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1 | 4090-4093 | e , we double
the number of turns, then
2
I
I
φ
φ
→
Thus, the current sensitivity doubles However, the resistance of the
galvanometer is also likely to double, since it is proportional to the length
of the wire In Eq |
1 | 4091-4094 | , we double
the number of turns, then
2
I
I
φ
φ
→
Thus, the current sensitivity doubles However, the resistance of the
galvanometer is also likely to double, since it is proportional to the length
of the wire In Eq (4 |
1 | 4092-4095 | However, the resistance of the
galvanometer is also likely to double, since it is proportional to the length
of the wire In Eq (4 40), N ®2N, and R ®2R, thus the voltage sensitivity,
V
V
φ
φ
→
remains unchanged |
1 | 4093-4096 | In Eq (4 40), N ®2N, and R ®2R, thus the voltage sensitivity,
V
V
φ
φ
→
remains unchanged So in general, the modification needed for conversion
of a galvanometer to an ammeter will be different from what is needed for
converting it into a voltmeter |
1 | 4094-4097 | (4 40), N ®2N, and R ®2R, thus the voltage sensitivity,
V
V
φ
φ
→
remains unchanged So in general, the modification needed for conversion
of a galvanometer to an ammeter will be different from what is needed for
converting it into a voltmeter Example 4 |
1 | 4095-4098 | 40), N ®2N, and R ®2R, thus the voltage sensitivity,
V
V
φ
φ
→
remains unchanged So in general, the modification needed for conversion
of a galvanometer to an ammeter will be different from what is needed for
converting it into a voltmeter Example 4 13 In the circuit (Fig |
1 | 4096-4099 | So in general, the modification needed for conversion
of a galvanometer to an ammeter will be different from what is needed for
converting it into a voltmeter Example 4 13 In the circuit (Fig 4 |
1 | 4097-4100 | Example 4 13 In the circuit (Fig 4 23) the current is to be
measured |
1 | 4098-4101 | 13 In the circuit (Fig 4 23) the current is to be
measured What is the value of the current if the ammeter shown
(a) is a galvanometer with a resistance RG = 60 |
1 | 4099-4102 | 4 23) the current is to be
measured What is the value of the current if the ammeter shown
(a) is a galvanometer with a resistance RG = 60 00 W; (b) is a
galvanometer described in (a) but converted to an ammeter by a
shunt resistance rs = 0 |
1 | 4100-4103 | 23) the current is to be
measured What is the value of the current if the ammeter shown
(a) is a galvanometer with a resistance RG = 60 00 W; (b) is a
galvanometer described in (a) but converted to an ammeter by a
shunt resistance rs = 0 02 W; (c) is an ideal ammeter with zero
resistance |
1 | 4101-4104 | What is the value of the current if the ammeter shown
(a) is a galvanometer with a resistance RG = 60 00 W; (b) is a
galvanometer described in (a) but converted to an ammeter by a
shunt resistance rs = 0 02 W; (c) is an ideal ammeter with zero
resistance FIGURE 4 |
1 | 4102-4105 | 00 W; (b) is a
galvanometer described in (a) but converted to an ammeter by a
shunt resistance rs = 0 02 W; (c) is an ideal ammeter with zero
resistance FIGURE 4 23
FIGURE 4 |
1 | 4103-4106 | 02 W; (c) is an ideal ammeter with zero
resistance FIGURE 4 23
FIGURE 4 22
Conversion of a
galvanometer (G) to a
voltmeter by the
introduction of a
resistance R of large
value in series |
1 | 4104-4107 | FIGURE 4 23
FIGURE 4 22
Conversion of a
galvanometer (G) to a
voltmeter by the
introduction of a
resistance R of large
value in series EXAMPLE 4 |
1 | 4105-4108 | 23
FIGURE 4 22
Conversion of a
galvanometer (G) to a
voltmeter by the
introduction of a
resistance R of large
value in series EXAMPLE 4 13
Rationalised 2023-24
Physics
132
SUMMARY
1 |
1 | 4106-4109 | 22
Conversion of a
galvanometer (G) to a
voltmeter by the
introduction of a
resistance R of large
value in series EXAMPLE 4 13
Rationalised 2023-24
Physics
132
SUMMARY
1 The total force on a charge q moving with velocity v in the presence of
magnetic and electric fields B and E, respectively is called the Lorentz
force |
1 | 4107-4110 | EXAMPLE 4 13
Rationalised 2023-24
Physics
132
SUMMARY
1 The total force on a charge q moving with velocity v in the presence of
magnetic and electric fields B and E, respectively is called the Lorentz
force It is given by the expression:
F = q (v × B + E)
The magnetic force q (v × B) is normal to v and work done by it is zero |
1 | 4108-4111 | 13
Rationalised 2023-24
Physics
132
SUMMARY
1 The total force on a charge q moving with velocity v in the presence of
magnetic and electric fields B and E, respectively is called the Lorentz
force It is given by the expression:
F = q (v × B + E)
The magnetic force q (v × B) is normal to v and work done by it is zero 2 |
1 | 4109-4112 | The total force on a charge q moving with velocity v in the presence of
magnetic and electric fields B and E, respectively is called the Lorentz
force It is given by the expression:
F = q (v × B + E)
The magnetic force q (v × B) is normal to v and work done by it is zero 2 A straight conductor of length l and carrying a steady current I
experiences a force F in a uniform external magnetic field B,
F = I l × B
where|l| = l and the direction of l is given by the direction of the
current |
1 | 4110-4113 | It is given by the expression:
F = q (v × B + E)
The magnetic force q (v × B) is normal to v and work done by it is zero 2 A straight conductor of length l and carrying a steady current I
experiences a force F in a uniform external magnetic field B,
F = I l × B
where|l| = l and the direction of l is given by the direction of the
current 3 |
1 | 4111-4114 | 2 A straight conductor of length l and carrying a steady current I
experiences a force F in a uniform external magnetic field B,
F = I l × B
where|l| = l and the direction of l is given by the direction of the
current 3 In a uniform magnetic field B, a charge q executes a circular orbit in
a plane normal to B |
1 | 4112-4115 | A straight conductor of length l and carrying a steady current I
experiences a force F in a uniform external magnetic field B,
F = I l × B
where|l| = l and the direction of l is given by the direction of the
current 3 In a uniform magnetic field B, a charge q executes a circular orbit in
a plane normal to B Its frequency of uniform circular motion is called
the cyclotron frequency and is given by:
2
c
q B
m
ν =
π
This frequency is independent of the particle’s speed and radius |
1 | 4113-4116 | 3 In a uniform magnetic field B, a charge q executes a circular orbit in
a plane normal to B Its frequency of uniform circular motion is called
the cyclotron frequency and is given by:
2
c
q B
m
ν =
π
This frequency is independent of the particle’s speed and radius This
fact is exploited in a machine, the cyclotron, which is used to
accelerate charged particles |
1 | 4114-4117 | In a uniform magnetic field B, a charge q executes a circular orbit in
a plane normal to B Its frequency of uniform circular motion is called
the cyclotron frequency and is given by:
2
c
q B
m
ν =
π
This frequency is independent of the particle’s speed and radius This
fact is exploited in a machine, the cyclotron, which is used to
accelerate charged particles 4 |
1 | 4115-4118 | Its frequency of uniform circular motion is called
the cyclotron frequency and is given by:
2
c
q B
m
ν =
π
This frequency is independent of the particle’s speed and radius This
fact is exploited in a machine, the cyclotron, which is used to
accelerate charged particles 4 The Biot-Savart law asserts that the magnetic field dB due to an
element dl carrying a steady current I at a point P at a distance r from
the current element is:
0
d3
d
4
I
r
µ
×
=
π
l
r
B
To obtain the total field at P, we must integrate this vector expression
over the entire length of the conductor |
1 | 4116-4119 | This
fact is exploited in a machine, the cyclotron, which is used to
accelerate charged particles 4 The Biot-Savart law asserts that the magnetic field dB due to an
element dl carrying a steady current I at a point P at a distance r from
the current element is:
0
d3
d
4
I
r
µ
×
=
π
l
r
B
To obtain the total field at P, we must integrate this vector expression
over the entire length of the conductor 5 |
1 | 4117-4120 | 4 The Biot-Savart law asserts that the magnetic field dB due to an
element dl carrying a steady current I at a point P at a distance r from
the current element is:
0
d3
d
4
I
r
µ
×
=
π
l
r
B
To obtain the total field at P, we must integrate this vector expression
over the entire length of the conductor 5 The magnitude of the magnetic field due to a circular coil of radius R
carrying a current I at an axial distance x from the centre is
EXAMPLE 4 |
1 | 4118-4121 | The Biot-Savart law asserts that the magnetic field dB due to an
element dl carrying a steady current I at a point P at a distance r from
the current element is:
0
d3
d
4
I
r
µ
×
=
π
l
r
B
To obtain the total field at P, we must integrate this vector expression
over the entire length of the conductor 5 The magnitude of the magnetic field due to a circular coil of radius R
carrying a current I at an axial distance x from the centre is
EXAMPLE 4 13
Solution
(a) Total resistance in the circuit is,
3
63
RG
+
=
Ω |
1 | 4119-4122 | 5 The magnitude of the magnetic field due to a circular coil of radius R
carrying a current I at an axial distance x from the centre is
EXAMPLE 4 13
Solution
(a) Total resistance in the circuit is,
3
63
RG
+
=
Ω Hence, I = 3/63 = 0 |
1 | 4120-4123 | The magnitude of the magnetic field due to a circular coil of radius R
carrying a current I at an axial distance x from the centre is
EXAMPLE 4 13
Solution
(a) Total resistance in the circuit is,
3
63
RG
+
=
Ω Hence, I = 3/63 = 0 048 A |
1 | 4121-4124 | 13
Solution
(a) Total resistance in the circuit is,
3
63
RG
+
=
Ω Hence, I = 3/63 = 0 048 A (b) Resistance of the galvanometer converted to an ammeter is,
R
r
R
r
G
s
G
+s
=
+×
60
0 02
60
Ω0 02 |
1 | 4122-4125 | Hence, I = 3/63 = 0 048 A (b) Resistance of the galvanometer converted to an ammeter is,
R
r
R
r
G
s
G
+s
=
+×
60
0 02
60
Ω0 02 ΩΩ
( |
1 | 4123-4126 | 048 A (b) Resistance of the galvanometer converted to an ammeter is,
R
r
R
r
G
s
G
+s
=
+×
60
0 02
60
Ω0 02 ΩΩ
( )
≃ 0 |
1 | 4124-4127 | (b) Resistance of the galvanometer converted to an ammeter is,
R
r
R
r
G
s
G
+s
=
+×
60
0 02
60
Ω0 02 ΩΩ
( )
≃ 0 02W
Total resistance in the circuit is,
0 |
1 | 4125-4128 | ΩΩ
( )
≃ 0 02W
Total resistance in the circuit is,
0 02
3
3 |
1 | 4126-4129 | )
≃ 0 02W
Total resistance in the circuit is,
0 02
3
3 02
Ω +
Ω =
Ω |
1 | 4127-4130 | 02W
Total resistance in the circuit is,
0 02
3
3 02
Ω +
Ω =
Ω Hence, I = 3/3 |
1 | 4128-4131 | 02
3
3 02
Ω +
Ω =
Ω Hence, I = 3/3 02 = 0 |
1 | 4129-4132 | 02
Ω +
Ω =
Ω Hence, I = 3/3 02 = 0 99 A |
1 | 4130-4133 | Hence, I = 3/3 02 = 0 99 A (c) For the ideal ammeter with zero resistance,
I = 3/3 = 1 |
1 | 4131-4134 | 02 = 0 99 A (c) For the ideal ammeter with zero resistance,
I = 3/3 = 1 00 A
Rationalised 2023-24
133
Moving Charges and
Magnetism
2
0
2
2 3/2
2(
)
IR
B
x
R
µ
=
+
At the centre this reduces to
0
2
I
B
R
µ
=
6 |
1 | 4132-4135 | 99 A (c) For the ideal ammeter with zero resistance,
I = 3/3 = 1 00 A
Rationalised 2023-24
133
Moving Charges and
Magnetism
2
0
2
2 3/2
2(
)
IR
B
x
R
µ
=
+
At the centre this reduces to
0
2
I
B
R
µ
=
6 Ampere’s Circuital Law: Let an open surface S be bounded by a loop
C |
1 | 4133-4136 | (c) For the ideal ammeter with zero resistance,
I = 3/3 = 1 00 A
Rationalised 2023-24
133
Moving Charges and
Magnetism
2
0
2
2 3/2
2(
)
IR
B
x
R
µ
=
+
At the centre this reduces to
0
2
I
B
R
µ
=
6 Ampere’s Circuital Law: Let an open surface S be bounded by a loop
C Then the Ampere’s law states that
B |
1 | 4134-4137 | 00 A
Rationalised 2023-24
133
Moving Charges and
Magnetism
2
0
2
2 3/2
2(
)
IR
B
x
R
µ
=
+
At the centre this reduces to
0
2
I
B
R
µ
=
6 Ampere’s Circuital Law: Let an open surface S be bounded by a loop
C Then the Ampere’s law states that
B dl
I
=
∫
µ0
C�
where I refers to
the current passing through S |
1 | 4135-4138 | Ampere’s Circuital Law: Let an open surface S be bounded by a loop
C Then the Ampere’s law states that
B dl
I
=
∫
µ0
C�
where I refers to
the current passing through S The sign of I is determined from the
right-hand rule |
1 | 4136-4139 | Then the Ampere’s law states that
B dl
I
=
∫
µ0
C�
where I refers to
the current passing through S The sign of I is determined from the
right-hand rule We have discussed a simplified form of this law |
1 | 4137-4140 | dl
I
=
∫
µ0
C�
where I refers to
the current passing through S The sign of I is determined from the
right-hand rule We have discussed a simplified form of this law If B
is directed along the tangent to every point on the perimeter L of a
closed curve and is constant in magnitude along perimeter then,
BL = m0 Ie
where Ie is the net current enclosed by the closed circuit |
1 | 4138-4141 | The sign of I is determined from the
right-hand rule We have discussed a simplified form of this law If B
is directed along the tangent to every point on the perimeter L of a
closed curve and is constant in magnitude along perimeter then,
BL = m0 Ie
where Ie is the net current enclosed by the closed circuit 7 |
1 | 4139-4142 | We have discussed a simplified form of this law If B
is directed along the tangent to every point on the perimeter L of a
closed curve and is constant in magnitude along perimeter then,
BL = m0 Ie
where Ie is the net current enclosed by the closed circuit 7 The magnitude of the magnetic field at a distance R from a long,
straight wire carrying a current I is given by:
π
0
2
I
B
R
µ
=
The field lines are circles concentric with the wire |
1 | 4140-4143 | If B
is directed along the tangent to every point on the perimeter L of a
closed curve and is constant in magnitude along perimeter then,
BL = m0 Ie
where Ie is the net current enclosed by the closed circuit 7 The magnitude of the magnetic field at a distance R from a long,
straight wire carrying a current I is given by:
π
0
2
I
B
R
µ
=
The field lines are circles concentric with the wire 8 |
1 | 4141-4144 | 7 The magnitude of the magnetic field at a distance R from a long,
straight wire carrying a current I is given by:
π
0
2
I
B
R
µ
=
The field lines are circles concentric with the wire 8 The magnitude of the field B inside a long solenoid carrying a current
I is
B = m0nI
where n is the number of turns per unit length |
1 | 4142-4145 | The magnitude of the magnetic field at a distance R from a long,
straight wire carrying a current I is given by:
π
0
2
I
B
R
µ
=
The field lines are circles concentric with the wire 8 The magnitude of the field B inside a long solenoid carrying a current
I is
B = m0nI
where n is the number of turns per unit length where N is the total number of turns and r is the average radius |
1 | 4143-4146 | 8 The magnitude of the field B inside a long solenoid carrying a current
I is
B = m0nI
where n is the number of turns per unit length where N is the total number of turns and r is the average radius 9 |
1 | 4144-4147 | The magnitude of the field B inside a long solenoid carrying a current
I is
B = m0nI
where n is the number of turns per unit length where N is the total number of turns and r is the average radius 9 Parallel currents attract and anti-parallel currents repel |
1 | 4145-4148 | where N is the total number of turns and r is the average radius 9 Parallel currents attract and anti-parallel currents repel 10 |
1 | 4146-4149 | 9 Parallel currents attract and anti-parallel currents repel 10 A planar loop carrying a current I, having N closely wound turns, and
an area A possesses a magnetic moment m where,
m = N I A
and the direction of m is given by the right-hand thumb rule : curl
the palm of your right hand along the loop with the fingers pointing
in the direction of the current |
1 | 4147-4150 | Parallel currents attract and anti-parallel currents repel 10 A planar loop carrying a current I, having N closely wound turns, and
an area A possesses a magnetic moment m where,
m = N I A
and the direction of m is given by the right-hand thumb rule : curl
the palm of your right hand along the loop with the fingers pointing
in the direction of the current The thumb sticking out gives the
direction of m (and A)
When this loop is placed in a uniform magnetic field B, the force F on
it is: F = 0
And the torque on it is,
t = m × B
In a moving coil galvanometer, this torque is balanced by a counter-
torque due to a spring, yielding
kf = NI AB
where f is the equilibrium deflection and k the torsion constant of
the spring |
1 | 4148-4151 | 10 A planar loop carrying a current I, having N closely wound turns, and
an area A possesses a magnetic moment m where,
m = N I A
and the direction of m is given by the right-hand thumb rule : curl
the palm of your right hand along the loop with the fingers pointing
in the direction of the current The thumb sticking out gives the
direction of m (and A)
When this loop is placed in a uniform magnetic field B, the force F on
it is: F = 0
And the torque on it is,
t = m × B
In a moving coil galvanometer, this torque is balanced by a counter-
torque due to a spring, yielding
kf = NI AB
where f is the equilibrium deflection and k the torsion constant of
the spring 11 |
1 | 4149-4152 | A planar loop carrying a current I, having N closely wound turns, and
an area A possesses a magnetic moment m where,
m = N I A
and the direction of m is given by the right-hand thumb rule : curl
the palm of your right hand along the loop with the fingers pointing
in the direction of the current The thumb sticking out gives the
direction of m (and A)
When this loop is placed in a uniform magnetic field B, the force F on
it is: F = 0
And the torque on it is,
t = m × B
In a moving coil galvanometer, this torque is balanced by a counter-
torque due to a spring, yielding
kf = NI AB
where f is the equilibrium deflection and k the torsion constant of
the spring 11 A moving coil galvanometer can be converted into a ammeter by
introducing a shunt resistance rs, of small value in parallel |
1 | 4150-4153 | The thumb sticking out gives the
direction of m (and A)
When this loop is placed in a uniform magnetic field B, the force F on
it is: F = 0
And the torque on it is,
t = m × B
In a moving coil galvanometer, this torque is balanced by a counter-
torque due to a spring, yielding
kf = NI AB
where f is the equilibrium deflection and k the torsion constant of
the spring 11 A moving coil galvanometer can be converted into a ammeter by
introducing a shunt resistance rs, of small value in parallel It can be
converted into a voltmeter by introducing a resistance of a large value
in series |
1 | 4151-4154 | 11 A moving coil galvanometer can be converted into a ammeter by
introducing a shunt resistance rs, of small value in parallel It can be
converted into a voltmeter by introducing a resistance of a large value
in series Rationalised 2023-24
Physics
134
Physical Quantity
Symbol
Nature
Dimensions
Units
Remarks
Permeability of free
m0
Scalar
[MLT –2A–2]
T m A–1
4p ´ 10–7 T m A–1
space
Magnetic Field
B
Vector
[M T –2A–1]
T (telsa)
Magnetic Moment
m
Vector
[L2A]
A m2 or J/T
Torsion Constant
k
Scalar
[M L2T –2]
N m rad–1
Appears in MCG
POINTS TO PONDER
1 |
1 | 4152-4155 | A moving coil galvanometer can be converted into a ammeter by
introducing a shunt resistance rs, of small value in parallel It can be
converted into a voltmeter by introducing a resistance of a large value
in series Rationalised 2023-24
Physics
134
Physical Quantity
Symbol
Nature
Dimensions
Units
Remarks
Permeability of free
m0
Scalar
[MLT –2A–2]
T m A–1
4p ´ 10–7 T m A–1
space
Magnetic Field
B
Vector
[M T –2A–1]
T (telsa)
Magnetic Moment
m
Vector
[L2A]
A m2 or J/T
Torsion Constant
k
Scalar
[M L2T –2]
N m rad–1
Appears in MCG
POINTS TO PONDER
1 Electrostatic field lines originate at a positive charge and terminate at a
negative charge or fade at infinity |
1 | 4153-4156 | It can be
converted into a voltmeter by introducing a resistance of a large value
in series Rationalised 2023-24
Physics
134
Physical Quantity
Symbol
Nature
Dimensions
Units
Remarks
Permeability of free
m0
Scalar
[MLT –2A–2]
T m A–1
4p ´ 10–7 T m A–1
space
Magnetic Field
B
Vector
[M T –2A–1]
T (telsa)
Magnetic Moment
m
Vector
[L2A]
A m2 or J/T
Torsion Constant
k
Scalar
[M L2T –2]
N m rad–1
Appears in MCG
POINTS TO PONDER
1 Electrostatic field lines originate at a positive charge and terminate at a
negative charge or fade at infinity Magnetic field lines always form
closed loops |
1 | 4154-4157 | Rationalised 2023-24
Physics
134
Physical Quantity
Symbol
Nature
Dimensions
Units
Remarks
Permeability of free
m0
Scalar
[MLT –2A–2]
T m A–1
4p ´ 10–7 T m A–1
space
Magnetic Field
B
Vector
[M T –2A–1]
T (telsa)
Magnetic Moment
m
Vector
[L2A]
A m2 or J/T
Torsion Constant
k
Scalar
[M L2T –2]
N m rad–1
Appears in MCG
POINTS TO PONDER
1 Electrostatic field lines originate at a positive charge and terminate at a
negative charge or fade at infinity Magnetic field lines always form
closed loops 2 |
1 | 4155-4158 | Electrostatic field lines originate at a positive charge and terminate at a
negative charge or fade at infinity Magnetic field lines always form
closed loops 2 The discussion in this Chapter holds only for steady currents which do
not vary with time |
1 | 4156-4159 | Magnetic field lines always form
closed loops 2 The discussion in this Chapter holds only for steady currents which do
not vary with time When currents vary with time Newton’s third law is valid only if momentum
carried by the electromagnetic field is taken into account |
1 | 4157-4160 | 2 The discussion in this Chapter holds only for steady currents which do
not vary with time When currents vary with time Newton’s third law is valid only if momentum
carried by the electromagnetic field is taken into account 3 |
1 | 4158-4161 | The discussion in this Chapter holds only for steady currents which do
not vary with time When currents vary with time Newton’s third law is valid only if momentum
carried by the electromagnetic field is taken into account 3 Recall the expression for the Lorentz force,
F = q (v × B + E)
This velocity dependent force has occupied the attention of some of the
greatest scientific thinkers |
1 | 4159-4162 | When currents vary with time Newton’s third law is valid only if momentum
carried by the electromagnetic field is taken into account 3 Recall the expression for the Lorentz force,
F = q (v × B + E)
This velocity dependent force has occupied the attention of some of the
greatest scientific thinkers If one switches to a frame with instantaneous
velocity v, the magnetic part of the force vanishes |
1 | 4160-4163 | 3 Recall the expression for the Lorentz force,
F = q (v × B + E)
This velocity dependent force has occupied the attention of some of the
greatest scientific thinkers If one switches to a frame with instantaneous
velocity v, the magnetic part of the force vanishes The motion of the
charged particle is then explained by arguing that there exists an
appropriate electric field in the new frame |
1 | 4161-4164 | Recall the expression for the Lorentz force,
F = q (v × B + E)
This velocity dependent force has occupied the attention of some of the
greatest scientific thinkers If one switches to a frame with instantaneous
velocity v, the magnetic part of the force vanishes The motion of the
charged particle is then explained by arguing that there exists an
appropriate electric field in the new frame We shall not discuss the
details of this mechanism |
1 | 4162-4165 | If one switches to a frame with instantaneous
velocity v, the magnetic part of the force vanishes The motion of the
charged particle is then explained by arguing that there exists an
appropriate electric field in the new frame We shall not discuss the
details of this mechanism However, we stress that the resolution of this
paradox implies that electricity and magnetism are linked phenomena
(electromagnetism) and that the Lorentz force expression does not imply
a universal preferred frame of reference in nature |
1 | 4163-4166 | The motion of the
charged particle is then explained by arguing that there exists an
appropriate electric field in the new frame We shall not discuss the
details of this mechanism However, we stress that the resolution of this
paradox implies that electricity and magnetism are linked phenomena
(electromagnetism) and that the Lorentz force expression does not imply
a universal preferred frame of reference in nature 4 |
1 | 4164-4167 | We shall not discuss the
details of this mechanism However, we stress that the resolution of this
paradox implies that electricity and magnetism are linked phenomena
(electromagnetism) and that the Lorentz force expression does not imply
a universal preferred frame of reference in nature 4 Ampere’s Circuital law is not independent of the Biot-Savart law |
1 | 4165-4168 | However, we stress that the resolution of this
paradox implies that electricity and magnetism are linked phenomena
(electromagnetism) and that the Lorentz force expression does not imply
a universal preferred frame of reference in nature 4 Ampere’s Circuital law is not independent of the Biot-Savart law It
can be derived from the Biot-Savart law |
1 | 4166-4169 | 4 Ampere’s Circuital law is not independent of the Biot-Savart law It
can be derived from the Biot-Savart law Its relationship to the
Biot-Savart law is similar to the relationship between Gauss’s law and
Coulomb’s law |
1 | 4167-4170 | Ampere’s Circuital law is not independent of the Biot-Savart law It
can be derived from the Biot-Savart law Its relationship to the
Biot-Savart law is similar to the relationship between Gauss’s law and
Coulomb’s law EXERCISES
4 |
1 | 4168-4171 | It
can be derived from the Biot-Savart law Its relationship to the
Biot-Savart law is similar to the relationship between Gauss’s law and
Coulomb’s law EXERCISES
4 1
A circular coil of wire consisting of 100 turns, each of radius 8 |
1 | 4169-4172 | Its relationship to the
Biot-Savart law is similar to the relationship between Gauss’s law and
Coulomb’s law EXERCISES
4 1
A circular coil of wire consisting of 100 turns, each of radius 8 0 cm
carries a current of 0 |
1 | 4170-4173 | EXERCISES
4 1
A circular coil of wire consisting of 100 turns, each of radius 8 0 cm
carries a current of 0 40 A |
1 | 4171-4174 | 1
A circular coil of wire consisting of 100 turns, each of radius 8 0 cm
carries a current of 0 40 A What is the magnitude of the magnetic
field B at the centre of the coil |
1 | 4172-4175 | 0 cm
carries a current of 0 40 A What is the magnitude of the magnetic
field B at the centre of the coil 4 |
1 | 4173-4176 | 40 A What is the magnitude of the magnetic
field B at the centre of the coil 4 2
A long straight wire carries a current of 35 A |
1 | 4174-4177 | What is the magnitude of the magnetic
field B at the centre of the coil 4 2
A long straight wire carries a current of 35 A What is the magnitude
of the field B at a point 20 cm from the wire |
1 | 4175-4178 | 4 2
A long straight wire carries a current of 35 A What is the magnitude
of the field B at a point 20 cm from the wire 4 |
1 | 4176-4179 | 2
A long straight wire carries a current of 35 A What is the magnitude
of the field B at a point 20 cm from the wire 4 3
A long straight wire in the horizontal plane carries a current of 50 A
in north to south direction |
1 | 4177-4180 | What is the magnitude
of the field B at a point 20 cm from the wire 4 3
A long straight wire in the horizontal plane carries a current of 50 A
in north to south direction Give the magnitude and direction of B
at a point 2 |
1 | 4178-4181 | 4 3
A long straight wire in the horizontal plane carries a current of 50 A
in north to south direction Give the magnitude and direction of B
at a point 2 5 m east of the wire |
1 | 4179-4182 | 3
A long straight wire in the horizontal plane carries a current of 50 A
in north to south direction Give the magnitude and direction of B
at a point 2 5 m east of the wire Rationalised 2023-24
135
Moving Charges and
Magnetism
4 |
1 | 4180-4183 | Give the magnitude and direction of B
at a point 2 5 m east of the wire Rationalised 2023-24
135
Moving Charges and
Magnetism
4 4
A horizontal overhead power line carries a current of 90 A in east to
west direction |
1 | 4181-4184 | 5 m east of the wire Rationalised 2023-24
135
Moving Charges and
Magnetism
4 4
A horizontal overhead power line carries a current of 90 A in east to
west direction What is the magnitude and direction of the magnetic
field due to the current 1 |
1 | 4182-4185 | Rationalised 2023-24
135
Moving Charges and
Magnetism
4 4
A horizontal overhead power line carries a current of 90 A in east to
west direction What is the magnitude and direction of the magnetic
field due to the current 1 5 m below the line |
1 | 4183-4186 | 4
A horizontal overhead power line carries a current of 90 A in east to
west direction What is the magnitude and direction of the magnetic
field due to the current 1 5 m below the line 4 |
1 | 4184-4187 | What is the magnitude and direction of the magnetic
field due to the current 1 5 m below the line 4 5
What is the magnitude of magnetic force per unit length on a wire
carrying a current of 8 A and making an angle of 30º with the
direction of a uniform magnetic field of 0 |
1 | 4185-4188 | 5 m below the line 4 5
What is the magnitude of magnetic force per unit length on a wire
carrying a current of 8 A and making an angle of 30º with the
direction of a uniform magnetic field of 0 15 T |
1 | 4186-4189 | 4 5
What is the magnitude of magnetic force per unit length on a wire
carrying a current of 8 A and making an angle of 30º with the
direction of a uniform magnetic field of 0 15 T 4 |
1 | 4187-4190 | 5
What is the magnitude of magnetic force per unit length on a wire
carrying a current of 8 A and making an angle of 30º with the
direction of a uniform magnetic field of 0 15 T 4 6
A 3 |
1 | 4188-4191 | 15 T 4 6
A 3 0 cm wire carrying a current of 10 A is placed inside a solenoid
perpendicular to its axis |
1 | 4189-4192 | 4 6
A 3 0 cm wire carrying a current of 10 A is placed inside a solenoid
perpendicular to its axis The magnetic field inside the solenoid is
given to be 0 |
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