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What is the storm name and max speed which affected the greatest number of regions? | CREATE TABLE storm (name VARCHAR, max_speed VARCHAR, storm_id VARCHAR); CREATE TABLE affected_region (storm_id VARCHAR) | SELECT T1.name, T1.max_speed FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE storm (name VARCHAR, max_speed VARCHAR, storm_id VARCHAR); CREATE TABLE affected_region (storm_id VARCHAR) ### Question: What is the storm name and max speed which affected the greatest number of regions? ### Answer: SELECT T1.name, T1.max_speed FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id ORDER BY COUNT(*) DESC LIMIT 1 |
Show the name of storms which don't have affected region in record. | CREATE TABLE affected_region (name VARCHAR, storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) | SELECT name FROM storm WHERE NOT storm_id IN (SELECT storm_id FROM affected_region) | ### Context: CREATE TABLE affected_region (name VARCHAR, storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) ### Question: Show the name of storms which don't have affected region in record. ### Answer: SELECT name FROM storm WHERE NOT storm_id IN (SELECT storm_id FROM affected_region) |
Show storm name with at least two regions and 10 cities affected. | CREATE TABLE affected_region (storm_id VARCHAR, number_city_affected INTEGER); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) | SELECT T1.name FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id HAVING COUNT(*) >= 2 INTERSECT SELECT T1.name FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id HAVING SUM(T2.number_city_affected) >= 10 | ### Context: CREATE TABLE affected_region (storm_id VARCHAR, number_city_affected INTEGER); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) ### Question: Show storm name with at least two regions and 10 cities affected. ### Answer: SELECT T1.name FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id HAVING COUNT(*) >= 2 INTERSECT SELECT T1.name FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id HAVING SUM(T2.number_city_affected) >= 10 |
Show all storm names except for those with at least two affected regions. | CREATE TABLE storm (name VARCHAR); CREATE TABLE affected_region (storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) | SELECT name FROM storm EXCEPT SELECT T1.name FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id HAVING COUNT(*) >= 2 | ### Context: CREATE TABLE storm (name VARCHAR); CREATE TABLE affected_region (storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) ### Question: Show all storm names except for those with at least two affected regions. ### Answer: SELECT name FROM storm EXCEPT SELECT T1.name FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id HAVING COUNT(*) >= 2 |
What are the region names affected by the storm with a number of deaths of least 10? | CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE storm (storm_id VARCHAR, number_deaths VARCHAR) | SELECT T2.region_name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T3.number_deaths >= 10 | ### Context: CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE storm (storm_id VARCHAR, number_deaths VARCHAR) ### Question: What are the region names affected by the storm with a number of deaths of least 10? ### Answer: SELECT T2.region_name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T3.number_deaths >= 10 |
Show all storm names affecting region "Denmark". | CREATE TABLE region (region_id VARCHAR, region_name VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) | SELECT T3.name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T2.region_name = 'Denmark' | ### Context: CREATE TABLE region (region_id VARCHAR, region_name VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) ### Question: Show all storm names affecting region "Denmark". ### Answer: SELECT T3.name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T2.region_name = 'Denmark' |
Show the region name with at least two storms. | CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR) | SELECT T1.region_name FROM region AS T1 JOIN affected_region AS T2 ON T1.region_id = T2.region_id GROUP BY T1.region_id HAVING COUNT(*) >= 2 | ### Context: CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR) ### Question: Show the region name with at least two storms. ### Answer: SELECT T1.region_name FROM region AS T1 JOIN affected_region AS T2 ON T1.region_id = T2.region_id GROUP BY T1.region_id HAVING COUNT(*) >= 2 |
Find the names of the regions which were affected by the storm that killed the greatest number of people. | CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE storm (storm_id VARCHAR, Number_Deaths VARCHAR) | SELECT T2.region_name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id ORDER BY T3.Number_Deaths DESC LIMIT 1 | ### Context: CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE storm (storm_id VARCHAR, Number_Deaths VARCHAR) ### Question: Find the names of the regions which were affected by the storm that killed the greatest number of people. ### Answer: SELECT T2.region_name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id ORDER BY T3.Number_Deaths DESC LIMIT 1 |
Find the name of the storm that affected both Afghanistan and Albania regions. | CREATE TABLE storm (Name VARCHAR, storm_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE region (region_id VARCHAR, Region_name VARCHAR) | SELECT T3.Name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T2.Region_name = 'Afghanistan' INTERSECT SELECT T3.Name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T2.Region_name = 'Albania' | ### Context: CREATE TABLE storm (Name VARCHAR, storm_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE region (region_id VARCHAR, Region_name VARCHAR) ### Question: Find the name of the storm that affected both Afghanistan and Albania regions. ### Answer: SELECT T3.Name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T2.Region_name = 'Afghanistan' INTERSECT SELECT T3.Name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T2.Region_name = 'Albania' |
How many counties are there in total? | CREATE TABLE county (Id VARCHAR) | SELECT COUNT(*) FROM county | ### Context: CREATE TABLE county (Id VARCHAR) ### Question: How many counties are there in total? ### Answer: SELECT COUNT(*) FROM county |
Show the county name and population of all counties. | CREATE TABLE county (County_name VARCHAR, Population VARCHAR) | SELECT County_name, Population FROM county | ### Context: CREATE TABLE county (County_name VARCHAR, Population VARCHAR) ### Question: Show the county name and population of all counties. ### Answer: SELECT County_name, Population FROM county |
Show the average population of all counties. | CREATE TABLE county (Population INTEGER) | SELECT AVG(Population) FROM county | ### Context: CREATE TABLE county (Population INTEGER) ### Question: Show the average population of all counties. ### Answer: SELECT AVG(Population) FROM county |
Return the maximum and minimum population among all counties. | CREATE TABLE county (Population INTEGER) | SELECT MAX(Population), MIN(Population) FROM county | ### Context: CREATE TABLE county (Population INTEGER) ### Question: Return the maximum and minimum population among all counties. ### Answer: SELECT MAX(Population), MIN(Population) FROM county |
Show all the distinct districts for elections. | CREATE TABLE election (District VARCHAR) | SELECT DISTINCT District FROM election | ### Context: CREATE TABLE election (District VARCHAR) ### Question: Show all the distinct districts for elections. ### Answer: SELECT DISTINCT District FROM election |
Show the zip code of the county with name "Howard". | CREATE TABLE county (Zip_code VARCHAR, County_name VARCHAR) | SELECT Zip_code FROM county WHERE County_name = "Howard" | ### Context: CREATE TABLE county (Zip_code VARCHAR, County_name VARCHAR) ### Question: Show the zip code of the county with name "Howard". ### Answer: SELECT Zip_code FROM county WHERE County_name = "Howard" |
Show the delegate from district 1 in election. | CREATE TABLE election (Delegate VARCHAR, District VARCHAR) | SELECT Delegate FROM election WHERE District = 1 | ### Context: CREATE TABLE election (Delegate VARCHAR, District VARCHAR) ### Question: Show the delegate from district 1 in election. ### Answer: SELECT Delegate FROM election WHERE District = 1 |
Show the delegate and committee information of elections. | CREATE TABLE election (Delegate VARCHAR, Committee VARCHAR) | SELECT Delegate, Committee FROM election | ### Context: CREATE TABLE election (Delegate VARCHAR, Committee VARCHAR) ### Question: Show the delegate and committee information of elections. ### Answer: SELECT Delegate, Committee FROM election |
How many distinct governors are there? | CREATE TABLE party (Governor VARCHAR) | SELECT COUNT(DISTINCT Governor) FROM party | ### Context: CREATE TABLE party (Governor VARCHAR) ### Question: How many distinct governors are there? ### Answer: SELECT COUNT(DISTINCT Governor) FROM party |
Show the lieutenant governor and comptroller from the democratic party. | CREATE TABLE party (Lieutenant_Governor VARCHAR, Comptroller VARCHAR, Party VARCHAR) | SELECT Lieutenant_Governor, Comptroller FROM party WHERE Party = "Democratic" | ### Context: CREATE TABLE party (Lieutenant_Governor VARCHAR, Comptroller VARCHAR, Party VARCHAR) ### Question: Show the lieutenant governor and comptroller from the democratic party. ### Answer: SELECT Lieutenant_Governor, Comptroller FROM party WHERE Party = "Democratic" |
In which distinct years was the governor "Eliot Spitzer"? | CREATE TABLE party (YEAR VARCHAR, Governor VARCHAR) | SELECT DISTINCT YEAR FROM party WHERE Governor = "Eliot Spitzer" | ### Context: CREATE TABLE party (YEAR VARCHAR, Governor VARCHAR) ### Question: In which distinct years was the governor "Eliot Spitzer"? ### Answer: SELECT DISTINCT YEAR FROM party WHERE Governor = "Eliot Spitzer" |
Show all the information about election. | CREATE TABLE election (Id VARCHAR) | SELECT * FROM election | ### Context: CREATE TABLE election (Id VARCHAR) ### Question: Show all the information about election. ### Answer: SELECT * FROM election |
Show the delegates and the names of county they belong to. | CREATE TABLE election (Delegate VARCHAR, District VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR) | SELECT T2.Delegate, T1.County_name FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District | ### Context: CREATE TABLE election (Delegate VARCHAR, District VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR) ### Question: Show the delegates and the names of county they belong to. ### Answer: SELECT T2.Delegate, T1.County_name FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District |
Which delegates are from counties with population smaller than 100000? | CREATE TABLE election (Delegate VARCHAR, District VARCHAR); CREATE TABLE county (County_id VARCHAR, Population INTEGER) | SELECT T2.Delegate FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District WHERE T1.Population < 100000 | ### Context: CREATE TABLE election (Delegate VARCHAR, District VARCHAR); CREATE TABLE county (County_id VARCHAR, Population INTEGER) ### Question: Which delegates are from counties with population smaller than 100000? ### Answer: SELECT T2.Delegate FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District WHERE T1.Population < 100000 |
How many distinct delegates are from counties with population larger than 50000? | CREATE TABLE election (Delegate VARCHAR, District VARCHAR); CREATE TABLE county (County_id VARCHAR, Population INTEGER) | SELECT COUNT(DISTINCT T2.Delegate) FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District WHERE T1.Population > 50000 | ### Context: CREATE TABLE election (Delegate VARCHAR, District VARCHAR); CREATE TABLE county (County_id VARCHAR, Population INTEGER) ### Question: How many distinct delegates are from counties with population larger than 50000? ### Answer: SELECT COUNT(DISTINCT T2.Delegate) FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District WHERE T1.Population > 50000 |
What are the names of the county that the delegates on "Appropriations" committee belong to? | CREATE TABLE election (District VARCHAR, Committee VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR) | SELECT T1.County_name FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District WHERE T2.Committee = "Appropriations" | ### Context: CREATE TABLE election (District VARCHAR, Committee VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR) ### Question: What are the names of the county that the delegates on "Appropriations" committee belong to? ### Answer: SELECT T1.County_name FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District WHERE T2.Committee = "Appropriations" |
Show the delegates and the names of the party they belong to. | CREATE TABLE election (Delegate VARCHAR, Party VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) | SELECT T1.Delegate, T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID | ### Context: CREATE TABLE election (Delegate VARCHAR, Party VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) ### Question: Show the delegates and the names of the party they belong to. ### Answer: SELECT T1.Delegate, T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID |
Who were the governors of the parties associated with delegates from district 1? | CREATE TABLE party (Governor VARCHAR, Party_ID VARCHAR); CREATE TABLE election (Party VARCHAR, District VARCHAR) | SELECT T2.Governor FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.District = 1 | ### Context: CREATE TABLE party (Governor VARCHAR, Party_ID VARCHAR); CREATE TABLE election (Party VARCHAR, District VARCHAR) ### Question: Who were the governors of the parties associated with delegates from district 1? ### Answer: SELECT T2.Governor FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.District = 1 |
Who were the comptrollers of the parties associated with the delegates from district 1 or district 2? | CREATE TABLE party (Comptroller VARCHAR, Party_ID VARCHAR); CREATE TABLE election (Party VARCHAR, District VARCHAR) | SELECT T2.Comptroller FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.District = 1 OR T1.District = 2 | ### Context: CREATE TABLE party (Comptroller VARCHAR, Party_ID VARCHAR); CREATE TABLE election (Party VARCHAR, District VARCHAR) ### Question: Who were the comptrollers of the parties associated with the delegates from district 1 or district 2? ### Answer: SELECT T2.Comptroller FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.District = 1 OR T1.District = 2 |
Return all the committees that have delegates from Democratic party. | CREATE TABLE election (Committee VARCHAR, Party VARCHAR); CREATE TABLE party (Party_ID VARCHAR, Party VARCHAR) | SELECT T1.Committee FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T2.Party = "Democratic" | ### Context: CREATE TABLE election (Committee VARCHAR, Party VARCHAR); CREATE TABLE party (Party_ID VARCHAR, Party VARCHAR) ### Question: Return all the committees that have delegates from Democratic party. ### Answer: SELECT T1.Committee FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T2.Party = "Democratic" |
Show the name of each county along with the corresponding number of delegates from that county. | CREATE TABLE election (District VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR) | SELECT T1.County_name, COUNT(*) FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District GROUP BY T1.County_id | ### Context: CREATE TABLE election (District VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR) ### Question: Show the name of each county along with the corresponding number of delegates from that county. ### Answer: SELECT T1.County_name, COUNT(*) FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District GROUP BY T1.County_id |
Show the name of each party and the corresponding number of delegates from that party. | CREATE TABLE election (Party VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) | SELECT T2.Party, COUNT(*) FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID GROUP BY T1.Party | ### Context: CREATE TABLE election (Party VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) ### Question: Show the name of each party and the corresponding number of delegates from that party. ### Answer: SELECT T2.Party, COUNT(*) FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID GROUP BY T1.Party |
Return the names of all counties sorted by population in ascending order. | CREATE TABLE county (County_name VARCHAR, Population VARCHAR) | SELECT County_name FROM county ORDER BY Population | ### Context: CREATE TABLE county (County_name VARCHAR, Population VARCHAR) ### Question: Return the names of all counties sorted by population in ascending order. ### Answer: SELECT County_name FROM county ORDER BY Population |
Return the names of all counties sorted by county name in descending alphabetical order. | CREATE TABLE county (County_name VARCHAR) | SELECT County_name FROM county ORDER BY County_name DESC | ### Context: CREATE TABLE county (County_name VARCHAR) ### Question: Return the names of all counties sorted by county name in descending alphabetical order. ### Answer: SELECT County_name FROM county ORDER BY County_name DESC |
Show the name of the county with the biggest population. | CREATE TABLE county (County_name VARCHAR, Population VARCHAR) | SELECT County_name FROM county ORDER BY Population DESC LIMIT 1 | ### Context: CREATE TABLE county (County_name VARCHAR, Population VARCHAR) ### Question: Show the name of the county with the biggest population. ### Answer: SELECT County_name FROM county ORDER BY Population DESC LIMIT 1 |
Show the 3 counties with the smallest population. | CREATE TABLE county (County_name VARCHAR, Population VARCHAR) | SELECT County_name FROM county ORDER BY Population LIMIT 3 | ### Context: CREATE TABLE county (County_name VARCHAR, Population VARCHAR) ### Question: Show the 3 counties with the smallest population. ### Answer: SELECT County_name FROM county ORDER BY Population LIMIT 3 |
Show the names of counties that have at least two delegates. | CREATE TABLE election (District VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR) | SELECT T1.County_name FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District GROUP BY T1.County_id HAVING COUNT(*) >= 2 | ### Context: CREATE TABLE election (District VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR) ### Question: Show the names of counties that have at least two delegates. ### Answer: SELECT T1.County_name FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District GROUP BY T1.County_id HAVING COUNT(*) >= 2 |
Show the name of the party that has at least two records. | CREATE TABLE party (Party VARCHAR) | SELECT Party FROM party GROUP BY Party HAVING COUNT(*) >= 2 | ### Context: CREATE TABLE party (Party VARCHAR) ### Question: Show the name of the party that has at least two records. ### Answer: SELECT Party FROM party GROUP BY Party HAVING COUNT(*) >= 2 |
Show the name of the party that has the most delegates. | CREATE TABLE election (Party VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) | SELECT T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID GROUP BY T1.Party ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE election (Party VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) ### Question: Show the name of the party that has the most delegates. ### Answer: SELECT T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID GROUP BY T1.Party ORDER BY COUNT(*) DESC LIMIT 1 |
Show the people that have been governor the most times. | CREATE TABLE party (Governor VARCHAR) | SELECT Governor FROM party GROUP BY Governor ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE party (Governor VARCHAR) ### Question: Show the people that have been governor the most times. ### Answer: SELECT Governor FROM party GROUP BY Governor ORDER BY COUNT(*) DESC LIMIT 1 |
Show the people that have been comptroller the most times and the corresponding number of times. | CREATE TABLE party (Comptroller VARCHAR) | SELECT Comptroller, COUNT(*) FROM party GROUP BY Comptroller ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE party (Comptroller VARCHAR) ### Question: Show the people that have been comptroller the most times and the corresponding number of times. ### Answer: SELECT Comptroller, COUNT(*) FROM party GROUP BY Comptroller ORDER BY COUNT(*) DESC LIMIT 1 |
What are the names of parties that do not have delegates in election? | CREATE TABLE election (Party VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) | SELECT Party FROM party WHERE NOT Party_ID IN (SELECT Party FROM election) | ### Context: CREATE TABLE election (Party VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) ### Question: What are the names of parties that do not have delegates in election? ### Answer: SELECT Party FROM party WHERE NOT Party_ID IN (SELECT Party FROM election) |
What are the names of parties that have both delegates on "Appropriations" committee and | CREATE TABLE election (Party VARCHAR, Committee VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) | SELECT T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.Committee = "Appropriations" INTERSECT SELECT T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.Committee = "Economic Matters" | ### Context: CREATE TABLE election (Party VARCHAR, Committee VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) ### Question: What are the names of parties that have both delegates on "Appropriations" committee and ### Answer: SELECT T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.Committee = "Appropriations" INTERSECT SELECT T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.Committee = "Economic Matters" |
Which committees have delegates from both democratic party and liberal party? | CREATE TABLE election (Committee VARCHAR, Party VARCHAR); CREATE TABLE party (Party_ID VARCHAR, Party VARCHAR) | SELECT T1.Committee FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T2.Party = "Democratic" INTERSECT SELECT T1.Committee FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T2.Party = "Liberal" | ### Context: CREATE TABLE election (Committee VARCHAR, Party VARCHAR); CREATE TABLE party (Party_ID VARCHAR, Party VARCHAR) ### Question: Which committees have delegates from both democratic party and liberal party? ### Answer: SELECT T1.Committee FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T2.Party = "Democratic" INTERSECT SELECT T1.Committee FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T2.Party = "Liberal" |
How many journalists are there? | CREATE TABLE journalist (Id VARCHAR) | SELECT COUNT(*) FROM journalist | ### Context: CREATE TABLE journalist (Id VARCHAR) ### Question: How many journalists are there? ### Answer: SELECT COUNT(*) FROM journalist |
List the names of journalists in ascending order of years working. | CREATE TABLE journalist (Name VARCHAR, Years_working VARCHAR) | SELECT Name FROM journalist ORDER BY Years_working | ### Context: CREATE TABLE journalist (Name VARCHAR, Years_working VARCHAR) ### Question: List the names of journalists in ascending order of years working. ### Answer: SELECT Name FROM journalist ORDER BY Years_working |
What are the nationalities and ages of journalists? | CREATE TABLE journalist (Nationality VARCHAR, Age VARCHAR) | SELECT Nationality, Age FROM journalist | ### Context: CREATE TABLE journalist (Nationality VARCHAR, Age VARCHAR) ### Question: What are the nationalities and ages of journalists? ### Answer: SELECT Nationality, Age FROM journalist |
Show the names of journalists from "England" or "Wales". | CREATE TABLE journalist (Name VARCHAR, Nationality VARCHAR) | SELECT Name FROM journalist WHERE Nationality = "England" OR Nationality = "Wales" | ### Context: CREATE TABLE journalist (Name VARCHAR, Nationality VARCHAR) ### Question: Show the names of journalists from "England" or "Wales". ### Answer: SELECT Name FROM journalist WHERE Nationality = "England" OR Nationality = "Wales" |
What is the average number of years spent working as a journalist? | CREATE TABLE journalist (Years_working INTEGER) | SELECT AVG(Years_working) FROM journalist | ### Context: CREATE TABLE journalist (Years_working INTEGER) ### Question: What is the average number of years spent working as a journalist? ### Answer: SELECT AVG(Years_working) FROM journalist |
What is the nationality of the journalist with the largest number of years working? | CREATE TABLE journalist (Nationality VARCHAR, Years_working VARCHAR) | SELECT Nationality FROM journalist ORDER BY Years_working DESC LIMIT 1 | ### Context: CREATE TABLE journalist (Nationality VARCHAR, Years_working VARCHAR) ### Question: What is the nationality of the journalist with the largest number of years working? ### Answer: SELECT Nationality FROM journalist ORDER BY Years_working DESC LIMIT 1 |
Show the different nationalities and the number of journalists of each nationality. | CREATE TABLE journalist (Nationality VARCHAR) | SELECT Nationality, COUNT(*) FROM journalist GROUP BY Nationality | ### Context: CREATE TABLE journalist (Nationality VARCHAR) ### Question: Show the different nationalities and the number of journalists of each nationality. ### Answer: SELECT Nationality, COUNT(*) FROM journalist GROUP BY Nationality |
Show the most common nationality for journalists. | CREATE TABLE journalist (Nationality VARCHAR) | SELECT Nationality FROM journalist GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE journalist (Nationality VARCHAR) ### Question: Show the most common nationality for journalists. ### Answer: SELECT Nationality FROM journalist GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1 |
Show the nations that have both journalists with more than 10 years of working and journalists with less than 3 years of working. | CREATE TABLE journalist (Nationality VARCHAR, Years_working INTEGER) | SELECT Nationality FROM journalist WHERE Years_working > 10 INTERSECT SELECT Nationality FROM journalist WHERE Years_working < 3 | ### Context: CREATE TABLE journalist (Nationality VARCHAR, Years_working INTEGER) ### Question: Show the nations that have both journalists with more than 10 years of working and journalists with less than 3 years of working. ### Answer: SELECT Nationality FROM journalist WHERE Years_working > 10 INTERSECT SELECT Nationality FROM journalist WHERE Years_working < 3 |
Show the dates, places, and names of events in descending order of the attendance. | CREATE TABLE event (Date VARCHAR, Name VARCHAR, venue VARCHAR, Event_Attendance VARCHAR) | SELECT Date, Name, venue FROM event ORDER BY Event_Attendance DESC | ### Context: CREATE TABLE event (Date VARCHAR, Name VARCHAR, venue VARCHAR, Event_Attendance VARCHAR) ### Question: Show the dates, places, and names of events in descending order of the attendance. ### Answer: SELECT Date, Name, venue FROM event ORDER BY Event_Attendance DESC |
Show the names of journalists and the dates of the events they reported. | CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Date VARCHAR, Event_ID VARCHAR) | SELECT T3.Name, T2.Date FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID | ### Context: CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Date VARCHAR, Event_ID VARCHAR) ### Question: Show the names of journalists and the dates of the events they reported. ### Answer: SELECT T3.Name, T2.Date FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID |
Show the names of journalists and the names of the events they reported in ascending order | CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Name VARCHAR, Event_ID VARCHAR, Event_Attendance VARCHAR) | SELECT T3.Name, T2.Name FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID ORDER BY T2.Event_Attendance | ### Context: CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Name VARCHAR, Event_ID VARCHAR, Event_Attendance VARCHAR) ### Question: Show the names of journalists and the names of the events they reported in ascending order ### Answer: SELECT T3.Name, T2.Name FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID ORDER BY T2.Event_Attendance |
Show the names of journalists and the number of events they reported. | CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Event_ID VARCHAR) | SELECT T3.Name, COUNT(*) FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID GROUP BY T3.Name | ### Context: CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Event_ID VARCHAR) ### Question: Show the names of journalists and the number of events they reported. ### Answer: SELECT T3.Name, COUNT(*) FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID GROUP BY T3.Name |
Show the names of journalists that have reported more than one event. | CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Event_ID VARCHAR) | SELECT T3.Name FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID GROUP BY T3.Name HAVING COUNT(*) > 1 | ### Context: CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Event_ID VARCHAR) ### Question: Show the names of journalists that have reported more than one event. ### Answer: SELECT T3.Name FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID GROUP BY T3.Name HAVING COUNT(*) > 1 |
List the names of journalists who have not reported any event. | CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Name VARCHAR, journalist_ID VARCHAR) | SELECT Name FROM journalist WHERE NOT journalist_ID IN (SELECT journalist_ID FROM news_report) | ### Context: CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Name VARCHAR, journalist_ID VARCHAR) ### Question: List the names of journalists who have not reported any event. ### Answer: SELECT Name FROM journalist WHERE NOT journalist_ID IN (SELECT journalist_ID FROM news_report) |
what are the average and maximum attendances of all events? | CREATE TABLE event (Event_Attendance INTEGER) | SELECT AVG(Event_Attendance), MAX(Event_Attendance) FROM event | ### Context: CREATE TABLE event (Event_Attendance INTEGER) ### Question: what are the average and maximum attendances of all events? ### Answer: SELECT AVG(Event_Attendance), MAX(Event_Attendance) FROM event |
Find the average age and experience working length of journalists working on different role type. | CREATE TABLE news_report (work_type VARCHAR, journalist_id VARCHAR); CREATE TABLE journalist (age INTEGER, journalist_id VARCHAR) | SELECT AVG(t1.age), AVG(Years_working), t2.work_type FROM journalist AS t1 JOIN news_report AS t2 ON t1.journalist_id = t2.journalist_id GROUP BY t2.work_type | ### Context: CREATE TABLE news_report (work_type VARCHAR, journalist_id VARCHAR); CREATE TABLE journalist (age INTEGER, journalist_id VARCHAR) ### Question: Find the average age and experience working length of journalists working on different role type. ### Answer: SELECT AVG(t1.age), AVG(Years_working), t2.work_type FROM journalist AS t1 JOIN news_report AS t2 ON t1.journalist_id = t2.journalist_id GROUP BY t2.work_type |
List the event venues and names that have the top 2 most number of people attended. | CREATE TABLE event (venue VARCHAR, name VARCHAR, Event_Attendance VARCHAR) | SELECT venue, name FROM event ORDER BY Event_Attendance DESC LIMIT 2 | ### Context: CREATE TABLE event (venue VARCHAR, name VARCHAR, Event_Attendance VARCHAR) ### Question: List the event venues and names that have the top 2 most number of people attended. ### Answer: SELECT venue, name FROM event ORDER BY Event_Attendance DESC LIMIT 2 |
Show me all the restaurants. | CREATE TABLE Restaurant (ResName VARCHAR) | SELECT ResName FROM Restaurant | ### Context: CREATE TABLE Restaurant (ResName VARCHAR) ### Question: Show me all the restaurants. ### Answer: SELECT ResName FROM Restaurant |
What is the address of the restaurant Subway? | CREATE TABLE Restaurant (Address VARCHAR, ResName VARCHAR) | SELECT Address FROM Restaurant WHERE ResName = "Subway" | ### Context: CREATE TABLE Restaurant (Address VARCHAR, ResName VARCHAR) ### Question: What is the address of the restaurant Subway? ### Answer: SELECT Address FROM Restaurant WHERE ResName = "Subway" |
What is the rating of the restaurant Subway? | CREATE TABLE Restaurant (Rating VARCHAR, ResName VARCHAR) | SELECT Rating FROM Restaurant WHERE ResName = "Subway" | ### Context: CREATE TABLE Restaurant (Rating VARCHAR, ResName VARCHAR) ### Question: What is the rating of the restaurant Subway? ### Answer: SELECT Rating FROM Restaurant WHERE ResName = "Subway" |
List all restaurant types. | CREATE TABLE Restaurant_Type (ResTypeName VARCHAR) | SELECT ResTypeName FROM Restaurant_Type | ### Context: CREATE TABLE Restaurant_Type (ResTypeName VARCHAR) ### Question: List all restaurant types. ### Answer: SELECT ResTypeName FROM Restaurant_Type |
What is the description of the restaurant type Sandwich? | CREATE TABLE Restaurant_Type (ResTypeDescription VARCHAR, ResTypeName VARCHAR) | SELECT ResTypeDescription FROM Restaurant_Type WHERE ResTypeName = "Sandwich" | ### Context: CREATE TABLE Restaurant_Type (ResTypeDescription VARCHAR, ResTypeName VARCHAR) ### Question: What is the description of the restaurant type Sandwich? ### Answer: SELECT ResTypeDescription FROM Restaurant_Type WHERE ResTypeName = "Sandwich" |
Which restaurants have highest rating? List the restaurant name and its rating. | CREATE TABLE Restaurant (ResName VARCHAR, Rating VARCHAR) | SELECT ResName, Rating FROM Restaurant ORDER BY Rating DESC LIMIT 1 | ### Context: CREATE TABLE Restaurant (ResName VARCHAR, Rating VARCHAR) ### Question: Which restaurants have highest rating? List the restaurant name and its rating. ### Answer: SELECT ResName, Rating FROM Restaurant ORDER BY Rating DESC LIMIT 1 |
What is the age of student Linda Smith? | CREATE TABLE Student (Age VARCHAR, Fname VARCHAR, Lname VARCHAR) | SELECT Age FROM Student WHERE Fname = "Linda" AND Lname = "Smith" | ### Context: CREATE TABLE Student (Age VARCHAR, Fname VARCHAR, Lname VARCHAR) ### Question: What is the age of student Linda Smith? ### Answer: SELECT Age FROM Student WHERE Fname = "Linda" AND Lname = "Smith" |
What is the gender of the student Linda Smith? | CREATE TABLE Student (Sex VARCHAR, Fname VARCHAR, Lname VARCHAR) | SELECT Sex FROM Student WHERE Fname = "Linda" AND Lname = "Smith" | ### Context: CREATE TABLE Student (Sex VARCHAR, Fname VARCHAR, Lname VARCHAR) ### Question: What is the gender of the student Linda Smith? ### Answer: SELECT Sex FROM Student WHERE Fname = "Linda" AND Lname = "Smith" |
List all students' first names and last names who majored in 600. | CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Major VARCHAR) | SELECT Fname, Lname FROM Student WHERE Major = 600 | ### Context: CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Major VARCHAR) ### Question: List all students' first names and last names who majored in 600. ### Answer: SELECT Fname, Lname FROM Student WHERE Major = 600 |
Which city does student Linda Smith live in? | CREATE TABLE Student (city_code VARCHAR, Fname VARCHAR, Lname VARCHAR) | SELECT city_code FROM Student WHERE Fname = "Linda" AND Lname = "Smith" | ### Context: CREATE TABLE Student (city_code VARCHAR, Fname VARCHAR, Lname VARCHAR) ### Question: Which city does student Linda Smith live in? ### Answer: SELECT city_code FROM Student WHERE Fname = "Linda" AND Lname = "Smith" |
Advisor 1121 has how many students? | CREATE TABLE Student (Advisor VARCHAR) | SELECT COUNT(*) FROM Student WHERE Advisor = 1121 | ### Context: CREATE TABLE Student (Advisor VARCHAR) ### Question: Advisor 1121 has how many students? ### Answer: SELECT COUNT(*) FROM Student WHERE Advisor = 1121 |
Which Advisor has most of students? List advisor and the number of students. | CREATE TABLE Student (Advisor VARCHAR) | SELECT Advisor, COUNT(*) FROM Student GROUP BY Advisor ORDER BY COUNT(Advisor) DESC LIMIT 1 | ### Context: CREATE TABLE Student (Advisor VARCHAR) ### Question: Which Advisor has most of students? List advisor and the number of students. ### Answer: SELECT Advisor, COUNT(*) FROM Student GROUP BY Advisor ORDER BY COUNT(Advisor) DESC LIMIT 1 |
Which major has least number of students? List the major and the number of students. | CREATE TABLE Student (Major VARCHAR) | SELECT Major, COUNT(*) FROM Student GROUP BY Major ORDER BY COUNT(Major) LIMIT 1 | ### Context: CREATE TABLE Student (Major VARCHAR) ### Question: Which major has least number of students? List the major and the number of students. ### Answer: SELECT Major, COUNT(*) FROM Student GROUP BY Major ORDER BY COUNT(Major) LIMIT 1 |
Which major has between 2 and 30 number of students? List major and the number of students. | CREATE TABLE Student (Major VARCHAR) | SELECT Major, COUNT(*) FROM Student GROUP BY Major HAVING COUNT(Major) BETWEEN 2 AND 30 | ### Context: CREATE TABLE Student (Major VARCHAR) ### Question: Which major has between 2 and 30 number of students? List major and the number of students. ### Answer: SELECT Major, COUNT(*) FROM Student GROUP BY Major HAVING COUNT(Major) BETWEEN 2 AND 30 |
Which student's age is older than 18 and is majoring in 600? List each student's first and last name. | CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Age VARCHAR, Major VARCHAR) | SELECT Fname, Lname FROM Student WHERE Age > 18 AND Major = 600 | ### Context: CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Age VARCHAR, Major VARCHAR) ### Question: Which student's age is older than 18 and is majoring in 600? List each student's first and last name. ### Answer: SELECT Fname, Lname FROM Student WHERE Age > 18 AND Major = 600 |
List all female students age is older than 18 who is not majoring in 600. List students' first name and last name. | CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Sex VARCHAR, Age VARCHAR, Major VARCHAR) | SELECT Fname, Lname FROM Student WHERE Age > 18 AND Major <> 600 AND Sex = 'F' | ### Context: CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Sex VARCHAR, Age VARCHAR, Major VARCHAR) ### Question: List all female students age is older than 18 who is not majoring in 600. List students' first name and last name. ### Answer: SELECT Fname, Lname FROM Student WHERE Age > 18 AND Major <> 600 AND Sex = 'F' |
How many restaurant is the Sandwich type restaurant? | CREATE TABLE Type_Of_Restaurant (Id VARCHAR); CREATE TABLE Restaurant (Id VARCHAR); CREATE TABLE Restaurant_Type (Id VARCHAR) | SELECT COUNT(*) FROM Restaurant JOIN Type_Of_Restaurant ON Restaurant.ResID = Type_Of_Restaurant.ResID JOIN Restaurant_Type ON Type_Of_Restaurant.ResTypeID = Restaurant_Type.ResTypeID GROUP BY Type_Of_Restaurant.ResTypeID HAVING Restaurant_Type.ResTypeName = 'Sandwich' | ### Context: CREATE TABLE Type_Of_Restaurant (Id VARCHAR); CREATE TABLE Restaurant (Id VARCHAR); CREATE TABLE Restaurant_Type (Id VARCHAR) ### Question: How many restaurant is the Sandwich type restaurant? ### Answer: SELECT COUNT(*) FROM Restaurant JOIN Type_Of_Restaurant ON Restaurant.ResID = Type_Of_Restaurant.ResID JOIN Restaurant_Type ON Type_Of_Restaurant.ResTypeID = Restaurant_Type.ResTypeID GROUP BY Type_Of_Restaurant.ResTypeID HAVING Restaurant_Type.ResTypeName = 'Sandwich' |
How long does student Linda Smith spend on the restaurant in total? | CREATE TABLE Visits_Restaurant (Spent INTEGER); CREATE TABLE Student (Spent INTEGER) | SELECT SUM(Spent) FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID WHERE Student.Fname = "Linda" AND Student.Lname = "Smith" | ### Context: CREATE TABLE Visits_Restaurant (Spent INTEGER); CREATE TABLE Student (Spent INTEGER) ### Question: How long does student Linda Smith spend on the restaurant in total? ### Answer: SELECT SUM(Spent) FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID WHERE Student.Fname = "Linda" AND Student.Lname = "Smith" |
How many times has the student Linda Smith visited Subway? | CREATE TABLE Visits_Restaurant (Id VARCHAR); CREATE TABLE Student (Id VARCHAR); CREATE TABLE Restaurant (Id VARCHAR) | SELECT COUNT(*) FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID JOIN Restaurant ON Visits_Restaurant.ResID = Restaurant.ResID WHERE Student.Fname = "Linda" AND Student.Lname = "Smith" AND Restaurant.ResName = "Subway" | ### Context: CREATE TABLE Visits_Restaurant (Id VARCHAR); CREATE TABLE Student (Id VARCHAR); CREATE TABLE Restaurant (Id VARCHAR) ### Question: How many times has the student Linda Smith visited Subway? ### Answer: SELECT COUNT(*) FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID JOIN Restaurant ON Visits_Restaurant.ResID = Restaurant.ResID WHERE Student.Fname = "Linda" AND Student.Lname = "Smith" AND Restaurant.ResName = "Subway" |
When did Linda Smith visit Subway? | CREATE TABLE Restaurant (TIME VARCHAR); CREATE TABLE Visits_Restaurant (TIME VARCHAR); CREATE TABLE Student (TIME VARCHAR) | SELECT TIME FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID JOIN Restaurant ON Visits_Restaurant.ResID = Restaurant.ResID WHERE Student.Fname = "Linda" AND Student.Lname = "Smith" AND Restaurant.ResName = "Subway" | ### Context: CREATE TABLE Restaurant (TIME VARCHAR); CREATE TABLE Visits_Restaurant (TIME VARCHAR); CREATE TABLE Student (TIME VARCHAR) ### Question: When did Linda Smith visit Subway? ### Answer: SELECT TIME FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID JOIN Restaurant ON Visits_Restaurant.ResID = Restaurant.ResID WHERE Student.Fname = "Linda" AND Student.Lname = "Smith" AND Restaurant.ResName = "Subway" |
At which restaurant did the students spend the least amount of time? List restaurant and the time students spent on in total. | CREATE TABLE Visits_Restaurant (Id VARCHAR); CREATE TABLE Restaurant (Id VARCHAR) | SELECT Restaurant.ResName, SUM(Visits_Restaurant.Spent) FROM Visits_Restaurant JOIN Restaurant ON Visits_Restaurant.ResID = Restaurant.ResID GROUP BY Restaurant.ResID ORDER BY SUM(Visits_Restaurant.Spent) LIMIT 1 | ### Context: CREATE TABLE Visits_Restaurant (Id VARCHAR); CREATE TABLE Restaurant (Id VARCHAR) ### Question: At which restaurant did the students spend the least amount of time? List restaurant and the time students spent on in total. ### Answer: SELECT Restaurant.ResName, SUM(Visits_Restaurant.Spent) FROM Visits_Restaurant JOIN Restaurant ON Visits_Restaurant.ResID = Restaurant.ResID GROUP BY Restaurant.ResID ORDER BY SUM(Visits_Restaurant.Spent) LIMIT 1 |
Which student visited restaurant most often? List student's first name and last name. | CREATE TABLE Visits_Restaurant (Id VARCHAR); CREATE TABLE Student (Id VARCHAR) | SELECT Student.Fname, Student.Lname FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID GROUP BY Student.StuID ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE Visits_Restaurant (Id VARCHAR); CREATE TABLE Student (Id VARCHAR) ### Question: Which student visited restaurant most often? List student's first name and last name. ### Answer: SELECT Student.Fname, Student.Lname FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID GROUP BY Student.StuID ORDER BY COUNT(*) DESC LIMIT 1 |
Find the ids of orders whose status is 'Success'. | CREATE TABLE actual_orders (actual_order_id VARCHAR, order_status_code VARCHAR) | SELECT actual_order_id FROM actual_orders WHERE order_status_code = 'Success' | ### Context: CREATE TABLE actual_orders (actual_order_id VARCHAR, order_status_code VARCHAR) ### Question: Find the ids of orders whose status is 'Success'. ### Answer: SELECT actual_order_id FROM actual_orders WHERE order_status_code = 'Success' |
Find the name and price of the product that has been ordered the greatest number of times. | CREATE TABLE products (product_name VARCHAR, product_price VARCHAR, product_id VARCHAR); CREATE TABLE regular_order_products (product_id VARCHAR) | SELECT t1.product_name, t1.product_price FROM products AS t1 JOIN regular_order_products AS t2 ON t1.product_id = t2.product_id GROUP BY t2.product_id ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE products (product_name VARCHAR, product_price VARCHAR, product_id VARCHAR); CREATE TABLE regular_order_products (product_id VARCHAR) ### Question: Find the name and price of the product that has been ordered the greatest number of times. ### Answer: SELECT t1.product_name, t1.product_price FROM products AS t1 JOIN regular_order_products AS t2 ON t1.product_id = t2.product_id GROUP BY t2.product_id ORDER BY COUNT(*) DESC LIMIT 1 |
Find the number of customers in total. | CREATE TABLE customers (Id VARCHAR) | SELECT COUNT(*) FROM customers | ### Context: CREATE TABLE customers (Id VARCHAR) ### Question: Find the number of customers in total. ### Answer: SELECT COUNT(*) FROM customers |
How many different payment methods are there? | CREATE TABLE customers (payment_method VARCHAR) | SELECT COUNT(DISTINCT payment_method) FROM customers | ### Context: CREATE TABLE customers (payment_method VARCHAR) ### Question: How many different payment methods are there? ### Answer: SELECT COUNT(DISTINCT payment_method) FROM customers |
Show the details of all trucks in the order of their license number. | CREATE TABLE trucks (truck_details VARCHAR, truck_licence_number VARCHAR) | SELECT truck_details FROM trucks ORDER BY truck_licence_number | ### Context: CREATE TABLE trucks (truck_details VARCHAR, truck_licence_number VARCHAR) ### Question: Show the details of all trucks in the order of their license number. ### Answer: SELECT truck_details FROM trucks ORDER BY truck_licence_number |
Find the name of the most expensive product. | CREATE TABLE products (product_name VARCHAR, product_price VARCHAR) | SELECT product_name FROM products ORDER BY product_price DESC LIMIT 1 | ### Context: CREATE TABLE products (product_name VARCHAR, product_price VARCHAR) ### Question: Find the name of the most expensive product. ### Answer: SELECT product_name FROM products ORDER BY product_price DESC LIMIT 1 |
Find the names of customers who are not living in the state of California. | CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR); CREATE TABLE addresses (address_id VARCHAR, state_province_county VARCHAR) | SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = 'California' | ### Context: CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR); CREATE TABLE addresses (address_id VARCHAR, state_province_county VARCHAR) ### Question: Find the names of customers who are not living in the state of California. ### Answer: SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = 'California' |
List the names and emails of customers who payed by Visa card. | CREATE TABLE customers (customer_email VARCHAR, customer_name VARCHAR, payment_method VARCHAR) | SELECT customer_email, customer_name FROM customers WHERE payment_method = 'Visa' | ### Context: CREATE TABLE customers (customer_email VARCHAR, customer_name VARCHAR, payment_method VARCHAR) ### Question: List the names and emails of customers who payed by Visa card. ### Answer: SELECT customer_email, customer_name FROM customers WHERE payment_method = 'Visa' |
Find the names and phone numbers of customers living in California state. | CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_phone VARCHAR, customer_id VARCHAR); CREATE TABLE addresses (address_id VARCHAR, state_province_county VARCHAR) | SELECT t1.customer_name, t1.customer_phone FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = 'California' | ### Context: CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_phone VARCHAR, customer_id VARCHAR); CREATE TABLE addresses (address_id VARCHAR, state_province_county VARCHAR) ### Question: Find the names and phone numbers of customers living in California state. ### Answer: SELECT t1.customer_name, t1.customer_phone FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = 'California' |
Find the states which do not have any employee in their record. | CREATE TABLE Employees (state_province_county VARCHAR, address_id VARCHAR, employee_address_id VARCHAR); CREATE TABLE addresses (state_province_county VARCHAR, address_id VARCHAR, employee_address_id VARCHAR) | SELECT state_province_county FROM addresses WHERE NOT address_id IN (SELECT employee_address_id FROM Employees) | ### Context: CREATE TABLE Employees (state_province_county VARCHAR, address_id VARCHAR, employee_address_id VARCHAR); CREATE TABLE addresses (state_province_county VARCHAR, address_id VARCHAR, employee_address_id VARCHAR) ### Question: Find the states which do not have any employee in their record. ### Answer: SELECT state_province_county FROM addresses WHERE NOT address_id IN (SELECT employee_address_id FROM Employees) |
List the names, phone numbers, and emails of all customers sorted by their dates of becoming customers. | CREATE TABLE Customers (customer_name VARCHAR, customer_phone VARCHAR, customer_email VARCHAR, date_became_customer VARCHAR) | SELECT customer_name, customer_phone, customer_email FROM Customers ORDER BY date_became_customer | ### Context: CREATE TABLE Customers (customer_name VARCHAR, customer_phone VARCHAR, customer_email VARCHAR, date_became_customer VARCHAR) ### Question: List the names, phone numbers, and emails of all customers sorted by their dates of becoming customers. ### Answer: SELECT customer_name, customer_phone, customer_email FROM Customers ORDER BY date_became_customer |
Find the name of the first 5 customers. | CREATE TABLE Customers (customer_name VARCHAR, date_became_customer VARCHAR) | SELECT customer_name FROM Customers ORDER BY date_became_customer LIMIT 5 | ### Context: CREATE TABLE Customers (customer_name VARCHAR, date_became_customer VARCHAR) ### Question: Find the name of the first 5 customers. ### Answer: SELECT customer_name FROM Customers ORDER BY date_became_customer LIMIT 5 |
Find the payment method that is used most frequently. | CREATE TABLE Customers (payment_method VARCHAR) | SELECT payment_method FROM Customers GROUP BY payment_method ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE Customers (payment_method VARCHAR) ### Question: Find the payment method that is used most frequently. ### Answer: SELECT payment_method FROM Customers GROUP BY payment_method ORDER BY COUNT(*) DESC LIMIT 1 |
List the names of all routes in alphabetic order. | CREATE TABLE Delivery_Routes (route_name VARCHAR) | SELECT route_name FROM Delivery_Routes ORDER BY route_name | ### Context: CREATE TABLE Delivery_Routes (route_name VARCHAR) ### Question: List the names of all routes in alphabetic order. ### Answer: SELECT route_name FROM Delivery_Routes ORDER BY route_name |
Find the name of route that has the highest number of deliveries. | CREATE TABLE Delivery_Routes (route_name VARCHAR, route_id VARCHAR); CREATE TABLE Delivery_Route_Locations (route_id VARCHAR) | SELECT t1.route_name FROM Delivery_Routes AS t1 JOIN Delivery_Route_Locations AS t2 ON t1.route_id = t2.route_id GROUP BY t1.route_id ORDER BY COUNT(*) DESC LIMIT 1 | ### Context: CREATE TABLE Delivery_Routes (route_name VARCHAR, route_id VARCHAR); CREATE TABLE Delivery_Route_Locations (route_id VARCHAR) ### Question: Find the name of route that has the highest number of deliveries. ### Answer: SELECT t1.route_name FROM Delivery_Routes AS t1 JOIN Delivery_Route_Locations AS t2 ON t1.route_id = t2.route_id GROUP BY t1.route_id ORDER BY COUNT(*) DESC LIMIT 1 |
List the state names and the number of customers living in each state. | CREATE TABLE customer_addresses (address_id VARCHAR); CREATE TABLE addresses (state_province_county VARCHAR, address_id VARCHAR) | SELECT t2.state_province_county, COUNT(*) FROM customer_addresses AS t1 JOIN addresses AS t2 ON t1.address_id = t2.address_id GROUP BY t2.state_province_county | ### Context: CREATE TABLE customer_addresses (address_id VARCHAR); CREATE TABLE addresses (state_province_county VARCHAR, address_id VARCHAR) ### Question: List the state names and the number of customers living in each state. ### Answer: SELECT t2.state_province_county, COUNT(*) FROM customer_addresses AS t1 JOIN addresses AS t2 ON t1.address_id = t2.address_id GROUP BY t2.state_province_county |
How many authors are there? | CREATE TABLE authors (Id VARCHAR) | SELECT COUNT(*) FROM authors | ### Context: CREATE TABLE authors (Id VARCHAR) ### Question: How many authors are there? ### Answer: SELECT COUNT(*) FROM authors |
Subsets and Splits