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What are names of the movies that are either made before 1980 or directed by James Cameron? | CREATE TABLE Movie (title VARCHAR, director VARCHAR, YEAR VARCHAR) | SELECT title FROM Movie WHERE director = "James Cameron" OR YEAR < 1980 | ### Context: CREATE TABLE Movie (title VARCHAR, director VARCHAR, YEAR VARCHAR) ### Question: What are names of the movies that are either made before 1980 or directed by James Cameron? ### Answer: SELECT title FROM Movie WHERE director = "James Cameron" OR YEAR < 1980 |
What are the names of reviewers who had rated 3 star and 4 star? | CREATE TABLE Reviewer (name VARCHAR, rID VARCHAR); CREATE TABLE Rating (rID VARCHAR, stars VARCHAR) | SELECT T2.name FROM Rating AS T1 JOIN Reviewer AS T2 ON T1.rID = T2.rID WHERE T1.stars = 3 INTERSECT SELECT T2.name FROM Rating AS T1 JOIN Reviewer AS T2 ON T1.rID = T2.rID WHERE T1.stars = 4 | ### Context: CREATE TABLE Reviewer (name VARCHAR, rID VARCHAR); CREATE TABLE Rating (rID VARCHAR, stars VARCHAR) ### Question: What are the names of reviewers who had rated 3 star and 4 star? ### Answer: SELECT T2.name FROM Rating AS T1 JOIN Reviewer AS T2 ON T1.rID = T2.rID WHERE T1.stars = 3 INTERSECT SELECT T2.name FROM Rating AS T1 JOIN Reviewer AS T2 ON T1.rID = T2.rID WHERE T1.stars = 4 |
What are the names of movies that get 3 star and 4 star? | CREATE TABLE Rating (mID VARCHAR, stars VARCHAR); CREATE TABLE Movie (title VARCHAR, mID VARCHAR) | SELECT T2.title FROM Rating AS T1 JOIN Movie AS T2 ON T1.mID = T2.mID WHERE T1.stars = 3 INTERSECT SELECT T2.title FROM Rating AS T1 JOIN Movie AS T2 ON T1.mID = T2.mID WHERE T1.stars = 4 | ### Context: CREATE TABLE Rating (mID VARCHAR, stars VARCHAR); CREATE TABLE Movie (title VARCHAR, mID VARCHAR) ### Question: What are the names of movies that get 3 star and 4 star? ### Answer: SELECT T2.title FROM Rating AS T1 JOIN Movie AS T2 ON T1.mID = T2.mID WHERE T1.stars = 3 INTERSECT SELECT T2.title FROM Rating AS T1 JOIN Movie AS T2 ON T1.mID = T2.mID WHERE T1.stars = 4 |
How many counties are there? | CREATE TABLE county_public_safety (Id VARCHAR) | SELECT COUNT(*) FROM county_public_safety | ### Context: CREATE TABLE county_public_safety (Id VARCHAR) ### Question: How many counties are there? ### Answer: SELECT COUNT(*) FROM county_public_safety |
List the names of counties in descending order of population. | CREATE TABLE county_public_safety (Name VARCHAR, Population VARCHAR) | SELECT Name FROM county_public_safety ORDER BY Population DESC | ### Context: CREATE TABLE county_public_safety (Name VARCHAR, Population VARCHAR) ### Question: List the names of counties in descending order of population. ### Answer: SELECT Name FROM county_public_safety ORDER BY Population DESC |
List the distinct police forces of counties whose location is not on east side. | CREATE TABLE county_public_safety (Police_force VARCHAR, LOCATION VARCHAR) | SELECT DISTINCT Police_force FROM county_public_safety WHERE LOCATION <> "East" | ### Context: CREATE TABLE county_public_safety (Police_force VARCHAR, LOCATION VARCHAR) ### Question: List the distinct police forces of counties whose location is not on east side. ### Answer: SELECT DISTINCT Police_force FROM county_public_safety WHERE LOCATION <> "East" |
What are the minimum and maximum crime rate of counties? | CREATE TABLE county_public_safety (Crime_rate INTEGER) | SELECT MIN(Crime_rate), MAX(Crime_rate) FROM county_public_safety | ### Context: CREATE TABLE county_public_safety (Crime_rate INTEGER) ### Question: What are the minimum and maximum crime rate of counties? ### Answer: SELECT MIN(Crime_rate), MAX(Crime_rate) FROM county_public_safety |
Show the crime rates of counties in ascending order of number of police officers. | CREATE TABLE county_public_safety (Crime_rate VARCHAR, Police_officers VARCHAR) | SELECT Crime_rate FROM county_public_safety ORDER BY Police_officers | ### Context: CREATE TABLE county_public_safety (Crime_rate VARCHAR, Police_officers VARCHAR) ### Question: Show the crime rates of counties in ascending order of number of police officers. ### Answer: SELECT Crime_rate FROM county_public_safety ORDER BY Police_officers |
What are the names of cities in ascending alphabetical order? | CREATE TABLE city (Name VARCHAR) | SELECT Name FROM city ORDER BY Name | ### Context: CREATE TABLE city (Name VARCHAR) ### Question: What are the names of cities in ascending alphabetical order? ### Answer: SELECT Name FROM city ORDER BY Name |
What are the percentage of hispanics in cities with the black percentage higher than 10? | CREATE TABLE city (Hispanic VARCHAR, Black INTEGER) | SELECT Hispanic FROM city WHERE Black > 10 | ### Context: CREATE TABLE city (Hispanic VARCHAR, Black INTEGER) ### Question: What are the percentage of hispanics in cities with the black percentage higher than 10? ### Answer: SELECT Hispanic FROM city WHERE Black > 10 |
List the name of the county with the largest population. | CREATE TABLE county_public_safety (Name VARCHAR, Population VARCHAR) | SELECT Name FROM county_public_safety ORDER BY Population DESC LIMIT 1 | ### Context: CREATE TABLE county_public_safety (Name VARCHAR, Population VARCHAR) ### Question: List the name of the county with the largest population. ### Answer: SELECT Name FROM county_public_safety ORDER BY Population DESC LIMIT 1 |
List the names of the city with the top 5 white percentages. | CREATE TABLE city (Name VARCHAR, White VARCHAR) | SELECT Name FROM city ORDER BY White DESC LIMIT 5 | ### Context: CREATE TABLE city (Name VARCHAR, White VARCHAR) ### Question: List the names of the city with the top 5 white percentages. ### Answer: SELECT Name FROM city ORDER BY White DESC LIMIT 5 |
Show names of cities and names of counties they are in. | CREATE TABLE city (Name VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Name VARCHAR, County_ID VARCHAR) | SELECT T1.Name, T2.Name FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID | ### Context: CREATE TABLE city (Name VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Name VARCHAR, County_ID VARCHAR) ### Question: Show names of cities and names of counties they are in. ### Answer: SELECT T1.Name, T2.Name FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID |
Show white percentages of cities and the crime rates of counties they are in. | CREATE TABLE city (White VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Crime_rate VARCHAR, County_ID VARCHAR) | SELECT T1.White, T2.Crime_rate FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID | ### Context: CREATE TABLE city (White VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Crime_rate VARCHAR, County_ID VARCHAR) ### Question: Show white percentages of cities and the crime rates of counties they are in. ### Answer: SELECT T1.White, T2.Crime_rate FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID |
Show the name of cities in the county that has the largest number of police officers. | CREATE TABLE city (name VARCHAR, county_ID VARCHAR, Police_officers VARCHAR); CREATE TABLE county_public_safety (name VARCHAR, county_ID VARCHAR, Police_officers VARCHAR) | SELECT name FROM city WHERE county_ID = (SELECT county_ID FROM county_public_safety ORDER BY Police_officers DESC LIMIT 1) | ### Context: CREATE TABLE city (name VARCHAR, county_ID VARCHAR, Police_officers VARCHAR); CREATE TABLE county_public_safety (name VARCHAR, county_ID VARCHAR, Police_officers VARCHAR) ### Question: Show the name of cities in the county that has the largest number of police officers. ### Answer: SELECT name FROM city WHERE county_ID = (SELECT county_ID FROM county_public_safety ORDER BY Police_officers DESC LIMIT 1) |
Show the number of cities in counties that have a population more than 20000. | CREATE TABLE county_public_safety (county_ID VARCHAR, population INTEGER); CREATE TABLE city (county_ID VARCHAR, population INTEGER) | SELECT COUNT(*) FROM city WHERE county_ID IN (SELECT county_ID FROM county_public_safety WHERE population > 20000) | ### Context: CREATE TABLE county_public_safety (county_ID VARCHAR, population INTEGER); CREATE TABLE city (county_ID VARCHAR, population INTEGER) ### Question: Show the number of cities in counties that have a population more than 20000. ### Answer: SELECT COUNT(*) FROM city WHERE county_ID IN (SELECT county_ID FROM county_public_safety WHERE population > 20000) |
Show the crime rate of counties with a city having white percentage more than 90. | CREATE TABLE county_public_safety (Crime_rate VARCHAR, County_ID VARCHAR); CREATE TABLE city (County_ID VARCHAR, White INTEGER) | SELECT T2.Crime_rate FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID WHERE T1.White > 90 | ### Context: CREATE TABLE county_public_safety (Crime_rate VARCHAR, County_ID VARCHAR); CREATE TABLE city (County_ID VARCHAR, White INTEGER) ### Question: Show the crime rate of counties with a city having white percentage more than 90. ### Answer: SELECT T2.Crime_rate FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID WHERE T1.White > 90 |
Please show the police forces and the number of counties with each police force. | CREATE TABLE county_public_safety (Police_force VARCHAR) | SELECT Police_force, COUNT(*) FROM county_public_safety GROUP BY Police_force | ### Context: CREATE TABLE county_public_safety (Police_force VARCHAR) ### Question: Please show the police forces and the number of counties with each police force. ### Answer: SELECT Police_force, COUNT(*) FROM county_public_safety GROUP BY Police_force |
What is the location shared by most counties? | CREATE TABLE county_public_safety (LOCATION VARCHAR) | SELECT LOCATION FROM county_public_safety GROUP BY LOCATION ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE county_public_safety (LOCATION VARCHAR) ### Question: What is the location shared by most counties? ### Answer: SELECT LOCATION FROM county_public_safety GROUP BY LOCATION ORDER BY COUNT(*) DESC LIMIT 1 |
List the names of counties that do not have any cities. | CREATE TABLE city (Name VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Name VARCHAR, County_ID VARCHAR) | SELECT Name FROM county_public_safety WHERE NOT County_ID IN (SELECT County_ID FROM city) | ### Context: CREATE TABLE city (Name VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Name VARCHAR, County_ID VARCHAR) ### Question: List the names of counties that do not have any cities. ### Answer: SELECT Name FROM county_public_safety WHERE NOT County_ID IN (SELECT County_ID FROM city) |
Show the police force shared by counties with location on the east and west. | CREATE TABLE county_public_safety (Police_force VARCHAR, LOCATION VARCHAR) | SELECT Police_force FROM county_public_safety WHERE LOCATION = "East" INTERSECT SELECT Police_force FROM county_public_safety WHERE LOCATION = "West" | ### Context: CREATE TABLE county_public_safety (Police_force VARCHAR, LOCATION VARCHAR) ### Question: Show the police force shared by counties with location on the east and west. ### Answer: SELECT Police_force FROM county_public_safety WHERE LOCATION = "East" INTERSECT SELECT Police_force FROM county_public_safety WHERE LOCATION = "West" |
Show the names of cities in counties that have a crime rate less than 100. | CREATE TABLE county_public_safety (name VARCHAR, county_id VARCHAR, Crime_rate INTEGER); CREATE TABLE city (name VARCHAR, county_id VARCHAR, Crime_rate INTEGER) | SELECT name FROM city WHERE county_id IN (SELECT county_id FROM county_public_safety WHERE Crime_rate < 100) | ### Context: CREATE TABLE county_public_safety (name VARCHAR, county_id VARCHAR, Crime_rate INTEGER); CREATE TABLE city (name VARCHAR, county_id VARCHAR, Crime_rate INTEGER) ### Question: Show the names of cities in counties that have a crime rate less than 100. ### Answer: SELECT name FROM city WHERE county_id IN (SELECT county_id FROM county_public_safety WHERE Crime_rate < 100) |
Show the case burden of counties in descending order of population. | CREATE TABLE county_public_safety (Case_burden VARCHAR, Population VARCHAR) | SELECT Case_burden FROM county_public_safety ORDER BY Population DESC | ### Context: CREATE TABLE county_public_safety (Case_burden VARCHAR, Population VARCHAR) ### Question: Show the case burden of counties in descending order of population. ### Answer: SELECT Case_burden FROM county_public_safety ORDER BY Population DESC |
Find the names of all modern rooms with a base price below $160 and two beds. | CREATE TABLE Rooms (roomName VARCHAR, decor VARCHAR, basePrice VARCHAR, beds VARCHAR) | SELECT roomName FROM Rooms WHERE basePrice < 160 AND beds = 2 AND decor = 'modern' | ### Context: CREATE TABLE Rooms (roomName VARCHAR, decor VARCHAR, basePrice VARCHAR, beds VARCHAR) ### Question: Find the names of all modern rooms with a base price below $160 and two beds. ### Answer: SELECT roomName FROM Rooms WHERE basePrice < 160 AND beds = 2 AND decor = 'modern' |
Find all the rooms that have a price higher than 160 and can accommodate more than 2 people. Report room names and ids. | CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR, basePrice VARCHAR, maxOccupancy VARCHAR) | SELECT roomName, RoomId FROM Rooms WHERE basePrice > 160 AND maxOccupancy > 2 | ### Context: CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR, basePrice VARCHAR, maxOccupancy VARCHAR) ### Question: Find all the rooms that have a price higher than 160 and can accommodate more than 2 people. Report room names and ids. ### Answer: SELECT roomName, RoomId FROM Rooms WHERE basePrice > 160 AND maxOccupancy > 2 |
Find the most popular room in the hotel. The most popular room is the room that had seen the largest number of reservations. | CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) | SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) ### Question: Find the most popular room in the hotel. The most popular room is the room that had seen the largest number of reservations. ### Answer: SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room ORDER BY COUNT(*) DESC LIMIT 1 |
How many kids stay in the rooms reserved by ROY SWEAZY? | CREATE TABLE Reservations (kids VARCHAR, FirstName VARCHAR, LastName VARCHAR) | SELECT kids FROM Reservations WHERE FirstName = "ROY" AND LastName = "SWEAZY" | ### Context: CREATE TABLE Reservations (kids VARCHAR, FirstName VARCHAR, LastName VARCHAR) ### Question: How many kids stay in the rooms reserved by ROY SWEAZY? ### Answer: SELECT kids FROM Reservations WHERE FirstName = "ROY" AND LastName = "SWEAZY" |
How many times does ROY SWEAZY has reserved a room. | CREATE TABLE Reservations (FirstName VARCHAR, LastName VARCHAR) | SELECT COUNT(*) FROM Reservations WHERE FirstName = "ROY" AND LastName = "SWEAZY" | ### Context: CREATE TABLE Reservations (FirstName VARCHAR, LastName VARCHAR) ### Question: How many times does ROY SWEAZY has reserved a room. ### Answer: SELECT COUNT(*) FROM Reservations WHERE FirstName = "ROY" AND LastName = "SWEAZY" |
Which room has the highest rate? List the room's full name, rate, check in and check out date. | CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR); CREATE TABLE Reservations (Rate VARCHAR, CheckIn VARCHAR, CheckOut VARCHAR, Room VARCHAR) | SELECT T2.roomName, T1.Rate, T1.CheckIn, T1.CheckOut FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room ORDER BY T1.Rate DESC LIMIT 1 | ### Context: CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR); CREATE TABLE Reservations (Rate VARCHAR, CheckIn VARCHAR, CheckOut VARCHAR, Room VARCHAR) ### Question: Which room has the highest rate? List the room's full name, rate, check in and check out date. ### Answer: SELECT T2.roomName, T1.Rate, T1.CheckIn, T1.CheckOut FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room ORDER BY T1.Rate DESC LIMIT 1 |
How many adults stay in the room CONRAD SELBIG checked in on Oct 23, 2010? | CREATE TABLE Reservations (Adults VARCHAR, LastName VARCHAR, CheckIn VARCHAR, FirstName VARCHAR) | SELECT Adults FROM Reservations WHERE CheckIn = "2010-10-23" AND FirstName = "CONRAD" AND LastName = "SELBIG" | ### Context: CREATE TABLE Reservations (Adults VARCHAR, LastName VARCHAR, CheckIn VARCHAR, FirstName VARCHAR) ### Question: How many adults stay in the room CONRAD SELBIG checked in on Oct 23, 2010? ### Answer: SELECT Adults FROM Reservations WHERE CheckIn = "2010-10-23" AND FirstName = "CONRAD" AND LastName = "SELBIG" |
How many kids stay in the room DAMIEN TRACHSEL checked in on Sep 21, 2010? | CREATE TABLE Reservations (Kids VARCHAR, LastName VARCHAR, CheckIn VARCHAR, FirstName VARCHAR) | SELECT Kids FROM Reservations WHERE CheckIn = "2010-09-21" AND FirstName = "DAMIEN" AND LastName = "TRACHSEL" | ### Context: CREATE TABLE Reservations (Kids VARCHAR, LastName VARCHAR, CheckIn VARCHAR, FirstName VARCHAR) ### Question: How many kids stay in the room DAMIEN TRACHSEL checked in on Sep 21, 2010? ### Answer: SELECT Kids FROM Reservations WHERE CheckIn = "2010-09-21" AND FirstName = "DAMIEN" AND LastName = "TRACHSEL" |
How many king beds are there? | CREATE TABLE Rooms (beds INTEGER, bedtype VARCHAR) | SELECT SUM(beds) FROM Rooms WHERE bedtype = 'King' | ### Context: CREATE TABLE Rooms (beds INTEGER, bedtype VARCHAR) ### Question: How many king beds are there? ### Answer: SELECT SUM(beds) FROM Rooms WHERE bedtype = 'King' |
List the names and decor of rooms that have a king bed. Sort the list by their price. | CREATE TABLE Rooms (roomName VARCHAR, decor VARCHAR, bedtype VARCHAR, basePrice VARCHAR) | SELECT roomName, decor FROM Rooms WHERE bedtype = 'King' ORDER BY basePrice | ### Context: CREATE TABLE Rooms (roomName VARCHAR, decor VARCHAR, bedtype VARCHAR, basePrice VARCHAR) ### Question: List the names and decor of rooms that have a king bed. Sort the list by their price. ### Answer: SELECT roomName, decor FROM Rooms WHERE bedtype = 'King' ORDER BY basePrice |
Which room has cheapest base price? List the room's name and the base price. | CREATE TABLE Rooms (roomName VARCHAR, basePrice VARCHAR) | SELECT roomName, basePrice FROM Rooms ORDER BY basePrice LIMIT 1 | ### Context: CREATE TABLE Rooms (roomName VARCHAR, basePrice VARCHAR) ### Question: Which room has cheapest base price? List the room's name and the base price. ### Answer: SELECT roomName, basePrice FROM Rooms ORDER BY basePrice LIMIT 1 |
What is the decor of room Recluse and defiance? | CREATE TABLE Rooms (decor VARCHAR, roomName VARCHAR) | SELECT decor FROM Rooms WHERE roomName = "Recluse and defiance" | ### Context: CREATE TABLE Rooms (decor VARCHAR, roomName VARCHAR) ### Question: What is the decor of room Recluse and defiance? ### Answer: SELECT decor FROM Rooms WHERE roomName = "Recluse and defiance" |
What is the average base price of different bed type? List bed type and average base price. | CREATE TABLE Rooms (bedType VARCHAR, basePrice INTEGER) | SELECT bedType, AVG(basePrice) FROM Rooms GROUP BY bedType | ### Context: CREATE TABLE Rooms (bedType VARCHAR, basePrice INTEGER) ### Question: What is the average base price of different bed type? List bed type and average base price. ### Answer: SELECT bedType, AVG(basePrice) FROM Rooms GROUP BY bedType |
What is the total number of people who could stay in the modern rooms in this inn? | CREATE TABLE Rooms (maxOccupancy INTEGER, decor VARCHAR) | SELECT SUM(maxOccupancy) FROM Rooms WHERE decor = 'modern' | ### Context: CREATE TABLE Rooms (maxOccupancy INTEGER, decor VARCHAR) ### Question: What is the total number of people who could stay in the modern rooms in this inn? ### Answer: SELECT SUM(maxOccupancy) FROM Rooms WHERE decor = 'modern' |
What kind of decor has the least number of reservations? | CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (decor VARCHAR, RoomId VARCHAR) | SELECT T2.decor FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T2.decor ORDER BY COUNT(T2.decor) LIMIT 1 | ### Context: CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (decor VARCHAR, RoomId VARCHAR) ### Question: What kind of decor has the least number of reservations? ### Answer: SELECT T2.decor FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T2.decor ORDER BY COUNT(T2.decor) LIMIT 1 |
List how many times the number of people in the room reached the maximum occupancy of the room. The number of people include adults and kids. | CREATE TABLE Rooms (RoomId VARCHAR, maxOccupancy VARCHAR); CREATE TABLE Reservations (Room VARCHAR, Adults VARCHAR, Kids VARCHAR) | SELECT COUNT(*) FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T2.maxOccupancy = T1.Adults + T1.Kids | ### Context: CREATE TABLE Rooms (RoomId VARCHAR, maxOccupancy VARCHAR); CREATE TABLE Reservations (Room VARCHAR, Adults VARCHAR, Kids VARCHAR) ### Question: List how many times the number of people in the room reached the maximum occupancy of the room. The number of people include adults and kids. ### Answer: SELECT COUNT(*) FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T2.maxOccupancy = T1.Adults + T1.Kids |
Find the first and last names of people who payed more than the rooms' base prices. | CREATE TABLE Reservations (firstname VARCHAR, lastname VARCHAR, Room VARCHAR, Rate VARCHAR); CREATE TABLE Rooms (RoomId VARCHAR, basePrice VARCHAR) | SELECT T1.firstname, T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T1.Rate - T2.basePrice > 0 | ### Context: CREATE TABLE Reservations (firstname VARCHAR, lastname VARCHAR, Room VARCHAR, Rate VARCHAR); CREATE TABLE Rooms (RoomId VARCHAR, basePrice VARCHAR) ### Question: Find the first and last names of people who payed more than the rooms' base prices. ### Answer: SELECT T1.firstname, T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T1.Rate - T2.basePrice > 0 |
How many rooms are there? | CREATE TABLE Rooms (Id VARCHAR) | SELECT COUNT(*) FROM Rooms | ### Context: CREATE TABLE Rooms (Id VARCHAR) ### Question: How many rooms are there? ### Answer: SELECT COUNT(*) FROM Rooms |
Find the number of rooms with a king bed. | CREATE TABLE Rooms (bedType VARCHAR) | SELECT COUNT(*) FROM Rooms WHERE bedType = "King" | ### Context: CREATE TABLE Rooms (bedType VARCHAR) ### Question: Find the number of rooms with a king bed. ### Answer: SELECT COUNT(*) FROM Rooms WHERE bedType = "King" |
Find the number of rooms for each bed type. | CREATE TABLE Rooms (bedType VARCHAR) | SELECT bedType, COUNT(*) FROM Rooms GROUP BY bedType | ### Context: CREATE TABLE Rooms (bedType VARCHAR) ### Question: Find the number of rooms for each bed type. ### Answer: SELECT bedType, COUNT(*) FROM Rooms GROUP BY bedType |
Find the name of the room with the maximum occupancy. | CREATE TABLE Rooms (roomName VARCHAR, maxOccupancy VARCHAR) | SELECT roomName FROM Rooms ORDER BY maxOccupancy DESC LIMIT 1 | ### Context: CREATE TABLE Rooms (roomName VARCHAR, maxOccupancy VARCHAR) ### Question: Find the name of the room with the maximum occupancy. ### Answer: SELECT roomName FROM Rooms ORDER BY maxOccupancy DESC LIMIT 1 |
Find the id and name of the most expensive base price room. | CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR, basePrice VARCHAR) | SELECT RoomId, roomName FROM Rooms ORDER BY basePrice DESC LIMIT 1 | ### Context: CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR, basePrice VARCHAR) ### Question: Find the id and name of the most expensive base price room. ### Answer: SELECT RoomId, roomName FROM Rooms ORDER BY basePrice DESC LIMIT 1 |
List the type of bed and name of all traditional rooms. | CREATE TABLE Rooms (roomName VARCHAR, bedType VARCHAR, decor VARCHAR) | SELECT roomName, bedType FROM Rooms WHERE decor = "traditional" | ### Context: CREATE TABLE Rooms (roomName VARCHAR, bedType VARCHAR, decor VARCHAR) ### Question: List the type of bed and name of all traditional rooms. ### Answer: SELECT roomName, bedType FROM Rooms WHERE decor = "traditional" |
Find the number of rooms with king bed for each decor type. | CREATE TABLE Rooms (decor VARCHAR, bedType VARCHAR) | SELECT decor, COUNT(*) FROM Rooms WHERE bedType = "King" GROUP BY decor | ### Context: CREATE TABLE Rooms (decor VARCHAR, bedType VARCHAR) ### Question: Find the number of rooms with king bed for each decor type. ### Answer: SELECT decor, COUNT(*) FROM Rooms WHERE bedType = "King" GROUP BY decor |
Find the average and minimum price of the rooms in different decor. | CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER) | SELECT decor, AVG(basePrice), MIN(basePrice) FROM Rooms GROUP BY decor | ### Context: CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER) ### Question: Find the average and minimum price of the rooms in different decor. ### Answer: SELECT decor, AVG(basePrice), MIN(basePrice) FROM Rooms GROUP BY decor |
List the name of all rooms sorted by their prices. | CREATE TABLE Rooms (roomName VARCHAR, basePrice VARCHAR) | SELECT roomName FROM Rooms ORDER BY basePrice | ### Context: CREATE TABLE Rooms (roomName VARCHAR, basePrice VARCHAR) ### Question: List the name of all rooms sorted by their prices. ### Answer: SELECT roomName FROM Rooms ORDER BY basePrice |
Find the number of rooms with price higher than 120 for different decor. | CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER) | SELECT decor, COUNT(*) FROM Rooms WHERE basePrice > 120 GROUP BY decor | ### Context: CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER) ### Question: Find the number of rooms with price higher than 120 for different decor. ### Answer: SELECT decor, COUNT(*) FROM Rooms WHERE basePrice > 120 GROUP BY decor |
List the name of rooms with king or queen bed. | CREATE TABLE Rooms (roomName VARCHAR, bedType VARCHAR) | SELECT roomName FROM Rooms WHERE bedType = "King" OR bedType = "Queen" | ### Context: CREATE TABLE Rooms (roomName VARCHAR, bedType VARCHAR) ### Question: List the name of rooms with king or queen bed. ### Answer: SELECT roomName FROM Rooms WHERE bedType = "King" OR bedType = "Queen" |
How many different types of beds are there? | CREATE TABLE Rooms (bedType VARCHAR) | SELECT COUNT(DISTINCT bedType) FROM Rooms | ### Context: CREATE TABLE Rooms (bedType VARCHAR) ### Question: How many different types of beds are there? ### Answer: SELECT COUNT(DISTINCT bedType) FROM Rooms |
Find the name and id of the top 3 expensive rooms. | CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR, basePrice VARCHAR) | SELECT RoomId, roomName FROM Rooms ORDER BY basePrice DESC LIMIT 3 | ### Context: CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR, basePrice VARCHAR) ### Question: Find the name and id of the top 3 expensive rooms. ### Answer: SELECT RoomId, roomName FROM Rooms ORDER BY basePrice DESC LIMIT 3 |
Find the name of rooms whose price is higher than the average price. | CREATE TABLE Rooms (roomName VARCHAR, basePrice INTEGER) | SELECT roomName FROM Rooms WHERE basePrice > (SELECT AVG(basePrice) FROM Rooms) | ### Context: CREATE TABLE Rooms (roomName VARCHAR, basePrice INTEGER) ### Question: Find the name of rooms whose price is higher than the average price. ### Answer: SELECT roomName FROM Rooms WHERE basePrice > (SELECT AVG(basePrice) FROM Rooms) |
Find the number of rooms that do not have any reservation. | CREATE TABLE rooms (roomid VARCHAR, room VARCHAR); CREATE TABLE reservations (roomid VARCHAR, room VARCHAR) | SELECT COUNT(*) FROM rooms WHERE NOT roomid IN (SELECT DISTINCT room FROM reservations) | ### Context: CREATE TABLE rooms (roomid VARCHAR, room VARCHAR); CREATE TABLE reservations (roomid VARCHAR, room VARCHAR) ### Question: Find the number of rooms that do not have any reservation. ### Answer: SELECT COUNT(*) FROM rooms WHERE NOT roomid IN (SELECT DISTINCT room FROM reservations) |
Return the name and number of reservations made for each of the rooms. | CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) | SELECT T2.roomName, COUNT(*), T1.Room FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room | ### Context: CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) ### Question: Return the name and number of reservations made for each of the rooms. ### Answer: SELECT T2.roomName, COUNT(*), T1.Room FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room |
Find the names of rooms that have been reserved for more than 60 times. | CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) | SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room HAVING COUNT(*) > 60 | ### Context: CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) ### Question: Find the names of rooms that have been reserved for more than 60 times. ### Answer: SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room HAVING COUNT(*) > 60 |
Find the name of rooms whose base price is between 120 and 150. | CREATE TABLE rooms (roomname VARCHAR, baseprice INTEGER) | SELECT roomname FROM rooms WHERE baseprice BETWEEN 120 AND 150 | ### Context: CREATE TABLE rooms (roomname VARCHAR, baseprice INTEGER) ### Question: Find the name of rooms whose base price is between 120 and 150. ### Answer: SELECT roomname FROM rooms WHERE baseprice BETWEEN 120 AND 150 |
Find the name of rooms booked by some customers whose first name contains ROY. | CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) | SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE firstname LIKE '%ROY%' | ### Context: CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) ### Question: Find the name of rooms booked by some customers whose first name contains ROY. ### Answer: SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE firstname LIKE '%ROY%' |
what are the details of the cmi masters that have the cross reference code 'Tax'? | CREATE TABLE CMI_Cross_References (master_customer_id VARCHAR, source_system_code VARCHAR); CREATE TABLE Customer_Master_Index (cmi_details VARCHAR, master_customer_id VARCHAR) | SELECT T1.cmi_details FROM Customer_Master_Index AS T1 JOIN CMI_Cross_References AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T2.source_system_code = 'Tax' | ### Context: CREATE TABLE CMI_Cross_References (master_customer_id VARCHAR, source_system_code VARCHAR); CREATE TABLE Customer_Master_Index (cmi_details VARCHAR, master_customer_id VARCHAR) ### Question: what are the details of the cmi masters that have the cross reference code 'Tax'? ### Answer: SELECT T1.cmi_details FROM Customer_Master_Index AS T1 JOIN CMI_Cross_References AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T2.source_system_code = 'Tax' |
What is the cmi cross reference id that is related to at least one council tax entry? List the cross reference id and source system code. | CREATE TABLE Council_Tax (cmi_cross_ref_id VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, source_system_code VARCHAR) | SELECT T1.cmi_cross_ref_id, T1.source_system_code FROM CMI_Cross_References AS T1 JOIN Council_Tax AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T1.cmi_cross_ref_id HAVING COUNT(*) >= 1 | ### Context: CREATE TABLE Council_Tax (cmi_cross_ref_id VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, source_system_code VARCHAR) ### Question: What is the cmi cross reference id that is related to at least one council tax entry? List the cross reference id and source system code. ### Answer: SELECT T1.cmi_cross_ref_id, T1.source_system_code FROM CMI_Cross_References AS T1 JOIN Council_Tax AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T1.cmi_cross_ref_id HAVING COUNT(*) >= 1 |
How many business rates are related to each cmi cross reference? List cross reference id, master customer id and the n | CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, master_customer_id VARCHAR); CREATE TABLE Business_Rates (cmi_cross_ref_id VARCHAR) | SELECT T2.cmi_cross_ref_id, T2.master_customer_id, COUNT(*) FROM Business_Rates AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T2.cmi_cross_ref_id | ### Context: CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, master_customer_id VARCHAR); CREATE TABLE Business_Rates (cmi_cross_ref_id VARCHAR) ### Question: How many business rates are related to each cmi cross reference? List cross reference id, master customer id and the n ### Answer: SELECT T2.cmi_cross_ref_id, T2.master_customer_id, COUNT(*) FROM Business_Rates AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T2.cmi_cross_ref_id |
What is the tax source system code related to the benefits and overpayments? List the code and the benifit id, order by benifit id. | CREATE TABLE CMI_Cross_References (source_system_code VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Benefits_Overpayments (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR) | SELECT T1.source_system_code, T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Benefits_Overpayments AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id ORDER BY T2.council_tax_id | ### Context: CREATE TABLE CMI_Cross_References (source_system_code VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Benefits_Overpayments (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR) ### Question: What is the tax source system code related to the benefits and overpayments? List the code and the benifit id, order by benifit id. ### Answer: SELECT T1.source_system_code, T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Benefits_Overpayments AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id ORDER BY T2.council_tax_id |
Wat is the tax source system code and master customer id of the taxes related to each parking fine id? | CREATE TABLE CMI_Cross_References (source_system_code VARCHAR, master_customer_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Parking_Fines (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR) | SELECT T1.source_system_code, T1.master_customer_id, T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Parking_Fines AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id | ### Context: CREATE TABLE CMI_Cross_References (source_system_code VARCHAR, master_customer_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Parking_Fines (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR) ### Question: Wat is the tax source system code and master customer id of the taxes related to each parking fine id? ### Answer: SELECT T1.source_system_code, T1.master_customer_id, T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Parking_Fines AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id |
What are the renting arrears tax ids related to the customer master index whose detail is not 'Schmidt, Kertzmann and Lubowitz'? | CREATE TABLE Rent_Arrears (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Customer_Master_Index (master_customer_id VARCHAR, cmi_details VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, master_customer_id VARCHAR) | SELECT T1.council_tax_id FROM Rent_Arrears AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id JOIN Customer_Master_Index AS T3 ON T3.master_customer_id = T2.master_customer_id WHERE T3.cmi_details <> 'Schmidt , Kertzmann and Lubowitz' | ### Context: CREATE TABLE Rent_Arrears (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Customer_Master_Index (master_customer_id VARCHAR, cmi_details VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, master_customer_id VARCHAR) ### Question: What are the renting arrears tax ids related to the customer master index whose detail is not 'Schmidt, Kertzmann and Lubowitz'? ### Answer: SELECT T1.council_tax_id FROM Rent_Arrears AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id JOIN Customer_Master_Index AS T3 ON T3.master_customer_id = T2.master_customer_id WHERE T3.cmi_details <> 'Schmidt , Kertzmann and Lubowitz' |
What are the register ids of electoral registries that have the cross reference source system code 'Electoral' or 'Tax'? | CREATE TABLE Electoral_Register (electoral_register_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, source_system_code VARCHAR) | SELECT T1.electoral_register_id FROM Electoral_Register AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id WHERE T2.source_system_code = 'Electoral' OR T2.source_system_code = 'Tax' | ### Context: CREATE TABLE Electoral_Register (electoral_register_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, source_system_code VARCHAR) ### Question: What are the register ids of electoral registries that have the cross reference source system code 'Electoral' or 'Tax'? ### Answer: SELECT T1.electoral_register_id FROM Electoral_Register AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id WHERE T2.source_system_code = 'Electoral' OR T2.source_system_code = 'Tax' |
How many different source system code for the cmi cross references are there? | CREATE TABLE CMI_cross_references (source_system_code VARCHAR) | SELECT COUNT(DISTINCT source_system_code) FROM CMI_cross_references | ### Context: CREATE TABLE CMI_cross_references (source_system_code VARCHAR) ### Question: How many different source system code for the cmi cross references are there? ### Answer: SELECT COUNT(DISTINCT source_system_code) FROM CMI_cross_references |
List all information about customer master index, and sort them by details in descending order. | CREATE TABLE customer_master_index (cmi_details VARCHAR) | SELECT * FROM customer_master_index ORDER BY cmi_details DESC | ### Context: CREATE TABLE customer_master_index (cmi_details VARCHAR) ### Question: List all information about customer master index, and sort them by details in descending order. ### Answer: SELECT * FROM customer_master_index ORDER BY cmi_details DESC |
List the council tax ids and their related cmi cross references of all the parking fines. | CREATE TABLE parking_fines (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR) | SELECT council_tax_id, cmi_cross_ref_id FROM parking_fines | ### Context: CREATE TABLE parking_fines (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR) ### Question: List the council tax ids and their related cmi cross references of all the parking fines. ### Answer: SELECT council_tax_id, cmi_cross_ref_id FROM parking_fines |
How many council taxes are collected for renting arrears ? | CREATE TABLE rent_arrears (Id VARCHAR) | SELECT COUNT(*) FROM rent_arrears | ### Context: CREATE TABLE rent_arrears (Id VARCHAR) ### Question: How many council taxes are collected for renting arrears ? ### Answer: SELECT COUNT(*) FROM rent_arrears |
What are the distinct cross reference source system codes which are related to the master customer details 'Gottlieb, Becker and Wyman'? | CREATE TABLE customer_master_index (master_customer_id VARCHAR, cmi_details VARCHAR); CREATE TABLE cmi_cross_references (source_system_code VARCHAR, master_customer_id VARCHAR) | SELECT DISTINCT T2.source_system_code FROM customer_master_index AS T1 JOIN cmi_cross_references AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T1.cmi_details = 'Gottlieb , Becker and Wyman' | ### Context: CREATE TABLE customer_master_index (master_customer_id VARCHAR, cmi_details VARCHAR); CREATE TABLE cmi_cross_references (source_system_code VARCHAR, master_customer_id VARCHAR) ### Question: What are the distinct cross reference source system codes which are related to the master customer details 'Gottlieb, Becker and Wyman'? ### Answer: SELECT DISTINCT T2.source_system_code FROM customer_master_index AS T1 JOIN cmi_cross_references AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T1.cmi_details = 'Gottlieb , Becker and Wyman' |
Which cmi cross reference id is not related to any parking taxes? | CREATE TABLE parking_fines (cmi_cross_ref_id VARCHAR); CREATE TABLE cmi_cross_references (cmi_cross_ref_id VARCHAR) | SELECT cmi_cross_ref_id FROM cmi_cross_references EXCEPT SELECT cmi_cross_ref_id FROM parking_fines | ### Context: CREATE TABLE parking_fines (cmi_cross_ref_id VARCHAR); CREATE TABLE cmi_cross_references (cmi_cross_ref_id VARCHAR) ### Question: Which cmi cross reference id is not related to any parking taxes? ### Answer: SELECT cmi_cross_ref_id FROM cmi_cross_references EXCEPT SELECT cmi_cross_ref_id FROM parking_fines |
Which distinct source system code includes the substring 'en'? | CREATE TABLE cmi_cross_references (source_system_code VARCHAR) | SELECT DISTINCT source_system_code FROM cmi_cross_references WHERE source_system_code LIKE '%en%' | ### Context: CREATE TABLE cmi_cross_references (source_system_code VARCHAR) ### Question: Which distinct source system code includes the substring 'en'? ### Answer: SELECT DISTINCT source_system_code FROM cmi_cross_references WHERE source_system_code LIKE '%en%' |
How many parties are there? | CREATE TABLE party (Id VARCHAR) | SELECT COUNT(*) FROM party | ### Context: CREATE TABLE party (Id VARCHAR) ### Question: How many parties are there? ### Answer: SELECT COUNT(*) FROM party |
List the themes of parties in ascending order of number of hosts. | CREATE TABLE party (Party_Theme VARCHAR, Number_of_hosts VARCHAR) | SELECT Party_Theme FROM party ORDER BY Number_of_hosts | ### Context: CREATE TABLE party (Party_Theme VARCHAR, Number_of_hosts VARCHAR) ### Question: List the themes of parties in ascending order of number of hosts. ### Answer: SELECT Party_Theme FROM party ORDER BY Number_of_hosts |
What are the themes and locations of parties? | CREATE TABLE party (Party_Theme VARCHAR, LOCATION VARCHAR) | SELECT Party_Theme, LOCATION FROM party | ### Context: CREATE TABLE party (Party_Theme VARCHAR, LOCATION VARCHAR) ### Question: What are the themes and locations of parties? ### Answer: SELECT Party_Theme, LOCATION FROM party |
Show the first year and last year of parties with theme "Spring" or "Teqnology". | CREATE TABLE party (First_year VARCHAR, Last_year VARCHAR, Party_Theme VARCHAR) | SELECT First_year, Last_year FROM party WHERE Party_Theme = "Spring" OR Party_Theme = "Teqnology" | ### Context: CREATE TABLE party (First_year VARCHAR, Last_year VARCHAR, Party_Theme VARCHAR) ### Question: Show the first year and last year of parties with theme "Spring" or "Teqnology". ### Answer: SELECT First_year, Last_year FROM party WHERE Party_Theme = "Spring" OR Party_Theme = "Teqnology" |
What is the average number of hosts for parties? | CREATE TABLE party (Number_of_hosts INTEGER) | SELECT AVG(Number_of_hosts) FROM party | ### Context: CREATE TABLE party (Number_of_hosts INTEGER) ### Question: What is the average number of hosts for parties? ### Answer: SELECT AVG(Number_of_hosts) FROM party |
What is the location of the party with the most hosts? | CREATE TABLE party (LOCATION VARCHAR, Number_of_hosts VARCHAR) | SELECT LOCATION FROM party ORDER BY Number_of_hosts DESC LIMIT 1 | ### Context: CREATE TABLE party (LOCATION VARCHAR, Number_of_hosts VARCHAR) ### Question: What is the location of the party with the most hosts? ### Answer: SELECT LOCATION FROM party ORDER BY Number_of_hosts DESC LIMIT 1 |
Show different nationalities along with the number of hosts of each nationality. | CREATE TABLE HOST (Nationality VARCHAR) | SELECT Nationality, COUNT(*) FROM HOST GROUP BY Nationality | ### Context: CREATE TABLE HOST (Nationality VARCHAR) ### Question: Show different nationalities along with the number of hosts of each nationality. ### Answer: SELECT Nationality, COUNT(*) FROM HOST GROUP BY Nationality |
Show the most common nationality of hosts. | CREATE TABLE HOST (Nationality VARCHAR) | SELECT Nationality FROM HOST GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE HOST (Nationality VARCHAR) ### Question: Show the most common nationality of hosts. ### Answer: SELECT Nationality FROM HOST GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1 |
Show the nations that have both hosts older than 45 and hosts younger than 35. | CREATE TABLE HOST (Nationality VARCHAR, Age INTEGER) | SELECT Nationality FROM HOST WHERE Age > 45 INTERSECT SELECT Nationality FROM HOST WHERE Age < 35 | ### Context: CREATE TABLE HOST (Nationality VARCHAR, Age INTEGER) ### Question: Show the nations that have both hosts older than 45 and hosts younger than 35. ### Answer: SELECT Nationality FROM HOST WHERE Age > 45 INTERSECT SELECT Nationality FROM HOST WHERE Age < 35 |
Show the themes of parties and the names of the party hosts. | CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party_Theme VARCHAR, Party_ID VARCHAR) | SELECT T3.Party_Theme, T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID | ### Context: CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party_Theme VARCHAR, Party_ID VARCHAR) ### Question: Show the themes of parties and the names of the party hosts. ### Answer: SELECT T3.Party_Theme, T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID |
Show the locations of parties and the names of the party hosts in ascending order of the age of the host. | CREATE TABLE party (Location VARCHAR, Party_ID VARCHAR); CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR, Age VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR) | SELECT T3.Location, T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID ORDER BY T2.Age | ### Context: CREATE TABLE party (Location VARCHAR, Party_ID VARCHAR); CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR, Age VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR) ### Question: Show the locations of parties and the names of the party hosts in ascending order of the age of the host. ### Answer: SELECT T3.Location, T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID ORDER BY T2.Age |
Show the locations of parties with hosts older than 50. | CREATE TABLE party (Location VARCHAR, Party_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE HOST (Host_ID VARCHAR, Age INTEGER) | SELECT T3.Location FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T2.Age > 50 | ### Context: CREATE TABLE party (Location VARCHAR, Party_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE HOST (Host_ID VARCHAR, Age INTEGER) ### Question: Show the locations of parties with hosts older than 50. ### Answer: SELECT T3.Location FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T2.Age > 50 |
Show the host names for parties with number of hosts greater than 20. | CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party_ID VARCHAR, Number_of_hosts INTEGER) | SELECT T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T3.Number_of_hosts > 20 | ### Context: CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party_ID VARCHAR, Number_of_hosts INTEGER) ### Question: Show the host names for parties with number of hosts greater than 20. ### Answer: SELECT T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T3.Number_of_hosts > 20 |
Show the name and the nationality of the oldest host. | CREATE TABLE HOST (Name VARCHAR, Nationality VARCHAR, Age VARCHAR) | SELECT Name, Nationality FROM HOST ORDER BY Age DESC LIMIT 1 | ### Context: CREATE TABLE HOST (Name VARCHAR, Nationality VARCHAR, Age VARCHAR) ### Question: Show the name and the nationality of the oldest host. ### Answer: SELECT Name, Nationality FROM HOST ORDER BY Age DESC LIMIT 1 |
List the names of hosts who did not serve as a host of any party in our record. | CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Name VARCHAR, Host_ID VARCHAR) | SELECT Name FROM HOST WHERE NOT Host_ID IN (SELECT Host_ID FROM party_host) | ### Context: CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Name VARCHAR, Host_ID VARCHAR) ### Question: List the names of hosts who did not serve as a host of any party in our record. ### Answer: SELECT Name FROM HOST WHERE NOT Host_ID IN (SELECT Host_ID FROM party_host) |
Show all region code and region name sorted by the codes. | CREATE TABLE region (region_code VARCHAR, region_name VARCHAR) | SELECT region_code, region_name FROM region ORDER BY region_code | ### Context: CREATE TABLE region (region_code VARCHAR, region_name VARCHAR) ### Question: Show all region code and region name sorted by the codes. ### Answer: SELECT region_code, region_name FROM region ORDER BY region_code |
List all region names in alphabetical order. | CREATE TABLE region (region_name VARCHAR) | SELECT region_name FROM region ORDER BY region_name | ### Context: CREATE TABLE region (region_name VARCHAR) ### Question: List all region names in alphabetical order. ### Answer: SELECT region_name FROM region ORDER BY region_name |
Show names for all regions except for Denmark. | CREATE TABLE region (region_name VARCHAR) | SELECT region_name FROM region WHERE region_name <> 'Denmark' | ### Context: CREATE TABLE region (region_name VARCHAR) ### Question: Show names for all regions except for Denmark. ### Answer: SELECT region_name FROM region WHERE region_name <> 'Denmark' |
How many storms had death records? | CREATE TABLE storm (Number_Deaths INTEGER) | SELECT COUNT(*) FROM storm WHERE Number_Deaths > 0 | ### Context: CREATE TABLE storm (Number_Deaths INTEGER) ### Question: How many storms had death records? ### Answer: SELECT COUNT(*) FROM storm WHERE Number_Deaths > 0 |
List name, dates active, and number of deaths for all storms with at least 1 death. | CREATE TABLE storm (name VARCHAR, dates_active VARCHAR, number_deaths VARCHAR) | SELECT name, dates_active, number_deaths FROM storm WHERE number_deaths >= 1 | ### Context: CREATE TABLE storm (name VARCHAR, dates_active VARCHAR, number_deaths VARCHAR) ### Question: List name, dates active, and number of deaths for all storms with at least 1 death. ### Answer: SELECT name, dates_active, number_deaths FROM storm WHERE number_deaths >= 1 |
Show the average and maximum damage for all storms with max speed higher than 1000. | CREATE TABLE storm (damage_millions_USD INTEGER, max_speed INTEGER) | SELECT AVG(damage_millions_USD), MAX(damage_millions_USD) FROM storm WHERE max_speed > 1000 | ### Context: CREATE TABLE storm (damage_millions_USD INTEGER, max_speed INTEGER) ### Question: Show the average and maximum damage for all storms with max speed higher than 1000. ### Answer: SELECT AVG(damage_millions_USD), MAX(damage_millions_USD) FROM storm WHERE max_speed > 1000 |
What is the total number of deaths and damage for all storms with a max speed greater than the average? | CREATE TABLE storm (number_deaths INTEGER, damage_millions_USD INTEGER, max_speed INTEGER) | SELECT SUM(number_deaths), SUM(damage_millions_USD) FROM storm WHERE max_speed > (SELECT AVG(max_speed) FROM storm) | ### Context: CREATE TABLE storm (number_deaths INTEGER, damage_millions_USD INTEGER, max_speed INTEGER) ### Question: What is the total number of deaths and damage for all storms with a max speed greater than the average? ### Answer: SELECT SUM(number_deaths), SUM(damage_millions_USD) FROM storm WHERE max_speed > (SELECT AVG(max_speed) FROM storm) |
List name and damage for all storms in a descending order of max speed. | CREATE TABLE storm (name VARCHAR, damage_millions_USD VARCHAR, max_speed VARCHAR) | SELECT name, damage_millions_USD FROM storm ORDER BY max_speed DESC | ### Context: CREATE TABLE storm (name VARCHAR, damage_millions_USD VARCHAR, max_speed VARCHAR) ### Question: List name and damage for all storms in a descending order of max speed. ### Answer: SELECT name, damage_millions_USD FROM storm ORDER BY max_speed DESC |
How many regions are affected? | CREATE TABLE affected_region (region_id VARCHAR) | SELECT COUNT(DISTINCT region_id) FROM affected_region | ### Context: CREATE TABLE affected_region (region_id VARCHAR) ### Question: How many regions are affected? ### Answer: SELECT COUNT(DISTINCT region_id) FROM affected_region |
Show the name for regions not affected. | CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_name VARCHAR, region_id VARCHAR) | SELECT region_name FROM region WHERE NOT region_id IN (SELECT region_id FROM affected_region) | ### Context: CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_name VARCHAR, region_id VARCHAR) ### Question: Show the name for regions not affected. ### Answer: SELECT region_name FROM region WHERE NOT region_id IN (SELECT region_id FROM affected_region) |
Show the name for regions and the number of storms for each region. | CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR) | SELECT T1.region_name, COUNT(*) FROM region AS T1 JOIN affected_region AS T2 ON T1.region_id = T2.region_id GROUP BY T1.region_id | ### Context: CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR) ### Question: Show the name for regions and the number of storms for each region. ### Answer: SELECT T1.region_name, COUNT(*) FROM region AS T1 JOIN affected_region AS T2 ON T1.region_id = T2.region_id GROUP BY T1.region_id |
List the name for storms and the number of affected regions for each storm. | CREATE TABLE affected_region (storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) | SELECT T1.name, COUNT(*) FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id | ### Context: CREATE TABLE affected_region (storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) ### Question: List the name for storms and the number of affected regions for each storm. ### Answer: SELECT T1.name, COUNT(*) FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id |
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