query_id
int64 0
7k
| database_id
stringclasses 140
values | table_id
sequencelengths 1
5
| query
stringlengths 16
224
| answer
stringlengths 18
577
| difficulty
stringclasses 4
values |
|---|---|---|---|---|---|
600 | store_1 | [
"employees"
] | What si the youngest employee's first and last name? | SELECT first_name , last_name FROM employees ORDER BY birth_date DESC LIMIT 1; | medium |
601 | store_1 | [
"employees"
] | List top 10 employee work longest in the company. List employee's first and last name. | SELECT first_name , last_name FROM employees ORDER BY hire_date ASC LIMIT 10; | medium |
602 | store_1 | [
"employees"
] | What are the first and last names of the top 10 longest-serving employees? | SELECT first_name , last_name FROM employees ORDER BY hire_date ASC LIMIT 10; | medium |
603 | store_1 | [
"employees"
] | Find the number of employees whose title is IT Staff from each city? | SELECT count(*) , city FROM employees WHERE title = 'IT Staff' GROUP BY city | medium |
604 | store_1 | [
"employees"
] | How many employees who are IT staff are from each city? | SELECT count(*) , city FROM employees WHERE title = 'IT Staff' GROUP BY city | medium |
605 | store_1 | [
"employees"
] | Which employee manage most number of peoples? List employee's first and last name, and number of people report to that employee. | SELECT T2.first_name , T2.last_name , count(T1.reports_to) FROM employees AS T1 JOIN employees AS T2 ON T1.reports_to = T2.id GROUP BY T1.reports_to ORDER BY count(T1.reports_to) DESC LIMIT 1; | extra |
606 | store_1 | [
"employees"
] | What are the first and last names of all the employees and how many people report to them? | SELECT T2.first_name , T2.last_name , count(T1.reports_to) FROM employees AS T1 JOIN employees AS T2 ON T1.reports_to = T2.id GROUP BY T1.reports_to ORDER BY count(T1.reports_to) DESC LIMIT 1; | extra |
607 | store_1 | [
"invoices",
"customers"
] | How many orders does Lucas Mancini has? | SELECT count(*) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini"; | medium |
608 | store_1 | [
"invoices",
"customers"
] | How many orders does Luca Mancini have in his invoices? | SELECT count(*) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini"; | medium |
609 | store_1 | [
"invoices",
"customers"
] | What is the total amount of money spent by Lucas Mancini? | SELECT sum(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini"; | medium |
610 | store_1 | [
"invoices",
"customers"
] | How much money did Lucas Mancini spend? | SELECT sum(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = "Lucas" AND T1.last_name = "Mancini"; | medium |
611 | store_1 | [
"media_types"
] | List all media types. | SELECT name FROM media_types; | easy |
612 | store_1 | [
"media_types"
] | What are the names of all the media types? | SELECT name FROM media_types; | easy |
613 | store_1 | [
"genres"
] | List all different genre types. | SELECT DISTINCT name FROM genres; | easy |
614 | store_1 | [
"genres"
] | What are the different names of the genres? | SELECT DISTINCT name FROM genres; | easy |
615 | store_1 | [
"playlists"
] | List the name of all playlist. | SELECT name FROM playlists; | easy |
616 | store_1 | [
"playlists"
] | What are the names of all the playlists? | SELECT name FROM playlists; | easy |
617 | store_1 | [
"tracks"
] | Who is the composer of track Fast As a Shark? | SELECT composer FROM tracks WHERE name = "Fast As a Shark"; | easy |
618 | store_1 | [
"tracks"
] | What is the composer who created the track "Fast As a Shark"? | SELECT composer FROM tracks WHERE name = "Fast As a Shark"; | easy |
619 | store_1 | [
"tracks"
] | How long does track Fast As a Shark has? | SELECT milliseconds FROM tracks WHERE name = "Fast As a Shark"; | easy |
620 | store_1 | [
"tracks"
] | How many milliseconds long is Fast As a Shark? | SELECT milliseconds FROM tracks WHERE name = "Fast As a Shark"; | easy |
621 | store_1 | [
"genres",
"tracks"
] | What is the name of tracks whose genre is Rock? | SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock"; | medium |
622 | store_1 | [
"genres",
"tracks"
] | What is the name of all tracks in the Rock genre? | SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock"; | medium |
623 | store_1 | [
"albums",
"tracks"
] | What is title of album which track Balls to the Wall belongs to? | SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T2.name = "Balls to the Wall"; | medium |
624 | store_1 | [
"albums",
"tracks"
] | What is the name of the album that has the track Ball to the Wall? | SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T2.name = "Balls to the Wall"; | medium |
625 | store_1 | [
"albums",
"tracks"
] | List name of all tracks in Balls to the Wall. | SELECT T2.name FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.title = "Balls to the Wall"; | medium |
626 | store_1 | [
"albums",
"tracks"
] | What is the name of all tracks in the album named Balls to the Wall? | SELECT T2.name FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.title = "Balls to the Wall"; | medium |
627 | store_1 | [
"albums",
"tracks"
] | List title of albums have the number of tracks greater than 10. | SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.album_id GROUP BY T1.id HAVING count(T1.id) > 10; | medium |
628 | store_1 | [
"albums",
"tracks"
] | What are the names of the albums that have more than 10 tracks? | SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.album_id GROUP BY T1.id HAVING count(T1.id) > 10; | medium |
629 | store_1 | [
"genres",
"tracks",
"media_types"
] | List the name of tracks belongs to genre Rock and whose media type is MPEG audio file. | SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" AND T3.name = "MPEG audio file"; | hard |
630 | store_1 | [
"genres",
"tracks",
"media_types"
] | What are the names of all Rock tracks that are stored on MPEG audio files? | SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" AND T3.name = "MPEG audio file"; | hard |
631 | store_1 | [
"genres",
"tracks",
"media_types"
] | List the name of tracks belongs to genre Rock or media type is MPEG audio file. | SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" OR T3.name = "MPEG audio file"; | extra |
632 | store_1 | [
"genres",
"tracks",
"media_types"
] | What are the names of all tracks that belong to the Rock genre and whose media type is MPEG? | SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = "Rock" OR T3.name = "MPEG audio file"; | extra |
633 | store_1 | [
"genres",
"tracks"
] | List the name of tracks belongs to genre Rock or genre Jazz. | SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock" OR T1.name = "Jazz" | hard |
634 | store_1 | [
"genres",
"tracks"
] | What are the names of the tracks that are Rock or Jazz songs? | SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = "Rock" OR T1.name = "Jazz" | hard |
635 | store_1 | [
"tracks",
"playlists",
"playlist_tracks"
] | List the name of all tracks in the playlists of Movies. | SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T3.id = T2.playlist_id WHERE T3.name = "Movies"; | hard |
636 | store_1 | [
"tracks",
"playlists",
"playlist_tracks"
] | What are the names of all tracks that are on playlists titled Movies? | SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T3.id = T2.playlist_id WHERE T3.name = "Movies"; | hard |
637 | store_1 | [
"playlists",
"playlist_tracks"
] | List the name of playlist which has number of tracks greater than 100. | SELECT T2.name FROM playlist_tracks AS T1 JOIN playlists AS T2 ON T2.id = T1.playlist_id GROUP BY T1.playlist_id HAVING count(T1.track_id) > 100; | medium |
638 | store_1 | [
"playlists",
"playlist_tracks"
] | What are the names of all playlists that have more than 100 tracks? | SELECT T2.name FROM playlist_tracks AS T1 JOIN playlists AS T2 ON T2.id = T1.playlist_id GROUP BY T1.playlist_id HAVING count(T1.track_id) > 100; | medium |
639 | store_1 | [
"customers",
"invoices",
"tracks",
"invoice_lines"
] | List all tracks bought by customer Daan Peeters. | SELECT T1.name FROM tracks AS T1 JOIN invoice_lines AS T2 ON T1.id = T2.track_id JOIN invoices AS T3 ON T3.id = T2.invoice_id JOIN customers AS T4 ON T4.id = T3.customer_id WHERE T4.first_name = "Daan" AND T4.last_name = "Peeters"; | extra |
640 | store_1 | [
"customers",
"invoices",
"tracks",
"invoice_lines"
] | What are the tracks that Dean Peeters bought? | SELECT T1.name FROM tracks AS T1 JOIN invoice_lines AS T2 ON T1.id = T2.track_id JOIN invoices AS T3 ON T3.id = T2.invoice_id JOIN customers AS T4 ON T4.id = T3.customer_id WHERE T4.first_name = "Daan" AND T4.last_name = "Peeters"; | extra |
641 | store_1 | [
"tracks"
] | How much is the track Fast As a Shark? | SELECT unit_price FROM tracks WHERE name = "Fast As a Shark"; | easy |
642 | store_1 | [
"tracks"
] | What is the unit price of the tune "Fast As a Shark"? | SELECT unit_price FROM tracks WHERE name = "Fast As a Shark"; | easy |
643 | store_1 | [
"tracks",
"playlists",
"playlist_tracks"
] | Find the name of tracks which are in Movies playlist but not in music playlist. | SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' EXCEPT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music' | extra |
644 | store_1 | [
"tracks",
"playlists",
"playlist_tracks"
] | What are the names of all tracks that are on the Movies playlist but not in the music playlist? | SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' EXCEPT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music' | extra |
645 | store_1 | [
"tracks",
"playlists",
"playlist_tracks"
] | Find the name of tracks which are in both Movies and music playlists. | SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' INTERSECT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music' | extra |
646 | store_1 | [
"tracks",
"playlists",
"playlist_tracks"
] | What are the names of all the tracks that are in both the Movies and music playlists? | SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' INTERSECT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music' | extra |
647 | store_1 | [
"genres",
"tracks"
] | Find number of tracks in each genre? | SELECT count(*) , T1.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id GROUP BY T1.name; | medium |
648 | store_1 | [
"genres",
"tracks"
] | How many tracks are in each genre? | SELECT count(*) , T1.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id GROUP BY T1.name; | medium |
649 | journal_committee | [
"editor"
] | How many editors are there? | SELECT count(*) FROM editor | easy |
650 | journal_committee | [
"editor"
] | List the names of editors in ascending order of age. | SELECT Name FROM editor ORDER BY Age ASC | easy |
651 | journal_committee | [
"editor"
] | What are the names and ages of editors? | SELECT Name , Age FROM editor | medium |
652 | journal_committee | [
"editor"
] | List the names of editors who are older than 25. | SELECT Name FROM editor WHERE Age > 25 | easy |
653 | journal_committee | [
"editor"
] | Show the names of editors of age either 24 or 25. | SELECT Name FROM editor WHERE Age = 24 OR Age = 25 | medium |
654 | journal_committee | [
"editor"
] | What is the name of the youngest editor? | SELECT Name FROM editor ORDER BY Age ASC LIMIT 1 | medium |
655 | journal_committee | [
"editor"
] | What are the different ages of editors? Show each age along with the number of editors of that age. | SELECT Age , COUNT(*) FROM editor GROUP BY Age | medium |
656 | journal_committee | [
"editor"
] | Please show the most common age of editors. | SELECT Age FROM editor GROUP BY Age ORDER BY COUNT(*) DESC LIMIT 1 | hard |
657 | journal_committee | [
"journal"
] | Show the distinct themes of journals. | SELECT DISTINCT Theme FROM journal | easy |
658 | journal_committee | [
"journal",
"journal_committee",
"editor"
] | Show the names of editors and the theme of journals for which they serve on committees. | SELECT T2.Name , T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID | medium |
659 | journal_committee | [
"journal",
"journal_committee",
"editor"
] | For each journal_committee, find the editor name and the journal theme. | SELECT T2.Name , T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID | medium |
660 | journal_committee | [
"journal",
"journal_committee",
"editor"
] | Show the names and ages of editors and the theme of journals for which they serve on committees, in ascending alphabetical order of theme. | SELECT T2.Name , T2.age , T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID ORDER BY T3.Theme ASC | hard |
661 | journal_committee | [
"journal",
"journal_committee",
"editor"
] | Show the names of editors that are on the committee of journals with sales bigger than 3000. | SELECT T2.Name FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID WHERE T3.Sales > 3000 | hard |
662 | journal_committee | [
"journal_committee",
"editor"
] | Show the id, name of each editor and the number of journal committees they are on. | SELECT T1.editor_id , T1.Name , COUNT(*) FROM editor AS T1 JOIN journal_committee AS T2 ON T1.Editor_ID = T2.Editor_ID GROUP BY T1.editor_id | medium |
663 | journal_committee | [
"journal_committee",
"editor"
] | Show the names of editors that are on at least two journal committees. | SELECT T1.Name FROM editor AS T1 JOIN journal_committee AS T2 ON T1.Editor_ID = T2.Editor_ID GROUP BY T1.Name HAVING COUNT(*) >= 2 | medium |
664 | journal_committee | [
"journal_committee",
"editor"
] | List the names of editors that are not on any journal committee. | SELECT Name FROM editor WHERE editor_id NOT IN (SELECT editor_id FROM journal_committee) | hard |
665 | journal_committee | [
"journal",
"journal_committee"
] | List the date, theme and sales of the journal which did not have any of the listed editors serving on committee. | SELECT date , theme , sales FROM journal EXCEPT SELECT T1.date , T1.theme , T1.sales FROM journal AS T1 JOIN journal_committee AS T2 ON T1.journal_ID = T2.journal_ID | extra |
666 | journal_committee | [
"journal",
"journal_committee"
] | What is the average sales of the journals that have an editor whose work type is 'Photo'? | SELECT avg(T1.sales) FROM journal AS T1 JOIN journal_committee AS T2 ON T1.journal_ID = T2.journal_ID WHERE T2.work_type = 'Photo' | medium |
667 | customers_card_transactions | [
"Accounts"
] | How many accounts do we have? | SELECT count(*) FROM Accounts | easy |
668 | customers_card_transactions | [
"Accounts"
] | Count the number of accounts. | SELECT count(*) FROM Accounts | easy |
669 | customers_card_transactions | [
"Accounts"
] | Show ids, customer ids, names for all accounts. | SELECT account_id , customer_id , account_name FROM Accounts | medium |
670 | customers_card_transactions | [
"Accounts"
] | What are the account ids, customer ids, and account names for all the accounts? | SELECT account_id , customer_id , account_name FROM Accounts | medium |
671 | customers_card_transactions | [
"Accounts"
] | Show other account details for account with name 338. | SELECT other_account_details FROM Accounts WHERE account_name = "338" | easy |
672 | customers_card_transactions | [
"Accounts"
] | What are the other account details for the account with the name 338? | SELECT other_account_details FROM Accounts WHERE account_name = "338" | easy |
673 | customers_card_transactions | [
"Accounts",
"Customers"
] | What is the first name, last name, and phone of the customer with account name 162? | SELECT T2.customer_first_name , T2.customer_last_name , T2.customer_phone FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = "162" | medium |
674 | customers_card_transactions | [
"Accounts",
"Customers"
] | Give the full name and phone of the customer who has the account name 162. | SELECT T2.customer_first_name , T2.customer_last_name , T2.customer_phone FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = "162" | medium |
675 | customers_card_transactions | [
"Accounts",
"Customers"
] | How many accounts does the customer with first name Art and last name Turcotte have? | SELECT count(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte" | medium |
676 | customers_card_transactions | [
"Accounts",
"Customers"
] | Return the number of accounts that the customer with the first name Art and last name Turcotte has. | SELECT count(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Art" AND T2.customer_last_name = "Turcotte" | medium |
677 | customers_card_transactions | [
"Accounts"
] | Show all customer ids and the number of accounts for each customer. | SELECT customer_id , count(*) FROM Accounts GROUP BY customer_id | medium |
678 | customers_card_transactions | [
"Accounts"
] | How many accounts are there for each customer id? | SELECT customer_id , count(*) FROM Accounts GROUP BY customer_id | medium |
679 | customers_card_transactions | [
"Accounts"
] | Show the customer id and number of accounts with most accounts. | SELECT customer_id , count(*) FROM Accounts GROUP BY customer_id ORDER BY count(*) DESC LIMIT 1 | hard |
680 | customers_card_transactions | [
"Accounts"
] | What is the customer id of the customer with the most accounts, and how many accounts does this person have? | SELECT customer_id , count(*) FROM Accounts GROUP BY customer_id ORDER BY count(*) DESC LIMIT 1 | hard |
681 | customers_card_transactions | [
"Accounts",
"Customers"
] | What is the customer first, last name and id with least number of accounts. | SELECT T2.customer_first_name , T2.customer_last_name , T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) ASC LIMIT 1 | extra |
682 | customers_card_transactions | [
"Accounts",
"Customers"
] | Give the full name and customer id of the customer with the fewest accounts. | SELECT T2.customer_first_name , T2.customer_last_name , T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) ASC LIMIT 1 | extra |
683 | customers_card_transactions | [
"Accounts",
"Customers"
] | Show the number of all customers without an account. | SELECT count(*) FROM Customers WHERE customer_id NOT IN (SELECT customer_id FROM Accounts) | extra |
684 | customers_card_transactions | [
"Accounts",
"Customers"
] | How many customers do not have an account? | SELECT count(*) FROM Customers WHERE customer_id NOT IN (SELECT customer_id FROM Accounts) | extra |
685 | customers_card_transactions | [
"Accounts",
"Customers"
] | Show the first names and last names of customers without any account. | SELECT customer_first_name , customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id | extra |
686 | customers_card_transactions | [
"Accounts",
"Customers"
] | What are the full names of customers who do not have any accounts? | SELECT customer_first_name , customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id | extra |
687 | customers_card_transactions | [
"Accounts",
"Customers"
] | Show distinct first and last names for all customers with an account. | SELECT DISTINCT T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id | medium |
688 | customers_card_transactions | [
"Accounts",
"Customers"
] | What are the full names of customers who have accounts? | SELECT DISTINCT T1.customer_first_name , T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id | medium |
689 | customers_card_transactions | [
"Accounts"
] | How many customers have an account? | SELECT count(DISTINCT customer_id) FROM Accounts | easy |
690 | customers_card_transactions | [
"Accounts"
] | Count the number of customers who hold an account. | SELECT count(DISTINCT customer_id) FROM Accounts | easy |
691 | customers_card_transactions | [
"Customers"
] | How many customers do we have? | SELECT count(*) FROM Customers | easy |
692 | customers_card_transactions | [
"Customers"
] | Count the number of customers. | SELECT count(*) FROM Customers | easy |
693 | customers_card_transactions | [
"Customers"
] | Show ids, first names, last names, and phones for all customers. | SELECT customer_id , customer_first_name , customer_last_name , customer_phone FROM Customers | medium |
694 | customers_card_transactions | [
"Customers"
] | What are the ids, full names, and phones of each customer? | SELECT customer_id , customer_first_name , customer_last_name , customer_phone FROM Customers | medium |
695 | customers_card_transactions | [
"Customers"
] | What is the phone and email for customer with first name Aniyah and last name Feest? | SELECT customer_phone , customer_email FROM Customers WHERE customer_first_name = "Aniyah" AND customer_last_name = "Feest" | medium |
696 | customers_card_transactions | [
"Customers"
] | Return the phone and email of the customer with the first name Aniyah and last name Feest. | SELECT customer_phone , customer_email FROM Customers WHERE customer_first_name = "Aniyah" AND customer_last_name = "Feest" | medium |
697 | customers_card_transactions | [
"Customers_cards"
] | Show the number of customer cards. | SELECT count(*) FROM Customers_cards | easy |
698 | customers_card_transactions | [
"Customers_cards"
] | How many customer cards are there? | SELECT count(*) FROM Customers_cards | easy |
699 | customers_card_transactions | [
"Customers_cards"
] | Show ids, customer ids, card type codes, card numbers for all cards. | SELECT card_id , customer_id , card_type_code , card_number FROM Customers_cards | medium |
Subsets and Splits