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205,794 |
help-1
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1771e47d2cf14a07a0555a62f2e30bda
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420244167726333953
|
James Anderson
|
01/31/2022 06:00:56
|
Use the formula
| 0 | 1 |
nan
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nan
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nan
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nan
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205,794 |
help-1
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1771e47d2cf14a07a0555a62f2e30bda
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478187837771087873
|
Devon Taylor
|
01/31/2022 06:00:57
|
i c
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,051 |
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205,794 |
help-1
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1771e47d2cf14a07a0555a62f2e30bda
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478187837771087873
|
Devon Taylor
|
01/31/2022 06:01:01
|
aight
| 1 | 0 |
933745748619702322
|
Lynn Adams
|
Lynn Adams
|
False
| 5,448,052 |
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205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
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478187837771087873
|
Devon Taylor
|
01/31/2022 06:01:13
|
can u teach with a different formula. one with rational roots
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nan
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nan
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nan
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nan
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205,794 |
help-1
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1771e47d2cf14a07a0555a62f2e30bda
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478187837771087873
|
Devon Taylor
|
01/31/2022 06:01:25
|
splitting the middle term
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,054 |
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205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
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420244167726333953
|
James Anderson
|
01/31/2022 06:01:26
|
Or you could use completing the square
| 0 | 1 |
nan
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nan
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nan
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nan
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205,794 |
help-1
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1771e47d2cf14a07a0555a62f2e30bda
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478187837771087873
|
Devon Taylor
|
01/31/2022 06:01:34
|
not sure how to do this either
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,056 |
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205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
|
420244167726333953
|
James Anderson
|
01/31/2022 06:01:45
|
Search up a video
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,057 |
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205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
|
478187837771087873
|
Devon Taylor
|
01/31/2022 06:01:51
|
fair enough
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,058 |
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205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
|
420244167726333953
|
James Anderson
|
01/31/2022 06:01:55
|
Sure
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,059 |
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205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
|
478187837771087873
|
Devon Taylor
|
01/31/2022 06:02:07
|
thanks
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,060 |
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205,794 |
help-1
|
1771e47d2cf14a07a0555a62f2e30bda
|
478187837771087873
|
Devon Taylor
|
01/31/2022 06:17:29
|
.close
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,061 |
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205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 06:53:02
|
On Archimedes' tombstone there is said to have been an inscription sol showed a cylinder with an inscribed sphere. 2500 years ago Archimedes found that the ratio between the globe volume and the cylinder volume was always 2/3.
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,062 |
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205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 06:53:15
|
A) show that the ball is 2/3 of the volume of the cylinder
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,063 |
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205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 06:53:24
|
B) it is actually the case that even the sphere area is 2/3 of the area of the cylinder. Show that it is so. Tip: put the measurement on the globe and the cylinder and count your measurements
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,064 |
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205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 06:57:18
|
Maybe using Cavalieri's principle?
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,065 |
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205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 07:00:14
|
Idk
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,066 |
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205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 07:03:23
|
Basically, it's a principle as follows:
Suppose two 3d-objects are included between two parallel planes. If the cross-section of two objects on a plane is equal in area, the two objects have the same area.
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,067 |
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205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 07:05:29
|
Huh
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,068 |
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205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 07:06:04
|
The standard way to do it is to compare a hemisphere of radius r and a cylinder of radius r and height r minus an upside-down cone with the same radius and height.
| 0 | 1 |
761155030513352705
|
Ruth Young
|
Ruth Young
|
False
| 5,448,069 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 07:06:29
|
Huh
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,070 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 07:07:35
|
I don't understand
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,071 |
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205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 07:07:57
|
This is a graph from wikipedia.
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,072 |
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205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 07:07:59
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,073 |
|||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 07:08:14
|
Ok
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,074 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 07:09:48
|
The volume of the cylinder without the cone part should be equal to the volume of the hemisphere.
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,075 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 07:10:31
|
To show that, we take a slice on a plane parallel to the base of the cylinder at an arbitrary height.
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,076 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 07:14:36
|
What
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,077 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 07:17:11
|
What words are you confused at?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,078 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 07:17:39
|
Hemisphere, perpendicularl, arbitrary
| 1 | 0 |
673062964059701258
|
Valeria Harris
|
Valeria Harris
|
False
| 5,448,079 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 07:19:00
|
1. Hemisphere = half of an sphere
2. sorry, I mean parallel
3. for any h, show that the slice of both objects have an equal area.
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,080 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 07:19:41
|
Hmm okb
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,081 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 07:19:45
|
But I still don't understand
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,082 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 07:35:07
|
Which part do you still not understand now?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,083 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 07:37:29
|
How do I answer a and b
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,084 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 07:37:59
|
That proof is answering a
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,085 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 07:39:36
|
Ok
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,086 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 08:11:55
|
@Helpers
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,087 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 08:27:16
|
I mean, I showed you how to solve it. Just apply the Cavalieri's principle on that diagram I have given to answer a.
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,088 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 09:02:49
|
I never learned that principle
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,089 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 09:18:51
|
Well, that's not usually taught in schools, because that technique was rendered obsolete with calculus. But if you want to solve it the was Archimedes did, you have to use that principle.
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,090 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 09:24:08
|
Uhh
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,091 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
898592085215674459
|
Marissa Flores
|
01/31/2022 09:24:16
|
How do I answer b then
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,092 |
||
205,795 |
help-1
|
deb288c2d3ea49a094b1c323dbfbcf79
|
503047891271680001
|
Sergio Moore
|
01/31/2022 09:34:54
|
Honestly, I don't know it yet.
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,093 |
||
205,796 |
help-1
|
4a42a3ec41b94839841cc05178121aff
|
321445119171756033
|
Bryce Martinez
|
01/31/2022 10:31:50
|
indeed
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,094 |
||
205,796 |
help-1
|
4a42a3ec41b94839841cc05178121aff
|
321445119171756033
|
Bryce Martinez
|
01/31/2022 10:31:53
|
triangle inequality
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,095 |
||
205,796 |
help-1
|
4a42a3ec41b94839841cc05178121aff
|
321445119171756033
|
Bryce Martinez
|
01/31/2022 10:32:04
|
look it up
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,096 |
||
205,796 |
help-1
|
4a42a3ec41b94839841cc05178121aff
|
321445119171756033
|
Bryce Martinez
|
01/31/2022 10:32:20
|
the one side cannot be longer than the sum of the other 2
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,097 |
||
205,797 |
help-1
|
7f9e6926fdcd4dc588b7cfa375115b5e
|
852592874754932768
|
Giselle Torres
|
01/31/2022 10:52:46
|
image0.jpg
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,098 |
||
205,797 |
help-1
|
7f9e6926fdcd4dc588b7cfa375115b5e
|
852592874754932768
|
Giselle Torres
|
01/31/2022 10:52:56
|
where does the x disappear to?
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,099 |
||
205,797 |
help-1
|
7f9e6926fdcd4dc588b7cfa375115b5e
|
852592874754932768
|
Giselle Torres
|
01/31/2022 10:54:19
|
o nvm i misread
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,100 |
||
205,797 |
help-1
|
7f9e6926fdcd4dc588b7cfa375115b5e
|
852592874754932768
|
Giselle Torres
|
01/31/2022 10:54:21
|
.close
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,101 |
||
205,798 |
help-1
|
76f7a1cc319344499bc67bf7e3f7023e
|
366576372203651072
|
Leon Lopez
|
12/23/2021 22:11:19
|
Hi I'm looking for help for a graphing issue
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,102 |
||
205,798 |
help-1
|
76f7a1cc319344499bc67bf7e3f7023e
|
366576372203651072
|
Leon Lopez
|
12/23/2021 22:11:40
|
((x/10)^2) + ((y/10)^2) = 1
((x/5)^2) + (((y-5)/x)^2) = 1
|x| + 6 {-3≼x≼3}
(0.5x^2) - 8 {-4≼x4}
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,103 |
||
205,798 |
help-1
|
76f7a1cc319344499bc67bf7e3f7023e
|
366576372203651072
|
Leon Lopez
|
12/23/2021 22:11:50
|
on desmos this graphs out a sorta smiley face
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,104 |
||
205,798 |
help-1
|
76f7a1cc319344499bc67bf7e3f7023e
|
366576372203651072
|
Leon Lopez
|
12/23/2021 22:12:24
|
I'm trying to make it work in a way that the average Joe can see this, enter it in a graphing calculator and say, damn that's a face
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,105 |
||
205,798 |
help-1
|
76f7a1cc319344499bc67bf7e3f7023e
|
366576372203651072
|
Leon Lopez
|
12/23/2021 22:26:11
|
@Helpers
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,106 |
||
205,798 |
help-1
|
76f7a1cc319344499bc67bf7e3f7023e
|
366576372203651072
|
Leon Lopez
|
12/23/2021 22:32:35
|
.close
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,107 |
||
205,799 |
help-1
|
9ba804b847e947e6b367928e7a82a390
|
852592874754932768
|
Giselle Torres
|
01/31/2022 11:03:43
|
image0.jpg
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,108 |
||
205,799 |
help-1
|
9ba804b847e947e6b367928e7a82a390
|
852592874754932768
|
Giselle Torres
|
01/31/2022 11:03:48
|
haha why is this wrong?
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,109 |
||
205,799 |
help-1
|
9ba804b847e947e6b367928e7a82a390
|
179622041505366016
|
Alexa Brown
|
01/31/2022 11:06:57
|
What does allow you to do `ln F(x) = Int ln(...)` ?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,110 |
||
205,799 |
help-1
|
9ba804b847e947e6b367928e7a82a390
|
852592874754932768
|
Giselle Torres
|
01/31/2022 11:07:56
|
I have no idea lol
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,111 |
||
205,799 |
help-1
|
9ba804b847e947e6b367928e7a82a390
|
852592874754932768
|
Giselle Torres
|
01/31/2022 11:08:16
|
I thought we could because we use ln to differentiate uhh
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,112 |
||
205,799 |
help-1
|
9ba804b847e947e6b367928e7a82a390
|
852592874754932768
|
Giselle Torres
|
01/31/2022 11:08:22
|
total differentiation qs?
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,113 |
||
205,799 |
help-1
|
9ba804b847e947e6b367928e7a82a390
|
179622041505366016
|
Alexa Brown
|
01/31/2022 11:08:45
|
How ?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,114 |
||
205,799 |
help-1
|
9ba804b847e947e6b367928e7a82a390
|
852592874754932768
|
Giselle Torres
|
01/31/2022 11:09:28
|
I forgot but I recall using it.
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,115 |
||
205,799 |
help-1
|
9ba804b847e947e6b367928e7a82a390
|
179622041505366016
|
Alexa Brown
|
01/31/2022 11:09:50
|
Well, you cannot do what you did here
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,116 |
||
205,799 |
help-1
|
9ba804b847e947e6b367928e7a82a390
|
179622041505366016
|
Alexa Brown
|
01/31/2022 11:10:20
|
Applying `ln` to an integral is _not_ the same as applying `ln` to the integrated function
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,117 |
||
205,799 |
help-1
|
9ba804b847e947e6b367928e7a82a390
|
852592874754932768
|
Giselle Torres
|
01/31/2022 11:11:21
|
Okay.
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,118 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 11:30:30
|
Any help here? I'm getting T --> infinity only when time --> -infinity, which doesnt make sense
|
Screen_Shot_2022-01-31_at_11.29.17_AM.png
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,119 |
|
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 11:30:49
|
I think the main problem I'm getting is coming from the integral
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,120 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 11:31:04
|
since I dont know if you have to use absolute values here or not
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,121 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
179622041505366016
|
Alexa Brown
|
01/31/2022 11:31:24
|
Show your work
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,122 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 11:32:29
|
one sec
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,123 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 11:32:43
|
IMG_0458.jpg
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,124 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 11:33:39
|
Screen_Shot_2022-01-31_at_11.33.31_AM.png
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,125 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 11:38:23
|
@Helpers
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,126 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 11:44:35
|
$\dd{t} = \frac{\dd{T}}{e^T-h}$
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,127 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 11:48:04
|
does the ansswer involve absolute values
| 1 | 0 |
321445119171756033
|
Bryce Martinez
|
Bryce Martinez
|
False
| 5,448,128 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 11:48:25
|
$ht=-\ln \qty|\frac{1-he^{-T}}{1-h}|$
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,129 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 11:51:17
|
hmmmmm
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,130 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 11:51:22
|
i didnt get that
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,131 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 11:51:30
|
I thought so
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,132 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 11:51:31
|
wait
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,133 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 11:52:24
|
the problem is with how you integrated
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,134 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 11:53:13
|
$\int \frac{\dd{T}}{e^T-h} = \int \frac{e^{-T}\dd{T}}{1-he^{-T}}$
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,135 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 11:54:07
|
$=\frac{1}{h} \int \frac{\dd{(1-he^{-T})}}{1-he^{-T}}$
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,136 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 11:54:50
|
$=\frac{ln|1-he^{-T}|}{h}$
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,137 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 11:55:40
|
So, your $\Delta ht = \ln \qty|\frac{1-he^{-T}}{1-h}|$
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,138 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 11:57:15
|
So you have, as $T \to \infty$, ignition time $t = -\frac{1}{h} \ln |1-h|$
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,139 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 11:58:32
|
figure the condition on h :O
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,140 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 12:09:07
|
how did you get this
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,141 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 12:09:15
|
from ln(1-he^-T)
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,142 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 12:18:34
|
how did you get this from ln(1-he^-T)
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,143 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 12:19:50
|
my question is
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,144 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 12:19:54
|
how were you able to do that
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,145 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 12:19:58
|
and combine the absolute values
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,146 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
239571360169459712
|
Genesis Garcia
|
01/31/2022 12:20:38
|
and after this, how would you isolate T? @Ansh_
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,147 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 12:52:39
|
Did you get the steps till here?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,148 |
||
205,800 |
help-1
|
56fad1cd1b3c451aa125875122ae1971
|
706934233012371577
|
Darius Clark
|
01/31/2022 12:53:35
|
All I did was simplify the dT/dt = e^T - h
And, integrate the right side till this step you're talking about
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,149 |
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