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1,500 | SELECT title FROM Movie WHERE director = "James Cameron" OR YEAR < 1980 | What are names of the movies that are either made before 1980 or directed by James Cameron? | CREATE TABLE Movie (title VARCHAR, director VARCHAR, YEAR VARCHAR) | Quais são os nomes dos filmes que são feitos antes de 1980 ou dirigidos por James Cameron? |
1,501 | SELECT T2.name FROM Rating AS T1 JOIN Reviewer AS T2 ON T1.rID = T2.rID WHERE T1.stars = 3 INTERSECT SELECT T2.name FROM Rating AS T1 JOIN Reviewer AS T2 ON T1.rID = T2.rID WHERE T1.stars = 4 | What are the names of reviewers who had rated 3 star and 4 star? | CREATE TABLE Reviewer (name VARCHAR, rID VARCHAR); CREATE TABLE Rating (rID VARCHAR, stars VARCHAR) | Quais são os nomes dos revisores que classificaram 3 estrelas e 4 estrelas? |
1,502 | SELECT T2.title FROM Rating AS T1 JOIN Movie AS T2 ON T1.mID = T2.mID WHERE T1.stars = 3 INTERSECT SELECT T2.title FROM Rating AS T1 JOIN Movie AS T2 ON T1.mID = T2.mID WHERE T1.stars = 4 | What are the names of movies that get 3 star and 4 star? | CREATE TABLE Rating (mID VARCHAR, stars VARCHAR); CREATE TABLE Movie (title VARCHAR, mID VARCHAR) | Quais são os nomes dos filmes que recebem 3 estrelas e 4 estrelas? |
1,503 | SELECT COUNT(*) FROM county_public_safety | How many counties are there? | CREATE TABLE county_public_safety (Id VARCHAR) | Quantos municípios existem? |
1,504 | SELECT Name FROM county_public_safety ORDER BY Population DESC | List the names of counties in descending order of population. | CREATE TABLE county_public_safety (Name VARCHAR, Population VARCHAR) | Listar os nomes dos condados em ordem decrescente de população. |
1,505 | SELECT DISTINCT Police_force FROM county_public_safety WHERE LOCATION <> "East" | List the distinct police forces of counties whose location is not on east side. | CREATE TABLE county_public_safety (Police_force VARCHAR, LOCATION VARCHAR) | Listar as forças policiais distintas de condados cuja localização não está no lado leste. |
1,506 | SELECT MIN(Crime_rate), MAX(Crime_rate) FROM county_public_safety | What are the minimum and maximum crime rate of counties? | CREATE TABLE county_public_safety (Crime_rate INTEGER) | Qual é a taxa de criminalidade mínima e máxima dos municípios? |
1,507 | SELECT Crime_rate FROM county_public_safety ORDER BY Police_officers | Show the crime rates of counties in ascending order of number of police officers. | CREATE TABLE county_public_safety (Crime_rate VARCHAR, Police_officers VARCHAR) | Mostrar as taxas de criminalidade dos condados em ordem crescente de número de policiais. |
1,508 | SELECT Name FROM city ORDER BY Name | What are the names of cities in ascending alphabetical order? | CREATE TABLE city (Name VARCHAR) | Quais são os nomes das cidades em ordem alfabética ascendente? |
1,509 | SELECT Hispanic FROM city WHERE Black > 10 | What are the percentage of hispanics in cities with the black percentage higher than 10? | CREATE TABLE city (Hispanic VARCHAR, Black INTEGER) | Qual é a porcentagem de hispânicos em cidades com a porcentagem de negros acima de 10? |
1,510 | SELECT Name FROM county_public_safety ORDER BY Population DESC LIMIT 1 | List the name of the county with the largest population. | CREATE TABLE county_public_safety (Name VARCHAR, Population VARCHAR) | Listar o nome do condado com a maior população. |
1,511 | SELECT Name FROM city ORDER BY White DESC LIMIT 5 | List the names of the city with the top 5 white percentages. | CREATE TABLE city (Name VARCHAR, White VARCHAR) | Listar os nomes da cidade com as 5 principais percentagens brancas. |
1,512 | SELECT T1.Name, T2.Name FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID | Show names of cities and names of counties they are in. | CREATE TABLE city (Name VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Name VARCHAR, County_ID VARCHAR) | Mostrar nomes de cidades e nomes de condados em que se encontram. |
1,513 | SELECT T1.White, T2.Crime_rate FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID | Show white percentages of cities and the crime rates of counties they are in. | CREATE TABLE city (White VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Crime_rate VARCHAR, County_ID VARCHAR) | Mostrar porcentagens brancas de cidades e as taxas de criminalidade dos condados em que estão. |
1,514 | SELECT name FROM city WHERE county_ID = (SELECT county_ID FROM county_public_safety ORDER BY Police_officers DESC LIMIT 1) | Show the name of cities in the county that has the largest number of police officers. | CREATE TABLE city (name VARCHAR, county_ID VARCHAR, Police_officers VARCHAR); CREATE TABLE county_public_safety (name VARCHAR, county_ID VARCHAR, Police_officers VARCHAR) | Mostre o nome das cidades do condado que tem o maior número de policiais. |
1,515 | SELECT COUNT(*) FROM city WHERE county_ID IN (SELECT county_ID FROM county_public_safety WHERE population > 20000) | Show the number of cities in counties that have a population more than 20000. | CREATE TABLE county_public_safety (county_ID VARCHAR, population INTEGER); CREATE TABLE city (county_ID VARCHAR, population INTEGER) | Mostrar o número de cidades em condados que têm uma população superior a 20000. |
1,516 | SELECT T2.Crime_rate FROM city AS T1 JOIN county_public_safety AS T2 ON T1.County_ID = T2.County_ID WHERE T1.White > 90 | Show the crime rate of counties with a city having white percentage more than 90. | CREATE TABLE county_public_safety (Crime_rate VARCHAR, County_ID VARCHAR); CREATE TABLE city (County_ID VARCHAR, White INTEGER) | Mostrar a taxa de criminalidade de condados com uma cidade com percentagem de brancos superior a 90. |
1,517 | SELECT Police_force, COUNT(*) FROM county_public_safety GROUP BY Police_force | Please show the police forces and the number of counties with each police force. | CREATE TABLE county_public_safety (Police_force VARCHAR) | Por favor, mostre as forças policiais e o número de condados com cada força policial. |
1,518 | SELECT LOCATION FROM county_public_safety GROUP BY LOCATION ORDER BY COUNT(*) DESC LIMIT 1 | What is the location shared by most counties? | CREATE TABLE county_public_safety (LOCATION VARCHAR) | Qual é a localização compartilhada pela maioria dos municípios? |
1,519 | SELECT Name FROM county_public_safety WHERE NOT County_ID IN (SELECT County_ID FROM city) | List the names of counties that do not have any cities. | CREATE TABLE city (Name VARCHAR, County_ID VARCHAR); CREATE TABLE county_public_safety (Name VARCHAR, County_ID VARCHAR) | Listar os nomes dos condados que não têm nenhuma cidade. |
1,520 | SELECT Police_force FROM county_public_safety WHERE LOCATION = "East" INTERSECT SELECT Police_force FROM county_public_safety WHERE LOCATION = "West" | Show the police force shared by counties with location on the east and west. | CREATE TABLE county_public_safety (Police_force VARCHAR, LOCATION VARCHAR) | Mostre a força policial compartilhada por condados com localização no leste e no oeste. |
1,521 | SELECT name FROM city WHERE county_id IN (SELECT county_id FROM county_public_safety WHERE Crime_rate < 100) | Show the names of cities in counties that have a crime rate less than 100. | CREATE TABLE county_public_safety (name VARCHAR, county_id VARCHAR, Crime_rate INTEGER); CREATE TABLE city (name VARCHAR, county_id VARCHAR, Crime_rate INTEGER) | Mostre os nomes das cidades em condados que têm uma taxa de criminalidade inferior a 100. |
1,522 | SELECT Case_burden FROM county_public_safety ORDER BY Population DESC | Show the case burden of counties in descending order of population. | CREATE TABLE county_public_safety (Case_burden VARCHAR, Population VARCHAR) | Mostrar a carga de casos dos condados em ordem decrescente de população. |
1,523 | SELECT roomName FROM Rooms WHERE basePrice < 160 AND beds = 2 AND decor = 'modern' | Find the names of all modern rooms with a base price below $160 and two beds. | CREATE TABLE Rooms (roomName VARCHAR, decor VARCHAR, basePrice VARCHAR, beds VARCHAR) | Encontre os nomes de todos os quartos modernos com um preço base abaixo de US $ 160 e duas camas. |
1,524 | SELECT roomName, RoomId FROM Rooms WHERE basePrice > 160 AND maxOccupancy > 2 | Find all the rooms that have a price higher than 160 and can accommodate more than 2 people. Report room names and ids. | CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR, basePrice VARCHAR, maxOccupancy VARCHAR) | Encontre todos os quartos que têm um preço superior a 160 e podem acomodar mais de 2 pessoas. Relatar nomes de quartos e IDs. |
1,525 | SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room ORDER BY COUNT(*) DESC LIMIT 1 | Find the most popular room in the hotel. The most popular room is the room that had seen the largest number of reservations. | CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) | Encontre o quarto mais popular do hotel. O quarto mais popular é o quarto que tinha visto o maior número de reservas. |
1,526 | SELECT kids FROM Reservations WHERE FirstName = "ROY" AND LastName = "SWEAZY" | How many kids stay in the rooms reserved by ROY SWEAZY? | CREATE TABLE Reservations (kids VARCHAR, FirstName VARCHAR, LastName VARCHAR) | Quantas crianças ficam nos quartos reservados por ROY SWEAZY? |
1,527 | SELECT COUNT(*) FROM Reservations WHERE FirstName = "ROY" AND LastName = "SWEAZY" | How many times does ROY SWEAZY has reserved a room. | CREATE TABLE Reservations (FirstName VARCHAR, LastName VARCHAR) | Quantas vezes ROY SWEAZY reservou um quarto? |
1,528 | SELECT T2.roomName, T1.Rate, T1.CheckIn, T1.CheckOut FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room ORDER BY T1.Rate DESC LIMIT 1 | Which room has the highest rate? List the room's full name, rate, check in and check out date. | CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR); CREATE TABLE Reservations (Rate VARCHAR, CheckIn VARCHAR, CheckOut VARCHAR, Room VARCHAR) | Qual quarto tem a tarifa mais alta? Liste o nome completo do quarto, a tarifa, o check-in e a data de check-out. |
1,529 | SELECT Adults FROM Reservations WHERE CheckIn = "2010-10-23" AND FirstName = "CONRAD" AND LastName = "SELBIG" | How many adults stay in the room CONRAD SELBIG checked in on Oct 23, 2010? | CREATE TABLE Reservations (Adults VARCHAR, LastName VARCHAR, CheckIn VARCHAR, FirstName VARCHAR) | Quantos adultos ficam no quarto CONRAD SELBIG check-in em 23 de out de 2010? |
1,530 | SELECT Kids FROM Reservations WHERE CheckIn = "2010-09-21" AND FirstName = "DAMIEN" AND LastName = "TRACHSEL" | How many kids stay in the room DAMIEN TRACHSEL checked in on Sep 21, 2010? | CREATE TABLE Reservations (Kids VARCHAR, LastName VARCHAR, CheckIn VARCHAR, FirstName VARCHAR) | Quantas crianças ficam no quarto DAMIEN TRACHSEL check-in em 21 de set de 2010? |
1,531 | SELECT SUM(beds) FROM Rooms WHERE bedtype = 'King' | How many king beds are there? | CREATE TABLE Rooms (beds INTEGER, bedtype VARCHAR) | Quantas camas king-size existem? |
1,532 | SELECT roomName, decor FROM Rooms WHERE bedtype = 'King' ORDER BY basePrice | List the names and decor of rooms that have a king bed. Sort the list by their price. | CREATE TABLE Rooms (roomName VARCHAR, decor VARCHAR, bedtype VARCHAR, basePrice VARCHAR) | Liste os nomes e a decoração dos quartos que têm uma cama king size. Classifique a lista pelo seu preço. |
1,533 | SELECT roomName, basePrice FROM Rooms ORDER BY basePrice LIMIT 1 | Which room has cheapest base price? List the room's name and the base price. | CREATE TABLE Rooms (roomName VARCHAR, basePrice VARCHAR) | Qual quarto tem o preço base mais barato? Liste o nome do quarto e o preço base. |
1,534 | SELECT decor FROM Rooms WHERE roomName = "Recluse and defiance" | What is the decor of room Recluse and defiance? | CREATE TABLE Rooms (decor VARCHAR, roomName VARCHAR) | Qual é a decoração do quarto Recluso e desafio? |
1,535 | SELECT bedType, AVG(basePrice) FROM Rooms GROUP BY bedType | What is the average base price of different bed type? List bed type and average base price. | CREATE TABLE Rooms (bedType VARCHAR, basePrice INTEGER) | Qual é o preço base médio do tipo de cama diferente? Lista tipo de cama e preço base médio. |
1,536 | SELECT SUM(maxOccupancy) FROM Rooms WHERE decor = 'modern' | What is the total number of people who could stay in the modern rooms in this inn? | CREATE TABLE Rooms (maxOccupancy INTEGER, decor VARCHAR) | Qual é o número total de pessoas que poderiam ficar nos quartos modernos nesta pousada? |
1,537 | SELECT T2.decor FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T2.decor ORDER BY COUNT(T2.decor) LIMIT 1 | What kind of decor has the least number of reservations? | CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (decor VARCHAR, RoomId VARCHAR) | Que tipo de decoração tem o menor número de reservas? |
1,538 | SELECT COUNT(*) FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T2.maxOccupancy = T1.Adults + T1.Kids | List how many times the number of people in the room reached the maximum occupancy of the room. The number of people include adults and kids. | CREATE TABLE Rooms (RoomId VARCHAR, maxOccupancy VARCHAR); CREATE TABLE Reservations (Room VARCHAR, Adults VARCHAR, Kids VARCHAR) | Listar quantas vezes o número de pessoas no quarto atingiu a ocupação máxima do quarto. O número de pessoas inclui adultos e crianças. |
1,539 | SELECT T1.firstname, T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T1.Rate - T2.basePrice > 0 | Find the first and last names of people who payed more than the rooms' base prices. | CREATE TABLE Reservations (firstname VARCHAR, lastname VARCHAR, Room VARCHAR, Rate VARCHAR); CREATE TABLE Rooms (RoomId VARCHAR, basePrice VARCHAR) | Encontre o primeiro e o último nome das pessoas que pagaram mais do que os preços base dos quartos. |
1,540 | SELECT COUNT(*) FROM Rooms | How many rooms are there? | CREATE TABLE Rooms (Id VARCHAR) | Quantos quartos existem? |
1,541 | SELECT COUNT(*) FROM Rooms WHERE bedType = "King" | Find the number of rooms with a king bed. | CREATE TABLE Rooms (bedType VARCHAR) | Encontre o número de quartos com uma cama king-size. |
1,542 | SELECT bedType, COUNT(*) FROM Rooms GROUP BY bedType | Find the number of rooms for each bed type. | CREATE TABLE Rooms (bedType VARCHAR) | Encontre o número de quartos para cada tipo de cama. |
1,543 | SELECT roomName FROM Rooms ORDER BY maxOccupancy DESC LIMIT 1 | Find the name of the room with the maximum occupancy. | CREATE TABLE Rooms (roomName VARCHAR, maxOccupancy VARCHAR) | Encontre o nome do quarto com a ocupação máxima. |
1,544 | SELECT RoomId, roomName FROM Rooms ORDER BY basePrice DESC LIMIT 1 | Find the id and name of the most expensive base price room. | CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR, basePrice VARCHAR) | Encontre o ID e o nome do quarto de preço base mais caro. |
1,545 | SELECT roomName, bedType FROM Rooms WHERE decor = "traditional" | List the type of bed and name of all traditional rooms. | CREATE TABLE Rooms (roomName VARCHAR, bedType VARCHAR, decor VARCHAR) | Liste o tipo de cama e o nome de todos os quartos tradicionais. |
1,546 | SELECT decor, COUNT(*) FROM Rooms WHERE bedType = "King" GROUP BY decor | Find the number of rooms with king bed for each decor type. | CREATE TABLE Rooms (decor VARCHAR, bedType VARCHAR) | Encontre o número de quartos com cama king size para cada tipo de decoração. |
1,547 | SELECT decor, AVG(basePrice), MIN(basePrice) FROM Rooms GROUP BY decor | Find the average and minimum price of the rooms in different decor. | CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER) | Encontre o preço médio e mínimo dos quartos em decoração diferente. |
1,548 | SELECT roomName FROM Rooms ORDER BY basePrice | List the name of all rooms sorted by their prices. | CREATE TABLE Rooms (roomName VARCHAR, basePrice VARCHAR) | Liste o nome de todos os quartos classificados por seus preços. |
1,549 | SELECT decor, COUNT(*) FROM Rooms WHERE basePrice > 120 GROUP BY decor | Find the number of rooms with price higher than 120 for different decor. | CREATE TABLE Rooms (decor VARCHAR, basePrice INTEGER) | Encontre o número de quartos com preço superior a 120 para decoração diferente. |
1,550 | SELECT roomName FROM Rooms WHERE bedType = "King" OR bedType = "Queen" | List the name of rooms with king or queen bed. | CREATE TABLE Rooms (roomName VARCHAR, bedType VARCHAR) | Liste o nome dos quartos com cama king ou queen-size. |
1,551 | SELECT COUNT(DISTINCT bedType) FROM Rooms | How many different types of beds are there? | CREATE TABLE Rooms (bedType VARCHAR) | Quantos tipos diferentes de camas existem? |
1,552 | SELECT RoomId, roomName FROM Rooms ORDER BY basePrice DESC LIMIT 3 | Find the name and id of the top 3 expensive rooms. | CREATE TABLE Rooms (RoomId VARCHAR, roomName VARCHAR, basePrice VARCHAR) | Encontre o nome e o ID dos 3 quartos mais caros. |
1,553 | SELECT roomName FROM Rooms WHERE basePrice > (SELECT AVG(basePrice) FROM Rooms) | Find the name of rooms whose price is higher than the average price. | CREATE TABLE Rooms (roomName VARCHAR, basePrice INTEGER) | Encontre o nome dos quartos cujo preço é maior do que o preço médio. |
1,554 | SELECT COUNT(*) FROM rooms WHERE NOT roomid IN (SELECT DISTINCT room FROM reservations) | Find the number of rooms that do not have any reservation. | CREATE TABLE rooms (roomid VARCHAR, room VARCHAR); CREATE TABLE reservations (roomid VARCHAR, room VARCHAR) | Encontre o número de quartos que não têm nenhuma reserva. |
1,555 | SELECT T2.roomName, COUNT(*), T1.Room FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room | Return the name and number of reservations made for each of the rooms. | CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) | Devolva o nome e o número de reservas feitas para cada um dos quartos. |
1,556 | SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room HAVING COUNT(*) > 60 | Find the names of rooms that have been reserved for more than 60 times. | CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) | Encontre os nomes dos quartos que foram reservados por mais de 60 vezes. |
1,557 | SELECT roomname FROM rooms WHERE baseprice BETWEEN 120 AND 150 | Find the name of rooms whose base price is between 120 and 150. | CREATE TABLE rooms (roomname VARCHAR, baseprice INTEGER) | Encontre o nome dos quartos cujo preço base é entre 120 e 150. |
1,558 | SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE firstname LIKE '%ROY%' | Find the name of rooms booked by some customers whose first name contains ROY. | CREATE TABLE Reservations (Room VARCHAR); CREATE TABLE Rooms (roomName VARCHAR, RoomId VARCHAR) | Encontre o nome dos quartos reservados por alguns clientes cujo primeiro nome contém ROY. |
1,559 | SELECT T1.cmi_details FROM Customer_Master_Index AS T1 JOIN CMI_Cross_References AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T2.source_system_code = 'Tax' | what are the details of the cmi masters that have the cross reference code 'Tax'? | CREATE TABLE CMI_Cross_References (master_customer_id VARCHAR, source_system_code VARCHAR); CREATE TABLE Customer_Master_Index (cmi_details VARCHAR, master_customer_id VARCHAR) | quais são os detalhes dos mestres cmi que têm o código de referência cruzada 'Tax'? |
1,560 | SELECT T1.cmi_cross_ref_id, T1.source_system_code FROM CMI_Cross_References AS T1 JOIN Council_Tax AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T1.cmi_cross_ref_id HAVING COUNT(*) >= 1 | What is the cmi cross reference id that is related to at least one council tax entry? List the cross reference id and source system code. | CREATE TABLE Council_Tax (cmi_cross_ref_id VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, source_system_code VARCHAR) | Qual é o id de referência cruzada cmi que está relacionado a pelo menos uma entrada de imposto do conselho? Liste o id de referência cruzada e o código do sistema de origem. |
1,561 | SELECT T2.cmi_cross_ref_id, T2.master_customer_id, COUNT(*) FROM Business_Rates AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T2.cmi_cross_ref_id | How many business rates are related to each cmi cross reference? List cross reference id, master customer id and the n | CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, master_customer_id VARCHAR); CREATE TABLE Business_Rates (cmi_cross_ref_id VARCHAR) | Quantas taxas de negócios estão relacionadas a cada referência cruzada cmi? Listar id de referência cruzada, id de cliente mestre e o n |
1,562 | SELECT T1.source_system_code, T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Benefits_Overpayments AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id ORDER BY T2.council_tax_id | What is the tax source system code related to the benefits and overpayments? List the code and the benifit id, order by benifit id. | CREATE TABLE CMI_Cross_References (source_system_code VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Benefits_Overpayments (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR) | Qual é o código do sistema de fonte fiscal relacionado com os benefícios e pagamentos em excesso? Liste o código e o id benifit, ordem por id benifit. |
1,563 | SELECT T1.source_system_code, T1.master_customer_id, T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Parking_Fines AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id | Wat is the tax source system code and master customer id of the taxes related to each parking fine id? | CREATE TABLE CMI_Cross_References (source_system_code VARCHAR, master_customer_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Parking_Fines (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR) | Wat é o código do sistema de fonte de imposto e ID mestre do cliente dos impostos relacionados a cada id multa de estacionamento? |
1,564 | SELECT T1.council_tax_id FROM Rent_Arrears AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id JOIN Customer_Master_Index AS T3 ON T3.master_customer_id = T2.master_customer_id WHERE T3.cmi_details <> 'Schmidt , Kertzmann and Lubowitz' | What are the renting arrears tax ids related to the customer master index whose detail is not 'Schmidt, Kertzmann and Lubowitz'? | CREATE TABLE Rent_Arrears (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE Customer_Master_Index (master_customer_id VARCHAR, cmi_details VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, master_customer_id VARCHAR) | Quais são os impostos de mora de aluguel relacionados ao índice mestre do cliente cujo detalhe não é 'Schmidt, Kertzmann e Lubowitz'? |
1,565 | SELECT T1.electoral_register_id FROM Electoral_Register AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id WHERE T2.source_system_code = 'Electoral' OR T2.source_system_code = 'Tax' | What are the register ids of electoral registries that have the cross reference source system code 'Electoral' or 'Tax'? | CREATE TABLE Electoral_Register (electoral_register_id VARCHAR, cmi_cross_ref_id VARCHAR); CREATE TABLE CMI_Cross_References (cmi_cross_ref_id VARCHAR, source_system_code VARCHAR) | Quais são os IDs de registro de registros eleitorais que possuem o código de sistema de referência cruzada 'Electoral' ou 'Tax'? |
1,566 | SELECT COUNT(DISTINCT source_system_code) FROM CMI_cross_references | How many different source system code for the cmi cross references are there? | CREATE TABLE CMI_cross_references (source_system_code VARCHAR) | Quantos códigos de sistema de origem diferentes para as referências cruzadas cmi existem? |
1,567 | SELECT * FROM customer_master_index ORDER BY cmi_details DESC | List all information about customer master index, and sort them by details in descending order. | CREATE TABLE customer_master_index (cmi_details VARCHAR) | Liste todas as informações sobre o índice mestre do cliente e classifique-as por detalhes em ordem decrescente. |
1,568 | SELECT council_tax_id, cmi_cross_ref_id FROM parking_fines | List the council tax ids and their related cmi cross references of all the parking fines. | CREATE TABLE parking_fines (council_tax_id VARCHAR, cmi_cross_ref_id VARCHAR) | Liste as ids fiscais do conselho e suas referências cruzadas cmi relacionadas de todas as multas de estacionamento. |
1,569 | SELECT COUNT(*) FROM rent_arrears | How many council taxes are collected for renting arrears ? | CREATE TABLE rent_arrears (Id VARCHAR) | Quantos impostos são cobrados para alugar atrasados? |
1,570 | SELECT DISTINCT T2.source_system_code FROM customer_master_index AS T1 JOIN cmi_cross_references AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T1.cmi_details = 'Gottlieb , Becker and Wyman' | What are the distinct cross reference source system codes which are related to the master customer details 'Gottlieb, Becker and Wyman'? | CREATE TABLE customer_master_index (master_customer_id VARCHAR, cmi_details VARCHAR); CREATE TABLE cmi_cross_references (source_system_code VARCHAR, master_customer_id VARCHAR) | Quais são os códigos de sistema de referência cruzada distintos que estão relacionados com os detalhes mestre do cliente 'Gottlieb, Becker e Wyman'? |
1,571 | SELECT cmi_cross_ref_id FROM cmi_cross_references EXCEPT SELECT cmi_cross_ref_id FROM parking_fines | Which cmi cross reference id is not related to any parking taxes? | CREATE TABLE parking_fines (cmi_cross_ref_id VARCHAR); CREATE TABLE cmi_cross_references (cmi_cross_ref_id VARCHAR) | Qual id de referência cruzada cmi não está relacionado a nenhum imposto de estacionamento? |
1,572 | SELECT DISTINCT source_system_code FROM cmi_cross_references WHERE source_system_code LIKE '%en%' | Which distinct source system code includes the substring 'en'? | CREATE TABLE cmi_cross_references (source_system_code VARCHAR) | Qual código-fonte distinto do sistema inclui a substring 'en'? |
1,573 | SELECT COUNT(*) FROM party | How many parties are there? | CREATE TABLE party (Id VARCHAR) | Quantos partidos existem? |
1,574 | SELECT Party_Theme FROM party ORDER BY Number_of_hosts | List the themes of parties in ascending order of number of hosts. | CREATE TABLE party (Party_Theme VARCHAR, Number_of_hosts VARCHAR) | Liste os temas das partes em ordem crescente de número de hosts. |
1,575 | SELECT Party_Theme, LOCATION FROM party | What are the themes and locations of parties? | CREATE TABLE party (Party_Theme VARCHAR, LOCATION VARCHAR) | Quais são os temas e locais das festas? |
1,576 | SELECT First_year, Last_year FROM party WHERE Party_Theme = "Spring" OR Party_Theme = "Teqnology" | Show the first year and last year of parties with theme "Spring" or "Teqnology". | CREATE TABLE party (First_year VARCHAR, Last_year VARCHAR, Party_Theme VARCHAR) | Mostre o primeiro ano e último ano de festas com o tema "Primavera" ou "Teqnologia". |
1,577 | SELECT AVG(Number_of_hosts) FROM party | What is the average number of hosts for parties? | CREATE TABLE party (Number_of_hosts INTEGER) | Qual é o número médio de anfitriões para festas? |
1,578 | SELECT LOCATION FROM party ORDER BY Number_of_hosts DESC LIMIT 1 | What is the location of the party with the most hosts? | CREATE TABLE party (LOCATION VARCHAR, Number_of_hosts VARCHAR) | Qual é a localização da festa com mais anfitriões? |
1,579 | SELECT Nationality, COUNT(*) FROM HOST GROUP BY Nationality | Show different nationalities along with the number of hosts of each nationality. | CREATE TABLE HOST (Nationality VARCHAR) | Mostrar diferentes nacionalidades, juntamente com o número de anfitriões de cada nacionalidade. |
1,580 | SELECT Nationality FROM HOST GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1 | Show the most common nationality of hosts. | CREATE TABLE HOST (Nationality VARCHAR) | Mostrar a nacionalidade mais comum dos anfitriões. |
1,581 | SELECT Nationality FROM HOST WHERE Age > 45 INTERSECT SELECT Nationality FROM HOST WHERE Age < 35 | Show the nations that have both hosts older than 45 and hosts younger than 35. | CREATE TABLE HOST (Nationality VARCHAR, Age INTEGER) | Mostre as nações que têm ambos os anfitriões com mais de 45 anos e anfitriões com menos de 35 anos. |
1,582 | SELECT T3.Party_Theme, T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID | Show the themes of parties and the names of the party hosts. | CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party_Theme VARCHAR, Party_ID VARCHAR) | Mostre os temas das festas e os nomes dos anfitriões do partido. |
1,583 | SELECT T3.Location, T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID ORDER BY T2.Age | Show the locations of parties and the names of the party hosts in ascending order of the age of the host. | CREATE TABLE party (Location VARCHAR, Party_ID VARCHAR); CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR, Age VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR) | Mostrar os locais das festas e os nomes dos anfitriões do partido em ordem crescente da idade do anfitrião. |
1,584 | SELECT T3.Location FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T2.Age > 50 | Show the locations of parties with hosts older than 50. | CREATE TABLE party (Location VARCHAR, Party_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE HOST (Host_ID VARCHAR, Age INTEGER) | Mostre os locais das festas com anfitriões com mais de 50 anos. |
1,585 | SELECT T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T3.Number_of_hosts > 20 | Show the host names for parties with number of hosts greater than 20. | CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Host_ID VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party_ID VARCHAR, Number_of_hosts INTEGER) | Mostrar os nomes dos anfitriões para as partes com número de anfitriões superior a 20. |
1,586 | SELECT Name, Nationality FROM HOST ORDER BY Age DESC LIMIT 1 | Show the name and the nationality of the oldest host. | CREATE TABLE HOST (Name VARCHAR, Nationality VARCHAR, Age VARCHAR) | Mostre o nome e a nacionalidade do anfitrião mais antigo. |
1,587 | SELECT Name FROM HOST WHERE NOT Host_ID IN (SELECT Host_ID FROM party_host) | List the names of hosts who did not serve as a host of any party in our record. | CREATE TABLE HOST (Name VARCHAR, Host_ID VARCHAR); CREATE TABLE party_host (Name VARCHAR, Host_ID VARCHAR) | Listar os nomes dos anfitriões que não serviram como um anfitrião de qualquer parte em nosso registro. |
1,588 | SELECT region_code, region_name FROM region ORDER BY region_code | Show all region code and region name sorted by the codes. | CREATE TABLE region (region_code VARCHAR, region_name VARCHAR) | Mostrar todos os códigos de região e nome de região classificados pelos códigos. |
1,589 | SELECT region_name FROM region ORDER BY region_name | List all region names in alphabetical order. | CREATE TABLE region (region_name VARCHAR) | Listar todos os nomes de região em ordem alfabética. |
1,590 | SELECT region_name FROM region WHERE region_name <> 'Denmark' | Show names for all regions except for Denmark. | CREATE TABLE region (region_name VARCHAR) | Mostrar nomes para todas as regiões, exceto para a Dinamarca. |
1,591 | SELECT COUNT(*) FROM storm WHERE Number_Deaths > 0 | How many storms had death records? | CREATE TABLE storm (Number_Deaths INTEGER) | Quantas tempestades tiveram registros de morte? |
1,592 | SELECT name, dates_active, number_deaths FROM storm WHERE number_deaths >= 1 | List name, dates active, and number of deaths for all storms with at least 1 death. | CREATE TABLE storm (name VARCHAR, dates_active VARCHAR, number_deaths VARCHAR) | Nome da lista, datas ativas e número de mortes para todas as tempestades com pelo menos 1 morte. |
1,593 | SELECT AVG(damage_millions_USD), MAX(damage_millions_USD) FROM storm WHERE max_speed > 1000 | Show the average and maximum damage for all storms with max speed higher than 1000. | CREATE TABLE storm (damage_millions_USD INTEGER, max_speed INTEGER) | Mostrar o dano médio e máximo para todas as tempestades com velocidade máxima superior a 1000. |
1,594 | SELECT SUM(number_deaths), SUM(damage_millions_USD) FROM storm WHERE max_speed > (SELECT AVG(max_speed) FROM storm) | What is the total number of deaths and damage for all storms with a max speed greater than the average? | CREATE TABLE storm (number_deaths INTEGER, damage_millions_USD INTEGER, max_speed INTEGER) | Qual é o número total de mortes e danos para todas as tempestades com uma velocidade máxima maior que a média? |
1,595 | SELECT name, damage_millions_USD FROM storm ORDER BY max_speed DESC | List name and damage for all storms in a descending order of max speed. | CREATE TABLE storm (name VARCHAR, damage_millions_USD VARCHAR, max_speed VARCHAR) | Listar nome e dano para todas as tempestades em uma ordem decrescente de velocidade máxima. |
1,596 | SELECT COUNT(DISTINCT region_id) FROM affected_region | How many regions are affected? | CREATE TABLE affected_region (region_id VARCHAR) | Quantas regiões são afetadas? |
1,597 | SELECT region_name FROM region WHERE NOT region_id IN (SELECT region_id FROM affected_region) | Show the name for regions not affected. | CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_name VARCHAR, region_id VARCHAR) | Mostrar o nome das regiões não afetadas. |
1,598 | SELECT T1.region_name, COUNT(*) FROM region AS T1 JOIN affected_region AS T2 ON T1.region_id = T2.region_id GROUP BY T1.region_id | Show the name for regions and the number of storms for each region. | CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR) | Mostre o nome das regiões e o número de tempestades para cada região. |
1,599 | SELECT T1.name, COUNT(*) FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id | List the name for storms and the number of affected regions for each storm. | CREATE TABLE affected_region (storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) | Liste o nome das tempestades e o número de regiões afetadas para cada tempestade. |
Subsets and Splits