query_id
int64 0
7k
| database_id
stringclasses 140
values | table_id
sequencelengths 1
5
| query
stringlengths 16
224
| answer
stringlengths 18
577
| difficulty
stringclasses 4
values |
|---|---|---|---|---|---|
500 | allergy_1 | [
"Student"
] | How many students does each advisor have? | SELECT advisor , count(*) FROM Student GROUP BY advisor | medium |
501 | allergy_1 | [
"Student"
] | Which advisor has most number of students? | SELECT advisor FROM Student GROUP BY advisor ORDER BY count(*) DESC LIMIT 1 | hard |
502 | allergy_1 | [
"Student"
] | Give the advisor with the most students. | SELECT advisor FROM Student GROUP BY advisor ORDER BY count(*) DESC LIMIT 1 | hard |
503 | allergy_1 | [
"Has_allergy"
] | How many students have cat allergies? | SELECT count(*) FROM Has_allergy WHERE Allergy = "Cat" | easy |
504 | allergy_1 | [
"Has_allergy"
] | How many students are affected by cat allergies? | SELECT count(*) FROM Has_allergy WHERE Allergy = "Cat" | easy |
505 | allergy_1 | [
"Has_allergy"
] | Show all student IDs who have at least two allergies. | SELECT StuID FROM Has_allergy GROUP BY StuID HAVING count(*) >= 2 | easy |
506 | allergy_1 | [
"Has_allergy"
] | What are the students ids of students who have more than one allergy? | SELECT StuID FROM Has_allergy GROUP BY StuID HAVING count(*) >= 2 | easy |
507 | allergy_1 | [
"Student",
"Has_allergy"
] | What are the student ids of students who don't have any allergies? | SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy | hard |
508 | allergy_1 | [
"Student",
"Has_allergy"
] | Which students are unaffected by allergies? | SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_allergy | hard |
509 | allergy_1 | [
"has_allergy",
"Student"
] | How many female students have milk or egg allergies? | SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = "F" AND T1.allergy = "Milk" OR T1.allergy = "Eggs" | hard |
510 | allergy_1 | [
"has_allergy",
"Student"
] | How many students who are female are allergic to milk or eggs? | SELECT count(*) FROM has_allergy AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.sex = "F" AND T1.allergy = "Milk" OR T1.allergy = "Eggs" | hard |
511 | allergy_1 | [
"Allergy_type",
"Has_allergy"
] | How many students have a food allergy? | SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = "food" | medium |
512 | allergy_1 | [
"Allergy_type",
"Has_allergy"
] | How many students are affected by food related allergies? | SELECT count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy WHERE T2.allergytype = "food" | medium |
513 | allergy_1 | [
"Has_allergy"
] | Which allergy has most number of students affected? | SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1 | hard |
514 | allergy_1 | [
"Has_allergy"
] | Which allergy is the most common? | SELECT Allergy FROM Has_allergy GROUP BY Allergy ORDER BY count(*) DESC LIMIT 1 | hard |
515 | allergy_1 | [
"Has_allergy"
] | Show all allergies with number of students affected. | SELECT Allergy , count(*) FROM Has_allergy GROUP BY Allergy | medium |
516 | allergy_1 | [
"Has_allergy"
] | How many students have each different allergy? | SELECT Allergy , count(*) FROM Has_allergy GROUP BY Allergy | medium |
517 | allergy_1 | [
"Allergy_type",
"Has_allergy"
] | Show all allergy type with number of students affected. | SELECT T2.allergytype , count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype | medium |
518 | allergy_1 | [
"Allergy_type",
"Has_allergy"
] | How many students are affected by each allergy type? | SELECT T2.allergytype , count(*) FROM Has_allergy AS T1 JOIN Allergy_type AS T2 ON T1.allergy = T2.allergy GROUP BY T2.allergytype | medium |
519 | allergy_1 | [
"Student",
"Has_allergy"
] | Find the last name and age of the student who has allergy to both milk and cat. | SELECT lname , age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat") | extra |
520 | allergy_1 | [
"Student",
"Has_allergy"
] | What are the last names and ages of the students who are allergic to milk and cat? | SELECT lname , age FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" INTERSECT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat") | extra |
521 | allergy_1 | [
"Student",
"Allergy_type",
"Has_allergy"
] | What are the allergies and their types that the student with first name Lisa has? And order the result by name of allergies. | SELECT T1.Allergy , T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = "Lisa" ORDER BY T1.Allergy | extra |
522 | allergy_1 | [
"Student",
"Allergy_type",
"Has_allergy"
] | What are the allergies the girl named Lisa has? And what are the types of them? Order the result by allergy names. | SELECT T1.Allergy , T1.AllergyType FROM Allergy_type AS T1 JOIN Has_allergy AS T2 ON T1.Allergy = T2.Allergy JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.Fname = "Lisa" ORDER BY T1.Allergy | extra |
523 | allergy_1 | [
"Student",
"Has_allergy"
] | Find the first name and gender of the student who has allergy to milk but not cat. | SELECT fname , sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat") | extra |
524 | allergy_1 | [
"Student",
"Has_allergy"
] | What are the first name and gender of the students who have allergy to milk but can put up with cats? | SELECT fname , sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Milk" EXCEPT SELECT StuID FROM Has_allergy WHERE Allergy = "Cat") | extra |
525 | allergy_1 | [
"Student",
"Allergy_Type",
"Has_allergy"
] | Find the average age of the students who have allergies with food and animal types. | SELECT avg(age) FROM Student WHERE StuID IN ( SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "animal") | hard |
526 | allergy_1 | [
"Student",
"Allergy_Type",
"Has_allergy"
] | How old are the students with allergies to food and animal types on average? | SELECT avg(age) FROM Student WHERE StuID IN ( SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" INTERSECT SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "animal") | hard |
527 | allergy_1 | [
"Student",
"Allergy_Type",
"Has_allergy"
] | List the first and last name of the students who do not have any food type allergy. | SELECT fname , lname FROM Student WHERE StuID NOT IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food") | extra |
528 | allergy_1 | [
"Student",
"Allergy_Type",
"Has_allergy"
] | What is the full name of each student who is not allergic to any type of food. | SELECT fname , lname FROM Student WHERE StuID NOT IN (SELECT T1.StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food") | extra |
529 | allergy_1 | [
"Student",
"Allergy_Type",
"Has_allergy"
] | Find the number of male (sex is 'M') students who have some food type allery. | SELECT count(*) FROM Student WHERE sex = "M" AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food") | extra |
530 | allergy_1 | [
"Student",
"Allergy_Type",
"Has_allergy"
] | How many male students (sex is 'M') are allergic to any type of food? | SELECT count(*) FROM Student WHERE sex = "M" AND StuID IN (SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food") | extra |
531 | allergy_1 | [
"Student",
"Has_Allergy"
] | Find the different first names and cities of the students who have allergy to milk or cat. | SELECT DISTINCT T1.fname , T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = "Milk" OR T2.Allergy = "Cat" | hard |
532 | allergy_1 | [
"Student",
"Has_Allergy"
] | What are the distinct first names and cities of the students who have allergy either to milk or to cat? | SELECT DISTINCT T1.fname , T1.city_code FROM Student AS T1 JOIN Has_Allergy AS T2 ON T1.stuid = T2.stuid WHERE T2.Allergy = "Milk" OR T2.Allergy = "Cat" | hard |
533 | allergy_1 | [
"Student",
"Allergy_Type",
"Has_allergy"
] | Find the number of students who are older than 18 and do not have allergy to either food or animal. | SELECT count(*) FROM Student WHERE age > 18 AND StuID NOT IN ( SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" OR T2.allergytype = "animal") | extra |
534 | allergy_1 | [
"Student",
"Allergy_Type",
"Has_allergy"
] | How many students are over 18 and do not have allergy to food type or animal type? | SELECT count(*) FROM Student WHERE age > 18 AND StuID NOT IN ( SELECT StuID FROM Has_allergy AS T1 JOIN Allergy_Type AS T2 ON T1.Allergy = T2.Allergy WHERE T2.allergytype = "food" OR T2.allergytype = "animal") | extra |
535 | allergy_1 | [
"Student",
"Has_allergy"
] | Find the first name and major of the students who are not allegry to soy. | SELECT fname , major FROM Student WHERE StuID NOT IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Soy") | extra |
536 | allergy_1 | [
"Student",
"Has_allergy"
] | What are the first name and major of the students who are able to consume soy? | SELECT fname , major FROM Student WHERE StuID NOT IN (SELECT StuID FROM Has_allergy WHERE Allergy = "Soy") | extra |
537 | store_1 | [
"invoices"
] | A list of the top 5 countries by number of invoices. List country name and number of invoices. | SELECT billing_country , COUNT(*) FROM invoices GROUP BY billing_country ORDER BY count(*) DESC LIMIT 5; | hard |
538 | store_1 | [
"invoices"
] | What are the top 5 countries by number of invoices and how many do they have? | SELECT billing_country , COUNT(*) FROM invoices GROUP BY billing_country ORDER BY count(*) DESC LIMIT 5; | hard |
539 | store_1 | [
"invoices"
] | A list of the top 8 countries by gross/total invoice size. List country name and gross invoice size. | SELECT billing_country , SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8; | hard |
540 | store_1 | [
"invoices"
] | What are the names of the top 8 countries by total invoice size and what are those sizes? | SELECT billing_country , SUM(total) FROM invoices GROUP BY billing_country ORDER BY SUM(total) DESC LIMIT 8; | hard |
541 | store_1 | [
"invoices"
] | A list of the top 10 countries by average invoice size. List country name and average invoice size. | SELECT billing_country , AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10; | hard |
542 | store_1 | [
"invoices"
] | What are the names of the countries and average invoice size of the top countries by size? | SELECT billing_country , AVG(total) FROM invoices GROUP BY billing_country ORDER BY AVG(total) DESC LIMIT 10; | hard |
543 | store_1 | [
"invoices",
"customers"
] | Find out 5 customers who most recently purchased something. List customers' first and last name. | SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5; | hard |
544 | store_1 | [
"invoices",
"customers"
] | What are the first and last names of the 5 customers who purchased something most recently? | SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY T2.invoice_date DESC LIMIT 5; | hard |
545 | store_1 | [
"invoices",
"customers"
] | Find out the top 10 customers by total number of orders. List customers' first and last name and the number of total orders. | SELECT T1.first_name , T1.last_name , COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10; | extra |
546 | store_1 | [
"invoices",
"customers"
] | What are the top 10 customers' first and last names by total number of orders and how many orders did they make? | SELECT T1.first_name , T1.last_name , COUNT(*) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 10; | extra |
547 | store_1 | [
"invoices",
"customers"
] | List the top 10 customers by total gross sales. List customers' first and last name and total gross sales. | SELECT T1.first_name , T1.last_name , SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10; | extra |
548 | store_1 | [
"invoices",
"customers"
] | What are the top 10 customers' first and last names with the highest gross sales, and also what are the sales? | SELECT T1.first_name , T1.last_name , SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id GROUP BY T1.id ORDER BY SUM(T2.total) DESC LIMIT 10; | extra |
549 | store_1 | [
"genres",
"tracks"
] | List the top 5 genres by number of tracks. List genres name and total tracks. | SELECT T1.name , COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 5; | extra |
550 | store_1 | [
"genres",
"tracks"
] | How many tracks does each genre have and what are the names of the top 5? | SELECT T1.name , COUNT(*) FROM genres AS T1 JOIN tracks AS T2 ON T2.genre_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 5; | extra |
551 | store_1 | [
"albums"
] | List every album's title. | SELECT title FROM albums; | easy |
552 | store_1 | [
"albums"
] | What are the titles of all the albums? | SELECT title FROM albums; | easy |
553 | store_1 | [
"albums"
] | List every album ordered by album title in ascending order. | SELECT title FROM albums ORDER BY title; | easy |
554 | store_1 | [
"albums"
] | What are the titles of all the albums alphabetically ascending? | SELECT title FROM albums ORDER BY title; | easy |
555 | store_1 | [
"albums"
] | List every album whose title starts with A in alphabetical order. | SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title; | hard |
556 | store_1 | [
"albums"
] | What are the titles of all albums that start with A in alphabetical order? | SELECT title FROM albums WHERE title LIKE 'A%' ORDER BY title; | hard |
557 | store_1 | [
"invoices",
"customers"
] | List the customers first and last name of 10 least expensive invoices. | SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY total LIMIT 10; | hard |
558 | store_1 | [
"invoices",
"customers"
] | What are the first and last names of the customers with the 10 cheapest invoices? | SELECT T1.first_name , T1.last_name FROM customers AS T1 JOIN invoices AS T2 ON T2.customer_id = T1.id ORDER BY total LIMIT 10; | hard |
559 | store_1 | [
"invoices"
] | List total amount of invoice from Chicago, IL. | SELECT sum(total) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"; | medium |
560 | store_1 | [
"invoices"
] | What are the total amount of money in the invoices billed from Chicago, Illinois? | SELECT sum(total) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"; | medium |
561 | store_1 | [
"invoices"
] | List the number of invoices from Chicago, IL. | SELECT COUNT(*) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"; | medium |
562 | store_1 | [
"invoices"
] | How many invoices were billed from Chicago, IL? | SELECT COUNT(*) FROM invoices WHERE billing_city = "Chicago" AND billing_state = "IL"; | medium |
563 | store_1 | [
"invoices"
] | List the number of invoices from the US, grouped by state. | SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state; | medium |
564 | store_1 | [
"invoices"
] | How many invoices were billed from each state? | SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state; | medium |
565 | store_1 | [
"invoices"
] | List the state in the US with the most invoices. | SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state ORDER BY COUNT(*) DESC LIMIT 1; | extra |
566 | store_1 | [
"invoices"
] | What are the states with the most invoices? | SELECT billing_state , COUNT(*) FROM invoices WHERE billing_country = "USA" GROUP BY billing_state ORDER BY COUNT(*) DESC LIMIT 1; | extra |
567 | store_1 | [
"invoices"
] | List the number of invoices and the invoice total from California. | SELECT billing_state , COUNT(*) , SUM(total) FROM invoices WHERE billing_state = "CA"; | medium |
568 | store_1 | [
"invoices"
] | What is the number of invoices and total money billed in them from CA? | SELECT billing_state , COUNT(*) , SUM(total) FROM invoices WHERE billing_state = "CA"; | medium |
569 | store_1 | [
"albums",
"artists"
] | List Aerosmith's albums. | SELECT T1.title FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Aerosmith"; | medium |
570 | store_1 | [
"albums",
"artists"
] | What are the titles of all the Aerosmith albums? | SELECT T1.title FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Aerosmith"; | medium |
571 | store_1 | [
"albums",
"artists"
] | How many albums does Billy Cobham has? | SELECT count(*) FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Billy Cobham"; | medium |
572 | store_1 | [
"albums",
"artists"
] | How many albums has Billy Cobam released? | SELECT count(*) FROM albums AS T1 JOIN artists AS T2 ON T1.artist_id = T2.id WHERE T2.name = "Billy Cobham"; | medium |
573 | store_1 | [
"customers"
] | Eduardo Martins is a customer at which company? | SELECT company FROM customers WHERE first_name = "Eduardo" AND last_name = "Martins"; | medium |
574 | store_1 | [
"customers"
] | What is the company where Eduardo Martins is a customer? | SELECT company FROM customers WHERE first_name = "Eduardo" AND last_name = "Martins"; | medium |
575 | store_1 | [
"customers"
] | What is Astrid Gruber's email and phone number? | SELECT email , phone FROM customers WHERE first_name = "Astrid" AND last_name = "Gruber"; | medium |
576 | store_1 | [
"customers"
] | What is the email and phone number of Astrid Gruber the customer? | SELECT email , phone FROM customers WHERE first_name = "Astrid" AND last_name = "Gruber"; | medium |
577 | store_1 | [
"customers"
] | How many customers live in Prague city? | SELECT count(*) FROM customers WHERE city = "Prague"; | easy |
578 | store_1 | [
"customers"
] | How many customers live in the city of Prague? | SELECT count(*) FROM customers WHERE city = "Prague"; | easy |
579 | store_1 | [
"customers"
] | How many customers in state of CA? | SELECT count(*) FROM customers WHERE state = "CA"; | easy |
580 | store_1 | [
"customers"
] | How many customers are from California? | SELECT count(*) FROM customers WHERE state = "CA"; | easy |
581 | store_1 | [
"customers"
] | What country does Roberto Almeida live? | SELECT country FROM customers WHERE first_name = "Roberto" AND last_name = "Almeida"; | medium |
582 | store_1 | [
"customers"
] | In which country does Roberto Almeida? | SELECT country FROM customers WHERE first_name = "Roberto" AND last_name = "Almeida"; | medium |
583 | store_1 | [
"artists",
"albums"
] | List the name of albums that are released by aritist whose name has 'Led' | SELECT T2.title FROM artists AS T1 JOIN albums AS T2 ON T1.id = T2.artist_id WHERE T1.name LIKE '%Led%' | hard |
584 | store_1 | [
"artists",
"albums"
] | What is the title of the album that was released by the artist whose name has the phrase 'Led'? | SELECT T2.title FROM artists AS T1 JOIN albums AS T2 ON T1.id = T2.artist_id WHERE T1.name LIKE '%Led%' | hard |
585 | store_1 | [
"employees",
"customers"
] | How many customers does Steve Johnson support? | SELECT count(*) FROM employees AS T1 JOIN customers AS T2 ON T2.support_rep_id = T1.id WHERE T1.first_name = "Steve" AND T1.last_name = "Johnson"; | medium |
586 | store_1 | [
"employees",
"customers"
] | What is the count of customers that Steve Johnson supports? | SELECT count(*) FROM employees AS T1 JOIN customers AS T2 ON T2.support_rep_id = T1.id WHERE T1.first_name = "Steve" AND T1.last_name = "Johnson"; | medium |
587 | store_1 | [
"employees"
] | What is the title, phone and hire date of Nancy Edwards? | SELECT title , phone , hire_date FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"; | medium |
588 | store_1 | [
"employees"
] | What is the title, phone number and hire date for the employee named Nancy Edwards? | SELECT title , phone , hire_date FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"; | medium |
589 | store_1 | [
"employees"
] | find the full name of employees who report to Nancy Edwards? | SELECT T2.first_name , T2.last_name FROM employees AS T1 JOIN employees AS T2 ON T1.id = T2.reports_to WHERE T1.first_name = "Nancy" AND T1.last_name = "Edwards"; | extra |
590 | store_1 | [
"employees"
] | What is the first and last name of the employee who reports to Nancy Edwards? | SELECT T2.first_name , T2.last_name FROM employees AS T1 JOIN employees AS T2 ON T1.id = T2.reports_to WHERE T1.first_name = "Nancy" AND T1.last_name = "Edwards"; | extra |
591 | store_1 | [
"employees"
] | What is the address of employee Nancy Edwards? | SELECT address FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"; | medium |
592 | store_1 | [
"employees"
] | What is Nancy Edwards's address? | SELECT address FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"; | medium |
593 | store_1 | [
"employees",
"customers"
] | Find the full name of employee who supported the most number of customers. | SELECT T1.first_name , T1.last_name FROM employees AS T1 JOIN customers AS T2 ON T1.id = T2.support_rep_id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1 | extra |
594 | store_1 | [
"employees",
"customers"
] | What is the full name of the employee who has the most customers? | SELECT T1.first_name , T1.last_name FROM employees AS T1 JOIN customers AS T2 ON T1.id = T2.support_rep_id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1 | extra |
595 | store_1 | [
"employees"
] | How many employees are living in Canada? | SELECT count(*) FROM employees WHERE country = "Canada"; | easy |
596 | store_1 | [
"employees"
] | How many employees live in Canada? | SELECT count(*) FROM employees WHERE country = "Canada"; | easy |
597 | store_1 | [
"employees"
] | What is employee Nancy Edwards's phone number? | SELECT phone FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"; | medium |
598 | store_1 | [
"employees"
] | What is the the phone number of Nancy Edwards? | SELECT phone FROM employees WHERE first_name = "Nancy" AND last_name = "Edwards"; | medium |
599 | store_1 | [
"employees"
] | Who is the youngest employee in the company? List employee's first and last name. | SELECT first_name , last_name FROM employees ORDER BY birth_date DESC LIMIT 1; | medium |
Subsets and Splits