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1
5190-5193
Now, let us recollect Experiment 6 3 in Section 6 2 In that experiment, emf is induced in coil C1 wherever there was any change in current through coil C2
1
5191-5194
3 in Section 6 2 In that experiment, emf is induced in coil C1 wherever there was any change in current through coil C2 Let F1 be the flux through coil C1 (say of N1 turns) when current in coil C2 is I2
1
5192-5195
2 In that experiment, emf is induced in coil C1 wherever there was any change in current through coil C2 Let F1 be the flux through coil C1 (say of N1 turns) when current in coil C2 is I2 Then, from Eq
1
5193-5196
In that experiment, emf is induced in coil C1 wherever there was any change in current through coil C2 Let F1 be the flux through coil C1 (say of N1 turns) when current in coil C2 is I2 Then, from Eq (6
1
5194-5197
Let F1 be the flux through coil C1 (say of N1 turns) when current in coil C2 is I2 Then, from Eq (6 7), we have N1F1 = MI2 For currents varrying with time, ( ) ( ) 1 1 2 d d d d N MI t t Φ = Since induced emf in coil C1 is given by ( ) 1 1 –d d N t Φ ε1 = We get, d2 – Id M t ε1 = Rationalised 2023-24 Physics 168 It shows that varying current in a coil can induce emf in a neighbouring coil
1
5195-5198
Then, from Eq (6 7), we have N1F1 = MI2 For currents varrying with time, ( ) ( ) 1 1 2 d d d d N MI t t Φ = Since induced emf in coil C1 is given by ( ) 1 1 –d d N t Φ ε1 = We get, d2 – Id M t ε1 = Rationalised 2023-24 Physics 168 It shows that varying current in a coil can induce emf in a neighbouring coil The magnitude of the induced emf depends upon the rate of change of current and mutual inductance of the two coils
1
5196-5199
(6 7), we have N1F1 = MI2 For currents varrying with time, ( ) ( ) 1 1 2 d d d d N MI t t Φ = Since induced emf in coil C1 is given by ( ) 1 1 –d d N t Φ ε1 = We get, d2 – Id M t ε1 = Rationalised 2023-24 Physics 168 It shows that varying current in a coil can induce emf in a neighbouring coil The magnitude of the induced emf depends upon the rate of change of current and mutual inductance of the two coils 6
1
5197-5200
7), we have N1F1 = MI2 For currents varrying with time, ( ) ( ) 1 1 2 d d d d N MI t t Φ = Since induced emf in coil C1 is given by ( ) 1 1 –d d N t Φ ε1 = We get, d2 – Id M t ε1 = Rationalised 2023-24 Physics 168 It shows that varying current in a coil can induce emf in a neighbouring coil The magnitude of the induced emf depends upon the rate of change of current and mutual inductance of the two coils 6 7
1
5198-5201
The magnitude of the induced emf depends upon the rate of change of current and mutual inductance of the two coils 6 7 2 Self-inductance In the previous sub-section, we considered the flux in one solenoid due to the current in the other
1
5199-5202
6 7 2 Self-inductance In the previous sub-section, we considered the flux in one solenoid due to the current in the other It is also possible that emf is induced in a single isolated coil due to change of flux through the coil by means of varying the current through the same coil
1
5200-5203
7 2 Self-inductance In the previous sub-section, we considered the flux in one solenoid due to the current in the other It is also possible that emf is induced in a single isolated coil due to change of flux through the coil by means of varying the current through the same coil This phenomenon is called self-induction
1
5201-5204
2 Self-inductance In the previous sub-section, we considered the flux in one solenoid due to the current in the other It is also possible that emf is induced in a single isolated coil due to change of flux through the coil by means of varying the current through the same coil This phenomenon is called self-induction In this case, flux linkage through a coil of N turns is proportional to the current through the coil and is expressed as NB I Φ ∝ B L N I Φ = (6
1
5202-5205
It is also possible that emf is induced in a single isolated coil due to change of flux through the coil by means of varying the current through the same coil This phenomenon is called self-induction In this case, flux linkage through a coil of N turns is proportional to the current through the coil and is expressed as NB I Φ ∝ B L N I Φ = (6 13) where constant of proportionality L is called self-inductance of the coil
1
5203-5206
This phenomenon is called self-induction In this case, flux linkage through a coil of N turns is proportional to the current through the coil and is expressed as NB I Φ ∝ B L N I Φ = (6 13) where constant of proportionality L is called self-inductance of the coil It is also called the coefficient of self-induction of the coil
1
5204-5207
In this case, flux linkage through a coil of N turns is proportional to the current through the coil and is expressed as NB I Φ ∝ B L N I Φ = (6 13) where constant of proportionality L is called self-inductance of the coil It is also called the coefficient of self-induction of the coil When the current is varied, the flux linked with the coil also changes and an emf is induced in the coil
1
5205-5208
13) where constant of proportionality L is called self-inductance of the coil It is also called the coefficient of self-induction of the coil When the current is varied, the flux linked with the coil also changes and an emf is induced in the coil Using Eq
1
5206-5209
It is also called the coefficient of self-induction of the coil When the current is varied, the flux linked with the coil also changes and an emf is induced in the coil Using Eq (6
1
5207-5210
When the current is varied, the flux linked with the coil also changes and an emf is induced in the coil Using Eq (6 13), the induced emf is given by ( B) –d d N t Φ ε = d – d I L t ε = (6
1
5208-5211
Using Eq (6 13), the induced emf is given by ( B) –d d N t Φ ε = d – d I L t ε = (6 14) Thus, the self-induced emf always opposes any change (increase or decrease) of current in the coil
1
5209-5212
(6 13), the induced emf is given by ( B) –d d N t Φ ε = d – d I L t ε = (6 14) Thus, the self-induced emf always opposes any change (increase or decrease) of current in the coil It is possible to calculate the self-inductance for circuits with simple geometries
1
5210-5213
13), the induced emf is given by ( B) –d d N t Φ ε = d – d I L t ε = (6 14) Thus, the self-induced emf always opposes any change (increase or decrease) of current in the coil It is possible to calculate the self-inductance for circuits with simple geometries Let us calculate the self-inductance of a long solenoid of cross- sectional area A and length l, having n turns per unit length
1
5211-5214
14) Thus, the self-induced emf always opposes any change (increase or decrease) of current in the coil It is possible to calculate the self-inductance for circuits with simple geometries Let us calculate the self-inductance of a long solenoid of cross- sectional area A and length l, having n turns per unit length The magnetic field due to a current I flowing in the solenoid is B = m0 n I (neglecting edge effects, as before)
1
5212-5215
It is possible to calculate the self-inductance for circuits with simple geometries Let us calculate the self-inductance of a long solenoid of cross- sectional area A and length l, having n turns per unit length The magnetic field due to a current I flowing in the solenoid is B = m0 n I (neglecting edge effects, as before) The total flux linked with the solenoid is ( )( )( ) 0 NB nl n I A Φ µ = 0n2AlI  where nl is the total number of turns
1
5213-5216
Let us calculate the self-inductance of a long solenoid of cross- sectional area A and length l, having n turns per unit length The magnetic field due to a current I flowing in the solenoid is B = m0 n I (neglecting edge effects, as before) The total flux linked with the solenoid is ( )( )( ) 0 NB nl n I A Φ µ = 0n2AlI  where nl is the total number of turns Thus, the self-inductance is, L I ΝΦΒ = 2 =µ0n Al (6
1
5214-5217
The magnetic field due to a current I flowing in the solenoid is B = m0 n I (neglecting edge effects, as before) The total flux linked with the solenoid is ( )( )( ) 0 NB nl n I A Φ µ = 0n2AlI  where nl is the total number of turns Thus, the self-inductance is, L I ΝΦΒ = 2 =µ0n Al (6 15) If we fill the inside of the solenoid with a material of relative permeability mr (for example soft iron, which has a high value of relative permeability), then, 2 0 r L =µ µn Al (6
1
5215-5218
The total flux linked with the solenoid is ( )( )( ) 0 NB nl n I A Φ µ = 0n2AlI  where nl is the total number of turns Thus, the self-inductance is, L I ΝΦΒ = 2 =µ0n Al (6 15) If we fill the inside of the solenoid with a material of relative permeability mr (for example soft iron, which has a high value of relative permeability), then, 2 0 r L =µ µn Al (6 16) The self-inductance of the coil depends on its geometry and on the permeability of the medium
1
5216-5219
Thus, the self-inductance is, L I ΝΦΒ = 2 =µ0n Al (6 15) If we fill the inside of the solenoid with a material of relative permeability mr (for example soft iron, which has a high value of relative permeability), then, 2 0 r L =µ µn Al (6 16) The self-inductance of the coil depends on its geometry and on the permeability of the medium The self-induced emf is also called the back emf as it opposes any change in the current in a circuit
1
5217-5220
15) If we fill the inside of the solenoid with a material of relative permeability mr (for example soft iron, which has a high value of relative permeability), then, 2 0 r L =µ µn Al (6 16) The self-inductance of the coil depends on its geometry and on the permeability of the medium The self-induced emf is also called the back emf as it opposes any change in the current in a circuit Physically, the self-inductance plays Rationalised 2023-24 Electromagnetic Induction 169 the role of inertia
1
5218-5221
16) The self-inductance of the coil depends on its geometry and on the permeability of the medium The self-induced emf is also called the back emf as it opposes any change in the current in a circuit Physically, the self-inductance plays Rationalised 2023-24 Electromagnetic Induction 169 the role of inertia It is the electromagnetic analogue of mass in mechanics
1
5219-5222
The self-induced emf is also called the back emf as it opposes any change in the current in a circuit Physically, the self-inductance plays Rationalised 2023-24 Electromagnetic Induction 169 the role of inertia It is the electromagnetic analogue of mass in mechanics So, work needs to be done against the back emf (e) in establishing the current
1
5220-5223
Physically, the self-inductance plays Rationalised 2023-24 Electromagnetic Induction 169 the role of inertia It is the electromagnetic analogue of mass in mechanics So, work needs to be done against the back emf (e) in establishing the current This work done is stored as magnetic potential energy
1
5221-5224
It is the electromagnetic analogue of mass in mechanics So, work needs to be done against the back emf (e) in establishing the current This work done is stored as magnetic potential energy For the current I at an instant in a circuit, the rate of work done is d d W I t ε = If we ignore the resistive losses and consider only inductive effect, then using Eq
1
5222-5225
So, work needs to be done against the back emf (e) in establishing the current This work done is stored as magnetic potential energy For the current I at an instant in a circuit, the rate of work done is d d W I t ε = If we ignore the resistive losses and consider only inductive effect, then using Eq (6
1
5223-5226
This work done is stored as magnetic potential energy For the current I at an instant in a circuit, the rate of work done is d d W I t ε = If we ignore the resistive losses and consider only inductive effect, then using Eq (6 16), d d d d W I L I t t = Total amount of work done in establishing the current I is W W L I I I = = ∫ ∫ d d 0 Thus, the energy required to build up the current I is, 2 21 W LI = (6
1
5224-5227
For the current I at an instant in a circuit, the rate of work done is d d W I t ε = If we ignore the resistive losses and consider only inductive effect, then using Eq (6 16), d d d d W I L I t t = Total amount of work done in establishing the current I is W W L I I I = = ∫ ∫ d d 0 Thus, the energy required to build up the current I is, 2 21 W LI = (6 17) This expression reminds us of mv 2/2 for the (mechanical) kinetic energy of a particle of mass m, and shows that L is analogous to m (i
1
5225-5228
(6 16), d d d d W I L I t t = Total amount of work done in establishing the current I is W W L I I I = = ∫ ∫ d d 0 Thus, the energy required to build up the current I is, 2 21 W LI = (6 17) This expression reminds us of mv 2/2 for the (mechanical) kinetic energy of a particle of mass m, and shows that L is analogous to m (i e
1
5226-5229
16), d d d d W I L I t t = Total amount of work done in establishing the current I is W W L I I I = = ∫ ∫ d d 0 Thus, the energy required to build up the current I is, 2 21 W LI = (6 17) This expression reminds us of mv 2/2 for the (mechanical) kinetic energy of a particle of mass m, and shows that L is analogous to m (i e , L is electrical inertia and opposes growth and decay of current in the circuit)
1
5227-5230
17) This expression reminds us of mv 2/2 for the (mechanical) kinetic energy of a particle of mass m, and shows that L is analogous to m (i e , L is electrical inertia and opposes growth and decay of current in the circuit) Consider the general case of currents flowing simultaneously in two nearby coils
1
5228-5231
e , L is electrical inertia and opposes growth and decay of current in the circuit) Consider the general case of currents flowing simultaneously in two nearby coils The flux linked with one coil will be the sum of two fluxes which exist independently
1
5229-5232
, L is electrical inertia and opposes growth and decay of current in the circuit) Consider the general case of currents flowing simultaneously in two nearby coils The flux linked with one coil will be the sum of two fluxes which exist independently Equation (6
1
5230-5233
Consider the general case of currents flowing simultaneously in two nearby coils The flux linked with one coil will be the sum of two fluxes which exist independently Equation (6 7) would be modified into N1 1 11 1 12 2 M I M I Φ = + where M11 represents inductance due to the same coil
1
5231-5234
The flux linked with one coil will be the sum of two fluxes which exist independently Equation (6 7) would be modified into N1 1 11 1 12 2 M I M I Φ = + where M11 represents inductance due to the same coil Therefore, using Faraday’s law, 1 2 1 11 12 d d d d I I M M t t ε = − − M11 is the self-inductance and is written as L1
1
5232-5235
Equation (6 7) would be modified into N1 1 11 1 12 2 M I M I Φ = + where M11 represents inductance due to the same coil Therefore, using Faraday’s law, 1 2 1 11 12 d d d d I I M M t t ε = − − M11 is the self-inductance and is written as L1 Therefore, 1 2 1 1 12 d d d d I I L M t t ε = − − Example 6
1
5233-5236
7) would be modified into N1 1 11 1 12 2 M I M I Φ = + where M11 represents inductance due to the same coil Therefore, using Faraday’s law, 1 2 1 11 12 d d d d I I M M t t ε = − − M11 is the self-inductance and is written as L1 Therefore, 1 2 1 1 12 d d d d I I L M t t ε = − − Example 6 9 (a) Obtain the expression for the magnetic energy stored in a solenoid in terms of magnetic field B, area A and length l of the solenoid
1
5234-5237
Therefore, using Faraday’s law, 1 2 1 11 12 d d d d I I M M t t ε = − − M11 is the self-inductance and is written as L1 Therefore, 1 2 1 1 12 d d d d I I L M t t ε = − − Example 6 9 (a) Obtain the expression for the magnetic energy stored in a solenoid in terms of magnetic field B, area A and length l of the solenoid (b) How does this magnetic energy compare with the electrostatic energy stored in a capacitor
1
5235-5238
Therefore, 1 2 1 1 12 d d d d I I L M t t ε = − − Example 6 9 (a) Obtain the expression for the magnetic energy stored in a solenoid in terms of magnetic field B, area A and length l of the solenoid (b) How does this magnetic energy compare with the electrostatic energy stored in a capacitor Solution (a) From Eq
1
5236-5239
9 (a) Obtain the expression for the magnetic energy stored in a solenoid in terms of magnetic field B, area A and length l of the solenoid (b) How does this magnetic energy compare with the electrostatic energy stored in a capacitor Solution (a) From Eq (6
1
5237-5240
(b) How does this magnetic energy compare with the electrostatic energy stored in a capacitor Solution (a) From Eq (6 17), the magnetic energy is 2 21 UB LI = =     = ( ) 1 2 2 L B n nI µ µ 0 0 sinceB for a solenoid , EXAMPLE 6
1
5238-5241
Solution (a) From Eq (6 17), the magnetic energy is 2 21 UB LI = =     = ( ) 1 2 2 L B n nI µ µ 0 0 sinceB for a solenoid , EXAMPLE 6 9 Rationalised 2023-24 Physics 170 EXAMPLE 6
1
5239-5242
(6 17), the magnetic energy is 2 21 UB LI = =     = ( ) 1 2 2 L B n nI µ µ 0 0 sinceB for a solenoid , EXAMPLE 6 9 Rationalised 2023-24 Physics 170 EXAMPLE 6 9 =     21 0 2 0 2 ( ) µ µ n Al B n [from Eq
1
5240-5243
17), the magnetic energy is 2 21 UB LI = =     = ( ) 1 2 2 L B n nI µ µ 0 0 sinceB for a solenoid , EXAMPLE 6 9 Rationalised 2023-24 Physics 170 EXAMPLE 6 9 =     21 0 2 0 2 ( ) µ µ n Al B n [from Eq (6
1
5241-5244
9 Rationalised 2023-24 Physics 170 EXAMPLE 6 9 =     21 0 2 0 2 ( ) µ µ n Al B n [from Eq (6 15)] 2 0 21 µB Al = (b) The magnetic energy per unit volume is, B B U u =V (where V is volume that contains flux) UB Al = 2 20 B µ = (6
1
5242-5245
9 =     21 0 2 0 2 ( ) µ µ n Al B n [from Eq (6 15)] 2 0 21 µB Al = (b) The magnetic energy per unit volume is, B B U u =V (where V is volume that contains flux) UB Al = 2 20 B µ = (6 18) We have already obtained the relation for the electrostatic energy stored per unit volume in a parallel plate capacitor (refer to Chapter 2, Eq
1
5243-5246
(6 15)] 2 0 21 µB Al = (b) The magnetic energy per unit volume is, B B U u =V (where V is volume that contains flux) UB Al = 2 20 B µ = (6 18) We have already obtained the relation for the electrostatic energy stored per unit volume in a parallel plate capacitor (refer to Chapter 2, Eq 2
1
5244-5247
15)] 2 0 21 µB Al = (b) The magnetic energy per unit volume is, B B U u =V (where V is volume that contains flux) UB Al = 2 20 B µ = (6 18) We have already obtained the relation for the electrostatic energy stored per unit volume in a parallel plate capacitor (refer to Chapter 2, Eq 2 73), 2 210 u E Ε ε = (2
1
5245-5248
18) We have already obtained the relation for the electrostatic energy stored per unit volume in a parallel plate capacitor (refer to Chapter 2, Eq 2 73), 2 210 u E Ε ε = (2 73) In both the cases energy is proportional to the square of the field strength
1
5246-5249
2 73), 2 210 u E Ε ε = (2 73) In both the cases energy is proportional to the square of the field strength Equations (6
1
5247-5250
73), 2 210 u E Ε ε = (2 73) In both the cases energy is proportional to the square of the field strength Equations (6 18) and (2
1
5248-5251
73) In both the cases energy is proportional to the square of the field strength Equations (6 18) and (2 73) have been derived for special cases: a solenoid and a parallel plate capacitor, respectively
1
5249-5252
Equations (6 18) and (2 73) have been derived for special cases: a solenoid and a parallel plate capacitor, respectively But they are general and valid for any region of space in which a magnetic field or/and an electric field exist
1
5250-5253
18) and (2 73) have been derived for special cases: a solenoid and a parallel plate capacitor, respectively But they are general and valid for any region of space in which a magnetic field or/and an electric field exist FIGURE 6
1
5251-5254
73) have been derived for special cases: a solenoid and a parallel plate capacitor, respectively But they are general and valid for any region of space in which a magnetic field or/and an electric field exist FIGURE 6 13 AC Generator Interactive animation on ac generator: http://micro
1
5252-5255
But they are general and valid for any region of space in which a magnetic field or/and an electric field exist FIGURE 6 13 AC Generator Interactive animation on ac generator: http://micro magnet
1
5253-5256
FIGURE 6 13 AC Generator Interactive animation on ac generator: http://micro magnet fsu
1
5254-5257
13 AC Generator Interactive animation on ac generator: http://micro magnet fsu edu/electromag/java/generator/ac
1
5255-5258
magnet fsu edu/electromag/java/generator/ac html 6
1
5256-5259
fsu edu/electromag/java/generator/ac html 6 8 AC GENERATOR The phenomenon of electromagnetic induction has been technologically exploited in many ways
1
5257-5260
edu/electromag/java/generator/ac html 6 8 AC GENERATOR The phenomenon of electromagnetic induction has been technologically exploited in many ways An exceptionally important application is the generation of alternating currents (ac)
1
5258-5261
html 6 8 AC GENERATOR The phenomenon of electromagnetic induction has been technologically exploited in many ways An exceptionally important application is the generation of alternating currents (ac) The modern ac generator with a typical output capacity of 100 MW is a highly evolved machine
1
5259-5262
8 AC GENERATOR The phenomenon of electromagnetic induction has been technologically exploited in many ways An exceptionally important application is the generation of alternating currents (ac) The modern ac generator with a typical output capacity of 100 MW is a highly evolved machine In this section, we shall describe the basic principles behind this machine
1
5260-5263
An exceptionally important application is the generation of alternating currents (ac) The modern ac generator with a typical output capacity of 100 MW is a highly evolved machine In this section, we shall describe the basic principles behind this machine The Yugoslav inventor Nicola Tesla is credited with the development of the machine
1
5261-5264
The modern ac generator with a typical output capacity of 100 MW is a highly evolved machine In this section, we shall describe the basic principles behind this machine The Yugoslav inventor Nicola Tesla is credited with the development of the machine As was pointed out in Section 6
1
5262-5265
In this section, we shall describe the basic principles behind this machine The Yugoslav inventor Nicola Tesla is credited with the development of the machine As was pointed out in Section 6 3, one method to induce an emf or current in a loop is through a change in the loop’s orientation or a change in its effective area
1
5263-5266
The Yugoslav inventor Nicola Tesla is credited with the development of the machine As was pointed out in Section 6 3, one method to induce an emf or current in a loop is through a change in the loop’s orientation or a change in its effective area As the coil rotates in a magnetic field B, the effective area of the loop (the face perpendicular to the field) is A cos q, where q is the angle between A and B
1
5264-5267
As was pointed out in Section 6 3, one method to induce an emf or current in a loop is through a change in the loop’s orientation or a change in its effective area As the coil rotates in a magnetic field B, the effective area of the loop (the face perpendicular to the field) is A cos q, where q is the angle between A and B This method of producing a flux change is the principle of operation of a Rationalised 2023-24 Electromagnetic Induction 171 simple ac generator
1
5265-5268
3, one method to induce an emf or current in a loop is through a change in the loop’s orientation or a change in its effective area As the coil rotates in a magnetic field B, the effective area of the loop (the face perpendicular to the field) is A cos q, where q is the angle between A and B This method of producing a flux change is the principle of operation of a Rationalised 2023-24 Electromagnetic Induction 171 simple ac generator An ac generator converts mechanical energy into electrical energy
1
5266-5269
As the coil rotates in a magnetic field B, the effective area of the loop (the face perpendicular to the field) is A cos q, where q is the angle between A and B This method of producing a flux change is the principle of operation of a Rationalised 2023-24 Electromagnetic Induction 171 simple ac generator An ac generator converts mechanical energy into electrical energy The basic elements of an ac generator are shown in Fig
1
5267-5270
This method of producing a flux change is the principle of operation of a Rationalised 2023-24 Electromagnetic Induction 171 simple ac generator An ac generator converts mechanical energy into electrical energy The basic elements of an ac generator are shown in Fig 6
1
5268-5271
An ac generator converts mechanical energy into electrical energy The basic elements of an ac generator are shown in Fig 6 13
1
5269-5272
The basic elements of an ac generator are shown in Fig 6 13 It consists of a coil mounted on a rotor shaft
1
5270-5273
6 13 It consists of a coil mounted on a rotor shaft The axis of rotation of the coil is perpendicular to the direction of the magnetic field
1
5271-5274
13 It consists of a coil mounted on a rotor shaft The axis of rotation of the coil is perpendicular to the direction of the magnetic field The coil (called armature) is mechanically rotated in the uniform magnetic field by some external means
1
5272-5275
It consists of a coil mounted on a rotor shaft The axis of rotation of the coil is perpendicular to the direction of the magnetic field The coil (called armature) is mechanically rotated in the uniform magnetic field by some external means The rotation of the coil causes the magnetic flux through it to change, so an emf is induced in the coil
1
5273-5276
The axis of rotation of the coil is perpendicular to the direction of the magnetic field The coil (called armature) is mechanically rotated in the uniform magnetic field by some external means The rotation of the coil causes the magnetic flux through it to change, so an emf is induced in the coil The ends of the coil are connected to an external circuit by means of slip rings and brushes
1
5274-5277
The coil (called armature) is mechanically rotated in the uniform magnetic field by some external means The rotation of the coil causes the magnetic flux through it to change, so an emf is induced in the coil The ends of the coil are connected to an external circuit by means of slip rings and brushes When the coil is rotated with a constant angular speed w, the angle q between the magnetic field vector B and the area vector A of the coil at any instant t is q = wt (assuming q = 0° at t = 0)
1
5275-5278
The rotation of the coil causes the magnetic flux through it to change, so an emf is induced in the coil The ends of the coil are connected to an external circuit by means of slip rings and brushes When the coil is rotated with a constant angular speed w, the angle q between the magnetic field vector B and the area vector A of the coil at any instant t is q = wt (assuming q = 0° at t = 0) As a result, the effective area of the coil exposed to the magnetic field lines changes with time, and from Eq
1
5276-5279
The ends of the coil are connected to an external circuit by means of slip rings and brushes When the coil is rotated with a constant angular speed w, the angle q between the magnetic field vector B and the area vector A of the coil at any instant t is q = wt (assuming q = 0° at t = 0) As a result, the effective area of the coil exposed to the magnetic field lines changes with time, and from Eq (6
1
5277-5280
When the coil is rotated with a constant angular speed w, the angle q between the magnetic field vector B and the area vector A of the coil at any instant t is q = wt (assuming q = 0° at t = 0) As a result, the effective area of the coil exposed to the magnetic field lines changes with time, and from Eq (6 1), the flux at any time t is FB = BA cos q = BA cos wt From Faraday’s law, the induced emf for the rotating coil of N turns is then, d d – – (cos ) dt d B N NBA t t Φ ε ω = = εThus, the instantaneous value of the emf is ω ω = NBA sin t (6
1
5278-5281
As a result, the effective area of the coil exposed to the magnetic field lines changes with time, and from Eq (6 1), the flux at any time t is FB = BA cos q = BA cos wt From Faraday’s law, the induced emf for the rotating coil of N turns is then, d d – – (cos ) dt d B N NBA t t Φ ε ω = = εThus, the instantaneous value of the emf is ω ω = NBA sin t (6 19) where NBAw is the maximum value of the emf, which occurs when sin wt = ±1
1
5279-5282
(6 1), the flux at any time t is FB = BA cos q = BA cos wt From Faraday’s law, the induced emf for the rotating coil of N turns is then, d d – – (cos ) dt d B N NBA t t Φ ε ω = = εThus, the instantaneous value of the emf is ω ω = NBA sin t (6 19) where NBAw is the maximum value of the emf, which occurs when sin wt = ±1 If we denote NBAw as e0, then e = e0 sin wt (6
1
5280-5283
1), the flux at any time t is FB = BA cos q = BA cos wt From Faraday’s law, the induced emf for the rotating coil of N turns is then, d d – – (cos ) dt d B N NBA t t Φ ε ω = = εThus, the instantaneous value of the emf is ω ω = NBA sin t (6 19) where NBAw is the maximum value of the emf, which occurs when sin wt = ±1 If we denote NBAw as e0, then e = e0 sin wt (6 20) Since the value of the sine fuction varies between +1 and –1, the sign, or polarity of the emf changes with time
1
5281-5284
19) where NBAw is the maximum value of the emf, which occurs when sin wt = ±1 If we denote NBAw as e0, then e = e0 sin wt (6 20) Since the value of the sine fuction varies between +1 and –1, the sign, or polarity of the emf changes with time Note from Fig
1
5282-5285
If we denote NBAw as e0, then e = e0 sin wt (6 20) Since the value of the sine fuction varies between +1 and –1, the sign, or polarity of the emf changes with time Note from Fig 6
1
5283-5286
20) Since the value of the sine fuction varies between +1 and –1, the sign, or polarity of the emf changes with time Note from Fig 6 14 that the emf has its extremum value when q = 90° or q = 270°, as the change of flux is greatest at these points
1
5284-5287
Note from Fig 6 14 that the emf has its extremum value when q = 90° or q = 270°, as the change of flux is greatest at these points The direction of the current changes periodically and therefore the current is called alternating current (ac)
1
5285-5288
6 14 that the emf has its extremum value when q = 90° or q = 270°, as the change of flux is greatest at these points The direction of the current changes periodically and therefore the current is called alternating current (ac) Since w = 2pn, Eq (6
1
5286-5289
14 that the emf has its extremum value when q = 90° or q = 270°, as the change of flux is greatest at these points The direction of the current changes periodically and therefore the current is called alternating current (ac) Since w = 2pn, Eq (6 20) can be written as e = e0sin 2p n t (6
1
5287-5290
The direction of the current changes periodically and therefore the current is called alternating current (ac) Since w = 2pn, Eq (6 20) can be written as e = e0sin 2p n t (6 21) where n is the frequency of revolution of the generator’s coil
1
5288-5291
Since w = 2pn, Eq (6 20) can be written as e = e0sin 2p n t (6 21) where n is the frequency of revolution of the generator’s coil Note that Eq
1
5289-5292
20) can be written as e = e0sin 2p n t (6 21) where n is the frequency of revolution of the generator’s coil Note that Eq (6