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1 | 4490-4493 | (f ) Wrong These field lines cannot possibly represent a magnetic field Look at the upper region All the field lines seem to emanate out of
the shaded plate |
1 | 4491-4494 | These field lines cannot possibly represent a magnetic field Look at the upper region All the field lines seem to emanate out of
the shaded plate The net flux through a surface surrounding the
shaded plate is not zero |
1 | 4492-4495 | Look at the upper region All the field lines seem to emanate out of
the shaded plate The net flux through a surface surrounding the
shaded plate is not zero This is impossible for a magnetic field |
1 | 4493-4496 | All the field lines seem to emanate out of
the shaded plate The net flux through a surface surrounding the
shaded plate is not zero This is impossible for a magnetic field The given field lines, in fact, show the electrostatic field lines
around a positively charged upper plate and a negatively charged
lower plate |
1 | 4494-4497 | The net flux through a surface surrounding the
shaded plate is not zero This is impossible for a magnetic field The given field lines, in fact, show the electrostatic field lines
around a positively charged upper plate and a negatively charged
lower plate The difference between Fig |
1 | 4495-4498 | This is impossible for a magnetic field The given field lines, in fact, show the electrostatic field lines
around a positively charged upper plate and a negatively charged
lower plate The difference between Fig [5 |
1 | 4496-4499 | The given field lines, in fact, show the electrostatic field lines
around a positively charged upper plate and a negatively charged
lower plate The difference between Fig [5 7(e) and (f)] should be
carefully grasped |
1 | 4497-4500 | The difference between Fig [5 7(e) and (f)] should be
carefully grasped (g) Wrong |
1 | 4498-4501 | [5 7(e) and (f)] should be
carefully grasped (g) Wrong Magnetic field lines between two pole pieces cannot be
precisely straight at the ends |
1 | 4499-4502 | 7(e) and (f)] should be
carefully grasped (g) Wrong Magnetic field lines between two pole pieces cannot be
precisely straight at the ends Some fringing of lines is inevitable |
1 | 4500-4503 | (g) Wrong Magnetic field lines between two pole pieces cannot be
precisely straight at the ends Some fringing of lines is inevitable Otherwise, Ampere’s law is violated |
1 | 4501-4504 | Magnetic field lines between two pole pieces cannot be
precisely straight at the ends Some fringing of lines is inevitable Otherwise, Ampere’s law is violated This is also true for electric
field lines |
1 | 4502-4505 | Some fringing of lines is inevitable Otherwise, Ampere’s law is violated This is also true for electric
field lines Example 5 |
1 | 4503-4506 | Otherwise, Ampere’s law is violated This is also true for electric
field lines Example 5 4
(a) Magnetic field lines show the direction (at every point) along which
a small magnetised needle aligns (at the point) |
1 | 4504-4507 | This is also true for electric
field lines Example 5 4
(a) Magnetic field lines show the direction (at every point) along which
a small magnetised needle aligns (at the point) Do the magnetic
field lines also represent the lines of force on a moving charged
particle at every point |
1 | 4505-4508 | Example 5 4
(a) Magnetic field lines show the direction (at every point) along which
a small magnetised needle aligns (at the point) Do the magnetic
field lines also represent the lines of force on a moving charged
particle at every point (b) If magnetic monopoles existed, how would the Gauss’s law of
magnetism be modified |
1 | 4506-4509 | 4
(a) Magnetic field lines show the direction (at every point) along which
a small magnetised needle aligns (at the point) Do the magnetic
field lines also represent the lines of force on a moving charged
particle at every point (b) If magnetic monopoles existed, how would the Gauss’s law of
magnetism be modified (c) Does a bar magnet exert a torque on itself due to its own field |
1 | 4507-4510 | Do the magnetic
field lines also represent the lines of force on a moving charged
particle at every point (b) If magnetic monopoles existed, how would the Gauss’s law of
magnetism be modified (c) Does a bar magnet exert a torque on itself due to its own field Does one element of a current-carrying wire exert a force on another
element of the same wire |
1 | 4508-4511 | (b) If magnetic monopoles existed, how would the Gauss’s law of
magnetism be modified (c) Does a bar magnet exert a torque on itself due to its own field Does one element of a current-carrying wire exert a force on another
element of the same wire Rationalised 2023-24
145
Magnetism and
Matter
EXAMPLE 5 |
1 | 4509-4512 | (c) Does a bar magnet exert a torque on itself due to its own field Does one element of a current-carrying wire exert a force on another
element of the same wire Rationalised 2023-24
145
Magnetism and
Matter
EXAMPLE 5 4
(d) Magnetic field arises due to charges in motion |
1 | 4510-4513 | Does one element of a current-carrying wire exert a force on another
element of the same wire Rationalised 2023-24
145
Magnetism and
Matter
EXAMPLE 5 4
(d) Magnetic field arises due to charges in motion Can a system
have magnetic moments even though its net charge is zero |
1 | 4511-4514 | Rationalised 2023-24
145
Magnetism and
Matter
EXAMPLE 5 4
(d) Magnetic field arises due to charges in motion Can a system
have magnetic moments even though its net charge is zero Solution
(a) No |
1 | 4512-4515 | 4
(d) Magnetic field arises due to charges in motion Can a system
have magnetic moments even though its net charge is zero Solution
(a) No The magnetic force is always normal to B (remember magnetic
force = qv × B) |
1 | 4513-4516 | Can a system
have magnetic moments even though its net charge is zero Solution
(a) No The magnetic force is always normal to B (remember magnetic
force = qv × B) It is misleading to call magnetic field lines as lines
of force |
1 | 4514-4517 | Solution
(a) No The magnetic force is always normal to B (remember magnetic
force = qv × B) It is misleading to call magnetic field lines as lines
of force (b) Gauss’s law of magnetism states that the flux of B through any
closed surface is always zero
B |
1 | 4515-4518 | The magnetic force is always normal to B (remember magnetic
force = qv × B) It is misleading to call magnetic field lines as lines
of force (b) Gauss’s law of magnetism states that the flux of B through any
closed surface is always zero
B ∆s
=
∫
0
s |
1 | 4516-4519 | It is misleading to call magnetic field lines as lines
of force (b) Gauss’s law of magnetism states that the flux of B through any
closed surface is always zero
B ∆s
=
∫
0
s If monopoles existed, the right hand side would be equal to the
monopole (magnetic charge) qm enclosed by S |
1 | 4517-4520 | (b) Gauss’s law of magnetism states that the flux of B through any
closed surface is always zero
B ∆s
=
∫
0
s If monopoles existed, the right hand side would be equal to the
monopole (magnetic charge) qm enclosed by S [Analogous to
Gauss’s law of electrostatics,
B |
1 | 4518-4521 | ∆s
=
∫
0
s If monopoles existed, the right hand side would be equal to the
monopole (magnetic charge) qm enclosed by S [Analogous to
Gauss’s law of electrostatics,
B ∆s
=
∫
µ0qm
S
where qm is the
(monopole) magnetic charge enclosed by S |
1 | 4519-4522 | If monopoles existed, the right hand side would be equal to the
monopole (magnetic charge) qm enclosed by S [Analogous to
Gauss’s law of electrostatics,
B ∆s
=
∫
µ0qm
S
where qm is the
(monopole) magnetic charge enclosed by S ]
(c) No |
1 | 4520-4523 | [Analogous to
Gauss’s law of electrostatics,
B ∆s
=
∫
µ0qm
S
where qm is the
(monopole) magnetic charge enclosed by S ]
(c) No There is no force or torque on an element due to the field
produced by that element itself |
1 | 4521-4524 | ∆s
=
∫
µ0qm
S
where qm is the
(monopole) magnetic charge enclosed by S ]
(c) No There is no force or torque on an element due to the field
produced by that element itself But there is a force (or torque)
on an element of the same wire |
1 | 4522-4525 | ]
(c) No There is no force or torque on an element due to the field
produced by that element itself But there is a force (or torque)
on an element of the same wire (For the special case of a straight
wire, this force is zero |
1 | 4523-4526 | There is no force or torque on an element due to the field
produced by that element itself But there is a force (or torque)
on an element of the same wire (For the special case of a straight
wire, this force is zero )
(d) Yes |
1 | 4524-4527 | But there is a force (or torque)
on an element of the same wire (For the special case of a straight
wire, this force is zero )
(d) Yes The average of the charge in the system may be zero |
1 | 4525-4528 | (For the special case of a straight
wire, this force is zero )
(d) Yes The average of the charge in the system may be zero Yet,
the mean of the magnetic moments due to various current loops
may not be zero |
1 | 4526-4529 | )
(d) Yes The average of the charge in the system may be zero Yet,
the mean of the magnetic moments due to various current loops
may not be zero We will come across such examples in connection
with paramagnetic material where atoms have net dipole moment
through their net charge is zero |
1 | 4527-4530 | The average of the charge in the system may be zero Yet,
the mean of the magnetic moments due to various current loops
may not be zero We will come across such examples in connection
with paramagnetic material where atoms have net dipole moment
through their net charge is zero 5 |
1 | 4528-4531 | Yet,
the mean of the magnetic moments due to various current loops
may not be zero We will come across such examples in connection
with paramagnetic material where atoms have net dipole moment
through their net charge is zero 5 4 MAGNETISATION AND MAGNETIC INTENSITY
The earth abounds with a bewildering variety of elements and compounds |
1 | 4529-4532 | We will come across such examples in connection
with paramagnetic material where atoms have net dipole moment
through their net charge is zero 5 4 MAGNETISATION AND MAGNETIC INTENSITY
The earth abounds with a bewildering variety of elements and compounds In addition, we have been synthesising new alloys, compounds and even
elements |
1 | 4530-4533 | 5 4 MAGNETISATION AND MAGNETIC INTENSITY
The earth abounds with a bewildering variety of elements and compounds In addition, we have been synthesising new alloys, compounds and even
elements One would like to classify the magnetic properties of these
substances |
1 | 4531-4534 | 4 MAGNETISATION AND MAGNETIC INTENSITY
The earth abounds with a bewildering variety of elements and compounds In addition, we have been synthesising new alloys, compounds and even
elements One would like to classify the magnetic properties of these
substances In the present section, we define and explain certain terms
which will help us to carry out this exercise |
1 | 4532-4535 | In addition, we have been synthesising new alloys, compounds and even
elements One would like to classify the magnetic properties of these
substances In the present section, we define and explain certain terms
which will help us to carry out this exercise We have seen that a circulating electron in an atom has a magnetic
moment |
1 | 4533-4536 | One would like to classify the magnetic properties of these
substances In the present section, we define and explain certain terms
which will help us to carry out this exercise We have seen that a circulating electron in an atom has a magnetic
moment In a bulk material, these moments add up vectorially and they
can give a net magnetic moment which is non-zero |
1 | 4534-4537 | In the present section, we define and explain certain terms
which will help us to carry out this exercise We have seen that a circulating electron in an atom has a magnetic
moment In a bulk material, these moments add up vectorially and they
can give a net magnetic moment which is non-zero We define
magnetisation M of a sample to be equal to its net magnetic moment per
unit volume:
M= mVnet
(5 |
1 | 4535-4538 | We have seen that a circulating electron in an atom has a magnetic
moment In a bulk material, these moments add up vectorially and they
can give a net magnetic moment which is non-zero We define
magnetisation M of a sample to be equal to its net magnetic moment per
unit volume:
M= mVnet
(5 7)
M is a vector with dimensions L–1 A and is measured in a units of A m–1 |
1 | 4536-4539 | In a bulk material, these moments add up vectorially and they
can give a net magnetic moment which is non-zero We define
magnetisation M of a sample to be equal to its net magnetic moment per
unit volume:
M= mVnet
(5 7)
M is a vector with dimensions L–1 A and is measured in a units of A m–1 Consider a long solenoid of n turns per unit length and carrying a
current I |
1 | 4537-4540 | We define
magnetisation M of a sample to be equal to its net magnetic moment per
unit volume:
M= mVnet
(5 7)
M is a vector with dimensions L–1 A and is measured in a units of A m–1 Consider a long solenoid of n turns per unit length and carrying a
current I The magnetic field in the interior of the solenoid was shown to
be given by
B0 = m0 nI
(5 |
1 | 4538-4541 | 7)
M is a vector with dimensions L–1 A and is measured in a units of A m–1 Consider a long solenoid of n turns per unit length and carrying a
current I The magnetic field in the interior of the solenoid was shown to
be given by
B0 = m0 nI
(5 8)
If the interior of the solenoid is filled with a material with non-zero
magnetisation, the field inside the solenoid will be greater than B0 |
1 | 4539-4542 | Consider a long solenoid of n turns per unit length and carrying a
current I The magnetic field in the interior of the solenoid was shown to
be given by
B0 = m0 nI
(5 8)
If the interior of the solenoid is filled with a material with non-zero
magnetisation, the field inside the solenoid will be greater than B0 The
net B field in the interior of the solenoid may be expressed as
B = B0 + Bm
(5 |
1 | 4540-4543 | The magnetic field in the interior of the solenoid was shown to
be given by
B0 = m0 nI
(5 8)
If the interior of the solenoid is filled with a material with non-zero
magnetisation, the field inside the solenoid will be greater than B0 The
net B field in the interior of the solenoid may be expressed as
B = B0 + Bm
(5 9)
Rationalised 2023-24
Physics
146
EXAMPLE 5 |
1 | 4541-4544 | 8)
If the interior of the solenoid is filled with a material with non-zero
magnetisation, the field inside the solenoid will be greater than B0 The
net B field in the interior of the solenoid may be expressed as
B = B0 + Bm
(5 9)
Rationalised 2023-24
Physics
146
EXAMPLE 5 5
where Bm is the field contributed by the material core |
1 | 4542-4545 | The
net B field in the interior of the solenoid may be expressed as
B = B0 + Bm
(5 9)
Rationalised 2023-24
Physics
146
EXAMPLE 5 5
where Bm is the field contributed by the material core It turns out that
this additional field Bm is proportional to the magnetisation M of the
material and is expressed as
Bm = m0M
(5 |
1 | 4543-4546 | 9)
Rationalised 2023-24
Physics
146
EXAMPLE 5 5
where Bm is the field contributed by the material core It turns out that
this additional field Bm is proportional to the magnetisation M of the
material and is expressed as
Bm = m0M
(5 10)
where m0 is the same constant (permittivity of vacuum) that appears in
Biot-Savart’s law |
1 | 4544-4547 | 5
where Bm is the field contributed by the material core It turns out that
this additional field Bm is proportional to the magnetisation M of the
material and is expressed as
Bm = m0M
(5 10)
where m0 is the same constant (permittivity of vacuum) that appears in
Biot-Savart’s law It is convenient to introduce another vector field H, called the magnetic
intensity, which is defined by
0
–
µ
H= B
M
(5 |
1 | 4545-4548 | It turns out that
this additional field Bm is proportional to the magnetisation M of the
material and is expressed as
Bm = m0M
(5 10)
where m0 is the same constant (permittivity of vacuum) that appears in
Biot-Savart’s law It is convenient to introduce another vector field H, called the magnetic
intensity, which is defined by
0
–
µ
H= B
M
(5 11)
where H has the same dimensions as M and is measured in units of A m–1 |
1 | 4546-4549 | 10)
where m0 is the same constant (permittivity of vacuum) that appears in
Biot-Savart’s law It is convenient to introduce another vector field H, called the magnetic
intensity, which is defined by
0
–
µ
H= B
M
(5 11)
where H has the same dimensions as M and is measured in units of A m–1 Thus, the total magnetic field B is written as
B = m0 (H + M)
(5 |
1 | 4547-4550 | It is convenient to introduce another vector field H, called the magnetic
intensity, which is defined by
0
–
µ
H= B
M
(5 11)
where H has the same dimensions as M and is measured in units of A m–1 Thus, the total magnetic field B is written as
B = m0 (H + M)
(5 12)
We repeat our defining procedure |
1 | 4548-4551 | 11)
where H has the same dimensions as M and is measured in units of A m–1 Thus, the total magnetic field B is written as
B = m0 (H + M)
(5 12)
We repeat our defining procedure We have partitioned the contribution
to the total magnetic field inside the sample into two parts: one, due to
external factors such as the current in the solenoid |
1 | 4549-4552 | Thus, the total magnetic field B is written as
B = m0 (H + M)
(5 12)
We repeat our defining procedure We have partitioned the contribution
to the total magnetic field inside the sample into two parts: one, due to
external factors such as the current in the solenoid This is represented
by H |
1 | 4550-4553 | 12)
We repeat our defining procedure We have partitioned the contribution
to the total magnetic field inside the sample into two parts: one, due to
external factors such as the current in the solenoid This is represented
by H The other is due to the specific nature of the magnetic material,
namely M |
1 | 4551-4554 | We have partitioned the contribution
to the total magnetic field inside the sample into two parts: one, due to
external factors such as the current in the solenoid This is represented
by H The other is due to the specific nature of the magnetic material,
namely M The latter quantity can be influenced by external factors |
1 | 4552-4555 | This is represented
by H The other is due to the specific nature of the magnetic material,
namely M The latter quantity can be influenced by external factors This
influence is mathematically expressed as
M=χ
H
(5 |
1 | 4553-4556 | The other is due to the specific nature of the magnetic material,
namely M The latter quantity can be influenced by external factors This
influence is mathematically expressed as
M=χ
H
(5 13)
where c , a dimensionless quantity, is appropriately called the magnetic
susceptibility |
1 | 4554-4557 | The latter quantity can be influenced by external factors This
influence is mathematically expressed as
M=χ
H
(5 13)
where c , a dimensionless quantity, is appropriately called the magnetic
susceptibility It is a measure of how a magnetic material responds to an
external field |
1 | 4555-4558 | This
influence is mathematically expressed as
M=χ
H
(5 13)
where c , a dimensionless quantity, is appropriately called the magnetic
susceptibility It is a measure of how a magnetic material responds to an
external field c is small and positive for materials, which are called
paramagnetic |
1 | 4556-4559 | 13)
where c , a dimensionless quantity, is appropriately called the magnetic
susceptibility It is a measure of how a magnetic material responds to an
external field c is small and positive for materials, which are called
paramagnetic It is small and negative for materials, which are termed
diamagnetic |
1 | 4557-4560 | It is a measure of how a magnetic material responds to an
external field c is small and positive for materials, which are called
paramagnetic It is small and negative for materials, which are termed
diamagnetic In the latter case M and H are opposite in direction |
1 | 4558-4561 | c is small and positive for materials, which are called
paramagnetic It is small and negative for materials, which are termed
diamagnetic In the latter case M and H are opposite in direction From
Eqs |
1 | 4559-4562 | It is small and negative for materials, which are termed
diamagnetic In the latter case M and H are opposite in direction From
Eqs (5 |
1 | 4560-4563 | In the latter case M and H are opposite in direction From
Eqs (5 12) and (5 |
1 | 4561-4564 | From
Eqs (5 12) and (5 13) we obtain,
0(1
)
µ
χ
=
+
B
H
(5 |
1 | 4562-4565 | (5 12) and (5 13) we obtain,
0(1
)
µ
χ
=
+
B
H
(5 14)
= m0 mr H
= m H
(5 |
1 | 4563-4566 | 12) and (5 13) we obtain,
0(1
)
µ
χ
=
+
B
H
(5 14)
= m0 mr H
= m H
(5 15)
where mr= 1 + c, is a dimensionless quantity called the relative magnetic
permeability of the substance |
1 | 4564-4567 | 13) we obtain,
0(1
)
µ
χ
=
+
B
H
(5 14)
= m0 mr H
= m H
(5 15)
where mr= 1 + c, is a dimensionless quantity called the relative magnetic
permeability of the substance It is the analog of the dielectric constant in
electrostatics |
1 | 4565-4568 | 14)
= m0 mr H
= m H
(5 15)
where mr= 1 + c, is a dimensionless quantity called the relative magnetic
permeability of the substance It is the analog of the dielectric constant in
electrostatics The magnetic permeability of the substance is m and it has
the same dimensions and units as m0;
m = m0mr = m0 (1+c) |
1 | 4566-4569 | 15)
where mr= 1 + c, is a dimensionless quantity called the relative magnetic
permeability of the substance It is the analog of the dielectric constant in
electrostatics The magnetic permeability of the substance is m and it has
the same dimensions and units as m0;
m = m0mr = m0 (1+c) The three quantities c, mr and m are interrelated and only one of
them is independent |
1 | 4567-4570 | It is the analog of the dielectric constant in
electrostatics The magnetic permeability of the substance is m and it has
the same dimensions and units as m0;
m = m0mr = m0 (1+c) The three quantities c, mr and m are interrelated and only one of
them is independent Given one, the other two may be easily determined |
1 | 4568-4571 | The magnetic permeability of the substance is m and it has
the same dimensions and units as m0;
m = m0mr = m0 (1+c) The three quantities c, mr and m are interrelated and only one of
them is independent Given one, the other two may be easily determined Example 5 |
1 | 4569-4572 | The three quantities c, mr and m are interrelated and only one of
them is independent Given one, the other two may be easily determined Example 5 5 A solenoid has a core of a material with relative
permeability 400 |
1 | 4570-4573 | Given one, the other two may be easily determined Example 5 5 A solenoid has a core of a material with relative
permeability 400 The windings of the solenoid are insulated from the
core and carry a current of 2A |
1 | 4571-4574 | Example 5 5 A solenoid has a core of a material with relative
permeability 400 The windings of the solenoid are insulated from the
core and carry a current of 2A If the number of turns is 1000 per
metre, calculate (a) H, (b) M, (c) B and (d) the magnetising current Im |
1 | 4572-4575 | 5 A solenoid has a core of a material with relative
permeability 400 The windings of the solenoid are insulated from the
core and carry a current of 2A If the number of turns is 1000 per
metre, calculate (a) H, (b) M, (c) B and (d) the magnetising current Im Rationalised 2023-24
147
Magnetism and
Matter
EXAMPLE 5 |
1 | 4573-4576 | The windings of the solenoid are insulated from the
core and carry a current of 2A If the number of turns is 1000 per
metre, calculate (a) H, (b) M, (c) B and (d) the magnetising current Im Rationalised 2023-24
147
Magnetism and
Matter
EXAMPLE 5 5
Solution
(a) The field H is dependent of the material of the core, and is
H = nI = 1000 × 2 |
1 | 4574-4577 | If the number of turns is 1000 per
metre, calculate (a) H, (b) M, (c) B and (d) the magnetising current Im Rationalised 2023-24
147
Magnetism and
Matter
EXAMPLE 5 5
Solution
(a) The field H is dependent of the material of the core, and is
H = nI = 1000 × 2 0 = 2 ×103 A/m |
1 | 4575-4578 | Rationalised 2023-24
147
Magnetism and
Matter
EXAMPLE 5 5
Solution
(a) The field H is dependent of the material of the core, and is
H = nI = 1000 × 2 0 = 2 ×103 A/m (b) The magnetic field B is given by
B = mr m0 H
= 400 × 4p ×10–7 (N/A2) × 2 × 103 (A/m)
= 1 |
1 | 4576-4579 | 5
Solution
(a) The field H is dependent of the material of the core, and is
H = nI = 1000 × 2 0 = 2 ×103 A/m (b) The magnetic field B is given by
B = mr m0 H
= 400 × 4p ×10–7 (N/A2) × 2 × 103 (A/m)
= 1 0 T
(c) Magnetisation is given by
M = (B– m0 H)/ m0
= (mr m0 H–m0 H)/m0 = (mr – 1)H = 399 × H
@ 8 × 105 A/m
(d) The magnetising current IM is the additional current that needs to
be passed through the windings of the solenoid in the absence of
the core which would give a B value as in the presence of the core |
1 | 4577-4580 | 0 = 2 ×103 A/m (b) The magnetic field B is given by
B = mr m0 H
= 400 × 4p ×10–7 (N/A2) × 2 × 103 (A/m)
= 1 0 T
(c) Magnetisation is given by
M = (B– m0 H)/ m0
= (mr m0 H–m0 H)/m0 = (mr – 1)H = 399 × H
@ 8 × 105 A/m
(d) The magnetising current IM is the additional current that needs to
be passed through the windings of the solenoid in the absence of
the core which would give a B value as in the presence of the core Thus B = mr n (I + IM) |
1 | 4578-4581 | (b) The magnetic field B is given by
B = mr m0 H
= 400 × 4p ×10–7 (N/A2) × 2 × 103 (A/m)
= 1 0 T
(c) Magnetisation is given by
M = (B– m0 H)/ m0
= (mr m0 H–m0 H)/m0 = (mr – 1)H = 399 × H
@ 8 × 105 A/m
(d) The magnetising current IM is the additional current that needs to
be passed through the windings of the solenoid in the absence of
the core which would give a B value as in the presence of the core Thus B = mr n (I + IM) Using I = 2A, B = 1 T, we get IM = 794 A |
1 | 4579-4582 | 0 T
(c) Magnetisation is given by
M = (B– m0 H)/ m0
= (mr m0 H–m0 H)/m0 = (mr – 1)H = 399 × H
@ 8 × 105 A/m
(d) The magnetising current IM is the additional current that needs to
be passed through the windings of the solenoid in the absence of
the core which would give a B value as in the presence of the core Thus B = mr n (I + IM) Using I = 2A, B = 1 T, we get IM = 794 A 5 |
1 | 4580-4583 | Thus B = mr n (I + IM) Using I = 2A, B = 1 T, we get IM = 794 A 5 5 MAGNETIC PROPERTIES OF MATERIALS
The discussion in the previous section helps us to classify materials as
diamagnetic, paramagnetic or ferromagnetic |
1 | 4581-4584 | Using I = 2A, B = 1 T, we get IM = 794 A 5 5 MAGNETIC PROPERTIES OF MATERIALS
The discussion in the previous section helps us to classify materials as
diamagnetic, paramagnetic or ferromagnetic In terms of the susceptibility
c, a material is diamagnetic if c is negative, para- if c is positive and small,
and ferro- if c is large and positive |
1 | 4582-4585 | 5 5 MAGNETIC PROPERTIES OF MATERIALS
The discussion in the previous section helps us to classify materials as
diamagnetic, paramagnetic or ferromagnetic In terms of the susceptibility
c, a material is diamagnetic if c is negative, para- if c is positive and small,
and ferro- if c is large and positive A glance at Table 5 |
1 | 4583-4586 | 5 MAGNETIC PROPERTIES OF MATERIALS
The discussion in the previous section helps us to classify materials as
diamagnetic, paramagnetic or ferromagnetic In terms of the susceptibility
c, a material is diamagnetic if c is negative, para- if c is positive and small,
and ferro- if c is large and positive A glance at Table 5 3 gives one a better feeling for these materials |
1 | 4584-4587 | In terms of the susceptibility
c, a material is diamagnetic if c is negative, para- if c is positive and small,
and ferro- if c is large and positive A glance at Table 5 3 gives one a better feeling for these materials Here e is a small positive number introduced to quantify paramagnetic
materials |
1 | 4585-4588 | A glance at Table 5 3 gives one a better feeling for these materials Here e is a small positive number introduced to quantify paramagnetic
materials Next, we describe these materials in some detail |
1 | 4586-4589 | 3 gives one a better feeling for these materials Here e is a small positive number introduced to quantify paramagnetic
materials Next, we describe these materials in some detail TABLE 5 |
1 | 4587-4590 | Here e is a small positive number introduced to quantify paramagnetic
materials Next, we describe these materials in some detail TABLE 5 3
Diamagnetic
Paramagnetic
Ferromagnetic
–1 £ c < 0
0 < c < e
c >> 1
0 £ mr < 1
1< mr < 1+ e
mr >> 1
m < m0
m > m0
m >> m0
5 |
1 | 4588-4591 | Next, we describe these materials in some detail TABLE 5 3
Diamagnetic
Paramagnetic
Ferromagnetic
–1 £ c < 0
0 < c < e
c >> 1
0 £ mr < 1
1< mr < 1+ e
mr >> 1
m < m0
m > m0
m >> m0
5 5 |
1 | 4589-4592 | TABLE 5 3
Diamagnetic
Paramagnetic
Ferromagnetic
–1 £ c < 0
0 < c < e
c >> 1
0 £ mr < 1
1< mr < 1+ e
mr >> 1
m < m0
m > m0
m >> m0
5 5 1 Diamagnetism
Diamagnetic substances are those which have tendency to move from
stronger to the weaker part of the external magnetic field |
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