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205,805 |
help-1
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eef24b107ba7461bbc3cf08c2a7cb0f1
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437300702960812033
|
Jan Anderson
|
01/31/2022 16:56:07
|
Is that correct?
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nan
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nan
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nan
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nan
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205,805 |
help-1
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eef24b107ba7461bbc3cf08c2a7cb0f1
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437300702960812033
|
Jan Anderson
|
01/31/2022 18:19:50
|
.close
| 1 | 0 |
nan
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nan
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nan
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nan
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205,806 |
help-1
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5fae48bc41f045b082b32ac88f3c1aec
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164771024263446528
|
Kimberly Brown
|
01/31/2022 18:36:50
|
Hello, the question im working on is
|
11fcd2c9e2fa08c8cdb100d9646755f3.png
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nan
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nan
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nan
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nan
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205,806 |
help-1
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5fae48bc41f045b082b32ac88f3c1aec
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164771024263446528
|
Kimberly Brown
|
01/31/2022 18:37:06
|
ive setup my lagrange formula as
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nan
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nan
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nan
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nan
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205,806 |
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5fae48bc41f045b082b32ac88f3c1aec
|
164771024263446528
|
Kimberly Brown
|
01/31/2022 18:37:52
|
```
L(x,y,lambda) = (x-1)^2 +(y-3)^2 -5 -
lambda(x+2y-4)
```
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nan
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nan
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nan
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nan
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205,806 |
help-1
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5fae48bc41f045b082b32ac88f3c1aec
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164771024263446528
|
Kimberly Brown
|
01/31/2022 18:38:43
|
im having issues with my derivate as it relates to x and y
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nan
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nan
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nan
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nan
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5fae48bc41f045b082b32ac88f3c1aec
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164771024263446528
|
Kimberly Brown
|
01/31/2022 18:39:16
|
for Lx is it 2(x-1) - lambda = 0
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nan
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nan
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nan
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nan
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205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
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164771024263446528
|
Kimberly Brown
|
01/31/2022 18:40:05
|
and Ly 2(y-3) - 2lambda or just lambda = 0
| 1 | 0 |
nan
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nan
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nan
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nan
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205,806 |
help-1
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5fae48bc41f045b082b32ac88f3c1aec
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193942262336454656
|
Gerardo Brown
|
01/31/2022 18:42:35
|
I wish I could help but it’s been a while
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nan
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nan
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nan
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nan
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205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
164771024263446528
|
Kimberly Brown
|
01/31/2022 18:43:08
|
do i ask in another math help thread?
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nan
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nan
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nan
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nan
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205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
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193942262336454656
|
Gerardo Brown
|
01/31/2022 18:43:22
|
No keep this one open
| 0 | 1 |
nan
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nan
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nan
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nan
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205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
164771024263446528
|
Kimberly Brown
|
01/31/2022 18:43:24
|
kk
| 1 | 0 |
nan
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nan
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nan
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nan
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205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
193942262336454656
|
Gerardo Brown
|
01/31/2022 18:44:22
|
Okay so is it only regarding your derivatives?
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nan
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nan
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nan
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nan
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205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
164771024263446528
|
Kimberly Brown
|
01/31/2022 18:44:53
|
yeah
| 1 | 0 |
nan
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nan
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nan
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nan
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205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
164771024263446528
|
Kimberly Brown
|
01/31/2022 18:45:08
|
if its one or two lamba for partial derivative for y
| 1 | 0 |
nan
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nan
|
nan
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nan
| 5,448,264 |
||
205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
193942262336454656
|
Gerardo Brown
|
01/31/2022 18:45:26
|
Oh two lambda yes
| 0 | 1 |
nan
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nan
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nan
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nan
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205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
193942262336454656
|
Gerardo Brown
|
01/31/2022 18:45:35
|
That’s your system
| 0 | 1 |
nan
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nan
|
nan
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nan
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205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
164771024263446528
|
Kimberly Brown
|
01/31/2022 18:45:45
|
so Lx = 2(x-1) - lamba = 0
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,267 |
||
205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
164771024263446528
|
Kimberly Brown
|
01/31/2022 18:46:04
|
and Ly = (2(y-3)-2lambda = 0
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,268 |
||
205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
193942262336454656
|
Gerardo Brown
|
01/31/2022 18:46:10
|
That looks right to me
| 0 | 1 |
nan
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nan
|
nan
|
nan
| 5,448,269 |
||
205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
164771024263446528
|
Kimberly Brown
|
01/31/2022 18:48:50
|
and then
|
e0a3e5d50e303960c4f1ff4d496419e9.png
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,270 |
|
205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
164771024263446528
|
Kimberly Brown
|
01/31/2022 18:49:13
|
so on this problem, we isolate lambda, if i have 2 lambda for Ly, how do i isolate it properly?
| 1 | 0 |
nan
|
nan
|
nan
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nan
| 5,448,271 |
||
205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
164771024263446528
|
Kimberly Brown
|
01/31/2022 19:09:18
|
This is my work for part a, if anyone could provide confirmation/feedback to my earlier question if i did it right that'd be great
| 1 | 0 |
nan
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nan
|
nan
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nan
| 5,448,272 |
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205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
164771024263446528
|
Kimberly Brown
|
01/31/2022 19:20:43
|
Solved thank you
| 1 | 0 |
nan
|
nan
|
nan
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nan
| 5,448,273 |
||
205,806 |
help-1
|
5fae48bc41f045b082b32ac88f3c1aec
|
164771024263446528
|
Kimberly Brown
|
01/31/2022 19:31:52
|
.close
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,274 |
||
205,807 |
help-1
|
12905c196aef45d99654885de12e58f0
|
263447448725225472
|
Darryl Miller
|
01/31/2022 20:16:36
|
IMG_8925.jpg
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,275 |
||
205,807 |
help-1
|
12905c196aef45d99654885de12e58f0
|
263447448725225472
|
Darryl Miller
|
01/31/2022 20:16:36
|
IMG_8924.jpg
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,276 |
||
205,807 |
help-1
|
12905c196aef45d99654885de12e58f0
|
485903210272391178
|
Kelvin Taylor
|
01/31/2022 20:17:02
|
,rotate
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,277 |
||
205,807 |
help-1
|
12905c196aef45d99654885de12e58f0
|
186109587366215691
|
Jenny Brown
|
01/31/2022 20:18:32
|
Ab^**x**
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,278 |
||
205,808 |
help-1
|
b2c0c90cd3bc4532b910b17d75ca60d6
|
284850606194294785
|
Bella Davis
|
01/31/2022 20:50:08
|
unknown.png
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,279 |
||
205,808 |
help-1
|
b2c0c90cd3bc4532b910b17d75ca60d6
|
284850606194294785
|
Bella Davis
|
01/31/2022 20:50:17
|
what the heck does t represent
| 1 | 0 |
nan
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nan
|
nan
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nan
| 5,448,280 |
||
205,808 |
help-1
|
b2c0c90cd3bc4532b910b17d75ca60d6
|
193942262336454656
|
Gerardo Brown
|
01/31/2022 20:51:17
|
What’s the equation
| 0 | 1 |
nan
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nan
|
nan
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nan
| 5,448,281 |
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205,808 |
help-1
|
b2c0c90cd3bc4532b910b17d75ca60d6
|
284850606194294785
|
Bella Davis
|
01/31/2022 20:51:25
|
that's all it says
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,282 |
||
205,808 |
help-1
|
b2c0c90cd3bc4532b910b17d75ca60d6
|
193942262336454656
|
Gerardo Brown
|
01/31/2022 20:51:36
|
You have no idea what P is?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,283 |
||
205,808 |
help-1
|
b2c0c90cd3bc4532b910b17d75ca60d6
|
284850606194294785
|
Bella Davis
|
01/31/2022 20:51:46
|
P is a point right
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,284 |
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205,808 |
help-1
|
b2c0c90cd3bc4532b910b17d75ca60d6
|
193942262336454656
|
Gerardo Brown
|
01/31/2022 20:52:06
|
It might be an angle
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,285 |
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205,808 |
help-1
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b2c0c90cd3bc4532b910b17d75ca60d6
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284850606194294785
|
Bella Davis
|
01/31/2022 20:52:12
|
I tried that
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,286 |
||
205,808 |
help-1
|
b2c0c90cd3bc4532b910b17d75ca60d6
|
193942262336454656
|
Gerardo Brown
|
01/31/2022 20:52:14
|
I’m not familiar with this notation though
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,287 |
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205,808 |
help-1
|
b2c0c90cd3bc4532b910b17d75ca60d6
|
193942262336454656
|
Gerardo Brown
|
01/31/2022 20:52:34
|
0,1 would traditionally be 90deg
| 0 | 1 |
nan
|
nan
|
nan
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nan
| 5,448,288 |
||
205,808 |
help-1
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b2c0c90cd3bc4532b910b17d75ca60d6
|
284850606194294785
|
Bella Davis
|
01/31/2022 20:53:07
|
oh it is an angle just in rads
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,289 |
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205,808 |
help-1
|
b2c0c90cd3bc4532b910b17d75ca60d6
|
193942262336454656
|
Gerardo Brown
|
01/31/2022 20:53:44
|
I’m not sure what class this is, but maybe it’s asking for the arctan
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,290 |
||
205,808 |
help-1
|
b2c0c90cd3bc4532b910b17d75ca60d6
|
284850606194294785
|
Bella Davis
|
01/31/2022 20:53:54
|
.close
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,291 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 22:46:41
|
Hi
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,292 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 22:47:10
|
How do I approach the following problem?
Let following be known about a real polynomial:
* deg(g) = 6
* g has at least the real zeros 2 and 3, of which one has the multiplicity 3.
* g has at least the complex zero i.
Show that g(0) is divisible by 6.
The Horner algorithm might play a role or be of help.
| 1 | 0 |
nan
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nan
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nan
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nan
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205,809 |
help-1
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8e56f39d9d704e209d984c55ffabc3ac
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332164791143759872
|
Barbara Hernandez
|
12/23/2021 22:50:08
|
My intuition says that for example let's take (x-2)^3 * (x-3)^2 * (x-i)
| 1 | 0 |
nan
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nan
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nan
|
nan
| 5,448,294 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
329749386315956225
|
Darius Martinez
|
12/23/2021 22:50:11
|
so am i missing something or is this a counterexample?
|
unknown.png
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,295 |
|
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 22:51:27
|
is the plus (x^2 + i) correct?
| 1 | 0 |
701895792763600896
|
Claudia Clark
|
Claudia Clark
|
False
| 5,448,296 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
329749386315956225
|
Darius Martinez
|
12/23/2021 22:51:35
|
that says x^2+1
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,297 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
329749386315956225
|
Darius Martinez
|
12/23/2021 22:51:53
|
i^2+1=0
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,298 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
329749386315956225
|
Darius Martinez
|
12/23/2021 22:53:29
|
it might help to remember the conjugate root theorem to understand where i got x^2+1 from. i being a zero implies -i being a zero, implies (x-i)(x+i)=x^2+1 being a factor.
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,299 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 22:55:00
|
I'm not accustomed with complex numbers yet, but about the exercise I'm sure it's like that
| 1 | 0 |
261933205387477002
|
Nicolas Miller
|
Nicolas Miller
|
False
| 5,448,300 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 22:56:10
|
I couldn't interpret the graph in regards to division by 6
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,301 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 22:56:37
|
ah, it states = 27
| 1 | 0 |
701895792763600896
|
Claudia Clark
|
Claudia Clark
|
False
| 5,448,302 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
329749386315956225
|
Darius Martinez
|
12/23/2021 22:57:37
|
It does work if g is meant to be an integer polynomial with those conditions
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,303 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
329749386315956225
|
Darius Martinez
|
12/23/2021 22:58:01
|
but in the realm of real polynomials, there are certainly many g st g(0) isn't divisible by 6
| 0 | 1 |
nan
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nan
|
nan
|
nan
| 5,448,304 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 22:58:30
|
when we take out the 0.5 we'd have 54 which is divisible
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,305 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
329749386315956225
|
Darius Martinez
|
12/23/2021 22:58:40
|
yes you would.
| 0 | 1 |
nan
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nan
|
nan
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nan
| 5,448,306 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
329749386315956225
|
Darius Martinez
|
12/23/2021 23:00:17
|
that doesn't discount the fact that 0.5(x-2)(x-3)^2(x^2+1) is a counterexample
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,307 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 23:02:31
|
it wouldn't save the question if I said if we scale the polynomial, we expect to scale the value 6 aswell, no?
| 1 | 0 |
701895792763600896
|
Claudia Clark
|
Claudia Clark
|
False
| 5,448,308 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 23:02:55
|
because instead of 0.5 we can use any arbitrary scaling
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,309 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 23:03:14
|
so division by whole number would get lost definitely
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,310 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 23:03:25
|
or not?
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,311 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
329749386315956225
|
Darius Martinez
|
12/23/2021 23:04:07
|
This could be me but I can't really figure out what you're trying to say
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,312 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
329749386315956225
|
Darius Martinez
|
12/23/2021 23:04:55
|
The simplest way to save the problem would be to say g has to be an integer polynomial, but I don't really like doing the "guess what the question is meant to say" thing
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,313 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 23:06:21
|
I had a fallacy
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,314 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 23:08:25
|
well then
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,315 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 23:08:49
|
seems like a dead end to me with having your counterexample, so I'll have to ask my tutor
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,316 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 23:09:06
|
I thank you for your help @Sneaky
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,317 |
||
205,809 |
help-1
|
8e56f39d9d704e209d984c55ffabc3ac
|
332164791143759872
|
Barbara Hernandez
|
12/23/2021 23:09:36
|
.close
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,318 |
||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
|
760358915925475368
|
Betty Young
|
01/31/2022 21:14:22
|
Hey, I'm stumped on lim(x->pi/2) for (cos^2 x)/(1-sin x). I've tried messing around with substituting identities, either I'm off base, or not seeing it, or w/e
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,319 |
||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
|
760358915925475368
|
Betty Young
|
01/31/2022 21:14:49
|
Any help for the answer is good, any insight into the intuition as to why it's the answer is what I'm looking for
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,320 |
||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
|
186109587366215691
|
Jenny Brown
|
01/31/2022 21:15:18
|
Hint: Pythagorean identity
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,321 |
||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
|
760358915925475368
|
Betty Young
|
01/31/2022 21:16:05
|
I tried throwing that in, (cos^2 x)/(cos^2 x + sin^2 x - sin x), but I'm stumped on that front
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,322 |
||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
|
186109587366215691
|
Jenny Brown
|
01/31/2022 21:16:18
|
$\cos^2(x)=1-\sin^2(x)$
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,323 |
||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
|
760358915925475368
|
Betty Young
|
01/31/2022 21:16:48
|
ahhh yeah
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,324 |
||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
|
308723121744248834
|
Eliana Rodriguez
|
01/31/2022 21:17:54
|
thanks pythagoras
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,325 |
||
205,810 |
help-1
|
5e1c9660972744508d4374eef73167e6
|
760358915925475368
|
Betty Young
|
01/31/2022 21:17:57
|
.close
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,326 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
760358915925475368
|
Betty Young
|
01/31/2022 21:18:02
|
thx all
| 1 | 0 |
706934233012371577
|
Darius Clark
|
Darius Clark
|
False
| 5,448,327 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
315292317315629057
|
Ava Martinez
|
01/31/2022 22:11:26
|
how do i understand what {u, v} is because i set up the equations but don't know how they are equal to {u, v}
|
unknown.png
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,328 |
|
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:12:24
|
wdym?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,329 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
315292317315629057
|
Ava Martinez
|
01/31/2022 22:12:53
|
i don't know how to set up the system of equations
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,330 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:14:35
|
ok so lets do the first one together
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,331 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:15:11
|
we want to see if there are numbers (scalars) a,b such that a*[1,-2] + b * [-2,5] = [-2,5] correct?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,332 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
315292317315629057
|
Ava Martinez
|
01/31/2022 22:15:30
|
yeah
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,333 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:15:58
|
ok, so then we simplify the LHS
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,334 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:16:14
|
we have [a-2a] + [-2b+5b] = [-2,5]
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,335 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:16:26
|
which implies that a-2b = -2, -2a+5b = 5
| 0 | 1 |
475966350322302977
|
Alison Taylor
|
Alison Taylor
|
False
| 5,448,336 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:16:28
|
with me so far?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,337 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:16:51
|
we then solve this system of linear equations
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,338 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:16:58
|
(which im assuming you know how to do)
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,339 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
315292317315629057
|
Ava Martinez
|
01/31/2022 22:18:16
|
ohh i think i understand how you made the system
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,340 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:18:20
|
yup
| 0 | 1 |
475966350322302977
|
Alison Taylor
|
Alison Taylor
|
False
| 5,448,341 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:18:35
|
because [a,b] + [c,d] = [a+c, b+d]
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,342 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
315292317315629057
|
Ava Martinez
|
01/31/2022 22:19:41
|
ok then you can prove its a linear combination by finding a and b?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,343 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
315292317315629057
|
Ava Martinez
|
01/31/2022 22:33:01
|
is the vector a linear combination of {u,v}? i solved the system of equations and got a=0 and b=1
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,344 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:33:15
|
great
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,345 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:33:20
|
yup
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,346 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
315292317315629057
|
Ava Martinez
|
01/31/2022 22:34:22
|
since the A vector is similar to C is it also a correct linear combination?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,347 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:34:47
|
what do you mean "similar"
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,348 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:34:58
|
but to answer your question, you did prove that it is a linear combination
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,349 |
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