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1 | 4990-4993 | 6 6 (a) and (b) They provide an easier
way to understand the direction of induced currents Note that the
direction shown by
and
indicate the directions of the induced
currents |
1 | 4991-4994 | 6 (a) and (b) They provide an easier
way to understand the direction of induced currents Note that the
direction shown by
and
indicate the directions of the induced
currents A little reflection on this matter should convince us on the
correctness of Lenz’s law |
1 | 4992-4995 | They provide an easier
way to understand the direction of induced currents Note that the
direction shown by
and
indicate the directions of the induced
currents A little reflection on this matter should convince us on the
correctness of Lenz’s law Suppose that the induced current was in
the direction opposite to the one depicted in Fig |
1 | 4993-4996 | Note that the
direction shown by
and
indicate the directions of the induced
currents A little reflection on this matter should convince us on the
correctness of Lenz’s law Suppose that the induced current was in
the direction opposite to the one depicted in Fig 6 |
1 | 4994-4997 | A little reflection on this matter should convince us on the
correctness of Lenz’s law Suppose that the induced current was in
the direction opposite to the one depicted in Fig 6 6(a) |
1 | 4995-4998 | Suppose that the induced current was in
the direction opposite to the one depicted in Fig 6 6(a) In that case,
the South-pole due to the induced current will face the approaching
North-pole of the magnet |
1 | 4996-4999 | 6 6(a) In that case,
the South-pole due to the induced current will face the approaching
North-pole of the magnet The bar magnet will then be attracted
towards the coil at an ever increasing acceleration |
1 | 4997-5000 | 6(a) In that case,
the South-pole due to the induced current will face the approaching
North-pole of the magnet The bar magnet will then be attracted
towards the coil at an ever increasing acceleration A gentle push on
the magnet will initiate the process and its velocity and kinetic energy
will continuously increase without expending any energy |
1 | 4998-5001 | In that case,
the South-pole due to the induced current will face the approaching
North-pole of the magnet The bar magnet will then be attracted
towards the coil at an ever increasing acceleration A gentle push on
the magnet will initiate the process and its velocity and kinetic energy
will continuously increase without expending any energy If this can
happen, one could construct a perpetual-motion machine by a
suitable arrangement |
1 | 4999-5002 | The bar magnet will then be attracted
towards the coil at an ever increasing acceleration A gentle push on
the magnet will initiate the process and its velocity and kinetic energy
will continuously increase without expending any energy If this can
happen, one could construct a perpetual-motion machine by a
suitable arrangement This violates the law of conservation of energy
and hence can not happen |
1 | 5000-5003 | A gentle push on
the magnet will initiate the process and its velocity and kinetic energy
will continuously increase without expending any energy If this can
happen, one could construct a perpetual-motion machine by a
suitable arrangement This violates the law of conservation of energy
and hence can not happen Now consider the correct case shown in Fig |
1 | 5001-5004 | If this can
happen, one could construct a perpetual-motion machine by a
suitable arrangement This violates the law of conservation of energy
and hence can not happen Now consider the correct case shown in Fig 6 |
1 | 5002-5005 | This violates the law of conservation of energy
and hence can not happen Now consider the correct case shown in Fig 6 6(a) |
1 | 5003-5006 | Now consider the correct case shown in Fig 6 6(a) In this situation,
the bar magnet experiences a repulsive force due to the induced
current |
1 | 5004-5007 | 6 6(a) In this situation,
the bar magnet experiences a repulsive force due to the induced
current Therefore, a person has to do work in moving the magnet |
1 | 5005-5008 | 6(a) In this situation,
the bar magnet experiences a repulsive force due to the induced
current Therefore, a person has to do work in moving the magnet Where does the energy spent by the person go |
1 | 5006-5009 | In this situation,
the bar magnet experiences a repulsive force due to the induced
current Therefore, a person has to do work in moving the magnet Where does the energy spent by the person go This energy is
dissipated by Joule heating produced by the induced current |
1 | 5007-5010 | Therefore, a person has to do work in moving the magnet Where does the energy spent by the person go This energy is
dissipated by Joule heating produced by the induced current FIGURE 6 |
1 | 5008-5011 | Where does the energy spent by the person go This energy is
dissipated by Joule heating produced by the induced current FIGURE 6 6
Illustration of
Lenz’s law |
1 | 5009-5012 | This energy is
dissipated by Joule heating produced by the induced current FIGURE 6 6
Illustration of
Lenz’s law Rationalised 2023-24
Electromagnetic
Induction
161
EXAMPLE 6 |
1 | 5010-5013 | FIGURE 6 6
Illustration of
Lenz’s law Rationalised 2023-24
Electromagnetic
Induction
161
EXAMPLE 6 4
Example 6 |
1 | 5011-5014 | 6
Illustration of
Lenz’s law Rationalised 2023-24
Electromagnetic
Induction
161
EXAMPLE 6 4
Example 6 4
Figure 6 |
1 | 5012-5015 | Rationalised 2023-24
Electromagnetic
Induction
161
EXAMPLE 6 4
Example 6 4
Figure 6 7 shows planar loops of different shapes moving out of or
into a region of a magnetic field which is directed normal to the plane
of the loop away from the reader |
1 | 5013-5016 | 4
Example 6 4
Figure 6 7 shows planar loops of different shapes moving out of or
into a region of a magnetic field which is directed normal to the plane
of the loop away from the reader Determine the direction of induced
current in each loop using Lenz’s law |
1 | 5014-5017 | 4
Figure 6 7 shows planar loops of different shapes moving out of or
into a region of a magnetic field which is directed normal to the plane
of the loop away from the reader Determine the direction of induced
current in each loop using Lenz’s law FIGURE 6 |
1 | 5015-5018 | 7 shows planar loops of different shapes moving out of or
into a region of a magnetic field which is directed normal to the plane
of the loop away from the reader Determine the direction of induced
current in each loop using Lenz’s law FIGURE 6 7
Solution
(i)
The magnetic flux through the rectangular loop abcd increases,
due to the motion of the loop into the region of magnetic field, The
induced current must flow along the path bcdab so that it opposes
the increasing flux |
1 | 5016-5019 | Determine the direction of induced
current in each loop using Lenz’s law FIGURE 6 7
Solution
(i)
The magnetic flux through the rectangular loop abcd increases,
due to the motion of the loop into the region of magnetic field, The
induced current must flow along the path bcdab so that it opposes
the increasing flux (ii) Due to the outward motion, magnetic flux through the triangular
loop abc decreases due to which the induced current flows along
bacb, so as to oppose the change in flux |
1 | 5017-5020 | FIGURE 6 7
Solution
(i)
The magnetic flux through the rectangular loop abcd increases,
due to the motion of the loop into the region of magnetic field, The
induced current must flow along the path bcdab so that it opposes
the increasing flux (ii) Due to the outward motion, magnetic flux through the triangular
loop abc decreases due to which the induced current flows along
bacb, so as to oppose the change in flux (iii) As the magnetic flux decreases due to motion of the irregular
shaped loop abcd out of the region of magnetic field, the induced
current flows along cdabc, so as to oppose change in flux |
1 | 5018-5021 | 7
Solution
(i)
The magnetic flux through the rectangular loop abcd increases,
due to the motion of the loop into the region of magnetic field, The
induced current must flow along the path bcdab so that it opposes
the increasing flux (ii) Due to the outward motion, magnetic flux through the triangular
loop abc decreases due to which the induced current flows along
bacb, so as to oppose the change in flux (iii) As the magnetic flux decreases due to motion of the irregular
shaped loop abcd out of the region of magnetic field, the induced
current flows along cdabc, so as to oppose change in flux Note that there are no induced current as long as the loops are
completely inside or outside the region of the magnetic field |
1 | 5019-5022 | (ii) Due to the outward motion, magnetic flux through the triangular
loop abc decreases due to which the induced current flows along
bacb, so as to oppose the change in flux (iii) As the magnetic flux decreases due to motion of the irregular
shaped loop abcd out of the region of magnetic field, the induced
current flows along cdabc, so as to oppose change in flux Note that there are no induced current as long as the loops are
completely inside or outside the region of the magnetic field Example 6 |
1 | 5020-5023 | (iii) As the magnetic flux decreases due to motion of the irregular
shaped loop abcd out of the region of magnetic field, the induced
current flows along cdabc, so as to oppose change in flux Note that there are no induced current as long as the loops are
completely inside or outside the region of the magnetic field Example 6 5
(a) A closed loop is held stationary in the magnetic field between the
north and south poles of two permanent magnets held fixed |
1 | 5021-5024 | Note that there are no induced current as long as the loops are
completely inside or outside the region of the magnetic field Example 6 5
(a) A closed loop is held stationary in the magnetic field between the
north and south poles of two permanent magnets held fixed Can
we hope to generate current in the loop by using very strong
magnets |
1 | 5022-5025 | Example 6 5
(a) A closed loop is held stationary in the magnetic field between the
north and south poles of two permanent magnets held fixed Can
we hope to generate current in the loop by using very strong
magnets (b) A closed loop moves normal to the constant electric field between
the plates of a large capacitor |
1 | 5023-5026 | 5
(a) A closed loop is held stationary in the magnetic field between the
north and south poles of two permanent magnets held fixed Can
we hope to generate current in the loop by using very strong
magnets (b) A closed loop moves normal to the constant electric field between
the plates of a large capacitor Is a current induced in the loop
(i) when it is wholly inside the region between the capacitor plates
(ii) when it is partially outside the plates of the capacitor |
1 | 5024-5027 | Can
we hope to generate current in the loop by using very strong
magnets (b) A closed loop moves normal to the constant electric field between
the plates of a large capacitor Is a current induced in the loop
(i) when it is wholly inside the region between the capacitor plates
(ii) when it is partially outside the plates of the capacitor The
electric field is normal to the plane of the loop |
1 | 5025-5028 | (b) A closed loop moves normal to the constant electric field between
the plates of a large capacitor Is a current induced in the loop
(i) when it is wholly inside the region between the capacitor plates
(ii) when it is partially outside the plates of the capacitor The
electric field is normal to the plane of the loop (c) A rectangular loop and a circular loop are moving out of a uniform
magnetic field region (Fig |
1 | 5026-5029 | Is a current induced in the loop
(i) when it is wholly inside the region between the capacitor plates
(ii) when it is partially outside the plates of the capacitor The
electric field is normal to the plane of the loop (c) A rectangular loop and a circular loop are moving out of a uniform
magnetic field region (Fig 6 |
1 | 5027-5030 | The
electric field is normal to the plane of the loop (c) A rectangular loop and a circular loop are moving out of a uniform
magnetic field region (Fig 6 8) to a field-free region with a constant
velocity v |
1 | 5028-5031 | (c) A rectangular loop and a circular loop are moving out of a uniform
magnetic field region (Fig 6 8) to a field-free region with a constant
velocity v In which loop do you expect the induced emf to be
constant during the passage out of the field region |
1 | 5029-5032 | 6 8) to a field-free region with a constant
velocity v In which loop do you expect the induced emf to be
constant during the passage out of the field region The field is
normal to the loops |
1 | 5030-5033 | 8) to a field-free region with a constant
velocity v In which loop do you expect the induced emf to be
constant during the passage out of the field region The field is
normal to the loops EXAMPLE 6 |
1 | 5031-5034 | In which loop do you expect the induced emf to be
constant during the passage out of the field region The field is
normal to the loops EXAMPLE 6 5
Rationalised 2023-24
Physics
162
EXAMPLE 6 |
1 | 5032-5035 | The field is
normal to the loops EXAMPLE 6 5
Rationalised 2023-24
Physics
162
EXAMPLE 6 5
FIGURE 6 |
1 | 5033-5036 | EXAMPLE 6 5
Rationalised 2023-24
Physics
162
EXAMPLE 6 5
FIGURE 6 8
(d) Predict the polarity of the capacitor in the situation described by
Fig |
1 | 5034-5037 | 5
Rationalised 2023-24
Physics
162
EXAMPLE 6 5
FIGURE 6 8
(d) Predict the polarity of the capacitor in the situation described by
Fig 6 |
1 | 5035-5038 | 5
FIGURE 6 8
(d) Predict the polarity of the capacitor in the situation described by
Fig 6 9 |
1 | 5036-5039 | 8
(d) Predict the polarity of the capacitor in the situation described by
Fig 6 9 FIGURE 6 |
1 | 5037-5040 | 6 9 FIGURE 6 9
Solution
(a) No |
1 | 5038-5041 | 9 FIGURE 6 9
Solution
(a) No However strong the magnet may be, current can be induced
only by changing the magnetic flux through the loop |
1 | 5039-5042 | FIGURE 6 9
Solution
(a) No However strong the magnet may be, current can be induced
only by changing the magnetic flux through the loop (b) No current is induced in either case |
1 | 5040-5043 | 9
Solution
(a) No However strong the magnet may be, current can be induced
only by changing the magnetic flux through the loop (b) No current is induced in either case Current can not be induced
by changing the electric flux |
1 | 5041-5044 | However strong the magnet may be, current can be induced
only by changing the magnetic flux through the loop (b) No current is induced in either case Current can not be induced
by changing the electric flux (c) The induced emf is expected to be constant only in the case of the
rectangular loop |
1 | 5042-5045 | (b) No current is induced in either case Current can not be induced
by changing the electric flux (c) The induced emf is expected to be constant only in the case of the
rectangular loop In the case of circular loop, the rate of change of
area of the loop during its passage out of the field region is not
constant, hence induced emf will vary accordingly |
1 | 5043-5046 | Current can not be induced
by changing the electric flux (c) The induced emf is expected to be constant only in the case of the
rectangular loop In the case of circular loop, the rate of change of
area of the loop during its passage out of the field region is not
constant, hence induced emf will vary accordingly (d) The polarity of plate ‘A’ will be positive with respect to plate ‘B’ in
the capacitor |
1 | 5044-5047 | (c) The induced emf is expected to be constant only in the case of the
rectangular loop In the case of circular loop, the rate of change of
area of the loop during its passage out of the field region is not
constant, hence induced emf will vary accordingly (d) The polarity of plate ‘A’ will be positive with respect to plate ‘B’ in
the capacitor 6 |
1 | 5045-5048 | In the case of circular loop, the rate of change of
area of the loop during its passage out of the field region is not
constant, hence induced emf will vary accordingly (d) The polarity of plate ‘A’ will be positive with respect to plate ‘B’ in
the capacitor 6 6 MOTIONAL ELECTROMOTIVE FORCE
Let us consider a straight conductor moving in a uniform and time-
independent magnetic field |
1 | 5046-5049 | (d) The polarity of plate ‘A’ will be positive with respect to plate ‘B’ in
the capacitor 6 6 MOTIONAL ELECTROMOTIVE FORCE
Let us consider a straight conductor moving in a uniform and time-
independent magnetic field Figure 6 |
1 | 5047-5050 | 6 6 MOTIONAL ELECTROMOTIVE FORCE
Let us consider a straight conductor moving in a uniform and time-
independent magnetic field Figure 6 10 shows a rectangular conductor
PQRS in which the conductor PQ is free to move |
1 | 5048-5051 | 6 MOTIONAL ELECTROMOTIVE FORCE
Let us consider a straight conductor moving in a uniform and time-
independent magnetic field Figure 6 10 shows a rectangular conductor
PQRS in which the conductor PQ is free to move The rod PQ is moved
towards the left with a constant velocity v as
shown in the figure |
1 | 5049-5052 | Figure 6 10 shows a rectangular conductor
PQRS in which the conductor PQ is free to move The rod PQ is moved
towards the left with a constant velocity v as
shown in the figure Assume that there is no
loss of energy due to friction |
1 | 5050-5053 | 10 shows a rectangular conductor
PQRS in which the conductor PQ is free to move The rod PQ is moved
towards the left with a constant velocity v as
shown in the figure Assume that there is no
loss of energy due to friction PQRS forms a
closed circuit enclosing an area that changes
as PQ moves |
1 | 5051-5054 | The rod PQ is moved
towards the left with a constant velocity v as
shown in the figure Assume that there is no
loss of energy due to friction PQRS forms a
closed circuit enclosing an area that changes
as PQ moves It is placed in a uniform magnetic
field B which is perpendicular to the plane of
this system |
1 | 5052-5055 | Assume that there is no
loss of energy due to friction PQRS forms a
closed circuit enclosing an area that changes
as PQ moves It is placed in a uniform magnetic
field B which is perpendicular to the plane of
this system If the length RQ = x and RS = l, the
magnetic flux FB enclosed by the loop PQRS
will be
FB = Blx
Since x is changing with time, the rate of change
of flux FB will induce an emf given by:
(
)
– d
–d
d
d
B
Blx
t
t
Φ
ε =
=
=
d
–
d
x
Bl
t =Blv
(6 |
1 | 5053-5056 | PQRS forms a
closed circuit enclosing an area that changes
as PQ moves It is placed in a uniform magnetic
field B which is perpendicular to the plane of
this system If the length RQ = x and RS = l, the
magnetic flux FB enclosed by the loop PQRS
will be
FB = Blx
Since x is changing with time, the rate of change
of flux FB will induce an emf given by:
(
)
– d
–d
d
d
B
Blx
t
t
Φ
ε =
=
=
d
–
d
x
Bl
t =Blv
(6 5)
FIGURE 6 |
1 | 5054-5057 | It is placed in a uniform magnetic
field B which is perpendicular to the plane of
this system If the length RQ = x and RS = l, the
magnetic flux FB enclosed by the loop PQRS
will be
FB = Blx
Since x is changing with time, the rate of change
of flux FB will induce an emf given by:
(
)
– d
–d
d
d
B
Blx
t
t
Φ
ε =
=
=
d
–
d
x
Bl
t =Blv
(6 5)
FIGURE 6 10 The arm PQ is moved to the left
side, thus decreasing the area of the
rectangular loop |
1 | 5055-5058 | If the length RQ = x and RS = l, the
magnetic flux FB enclosed by the loop PQRS
will be
FB = Blx
Since x is changing with time, the rate of change
of flux FB will induce an emf given by:
(
)
– d
–d
d
d
B
Blx
t
t
Φ
ε =
=
=
d
–
d
x
Bl
t =Blv
(6 5)
FIGURE 6 10 The arm PQ is moved to the left
side, thus decreasing the area of the
rectangular loop This movement
induces a current I as shown |
1 | 5056-5059 | 5)
FIGURE 6 10 The arm PQ is moved to the left
side, thus decreasing the area of the
rectangular loop This movement
induces a current I as shown Rationalised 2023-24
Electromagnetic
Induction
163
where we have used dx/dt = –v which is the speed of the conductor PQ |
1 | 5057-5060 | 10 The arm PQ is moved to the left
side, thus decreasing the area of the
rectangular loop This movement
induces a current I as shown Rationalised 2023-24
Electromagnetic
Induction
163
where we have used dx/dt = –v which is the speed of the conductor PQ The induced emf Blv is called motional emf |
1 | 5058-5061 | This movement
induces a current I as shown Rationalised 2023-24
Electromagnetic
Induction
163
where we have used dx/dt = –v which is the speed of the conductor PQ The induced emf Blv is called motional emf Thus, we are able to produce
induced emf by moving a conductor instead of varying the magnetic field,
that is, by changing the magnetic flux enclosed by the circuit |
1 | 5059-5062 | Rationalised 2023-24
Electromagnetic
Induction
163
where we have used dx/dt = –v which is the speed of the conductor PQ The induced emf Blv is called motional emf Thus, we are able to produce
induced emf by moving a conductor instead of varying the magnetic field,
that is, by changing the magnetic flux enclosed by the circuit It is also possible to explain the motional emf expression in Eq |
1 | 5060-5063 | The induced emf Blv is called motional emf Thus, we are able to produce
induced emf by moving a conductor instead of varying the magnetic field,
that is, by changing the magnetic flux enclosed by the circuit It is also possible to explain the motional emf expression in Eq (6 |
1 | 5061-5064 | Thus, we are able to produce
induced emf by moving a conductor instead of varying the magnetic field,
that is, by changing the magnetic flux enclosed by the circuit It is also possible to explain the motional emf expression in Eq (6 5)
by invoking the Lorentz force acting on the free charge carriers of conductor
PQ |
1 | 5062-5065 | It is also possible to explain the motional emf expression in Eq (6 5)
by invoking the Lorentz force acting on the free charge carriers of conductor
PQ Consider any arbitrary charge q in the conductor PQ |
1 | 5063-5066 | (6 5)
by invoking the Lorentz force acting on the free charge carriers of conductor
PQ Consider any arbitrary charge q in the conductor PQ When the rod
moves with speed v, the charge will also be moving with speed v in the
magnetic field B |
1 | 5064-5067 | 5)
by invoking the Lorentz force acting on the free charge carriers of conductor
PQ Consider any arbitrary charge q in the conductor PQ When the rod
moves with speed v, the charge will also be moving with speed v in the
magnetic field B The Lorentz force on this charge is qvB in magnitude,
and its direction is towards Q |
1 | 5065-5068 | Consider any arbitrary charge q in the conductor PQ When the rod
moves with speed v, the charge will also be moving with speed v in the
magnetic field B The Lorentz force on this charge is qvB in magnitude,
and its direction is towards Q All charges experience the same force, in
magnitude and direction, irrespective of their position in the rod PQ |
1 | 5066-5069 | When the rod
moves with speed v, the charge will also be moving with speed v in the
magnetic field B The Lorentz force on this charge is qvB in magnitude,
and its direction is towards Q All charges experience the same force, in
magnitude and direction, irrespective of their position in the rod PQ The work done in moving the charge from P to Q is,
W = qvBl
Since emf is the work done per unit charge,
W
q
ε =
= Blv
This equation gives emf induced across the rod PQ and is identical
to Eq |
1 | 5067-5070 | The Lorentz force on this charge is qvB in magnitude,
and its direction is towards Q All charges experience the same force, in
magnitude and direction, irrespective of their position in the rod PQ The work done in moving the charge from P to Q is,
W = qvBl
Since emf is the work done per unit charge,
W
q
ε =
= Blv
This equation gives emf induced across the rod PQ and is identical
to Eq (6 |
1 | 5068-5071 | All charges experience the same force, in
magnitude and direction, irrespective of their position in the rod PQ The work done in moving the charge from P to Q is,
W = qvBl
Since emf is the work done per unit charge,
W
q
ε =
= Blv
This equation gives emf induced across the rod PQ and is identical
to Eq (6 5) |
1 | 5069-5072 | The work done in moving the charge from P to Q is,
W = qvBl
Since emf is the work done per unit charge,
W
q
ε =
= Blv
This equation gives emf induced across the rod PQ and is identical
to Eq (6 5) We stress that our presentation is not wholly rigorous |
1 | 5070-5073 | (6 5) We stress that our presentation is not wholly rigorous But
it does help us to understand the basis of Faraday’s law when
the conductor is moving in a uniform and time-independent
magnetic field |
1 | 5071-5074 | 5) We stress that our presentation is not wholly rigorous But
it does help us to understand the basis of Faraday’s law when
the conductor is moving in a uniform and time-independent
magnetic field On the other hand, it is not obvious how an emf is induced when a
conductor is stationary and the magnetic field is changing – a fact which
Faraday verified by numerous experiments |
1 | 5072-5075 | We stress that our presentation is not wholly rigorous But
it does help us to understand the basis of Faraday’s law when
the conductor is moving in a uniform and time-independent
magnetic field On the other hand, it is not obvious how an emf is induced when a
conductor is stationary and the magnetic field is changing – a fact which
Faraday verified by numerous experiments In the case of a stationary
conductor, the force on its charges is given by
F = q (E + v ´´´´´ B) = qE
(6 |
1 | 5073-5076 | But
it does help us to understand the basis of Faraday’s law when
the conductor is moving in a uniform and time-independent
magnetic field On the other hand, it is not obvious how an emf is induced when a
conductor is stationary and the magnetic field is changing – a fact which
Faraday verified by numerous experiments In the case of a stationary
conductor, the force on its charges is given by
F = q (E + v ´´´´´ B) = qE
(6 6)
since v = 0 |
1 | 5074-5077 | On the other hand, it is not obvious how an emf is induced when a
conductor is stationary and the magnetic field is changing – a fact which
Faraday verified by numerous experiments In the case of a stationary
conductor, the force on its charges is given by
F = q (E + v ´´´´´ B) = qE
(6 6)
since v = 0 Thus, any force on the charge must arise from the electric
field term E alone |
1 | 5075-5078 | In the case of a stationary
conductor, the force on its charges is given by
F = q (E + v ´´´´´ B) = qE
(6 6)
since v = 0 Thus, any force on the charge must arise from the electric
field term E alone Therefore, to explain the existence of induced emf or
induced current, we must assume that a time-varying magnetic field
generates an electric field |
1 | 5076-5079 | 6)
since v = 0 Thus, any force on the charge must arise from the electric
field term E alone Therefore, to explain the existence of induced emf or
induced current, we must assume that a time-varying magnetic field
generates an electric field However, we hasten to add that electric fields
produced by static electric charges have properties different from those
produced by time-varying magnetic fields |
1 | 5077-5080 | Thus, any force on the charge must arise from the electric
field term E alone Therefore, to explain the existence of induced emf or
induced current, we must assume that a time-varying magnetic field
generates an electric field However, we hasten to add that electric fields
produced by static electric charges have properties different from those
produced by time-varying magnetic fields In Chapter 4, we learnt that
charges in motion (current) can exert force/torque on a stationary magnet |
1 | 5078-5081 | Therefore, to explain the existence of induced emf or
induced current, we must assume that a time-varying magnetic field
generates an electric field However, we hasten to add that electric fields
produced by static electric charges have properties different from those
produced by time-varying magnetic fields In Chapter 4, we learnt that
charges in motion (current) can exert force/torque on a stationary magnet Conversely, a bar magnet in motion (or more generally, a changing
magnetic field) can exert a force on the stationary charge |
1 | 5079-5082 | However, we hasten to add that electric fields
produced by static electric charges have properties different from those
produced by time-varying magnetic fields In Chapter 4, we learnt that
charges in motion (current) can exert force/torque on a stationary magnet Conversely, a bar magnet in motion (or more generally, a changing
magnetic field) can exert a force on the stationary charge This is the
fundamental significance of the Faraday’s discovery |
1 | 5080-5083 | In Chapter 4, we learnt that
charges in motion (current) can exert force/torque on a stationary magnet Conversely, a bar magnet in motion (or more generally, a changing
magnetic field) can exert a force on the stationary charge This is the
fundamental significance of the Faraday’s discovery Electricity and
magnetism are related |
1 | 5081-5084 | Conversely, a bar magnet in motion (or more generally, a changing
magnetic field) can exert a force on the stationary charge This is the
fundamental significance of the Faraday’s discovery Electricity and
magnetism are related Example 6 |
1 | 5082-5085 | This is the
fundamental significance of the Faraday’s discovery Electricity and
magnetism are related Example 6 6 A metallic rod of 1 m length is rotated with a frequency
of 50 rev/s, with one end hinged at the centre and the other end at the
circumference of a circular metallic ring of radius 1 m, about an axis
passing through the centre and perpendicular to the plane of the ring
(Fig |
1 | 5083-5086 | Electricity and
magnetism are related Example 6 6 A metallic rod of 1 m length is rotated with a frequency
of 50 rev/s, with one end hinged at the centre and the other end at the
circumference of a circular metallic ring of radius 1 m, about an axis
passing through the centre and perpendicular to the plane of the ring
(Fig 6 |
1 | 5084-5087 | Example 6 6 A metallic rod of 1 m length is rotated with a frequency
of 50 rev/s, with one end hinged at the centre and the other end at the
circumference of a circular metallic ring of radius 1 m, about an axis
passing through the centre and perpendicular to the plane of the ring
(Fig 6 11) |
1 | 5085-5088 | 6 A metallic rod of 1 m length is rotated with a frequency
of 50 rev/s, with one end hinged at the centre and the other end at the
circumference of a circular metallic ring of radius 1 m, about an axis
passing through the centre and perpendicular to the plane of the ring
(Fig 6 11) A constant and uniform magnetic field of 1 T parallel to the
axis is present everywhere |
1 | 5086-5089 | 6 11) A constant and uniform magnetic field of 1 T parallel to the
axis is present everywhere What is the emf between the centre and
the metallic ring |
1 | 5087-5090 | 11) A constant and uniform magnetic field of 1 T parallel to the
axis is present everywhere What is the emf between the centre and
the metallic ring EXAMPLE 6 |
1 | 5088-5091 | A constant and uniform magnetic field of 1 T parallel to the
axis is present everywhere What is the emf between the centre and
the metallic ring EXAMPLE 6 6
Rationalised 2023-24
Physics
164
EXAMPLE 6 |
1 | 5089-5092 | What is the emf between the centre and
the metallic ring EXAMPLE 6 6
Rationalised 2023-24
Physics
164
EXAMPLE 6 6
FIGURE 6 |
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