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http://rosettacode.org/wiki/Create_a_two-dimensional_array_at_runtime | Create a two-dimensional array at runtime |
Data Structure
This illustrates a data structure, a means of storing data within a program.
You may see other such structures in the Data Structures category.
Get two integers from the user, then create a two-dimensional array where the two dimensions have the sizes given by those numbers, and which can be accessed in the most natural way possible. Write some element of that array, and then output that element. Finally destroy the array if not done by the language itself.
| #Clean | Clean | import StdEnv
Start :: *World -> { {Real} }
Start world
# (console, world) = stdio world
(_, dim1, console) = freadi console
(_, dim2, console) = freadi console
= createArray dim1 (createArray dim2 1.0) |
http://rosettacode.org/wiki/Create_a_two-dimensional_array_at_runtime | Create a two-dimensional array at runtime |
Data Structure
This illustrates a data structure, a means of storing data within a program.
You may see other such structures in the Data Structures category.
Get two integers from the user, then create a two-dimensional array where the two dimensions have the sizes given by those numbers, and which can be accessed in the most natural way possible. Write some element of that array, and then output that element. Finally destroy the array if not done by the language itself.
| #Clojure | Clojure | (let [rows (Integer/parseInt (read-line))
cols (Integer/parseInt (read-line))
a (to-array-2d (repeat rows (repeat cols nil)))]
(aset a 0 0 12)
(println "Element at 0,0:" (aget a 0 0))) |
http://rosettacode.org/wiki/Cumulative_standard_deviation | Cumulative standard deviation | Task[edit]
Write a stateful function, class, generator or co-routine that takes a series of floating point numbers, one at a time, and returns the running standard deviation of the series.
The task implementation should use the most natural programming style of those listed for the function in the implementation language; the task must state which is being used.
Do not apply Bessel's correction; the returned standard deviation should always be computed as if the sample seen so far is the entire population.
Test case
Use this to compute the standard deviation of this demonstration set,
{
2
,
4
,
4
,
4
,
5
,
5
,
7
,
9
}
{\displaystyle \{2,4,4,4,5,5,7,9\}}
, which is
2
{\displaystyle 2}
.
Related tasks
Random numbers
Tasks for calculating statistical measures
in one go
moving (sliding window)
moving (cumulative)
Mean
Arithmetic
Statistics/Basic
Averages/Arithmetic mean
Averages/Pythagorean means
Averages/Simple moving average
Geometric
Averages/Pythagorean means
Harmonic
Averages/Pythagorean means
Quadratic
Averages/Root mean square
Circular
Averages/Mean angle
Averages/Mean time of day
Median
Averages/Median
Mode
Averages/Mode
Standard deviation
Statistics/Basic
Cumulative standard deviation
| #Forth | Forth | : f+! ( x addr -- ) dup f@ f+ f! ;
: st-count ( stats -- n ) f@ ;
: st-sum ( stats -- sum ) float+ f@ ;
: st-sumsq ( stats -- sum*sum ) 2 floats + f@ ;
: st-mean ( stats -- mean )
dup st-sum st-count f/ ;
: st-variance ( stats -- var )
dup st-sumsq
dup st-mean fdup f* dup st-count f* f-
st-count f/ ;
: st-stddev ( stats -- stddev )
st-variance fsqrt ;
: st-add ( fnum stats -- )
dup
1e dup f+! float+
fdup dup f+! float+
fdup f* f+!
std-stddev ; |
http://rosettacode.org/wiki/CRC-32 | CRC-32 |
Task
Demonstrate a method of deriving the Cyclic Redundancy Check from within the language.
The result should be in accordance with ISO 3309, ITU-T V.42, Gzip and PNG.
Algorithms are described on Computation of CRC in Wikipedia.
This variant of CRC-32 uses LSB-first order, sets the initial CRC to FFFFFFFF16, and complements the final CRC.
For the purpose of this task, generate a CRC-32 checksum for the ASCII encoded string:
The quick brown fox jumps over the lazy dog
| #FreeBASIC | FreeBASIC | ' version 18-03-2017
' compile with: fbc -s console
Function crc32(buf As String) As UInteger<32>
Static As UInteger<32> table(256)
Static As UInteger<32> have_table
Dim As UInteger<32> crc, k
Dim As ULong i, j
If have_table = 0 Then
For i = 0 To 255
k = i
For j = 0 To 7
If (k And 1) Then
k Shr= 1
k Xor= &Hedb88320
Else
k Shr= 1
End If
table(i) = k
Next
Next
have_table = 1
End If
crc = Not crc ' crc = &Hffffffff
For i = 0 To Len(buf) -1
crc = (crc Shr 8) Xor table((crc And &hff) Xor buf[i])
Next
Return Not crc
End Function
' ------=< MAIN >=------
Dim As String l = "The quick brown fox jumps over the lazy dog"
Dim As UInteger<32> crc
Print "input = "; l
print
Print "The CRC-32 checksum = "; Hex(crc32(l), 8)
' empty keyboard buffer
While Inkey <> "" : Wend
Print : Print "hit any key to end program"
Sleep
End |
http://rosettacode.org/wiki/Count_the_coins | Count the coins | There are four types of common coins in US currency:
quarters (25 cents)
dimes (10 cents)
nickels (5 cents), and
pennies (1 cent)
There are six ways to make change for 15 cents:
A dime and a nickel
A dime and 5 pennies
3 nickels
2 nickels and 5 pennies
A nickel and 10 pennies
15 pennies
Task
How many ways are there to make change for a dollar using these common coins? (1 dollar = 100 cents).
Optional
Less common are dollar coins (100 cents); and very rare are half dollars (50 cents). With the addition of these two coins, how many ways are there to make change for $1000?
(Note: the answer is larger than 232).
References
an algorithm from the book Structure and Interpretation of Computer Programs.
an article in the algorithmist.
Change-making problem on Wikipedia.
| #AutoHotkey | AutoHotkey | countChange(amount){
return cc(amount, 4)
}
cc(amount, kindsOfCoins){
if ( amount == 0 )
return 1
if ( amount < 0 ) || ( kindsOfCoins == 0 )
return 0
return cc(amount, kindsOfCoins-1)
+ cc(amount - firstDenomination(kindsOfCoins), kindsOfCoins)
}
firstDenomination(kindsOfCoins){
return [1, 5, 10, 25][kindsOfCoins]
}
MsgBox % countChange(100) |
http://rosettacode.org/wiki/Count_occurrences_of_a_substring | Count occurrences of a substring | Task
Create a function, or show a built-in function, to count the number of non-overlapping occurrences of a substring inside a string.
The function should take two arguments:
the first argument being the string to search, and
the second a substring to be searched for.
It should return an integer count.
print countSubstring("the three truths","th")
3
// do not count substrings that overlap with previously-counted substrings:
print countSubstring("ababababab","abab")
2
The matching should yield the highest number of non-overlapping matches.
In general, this essentially means matching from left-to-right or right-to-left (see proof on talk page).
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #8086_Assembly | 8086 Assembly | cpu 8086
org 100h
section .text
jmp demo
;;; Count non-overlapping substrings [ES:DI] in [DS:SI]
;;; Return count in AX
subcnt: xor ax,ax ; Set count to 0
xor dl,dl ; Zero to compare to
mov bp,di ; Keep copy of substring pointer
.scan: cmp dl,[si] ; End of string?
je .out ; Then we're done
mov bx,si ; Keep copy of search position
mov di,bp ; Start at beginning of substring
.cmp: xor cx,cx
dec cx
repe cmpsb ; Scan until no match
dec si ; Go to first non-match
dec di
cmp dl,[es:di] ; Reached end of substring?
je .match ; Then we found a match
mov si,bx ; If not, continue searching one
inc si ; position further
jmp .scan
.match: inc ax ; Found a match - increment count
jmp .scan
.out: ret
;;; Test the routine on a few examples
demo: mov si,pairs
.loop: lodsw ; Load string pointer
test ax,ax ; If 0, stop
jz .out
xchg dx,ax
lodsw ; Load substring pointer
xchg di,ax
push si ; Keep example pointer
xchg si,dx
call subcnt ; Count substrings
call prax ; Print amount of substrings
pop si ; Restore example pointer
jmp .loop
.out: ret
;;; Print AX as number
prax: mov bx,num ; Pointer to end of number string
mov cx,10 ; Divisor
.dgt: xor dx,dx ; Divide by 10
div cx
add dl,'0' ; Add ASCII 0 to remainder
dec bx ; Store digit
mov [bx],dl
test ax,ax ; If number not zero yet
jnz .dgt ; Find rest of digits
mov dx,bx ; Print number string
mov ah,9
int 21h
ret
section .data
db '*****' ; Output number placeholder
num: db ' $'
;;; Examples
pairs: dw .str1,.sub1,.str2,.sub2,.str3,.sub3,0
.str1: db 'the three truths',0
.sub1: db 'th',0 ; result should be 3
.str2: db 'ababababab',0
.sub2: db 'abab',0 ; result should be 2
.str3: db 'cat',0
.sub3: db 'dog',0 ; result should be 0 |
http://rosettacode.org/wiki/Count_in_octal | Count in octal | Task
Produce a sequential count in octal, starting at zero, and using an increment of a one for each consecutive number.
Each number should appear on a single line, and the program should count until terminated, or until the maximum value of the numeric type in use is reached.
Related task
Integer sequence is a similar task without the use of octal numbers.
| #8080_Assembly | 8080 Assembly |
;-------------------------------------------------------
; useful equates
;-------------------------------------------------------
bdos equ 5 ; CP/M BDOS entry
conout equ 2 ; BDOS console output function
cr equ 13 ; ASCII carriage return
lf equ 10 ; ASCII line feed
;------------------------------------------------------
; main code begins here
;------------------------------------------------------
org 100h ; start of tpa under CP/M
lxi h,0 ; save CP/M's stack
dad sp
shld oldstk
lxi sp,stack ; set our own stack
lxi h,1 ; start counting at 1
count: call putoct
call crlf
inx h
mov a,h ; check for overflow (hl = 0)
ora l
jnz count
;
; all finished. clean up and exit.
;
lhld oldstk ; get CP/M's stack back
sphl ; restore it
ret ; back to the ccp w/o warm booting
;------------------------------------------------------
; Console output routine
; print character in A register to console
;------------------------------------------------------
putchr: push h
push d
push b
mov e,a ; character to E for CP/M
mvi c,2 ; console output function
call bdos ; call on BDOS to perform
pop b
pop d
pop h
ret
;------------------------------------------------------
; output CRLF to console
;------------------------------------------------------
crlf: mvi a,cr
call putchr
mvi a,lf
call putchr
ret
;------------------------------------------------------
; Octal output routine
; entry: hl = number to output on console in octal
; this is a recursive routine and uses 6 bytes of stack
; space for each digit
;------------------------------------------------------
putoct: push b
push d
push h
mvi b,3 ; hl = hl >> 3
div2: call shlr
dcr b
jnz div2
mov a,l ; test if hl = 0
ora h
cnz putoct
pop h ; get unshifted hl back
push h
mov a,l ; get low byte
ani 7 ; a = a mod 8
adi '0' ; make printable
call putchr
pop h
pop d
pop b
ret
;-------------------------------------------------------
; logical shift of 16-bit value in HL right by one bit
;-------------------------------------------------------
shlr: ora a ; clear carry
mov a,h ; begin with most significant byte
rar ; bit 0 goes into carry
mov h,a ; put shifted byte back
mov a,l ; get least significant byte
rar ; bit 0 of MSB has shifted in
mov l,a
ret
;-------------------------------------------------------
; data area
;-------------------------------------------------------
oldstk: dw 1
stack equ $+128 ; 64 level stack
;
end
|
http://rosettacode.org/wiki/Count_in_octal | Count in octal | Task
Produce a sequential count in octal, starting at zero, and using an increment of a one for each consecutive number.
Each number should appear on a single line, and the program should count until terminated, or until the maximum value of the numeric type in use is reached.
Related task
Integer sequence is a similar task without the use of octal numbers.
| #AArch64_Assembly | AArch64 Assembly |
/* ARM assembly AARCH64 Raspberry PI 3B */
/* program countOctal64.s */
/*******************************************/
/* Constantes file */
/*******************************************/
/* for this file see task include a file in language AArch64 assembly*/
.include "../includeConstantesARM64.inc"
/*********************************/
/* Initialized data */
/*********************************/
.data
sMessResult: .ascii "Count : "
sMessValeur: .fill 11, 1, ' ' // size => 11
szCarriageReturn: .asciz "\n"
/*********************************/
/* UnInitialized data */
/*********************************/
.bss
/*********************************/
/* code section */
/*********************************/
.text
.global main
main: // entry of program
mov x20,0 // loop indice
1: // begin loop
mov x0,x20
ldr x1,qAdrsMessValeur
bl conversion8 // call conversion octal
ldr x0,qAdrsMessResult
bl affichageMess // display message
add x20,x20,1
cmp x20,64
ble 1b
100: // standard end of the program
mov x0,0 // return code
mov x8,EXIT // request to exit program
svc 0 // perform the system call
qAdrsMessValeur: .quad sMessValeur
qAdrszCarriageReturn: .quad szCarriageReturn
qAdrsMessResult: .quad sMessResult
/******************************************************************/
/* Converting a register to octal */
/******************************************************************/
/* x0 contains value and x1 address area */
/* x0 return size of result (no zero final in area) */
/* area size => 11 bytes */
.equ LGZONECAL, 10
conversion8:
stp x1,lr,[sp,-16]! // save registers
mov x3,x1
mov x2,LGZONECAL
1: // start loop
mov x1,x0
lsr x0,x0,3 // / by 8
lsl x4,x0,3
sub x1,x1,x4 // compute remainder x1 - (x0 * 8)
add x1,x1,48 // digit
strb w1,[x3,x2] // store digit on area
cmp x0,0 // stop if quotient = 0
sub x4,x2,1
csel x2,x4,x2,ne
bne 1b // and loop
// and move digit from left of area
mov x4,0
2:
ldrb w1,[x3,x2]
strb w1,[x3,x4]
add x2,x2,1
add x4,x4,1
cmp x2,LGZONECAL
ble 2b
// and move spaces in end on area
mov x0,x4 // result length
mov x1,' ' // space
3:
strb w1,[x3,x4] // store space in area
add x4,x4,1 // next position
cmp x4,LGZONECAL
ble 3b // loop if x4 <= area size
100:
ldp x1,lr,[sp],16 // restaur 2 registers
ret // return to address lr x30
/********************************************************/
/* File Include fonctions */
/********************************************************/
/* for this file see task include a file in language AArch64 assembly */
.include "../includeARM64.inc"
|
http://rosettacode.org/wiki/Count_in_factors | Count in factors | Task
Write a program which counts up from 1, displaying each number as the multiplication of its prime factors.
For the purpose of this task, 1 (unity) may be shown as itself.
Example
2 is prime, so it would be shown as itself.
6 is not prime; it would be shown as
2
×
3
{\displaystyle 2\times 3}
.
2144 is not prime; it would be shown as
2
×
2
×
2
×
2
×
2
×
67
{\displaystyle 2\times 2\times 2\times 2\times 2\times 67}
.
Related tasks
prime decomposition
factors of an integer
Sieve of Eratosthenes
primality by trial division
factors of a Mersenne number
trial factoring of a Mersenne number
partition an integer X into N primes
| #360_Assembly | 360 Assembly | * Count in factors 24/03/2017
COUNTFAC CSECT assist plig\COUNTFAC
USING COUNTFAC,R13 base register
B 72(R15) skip savearea
DC 17F'0' savearea
STM R14,R12,12(R13) save previous context
ST R13,4(R15) link backward
ST R15,8(R13) link forward
LR R13,R15 set addressability
L R6,=F'1' i=1
DO WHILE=(C,R6,LE,=F'40') do i=1 to 40
LR R7,R6 n=i
MVI F,X'01' f=true
MVC PG,=CL80' ' clear buffer
LA R10,PG pgi=0
XDECO R6,XDEC edit i
MVC 0(12,R10),XDEC output i
LA R10,12(R10) pgi=pgi+12
MVC 0(1,R10),=C'=' output '='
LA R10,1(R10) pgi=pgi+1
IF C,R7,EQ,=F'1' THEN if n=1 then
MVI 0(R10),C'1' output n
ELSE , else
LA R8,2 p=2
DO WHILE=(CR,R8,LE,R7) do while p<=n
LR R4,R7 n
SRDA R4,32 ~
DR R4,R8 /p
IF LTR,R4,Z,R4 THEN if n//p=0 then
IF CLI,F,EQ,X'00' THEN if not f then
MVC 0(1,R10),=C'*' output '*'
LA R10,1(R10) pgi=pgi+1
ELSE , else
MVI F,X'00' f=false
ENDIF , endif
CVD R8,PP convert bin p to packed pp
MVC WORK12,MASX12 in fact L13
EDMK WORK12,PP+2 edit and mark
LA R9,WORK12+12 end of string(p)
SR R9,R1 li=lengh(p) {r1 from edmk}
MVC EDIT12,WORK12 L12<-L13
LA R4,EDIT12+12 source+12
SR R4,R9 -lengh(p)
LR R5,R9 lengh(p)
LR R2,R10 target ix
LR R3,R9 lengh(p)
MVCL R2,R4 f=f||p
AR R10,R9 ix=ix+lengh(p)
LR R4,R7 n
SRDA R4,32 ~
DR R4,R8 /p
LR R7,R5 n=n/p
ELSE , else
LA R8,1(R8) p=p+1
ENDIF , endif
ENDDO , enddo while
ENDIF , endif
XPRNT PG,L'PG print buffer
LA R6,1(R6) i++
ENDDO , enddo i
L R13,4(0,R13) restore previous savearea pointer
LM R14,R12,12(R13) restore previous context
XR R15,R15 rc=0
BR R14 exit
F DS X flag first factor
DS 0D alignment for cvd
PP DS PL8 packed CL8
EDIT12 DS CL12 target CL12
WORK12 DS CL13 char CL13
MASX12 DC X'40',9X'20',X'212060' CL13
XDEC DS CL12 temp
PG DS CL80 buffer
YREGS
END COUNTFAC |
http://rosettacode.org/wiki/Count_in_factors | Count in factors | Task
Write a program which counts up from 1, displaying each number as the multiplication of its prime factors.
For the purpose of this task, 1 (unity) may be shown as itself.
Example
2 is prime, so it would be shown as itself.
6 is not prime; it would be shown as
2
×
3
{\displaystyle 2\times 3}
.
2144 is not prime; it would be shown as
2
×
2
×
2
×
2
×
2
×
67
{\displaystyle 2\times 2\times 2\times 2\times 2\times 67}
.
Related tasks
prime decomposition
factors of an integer
Sieve of Eratosthenes
primality by trial division
factors of a Mersenne number
trial factoring of a Mersenne number
partition an integer X into N primes
| #Action.21 | Action! | PROC PrintFactors(CARD a)
BYTE notFirst
CARD p
IF a=1 THEN
PrintC(a) RETURN
FI
p=2 notFirst=0
WHILE p<=a
DO
IF a MOD p=0 THEN
IF notFirst THEN
Put('x)
FI
notFirst=1
PrintC(p)
a==/p
ELSE
p==+1
FI
OD
RETURN
PROC Main()
CARD i
FOR i=1 TO 1000
DO
PrintC(i) Put('=)
PrintFactors(i)
PutE()
OD
RETURN |
http://rosettacode.org/wiki/Create_an_HTML_table | Create an HTML table | Create an HTML table.
The table body should have at least three rows of three columns.
Each of these three columns should be labelled "X", "Y", and "Z".
An extra column should be added at either the extreme left or the extreme right of the table that has no heading, but is filled with sequential row numbers.
The rows of the "X", "Y", and "Z" columns should be filled with random or sequential integers having 4 digits or less.
The numbers should be aligned in the same fashion for all columns.
| #AutoHotkey | AutoHotkey | out = <table style="text-align:center; border: 1px solid"><th></th><th>X</th><th>Y</th><th>Z</th><tr>
Loop 4
out .= "`r`n<tr><th>" A_Index "</th><td>" Rand() "</td><td>" Rand() "</td><td>" Rand() "</tr>"
out .= "`r`n</table>"
MsgBox % clipboard := out
Rand(u=1000){
Random, n, 1, % u
return n
} |
http://rosettacode.org/wiki/Date_format | Date format | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Task
Display the current date in the formats of:
2007-11-23 and
Friday, November 23, 2007
| #Lua | Lua | print( os.date( "%Y-%m-%d" ) )
print( os.date( "%A, %B %d, %Y" ) ) |
http://rosettacode.org/wiki/Date_format | Date format | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Task
Display the current date in the formats of:
2007-11-23 and
Friday, November 23, 2007
| #M2000_Interpreter | M2000 Interpreter |
Print str$(today, "yyyy-mm-dd")
Print str$(today, "dddd, mmm, dd, yyyy")
|
http://rosettacode.org/wiki/Cramer%27s_rule | Cramer's rule | linear algebra
Cramer's rule
system of linear equations
Given
{
a
1
x
+
b
1
y
+
c
1
z
=
d
1
a
2
x
+
b
2
y
+
c
2
z
=
d
2
a
3
x
+
b
3
y
+
c
3
z
=
d
3
{\displaystyle \left\{{\begin{matrix}a_{1}x+b_{1}y+c_{1}z&={\color {red}d_{1}}\\a_{2}x+b_{2}y+c_{2}z&={\color {red}d_{2}}\\a_{3}x+b_{3}y+c_{3}z&={\color {red}d_{3}}\end{matrix}}\right.}
which in matrix format is
[
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
]
[
x
y
z
]
=
[
d
1
d
2
d
3
]
.
{\displaystyle {\begin{bmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{bmatrix}}{\begin{bmatrix}x\\y\\z\end{bmatrix}}={\begin{bmatrix}{\color {red}d_{1}}\\{\color {red}d_{2}}\\{\color {red}d_{3}}\end{bmatrix}}.}
Then the values of
x
,
y
{\displaystyle x,y}
and
z
{\displaystyle z}
can be found as follows:
x
=
|
d
1
b
1
c
1
d
2
b
2
c
2
d
3
b
3
c
3
|
|
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
|
,
y
=
|
a
1
d
1
c
1
a
2
d
2
c
2
a
3
d
3
c
3
|
|
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
|
,
and
z
=
|
a
1
b
1
d
1
a
2
b
2
d
2
a
3
b
3
d
3
|
|
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
|
.
{\displaystyle x={\frac {\begin{vmatrix}{\color {red}d_{1}}&b_{1}&c_{1}\\{\color {red}d_{2}}&b_{2}&c_{2}\\{\color {red}d_{3}}&b_{3}&c_{3}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}},\quad y={\frac {\begin{vmatrix}a_{1}&{\color {red}d_{1}}&c_{1}\\a_{2}&{\color {red}d_{2}}&c_{2}\\a_{3}&{\color {red}d_{3}}&c_{3}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}},{\text{ and }}z={\frac {\begin{vmatrix}a_{1}&b_{1}&{\color {red}d_{1}}\\a_{2}&b_{2}&{\color {red}d_{2}}\\a_{3}&b_{3}&{\color {red}d_{3}}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}}.}
Task
Given the following system of equations:
{
2
w
−
x
+
5
y
+
z
=
−
3
3
w
+
2
x
+
2
y
−
6
z
=
−
32
w
+
3
x
+
3
y
−
z
=
−
47
5
w
−
2
x
−
3
y
+
3
z
=
49
{\displaystyle {\begin{cases}2w-x+5y+z=-3\\3w+2x+2y-6z=-32\\w+3x+3y-z=-47\\5w-2x-3y+3z=49\\\end{cases}}}
solve for
w
{\displaystyle w}
,
x
{\displaystyle x}
,
y
{\displaystyle y}
and
z
{\displaystyle z}
, using Cramer's rule.
| #D | D | import std.array : array, uninitializedArray;
import std.range : iota;
import std.stdio : writeln;
import std.typecons : tuple;
alias vector = double[4];
alias matrix = vector[4];
auto johnsonTrotter(int n) {
auto p = iota(n).array;
auto q = iota(n).array;
auto d = uninitializedArray!(int[])(n);
d[] = -1;
auto sign = 1;
int[][] perms;
int[] signs;
void permute(int k) {
if (k >= n) {
perms ~= p.dup;
signs ~= sign;
sign *= -1;
return;
}
permute(k + 1);
foreach (i; 0..k) {
auto z = p[q[k] + d[k]];
p[q[k]] = z;
p[q[k] + d[k]] = k;
q[z] = q[k];
q[k] += d[k];
permute(k + 1);
}
d[k] *= -1;
}
permute(0);
return tuple!("sigmas", "signs")(perms, signs);
}
auto determinant(matrix m) {
auto jt = johnsonTrotter(m.length);
auto sum = 0.0;
foreach (i,sigma; jt.sigmas) {
auto prod = 1.0;
foreach (j,s; sigma) {
prod *= m[j][s];
}
sum += jt.signs[i] * prod;
}
return sum;
}
auto cramer(matrix m, vector d) {
auto divisor = determinant(m);
auto numerators = uninitializedArray!(matrix[])(m.length);
foreach (i; 0..m.length) {
foreach (j; 0..m.length) {
foreach (k; 0..m.length) {
numerators[i][j][k] = m[j][k];
}
}
}
vector v;
foreach (i; 0..m.length) {
foreach (j; 0..m.length) {
numerators[i][j][i] = d[j];
}
}
foreach (i; 0..m.length) {
v[i] = determinant(numerators[i]) / divisor;
}
return v;
}
void main() {
matrix m = [
[2.0, -1.0, 5.0, 1.0],
[3.0, 2.0, 2.0, -6.0],
[1.0, 3.0, 3.0, -1.0],
[5.0, -2.0, -3.0, 3.0]
];
vector d = [-3.0, -32.0, -47.0, 49.0];
auto wxyz = cramer(m, d);
writeln("w = ", wxyz[0], ", x = ", wxyz[1], ", y = ", wxyz[2], ", z = ", wxyz[3]);
} |
http://rosettacode.org/wiki/Create_a_file | Create a file | In this task, the job is to create a new empty file called "output.txt" of size 0 bytes
and an empty directory called "docs". This should be done twice: once "here", i.e. in the current working directory and once in the filesystem root.
| #BBC_BASIC | BBC BASIC | CLOSE #OPENOUT("output.txt")
CLOSE #OPENOUT("\output.txt")
*MKDIR docs
*MKDIR \docs |
http://rosettacode.org/wiki/Create_a_file | Create a file | In this task, the job is to create a new empty file called "output.txt" of size 0 bytes
and an empty directory called "docs". This should be done twice: once "here", i.e. in the current working directory and once in the filesystem root.
| #Blue | Blue | global _start
: syscall ( num:eax -- result:eax ) syscall ;
: exit ( status:edi -- noret ) 60 syscall ;
: bye ( -- noret ) 0 exit ;
: die ( err:eax -- noret ) neg exit ;
: unwrap ( result:eax -- value:eax ) dup 0 cmp ' die xl ;
: ordie ( result -- ) unwrap drop ;
: open ( pathname:edi flags:esi mode:edx -- fd:eax ) 2 syscall unwrap ;
: close ( fd:edi -- ) 3 syscall ordie ;
: mkdir ( pathname:edi mode:esi -- ) 83 syscall ordie ;
00001 const for-writing
00100 const create
01000 const truncate
: create-file ( pathname -- )
create for-writing or truncate or
0640 open close ;
: make-directory ( pathname -- ) 0750 mkdir ;
: create-output-file ( -- ) s" output.txt" drop create-file ;
: make-docs-directory ( -- ) s" docs" drop make-directory ;
: _start ( -- noret )
create-output-file
make-docs-directory
bye
; |
http://rosettacode.org/wiki/CSV_to_HTML_translation | CSV to HTML translation | Consider a simplified CSV format where all rows are separated by a newline
and all columns are separated by commas.
No commas are allowed as field data, but the data may contain
other characters and character sequences that would
normally be escaped when converted to HTML
Task
Create a function that takes a string representation of the CSV data
and returns a text string of an HTML table representing the CSV data.
Use the following data as the CSV text to convert, and show your output.
Character,Speech
The multitude,The messiah! Show us the messiah!
Brians mother,<angry>Now you listen here! He's not the messiah; he's a very naughty boy! Now go away!</angry>
The multitude,Who are you?
Brians mother,I'm his mother; that's who!
The multitude,Behold his mother! Behold his mother!
Extra credit
Optionally allow special formatting for the first row of the table as if it is the tables header row
(via <thead> preferably; CSS if you must).
| #C.23 | C# |
using System;
using System.Collections.Generic;
using System.Linq;
using System.Net;
class Program
{
private static string ConvertCsvToHtmlTable(string csvText)
{
//split the CSV, assume no commas or line breaks in text
List<List<string>> splitString = new List<List<string>>();
List<string> lineSplit = csvText.Split('\n').ToList();
foreach (string line in lineSplit)
{
splitString.Add(line.Split(',').ToList());
}
//encode text safely, and create table
string tableResult = "<table>";
foreach(List<string> splitLine in splitString)
{
tableResult += "<tr>";
foreach(string splitText in splitLine)
{
tableResult += "<td>" + WebUtility.HtmlEncode(splitText) + "</td>";
}
tableResult += "</tr>";
}
tableResult += "</table>";
return tableResult;
}
}
|
http://rosettacode.org/wiki/CSV_data_manipulation | CSV data manipulation | CSV spreadsheet files are suitable for storing tabular data in a relatively portable way.
The CSV format is flexible but somewhat ill-defined.
For present purposes, authors may assume that the data fields contain no commas, backslashes, or quotation marks.
Task
Read a CSV file, change some values and save the changes back to a file.
For this task we will use the following CSV file:
C1,C2,C3,C4,C5
1,5,9,13,17
2,6,10,14,18
3,7,11,15,19
4,8,12,16,20
Suggestions
Show how to add a column, headed 'SUM', of the sums of the rows.
If possible, illustrate the use of built-in or standard functions, methods, or libraries, that handle generic CSV files.
| #Go | Go | package main
import (
"encoding/csv"
"log"
"os"
"strconv"
)
func main() {
rows := readSample()
appendSum(rows)
writeChanges(rows)
}
func readSample() [][]string {
f, err := os.Open("sample.csv")
if err != nil {
log.Fatal(err)
}
rows, err := csv.NewReader(f).ReadAll()
f.Close()
if err != nil {
log.Fatal(err)
}
return rows
}
func appendSum(rows [][]string) {
rows[0] = append(rows[0], "SUM")
for i := 1; i < len(rows); i++ {
rows[i] = append(rows[i], sum(rows[i]))
}
}
func sum(row []string) string {
sum := 0
for _, s := range row {
x, err := strconv.Atoi(s)
if err != nil {
return "NA"
}
sum += x
}
return strconv.Itoa(sum)
}
func writeChanges(rows [][]string) {
f, err := os.Create("output.csv")
if err != nil {
log.Fatal(err)
}
err = csv.NewWriter(f).WriteAll(rows)
f.Close()
if err != nil {
log.Fatal(err)
}
} |
http://rosettacode.org/wiki/Damm_algorithm | Damm algorithm | The Damm algorithm is a checksum algorithm which detects all single digit errors and adjacent transposition errors.
The algorithm is named after H. Michael Damm.
Task
Verify the checksum, stored as last digit of an input.
| #Python | Python | def damm(num: int) -> bool:
row = 0
for digit in str(num):
row = _matrix[row][int(digit)]
return row == 0
_matrix = (
(0, 3, 1, 7, 5, 9, 8, 6, 4, 2),
(7, 0, 9, 2, 1, 5, 4, 8, 6, 3),
(4, 2, 0, 6, 8, 7, 1, 3, 5, 9),
(1, 7, 5, 0, 9, 8, 3, 4, 2, 6),
(6, 1, 2, 3, 0, 4, 5, 9, 7, 8),
(3, 6, 7, 4, 2, 0, 9, 5, 8, 1),
(5, 8, 6, 9, 7, 2, 0, 1, 3, 4),
(8, 9, 4, 5, 3, 6, 2, 0, 1, 7),
(9, 4, 3, 8, 6, 1, 7, 2, 0, 5),
(2, 5, 8, 1, 4, 3, 6, 7, 9, 0)
)
if __name__ == '__main__':
for test in [5724, 5727, 112946]:
print(f'{test}\t Validates as: {damm(test)}') |
http://rosettacode.org/wiki/Cuban_primes | Cuban primes | The name cuban has nothing to do with Cuba (the country), but has to do with the
fact that cubes (3rd powers) play a role in its definition.
Some definitions of cuban primes
primes which are the difference of two consecutive cubes.
primes of the form: (n+1)3 - n3.
primes of the form: n3 - (n-1)3.
primes p such that n2(p+n) is a cube for some n>0.
primes p such that 4p = 1 + 3n2.
Cuban primes were named in 1923 by Allan Joseph Champneys Cunningham.
Task requirements
show the first 200 cuban primes (in a multi─line horizontal format).
show the 100,000th cuban prime.
show all cuban primes with commas (if appropriate).
show all output here.
Note that cuban prime isn't capitalized (as it doesn't refer to the nation of Cuba).
Also see
Wikipedia entry: cuban prime.
MathWorld entry: cuban prime.
The OEIS entry: A002407. The 100,000th cuban prime can be verified in the 2nd example on this OEIS web page.
| #Phix | Phix | with javascript_semantics
include mpfr.e
integer np = 0,
i = 2
mpz p3 = mpz_init(1*1*1),
i3 = mpz_init(),
p = mpz_init(),
pn = mpz_init()
printf(1,"The first 200 cuban primes are:\n")
sequence first200 = {}
atom t0 = time()
constant lim = iff(platform()=JS?10000:100000)
while np<lim do
mpz_ui_pow_ui(i3,i,3)
mpz_sub(p,i3,p3)
if mpz_prime(p) then
mpz_set(pn,p)
np += 1
if np<=200 then
first200 = append(first200,sprintf("%,9d",mpz_get_integer(pn)))
if mod(np,10)=0 then
printf(1,"%s\n",join(first200[-10..-1]))
end if
end if
end if
mpz_set(p3,i3)
i += 1
end while
printf(1,"\nThe %,dth cuban prime is %s\n",{np,mpz_get_str(pn,comma_fill:=true)})
{p3,i3,p} = mpz_free({p3,i3,p})
?elapsed(time()-t0)
|
http://rosettacode.org/wiki/Currying | Currying |
This page uses content from Wikipedia. The original article was at Currying. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
Task
Create a simple demonstrative example of Currying in a specific language.
Add any historic details as to how the feature made its way into the language.
| #TXR | TXR | (op - 10 @1 @2 5) |
http://rosettacode.org/wiki/Currying | Currying |
This page uses content from Wikipedia. The original article was at Currying. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
Task
Create a simple demonstrative example of Currying in a specific language.
Add any historic details as to how the feature made its way into the language.
| #Vala | Vala | delegate double Dbl_Op(double d);
Dbl_Op curried_add(double a) {
return (b) => a + b;
}
void main() {
print(@"$(curried_add(3.0)(4.0))\n");
double sum2 = curried_add(2.0) (curried_add(3.0)(4.0)); //sum2 = 9
print(@"$sum2\n");
} |
http://rosettacode.org/wiki/Currying | Currying |
This page uses content from Wikipedia. The original article was at Currying. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
Task
Create a simple demonstrative example of Currying in a specific language.
Add any historic details as to how the feature made its way into the language.
| #Visual_Basic_.NET | Visual Basic .NET | Option Explicit On
Option Infer On
Option Strict On
Module Currying
' The trivial curry.
Function Curry(Of T1, TResult)(func As Func(Of T1, TResult)) As Func(Of T1, TResult)
' At least satisfy the implicit contract that the result isn't reference-equal to the original function.
Return Function(a) func(a)
End Function
Function Curry(Of T1, T2, TResult)(func As Func(Of T1, T2, TResult)) As Func(Of T1, Func(Of T2, TResult))
Return Function(a) Function(b) func(a, b)
End Function
Function Curry(Of T1, T2, T3, TResult)(func As Func(Of T1, T2, T3, TResult)) As Func(Of T1, Func(Of T2, Func(Of T3, TResult)))
Return Function(a) Function(b) Function(c) func(a, b, c)
End Function
' And so on.
End Module |
http://rosettacode.org/wiki/Date_manipulation | Date manipulation | Task
Given the date string "March 7 2009 7:30pm EST",
output the time 12 hours later in any human-readable format.
As extra credit, display the resulting time in a time zone different from your own.
| #Smalltalk | Smalltalk | DateTime extend [
setYear: aNum [ year := aNum ]
].
Object subclass: DateTimeTZ [
|dateAndTime timeZoneDST timeZoneName timeZoneVar|
DateTimeTZ class >> new [ ^(super basicNew) ]
DateTimeTZ class >> readFromWithMeridian: aStream andTimeZone: aDict [
|me|
me := self new.
^ me initWithMeridian: aStream andTimeZone: aDict
]
initWithMeridian: aStream andTimeZone: aDict [ |s|
dateAndTime := DateTime readFrom: aStream copy.
s := aStream collection asString.
s =~ '[pP][mM]'
ifMatched: [ :m |
dateAndTime := dateAndTime + (Duration days: 0 hours: 12 minutes: 0 seconds: 0)
].
aDict keysAndValuesDo: [ :k :v |
s =~ k
ifMatched: [ :x |
dateAndTime := dateAndTime setOffset: (v at: 1).
timeZoneDST := (v at: 2) setOffset: (v at: 1).
timeZoneVar := (v at: 3).
timeZoneDST setYear: (self year). "ignore the year"
timeZoneName := k
]
].
^ self
]
setYear: aNum [ dateAndTime setYear: aNum ]
year [ ^ dateAndTime year ]
timeZoneName [ ^timeZoneName ]
+ aDuration [ |n|
n := dateAndTime + aDuration.
(n > timeZoneDST) ifTrue: [ n := n + timeZoneVar ].
^ (self copy dateTime: n)
]
dateTime [ ^dateAndTime ]
dateTime: aDT [ dateAndTime := aDT ]
]. |
http://rosettacode.org/wiki/Day_of_the_week | Day of the week | A company decides that whenever Xmas falls on a Sunday they will give their workers all extra paid holidays so that, together with any public holidays, workers will not have to work the following week (between the 25th of December and the first of January).
Task
In what years between 2008 and 2121 will the 25th of December be a Sunday?
Using any standard date handling libraries of your programming language;
compare the dates calculated with the output of other languages to discover any anomalies in the handling of dates which may be due to, for example, overflow in types used to represent dates/times similar to y2k type problems.
| #MUMPS | MUMPS |
DOWHOLIDAY
;In what years between 2008 and 2121 will December 25 be a Sunday?
;Uses the VA's public domain routine %DTC (Part of the Kernel) named here DIDTC
NEW BDT,EDT,CHECK,CHKFOR,LIST,I,X,Y
;BDT - the beginning year to check
;EDT - the end year to check
;BDT and EDT are year offsets from the epoch date 1/1/1700
;CHECK - the month and day to look at
;CHKFOR - what day of the week to look for
;LIST - list of years in which the condition is true
;I - the year currently being checked
;X - the date in an "internal" format, for input to DOW^DIDTC
;Y - the output from DOW^DIDTC
SET BDT=308,EDT=421,CHECK="1225",CHKFOR=0,LIST=""
FOR I=BDT:1:EDT SET X=I_CHECK D DOW^DIDTC SET:(Y=0) LIST=$SELECT($LENGTH(LIST):LIST_", ",1:"")_(I+1700)
IF $LENGTH(LIST)=0 WRITE !,"There are no years that have Christmas on a Sunday in the given range."
IF $LENGTH(LIST) WRITE !,"The following years have Christmas on a Sunday: ",LIST
KILL BDT,EDT,CHECK,CHKFOR,LIST,I,X,Y
QUIT
|
http://rosettacode.org/wiki/Day_of_the_week | Day of the week | A company decides that whenever Xmas falls on a Sunday they will give their workers all extra paid holidays so that, together with any public holidays, workers will not have to work the following week (between the 25th of December and the first of January).
Task
In what years between 2008 and 2121 will the 25th of December be a Sunday?
Using any standard date handling libraries of your programming language;
compare the dates calculated with the output of other languages to discover any anomalies in the handling of dates which may be due to, for example, overflow in types used to represent dates/times similar to y2k type problems.
| #Nanoquery | Nanoquery | import Nanoquery.Util
// loop through the years 2008 through 2121
for year in range(2008, 2121)
if (new(Date,"12/25/" + str(year)).getDayOfWeek() = "Sunday")
println "In " + year + ", December 25th is a Sunday."
end if
end for |
http://rosettacode.org/wiki/CUSIP | CUSIP |
This page uses content from Wikipedia. The original article was at CUSIP. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
A CUSIP is a nine-character alphanumeric code that identifies a North American financial security for the purposes of facilitating clearing and settlement of trades. The CUSIP was adopted as an American National Standard under Accredited Standards X9.6.
Task
Ensure the last digit (i.e., the check digit) of the CUSIP code (the 1st column) is correct, against the following:
037833100 Apple Incorporated
17275R102 Cisco Systems
38259P508 Google Incorporated
594918104 Microsoft Corporation
68389X106 Oracle Corporation (incorrect)
68389X105 Oracle Corporation
Example pseudo-code below.
algorithm Cusip-Check-Digit(cusip) is
Input: an 8-character CUSIP
sum := 0
for 1 ≤ i ≤ 8 do
c := the ith character of cusip
if c is a digit then
v := numeric value of the digit c
else if c is a letter then
p := ordinal position of c in the alphabet (A=1, B=2...)
v := p + 9
else if c = "*" then
v := 36
else if c = "@" then
v := 37
else if' c = "#" then
v := 38
end if
if i is even then
v := v × 2
end if
sum := sum + int ( v div 10 ) + v mod 10
repeat
return (10 - (sum mod 10)) mod 10
end function
See related tasks
SEDOL
ISIN
| #Tcl | Tcl | proc ordinal-of-alpha {c} { ;# returns ordinal position of c in the alphabet (A=1, B=2...)
lsearch {_ A B C D E F G H I J K L M N O P Q R S T U V W X Y Z} [string toupper $c]
}
proc Cusip-Check-Digit {cusip} { ;# algorithm Cusip-Check-Digit(cusip) is
if {[string length $cusip] != 8} { ;# Input: an 8-character CUSIP
return false
}
set sum 0 ;# sum := 0
for {set i 1} {$i <= 8} {incr i} { ;# for 1 ≤ i ≤ 8 do
set c [string index $cusip $i-1] ;# c := the ith character of cusip
if {[string is digit $c]} { ;# if c is a digit then
set v $c ;# v := numeric value of the digit c
} elseif {[string is alpha $c]} { ;# else if c is a letter then
set p [ordinal-of-alpha $c] ;# p := ordinal position of c in the alphabet (A=1, B=2...)
set v [expr {$p + 9}] ;# v := p + 9
} elseif {$c eq "*"} { ;# else if c = "*" then
set v 36 ;# v := 36
} elseif {$c eq "@"} { ;# else if c = "@" then
set v 37 ;# v := 37
} elseif {$c eq "#"} { ;# else if c = "#" then
set v 38 ;# v := 38
} ;# end if
if {$i % 2 == 0} { ;# if i is even then
set v [expr {$v * 2}] ;# v := v × 2
} ;# end if
incr sum [expr {$v / 10 + $v % 10}] ;# sum := sum + int ( v div 10 ) + v mod 10
} ;# repeat
expr {(10 - ($sum % 10)) % 10} ;# return (10 - (sum mod 10)) mod 10
}
proc check-cusip {cusip} {
set last [string index $cusip end]
set cusip [string range $cusip 0 end-1]
expr {$last eq [Cusip-Check-Digit $cusip]}
} |
http://rosettacode.org/wiki/Create_a_two-dimensional_array_at_runtime | Create a two-dimensional array at runtime |
Data Structure
This illustrates a data structure, a means of storing data within a program.
You may see other such structures in the Data Structures category.
Get two integers from the user, then create a two-dimensional array where the two dimensions have the sizes given by those numbers, and which can be accessed in the most natural way possible. Write some element of that array, and then output that element. Finally destroy the array if not done by the language itself.
| #CLU | CLU | prompt = proc (s: string) returns (int)
stream$puts(stream$primary_output(), s)
return(int$parse(stream$getl(stream$primary_input())))
end prompt
start_up = proc ()
po: stream := stream$primary_output()
% Ask for width and height
width: int := prompt("Width? ")
height: int := prompt("Height? ")
% Create an array of arrays.
% In order to actually create separate arrays, rather than repeating
% a reference to the same array over and over, fill_copy must be used.
arr: array[array[int]] :=
array[array[int]]$fill_copy(1, width, array[int]$fill(1, height, 0))
% Set a value
x: int := 1+width/2
y: int := 1+height/2
arr[x][y] := 123
% Retrieve the value
stream$putl(po, "arr[" || int$unparse(x) || "][" || int$unparse(y)
|| "] = " || int$unparse(arr[x][y]))
% The array will be automatically garbage-collected once there
% are no more references to it.
end start_up |
http://rosettacode.org/wiki/Create_a_two-dimensional_array_at_runtime | Create a two-dimensional array at runtime |
Data Structure
This illustrates a data structure, a means of storing data within a program.
You may see other such structures in the Data Structures category.
Get two integers from the user, then create a two-dimensional array where the two dimensions have the sizes given by those numbers, and which can be accessed in the most natural way possible. Write some element of that array, and then output that element. Finally destroy the array if not done by the language itself.
| #Common_Lisp | Common Lisp | (let ((d1 (read))
(d2 (read)))
(assert (and (typep d1 '(integer 1))
(typep d2 '(integer 1)))
(d1 d2))
(let ((array (make-array (list d1 d2) :initial-element nil))
(p1 0)
(p2 (floor d2 2)))
(setf (aref array p1 p2) t)
(print (aref array p1 p2)))) |
http://rosettacode.org/wiki/Cumulative_standard_deviation | Cumulative standard deviation | Task[edit]
Write a stateful function, class, generator or co-routine that takes a series of floating point numbers, one at a time, and returns the running standard deviation of the series.
The task implementation should use the most natural programming style of those listed for the function in the implementation language; the task must state which is being used.
Do not apply Bessel's correction; the returned standard deviation should always be computed as if the sample seen so far is the entire population.
Test case
Use this to compute the standard deviation of this demonstration set,
{
2
,
4
,
4
,
4
,
5
,
5
,
7
,
9
}
{\displaystyle \{2,4,4,4,5,5,7,9\}}
, which is
2
{\displaystyle 2}
.
Related tasks
Random numbers
Tasks for calculating statistical measures
in one go
moving (sliding window)
moving (cumulative)
Mean
Arithmetic
Statistics/Basic
Averages/Arithmetic mean
Averages/Pythagorean means
Averages/Simple moving average
Geometric
Averages/Pythagorean means
Harmonic
Averages/Pythagorean means
Quadratic
Averages/Root mean square
Circular
Averages/Mean angle
Averages/Mean time of day
Median
Averages/Median
Mode
Averages/Mode
Standard deviation
Statistics/Basic
Cumulative standard deviation
| #Fortran | Fortran |
program standard_deviation
implicit none
integer(kind=4), parameter :: dp = kind(0.0d0)
real(kind=dp), dimension(:), allocatable :: vals
integer(kind=4) :: i
real(kind=dp), dimension(8) :: sample_data = (/ 2, 4, 4, 4, 5, 5, 7, 9 /)
do i = lbound(sample_data, 1), ubound(sample_data, 1)
call sample_add(vals, sample_data(i))
write(*, fmt='(''#'',I1,1X,''value = '',F3.1,1X,''stddev ='',1X,F10.8)') &
i, sample_data(i), stddev(vals)
end do
if (allocated(vals)) deallocate(vals)
contains
! Adds value :val: to array :population: dynamically resizing array
subroutine sample_add(population, val)
real(kind=dp), dimension(:), allocatable, intent (inout) :: population
real(kind=dp), intent (in) :: val
real(kind=dp), dimension(:), allocatable :: tmp
integer(kind=4) :: n
if (.not. allocated(population)) then
allocate(population(1))
population(1) = val
else
n = size(population)
call move_alloc(population, tmp)
allocate(population(n + 1))
population(1:n) = tmp
population(n + 1) = val
endif
end subroutine sample_add
! Calculates standard deviation for given set of values
real(kind=dp) function stddev(vals)
real(kind=dp), dimension(:), intent(in) :: vals
real(kind=dp) :: mean
integer(kind=4) :: n
n = size(vals)
mean = sum(vals)/n
stddev = sqrt(sum((vals - mean)**2)/n)
end function stddev
end program standard_deviation
|
http://rosettacode.org/wiki/CRC-32 | CRC-32 |
Task
Demonstrate a method of deriving the Cyclic Redundancy Check from within the language.
The result should be in accordance with ISO 3309, ITU-T V.42, Gzip and PNG.
Algorithms are described on Computation of CRC in Wikipedia.
This variant of CRC-32 uses LSB-first order, sets the initial CRC to FFFFFFFF16, and complements the final CRC.
For the purpose of this task, generate a CRC-32 checksum for the ASCII encoded string:
The quick brown fox jumps over the lazy dog
| #Go | Go | package main
import (
"fmt"
"hash/crc32"
)
func main() {
s := []byte("The quick brown fox jumps over the lazy dog")
result := crc32.ChecksumIEEE(s)
fmt.Printf("%X\n", result)
} |
http://rosettacode.org/wiki/CRC-32 | CRC-32 |
Task
Demonstrate a method of deriving the Cyclic Redundancy Check from within the language.
The result should be in accordance with ISO 3309, ITU-T V.42, Gzip and PNG.
Algorithms are described on Computation of CRC in Wikipedia.
This variant of CRC-32 uses LSB-first order, sets the initial CRC to FFFFFFFF16, and complements the final CRC.
For the purpose of this task, generate a CRC-32 checksum for the ASCII encoded string:
The quick brown fox jumps over the lazy dog
| #Groovy | Groovy | def crc32(byte[] bytes) {
new java.util.zip.CRC32().with { update bytes; value }
} |
http://rosettacode.org/wiki/Count_the_coins | Count the coins | There are four types of common coins in US currency:
quarters (25 cents)
dimes (10 cents)
nickels (5 cents), and
pennies (1 cent)
There are six ways to make change for 15 cents:
A dime and a nickel
A dime and 5 pennies
3 nickels
2 nickels and 5 pennies
A nickel and 10 pennies
15 pennies
Task
How many ways are there to make change for a dollar using these common coins? (1 dollar = 100 cents).
Optional
Less common are dollar coins (100 cents); and very rare are half dollars (50 cents). With the addition of these two coins, how many ways are there to make change for $1000?
(Note: the answer is larger than 232).
References
an algorithm from the book Structure and Interpretation of Computer Programs.
an article in the algorithmist.
Change-making problem on Wikipedia.
| #AWK | AWK | #!/usr/bin/awk -f
BEGIN {
print cc(100)
exit
}
function cc(amount, coins, numPennies, numNickles, numQuarters, p, n, d, q, s, count) {
numPennies = amount
numNickles = int(amount / 5)
numDimes = int(amount / 10)
numQuarters = int(amount / 25)
count = 0
for (p = 0; p <= numPennies; p++) {
for (n = 0; n <= numNickles; n++) {
for (d = 0; d <= numDimes; d++) {
for (q = 0; q <= numQuarters; q++) {
s = p + n * 5 + d * 10 + q * 25;
if (s == 100) count++;
}
}
}
}
return count;
}
|
http://rosettacode.org/wiki/Count_occurrences_of_a_substring | Count occurrences of a substring | Task
Create a function, or show a built-in function, to count the number of non-overlapping occurrences of a substring inside a string.
The function should take two arguments:
the first argument being the string to search, and
the second a substring to be searched for.
It should return an integer count.
print countSubstring("the three truths","th")
3
// do not count substrings that overlap with previously-counted substrings:
print countSubstring("ababababab","abab")
2
The matching should yield the highest number of non-overlapping matches.
In general, this essentially means matching from left-to-right or right-to-left (see proof on talk page).
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #Action.21 | Action! | BYTE FUNC CountSubstring(CHAR ARRAY s,sub)
BYTE i,j,res,found
i=1 res=0
WHILE i-1+sub(0)<=s(0)
DO
found=1
FOR j=1 TO sub(0)
DO
IF s(j+i-1)#sub(j) THEN
found=0
EXIT
FI
OD
IF found=1 THEN
i==+sub(0)
res==+1
ELSE
i==+1
FI
OD
RETURN (res)
PROC Test(CHAR ARRAY s,sub)
BYTE c
c=CountSubstring(s,sub)
PrintF("%B ""%S"" in ""%S""%E",c,sub,s)
RETURN
PROC Main()
Test("the three truths","th")
Test("ababababab","abab")
Test("11111111","11")
Test("abcdefg","123")
RETURN |
http://rosettacode.org/wiki/Count_occurrences_of_a_substring | Count occurrences of a substring | Task
Create a function, or show a built-in function, to count the number of non-overlapping occurrences of a substring inside a string.
The function should take two arguments:
the first argument being the string to search, and
the second a substring to be searched for.
It should return an integer count.
print countSubstring("the three truths","th")
3
// do not count substrings that overlap with previously-counted substrings:
print countSubstring("ababababab","abab")
2
The matching should yield the highest number of non-overlapping matches.
In general, this essentially means matching from left-to-right or right-to-left (see proof on talk page).
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #Ada | Ada | with Ada.Strings.Fixed, Ada.Integer_Text_IO;
procedure Substrings is
begin
Ada.Integer_Text_IO.Put (Ada.Strings.Fixed.Count (Source => "the three truths",
Pattern => "th"));
Ada.Integer_Text_IO.Put (Ada.Strings.Fixed.Count (Source => "ababababab",
Pattern => "abab"));
end Substrings; |
http://rosettacode.org/wiki/Count_in_octal | Count in octal | Task
Produce a sequential count in octal, starting at zero, and using an increment of a one for each consecutive number.
Each number should appear on a single line, and the program should count until terminated, or until the maximum value of the numeric type in use is reached.
Related task
Integer sequence is a similar task without the use of octal numbers.
| #Action.21 | Action! | PROC PrintOctal(CARD v)
CHAR ARRAY a(6)
BYTE i=[0]
DO
a(i)=(v&7)+'0
i==+1
v=v RSH 3
UNTIL v=0
OD
DO
i==-1
Put(a(i))
UNTIL i=0
OD
RETURN
PROC Main()
CARD i=[0]
DO
PrintF("decimal=%U octal=",i)
PrintOctal(i) PutE()
i==+1
UNTIL i=0
OD
RETURN |
http://rosettacode.org/wiki/Count_in_octal | Count in octal | Task
Produce a sequential count in octal, starting at zero, and using an increment of a one for each consecutive number.
Each number should appear on a single line, and the program should count until terminated, or until the maximum value of the numeric type in use is reached.
Related task
Integer sequence is a similar task without the use of octal numbers.
| #Ada | Ada | with Ada.Text_IO;
procedure Octal is
package IIO is new Ada.Text_IO.Integer_IO(Integer);
begin
for I in 0 .. Integer'Last loop
IIO.Put(I, Base => 8);
Ada.Text_IO.New_Line;
end loop;
end Octal; |
http://rosettacode.org/wiki/Count_in_factors | Count in factors | Task
Write a program which counts up from 1, displaying each number as the multiplication of its prime factors.
For the purpose of this task, 1 (unity) may be shown as itself.
Example
2 is prime, so it would be shown as itself.
6 is not prime; it would be shown as
2
×
3
{\displaystyle 2\times 3}
.
2144 is not prime; it would be shown as
2
×
2
×
2
×
2
×
2
×
67
{\displaystyle 2\times 2\times 2\times 2\times 2\times 67}
.
Related tasks
prime decomposition
factors of an integer
Sieve of Eratosthenes
primality by trial division
factors of a Mersenne number
trial factoring of a Mersenne number
partition an integer X into N primes
| #Ada | Ada | with Ada.Command_Line, Ada.Text_IO, Prime_Numbers;
procedure Count is
package Prime_Nums is new Prime_Numbers
(Number => Natural, Zero => 0, One => 1, Two => 2); use Prime_Nums;
procedure Put (List : Number_List) is
begin
for Index in List'Range loop
Ada.Text_IO.Put (Integer'Image (List (Index)));
if Index /= List'Last then
Ada.Text_IO.Put (" x");
end if;
end loop;
end Put;
N : Natural := 1;
Max_N : Natural := 15; -- the default for Max_N
begin
if Ada.Command_Line.Argument_Count = 1 then -- read Max_N from command line
Max_N := Integer'Value (Ada.Command_Line.Argument (1));
end if; -- else use the default
loop
Ada.Text_IO.Put (Integer'Image (N) & ": ");
Put (Decompose (N));
Ada.Text_IO.New_Line;
N := N + 1;
exit when N > Max_N;
end loop;
end Count; |
http://rosettacode.org/wiki/Create_an_HTML_table | Create an HTML table | Create an HTML table.
The table body should have at least three rows of three columns.
Each of these three columns should be labelled "X", "Y", and "Z".
An extra column should be added at either the extreme left or the extreme right of the table that has no heading, but is filled with sequential row numbers.
The rows of the "X", "Y", and "Z" columns should be filled with random or sequential integers having 4 digits or less.
The numbers should be aligned in the same fashion for all columns.
| #AWK | AWK | #!/usr/bin/awk -f
BEGIN {
print "<table>\n <thead align = \"right\">"
printf " <tr><th></th><td>X</td><td>Y</td><td>Z</td></tr>\n </thead>\n <tbody align = \"right\">\n"
for (i=1; i<=10; i++) {
printf " <tr><td>%2i</td><td>%5i</td><td>%5i</td><td>%5i</td></tr>\n",i, 10*i, 100*i, 1000*i-1
}
print " </tbody>\n</table>\n"
} |
http://rosettacode.org/wiki/Date_format | Date format | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Task
Display the current date in the formats of:
2007-11-23 and
Friday, November 23, 2007
| #Maple | Maple |
with(StringTools);
FormatTime("%Y-%m-%d")
FormatTime("%A,%B %d, %y")
|
http://rosettacode.org/wiki/Date_format | Date format | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Task
Display the current date in the formats of:
2007-11-23 and
Friday, November 23, 2007
| #Mathematica.2FWolfram_Language | Mathematica/Wolfram Language | DateString[{"Year", "-", "Month", "-", "Day"}]
DateString[{"DayName", ", ", "MonthName", " ", "Day", ", ", "Year"}] |
http://rosettacode.org/wiki/Cramer%27s_rule | Cramer's rule | linear algebra
Cramer's rule
system of linear equations
Given
{
a
1
x
+
b
1
y
+
c
1
z
=
d
1
a
2
x
+
b
2
y
+
c
2
z
=
d
2
a
3
x
+
b
3
y
+
c
3
z
=
d
3
{\displaystyle \left\{{\begin{matrix}a_{1}x+b_{1}y+c_{1}z&={\color {red}d_{1}}\\a_{2}x+b_{2}y+c_{2}z&={\color {red}d_{2}}\\a_{3}x+b_{3}y+c_{3}z&={\color {red}d_{3}}\end{matrix}}\right.}
which in matrix format is
[
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
]
[
x
y
z
]
=
[
d
1
d
2
d
3
]
.
{\displaystyle {\begin{bmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{bmatrix}}{\begin{bmatrix}x\\y\\z\end{bmatrix}}={\begin{bmatrix}{\color {red}d_{1}}\\{\color {red}d_{2}}\\{\color {red}d_{3}}\end{bmatrix}}.}
Then the values of
x
,
y
{\displaystyle x,y}
and
z
{\displaystyle z}
can be found as follows:
x
=
|
d
1
b
1
c
1
d
2
b
2
c
2
d
3
b
3
c
3
|
|
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
|
,
y
=
|
a
1
d
1
c
1
a
2
d
2
c
2
a
3
d
3
c
3
|
|
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
|
,
and
z
=
|
a
1
b
1
d
1
a
2
b
2
d
2
a
3
b
3
d
3
|
|
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
|
.
{\displaystyle x={\frac {\begin{vmatrix}{\color {red}d_{1}}&b_{1}&c_{1}\\{\color {red}d_{2}}&b_{2}&c_{2}\\{\color {red}d_{3}}&b_{3}&c_{3}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}},\quad y={\frac {\begin{vmatrix}a_{1}&{\color {red}d_{1}}&c_{1}\\a_{2}&{\color {red}d_{2}}&c_{2}\\a_{3}&{\color {red}d_{3}}&c_{3}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}},{\text{ and }}z={\frac {\begin{vmatrix}a_{1}&b_{1}&{\color {red}d_{1}}\\a_{2}&b_{2}&{\color {red}d_{2}}\\a_{3}&b_{3}&{\color {red}d_{3}}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}}.}
Task
Given the following system of equations:
{
2
w
−
x
+
5
y
+
z
=
−
3
3
w
+
2
x
+
2
y
−
6
z
=
−
32
w
+
3
x
+
3
y
−
z
=
−
47
5
w
−
2
x
−
3
y
+
3
z
=
49
{\displaystyle {\begin{cases}2w-x+5y+z=-3\\3w+2x+2y-6z=-32\\w+3x+3y-z=-47\\5w-2x-3y+3z=49\\\end{cases}}}
solve for
w
{\displaystyle w}
,
x
{\displaystyle x}
,
y
{\displaystyle y}
and
z
{\displaystyle z}
, using Cramer's rule.
| #EchoLisp | EchoLisp |
(lib 'matrix)
(string-delimiter "")
(define (cramer A B (X)) ;; --> vector X
(define ∆ (determinant A))
(for/vector [(i (matrix-col-num A))]
(set! X (matrix-set-col! (array-copy A) i B))
(// (determinant X) ∆)))
(define (task)
(define A (list->array
'( 2 -1 5 1 3 2 2 -6 1 3 3 -1 5 -2 -3 3) 4 4))
(define B #(-3 -32 -47 49))
(writeln "Solving A * X = B")
(array-print A)
(writeln "B = " B)
(writeln "X = " (cramer A B)))
|
http://rosettacode.org/wiki/Create_a_file | Create a file | In this task, the job is to create a new empty file called "output.txt" of size 0 bytes
and an empty directory called "docs". This should be done twice: once "here", i.e. in the current working directory and once in the filesystem root.
| #Bracmat | Bracmat | put$(,"output.txt",NEW) |
http://rosettacode.org/wiki/Create_a_file | Create a file | In this task, the job is to create a new empty file called "output.txt" of size 0 bytes
and an empty directory called "docs". This should be done twice: once "here", i.e. in the current working directory and once in the filesystem root.
| #C | C | #include <stdio.h>
int main() {
FILE *fh = fopen("output.txt", "w");
fclose(fh);
return 0;
} |
http://rosettacode.org/wiki/CSV_to_HTML_translation | CSV to HTML translation | Consider a simplified CSV format where all rows are separated by a newline
and all columns are separated by commas.
No commas are allowed as field data, but the data may contain
other characters and character sequences that would
normally be escaped when converted to HTML
Task
Create a function that takes a string representation of the CSV data
and returns a text string of an HTML table representing the CSV data.
Use the following data as the CSV text to convert, and show your output.
Character,Speech
The multitude,The messiah! Show us the messiah!
Brians mother,<angry>Now you listen here! He's not the messiah; he's a very naughty boy! Now go away!</angry>
The multitude,Who are you?
Brians mother,I'm his mother; that's who!
The multitude,Behold his mother! Behold his mother!
Extra credit
Optionally allow special formatting for the first row of the table as if it is the tables header row
(via <thead> preferably; CSS if you must).
| #C.2B.2B | C++ | #include <string>
#include <boost/regex.hpp>
#include <iostream>
std::string csvToHTML( const std::string & ) ;
int main( ) {
std::string text = "Character,Speech\n"
"The multitude,The messiah! Show us the messiah!\n"
"Brians mother,<angry>Now you listen here! He's not the messiah; he's a very naughty boy! Now go away!</angry>\n"
"The multitude,Who are you?\n"
"Brians mother,I'm his mother; that's who!\n"
"The multitude,Behold his mother! Behold his mother!\n" ;
std::cout << csvToHTML( text ) ;
return 0 ;
}
std::string csvToHTML( const std::string & csvtext ) {
//the order of the regexes and the replacements is decisive!
std::string regexes[ 5 ] = { "<" , ">" , "^(.+?)\\b" , "," , "\n" } ;
const char* replacements [ 5 ] = { "<" , ">" , " <TR><TD>$1" , "</TD><TD>", "</TD></TR>\n" } ;
boost::regex e1( regexes[ 0 ] ) ;
std::string tabletext = boost::regex_replace( csvtext , e1 ,
replacements[ 0 ] , boost::match_default | boost::format_all ) ;
for ( int i = 1 ; i < 5 ; i++ ) {
e1.assign( regexes[ i ] ) ;
tabletext = boost::regex_replace( tabletext , e1 , replacements[ i ] , boost::match_default | boost::format_all ) ;
}
tabletext = std::string( "<TABLE>\n" ) + tabletext ;
tabletext.append( "</TABLE>\n" ) ;
return tabletext ;
} |
http://rosettacode.org/wiki/CSV_data_manipulation | CSV data manipulation | CSV spreadsheet files are suitable for storing tabular data in a relatively portable way.
The CSV format is flexible but somewhat ill-defined.
For present purposes, authors may assume that the data fields contain no commas, backslashes, or quotation marks.
Task
Read a CSV file, change some values and save the changes back to a file.
For this task we will use the following CSV file:
C1,C2,C3,C4,C5
1,5,9,13,17
2,6,10,14,18
3,7,11,15,19
4,8,12,16,20
Suggestions
Show how to add a column, headed 'SUM', of the sums of the rows.
If possible, illustrate the use of built-in or standard functions, methods, or libraries, that handle generic CSV files.
| #Groovy | Groovy | def csv = []
def loadCsv = { source -> source.splitEachLine(/,/) { csv << it.collect { it } } }
def saveCsv = { target -> target.withWriter { writer -> csv.each { writer.println it.join(',') } } }
loadCsv new File('csv.txt')
csv[0][0] = 'Column0'
(1..4).each { i -> csv[i][i] = i * 100 }
saveCsv new File('csv_out.txt') |
http://rosettacode.org/wiki/Damm_algorithm | Damm algorithm | The Damm algorithm is a checksum algorithm which detects all single digit errors and adjacent transposition errors.
The algorithm is named after H. Michael Damm.
Task
Verify the checksum, stored as last digit of an input.
| #Quackery | Quackery | [ 0 swap witheach
[ char 0 - dip
[ table
[ 0 3 1 7 5 9 8 6 4 2 ]
[ 7 0 9 2 1 5 4 8 6 3 ]
[ 4 2 0 6 8 7 1 3 5 9 ]
[ 1 7 5 0 9 8 3 4 2 6 ]
[ 6 1 2 3 0 4 5 9 7 8 ]
[ 3 6 7 4 2 0 9 5 8 1 ]
[ 5 8 6 9 7 2 0 1 3 4 ]
[ 8 9 4 5 3 6 2 0 1 7 ]
[ 9 4 3 8 6 1 7 2 0 5 ]
[ 2 5 8 1 4 3 6 7 9 0 ] ]
peek ] ] is damm ( $ --> n )
[ damm 0 = ] is dammvalid ( $ --> b )
[ dup echo$ say " is "
dammvalid not if [ say "not " ]
say "valid." cr ] is validate ( & --> )
$ "5724 5725 112946 112949"
nest$ witheach validate |
http://rosettacode.org/wiki/Damm_algorithm | Damm algorithm | The Damm algorithm is a checksum algorithm which detects all single digit errors and adjacent transposition errors.
The algorithm is named after H. Michael Damm.
Task
Verify the checksum, stored as last digit of an input.
| #R | R | Damm_algo <- function(number){
row_i = 0
iterable = strsplit(toString(number), "")[[1]]
validation_matrix =
matrix(
c(
0, 3, 1, 7, 5, 9, 8, 6, 4, 2,
7, 0, 9, 2, 1, 5, 4, 8, 6, 3,
4, 2, 0, 6, 8, 7, 1, 3, 5, 9,
1, 7, 5, 0, 9, 8, 3, 4, 2, 6,
6, 1, 2, 3, 0, 4, 5, 9, 7, 8,
3, 6, 7, 4, 2, 0, 9, 5, 8, 1,
5, 8, 6, 9, 7, 2, 0, 1, 3, 4,
8, 9, 4, 5, 3, 6, 2, 0, 1, 7,
9, 4, 3, 8, 6, 1, 7, 2, 0, 5,
2, 5, 8, 1, 4, 3, 6, 7, 9, 0),
nrow = 10, ncol = 10, byrow = T
)
for(digit in as.integer(iterable)){
row_i = validation_matrix[row_i + 1, digit + 1] #in R indexes start from 1 and not from zero
}
test <- ifelse(row_i == 0, "VALID", "NOT VALID")
message(paste("Number", number, "is", test))
}
for(number in c(5724, 5727, 112946, 112949)){
Damm_algo(number)
} |
http://rosettacode.org/wiki/Cuban_primes | Cuban primes | The name cuban has nothing to do with Cuba (the country), but has to do with the
fact that cubes (3rd powers) play a role in its definition.
Some definitions of cuban primes
primes which are the difference of two consecutive cubes.
primes of the form: (n+1)3 - n3.
primes of the form: n3 - (n-1)3.
primes p such that n2(p+n) is a cube for some n>0.
primes p such that 4p = 1 + 3n2.
Cuban primes were named in 1923 by Allan Joseph Champneys Cunningham.
Task requirements
show the first 200 cuban primes (in a multi─line horizontal format).
show the 100,000th cuban prime.
show all cuban primes with commas (if appropriate).
show all output here.
Note that cuban prime isn't capitalized (as it doesn't refer to the nation of Cuba).
Also see
Wikipedia entry: cuban prime.
MathWorld entry: cuban prime.
The OEIS entry: A002407. The 100,000th cuban prime can be verified in the 2nd example on this OEIS web page.
| #Python | Python |
import datetime
import math
primes = [ 3, 5 ]
cutOff = 200
bigUn = 100_000
chunks = 50
little = bigUn / chunks
tn = " cuban prime"
print ("The first {:,}{}s:".format(cutOff, tn))
c = 0
showEach = True
u = 0
v = 1
st = datetime.datetime.now()
for i in range(1, int(math.pow(2,20))):
found = False
u += 6
v += u
mx = int(math.sqrt(v))
for item in primes:
if (item > mx):
break
if (v % item == 0):
found = True
break
if (found == 0):
c += 1
if (showEach):
z = primes[-1]
while (z <= v - 2):
z += 2
fnd = False
for item in primes:
if (item > mx):
break
if (z % item == 0):
fnd = True
break
if (not fnd):
primes.append(z)
primes.append(v)
print("{:>11,}".format(v), end='')
if (c % 10 == 0):
print("");
if (c == cutOff):
showEach = False
print ("Progress to the {:,}th {}:".format(bigUn, tn), end='')
if (c % little == 0):
print('.', end='')
if (c == bigUn):
break
print("");
print ("The {:,}th{} is {:,}".format(c, tn, v))
print("Computation time was {} seconds".format((datetime.datetime.now() - st).seconds))
|
http://rosettacode.org/wiki/Currying | Currying |
This page uses content from Wikipedia. The original article was at Currying. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
Task
Create a simple demonstrative example of Currying in a specific language.
Add any historic details as to how the feature made its way into the language.
| #Wortel | Wortel | @let {
addOne \+ 1
subtractFrom1 \- 1
subtract1 \~- 1
subtract1_2 &\- [. 1]
add ^+
; partial apply to named functions
addOne_2 \add 1
; testing
[[
!addOne 5 ; returns 6
!subtractFrom1 5 ; returns -4
!subtract1 5 ; returns 4
!subtract1_2 5 ; returns 4
!addOne_2 5 ; returns 6
]]
} |
http://rosettacode.org/wiki/Currying | Currying |
This page uses content from Wikipedia. The original article was at Currying. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
Task
Create a simple demonstrative example of Currying in a specific language.
Add any historic details as to how the feature made its way into the language.
| #Wren | Wren | var addN = Fn.new { |n| Fn.new { |x| n + x } }
var adder = addN.call(40)
System.print("The answer to life is %(adder.call(2)).") |
http://rosettacode.org/wiki/Currying | Currying |
This page uses content from Wikipedia. The original article was at Currying. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
Task
Create a simple demonstrative example of Currying in a specific language.
Add any historic details as to how the feature made its way into the language.
| #Z80_Assembly | Z80 Assembly | macro ResetCursors
ld hl,&0101
call &BB75
endm |
http://rosettacode.org/wiki/Date_manipulation | Date manipulation | Task
Given the date string "March 7 2009 7:30pm EST",
output the time 12 hours later in any human-readable format.
As extra credit, display the resulting time in a time zone different from your own.
| #SQL | SQL |
-- March 7 2009 7:30pm EST
SELECT
TO_TIMESTAMP_TZ(
'March 7 2009 7:30pm EST',
'MONTH DD YYYY HH:MIAM TZR'
)
at TIME zone 'US/Eastern' orig_dt_time
FROM dual;
-- 12 hours later DST change
SELECT
(TO_TIMESTAMP_TZ(
'March 7 2009 7:30pm EST',
'MONTH DD YYYY HH:MIAM TZR'
)+
INTERVAL '12' HOUR)
at TIME zone 'US/Eastern' plus_12_dst
FROM dual;
-- 12 hours later no DST change
-- Arizona time, always MST
SELECT
(TO_TIMESTAMP_TZ(
'March 7 2009 7:30pm EST',
'MONTH DD YYYY HH:MIAM TZR'
)+
INTERVAL '12' HOUR)
at TIME zone 'US/Arizona' plus_12_nodst
FROM dual;
|
http://rosettacode.org/wiki/Date_manipulation | Date manipulation | Task
Given the date string "March 7 2009 7:30pm EST",
output the time 12 hours later in any human-readable format.
As extra credit, display the resulting time in a time zone different from your own.
| #Standard_ML | Standard ML |
val smltime= fn input => (* parse given format *)
let
val mth::day::year::itime::t = String.fields Char.isSpace input ;
val tmp = String.fields (fn x=> x= #":") itime;
val h = (valOf(Int.fromString (hd tmp) )) + (if String.isSuffix "pm" (hd(tl tmp)) then 12 else 0 ) ;
val ms = (String.extract (hd (tl tmp), 0 ,SOME 2))^":00" ;
val mth = String.extract (mth,0,SOME 3)
in
(* Sat is a dummy *)
Date.fromString ("Sat "^mth ^" " ^ (StringCvt.padLeft #"0" 2 day) ^ " "^(StringCvt.padLeft #"0" 2 (Int.toString h))^":" ^ ms^" "^ year )
end;
local
val date2real = Time.toReal o Date.toTime o valOf
val onehour = date2real ( Date.fromString "Mon Jan 01 23:59:59 1973" ) - ( date2real ( Date.fromString "Mon Jan 01 22:59:59 1973" )) ;
in
val hoursFrom = fn hours => fn from =>
(Date.fromTimeLocal o Time.fromReal)( ( date2real from) + hours * onehour );
end;
|
http://rosettacode.org/wiki/Day_of_the_week | Day of the week | A company decides that whenever Xmas falls on a Sunday they will give their workers all extra paid holidays so that, together with any public holidays, workers will not have to work the following week (between the 25th of December and the first of January).
Task
In what years between 2008 and 2121 will the 25th of December be a Sunday?
Using any standard date handling libraries of your programming language;
compare the dates calculated with the output of other languages to discover any anomalies in the handling of dates which may be due to, for example, overflow in types used to represent dates/times similar to y2k type problems.
| #NetRexx | NetRexx | /* NetRexx */
options replace format comments java crossref savelog symbols nobinary
yearRanges = [int 2008, 2121]
searchday = ''
cal = Calendar
loop year = yearRanges[0] to yearRanges[1]
cal = GregorianCalendar(year, Calendar.DECEMBER, 25)
dayIndex = cal.get(Calendar.DAY_OF_WEEK)
if dayIndex = Calendar.SUNDAY then searchday = searchday year
end year
say 'Between' yearRanges[0] 'and' yearRanges[1]', Christmas day falls on a Sunday on the following years:'
searchday = searchday.strip.changestr(' ', ',')
say ' 'searchday
return
|
http://rosettacode.org/wiki/Day_of_the_week | Day of the week | A company decides that whenever Xmas falls on a Sunday they will give their workers all extra paid holidays so that, together with any public holidays, workers will not have to work the following week (between the 25th of December and the first of January).
Task
In what years between 2008 and 2121 will the 25th of December be a Sunday?
Using any standard date handling libraries of your programming language;
compare the dates calculated with the output of other languages to discover any anomalies in the handling of dates which may be due to, for example, overflow in types used to represent dates/times similar to y2k type problems.
| #Nim | Nim | import times
for year in 2008..2121:
if getDayOfWeek(25, mDec, year) == dSun:
stdout.write year, ' '
echo "" |
http://rosettacode.org/wiki/CUSIP | CUSIP |
This page uses content from Wikipedia. The original article was at CUSIP. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
A CUSIP is a nine-character alphanumeric code that identifies a North American financial security for the purposes of facilitating clearing and settlement of trades. The CUSIP was adopted as an American National Standard under Accredited Standards X9.6.
Task
Ensure the last digit (i.e., the check digit) of the CUSIP code (the 1st column) is correct, against the following:
037833100 Apple Incorporated
17275R102 Cisco Systems
38259P508 Google Incorporated
594918104 Microsoft Corporation
68389X106 Oracle Corporation (incorrect)
68389X105 Oracle Corporation
Example pseudo-code below.
algorithm Cusip-Check-Digit(cusip) is
Input: an 8-character CUSIP
sum := 0
for 1 ≤ i ≤ 8 do
c := the ith character of cusip
if c is a digit then
v := numeric value of the digit c
else if c is a letter then
p := ordinal position of c in the alphabet (A=1, B=2...)
v := p + 9
else if c = "*" then
v := 36
else if c = "@" then
v := 37
else if' c = "#" then
v := 38
end if
if i is even then
v := v × 2
end if
sum := sum + int ( v div 10 ) + v mod 10
repeat
return (10 - (sum mod 10)) mod 10
end function
See related tasks
SEDOL
ISIN
| #VBA | VBA | Private Function Cusip_Check_Digit(s As Variant) As Integer
Dim Sum As Integer, c As String, v As Integer
For i = 1 To 8
c = Mid(s, i, 1)
If IsNumeric(c) Then
v = Val(c)
Else
Select Case c
Case "a" To "z"
v = Asc(c) - Asc("a") + 10
Case "A" To "Z"
v = Asc(c) - Asc("A") + 10
Case "*"
v = 36
Case "@"
v = 37
Case "#"
v = 38
Case Else
Debug.Print "not expected"
End Select
End If
If i Mod 2 = 0 Then v = v * 2
Sum = Sum + Int(v \ 10) + v Mod 10
Next i
Cusip_Check_Digit = (10 - (Sum Mod 10)) Mod 10
End Function |
http://rosettacode.org/wiki/CUSIP | CUSIP |
This page uses content from Wikipedia. The original article was at CUSIP. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
A CUSIP is a nine-character alphanumeric code that identifies a North American financial security for the purposes of facilitating clearing and settlement of trades. The CUSIP was adopted as an American National Standard under Accredited Standards X9.6.
Task
Ensure the last digit (i.e., the check digit) of the CUSIP code (the 1st column) is correct, against the following:
037833100 Apple Incorporated
17275R102 Cisco Systems
38259P508 Google Incorporated
594918104 Microsoft Corporation
68389X106 Oracle Corporation (incorrect)
68389X105 Oracle Corporation
Example pseudo-code below.
algorithm Cusip-Check-Digit(cusip) is
Input: an 8-character CUSIP
sum := 0
for 1 ≤ i ≤ 8 do
c := the ith character of cusip
if c is a digit then
v := numeric value of the digit c
else if c is a letter then
p := ordinal position of c in the alphabet (A=1, B=2...)
v := p + 9
else if c = "*" then
v := 36
else if c = "@" then
v := 37
else if' c = "#" then
v := 38
end if
if i is even then
v := v × 2
end if
sum := sum + int ( v div 10 ) + v mod 10
repeat
return (10 - (sum mod 10)) mod 10
end function
See related tasks
SEDOL
ISIN
| #Visual_Basic_.NET | Visual Basic .NET | Module Module1
Function IsCUSIP(s As String) As Boolean
If s.Length <> 9 Then
Return False
End If
Dim sum = 0
For i = 0 To 7
Dim c = s(i)
Dim v As Integer
If "0" <= c AndAlso c <= "9" Then
v = Asc(c) - 48
ElseIf "A" <= c AndAlso c <= "Z" Then
v = Asc(c) - 55 ' Lower case letters are apparently invalid
ElseIf c = "*" Then
v = 36
ElseIf c = "#" Then
v = 38
Else
Return False
End If
If i Mod 2 = 1 Then
v *= 2 ' check if odd as using 0-based indexing
End If
sum += v \ 10 + v Mod 10
Next
Return Asc(s(8)) - 48 = (10 - (sum Mod 10)) Mod 10
End Function
Sub Main()
Dim candidates As New List(Of String) From {
"037833100",
"17275R102",
"38259P508",
"594918104",
"68389X106",
"68389X105"
}
For Each candidate In candidates
Console.WriteLine("{0} -> {1}", candidate, If(IsCUSIP(candidate), "correct", "incorrect"))
Next
End Sub
End Module |
http://rosettacode.org/wiki/Create_a_two-dimensional_array_at_runtime | Create a two-dimensional array at runtime |
Data Structure
This illustrates a data structure, a means of storing data within a program.
You may see other such structures in the Data Structures category.
Get two integers from the user, then create a two-dimensional array where the two dimensions have the sizes given by those numbers, and which can be accessed in the most natural way possible. Write some element of that array, and then output that element. Finally destroy the array if not done by the language itself.
| #Component_Pascal | Component Pascal |
MODULE TestArray;
(* Implemented in BlackBox Component Builder *)
IMPORT Out;
(* Open array *)
PROCEDURE DoTwoDim*;
VAR d: POINTER TO ARRAY OF ARRAY OF INTEGER;
BEGIN
NEW(d, 5, 4); (* allocating array in memory *)
d[1, 2] := 100; (* second row, third column element *)
d[4, 3] := -100; (* fifth row, fourth column element *)
Out.Int(d[1, 2], 0); Out.Ln;
Out.Int(d[4, 3], 0); Out.Ln;
END DoTwoDim;
END TestArray. |
http://rosettacode.org/wiki/Cumulative_standard_deviation | Cumulative standard deviation | Task[edit]
Write a stateful function, class, generator or co-routine that takes a series of floating point numbers, one at a time, and returns the running standard deviation of the series.
The task implementation should use the most natural programming style of those listed for the function in the implementation language; the task must state which is being used.
Do not apply Bessel's correction; the returned standard deviation should always be computed as if the sample seen so far is the entire population.
Test case
Use this to compute the standard deviation of this demonstration set,
{
2
,
4
,
4
,
4
,
5
,
5
,
7
,
9
}
{\displaystyle \{2,4,4,4,5,5,7,9\}}
, which is
2
{\displaystyle 2}
.
Related tasks
Random numbers
Tasks for calculating statistical measures
in one go
moving (sliding window)
moving (cumulative)
Mean
Arithmetic
Statistics/Basic
Averages/Arithmetic mean
Averages/Pythagorean means
Averages/Simple moving average
Geometric
Averages/Pythagorean means
Harmonic
Averages/Pythagorean means
Quadratic
Averages/Root mean square
Circular
Averages/Mean angle
Averages/Mean time of day
Median
Averages/Median
Mode
Averages/Mode
Standard deviation
Statistics/Basic
Cumulative standard deviation
| #FreeBASIC | FreeBASIC | ' FB 1.05.0 Win64
Function calcStandardDeviation(number As Double) As Double
Static a() As Double
Redim Preserve a(0 To UBound(a) + 1)
Dim ub As UInteger = UBound(a)
a(ub) = number
Dim sum As Double = 0.0
For i As UInteger = 0 To ub
sum += a(i)
Next
Dim mean As Double = sum / (ub + 1)
Dim diff As Double
sum = 0.0
For i As UInteger = 0 To ub
diff = a(i) - mean
sum += diff * diff
Next
Return Sqr(sum/ (ub + 1))
End Function
Dim a(0 To 7) As Double = {2, 4, 4, 4, 5, 5, 7, 9}
For i As UInteger = 0 To 7
Print "Added"; a(i); " SD now : "; calcStandardDeviation(a(i))
Next
Print
Print "Press any key to quit"
Sleep |
http://rosettacode.org/wiki/CRC-32 | CRC-32 |
Task
Demonstrate a method of deriving the Cyclic Redundancy Check from within the language.
The result should be in accordance with ISO 3309, ITU-T V.42, Gzip and PNG.
Algorithms are described on Computation of CRC in Wikipedia.
This variant of CRC-32 uses LSB-first order, sets the initial CRC to FFFFFFFF16, and complements the final CRC.
For the purpose of this task, generate a CRC-32 checksum for the ASCII encoded string:
The quick brown fox jumps over the lazy dog
| #Haskell | Haskell | import Data.Bits ((.&.), complement, shiftR, xor)
import Data.Word (Word32)
import Numeric (showHex)
crcTable :: Word32 -> Word32
crcTable = (table !!) . fromIntegral
where
table = ((!! 8) . iterate xf) <$> [0 .. 255]
shifted x = shiftR x 1
xf r
| r .&. 1 == 1 = xor (shifted r) 0xedb88320
| otherwise = shifted r
charToWord :: Char -> Word32
charToWord = fromIntegral . fromEnum
calcCrc :: String -> Word32
calcCrc = complement . foldl cf (complement 0)
where
cf crc x = xor (shiftR crc 8) (crcTable $ xor (crc .&. 0xff) (charToWord x))
crc32 :: String -> String
crc32 = flip showHex [] . calcCrc
main :: IO ()
main = putStrLn $ crc32 "The quick brown fox jumps over the lazy dog" |
http://rosettacode.org/wiki/Count_the_coins | Count the coins | There are four types of common coins in US currency:
quarters (25 cents)
dimes (10 cents)
nickels (5 cents), and
pennies (1 cent)
There are six ways to make change for 15 cents:
A dime and a nickel
A dime and 5 pennies
3 nickels
2 nickels and 5 pennies
A nickel and 10 pennies
15 pennies
Task
How many ways are there to make change for a dollar using these common coins? (1 dollar = 100 cents).
Optional
Less common are dollar coins (100 cents); and very rare are half dollars (50 cents). With the addition of these two coins, how many ways are there to make change for $1000?
(Note: the answer is larger than 232).
References
an algorithm from the book Structure and Interpretation of Computer Programs.
an article in the algorithmist.
Change-making problem on Wikipedia.
| #BBC_BASIC | BBC BASIC | DIM uscoins%(3)
uscoins%() = 1, 5, 10, 25
PRINT FNchange(100, uscoins%()) " ways of making $1"
PRINT FNchange(1000, uscoins%()) " ways of making $10"
DIM ukcoins%(7)
ukcoins%() = 1, 2, 5, 10, 20, 50, 100, 200
PRINT FNchange(100, ukcoins%()) " ways of making £1"
PRINT FNchange(1000, ukcoins%()) " ways of making £10"
END
DEF FNchange(sum%, coins%())
LOCAL C%, D%, I%, N%, P%, Q%, S%, table()
C% = 0
N% = DIM(coins%(),1) + 1
FOR I% = 0 TO N% - 1
D% = coins%(I%)
IF D% <= sum% IF D% >= C% C% = D% + 1
NEXT
C% *= N%
DIM table(C%-1)
FOR I% = 0 TO N%-1 : table(I%) = 1 : NEXT
P% = N%
FOR S% = 1 TO sum%
FOR I% = 0 TO N% - 1
IF I% = 0 IF P% >= C% P% = 0
IF coins%(I%) <= S% THEN
Q% = P% - coins%(I%) * N%
IF Q% >= 0 table(P%) = table(Q%) ELSE table(P%) = table(Q% + C%)
ENDIF
IF I% table(P%) += table(P% - 1)
P% += 1
NEXT
NEXT
= table(P%-1)
|
http://rosettacode.org/wiki/Count_the_coins | Count the coins | There are four types of common coins in US currency:
quarters (25 cents)
dimes (10 cents)
nickels (5 cents), and
pennies (1 cent)
There are six ways to make change for 15 cents:
A dime and a nickel
A dime and 5 pennies
3 nickels
2 nickels and 5 pennies
A nickel and 10 pennies
15 pennies
Task
How many ways are there to make change for a dollar using these common coins? (1 dollar = 100 cents).
Optional
Less common are dollar coins (100 cents); and very rare are half dollars (50 cents). With the addition of these two coins, how many ways are there to make change for $1000?
(Note: the answer is larger than 232).
References
an algorithm from the book Structure and Interpretation of Computer Programs.
an article in the algorithmist.
Change-making problem on Wikipedia.
| #C | C | #include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
// ad hoc 128 bit integer type; faster than using GMP because of low
// overhead
typedef struct { uint64_t x[2]; } i128;
// display in decimal
void show(i128 v) {
uint32_t x[4] = {v.x[0], v.x[0] >> 32, v.x[1], v.x[1] >> 32};
int i, j = 0, len = 4;
char buf[100];
do {
uint64_t c = 0;
for (i = len; i--; ) {
c = (c << 32) + x[i];
x[i] = c / 10, c %= 10;
}
buf[j++] = c + '0';
for (len = 4; !x[len - 1]; len--);
} while (len);
while (j--) putchar(buf[j]);
putchar('\n');
}
i128 count(int sum, int *coins)
{
int n, i, k;
for (n = 0; coins[n]; n++);
i128 **v = malloc(sizeof(int*) * n);
int *idx = malloc(sizeof(int) * n);
for (i = 0; i < n; i++) {
idx[i] = coins[i];
// each v[i] is a cyclic buffer
v[i] = calloc(sizeof(i128), coins[i]);
}
v[0][coins[0] - 1] = (i128) {{1, 0}};
for (k = 0; k <= sum; k++) {
for (i = 0; i < n; i++)
if (!idx[i]--) idx[i] = coins[i] - 1;
i128 c = v[0][ idx[0] ];
for (i = 1; i < n; i++) {
i128 *p = v[i] + idx[i];
// 128 bit addition
p->x[0] += c.x[0];
p->x[1] += c.x[1];
if (p->x[0] < c.x[0]) // carry
p->x[1] ++;
c = *p;
}
}
i128 r = v[n - 1][idx[n-1]];
for (i = 0; i < n; i++) free(v[i]);
free(v);
free(idx);
return r;
}
// simple recursive method; slow
int count2(int sum, int *coins)
{
if (!*coins || sum < 0) return 0;
if (!sum) return 1;
return count2(sum - *coins, coins) + count2(sum, coins + 1);
}
int main(void)
{
int us_coins[] = { 100, 50, 25, 10, 5, 1, 0 };
int eu_coins[] = { 200, 100, 50, 20, 10, 5, 2, 1, 0 };
show(count( 100, us_coins + 2));
show(count( 1000, us_coins));
show(count( 1000 * 100, us_coins));
show(count( 10000 * 100, us_coins));
show(count(100000 * 100, us_coins));
putchar('\n');
show(count( 1 * 100, eu_coins));
show(count( 1000 * 100, eu_coins));
show(count( 10000 * 100, eu_coins));
show(count(100000 * 100, eu_coins));
return 0;
} |
http://rosettacode.org/wiki/Count_occurrences_of_a_substring | Count occurrences of a substring | Task
Create a function, or show a built-in function, to count the number of non-overlapping occurrences of a substring inside a string.
The function should take two arguments:
the first argument being the string to search, and
the second a substring to be searched for.
It should return an integer count.
print countSubstring("the three truths","th")
3
// do not count substrings that overlap with previously-counted substrings:
print countSubstring("ababababab","abab")
2
The matching should yield the highest number of non-overlapping matches.
In general, this essentially means matching from left-to-right or right-to-left (see proof on talk page).
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #ALGOL_68 | ALGOL 68 | #!/usr/local/bin/a68g --script #
PROC count string in string = (STRING needle, haystack)INT: (
INT start:=LWB haystack, next, out:=0;
FOR count WHILE string in string(needle, next, haystack[start:]) DO
start+:=next+UPB needle-LWB needle;
out:=count
OD;
out
);
printf(($d" "$,
count string in string("th", "the three truths"), # expect 3 #
count string in string("abab", "ababababab"), # expect 2 #
count string in string("a*b", "abaabba*bbaba*bbab"), # expect 2 #
$l$
)) |
http://rosettacode.org/wiki/Count_occurrences_of_a_substring | Count occurrences of a substring | Task
Create a function, or show a built-in function, to count the number of non-overlapping occurrences of a substring inside a string.
The function should take two arguments:
the first argument being the string to search, and
the second a substring to be searched for.
It should return an integer count.
print countSubstring("the three truths","th")
3
// do not count substrings that overlap with previously-counted substrings:
print countSubstring("ababababab","abab")
2
The matching should yield the highest number of non-overlapping matches.
In general, this essentially means matching from left-to-right or right-to-left (see proof on talk page).
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #Apex | Apex |
String substr = 'ABC';
String str = 'ABCZZZABCYABCABCXXABC';
Integer substrLen = substr.length();
Integer count = 0;
Integer index = str.indexOf(substr);
while (index >= 0) {
count++;
str = str.substring(index+substrLen);
index = str.indexOf(substr);
}
System.debug('Count String : '+count);
|
http://rosettacode.org/wiki/Count_in_octal | Count in octal | Task
Produce a sequential count in octal, starting at zero, and using an increment of a one for each consecutive number.
Each number should appear on a single line, and the program should count until terminated, or until the maximum value of the numeric type in use is reached.
Related task
Integer sequence is a similar task without the use of octal numbers.
| #Aime | Aime | integer o;
o = 0;
do {
o_xinteger(8, o);
o_byte('\n');
o += 1;
} while (0 < o); |
http://rosettacode.org/wiki/Count_in_octal | Count in octal | Task
Produce a sequential count in octal, starting at zero, and using an increment of a one for each consecutive number.
Each number should appear on a single line, and the program should count until terminated, or until the maximum value of the numeric type in use is reached.
Related task
Integer sequence is a similar task without the use of octal numbers.
| #ALGOL_68 | ALGOL 68 | #!/usr/local/bin/a68g --script #
INT oct width = (bits width-1) OVER 3 + 1;
main:
(
FOR i TO 17 # max int # DO
printf(($"8r"8r n(oct width)dl$, BIN i))
OD
) |
http://rosettacode.org/wiki/Count_in_factors | Count in factors | Task
Write a program which counts up from 1, displaying each number as the multiplication of its prime factors.
For the purpose of this task, 1 (unity) may be shown as itself.
Example
2 is prime, so it would be shown as itself.
6 is not prime; it would be shown as
2
×
3
{\displaystyle 2\times 3}
.
2144 is not prime; it would be shown as
2
×
2
×
2
×
2
×
2
×
67
{\displaystyle 2\times 2\times 2\times 2\times 2\times 67}
.
Related tasks
prime decomposition
factors of an integer
Sieve of Eratosthenes
primality by trial division
factors of a Mersenne number
trial factoring of a Mersenne number
partition an integer X into N primes
| #ALGOL_68 | ALGOL 68 | OP +:= = (REF FLEX []INT a, INT b) VOID:
BEGIN
[⌈a + 1] INT c;
c[:⌈a] := a;
c[⌈a+1:] := b;
a := c
END;
PROC factorize = (INT nn) []INT:
BEGIN
IF nn = 1 THEN (1)
ELSE
INT k := 2, n := nn;
FLEX[0]INT result;
WHILE n > 1 DO
WHILE n MOD k = 0 DO
result +:= k;
n := n % k
OD;
k +:= 1
OD;
result
FI
END;
FLEX[0]INT factors;
FOR i TO 22 DO
factors := factorize (i);
print ((whole (i, 0), " = "));
FOR j TO UPB factors DO
(j /= 1 | print (" × "));
print ((whole (factors[j], 0)))
OD;
print ((new line))
OD |
http://rosettacode.org/wiki/Create_an_HTML_table | Create an HTML table | Create an HTML table.
The table body should have at least three rows of three columns.
Each of these three columns should be labelled "X", "Y", and "Z".
An extra column should be added at either the extreme left or the extreme right of the table that has no heading, but is filled with sequential row numbers.
The rows of the "X", "Y", and "Z" columns should be filled with random or sequential integers having 4 digits or less.
The numbers should be aligned in the same fashion for all columns.
| #Batch_File | Batch File |
@echo off
setlocal enabledelayedexpansion
:: It's easier and neater to create the variables holding the random 4 digit numbers ahead of time
for /l %%i in (1,1,12) do set /a rand%%i=!random! %% 9999
:: The command output of everything within the brackets is sent to the file "table.html", overwriting anything already in there
(
echo ^<html^>^<head^>^</head^>^<body^>
echo ^<table border=1 cellpadding=10 cellspacing=0^>
echo ^<tr^>^<th^>^</th^>
echo ^<th^>X^</th^>
echo ^<th^>Y^</th^>
echo ^<th^>Z^</th^>
echo ^</tr^>
echo ^<tr^>^<th^>1^</th^>
echo ^<td align="right"^>%rand1%^</td^>
echo ^<td align="right"^>%rand2%^</td^>
echo ^<td align="right"^>%rand3%^</td^>
echo ^</tr^>
echo ^<tr^>^<th^>2^</th^>
echo ^<td align="right"^>%rand4%^</td^>
echo ^<td align="right"^>%rand5%^</td^>
echo ^<td align="right"^>%rand6%^</td^>
echo ^</tr^>
echo ^<tr^>^<th^>3^</th^>
echo ^<td align="right"^>%rand7%^</td^>
echo ^<td align="right"^>%rand8%^</td^>
echo ^<td align="right"^>%rand9%^</td^>
echo ^</tr^>
echo ^<tr^>^<th^>4^</th^>
echo ^<td align="right"^>%rand10%^</td^>
echo ^<td align="right"^>%rand11%^</td^>
echo ^<td align="right"^>%rand12%^</td^>
echo ^</tr^>
echo ^</table^>
echo ^</body^>^</html^>
) > table.html
start table.html
|
http://rosettacode.org/wiki/Date_format | Date format | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Task
Display the current date in the formats of:
2007-11-23 and
Friday, November 23, 2007
| #MATLAB_.2F_Octave | MATLAB / Octave | >> datestr(now,'yyyy-mm-dd')
ans =
2010-06-18
>> datestr(now,'dddd, mmmm dd, yyyy')
ans =
Friday, June 18, 2010 |
http://rosettacode.org/wiki/Date_format | Date format | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Task
Display the current date in the formats of:
2007-11-23 and
Friday, November 23, 2007
| #min | min | ("YYYY-MM-dd" "dddd, MMMM dd, YYYY") ('timestamp dip tformat puts!) foreach |
http://rosettacode.org/wiki/Cramer%27s_rule | Cramer's rule | linear algebra
Cramer's rule
system of linear equations
Given
{
a
1
x
+
b
1
y
+
c
1
z
=
d
1
a
2
x
+
b
2
y
+
c
2
z
=
d
2
a
3
x
+
b
3
y
+
c
3
z
=
d
3
{\displaystyle \left\{{\begin{matrix}a_{1}x+b_{1}y+c_{1}z&={\color {red}d_{1}}\\a_{2}x+b_{2}y+c_{2}z&={\color {red}d_{2}}\\a_{3}x+b_{3}y+c_{3}z&={\color {red}d_{3}}\end{matrix}}\right.}
which in matrix format is
[
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
]
[
x
y
z
]
=
[
d
1
d
2
d
3
]
.
{\displaystyle {\begin{bmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{bmatrix}}{\begin{bmatrix}x\\y\\z\end{bmatrix}}={\begin{bmatrix}{\color {red}d_{1}}\\{\color {red}d_{2}}\\{\color {red}d_{3}}\end{bmatrix}}.}
Then the values of
x
,
y
{\displaystyle x,y}
and
z
{\displaystyle z}
can be found as follows:
x
=
|
d
1
b
1
c
1
d
2
b
2
c
2
d
3
b
3
c
3
|
|
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
|
,
y
=
|
a
1
d
1
c
1
a
2
d
2
c
2
a
3
d
3
c
3
|
|
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
|
,
and
z
=
|
a
1
b
1
d
1
a
2
b
2
d
2
a
3
b
3
d
3
|
|
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
|
.
{\displaystyle x={\frac {\begin{vmatrix}{\color {red}d_{1}}&b_{1}&c_{1}\\{\color {red}d_{2}}&b_{2}&c_{2}\\{\color {red}d_{3}}&b_{3}&c_{3}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}},\quad y={\frac {\begin{vmatrix}a_{1}&{\color {red}d_{1}}&c_{1}\\a_{2}&{\color {red}d_{2}}&c_{2}\\a_{3}&{\color {red}d_{3}}&c_{3}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}},{\text{ and }}z={\frac {\begin{vmatrix}a_{1}&b_{1}&{\color {red}d_{1}}\\a_{2}&b_{2}&{\color {red}d_{2}}\\a_{3}&b_{3}&{\color {red}d_{3}}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}}.}
Task
Given the following system of equations:
{
2
w
−
x
+
5
y
+
z
=
−
3
3
w
+
2
x
+
2
y
−
6
z
=
−
32
w
+
3
x
+
3
y
−
z
=
−
47
5
w
−
2
x
−
3
y
+
3
z
=
49
{\displaystyle {\begin{cases}2w-x+5y+z=-3\\3w+2x+2y-6z=-32\\w+3x+3y-z=-47\\5w-2x-3y+3z=49\\\end{cases}}}
solve for
w
{\displaystyle w}
,
x
{\displaystyle x}
,
y
{\displaystyle y}
and
z
{\displaystyle z}
, using Cramer's rule.
| #Factor | Factor | USING: kernel math math.matrices.laplace prettyprint sequences ;
IN: rosetta-code.cramers-rule
: replace-col ( elt n seq -- seq' ) flip [ set-nth ] keep flip ;
: solve ( m v -- seq )
dup length <iota> [
rot [ replace-col ] keep [ determinant ] bi@ /
] 2with map ;
: cramers-rule-demo ( -- )
{
{ 2 -1 5 1 }
{ 3 2 2 -6 }
{ 1 3 3 -1 }
{ 5 -2 -3 3 }
}
{ -3 -32 -47 49 } solve . ;
MAIN: cramers-rule-demo |
http://rosettacode.org/wiki/Cramer%27s_rule | Cramer's rule | linear algebra
Cramer's rule
system of linear equations
Given
{
a
1
x
+
b
1
y
+
c
1
z
=
d
1
a
2
x
+
b
2
y
+
c
2
z
=
d
2
a
3
x
+
b
3
y
+
c
3
z
=
d
3
{\displaystyle \left\{{\begin{matrix}a_{1}x+b_{1}y+c_{1}z&={\color {red}d_{1}}\\a_{2}x+b_{2}y+c_{2}z&={\color {red}d_{2}}\\a_{3}x+b_{3}y+c_{3}z&={\color {red}d_{3}}\end{matrix}}\right.}
which in matrix format is
[
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
]
[
x
y
z
]
=
[
d
1
d
2
d
3
]
.
{\displaystyle {\begin{bmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{bmatrix}}{\begin{bmatrix}x\\y\\z\end{bmatrix}}={\begin{bmatrix}{\color {red}d_{1}}\\{\color {red}d_{2}}\\{\color {red}d_{3}}\end{bmatrix}}.}
Then the values of
x
,
y
{\displaystyle x,y}
and
z
{\displaystyle z}
can be found as follows:
x
=
|
d
1
b
1
c
1
d
2
b
2
c
2
d
3
b
3
c
3
|
|
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
|
,
y
=
|
a
1
d
1
c
1
a
2
d
2
c
2
a
3
d
3
c
3
|
|
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
|
,
and
z
=
|
a
1
b
1
d
1
a
2
b
2
d
2
a
3
b
3
d
3
|
|
a
1
b
1
c
1
a
2
b
2
c
2
a
3
b
3
c
3
|
.
{\displaystyle x={\frac {\begin{vmatrix}{\color {red}d_{1}}&b_{1}&c_{1}\\{\color {red}d_{2}}&b_{2}&c_{2}\\{\color {red}d_{3}}&b_{3}&c_{3}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}},\quad y={\frac {\begin{vmatrix}a_{1}&{\color {red}d_{1}}&c_{1}\\a_{2}&{\color {red}d_{2}}&c_{2}\\a_{3}&{\color {red}d_{3}}&c_{3}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}},{\text{ and }}z={\frac {\begin{vmatrix}a_{1}&b_{1}&{\color {red}d_{1}}\\a_{2}&b_{2}&{\color {red}d_{2}}\\a_{3}&b_{3}&{\color {red}d_{3}}\end{vmatrix}}{\begin{vmatrix}a_{1}&b_{1}&c_{1}\\a_{2}&b_{2}&c_{2}\\a_{3}&b_{3}&c_{3}\end{vmatrix}}}.}
Task
Given the following system of equations:
{
2
w
−
x
+
5
y
+
z
=
−
3
3
w
+
2
x
+
2
y
−
6
z
=
−
32
w
+
3
x
+
3
y
−
z
=
−
47
5
w
−
2
x
−
3
y
+
3
z
=
49
{\displaystyle {\begin{cases}2w-x+5y+z=-3\\3w+2x+2y-6z=-32\\w+3x+3y-z=-47\\5w-2x-3y+3z=49\\\end{cases}}}
solve for
w
{\displaystyle w}
,
x
{\displaystyle x}
,
y
{\displaystyle y}
and
z
{\displaystyle z}
, using Cramer's rule.
| #Fortran | Fortran | DATA A/2, -1, 5, 1
1 3, 2, 2, -6
2 1, 3, 3, -1
3 5, -2, -3, 3/ |
http://rosettacode.org/wiki/Create_a_file | Create a file | In this task, the job is to create a new empty file called "output.txt" of size 0 bytes
and an empty directory called "docs". This should be done twice: once "here", i.e. in the current working directory and once in the filesystem root.
| #C.23 | C# | using System;
using System.IO;
class Program {
static void Main(string[] args) {
File.Create("output.txt");
File.Create(@"\output.txt");
Directory.CreateDirectory("docs");
Directory.CreateDirectory(@"\docs");
}
} |
http://rosettacode.org/wiki/Create_a_file | Create a file | In this task, the job is to create a new empty file called "output.txt" of size 0 bytes
and an empty directory called "docs". This should be done twice: once "here", i.e. in the current working directory and once in the filesystem root.
| #C.2B.2B | C++ | #include <direct.h>
#include <fstream>
int main() {
std::fstream f("output.txt", std::ios::out);
f.close();
f.open("/output.txt", std::ios::out);
f.close();
_mkdir("docs");
_mkdir("/docs");
return 0;
} |
http://rosettacode.org/wiki/CSV_to_HTML_translation | CSV to HTML translation | Consider a simplified CSV format where all rows are separated by a newline
and all columns are separated by commas.
No commas are allowed as field data, but the data may contain
other characters and character sequences that would
normally be escaped when converted to HTML
Task
Create a function that takes a string representation of the CSV data
and returns a text string of an HTML table representing the CSV data.
Use the following data as the CSV text to convert, and show your output.
Character,Speech
The multitude,The messiah! Show us the messiah!
Brians mother,<angry>Now you listen here! He's not the messiah; he's a very naughty boy! Now go away!</angry>
The multitude,Who are you?
Brians mother,I'm his mother; that's who!
The multitude,Behold his mother! Behold his mother!
Extra credit
Optionally allow special formatting for the first row of the table as if it is the tables header row
(via <thead> preferably; CSS if you must).
| #Clojure | Clojure |
Character,Speech
The multitude,The messiah! Show us the messiah!
Brians mother,<angry>Now you listen here! He's not the messiah; he's a very naughty boy! Now go away!</angry>
The multitude,Who are you?
Brians mother,I'm his mother; that's who!
The multitude,Behold his mother! Behold his mother!
|
http://rosettacode.org/wiki/CSV_data_manipulation | CSV data manipulation | CSV spreadsheet files are suitable for storing tabular data in a relatively portable way.
The CSV format is flexible but somewhat ill-defined.
For present purposes, authors may assume that the data fields contain no commas, backslashes, or quotation marks.
Task
Read a CSV file, change some values and save the changes back to a file.
For this task we will use the following CSV file:
C1,C2,C3,C4,C5
1,5,9,13,17
2,6,10,14,18
3,7,11,15,19
4,8,12,16,20
Suggestions
Show how to add a column, headed 'SUM', of the sums of the rows.
If possible, illustrate the use of built-in or standard functions, methods, or libraries, that handle generic CSV files.
| #Haskell | Haskell | import Data.Array (Array(..), (//), bounds, elems, listArray)
import Data.List (intercalate)
import Control.Monad (when)
import Data.Maybe (isJust)
delimiters :: String
delimiters = ",;:"
fields :: String -> [String]
fields [] = []
fields xs =
let (item, rest) = break (`elem` delimiters) xs
(_, next) = break (`notElem` delimiters) rest
in item : fields next
unfields :: Maybe (Array (Int, Int) String) -> [String]
unfields Nothing = []
unfields (Just a) = every fieldNumber $ elems a
where
((_, _), (_, fieldNumber)) = bounds a
every _ [] = []
every n xs =
let (y, z) = splitAt n xs
in intercalate "," y : every n z
fieldArray :: [[String]] -> Maybe (Array (Int, Int) String)
fieldArray [] = Nothing
fieldArray xs =
Just $ listArray ((1, 1), (length xs, length $ head xs)) $ concat xs
fieldsFromFile :: FilePath -> IO (Maybe (Array (Int, Int) String))
fieldsFromFile = fmap (fieldArray . map fields . lines) . readFile
fieldsToFile :: FilePath -> Maybe (Array (Int, Int) String) -> IO ()
fieldsToFile f = writeFile f . unlines . unfields
someChanges :: Maybe (Array (Int, Int) String)
-> Maybe (Array (Int, Int) String)
someChanges =
fmap (// [((1, 1), "changed"), ((3, 4), "altered"), ((5, 2), "modified")])
main :: IO ()
main = do
a <- fieldsFromFile "example.txt"
when (isJust a) $ fieldsToFile "output.txt" $ someChanges a |
http://rosettacode.org/wiki/Damm_algorithm | Damm algorithm | The Damm algorithm is a checksum algorithm which detects all single digit errors and adjacent transposition errors.
The algorithm is named after H. Michael Damm.
Task
Verify the checksum, stored as last digit of an input.
| #Racket | Racket | #lang racket/base
(require racket/match)
(define operation-table
#(#(0 3 1 7 5 9 8 6 4 2)
#(7 0 9 2 1 5 4 8 6 3)
#(4 2 0 6 8 7 1 3 5 9)
#(1 7 5 0 9 8 3 4 2 6)
#(6 1 2 3 0 4 5 9 7 8)
#(3 6 7 4 2 0 9 5 8 1)
#(5 8 6 9 7 2 0 1 3 4)
#(8 9 4 5 3 6 2 0 1 7)
#(9 4 3 8 6 1 7 2 0 5)
#(2 5 8 1 4 3 6 7 9 0)))
(define (integer->digit-list n)
(let loop ((n n) (a null))
(if (zero? n) a (let-values (([q r] (quotient/remainder n 10))) (loop q (cons r a))))))
(define/match (check-digit n)
[((list ds ...))
(foldl
(λ (d interim)
(vector-ref (vector-ref operation-table interim) d))
0 ds)]
[((? integer? i))
(check-digit (integer->digit-list i))])
(define/match (valid-number? n)
[((? integer? i))
(valid-number? (integer->digit-list i))]
[((list ds ...))
(zero? (check-digit ds))])
(module+ test
(require rackunit)
(check-equal? (integer->digit-list 572) '(5 7 2))
(check-equal? (check-digit 572) 4)
(check-equal? (check-digit '(5 7 2)) 4)
(check-true (valid-number? 5724))
(check-false (valid-number? 5274))
(check-true (valid-number? 112946))) |
http://rosettacode.org/wiki/Damm_algorithm | Damm algorithm | The Damm algorithm is a checksum algorithm which detects all single digit errors and adjacent transposition errors.
The algorithm is named after H. Michael Damm.
Task
Verify the checksum, stored as last digit of an input.
| #Raku | Raku | sub damm ( *@digits ) {
my @tbl = [0, 3, 1, 7, 5, 9, 8, 6, 4, 2],
[7, 0, 9, 2, 1, 5, 4, 8, 6, 3],
[4, 2, 0, 6, 8, 7, 1, 3, 5, 9],
[1, 7, 5, 0, 9, 8, 3, 4, 2, 6],
[6, 1, 2, 3, 0, 4, 5, 9, 7, 8],
[3, 6, 7, 4, 2, 0, 9, 5, 8, 1],
[5, 8, 6, 9, 7, 2, 0, 1, 3, 4],
[8, 9, 4, 5, 3, 6, 2, 0, 1, 7],
[9, 4, 3, 8, 6, 1, 7, 2, 0, 5],
[2, 5, 8, 1, 4, 3, 6, 7, 9, 0];
my $row = 0;
for @digits -> $col { $row = @tbl[$row][$col] }
not $row
}
# Testing
for 5724, 5727, 112946 {
say "$_:\tChecksum digit { damm( $_.comb ) ?? '' !! 'in' }correct."
} |
http://rosettacode.org/wiki/Cuban_primes | Cuban primes | The name cuban has nothing to do with Cuba (the country), but has to do with the
fact that cubes (3rd powers) play a role in its definition.
Some definitions of cuban primes
primes which are the difference of two consecutive cubes.
primes of the form: (n+1)3 - n3.
primes of the form: n3 - (n-1)3.
primes p such that n2(p+n) is a cube for some n>0.
primes p such that 4p = 1 + 3n2.
Cuban primes were named in 1923 by Allan Joseph Champneys Cunningham.
Task requirements
show the first 200 cuban primes (in a multi─line horizontal format).
show the 100,000th cuban prime.
show all cuban primes with commas (if appropriate).
show all output here.
Note that cuban prime isn't capitalized (as it doesn't refer to the nation of Cuba).
Also see
Wikipedia entry: cuban prime.
MathWorld entry: cuban prime.
The OEIS entry: A002407. The 100,000th cuban prime can be verified in the 2nd example on this OEIS web page.
| #Racket | Racket | #lang racket
(require math/number-theory
racket/generator)
(define (make-cuban-prime-generator)
(generator ()
(let loop ((y 1) (y3 1))
(let* ((x (+ y 1))
(x3 (expt x 3))
(p (quotient (- x3 y3) (- x y))))
(when (prime? p) (yield p))
(loop x x3)))))
(define (tabulate l (line-width 80))
(let* ((w (add1 (string-length (argmax string-length (map ~a l)))))
(cols (quotient line-width w)))
(for ((n (in-range 1 (add1 (length l))))
(i l))
(display (~a i #:width w #:align 'right))
(when (zero? (modulo n cols)) (newline)))))
(define (progress-report x)
(when (zero? (modulo x 1000))
(eprintf (if (zero? (modulo x 10000)) "|" "."))
(flush-output (current-error-port))))
(let ((200-cuban-primes (for/list ((_ 200)
(p (in-producer (make-cuban-prime-generator))))
p)))
(tabulate 200-cuban-primes))
(begin0
(for/last ((x 100000)
(p (in-producer (make-cuban-prime-generator))))
(progress-report x)
p)
(newline)) |
http://rosettacode.org/wiki/Cuban_primes | Cuban primes | The name cuban has nothing to do with Cuba (the country), but has to do with the
fact that cubes (3rd powers) play a role in its definition.
Some definitions of cuban primes
primes which are the difference of two consecutive cubes.
primes of the form: (n+1)3 - n3.
primes of the form: n3 - (n-1)3.
primes p such that n2(p+n) is a cube for some n>0.
primes p such that 4p = 1 + 3n2.
Cuban primes were named in 1923 by Allan Joseph Champneys Cunningham.
Task requirements
show the first 200 cuban primes (in a multi─line horizontal format).
show the 100,000th cuban prime.
show all cuban primes with commas (if appropriate).
show all output here.
Note that cuban prime isn't capitalized (as it doesn't refer to the nation of Cuba).
Also see
Wikipedia entry: cuban prime.
MathWorld entry: cuban prime.
The OEIS entry: A002407. The 100,000th cuban prime can be verified in the 2nd example on this OEIS web page.
| #Raku | Raku | use Lingua::EN::Numbers;
use ntheory:from<Perl5> <:all>;
my @cubans = lazy (1..Inf).map({ ($_+1)³ - .³ }).grep: *.&is_prime;
put @cubans[^200]».&comma».fmt("%9s").rotor(10).join: "\n";
put '';
put @cubans[99_999]., # zero indexed |
http://rosettacode.org/wiki/Currying | Currying |
This page uses content from Wikipedia. The original article was at Currying. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
Task
Create a simple demonstrative example of Currying in a specific language.
Add any historic details as to how the feature made its way into the language.
| #zkl | zkl | addOne:= Op("+").fp(1); addOne(5) //-->6
minusOne:=Op("-").fp1(1); minusOne(5) //-->4, note that this fixed 1 as the second parameter
// fix first and third parameters:
foo:=String.fpM("101","<foo>","</foo>"); foo("zkl"); //-->"<foo>zkl</foo>"
fcn g(x){x+1} f:=fcn(f,x){f(x)+x}.fp(g); f(5); //-->11
f:=fcn(f,x){f(x)+x}.fp(fcn(x){x+1}); // above with lambdas all the way down |
http://rosettacode.org/wiki/Date_manipulation | Date manipulation | Task
Given the date string "March 7 2009 7:30pm EST",
output the time 12 hours later in any human-readable format.
As extra credit, display the resulting time in a time zone different from your own.
| #Swift | Swift | import Foundation
let formatter = DateFormatter()
formatter.dateFormat = "MMMM dd yyyy hh:mma zzz"
guard let date = formatter.date(from: "March 7 2009 7:30pm EST") else {
fatalError()
}
print(formatter.string(from: date))
print(formatter.string(from: date + 60 * 60 * 12)) |
http://rosettacode.org/wiki/Date_manipulation | Date manipulation | Task
Given the date string "March 7 2009 7:30pm EST",
output the time 12 hours later in any human-readable format.
As extra credit, display the resulting time in a time zone different from your own.
| #Tcl | Tcl | set date "March 7 2009 7:30pm EST"
set epoch [clock scan $date -format "%B %d %Y %I:%M%p %z"]
set later [clock add $epoch 12 hours]
puts [clock format $later] ;# Sun Mar 08 08:30:00 EDT 2009
puts [clock format $later -timezone :Asia/Shanghai] ;# Sun Mar 08 20:30:00 CST 2009 |
http://rosettacode.org/wiki/Day_of_the_week | Day of the week | A company decides that whenever Xmas falls on a Sunday they will give their workers all extra paid holidays so that, together with any public holidays, workers will not have to work the following week (between the 25th of December and the first of January).
Task
In what years between 2008 and 2121 will the 25th of December be a Sunday?
Using any standard date handling libraries of your programming language;
compare the dates calculated with the output of other languages to discover any anomalies in the handling of dates which may be due to, for example, overflow in types used to represent dates/times similar to y2k type problems.
| #Oberon-2 | Oberon-2 |
MODULE DayOfWeek;
IMPORT NPCT:Dates, Out;
VAR
year: INTEGER;
date: Dates.Date;
BEGIN
FOR year := 2008 TO 2121 DO
date := Dates.NewDate(25,12,year);
IF date.DayOfWeek() = Dates.sunday THEN
Out.Int(date.year,4);Out.Ln
END
END
END DayOfWeek.
|
http://rosettacode.org/wiki/CUSIP | CUSIP |
This page uses content from Wikipedia. The original article was at CUSIP. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
A CUSIP is a nine-character alphanumeric code that identifies a North American financial security for the purposes of facilitating clearing and settlement of trades. The CUSIP was adopted as an American National Standard under Accredited Standards X9.6.
Task
Ensure the last digit (i.e., the check digit) of the CUSIP code (the 1st column) is correct, against the following:
037833100 Apple Incorporated
17275R102 Cisco Systems
38259P508 Google Incorporated
594918104 Microsoft Corporation
68389X106 Oracle Corporation (incorrect)
68389X105 Oracle Corporation
Example pseudo-code below.
algorithm Cusip-Check-Digit(cusip) is
Input: an 8-character CUSIP
sum := 0
for 1 ≤ i ≤ 8 do
c := the ith character of cusip
if c is a digit then
v := numeric value of the digit c
else if c is a letter then
p := ordinal position of c in the alphabet (A=1, B=2...)
v := p + 9
else if c = "*" then
v := 36
else if c = "@" then
v := 37
else if' c = "#" then
v := 38
end if
if i is even then
v := v × 2
end if
sum := sum + int ( v div 10 ) + v mod 10
repeat
return (10 - (sum mod 10)) mod 10
end function
See related tasks
SEDOL
ISIN
| #Vlang | Vlang | fn is_cusip(s string) bool {
if s.len != 9 { return false }
mut sum := 0
for i in 0..8 {
c := s[i]
mut v :=0
match true {
c >= '0'[0] && c <= '9'[0] {
v = c - 48
}
c >= 'A'[0] && c <= 'Z'[0] {
v = c - 55
}
c == '*'[0] {
v = 36
}
c == '@'[0] {
v = 37
}
c == '#'[0] {
v = 38
}
else {
return false
}
}
if i % 2 == 1 { v *= 2 } // check if odd as using 0-based indexing
sum += v/10 + v%10
}
return int(s[8]) - 48 == (10 - (sum%10)) % 10
}
fn main() {
candidates := [
"037833100",
"17275R102",
"38259P508",
"594918104",
"68389X106",
"68389X105",
]
for candidate in candidates {
mut b :=' '
if is_cusip(candidate) {
b = "correct"
} else {
b = "incorrect"
}
println("$candidate -> $b")
}
} |
http://rosettacode.org/wiki/CUSIP | CUSIP |
This page uses content from Wikipedia. The original article was at CUSIP. The list of authors can be seen in the page history. As with Rosetta Code, the text of Wikipedia is available under the GNU FDL. (See links for details on variance)
A CUSIP is a nine-character alphanumeric code that identifies a North American financial security for the purposes of facilitating clearing and settlement of trades. The CUSIP was adopted as an American National Standard under Accredited Standards X9.6.
Task
Ensure the last digit (i.e., the check digit) of the CUSIP code (the 1st column) is correct, against the following:
037833100 Apple Incorporated
17275R102 Cisco Systems
38259P508 Google Incorporated
594918104 Microsoft Corporation
68389X106 Oracle Corporation (incorrect)
68389X105 Oracle Corporation
Example pseudo-code below.
algorithm Cusip-Check-Digit(cusip) is
Input: an 8-character CUSIP
sum := 0
for 1 ≤ i ≤ 8 do
c := the ith character of cusip
if c is a digit then
v := numeric value of the digit c
else if c is a letter then
p := ordinal position of c in the alphabet (A=1, B=2...)
v := p + 9
else if c = "*" then
v := 36
else if c = "@" then
v := 37
else if' c = "#" then
v := 38
end if
if i is even then
v := v × 2
end if
sum := sum + int ( v div 10 ) + v mod 10
repeat
return (10 - (sum mod 10)) mod 10
end function
See related tasks
SEDOL
ISIN
| #Wren | Wren | var isCusip = Fn.new { |s|
if (s.count != 9) return false
var sum = 0
for (i in 0..7) {
var c = s[i].bytes[0]
var v
if (c >= 48 && c <= 57) { // '0' to '9'
v = c - 48
} else if (c >= 65 && c <= 90) { // 'A' to 'Z'
v = c - 55
} else if (s[i] == "*") {
v = 36
} else if (s[i] == "@") {
v = 37
} else if (s[i] == "#") {
v = 38
} else {
return false
}
if (i%2 == 1) v = v * 2 // check if odd as using 0-based indexing
sum = sum + (v/10).floor + v%10
}
return s[8].bytes[0] - 48 == (10 - (sum%10)) % 10
}
var candidates = [
"037833100",
"17275R102",
"38259P508",
"594918104",
"68389X106",
"68389X105"
]
for (candidate in candidates) {
var b = (isCusip.call(candidate)) ? "correct" : "incorrect"
System.print("%(candidate) -> %(b)")
} |
http://rosettacode.org/wiki/Create_a_two-dimensional_array_at_runtime | Create a two-dimensional array at runtime |
Data Structure
This illustrates a data structure, a means of storing data within a program.
You may see other such structures in the Data Structures category.
Get two integers from the user, then create a two-dimensional array where the two dimensions have the sizes given by those numbers, and which can be accessed in the most natural way possible. Write some element of that array, and then output that element. Finally destroy the array if not done by the language itself.
| #Crystal | Crystal | require "random"
first = gets.not_nil!.to_i32
second = gets.not_nil!.to_i32
arr = Array(Array(Int32)).new(first, Array(Int32).new second, 0)
random = Random.new
first = random.rand 0..(first - 1)
second = random.rand 0..(second - 1)
arr[first][second] = random.next_int
puts arr[first][second] |
http://rosettacode.org/wiki/Cumulative_standard_deviation | Cumulative standard deviation | Task[edit]
Write a stateful function, class, generator or co-routine that takes a series of floating point numbers, one at a time, and returns the running standard deviation of the series.
The task implementation should use the most natural programming style of those listed for the function in the implementation language; the task must state which is being used.
Do not apply Bessel's correction; the returned standard deviation should always be computed as if the sample seen so far is the entire population.
Test case
Use this to compute the standard deviation of this demonstration set,
{
2
,
4
,
4
,
4
,
5
,
5
,
7
,
9
}
{\displaystyle \{2,4,4,4,5,5,7,9\}}
, which is
2
{\displaystyle 2}
.
Related tasks
Random numbers
Tasks for calculating statistical measures
in one go
moving (sliding window)
moving (cumulative)
Mean
Arithmetic
Statistics/Basic
Averages/Arithmetic mean
Averages/Pythagorean means
Averages/Simple moving average
Geometric
Averages/Pythagorean means
Harmonic
Averages/Pythagorean means
Quadratic
Averages/Root mean square
Circular
Averages/Mean angle
Averages/Mean time of day
Median
Averages/Median
Mode
Averages/Mode
Standard deviation
Statistics/Basic
Cumulative standard deviation
| #Go | Go | package main
import (
"fmt"
"math"
)
func newRsdv() func(float64) float64 {
var n, a, q float64
return func(x float64) float64 {
n++
a1 := a+(x-a)/n
q, a = q+(x-a)*(x-a1), a1
return math.Sqrt(q/n)
}
}
func main() {
r := newRsdv()
for _, x := range []float64{2,4,4,4,5,5,7,9} {
fmt.Println(r(x))
}
} |
http://rosettacode.org/wiki/CRC-32 | CRC-32 |
Task
Demonstrate a method of deriving the Cyclic Redundancy Check from within the language.
The result should be in accordance with ISO 3309, ITU-T V.42, Gzip and PNG.
Algorithms are described on Computation of CRC in Wikipedia.
This variant of CRC-32 uses LSB-first order, sets the initial CRC to FFFFFFFF16, and complements the final CRC.
For the purpose of this task, generate a CRC-32 checksum for the ASCII encoded string:
The quick brown fox jumps over the lazy dog
| #Haxe | Haxe | using StringTools;
class Main {
static function main() {
var data = haxe.io.Bytes.ofString("The quick brown fox jumps over the lazy dog");
var crc = haxe.crypto.Crc32.make(data);
Sys.println(crc.hex());
}
} |
http://rosettacode.org/wiki/CRC-32 | CRC-32 |
Task
Demonstrate a method of deriving the Cyclic Redundancy Check from within the language.
The result should be in accordance with ISO 3309, ITU-T V.42, Gzip and PNG.
Algorithms are described on Computation of CRC in Wikipedia.
This variant of CRC-32 uses LSB-first order, sets the initial CRC to FFFFFFFF16, and complements the final CRC.
For the purpose of this task, generate a CRC-32 checksum for the ASCII encoded string:
The quick brown fox jumps over the lazy dog
| #Icon_and_Unicon | Icon and Unicon | link hexcvt,printf
procedure main()
s := "The quick brown fox jumps over the lazy dog"
a := "414FA339"
printf("crc(%i)=%s - implementation is %s\n",
s,r := crc32(s),if r == a then "correct" else "in error")
end
procedure crc32(s) #: return crc-32 (ISO 3309, ITU-T V.42, Gzip, PNG) of s
static crcL,mask
initial {
crcL := list(256) # crc table
p := [0,1,2,4,5,7,8,10,11,12,16,22,23,26] # polynomial terms
mask := 2^32-1 # word size mask
every (poly := 0) := ior(poly,ishift(1,31-p[1 to *p]))
every c := n := 0 to *crcL-1 do { # table
every 1 to 8 do
c := iand(mask,
if iand(c,1) = 1 then
ixor(poly,ishift(c,-1))
else
ishift(c,-1)
)
crcL[n+1] := c
}
}
crc := ixor(0,mask) # invert bits
every crc := iand(mask,
ixor(crcL[iand(255,ixor(crc,ord(!s)))+1],ishift(crc,-8)))
return hexstring(ixor(crc,mask)) # return hexstring
end |
http://rosettacode.org/wiki/Count_the_coins | Count the coins | There are four types of common coins in US currency:
quarters (25 cents)
dimes (10 cents)
nickels (5 cents), and
pennies (1 cent)
There are six ways to make change for 15 cents:
A dime and a nickel
A dime and 5 pennies
3 nickels
2 nickels and 5 pennies
A nickel and 10 pennies
15 pennies
Task
How many ways are there to make change for a dollar using these common coins? (1 dollar = 100 cents).
Optional
Less common are dollar coins (100 cents); and very rare are half dollars (50 cents). With the addition of these two coins, how many ways are there to make change for $1000?
(Note: the answer is larger than 232).
References
an algorithm from the book Structure and Interpretation of Computer Programs.
an article in the algorithmist.
Change-making problem on Wikipedia.
| #C.23 | C# |
// Adapted from http://www.geeksforgeeks.org/dynamic-programming-set-7-coin-change/
class Program
{
static long Count(int[] C, int m, int n)
{
var table = new long[n + 1];
table[0] = 1;
for (int i = 0; i < m; i++)
for (int j = C[i]; j <= n; j++)
table[j] += table[j - C[i]];
return table[n];
}
static void Main(string[] args)
{
var C = new int[] { 1, 5, 10, 25 };
int m = C.Length;
int n = 100;
Console.WriteLine(Count(C, m, n)); //242
Console.ReadLine();
}
}
|
http://rosettacode.org/wiki/Count_occurrences_of_a_substring | Count occurrences of a substring | Task
Create a function, or show a built-in function, to count the number of non-overlapping occurrences of a substring inside a string.
The function should take two arguments:
the first argument being the string to search, and
the second a substring to be searched for.
It should return an integer count.
print countSubstring("the three truths","th")
3
// do not count substrings that overlap with previously-counted substrings:
print countSubstring("ababababab","abab")
2
The matching should yield the highest number of non-overlapping matches.
In general, this essentially means matching from left-to-right or right-to-left (see proof on talk page).
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #APL | APL | csubs←{0=x←⊃⍸⍺⍷⍵:0 ⋄ 1+⍺∇(¯1+x+⍴⍺)↓⍵} |
http://rosettacode.org/wiki/Count_occurrences_of_a_substring | Count occurrences of a substring | Task
Create a function, or show a built-in function, to count the number of non-overlapping occurrences of a substring inside a string.
The function should take two arguments:
the first argument being the string to search, and
the second a substring to be searched for.
It should return an integer count.
print countSubstring("the three truths","th")
3
// do not count substrings that overlap with previously-counted substrings:
print countSubstring("ababababab","abab")
2
The matching should yield the highest number of non-overlapping matches.
In general, this essentially means matching from left-to-right or right-to-left (see proof on talk page).
Other tasks related to string operations:
Metrics
Array length
String length
Copy a string
Empty string (assignment)
Counting
Word frequency
Letter frequency
Jewels and stones
I before E except after C
Bioinformatics/base count
Count occurrences of a substring
Count how many vowels and consonants occur in a string
Remove/replace
XXXX redacted
Conjugate a Latin verb
Remove vowels from a string
String interpolation (included)
Strip block comments
Strip comments from a string
Strip a set of characters from a string
Strip whitespace from a string -- top and tail
Strip control codes and extended characters from a string
Anagrams/Derangements/shuffling
Word wheel
ABC problem
Sattolo cycle
Knuth shuffle
Ordered words
Superpermutation minimisation
Textonyms (using a phone text pad)
Anagrams
Anagrams/Deranged anagrams
Permutations/Derangements
Find/Search/Determine
ABC words
Odd words
Word ladder
Semordnilap
Word search
Wordiff (game)
String matching
Tea cup rim text
Alternade words
Changeable words
State name puzzle
String comparison
Unique characters
Unique characters in each string
Extract file extension
Levenshtein distance
Palindrome detection
Common list elements
Longest common suffix
Longest common prefix
Compare a list of strings
Longest common substring
Find common directory path
Words from neighbour ones
Change e letters to i in words
Non-continuous subsequences
Longest common subsequence
Longest palindromic substrings
Longest increasing subsequence
Words containing "the" substring
Sum of the digits of n is substring of n
Determine if a string is numeric
Determine if a string is collapsible
Determine if a string is squeezable
Determine if a string has all unique characters
Determine if a string has all the same characters
Longest substrings without repeating characters
Find words which contains all the vowels
Find words which contains most consonants
Find words which contains more than 3 vowels
Find words which first and last three letters are equals
Find words which odd letters are consonants and even letters are vowels or vice_versa
Formatting
Substring
Rep-string
Word wrap
String case
Align columns
Literals/String
Repeat a string
Brace expansion
Brace expansion using ranges
Reverse a string
Phrase reversals
Comma quibbling
Special characters
String concatenation
Substring/Top and tail
Commatizing numbers
Reverse words in a string
Suffixation of decimal numbers
Long literals, with continuations
Numerical and alphabetical suffixes
Abbreviations, easy
Abbreviations, simple
Abbreviations, automatic
Song lyrics/poems/Mad Libs/phrases
Mad Libs
Magic 8-ball
99 Bottles of Beer
The Name Game (a song)
The Old lady swallowed a fly
The Twelve Days of Christmas
Tokenize
Text between
Tokenize a string
Word break problem
Tokenize a string with escaping
Split a character string based on change of character
Sequences
Show ASCII table
De Bruijn sequences
Self-referential sequences
Generate lower case ASCII alphabet
| #AppleScript | AppleScript | use framework "OSAKit"
on run
{countSubstring("the three truths", "th"), ¬
countSubstring("ababababab", "abab")}
end run
on countSubstring(str, subStr)
return evalOSA("JavaScript", "var matches = '" & str & "'" & ¬
".match(new RegExp('" & subStr & "', 'g'));" & ¬
"matches ? matches.length : 0") as integer
end countSubstring
-- evalOSA :: ("JavaScript" | "AppleScript") -> String -> String
on evalOSA(strLang, strCode)
set ca to current application
set oScript to ca's OSAScript's alloc's initWithSource:strCode ¬
|language|:(ca's OSALanguage's languageForName:(strLang))
set {blnCompiled, oError} to oScript's compileAndReturnError:(reference)
if blnCompiled then
set {oDesc, oError} to oScript's executeAndReturnError:(reference)
if (oError is missing value) then return oDesc's stringValue as text
end if
return oError's NSLocalizedDescription as text
end evalOSA |
http://rosettacode.org/wiki/Count_in_octal | Count in octal | Task
Produce a sequential count in octal, starting at zero, and using an increment of a one for each consecutive number.
Each number should appear on a single line, and the program should count until terminated, or until the maximum value of the numeric type in use is reached.
Related task
Integer sequence is a similar task without the use of octal numbers.
| #ALGOL_W | ALGOL W | begin
string(12) r;
string(8) octDigits;
integer number;
octDigits := "01234567";
number := -1;
while number < MAXINTEGER do begin
integer v, cPos;
number := number + 1;
v := number;
% build a string of octal digits in r, representing number %
% Algol W uses 32 bit integers, so r should be big enough %
% the most significant digit is on the right %
cPos := 0;
while begin
r( cPos // 1 ) := octDigits( v rem 8 // 1 );
v := v div 8;
( v > 0 )
end do begin
cPos := cPos + 1
end while_v_gt_0;
% show most significant digit on a newline %
write( r( cPos // 1 ) );
% continue the line with the remaining digits (if any) %
for c := cPos - 1 step -1 until 0 do writeon( r( c // 1 ) )
end while_r_lt_MAXINTEGER
end. |
http://rosettacode.org/wiki/Count_in_octal | Count in octal | Task
Produce a sequential count in octal, starting at zero, and using an increment of a one for each consecutive number.
Each number should appear on a single line, and the program should count until terminated, or until the maximum value of the numeric type in use is reached.
Related task
Integer sequence is a similar task without the use of octal numbers.
| #APL | APL | 10⊥¨8∘⊥⍣¯1¨⍳100000 |
http://rosettacode.org/wiki/Count_in_factors | Count in factors | Task
Write a program which counts up from 1, displaying each number as the multiplication of its prime factors.
For the purpose of this task, 1 (unity) may be shown as itself.
Example
2 is prime, so it would be shown as itself.
6 is not prime; it would be shown as
2
×
3
{\displaystyle 2\times 3}
.
2144 is not prime; it would be shown as
2
×
2
×
2
×
2
×
2
×
67
{\displaystyle 2\times 2\times 2\times 2\times 2\times 67}
.
Related tasks
prime decomposition
factors of an integer
Sieve of Eratosthenes
primality by trial division
factors of a Mersenne number
trial factoring of a Mersenne number
partition an integer X into N primes
| #ARM_Assembly | ARM Assembly |
/* ARM assembly Raspberry PI */
/* program countFactors.s */
/* REMARK 1 : this program use routines in a include file
see task Include a file language arm assembly
for the routine affichageMess conversion10
see at end of this program the instruction include */
/* for constantes see task include a file in arm assembly */
/************************************/
/* Constantes */
/************************************/
.include "../constantes.inc"
.equ NBFACT, 33
.equ MAXI, 1<<31
//.equ NOMBRE, 65537
//.equ NOMBRE, 99999999
.equ NOMBRE, 2144
//.equ NOMBRE, 529
/*********************************/
/* Initialized data */
/*********************************/
.data
szMessNumber: .asciz "Number @ : "
szMessResultFact: .asciz "@ "
szCarriageReturn: .asciz "\n"
szErrorGen: .asciz "Program error !!!\n"
szMessPrime: .asciz "This number is prime.\n"
/*********************************/
/* UnInitialized data */
/*********************************/
.bss
sZoneConv: .skip 24
tbZoneDecom: .skip 8 * NBFACT // factor 4 bytes, number of each factor 4 bytes
/*********************************/
/* code section */
/*********************************/
.text
.global main
main: @ entry of program
ldr r7,iNombre @ number
mov r0,r7
ldr r1,iAdrsZoneConv
bl conversion10 @ call décimal conversion
ldr r0,iAdrszMessNumber
ldr r1,iAdrsZoneConv @ insert conversion in message
bl strInsertAtCharInc
bl affichageMess @ display message
mov r0,r7
ldr r1,iAdrtbZoneDecom
bl decompFact
cmp r0,#-1
beq 98f @ error ?
mov r1,r0
ldr r0,iAdrtbZoneDecom
bl displayDivisors
b 100f
98:
ldr r0,iAdrszErrorGen
bl affichageMess
100: @ standard end of the program
mov r0, #0 @ return code
mov r7, #EXIT @ request to exit program
svc #0 @ perform the system call
iAdrszCarriageReturn: .int szCarriageReturn
iAdrszMessResultFact: .int szMessResultFact
iAdrszErrorGen: .int szErrorGen
iAdrsZoneConv: .int sZoneConv
iAdrtbZoneDecom: .int tbZoneDecom
iAdrszMessNumber: .int szMessNumber
iNombre: .int NOMBRE
/******************************************************************/
/* display divisors function */
/******************************************************************/
/* r0 contains address of divisors area */
/* r1 contains the number of area items */
displayDivisors:
push {r2-r8,lr} @ save registers
cmp r1,#0
beq 100f
mov r2,r1
mov r3,#0 @ indice
mov r4,r0
1:
add r5,r4,r3,lsl #3
ldr r7,[r5] @ load factor
ldr r6,[r5,#4] @ load number of factor
mov r8,#0 @ display factor counter
2:
mov r0,r7
ldr r1,iAdrsZoneConv
bl conversion10 @ call décimal conversion
ldr r0,iAdrszMessResultFact
ldr r1,iAdrsZoneConv @ insert conversion in message
bl strInsertAtCharInc
bl affichageMess @ display message
add r8,#1 @ increment counter
cmp r8,r6 @ same factors number ?
blt 2b
add r3,#1 @ other ithem
cmp r3,r2 @ items maxi ?
blt 1b
ldr r0,iAdrszCarriageReturn
bl affichageMess
b 100f
100:
pop {r2-r8,lr} @ restaur registers
bx lr @ return
/******************************************************************/
/* factor decomposition */
/******************************************************************/
/* r0 contains number */
/* r1 contains address of divisors area */
/* r0 return divisors items in table */
decompFact:
push {r1-r8,lr} @ save registers
mov r5,r1
mov r8,r0 @ save number
bl isPrime @ prime ?
cmp r0,#1
beq 98f @ yes is prime
mov r4,#0 @ raz indice
mov r1,#2 @ first divisor
mov r6,#0 @ previous divisor
mov r7,#0 @ number of same divisors
2:
mov r0,r8 @ dividende
bl division @ r1 divisor r2 quotient r3 remainder
cmp r3,#0
bne 5f @ if remainder <> zero -> no divisor
mov r8,r2 @ else quotient -> new dividende
cmp r1,r6 @ same divisor ?
beq 4f @ yes
cmp r6,#0 @ no but is the first divisor ?
beq 3f @ yes
str r6,[r5,r4,lsl #2] @ else store in the table
add r4,r4,#1 @ and increment counter
str r7,[r5,r4,lsl #2] @ store counter
add r4,r4,#1 @ next item
mov r7,#0 @ and raz counter
3:
mov r6,r1 @ new divisor
4:
add r7,r7,#1 @ increment counter
b 7f @ and loop
/* not divisor -> increment next divisor */
5:
cmp r1,#2 @ if divisor = 2 -> add 1
addeq r1,#1
addne r1,#2 @ else add 2
b 2b
/* divisor -> test if new dividende is prime */
7:
mov r3,r1 @ save divisor
cmp r8,#1 @ dividende = 1 ? -> end
beq 10f
mov r0,r8 @ new dividende is prime ?
mov r1,#0
bl isPrime @ the new dividende is prime ?
cmp r0,#1
bne 10f @ the new dividende is not prime
cmp r8,r6 @ else dividende is same divisor ?
beq 9f @ yes
cmp r6,#0 @ no but is the first divisor ?
beq 8f @ yes it is a first
str r6,[r5,r4,lsl #2] @ else store in table
add r4,r4,#1 @ and increment counter
str r7,[r5,r4,lsl #2] @ and store counter
add r4,r4,#1 @ next item
8:
mov r6,r8 @ new dividende -> divisor prec
mov r7,#0 @ and raz counter
9:
add r7,r7,#1 @ increment counter
b 11f
10:
mov r1,r3 @ current divisor = new divisor
cmp r1,r8 @ current divisor > new dividende ?
ble 2b @ no -> loop
/* end decomposition */
11:
str r6,[r5,r4,lsl #2] @ store last divisor
add r4,r4,#1
str r7,[r5,r4,lsl #2] @ and store last number of same divisors
add r4,r4,#1
lsr r0,r4,#1 @ return number of table items
mov r3,#0
str r3,[r5,r4,lsl #2] @ store zéro in last table item
add r4,r4,#1
str r3,[r5,r4,lsl #2] @ and zero in counter same divisor
b 100f
98:
ldr r0,iAdrszMessPrime
bl affichageMess
mov r0,#1 @ return code
b 100f
99:
ldr r0,iAdrszErrorGen
bl affichageMess
mov r0,#-1 @ error code
b 100f
100:
pop {r1-r8,lr} @ restaur registers
bx lr
iAdrszMessPrime: .int szMessPrime
/***************************************************/
/* check if a number is prime */
/***************************************************/
/* r0 contains the number */
/* r0 return 1 if prime 0 else */
@2147483647
@4294967297
@131071
isPrime:
push {r1-r6,lr} @ save registers
cmp r0,#0
beq 90f
cmp r0,#17
bhi 1f
cmp r0,#3
bls 80f @ for 1,2,3 return prime
cmp r0,#5
beq 80f @ for 5 return prime
cmp r0,#7
beq 80f @ for 7 return prime
cmp r0,#11
beq 80f @ for 11 return prime
cmp r0,#13
beq 80f @ for 13 return prime
cmp r0,#17
beq 80f @ for 17 return prime
1:
tst r0,#1 @ even ?
beq 90f @ yes -> not prime
mov r2,r0 @ save number
sub r1,r0,#1 @ exposant n - 1
mov r0,#3 @ base
bl moduloPuR32 @ compute base power n - 1 modulo n
cmp r0,#1
bne 90f @ if <> 1 -> not prime
mov r0,#5
bl moduloPuR32
cmp r0,#1
bne 90f
mov r0,#7
bl moduloPuR32
cmp r0,#1
bne 90f
mov r0,#11
bl moduloPuR32
cmp r0,#1
bne 90f
mov r0,#13
bl moduloPuR32
cmp r0,#1
bne 90f
mov r0,#17
bl moduloPuR32
cmp r0,#1
bne 90f
80:
mov r0,#1 @ is prime
b 100f
90:
mov r0,#0 @ no prime
100: @ fin standard de la fonction
pop {r1-r6,lr} @ restaur des registres
bx lr @ retour de la fonction en utilisant lr
/********************************************************/
/* Calcul modulo de b puissance e modulo m */
/* Exemple 4 puissance 13 modulo 497 = 445 */
/* */
/********************************************************/
/* r0 nombre */
/* r1 exposant */
/* r2 modulo */
/* r0 return result */
moduloPuR32:
push {r1-r7,lr} @ save registers
cmp r0,#0 @ verif <> zero
beq 100f
cmp r2,#0 @ verif <> zero
beq 100f @
1:
mov r4,r2 @ save modulo
mov r5,r1 @ save exposant
mov r6,r0 @ save base
mov r3,#1 @ start result
mov r1,#0 @ division de r0,r1 par r2
bl division32R
mov r6,r2 @ base <- remainder
2:
tst r5,#1 @ exposant even or odd
beq 3f
umull r0,r1,r6,r3
mov r2,r4
bl division32R
mov r3,r2 @ result <- remainder
3:
umull r0,r1,r6,r6
mov r2,r4
bl division32R
mov r6,r2 @ base <- remainder
lsr r5,#1 @ left shift 1 bit
cmp r5,#0 @ end ?
bne 2b
mov r0,r3
100: @ fin standard de la fonction
pop {r1-r7,lr} @ restaur des registres
bx lr @ retour de la fonction en utilisant lr
/***************************************************/
/* division number 64 bits in 2 registers by number 32 bits */
/***************************************************/
/* r0 contains lower part dividende */
/* r1 contains upper part dividende */
/* r2 contains divisor */
/* r0 return lower part quotient */
/* r1 return upper part quotient */
/* r2 return remainder */
division32R:
push {r3-r9,lr} @ save registers
mov r6,#0 @ init upper upper part remainder !!
mov r7,r1 @ init upper part remainder with upper part dividende
mov r8,r0 @ init lower part remainder with lower part dividende
mov r9,#0 @ upper part quotient
mov r4,#0 @ lower part quotient
mov r5,#32 @ bits number
1: @ begin loop
lsl r6,#1 @ shift upper upper part remainder
lsls r7,#1 @ shift upper part remainder
orrcs r6,#1
lsls r8,#1 @ shift lower part remainder
orrcs r7,#1
lsls r4,#1 @ shift lower part quotient
lsl r9,#1 @ shift upper part quotient
orrcs r9,#1
@ divisor sustract upper part remainder
subs r7,r2
sbcs r6,#0 @ and substract carry
bmi 2f @ négative ?
@ positive or equal
orr r4,#1 @ 1 -> right bit quotient
b 3f
2: @ negative
orr r4,#0 @ 0 -> right bit quotient
adds r7,r2 @ and restaur remainder
adc r6,#0
3:
subs r5,#1 @ decrement bit size
bgt 1b @ end ?
mov r0,r4 @ lower part quotient
mov r1,r9 @ upper part quotient
mov r2,r7 @ remainder
100: @ function end
pop {r3-r9,lr} @ restaur registers
bx lr
/***************************************************/
/* ROUTINES INCLUDE */
/***************************************************/
.include "../affichage.inc"
|
http://rosettacode.org/wiki/Create_an_HTML_table | Create an HTML table | Create an HTML table.
The table body should have at least three rows of three columns.
Each of these three columns should be labelled "X", "Y", and "Z".
An extra column should be added at either the extreme left or the extreme right of the table that has no heading, but is filled with sequential row numbers.
The rows of the "X", "Y", and "Z" columns should be filled with random or sequential integers having 4 digits or less.
The numbers should be aligned in the same fashion for all columns.
| #BBC_BASIC | BBC BASIC | ncols% = 3
nrows% = 4
*spool temp.htm
PRINT "<html><head></head><body>"
PRINT "<table border=1 cellpadding=10 cellspacing=0>"
FOR row% = 0 TO nrows%
IF row% = 0 THEN
PRINT "<tr><th></th>" ;
ELSE
PRINT "<tr><th>" ; row% "</th>" ;
ENDIF
FOR col% = 1 TO ncols%
IF row% = 0 THEN
PRINT "<th>" CHR$(87 + col%) "</th>" ;
ELSE
PRINT "<td align=""right"">" ; RND(9999) "</td>" ;
ENDIF
NEXT col%
PRINT "</tr>"
NEXT row%
PRINT "</table>"
PRINT "</body></html>"
*spool
SYS "ShellExecute", @hwnd%, 0, "temp.htm", 0, 0, 1
|
http://rosettacode.org/wiki/Date_format | Date format | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Task
Display the current date in the formats of:
2007-11-23 and
Friday, November 23, 2007
| #mIRC_Scripting_Language | mIRC Scripting Language | echo -ag $time(yyyy-mm-dd)
echo -ag $time(dddd $+ $chr(44) mmmm dd $+ $chr(44) yyyy) |
http://rosettacode.org/wiki/Date_format | Date format | This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.
Task
Display the current date in the formats of:
2007-11-23 and
Friday, November 23, 2007
| #MUMPS | MUMPS | DTZ
WRITE !,"Date format 3: ",$ZDATE($H,3)
WRITE !,"Or ",$ZDATE($H,12),", ",$ZDATE($H,9)
QUIT |
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