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pythondev
help
<@Keena> In python 3 a lambda doesn’t take multiple params. You need to access the params as a list, so `return sorted(dict_of_word_count.iteritems(), key=lambda v_k: (v_k[1],v_k[0]), reverse=True)[0:20]` should work I think (found at <http://cheng.logdown.com/posts/2016/11/30/python3-lambda-parameter>)
2019-02-25T11:28:00.569800
Clemmie
pythondev_help_Clemmie_2019-02-25T11:28:00.569800
1,551,094,080.5698
10,421
pythondev
help
<@Clemmie> thanks for quick reply. will look into it. is this good? --&gt; return sorted(dict_of_word_count.iteritems(), key=lambda k_v: v_k[1], reverse=True)[0:20]
2019-02-25T11:29:20.570500
Keena
pythondev_help_Keena_2019-02-25T11:29:20.570500
1,551,094,160.5705
10,422
pythondev
help
if you want to sort on the values that should work I think, yes
2019-02-25T11:37:56.571400
Clemmie
pythondev_help_Clemmie_2019-02-25T11:37:56.571400
1,551,094,676.5714
10,423
pythondev
help
but you switch the name `v_k` and `k_v` - jsut keep that variable name consistent
2019-02-25T11:38:35.571800
Clemmie
pythondev_help_Clemmie_2019-02-25T11:38:35.571800
1,551,094,715.5718
10,424
pythondev
help
`k_v` is more correct
2019-02-25T11:38:47.572100
Clemmie
pythondev_help_Clemmie_2019-02-25T11:38:47.572100
1,551,094,727.5721
10,425
pythondev
help
actually I got that code snippet on web as lambda(v, k): (k, v), reverse=True
2019-02-25T11:39:27.573000
Keena
pythondev_help_Keena_2019-02-25T11:39:27.573000
1,551,094,767.573
10,426
pythondev
help
so I thought about doing that thing
2019-02-25T11:39:41.573400
Keena
pythondev_help_Keena_2019-02-25T11:39:41.573400
1,551,094,781.5734
10,427
pythondev
help
what do you say?
2019-02-25T11:39:47.573700
Keena
pythondev_help_Keena_2019-02-25T11:39:47.573700
1,551,094,787.5737
10,428
pythondev
help
Right, but now you are naming one variable, not multiples. Before you named them so you could sort on them in reverse (v,k -&gt; k,v), now it is just one and you are using the list index to pick them out
2019-02-25T11:41:01.575100
Clemmie
pythondev_help_Clemmie_2019-02-25T11:41:01.575100
1,551,094,861.5751
10,429
pythondev
help
`iteritems()` gives a them as `(key, value)` so `k_v` is most internally consistent
2019-02-25T11:41:51.576000
Clemmie
pythondev_help_Clemmie_2019-02-25T11:41:51.576000
1,551,094,911.576
10,430
pythondev
help
<@Marth> Are your friends technical? Are you expecting them to run the script? Visit a webpage? The exactly workflow you want your friends to follow to get the data will help dictate what tools make the most sense.
2019-02-25T11:42:51.576300
Carmen
pythondev_help_Carmen_2019-02-25T11:42:51.576300
1,551,094,971.5763
10,431
pythondev
help
got your point. trying out the thing which you explained.thank you buddy.
2019-02-25T11:44:39.576400
Keena
pythondev_help_Keena_2019-02-25T11:44:39.576400
1,551,095,079.5764
10,432
pythondev
help
:thumbsup:
2019-02-25T11:44:54.576600
Clemmie
pythondev_help_Clemmie_2019-02-25T11:44:54.576600
1,551,095,094.5766
10,433
pythondev
help
<@Carmen> They're gamers....so while certainly computer savvy, not "technical" in the sense that I'm not expecting them to edit the script. I'm expecting them to run the script which will provide an interface. That interface is going to list their twitch clips and allow them to sort/filter and then download those clips. Currently, (as I'm told) filtering and sorting their clips is really bad....and then Twitch DOES allow them to download their clips, but it takes 3+ clicks per clip. So I'm trying to help automate that process. I'm not sure if a local .exe with gui or a webpage makes more sense.
2019-02-25T11:56:46.583900
Marth
pythondev_help_Marth_2019-02-25T11:56:46.583900
1,551,095,806.5839
10,434
pythondev
help
Well it depends if you are familiar with any of the two
2019-02-25T11:59:41.584400
Jimmy
pythondev_help_Jimmy_2019-02-25T11:59:41.584400
1,551,095,981.5844
10,435
pythondev
help
I think you could honestly use either for that. If you've got webdev experience, doing it as a webapp might be easier than learning GUI programming, but if you'd have to learn either, I'd probably argue this particular app makes more sense as a local exe with GUI.
2019-02-25T12:01:25.585700
Carmen
pythondev_help_Carmen_2019-02-25T12:01:25.585700
1,551,096,085.5857
10,436
pythondev
help
awesome. Thanks! That's helpful! <@Carmen> :taco:
2019-02-25T12:16:26.586400
Marth
pythondev_help_Marth_2019-02-25T12:16:26.586400
1,551,096,986.5864
10,437
pythondev
help
you could use something like Electron
2019-02-25T12:17:38.586600
Mica
pythondev_help_Mica_2019-02-25T12:17:38.586600
1,551,097,058.5866
10,438
pythondev
help
basically a local desktop application built with web tech
2019-02-25T12:17:48.587000
Mica
pythondev_help_Mica_2019-02-25T12:17:48.587000
1,551,097,068.587
10,439
pythondev
help
<https://www.pyinstaller.org/> is also an option, if you want to keep it mostly-Python
2019-02-25T12:19:40.588000
Carmen
pythondev_help_Carmen_2019-02-25T12:19:40.588000
1,551,097,180.588
10,440
pythondev
help
Hello all, I want to alternate capital and lowercase letters into a new array. The way I could think of to capitalize letters was breaking the original word into two arrays. I want to join them back but alternate the letters when I do so. I keep running into the error and am stumped. If anyone could lend some advice, I would appreciate it. if i % 2 == 0: TypeError: not all arguments converted during string formatting
2019-02-25T12:19:50.588200
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:19:50.588200
1,551,097,190.5882
10,441
pythondev
help
Thanks <@Mica> I'll look into that as well...I'm sure I can google it, but do you happen to know what python libraries/modules I should google for that? Or is that outside of python itself?
2019-02-25T12:20:22.588900
Marth
pythondev_help_Marth_2019-02-25T12:20:22.588900
1,551,097,222.5889
10,442
pythondev
help
<@Leopoldo> `"".join(c.upper() if i % 2 else c.lower() for i, c in enumerate(word))`
2019-02-25T12:22:11.589700
Jonas
pythondev_help_Jonas_2019-02-25T12:22:11.589700
1,551,097,331.5897
10,443
pythondev
help
also the error you have given us is not the one you are experiencing, you are not doing string formatting
2019-02-25T12:22:51.590100
Jonas
pythondev_help_Jonas_2019-02-25T12:22:51.590100
1,551,097,371.5901
10,444
pythondev
help
Note that `for i in word` iterates over the characters in the string, not their index position.
2019-02-25T12:23:57.590900
Sasha
pythondev_help_Sasha_2019-02-25T12:23:57.590900
1,551,097,437.5909
10,445
pythondev
help
<@Jonas> thank you. I’ll play with that and try to understand. What does the c in enumerate(word) do?
2019-02-25T12:25:12.591900
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:25:12.591900
1,551,097,512.5919
10,446
pythondev
help
`enumerate` is a generator that for each iteration, returns a tuple of index, value
2019-02-25T12:25:42.592600
Hiroko
pythondev_help_Hiroko_2019-02-25T12:25:42.592600
1,551,097,542.5926
10,447
pythondev
help
`i` is the index of the location currently being looked at
2019-02-25T12:26:03.593300
Hiroko
pythondev_help_Hiroko_2019-02-25T12:26:03.593300
1,551,097,563.5933
10,448
pythondev
help
<@Sasha> ok so I wouldn’t need to create an array if it’s going to iterate over each character in a string?
2019-02-25T12:26:15.593800
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:26:15.593800
1,551,097,575.5938
10,449
pythondev
help
`c` is the variable name for the value at that index location
2019-02-25T12:26:18.593900
Hiroko
pythondev_help_Hiroko_2019-02-25T12:26:18.593900
1,551,097,578.5939
10,450
pythondev
help
<@Leopoldo> a string is already a list of characters
2019-02-25T12:26:32.594400
Clemmie
pythondev_help_Clemmie_2019-02-25T12:26:32.594400
1,551,097,592.5944
10,451
pythondev
help
<@Hiroko> Thank you for explaining that
2019-02-25T12:26:42.594600
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:26:42.594600
1,551,097,602.5946
10,452
pythondev
help
Well, I was more explaining why `i % 2` was giving you that error. In your code, `i` is a character, not a number.
2019-02-25T12:27:35.595800
Sasha
pythondev_help_Sasha_2019-02-25T12:27:35.595800
1,551,097,655.5958
10,453
pythondev
help
<@Clemmie> ok thanks
2019-02-25T12:28:09.596400
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:28:09.596400
1,551,097,689.5964
10,454
pythondev
help
Ok that makes sense, thank you <@Sasha>
2019-02-25T12:28:31.596800
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:28:31.596800
1,551,097,711.5968
10,455
pythondev
help
If I wanted to use i % 2, then I could combine that with say len(word)
2019-02-25T12:28:56.597200
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:28:56.597200
1,551,097,736.5972
10,456
pythondev
help
And define i = 0
2019-02-25T12:29:13.597400
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:29:13.597400
1,551,097,753.5974
10,457
pythondev
help
Yes, you could do `for i in range(len(word))`. No need for the `i = 0`, since the `for` loop initializes it anyway. But I'd suggest you think about `enumerate` more... it's a nice elegant solution to have access to both the character and its position in your loop.
2019-02-25T12:31:27.599200
Sasha
pythondev_help_Sasha_2019-02-25T12:31:27.599200
1,551,097,887.5992
10,458
pythondev
help
Thank you for that for that @ <@Sasha>. I will do some more research.
2019-02-25T12:32:28.599900
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:32:28.599900
1,551,097,948.5999
10,459
pythondev
help
<@Marth> Electron is based on Node.js and Chromium. So there won't be Python involved at all, really.
2019-02-25T12:37:37.600600
Carmen
pythondev_help_Carmen_2019-02-25T12:37:37.600600
1,551,098,257.6006
10,460
pythondev
help
gotcha
2019-02-25T12:38:19.600800
Marth
pythondev_help_Marth_2019-02-25T12:38:19.600800
1,551,098,299.6008
10,461
pythondev
help
I don’t understand how to implement your suggestion. I’ve tried a couple of different ways but am failing so far. <@Jonas>
2019-02-25T12:47:37.602200
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:47:37.602200
1,551,098,857.6022
10,462
pythondev
help
`bird = ''.join()`
2019-02-25T12:49:24.603100
Candra
pythondev_help_Candra_2019-02-25T12:49:24.603100
1,551,098,964.6031
10,463
pythondev
help
and
2019-02-25T12:50:05.603600
Candra
pythondev_help_Candra_2019-02-25T12:50:05.603600
1,551,099,005.6036
10,464
pythondev
help
also
2019-02-25T12:50:06.603800
Candra
pythondev_help_Candra_2019-02-25T12:50:06.603800
1,551,099,006.6038
10,465
pythondev
help
you have it all in a for loop
2019-02-25T12:50:10.604100
Candra
pythondev_help_Candra_2019-02-25T12:50:10.604100
1,551,099,010.6041
10,466
pythondev
help
<@Leopoldo> you are mixing a few different concepts that each could do it themselves and getting twisted up. The easiest way is:
2019-02-25T12:50:38.604500
Clemmie
pythondev_help_Clemmie_2019-02-25T12:50:38.604500
1,551,099,038.6045
10,467
pythondev
help
``` def myfunc(word ='TEST'): return "".join(c.upper() if i % 2 else c.lower() for i, c in enumerate(word)) myfunc() ```
2019-02-25T12:51:12.605100
Clemmie
pythondev_help_Clemmie_2019-02-25T12:51:12.605100
1,551,099,072.6051
10,468
pythondev
help
None
2019-02-25T12:51:17.605200
Candra
pythondev_help_Candra_2019-02-25T12:51:17.605200
1,551,099,077.6052
10,469
pythondev
help
Thank you <@Candra> That was helpful for me
2019-02-25T12:51:28.605700
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:51:28.605700
1,551,099,088.6057
10,470
pythondev
help
Yep
2019-02-25T12:51:31.605900
Candra
pythondev_help_Candra_2019-02-25T12:51:31.605900
1,551,099,091.6059
10,471
pythondev
help
<@Clemmie> has the same thing
2019-02-25T12:51:39.606400
Candra
pythondev_help_Candra_2019-02-25T12:51:39.606400
1,551,099,099.6064
10,472
pythondev
help
:slightly_smiling_face:
2019-02-25T12:51:40.606600
Candra
pythondev_help_Candra_2019-02-25T12:51:40.606600
1,551,099,100.6066
10,473
pythondev
help
<@Clemmie> Thank you. I didn’t realize it could be done so simply.
2019-02-25T12:51:59.607400
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:51:59.607400
1,551,099,119.6074
10,474
pythondev
help
I can see my attempt was getting confusing. Now that it’s working I’ll take time to understand it a little.
2019-02-25T12:52:40.608400
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:52:40.608400
1,551,099,160.6084
10,475
pythondev
help
What does the ‘’.join() stand for?
2019-02-25T12:53:00.609000
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:53:00.609000
1,551,099,180.609
10,476
pythondev
help
That way <@Candra> and I showed uses a list comprehension in the `join` call. List comprehensions are basically for loops for free, when you want the result to be a list
2019-02-25T12:53:19.609500
Clemmie
pythondev_help_Clemmie_2019-02-25T12:53:19.609500
1,551,099,199.6095
10,477
pythondev
help
`str.join()` takes a list of strings and joins them into one string, with the str you called join on in between
2019-02-25T12:54:08.610600
Clemmie
pythondev_help_Clemmie_2019-02-25T12:54:08.610600
1,551,099,248.6106
10,478
pythondev
help
so `','.join(['1','2','3'])` would result in `"1,2,3"`
2019-02-25T12:54:31.611500
Clemmie
pythondev_help_Clemmie_2019-02-25T12:54:31.611500
1,551,099,271.6115
10,479
pythondev
help
and you did this by initiating an empty string with `''`
2019-02-25T12:54:37.611700
Hiroko
pythondev_help_Hiroko_2019-02-25T12:54:37.611700
1,551,099,277.6117
10,480
pythondev
help
which made the `join` method available, because that’s part of the string type
2019-02-25T12:54:52.612100
Hiroko
pythondev_help_Hiroko_2019-02-25T12:54:52.612100
1,551,099,292.6121
10,481
pythondev
help
Thank you both <@Clemmie> <@Hiroko> You two rock, you’ve helped me a few times before and I really appreciate your patience and explanations.
2019-02-25T12:56:03.613100
Leopoldo
pythondev_help_Leopoldo_2019-02-25T12:56:03.613100
1,551,099,363.6131
10,482
pythondev
help
I'm writing a function that takes in an input from the user and inputs that into a string. But when the user input is blank i want it to default to the word "you" However i can't get it to do that.
2019-02-25T14:03:46.615000
Demetrice
pythondev_help_Demetrice_2019-02-25T14:03:46.615000
1,551,103,426.615
10,483
pythondev
help
what have you tried?
2019-02-25T14:06:24.615400
Clemmie
pythondev_help_Clemmie_2019-02-25T14:06:24.615400
1,551,103,584.6154
10,484
pythondev
help
Actually i think i just figured it out. This seems to be working
2019-02-25T14:08:25.615800
Demetrice
pythondev_help_Demetrice_2019-02-25T14:08:25.615800
1,551,103,705.6158
10,485
pythondev
help
I think i just needed to define Name before the if statement
2019-02-25T14:08:36.616200
Demetrice
pythondev_help_Demetrice_2019-02-25T14:08:36.616200
1,551,103,716.6162
10,486
pythondev
help
Name = input("What is your name?") if Name == '': Name = 'you' def two_fer(name='you'): return("One for %s, one for me." %Name) print(two_fer())
2019-02-25T14:08:37.616400
Demetrice
pythondev_help_Demetrice_2019-02-25T14:08:37.616400
1,551,103,717.6164
10,487
pythondev
help
Well, the first issue is that you are referencing two different variables `Name` != `name`
2019-02-25T14:09:42.617200
Clemmie
pythondev_help_Clemmie_2019-02-25T14:09:42.617200
1,551,103,782.6172
10,488
pythondev
help
also, generally you don’t want to use uppercase for variable names.
2019-02-25T14:10:19.617600
Clemmie
pythondev_help_Clemmie_2019-02-25T14:10:19.617600
1,551,103,819.6176
10,489
pythondev
help
given what you have, with me not changing variable names, you want to pass `Name` in the call to `two_fer()` and in the return you want to use the variable `name` which is scoped to the function
2019-02-25T14:11:32.619200
Clemmie
pythondev_help_Clemmie_2019-02-25T14:11:32.619200
1,551,103,892.6192
10,490
pythondev
help
So i made some minor changes and now this does seem to do what it's supposed to
2019-02-25T14:12:18.619700
Demetrice
pythondev_help_Demetrice_2019-02-25T14:12:18.619700
1,551,103,938.6197
10,491
pythondev
help
But how can i make it better?
2019-02-25T14:12:24.620000
Demetrice
pythondev_help_Demetrice_2019-02-25T14:12:24.620000
1,551,103,944.62
10,492
pythondev
help
lets see
2019-02-25T14:12:33.620200
Clemmie
pythondev_help_Clemmie_2019-02-25T14:12:33.620200
1,551,103,953.6202
10,493
pythondev
help
name = input("What is your name?") if name == '': name = 'you' def two_fer(name='you'): return("One for %s, one for me." %name) print(two_fer())
2019-02-25T14:12:37.620400
Demetrice
pythondev_help_Demetrice_2019-02-25T14:12:37.620400
1,551,103,957.6204
10,494
pythondev
help
so your scoping is still wrong - if you input “Hello” it will still print out “you”
2019-02-25T14:13:26.621000
Clemmie
pythondev_help_Clemmie_2019-02-25T14:13:26.621000
1,551,104,006.621
10,495
pythondev
help
By scoping what line are you referring to? I thought it would only print out you if the user inputs a blank
2019-02-25T14:14:14.621600
Demetrice
pythondev_help_Demetrice_2019-02-25T14:14:14.621600
1,551,104,054.6216
10,496
pythondev
help
This passes the `name` that the user input to the method `two_fer`
2019-02-25T14:14:21.621700
Clemmie
pythondev_help_Clemmie_2019-02-25T14:14:21.621700
1,551,104,061.6217
10,497
pythondev
help
No, because you were calling the method without a parameter, which will then used the default parameter in the method signature(`def two_fer(name='you'):`)
2019-02-25T14:15:22.622900
Clemmie
pythondev_help_Clemmie_2019-02-25T14:15:22.622900
1,551,104,122.6229
10,498
pythondev
help
I see what you're saying
2019-02-25T14:15:48.623200
Demetrice
pythondev_help_Demetrice_2019-02-25T14:15:48.623200
1,551,104,148.6232
10,499
pythondev
help
Because i left it blank on the print statement in the bottom it would always default to the you that i put in the def statement
2019-02-25T14:16:12.624100
Demetrice
pythondev_help_Demetrice_2019-02-25T14:16:12.624100
1,551,104,172.6241
10,500
pythondev
help
I getya i getya. Thank you
2019-02-25T14:16:26.624800
Demetrice
pythondev_help_Demetrice_2019-02-25T14:16:26.624800
1,551,104,186.6248
10,501
pythondev
help
What else did i do wrong?
2019-02-25T14:16:31.625300
Demetrice
pythondev_help_Demetrice_2019-02-25T14:16:31.625300
1,551,104,191.6253
10,502
pythondev
help
You handled the blank case in your `if` logic, and the default is handling the `None` case if no parameter (or `None`) is passed to the method
2019-02-25T14:16:34.625400
Clemmie
pythondev_help_Clemmie_2019-02-25T14:16:34.625400
1,551,104,194.6254
10,503
pythondev
help
otherwise it is fine
2019-02-25T14:16:59.626100
Clemmie
pythondev_help_Clemmie_2019-02-25T14:16:59.626100
1,551,104,219.6261
10,504
pythondev
help
you can also do `if not name`, because `""` is falsey
2019-02-25T14:17:28.627700
Ashley
pythondev_help_Ashley_2019-02-25T14:17:28.627700
1,551,104,248.6277
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pythondev
help
Gezz. Such a simple assignment. Hard to believe i was doing so much wrong. Thank you so much for the help
2019-02-25T14:17:28.627800
Demetrice
pythondev_help_Demetrice_2019-02-25T14:17:28.627800
1,551,104,248.6278
10,506
pythondev
help
If you only wanted to mutate the `name` if name is blank for the `two_fer` method you could do the check for `''` inside the method
2019-02-25T14:17:36.628100
Clemmie
pythondev_help_Clemmie_2019-02-25T14:17:36.628100
1,551,104,256.6281
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pythondev
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<@Ashley> is correct, but be aware that a lot of things are falsey, including `0` and `False`, also the time midnight and empty iterators. Take that into account if you are using falsey checking
2019-02-25T14:18:49.630200
Clemmie
pythondev_help_Clemmie_2019-02-25T14:18:49.630200
1,551,104,329.6302
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pythondev
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Okay. In the interest of learning i don't actually know how to use if not to check to see if a user input a value
2019-02-25T14:19:49.631200
Demetrice
pythondev_help_Demetrice_2019-02-25T14:19:49.631200
1,551,104,389.6312
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pythondev
help
I'm looking up the syntax for that now
2019-02-25T14:19:55.631500
Demetrice
pythondev_help_Demetrice_2019-02-25T14:19:55.631500
1,551,104,395.6315
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pythondev
help
&gt;also the time midnight how do you get midnight to evaluate falsey? do datetime objects representing midnight evaluate to false?
2019-02-25T14:21:04.632700
Cherish
pythondev_help_Cherish_2019-02-25T14:21:04.632700
1,551,104,464.6327
10,511
pythondev
help
None
2019-02-25T14:22:51.632900
Clemmie
pythondev_help_Clemmie_2019-02-25T14:22:51.632900
1,551,104,571.6329
10,512
pythondev
help
Datetime objects are ok because of the date portion
2019-02-25T14:23:46.633600
Clemmie
pythondev_help_Clemmie_2019-02-25T14:23:46.633600
1,551,104,626.6336
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pythondev
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^ is true as of at least 3.4, there was some talk about changing it later, but I can’t find a reference if it has
2019-02-25T14:24:32.634700
Clemmie
pythondev_help_Clemmie_2019-02-25T14:24:32.634700
1,551,104,672.6347
10,514
pythondev
help
ah ok, I always end up using datetime's so I never actually realized this^
2019-02-25T14:24:40.634900
Cherish
pythondev_help_Cherish_2019-02-25T14:24:40.634900
1,551,104,680.6349
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pythondev
help
<https://docs.python.org/2.4/lib/truth.html> here's a general list
2019-02-25T14:25:05.635400
Ashley
pythondev_help_Ashley_2019-02-25T14:25:05.635400
1,551,104,705.6354
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pythondev
help
Yeah, it is one of those fun edge cases. Shows up with some regularity in new years type checks
2019-02-25T14:25:28.635900
Clemmie
pythondev_help_Clemmie_2019-02-25T14:25:28.635900
1,551,104,728.6359
10,517
pythondev
help
looks like that might have been changed actually <@Clemmie> -- I'm on 3.7.2 and not getting that behavior, although I haven't seen this mentioned in a changelog equivalent anywhere ```Python 3.7.2 (default, Feb 12 2019, 08:15:36) [Clang 10.0.0 (clang-1000.11.45.5)] on darwin Type "help", "copyright", "credits" or "license" for more information. &gt;&gt;&gt; from datetime import time &gt;&gt;&gt; bool(time(0, 0)) True```
2019-02-25T14:45:30.637700
Cherish
pythondev_help_Cherish_2019-02-25T14:45:30.637700
1,551,105,930.6377
10,518
pythondev
help
found it <https://hg.python.org/cpython/rev/89aa669dcc61>
2019-02-25T14:46:24.637900
Cherish
pythondev_help_Cherish_2019-02-25T14:46:24.637900
1,551,105,984.6379
10,519
pythondev
help
&gt;remove the ability of datetime.time to be considered false (closes #13936) [#13936]
2019-02-25T14:46:37.638100
Cherish
pythondev_help_Cherish_2019-02-25T14:46:37.638100
1,551,105,997.6381
10,520