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205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
315292317315629057
Ava Martinez
01/31/2022 22:35:34
they are both equal to the given vectors u and v
0
1
nan
nan
nan
nan
5,448,350
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
714316705303625818
Preston Ramirez
01/31/2022 22:35:56
i dont see what you mean
0
1
nan
nan
nan
nan
5,448,351
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
714316705303625818
Preston Ramirez
01/31/2022 22:36:01
plz give an example
0
1
nan
nan
nan
nan
5,448,352
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
315292317315629057
Ava Martinez
01/31/2022 22:36:36
https://cdn.discordapp.c…8807/unknown.png
unknown.png
0
1
nan
nan
nan
nan
5,448,353
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
315292317315629057
Ava Martinez
01/31/2022 22:36:36
https://cdn.discordapp.c…0628/unknown.png
unknown.png
0
1
nan
nan
nan
nan
5,448,354
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
315292317315629057
Ava Martinez
01/31/2022 22:36:36
https://cdn.discordapp.c…2752/unknown.png
unknown.png
0
1
nan
nan
nan
nan
5,448,355
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
714316705303625818
Preston Ramirez
01/31/2022 22:37:12
correct
0
1
nan
nan
nan
nan
5,448,356
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
315292317315629057
Ava Martinez
01/31/2022 22:38:33
are those the only linear combinations in the list?
https://cdn.discordapp.c…4664/unknown.png
unknown.png
0
1
nan
nan
nan
nan
5,448,357
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
714316705303625818
Preston Ramirez
01/31/2022 22:38:44
that is for you to figure out
0
1
nan
nan
nan
nan
5,448,358
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
714316705303625818
Preston Ramirez
01/31/2022 22:38:47
repeat the process
0
1
nan
nan
nan
nan
5,448,359
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
714316705303625818
Preston Ramirez
01/31/2022 22:38:48
😉
0
1
nan
nan
nan
nan
5,448,360
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
315292317315629057
Ava Martinez
01/31/2022 22:39:21
is it only a linear comb if there's a solution to the system
0
1
nan
nan
nan
nan
5,448,361
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
714316705303625818
Preston Ramirez
01/31/2022 22:39:41
well yes
0
1
nan
nan
nan
nan
5,448,362
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
714316705303625818
Preston Ramirez
01/31/2022 22:39:47
like if u = v = [0,0]
0
1
nan
nan
nan
nan
5,448,363
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
714316705303625818
Preston Ramirez
01/31/2022 22:40:07
then if answer H is "The vector [1,1] is a lin. comb. of {u,v}
0
1
nan
nan
nan
nan
5,448,364
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
714316705303625818
Preston Ramirez
01/31/2022 22:40:09
it is false
0
1
nan
nan
nan
nan
5,448,365
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
714316705303625818
Preston Ramirez
01/31/2022 22:40:11
get it?
0
1
nan
nan
nan
nan
5,448,366
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
315292317315629057
Ava Martinez
01/31/2022 22:40:52
ohh ok then this probably means all real vectors are linear combinations
0
1
nan
nan
nan
nan
5,448,367
205,811
help-1
5a7aec2de37a4a9588e6f74e2ca31bd1
315292317315629057
Ava Martinez
01/31/2022 22:48:17
@Invictus is choosing every vector that's not a multiple of u1 and u2 a good strategy to tell what's not in the span?
https://cdn.discordapp.c…6158/unknown.png
unknown.png
0
1
nan
nan
nan
nan
5,448,368
205,812
help-1
23adb9c9ea384313bf6c80dbb3393f7a
551269104800104449
Celeste Martin
01/31/2022 23:16:13
the one sheeted hyperboloid has cartesian eqn:
1
0
nan
nan
nan
nan
5,448,369
205,812
help-1
23adb9c9ea384313bf6c80dbb3393f7a
551269104800104449
Celeste Martin
01/31/2022 23:16:40
x^2/a^2 + y^2/b^2 - z^2/c^2 = 1
1
0
183668144404037632
Kendra Brown
Kendra Brown
False
5,448,370
205,812
help-1
23adb9c9ea384313bf6c80dbb3393f7a
551269104800104449
Celeste Martin
01/31/2022 23:16:51
what do a b c represent here
1
0
nan
nan
nan
nan
5,448,371
205,812
help-1
23adb9c9ea384313bf6c80dbb3393f7a
551269104800104449
Celeste Martin
01/31/2022 23:17:05
geometrically speaking!
1
0
nan
nan
nan
nan
5,448,372
205,812
help-1
23adb9c9ea384313bf6c80dbb3393f7a
551269104800104449
Celeste Martin
01/31/2022 23:17:09
lol
1
0
nan
nan
nan
nan
5,448,373
205,812
help-1
23adb9c9ea384313bf6c80dbb3393f7a
551269104800104449
Celeste Martin
01/31/2022 23:19:12
@Helpers
1
0
nan
nan
nan
nan
5,448,374
205,812
help-1
23adb9c9ea384313bf6c80dbb3393f7a
551269104800104449
Celeste Martin
01/31/2022 23:44:22
@Helpers
1
0
nan
nan
nan
nan
5,448,375
205,812
help-1
23adb9c9ea384313bf6c80dbb3393f7a
569167697925898261
Kendra Lee
02/01/2022 00:24:04
geometrically they're the principal semi-axes
0
1
nan
nan
nan
nan
5,448,376
205,812
help-1
23adb9c9ea384313bf6c80dbb3393f7a
183668144404037632
Kendra Brown
02/01/2022 00:51:08
@EndTimes the 'unit' hyperboloid of one sheet has equation x^2 + y^2 - z^2 = 1
0
1
nan
nan
nan
nan
5,448,377
205,812
help-1
23adb9c9ea384313bf6c80dbb3393f7a
183668144404037632
Kendra Brown
02/01/2022 00:51:22
dilating it by a, b and c along the x, y and z axes gives yours
0
1
nan
nan
nan
nan
5,448,378
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 02:27:44
Hey Guys, I have a problem with the calculation I have to get x1, x2 and x3 and it uses ZZ7, so Im not sure how to solve it, I used the gauss algorithm already, but I dont know whether its correct or not:
https://cdn.discordapp.c…6182/unknown.png
unknown.png
1
0
nan
nan
nan
nan
5,448,379
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 02:27:44
Hey Guys, I have a problem with the calculation I have to get x1, x2 and x3 and it uses ZZ7, so Im not sure how to solve it, I used the gauss algorithm already, but I dont know whether its correct or not:
https://cdn.discordapp.c…0592/unknown.png
unknown.png
1
0
nan
nan
nan
nan
5,448,380
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 02:28:17
Also, I got out for x1 = 1.5, for x2 =0 and for x3 = -1
1
0
nan
nan
nan
nan
5,448,381
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 02:29:34
Or was I wrong to use the Gauss Algorithm here?
1
0
nan
nan
nan
nan
5,448,382
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
706934233012371577
Darius Clark
02/01/2022 02:33:17
hmm the Z7
0
1
nan
nan
nan
nan
5,448,383
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 02:33:45
Well, I was a bit confused because I'm limited to the body ZZ7 right? This one
https://cdn.discordapp.c…9578/unknown.png
unknown.png
1
0
nan
nan
nan
nan
5,448,384
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 02:34:16
Or maybe its called a "field" in english
1
0
nan
nan
nan
nan
5,448,385
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 02:34:35
So the number only goes from 0 up to 6
1
0
nan
nan
nan
nan
5,448,386
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 02:34:42
(I think)
1
0
nan
nan
nan
nan
5,448,387
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 02:41:53
yup
1
0
nan
nan
nan
nan
5,448,388
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 03:42:42
Well, if no one knows the answer to those, I would need help with something else as well
1
0
nan
nan
nan
nan
5,448,389
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 03:43:18
Give the generator polynomials and the corresponding generator matrices and control polynomials of all 6-digit cyclic codes with 3 control digits over Z5.
1
0
nan
nan
nan
nan
5,448,390
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 03:43:43
And I'm absolutely confused on how I can do that
1
0
nan
nan
nan
nan
5,448,391
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
915938343857037314
Beth Green
02/01/2022 04:05:27
If u know inverse matrix, then just multiply inverse of the 3*3 matrix to both the sides. The LHS become only x1,x2,x3 and RHS will be inv(3*3) matrix * (1,3,1) matrix
0
1
nan
nan
nan
nan
5,448,392
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:27:27
i think i know how to do it, i think it's like gauss algorithm but instead of dividing, you multiply it by its multiplicative inverse in the finite field i think it helps if you make the multiplication table for the finite field first
0
1
nan
nan
nan
nan
5,448,393
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:29:13
Well, this was my first attempt, what do you mean by the finite field? Like what would I change?
https://cdn.discordapp.c…20201_102828.jpg
20220201_102828.jpg
1
0
nan
nan
nan
nan
5,448,394
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:29:20
Not sure what the finite field is
1
0
nan
nan
nan
nan
5,448,395
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:29:37
it's the Z7
0
1
nan
nan
nan
nan
5,448,396
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:29:45
Ahhh
1
0
nan
nan
nan
nan
5,448,397
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:31:33
So then I first multiply everything by 7? But that wouldnt make sense 🤔
1
0
nan
nan
nan
nan
5,448,398
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:32:27
no, yeah, try to make the multiplication table for the Z7 first
0
1
nan
nan
nan
nan
5,448,399
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:32:58
if you multiply everything by 7, it's like multiplying everything by 0
0
1
nan
nan
nan
nan
5,448,400
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:33:08
by 1
1
0
nan
nan
nan
nan
5,448,401
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:33:11
Z7 is the integers mod 7
0
1
nan
nan
nan
nan
5,448,402
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:33:31
$7\equiv0(mod 7)$
0
1
nan
nan
nan
nan
5,448,403
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:33:55
hmmm
1
0
nan
nan
nan
nan
5,448,404
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:35:32
I still dont get it :/
1
0
nan
nan
nan
nan
5,448,405
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:35:42
I know what mod 7 does
1
0
nan
nan
nan
nan
5,448,406
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:35:51
But I dont know how to apply it in that matrix
1
0
nan
nan
nan
nan
5,448,407
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:36:01
it's the remainder after the division
0
1
nan
nan
nan
nan
5,448,408
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:36:32
oh, i read that as i don't know
0
1
nan
nan
nan
nan
5,448,409
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:38:18
:/
1
0
nan
nan
nan
nan
5,448,410
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:39:43
ok, so, can you make the multiplication table for Z7?
0
1
nan
nan
nan
nan
5,448,411
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:43:33
Not really
1
0
348696743388381195
Reese Hernandez
Reese Hernandez
False
5,448,412
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:43:46
Ahhhhh
1
0
nan
nan
nan
nan
5,448,413
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:44:10
Do I need to just use the mod 7 on every single number there perhaps? 🤔
1
0
nan
nan
nan
nan
5,448,414
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:45:49
maybe that'll work, and instead of dividing, you multiply it by its multiplicative inverse
0
1
nan
nan
nan
nan
5,448,415
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:47:51
also, the multiplication table for Z7 is just like a normal multiplication table, but from 1 to 6 because after that I'll come back because of the mod 7 and the result is also mod 7
0
1
nan
nan
nan
nan
5,448,416
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:49:01
But how will I know whetherr thats correct and whether I will get the correct answers for that?
1
0
nan
nan
nan
nan
5,448,417
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:49:58
well, put the x1, x2, and x3 back into there and see if the result is the same
0
1
nan
nan
nan
nan
5,448,418
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:51:28
oh... Yeah true, mb
1
0
220517274845577216
Lena Jones
Lena Jones
False
5,448,419
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:53:13
also, it shouldn't have a number outside of Z7
0
1
nan
nan
nan
nan
5,448,420
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:53:52
Yes, but Is -1 to -6 also in that Z7 zone?
1
0
nan
nan
nan
nan
5,448,421
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:54:06
prrobably not right?
1
0
220517274845577216
Lena Jones
Lena Jones
False
5,448,422
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:54:24
you can add 7 to it and I'll be in it
0
1
nan
nan
nan
nan
5,448,423
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 04:54:43
like $-1\equiv6 (mod 7)$
0
1
nan
nan
nan
nan
5,448,424
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 04:54:53
ahh okay
1
0
nan
nan
nan
nan
5,448,425
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:02:02
Wait
1
0
nan
nan
nan
nan
5,448,426
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:02:19
I got a point numberr
1
0
nan
nan
nan
nan
5,448,427
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:02:27
and that shouldnt be in the zone
1
0
nan
nan
nan
nan
5,448,428
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 05:02:39
yup, only integers
0
1
nan
nan
nan
nan
5,448,429
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 05:03:28
did you divide?
0
1
nan
nan
nan
nan
5,448,430
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:03:42
Yes, I needed to divide
1
0
nan
nan
nan
nan
5,448,431
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:05:19
https://cdn.discordapp.c…20201_110500.jpg
20220201_110500.jpg
1
0
nan
nan
nan
nan
5,448,432
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 05:06:00
instead of dividing you need to find a number y such that\\ $x*y=1\ \text{(mod 7)}$
0
1
nan
nan
nan
nan
5,448,433
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 05:08:18
also, that's not how you read the x1, x2, or x3, you need to solve it to where each collum only have one number that's not 0 and all the others are 0
0
1
220517274845577216
Lena Jones
Lena Jones
False
5,448,434
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:09:03
aahhh
1
0
nan
nan
nan
nan
5,448,435
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:09:04
okay
1
0
nan
nan
nan
nan
5,448,436
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:09:06
I got it
1
0
nan
nan
nan
nan
5,448,437
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:09:30
I got the last part
1
0
nan
nan
nan
nan
5,448,438
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:09:50
But I didnt understand how to fix the point number thing
1
0
nan
nan
nan
nan
5,448,439
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:10:01
Here you can see my process
1
0
nan
nan
nan
nan
5,448,440
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 05:11:28
that's why it's easier if we have the multiplication table, so make something like this, and fill it in
https://cdn.discordapp.c…20201_171058.jpg
IMG_20220201_171058.jpg
0
1
nan
nan
nan
nan
5,448,441
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:11:39
okay
1
0
nan
nan
nan
nan
5,448,442
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 05:11:41
mod 7 of course
0
1
nan
nan
nan
nan
5,448,443
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:15:16
https://cdn.discordapp.c…20201_111509.jpg
20220201_111509.jpg
1
0
320090412012404737
Ronnie Martinez
Ronnie Martinez
False
5,448,444
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 05:16:38
yup, that's right
0
1
nan
nan
nan
nan
5,448,445
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 05:17:37
so, to find which number you have to multiply in order to get 1 you just start at that number and go right or down until you get to 1
0
1
nan
nan
nan
nan
5,448,446
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:18:45
im so confused rn
1
0
nan
nan
nan
nan
5,448,447
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
595185421743554570
Reginald Perez
02/01/2022 05:20:03
so, like for 4, you can multiply it by 2 and get 1
https://cdn.discordapp.c…20201_171922.jpg
IMG_20220201_171922.jpg
0
1
nan
nan
nan
nan
5,448,448
205,813
help-1
3cb2f7639f2549b1a75e0907763ac032
236549522178834432
Alison Garcia
02/01/2022 05:20:37
ah, yeah
1
0
nan
nan
nan
nan
5,448,449