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1 | 4890-4893 | FIGURE 6 4 A plane of
surface area A placed in a
uniform magnetic field B FIGURE 6 5 Magnetic field Bi
at the ith area element |
1 | 4891-4894 | 4 A plane of
surface area A placed in a
uniform magnetic field B FIGURE 6 5 Magnetic field Bi
at the ith area element dAi
represents area vector of the
ith area element |
1 | 4892-4895 | FIGURE 6 5 Magnetic field Bi
at the ith area element dAi
represents area vector of the
ith area element *
Note that sensitive electrical instruments in the vicinity of an electromagnet
can be damaged due to the induced emfs (and the resulting currents) when the
electromagnet is turned on or off |
1 | 4893-4896 | 5 Magnetic field Bi
at the ith area element dAi
represents area vector of the
ith area element *
Note that sensitive electrical instruments in the vicinity of an electromagnet
can be damaged due to the induced emfs (and the resulting currents) when the
electromagnet is turned on or off Rationalised 2023-24
Physics
158
EXAMPLE 6 |
1 | 4894-4897 | dAi
represents area vector of the
ith area element *
Note that sensitive electrical instruments in the vicinity of an electromagnet
can be damaged due to the induced emfs (and the resulting currents) when the
electromagnet is turned on or off Rationalised 2023-24
Physics
158
EXAMPLE 6 1
The magnitude of the induced emf in a circuit is equal
to the time rate of change of magnetic flux through the
circuit |
1 | 4895-4898 | *
Note that sensitive electrical instruments in the vicinity of an electromagnet
can be damaged due to the induced emfs (and the resulting currents) when the
electromagnet is turned on or off Rationalised 2023-24
Physics
158
EXAMPLE 6 1
The magnitude of the induced emf in a circuit is equal
to the time rate of change of magnetic flux through the
circuit Mathematically, the induced emf is given by
d
– d
ΦtB
ε =
(6 |
1 | 4896-4899 | Rationalised 2023-24
Physics
158
EXAMPLE 6 1
The magnitude of the induced emf in a circuit is equal
to the time rate of change of magnetic flux through the
circuit Mathematically, the induced emf is given by
d
– d
ΦtB
ε =
(6 3)
The negative sign indicates the direction of e and hence
the direction of current in a closed loop |
1 | 4897-4900 | 1
The magnitude of the induced emf in a circuit is equal
to the time rate of change of magnetic flux through the
circuit Mathematically, the induced emf is given by
d
– d
ΦtB
ε =
(6 3)
The negative sign indicates the direction of e and hence
the direction of current in a closed loop This will be
discussed in detail in the next section |
1 | 4898-4901 | Mathematically, the induced emf is given by
d
– d
ΦtB
ε =
(6 3)
The negative sign indicates the direction of e and hence
the direction of current in a closed loop This will be
discussed in detail in the next section In the case of a closely wound coil of N turns, change
of flux associated with each turn, is the same |
1 | 4899-4902 | 3)
The negative sign indicates the direction of e and hence
the direction of current in a closed loop This will be
discussed in detail in the next section In the case of a closely wound coil of N turns, change
of flux associated with each turn, is the same Therefore,
the expression for the total induced emf is given by
d
–
d
B
N
Φt
ε =
(6 |
1 | 4900-4903 | This will be
discussed in detail in the next section In the case of a closely wound coil of N turns, change
of flux associated with each turn, is the same Therefore,
the expression for the total induced emf is given by
d
–
d
B
N
Φt
ε =
(6 4)
The induced emf can be increased by increasing the
number of turns N of a closed coil |
1 | 4901-4904 | In the case of a closely wound coil of N turns, change
of flux associated with each turn, is the same Therefore,
the expression for the total induced emf is given by
d
–
d
B
N
Φt
ε =
(6 4)
The induced emf can be increased by increasing the
number of turns N of a closed coil From Eqs |
1 | 4902-4905 | Therefore,
the expression for the total induced emf is given by
d
–
d
B
N
Φt
ε =
(6 4)
The induced emf can be increased by increasing the
number of turns N of a closed coil From Eqs (6 |
1 | 4903-4906 | 4)
The induced emf can be increased by increasing the
number of turns N of a closed coil From Eqs (6 1) and (6 |
1 | 4904-4907 | From Eqs (6 1) and (6 2), we see that the flux can be
varied by changing any one or more of the terms B, A and
q |
1 | 4905-4908 | (6 1) and (6 2), we see that the flux can be
varied by changing any one or more of the terms B, A and
q In Experiments 6 |
1 | 4906-4909 | 1) and (6 2), we see that the flux can be
varied by changing any one or more of the terms B, A and
q In Experiments 6 1 and 6 |
1 | 4907-4910 | 2), we see that the flux can be
varied by changing any one or more of the terms B, A and
q In Experiments 6 1 and 6 2 in Section 6 |
1 | 4908-4911 | In Experiments 6 1 and 6 2 in Section 6 2, the flux is
changed by varying B |
1 | 4909-4912 | 1 and 6 2 in Section 6 2, the flux is
changed by varying B The flux can also be altered by
changing the shape of a coil (that is, by shrinking it or
stretching it) in a magnetic field, or rotating a coil in a
magnetic field such that the angle q between B and A
changes |
1 | 4910-4913 | 2 in Section 6 2, the flux is
changed by varying B The flux can also be altered by
changing the shape of a coil (that is, by shrinking it or
stretching it) in a magnetic field, or rotating a coil in a
magnetic field such that the angle q between B and A
changes In these cases too, an emf is induced in the
respective coils |
1 | 4911-4914 | 2, the flux is
changed by varying B The flux can also be altered by
changing the shape of a coil (that is, by shrinking it or
stretching it) in a magnetic field, or rotating a coil in a
magnetic field such that the angle q between B and A
changes In these cases too, an emf is induced in the
respective coils Example 6 |
1 | 4912-4915 | The flux can also be altered by
changing the shape of a coil (that is, by shrinking it or
stretching it) in a magnetic field, or rotating a coil in a
magnetic field such that the angle q between B and A
changes In these cases too, an emf is induced in the
respective coils Example 6 1 Consider Experiment 6 |
1 | 4913-4916 | In these cases too, an emf is induced in the
respective coils Example 6 1 Consider Experiment 6 2 |
1 | 4914-4917 | Example 6 1 Consider Experiment 6 2 (a) What would you do to obtain
a large deflection of the galvanometer |
1 | 4915-4918 | 1 Consider Experiment 6 2 (a) What would you do to obtain
a large deflection of the galvanometer (b) How would you demonstrate
the presence of an induced current in the absence of a galvanometer |
1 | 4916-4919 | 2 (a) What would you do to obtain
a large deflection of the galvanometer (b) How would you demonstrate
the presence of an induced current in the absence of a galvanometer Solution
(a) To obtain a large deflection, one or more of the following steps can
be taken: (i) Use a rod made of soft iron inside the coil C2, (ii) Connect
the coil to a powerful battery, and (iii) Move the arrangement rapidly
towards the test coil C1 |
1 | 4917-4920 | (a) What would you do to obtain
a large deflection of the galvanometer (b) How would you demonstrate
the presence of an induced current in the absence of a galvanometer Solution
(a) To obtain a large deflection, one or more of the following steps can
be taken: (i) Use a rod made of soft iron inside the coil C2, (ii) Connect
the coil to a powerful battery, and (iii) Move the arrangement rapidly
towards the test coil C1 (b) Replace the galvanometer by a small bulb, the kind one finds in a
small torch light |
1 | 4918-4921 | (b) How would you demonstrate
the presence of an induced current in the absence of a galvanometer Solution
(a) To obtain a large deflection, one or more of the following steps can
be taken: (i) Use a rod made of soft iron inside the coil C2, (ii) Connect
the coil to a powerful battery, and (iii) Move the arrangement rapidly
towards the test coil C1 (b) Replace the galvanometer by a small bulb, the kind one finds in a
small torch light The relative motion between the two coils will cause
the bulb to glow and thus demonstrate the presence of an induced
current |
1 | 4919-4922 | Solution
(a) To obtain a large deflection, one or more of the following steps can
be taken: (i) Use a rod made of soft iron inside the coil C2, (ii) Connect
the coil to a powerful battery, and (iii) Move the arrangement rapidly
towards the test coil C1 (b) Replace the galvanometer by a small bulb, the kind one finds in a
small torch light The relative motion between the two coils will cause
the bulb to glow and thus demonstrate the presence of an induced
current In experimental physics one must learn to innovate |
1 | 4920-4923 | (b) Replace the galvanometer by a small bulb, the kind one finds in a
small torch light The relative motion between the two coils will cause
the bulb to glow and thus demonstrate the presence of an induced
current In experimental physics one must learn to innovate Michael Faraday
who is ranked as one of the best experimentalists ever, was legendary
for his innovative skills |
1 | 4921-4924 | The relative motion between the two coils will cause
the bulb to glow and thus demonstrate the presence of an induced
current In experimental physics one must learn to innovate Michael Faraday
who is ranked as one of the best experimentalists ever, was legendary
for his innovative skills Example 6 |
1 | 4922-4925 | In experimental physics one must learn to innovate Michael Faraday
who is ranked as one of the best experimentalists ever, was legendary
for his innovative skills Example 6 2 A square loop of side 10 cm and resistance 0 |
1 | 4923-4926 | Michael Faraday
who is ranked as one of the best experimentalists ever, was legendary
for his innovative skills Example 6 2 A square loop of side 10 cm and resistance 0 5 W is
placed vertically in the east-west plane |
1 | 4924-4927 | Example 6 2 A square loop of side 10 cm and resistance 0 5 W is
placed vertically in the east-west plane A uniform magnetic field of
0 |
1 | 4925-4928 | 2 A square loop of side 10 cm and resistance 0 5 W is
placed vertically in the east-west plane A uniform magnetic field of
0 10 T is set up across the plane in the north-east direction |
1 | 4926-4929 | 5 W is
placed vertically in the east-west plane A uniform magnetic field of
0 10 T is set up across the plane in the north-east direction The
magnetic field is decreased to zero in 0 |
1 | 4927-4930 | A uniform magnetic field of
0 10 T is set up across the plane in the north-east direction The
magnetic field is decreased to zero in 0 70 s at a steady rate |
1 | 4928-4931 | 10 T is set up across the plane in the north-east direction The
magnetic field is decreased to zero in 0 70 s at a steady rate Determine
the magnitudes of induced emf and current during this time-interval |
1 | 4929-4932 | The
magnetic field is decreased to zero in 0 70 s at a steady rate Determine
the magnitudes of induced emf and current during this time-interval Michael Faraday [1791–
1867]
Faraday
made
numerous contributions to
science, viz |
1 | 4930-4933 | 70 s at a steady rate Determine
the magnitudes of induced emf and current during this time-interval Michael Faraday [1791–
1867]
Faraday
made
numerous contributions to
science, viz , the discovery
of
electromagnetic
induction, the laws of
electrolysis, benzene, and
the fact that the plane of
polarisation is rotated in an
electric field |
1 | 4931-4934 | Determine
the magnitudes of induced emf and current during this time-interval Michael Faraday [1791–
1867]
Faraday
made
numerous contributions to
science, viz , the discovery
of
electromagnetic
induction, the laws of
electrolysis, benzene, and
the fact that the plane of
polarisation is rotated in an
electric field He is also
credited with the invention
of the electric motor, the
electric generator and the
transformer |
1 | 4932-4935 | Michael Faraday [1791–
1867]
Faraday
made
numerous contributions to
science, viz , the discovery
of
electromagnetic
induction, the laws of
electrolysis, benzene, and
the fact that the plane of
polarisation is rotated in an
electric field He is also
credited with the invention
of the electric motor, the
electric generator and the
transformer He is widely
regarded as the greatest
experimental scientist of
the nineteenth century |
1 | 4933-4936 | , the discovery
of
electromagnetic
induction, the laws of
electrolysis, benzene, and
the fact that the plane of
polarisation is rotated in an
electric field He is also
credited with the invention
of the electric motor, the
electric generator and the
transformer He is widely
regarded as the greatest
experimental scientist of
the nineteenth century MICHAEL FARADAY (1791–1867)
EXAMPLE 6 |
1 | 4934-4937 | He is also
credited with the invention
of the electric motor, the
electric generator and the
transformer He is widely
regarded as the greatest
experimental scientist of
the nineteenth century MICHAEL FARADAY (1791–1867)
EXAMPLE 6 2
Rationalised 2023-24
Electromagnetic
Induction
159
EXAMPLE 6 |
1 | 4935-4938 | He is widely
regarded as the greatest
experimental scientist of
the nineteenth century MICHAEL FARADAY (1791–1867)
EXAMPLE 6 2
Rationalised 2023-24
Electromagnetic
Induction
159
EXAMPLE 6 2
Solution The angle q made by the area vector of the coil with the
magnetic field is 45° |
1 | 4936-4939 | MICHAEL FARADAY (1791–1867)
EXAMPLE 6 2
Rationalised 2023-24
Electromagnetic
Induction
159
EXAMPLE 6 2
Solution The angle q made by the area vector of the coil with the
magnetic field is 45° From Eq |
1 | 4937-4940 | 2
Rationalised 2023-24
Electromagnetic
Induction
159
EXAMPLE 6 2
Solution The angle q made by the area vector of the coil with the
magnetic field is 45° From Eq (6 |
1 | 4938-4941 | 2
Solution The angle q made by the area vector of the coil with the
magnetic field is 45° From Eq (6 1), the initial magnetic flux is
F = BA cos q
–2
0 |
1 | 4939-4942 | From Eq (6 1), the initial magnetic flux is
F = BA cos q
–2
0 1
10
Wb
2
×
=
Final flux, Fmin = 0
The change in flux is brought about in 0 |
1 | 4940-4943 | (6 1), the initial magnetic flux is
F = BA cos q
–2
0 1
10
Wb
2
×
=
Final flux, Fmin = 0
The change in flux is brought about in 0 70 s |
1 | 4941-4944 | 1), the initial magnetic flux is
F = BA cos q
–2
0 1
10
Wb
2
×
=
Final flux, Fmin = 0
The change in flux is brought about in 0 70 s From Eq |
1 | 4942-4945 | 1
10
Wb
2
×
=
Final flux, Fmin = 0
The change in flux is brought about in 0 70 s From Eq (6 |
1 | 4943-4946 | 70 s From Eq (6 3), the
magnitude of the induced emf is given by
(
– 0)
tB
t
Φ
Φ
ε
=∆
=
∆
∆
10–3
=
1 |
1 | 4944-4947 | From Eq (6 3), the
magnitude of the induced emf is given by
(
– 0)
tB
t
Φ
Φ
ε
=∆
=
∆
∆
10–3
=
1 0 mV
2
0 |
1 | 4945-4948 | (6 3), the
magnitude of the induced emf is given by
(
– 0)
tB
t
Φ
Φ
ε
=∆
=
∆
∆
10–3
=
1 0 mV
2
0 7
=
×
And the magnitude of the current is
10–3
V
2 mA
0 |
1 | 4946-4949 | 3), the
magnitude of the induced emf is given by
(
– 0)
tB
t
Φ
Φ
ε
=∆
=
∆
∆
10–3
=
1 0 mV
2
0 7
=
×
And the magnitude of the current is
10–3
V
2 mA
0 5
I
=εR
=
=
Ω
Note that the earth’s magnetic field also produces a flux through the
loop |
1 | 4947-4950 | 0 mV
2
0 7
=
×
And the magnitude of the current is
10–3
V
2 mA
0 5
I
=εR
=
=
Ω
Note that the earth’s magnetic field also produces a flux through the
loop But it is a steady field (which does not change within the time
span of the experiment) and hence does not induce any emf |
1 | 4948-4951 | 7
=
×
And the magnitude of the current is
10–3
V
2 mA
0 5
I
=εR
=
=
Ω
Note that the earth’s magnetic field also produces a flux through the
loop But it is a steady field (which does not change within the time
span of the experiment) and hence does not induce any emf Example 6 |
1 | 4949-4952 | 5
I
=εR
=
=
Ω
Note that the earth’s magnetic field also produces a flux through the
loop But it is a steady field (which does not change within the time
span of the experiment) and hence does not induce any emf Example 6 3
A circular coil of radius 10 cm, 500 turns and resistance 2 W is placed
with its plane perpendicular to the horizontal component of the earth’s
magnetic field |
1 | 4950-4953 | But it is a steady field (which does not change within the time
span of the experiment) and hence does not induce any emf Example 6 3
A circular coil of radius 10 cm, 500 turns and resistance 2 W is placed
with its plane perpendicular to the horizontal component of the earth’s
magnetic field It is rotated about its vertical diameter through 180°
in 0 |
1 | 4951-4954 | Example 6 3
A circular coil of radius 10 cm, 500 turns and resistance 2 W is placed
with its plane perpendicular to the horizontal component of the earth’s
magnetic field It is rotated about its vertical diameter through 180°
in 0 25 s |
1 | 4952-4955 | 3
A circular coil of radius 10 cm, 500 turns and resistance 2 W is placed
with its plane perpendicular to the horizontal component of the earth’s
magnetic field It is rotated about its vertical diameter through 180°
in 0 25 s Estimate the magnitudes of the emf and current induced in
the coil |
1 | 4953-4956 | It is rotated about its vertical diameter through 180°
in 0 25 s Estimate the magnitudes of the emf and current induced in
the coil Horizontal component of the earth’s magnetic field at the
place is 3 |
1 | 4954-4957 | 25 s Estimate the magnitudes of the emf and current induced in
the coil Horizontal component of the earth’s magnetic field at the
place is 3 0 × 10–5 T |
1 | 4955-4958 | Estimate the magnitudes of the emf and current induced in
the coil Horizontal component of the earth’s magnetic field at the
place is 3 0 × 10–5 T Solution
Initial flux through the coil,
FB (initial) = BA cos q
= 3 |
1 | 4956-4959 | Horizontal component of the earth’s magnetic field at the
place is 3 0 × 10–5 T Solution
Initial flux through the coil,
FB (initial) = BA cos q
= 3 0 × 10–5 × (p ×10–2) × cos 0°
= 3p × 10–7 Wb
Final flux after the rotation,
FB (final) = 3 |
1 | 4957-4960 | 0 × 10–5 T Solution
Initial flux through the coil,
FB (initial) = BA cos q
= 3 0 × 10–5 × (p ×10–2) × cos 0°
= 3p × 10–7 Wb
Final flux after the rotation,
FB (final) = 3 0 × 10–5 × (p ×10–2) × cos 180°
= –3p × 10–7 Wb
Therefore, estimated value of the induced emf is,
N
Φt
ε
∆
=
∆
= 500 × (6p × 10–7)/0 |
1 | 4958-4961 | Solution
Initial flux through the coil,
FB (initial) = BA cos q
= 3 0 × 10–5 × (p ×10–2) × cos 0°
= 3p × 10–7 Wb
Final flux after the rotation,
FB (final) = 3 0 × 10–5 × (p ×10–2) × cos 180°
= –3p × 10–7 Wb
Therefore, estimated value of the induced emf is,
N
Φt
ε
∆
=
∆
= 500 × (6p × 10–7)/0 25
= 3 |
1 | 4959-4962 | 0 × 10–5 × (p ×10–2) × cos 0°
= 3p × 10–7 Wb
Final flux after the rotation,
FB (final) = 3 0 × 10–5 × (p ×10–2) × cos 180°
= –3p × 10–7 Wb
Therefore, estimated value of the induced emf is,
N
Φt
ε
∆
=
∆
= 500 × (6p × 10–7)/0 25
= 3 8 × 10–3 V
I = e/R = 1 |
1 | 4960-4963 | 0 × 10–5 × (p ×10–2) × cos 180°
= –3p × 10–7 Wb
Therefore, estimated value of the induced emf is,
N
Φt
ε
∆
=
∆
= 500 × (6p × 10–7)/0 25
= 3 8 × 10–3 V
I = e/R = 1 9 × 10–3 A
Note that the magnitudes of e and I are the estimated values |
1 | 4961-4964 | 25
= 3 8 × 10–3 V
I = e/R = 1 9 × 10–3 A
Note that the magnitudes of e and I are the estimated values Their
instantaneous values are different and depend upon the speed of
rotation at the particular instant |
1 | 4962-4965 | 8 × 10–3 V
I = e/R = 1 9 × 10–3 A
Note that the magnitudes of e and I are the estimated values Their
instantaneous values are different and depend upon the speed of
rotation at the particular instant EXAMPLE 6 |
1 | 4963-4966 | 9 × 10–3 A
Note that the magnitudes of e and I are the estimated values Their
instantaneous values are different and depend upon the speed of
rotation at the particular instant EXAMPLE 6 3
Rationalised 2023-24
Physics
160
6 |
1 | 4964-4967 | Their
instantaneous values are different and depend upon the speed of
rotation at the particular instant EXAMPLE 6 3
Rationalised 2023-24
Physics
160
6 5 LENZ’S LAW AND CONSERVATION OF ENERGY
In 1834, German physicist Heinrich Friedrich Lenz (1804-1865) deduced
a rule, known as Lenz’s law which gives the polarity of the induced emf
in a clear and concise fashion |
1 | 4965-4968 | EXAMPLE 6 3
Rationalised 2023-24
Physics
160
6 5 LENZ’S LAW AND CONSERVATION OF ENERGY
In 1834, German physicist Heinrich Friedrich Lenz (1804-1865) deduced
a rule, known as Lenz’s law which gives the polarity of the induced emf
in a clear and concise fashion The statement of the law is:
The polarity of induced emf is such that it tends to produce a current
which opposes the change in magnetic flux that produced it |
1 | 4966-4969 | 3
Rationalised 2023-24
Physics
160
6 5 LENZ’S LAW AND CONSERVATION OF ENERGY
In 1834, German physicist Heinrich Friedrich Lenz (1804-1865) deduced
a rule, known as Lenz’s law which gives the polarity of the induced emf
in a clear and concise fashion The statement of the law is:
The polarity of induced emf is such that it tends to produce a current
which opposes the change in magnetic flux that produced it The negative sign shown in Eq |
1 | 4967-4970 | 5 LENZ’S LAW AND CONSERVATION OF ENERGY
In 1834, German physicist Heinrich Friedrich Lenz (1804-1865) deduced
a rule, known as Lenz’s law which gives the polarity of the induced emf
in a clear and concise fashion The statement of the law is:
The polarity of induced emf is such that it tends to produce a current
which opposes the change in magnetic flux that produced it The negative sign shown in Eq (6 |
1 | 4968-4971 | The statement of the law is:
The polarity of induced emf is such that it tends to produce a current
which opposes the change in magnetic flux that produced it The negative sign shown in Eq (6 3) represents this effect |
1 | 4969-4972 | The negative sign shown in Eq (6 3) represents this effect We can
understand Lenz’s law by examining Experiment 6 |
1 | 4970-4973 | (6 3) represents this effect We can
understand Lenz’s law by examining Experiment 6 1 in Section 6 |
1 | 4971-4974 | 3) represents this effect We can
understand Lenz’s law by examining Experiment 6 1 in Section 6 2 |
1 | 4972-4975 | We can
understand Lenz’s law by examining Experiment 6 1 in Section 6 2 1 |
1 | 4973-4976 | 1 in Section 6 2 1 In
Fig |
1 | 4974-4977 | 2 1 In
Fig 6 |
1 | 4975-4978 | 1 In
Fig 6 1, we see that the North-pole of a bar magnet is being pushed
towards the closed coil |
1 | 4976-4979 | In
Fig 6 1, we see that the North-pole of a bar magnet is being pushed
towards the closed coil As the North-pole of the bar magnet moves towards
the coil, the magnetic flux through the coil increases |
1 | 4977-4980 | 6 1, we see that the North-pole of a bar magnet is being pushed
towards the closed coil As the North-pole of the bar magnet moves towards
the coil, the magnetic flux through the coil increases Hence current is
induced in the coil in such a direction that it opposes the increase in flux |
1 | 4978-4981 | 1, we see that the North-pole of a bar magnet is being pushed
towards the closed coil As the North-pole of the bar magnet moves towards
the coil, the magnetic flux through the coil increases Hence current is
induced in the coil in such a direction that it opposes the increase in flux This is possible only if the current in the coil is in a counter-clockwise
direction with respect to an observer situated on the side of the magnet |
1 | 4979-4982 | As the North-pole of the bar magnet moves towards
the coil, the magnetic flux through the coil increases Hence current is
induced in the coil in such a direction that it opposes the increase in flux This is possible only if the current in the coil is in a counter-clockwise
direction with respect to an observer situated on the side of the magnet Note that magnetic moment associated with this current has North polarity
towards the North-pole of the approaching magnet |
1 | 4980-4983 | Hence current is
induced in the coil in such a direction that it opposes the increase in flux This is possible only if the current in the coil is in a counter-clockwise
direction with respect to an observer situated on the side of the magnet Note that magnetic moment associated with this current has North polarity
towards the North-pole of the approaching magnet Similarly, if the North-
pole of the magnet is being withdrawn from the coil, the magnetic flux
through the coil will decrease |
1 | 4981-4984 | This is possible only if the current in the coil is in a counter-clockwise
direction with respect to an observer situated on the side of the magnet Note that magnetic moment associated with this current has North polarity
towards the North-pole of the approaching magnet Similarly, if the North-
pole of the magnet is being withdrawn from the coil, the magnetic flux
through the coil will decrease To counter this decrease in magnetic flux,
the induced current in the coil flows in clockwise direction and its South-
pole faces the receding North-pole of the bar magnet |
1 | 4982-4985 | Note that magnetic moment associated with this current has North polarity
towards the North-pole of the approaching magnet Similarly, if the North-
pole of the magnet is being withdrawn from the coil, the magnetic flux
through the coil will decrease To counter this decrease in magnetic flux,
the induced current in the coil flows in clockwise direction and its South-
pole faces the receding North-pole of the bar magnet This would result in
an attractive force which opposes the motion of the magnet and the
corresponding decrease in flux |
1 | 4983-4986 | Similarly, if the North-
pole of the magnet is being withdrawn from the coil, the magnetic flux
through the coil will decrease To counter this decrease in magnetic flux,
the induced current in the coil flows in clockwise direction and its South-
pole faces the receding North-pole of the bar magnet This would result in
an attractive force which opposes the motion of the magnet and the
corresponding decrease in flux What will happen if an open circuit is used in place of the closed loop
in the above example |
1 | 4984-4987 | To counter this decrease in magnetic flux,
the induced current in the coil flows in clockwise direction and its South-
pole faces the receding North-pole of the bar magnet This would result in
an attractive force which opposes the motion of the magnet and the
corresponding decrease in flux What will happen if an open circuit is used in place of the closed loop
in the above example In this case too, an emf is induced across the open
ends of the circuit |
1 | 4985-4988 | This would result in
an attractive force which opposes the motion of the magnet and the
corresponding decrease in flux What will happen if an open circuit is used in place of the closed loop
in the above example In this case too, an emf is induced across the open
ends of the circuit The direction of the induced emf can be found
using Lenz’s law |
1 | 4986-4989 | What will happen if an open circuit is used in place of the closed loop
in the above example In this case too, an emf is induced across the open
ends of the circuit The direction of the induced emf can be found
using Lenz’s law Consider Figs |
1 | 4987-4990 | In this case too, an emf is induced across the open
ends of the circuit The direction of the induced emf can be found
using Lenz’s law Consider Figs 6 |
1 | 4988-4991 | The direction of the induced emf can be found
using Lenz’s law Consider Figs 6 6 (a) and (b) |
1 | 4989-4992 | Consider Figs 6 6 (a) and (b) They provide an easier
way to understand the direction of induced currents |
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