Unnamed: 0
int64
0
78.6k
answer
stringlengths
18
557
question
stringlengths
12
244
context
stringlengths
27
489
translated_answer
stringlengths
12
992
2,300
SELECT name FROM physician WHERE POSITION LIKE '%senior%'
Find the name of physicians whose position title contains the word 'senior'.
CREATE TABLE physician (name VARCHAR, POSITION VARCHAR)
Encontre o nome dos médicos cujo título de posição contém a palavra 'sênior'.
2,301
SELECT patient FROM undergoes ORDER BY dateundergoes LIMIT 1
Find the patient who has the most recent undergoing treatment?
CREATE TABLE undergoes (patient VARCHAR, dateundergoes VARCHAR)
Encontrar o paciente que tem o mais recente em tratamento?
2,302
SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN patient AS T2 ON T1.patient = T2.SSN JOIN stay AS T3 ON T1.Stay = T3.StayID WHERE T3.room = 111
Find the names of all patients who have an undergoing treatment and are staying in room 111.
CREATE TABLE undergoes (patient VARCHAR, Stay VARCHAR); CREATE TABLE stay (StayID VARCHAR, room VARCHAR); CREATE TABLE patient (name VARCHAR, SSN VARCHAR)
Encontre os nomes de todos os pacientes que estão em tratamento e estão hospedados no quarto 111.
2,303
SELECT DISTINCT name FROM nurse ORDER BY name
List the names of all distinct nurses ordered by alphabetical order?
CREATE TABLE nurse (name VARCHAR)
Listar os nomes de todas as enfermeiras distintas ordenadas por ordem alfabética?
2,304
SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN nurse AS T2 ON T1.AssistingNurse = T2.EmployeeID
Find the names of nurses who are nursing an undergoing treatment.
CREATE TABLE undergoes (AssistingNurse VARCHAR); CREATE TABLE nurse (name VARCHAR, EmployeeID VARCHAR)
Encontre os nomes das enfermeiras que estão cuidando de um tratamento em fase de tratamento.
2,305
SELECT DISTINCT name FROM medication ORDER BY name
List the names of all distinct medications, ordered in an alphabetical order.
CREATE TABLE medication (name VARCHAR)
Liste os nomes de todos os medicamentos distintos, ordenados em ordem alfabética.
2,306
SELECT T1.name FROM physician AS T1 JOIN prescribes AS T2 ON T1.employeeid = T2.physician ORDER BY T2.dose DESC LIMIT 1
What are the names of the physician who prescribed the highest dose?
CREATE TABLE prescribes (physician VARCHAR, dose VARCHAR); CREATE TABLE physician (name VARCHAR, employeeid VARCHAR)
Quais são os nomes do médico que prescreveu a dose mais alta?
2,307
SELECT physician, department FROM affiliated_with WHERE primaryaffiliation = 1
List the physicians' employee ids together with their primary affiliation departments' ids.
CREATE TABLE affiliated_with (physician VARCHAR, department VARCHAR, primaryaffiliation VARCHAR)
Liste as identificações dos funcionários dos médicos juntamente com as identificações dos departamentos de afiliação primários.
2,308
SELECT DISTINCT T2.name FROM affiliated_with AS T1 JOIN department AS T2 ON T1.department = T2.departmentid WHERE PrimaryAffiliation = 1
List the names of departments where some physicians are primarily affiliated with.
CREATE TABLE affiliated_with (department VARCHAR); CREATE TABLE department (name VARCHAR, departmentid VARCHAR)
Listar os nomes dos departamentos onde alguns médicos são afiliados principalmente.
2,309
SELECT nurse FROM on_call WHERE blockfloor = 1 AND blockcode = 1
What nurses are on call with block floor 1 and block code 1? Tell me their names.
CREATE TABLE on_call (nurse VARCHAR, blockfloor VARCHAR, blockcode VARCHAR)
O que as enfermeiras estão de plantão com o quarteirão 1 e o código 1?
2,310
SELECT MAX(cost), MIN(cost), AVG(cost) FROM procedures
What are the highest cost, lowest cost and average cost of procedures?
CREATE TABLE procedures (cost INTEGER)
Qual é o custo mais alto, o menor custo e o custo médio dos procedimentos?
2,311
SELECT name, cost FROM procedures ORDER BY cost DESC
List the name and cost of all procedures sorted by the cost from the highest to the lowest.
CREATE TABLE procedures (name VARCHAR, cost VARCHAR)
Liste o nome e o custo de todos os procedimentos classificados pelo custo do mais alto para o mais baixo.
2,312
SELECT name FROM procedures ORDER BY cost LIMIT 3
Find the three most expensive procedures.
CREATE TABLE procedures (name VARCHAR, cost VARCHAR)
Encontre os três procedimentos mais caros.
2,313
SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T3.cost > 5000
Find the physicians who are trained in a procedure that costs more than 5000.
CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE physician (name VARCHAR, employeeid VARCHAR); CREATE TABLE procedures (code VARCHAR, cost INTEGER)
Encontre os médicos que são treinados em um procedimento que custa mais de 5000.
2,314
SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment ORDER BY T3.cost DESC LIMIT 1
Find the physician who was trained in the most expensive procedure?
CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE physician (name VARCHAR, employeeid VARCHAR); CREATE TABLE procedures (code VARCHAR, cost VARCHAR)
Encontrar o médico que foi treinado no procedimento mais caro?
2,315
SELECT AVG(T3.cost) FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
What is the average cost of procedures that physician John Wen was trained in?
CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (cost INTEGER, code VARCHAR); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR)
Qual é o custo médio dos procedimentos em que o médico John Wen foi treinado?
2,316
SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
Find the names of procedures which physician John Wen was trained in.
CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR)
Encontre os nomes dos procedimentos em que o médico John Wen foi treinado.
2,317
SELECT name FROM procedures WHERE cost > 1000 UNION SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
Find all procedures which cost more than 1000 or which physician John Wen was trained in.
CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (name VARCHAR, cost INTEGER); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR)
Encontre todos os procedimentos que custam mais de 1000 ou em qual médico John Wen foi treinado.
2,318
SELECT name FROM procedures WHERE cost > 1000 EXCEPT SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
Find the names of all procedures which cost more than 1000 but which physician John Wen was not trained in?
CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (name VARCHAR, cost INTEGER); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR)
Encontre os nomes de todos os procedimentos que custam mais de 1000, mas em qual médico John Wen não foi treinado?
2,319
SELECT name FROM procedures WHERE cost < 5000 INTERSECT SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
Find the names of all procedures such that the cost is less than 5000 and physician John Wen was trained in.
CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (name VARCHAR, cost INTEGER); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR)
Encontre os nomes de todos os procedimentos, de modo que o custo seja inferior a 5000 e o médico John Wen tenha sido treinado.
2,320
SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' INTERSECT SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Psychiatry'
Find the name of physicians who are affiliated with both Surgery and Psychiatry departments.
CREATE TABLE affiliated_with (physician VARCHAR, department VARCHAR); CREATE TABLE department (DepartmentID VARCHAR, name VARCHAR); CREATE TABLE physician (name VARCHAR, EmployeeID VARCHAR)
Encontre o nome dos médicos que são afiliados com ambos os departamentos de Cirurgia e Psiquiatria.
2,321
SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' OR T3.name = 'Psychiatry'
Find the name of physicians who are affiliated with Surgery or Psychiatry department.
CREATE TABLE affiliated_with (physician VARCHAR, department VARCHAR); CREATE TABLE department (DepartmentID VARCHAR, name VARCHAR); CREATE TABLE physician (name VARCHAR, EmployeeID VARCHAR)
Encontre o nome dos médicos que são afiliados com o departamento de Cirurgia ou Psiquiatria.
2,322
SELECT name FROM patient EXCEPT SELECT T1.name FROM patient AS T1 JOIN Prescribes AS T2 ON T2.Patient = T1.SSN JOIN Medication AS T3 ON T2.Medication = T3.Code WHERE T3.name = 'Procrastin-X'
Find the names of patients who are not using the medication of Procrastin-X.
CREATE TABLE Prescribes (Patient VARCHAR, Medication VARCHAR); CREATE TABLE Medication (Code VARCHAR, name VARCHAR); CREATE TABLE patient (name VARCHAR, SSN VARCHAR); CREATE TABLE patient (name VARCHAR)
Encontre os nomes dos pacientes que não estão usando a medicação de Procrastin-X.
2,323
SELECT COUNT(*) FROM patient WHERE NOT SSN IN (SELECT T1.patient FROM Prescribes AS T1 JOIN Medication AS T2 ON T1.Medication = T2.Code WHERE T2.name = 'Procrastin-X')
Find the number of patients who are not using the medication of Procrastin-X.
CREATE TABLE Prescribes (patient VARCHAR, Medication VARCHAR); CREATE TABLE patient (SSN VARCHAR); CREATE TABLE Medication (Code VARCHAR, name VARCHAR)
Encontre o número de pacientes que não estão usando a medicação de Procrastin-X.
2,324
SELECT COUNT(*) FROM appointment
How many appointments are there?
CREATE TABLE appointment (Id VARCHAR)
Quantos compromissos existem?
2,325
SELECT DISTINCT T1.name FROM nurse AS T1 JOIN on_call AS T2 ON T1.EmployeeID = T2.nurse
Find the names of nurses who are on call.
CREATE TABLE on_call (nurse VARCHAR); CREATE TABLE nurse (name VARCHAR, EmployeeID VARCHAR)
Encontre os nomes das enfermeiras que estão de plantão.
2,326
SELECT COUNT(*) FROM ship
How many ships are there?
CREATE TABLE ship (Id VARCHAR)
Quantos navios existem?
2,327
SELECT Name FROM ship ORDER BY Tonnage
List the name of ships in ascending order of tonnage.
CREATE TABLE ship (Name VARCHAR, Tonnage VARCHAR)
Listar o nome dos navios em ordem crescente de tonelagem.
2,328
SELECT TYPE, Nationality FROM ship
What are the type and nationality of ships?
CREATE TABLE ship (TYPE VARCHAR, Nationality VARCHAR)
Quais são o tipo e a nacionalidade dos navios?
2,329
SELECT Name FROM ship WHERE Nationality <> "United States"
List the name of ships whose nationality is not "United States".
CREATE TABLE ship (Name VARCHAR, Nationality VARCHAR)
Listar o nome dos navios cuja nacionalidade não é "Estados Unidos".
2,330
SELECT Name FROM ship WHERE Nationality = "United States" OR Nationality = "United Kingdom"
Show the name of ships whose nationality is either United States or United Kingdom.
CREATE TABLE ship (Name VARCHAR, Nationality VARCHAR)
Indicar o nome dos navios cuja nacionalidade seja Estados Unidos ou Reino Unido.
2,331
SELECT Name FROM ship ORDER BY Tonnage DESC LIMIT 1
What is the name of the ship with the largest tonnage?
CREATE TABLE ship (Name VARCHAR, Tonnage VARCHAR)
Qual é o nome do navio com a maior tonelagem?
2,332
SELECT TYPE, COUNT(*) FROM ship GROUP BY TYPE
Show different types of ships and the number of ships of each type.
CREATE TABLE ship (TYPE VARCHAR)
Mostrar diferentes tipos de navios e o número de navios de cada tipo.
2,333
SELECT TYPE FROM ship GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1
Please show the most common type of ships.
CREATE TABLE ship (TYPE VARCHAR)
Por favor, mostre o tipo mais comum de navios.
2,334
SELECT Nationality FROM ship GROUP BY Nationality HAVING COUNT(*) > 2
List the nations that have more than two ships.
CREATE TABLE ship (Nationality VARCHAR)
Listar as nações que têm mais de dois navios.
2,335
SELECT TYPE, AVG(Tonnage) FROM ship GROUP BY TYPE
Show different types of ships and the average tonnage of ships of each type.
CREATE TABLE ship (TYPE VARCHAR, Tonnage INTEGER)
Mostrar diferentes tipos de navios e a tonelagem média de navios de cada tipo.
2,336
SELECT T1.Code, T1.Fate, T2.Name FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID
Show codes and fates of missions, and names of ships involved.
CREATE TABLE mission (Code VARCHAR, Fate VARCHAR, Ship_ID VARCHAR); CREATE TABLE ship (Name VARCHAR, Ship_ID VARCHAR)
Mostre códigos e destinos de missões e nomes de navios envolvidos.
2,337
SELECT T2.Name FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID WHERE T1.Launched_Year > 1928
Show names of ships involved in a mission launched after 1928.
CREATE TABLE mission (Ship_ID VARCHAR, Launched_Year INTEGER); CREATE TABLE ship (Name VARCHAR, Ship_ID VARCHAR)
Mostre os nomes dos navios envolvidos em uma missão lançada após 1928.
2,338
SELECT DISTINCT T1.Fate FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID WHERE T2.Nationality = "United States"
Show the distinct fate of missions that involve ships with nationality "United States"
CREATE TABLE mission (Fate VARCHAR, Ship_ID VARCHAR); CREATE TABLE ship (Ship_ID VARCHAR, Nationality VARCHAR)
Mostrar o destino distinto de missões que envolvem navios com nacionalidade "Estados Unidos"
2,339
SELECT Name FROM ship WHERE NOT Ship_ID IN (SELECT Ship_ID FROM mission)
List the name of ships that are not involved in any mission
CREATE TABLE mission (Name VARCHAR, Ship_ID VARCHAR); CREATE TABLE ship (Name VARCHAR, Ship_ID VARCHAR)
Listar o nome dos navios que não estão envolvidos em qualquer missão
2,340
SELECT TYPE FROM ship WHERE Tonnage > 6000 INTERSECT SELECT TYPE FROM ship WHERE Tonnage < 4000
Show the types of ships that have both ships with tonnage larger than 6000 and ships with tonnage smaller than 4000.
CREATE TABLE ship (TYPE VARCHAR, Tonnage INTEGER)
Mostrar os tipos de navios que têm ambos os navios com tonelagem maior que 6000 e navios com tonelagem menor que 4000.
2,341
SELECT COUNT(*) FROM list
Find the number of students in total.
CREATE TABLE list (Id VARCHAR)
Determine o número de alunos no total.
2,342
SELECT lastname FROM list WHERE classroom = 111
Find the last names of students studying in room 111.
CREATE TABLE list (lastname VARCHAR, classroom VARCHAR)
Encontre os sobrenomes dos alunos que estudam no quarto 111.
2,343
SELECT firstname FROM list WHERE classroom = 108
Find the first names of students studying in room 108.
CREATE TABLE list (firstname VARCHAR, classroom VARCHAR)
Encontre os primeiros nomes dos alunos que estudam no quarto 108.
2,344
SELECT DISTINCT firstname FROM list WHERE classroom = 107
What are the first names of students studying in room 107?
CREATE TABLE list (firstname VARCHAR, classroom VARCHAR)
Quais são os primeiros nomes dos alunos que estudam na sala 107?
2,345
SELECT DISTINCT classroom, grade FROM list
For each classroom report the grade that is taught in it. Report just the classroom number and the grade number.
CREATE TABLE list (classroom VARCHAR, grade VARCHAR)
Para cada sala de aula, relate a nota que é ensinada nela. Relate apenas o número da sala de aula e o número da nota.
2,346
SELECT DISTINCT grade FROM list WHERE classroom = 103
Which grade is studying in classroom 103?
CREATE TABLE list (grade VARCHAR, classroom VARCHAR)
Qual é o curso que estuda em sala de aula 103?
2,347
SELECT DISTINCT grade FROM list WHERE classroom = 105
Find the grade studying in room 105.
CREATE TABLE list (grade VARCHAR, classroom VARCHAR)
Encontre a nota estudando na sala 105.
2,348
SELECT DISTINCT classroom FROM list WHERE grade = 4
Which classrooms are used by grade 4?
CREATE TABLE list (classroom VARCHAR, grade VARCHAR)
Quais salas de aula são usadas pelo grau 4?
2,349
SELECT DISTINCT classroom FROM list WHERE grade = 5
Which classrooms are used by grade 5?
CREATE TABLE list (classroom VARCHAR, grade VARCHAR)
Quais salas de aula são usadas pelo 5o ano?
2,350
SELECT DISTINCT T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE grade = 5
Find the last names of the teachers that teach fifth grade.
CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (lastname VARCHAR, classroom VARCHAR)
Encontre os sobrenomes dos professores que ensinam a quinta série.
2,351
SELECT DISTINCT T2.firstname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE grade = 1
Find the first names of the teachers that teach first grade.
CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (firstname VARCHAR, classroom VARCHAR)
Encontre os primeiros nomes dos professores que ensinam a primeira série.
2,352
SELECT firstname FROM teachers WHERE classroom = 110
Find the first names of all the teachers that teach in classroom 110.
CREATE TABLE teachers (firstname VARCHAR, classroom VARCHAR)
Encontre os primeiros nomes de todos os professores que ensinam na sala de aula 110.
2,353
SELECT lastname FROM teachers WHERE classroom = 109
Find the last names of teachers teaching in classroom 109.
CREATE TABLE teachers (lastname VARCHAR, classroom VARCHAR)
Encontre os sobrenomes dos professores que ensinam na sala de aula 109.
2,354
SELECT DISTINCT firstname, lastname FROM teachers
Report the first name and last name of all the teachers.
CREATE TABLE teachers (firstname VARCHAR, lastname VARCHAR)
Informe o primeiro e último nome de todos os professores.
2,355
SELECT DISTINCT firstname, lastname FROM list
Report the first name and last name of all the students.
CREATE TABLE list (firstname VARCHAR, lastname VARCHAR)
Informe o primeiro e último nome de todos os alunos.
2,356
SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "OTHA" AND T2.lastname = "MOYER"
Find all students taught by OTHA MOYER. Output the first and last names of the students.
CREATE TABLE list (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
Encontre todos os alunos ensinados por OTHA MOYER. Produza o primeiro e o último nome dos alunos.
2,357
SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "MARROTTE" AND T2.lastname = "KIRK"
Find all students taught by MARROTTE KIRK. Output first and last names of students.
CREATE TABLE list (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
Encontre todos os alunos ensinados por MARROTTE KIRK. Saída primeiro e último nome dos alunos.
2,358
SELECT T2.firstname, T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "EVELINA" AND T1.lastname = "BROMLEY"
Find the first and last name of all the teachers that teach EVELINA BROMLEY.
CREATE TABLE teachers (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
Encontre o primeiro e o último nome de todos os professores que ensinam EVELINA BROMLEY.
2,359
SELECT T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "GELL" AND T1.lastname = "TAMI"
Find the last names of all the teachers that teach GELL TAMI.
CREATE TABLE teachers (lastname VARCHAR, classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
Encontre os sobrenomes de todos os professores que ensinam GELL TAMI.
2,360
SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "LORIA" AND T2.lastname = "ONDERSMA"
How many students does LORIA ONDERSMA teaches?
CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
Quantos alunos a LORIA ONDERSMA ensina?
2,361
SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "KAWA" AND T2.lastname = "GORDON"
How many students does KAWA GORDON teaches?
CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
Quantos alunos a KAWA GORDON ensina?
2,362
SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "TARRING" AND T2.lastname = "LEIA"
Find the number of students taught by TARRING LEIA.
CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
Encontre o número de alunos ensinados pela TARRING LEIA.
2,363
SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "CHRISSY" AND T1.lastname = "NABOZNY"
How many teachers does the student named CHRISSY NABOZNY have?
CREATE TABLE teachers (classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
Quantos professores o aluno chamado CRISSY NABOZNY tem?
2,364
SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "MADLOCK" AND T1.lastname = "RAY"
How many teachers does the student named MADLOCK RAY have?
CREATE TABLE teachers (classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
Quantos professores o aluno chamado MADLOCK RAY tem?
2,365
SELECT DISTINCT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.grade = 1 EXCEPT SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "OTHA" AND T2.lastname = "MOYER"
Find all first-grade students who are NOT taught by OTHA MOYER. Report their first and last names.
CREATE TABLE list (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR, grade VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
Encontre todos os alunos da primeira série que NO são ensinados por OTHA MOYER. Relate seu primeiro e último nome.
2,366
SELECT DISTINCT T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.grade = 3 AND T2.firstname <> "COVIN" AND T2.lastname <> "JEROME"
Find the last names of the students in third grade that are not taught by COVIN JEROME.
CREATE TABLE list (lastname VARCHAR, classroom VARCHAR, grade VARCHAR); CREATE TABLE teachers (classroom VARCHAR, lastname VARCHAR, firstname VARCHAR)
Encontre os sobrenomes dos alunos do terceiro ano que não são ensinados pelo COVIN JEROME.
2,367
SELECT grade, COUNT(DISTINCT classroom), COUNT(*) FROM list GROUP BY grade
For each grade, report the grade, the number of classrooms in which it is taught and the total number of students in the grade.
CREATE TABLE list (grade VARCHAR, classroom VARCHAR)
Para cada nota, relate a nota, o número de salas de aula em que ela é ensinada e o número total de alunos na nota.
2,368
SELECT classroom, COUNT(DISTINCT grade) FROM list GROUP BY classroom
For each classroom, report the classroom number and the number of grades using it.
CREATE TABLE list (classroom VARCHAR, grade VARCHAR)
Para cada sala de aula, informe o número da sala de aula e o número de notas que a utilizam.
2,369
SELECT classroom FROM list GROUP BY classroom ORDER BY COUNT(*) DESC LIMIT 1
Which classroom has the most students?
CREATE TABLE list (classroom VARCHAR)
Qual sala de aula tem mais alunos?
2,370
SELECT classroom, COUNT(*) FROM list GROUP BY classroom
Report the number of students in each classroom.
CREATE TABLE list (classroom VARCHAR)
Informe o número de alunos em cada sala de aula.
2,371
SELECT classroom, COUNT(*) FROM list WHERE grade = "0" GROUP BY classroom
For each grade 0 classroom, report the total number of students.
CREATE TABLE list (classroom VARCHAR, grade VARCHAR)
Para cada sala de aula de grau 0, relate o número total de alunos.
2,372
SELECT classroom, COUNT(*) FROM list WHERE grade = "4" GROUP BY classroom
Report the total number of students for each fourth-grade classroom.
CREATE TABLE list (classroom VARCHAR, grade VARCHAR)
Relate o número total de alunos para cada sala de aula da quarta série.
2,373
SELECT T2.firstname, T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom GROUP BY T2.firstname, T2.lastname ORDER BY COUNT(*) DESC LIMIT 1
Find the name of the teacher who teaches the largest number of students.
CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR)
Encontre o nome do professor que ensina o maior número de alunos.
2,374
SELECT COUNT(*), classroom FROM list GROUP BY classroom
Find the number of students in one classroom.
CREATE TABLE list (classroom VARCHAR)
Encontre o número de alunos em uma sala de aula.
2,375
SELECT COUNT(*) FROM company WHERE Headquarters = 'USA'
How many companies are headquartered in the US?
CREATE TABLE company (Headquarters VARCHAR)
Quantas empresas estão sediadas nos EUA?
2,376
SELECT Name FROM company ORDER BY Sales_in_Billion
List the names of companies by ascending number of sales.
CREATE TABLE company (Name VARCHAR, Sales_in_Billion VARCHAR)
Liste os nomes das empresas por número crescente de vendas.
2,377
SELECT Headquarters, Industry FROM company
What are the headquarters and industries of all companies?
CREATE TABLE company (Headquarters VARCHAR, Industry VARCHAR)
Quais são as sedes e indústrias de todas as empresas?
2,378
SELECT Name FROM company WHERE Industry = "Banking" OR Industry = "Retailing"
Show the names of companies in the banking or retailing industry?
CREATE TABLE company (Name VARCHAR, Industry VARCHAR)
Mostrar os nomes das empresas do setor bancário ou de varejo?
2,379
SELECT MAX(Market_Value_in_Billion), MIN(Market_Value_in_Billion) FROM company
What is the maximum and minimum market value of companies?
CREATE TABLE company (Market_Value_in_Billion INTEGER)
Qual é o valor máximo e mínimo de mercado das empresas?
2,380
SELECT Headquarters FROM company ORDER BY Sales_in_Billion DESC LIMIT 1
What is the headquarter of the company with the largest sales?
CREATE TABLE company (Headquarters VARCHAR, Sales_in_Billion VARCHAR)
Qual é a sede da empresa com as maiores vendas?
2,381
SELECT Headquarters, COUNT(*) FROM company GROUP BY Headquarters
Show the different headquarters and number of companies at each headquarter.
CREATE TABLE company (Headquarters VARCHAR)
Mostrar as diferentes sedes e número de empresas em cada sede.
2,382
SELECT Headquarters FROM company GROUP BY Headquarters ORDER BY COUNT(*) DESC LIMIT 1
Show the most common headquarter for companies.
CREATE TABLE company (Headquarters VARCHAR)
Mostre a sede mais comum para as empresas.
2,383
SELECT Headquarters FROM company GROUP BY Headquarters HAVING COUNT(*) >= 2
Show the headquarters that have at least two companies.
CREATE TABLE company (Headquarters VARCHAR)
Mostre a sede que tem pelo menos duas empresas.
2,384
SELECT Headquarters FROM company WHERE Industry = "Banking" INTERSECT SELECT Headquarters FROM company WHERE Industry = "Oil and gas"
Show the headquarters that have both companies in banking industry and companies in oil and gas industry.
CREATE TABLE company (Headquarters VARCHAR, Industry VARCHAR)
Mostre a sede que tem empresas do setor bancário e empresas do setor de petróleo e gás.
2,385
SELECT T3.Name, T2.Name FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID
Show the names of companies and of employees.
CREATE TABLE company (Name VARCHAR, Company_ID VARCHAR); CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR)
Mostre os nomes das empresas e dos funcionários.
2,386
SELECT T3.Name, T2.Name FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID ORDER BY T1.Year_working
Show names of companies and that of employees in descending order of number of years working for that employee.
CREATE TABLE people (Name VARCHAR, People_ID VARCHAR); CREATE TABLE company (Name VARCHAR, Company_ID VARCHAR); CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR, Year_working VARCHAR)
Mostrar nomes de empresas e de funcionários em ordem decrescente de anos trabalhando para esse funcionário.
2,387
SELECT T2.Name FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID WHERE T3.Sales_in_Billion > 200
Show the names of employees that work for companies with sales bigger than 200.
CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR); CREATE TABLE company (Company_ID VARCHAR, Sales_in_Billion INTEGER); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR)
Mostre os nomes dos funcionários que trabalham para empresas com vendas maiores que 200.
2,388
SELECT T3.Name, COUNT(*) FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID GROUP BY T3.Name
Show the names of companies and the number of employees they have
CREATE TABLE company (Name VARCHAR, Company_ID VARCHAR); CREATE TABLE people (People_ID VARCHAR); CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR)
Mostre os nomes das empresas e o número de funcionários que elas têm
2,389
SELECT Name FROM people WHERE NOT People_ID IN (SELECT People_ID FROM employment)
List the names of people that are not employed by any company
CREATE TABLE employment (Name VARCHAR, People_ID VARCHAR); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR)
Listar os nomes das pessoas que não são empregadas por nenhuma empresa
2,390
SELECT name FROM company WHERE Sales_in_Billion > 200 ORDER BY Sales_in_Billion, Profits_in_Billion DESC
list the names of the companies with more than 200 sales in the descending order of sales and profits.
CREATE TABLE company (name VARCHAR, Sales_in_Billion INTEGER, Profits_in_Billion VARCHAR)
listar os nomes das empresas com mais de 200 vendas na ordem decrescente de vendas e lucros.
2,391
SELECT COUNT(*) FROM film
How many film are there?
CREATE TABLE film (Id VARCHAR)
Quantos filmes existem?
2,392
SELECT DISTINCT Director FROM film
List the distinct director of all films.
CREATE TABLE film (Director VARCHAR)
Liste o diretor distinto de todos os filmes.
2,393
SELECT AVG(Gross_in_dollar) FROM film
What is the average ticket sales gross in dollars of films?
CREATE TABLE film (Gross_in_dollar INTEGER)
Qual é a média de vendas de ingressos brutos em dólares de filmes?
2,394
SELECT Low_Estimate, High_Estimate FROM film_market_estimation
What are the low and high estimates of film markets?
CREATE TABLE film_market_estimation (Low_Estimate VARCHAR, High_Estimate VARCHAR)
Quais são as estimativas baixas e altas dos mercados de filmes?
2,395
SELECT TYPE FROM film_market_estimation WHERE YEAR = 1995
What are the types of film market estimations in year 1995?
CREATE TABLE film_market_estimation (TYPE VARCHAR, YEAR VARCHAR)
Quais são os tipos de estimativas de mercado de filmes no ano de 1995?
2,396
SELECT MAX(Number_cities), MIN(Number_cities) FROM market
What are the maximum and minimum number of cities in all markets.
CREATE TABLE market (Number_cities INTEGER)
Qual é o número máximo e mínimo de cidades em todos os mercados?
2,397
SELECT COUNT(*) FROM market WHERE Number_cities < 300
How many markets have number of cities smaller than 300?
CREATE TABLE market (Number_cities INTEGER)
Quantos mercados têm número de cidades menores que 300?
2,398
SELECT Country FROM market ORDER BY Country
List all countries of markets in ascending alphabetical order.
CREATE TABLE market (Country VARCHAR)
Listar todos os países de mercado em ordem alfabética ascendente.
2,399
SELECT Country FROM market ORDER BY Number_cities DESC
List all countries of markets in descending order of number of cities.
CREATE TABLE market (Country VARCHAR, Number_cities VARCHAR)
Listar todos os países de mercados em ordem decrescente de número de cidades.