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1,700 | SELECT COUNT(*) FROM inst | How many institutions are there? | CREATE TABLE inst (Id VARCHAR) | Quantas instituições existem? |
1,701 | SELECT COUNT(*) FROM papers | How many papers are published in total? | CREATE TABLE papers (Id VARCHAR) | Quantos artigos são publicados no total? |
1,702 | SELECT t3.title FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t1.fname = "Jeremy" AND t1.lname = "Gibbons" | What are the titles of papers published by "Jeremy Gibbons"? | CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR) | Quais são os títulos dos artigos publicados por "Jeremy Gibbons"? |
1,703 | SELECT t3.title FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t1.fname = "Aaron" AND t1.lname = "Turon" | Find all the papers published by "Aaron Turon". | CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR) | Encontre todos os artigos publicados por "Aaron Turon". |
1,704 | SELECT COUNT(*) FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t1.fname = "Atsushi" AND t1.lname = "Ohori" | How many papers have "Atsushi Ohori" published? | CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE papers (paperid VARCHAR) | Quantos artigos foram publicados em "Atsushi Ohori"? |
1,705 | SELECT DISTINCT t3.name FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t1.fname = "Matthias" AND t1.lname = "Blume" | What is the name of the institution that "Matthias Blume" belongs to? | CREATE TABLE authorship (authid VARCHAR, instid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE inst (name VARCHAR, instid VARCHAR) | Qual é o nome da instituição a que "Matthias Blume" pertence? |
1,706 | SELECT DISTINCT t3.name FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t1.fname = "Katsuhiro" AND t1.lname = "Ueno" | Which institution does "Katsuhiro Ueno" belong to? | CREATE TABLE authorship (authid VARCHAR, instid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE inst (name VARCHAR, instid VARCHAR) | A que instituição pertence "Katsuhiro Ueno"? |
1,707 | SELECT DISTINCT t1.fname, t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t3.name = "University of Oxford" | Who belong to the institution "University of Oxford"? Show the first names and last names. | CREATE TABLE authorship (authid VARCHAR, instid VARCHAR); CREATE TABLE authors (fname VARCHAR, lname VARCHAR, authid VARCHAR); CREATE TABLE inst (instid VARCHAR, name VARCHAR) | Quem pertence à instituição "Universidade de Oxford"? Mostrar os primeiros nomes e apelidos. |
1,708 | SELECT DISTINCT t1.fname, t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t3.name = "Google" | Which authors belong to the institution "Google"? Show the first names and last names. | CREATE TABLE authorship (authid VARCHAR, instid VARCHAR); CREATE TABLE authors (fname VARCHAR, lname VARCHAR, authid VARCHAR); CREATE TABLE inst (instid VARCHAR, name VARCHAR) | Quais autores pertencem à instituição "Google"? Mostrar os primeiros nomes e sobrenomes. |
1,709 | SELECT t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title = "Binders Unbound" | What are the last names of the author of the paper titled "Binders Unbound"? | CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE authors (lname VARCHAR, authid VARCHAR); CREATE TABLE papers (paperid VARCHAR, title VARCHAR) | Quais são os sobrenomes do autor do artigo intitulado "Binders Unbound"? |
1,710 | SELECT t1.fname, t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title = "Nameless , Painless" | Find the first and last name of the author(s) who wrote the paper "Nameless, Painless". | CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE papers (paperid VARCHAR, title VARCHAR); CREATE TABLE authors (fname VARCHAR, lname VARCHAR, authid VARCHAR) | Encontre o primeiro e último nome do(s) autor(es) que escreveram o artigo "Nameless, Painless". |
1,711 | SELECT DISTINCT t1.title FROM papers AS t1 JOIN authorship AS t2 ON t1.paperid = t2.paperid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t3.name = "Indiana University" | What are the papers published under the institution "Indiana University"? | CREATE TABLE inst (instid VARCHAR, name VARCHAR); CREATE TABLE authorship (paperid VARCHAR, instid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR) | Quais são os artigos publicados sob a instituição "Universidade Indiana"? |
1,712 | SELECT DISTINCT t1.title FROM papers AS t1 JOIN authorship AS t2 ON t1.paperid = t2.paperid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t3.name = "Google" | Find all the papers published by the institution "Google". | CREATE TABLE inst (instid VARCHAR, name VARCHAR); CREATE TABLE authorship (paperid VARCHAR, instid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR) | Encontre todos os artigos publicados pela instituição "Google". |
1,713 | SELECT COUNT(DISTINCT t1.title) FROM papers AS t1 JOIN authorship AS t2 ON t1.paperid = t2.paperid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t3.name = "Tokohu University" | How many papers are published by the institution "Tokohu University"? | CREATE TABLE inst (instid VARCHAR, name VARCHAR); CREATE TABLE authorship (paperid VARCHAR, instid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR) | Quantos artigos são publicados pela instituição "Tokohu University"? |
1,714 | SELECT COUNT(DISTINCT t1.title) FROM papers AS t1 JOIN authorship AS t2 ON t1.paperid = t2.paperid JOIN inst AS t3 ON t2.instid = t3.instid WHERE t3.name = "University of Pennsylvania" | Find the number of papers published by the institution "University of Pennsylvania". | CREATE TABLE inst (instid VARCHAR, name VARCHAR); CREATE TABLE authorship (paperid VARCHAR, instid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR) | Encontre o número de artigos publicados pela instituição "Universidade da Pensilvânia". |
1,715 | SELECT t3.title FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t1.fname = "Olin" AND t1.lname = "Shivers" | Find the papers which have "Olin Shivers" as an author. | CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR) | Encontre os papéis que têm "Olin Shivers" como autor. |
1,716 | SELECT t3.title FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t1.fname = "Stephanie" AND t1.lname = "Weirich" | Which papers have "Stephanie Weirich" as an author? | CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR); CREATE TABLE authors (authid VARCHAR, fname VARCHAR, lname VARCHAR) | Quais artigos têm "Stephanie Weirich" como autor? |
1,717 | SELECT t3.title FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid JOIN inst AS t4 ON t2.instid = t4.instid WHERE t4.country = "USA" AND t2.authorder = 2 AND t1.lname = "Turon" | Which paper is published in an institution in "USA" and have "Turon" as its second author? | CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR, instid VARCHAR, authorder VARCHAR); CREATE TABLE authors (authid VARCHAR, lname VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR); CREATE TABLE inst (instid VARCHAR, country VARCHAR) | Qual artigo é publicado em uma instituição em "EUA" e tem "Turon" como seu segundo autor? |
1,718 | SELECT t3.title FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid JOIN inst AS t4 ON t2.instid = t4.instid WHERE t4.country = "Japan" AND t2.authorder = 1 AND t1.lname = "Ohori" | Find the titles of papers whose first author is affiliated with an institution in the country "Japan" and has last name "Ohori"? | CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR, instid VARCHAR, authorder VARCHAR); CREATE TABLE authors (authid VARCHAR, lname VARCHAR); CREATE TABLE papers (title VARCHAR, paperid VARCHAR); CREATE TABLE inst (instid VARCHAR, country VARCHAR) | Encontre os títulos de papéis cujo primeiro autor é afiliado a uma instituição no país "África" e tem o sobrenome "Ohori"? |
1,719 | SELECT t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.fname, t1.lname ORDER BY COUNT(*) DESC LIMIT 1 | What is the last name of the author that has published the most papers? | CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE authors (lname VARCHAR, fname VARCHAR, authid VARCHAR); CREATE TABLE papers (paperid VARCHAR) | Qual é o sobrenome do autor que mais publicou artigos? |
1,720 | SELECT t1.country FROM inst AS t1 JOIN authorship AS t2 ON t1.instid = t2.instid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.country ORDER BY COUNT(*) DESC LIMIT 1 | Retrieve the country that has published the most papers. | CREATE TABLE inst (country VARCHAR, instid VARCHAR); CREATE TABLE authorship (instid VARCHAR, paperid VARCHAR); CREATE TABLE papers (paperid VARCHAR) | Recupere o país que mais publicou artigos. |
1,721 | SELECT t1.name FROM inst AS t1 JOIN authorship AS t2 ON t1.instid = t2.instid JOIN papers AS t3 ON t2.paperid = t3.paperid GROUP BY t1.name ORDER BY COUNT(*) DESC LIMIT 1 | Find the name of the organization that has published the largest number of papers. | CREATE TABLE inst (name VARCHAR, instid VARCHAR); CREATE TABLE authorship (instid VARCHAR, paperid VARCHAR); CREATE TABLE papers (paperid VARCHAR) | Encontre o nome da organização que publicou o maior número de artigos. |
1,722 | SELECT title FROM papers WHERE title LIKE "%ML%" | Find the titles of the papers that contain the word "ML". | CREATE TABLE papers (title VARCHAR) | Encontre os títulos dos papéis que contêm a palavra "ML". |
1,723 | SELECT title FROM papers WHERE title LIKE "%Database%" | Which paper's title contains the word "Database"? | CREATE TABLE papers (title VARCHAR) | Qual o título do artigo que contém a palavra "Base de Dados"? |
1,724 | SELECT t1.fname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title LIKE "%Functional%" | Find the first names of all the authors who have written a paper with title containing the word "Functional". | CREATE TABLE authors (fname VARCHAR, authid VARCHAR); CREATE TABLE papers (paperid VARCHAR, title VARCHAR); CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR) | Encontre os primeiros nomes de todos os autores que escreveram um artigo com o título contendo a palavra "Funcional". |
1,725 | SELECT t1.lname FROM authors AS t1 JOIN authorship AS t2 ON t1.authid = t2.authid JOIN papers AS t3 ON t2.paperid = t3.paperid WHERE t3.title LIKE "%Monadic%" | Find the last names of all the authors that have written a paper with title containing the word "Monadic". | CREATE TABLE authorship (authid VARCHAR, paperid VARCHAR); CREATE TABLE authors (lname VARCHAR, authid VARCHAR); CREATE TABLE papers (paperid VARCHAR, title VARCHAR) | Encontre os sobrenomes de todos os autores que escreveram um artigo com título contendo a palavra "Monádico". |
1,726 | SELECT t2.title FROM authorship AS t1 JOIN papers AS t2 ON t1.paperid = t2.paperid WHERE t1.authorder = (SELECT MAX(authorder) FROM authorship) | Retrieve the title of the paper that has the largest number of authors. | CREATE TABLE authorship (authorder INTEGER); CREATE TABLE authorship (paperid VARCHAR, authorder INTEGER); CREATE TABLE papers (title VARCHAR, paperid VARCHAR) | Recupere o título do artigo que tem o maior número de autores. |
1,727 | SELECT fname FROM authors WHERE lname = "Ueno" | What is the first name of the author with last name "Ueno"? | CREATE TABLE authors (fname VARCHAR, lname VARCHAR) | Qual é o primeiro nome do autor com o sobrenome "Ueno"? |
1,728 | SELECT lname FROM authors WHERE fname = "Amal" | Find the last name of the author with first name "Amal". | CREATE TABLE authors (lname VARCHAR, fname VARCHAR) | Encontre o último nome do autor com o nome "Amal". |
1,729 | SELECT fname FROM authors ORDER BY fname | Find the first names of all the authors ordered in alphabetical order. | CREATE TABLE authors (fname VARCHAR) | Encontre os primeiros nomes de todos os autores ordenados em ordem alfabética. |
1,730 | SELECT lname FROM authors ORDER BY lname | Retrieve all the last names of authors in alphabetical order. | CREATE TABLE authors (lname VARCHAR) | Recupere todos os sobrenomes dos autores em ordem alfabética. |
1,731 | SELECT fname, lname FROM authors ORDER BY lname | Retrieve all the first and last names of authors in the alphabetical order of last names. | CREATE TABLE authors (fname VARCHAR, lname VARCHAR) | Recupere todos os nomes e sobrenomes dos autores na ordem alfabética dos sobrenomes. |
1,732 | SELECT COUNT(DISTINCT last_name) FROM actor | How many different last names do the actors and actresses have? | CREATE TABLE actor (last_name VARCHAR) | Quantos sobrenomes diferentes os atores e atrizes têm? |
1,733 | SELECT first_name FROM actor GROUP BY first_name ORDER BY COUNT(*) DESC LIMIT 1 | What is the most popular first name of the actors? | CREATE TABLE actor (first_name VARCHAR) | Qual é o primeiro nome mais popular dos atores? |
1,734 | SELECT first_name, last_name FROM actor GROUP BY first_name, last_name ORDER BY COUNT(*) DESC LIMIT 1 | What is the most popular full name of the actors? | CREATE TABLE actor (first_name VARCHAR, last_name VARCHAR) | Qual é o nome completo mais popular dos atores? |
1,735 | SELECT district FROM address GROUP BY district HAVING COUNT(*) >= 2 | Which districts have at least two addresses? | CREATE TABLE address (district VARCHAR) | Quais distritos têm pelo menos dois endereços? |
1,736 | SELECT phone, postal_code FROM address WHERE address = '1031 Daugavpils Parkway' | What is the phone number and postal code of the address 1031 Daugavpils Parkway? | CREATE TABLE address (phone VARCHAR, postal_code VARCHAR, address VARCHAR) | Qual é o número de telefone e código postal do endereço 1031 Daugavpils Parkway? |
1,737 | SELECT T2.city, COUNT(*), T1.city_id FROM address AS T1 JOIN city AS T2 ON T1.city_id = T2.city_id GROUP BY T1.city_id ORDER BY COUNT(*) DESC LIMIT 1 | Which city has the most addresses? List the city name, number of addresses, and city id. | CREATE TABLE address (city_id VARCHAR); CREATE TABLE city (city VARCHAR, city_id VARCHAR) | Qual cidade tem mais endereços? Listar o nome da cidade, número de endereços e ID da cidade. |
1,738 | SELECT COUNT(*) FROM address WHERE district = 'California' | How many addresses are in the district of California? | CREATE TABLE address (district VARCHAR) | Quantos endereços existem no distrito da Califórnia? |
1,739 | SELECT title, film_id FROM film WHERE rental_rate = 0.99 INTERSECT SELECT T1.title, T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id GROUP BY T1.film_id HAVING COUNT(*) < 3 | Which film is rented at a fee of 0.99 and has less than 3 in the inventory? List the film title and id. | CREATE TABLE film (title VARCHAR, film_id VARCHAR, rental_rate VARCHAR); CREATE TABLE inventory (film_id VARCHAR); CREATE TABLE film (title VARCHAR, film_id VARCHAR) | Qual filme é alugado a uma taxa de 0,99 e tem menos de 3 no inventário? Listar o título do filme e ID. |
1,740 | SELECT COUNT(*) FROM city AS T1 JOIN country AS T2 ON T1.country_id = T2.country_id WHERE T2.country = 'Australia' | How many cities are in Australia? | CREATE TABLE country (country_id VARCHAR, country VARCHAR); CREATE TABLE city (country_id VARCHAR) | Quantas cidades existem na Austrália? |
1,741 | SELECT T2.country FROM city AS T1 JOIN country AS T2 ON T1.country_id = T2.country_id GROUP BY T2.country_id HAVING COUNT(*) >= 3 | Which countries have at least 3 cities? | CREATE TABLE country (country VARCHAR, country_id VARCHAR); CREATE TABLE city (country_id VARCHAR) | Quais países têm pelo menos três cidades? |
1,742 | SELECT payment_date FROM payment WHERE amount > 10 UNION SELECT T1.payment_date FROM payment AS T1 JOIN staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = 'Elsa' | Find all the payment dates for the payments with an amount larger than 10 and the payments handled by a staff person with the first name Elsa. | CREATE TABLE payment (payment_date VARCHAR, staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, first_name VARCHAR); CREATE TABLE payment (payment_date VARCHAR, amount INTEGER) | Encontre todas as datas de pagamento para os pagamentos com um valor superior a 10 e os pagamentos tratados por uma pessoa da equipe com o primeiro nome Elsa. |
1,743 | SELECT COUNT(*) FROM customer WHERE active = '1' | How many customers have an active value of 1? | CREATE TABLE customer (active VARCHAR) | Quantos clientes têm um valor ativo de 1? |
1,744 | SELECT title, rental_rate FROM film ORDER BY rental_rate DESC LIMIT 1 | Which film has the highest rental rate? And what is the rate? | CREATE TABLE film (title VARCHAR, rental_rate VARCHAR) | Qual filme tem a maior taxa de aluguel? E qual é a taxa? |
1,745 | SELECT T2.title, T2.film_id, T2.description FROM film_actor AS T1 JOIN film AS T2 ON T1.film_id = T2.film_id GROUP BY T2.film_id ORDER BY COUNT(*) DESC LIMIT 1 | Which film has the most number of actors or actresses? List the film name, film id and description. | CREATE TABLE film_actor (film_id VARCHAR); CREATE TABLE film (title VARCHAR, film_id VARCHAR, description VARCHAR) | Qual filme tem o maior número de atores ou atrizes? Listar o nome do filme, ID do filme e descrição. |
1,746 | SELECT T2.first_name, T2.last_name, T2.actor_id FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.actor_id ORDER BY COUNT(*) DESC LIMIT 1 | Which film actor (actress) starred the most films? List his or her first name, last name and actor id. | CREATE TABLE film_actor (actor_id VARCHAR); CREATE TABLE actor (first_name VARCHAR, last_name VARCHAR, actor_id VARCHAR) | Qual ator de cinema (atriz) estrelou mais filmes? Liste seu primeiro nome, sobrenome e identidade do ator. |
1,747 | SELECT T2.first_name, T2.last_name FROM film_actor AS T1 JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.actor_id HAVING COUNT(*) > 30 | Which film actors (actresses) played a role in more than 30 films? List his or her first name and last name. | CREATE TABLE film_actor (actor_id VARCHAR); CREATE TABLE actor (first_name VARCHAR, last_name VARCHAR, actor_id VARCHAR) | Quais atores de cinema (atrizes) desempenharam um papel em mais de 30 filmes? Listar seu primeiro nome e sobrenome. |
1,748 | SELECT store_id FROM inventory GROUP BY store_id ORDER BY COUNT(*) DESC LIMIT 1 | Which store owns most items? | CREATE TABLE inventory (store_id VARCHAR) | Qual loja possui a maioria dos itens? |
1,749 | SELECT SUM(amount) FROM payment | What is the total amount of all payments? | CREATE TABLE payment (amount INTEGER) | Qual é o valor total de todos os pagamentos? |
1,750 | SELECT T1.first_name, T1.last_name, T1.customer_id FROM customer AS T1 JOIN payment AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY SUM(amount) LIMIT 1 | Which customer, who has made at least one payment, has spent the least money? List his or her first name, last name, and the id. | CREATE TABLE payment (customer_id VARCHAR); CREATE TABLE customer (first_name VARCHAR, last_name VARCHAR, customer_id VARCHAR) | Qual cliente, que fez pelo menos um pagamento, gastou menos dinheiro? Liste seu primeiro nome, sobrenome e ID. |
1,751 | SELECT T1.name FROM category AS T1 JOIN film_category AS T2 ON T1.category_id = T2.category_id JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.title = 'HUNGER ROOF' | What is the genre name of the film HUNGER ROOF? | CREATE TABLE film_category (category_id VARCHAR, film_id VARCHAR); CREATE TABLE film (film_id VARCHAR, title VARCHAR); CREATE TABLE category (name VARCHAR, category_id VARCHAR) | Qual é o nome do gênero do filme HUNGER ROOF? |
1,752 | SELECT T2.name, T1.category_id, COUNT(*) FROM film_category AS T1 JOIN category AS T2 ON T1.category_id = T2.category_id GROUP BY T1.category_id | How many films are there in each category? List the genre name, genre id and the count. | CREATE TABLE film_category (category_id VARCHAR); CREATE TABLE category (name VARCHAR, category_id VARCHAR) | Quantos filmes existem em cada categoria? Liste o nome do gênero, o ID do gênero e a contagem. |
1,753 | SELECT T1.title, T1.film_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id GROUP BY T1.film_id ORDER BY COUNT(*) DESC LIMIT 1 | Which film has the most copies in the inventory? List both title and id. | CREATE TABLE film (title VARCHAR, film_id VARCHAR); CREATE TABLE inventory (film_id VARCHAR) | Qual filme tem mais cópias no inventário? Liste o título e o ID. |
1,754 | SELECT T1.title, T2.inventory_id FROM film AS T1 JOIN inventory AS T2 ON T1.film_id = T2.film_id JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id GROUP BY T2.inventory_id ORDER BY COUNT(*) DESC LIMIT 1 | What is the film title and inventory id of the item in the inventory which was rented most frequently? | CREATE TABLE film (title VARCHAR, film_id VARCHAR); CREATE TABLE inventory (inventory_id VARCHAR, film_id VARCHAR); CREATE TABLE rental (inventory_id VARCHAR) | Qual é o título do filme e o ID do inventário do item no inventário que foi alugado com mais frequência? |
1,755 | SELECT COUNT(DISTINCT language_id) FROM film | How many languages are in these films? | CREATE TABLE film (language_id VARCHAR) | Quantas línguas existem nesses filmes? |
1,756 | SELECT title FROM film WHERE rating = 'R' | What are all the movies rated as R? List the titles. | CREATE TABLE film (title VARCHAR, rating VARCHAR) | Quais são todos os filmes classificados como R? Listar os títulos. |
1,757 | SELECT T2.address FROM store AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE store_id = 1 | Where is store 1 located? | CREATE TABLE store (address_id VARCHAR); CREATE TABLE address (address VARCHAR, address_id VARCHAR) | Onde fica a loja 1? |
1,758 | SELECT T1.first_name, T1.last_name, T1.staff_id FROM staff AS T1 JOIN payment AS T2 ON T1.staff_id = T2.staff_id GROUP BY T1.staff_id ORDER BY COUNT(*) LIMIT 1 | Which staff handled least number of payments? List the full name and the id. | CREATE TABLE payment (staff_id VARCHAR); CREATE TABLE staff (first_name VARCHAR, last_name VARCHAR, staff_id VARCHAR) | Quais funcionários lidaram com o menor número de pagamentos? Liste o nome completo e o ID. |
1,759 | SELECT T2.name FROM film AS T1 JOIN LANGUAGE AS T2 ON T1.language_id = T2.language_id WHERE T1.title = 'AIRPORT POLLOCK' | Which language does the film AIRPORT POLLOCK use? List the language name. | CREATE TABLE film (language_id VARCHAR, title VARCHAR); CREATE TABLE LANGUAGE (name VARCHAR, language_id VARCHAR) | Qual idioma o filme AIRPORT POLLOCK usa? Liste o nome do idioma. |
1,760 | SELECT COUNT(*) FROM store | How many stores are there? | CREATE TABLE store (Id VARCHAR) | Quantas lojas existem? |
1,761 | SELECT COUNT(DISTINCT rating) FROM film | How many kinds of different ratings are listed? | CREATE TABLE film (rating VARCHAR) | Quantos tipos de classificações diferentes estão listadas? |
1,762 | SELECT title FROM film WHERE special_features LIKE '%Deleted Scenes%' | Which movies have 'Deleted Scenes' as a substring in the special feature? | CREATE TABLE film (title VARCHAR, special_features VARCHAR) | Quais filmes têm "Scenes Excluídas" como uma substring no recurso especial? |
1,763 | SELECT COUNT(*) FROM inventory WHERE store_id = 1 | How many items in inventory does store 1 have? | CREATE TABLE inventory (store_id VARCHAR) | Quantos itens no inventário o 1 tem? |
1,764 | SELECT payment_date FROM payment ORDER BY payment_date LIMIT 1 | When did the first payment happen? | CREATE TABLE payment (payment_date VARCHAR) | Quando aconteceu o primeiro pagamento? |
1,765 | SELECT T2.address, T1.email FROM customer AS T1 JOIN address AS T2 ON T2.address_id = T1.address_id WHERE T1.first_name = 'LINDA' | Where does the customer with the first name Linda live? And what is her email? | CREATE TABLE customer (email VARCHAR, address_id VARCHAR, first_name VARCHAR); CREATE TABLE address (address VARCHAR, address_id VARCHAR) | Onde mora o cliente com o primeiro nome Linda? E qual é o e-mail dela? |
1,766 | SELECT title FROM film WHERE LENGTH > 100 OR rating = 'PG' EXCEPT SELECT title FROM film WHERE replacement_cost > 200 | Find all the films longer than 100 minutes, or rated PG, except those who cost more than 200 for replacement. List the titles. | CREATE TABLE film (title VARCHAR, replacement_cost INTEGER, LENGTH VARCHAR, rating VARCHAR) | Encontre todos os filmes com mais de 100 minutos, ou PG avaliado, exceto aqueles que custam mais de 200 para substituição. Liste os títulos. |
1,767 | SELECT T1.first_name, T1.last_name FROM customer AS T1 JOIN rental AS T2 ON T1.customer_id = T2.customer_id ORDER BY T2.rental_date LIMIT 1 | What is the first name and the last name of the customer who made the earliest rental? | CREATE TABLE customer (first_name VARCHAR, last_name VARCHAR, customer_id VARCHAR); CREATE TABLE rental (customer_id VARCHAR, rental_date VARCHAR) | Qual é o primeiro nome e o sobrenome do cliente que fez o aluguel mais cedo? |
1,768 | SELECT DISTINCT T1.first_name, T1.last_name FROM staff AS T1 JOIN rental AS T2 ON T1.staff_id = T2.staff_id JOIN customer AS T3 ON T2.customer_id = T3.customer_id WHERE T3.first_name = 'APRIL' AND T3.last_name = 'BURNS' | What is the full name of the staff member who has rented a film to a customer with the first name April and the last name Burns? | CREATE TABLE customer (customer_id VARCHAR, first_name VARCHAR, last_name VARCHAR); CREATE TABLE rental (staff_id VARCHAR, customer_id VARCHAR); CREATE TABLE staff (first_name VARCHAR, last_name VARCHAR, staff_id VARCHAR) | Qual é o nome completo do membro da equipe que alugou um filme para um cliente com o primeiro nome Abril e o sobrenome Burns? |
1,769 | SELECT store_id FROM customer GROUP BY store_id ORDER BY COUNT(*) DESC LIMIT 1 | Which store has most the customers? | CREATE TABLE customer (store_id VARCHAR) | Qual loja tem mais clientes? |
1,770 | SELECT amount FROM payment ORDER BY amount DESC LIMIT 1 | What is the largest payment amount? | CREATE TABLE payment (amount VARCHAR) | Qual é o maior valor de pagamento? |
1,771 | SELECT T2.address FROM staff AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE T1.first_name = 'Elsa' | Where does the staff member with the first name Elsa live? | CREATE TABLE staff (address_id VARCHAR, first_name VARCHAR); CREATE TABLE address (address VARCHAR, address_id VARCHAR) | Onde mora o membro da equipe com o nome Elsa? |
1,772 | SELECT first_name FROM customer WHERE NOT customer_id IN (SELECT customer_id FROM rental WHERE rental_date > '2005-08-23 02:06:01') | What are the first names of customers who have not rented any films after '2005-08-23 02:06:01'? | CREATE TABLE customer (first_name VARCHAR, customer_id VARCHAR, rental_date INTEGER); CREATE TABLE rental (first_name VARCHAR, customer_id VARCHAR, rental_date INTEGER) | Quais são os primeiros nomes dos clientes que não alugaram nenhum filme após '2005-08-23 02:06:01'? |
1,773 | SELECT COUNT(*) FROM bank | How many bank branches are there? | CREATE TABLE bank (Id VARCHAR) | Quantas agências bancárias existem? |
1,774 | SELECT SUM(no_of_customers) FROM bank | How many customers are there? | CREATE TABLE bank (no_of_customers INTEGER) | Quantos clientes existem? |
1,775 | SELECT SUM(no_of_customers) FROM bank WHERE city = 'New York City' | Find the number of customers in the banks at New York City. | CREATE TABLE bank (no_of_customers INTEGER, city VARCHAR) | Encontre o número de clientes nos bancos da cidade de Nova York. |
1,776 | SELECT AVG(no_of_customers) FROM bank WHERE state = 'Utah' | Find the average number of customers in all banks of Utah state. | CREATE TABLE bank (no_of_customers INTEGER, state VARCHAR) | Encontre o número médio de clientes em todos os bancos do estado de Utah. |
1,777 | SELECT AVG(no_of_customers) FROM bank | Find the average number of customers cross all banks. | CREATE TABLE bank (no_of_customers INTEGER) | Encontre o número médio de clientes em todos os bancos. |
1,778 | SELECT city, state FROM bank WHERE bname = 'morningside' | Find the city and state of the bank branch named morningside. | CREATE TABLE bank (city VARCHAR, state VARCHAR, bname VARCHAR) | Encontre a cidade e o estado da agência bancária chamada Morningside. |
1,779 | SELECT bname FROM bank WHERE state = 'New York' | Find the branch names of banks in the New York state. | CREATE TABLE bank (bname VARCHAR, state VARCHAR) | Encontre os nomes de agências de bancos no estado de Nova York. |
1,780 | SELECT cust_name FROM customer ORDER BY acc_bal | List the name of all customers sorted by their account balance in ascending order. | CREATE TABLE customer (cust_name VARCHAR, acc_bal VARCHAR) | Liste o nome de todos os clientes classificados pelo saldo da conta em ordem crescente. |
1,781 | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY SUM(T2.amount) | List the name of all different customers who have some loan sorted by their total loan amount. | CREATE TABLE loan (cust_id VARCHAR, amount INTEGER); CREATE TABLE customer (cust_name VARCHAR, cust_id VARCHAR) | Liste o nome de todos os clientes diferentes que têm algum empréstimo classificado pelo valor total do empréstimo. |
1,782 | SELECT state, acc_type, credit_score FROM customer WHERE no_of_loans = 0 | Find the state, account type, and credit score of the customer whose number of loan is 0. | CREATE TABLE customer (state VARCHAR, acc_type VARCHAR, credit_score VARCHAR, no_of_loans VARCHAR) | Encontre o estado, o tipo de conta e a pontuação de crédito do cliente cujo número de empréstimo é 0. |
1,783 | SELECT COUNT(DISTINCT city) FROM bank | Find the number of different cities which banks are located at. | CREATE TABLE bank (city VARCHAR) | Encontre o número de cidades diferentes em que os bancos estão localizados. |
1,784 | SELECT COUNT(DISTINCT state) FROM bank | Find the number of different states which banks are located at. | CREATE TABLE bank (state VARCHAR) | Encontre o número de estados diferentes em que os bancos estão localizados. |
1,785 | SELECT COUNT(DISTINCT acc_type) FROM customer | How many distinct types of accounts are there? | CREATE TABLE customer (acc_type VARCHAR) | Quantos tipos distintos de contas existem? |
1,786 | SELECT cust_name, acc_bal FROM customer WHERE cust_name LIKE '%a%' | Find the name and account balance of the customer whose name includes the letter ‘a’. | CREATE TABLE customer (cust_name VARCHAR, acc_bal VARCHAR) | Encontre o nome e o saldo da conta do cliente cujo nome inclui a letra “a”. |
1,787 | SELECT SUM(acc_bal) FROM customer WHERE state = 'Utah' OR state = 'Texas' | Find the total account balance of each customer from Utah or Texas. | CREATE TABLE customer (acc_bal INTEGER, state VARCHAR) | Encontre o saldo total da conta de cada cliente de Utah ou Texas. |
1,788 | SELECT cust_name FROM customer WHERE acc_type = 'saving' INTERSECT SELECT cust_name FROM customer WHERE acc_type = 'checking' | Find the name of customers who have both saving and checking account types. | CREATE TABLE customer (cust_name VARCHAR, acc_type VARCHAR) | Encontre o nome dos clientes que têm ambos os tipos de conta de poupança e de verificação. |
1,789 | SELECT cust_name FROM customer EXCEPT SELECT cust_name FROM customer WHERE acc_type = 'saving' | Find the name of customers who do not have an saving account. | CREATE TABLE customer (cust_name VARCHAR, acc_type VARCHAR) | Encontre o nome dos clientes que não têm uma conta de salvamento. |
1,790 | SELECT cust_name FROM customer EXCEPT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE T2.loan_type = 'Mortgages' | Find the name of customers who do not have a loan with a type of Mortgages. | CREATE TABLE loan (cust_id VARCHAR, loan_type VARCHAR); CREATE TABLE customer (cust_name VARCHAR); CREATE TABLE customer (cust_name VARCHAR, cust_id VARCHAR) | Encontre o nome dos clientes que não têm um empréstimo com um tipo de hipotecas. |
1,791 | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = 'Mortgages' INTERSECT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = 'Auto' | Find the name of customers who have loans of both Mortgages and Auto. | CREATE TABLE customer (cust_name VARCHAR, cust_id VARCHAR); CREATE TABLE loan (cust_id VARCHAR) | Encontre o nome dos clientes que têm empréstimos de hipotecas e Auto. |
1,792 | SELECT cust_name FROM customer WHERE credit_score < (SELECT AVG(credit_score) FROM customer) | Find the name of customers whose credit score is below the average credit scores of all customers. | CREATE TABLE customer (cust_name VARCHAR, credit_score INTEGER) | Encontre o nome dos clientes cuja pontuação de crédito está abaixo da pontuação média de crédito de todos os clientes. |
1,793 | SELECT bname FROM bank ORDER BY no_of_customers DESC LIMIT 1 | Find the branch name of the bank that has the most number of customers. | CREATE TABLE bank (bname VARCHAR, no_of_customers VARCHAR) | Encontre o nome da filial do banco que tem o maior número de clientes. |
1,794 | SELECT cust_name FROM customer ORDER BY credit_score LIMIT 1 | Find the name of customer who has the lowest credit score. | CREATE TABLE customer (cust_name VARCHAR, credit_score VARCHAR) | Encontre o nome do cliente que tem a menor pontuação de crédito. |
1,795 | SELECT cust_name, acc_type, acc_bal FROM customer ORDER BY credit_score DESC LIMIT 1 | Find the name, account type, and account balance of the customer who has the highest credit score. | CREATE TABLE customer (cust_name VARCHAR, acc_type VARCHAR, acc_bal VARCHAR, credit_score VARCHAR) | Encontre o nome, o tipo de conta e o saldo da conta do cliente que tem a maior pontuação de crédito. |
1,796 | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY SUM(T2.amount) DESC LIMIT 1 | Find the name of customer who has the highest amount of loans. | CREATE TABLE loan (cust_id VARCHAR, amount INTEGER); CREATE TABLE customer (cust_name VARCHAR, cust_id VARCHAR) | Encontre o nome do cliente que tem a maior quantidade de empréstimos. |
1,797 | SELECT state FROM bank GROUP BY state ORDER BY SUM(no_of_customers) DESC LIMIT 1 | Find the state which has the most number of customers. | CREATE TABLE bank (state VARCHAR, no_of_customers INTEGER) | Encontre o estado que tem o maior número de clientes. |
1,798 | SELECT AVG(acc_bal), acc_type FROM customer WHERE credit_score < 50 GROUP BY acc_type | For each account type, find the average account balance of customers with credit score lower than 50. | CREATE TABLE customer (acc_type VARCHAR, acc_bal INTEGER, credit_score INTEGER) | Para cada tipo de conta, encontre o saldo médio da conta de clientes com pontuação de crédito inferior a 50. |
1,799 | SELECT SUM(acc_bal), state FROM customer WHERE credit_score > 100 GROUP BY state | For each state, find the total account balance of customers whose credit score is above 100. | CREATE TABLE customer (state VARCHAR, acc_bal INTEGER, credit_score INTEGER) | Para cada estado, encontre o saldo total da conta de clientes cuja pontuação de crédito esteja acima de 100. |
Subsets and Splits