), name="x") y = tf.square(x) train_op = tf.train.GradientDescentOptimizer(LEARNING_RATE).minimize(y, global_step=global_step) with tf.Session() as sess: sess.run(tf.global_variables_initializer()) for i in range(TRAINING_STEPS): sess.run(train_op) if i % 10 == 0: LEARNING_RATE_value = sess.run(LEARNING_RATE) x_value = sess.run(x) print("After %s iteration(s): x%s is %f, learning rate is %f."% (i+1, i+1, x_value, LEARNING_RATE_value)) # After 1 iteration(s): x1 is -5.000000. # After 2 iteration(s): x2 is 5.000000. # After 3 iteration(s): x3 is -5.000000. # After 4 iteration(s): x4 is 5.000000. # After 5 iteration(s): x5 is -5.000000. # After 6 iteration(s): x6 is 5.000000. # After 7 iteration(s): x7 is -5.000000. # After 8 iteration(s): x8 is 5.000000. # After 9 iteration(s): x9 is -5.000000. # After 10 iteration(s): x10 is 5.000000. # After 1 iteration(s): x1 is 4.990000. # After 101 iteration(s): x101 is 4.084646. # After 201 iteration(s): x201 is 3.343555. # After 301 iteration(s): x301 is 2.736923. # After 401 iteration(s): x401 is 2.240355. # After 501 iteration(s): x501 is 1.833880. # After 601 iteration(s): x601 is 1.501153. # After 701 iteration(s): x701 is 1.228794. # After 801 iteration(s): x801 is 1.005850. # After 901 iteration(s): x901 is 0.823355. # After 1 iteration(s): x1 is 4.000000, learning rate is 0.096000. # After 11 iteration(s): x11 is 0.690561, learning rate is 0.063824. # After 21 iteration(s): x21 is 0.222583, learning rate is 0.042432. # After 31 iteration(s): x31 is 0.106405, learning rate is 0.028210. # After 41 iteration(s): x41 is 0.065548, learning rate is 0.018755. # After 51 iteration(s): x51 is 0.047625, learning rate is 0.012469. # After 61 iteration(s): x61 is 0.038558, learning rate is 0.008290. # After 71 iteration(s): x71 is 0.033523, learning rate is 0.005511. # After 81 iteration(s): x81 is 0.030553, learning rate is 0.003664. # After 91 iteration(s): x91 is 0.028727, learning rate is 0.002436.
a9306f484cad43c8ea224c51a8811fbbc336f0a2
hshafy/semtest
/src/main.py
2,463
3.75
4
"""Main""" import csv import sys def read_csv(filename): """ Read CSV data and return a list with reocrds """ # TODO: get filename from script argument and check path and validate data = [] with open(filename, newline='') as file: reader = csv.DictReader(file) try: for row in reader: data.append(process_one_record(row)) except csv.Error as exp: sys.exit('file {}, line {}: {}'.format(filename, reader.line_num, exp)) return data def process_one_record(record): """ Process each record to update data in one take while reading """ # TODO: check safety of this conversion cost = float(record['Cost']) if cost != 0: record['ROI'] = (float(record['Revenue']) - cost) / cost else: record['ROI'] = float(record['Revenue']) return record def filter_by_key_value(data, key, value): """ Filter data by key value """ return list(filter(lambda d: d[key] == value, data)) def print_top_kewyord_by_roi(data, company_name, limit): """ Prints the top number of keywords for a company """ print('') filtered_data = filter_by_key_value(data, 'Company', company_name) if filtered_data is not None: print('Found {} {} records.'.format(len(filtered_data), company_name)) else: print('No data found for {}.'.format(company_name)) sorted_by_roi = sorted(filtered_data, key=lambda k: k["ROI"], reverse=True) print('Top {} keywords by ROI for {}'.format(limit, company_name)) top_10 = sorted_by_roi[0:limit-1] for item in top_10: print('Keyword: {0}, ROI: {1:.2f}'.format(item['Search keyword'], item['ROI'])) def main(): """ main """ if len(sys.argv) < 2: print('Please provide filename as a first argument') return provided_filename = sys.argv[1] data = read_csv(provided_filename) if not data: print('No data found') return print('Found {} records.'.format(len(data))) print_top_kewyord_by_roi(data, 'GetYourGuide', 10) # TODO: get list or remanining company names from data print_top_kewyord_by_roi(data, 'Company A', 10) print_top_kewyord_by_roi(data, 'Company B', 10) print_top_kewyord_by_roi(data, 'Company C', 10) print_top_kewyord_by_roi(data, 'Company D', 10) print_top_kewyord_by_roi(data, 'Company E', 10) if __name__ == '__main__': main()
6fcec8ce9310565eada36790a1726d9784f76416
rewonderful/MLC
/src/归并排序.py
1,290
4
4
#!/usr/bin/env python # _*_ coding:utf-8 _*_ def merge(nums): if len(nums) < 2: return nums mid = len(nums)//2 leftpart = merge(nums[:mid]) rightpart = merge(nums[mid:]) return mergesort(leftpart,rightpart) def mergesort(left,right): result = [] i = 0 j = 0 while i<len(left) and j < len(right): if left[i] < right[j]: result.append(left[i]) i += 1 else: result.append(right[j]) j += 1 if i < len(left): result.extend(left[i:]) if j < len(right): result.extend(right[j:]) return result def merge7(nums): if len(nums) < 2: return nums mid = len(nums)//2 left = merge7(nums[:mid]) right = merge7(nums[mid:]) return merge_sort7(left,right) def merge_sort7(left,right): dummy = [] i,j = 0,0 while i < len(left) and j < len(right): if left[i] <= right[j]: dummy.append(left[i]) i += 1 else: dummy.append(right[j]) j += 1 if i < len(left): dummy.extend(left[i:]) if j < len(right): dummy.extend(right[j:]) return dummy if __name__ == '__main__': print(merge7([9,8,7,6,5,4,3,2,1,0])) #print(mergesort([1,5,7],[2,4,6]))
3079ae52457f06417737d1a195c4e110e8142cc7
Endlex-net/Demo_of_design_patterns_by_python
/proxy_pattern/demo.py
1,318
3.578125
4
from abc import ABC, abstractmethod class Subject(ABC): """主题类""" @abstractmethod def request(self): pass class RealSubject(Subject): def request(self): raise NotImplementedError class ProxySubject(Subject): def request(self): raise NotImplementedError class TonyReception(RealSubject): def __init__(self, name, phone_number): self.phone_number = phone_number self.name = name def request(self, parcel_content): print(f"货物主任:{self.name}, 手机号: {self.phone_number}") print(f"接收到一个包裹,包裹内容是: {parcel_content}") class WendyReception(ProxySubject): """Wendy代收""" def __init__(self, name, receiver: TonyReception): self.name = name self.receiver: TonyReception = receiver def request(self, parcel_content): print(f"我是{self.receiver.name} 的朋友, 我来帮他代收快递!") if self.receiver: self.receiver.request(parcel_content) print(f"代收人: {self.name}") if __name__ == "__main__": tony = TonyReception("Tony", "123424") print("Tony接收:") tony.request("雪地靴") print() print("Wendy代收:") wendy = WendyReception("Wendy", tony) wendy.request("雪地靴")
82c722a169742a41e145c7c53dacd7a25011503e
jmshih/clothes_detector
/download_images.py
862
3.5
4
import argparse import csv import os import sys from urllib import request def parse_args(): parser = argparse.ArgumentParser(description='script to download images') parser.add_argument('--file', help='file containing image urls') parser.add_argument('--output', help='directory to which to write images') return parser.parse_args() def main(): args = parse_args() if not os.path.exists(args.output): os.makedirs(args.output) with open(args.file, newline='') as csvfile: reader = csv.reader(csvfile, delimiter=',') for row in reader: url = row[0] outfn = os.path.join(args.output, os.path.basename(url)) if not os.path.exists(outfn): print(outfn) request.urlretrieve(url, filename=outfn) if __name__ == '__main__': sys.exit(main())
1e970fb7e9f38b4a869ebe187a606e93b829d97a
lovepreetbegu/lovepreetbegu
/3rd programme interchang2.py
138
4
4
X = input("enter value of x ") Y = input("enter value of y") temp = X X=Y Y = temp print("value of X",X) print("value of Y",Y)
24ce85ab2f75d6744e9226d214a21d06c0d95346
zhumike/python_test
/算法/冒泡排序.py
1,500
3.796875
4
class solutionMethod: def bubble_sort(self,arr): n = len(arr) # 遍历所有数组元素 for i in range(n): for j in range(0, n - i - 1): if arr[j] > arr[j + 1]: arr[j], arr[j + 1] = arr[j + 1], arr[j] #改良版本 """ 因为冒泡排序必须要在最终位置找到之前不断 交换数据项,所以它经常被认为是最低效的排 序方法。这些 “浪费式” 的交换操作消耗了 许多时间。但是,由于冒泡排序要遍历整个 未排好的 部分,它可以做一些大多数排序方 法做不到的事。尤其是如果在整个排序过程中 没有交换,我们就可断定列表已经排好。因此 可改良冒泡排序,使其在已知列表排好的情况 下提前结束。这就是说,如果一个列表只需要几次遍 历就可排好,冒泡排序就占有优势:它可以在 发现列表已排好时立刻结束。 """ # 冒泡排序改良版本 def bubbleSort(alist): n = len(alist) exchange = False for i in range(n-1, 0, -1): for j in range(0, i): if alist[j] > alist[j+1]: alist[j], alist[j+1] = alist[j+1], alist[j] exchange = True # 如果发现整个排序过程中没有交换,提前结束 if not exchange: break return alist if __name__=="__main__": demo = solutionMethod() arr = [3, 2, 0, 7, 4] demo.bubble_sort(arr) print(arr)
73b0560c33f081fd72ea3cf7ba6561b4f343b544
elaneyc/wallbreakers
/week4/stacks/valid_parens.py
717
3.59375
4
class Solution(object): def isValid(self, s): """ :type s: str :rtype: bool """ stack = [] # Helper method to return opening brace def getOpen(p): if p == ")": return "(" elif p == "]": return "[" elif p == "}": return "{" for p in s: if p == "(" or p == "{" or p == "[": stack.append(p) else: try: open = stack.pop() if open != getOpen(p): return False except: return False return len(stack) == 0
741d61f62f7d1cc625916bff1706af794780c984
tope628/holbertonschool-higher_level_programming
/0x07-python-test_driven_development/0-add_integer.py
702
4.53125
5
#!/usr/bin/python3 """Add Integer Module This module takes 2 integers and/ or floats, and adds them. otherwise raise a TypeError exception with the message a must be an integer or b must be an integer. Floats must be casted into integers. """ def add_integer(a, b): """ Args: a (int): The first parameter. b (int): The second parameter. Returns: int: Addition of a and b. TypeError otherwise. """ if type(a) is float: a = int(a) if type(b) is float: b = int(b) if type(a) is not int: raise TypeError("a must be an integer") if type(b) is not int: raise TypeError("b must be an integer") return a + b
c30ef439685a615c30d4514accf822512a3bab8e
javvidd/gitProject
/Sep_03_files_execption_summary/exception_handling.py
793
3.59375
4
# exception (errors) handling # 03-Sep - Done def division(a, b): try: print(a/b) except ZeroDivisionError as zerodv: print(f"u cant divide by ZERO - err: {zerodv}") except (TypeError, NameError) as errmsg: print(f"check yur input - err: {errmsg}") # raise errmsg # will show regular error message finally: # will always be executed in either try or except block print("finally block is executed") division(45, 15) division(45, 10) division(45, 0) division(100, "a") division(100, 2) filename = "dat/inputData.txt" try: with open(filename) as input_data: contents = input_data.read() # it will read line by line print(contents) except FileNotFoundError as noFile: print(f"filename compromised - {noFile}")
bfb046b84c0848b3bda806e96502410ad6511851
zarix908/Crossword
/model/file_reader.py
770
3.53125
4
import sys class FileReader: def read(self, file_name): try: with open(file_name, 'r') as file: return list(map(lambda el: el.strip(), file.readlines())) except FileExistsError: self.error(file_name, is_exist_error=True) except FileNotFoundError: self.error(file_name, is_exist_error=False) except UnicodeDecodeError: print("File content should be utf-8 encoded.", file=sys.stderr) exit(1) def error(self, file_name, is_exist_error): print( "File " + '\"' + file_name + '\"' + " not" + (" exist." if is_exist_error else " found.") + " Try main.py -h or --help", file=sys.stderr) exit(1)
1bfa2109139b1671a1e60e39e3f05f1c92c6d2b1
lucnortiz/pooej2
/modulo_helado.py
932
3.53125
4
class Helado: __gramos= 0 __sabores= [] def __init__(self,gr,sbr): self.__gramos= gr self.__sabores= sbr def __str__(self): cadenaHelado = 'Gramos: '+ str(self.__gramos) for i in range(len(self.__sabores)): cadenaHelado += '\nGusto: '+ self.__sabores[i].get_nombre() return cadenaHelado def get_gramos(self): return self.__gramos def get_cant_sabores(self): return len(self.__sabores) def cargar_lista_codigos(self): lista_aux= [] for i in range(len(self.__sabores)): lista_aux.append(self.__sabores[i].get_numero()) return lista_aux def cargar_lista_nombres(self): lista_aux= [] for i in range(len(self.__sabores)): lista_aux.append(self.__sabores[i].get_nombre()) return lista_aux
9b1a4963f5ca7054de39a09508e8b2685b0e1b81
akhilakr06/pythonluminar
/data_collections/list/nexting.py
150
3.71875
4
#nexting possible # l=[1,2,3,[5,6,[8,9]]] # print(l) lst=[1,2,3] lst.append(9) print(lst) lst.remove(2) print(lst) lst.clear() # del lst print(lst)
2d7e71b8f051faf614840e65225548eb31f5de9b
MiguelMontoya-R/holbertonschool-higher_level_programming
/0x0B-python-input_output/2-read_lines.py
567
3.59375
4
#!/usr/bin/python3 """[summary] """ def read_lines(filename="", nb_lines=0): """[summary] Keyword Arguments: filename {str} -- [description] (default: {""}) nb_lines {int} -- [description] (default: {0}) """ counter = 0 if nb_lines <= 0: with open(filename, 'r') as f: for line in f: print(line, end="") else: with open(filename, 'r') as f: for line in f: if counter < nb_lines: print(line, end="") counter += 1
858659c6e38706fd893a5b6eadff40ce2aaa7cf2
alexagrchkva/for_reference
/theory/14th_sprint/B.in_place_quick_sort.py
2,697
4.03125
4
# success try: 49534211, 16 мар 2021, 21:55:36, 1.532s, 29.95Mb def in_place_quick_sort(array, compare_func=None) -> None: """ Just one more version of in place quick sort algorithm. Array is sorted on place, without extra memory usage. Default sorting is ascending. @param array: Any iterable of objects with defined comparison methods @param compare_func: function of x,y returning True if x > y, esle False @return: None """ if compare_func is None: compare_func = lambda x, y: x > y def run_compare_around_pivot(from_index, to_index): pivot = array[from_index] left, right = from_index, to_index while True: while compare_func(pivot, array[left]): left += 1 while compare_func(array[right], pivot): right -= 1 if left >= right: return right array[left], array[right] = array[right], array[left] left += 1 right -= 1 def inner_in_place_quick_sort(array, from_index, to_index, compare_func): if from_index < to_index: pivot_index = run_compare_around_pivot(from_index, to_index) inner_in_place_quick_sort(array, from_index, pivot_index, compare_func=compare_func) inner_in_place_quick_sort(array, pivot_index+1, to_index, compare_func=compare_func) inner_in_place_quick_sort(array, 0, len(array) - 1, compare_func) if __name__ == '__main__': from collections import namedtuple Participant = namedtuple('Participant', ['name', 'tasks', 'penalty']) with open('input.txt') as in_file: participants_count = int(in_file.readline()) participants = [None] * participants_count data = in_file.read().split('\n') for index in range(participants_count): line = data[index].split() participants[index] = Participant( name=line[0], tasks=int(line[1]), penalty=int(line[2])) def participants_compare(participant_x, participant_y): if participant_x.tasks < participant_y.tasks: return True if participant_x.tasks > participant_y.tasks: return False if participant_x.penalty > participant_y.penalty: return True if participant_x.penalty < participant_y.penalty: return False return participant_x.name > participant_y.name in_place_quick_sort(participants, compare_func=participants_compare) with open('output.txt', 'w') as out_file: out_file.write('\n'.join(x.name for x in participants))
62b72c00290591f7171927252c435f3bcb727e8c
wjpe/EjemplosPython-Cisco
/ej13.py
134
3.640625
4
#ciclo for que imprime 2 a la X potencia pow = 1 for exp in range(16): print("2 a la potencia de ", exp, "es", pow) pow *= 2
4d50463042048bdde3cd25963ebd94a6bdd28e6a
anrl-utd/clearShallowAtEase
/Experiment/mlp_Vanilla_camera.py
3,997
3.53125
4
from keras.models import Sequential from keras.layers import Dense,Input,Lambda, Activation, add, Flatten from keras.models import Model import keras.layers as layers def define_vanilla_model_MLP(input_shape, num_classes, hidden_units = 32): """Define a normal neural network. ### Naming Convention ex: f2f1 = connection between fog node 2 and fog node 1 ### Arguments num_vars (int): specifies number of variables from the data, used to determine input size. num_classes (int): specifies number of classes to be outputted by the model hidden_units (int): specifies number of hidden units per layer in network ### Returns Keras Model object """ # IoT Node (input image) img_input_1 = Input(shape = input_shape) img_input_2 = Input(shape = input_shape) img_input_3 = Input(shape = input_shape) img_input_4 = Input(shape = input_shape) img_input_5 = Input(shape = input_shape) img_input_6 = Input(shape = input_shape) input_edge1 = add([img_input_1,img_input_2]) input_edge2 = img_input_3 input_edge3 = add([img_input_4,img_input_5]) input_edge4 = img_input_6 # edge nodes edge1 = define_MLP_architecture_edge(input_edge1, hidden_units, "edge1_output_layer") edge2 = define_MLP_architecture_edge(input_edge2, hidden_units, "edge2_output_layer") edge3 = define_MLP_architecture_edge(input_edge3, hidden_units, "edge3_output_layer") edge4 = define_MLP_architecture_edge(input_edge4, hidden_units, "edge4_output_layer") # fog node 4 fog4_input = layers.add([edge2,edge3, edge4], name = "node5_input") fog4 = define_MLP_architecture_fog_with_two_layers(fog4_input, hidden_units,"fog4_output_layer","fog4_input_layer") # fog node 3 fog3 = Lambda(lambda x: x * 1,name="node4_input")(edge1) fog3 = define_MLP_architecture_fog_with_one_layer(fog3, hidden_units, "fog3_output_layer") # fog node 2 fog2_input = layers.add([fog3, fog4], name = "node3_input") fog2 = define_MLP_architecture_fog_with_two_layers(fog2_input, hidden_units, "fog2_output_layer", "fog2_input_layer") # fog node 1 fog1 = Lambda(lambda x: x * 1,name="node2_input")(fog2) fog1 = define_MLP_architecture_fog_with_two_layers(fog1, hidden_units, "fog1_output_layer", "fog1_input_layer") # cloud node cloud = Lambda(lambda x: x * 1,name="node1_input")(fog1) cloud = define_MLP_architecture_cloud(cloud, hidden_units, num_classes) model = Model(inputs=[img_input_1,img_input_2,img_input_3,img_input_4,img_input_5,img_input_6], outputs=cloud) model.compile(loss='sparse_categorical_crossentropy', optimizer='adam', metrics=['accuracy']) return model def define_MLP_architecture_edge(edge_input, hidden_units, output_layer_name): edge_output = Dense(units=hidden_units, name=output_layer_name, activation='relu')(edge_input) return edge_output def define_MLP_architecture_fog_with_two_layers(fog_input, hidden_units, output_layer_name, input_layer_name): fog = Dense(units=hidden_units,name=input_layer_name ,activation='relu')(fog_input) fog_output = Dense(units=hidden_units,name=output_layer_name, activation='relu')(fog) return fog_output def define_MLP_architecture_fog_with_one_layer(fog_input, hidden_units, output_layer_name): fog_output = Dense(units=hidden_units,name=output_layer_name ,activation='relu')(fog_input) return fog_output def define_MLP_architecture_cloud(cloud_input, hidden_units, num_classes): cloud = Dense(units=hidden_units,name="cloud_input_layer",activation='relu')(cloud_input) cloud = Dense(units=hidden_units,name="cloud_layer_1",activation='relu')(cloud) cloud = Dense(units=hidden_units,name="cloud_layer_2",activation='relu')(cloud) cloud = Flatten()(cloud) cloud_output = Dense(units=num_classes,activation='softmax',name = "output")(cloud) return cloud_output
af113d96ad81c4c5245dee8e7cabb533fd8879c5
xxNB/sword-offer
/leetcode/heapqqq/find_median_from_data_stream.py
2,190
3.828125
4
class Heap: def __init__(self, cmp): self.cmp = cmp self.heap = [None] def __swap__(self, x, y, a): a[x], a[y] = a[y], a[x] def size(self): return len(self.heap) - 1 def top(self): return self.heap[1] if self.size() else None def append(self, num): self.heap.append(num) self.siftUp(self.size()) def pop(self): top, last = self.heap[1], self.heap.pop() if self.size(): self.heap[1] = last self.siftDown(1) return top def siftUp(self, idx): while idx > 1 and self.cmp(idx, idx / 2, self.heap): self.__swap__(idx / 2, idx, self.heap) idx /= 2 def siftDown(self, idx): while idx * 2 <= self.size(): nidx = idx * 2 if nidx + 1 <= self.size() and self.cmp(nidx + 1, nidx, self.heap): nidx += 1 if self.cmp(nidx, idx, self.heap): self.__swap__(nidx, idx, self.heap) idx = nidx else: break class MedianFinder: def __init__(self): """ Initialize your data structure here. """ self.minHeap = Heap(cmp=lambda x, y, a: a[x] < a[y]) self.maxHeap = Heap(cmp=lambda x, y, a: a[x] > a[y]) def addNum(self, num): """ Adds a num into the data structure. :type num: int :rtype: void """ if not self.maxHeap or num > -self.maxHeap.top(): self.minHeap.append(num) if self.minHeap.size() > self.maxHeap.size() + 1: self.maxHeap.append(self.minHeap.pop()) else: self.maxHeap.append( -num) if self.maxHeap.size() > self.minHeap.size(): self.minHeap.append(self.maxHeap.pop()) def findMedian(self): """ Returns the median of current data stream :rtype: float """ if self.minHeap.size() < self.maxHeap.size(): return self.maxHeap.top() else: return (self.minHeap.top() + self.maxHeap.top()) / 2.0 c = MedianFinder() c.addNum(1) c.addNum(2) c.findMedian()
08c8f99dba6fcfce683e9e49eba1e3aff7781c7d
Conanjun/Leetcode_Practice
/leetcode_543.py
2,329
4.375
4
# -*- coding: utf-8 -*- # Author: Conan0xff # Mail : [email protected] # Func : leetcode_543 from utils.BinaryTree import TreeNode ''' Diameter of Binary Tree Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root. Example: Given a binary tree 1 / \ 2 3 / \ 4 5 Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3]. ''' # *********************************************************************************************************************** class Solution(object): ''' 思路: 递归遍历每个节点,记录当前最大长度(通过某个节点的最大长度为depth of node.left + depth of node.right + 1) ''' def diameterOfBinaryTree(self, root): """ :type root: TreeNode :rtype: int """ max_diameter = 0 # 0为最小直径(只有一个结点) def depth(root): if root is None: return 0 ldep = depth(root.left) rdep = depth(root.right) nonlocal max_diameter max_diameter = max(max_diameter, ldep + rdep) return 1 + max(ldep, rdep) depth(root) return max_diameter import unittest class SolutionTest(unittest.TestCase): def setUp(self): pass def tearDown(self): pass def test_solution(self): solution = Solution() ''' 1 / \ 2 3 / \ 4 5 ''' node1 = TreeNode(1) node2 = TreeNode(2) node3 = TreeNode(3) node4 = TreeNode(4) node5 = TreeNode(5) node1.left = node2 node1.right = node3 node2.left = node4 node2.right = node5 self.assertTrue(solution.diameterOfBinaryTree(node1) == 3) ''' 1 / \ 2 3 / \ 4 5 / \ 6 7 / \ 8 9 ''' node1 = TreeNode(1) node2 = TreeNode(2) node3 = TreeNode(3) node4 = TreeNode(4) node5 = TreeNode(5) node6 = TreeNode(6) node7 = TreeNode(7) node8 = TreeNode(8) node9 = TreeNode(9) node1.left = node2 node1.right = node3 node2.left = node4 node2.right = node5 node4.left = node6 node6.left = node8 node5.right = node7 node7.right = node9 self.assertTrue(solution.diameterOfBinaryTree(node1) == 6) if __name__ == "__main__": unittest.main()
3b561c5a7281736458316a16aaf5fc5db9526646
Inkatha/PythonPluralsight
/python-scripts/phoneEmailScraper.py
663
3.578125
4
#! python3 import re, pyperclip # TODO: Create a regex for phone numbers re.compile(r''' # 415-555-0000, 555-0000, (415) 555-0000, 555-000 ext 12345, ext.12345, x.12345 ((\d\d\d)|(\(\d\d\d)))? #area code (optional) (\s|-) # first separator \d\d\d # first 3 digits - # separator \d\d\d\d # last 4 digits (((ext(\.)?\s|x) # extension (optional (\d{2,5})))? # Extension number (optional) ''', re.VERBOSE) # TODO: Create a regex object for email addresses emailRegex = re.compile(r''' ''') # TODO: Get the text off the clipboard # TODO: Extract the email/phone from this text # TODO: Copy the extracted email/phone to the clipboard
aae92bf397af6734a10f169bcde2e12c7bf4a4e5
malaggang2/project_euler
/problem_41~80/problem_41.py
959
3.765625
4
# Problem_41 # Pandigital prime # We shall say that an n-digit number is pandigital if it makes use of all the # digits 1 to n exactly once. For example, 2143 is a 4-digit pandigital and is also prime. # # What is the largest n-digit pandigital prime that exists? import time def is_prime(n): if n == 1: return False for d in range(2, int(n**0.5) + 1): if n % d == 0: return False return True def is_pandigital(n): for d in range(1, len(str(n))+1): if str(n).count(str(d)) != 1: return False return True start_time = time.time() for i in range(7654321, 7123456, -1): if is_prime(i) and is_pandigital(i): print(i) break print("%.6f seconds" % (time.time() - start_time)) # from itertools import permutations # t1 = time.time() # print(max([int(''.join(i)) for i in permutations('1234567') if is_prime(int(''.join(i)))])) # print("%.6f seconds" % (time.time() - t1))
a50434d826bd01b70c10f90b62abc04b676d3f44
Angelpacman/codecademy-py3
/Unit 02 Strings and Console Output/02 Date and Time/3-Extracting Information.py
177
4.0625
4
from datetime import datetime now = datetime.now() current_year = now.year current_month = now.month current_day = now.day print (now.year) print (now.month) print (now.day)
bb4566515aecfe1ef4ade3a15396a6b5009f400b
yasuo-/python_lesson
/chapter01/range_function.py
539
4.1875
4
""" range関数 """ num_list = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] # for なら for i in num_list: print(i) # めんどくさい... for j in range(10): # 0から9まで表示される print(j) for k in range(2, 10): # 2からスタート print(k) for l in range(2, 10, 3): # 3飛ばし print(l) # 10回処理する for h in range(10): print('hello') for _ in range(10): print('Hello') # indexに _ で書くと、rangeから入ってくるindexはループでは使われないと理解できる
370f72a8b93b9db6908c3335c0eb50fd190832ae
tanshinjie/FoundationOfCyberSecurity
/cyber_lab6/primes_template.py
1,484
3.609375
4
# 50.042 FCS Lab 6 template # Year 2019 """ Tan Shin Jie 1003715 """ import random MR_ROUND = 40 def square_multiply(a, x, n): res = 1 for i in bin(x)[2:]: res = res * res % n if i == "1": res = res * a % n return res def miller_rabin(n, a): # Check is n is 2 or 3 if n == 2 or n == 3: return True # Check if n is not even. if n <= 1 or n % 2 == 0: return False s = 0 r = n - 1 while r & 1 == 0: s += 1 r >>= 1 for _ in range(a): a = random.randrange(2, n - 1) x = pow(a, r, n) if x != 1 and x != n - 1: j = 1 while j < s and x != n - 1: x = pow(x, 2, n) if x == 1: return False j += 1 if x != n - 1: return False return True def gen_prime_nbits(n): p = 0 while not miller_rabin(p, MR_ROUND): p = generate_prime_candidate(n) return p def generate_prime_candidate(n): p = random.getrandbits(n) p |= (1 << n - 1) | 1 return p if __name__ == "__main__": print("Is 561 a prime?") print(miller_rabin(561, MR_ROUND)) print("Is 27 a prime?") print(miller_rabin(27, MR_ROUND)) print("Is 61 a prime?") print(miller_rabin(61, MR_ROUND)) print("Random number (100 bits):") print(gen_prime_nbits(100)) print("Random number (80 bits):") print(gen_prime_nbits(80))
e714929c319460b65728ef23e6858f1c34f80aac
CloudChaoszero/Data-Analyst-Track-Dataquest.io-Projects
/Python-Programming-Beginner/Python Basics-1.py
2,159
4.625
5
## 1. Programming And Data Science ## england = 135 china=123 india=124 united_states=134 ## 2. Display Values Using The Print Function ## china = 123 india = 124 united_states = 134 print(china) print(india) print(united_states) ## 3. Data Types ## china_name = "China" china_rounded = 123 china_exact = 122.5 print(china_name, '\n', china_rounded, '\n',china_exact) ## 4. The Type Function ## china_name = "China" china_exact = 122.5 print(type(china_exact)) ## 5. Converting Types ## china_rounded = 123 int_to_str = str(china_rounded) str_to_int = int(int_to_str) ## 6. Comments ## #China is china = 123 #Hey india = 124 #wha united_states = 134 ## 7. Arithmetic Operators ## china_plus_10 = 10+china us_times_100 = united_states*100 print(china_plus_10,"\n",us_times_100) ## 8. Order Of Operations ## china = 123 india = 124 united_states = 134 china_celsius = (china-32)*.56 india_celsius=(india-32)*0.56 us_celsius=(united_states-32)*0.56 ## 9. Console ## 5/10 indonesia =103 print(indonesia ) ## 10. Using A List To Store Multiple Values ## countries=[] temperatures=[] countries.append("China") countries.append("India") countries.append("United States") temperatures = [122.5,124.0,134.1] print(countries,"\n",temperatures) ## 11. Creating Lists With Values ## temps = ["China",122.5,"India",124.0,"United States",134.1] ## 12. Accessing Elements In A List ## countries = [] temperatures = [] countries.append("China") countries.append("India") countries.append("United States") temperatures.append(122.5) temperatures.append(124.0) temperatures.append(134.1) china=countries[0] china_temperature=temperatures[0] # Add your code here. ## 13. Retrieving The Length Of A List ## countries = ["China", "India", "United States", "Indonesia", "Brazil", "Pakistan"] temperatures = [122.5, 124.0, 134.1, 103.1, 112.5, 128.3] a=len(countries) b=len(temperatures) two_sum=a+b print(two_sum) ## 14. Slicing Lists ## countries = ["China", "India", "United States", "Indonesia", "Brazil", "Pakistan"] temperatures = [122.5, 124.0, 134.1, 103.1, 112.5, 128.3] countries_slice = countries[1:4] temperatures_slice = temperatures[-3:]
b4f3fbffbf8940cbb1adbcf83122c3c98421891b
Bhartendu-Kumar/Computer-Pointer-Controller
/src/input_feeder.py
1,754
3.609375
4
''' This class can be used to feed input from an image, webcam, or video to your model. Sample usage: feed=InputFeeder(input_type='video', input_file='video.mp4') feed.load_data() for batch in feed.next_batch(): do_something(batch) feed.close() ''' import cv2 from numpy import ndarray class InputFeeder: def __init__(self, input_type, input_file=None): ''' input_type: str, The type of input. Can be 'video' for video file, 'image' for image file, or 'cam' to use webcam feed. input_file: str, The file that contains the input image or video file. Leave empty for cam input_type. ''' self.input_type=input_type if input_type=='video' or input_type=='image': self.input_file=input_file def load_data(self): if self.input_type=='video': self.cap=cv2.VideoCapture(self.input_file) elif self.input_type=='cam': self.cap=cv2.VideoCapture(0) else: self.cap=cv2.imread(self.input_file) def next_batch(self): ''' Returns the next image from either a video file or webcam. If input_type is 'image', then it returns the same image. ''' if isinstance(self.cap, ndarray): while True: yield self.cap else: while True: #self.cap.set(3, 672) #self.cap.set(4, 384) _, frame=self.cap.read() self.cap.release() yield frame self.cap=cv2.VideoCapture(0) def close(self): ''' Closes the VideoCapture. ''' if not self.input_type=='image': self.cap.release()
14f235d471e3a4024cc183afb1d1389fcce0addb
samueljml/URI-Online-Judge
/Strings/1237/1237.py
637
3.5
4
while 1: try: fra1 = input() fra2 = input() if len(fra1) <= len(fra2): menor = fra1 maior = fra2 else: menor = fra2 maior = fra1 idf = 0 for i in range(len(menor), 0, -1): cont = 0 j = i if idf: break for j in range(j, len(menor) + 1, 1): if menor[cont:j] in maior: print(i) idf = 1 break cont += 1 if idf == 0: print('0') except EOFError: break
eedb392a74a3fdec7c66c516369b97b81dbe7d37
parrot125/myPy
/16_vote_eligibility.py
314
4.125
4
loop = 0 while loop == 0: try: age = int(input("Enter the age of the candidate:")) loop = 1 except: print("Invalid input") loop = 0 if age > 18: print("Eligible to vote.") elif age < 0: print("Please enter a positive age.") else: print("Not eligible to vote.")
a002fec1ed9442782a735ce6bd3ec37b67c873e4
carlosbognar/Estudos
/Conjuntos.py
866
4.375
4
# Conjuntos são estruturas de dados que não possuem elementos duplicados. # Podemos aplicar operações matemáticas aos conjuntos. a = set('abcdefghijkla') b = set('abcdefx') print(type(a)) print(a) # imprime todas as letras do conjunto a, sem duplicidade print(a - b) # imprime o conjunto de letras em a que não estejam não em b print(a | b) # imprime o conjunto de letras em a OU em b print(a & b) # imprime o conjunto de letras em a E em b print(a ^ b) # imprime o conjunto de letras em a OU em b, mas NÃO em AMBOSˆ ######################################################## # Pode-se executar as operações ADD ou POP em conjuntos ####################################################### a.add('w') # adiciona o elemento "w" ao conjunto a print(a) a.pop() # Retira o primeiro elemento do conjunto a print(a)
7a22c700bfe0a61f8142bebcb3c19c51218e87c2
gutierrecunha/urionlinejudge_python
/URI_1329 - (8672793) - Accepted.py
226
3.6875
4
# -*- coding: utf-8 -*- while True: quant = int(input()) if quant == 0: break num = list(map(int,input().split())) print("Mary won",num.count(0),"times and John won",num.count(1),"times")
081cd0007e071af17efeb5a363cfa75afcfd0417
jiankangliu/baseOfPython
/PycharmProjects/untitled1/demo.py
312
3.703125
4
# 复数,输入 n = 1 n1 = 2 print(n+n1) # n2=int(input("请输入第一个数:")) # n3=int(input("请输入第二个数:")) # print(n2+n3) a,b,c=1,[1,2,3],"liu" #多个变量赋值 print(a) print(b) print(c) b1=1 b2=2 print(b2<b1) c=complex(1,2) print(c.real) print(c.imag) print(c)
46e080c36913598ce5278f6b29c65b396e80cf18
salfaris/CS50
/pset7/houses/roster.py
786
3.625
4
from sys import argv, exit from cs50 import SQL # Check len of CLI if len(argv) != 2: print("Usage: roster.py house_name") exit(1) # Get house name house = argv[1] # Get access to sqlite database students.db db = SQL("sqlite:///students.db") # Query for student roster roster = db.execute("SELECT * FROM students WHERE house = ? ORDER BY last, first", house) # Iterate over each student (is dictionary) for student in roster: if student['middle'] is None: names = [student['first'], student['last']] else: names = [student['first'], student['middle'], student['last']] # Get full name full_name = " ".join(names) # Get birth date birth = student['birth'] # Print the name and birth date print(f"{full_name}, born {birth}")
e15ab2773d71e7e77f6d9942e1712d7bc06db6ca
GalinaR/hailstone_sequence
/main.py
805
4.34375
4
""" Pick some positive integer and call it n. If n is even, divide it by two. If n is odd, multiply it by three and add one. Continue this process until n is equal to one. """ def main(): num = int(input("Enter a number: ")) result = 0 # variable that will be the result of the action and then the original value i = 0 # variable to count steps until num is equal to one while result != 1: if num % 2 == 0: result = num // 2 print(num, "is even, so I take half:", result) num = result i += 1 else: result = num * 3 + 1 print(num, "is odd, so I make 3n+1:", result) num = result i += 1 print("The process took", i, "steps to reach 1") if __name__ == "__main__": main()
9d0533e0383cc2762e0b9f22f99a795f3c1f463d
hanmeimei222/CorePythonEx
/for.py
146
3.640625
4
squared = [x**2 for x in range(4)] for i in squared: print i, sqdEvens = [x**2 for x in range(8) if not x%2] for i in sqdEvens: print i,
a6b749265854050a22e63036bc09748b8fe70ee6
bvchand/algorithmic-toolbox
/Week-4/4.1_Binary_Search.py
999
3.8125
4
# python3 import math def binary_search(a, low, high, key): if high < low: return -1 mid = low + math.floor((high - low) / 2) # print("mid, a[mid]:", mid, a[mid]) if key == a[mid]: return mid elif key < a[mid]: return binary_search(a, low, mid-1, key) else: return binary_search(a, mid+1, high, key) def compute_result(a, b): # prepare the arrays n = a[0] a.remove(a[0]) k = b[0] b.remove(b[0]) # traverse through array 'b' result = [] i = 0 while i < k: key = b[i] # print("key:", key) low = 0 high = n-1 # print("result value:", binary_search(a, low, high, key)) result.append(binary_search(a, low, high, key)) i += 1 for x in result: print(x, end=' ') if __name__ == '__main__': A = [int(x) for x in input().split()] B = [int(x) for x in input().split()] A_terms = A[0] B_terms = B[0] compute_result(A, B)
0683e12c6d8a59f033694d9f6d703362b7f6e1f0
dhpn3/Atividades_MetodosNumericos
/Aulas/06-17/Numpy/06-17_intro_NumPy.py
2,711
4.09375
4
import numpy as np #para dar um apelido e n ter que digitar numpy sempre # www.numpy.org #python padrão: v = [1, 2, 3, 4] #v.append(5) coloca 5 no final do vetor/da lista print(v) print(type(v)) print(type(v[0])) vet = np.array(v) #criando vetor no numpy #1 jeito de criar vetor no numpy é passando uma lista do python padrao print(vet) print(type(vet)) print(vet.dtype) print(type(vet[0])) #tipo do elemento 1 da lista print(vet.dtype.name) print(vet.itemsize) #tamanho de cada elemento do vetor print(vet.shape) #retorna dimensao, uma tupla print(vet.ndim) #vetor de dimensao 1, unidimensional print(vet.size) #tamanho do vetor inteiro, 4 elementos m = [[1,2,3], [4, 5, 6]] print(m) print(m[0]) print(m[0][1]) print(type(m)) #matriz = lista de listas mat = np.array(m) #array específico para processamento matemático da biblioteca, q transforma a lista pro array do numpy print(mat) print(type(mat)) print(mat.shape) #dimensões do array, devolve uma tupla (2,3), q é uma matriz 2x3 print(mat.ndim) # numero de dimensões: 2, pois é bidimensional (2x3) print(mat.size) #quantos elementos tem na matriz/lista vp = list(range(1, 6, 1)) #vetor do python original, que cria e printa uma lista com valores separados por vírgula e n aceita passo float, só inteiro print(vp) vnp = np.arange(1, 6, 1) #vetor do numpy (vnp), range do numpy q substitui o do python= arange print(vnp) print(vnp.shape) vnp2 = np.arange(0, 4.1, 0.5) # inicio, fim-, passo #cria a lista com passo de 0.5, e vai até menos que 4.1 (4.0). O numpy tem essa precisão e possibilidade print(vnp2) vnp3 = np.linspace(0, 4, 20) #inicio, fim, qtde de elementos (fim fechado, conta até o número que colocou no linspace, no caso até o 4) #nao fala o passo, fala quanto de elemento que quer print(vnp3) mnp = np.arange(15).reshape(3, 5) #arange cria lista com 15 elementos. Já o reshape = 3x5, dimensao que quer print(mnp) lp = list(range(200)) #lista padrao python sem os valores default, sem o 0 q é o inicio, sem o passo (1 é o default), e usando só o 200 que é qtde de elementos print(lp) mnp2 = np.array(lp).reshape(5, 40) #reshape cria a matriz com o array e atribui a mnp2, q é a matriz em numpy com o comando do numpy reshape print(mnp2) mnp3 = np.zeros((3, 3)) #cria matriz no numpy de dim 3x3 preenchida de zeros print(mnp3) print(mnp3.shape) #(3,3) print(mnp3.dtype.name) # dtype.name nesse caso = float 64 bits mnp4 = np.ones((3, 2, 6), dtype=np.int16) #matriz tridimensional preenchida de um's, 3x2x6, 3 faces de 2 linhas e 6 colunas print(mnp4) print(mnp4.dtype.name) mnp5 = np.empty((4, 8), dtype=np.int64) #preenchida com sujeira de memória, valores qualquer = empty print(mnp5) print(mnp5.dtype.name)
e58b699c1bb83fc953cd6996b446a4c9bfea7dce
ktny/atcoder
/ABC084/d.py
596
3.625
4
Q = int(input()) from functools import lru_cache @lru_cache(maxsize=None) def is_prime(n: int): if n == 2: return True if n == 1 or n % 2 == 0: return False for p in range(3, int(n**0.5)+1, 2): if n % p == 0: return False return True like_2017s = [] for i in range(3, 10**5, 2): if is_prime(i) and is_prime((i+1)//2): like_2017s.append(i) from bisect import bisect_left, bisect_right for _ in range(Q): l, r = map(int, input().split()) li = bisect_left(like_2017s, l) ri = bisect_right(like_2017s, r) print(ri-li)
7e8583b9565658deba77d10efb8cd14ab8e25d42
rafaelperazzo/programacao-web
/moodledata/vpl_data/34/usersdata/130/12894/submittedfiles/moedas.py
682
3.828125
4
# -*- coding: utf-8 -*- from __future__ import division a=input('Digite o valor de a:') b=input('Digite o valor de b:') c=input('Digite o valor de c:') if a>=b: qa=0 qb=0 if c%a==0: qa=c//a print(qa) print(qb) else: qa=c//a d=c%a if d%b==0: qb=d//b print(qa) print(qb) else: print('N') else: qb=0 qa=0 if c%b==0: qb=c//b print(qb) print(qa) else: qb=c//b d=c%b if d%a==0: qa=d//a print(qb) print(qa) else: print('N')
bc4c830f0313ae511cee21d9af0f64d8bb09be4c
Erkebulannn/seminar3
/exercise1.py
166
3.859375
4
a= input('Введите числа: ') b= input('Введите числа: ') c= input('Введите числа: ') if((a==b)or(a==c)or(b==c)): print('yes')
362652fd22d05e1301fe42717101ba8cf3cc338d
viniciu-sena/Python-Logica
/lista05/L5E08.py
145
3.890625
4
# Feito por Kelvin Schneider #08 num = int(input("Digite um numero: ")) def contar(num): print("Quantidade de digitos: ", len(str(num))) contar(num)
2548004dff28e2db89afae83b3c1f3ad2c6c2cd6
adichouhan14/python-assignment
/py assignments/module 7/car.py
249
3.84375
4
#The __str__ method class Car: def __init__(self,color,mileage): self.color=color self.mileage=mileage def __str__(self): return f'A {self.color} car with mileage {self.mileage}' car=Car('RED',20) print(car)
e014caf6f868c367460df9d8fea9bb2b363ad255
danapplegate/AdventOfCode2020
/src/aoc2020/9/solution.py
1,638
3.921875
4
#!/usr/bin/env python3 import argparse import sys def is_valid(numbers, target_index, preamble_size): preamble = numbers[target_index - preamble_size : target_index] target = numbers[target_index] complements = set() for n in preamble: if n in complements: return True complements.add(target - n) return False def find_contiguous_range(numbers, target): for i in range(len(numbers)): for j in range(i + 1, len(numbers)): contiguous = numbers[i : j + 1] contiguous_sum = sum(contiguous) if contiguous_sum == target: return contiguous if __name__ == "__main__": parser = argparse.ArgumentParser(description="Advent of Code Day 9: Encoding Error") parser.add_argument( "filename", nargs="?", type=argparse.FileType("r"), default=sys.stdin ) parser.add_argument("part", nargs="?", type=int, default=1) parser.add_argument( "-s", dest="preamble_size", type=int, default=25, help="The number of previous numbers to consider (default 25)", ) args = parser.parse_args() numbers = [int(n) for n in args.filename.read().split("\n")] first_invalid = None for i in range(args.preamble_size, len(numbers)): if not is_valid(numbers, i, args.preamble_size): first_invalid = numbers[i] if args.part == 1: print(first_invalid) exit break contiguous_range = find_contiguous_range(numbers, first_invalid) print(sum([min(contiguous_range), max(contiguous_range)]))
bdaf2c1f20b1bcea4d5820f613d8c3696d692917
giancarlo-garbagnati/dsp
/python/q8_parsing.py
1,473
4.40625
4
# The football.csv file contains the results from the English Premier League. # The columns labeled ‘Goals’ and ‘Goals Allowed’ contain the total number of # goals scored for and against each team in that season (so Arsenal scored 79 # goals against opponents, and had 36 goals scored against them). Write a # program to read the file, then print the name of the team with the smallest # difference in ‘for’ and ‘against’ goals. import csv # open the file, convert it to first a csv reader object, then a list f = open('football.csv', 'r') r = csv.reader(f) l = list(r) # remove the header entry header = l.pop(0) # goals are in index 5 and goals allowed are in index 6 in the original csv, # but let's see if we find it without prior knowledge of which rows they're # in for col in range(len(header)): if header[col] == 'Team': teamname = col next if header[col] == 'Goals': goals = col next if header[col] == 'Goals Allowed': goals_allowed = col # makes a list of two element lists by parsing out each team name followed by # that team's goals-goals allowed goal_diff_list = [] for team in l: goal_diff_list.append( [ team[teamname], int(team[goals])-int(team[goals_allowed]) ] ) # now to sort by goal difference (lowest goal difference should be element 0) sorted_goal_diff = sorted(goal_diff_list, key = lambda x: x[-1]) print(sorted_goal_diff[0][0]) # poor Leicester, at least they got their title in the 15-16 season
24b5f5a4125c5d2040ff6f7868421cd822b1bd0f
andersonbispos/secPython
/wordlist.py
150
3.578125
4
import itertools import string resultado = itertools.permutations(string.ascii_letters + string.digits, 5) for i in resultado: print(''.join(i))
671b1459dd44a026bdfb7732310467ffda43a19b
cocvu99/head-first-python
/chapter1/page18to22.py
717
4.25
4
movies = [ "The Holy Grail", 1975, "Terry Jone @ Terry Gilliam", 91, ["Graham Chapman", ["Michael Palin", "John Cleese", "Terry Gilliam", "Eric Idle", "Terry Jones"]] ] print(movies[4][1][3]) ## Result: Eric Idle print("----------") print(movies) print("----------") for each_item in movies: print(each_item) print("----------") names = ['Michael', 'Terry'] print(isinstance(names, list)) # isinstance() BIF = check if a specific identifier holds data of a specific type #True print("----------") num_names = len(names) print(isinstance(num_names, list)) print("----------") for each_item in movies: if isinstance(each_item, list): for nested_item in each_item: print(nested_item) else: print(each_item)
842527b86d081d90eed10f15ac1fece49005627e
jadenpadua/Data-Structures-and-Algorithms
/bruteforce/box_volume.py
415
3.625
4
#Create a function that gets an object arguments with height, width and length of a box and returns the volume of the box. #Examples #volume_of_box({ "width": 2, "length": 5, "height": 1 }) ➞ 10 #volume_of_box({ "width": 4, "length": 2, "height": 2 }) ➞ 16 #volume_of_box({ "width": 2, "length": 3, "height": 5 }) ➞ 30 def volume_of_box(sizes): return sizes['width'] * sizes['length'] * sizes['height']
f15339cb6d1b7353c66a4be054f11a5c19aea223
gabqueiroz/roaming
/PacoteFuncoes.py
1,472
3.546875
4
import os import zipfile from TransformacaoRomming import TrasformarRomming class PacoteFuncoes(): @staticmethod def descompactar(dir_name, extension): # change directory from working dir to dir with files os.chdir(dir_name) for item in os.listdir(dir_name): # loop through items in dir if item.endswith(extension): # check for ".zip" extension file_name = os.path.abspath(item) # get full path of files # create zipfile object zip_ref = zipfile.ZipFile(file_name) zip_ref.extractall(dir_name) # extract file to dir zip_ref.close() # close file os.remove(file_name) # delete zipped @staticmethod def converter(extension, dir_name): os.chdir(dir_name) # muda para o diretorio ques esta os arquivos # olha os arquivos que estao no diretorio for item in os.listdir(dir_name): # procura os arquivos q terminam com a extencao passada if item.endswith(extension) and extension=='.GS3': # pega o caminho td do arquivo file_name = os.path.abspath(item) TrasformarRomming.transformarGS3(file_name, item) os.remove(file_name)
93301089a2a4a8689dbf71ab6c03d55b60cb4ba0
mullevik/advent-of-code-2019
/day_06.py
1,752
3.90625
4
from typing import Dict, List def bfs(start: str, end: str, graph: Dict[str, List[str]]) -> int: queue: List[str] = [start] visited = set() distances = {} for node in graph.keys(): distances[node] = 0 while queue: current = queue.pop(0) for child in graph[current]: if child not in visited: visited.add(child) queue.append(child) distances[child] = distances[current] + 1 if child == end: return distances[end] raise ValueError("End not found") def count_orbits_for_planet(node: str, graph: Dict[str, List[str]]) -> int: stack: List[str] = [node] visited = set() orbits = 0 while stack: current = stack.pop() for child in graph[current]: # if child not in visited: orbits += 1 stack.append(child) return orbits def count_orbits(graph: Dict[str, List[str]]) -> int: total_number_of_orbits = 0 for node in graph.keys(): total_number_of_orbits += count_orbits_for_planet(node, graph) return total_number_of_orbits def main(): graph = {} while True: input_string = input() if input_string == "": break input_list = input_string.split(")") parent = input_list[0] child = input_list[1] if child not in graph: graph[child] = [] if parent not in graph: graph[parent] = [] # make undirected edge graph[parent].append(child) graph[child].append(parent) number_of_jumps = bfs("YOU", "SAN", graph) - 2 print(number_of_jumps) if __name__ == "__main__": main()
236d2b467e39c74e657d7250ffdfa0230f69f63d
tordjoha/kattis-problems
/python/cetvrta.py
336
3.6875
4
points = [] x = [] y = [] for __ in range(0, 3): points.append(list(input().split())) for i in points: x.append(i[0]) y.append(i[1]) points = [0, 0] for i in range(0, 3): if x.count(x[i]) == 1: points[0] = x[i] if y.count(y[i]) == 1: points[1] = y[i] print('{} {}'.format(points[0], points[1]))