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205,811 |
help-1
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5a7aec2de37a4a9588e6f74e2ca31bd1
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315292317315629057
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Ava Martinez
|
01/31/2022 22:35:34
|
they are both equal to the given vectors u and v
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,350 |
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205,811 |
help-1
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5a7aec2de37a4a9588e6f74e2ca31bd1
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714316705303625818
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Preston Ramirez
|
01/31/2022 22:35:56
|
i dont see what you mean
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nan
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nan
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nan
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nan
| 5,448,351 |
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205,811 |
help-1
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5a7aec2de37a4a9588e6f74e2ca31bd1
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714316705303625818
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Preston Ramirez
|
01/31/2022 22:36:01
|
plz give an example
| 0 | 1 |
nan
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nan
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nan
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nan
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205,811 |
help-1
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5a7aec2de37a4a9588e6f74e2ca31bd1
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315292317315629057
|
Ava Martinez
|
01/31/2022 22:36:36
|
unknown.png
| 0 | 1 |
nan
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nan
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nan
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nan
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205,811 |
help-1
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5a7aec2de37a4a9588e6f74e2ca31bd1
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315292317315629057
|
Ava Martinez
|
01/31/2022 22:36:36
|
unknown.png
| 0 | 1 |
nan
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nan
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nan
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nan
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205,811 |
help-1
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5a7aec2de37a4a9588e6f74e2ca31bd1
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315292317315629057
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Ava Martinez
|
01/31/2022 22:36:36
|
unknown.png
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,355 |
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205,811 |
help-1
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5a7aec2de37a4a9588e6f74e2ca31bd1
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714316705303625818
|
Preston Ramirez
|
01/31/2022 22:37:12
|
correct
| 0 | 1 |
nan
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nan
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nan
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nan
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205,811 |
help-1
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5a7aec2de37a4a9588e6f74e2ca31bd1
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315292317315629057
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Ava Martinez
|
01/31/2022 22:38:33
|
are those the only linear combinations in the list?
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unknown.png
| 0 | 1 |
nan
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nan
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nan
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nan
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205,811 |
help-1
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5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:38:44
|
that is for you to figure out
| 0 | 1 |
nan
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nan
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nan
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nan
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205,811 |
help-1
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5a7aec2de37a4a9588e6f74e2ca31bd1
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714316705303625818
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Preston Ramirez
|
01/31/2022 22:38:47
|
repeat the process
| 0 | 1 |
nan
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nan
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nan
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nan
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
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714316705303625818
|
Preston Ramirez
|
01/31/2022 22:38:48
|
😉
| 0 | 1 |
nan
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nan
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nan
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nan
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
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315292317315629057
|
Ava Martinez
|
01/31/2022 22:39:21
|
is it only a linear comb if there's a solution to the system
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,361 |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
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714316705303625818
|
Preston Ramirez
|
01/31/2022 22:39:41
|
well yes
| 0 | 1 |
nan
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nan
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nan
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nan
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
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714316705303625818
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Preston Ramirez
|
01/31/2022 22:39:47
|
like if u = v = [0,0]
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,363 |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:40:07
|
then if answer H is "The vector [1,1] is a lin. comb. of {u,v}
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,364 |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:40:09
|
it is false
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,365 |
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205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
714316705303625818
|
Preston Ramirez
|
01/31/2022 22:40:11
|
get it?
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,366 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
|
315292317315629057
|
Ava Martinez
|
01/31/2022 22:40:52
|
ohh ok then this probably means all real vectors are linear combinations
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,367 |
||
205,811 |
help-1
|
5a7aec2de37a4a9588e6f74e2ca31bd1
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315292317315629057
|
Ava Martinez
|
01/31/2022 22:48:17
|
@Invictus is choosing every vector that's not a multiple of u1 and u2 a good strategy to tell what's not in the span?
|
unknown.png
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,368 |
|
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
|
551269104800104449
|
Celeste Martin
|
01/31/2022 23:16:13
|
the one sheeted hyperboloid has cartesian eqn:
| 1 | 0 |
nan
|
nan
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nan
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nan
| 5,448,369 |
||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
|
551269104800104449
|
Celeste Martin
|
01/31/2022 23:16:40
|
x^2/a^2 + y^2/b^2 - z^2/c^2 = 1
| 1 | 0 |
183668144404037632
|
Kendra Brown
|
Kendra Brown
|
False
| 5,448,370 |
||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
|
551269104800104449
|
Celeste Martin
|
01/31/2022 23:16:51
|
what do a b c represent here
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,371 |
||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
|
551269104800104449
|
Celeste Martin
|
01/31/2022 23:17:05
|
geometrically speaking!
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,372 |
||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
|
551269104800104449
|
Celeste Martin
|
01/31/2022 23:17:09
|
lol
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,373 |
||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
|
551269104800104449
|
Celeste Martin
|
01/31/2022 23:19:12
|
@Helpers
| 1 | 0 |
nan
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nan
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nan
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nan
| 5,448,374 |
||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
|
551269104800104449
|
Celeste Martin
|
01/31/2022 23:44:22
|
@Helpers
| 1 | 0 |
nan
|
nan
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nan
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nan
| 5,448,375 |
||
205,812 |
help-1
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23adb9c9ea384313bf6c80dbb3393f7a
|
569167697925898261
|
Kendra Lee
|
02/01/2022 00:24:04
|
geometrically they're the principal semi-axes
| 0 | 1 |
nan
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nan
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nan
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nan
| 5,448,376 |
||
205,812 |
help-1
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23adb9c9ea384313bf6c80dbb3393f7a
|
183668144404037632
|
Kendra Brown
|
02/01/2022 00:51:08
|
@EndTimes the 'unit' hyperboloid of one sheet has equation x^2 + y^2 - z^2 = 1
| 0 | 1 |
nan
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nan
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nan
|
nan
| 5,448,377 |
||
205,812 |
help-1
|
23adb9c9ea384313bf6c80dbb3393f7a
|
183668144404037632
|
Kendra Brown
|
02/01/2022 00:51:22
|
dilating it by a, b and c along the x, y and z axes gives yours
| 0 | 1 |
nan
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nan
|
nan
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nan
| 5,448,378 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 02:27:44
|
Hey Guys, I have a problem with the calculation
I have to get x1, x2 and x3 and it uses ZZ7, so Im not sure how to solve it, I used the gauss algorithm already, but I dont know whether its correct or not:
|
unknown.png
| 1 | 0 |
nan
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nan
|
nan
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nan
| 5,448,379 |
|
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 02:27:44
|
Hey Guys, I have a problem with the calculation
I have to get x1, x2 and x3 and it uses ZZ7, so Im not sure how to solve it, I used the gauss algorithm already, but I dont know whether its correct or not:
|
unknown.png
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,380 |
|
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 02:28:17
|
Also, I got out for x1 = 1.5, for x2 =0 and for x3 = -1
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,381 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 02:29:34
|
Or was I wrong to use the Gauss Algorithm here?
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,382 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
706934233012371577
|
Darius Clark
|
02/01/2022 02:33:17
|
hmm the Z7
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,383 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 02:33:45
|
Well, I was a bit confused because I'm limited to the body ZZ7 right? This one
|
unknown.png
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,384 |
|
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 02:34:16
|
Or maybe its called a "field" in english
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,385 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 02:34:35
|
So the number only goes from 0 up to 6
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,386 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 02:34:42
|
(I think)
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,387 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 02:41:53
|
yup
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,388 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 03:42:42
|
Well, if no one knows the answer to those, I would need help with something else as well
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,389 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 03:43:18
|
Give the generator polynomials and the corresponding generator matrices and control polynomials of all 6-digit cyclic codes with 3 control digits over Z5.
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,390 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 03:43:43
|
And I'm absolutely confused on how I can do that
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,391 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
915938343857037314
|
Beth Green
|
02/01/2022 04:05:27
|
If u know inverse matrix, then just multiply inverse of the 3*3 matrix to both the sides. The LHS become only x1,x2,x3 and RHS will be inv(3*3) matrix * (1,3,1) matrix
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,392 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:27:27
|
i think i know how to do it, i think it's like gauss algorithm but instead of dividing, you multiply it by its multiplicative inverse in the finite field
i think it helps if you make the multiplication table for the finite field first
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,393 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:29:13
|
Well, this was my first attempt, what do you mean by the finite field? Like what would I change?
|
20220201_102828.jpg
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,394 |
|
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:29:20
|
Not sure what the finite field is
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,395 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:29:37
|
it's the Z7
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,396 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:29:45
|
Ahhh
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,397 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:31:33
|
So then I first multiply everything by 7? But that wouldnt make sense 🤔
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,398 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:32:27
|
no, yeah, try to make the multiplication table for the Z7 first
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,399 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:32:58
|
if you multiply everything by 7, it's like multiplying everything by 0
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,400 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:33:08
|
by 1
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,401 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:33:11
|
Z7 is the integers mod 7
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,402 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:33:31
|
$7\equiv0(mod 7)$
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,403 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:33:55
|
hmmm
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,404 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:35:32
|
I still dont get it :/
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,405 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:35:42
|
I know what mod 7 does
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,406 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:35:51
|
But I dont know how to apply it in that matrix
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,407 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:36:01
|
it's the remainder after the division
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,408 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:36:32
|
oh, i read that as i don't know
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,409 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:38:18
|
:/
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,410 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:39:43
|
ok, so, can you make the multiplication table for Z7?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,411 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:43:33
|
Not really
| 1 | 0 |
348696743388381195
|
Reese Hernandez
|
Reese Hernandez
|
False
| 5,448,412 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:43:46
|
Ahhhhh
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,413 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:44:10
|
Do I need to just use the mod 7 on every single number there perhaps? 🤔
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,414 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:45:49
|
maybe that'll work, and instead of dividing, you multiply it by its multiplicative inverse
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,415 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:47:51
|
also, the multiplication table for Z7 is just like a normal multiplication table, but from 1 to 6 because after that I'll come back because of the mod 7
and the result is also mod 7
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,416 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:49:01
|
But how will I know whetherr thats correct and whether I will get the correct answers for that?
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,417 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:49:58
|
well, put the x1, x2, and x3 back into there and see if the result is the same
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,418 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:51:28
|
oh... Yeah true, mb
| 1 | 0 |
220517274845577216
|
Lena Jones
|
Lena Jones
|
False
| 5,448,419 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:53:13
|
also, it shouldn't have a number outside of Z7
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,420 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:53:52
|
Yes, but Is -1 to -6 also in that Z7 zone?
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,421 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:54:06
|
prrobably not right?
| 1 | 0 |
220517274845577216
|
Lena Jones
|
Lena Jones
|
False
| 5,448,422 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:54:24
|
you can add 7 to it and I'll be in it
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,423 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 04:54:43
|
like $-1\equiv6 (mod 7)$
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,424 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 04:54:53
|
ahh okay
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,425 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:02:02
|
Wait
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,426 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:02:19
|
I got a point numberr
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,427 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:02:27
|
and that shouldnt be in the zone
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,428 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 05:02:39
|
yup, only integers
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,429 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 05:03:28
|
did you divide?
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,430 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:03:42
|
Yes, I needed to divide
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,431 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:05:19
|
20220201_110500.jpg
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,432 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 05:06:00
|
instead of dividing you need to find a number y such that\\
$x*y=1\ \text{(mod 7)}$
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,433 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 05:08:18
|
also, that's not how you read the x1, x2, or x3, you need to solve it to where each collum only have one number that's not 0 and all the others are 0
| 0 | 1 |
220517274845577216
|
Lena Jones
|
Lena Jones
|
False
| 5,448,434 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:09:03
|
aahhh
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,435 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:09:04
|
okay
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,436 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:09:06
|
I got it
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,437 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:09:30
|
I got the last part
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,438 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:09:50
|
But I didnt understand how to fix the point number thing
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,439 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:10:01
|
Here you can see my process
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,440 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 05:11:28
|
that's why it's easier if we have the multiplication table, so make something like this, and fill it in
|
IMG_20220201_171058.jpg
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,441 |
|
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:11:39
|
okay
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,442 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 05:11:41
|
mod 7 of course
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,443 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:15:16
|
20220201_111509.jpg
| 1 | 0 |
320090412012404737
|
Ronnie Martinez
|
Ronnie Martinez
|
False
| 5,448,444 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 05:16:38
|
yup, that's right
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,445 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 05:17:37
|
so, to find which number you have to multiply in order to get 1
you just start at that number and go right or down until you get to 1
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,446 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:18:45
|
im so confused rn
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,447 |
||
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
595185421743554570
|
Reginald Perez
|
02/01/2022 05:20:03
|
so, like for 4, you can multiply it by 2 and get 1
|
IMG_20220201_171922.jpg
| 0 | 1 |
nan
|
nan
|
nan
|
nan
| 5,448,448 |
|
205,813 |
help-1
|
3cb2f7639f2549b1a75e0907763ac032
|
236549522178834432
|
Alison Garcia
|
02/01/2022 05:20:37
|
ah, yeah
| 1 | 0 |
nan
|
nan
|
nan
|
nan
| 5,448,449 |
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